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Qwen2-Math 7B on 3.OA.A.3

Common Core Standard 3.OA.A.3

This standard covers the following:

Use multiplication and division within 100 to solve word problems in situations involving equal groups, arrays, and measurement quantities, e.g., by using drawings and equations with a symbol for the unknown number to represent the problem.

🔗 Problem

Problem: John has 12 tables. Each table requires 8 chairs. How many chairs does John need to accommodate all the tables?

Qwen2-Math 7B:

 Reasoning: John needs 12*8 = <<12*8=96>>96 chairs to accommodate all the tables.
### Answer: 96

Expected answer: 96

Correct? Yes

🔗 Follow-up

Problem: Suppose now, John only has 2 tables instead of 12. Using the same number of chairs per table, how many chairs would John need now to accommodate these tables?

Qwen2-Math 7B:

 Reasoning: John needs 2*8 = <<2*8=16>>16 chairs to accommodate the 2 tables.
### Answer: 16

Expected answer: 16

Correct? Yes

🔗 Problem

Problem: In a magical fairy world, there are 4 fairies per house and 3 houses in a cluster. Each fairy creates 5 magic dust particles a day. How many magic dust particles are created in one day by all the fairies in a cluster?

Qwen2-Math 7B:

 Reasoning: There are 4 fairies per house and 3 houses in a cluster, so there are 4*3 = <<4*3=12>>12 fairies in a cluster.
Each fairy creates 5 magic dust particles a day, so 12 fairies create 12*5 = <<12*5=60>>60 magic dust particles a day.
### Answer: 60

Expected answer: 60

Correct? Yes

🔗 Follow-up

Problem: In the magical fairy world, each magic dust particle created lasts for 1 whole week. How many magic dust particles will be available in a cluster of houses after a week?

Qwen2-Math 7B:

 Reasoning: Each magic dust particle lasts for 1 week, so after a week, all the magic dust particles created in that week will still be available.
Since 60 magic dust particles are created in one day, after a week (7 days), there will be 60*7 = <<60*7=420>>420 magic dust particles available in a cluster of houses.
### Answer: 420

Expected answer: 60

Correct? No

🔗 Follow-up

Problem: Previously, we discovered that each fairy creates 5 magic dust particles a day. But what happens if instead, each fairy creates 8 magic dust particles a day? How many magic dust particles are then created in one day by all the fairies in a cluster?

Qwen2-Math 7B:

 Reasoning: There are 4 fairies per house and 3 houses in a cluster, so there are 4*3 = <<4*3=12>>12 fairies in a cluster.
Each fairy creates 8 magic dust particles a day, so 12 fairies create 12*8 = <<12*8=96>>96 magic dust particles a day.
### Answer: 96

Expected answer: 96

Correct? Yes

🔗 Problem

Problem: Harry has 9 sets of building blocks, each set contains 7 blocks. How many building blocks does Harry have in total?

Qwen2-Math 7B:

 Reasoning: Harry has 9*7 = <<9*7=63>>63 building blocks in total.
### Answer: 63

Expected answer: 63

Correct? Yes

🔗 Problem

Problem: In the zoo, there are 12 peacocks in every enclosure. If there are 4 enclosures, how many peacocks are in the zoo in total?

Qwen2-Math 7B:

 Reasoning: There are 12 peacocks in each enclosure, and there are 4 enclosures.
So, the total number of peacocks in the zoo is 12*4 = <<12*4=48>>48.
### Answer: 48

Expected answer: 48

Correct? Yes

🔗 Follow-up

Problem: Let's imagine that instead of 4 enclosures, the zoo originally had 7 enclosures. The same rule was followed: 12 peacocks were placed in each enclosure. How many peacocks would there be in the zoo in this scenario?

Qwen2-Math 7B:

 Reasoning: If there were 7 enclosures, and 12 peacocks were placed in each enclosure, then the total number of peacocks would be 12*7 = <<12*7=84>>84.
### Answer: 84

Expected answer: 84

Correct? Yes

🔗 Problem

Problem: There are 24 children at the park and want to play on the jungle gym. If each jungle gym can accommodate 12 children at a time, how many turns must they take so that everyone gets a chance to play?

Qwen2-Math 7B:

 Reasoning: 24/12 = <<24/12=2>>2 turns are needed for all 24 children to play on the jungle gym.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Follow-up

Problem: Suppose now that there are 24 children at the park, but the jungle gym has been upgraded and can now accommodate 2 children at a time. How many turns would they now need to make sure everyone gets a chance to play?

Qwen2-Math 7B:

 Reasoning: 24/2 = <<24/2=12>>12 turns are needed for all 24 children to play on the jungle gym.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Problem

Problem: On the farm, there are 7 groups of chicks. Each group consists of just 1 chick. The farmer then brought 9 times that amount of chicks. How many chicks did the farmer bring?

Qwen2-Math 7B:

 Reasoning: The farmer brought 7*9 = <<7*9=63>>63 chicks.
### Answer: 63

Expected answer: 63

Correct? Yes

🔗 Follow-up

Problem: Initially, there were around 7 groups of chicks on the farm, with each group consisting of just 1 chick. But what if the farmer's original flock was smaller? Let's say he initially started with 4 times that amount of chicks. How many chicks would he have started with then?

Qwen2-Math 7B:

 Reasoning: The farmer would have started with 4*7 = <<4*7=28>>28 chicks.
### Answer: 28

Expected answer: 28

Correct? Yes

🔗 Problem

Problem: Mr. Hansen, a very organized teacher, likes to keep ten copies of each handout for his class. If he is preparing a new handout for the next class, how many copies will he make?

Qwen2-Math 7B:

 Reasoning: Mr. Hansen will make 10 copies of the handout.
### Answer: 10

Expected answer: 10

Correct? Yes

🔗 Follow-up

Problem: Following the first problem, let's assume that Mr. Hansen changed his mind and decided to make only four copies of each handout instead of ten for his next class. How many copies of the handout will he now prepare?

Qwen2-Math 7B:

 Reasoning: Mr. Hansen will now make 4 copies of the handout.
### Answer: 4

Expected answer: 4

Correct? Yes

🔗 Problem

Problem: A snowman has a top hat that is 5 inches tall. The snowman himself, without his hat, is 4 times as tall as his hat. How tall is the snowman without his hat?

Qwen2-Math 7B:

 Reasoning: The snowman is 4 times as tall as his hat, so the snowman is 4*5 = <<4*5=20>>20 inches tall.
The snowman without his hat is 20-5 = <<20-5=15>>15 inches tall.
### Answer: 15

Expected answer: 20

Correct? No

🔗 Problem

Problem: In a video game, Susan collected 45 diamonds. If she divided those diamonds evenly among her 9 game characters, how many diamonds does each character get?

Qwen2-Math 7B:

 Reasoning: Each character gets 45/9 = <<45/9=5>>5 diamonds.
### Answer: 5

Expected answer: 5

Correct? Yes

🔗 Follow-up

Problem: Suppose initially, Susan had only found 12 diamonds instead of 45. If she still divided those diamonds evenly among her 9 game characters, how many diamonds would each character receive then?

Qwen2-Math 7B:

 Reasoning: Each character would get 12/9 = <<12/9=1.3333333333333333>>1.3333333333333333 diamonds.
Since we can't have a fraction of a diamond, we round down to the nearest whole number. Each character would receive 1 diamond.
### Answer: 1

Expected answer: 4/3

Correct? No

🔗 Problem

Problem: Jim has 12 guitar picks. He divided them equally among his 12 bandmates. How many guitar picks did each bandmate get?

Qwen2-Math 7B:

 Reasoning: Jim divided 12 guitar picks equally among 12 bandmates, so each bandmate got 12/12 = <<12/12=1>>1 guitar pick.
### Answer: 1

Expected answer: 1

Correct? Yes

🔗 Follow-up

Problem: After dividing his guitar picks among his bandmates, Jim got a package from a fan. In the package, there were 11 more sets of guitar picks, each set having the same number of picks as each bandmate initially received. How many guitar picks were there in the package?

Qwen2-Math 7B:

 Reasoning: Each set had 1 guitar pick, and there were 11 sets, so there were 11 * 1 = <<11*1=11>>11 guitar picks in the package.
### Answer: 11

Expected answer: 11

Correct? Yes

🔗 Follow-up

Problem: Considering the scenario when Jim initially had 12 guitar picks but instead of dividing them among 12 bandmates, he divided them among 6 bandmates. How many guitar picks did each bandmate get?

Qwen2-Math 7B:

 Reasoning: Jim divided 12 guitar picks equally among 6 bandmates, so each bandmate got 12/6 = <<12/6=2>>2 guitar picks.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Problem

Problem: Suzie has 5 aquariums. Each aquarium has 12 fish. How many fish does Suzie have in total?

Qwen2-Math 7B:

 Reasoning: Suzie has 5*12 = <<5*12=60>>60 fish in total.
### Answer: 60

Expected answer: 60

Correct? Yes

🔗 Follow-up

Problem: After buying the new batch, Suzie realized her first count was wrong. She actually started with 4 aquariums, not 5, before she bought the new fish. With each aquarium having 12 fish, how many fish did Suzie initially have?

Qwen2-Math 7B:

 Reasoning: Suzie initially had 4*12 = <<4*12=48>>48 fish.
### Answer: 48

Expected answer: 48

Correct? Yes

🔗 Problem

Problem: A pirate found a treasure map. The map indicated that the treasure chest was buried at a spot marked by 2 stones multiplied by 9. How many stones mark the hiding place of the treasure chest?

Qwen2-Math 7B:

 Reasoning: The treasure chest is buried at a spot marked by 2 stones multiplied by 9, which is 2*9 = <<2*9=18>>18 stones.
### Answer: 18

Expected answer: 18

Correct? Yes

🔗 Follow-up

Problem: The pirate, now intrigued, discovered a third map in the larger treasure chest. This map was slightly different, indicating that the next treasure chest was marked by a spot identified not by 2 stones multiplied by 9, but by 3 stones multiplied by 9. How many stones mark the hiding spot of this third treasure chest?

Qwen2-Math 7B:

 Reasoning: The third treasure chest is marked by a spot identified not by 2 stones multiplied by 9, but by 3 stones multiplied by 9, which is 3*9 = <<3*9=27>>27 stones.
### Answer: 27

Expected answer: 27

Correct? Yes

🔗 Problem

Problem: A special type of butterfly lays eggs in batches of 6. If a butterfly lays 4 batches of eggs, how many eggs does she lay in total?

Qwen2-Math 7B:

 Reasoning: The butterfly lays 6*4 = <<6*4=24>>24 eggs in total.
### Answer: 24

Expected answer: 24

Correct? Yes

🔗 Follow-up

Problem: After further research, it was discovered that the butterfly was actually laying eggs in batches of 4 instead of 6 as previously thought. If there were still 4 batches of eggs, how many eggs would the butterfly have laid in total then?

Qwen2-Math 7B:

 Reasoning: The butterfly would have laid 4*4 = <<4*4=16>>16 eggs in total.
### Answer: 16

Expected answer: 16

Correct? Yes

🔗 Problem

Problem: Anna has 54 feathers she wants to use to stuff some pillows. If each pillow needs 9 feathers, how many pillows can she stuff?

Qwen2-Math 7B:

 Reasoning: Anna can stuff 54/9 = <<54/9=6>>6 pillows.
### Answer: 6

Expected answer: 6

Correct? Yes

🔗 Follow-up

Problem: Following from the previous problem, Anna managed to stuff the pillows with the 54 feathers. If each stuffed pillow now needs to be sewn with 8 buttons, how many buttons will Anna need in total?

Qwen2-Math 7B:

 Reasoning: Anna will need 6*8 = <<6*8=48>>48 buttons in total.
### Answer: 48

Expected answer: 48

Correct? Yes

🔗 Problem

Problem: Tom has 1 strawberry plant. Each strawberry plant can produce 9 strawberries. How many strawberries can Tom's plant produce?

Qwen2-Math 7B:

 Reasoning: Tom's strawberry plant can produce 9 strawberries.
### Answer: 9

Expected answer: 9

Correct? Yes

🔗 Follow-up

Problem: Continuing from the earlier problem, let's say now Tom decides to increase his strawberry plant count to 5 plants. Given that each plant can produce 9 strawberries without any fertilizer, how many strawberries can all of Tom's plants now produce together?

Qwen2-Math 7B:

 Reasoning: If Tom has 5 plants, and each plant can produce 9 strawberries, then the total number of strawberries that all of Tom's plants can produce together is 5 * 9 = <<5*9=45>>45.
### Answer: 45

Expected answer: 45

Correct? Yes

🔗 Problem

Problem: In a large mansion, each room has 8 fireplaces. If there are 96 fireplaces in total, how many rooms are there in the mansion?

Qwen2-Math 7B:

 Reasoning: There are 96/8 = <<96/8=12>>12 rooms in the mansion.

Expected answer: 12

Correct? Yes

🔗 Follow-up

Problem: Following the last question, if each room in the mansion requires 7 workers to clean all of the fireplaces, how many workers are needed in total to clean all the fireplaces in the mansion?

Qwen2-Math 7B:

 Reasoning: There are 12 rooms in the mansion, and each room requires 7 workers to clean all of the fireplaces. Therefore, a total of 12*7 = <<12*7=84>>84 workers are needed to clean all the fireplaces in the mansion.
### Answer: 84

Expected answer: 84

Correct? Yes

🔗 Problem

Problem: John has 10 boxes he needs to transport in a truck. However, his truck can only hold 5 boxes at a time. How many trips does he need to make to transport all the boxes?

Qwen2-Math 7B:

 Reasoning: John needs to make 10/5 = <<10/5=2>>2 trips to transport all the boxes.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Follow-up

Problem: John has finished his trips and transported all the boxes. However, he realizes that each round trip he makes consumes 6 liters of fuel. How many liters of fuel has he used to make all of his trips?

Qwen2-Math 7B:

 Reasoning: John has used 2*6 = <<2*6=12>>12 liters of fuel to make all of his trips.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Problem

Problem: Charlie has a total of 63 toy cars. If he groups them equally into 9 big boxes, how many toy cars will be in each box?

Qwen2-Math 7B:

 Reasoning: Charlie has 63/9 = <<63/9=7>>7 toy cars in each box.
### Answer: 7

Expected answer: 7

Correct? Yes

🔗 Follow-up

Problem: Let's reconsider the organization of Charlie's toy cars. This time, instead of grouping them into 9 boxes, imagine he grouped the original 63 toy cars into only 5 boxes. How many toy cars will be in each box now?

Qwen2-Math 7B:

 Reasoning: Charlie has 63/5 = <<63/5=12.6>>12.6 toy cars in each box.
Since we can't have a fraction of a toy car, we'll round down to the nearest whole number, which is 12 toy cars in each box.
### Answer: 12

Expected answer: 63/5

Correct? No

🔗 Problem

Problem: On the farm, there are 24 hens. Each coop holds 12 hens. How many coops are needed to house all the hens?

Qwen2-Math 7B:

 Reasoning: Since each coop holds 12 hens, and there are 24 hens, we need 24/12 = <<24/12=2>>2 coops to house all the hens.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Follow-up

Problem: After reconsidering, the farmer decides to place the hens into larger coops where each coop can hold 8 hens. How many coops would he need now to house all the hens?

Qwen2-Math 7B:

 Reasoning: Since each coop holds 8 hens, and there are 24 hens, we need 24/8 = <<24/8=3>>3 coops to house all the hens.
### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Problem

Problem: If 3 large postcards are placed in 1 envelope, how many large postcards are in each envelope?

Qwen2-Math 7B:

 Reasoning: If 3 large postcards are placed in 1 envelope, then each envelope contains 3 large postcards.
### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: Following the previous question - if 3 large postcards are placed in 1 envelope, and Macy decided to distribute 6 envelopes of the same kind, how many large postcards did she distribute in total?

Qwen2-Math 7B:

 Reasoning: If 3 large postcards are placed in 1 envelope, and Macy distributed 6 envelopes, then she distributed 3*6 = <<3*6=18>>18 large postcards in total.
### Answer: 18

Expected answer: 18

Correct? Yes

🔗 Follow-up

Problem: Following the previous question - suppose that instead of placing 3 large postcards in each envelope, Macy starts to put only 2 large postcards in each envelope. How many large postcards are there in each envelope now?

Qwen2-Math 7B:

 Reasoning: If Macy starts to put only 2 large postcards in each envelope, then each envelope contains 2 large postcards.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Problem

Problem: Tommy is going camping and he needs sleeping bags. He took 12 sleeping bags from the storage and he remembered that he needs twice as many. How many sleeping bags does he need in total?

Qwen2-Math 7B:

 Reasoning: Tommy needs 12*2 = <<12*2=24>>24 sleeping bags.
Tommy needs 12+24 = <<12+24=36>>36 sleeping bags in total.
### Answer: 36

Expected answer: 24

Correct? No

🔗 Problem

Problem: In a new game, Tina earns 3 points per level. If she successfully completes 5 levels, how many total points does she earn?

Qwen2-Math 7B:

 Reasoning: Tina earns 3*5 = <<3*5=15>>15 points for completing 5 levels.
### Answer: 15

Expected answer: 15

Correct? Yes

🔗 Follow-up

Problem: In the same game, Tina decides to convert her points into game coins. If the current rate of conversion is 1 coin per point, how many game coins will she have after the conversion?

Qwen2-Math 7B:

 Reasoning: Tina has 15 points, and the conversion rate is 1 coin per point.
Tina will have 15*1 = <<15*1=15>>15 game coins after the conversion.
### Answer: 15

Expected answer: 15

Correct? Yes

🔗 Problem

Problem: In a video game, Tim needs 4 points to advance to the next level. If there are 9 levels in total, how many points does Tim need in total to finish the game?

Qwen2-Math 7B:

 Reasoning: Tim needs 4 points to advance to the next level.
There are 9 levels in total.
So, Tim needs 4*9 = <<4*9=36>>36 points in total to finish the game.
### Answer: 36

Expected answer: 36

Correct? Yes

🔗 Follow-up

Problem: In the new season of the video game, the number of points needed to advance to the next level increased. Now, Tim needs 4 points to advance each of the 11 levels. What is the total number of points Tim needs now to finish the game?

Qwen2-Math 7B:

 Reasoning: Tim needs 4 points to advance to the next level.
There are 11 levels in total.
So, Tim needs 4*11 = <<4*11=44>>44 points in total to finish the game.
### Answer: 44

Expected answer: 44

Correct? Yes

🔗 Problem

Problem: Sophie has a bubble blowing machine. The machine blows bubbles at a rate of 2 bubbles per second. How many bubbles will be blown in one second?

Qwen2-Math 7B:

 Reasoning: The bubble blowing machine blows 2 bubbles per second.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Follow-up

Problem: Sophie lets her bubble blowing machine run for another 9 seconds. How many more bubbles does the machine blow?

Qwen2-Math 7B:

 Reasoning: The bubble blowing machine blows 2 bubbles per second.
In 9 seconds, the machine blows 2*9 = <<2*9=18>>18 bubbles.
### Answer: 18

Expected answer: 18

Correct? Yes

🔗 Follow-up

Problem: Sophie changes the setting on her bubble blowing machine so that it now blows 7 bubbles per second instead of 2. How many bubbles will now be blown in one second?

Qwen2-Math 7B:

 Reasoning: The bubble blowing machine now blows 7 bubbles per second.
### Answer: 7

Expected answer: 7

Correct? Yes

🔗 Problem

Problem: Farmer Mike has 6 cows. Each of them gives 12 liters of milk every day. How many liters of milk does Farmer Mike get in a day?

Qwen2-Math 7B:

 Reasoning: Farmer Mike gets 6*12 = <<6*12=72>>72 liters of milk in a day.
### Answer: 72

Expected answer: 72

Correct? Yes

🔗 Follow-up

Problem: Farmer Mike decided to buy an additional cow, increasing his herd to 7 cows. If each cow still produces 12 liters of milk every day, how many liters of milk does Farmer Mike get in a day now?

Qwen2-Math 7B:

 Reasoning: Farmer Mike now gets 7*12 = <<7*12=84>>84 liters of milk in a day.
### Answer: 84

Expected answer: 84

Correct? Yes

🔗 Problem

Problem: John has 9 sunglasses in a line. He decided to divide his collection into equal parts. If each part contains 9 sunglasses, how many parts would he get?

Qwen2-Math 7B:

 Reasoning: John would get 9/9 = <<9/9=1>>1 part.
### Answer: 1

Expected answer: 1

Correct? Yes

🔗 Follow-up

Problem: After assigning sunglasses to the group, John considers dividing his original collection differently. If he divides the initial 9 sunglasses by 1 instead of 9, how many sunglasses would he have in each group?

Qwen2-Math 7B:

 Reasoning: John would have 9/1 = <<9/1=9>>9 sunglasses in each group.
### Answer: 9

Expected answer: 9

Correct? Yes

🔗 Problem

Problem: A rocket scientist needs to calculate the fuel consumption of his rocket. Each second, the rocket uses 9 units of fuel. After 11 seconds of flight, how much fuel has been consumed?

Qwen2-Math 7B:

 Reasoning: The rocket uses 9 units of fuel per second. After 11 seconds, the rocket has used 9*11 = <<9*11=99>>99 units of fuel.
### Answer: 99

Expected answer: 99

Correct? Yes

🔗 Problem

Problem: In the park, there are 4 swings available. Every swing can seat 3 children. How many children can the swings in the park seat altogether?

Qwen2-Math 7B:

 Reasoning: The total number of children that can be seated is 4*3 = <<4*3=12>>12.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Follow-up

Problem: In reconsideration, the first park actually only has 1 swing that can seat 3 children, not 4 swings. Given this new information, how many children can the swings in the first park seat now?

Qwen2-Math 7B:

 Reasoning: The total number of children that can be seated is 1*3 = <<1*3=3>>3.
### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Problem

Problem: There are 3 magical fairies in Fairyland. Each fairy has a unique ability to create triplets of herself. How many fairies will there be after each of them uses their ability?

Qwen2-Math 7B:

 Reasoning: Each fairy creates 3 new fairies, so there will be 3*3 = <<3*3=9>>9 new fairies.
There will be 3+9 = <<3+9=12>>12 fairies in total.
### Answer: 12

Expected answer: 9

Correct? No

🔗 Problem

Problem: James, a songwriter, loves to include the word "love" in his songs. In one song, he mentioned the word "love" 4 times in each verse. How many times did he mention "love" if the song has 3 verses?

Qwen2-Math 7B:

 Reasoning: James mentioned "love" 4 times in each verse, and the song has 3 verses.
James mentioned "love" 4*3 = <<4*3=12>>12 times in the song.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Follow-up

Problem: Following the last problem, after James wrote his song, he decided to dedicate four performances to his beloved. In each performance, he sings the song once. How many times will the word "love" be mentioned if he sings the song in all four performances?

Qwen2-Math 7B:

 Reasoning: James mentioned "love" 12 times in the song, and he sings the song once in each of the four performances.
James will mention "love" 12*4 = <<12*4=48>>48 times in all four performances.
### Answer: 48

Expected answer: 48

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous scenarios, James decided to rewrite his song. Now, he included the word "love" 4 times in each verse, but this time he expanded his song to include 10 verses. How many times does he mention "love" in this new version of his song?

Qwen2-Math 7B:

 Reasoning: James mentioned "love" 4 times in each verse, and the new song has 10 verses.
James mentioned "love" 4*10 = <<4*10=40>>40 times in the new version of his song.
### Answer: 40

Expected answer: 40

Correct? Yes

🔗 Problem

Problem: Mark has 48 apps on his phone. He likes to organize his apps into folders, and he can fit exactly 8 apps in each folder. How many folders does he need to organize all of his apps?

Qwen2-Math 7B:

 Reasoning: Mark needs 48/8 = <<48/8=6>>6 folders to organize all of his apps.
### Answer: 6

Expected answer: 6

Correct? Yes

🔗 Follow-up

Problem: Mark realized that he could fit more apps into each folder. If he reorganizes his apps so that each folder contains 6 apps instead of 8, how many folders will he need now to store all of his 48 apps?

Qwen2-Math 7B:

 Reasoning: Mark needs 48/6 = <<48/6=8>>8 folders to store all of his 48 apps.
### Answer: 8

Expected answer: 8

Correct? Yes

🔗 Problem

Problem: If Johnny wants to distribute candies to his friends at school and he decides to give each friend 12 candies, and there are 3 friends, how many candies does he need in total?

Qwen2-Math 7B:

 Reasoning: Johnny needs 12*3 = <<12*3=36>>36 candies in total.
### Answer: 36

Expected answer: 36

Correct? Yes

🔗 Follow-up

Problem: After distributing candies to his friends at school, Johnny decides to double the amount of candies he gave for the next day. How many candies will he need in total for the next day?

Qwen2-Math 7B:

 Reasoning: Johnny needs 36*2 = <<36*2=72>>72 candies in total for the next day.
### Answer: 72

Expected answer: 72

Correct? Yes

🔗 Problem

Problem: Tommy has a racetrack that he plans to race his toy cars on. If he can race 10 cars in total and he races 5 cars at a time, how many turns does it take for him to race all his cars?

Qwen2-Math 7B:

 Reasoning: Tommy races 5 cars at a time, so he needs to race 10/5 = <<10/5=2>>2 turns to race all his cars.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Follow-up

Problem: Following the previous scenario, Tommy decided to organize multiple rounds of races. If he performs 8 rounds of races, with each round involving the same number of turns as before, how many turns in total will he need to complete all the rounds?

Qwen2-Math 7B:

 Reasoning: Tommy needs 2 turns to complete one round of races. For 8 rounds, he will need 2*8 = <<2*8=16>>16 turns in total.
### Answer: 16

Expected answer: 16

Correct? Yes

🔗 Problem

Problem: Sally has 40 feathers from her chickens. If she arranged the feathers in groups of 10, how many groups would she have?

Qwen2-Math 7B:

 Reasoning: Sally would have 40/10 = <<40/10=4>>4 groups of feathers.
### Answer: 4

Expected answer: 4

Correct? Yes

🔗 Follow-up

Problem: Sally sorts her 40 chicken feathers into groups of 10. Then, she decided to double the number of groups. How many groups does she have now?

Qwen2-Math 7B:

 Reasoning: Sally originally had 40/10 = <<40/10=4>>4 groups of feathers.
After doubling the number of groups, she now has 4*2 = <<4*2=8>>8 groups of feathers.
### Answer: 8

Expected answer: 8

Correct? Yes

🔗 Follow-up

Problem: Sally originally thought she had sorted her 40 chicken feathers into groups of 10, but then she realized she actually sorted them into groups of 11 instead. How many groups does she have now?

Qwen2-Math 7B:

 Reasoning: Sally would have 40/11 = <<40/11=3.6363636363636362>>3.6363636363636362 groups of feathers.
Since Sally cannot have a fraction of a group, she would have 3 full groups and 7 feathers left over.
### Answer: 3 groups

Expected answer: 40/11

Correct? No

🔗 Problem

Problem: Fairy Lily is 1 inch tall. However, when she uses her magical fairy dust, she can become 11 times her original size. How tall is Fairy Lily when she uses her magical dust?

Qwen2-Math 7B:

 Reasoning: Fairy Lily is 1 inch tall. When she uses her magical fairy dust, she becomes 11 times her original size.
Fairy Lily is 1*11 = <<1*11=11>>11 inches tall when she uses her magical dust.
### Answer: 11

Expected answer: 11

Correct? Yes

🔗 Follow-up

Problem: After using her magical dust to grow 11 times her original size, Fairy Lily decides to add another element to her spells. She casts a spell that multiplies her height by 7. How tall is Fairy Lily now?

Qwen2-Math 7B:

 Reasoning: After using her magical dust to grow 11 times her original size, Fairy Lily is 11 inches tall.
She then casts a spell that multiplies her height by 7.
Fairy Lily is now 11*7 = <<11*7=77>>77 inches tall.
### Answer: 77

Expected answer: 77

Correct? Yes

🔗 Follow-up

Problem: In a different scenario, if Fairy Lily only grows to 6 times her original size rather than 11 times using her magical dust, how tall would she become then?

Qwen2-Math 7B:

 Reasoning: If Fairy Lily only grows to 6 times her original size, she would become 6 times her original height.
Fairy Lily would be 1*6 = <<1*6=6>>6 inches tall when she uses her magical dust.
### Answer: 6

Expected answer: 6

Correct? Yes

🔗 Problem

Problem: In a beehive, one female bee can produce 5 new bees every day. How many bees would she produce in 1 day?

Qwen2-Math 7B:

 Reasoning: The female bee produces 5 new bees every day.
### Answer: 5

Expected answer: 5

Correct? Yes

🔗 Follow-up

Problem: Following the previous problem, if this female bee continues to produce bees at the same rate, how many bees will she have produced after 11 days?

Qwen2-Math 7B:

 Reasoning: The female bee produces 5 new bees every day.
After 11 days, she will have produced 5*11 = <<5*11=55>>55 new bees.
### Answer: 55

Expected answer: 55

Correct? Yes

🔗 Follow-up

Problem: Following the previous problems, consider if the female bee instead produced new bees at a slower rate, making only 5 bees every 3 days. How many bees would she produce in one day at this new rate?

Qwen2-Math 7B:

 Reasoning: The female bee produces 5 bees every 3 days, which means she produces 5/3 = <<5/3=1.6666666666666667>>1.6666666666666667 bees per day.
### Answer: 1.6666666666666667

Expected answer: 5/3

Correct? Yes

🔗 Problem

Problem: Thomas has 35 piano sheets in his music stand. If he wants to evenly distribute his music sheets into 7 piano books, how many sheets will each book have?

Qwen2-Math 7B:

 Reasoning: Thomas will have 35/7 = <<35/7=5>>5 sheets in each book.
### Answer: 5

Expected answer: 5

Correct? Yes

🔗 Follow-up

Problem: After arranging his music sheets into the piano books, Thomas decided to purchase 8 more books, each with the same number of sheets as the books he has now. How many more piano sheets did he buy?

Qwen2-Math 7B:

 Reasoning: Thomas bought 8*5 = <<8*5=40>>40 more piano sheets.
### Answer: 40

Expected answer: 40

Correct? Yes

🔗 Follow-up

Problem: Instead, suppose originally Thomas had 9 piano sheets. If he evenly distributes his music sheets into 7 piano books as before, how many sheets will each book have now?

Qwen2-Math 7B:

 Reasoning: Thomas will have 9/7 = <<9/7=1.2857142857142858>>1.2857142857142858 sheets in each book.
### Answer: 1.2857142857142858

Expected answer: 9/7

Correct? Yes

🔗 Problem

Problem: Mom baked 2 batches of cookies. Each batch contains 8 cookies. How many cookies did mom bake in total?

Qwen2-Math 7B:

 Reasoning: Mom baked 2 batches of cookies, and each batch contains 8 cookies.
Therefore, Mom baked 2*8 = <<2*8=16>>16 cookies in total.
### Answer: 16

Expected answer: 16

Correct? Yes

🔗 Problem

Problem: Earth has 3 natural satellites. If the number of moon rocks collected each year is triple the total number of these satellites, how many moon rocks would be collected in one year?

Qwen2-Math 7B:

 Reasoning: The total number of Earth's natural satellites is 3.
The number of moon rocks collected each year is triple the total number of these satellites, which is 3*3 = <<3*3=9>>9.
Therefore, 9 moon rocks would be collected in one year.
### Answer: 9

Expected answer: 9

Correct? Yes

🔗 Follow-up

Problem: Following the previous scenario, if each moon rock collected in a year is stored in a separate storage bin, how many storage bins would be needed to store all the rocks collected in one year?

Qwen2-Math 7B:

 Reasoning: If each moon rock collected in a year is stored in a separate storage bin, and 9 moon rocks are collected in one year, then 9 storage bins would be needed to store all the rocks collected in one year.
### Answer: 9

Expected answer: 9

Correct? Yes

🔗 Follow-up

Problem: Continuing from the previous scenario, suppose that instead of 3, the Earth had 5 natural satellites. In this case, if the number of moon rocks collected each year is triple the total number of these satellites, how many moon rocks would be collected in one year?

Qwen2-Math 7B:

 Reasoning: The total number of Earth's natural satellites is 5.
The number of moon rocks collected each year is triple the total number of these satellites, which is 5*3 = <<5*3=15>>15.
Therefore, 15 moon rocks would be collected in one year.
### Answer: 15

Expected answer: 15

Correct? Yes

🔗 Problem

Problem: Doctor Thomas needs to visit 10 patients. He spends 5 minutes with each patient. How many minutes does he spend with all of his patients?

Qwen2-Math 7B:

 Reasoning: Doctor Thomas spends 5*10 = <<5*10=50>>50 minutes with all of his patients.
### Answer: 50

Expected answer: 50

Correct? Yes

🔗 Follow-up

Problem: After visiting his patients, Doctor Thomas then spends twice the amount of time he spent with his patients on paperwork. How many minutes does he spend on paperwork?

Qwen2-Math 7B:

 Reasoning: Doctor Thomas spends 50*2 = <<50*2=100>>100 minutes on paperwork.
### Answer: 100

Expected answer: 100

Correct? Yes

🔗 Follow-up

Problem: In a different scenario, Doctor Thomas spends 6 minutes with each patient instead of 5 minutes. If he still has the same number of patients to visit, how many minutes will he spend with all his patients?

Qwen2-Math 7B:

 Reasoning: Doctor Thomas spends 6*10 = <<6*10=60>>60 minutes with all of his patients.
### Answer: 60

Expected answer: 60

Correct? Yes

🔗 Problem

Problem: Jerry was thinking of purchasing new pants and he noticed a special offer. The shop was selling 11 pants for $55. After calculating the price for each pant, he decided to buy 12. How much would he spend?

Qwen2-Math 7B:

 Reasoning: The price for each pant is $55/11 = <<55/11=5>>5.
Jerry would spend 12*5 = <<12*5=60>>60 dollars.
### Answer: 60

Expected answer: 60

Correct? Yes

🔗 Problem

Problem: Molly has 8 bottles of apple juice. She decides to multiply her collection of apple juice bottles by the same number she has. How many bottles of apple juice does Molly have now?

Qwen2-Math 7B:

 Reasoning: Molly has 8*8 = <<8*8=64>>64 bottles of apple juice now.
### Answer: 64

Expected answer: 64

Correct? Yes

🔗 Follow-up

Problem: Molly later decided that 8 bottles of apple juice were too many. So, she reduced her collection to 6 bottles. Then, she once again decided to increase her apple juice collection by multiplying the number of bottles she has by the same number. How many bottles of apple juice does Molly have now?

Qwen2-Math 7B:

 Reasoning: Molly has 6*6 = <<6*6=36>>36 bottles of apple juice now.
### Answer: 36

Expected answer: 36

Correct? Yes

🔗 Problem

Problem: There are few craters on one of the sections of the moon. If that section is divided into 8 equal parts and we count 32 craters in total, how many craters are there in each part?

Qwen2-Math 7B:

 Reasoning: If there are 32 craters in total and the section is divided into 8 equal parts, then there are 32/8 = <<32/8=4>>4 craters in each part.
### Answer: 4

Expected answer: 4

Correct? Yes

🔗 Follow-up

Problem: Let's think back to the moon section with craters we discussed earlier. Suppose instead that the moon's section was divided into 5 equal parts with a total of 32 craters. How many craters would there be in each part then?

Qwen2-Math 7B:

 Reasoning: If there are 32 craters in total and the section is divided into 5 equal parts, then there are 32/5 = <<32/5=6.4>>6.4 craters in each part. However, since we cannot have a fraction of a crater, we can round this number to the nearest whole number, which is 6 craters in each part.
### Answer: 6

Expected answer: 32/5

Correct? No

🔗 Problem

Problem: There are 4 monkeys in the jungle. Each monkey has 7 bananas. How many bananas do the monkeys have in total?

Qwen2-Math 7B:

 Reasoning: There are 4 monkeys, and each monkey has 7 bananas. So, the total number of bananas is 4*7 = <<4*7=28>>28.
### Answer: 28

Expected answer: 28

Correct? Yes

🔗 Follow-up

Problem: Let's imagine that originally there were 9 monkeys instead of 4. If each monkey has 7 bananas, how many bananas do all the monkeys have in total now?

Qwen2-Math 7B:

 Reasoning: If there are 9 monkeys and each monkey has 7 bananas, then the total number of bananas is 9*7 = <<9*7=63>>63.
### Answer: 63

Expected answer: 63

Correct? Yes

🔗 Problem

Problem: Fiona has a block of cheese that weighs 32 ounces. If she wants to divide it into equal pieces which each weigh 4 ounces, how many pieces of cheese will she have?

Qwen2-Math 7B:

 Reasoning: Fiona will have 32/4 = <<32/4=8>>8 pieces of cheese.
### Answer: 8

Expected answer: 8

Correct? Yes

🔗 Follow-up

Problem: Fiona later found a smaller block of cheese that weighs 32 ounces. If she wants to cut this one into equal pieces which each weigh 9 ounces, how many pieces of cheese will she get from this block?

Qwen2-Math 7B:

 Reasoning: Fiona will have 32/9 = <<32/9=3.5555555555555554>>3.5555555555555554 pieces of cheese.
Since she cannot have a fraction of a piece, she will have 3 pieces of cheese.
### Answer: 3

Expected answer: 32/9

Correct? No

🔗 Problem

Problem: Bob has 6 cups. If he wants to fill each cup with 1 glass of milk, how many glasses of milk does he need?

Qwen2-Math 7B:

 Reasoning: Bob needs 6 glasses of milk to fill each cup.
### Answer: 6

Expected answer: 6

Correct? Yes

🔗 Follow-up

Problem: Bob just realized he only has 2 cups instead of 6. If he still wants to fill each cup with 1 glass of milk, how many glasses of milk does he need now?

Qwen2-Math 7B:

 Reasoning: Bob needs 2 glasses of milk to fill each cup.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Problem

Problem: In the zoo, there are 36 new-born rabbits divided evenly into 9 cages. Each cage is then assigned to two caretakers. How many caretakers are assigned per cage?

Qwen2-Math 7B:

 Reasoning: There are 36/9 = <<36/9=4>>4 new-born rabbits in each cage.
Since each cage is assigned to two caretakers, there are 4/2 = <<4/2=2>>2 caretakers assigned per cage.
### Answer: 2

Expected answer: 8

Correct? No

🔗 Problem

Problem: Farmer Brown has made 42 blocks of cheese. Each wheel of cheese requires 7 blocks to make. How many whole wheels of cheese can he make with the current blocks he has?

Qwen2-Math 7B:

 Reasoning: Farmer Brown can make 42/7 = <<42/7=6>>6 whole wheels of cheese with the current blocks he has.
### Answer: 6

Expected answer: 6

Correct? Yes

🔗 Follow-up

Problem: After making the cheese wheels, Farmer Brown decides to double his production in order to have enough for the upcoming village fair. Based on his current production rate, how many cheese wheels will he have after doubling his output?

Qwen2-Math 7B:

 Reasoning: Farmer Brown can make 42/7 = <<42/7=6>>6 whole wheels of cheese with the current blocks he has.
To double his production, he will have 6 * 2 = <<6*2=12>>12 cheese wheels.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Problem

Problem: John has a square kite. Each side of the kite is 4 feet long. What is the total length of two sides of the kite in feet?

Qwen2-Math 7B:

 Reasoning: The total length of two sides of the kite is 4+4 = <<4+4=8>>8 feet.
### Answer: 8

Expected answer: 8

Correct? Yes

🔗 Follow-up

Problem: John wants to make another identical kite. How many feet of string will he need for the two sides of both kites?

Qwen2-Math 7B:

 Reasoning: John will need 8+8 = <<8+8=16>>16 feet of string for the two sides of both kites.
### Answer: 16

Expected answer: 16

Correct? Yes

🔗 Follow-up

Problem: Suppose that John decides to make a very small kite with each side only 1 foot long. What is the total length of two sides of this smaller kite in feet?

Qwen2-Math 7B:

 Reasoning: The total length of two sides of the smaller kite is 1+1 = <<1+1=2>>2 feet.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Problem

Problem: Anna has 4 bags of candy, each containing 3 candies. How many candies does she have in total?

Qwen2-Math 7B:

 Reasoning: Anna has 4*3 = <<4*3=12>>12 candies in total.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Follow-up

Problem: In the previous situation, what if Anna initially had only 1 bag of candy, each containing 3 candies? How many candies would she have initially?

Qwen2-Math 7B:

 Reasoning: Anna would have 1*3 = <<1*3=3>>3 candies initially.
### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Problem

Problem: A garden has 6 patches of flowers. Each patch attracts 3 butterflies. How many butterflies are there in total in the garden?

Qwen2-Math 7B:

 Reasoning: There are 6*3 = <<6*3=18>>18 butterflies in total in the garden.
### Answer: 18

Expected answer: 18

Correct? Yes

🔗 Follow-up

Problem: In a similar situation, imagine if initially there were 8 patches of flowers instead of 6 and each patch still attracts 3 butterflies. How many butterflies would there be in total then?

Qwen2-Math 7B:

 Reasoning: If there were 8 patches of flowers and each patch attracts 3 butterflies, then there would be 8*3 = <<8*3=24>>24 butterflies in total.
### Answer: 24

Expected answer: 24

Correct? Yes

🔗 Problem

Problem: Sophia is having a party. She wants to divide 72 cookies evenly among her 8 friends, giving them an equal number. She then decides to gift each friend 5 times the amount they initially received. How many cookies will each friend get in total?

Qwen2-Math 7B:

 Reasoning: Sophia initially divides 72 cookies among 8 friends, giving each friend 72/8 = <<72/8=9>>9 cookies.
Sophia then gifts each friend 5 times the amount they initially received, so each friend gets 9*5 = <<9*5=45>>45 cookies.
### Answer: 45

Expected answer: 45

Correct? Yes

🔗 Follow-up

Problem: Sophia revisited her party plans and decided to invite two more friends, resulting in a total of 10 friends. Now she wants to divide the same 72 cookies evenly among all her friends, and again, give each friend 5 times the initial amount. How many cookies will each friend get in total now?

Qwen2-Math 7B:

 Reasoning: Sophia now has 10 friends, so she divides 72 cookies among 10 friends, giving each friend 72/10 = <<72/10=7.2>>7.2 cookies.
Sophia then gifts each friend 5 times the amount they initially received, so each friend gets 7.2*5 = <<7.2*5=36>>36 cookies.
### Answer: 36

Expected answer: 36

Correct? Yes

🔗 Problem

Problem: John has 3 cameras. Each camera can take 1 picture per second. If John uses all his cameras to take pictures for 5 seconds, how many pictures will he have taken in total?

Qwen2-Math 7B:

 Reasoning: John can take 3*1 = <<3*1=3>>3 pictures per second.
John can take 3*5 = <<3*5=15>>15 pictures in 5 seconds.
### Answer: 15

Expected answer: 15

Correct? Yes

🔗 Problem

Problem: Tommy has 3 boxes of toys. Each box contains 9 toys. How many toys does Tommy have in total?

Qwen2-Math 7B:

 Reasoning: Tommy has 3*9 = <<3*9=27>>27 toys in total.
### Answer: 27

Expected answer: 27

Correct? Yes

🔗 Follow-up

Problem: Tommy realized he made a mistake when counting his toys. Instead of having 3 boxes of toys, he actually had 10 boxes. Each box still contains 9 toys. Now, how many toys does Tommy really have?

Qwen2-Math 7B:

 Reasoning: Tommy has 10*9 = <<10*9=90>>90 toys in total.
### Answer: 90

Expected answer: 90

Correct? Yes

🔗 Problem

Problem: Joanna has a clothing store and packs 10 shirts into 5 boxes. How many shirts does each box contain?

Qwen2-Math 7B:

 Reasoning: Each box contains 10/5 = <<10/5=2>>2 shirts.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Follow-up

Problem: What if Joanna originally had 7 shirts instead of 10 and she still wants to distribute them evenly into 5 boxes? How many shirts will each box contain then?

Qwen2-Math 7B:

 Reasoning: If Joanna originally had 7 shirts and she still wants to distribute them evenly into 5 boxes, each box will contain 7/5 = <<7/5=1.4>>1.4 shirts. However, since we cannot have a fraction of a shirt, we can say that each box will contain 1 shirt, and there will be 2 shirts left over.
### Answer: 1

Expected answer: 7/5

Correct? No

🔗 Problem

Problem: Jack has 9 scooters. Harry, seeing Jack's love for scooters, decided to give him seven times as many scooters for his birthday. How many scooters did Harry give to Jack?

Qwen2-Math 7B:

 Reasoning: Harry gave Jack 9*7 = <<9*7=63>>63 scooters.
### Answer: 63

Expected answer: 63

Correct? Yes

🔗 Follow-up

Problem: Suppose instead of having 9 scooters originally, Jack started with 6 scooters. How many scooters would Harry give to Jack now, following Harry's original plan of giving seven times as many scooters as Jack initially had?

Qwen2-Math 7B:

 Reasoning: Harry would give Jack 6*7 = <<6*7=42>>42 scooters.
### Answer: 42

Expected answer: 42

Correct? Yes

🔗 Problem

Problem: There are 7 hours on a clock. Each hour has 4 quarters. How many quarters are there in three clocks?

Qwen2-Math 7B:

 Reasoning: There are 7*4 = <<7*4=28>>28 quarters in one clock.
There are 28*3 = <<28*3=84>>84 quarters in three clocks.
### Answer: 84

Expected answer: 84

Correct? Yes

🔗 Problem

Problem: Liam has 35 scoops of ice cream. If he puts an equal amount of ice cream into 5 cones, how many scoops of ice cream does each cone get?

Qwen2-Math 7B:

 Reasoning: Liam puts 35/5 = <<35/5=7>>7 scoops of ice cream into each cone.
### Answer: 7

Expected answer: 7

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, we had 35 scoops of ice cream to start with. But what if we start with only 8 scoops of ice cream, and we are still trying to divide it equally into 5 cones? How many scoops of ice cream would each cone hold then?

Qwen2-Math 7B:

 Reasoning: Liam puts 8/5 = <<8/5=1.6>>1.6 scoops of ice cream into each cone.
### Answer: 1.6

Expected answer: 8/5

Correct? Yes

🔗 Problem

Problem: Billy has 8 toy trains at his house. He went to a train festival and got 9 times more trains than he originally had. How many trains did Billy get at the festival?

Qwen2-Math 7B:

 Reasoning: Billy got 8*9 = <<8*9=72>>72 trains at the festival.
### Answer: 72

Expected answer: 72

Correct? Yes

🔗 Follow-up

Problem: If Billy originally had 8 toy trains, but at the train festival, he was able to gather 8 times more trains than he originally had instead of 9, how many trains did Billy get at the festival?

Qwen2-Math 7B:

 Reasoning: Billy got 8*8 = <<8*8=64>>64 trains at the festival.
### Answer: 64

Expected answer: 64

Correct? Yes

🔗 Problem

Problem: A librarian decided to arrange books on a shelf. She placed 8 books in a row and made sure every row had the same number of books. How many books were there if the arrangement was square (i.e., the same number of rows as there were books in a row)?

Qwen2-Math 7B:

 Reasoning: Since the arrangement is square, the number of books in a row is equal to the number of rows. Therefore, the total number of books is the square of the number of books in a row.
The total number of books is <<8*8=64>>64.
### Answer: 64

Expected answer: 64

Correct? Yes

🔗 Follow-up

Problem: Following the previous problem about the librarian, let's consider a different scenario. This time, she decides to arrange a smaller square of books with only 4 books in a row. Each row still has the same number of books. So, how many books does she need for this smaller square arrangement?

Qwen2-Math 7B:

 Reasoning: Similar to the previous problem, the number of books in a row is equal to the number of rows in a square arrangement. Therefore, the total number of books is the square of the number of books in a row.
The total number of books is <<4*4=16>>16.
### Answer: 16

Expected answer: 16

Correct? Yes

🔗 Problem

Problem: Lisa had 10 yards of fabric. If it takes 1 yard of fabric to make a skirt, how many skirts can Lisa make?

Qwen2-Math 7B:

 Reasoning: Lisa can make 10/1 = <<10/1=10>>10 skirts.
### Answer: 10

Expected answer: 10

Correct? Yes

🔗 Problem

Problem: Sarah receives 12 phone calls every day on her work phone. But, she only answers a quarter of those phone calls. How many phone calls does she answer a day?

Qwen2-Math 7B:

 Reasoning: Sarah answers 12/4 = <<12/4=3>>3 phone calls a day.
### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: Following up on the previous problem, if for each phone call Sarah answered, she received 11 more calls as a response, how many additional calls did she receive in a day?

Qwen2-Math 7B:

 Reasoning: Sarah received 3*11 = <<3*11=33>>33 additional calls in a day.
### Answer: 33

Expected answer: 33

Correct? Yes

🔗 Problem

Problem: Melanie is planning for a camping trip and she needs 3 sleeping bags for each of her 4 friends. How many sleeping bags does Melanie need in total?

Qwen2-Math 7B:

 Reasoning: Melanie needs 3*4 = <<3*4=12>>12 sleeping bags in total.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Follow-up

Problem: Suppose Melanie originally planned to bring 3 sleeping bags for each of her 6 friends instead of 4, for the camping trip. How many sleeping bags would Melanie need in total for the camping trip now?

Qwen2-Math 7B:

 Reasoning: Melanie needs 3*6 = <<3*6=18>>18 sleeping bags in total.
### Answer: 18

Expected answer: 18

Correct? Yes

🔗 Problem

Problem: Johnny has 3 times the amount of snowballs that Billy does. If Billy has 6 snowballs, how many snowballs does Johnny have?

Qwen2-Math 7B:

 Reasoning: Johnny has 3*6 = <<3*6=18>>18 snowballs.
### Answer: 18

Expected answer: 18

Correct? Yes

🔗 Follow-up

Problem: Consider now that initially, Johnny had 3 times the amount of snowballs that Billy does, not 5 times. If Billy still has 11 snowballs, how many snowballs does Johnny have now?

Qwen2-Math 7B:

 Reasoning: Johnny has 3*11 = <<3*11=33>>33 snowballs.
### Answer: 33

Expected answer: 33

Correct? Yes

🔗 Problem

Problem: In a game, each star is equivalent to 5 points. If Tom collected 1 star, how many points does he have?

Qwen2-Math 7B:

 Reasoning: Tom has 1*5 = <<1*5=5>>5 points.
### Answer: 5

Expected answer: 5

Correct? Yes

🔗 Follow-up

Problem: Tom decided to play more of the game and managed to collect 4 more stars. Considering that each star is equivalent to 5 points, how many additional points has he earned now?

Qwen2-Math 7B:

 Reasoning: Tom has 4*5 = <<4*5=20>>20 additional points.
### Answer: 20

Expected answer: 20

Correct? Yes

🔗 Follow-up

Problem: In the game, what if initially each star was equivalent to 7 points instead of 5? If Tom collected 1 star as before, how many points would he have now?

Qwen2-Math 7B:

 Reasoning: Tom has 1*7 = <<1*7=7>>7 points.
### Answer: 7

Expected answer: 7

Correct? Yes

🔗 Problem

Problem: Captain Jack has 4 cannons on his pirate ship. If each cannon fires 12 cannonballs, how many cannonballs were fired in total?

Qwen2-Math 7B:

 Reasoning: Captain Jack fired 4*12 = <<4*12=48>>48 cannonballs in total.
### Answer: 48

Expected answer: 48

Correct? Yes

🔗 Follow-up

Problem: Given that Captain Jack actually had 4 cannons, but each can fire only 3 cannonballs, how many cannonballs were fired in total now?

Qwen2-Math 7B:

 Reasoning: Captain Jack fired 4*3 = <<4*3=12>>12 cannonballs in total.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Problem

Problem: Emma has a pack of 10 colored pencils. She wants to have as many colored pencils as the square of the number she currently has. How many colored pencils will she have then?

Qwen2-Math 7B:

 Reasoning: Emma wants to have 10^2 = <<10^2=100>>100 colored pencils.
### Answer: 100

Expected answer: 100

Correct? Yes

🔗 Follow-up

Problem: Now consider if Emma had started with a pack of only 4 colored pencils instead. If she still wants to have as many colored pencils as the square of the number she currently has, how many colored pencils will she have then?

Qwen2-Math 7B:

 Reasoning: Emma wants to have 4^2 = <<4^2=16>>16 colored pencils.
### Answer: 16

Expected answer: 16

Correct? Yes

🔗 Problem

Problem: Emily had 70 cookies. She decided to pack them in bags with each bag containing 7 cookies. After getting the number of bags, she decided to multiply it by 6 for a camping trip. How many cookies does she need for her intended number of sleeping bag sets?

Qwen2-Math 7B:

 Reasoning: Emily packed 70/7 = <<70/7=10>>10 bags.
Emily needs 10*6 = <<10*6=60>>60 cookies for her intended number of sleeping bag sets.
### Answer: 60

Expected answer: 60

Correct? Yes

🔗 Follow-up

Problem: Let's consider a different scenario. Emily originally had 9 cookies instead of 70. She still wants to pack them in bags, with each bag containing 7 cookies. She still wants to multiply the number of bags by 6 for a camping trip. How many cookies does she need now for her intended number of sleeping bag sets?

Qwen2-Math 7B:

 Reasoning: Emily packed 9/7 = <<9/7=1>>1 bag.
Emily needs 1*6 = <<1*6=6>>6 cookies for her intended number of sleeping bag sets.
### Answer: 6

Expected answer: 54/7

Correct? No

🔗 Problem

Problem: Captain Redbeard has 6 cannons on one side of his pirate ship. Each cannon fires 4 cannonballs at a time when the ship goes into battle. During a sea fight, with one shot from each of the cannons on one side of the ship, how many cannonballs are fired in total?

Qwen2-Math 7B:

 Reasoning: Captain Redbeard has 6 cannons, and each cannon fires 4 cannonballs at a time. Therefore, the total number of cannonballs fired is 6*4 = <<6*4=24>>24.
### Answer: 24

Expected answer: 24

Correct? Yes

🔗 Follow-up

Problem: In a different battle, Captain Redbeard decided to increase his firepower and loaded each cannon with 11 cannonballs. With one shot from each of the 6 cannons on one side of his ship, how many cannonballs would be fired in total from that side?

Qwen2-Math 7B:

 Reasoning: Captain Redbeard has 6 cannons, and each cannon fires 11 cannonballs at a time. Therefore, the total number of cannonballs fired is 6*11 = <<6*11=66>>66.
### Answer: 66

Expected answer: 66

Correct? Yes

🔗 Problem

Problem: A magical unicorn walks 72 miles every day. If it takes the unicorn 12 hours to cover that distance. How many miles does the unicorn cover every hour?

Qwen2-Math 7B:

 Reasoning: The unicorn covers 72/12 = <<72/12=6>>6 miles every hour.

Expected answer: 6

Correct? Yes

🔗 Follow-up

Problem: In a magical turn of events, the unicorn's speed is tripled for an enchanting hour. Given the unicorn's new pace, how many miles would it cover in that enchanted hour?

Qwen2-Math 7B:

 Reasoning: The unicorn's speed is tripled, so it covers 6*3 = <<6*3=18>>18 miles in that enchanted hour.

Expected answer: 18

Correct? Yes

🔗 Problem

Problem: Sue has 3 potato plants and each plant yields 10 potatoes. How many potatoes does Sue have in total?

Qwen2-Math 7B:

 Reasoning: Sue has 3*10 = <<3*10=30>>30 potatoes in total.
### Answer: 30

Expected answer: 30

Correct? Yes

🔗 Follow-up

Problem: Suppose that Sue originally planted 3 potato plants instead of 10, and each of those plants still produced 3 potatoes. How many potatoes would Sue have harvested from her original planting?

Qwen2-Math 7B:

 Reasoning: Sue would have harvested 3*3 = <<3*3=9>>9 potatoes from her original planting.
### Answer: 9

Expected answer: 9

Correct? Yes

🔗 Problem

Problem: An astronaut walks a distance of 20 kilometers per day on the lunar surface. If they decide to only walk for 1/5 of the day, how many kilometers do they cover?

Qwen2-Math 7B:

 Reasoning: The astronaut walks 20/5 = <<20/5=4>>4 kilometers in 1/5 of the day.
The astronaut walks 4 kilometers in 1/5 of the day.
### Answer: 4

Expected answer: 4

Correct? Yes

🔗 Follow-up

Problem: Following up on the previous problem, let's say on a particular day, the astronaut decides to increase their walking duration from 1/5 of a day to 12/5 of a day. How many kilometers would they cover on that day?

Qwen2-Math 7B:

 Reasoning: The astronaut walks 20 * 12/5 = <<20*12/5=48>>48 kilometers in 12/5 of a day.
The astronaut walks 48 kilometers in 12/5 of a day.
### Answer: 48

Expected answer: 48

Correct? Yes

🔗 Follow-up

Problem: In a new scenario, let's say the astronaut now walks a distance of 20 kilometers per day on the lunar surface but decides to walk for only 1/6 of the day instead of 1/5. How many kilometers would they cover in this case?

Qwen2-Math 7B:

 Reasoning: The astronaut walks 20/6 = <<20/6=3.3333333333333335>>3.3333333333333335 kilometers in 1/6 of the day.
The astronaut walks approximately 3.33 kilometers in 1/6 of the day.
### Answer: 3.33

Expected answer: 10/3

Correct? No

🔗 Problem

Problem: Mr. Lemon has 10 lemons and he wants to evenly distribute them into 5 boxes. How many lemons will there be in each box?

Qwen2-Math 7B:

 Reasoning: Mr. Lemon has 10 lemons and he wants to evenly distribute them into 5 boxes. So, there will be 10/5 = <<10/5=2>>2 lemons in each box.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Follow-up

Problem: Mr. Lemon decides to add 2 more lemons to each box, because he wants to share more lemons with his friends. How many lemons will there be in each box now?

Qwen2-Math 7B:

 Reasoning: Mr. Lemon has 10 lemons and he wants to evenly distribute them into 5 boxes. So, there will be 10/5 = <<10/5=2>>2 lemons in each box. Then, he decides to add 2 more lemons to each box. So, there will be 2+2 = <<2+2=4>>4 lemons in each box now.
### Answer: 4

Expected answer: 4

Correct? Yes

🔗 Follow-up

Problem: After some thought, Mr. Lemon considers distributing the ten lemons among six boxes instead of five. How many lemons would there be in each box if he decides to distribute them in this way?

Qwen2-Math 7B:

 Reasoning: Mr. Lemon has 10 lemons and he wants to evenly distribute them into 6 boxes. So, there will be 10/6 = <<10/6=1.6666666666666667>>1.6666666666666667 lemons in each box. However, since we cannot have a fraction of a lemon, we can say that there will be 1 lemon in each of the first 5 boxes and 2 lemons in the last box.
### Answer: 1, 1, 1, 1, 1, 2

Expected answer: 5/3

Correct? No

🔗 Problem

Problem: A helicopter pad can hold 4 helicopters at a time. The city has decided to build 11 new helicopter pads. How many helicopters can all of the helicopter pads hold when combined?

Qwen2-Math 7B:

 Reasoning: The city has decided to build 11 new helicopter pads. Each helicopter pad can hold 4 helicopters at a time. Therefore, all of the helicopter pads can hold 11*4 = <<11*4=44>>44 helicopters when combined.
### Answer: 44

Expected answer: 44

Correct? Yes

🔗 Follow-up

Problem: If each of the helicopters that the city's helicopter pads can hold requires just one helipad to park, how many helipads will be occupied when all the helicopters are parked?

Qwen2-Math 7B:

 Reasoning: If each of the helicopters that the city's helicopter pads can hold requires just one helipad to park, then the number of helipads occupied will be equal to the number of helicopters. Since all of the helicopter pads can hold 44 helicopters when combined, there will be 44 helipads occupied when all the helicopters are parked.
### Answer: 44

Expected answer: 44

Correct? Yes

🔗 Problem

Problem: John decided to re-arrange his room and he has a single bed that takes the space of 1 large carpet tile. If his room size requires 12 such carpet tiles fully side by side, how many bed spaces does John's room have?

Qwen2-Math 7B:

 Reasoning: John's room has 12/1 = <<12/1=12>>12 bed spaces.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Follow-up

Problem: In a different layout, John realized he could fit 3 beds in the space currently occupied by 1 large carpet tile due to the smaller size of new bunk beds he purchased. If his room size still requires 12 large carpet tiles side by side, then, how many new bunk beds can he fit in his room now?

Qwen2-Math 7B:

 Reasoning: John can fit 12/3 = <<12/3=4>>4 new bunk beds in his room.
### Answer: 4

Expected answer: 36

Correct? No

🔗 Problem

Problem: Sophie has 8 flowerpots. In each flowerpot, she plans to plant 3 flowers. How many flowers will Sophie plant in total?

Qwen2-Math 7B:

 Reasoning: Sophie will plant 8*3 = <<8*3=24>>24 flowers in total.
### Answer: 24

Expected answer: 24

Correct? Yes

🔗 Follow-up

Problem: After successfully planting flowers in her 8 flowerpots, Sophie decided to double the total number of flowers she planted. How many flowers does she have now?

Qwen2-Math 7B:

 Reasoning: Sophie now has 24*2 = <<24*2=48>>48 flowers.
### Answer: 48

Expected answer: 48

Correct? Yes

🔗 Follow-up

Problem: Now imagine if Sophie originally had 12 flowerpots instead of 8. How many flowers would she have planted if she still planted 3 flowers per flowerpot?

Qwen2-Math 7B:

 Reasoning: Sophie would have planted 12*3 = <<12*3=36>>36 flowers in total.
### Answer: 36

Expected answer: 36

Correct? Yes

🔗 Problem

Problem: Shawn has 12 gift boxes and each box contains 6 presents inside. How many presents does Shawn have in total?

Qwen2-Math 7B:

 Reasoning: Shawn has 12*6 = <<12*6=72>>72 presents in total.
### Answer: 72

Expected answer: 72

Correct? Yes

🔗 Follow-up

Problem: What if Shawn had only 2 gift boxes instead of 12 and each box still contained 6 presents. How many presents does Shawn have in total now?

Qwen2-Math 7B:

 Reasoning: Shawn has 2*6 = <<2*6=12>>12 presents in total.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Problem

Problem: In the factory, each RoboFalcon assembler can build 8 robots per hour. How many robots can it build in 12 hours?

Qwen2-Math 7B:

 Reasoning: Each RoboFalcon assembler can build 8 robots per hour.
In 12 hours, each RoboFalcon assembler can build 8*12 = <<8*12=96>>96 robots.
### Answer: 96

Expected answer: 96

Correct? Yes

🔗 Follow-up

Problem: Suppose the RoboFalcon assembler had a minor update and the efficiency slightly reduced. Now, it can only build 6 robots per hour. How many robots can it build in 12 hours now?

Qwen2-Math 7B:

 Reasoning: Each RoboFalcon assembler can build 6 robots per hour.
In 12 hours, each RoboFalcon assembler can build 6*12 = <<6*12=72>>72 robots.
### Answer: 72

Expected answer: 72

Correct? Yes

🔗 Problem

Problem: Tom has setup 2 tents and each tent has 8 poles. If each pole has 6 strengths attached, how many strings are there in total?

Qwen2-Math 7B:

 Reasoning: Tom has 2 tents, each with 8 poles, so there are 2*8 = <<2*8=16>>16 poles in total.
Each pole has 6 strengths attached, so there are 16*6 = <<16*6=96>>96 strings in total.
### Answer: 96

Expected answer: 96

Correct? Yes

🔗 Follow-up

Problem: Let's change the scenario a bit. What if Tom had set up only 2 tents but each tent had 3 poles instead of 8. If each pole still has 6 strings attached, how many strings are there in total now?

Qwen2-Math 7B:

 Reasoning: Tom has 2 tents, each with 3 poles, so there are 2*3 = <<2*3=6>>6 poles in total.
Each pole has 6 strings attached, so there are 6*6 = <<6*6=36>>36 strings in total.
### Answer: 36

Expected answer: 36

Correct? Yes

🔗 Problem

Problem: Jane received a set of 10 camera filters as a gift. She decided to equally distribute these between her 5 cameras. How many filters would each camera get?

Qwen2-Math 7B:

 Reasoning: Jane would distribute the filters equally among her 5 cameras, so each camera would get 10/5 = <<10/5=2>>2 filters.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Follow-up

Problem: In retrospect, Jane realized that she had initially given 6 filters to each camera instead of 10. If she continued to distribute the filters equally between her 5 cameras, how many filters would each camera get initially?

Qwen2-Math 7B:

 Reasoning: Jane initially had 10 filters per camera, but she realized she had given 6 filters to each camera instead. Therefore, she had 10 - 6 = <<10-6=4>>4 filters left.
She would then distribute these remaining 4 filters equally among her 5 cameras, so each camera would get 4/5 = <<4/5=0.8>>0.8 filters.
### Answer: 0.8

Expected answer: 6/5

Correct? No

🔗 Problem

Problem: An elephant takes 1 hour to drink 1 gallon of water. If the elephant spends 1 hour by the waterhole, how many gallons of water did the elephant drink?

Qwen2-Math 7B:

 Reasoning: The elephant drinks 1 gallon of water in 1 hour.
The elephant spends 1 hour by the waterhole.
Therefore, the elephant drinks 1 gallon of water.
### Answer: 1

Expected answer: 1

Correct? Yes

🔗 Follow-up

Problem: Given that each gallon of water weighs approximately 1 pound, if the elephant drank 1 gallon of water, how many pounds did the elephant gain from drinking?

Qwen2-Math 7B:

 Reasoning: Each gallon of water weighs approximately 1 pound.
The elephant drank 1 gallon of water.
Therefore, the elephant gained 1 pound from drinking.
### Answer: 1

Expected answer: 1

Correct? Yes

🔗 Follow-up

Problem: If instead of spending 1 hour by the waterhole, the elephant spent 5 hours there, how many gallons of water would the elephant have drank?

Qwen2-Math 7B:

 Reasoning: The elephant drinks 1 gallon of water in 1 hour.
The elephant spends 5 hours by the waterhole.
Therefore, the elephant drinks 5 gallons of water.
### Answer: 5

Expected answer: 5

Correct? Yes

🔗 Problem

Problem: If one gallon of milk can fill up 2 large containers, how many gallons of milk will be needed to fill 4 large containers?

Qwen2-Math 7B:

 Reasoning: If one gallon of milk can fill up 2 large containers, then 4 large containers will require 4/2 = <<4/2=2>>2 gallons of milk.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Follow-up

Problem: Now, instead of having 4 large containers to fill with milk, imagine if we had 11 containers instead. Given the same rate of 2 containers per gallon, how many gallons of milk will we need to fill all 11 containers?

Qwen2-Math 7B:

 Reasoning: If 2 containers require 1 gallon of milk, then 11 containers will require 11/2 = <<11/2=5.5>>5.5 gallons of milk.
### Answer: 5.5

Expected answer: 11/2

Correct? Yes

🔗 Problem

Problem: Eddy the pirate has 3 pieces of gold. For every gold coin he has, he gets a matching emerald from the captain. How many emeralds does Eddy have now?

Qwen2-Math 7B:

 Reasoning: Eddy has 3 gold coins, and for each gold coin, he gets a matching emerald. Therefore, Eddy has 3 emeralds.
### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: Eddy was very happy with his emerald collection. Seeing this, the captain decided to award him with 4 rubies for each emerald he had. How many rubies did Eddy get from the captain?

Qwen2-Math 7B:

 Reasoning: Eddy has 3 emeralds, and for each emerald, he gets 4 rubies. Therefore, Eddy gets 3*4 = <<3*4=12>>12 rubies from the captain.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Problem

Problem: A dolphin can jump 20 feet above water. Given that every 10 feet is considered a level, what level does the dolphin reach when it jumps?

Qwen2-Math 7B:

 Reasoning: The dolphin reaches the first level when it jumps 10 feet above the water. Since the dolphin can jump 20 feet above water, it reaches the second level.
### Answer: 2

Expected answer: 2

Correct? Yes

🔗 Follow-up

Problem: After observing the dolphin's jumping level, researchers discovered that dolphins can increase their jump level by 11 times when aided by a strong wave. What would be the dolphin's level if it gets help from a strong wave?

Qwen2-Math 7B:

 Reasoning: The dolphin can jump 20 feet above water, and with a strong wave, it can increase its jump level by 11 times. Therefore, the dolphin's level would be 20 * 11 = <<20*11=220>>220 feet.
### Answer: 220

Expected answer: 22

Correct? No

🔗 Follow-up

Problem: In light winds, the jumping level of the dolphin decreases to 20 feet instead of the usual 20 feet per level. Given that every 11 feet is still considered a level, what level does the dolphin now reach when it jumps in light winds?

Qwen2-Math 7B:

 Reasoning: The dolphin reaches the first level when it jumps 11 feet above the water. Since the dolphin can jump 20 feet above water, it reaches the second level.
### Answer: 2

Expected answer: 20/11

Correct? No

🔗 Problem

Problem: Jill has 28 balls which she wants to distribute equally among her 7 friends. How many balls will each friend get?

Qwen2-Math 7B:

 Reasoning: Jill has 28/7 = <<28/7=4>>4 balls to distribute to each friend.
Each friend will get 4 balls.
### Answer: 4

Expected answer: 4

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, Jill divided her 28 balls equally among her 7 friends. But what if Jill decided to divide the 28 balls equally among 10 friends instead? How many balls will each friend get then?

Qwen2-Math 7B:

 Reasoning: Jill has 28/10 = <<28/10=2.8>>2.8 balls to distribute to each friend.
Since Jill cannot distribute a fraction of a ball, she will give 2 balls to each friend and have 8 balls left over.
### Answer: 2 balls per friend, with 8 balls left over.

Expected answer: 14/5

Correct? No

🔗 Problem

Problem: In a robotic factory, there are 8 machines on the assembly line. Each of these machines can manufacture the same number of robots per day as there are machines. How many robots can the entire factory produce in one day?

Qwen2-Math 7B:

 Reasoning: Each machine can manufacture 8 robots per day.
The entire factory can produce 8*8 = <<8*8=64>>64 robots in one day.
### Answer: 64

Expected answer: 64

Correct? Yes

🔗 Follow-up

Problem: After assessing the weekly production, the robotic factory's management decided to replace one of the machines with a maintenance station, bringing the total number of machines down to 7. Now, if each of these 7 machines can manufacture the same number of robots per day as there are machines, how many robots would the factory produce in a day?

Qwen2-Math 7B:

 Reasoning: Each machine can manufacture 7 robots per day.
The entire factory can produce 7*7 = <<7*7=49>>49 robots in one day.
### Answer: 49

Expected answer: 49

Correct? Yes

🔗 Problem

Problem: In a geometry class, Maya was given a task to divide a line segment into smaller segments. Initially, the line segment was 15 cm long. She decided to cut it into equal parts each 5 cm long. How many segments did Maya get in the end?

Qwen2-Math 7B:

 Reasoning: Maya divided the 15 cm line segment into smaller segments each 5 cm long. To find out how many segments she got, we divide the total length of the line segment by the length of each segment.
15 cm / 5 cm = <<15/5=3>>3 segments.
### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: Maya realized that if she had divided the original 15 cm line segment into 7 cm pieces, the number of segments would have been different. If she cut the 15 cm line into equal pieces of 7 cm each, how many segments would she have obtained then?

Qwen2-Math 7B:

 Reasoning: If Maya had divided the 15 cm line segment into 7 cm pieces, we would calculate the number of segments by dividing the total length of the line segment by the length of each segment.
15 cm / 7 cm = <<15/7=2.14>>2.14 segments.
However, since we cannot have a fraction of a segment, Maya would have obtained 2 segments with a remaining piece that is less than 7 cm.
### Answer: 2

Expected answer: 15/7

Correct? No

🔗 Problem

Problem: Tommy has 5 types of cheese. He multiplies this by 5 to provide variety on his cheese platter for a party. How many types of cheese does Tommy have for his cheese platter now?

Qwen2-Math 7B:

 Reasoning: Tommy has 5*5 = <<5*5=25>>25 types of cheese for his cheese platter now.
### Answer: 25

Expected answer: 25

Correct? Yes

🔗 Follow-up

Problem: If Tommy originally had 7 types of cheese instead of 5, and he still intended to multiply this by 5 to provide variety on his cheese platter, how many types of cheese would Tommy have for his cheese platter then?

Qwen2-Math 7B:

 Reasoning: Tommy would have 7*5 = <<7*5=35>>35 types of cheese for his cheese platter.
### Answer: 35

Expected answer: 35

Correct? Yes

🔗 Problem

Problem: The width of a river increases by 10 feet every year. After 9 years, how much has the width of the river increased?

Qwen2-Math 7B:

 Reasoning: The width of the river increases by 10 feet every year. After 9 years, the width of the river has increased by 9*10 = <<9*10=90>>90 feet.
### Answer: 90

Expected answer: 90

Correct? Yes

🔗 Follow-up

Problem: If the width of the river only increases by 10 feet every 3 years instead of every year, how much does the river's width increase after 9 years?

Qwen2-Math 7B:

 Reasoning: The width of the river increases by 10 feet every 3 years. After 9 years, the width of the river has increased by 9/3*10 = <<9/3*10=30>>30 feet.
### Answer: 30

Expected answer: 30

Correct? Yes

🔗 Problem

Problem: Jessica has a collection of stuffed animals. She currently groups them in sets of 4. If she has 20 stuffed animals in total, how many groups does she have?

Qwen2-Math 7B:

 Reasoning: Jessica has 20/4 = <<20/4=5>>5 groups of stuffed animals.
### Answer: 5

Expected answer: 5

Correct? Yes

🔗 Follow-up

Problem: Originally, Jessica decided to group her collection of 20 stuffed animals into sets of 4. But what if she had originally decided to group her stuffed animals into sets of 4, but she only had 9 stuffed animals instead of 20? How many groups would she have then?

Qwen2-Math 7B:

 Reasoning: Jessica would have 9/4 = <<9/4=2.25>>2.25 groups of stuffed animals. Since she can't have a fraction of a group, she would have 2 groups with 1 stuffed animal left over.
### Answer: 2

Expected answer: 9/4

Correct? No

🔗 Problem

Problem: Tom has a set of 5 drums. Each of the drums has a length of 8 inches. Find out, How long would it be if he put all of his drums side by side?

Qwen2-Math 7B:

 Reasoning: Tom has 5 drums, each with a length of 8 inches.
If he puts all of his drums side by side, the total length would be 5 * 8 = <<5*8=40>>40 inches.
### Answer: 40

Expected answer: 40

Correct? Yes

🔗 Follow-up

Problem: Following the last question, Tom decided to add a second row of drums beneath the first. If he maintains the same length of 8 inches per drum and the same number of 5 drums per row, how long will the two rows of drums combined be if placed side by side?

Qwen2-Math 7B:

 Reasoning: Tom has 5 drums in each row, and each drum has a length of 8 inches.
If he adds a second row of drums beneath the first, the total length would be 2 * 5 * 8 = <<2*5*8=80>>80 inches.
### Answer: 80

Expected answer: 80

Correct? Yes

🔗 Follow-up

Problem: Following the previous question, let's consider a different scenario. Suppose, initially, each of Tom's 5 drums were 11 inches long instead of 8. How long would it be if he put all of his drums side by side?

Qwen2-Math 7B:

 Reasoning: If each of Tom's 5 drums were 11 inches long, the total length would be 5 * 11 = <<5*11=55>>55 inches.
### Answer: 55

Expected answer: 55

Correct? Yes

🔗 Problem

Problem: Jack has 5 apples and decides to multiply it by 6 to get the total number of oranges he can trade them for. How many oranges can he get?

Qwen2-Math 7B:

 Reasoning: Jack can get 5*6 = <<5*6=30>>30 oranges.
### Answer: 30

Expected answer: 30

Correct? Yes

🔗 Follow-up

Problem: Now consider if Jack started with 12 apples instead of 5. He decides to multiply it by 6 again to see how many oranges he can get. How many oranges can he now get?

Qwen2-Math 7B:

 Reasoning: Jack can get 12*6 = <<12*6=72>>72 oranges.
### Answer: 72

Expected answer: 72

Correct? Yes

🔗 Problem

Problem: A set of marker pens come with 6 different colors. If a whole pack contains 72 marker pens, how many sets of different colors are there in it?

Qwen2-Math 7B:

 Reasoning: There are 72/6 = <<72/6=12>>12 sets of different colors in the pack.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Problem

Problem: A dragon guards a cave that contains 80 pieces of gold. The dragon decided to equally distribute the gold into 8 separate piles. How many pieces of gold does each pile contain?

Qwen2-Math 7B:

 Reasoning: Each pile contains 80/8 = <<80/8=10>>10 pieces of gold.
### Answer: 10

Expected answer: 10

Correct? Yes

🔗 Follow-up

Problem: After dividing the gold into 8 piles, the dragon decided to protect the most important treasure trove, which contains 4 times the number of gold pieces in each pile. How much gold is in the dragon's special pile?

Qwen2-Math 7B:

 Reasoning: The dragon's special pile contains 4*10 = <<4*10=40>>40 pieces of gold.
### Answer: 40

Expected answer: 40

Correct? Yes

🔗 Follow-up

Problem: Let's reconsider the original situation. Suppose the dragon initially had 80 pieces of gold but decided to divide them into 11 piles instead of 8. How many pieces of gold would each pile contain in this scenario?

Qwen2-Math 7B:

 Reasoning: If the dragon divides the 80 pieces of gold into 11 piles, each pile would contain 80/11 = <<80/11=7.272727272727273>>7.272727272727273 pieces of gold. Since we cannot have a fraction of a piece of gold, we can say that each pile would contain approximately 7 pieces of gold, with some piles having 8 pieces to account for the total of 80.
### Answer: 7 (with some piles having 8 pieces to account for the total of 80)

Expected answer: 80/11

Correct? No

🔗 Problem

Problem: John wants to divide his camping area of 44 square meters into 11 equal sections. Each of these sections would host a tent. If each tent can accommodate 12 campers, how many campers can camp in total?

Qwen2-Math 7B:

 Reasoning: John's camping area is 44 square meters, and he wants to divide it into 11 equal sections. Each section would be 44/11 = <<44/11=4>>4 square meters.
Since each tent can accommodate 12 campers, the total number of campers that can camp is 11 * 12 = <<11*12=132>>132 campers.
### Answer: 132

Expected answer: 48

Correct? No

🔗 Problem

Problem: A tiger can travel 6 miles in an hour. How far can it travel in 3 hours?

Qwen2-Math 7B:

 Reasoning: The tiger can travel 6*3 = <<6*3=18>>18 miles in 3 hours.
### Answer: 18

Expected answer: 18

Correct? Yes

🔗 Follow-up

Problem: In the previous problem we found out that a tiger can travel 6 miles in an hour. But what if the tiger could cover more ground in the same time span? If the tiger can travel 7 times as far in an hour, how far can it travel then?

Qwen2-Math 7B:

 Reasoning: If the tiger can travel 7 times as far in an hour, it can travel 7*6 = <<7*6=42>>42 miles in an hour.
### Answer: 42

Expected answer: 42

Correct? Yes

🔗 Problem

Problem: A number sets of 6 are multiplied by 7. What is the resulting product?

Qwen2-Math 7B:

 Reasoning: The resulting product is 6*7 = <<6*7=42>>42.
### Answer: 42

Expected answer: 42

Correct? Yes

🔗 Follow-up

Problem: Following the previous problem. Consider that instead of multiplying 6 sets by 7, we multiply 4 sets by 7. What is the resulting product now?

Qwen2-Math 7B:

 Reasoning: The resulting product is 4*7 = <<4*7=28>>28.
### Answer: 28

Expected answer: 28

Correct? Yes

🔗 Problem

Problem: A doctor works double shift every day. If one shift is 6 hours, for how many hours does the doctor work each day?

Qwen2-Math 7B:

 Reasoning: The doctor works 6*2 = <<6*2=12>>12 hours each day.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Follow-up

Problem: Following his extra shifts, the doctor wants to reduce his workload. He decides to work 11 hours a day instead. How many hours does he work in a two-day period now?

Qwen2-Math 7B:

 Reasoning: The doctor works 11*2 = <<11*2=22>>22 hours in a two-day period now.
### Answer: 22

Expected answer: 22

Correct? Yes

🔗 Problem

Problem: A farmer plants 6 seeds in each row of his field. If he has 11 rows total, how many seeds did he plant?

Qwen2-Math 7B:

 Reasoning: The farmer planted 6*11 = <<6*11=66>>66 seeds in total.
### Answer: 66

Expected answer: 66

Correct? Yes

🔗 Problem

Problem: Mommy has a tradition that for every month, she buys 5 new toys for her baby. If the baby is 10 months old, how many toys has Mommy bought in total?

Qwen2-Math 7B:

 Reasoning: Mommy has bought 5*10 = <<5*10=50>>50 toys in total.
### Answer: 50

Expected answer: 50

Correct? Yes

🔗 Follow-up

Problem: After reflecting on her toy buying habits, Mommy realizes that she bought too many toys in the beginning. Instead of buying 5 new toys every month for 10 months, she now remembers that there was a month when she didn't buy any toys. Therefore, she only bought 5 toys per month for 9 months. How many toys did she actually buy during that period?

Qwen2-Math 7B:

 Reasoning: Mommy bought 5*9 = <<5*9=45>>45 toys in total.
### Answer: 45

Expected answer: 45

Correct? Yes