Problem: Given the previous scenario but this time, let's say that the full-grown giraffe has a different height of 78 feet. If a baby giraffe is still 7.34 feet shorter than this full-grown giraffe, then how tall is the baby giraffe now?

Qwen2-Math 72B:

 Reasoning: The baby giraffe is 78-7.34 = <<78-7.34=70.66>>70.66 feet tall.
### Answer: 70.66

Expected answer: 70.6600000000000

Correct? Yes

Problem: The scooter store decided to multiply the discount you received, $j, by 15.1 to determine how much they'd donate to a local charity based on your purchase. How much money would be donated to the charity as a result of your scooter purchase?

Qwen2-Math 72B:

 Reasoning: The scooter store would donate $j*15.1 = <<20.6*15.1=311.06>>$311.06 to the charity.
### Answer: $311.06

Expected answer: 311.060000000000

Correct? Yes

Problem: If instead the scooter was initially priced at $66 before being discounted to $39.3, how much would be the discount on the scooter?

Qwen2-Math 72B:

 Reasoning: The discount on the scooter is $66-$39.3 = <<66-39.3=26.7>>$26.7.
### Answer: $26.7

Expected answer: 26.7000000000000

Correct? Yes

Problem: In a different playground, there was also a slide that was initially 71.36 meters long. However, safety concerns caused the officials to reduce the length by 24 meters instead of the original 50.0 meters. What is the new length of this slide?

Qwen2-Math 72B:

 Reasoning: The new length of the slide is 71.36 - 24 = <<71.36-24=47.36>>47.36 meters.
### Answer: 47.36

Expected answer: 47.3600000000000

Correct? Yes

Problem: The farmer decides to make tomato sauce and uses up 81.0 kg of the tomatoes he collected. After processing those tomatoes into sauce, how much weight in tomatoes does he have left?

Qwen2-Math 72B:

 Reasoning: The farmer had 143.89 kg of tomatoes initially. After using 81.0 kg for sauce, he has 143.89 - 81.0 = <<143.89-81.0=62.89>>62.89 kg of tomatoes left.
### Answer: 62.89

Expected answer: 62.8900000000000

Correct? Yes

Problem: If instead of 57.19 kg, the farmer actually collected 84 kg of tomatoes on the second day, what would be the new total weight of tomatoes he collected over the two days?

Qwen2-Math 72B:

 Reasoning: The new total weight of the tomatoes collected over the two days is 86.7 + 84 = <<86.7+84=170.7>>170.7 kg.
### Answer: 170.7

Expected answer: 170.700000000000

Correct? Yes

Problem: Following his earlier sales, the farmer sold an additional 4.8 batches of tomatoes. Including the new sales, how many total batches of tomatoes has the farmer sold now?

Qwen2-Math 72B:

 Reasoning: The farmer sold 38.6+4.8 = <<38.6+4.8=43.4>>43.4 batches of tomatoes altogether.
### Answer: 43.4

Expected answer: 43.4000000000000

Correct? Yes

Problem: After recalculating, it turns out the farmer had actually sold 83 kilograms of tomatoes, not 111.94 kilograms, still in batches of 2.9 kilograms each. How many batches of tomatoes did he actually sell?

Qwen2-Math 72B:

 Reasoning: The farmer sold 83/2.9 = <<83/2.9=28.62>>28.62 batches of tomatoes.
### Answer: 28.62

Expected answer: 28.6206896551724

Correct? Yes

Problem: Instead of the original price being $75.0, assume that the original price of the skirt was $49. How much would the skirt cost after the first discount of $37.5?

Qwen2-Math 72B:

 Reasoning: The sale price of the skirt is $49-$37.5 = <<49-37.5=11.5>>$11.5.
### Answer: $11.5

Expected answer: 11.5000000000000

Correct? Yes

Problem: In addition to the existing wheat and corn fields, the farm has a newly acquired barley field that spans 7.16 acres. What is the total acreage of wheat, corn, and barley fields altogether on the farm now?

Qwen2-Math 72B:

 Reasoning: The total acreage of wheat, corn, and barley fields altogether on the farm now is 47.4+7.16 = <<47.4+7.16=54.56>>54.56 acres.
### Answer: 54.56

Expected answer: 54.5600000000000

Correct? Yes

Problem: Suppose instead of the 35.9 acres of wheat in the original calculation, the farm actually has 93 acres of wheat fields. Taking the updated acreage of wheat fields into account and keeping the 11.5 acres of corn fields the same, what would then be the total acreage of wheat and corn fields on the farm?

Qwen2-Math 72B:

 Reasoning: The total acreage of wheat and corn fields on the farm is 93+11.5 = <<93+11.5=104.5>>104.5 acres.
### Answer: 104.5

Expected answer: 104.500000000000

Correct? Yes

Problem: Following the previous problem, after filling each bucket, 2.4 liters of water is lost due to leakage. What would be the revised amount of water in each bucket?

Qwen2-Math 72B:

 Reasoning: To find the revised amount of water in each bucket, we need to subtract the amount of water lost due to leakage from the original amount of water in each bucket.
8.2 liters - 2.4 liters = <<8.2-2.4=5.8>>5.8 liters per bucket.
### Answer: 5.8 liters

Expected answer: 5.80000000000000

Correct? Yes

Problem: Following the previous problem, suppose that instead of 65.9 buckets the water was divided into 33 buckets. How many liters of water would have been in each bucket under this new arrangement?

Qwen2-Math 72B:

 Reasoning: To find out how many liters of water would have been in each bucket under the new arrangement, we need to divide the total amount of water by the new number of buckets.
540.38 liters / 33 buckets = <<540.38/33=16.37>>16.37 liters per bucket.
### Answer: 16.37 liters

Expected answer: 16.3751515151515

Correct? Yes

Problem: After increasing its speed, the UFO maintained its new speed for 52.9 hours. How many miles did the UFO travel at its new speed?

Qwen2-Math 72B:

 Reasoning: The UFO traveled 97.46*52.9 = <<97.46*52.9=5155.034>>5155.034 miles at its new speed.
### Answer: 5155.034

Expected answer: 5155.63400000000

Correct? No

Problem: Suppose that the UFO was originally moving at a speed of 94.83 mph, but then it increased its speed by 72 mph instead of 2.63 mph. What would its new speed be now?

Qwen2-Math 72B:

 Reasoning: The UFO's new speed is 94.83+72 = <<94.83+72=166.83>>166.83 miles per hour.
### Answer: 166.83

Expected answer: 166.830000000000

Correct? Yes

Problem: After calculating the speed of the wind, notice that there is a separate current of air pushing in the same direction with a speed of 64.91 km/h. If we add the speed of this current to the speed of the wind calculated earlier, what would be the total speed of the wind now?

Qwen2-Math 72B:

 Reasoning: The total speed of the wind now is 39.0+64.91 = <<39.0+64.91=103.91>>103.91 km/h.
### Answer: 103.91

Expected answer: 103.910000000000

Correct? Yes

Problem: After re-calculating the data, it turns out the strong wind actually traveled 2250.3 km, but over a period of 96 hours instead of 57.7 hours. How would this change affect the speed of the wind per hour?

Qwen2-Math 72B:

 Reasoning: The wind covers 2250.3/96 = <<2250.3/96=23.4>>23.4 kilometers in each hour.
### Answer: 23.4

Expected answer: 23.4406250000000

Correct? Yes

Problem: After swimming 95.34 kilometers to the east and another 41.6 kilometers in the same direction, the Penguin continued its journey and swam an additional 97.85 kilometers. What is the total distance that the Penguin swam?

Qwen2-Math 72B:

 Reasoning: The total distance that the Penguin swam is 95.34+41.6+97.85 = <<95.34+41.6+97.85=234.79>>234.79 kilometers.
### Answer: 234.79

Expected answer: 234.790000000000

Correct? Yes

Problem: Suppose instead of swimming 95.34 kilometers to the east initially, the penguin only swam 12 kilometers before continuing for another 41.6 kilometers in the same direction. How much distance would the penguin have covered in this scenario?

Qwen2-Math 72B:

 Reasoning: The total distance that the Penguin swam is 12+41.6 = <<12+41.6=53.6>>53.6 kilometers.
### Answer: 53.6

Expected answer: 53.6000000000000

Correct? Yes

Problem: In the park, there is another identical slide next to the first one which also gets extended by the same 9.86 feet. After this extension, what is the total length of the two slides put together?

Qwen2-Math 72B:

 Reasoning: The length of the second slide is also 96.28 feet, so the total length of the two slides put together is 96.28+96.28 = <<96.28+96.28=192.56>>192.56 feet.
### Answer: 192.56

Expected answer: 192.560000000000

Correct? Yes

Problem: Suppose the park decided to make an alteration to the plan and instead wanted to extend the slide by 81 feet rather than 9.86 feet. How long would the slide be after this extension?

Qwen2-Math 72B:

 Reasoning: The slide is extended by another 81 feet, so the new length of the slide is 86.42+81 = <<86.42+81=167.42>>167.42 feet.
### Answer: 167.42

Expected answer: 167.420000000000

Correct? Yes

Problem: Considering the ice cream shop you previously calculated about. If the total amount of ice cream sold (1878.8 gallons) was actually spread over 87 days instead of 44.0 days, how many gallons of ice cream would have been sold each day?

Qwen2-Math 72B:

 Reasoning: To find the number of gallons of ice cream sold each day, we need to divide the total number of gallons sold by the number of days.
Total gallons sold = 1878.8
Number of days = 87
Gallons sold per day = Total gallons sold / Number of days
Gallons sold per day = 1878.8 / 87
Gallons sold per day = 21.6
### Answer: 21.6

Expected answer: 21.5954022988506

Correct? Yes

Problem: In the book mentioned previously with a total character count of 1540.93 and each word consisting of around 22.3 characters, after reviewing, an editor finds that the word count is actually 59.3 words less than what was originally calculated. What is the adjusted word count now?

Qwen2-Math 72B:

 Reasoning: The original word count was 69.10000000000001 words.
The adjusted word count is 69.10000000000001-59.3 = <<69.10000000000001-59.3=9.800000000000009>>9.800000000000009 words.
### Answer: 9.800000000000009

Expected answer: 9.80000000000000

Correct? Yes

Problem: In the book review process, the editor realizes that there's been a mistake. Instead of 72 characters per word, each word only takes up about 22.3 characters. How many words would be in a section of the book where the character count totals 72?

Qwen2-Math 72B:

 Reasoning: The number of words in the section is 72/22.3 = <<72/22.3=3.2286995515695067>>3.2286995515695067.
### Answer: 3.2286995515695067

Expected answer: 3.22869955156951

Correct? No

Problem: After buying the ice skates and skate guards, you decide to take advantage of a special offer that gives you a discount of $46.83. What would be your new total cost after this discount is applied?

Qwen2-Math 72B:

 Reasoning: The new total cost after the discount is applied is $136.26 - $46.83 = <<136.26-46.83=89.43>>$89.43.
### Answer: $89.43

Expected answer: 89.4300000000000

Correct? Yes

Problem: Suppose instead of the original pair of ice skates costing $81.66, you found a different pair on sale for only $25. If you still buy the skate guards for an additional $54.6, what would be the total cost of these discounted ice skates combined with the skate guards?

Qwen2-Math 72B:

 Reasoning: The total cost of the discounted ice skates and skate guards is $25 + $54.6 = <<25+54.6=79.6>>$79.6.
### Answer: $79.6

Expected answer: 79.6000000000000

Correct? Yes

Problem: If originally, the farmer had harvested 36.0 kilograms of strawberries and now instead, he sold 12 kilograms of strawberries. How many kilograms of strawberries does he have left now?

Qwen2-Math 72B:

 Reasoning: The farmer has 36.0 - 12 = <<36.0-12=24>>24 kilograms of strawberries left.
### Answer: 24

Expected answer: 24.0000000000000

Correct? Yes

Problem: Consider the same scenario but with a different original cost. If the pillow originally cost $72 instead of $22.88 and its price is reduced to $14.2 after a sale, what would be the amount of the discount now?

Qwen2-Math 72B:

 Reasoning: The amount of the discount is $72-$14.2 = <<72-14.2=57.8>>57.8.
### Answer: 57.8

Expected answer: 57.8000000000000

Correct? Yes

Problem: In the initial situation, the bunch of bananas weighed 79 grams instead of 77.8 grams. After removing the peel, which weighed 7.0 grams as before, what would be the new weight of the bananas this time?

Qwen2-Math 72B:

 Reasoning: The weight of the bananas after removing the peel is 79 - 7.0 = <<79-7.0=72>>72 grams.
### Answer: 72 grams

Expected answer: 72.0000000000000

Correct? Yes

Problem: Following up on our previous question about the book with 15.18 words per page and 24.0 pages, if 45.7 words were removed from the book for editing, how many words does the book contain now?

Qwen2-Math 72B:

 Reasoning: The book originally had 364.32 words. After removing 45.7 words, the book now contains 364.32 - 45.7 = <<364.32-45.7=318.62>>318.62 words.
### Answer: 318.62

Expected answer: 318.620000000000

Correct? Yes

Problem: Let's revisit the book situation again. What if, initially, each page in the book had 30 words instead of 15.18, and the book still had 24.0 pages. How many words would the book contain in that case?

Qwen2-Math 72B:

 Reasoning: The book would have 30*24.0 = <<30*24.0=720>>720 words in total.
### Answer: 720

Expected answer: 720.000000000000

Correct? Yes

Problem: After the kids added sand to their sandcastle, they decided to make it even bigger. They multiplied the original weight of the sand by 46.6. What is the total weight of the sand in the sandcastle after their addition?

Qwen2-Math 72B:

 Reasoning: The total weight of the sand in the sandcastle after their addition is 62.78*46.6 = <<62.78*46.6=2923.648>>2923.648 pounds.
### Answer: 2923.648

Expected answer: 2925.54800000000

Correct? No

Problem: Suppose the retailer has recalculated his inventory and found that they have made an error in their initial calculation. In actuality, it only takes 27 meters of material to make one pair of socks instead of 98.6 meters. How many pairs of socks can they now make with the corrected amount of material?

Qwen2-Math 72B:

 Reasoning: To find out how many pairs of socks can be made with the corrected amount of material, we need to divide the total amount of material by the corrected amount of material required for one pair of socks.
5600.48 meters of material / 27 meters of material per pair of socks = <<5600.48/27=207.4>>207.4 pairs of socks.
Since we can't make a fraction of a pair of socks, we can only make 207 pairs of socks.
### Answer: 207

Expected answer: 207.425185185185

Correct? Yes

Problem: As a follow-up to the previous problem, suppose that a space probe needs to use 50.03 kilograms of fuel for every million kilometers it travels towards the sun. If it starts its journey on the second day, how many kilograms of fuel will it need to reach the Sun?

Qwen2-Math 72B:

 Reasoning: The distance from the Earth to the Sun on the second day is 71.39 million kilometers.
The space probe will need 71.39 * 50.03 = <<71.39*50.03=3571.9917>>3571.9917 kilograms of fuel to reach the Sun.
### Answer: 3571.9917

Expected answer: 3571.64170000000

Correct? No

Problem: As a follow up to the previous problem, suppose that instead of the initial distance being 56.14 million kilometers, the Earth was initially 60 million kilometers far from the Sun. After increasing by 15.25 million kilometers, what would be the distance from Earth to the Sun on the following day, in millions of kilometers?

Qwen2-Math 72B:

 Reasoning: The distance on the second day is 60 + 15.25 = <<60+15.25=75.25>>75.25 million kilometers.
### Answer: 75.25

Expected answer: 75.2500000000000

Correct? Yes

Problem: Suppose that for each degree drop in temperature, the cloud loses 97.29 liters of water vapor. How much water vapor would the cloud lose given the temperature change from the previous question?

Qwen2-Math 72B:

 Reasoning: The temperature change is 35.43 degrees Fahrenheit.
The cloud would lose 35.43*97.29 = <<35.43*97.29=3445.9247>>3445.9247 liters of water vapor.
### Answer: 3445.9247

Expected answer: 3446.98470000000

Correct? No

Problem: Suppose that instead of dropping from 92.5 degrees Fahrenheit, the temperature in the cloud layer had dropped from 87 degrees Fahrenheit. How much would the temperature change be in this situation?

Qwen2-Math 72B:

 Reasoning: The temperature change would be 87-57.07 = <<87-57.07=29.93>>29.93 degrees Fahrenheit.
### Answer: 29.93

Expected answer: 29.9300000000000

Correct? Yes

Problem: After the giraffe walks 42.53 miles to the north in the morning and 28.9 miles to the east in the afternoon, it then retraces 60.5 miles back towards its starting point. How many miles is the giraffe from its starting point now?

Qwen2-Math 72B:

 Reasoning: The giraffe walked a total of 42.53+28.9 = <<42.53+28.9=71.43>>71.43 miles in the morning and afternoon. After retracing 60.5 miles, the giraffe is 71.43-60.5 = <<71.43-60.5=10.93>>10.93 miles from its starting point.
### Answer: 10.93

Expected answer: 10.9300000000000

Correct? Yes

Problem: If the giraffe had walked 42.53 miles to the north in the morning and then 57 miles to the east in the afternoon instead of 28.9, how many miles in total would the giraffe have walked?

Qwen2-Math 72B:

 Reasoning: The total distance the Giraffe walked is 42.53+57 = <<42.53+57=99.53>>99.53 miles.
### Answer: 99.53

Expected answer: 99.5300000000000

Correct? Yes

Problem: From the previous word problem: The sandbox originally had 90.74 kilograms of sand on one side and 95.27 kilograms of sand on the other side. Follow-up question: But what if the sandbox originally had 59 kilograms of sand on the one side instead of 90.74 kilograms? What would be the total weight of the sand in the sandbox then, still considering there were 95.27 kilograms of sand on the other side?

Qwen2-Math 72B:

 Reasoning: The total weight of sand in the sandbox would be 59 + 95.27 = <<59+95.27=154.27>>154.27 kilograms.
### Answer: 154.27

Expected answer: 154.270000000000

Correct? Yes

Problem: A train ticket costs $14.15 and the cost of a meal on the train is $95.07. After your meal, you decide to buy a cool souvenir train mug for $4.02. How much would it cost in total for the train ticket, meal, and souvenir mug?

Qwen2-Math 72B:

 Reasoning: The total cost is $14.15+$95.07+$4.02 = <<14.15+95.07+4.02=113.24>>$113.24.
### Answer: $113.24

Expected answer: 113.240000000000

Correct? Yes

Problem: The train ticket originally costs $14.15, and in this follow-up question, we're considering what happens if the meal cost is changed to $59. Now, how much is the total cost for the ticket and the meal?

Qwen2-Math 72B:

 Reasoning: The total cost is $14.15+$59 = <<14.15+59=73.15>>$73.15.
### Answer: $73.15

Expected answer: 73.1500000000000

Correct? Yes

Problem: Following the viewing of the galaxy, the scientist decides to amplify her binocular lens, multiplying the viewing scope by 5.21 times. What is the new approximate distance in light years that she can view through each scope after amplification?

Qwen2-Math 72B:

 Reasoning: The new approximate distance in light years that she can view through each scope after amplification is 50.40*5.21 = <<50.40*5.21=262.58>>262.58 light years.
### Answer: 262.58

Expected answer: 262.584000000000

Correct? Yes

Problem: Following her studies, the scientist decides to adjust her binoculars to view the galaxy through only 65 different scopes instead of the previous 85.3. If the total distance remains the same, 4299.12 light years, what is the new approximate distance in light years that she sees through each scope?

Qwen2-Math 72B:

 Reasoning: The new approximate distance in light years that she sees through each scope is 4299.12/65 = <<4299.12/65=66.14>>66.14 light years.
### Answer: 66.14

Expected answer: 66.1403076923077

Correct? Yes

Problem: Originally, the water company decided to divide the 1774.46 cubic meters of water between 28.9 storage tanks. However, it later decides to evenly distribute the water among 46 tanks instead. How many cubic meters of water will each tank contain under this new distribution plan?

Qwen2-Math 72B:

 Reasoning: To find out how many cubic meters of water each tank will contain under the new distribution plan, we need to divide the total amount of water by the new number of tanks.
1774.46 cubic meters / 46 tanks = <<1774.46/46=38.575217391304346>>38.58 cubic meters per tank (rounded to two decimal places).
### Answer: 38.58 cubic meters

Expected answer: 38.5752173913043

Correct? Yes

Problem: After the modifications, the star's magnitude brightness is multiplied by a factor of 96.1 due to interference from the earth's atmosphere. What is the value of the star's final observed brightness after being adjusted for atmospheric interference?

Qwen2-Math 72B:

 Reasoning: The final observed brightness is the product of the total magnitude brightness and the atmospheric interference factor.
Final observed brightness = 101.16 * 96.1 = <<101.16*96.1=9722.476>>9722.476
### Answer: 9722.476

Expected answer: 9721.47600000000

Correct? No

Problem: Suppose the star's observed magnitude brightness was modified by 54 units instead of 4.7 units, keeping its intrinsic brightness the same at 96.46 units. What would be the total magnitude brightness of the star then when these modifications are added?

Qwen2-Math 72B:

 Reasoning: The total magnitude brightness is the sum of the observed magnitude and the intrinsic brightness.
Total magnitude brightness = 54 + 96.46 = <<54+96.46=150.46>>150.46
### Answer: 150.46

Expected answer: 150.460000000000

Correct? Yes

Problem: If a smaller blanket has a width of 94.35 feet, what would be the total width in feet if you laid the large and small blankets side by side?

Qwen2-Math 72B:

 Reasoning: To find the total width, we add the width of the large blanket to the width of the smaller blanket. The total width is 3.8 + 94.35 = <<3.8 + 94.35 = 98.15>>98.15 feet.
### Answer: 98.15

Expected answer: 98.1500000000000

Correct? Yes

Problem: If the large blanket actually had a total area of 86 square feet instead of 175.56 while keeping the length identical at 46.2 feet, what would be the new width in feet?

Qwen2-Math 72B:

 Reasoning: Using the same formula for the area of a rectangle, we divide the new area by the length to find the new width. Therefore, the new width is 86 / 46.2 = <<86 / 46.2 = 1.8614718614718615>>1.86 feet.
### Answer: 1.86

Expected answer: 1.86147186147186

Correct? Yes

Problem: After successfully handling the small fire, the firefighter then moves on to control a medium fire, using an additional 46.61 liters of water. How many liters of water has the firefighter used in total?

Qwen2-Math 72B:

 Reasoning: The firefighter used 123.63 + 46.61 = <<123.63+46.61=170.24>>170.24 liters of water in total.
### Answer: 170.24

Expected answer: 170.240000000000

Correct? Yes

Problem: Suppose the firefighter initially used 92 liters of water to extinguish the small fire instead of 37.7 liters, but still uses an additional 85.93 liters to cool down the area. How many liters of water has the firefighter used in total now?

Qwen2-Math 72B:

 Reasoning: The firefighter used 92 + 85.93 = <<92+85.93=177.93>>177.93 liters of water in total.
### Answer: 177.93

Expected answer: 177.930000000000

Correct? Yes

Problem: Instead of making 98.3 pounds of special chocolate per hour, the factory decides to produce 64 pounds per hour. Using the same production cycle of 44.2 hours, how many pounds of the special chocolate would the factory produce under these adjusted conditions?

Qwen2-Math 72B:

 Reasoning: The factory produces 64*44.2 = <<64*44.2=2828.8>>2828.8 pounds of chocolate in 44.2 hours.
### Answer: 2828.8

Expected answer: 2828.80000000000

Correct? Yes

Problem: Following the last snow season, the weather department is predicting that the upcoming season will have double the number of snowfalls as the previous season. If the previous season had a certain number of snowfalls, each measuring 38.3 inches for a total of 509.39 inches, how many snowfalls are expected in the upcoming winter season?

Qwen2-Math 72B:

 Reasoning: To find the number of snowfalls in the upcoming winter season, we need to first find the number of snowfalls in the previous season.
Total snowfall in the previous season = 509.39 inches
Snowfall per event = 38.3 inches
Number of snowfalls in the previous season = Total snowfall / Snowfall per event
Number of snowfalls in the previous season = 509.39 / 38.3
Number of snowfalls in the previous season = 13.3
Since the number of snowfalls must be a whole number, we can round down to the nearest whole number.
Number of snowfalls in the previous season = 13
The upcoming season is predicted to have double the number of snowfalls as the previous season.
Number of snowfalls in the upcoming season = Number of snowfalls in the previous season * 2
Number of snowfalls in the upcoming season = 13 * 2
Number of snowfalls in the upcoming season = 26
### Answer: 26

Expected answer: 26.6000000000000

Correct? No

Problem: In retrospect, the Met Office revised their measurements for the previous winter season. Instead of a total of 509.39 inches of snowfall, there were only 83 inches, still with each snowfall measuring 38.3 inches. With that in mind, how many snowfalls were there truly last winter season?

Qwen2-Math 72B:

 Reasoning: To find the number of snowfalls, we need to divide the total snowfall by the amount of snowfall per event.
Total snowfall = 83 inches
Snowfall per event = 38.3 inches
Number of snowfalls = Total snowfall / Snowfall per event
Number of snowfalls = 83 / 38.3
Number of snowfalls = 2.167
Since the number of snowfalls must be a whole number, we can round down to the nearest whole number.
Number of snowfalls = 2
### Answer: 2

Expected answer: 2.16710182767624

Correct? No

Problem: Following from the previous question, let's consider a smaller clock that initially measures 6 cm in height. If it also has a base of 1.58 cm that is removed, what would be the height of the main body of this smaller clock without the base?

Qwen2-Math 72B:

 Reasoning: The main body of the smaller clock is 6-1.58 = <<6-1.58=4.42>>4.42 cm tall.
### Answer: 4.42

Expected answer: 4.42000000000000

Correct? Yes

Problem: Following up on the previous problem, the toy car runs on a battery that drains power proportional to the change in its speed per second. The rate is 24.8 mAh for each cm/s change in speed. How much power would the battery have drained in 1 second due to the speed change?

Qwen2-Math 72B:

 Reasoning: The power drained is the rate of power drain times the change in speed.
Power drained = 24.8 mAh/cm/s * 70.9 cm/s = <<24.8*70.9=1750.32>>1750.32 mAh.
### Answer: 1750.32 mAh

Expected answer: 1758.32000000000

Correct? No

Problem: In the previous scenario, if the toy car's speed after 1 second was modified to 29 cm/s instead of 28.0 cm/s, what would be the new change in the toy car's speed?

Qwen2-Math 72B:

 Reasoning: The change in speed is the initial speed minus the final speed.
Change in speed = 98.9 cm/s - 29 cm/s = <<98.9-29=69.9>>69.9 cm/s.
### Answer: 69.9 cm/s

Expected answer: 69.9000000000000

Correct? Yes

Problem: In the previous scenario, we assumed the turtle was traveling at a speed of 23.0 km/h. However, let's consider a different scenario where the turtle travels at an increased speed of 70 km/h. In this case, how far would the turtle travel in 46.7 hours?

Qwen2-Math 72B:

 Reasoning: The turtle will travel 70 * 46.7 = <<70*46.7=3269>>3269 km in 46.7 hours.
### Answer: 3269

Expected answer: 3269.00000000000

Correct? Yes

Problem: Following the previous question, the lion hunter then sees a third pride that has a total of 3.72 lions (including cubs as half). How many lions (taking cubs as half each) did the lion hunter count across all three prides?

Qwen2-Math 72B:

 Reasoning: The lion hunter counted 55.4+3.72 = <<55.4+3.72=59.12>>59.12 lions across all three prides.
### Answer: 59.12

Expected answer: 59.1200000000000

Correct? Yes

Problem: Following the previous story, what if the lion hunter actually saw 76 lions in the first pride instead of 25.5 that he initially counted? When he then counted the second pride with 29.9 lions (including cubs as half), how many lions (considering cubs as half each) did the lion hunter count in total?

Qwen2-Math 72B:

 Reasoning: The lion hunter counted 76+29.9 = <<76+29.9=105.9>>105.9 lions in total.
### Answer: 105.9

Expected answer: 105.900000000000

Correct? Yes

Problem: A brown bear ate 50.1 pounds of fish in the morning. Then, it ate another 21 pounds in the afternoon instead of 65.7 pounds. How many total pounds of fish did the brown bear consume in one day now?

Qwen2-Math 72B:

 Reasoning: The brown bear ate 50.1+21 = <<50.1+21=71.1>>71.1 pounds of fish in total.
### Answer: 71.1

Expected answer: 71.1000000000000

Correct? Yes

Problem: After calculating the flour used to make the cakes, suppose this amount is then mixed with 74.2 grams of sugar per kilogram of the flour. How many grams of sugar would be needed in total?

Qwen2-Math 72B:

 Reasoning: The total amount of sugar needed is 10.47 * 74.2 = <<10.47*74.2=776.974>>776.974 grams.
### Answer: 776.974

Expected answer: 776.874000000000

Correct? No

Problem: Suppose the bakery initially started with 68 kilograms of flour instead of 62.06 kilograms. How many kilograms of flour would have been used to make the cakes then?

Qwen2-Math 72B:

 Reasoning: The bakery would have used 68 - 51.59 = <<68-51.59=16.41>>16.41 kilograms of flour to make the cakes.
### Answer: 16.41

Expected answer: 16.4100000000000

Correct? Yes

Problem: After adding the value of the gold and the pearl, the mermaid decides to give $28.05 worth of her treasure to her best sea creature friend. How much is the value of the remaining treasures after giving away part of it?

Qwen2-Math 72B:

 Reasoning: The remaining value of the treasures is $98.69 - $28.05 = <<98.69-28.05=70.64>>$70.64.
### Answer: $70.64

Expected answer: 70.6400000000000

Correct? Yes

Problem: Suppose instead of the gold being worth $86.7, it was actually worth $71. Now how much is the total value of the treasure the mermaid found?

Qwen2-Math 72B:

 Reasoning: The total worth of the treasure is now $71 + $11.99 = <<71+11.99=82.99>>$82.99.
### Answer: $82.99

Expected answer: 82.9900000000000

Correct? Yes

Problem: The astronaut originally was at a distance of 61 meters from the spaceship before he moved an additional 85.98 meters further out into space. What is the total distance the astronaut moved away from the spaceship given this new initial distance?

Qwen2-Math 72B:

 Reasoning: The total distance the astronaut moved away from the spaceship is 61 + 85.98 = <<61+85.98=146.98>>146.98 meters.
### Answer: 146.98

Expected answer: 146.980000000000

Correct? Yes

Problem: Now consider that the craftsman is planning to make two such identical bracelets. How many grams of silver are needed in total for the charms on both bracelets?

Qwen2-Math 72B:

 Reasoning: Since the total grams of silver needed for one bracelet is 48.578 grams, for two bracelets, it would be 48.578 grams * 2 = <<48.578*2=97.156>>97.156 grams.
### Answer: 97.156

Expected answer: 97.1560000000000

Correct? Yes

Problem: Now consider that the craftsman decided to make a different bracelet which requires 12 charms instead of 4.54. How many grams of silver are needed in total for the charms on this new bracelet?

Qwen2-Math 72B:

 Reasoning: To find the total grams of silver needed for the new bracelet, multiply the grams per charm by the new number of charms: 10.7 grams/charm * 12 charms = <<10.7*12=128.4>>128.4 grams.
### Answer: 128.4

Expected answer: 128.400000000000

Correct? Yes

Problem: From the previous problem, we knew a city bus has a capacity of 68.0 passengers with 10.66 seats reserved for specific riders. Now, suppose there are an additional 73.24 available seats added to the bus after an upgrade. How many total seats are now available for general riders after the upgrade?

Qwen2-Math 72B:

 Reasoning: The number of seats available for general riders after the upgrade is 57.34 + 73.24 = <<57.34+73.24=130.58>>130.58 seats.
### Answer: 130.58

Expected answer: 130.580000000000

Correct? Yes

Problem: From the previous problem, a city bus was upgraded to have more seats for general riders. However, now consider that originally, the bus only had a capacity of 28 passengers instead of 68.0, with the same 10.66 seats reserved for specific riders. How many seats would then have been available for general riders before the upgrade?

Qwen2-Math 72B:

 Reasoning: The number of seats available for general riders would have been 28 - 10.66 = <<28-10.66=17.34>>17.34 seats.
### Answer: 17.34

Expected answer: 17.3400000000000

Correct? Yes

Problem: If the same type of flower were to take in water for 29.3 days at the same average rate, how much total water would the flower consume in that time?

Qwen2-Math 72B:

 Reasoning: The flower consumes 92.9 milliliters of water every day.
The flower would consume 92.9*29.3 = <<92.9*29.3=2722.97>>2722.97 milliliters of water in 29.3 days.
### Answer: 2722.97

Expected answer: 2721.97000000000

Correct? No

Problem: If the flower was instead taking up 2833.45 milliliters of water over a longer period of 51 days, how much water would this flower consume on average each day?

Qwen2-Math 72B:

 Reasoning: The flower consumes 2833.45/51 = <<2833.45/51=55.5578431372549>>55.56 milliliters of water every day.
### Answer: 55.56

Expected answer: 55.5578431372549

Correct? Yes

Problem: The artist had initially set aside 54.95 dollars for buying the blue paint. After purchasing all the paint needed for the mural, how much did they spent in excess of the initial amount?

Qwen2-Math 72B:

 Reasoning: The artist spent 163.7602-54.95 = <<163.7602-54.95=108.8102>>108.8102 dollars in excess of the initial amount.
### Answer: 108.8102

Expected answer: 108.810200000000

Correct? Yes

Problem: Instead of using 1.67 dollars per liter, imagine that each liter of blue paint cost 81 dollars. Under these altered circumstances, how much would the volume of paint used cost in total?

Qwen2-Math 72B:

 Reasoning: The cost of the paint used in the mural is 98.06*81 = <<98.06*81=7942.86>>7942.86 dollars.
### Answer: 7942.86

Expected answer: 7942.86000000000

Correct? Yes

Problem: The chocolate maker originally thought they had purchased 23.76 kg of milk chocolate, but realized later that they had actually bought 91 kg of milk chocolate. Given that they still purchased 49.8 kg of dark chocolate as initially thought, what would be the new total weight in kg of the chocolate purchased?

Qwen2-Math 72B:

 Reasoning: The total weight of the chocolate purchased is now 91+49.8 = <<91+49.8=140.8>>140.8 kg.
### Answer: 140.8

Expected answer: 140.800000000000

Correct? Yes

Problem: After the tuning slips, the frequency a piano plays notes at is further reduced by 39.2 Hz. What frequency does the piano play notes at now?

Qwen2-Math 72B:

 Reasoning: The piano's tuning slips by 39.2 Hz, so the new frequency is 52.9 Hz - 39.2 Hz = <<52.9-39.2=13.7>>13.7 Hz.
### Answer: 13.7 Hz

Expected answer: 13.7000000000000

Correct? Yes

Problem: Following up on the previous scenario, the toy factory also made an additional $74.2 from selling accessories for the toy cars on the same day. What is the total amount of money the factory made from selling both the toy cars and the accessories?

Qwen2-Math 72B:

 Reasoning: To find the total amount made from selling both the toy cars and the accessories, we add the amount made from selling the toy cars to the amount made from selling the accessories.
Total amount = $489.294 + $74.2 = <<489.294+74.2=563.494>>$563.494
### Answer: $563.494

Expected answer: 563.494000000000

Correct? Yes

Problem: Let's revisit the scenario at the toy factory. Instead of selling 10.2 toy cars, they actually sold 63 toy cars in a day, with each car still priced at $47.97. How much total revenue did the factory now make from selling toy cars?

Qwen2-Math 72B:

 Reasoning: To find the total revenue, we multiply the number of cars sold by the price per car.
Total revenue = 63 * $47.97 = <<63*47.97=3011.11>>$3011.11
### Answer: $3011.11

Expected answer: 3022.11000000000

Correct? No

Problem: Following up from the previous question where the superhero could fly a certain distance in an hour, let's assume he has a battery pack that allows him to fly an additional 81.04 miles per hour. Adding this extra distance to the previously calculated hourly flight distance, how many miles can the superhero now travels in an hour with his improved abilities?

Qwen2-Math 72B:

 Reasoning: The superhero can fly 35.0 + 81.04 = <<35.0+81.04=116.04>>116.04 miles in one hour with his improved abilities.
### Answer: 116.04

Expected answer: 116.040000000000

Correct? Yes

Problem: Following the UFO's descent from an altitude of 72.18 km to 70.7 km, it then flew an additional distance calculated by multiplying the distance it descended by 37.2. What is this additional distance flown by the UFO?

Qwen2-Math 72B:

 Reasoning: The UFO descended by 72.18-70.7 = <<72.18-70.7=1.48>>1.48 km.
The UFO flew an additional distance of 1.48*37.2 = <<1.48*37.2=55.056>>55.056 km.
### Answer: 55.056

Expected answer: 55.0560000000000

Correct? Yes

Problem: Following the UFO's additional movement, suppose it originally descended from an altitude of 90 km instead of 72.18 km to the same final altitude of 70.7 km. How much would it have descended then?

Qwen2-Math 72B:

 Reasoning: The UFO descended by 90-70.7 = <<90-70.7=19.3>>19.3 km.
### Answer: 19.3

Expected answer: 19.3000000000000

Correct? Yes

Problem: If the region continued to receive the same amount of rain per day for the following 6.43 days, how many additional inches of rain would the region receive?

Qwen2-Math 72B:

 Reasoning: To find the additional inches of rain received, we need to multiply the amount of rain received each day by the number of additional days.
3.6 inches per day * 6.43 days = <<3.6*6.43=23.148>>23.148 inches.
### Answer: 23.148 inches

Expected answer: 23.1480000000000

Correct? Yes

Problem: If instead of 11.5 days, the region originally received the total of 41.4 inches of rain over a period of 21 days, how many inches of rain would the region have received each day?

Qwen2-Math 72B:

 Reasoning: To find the amount of rain received each day, we need to divide the total amount of rain by the number of days.
41.4 inches / 21 days = <<41.4/21=1.97>>1.97 inches per day.
### Answer: 1.97 inches per day

Expected answer: 1.97142857142857

Correct? Yes

Problem: If the optimal work rate for such robots is 43.9 units per hour, by how much was this robot's work rate short of the optimal rate?

Qwen2-Math 72B:

 Reasoning: To find the difference between the robot's work rate and the optimal work rate, we need to subtract the robot's work rate from the optimal work rate.
Optimal work rate = 43.9 units per hour
Robot's work rate = 16.6 units per hour
Difference = Optimal work rate - Robot's work rate
Difference = 43.9 - 16.6
Difference = <<43.9-16.6=27.3>>27.3
### Answer: 27.3

Expected answer: 27.3000000000000

Correct? Yes

Problem: Suppose the robot completed the work over 76 hours instead of 84.5 hours, while still accomplishing 1402.7 units of work. What would then be the unit of work completed per hour in this case?

Qwen2-Math 72B:

 Reasoning: To find the number of units of work completed per hour, we need to divide the total units of work by the total hours worked.
Total units of work = 1402.7
Total hours worked = 76
Units of work per hour = Total units of work / Total hours worked
Units of work per hour = 1402.7 / 76
Units of work per hour = <<1402.7/76=18.4>>18.4
### Answer: 18.4

Expected answer: 18.4565789473684

Correct? Yes

Problem: A competitor's toy car runs at a speed of 66.1 meters per minute. By how much is this faster than our toy car that runs at a speed determined by traveling a total distance of 5460.48 meters over 86.4 minutes of battery life?

Qwen2-Math 72B:

 Reasoning: First, we need to find the speed of our toy car.
Speed = Total distance / Time
Speed = 5460.48 meters / 86.4 minutes
Speed = 63.2 meters per minute
Now, we can find the difference in speed between the competitor's toy car and our toy car.
Difference in speed = Speed of competitor's toy car - Speed of our toy car
Difference in speed = 66.1 meters per minute - 63.2 meters per minute
Difference in speed = <<66.1-63.2=2.9>>2.9 meters per minute
### Answer: 2.9

Expected answer: 2.90000000000000

Correct? Yes

Problem: If the battery life of our toy car was instead 41 minutes while still covering the distance of 5460.48 meters, how would that alter the toy car's speed in meters per minute?

Qwen2-Math 72B:

 Reasoning: The toy car's speed is the total distance traveled divided by the time taken.
Speed = Total distance / Time
Speed = 5460.48 meters / 41 minutes
Speed = <<5460.48/41=133.18>>133.18 meters per minute
### Answer: 133.18

Expected answer: 133.182439024390

Correct? Yes

Problem: The robot mentioned before that travels a total distance of 1149.72 meters over a time span of 15.6 minutes has an energy consumption rate of 25.58 joules per meter. How much total energy does the robot consume in joules during this span of time?

Qwen2-Math 72B:

 Reasoning: The robot travels 1149.72 meters over a time span of 15.6 minutes.
The robot consumes 25.58 joules per meter.
The robot consumes 1149.72*25.58 = <<1149.72*25.58=29400.0016>>29400.0016 joules during this span of time.
### Answer: 29400.0016

Expected answer: 1885.24600000000

Correct? No

Problem: In the same scenario as before, let's consider if the robot traveled a lesser distance of 46 meters over the same time span of 15.6 minutes. How many meters would the robot travel per minute then?

Qwen2-Math 72B:

 Reasoning: The robot travels 46/15.6 = <<46/15.6=2.95>>2.95 meters per minute.
### Answer: 2.95

Expected answer: 2.94871794871795

Correct? Yes

Problem: In light of a new sleeping bag design, the manufacturer has decided to adjust the material requirements. Now each sleeping bag will use 94 square feet of material instead of 51.2. Given the same total amount of material available as before, 2631.68 square feet, how many of these new sleeping bags can now be produced?

Qwen2-Math 72B:

 Reasoning: To find out how many new sleeping bags can be produced, we need to divide the total amount of material by the new amount of material required for each sleeping bag.
2631.68 square feet / 94 square feet per sleeping bag = <<2631.68/94=28>>28 sleeping bags.
### Answer: 28

Expected answer: 27.9965957446808

Correct? No

Problem: Continuing from the previous scenario, suppose the plane increases its speed again by 89.64 km/hr. What is the total speed of the plane now, considering all three speed rates?

Qwen2-Math 72B:

 Reasoning: The total speed of the plane now, considering all three speed rates, is 144.44+89.64 = <<144.44+89.64=234.08>>234.08 km/hr.
### Answer: 234.08

Expected answer: 234.080000000000

Correct? Yes

Problem: In the original scenario, assume instead that the computer game consumes 2714.46 MBs of data over 4 hours of gameplay. In this case, how many MBs of data would the game consume per hour?

Qwen2-Math 72B:

 Reasoning: To find the data consumption per hour, we divide the total data consumption by the total hours played.
2714.46 MBs / 4 hours = <<2714.46/4=678.615>>678.615 MBs per hour.
### Answer: 678.615

Expected answer: 678.615000000000

Correct? Yes

Problem: In a revision of the previous scenario, let's say the kite actually traveled 7102.88 meters over the course of 83 minutes instead of 86.2 minutes. In this case, how many meters would the kite have traveled per minute?

Qwen2-Math 72B:

 Reasoning: To find the distance traveled per minute, we need to divide the total distance by the total time.
7102.88 meters / 83 minutes = <<7102.88/83=85.5768>>85.5768 meters per minute.
### Answer: 85.5768

Expected answer: 85.5768674698795

Correct? Yes

Problem: Follow up question to previous problem: After finding out how many liters of juice each kilogram of oranges produces, if we have 4.8 kilograms of oranges, how many liters of juice can we make from them?

Qwen2-Math 72B:

 Reasoning: We know that each kilogram of oranges produces 43.8 liters of juice. Therefore, to find out how many liters of juice we can make from 4.8 kilograms of oranges, we need to multiply the weight of the oranges by the amount of juice produced per kilogram.
4.8 kilograms * 43.8 liters per kilogram = <<4.8*43.8=210.24>>210.24 liters.
### Answer: 210.24

Expected answer: 210.240000000000

Correct? Yes

Problem: Follow-up to the previous problem: Instead of using 18.1 kilograms of oranges, what if the juice stand used 38 kilograms of oranges to make 792.78 liters of juice? In this case, how many liters of juice would be produced by each kilogram of oranges?

Qwen2-Math 72B:

 Reasoning: To find out how many liters of juice each kilogram of oranges produces, we need to divide the total amount of juice by the total weight of the oranges.
792.78 liters / 38 kilograms = <<792.78/38=20.86>>20.86 liters per kilogram.
### Answer: 20.86

Expected answer: 20.8626315789474

Correct? Yes

Problem: In addition to the skateboard part and the sticker, you also plan on buying a helmet that costs $84.8. What would the total cost be for all three items?

Qwen2-Math 72B:

 Reasoning: The total cost of the skateboard part, the sticker, and the helmet is $52.9 + $95.23 + $84.8 = <<52.9+95.23+84.8=232.93>>$232.93.
### Answer: $232.93

Expected answer: 232.930000000000

Correct? Yes

Problem: Suppose instead of the skateboard part costing $52.9, it actually cost $33. How much would the total cost be if you purchased this skateboard part and the $95.23 sticker?

Qwen2-Math 72B:

 Reasoning: The total cost of the skateboard part and the sticker is $33 + $95.23 = <<33+95.23=128.23>>$128.23.
### Answer: $128.23

Expected answer: 128.230000000000

Correct? Yes

Problem: In the same scenario, suppose instead that the elephant's original weight was 49 tons before it started losing weight and reached 42.8 tons. How much weight did the elephant lose in this case?

Qwen2-Math 72B:

 Reasoning: The elephant lost 49-42.8 = <<49-42.8=6.2>>6.2 tons.
### Answer: 6.2

Expected answer: 6.20000000000000

Correct? Yes

Problem: After packaging together the two types of cheese, the food manufacturer realizes that the package needs to maintain a standard weight of 72.5 grams. How much does the manufacturer need to subtract from the total weight of the combination of the two cheeses to meet this standard?

Qwen2-Math 72B:

 Reasoning: The manufacturer needs to subtract 184.3-72.5 = <<184.3-72.5=111.8>>111.8 grams from the total weight of the combination of the two cheeses to meet the standard.
### Answer: 111.8

Expected answer: 111.800000000000

Correct? Yes

Problem: Let's reconsider the problem by supposing that the weight of the first type of cheese was originally 15 grams instead of 92.6 grams. What would then be the total weight of the two types of cheese when packaged together?

Qwen2-Math 72B:

 Reasoning: The total weight of the two types of cheese when packaged together is 15+91.7 = <<15+91.7=106.7>>106.7 grams.
### Answer: 106.7

Expected answer: 106.700000000000

Correct? Yes

Problem: On a farm, there are 77.66 acres of land. If 31.94 acres are used for growing corn, how many acres are not used for growing corn? If each of the unused acres can yield 6.5 bushels of wheat, how many bushels of wheat can be grown in total?

Qwen2-Math 72B:

 Reasoning: To find the number of acres not used for growing corn, we subtract the acres used for corn from the total acres of land.
77.66 - 31.94 = <<77.66-31.94=45.72>>45.72 acres are not used for growing corn.
To find the total bushels of wheat that can be grown, we multiply the number of unused acres by the bushels of wheat per acre.
45.72 * 6.5 = <<45.72*6.5=297.18>>297.18 bushels of wheat can be grown in total.
### Answer: 297.18

Expected answer: 297.180000000000

Correct? Yes

Problem: In the same farm scenario, suppose there had originally been 81 acres of land instead of 77.66. If still 31.94 acres are used for growing corn, how many acres would now be left unused?

Qwen2-Math 72B:

 Reasoning: To find the number of acres left unused, we subtract the acres used for corn from the new total acres of land.
81 - 31.94 = <<81-31.94=49.06>>49.06 acres are now left unused.
### Answer: 49.06

Expected answer: 49.0600000000000

Correct? Yes

Problem: Continuing from the initial scenario, suppose the rocket initially only rose to an altitude of 43.2 km and needed to ascend an additional 15 km to deliver the satellite into its required position. What would be the rocket's altitude when it has ascended the additional distance?

Qwen2-Math 72B:

 Reasoning: The rocket needs to ascend an additional 15 km to deliver the satellite into its required position.
The rocket's current altitude is 43.2 km.
The rocket's altitude when it has ascended the additional distance will be 43.2 km + 15 km = <<43.2+15=58.2>>58.2 km.
### Answer: 58.2 km

Expected answer: 58.2000000000000

Correct? Yes

Problem: The skateboard travels a total of 3769.24 meters in 48.2 minutes. If it traveled at a constant speed, how many meters does it cover in one minute? After subtracting 58.8 meters from this distance, how far has the skateboard traveled?

Qwen2-Math 72B:

 Reasoning: To find the distance covered in one minute, we need to divide the total distance by the total time.
Distance covered in one minute = Total distance / Total time
Distance covered in one minute = 3769.24 meters / 48.2 minutes
Distance covered in one minute = <<3769.24/48.2=78.2>>78.2 meters
After subtracting 58.8 meters from this distance, the skateboard has traveled 78.2 - 58.8 = <<78.2-58.8=19.4>>19.4 meters.
### Answer: 19.4 meters

Expected answer: 19.4000000000000

Correct? Yes

Problem: A skateboard travels a total of 63 meters in 48.2 minutes. If it traveled at a constant speed, how many meters does it cover in one minute?

Qwen2-Math 72B:

  Reasoning: To find the distance covered in one minute, we need to divide the total distance by the total time.
Distance covered in one minute = Total distance / Total time
Distance covered in one minute = 63 meters / 48.2 minutes
Distance covered in one minute = <<63/48.2=1.307>>1.307 meters
### Answer: 1.307 meters

Expected answer: 1.30705394190871

Correct? Yes

Problem: If each marshmallow in both bags was replicated the exact number of times equal to the total of marshmallows in the two bags, how many marshmallows would there then be in total?

Qwen2-Math 72B:

 Reasoning: First, we need to find the total number of marshmallows in both bags, which we already calculated as 20.9.
If each marshmallow is replicated 20.9 times, then the total number of marshmallows would be:
Total marshmallows = 20.9 * 20.9 = <<20.9*20.9=436.81>>436.81
### Answer: 436.81

Expected answer: 436.810000000000

Correct? Yes

Problem: If there were 90 marshmallows in the first bag instead of 14.0, and 6.9 marshmallows in the second bag, how many marshmallows would there be in total?

Qwen2-Math 72B:

 Reasoning: To find the total number of marshmallows, we need to add the number of marshmallows in both bags.
Total marshmallows = 90 + 6.9 = <<90+6.9=96.9>>96.9
### Answer: 96.9

Expected answer: 96.9000000000000

Correct? Yes

Problem: After the Triceratops dinosaur, the heaviest dinosaur is a type that is 59.6 times the weight of the Triceratops. How heavy is this dinosaur?

Qwen2-Math 72B:

 Reasoning: The heaviest dinosaur weighs 162.1*59.6 = <<162.1*59.6=9649.16>>9649.16 tons.
### Answer: 9649.16

Expected answer: 9661.16000000000

Correct? No

Problem: Suppose instead of the Triceratops being 69.3 tons heavier than the Stegosaurus, it was only 26 tons heavier. How heavy would the Triceratops be then?

Qwen2-Math 72B:

 Reasoning: The Triceratops dinosaur weighs 92.8+26 = <<92.8+26=118.8>>118.8 tons.
### Answer: 118.8

Expected answer: 118.800000000000

Correct? Yes

Problem: After using the oxygen from the supplementary bottle, the firefighter finds another backup oxygen source that adds an additional 21.46 liters of oxygen. How much total oxygen does he now have for the mission, including the backup source?

Qwen2-Math 72B:

 Reasoning: The firefighter initially had 119.4 liters of oxygen (from the previous calculation).
He then finds another backup oxygen source that adds an additional 21.46 liters of oxygen.
Therefore, the total amount of oxygen he now has for the mission, including the backup source, is 119.4 + 21.46 = <<119.4+21.46=140.86>>140.86 liters.
### Answer: 140.86 liters

Expected answer: 140.860000000000

Correct? Yes

Problem: Originally, the firefighter's oxygen tank did not start with 97.3 liters, but with 36 liters of oxygen instead. After adding the 22.1 liters of oxygen from the supplementary bottle, how much total oxygen does he have for the mission at that point?

Qwen2-Math 72B:

 Reasoning: The firefighter starts with 36 liters of oxygen and uses an additional 22.1 liters from a supplementary bottle.
Therefore, the total amount of oxygen he has for this mission is 36 + 22.1 = <<36+22.1=58.1>>58.1 liters.
### Answer: 58.1 liters

Expected answer: 58.1000000000000

Correct? Yes

Problem: In the previous problem, the scooter initially traveled at a constant speed of 95.1 kilometers per hour. What if instead, the scooter initially traveled at a lower speed of 27 kilometers per hour. What will be the total distance traveled in 4.8 hours at this reduced speed?

Qwen2-Math 72B:

 Reasoning: The scooter will travel 27*4.8 = <<27*4.8=129.6>>129.6 kilometers in 4.8 hours.
### Answer: 129.6

Expected answer: 129.600000000000

Correct? Yes

Problem: A snowball that was 15.8 inches in diameter was rolled and grew at a constant rate until it was 30.8 times its original size. Then, due to the sun's heat, it shrank, losing 82.03 inches of its size. What is the size of the snowball now?

Qwen2-Math 72B:

 Reasoning: The original diameter of the snowball was 15.8 inches.
The snowball grew to 30.8 times its original size, so its new diameter is 15.8 * 30.8 = <<15.8*30.8=486.64>>486.64 inches.
Then, due to the sun's heat, it shrank, losing 82.03 inches of its size, so its new diameter is 486.64 - 82.03 = <<486.64-82.03=404.61>>404.61 inches.
### Answer: 404.61 inches

Expected answer: 404.610000000000

Correct? Yes

Problem: Suppose the snowball that was initially 15.8 inches in diameter was rolled and grew at a constant rate until it was 38 times its original size, instead of 30.8 times. What would be the size of the snowball then?

Qwen2-Math 72B:

 Reasoning: The original diameter of the snowball was 15.8 inches.
The snowball grew to 38 times its original size, so its new diameter is 15.8 * 38 = <<15.8*38=600.4>>600.4 inches.
### Answer: 600.4 inches

Expected answer: 600.400000000000

Correct? Yes

Problem: The length of the chain on one side of a swing is 89.5 cm. The length of the chain on the other side of the swing is 70.77 cm, and there is an additional 3.5 cm chain used to attach the swing to the frame. What is the total length of the chain used for the swing, including the attachment?

Qwen2-Math 72B:

 Reasoning: The total length of the chain used for the swing, excluding the attachment, is 89.5 + 70.77 = <<89.5+70.77=160.27>>160.27 cm.
Including the 3.5 cm attachment, the total length is 160.27 + 3.5 = <<160.27+3.5=163.77>>163.77 cm.
### Answer: 163.77

Expected answer: 163.770000000000

Correct? Yes

Problem: Previously, the length of the chain on one side of a swing was 89.5 cm. However, after some adjustments, the new length of the chain on this side is now 13 cm. The length of the chain on the other side remains the same at 70.77 cm. What is the total length of the chain used for the swing now?

Qwen2-Math 72B:

 Reasoning: The total length of the chain used for the swing now is 13 + 70.77 = <<13+70.77=83.77>>83.77 cm.
### Answer: 83.77

Expected answer: 83.7700000000000

Correct? Yes

Problem: The candy store manager realized that they had made an error in their original calculation, and the store was actually initially stocked with 30.83 pounds of chocolate candies but ended up with 15 pounds after some sales. How many pounds of candies were really sold?

Qwen2-Math 72B:

 Reasoning: The store sold 30.83-15 = <<30.83-15=15.83>>15.83 pounds of candies.
### Answer: 15.83

Expected answer: 15.8300000000000

Correct? Yes

Problem: Continuing from the previous question, you decide to sell the watch you bought for a profit, marking up the price you paid by 15.28 times. How much are you selling the watch for?

Qwen2-Math 72B:

 Reasoning: You bought the watch for $38.40 and want to mark up the price by 15.28 times.
So, the selling price of the watch is $38.40 * 15.28 = <<38.40*15.28=586.368>>$586.368.
### Answer: $586.368

Expected answer: 586.752000000000

Correct? No

Problem: In the previous scenario, what if the discount on the watch was instead $36.00 instead of $19.96? How much would you have paid for the watch in this case?

Qwen2-Math 72B:

 Reasoning: The watch was originally $58.36, but you got a discount of $36.00.
So, you ended up paying $58.36 - $36.00 = <<58.36-36=22.36>>$22.36 for the watch.
### Answer: $22.36

Expected answer: 22.3600000000000

Correct? Yes

Problem: Following on from the previous scenario, the observatory is offering a package deal where an individual or group can purchase 22.1 lots of the 63.2-minute observation time at a reduced price. If one lot (which consists of 63.2 minutes) of observation time costs $6.9, how much would it cost to purchase the entire package through this deal?

Qwen2-Math 72B:

 Reasoning: The cost for one lot of 63.2 minutes of observation time is $6.9. Therefore, the cost for 22.1 lots of 63.2 minutes of observation time is 22.1 * $6.9 = <<22.1*6.9=152.49>>$152.49.
### Answer: $152.49

Expected answer: 9637.36800000000

Correct? No

Problem: Following on from our previous scenario, what if instead of 63.2 minutes, an individual or a group wants to purchase a block of 82 minutes of telescope observing time at the same rate of $6.9 per minute. How much would it cost then?

Qwen2-Math 72B:

 Reasoning: The cost for 82 minutes of observation time is 82 * $6.9 = <<82*6.9=565.8>>$565.8.
### Answer: $565.8

Expected answer: 565.800000000000

Correct? Yes

Problem: Reconsidering the two comets, suppose this time the first comet covered a distance of 61 million kilometers instead of 32.52 million kilometers, and the second traveled the same distance as before, i.e. 27.3 million kilometers. Combining the two, what is the total distance both comets traveled now?

Qwen2-Math 72B:

 Reasoning: The total distance traveled by both comets is the sum of the distances traveled by each comet.
Total distance = 61 million kilometers + 27.3 million kilometers = <<61+27.3=88.3>>88.3 million kilometers.
### Answer: 88.3 million kilometers

Expected answer: 88.3000000000000

Correct? Yes

Problem: Suppose the wizard initially started with a different quantity of the first ingredient, having 51 units instead of 56.9 units. How many units would there be in total in the potion then?

Qwen2-Math 72B:

 Reasoning: The total quantity of the potion would be 51+59.42 = <<51+59.42=110.42>>110.42 units.
### Answer: 110.42

Expected answer: 110.420000000000

Correct? Yes