Problem: Given the previous scenario but this time, let's say that the full-grown giraffe has a different height of 78 feet. If a baby giraffe is still 7.34 feet shorter than this full-grown giraffe, then how tall is the baby giraffe now?

LLemma 34B:

 Reasoning: The full-grown giraffe is 78 feet tall.
The baby giraffe is 7.34 feet shorter than the full-grown giraffe.
The baby giraffe is 78-7.34 = <<78-7.34=70.66>>70.66 feet tall.
### Answer: 70.66

Expected answer: 70.6600000000000

Correct? Yes

Problem: In a different playground, there was also a slide that was initially 71.36 meters long. However, safety concerns caused the officials to reduce the length by 24 meters instead of the original 50.0 meters. What is the new length of this slide?

LLemma 34B:

 Reasoning: The new length of the slide is 71.36-24 = <<71.36-24=47.36>>47.36 meters.
### Answer: 47.36

Expected answer: 47.3600000000000

Correct? Yes

Problem: The farmer decides to make tomato sauce and uses up 81.0 kg of the tomatoes he collected. After processing those tomatoes into sauce, how much weight in tomatoes does he have left?

LLemma 34B:

 Reasoning: The farmer has 143.89-81.0 = <<143.89-81.0=62.89>>62.89 kg of tomatoes left.
### Answer: 62.89

Expected answer: 62.8900000000000

Correct? Yes

Problem: If instead of 57.19 kg, the farmer actually collected 84 kg of tomatoes on the second day, what would be the new total weight of tomatoes he collected over the two days?

LLemma 34B:

 Reasoning: The farmer collected 86.7+84 = <<86.7+84=170.7>>170.7 kg of tomatoes over the two days.
### Answer: 170.7

Expected answer: 170.700000000000

Correct? Yes

Problem: Instead of the original price being $75.0, assume that the original price of the skirt was $49. How much would the skirt cost after the first discount of $37.5?

LLemma 34B:

 Reasoning: The skirt would cost $49-$37.5 = <<49-37.5=11.5>>$11.5 after the first discount.
### Answer: $11.5 

Expected answer: 11.5000000000000

Correct? Yes

Problem: In addition to the existing wheat and corn fields, the farm has a newly acquired barley field that spans 7.16 acres. What is the total acreage of wheat, corn, and barley fields altogether on the farm now?

LLemma 34B:

 Reasoning: 47.4+7.16 = <<47.4+7.16=54.56>>54.56 acres
### Answer: 54.56

Expected answer: 54.5600000000000

Correct? Yes

Problem: Suppose instead of the 35.9 acres of wheat in the original calculation, the farm actually has 93 acres of wheat fields. Taking the updated acreage of wheat fields into account and keeping the 11.5 acres of corn fields the same, what would then be the total acreage of wheat and corn fields on the farm?

LLemma 34B:

 Reasoning: 93+11.5 = <<93+11.5=104.5>>104.5 acres
### Answer: 104.5

Expected answer: 104.500000000000

Correct? Yes

Problem: Following the previous problem, after filling each bucket, 2.4 liters of water is lost due to leakage. What would be the revised amount of water in each bucket?

LLemma 34B:

 Reasoning: 8.2-2.4 = <<8.2-2.4=5.8>>5.8 liters of water is in each bucket.
### Answer: 5.8

Expected answer: 5.80000000000000

Correct? Yes

Problem: Following the previous problem, suppose that instead of 65.9 buckets the water was divided into 33 buckets. How many liters of water would have been in each bucket under this new arrangement?

LLemma 34B:

 Reasoning: 540.38/33 = <<540.38/33=16.4>>16.4 liters of water would have been in each bucket under this new arrangement.
### Answer: 16.4

Expected answer: 16.3751515151515

Correct? Yes

Problem: After increasing its speed, the UFO maintained its new speed for 52.9 hours. How many miles did the UFO travel at its new speed?

LLemma 34B:

 Reasoning: The UFO traveled 97.46*52.9 = <<97.46*52.9=5154.92>>5154.92 miles at its new speed.
### Answer: 5154.92

Expected answer: 5155.63400000000

Correct? No

Problem: Suppose that the UFO was originally moving at a speed of 94.83 mph, but then it increased its speed by 72 mph instead of 2.63 mph. What would its new speed be now?

LLemma 34B:

 Reasoning: The UFO increased its speed by 72 miles per hour.
The new speed of the UFO is 94.83+72 = <<94.83+72=166.83>>166.83 miles per hour.
### Answer: 166.83

Expected answer: 166.830000000000

Correct? Yes

Problem: After swimming 95.34 kilometers to the east and another 41.6 kilometers in the same direction, the Penguin continued its journey and swam an additional 97.85 kilometers. What is the total distance that the Penguin swam?

LLemma 34B:

 Reasoning: The Penguin swam 95.34+41.6+97.85 = <<95.34+41.6+97.85=234.8>>234.8 kilometers.
### Answer: 234.8

Expected answer: 234.790000000000

Correct? Yes

Problem: Suppose instead of swimming 95.34 kilometers to the east initially, the penguin only swam 12 kilometers before continuing for another 41.6 kilometers in the same direction. How much distance would the penguin have covered in this scenario?

LLemma 34B:

 Reasoning: The Penguin swam 12+41.6 = <<12+41.6=53.6>>53.6 kilometers.
### Answer: 53.6

Expected answer: 53.6000000000000

Correct? Yes

Problem: In the park, there is another identical slide next to the first one which also gets extended by the same 9.86 feet. After this extension, what is the total length of the two slides put together?

LLemma 34B:

 Reasoning: The total length of the two slides is 96.28+96.28 = <<96.28+96.28=192.56>>192.56 feet.
### Answer: 192.56

Expected answer: 192.560000000000

Correct? Yes

Problem: Suppose the park decided to make an alteration to the plan and instead wanted to extend the slide by 81 feet rather than 9.86 feet. How long would the slide be after this extension?

LLemma 34B:

 Reasoning: The slide is 86.42+81 = <<86.42+81=167.42>>167.42 feet long.
### Answer: 167.42

Expected answer: 167.420000000000

Correct? Yes

Problem: Considering the ice cream shop you previously calculated about. If the total amount of ice cream sold (1878.8 gallons) was actually spread over 87 days instead of 44.0 days, how many gallons of ice cream would have been sold each day?

LLemma 34B:

 Reasoning: They sold 1878.8/87 = <<1878.8/87=21.7>>21.7 gallons of ice cream each day.
### Answer: 21.7

Expected answer: 21.5954022988506

Correct? Yes

Problem: After buying the ice skates and skate guards, you decide to take advantage of a special offer that gives you a discount of $46.83. What would be your new total cost after this discount is applied?

LLemma 34B:

 Reasoning: The new total cost after the discount is applied is 136.26-46.83 = <<136.26-46.83=89.43>>89.43.
### Answer: 89.43

Expected answer: 89.4300000000000

Correct? Yes

Problem: Suppose instead of the original pair of ice skates costing $81.66, you found a different pair on sale for only $25. If you still buy the skate guards for an additional $54.6, what would be the total cost of these discounted ice skates combined with the skate guards?

LLemma 34B:

 Reasoning: The total cost of the ice skates combined with the skate guards is 25+54.6 = <<25+54.6=79.6>>79.6.
### Answer: 79.6

Expected answer: 79.6000000000000

Correct? Yes

Problem: If originally, the farmer had harvested 36.0 kilograms of strawberries and now instead, he sold 12 kilograms of strawberries. How many kilograms of strawberries does he have left now?

LLemma 34B:

 Reasoning: The farmer has 36.0-12 = <<36.0-12=24>>24 kilograms of strawberries left.
### Answer: 24

Expected answer: 24.0000000000000

Correct? Yes

Problem: Consider the same scenario but with a different original cost. If the pillow originally cost $72 instead of $22.88 and its price is reduced to $14.2 after a sale, what would be the amount of the discount now?

LLemma 34B:

 Reasoning: The amount of the discount is $72-$14.2 = <<72-14.2=57.8>>$57.8.
### Answer: $57.8 

Expected answer: 57.8000000000000

Correct? Yes

Problem: In the initial situation, the bunch of bananas weighed 79 grams instead of 77.8 grams. After removing the peel, which weighed 7.0 grams as before, what would be the new weight of the bananas this time?

LLemma 34B:

 Reasoning: The weight of the bananas after removing the peel is 79-7.0 = <<79-7.0=72.0>>72.0 grams.
### Answer: 72.0

Expected answer: 72.0000000000000

Correct? Yes

Problem: After the kids added sand to their sandcastle, they decided to make it even bigger. They multiplied the original weight of the sand by 46.6. What is the total weight of the sand in the sandcastle after their addition?

LLemma 34B:

 Reasoning: The sandcastle weighs 62.78*46.6 = <<62.78*46.6=2910.168>>2910.168 pounds in total.
### Answer: 2910.168

Expected answer: 2925.54800000000

Correct? No

Problem: As a follow-up to the previous problem, suppose that a space probe needs to use 50.03 kilograms of fuel for every million kilometers it travels towards the sun. If it starts its journey on the second day, how many kilograms of fuel will it need to reach the Sun?

LLemma 34B:

 Reasoning: The distance from the Earth to the Sun on the second day is 71.39 million kilometers.
The space probe needs 50.03 kilograms of fuel for every million kilometers it travels towards the sun.
The space probe needs 71.39*50.03 = <<71.39*50.03=3569.94>>3569.94 kilograms of fuel to reach the Sun.
### Answer: 3569.94

Expected answer: 3571.64170000000

Correct? No

Problem: As a follow up to the previous problem, suppose that instead of the initial distance being 56.14 million kilometers, the Earth was initially 60 million kilometers far from the Sun. After increasing by 15.25 million kilometers, what would be the distance from Earth to the Sun on the following day, in millions of kilometers?

LLemma 34B:

 Reasoning: The distance from the Earth to the Sun on the second day is 60+15.25 = <<60+15.25=75.25>>75.25 million kilometers.
### Answer: 75.25

Expected answer: 75.2500000000000

Correct? Yes

Problem: Suppose that for each degree drop in temperature, the cloud loses 97.29 liters of water vapor. How much water vapor would the cloud lose given the temperature change from the previous question?

LLemma 34B:

 Reasoning: The cloud would lose 35.43*97.29 = <<35.43*97.29=3450.95>>3450.95 liters of water vapor.
### Answer: 3450.95

Expected answer: 3446.98470000000

Correct? No

Problem: Suppose that instead of dropping from 92.5 degrees Fahrenheit, the temperature in the cloud layer had dropped from 87 degrees Fahrenheit. How much would the temperature change be in this situation?

LLemma 34B:

 Reasoning: The temperature change is 87-57.07 = <<87-57.07=30.93>>30.93 degrees Fahrenheit.
### Answer: 30.93

Expected answer: 29.9300000000000

Correct? No

Problem: After the giraffe walks 42.53 miles to the north in the morning and 28.9 miles to the east in the afternoon, it then retraces 60.5 miles back towards its starting point. How many miles is the giraffe from its starting point now?

LLemma 34B:

 Reasoning: The giraffe is 42.53+28.9-60.5 = <<42.53+28.9-60.5=14.43>>14.43 miles from its starting point.
### Answer: 14.43

Expected answer: 10.9300000000000

Correct? No

Problem: If the giraffe had walked 42.53 miles to the north in the morning and then 57 miles to the east in the afternoon instead of 28.9, how many miles in total would the giraffe have walked?

LLemma 34B:

 Reasoning: The Giraffe walked 42.53+57 = <<42.53+57=99.53>>99.53 miles in total.
### Answer: 99.53

Expected answer: 99.5300000000000

Correct? Yes

Problem: A train ticket costs $14.15 and the cost of a meal on the train is $95.07. After your meal, you decide to buy a cool souvenir train mug for $4.02. How much would it cost in total for the train ticket, meal, and souvenir mug?

LLemma 34B:

 Reasoning: The total cost is $14.15+$95.07+$4.02 = <<14.15+95.07+4.02=113.24>>113.24.
### Answer: 113.24

Expected answer: 113.240000000000

Correct? Yes

Problem: The train ticket originally costs $14.15, and in this follow-up question, we're considering what happens if the meal cost is changed to $59. Now, how much is the total cost for the ticket and the meal?

LLemma 34B:

 Reasoning: The total cost is $14.15+$59 = <<14.15+59=73.15>>73.15.
### Answer: 73.15

Expected answer: 73.1500000000000

Correct? Yes

Problem: Following the viewing of the galaxy, the scientist decides to amplify her binocular lens, multiplying the viewing scope by 5.21 times. What is the new approximate distance in light years that she can view through each scope after amplification?

LLemma 34B:

 Reasoning: 50.5*5.21 = <<50.5*5.21=266.955>>266.955 light years.
### Answer: 266.955

Expected answer: 262.584000000000

Correct? No

Problem: Following her studies, the scientist decides to adjust her binoculars to view the galaxy through only 65 different scopes instead of the previous 85.3. If the total distance remains the same, 4299.12 light years, what is the new approximate distance in light years that she sees through each scope?

LLemma 34B:

 Reasoning: 4299.12/65 = <<4299.12/65=66.1>>66.1 light years.
### Answer: 66.1

Expected answer: 66.1403076923077

Correct? Yes

Problem: Originally, the water company decided to divide the 1774.46 cubic meters of water between 28.9 storage tanks. However, it later decides to evenly distribute the water among 46 tanks instead. How many cubic meters of water will each tank contain under this new distribution plan?

LLemma 34B:

 Reasoning: 1774.46/46 = <<1774.46/46=38.3>>38.3 cubic meters of water will each tank contain under this new distribution plan.
### Answer: 38.3

Expected answer: 38.5752173913043

Correct? Yes

Problem: After the modifications, the star's magnitude brightness is multiplied by a factor of 96.1 due to interference from the earth's atmosphere. What is the value of the star's final observed brightness after being adjusted for atmospheric interference?

LLemma 34B:

 Reasoning: The star's final observed brightness is 101.16*96.1 = <<101.16*96.1=9749.96>>9749.96.
### Answer: 9749.96

Expected answer: 9721.47600000000

Correct? No

Problem: Suppose the star's observed magnitude brightness was modified by 54 units instead of 4.7 units, keeping its intrinsic brightness the same at 96.46 units. What would be the total magnitude brightness of the star then when these modifications are added?

LLemma 34B:

 Reasoning: The total magnitude brightness of the star would be 96.46+54 = <<96.46+54=150.46>>150.46.
### Answer: 150.46

Expected answer: 150.460000000000

Correct? Yes

Problem: If a smaller blanket has a width of 94.35 feet, what would be the total width in feet if you laid the large and small blankets side by side?

LLemma 34B:

 Reasoning: The total width of the blankets is 94.35+3.8 = <<94.35+3.8=98.15>>98.15 feet.
### Answer: 98.15

Expected answer: 98.1500000000000

Correct? Yes

Problem: If the large blanket actually had a total area of 86 square feet instead of 175.56 while keeping the length identical at 46.2 feet, what would be the new width in feet?

LLemma 34B:

 Reasoning: The width of the blanket is 86/46.2 = <<86/46.2=1.86>>1.86 feet.
### Answer: 1.86

Expected answer: 1.86147186147186

Correct? Yes

Problem: After successfully handling the small fire, the firefighter then moves on to control a medium fire, using an additional 46.61 liters of water. How many liters of water has the firefighter used in total?

LLemma 34B:

 Reasoning: The firefighter used 123.63+46.61 = <<123.63+46.61=170.24>>170.24 liters of water in total.
### Answer: 170.24

Expected answer: 170.240000000000

Correct? Yes

Problem: Suppose the firefighter initially used 92 liters of water to extinguish the small fire instead of 37.7 liters, but still uses an additional 85.93 liters to cool down the area. How many liters of water has the firefighter used in total now?

LLemma 34B:

 Reasoning: The firefighter used 92+85.93 = <<92+85.93=177.93>>177.93 liters of water in total.
### Answer: 177.93

Expected answer: 177.930000000000

Correct? Yes

Problem: Following the last snow season, the weather department is predicting that the upcoming season will have double the number of snowfalls as the previous season. If the previous season had a certain number of snowfalls, each measuring 38.3 inches for a total of 509.39 inches, how many snowfalls are expected in the upcoming winter season?

LLemma 34B:

 Reasoning: 509.39/38.3 = <<509.39/38.3=13.3>>13.3 snowfalls were there during the season.
2*13.3 = <<2*13.3=26.6>>26.6 snowfalls are expected in the upcoming winter season.
### Answer: 26.6

Expected answer: 26.6000000000000

Correct? Yes

Problem: In retrospect, the Met Office revised their measurements for the previous winter season. Instead of a total of 509.39 inches of snowfall, there were only 83 inches, still with each snowfall measuring 38.3 inches. With that in mind, how many snowfalls were there truly last winter season?

LLemma 34B:

 Reasoning: 83/38.3 = <<83/38.3=2.17>>2.17 snowfalls were there last winter season.
### Answer: 2.17

Expected answer: 2.16710182767624

Correct? Yes

Problem: Following from the previous question, let's consider a smaller clock that initially measures 6 cm in height. If it also has a base of 1.58 cm that is removed, what would be the height of the main body of this smaller clock without the base?

LLemma 34B:

 Reasoning: The main body of the smaller clock is 6-1.58 = <<6-1.58=4.42>>4.42 cm tall.
### Answer: 4.42

Expected answer: 4.42000000000000

Correct? Yes

Problem: Following up on the previous problem, the toy car runs on a battery that drains power proportional to the change in its speed per second. The rate is 24.8 mAh for each cm/s change in speed. How much power would the battery have drained in 1 second due to the speed change?

LLemma 34B:

 Reasoning: The toy car's speed changed by 98.9-28.0 = <<98.9-28.0=70.9>>70.9 cm/s.
The toy car's speed changed by 70.9 cm/s.
The battery drained 70.9*24.8 = <<70.9*24.8=1741.2>>1741.2 mAh.
### Answer: 1741.2

Expected answer: 1758.32000000000

Correct? No

Problem: In the previous scenario, if the toy car's speed after 1 second was modified to 29 cm/s instead of 28.0 cm/s, what would be the new change in the toy car's speed?

LLemma 34B:

 Reasoning: The toy car's speed changed by 98.9-29.0 = <<98.9-29.0=69.9>>69.9 cm/s.
### Answer: 69.9

Expected answer: 69.9000000000000

Correct? Yes

Problem: Following the previous question, the lion hunter then sees a third pride that has a total of 3.72 lions (including cubs as half). How many lions (taking cubs as half each) did the lion hunter count across all three prides?

LLemma 34B:

 Reasoning: The lion hunter counted 55.4+3.72 = <<55.4+3.72=59.12>>59.12 lions in total.
### Answer: 59.12

Expected answer: 59.1200000000000

Correct? Yes

Problem: Following the previous story, what if the lion hunter actually saw 76 lions in the first pride instead of 25.5 that he initially counted? When he then counted the second pride with 29.9 lions (including cubs as half), how many lions (considering cubs as half each) did the lion hunter count in total?

LLemma 34B:

 Reasoning: The lion hunter counted 76+29.9 = <<76+29.9=105.9>>105.9 lions in total.
### Answer: 105.9

Expected answer: 105.900000000000

Correct? Yes

Problem: A brown bear ate 50.1 pounds of fish in the morning. Then, it ate another 21 pounds in the afternoon instead of 65.7 pounds. How many total pounds of fish did the brown bear consume in one day now?

LLemma 34B:

 Reasoning: The brown bear ate 50.1+21 = <<50.1+21=71.1>>71.1 pounds of fish in one day.
### Answer: 71.1

Expected answer: 71.1000000000000

Correct? Yes

Problem: After calculating the flour used to make the cakes, suppose this amount is then mixed with 74.2 grams of sugar per kilogram of the flour. How many grams of sugar would be needed in total?

LLemma 34B:

 Reasoning: 10.47*74.2 = <<10.47*74.2=770.144>>770.144 grams of sugar would be needed in total.
### Answer: 770.144

Expected answer: 776.874000000000

Correct? No

Problem: Suppose the bakery initially started with 68 kilograms of flour instead of 62.06 kilograms. How many kilograms of flour would have been used to make the cakes then?

LLemma 34B:

 Reasoning: 68-51.59 = <<68-51.59=16.41>>16.41 kilograms of flour would have been used to make the cakes then.
### Answer: 16.41

Expected answer: 16.4100000000000

Correct? Yes

Problem: After adding the value of the gold and the pearl, the mermaid decides to give $28.05 worth of her treasure to her best sea creature friend. How much is the value of the remaining treasures after giving away part of it?

LLemma 34B:

 Reasoning: The value of the remaining treasure is $98.69-$28.05 = <<98.69-28.05=69.64>>$69.64.
### Answer: $69.64 

Expected answer: 70.6400000000000

Correct? No

Problem: Suppose instead of the gold being worth $86.7, it was actually worth $71. Now how much is the total value of the treasure the mermaid found?

LLemma 34B:

 Reasoning: The total worth of the treasure is $71+$11.99 = <<71+11.99=82.99>>$82.99.
### Answer: $82.99 

Expected answer: 82.9900000000000

Correct? Yes

Problem: The astronaut originally was at a distance of 61 meters from the spaceship before he moved an additional 85.98 meters further out into space. What is the total distance the astronaut moved away from the spaceship given this new initial distance?

LLemma 34B:

 Reasoning: The total distance the astronaut moved away from the spaceship is 61+85.98 = <<61+85.98=146.98>>146.98 meters.
### Answer: 146.98

Expected answer: 146.980000000000

Correct? Yes

Problem: From the previous problem, we knew a city bus has a capacity of 68.0 passengers with 10.66 seats reserved for specific riders. Now, suppose there are an additional 73.24 available seats added to the bus after an upgrade. How many total seats are now available for general riders after the upgrade?

LLemma 34B:

 Reasoning: 57.34+73.24 = <<57.34+73.24=130.58>>130.58 seats are available for general riders after the upgrade.
### Answer: 130.58

Expected answer: 130.580000000000

Correct? Yes

Problem: From the previous problem, a city bus was upgraded to have more seats for general riders. However, now consider that originally, the bus only had a capacity of 28 passengers instead of 68.0, with the same 10.66 seats reserved for specific riders. How many seats would then have been available for general riders before the upgrade?

LLemma 34B:

 Reasoning: 28-10.66 = <<28-10.66=17.34>>17.34 seats would have been available for general riders before the upgrade.
### Answer: 17.34

Expected answer: 17.3400000000000

Correct? Yes

Problem: If the same type of flower were to take in water for 29.3 days at the same average rate, how much total water would the flower consume in that time?

LLemma 34B:

 Reasoning: The flower would consume 92.9*29.3 = <<92.9*29.3=2711.57>>2711.57 milliliters of water in that time.
### Answer: 2711.57

Expected answer: 2721.97000000000

Correct? No

Problem: If the flower was instead taking up 2833.45 milliliters of water over a longer period of 51 days, how much water would this flower consume on average each day?

LLemma 34B:

 Reasoning: The flower consumes 2833.45/51 = <<2833.45/51=55.5>>55.5 milliliters of water every day.
### Answer: 55.5

Expected answer: 55.5578431372549

Correct? Yes

Problem: The chocolate maker originally thought they had purchased 23.76 kg of milk chocolate, but realized later that they had actually bought 91 kg of milk chocolate. Given that they still purchased 49.8 kg of dark chocolate as initially thought, what would be the new total weight in kg of the chocolate purchased?

LLemma 34B:

 Reasoning: 91+49.8 = <<91+49.8=140.8>>140.8 kg
### Answer: 140.8

Expected answer: 140.800000000000

Correct? Yes

Problem: After the tuning slips, the frequency a piano plays notes at is further reduced by 39.2 Hz. What frequency does the piano play notes at now?

LLemma 34B:

 Reasoning: The piano now plays notes at 52.9-39.2 = <<52.9-39.2=13.7>>13.7 Hz.
### Answer: 13.7

Expected answer: 13.7000000000000

Correct? Yes

Problem: Following up from the previous question where the superhero could fly a certain distance in an hour, let's assume he has a battery pack that allows him to fly an additional 81.04 miles per hour. Adding this extra distance to the previously calculated hourly flight distance, how many miles can the superhero now travels in an hour with his improved abilities?

LLemma 34B:

 Reasoning: The superhero can fly 35.0+81.04 = <<35.0+81.04=116.04>>116.04 miles in one hour.
### Answer: 116.04

Expected answer: 116.040000000000

Correct? Yes

Problem: Following the UFO's descent from an altitude of 72.18 km to 70.7 km, it then flew an additional distance calculated by multiplying the distance it descended by 37.2. What is this additional distance flown by the UFO?

LLemma 34B:

 Reasoning: The UFO descended 72.18-70.7 = <<72.18-70.7=1.48>>1.48 km.
The UFO flew 1.48*37.2 = <<1.48*37.2=54.916>>54.916 km.
### Answer: 54.916

Expected answer: 55.0560000000000

Correct? No

Problem: Following the UFO's additional movement, suppose it originally descended from an altitude of 90 km instead of 72.18 km to the same final altitude of 70.7 km. How much would it have descended then?

LLemma 34B:

 Reasoning: The UFO would have descended 90-70.7 = <<90-70.7=19.3>>19.3 km.
### Answer: 19.3

Expected answer: 19.3000000000000

Correct? Yes

Problem: If the region continued to receive the same amount of rain per day for the following 6.43 days, how many additional inches of rain would the region receive?

LLemma 34B:

 Reasoning: The region would receive 3.6*6.43 = <<3.6*6.43=22.918>>22.918 inches of rain.
### Answer: 22.918

Expected answer: 23.1480000000000

Correct? No

Problem: If instead of 11.5 days, the region originally received the total of 41.4 inches of rain over a period of 21 days, how many inches of rain would the region have received each day?

LLemma 34B:

 Reasoning: The region received 41.4/21 = <<41.4/21=1.95>>1.95 inches of rain each day.
### Answer: 1.95

Expected answer: 1.97142857142857

Correct? Yes

Problem: If the optimal work rate for such robots is 43.9 units per hour, by how much was this robot's work rate short of the optimal rate?

LLemma 34B:

 Reasoning: The robot's work rate was 16.5-43.9 = <<16.5-43.9=-27.4>>-27.4 units per hour short of the optimal rate.
### Answer: -27.4

Expected answer: 27.3000000000000

Correct? Yes

Problem: Suppose the robot completed the work over 76 hours instead of 84.5 hours, while still accomplishing 1402.7 units of work. What would then be the unit of work completed per hour in this case?

LLemma 34B:

 Reasoning: The robot completed 1402.7/76 = <<1402.7/76=18.5>>18.5 units of work per hour.
### Answer: 18.5

Expected answer: 18.4565789473684

Correct? Yes

Problem: A competitor's toy car runs at a speed of 66.1 meters per minute. By how much is this faster than our toy car that runs at a speed determined by traveling a total distance of 5460.48 meters over 86.4 minutes of battery life?

LLemma 34B:

 Reasoning: Our toy car runs at a speed of 5460.48/86.4 = <<5460.48/86.4=63.1>>63.1 meters per minute.
The competitor's toy car is 66.1-63.1 = <<66.1-63.1=3.0>>3.0 meters per minute faster than our toy car.
### Answer: 3.0

Expected answer: 2.90000000000000

Correct? No

Problem: If the battery life of our toy car was instead 41 minutes while still covering the distance of 5460.48 meters, how would that alter the toy car's speed in meters per minute?

LLemma 34B:

 Reasoning: The toy car's speed is 5460.48/41 = <<5460.48/41=133.4>>133.4 meters per minute.
### Answer: 133.4

Expected answer: 133.182439024390

Correct? Yes

Problem: In light of a new sleeping bag design, the manufacturer has decided to adjust the material requirements. Now each sleeping bag will use 94 square feet of material instead of 51.2. Given the same total amount of material available as before, 2631.68 square feet, how many of these new sleeping bags can now be produced?

LLemma 34B:

 Reasoning: 2631.68/94 = <<2631.68/94=28.2>>28 sleeping bags can be produced.
### Answer: 28

Expected answer: 27.9965957446808

Correct? No

Problem: Continuing from the previous scenario, suppose the plane increases its speed again by 89.64 km/hr. What is the total speed of the plane now, considering all three speed rates?

LLemma 34B:

 Reasoning: The plane traveled 144.44 km/hr for 1 hour.
The plane traveled 89.64 km/hr for 1 hour.
The plane traveled 144.44+89.64 = <<144.44+89.64=234.08>>234.08 km in 2 hours.
### Answer: 234.08

Expected answer: 234.080000000000

Correct? Yes

Problem: In the original scenario, assume instead that the computer game consumes 2714.46 MBs of data over 4 hours of gameplay. In this case, how many MBs of data would the game consume per hour?

LLemma 34B:

 Reasoning: 2714.46/4 = <<2714.46/4=678.61>>678.61 MBs of data per hour.
### Answer: 678.61

Expected answer: 678.615000000000

Correct? Yes

Problem: In a revision of the previous scenario, let's say the kite actually traveled 7102.88 meters over the course of 83 minutes instead of 86.2 minutes. In this case, how many meters would the kite have traveled per minute?

LLemma 34B:

 Reasoning: 7102.88/83 = <<7102.88/83=86.2>>86.2 meters per minute.
### Answer: 86.2

Expected answer: 85.5768674698795

Correct? No

Problem: Follow up question to previous problem: After finding out how many liters of juice each kilogram of oranges produces, if we have 4.8 kilograms of oranges, how many liters of juice can we make from them?

LLemma 34B:

 Reasoning: 4.8*43.8 = <<4.8*43.8=203.04>>203.04 liters of juice can be made from 4.8 kilograms of oranges.
### Answer: 203.04

Expected answer: 210.240000000000

Correct? No

Problem: Follow-up to the previous problem: Instead of using 18.1 kilograms of oranges, what if the juice stand used 38 kilograms of oranges to make 792.78 liters of juice? In this case, how many liters of juice would be produced by each kilogram of oranges?

LLemma 34B:

 Reasoning: 792.78/38 = <<792.78/38=20.8>>20.8 liters of juice is produced by each kilogram of oranges.
### Answer: 20.8

Expected answer: 20.8626315789474

Correct? Yes

Problem: In addition to the skateboard part and the sticker, you also plan on buying a helmet that costs $84.8. What would the total cost be for all three items?

LLemma 34B:

 Reasoning: The total cost is $52.9+$95.23+$84.8 = <<52.9+95.23+84.8=232.93>>$232.93.
### Answer: $232.93  

Expected answer: 232.930000000000

Correct? Yes

Problem: Suppose instead of the skateboard part costing $52.9, it actually cost $33. How much would the total cost be if you purchased this skateboard part and the $95.23 sticker?

LLemma 34B:

 Reasoning: The total cost is $33+$95.23 = <<33+95.23=128.23>>$128.23.
### Answer: $128.23 

Expected answer: 128.230000000000

Correct? Yes

Problem: In the same scenario, suppose instead that the elephant's original weight was 49 tons before it started losing weight and reached 42.8 tons. How much weight did the elephant lose in this case?

LLemma 34B:

 Reasoning: The elephant lost 49-42.8 = <<49-42.8=6.2>>6.2 tons.
### Answer: 6.2

Expected answer: 6.20000000000000

Correct? Yes

Problem: After packaging together the two types of cheese, the food manufacturer realizes that the package needs to maintain a standard weight of 72.5 grams. How much does the manufacturer need to subtract from the total weight of the combination of the two cheeses to meet this standard?

LLemma 34B:

 Reasoning: The manufacturer needs to subtract 184.3-72.5 = <<184.3-72.5=111.8>>111.8 grams from the total weight of the combination of the two cheeses to meet the standard.
### Answer: 111.8

Expected answer: 111.800000000000

Correct? Yes

Problem: Let's reconsider the problem by supposing that the weight of the first type of cheese was originally 15 grams instead of 92.6 grams. What would then be the total weight of the two types of cheese when packaged together?

LLemma 34B:

 Reasoning: The total weight of the two types of cheese is 15+91.7 = <<15+91.7=106.7>>106.7 grams.
### Answer: 106.7

Expected answer: 106.700000000000

Correct? Yes

Problem: On a farm, there are 77.66 acres of land. If 31.94 acres are used for growing corn, how many acres are not used for growing corn? If each of the unused acres can yield 6.5 bushels of wheat, how many bushels of wheat can be grown in total?

LLemma 34B:

 Reasoning: 77.66-31.94 = <<77.66-31.94=45.72>>45.72 acres are not used for growing corn.
45.72*6.5 = <<45.72*6.5=298.48>>298.48 bushels of wheat can be grown in total.
### Answer: 298.48

Expected answer: 297.180000000000

Correct? No

Problem: In the same farm scenario, suppose there had originally been 81 acres of land instead of 77.66. If still 31.94 acres are used for growing corn, how many acres would now be left unused?

LLemma 34B:

 Reasoning: 81-31.94 = <<81-31.94=49.06>>49.06 acres would now be left unused.
### Answer: 49.06

Expected answer: 49.0600000000000

Correct? Yes

Problem: Continuing from the initial scenario, suppose the rocket initially only rose to an altitude of 43.2 km and needed to ascend an additional 15 km to deliver the satellite into its required position. What would be the rocket's altitude when it has ascended the additional distance?

LLemma 34B:

 Reasoning: The rocket's altitude will be 43.2+15 = <<43.2+15=58.2>>58.2 km.
### Answer: 58.2

Expected answer: 58.2000000000000

Correct? Yes

Problem: The skateboard travels a total of 3769.24 meters in 48.2 minutes. If it traveled at a constant speed, how many meters does it cover in one minute? After subtracting 58.8 meters from this distance, how far has the skateboard traveled?

LLemma 34B:

 Reasoning: 3769.24/48.2 = <<3769.24/48.2=78.4>>78.4 meters in one minute.
78.4-58.8 = <<78.4-58.8=19.6>>19.6 meters.
### Answer: 19.6

Expected answer: 19.4000000000000

Correct? Yes

Problem: A skateboard travels a total of 63 meters in 48.2 minutes. If it traveled at a constant speed, how many meters does it cover in one minute?

LLemma 34B:

 Reasoning: 63/48.2 = <<63/48.2=1.3>>1.3 meters in one minute.
### Answer: 1.3

Expected answer: 1.30705394190871

Correct? Yes

Problem: If each marshmallow in both bags was replicated the exact number of times equal to the total of marshmallows in the two bags, how many marshmallows would there then be in total?

LLemma 34B:

 Reasoning: There are 14.0+6.9 = <<14.0+6.9=20.9>>20.9 marshmallows in total.
There are 20.9*20.9 = <<20.9*20.9=436.41>>436.41 marshmallows in total.
### Answer: 436.41

Expected answer: 436.810000000000

Correct? No

Problem: If there were 90 marshmallows in the first bag instead of 14.0, and 6.9 marshmallows in the second bag, how many marshmallows would there be in total?

LLemma 34B:

 Reasoning: There are 90+6.9 = <<90+6.9=96.9>>96.9 marshmallows in total.
### Answer: 96.9

Expected answer: 96.9000000000000

Correct? Yes

Problem: After the Triceratops dinosaur, the heaviest dinosaur is a type that is 59.6 times the weight of the Triceratops. How heavy is this dinosaur?

LLemma 34B:

 Reasoning: A Triceratops dinosaur weighs 162.1 tons.
A type of dinosaur that is 59.6 times the weight of the Triceratops weighs 162.1*59.6 = <<162.1*59.6=9811.36>>9811.36 tons.
### Answer: 9811.36

Expected answer: 9661.16000000000

Correct? No

Problem: Suppose instead of the Triceratops being 69.3 tons heavier than the Stegosaurus, it was only 26 tons heavier. How heavy would the Triceratops be then?

LLemma 34B:

 Reasoning: A Stegosaurus dinosaur weighs 92.8 tons.
A Triceratops dinosaur is 26 tons heavier than a Stegosaurus.
A Triceratops dinosaur weighs 92.8+26 = <<92.8+26=118.8>>118.8 tons.
### Answer: 118.8

Expected answer: 118.800000000000

Correct? Yes

Problem: After using the oxygen from the supplementary bottle, the firefighter finds another backup oxygen source that adds an additional 21.46 liters of oxygen. How much total oxygen does he now have for the mission, including the backup source?

LLemma 34B:

 Reasoning: The firefighter has 119.4+21.46 = <<119.4+21.46=140.86>>140.86 liters of oxygen for this mission.
### Answer: 140.86

Expected answer: 140.860000000000

Correct? Yes

Problem: Originally, the firefighter's oxygen tank did not start with 97.3 liters, but with 36 liters of oxygen instead. After adding the 22.1 liters of oxygen from the supplementary bottle, how much total oxygen does he have for the mission at that point?

LLemma 34B:

 Reasoning: The firefighter has 36+22.1 = <<36+22.1=58.1>>58.1 liters of oxygen for this mission.
### Answer: 58.1

Expected answer: 58.1000000000000

Correct? Yes

Problem: The length of the chain on one side of a swing is 89.5 cm. The length of the chain on the other side of the swing is 70.77 cm, and there is an additional 3.5 cm chain used to attach the swing to the frame. What is the total length of the chain used for the swing, including the attachment?

LLemma 34B:

 Reasoning: The total length of the chain is 89.5+70.77+3.5 = <<89.5+70.77+3.5=163.77>>163.77 cm.
### Answer: 163.77

Expected answer: 163.770000000000

Correct? Yes

Problem: Previously, the length of the chain on one side of a swing was 89.5 cm. However, after some adjustments, the new length of the chain on this side is now 13 cm. The length of the chain on the other side remains the same at 70.77 cm. What is the total length of the chain used for the swing now?

LLemma 34B:

 Reasoning: The total length of the chain is 13+70.77 = <<13+70.77=83.77>>83.77 cm.
### Answer: 83.77

Expected answer: 83.7700000000000

Correct? Yes

Problem: The candy store manager realized that they had made an error in their original calculation, and the store was actually initially stocked with 30.83 pounds of chocolate candies but ended up with 15 pounds after some sales. How many pounds of candies were really sold?

LLemma 34B:

 Reasoning: 30.83-15 = <<30.83-15=15.83>>15.83 pounds of candies were sold.
### Answer: 15.83

Expected answer: 15.8300000000000

Correct? Yes

Problem: Continuing from the previous question, you decide to sell the watch you bought for a profit, marking up the price you paid by 15.28 times. How much are you selling the watch for?

LLemma 34B:

 Reasoning: You are selling the watch for $38.40*15.28 = <<38.4*15.28=580.72>>$580.72.
### Answer: $580.72  

Expected answer: 586.752000000000

Correct? No

Problem: In the previous scenario, what if the discount on the watch was instead $36.00 instead of $19.96? How much would you have paid for the watch in this case?

LLemma 34B:

 Reasoning: You paid $58.36-$36.00 = <<58.36-36=22.36>>$22.36 for the watch.
### Answer: $22.36 

Expected answer: 22.3600000000000

Correct? Yes

Problem: Suppose the wizard initially started with a different quantity of the first ingredient, having 51 units instead of 56.9 units. How many units would there be in total in the potion then?

LLemma 34B:

 Reasoning: The total quantity of the potion would be 51+59.42 = <<51+59.42=110.42>>110.42 units.
### Answer: 110.42

Expected answer: 110.420000000000

Correct? Yes