Problem: In light of the original problem, suppose for each 1 meter of sliding, Isaac now gains 5 times the speed instead of 3 times the speed. In this case, how much speed does he gain after sliding 1 meter?

Qwen2-Math 7B:

 Reasoning: Isaac now gains 5 times the speed for each 1 meter of sliding.
If Isaac slides down 1 meter, he gains 5*1 = <<5*1=5>>5 meters per second.
### Answer: 5

Expected answer: 5

Correct? Yes

Problem: In a further experiment, a third rocket with the same mass of 8 is tested, but this time it is equipped with an improved fuel system that requires less fuel. Now, this rocket requires only 5 units of fuel per mass. How much fuel is this third rocket going to need?

Qwen2-Math 7B:

 Reasoning: The fuel needed for the rocket is 8*5 = <<8*5=40>>40.
### Answer: 40

Expected answer: 40

Correct? Yes

Problem: In addition to planting seeds in the plots, Theresa wanted to give 7 gift bags each containing as many seeds as the number she planted in each plot. How many seeds should Theresa set aside for the gift bags?

Qwen2-Math 7B:

 Reasoning: Theresa planted 8 seeds in each of the 10 plots, so she planted a total of 8*10 = <<8*10=80>>80 seeds.
She wants to give 7 gift bags, each containing 8 seeds, so she needs to set aside 7*8 = <<7*8=56>>56 seeds for the gift bags.
### Answer: 56

Expected answer: 56

Correct? Yes

Problem: In a change of plans, Theresa divided the 80 seeds evenly between only 2 plots instead of 10. This meant each plot now received a different number of seeds than before. If she later planted an extra plot with the same amount of seeds as in each of the new plots, how many seeds did she use for the extra plot?

Qwen2-Math 7B:

 Reasoning: Theresa planted 80/2 = <<80/2=40>>40 seeds in each of the 2 plots.
Since she planted an extra plot with the same amount of seeds, she used <<40>>40 seeds for the extra plot.
### Answer: 40

Expected answer: 40

Correct? Yes

Problem: Going back to the first part of the previous problem, suppose that each section of the dress actually requires 6 yards of fabric instead of 1. How many yards of fabric are needed for one section of the dress in this case?

Qwen2-Math 7B:

 Reasoning: If each section of the dress requires 6 yards of fabric, then for one section, we need 6 yards of fabric.
### Answer: 6

Expected answer: 6

Correct? Yes

Problem: Remembering his magical spell, Captain Blackbeard starts to second guess himself. What if his magical spell had only doubled the amount of treasure chests instead of tripling? How many treasure chests would be in the cave in that case, after the spell is cast?

Qwen2-Math 7B:

 Reasoning: Captain Blackbeard creates a magical spell that doubles the amount of treasure chests inside the cave.
The number of treasure chests after the spell is cast is 11*2 = <<11*2=22>>22.
### Answer: 22

Expected answer: 22

Correct? Yes

Problem: After examining his ropes, Pete figures out that he needs to use all of his rope for a project. If he combines all 4 pieces of his 8 foot long ropes, how many feet of rope will he have for his project?

Qwen2-Math 7B:

 Reasoning: Pete will have 4*8 = <<4*8=32>>32 feet of rope for his project.
### Answer: 32

Expected answer: 32

Correct? Yes

Problem: Upon rechecking his inventory, Pete realizes he actually has 12 pieces of rope not 4. If each of these 12 ropes are 8 feet each, how much total length of rope does Pete have now?

Qwen2-Math 7B:

 Reasoning: Pete has 12*8 = <<12*8=96>>96 feet of rope in total.
### Answer: 96

Expected answer: 96

Correct? Yes

Problem: Earlier, we learned the Marine Institute distributed 81 starfish equally across 9 tanks. But what if they had only 12 starfish instead? How many starfish would equal distribution across the 9 tanks result in then?

Qwen2-Math 7B:

 Reasoning: If there are 12 starfish, then each tank would have 12/9 = <<12/9=1.3333333333333333>>1.3333333333333333 starfish. Since we can't have a fraction of a starfish, we can say that each tank would have 1 starfish, and there would be 3 starfish left over.
### Answer: 1 starfish per tank, with 3 starfish left over.

Expected answer: 4/3

Correct? No

Problem: Given that the robot processed information to match the system's speed, it needed to multiply this new processing speed by itself to calculate its efficiency rate. What is the robot's efficiency rate?

Qwen2-Math 7B:

 Reasoning: The robot's efficiency rate is 1*1 = <<1*1=1>>1.
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: If the robot's processing speed were slightly faster and instead was able to process information in 12 microseconds which still needed to be divided by 11 to match the system's speed, how quickly could the robot process information to match the system's speed then?

Qwen2-Math 7B:

 Reasoning: The robot can process information in 12/11 = <<12/11=1.0909090909090908>>1.0909090909090908 microseconds to match the system's speed.
### Answer: 1.0909090909090908

Expected answer: 12/11

Correct? Yes

Problem: Each of these tomatoes will produce 3 new seeds of its own. Using all the seeds from the tomatoes that Nina grows, how many new tomato plants could she potentially grow?

Qwen2-Math 7B:

 Reasoning: If each tomato will produce 3 new seeds, then 18 tomatoes will produce 18*3 = <<18*3=54>>54 new seeds.
Nina could potentially grow 54 new tomato plants.
### Answer: 54

Expected answer: 54

Correct? Yes

Problem: In the above problem, the alien learned another new word. If they transmit each word 11 times per minute and the alien can now transmit two words, how many transmissions will the alien be able to make after 1 minute?

Qwen2-Math 7B:

 Reasoning: The alien can transmit 11 words per minute.
After 1 minute, the alien will be able to transmit 11*2 = <<11*2=22>>22 words.
### Answer: 22

Expected answer: 22

Correct? Yes

Problem: In the previous problem, instead of transmitting each word 11 times per minute, suppose the alien can only transmit each word 3 times per minute. How many transmissions will the alien be able to make after 1 minute if they learn a new word?

Qwen2-Math 7B:

 Reasoning: The alien can transmit 3 words per minute.
After 1 minute, the alien will be able to transmit 3*1 = <<3*1=3>>3 words.
### Answer: 3

Expected answer: 3

Correct? Yes

Problem: If the unicorn maintains the same speed, how many miles would it travel in 3 hours?

Qwen2-Math 7B:

 Reasoning: If the unicorn maintains the same speed, it would travel 5*3 = <<5*3=15>>15 miles in 3 hours.
### Answer: 15

Expected answer: 15

Correct? Yes

Problem: If instead the unicorn traveled 35 miles in 2 hours, how many miles would the unicorn travel in one hour?

Qwen2-Math 7B:

 Reasoning: The unicorn travels 35/2 = <<35/2=17.5>>17.5 miles in one hour.
### Answer: 17.5

Expected answer: 35/2

Correct? Yes

Problem: Following from the previous problem, suppose Spectra, another superhero, has 5 times the strength of Jetstream. What is the strength of Spectra?

Qwen2-Math 7B:

 Reasoning: From the previous problem, we know that Jetstream's strength is 15G.
Since Spectra has 5 times the strength of Jetstream, Spectra's strength is 5 * 15G = <<5*15=75>>75G.
### Answer: 75G

Expected answer: 75

Correct? Yes

Problem: Jason had made one necklace requiring 6 beads, but now he wants to make a total of 3 necklaces. How many beads will he need in total to make these 3 necklaces?

Qwen2-Math 7B:

 Reasoning: Jason needs 6 beads for each necklace. For 3 necklaces, he will need 6*3 = <<6*3=18>>18 beads in total.
### Answer: 18

Expected answer: 18

Correct? Yes

Problem: In the original problem, Jason made one necklace using 6 beads. But what if he wanted to use a new design that requires 8 times as many beads as his original design? How many beads would Jason need to create this new necklace?

Qwen2-Math 7B:

 Reasoning: If Jason's original design required 6 beads, then the new design would require 6 * 8 = <<6*8=48>>48 beads.
### Answer: 48

Expected answer: 48

Correct? Yes

Problem: After successfully unlocking the puzzle box with the code obtained by multiplying 2 by 3, a new challenge appears on the screen inside the box. It tells you to multiply the previous code by 12 to get the final secret code to complete the puzzle. What is the final code?

Qwen2-Math 7B:

 Reasoning: The final code is 6*12 = <<6*12=72>>72.
### Answer: 72

Expected answer: 72

Correct? Yes

Problem: After completing the previous challenge, another puzzle appears on the next screen inside the box. It instructs you to multiply 2 by 7 instead of 3. What number will you get by following this new instruction for the puzzle?

Qwen2-Math 7B:

 Reasoning: The number you will get by following the new instruction is 2*7 = <<2*7=14>>14.
### Answer: 14

Expected answer: 14

Correct? Yes

Problem: If Peter then puts all of the money from the one wallet into a piggy bank, how much money will be in the piggy bank?

Qwen2-Math 7B:

 Reasoning: Peter has 54 dollars in one wallet. If he puts all of the money from the one wallet into a piggy bank, the total amount of money in the piggy bank will be 54 dollars.
### Answer: 54

Expected answer: 54

Correct? Yes

Problem: If Peter originally had 12 dollars in each of the 6 wallets instead of 9, how much money would be in the one wallet then?

Qwen2-Math 7B:

 Reasoning: If Peter originally had 12 dollars in each of the 6 wallets, the total amount of money in one wallet would be 6*12 = <<6*12=72>>72 dollars.
### Answer: 72

Expected answer: 72

Correct? Yes

Problem: Now consider that the butterfly only flaps its wings 9 times in one second. How many times would it flap its wings in 4 seconds?

Qwen2-Math 7B:

 Reasoning: The butterfly flaps its wings 9 times in one second.
In 4 seconds, the butterfly flaps its wings 9*4 = <<9*4=36>>36 times.
### Answer: 36

Expected answer: 36

Correct? Yes

Problem: If the plane's speed was instead 11 miles per minute, how many miles would the plane cover in the same time period of 6 minutes?

Qwen2-Math 7B:

 Reasoning: The plane would cover 11*6 = <<11*6=66>>66 miles in 6 minutes.
### Answer: 66

Expected answer: 66

Correct? Yes

Problem: In a different scenario, Josephine originally had 9 pairs of ice skates instead of 27 that she wanted to distribute equally among the 9 stores. How many pairs of ice skates would each store receive in this case?

Qwen2-Math 7B:

 Reasoning: Josephine will give 9/9 = <<9/9=1>>1 pair of ice skates to each store.
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: Billy decides to double his collection of kites. After doubling the initial amount, how many kites will he have in total?

Qwen2-Math 7B:

 Reasoning: Billy has 27*2 = <<27*2=54>>54 kites after doubling his collection.
### Answer: 54

Expected answer: 54

Correct? Yes

Problem: Billy initially thought he had 9 sets of kites, but he actually had 11 sets. Given that each set contains 9 kites, how many kites does he really have in total?

Qwen2-Math 7B:

 Reasoning: Billy has 11*9 = <<11*9=99>>99 kites in total.
### Answer: 99

Expected answer: 99

Correct? Yes

Problem: Continuing the fairy tale, the magical creature took the outcome from her previous spell and multiplied it by 5. What is the new number after this spell?

Qwen2-Math 7B:

 Reasoning: The magical creature multiplies the outcome 16 by 5, which is 16*5 = <<16*5=80>>80.
The new number after the spell is 80.
### Answer: 80

Expected answer: 80

Correct? Yes

Problem: Continuing the magical story, suppose the magical creature had initially started with the number 11 instead of 4, and had multiplied this number by 4. What would have been the outcome of the first spell in that case?

Qwen2-Math 7B:

 Reasoning: The magical creature multiplies the number 11 by 4, which is 11*4 = <<11*4=44>>44.
The outcome of the first spell would have been 44.
### Answer: 44

Expected answer: 44

Correct? Yes

Problem: At first, there were 12 rooms instead of 3 to distribute the 27 chairs into. How many chairs would each room have in this case?

Qwen2-Math 7B:

 Reasoning: There are 27/12 = <<27/12=2.25>>2.25 chairs in each room.
### Answer: 2.25

Expected answer: 9/4

Correct? Yes

Problem: Now, imagine if the store decided to stock only one toy car per shelf instead, distributing 8 toy cars uniformly over 8 shelves. How many toy cars would be there per shelf?

Qwen2-Math 7B:

 Reasoning: If the store decides to stock only one toy car per shelf, then there would be 8/8 = <<8/8=1>>1 toy car per shelf.
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: In addition to the 3 pizzas, the restaurant also wants to make a special pizza that takes the same amount of time as the 3 pizzas combined. How long will it take to make the special pizza?

Qwen2-Math 7B:

 Reasoning: It will take 54 minutes to make the special pizza.
### Answer: 54

Expected answer: 54

Correct? Yes

Problem: The restaurant has revised its pizza cooking time. Now, each slice of pizza takes only 1 minute to cook but a full pizza still has 3 slices. Now, how long will it take to make 3 full pizzas?

Qwen2-Math 7B:

 Reasoning: It will take 3*1 = <<3*1=3>>3 minutes to cook one pizza.
It will take 3*3 = <<3*3=9>>9 minutes to cook 3 pizzas.
### Answer: 9

Expected answer: 9

Correct? Yes

Problem: Considering the previous problem, what if Arthur only drove his car for 2 hours each day for that same 4-day period? How many total hours did Arthur spend driving his car over this period?

Qwen2-Math 7B:

 Reasoning: Arthur drove for 2*4 = <<2*4=8>>8 hours over this period.
### Answer: 8

Expected answer: 8

Correct? Yes

Problem: Following the previous problem, if you were given the task to make two blankets with the same size and design, how many yards of yarn would you need in total?

Qwen2-Math 7B:

 Reasoning: If you were given the task to make two blankets with the same size and design, you would need twice the amount of yarn needed for one blanket. Therefore, the total amount of yarn needed for two blankets is 30*2 = <<30*2=60>>60 yards.
### Answer: 60

Expected answer: 60

Correct? Yes

Problem: Following the initial problem, consider if each blanket requires six yards of yarn for just one section, but the new design demands that a blanket is made up of 12 such sections. How many yards of yarn would you now need to create one blanket with this new design?

Qwen2-Math 7B:

 Reasoning: Each blanket requires 6 yards of yarn for one section, and each finished blanket is made up of 12 such sections. Therefore, the total amount of yarn needed for one blanket is 6*12 = <<6*12=72>>72 yards.
### Answer: 72

Expected answer: 72

Correct? Yes

Problem: Following the previous scenario, consider that the bus was actually traveling at a speed of 10 miles per hour, not 7. How many miles would the bus have travelled after 6 hours in this case?

Qwen2-Math 7B:

 Reasoning: The bus travels 10 miles per hour. After 6 hours, the bus will travel 10*6 = <<10*6=60>>60 miles.
### Answer: 60

Expected answer: 60

Correct? Yes

Problem: Superhero Starlight, after completing her special power-up training, can now increase her initial power level by three times. If her initial power level was the product of multiplying 3 by 5, what is her new power level after the power-up training?

Qwen2-Math 7B:

 Reasoning: Starlight's initial power level is 3*5 = <<3*5=15>>15.
After the power-up training, her power level is 15*3 = <<15*3=45>>45.
### Answer: 45

Expected answer: 45

Correct? Yes

Problem: Considering that Superhero Starlight initially had a power level that was the product of multiplying 3 by 5, let's imagine if her initial power level was actually the product of multiplying 3 by 6. What would her initial power level be in this scenario?

Qwen2-Math 7B:

 Reasoning: Starlight's initial power level would be 3*6 = <<3*6=18>>18.
### Answer: 18

Expected answer: 18

Correct? Yes

Problem: Now consider that Jessica has another backpack, this one has a side that measures 4 inches. What is the area of one side of this backpack, again assuming it is a perfect square?

Qwen2-Math 7B:

 Reasoning: The area of a square is calculated by squaring the length of one side. Since the side of Jessica's second backpack is 4 inches, the area of one side is 4 inches * 4 inches = <<4*4=16>>16 square inches.
### Answer: 16

Expected answer: 16

Correct? Yes

Problem: Suppose Captain Sparrow had initially found 36 gold doubloons, but this time he wants to divide them equally among 7 crew members, not 3. How many gold doubloons will each crew member get now?

Qwen2-Math 7B:

 Reasoning: Captain Sparrow will divide the 36 gold doubloons equally among his 7 crew members, so each crew member will get 36/7 = <<36/7=5.142857142857143>>5.142857142857143 gold doubloons.
Since we can't have a fraction of a gold doubloon, we round down to the nearest whole number. Each crew member will get 5 gold doubloons, and there will be 1 gold doubloon left over.
### Answer: 5

Expected answer: 36/7

Correct? No

Problem: In the previous problem, the robot factory increased its output to twice its original amount, making 10 robots each hour. If the factory were to then multiply this new hourly output by the same amount they were originally making each hour (5 robots), how many robots would the factory make every hour?

Qwen2-Math 7B:

 Reasoning: The factory would make 10*5 = <<10*5=50>>50 robots each hour.
### Answer: 50

Expected answer: 50

Correct? Yes

Problem: In the previous problem, the robot factory was originally making 5 robots each hour. However, if the factory were to increase its output to six times the original amount instead, how many robots would it produce each hour?

Qwen2-Math 7B:

 Reasoning: The factory will produce 5*6 = <<5*6=30>>30 robots each hour.
### Answer: 30

Expected answer: 30

Correct? Yes

Problem: If one bike wheel still has a radius of 81/9 units, but now the height of a certain bike rack is only 6 times this radius, what is the height of the bike rack?

Qwen2-Math 7B:

 Reasoning: The radius of the bike wheel is 81 / 9 = <<81 / 9=9>>9 units.
The height of the bike rack is 6 times this radius, so the height of the bike rack is 6 * 9 = <<6 * 9=54>>54 units.
### Answer: 54

Expected answer: 54

Correct? Yes

Problem: Following on from the previous problem, if Jamie continued swinging at the same pace for 3 more minutes, how many times would he have swung in total over those extra minutes?

Qwen2-Math 7B:

 Reasoning: Jamie swung 11 times in every minute and he spent 3 minutes swinging.
Jamie swung 11*3 = <<11*3=33>>33 times in total over those extra minutes.
### Answer: 33

Expected answer: 33

Correct? Yes

Problem: After his first session, Jamie took a break and then returned to the swing. This second time, he swung 6 times per minute for one minute. How many times did he swing in that minute?

Qwen2-Math 7B:

 Reasoning: Jamie swung 6 times per minute for one minute.
Jamie swung 6*1 = <<6*1=6>>6 times in that minute.
### Answer: 6

Expected answer: 6

Correct? Yes

Problem: Let's say instead of initially having 9 robot toys and buying the same amount again, James originally had 9 robot toys, but this time, he decided to buy 5 more sets of 9 toys each. How many robot toys does James have now?

Qwen2-Math 7B:

 Reasoning: James originally had 9 robot toys. He bought 5 more sets of 9 toys each, which is 5 * 9 = <<5*9=45>>45 toys. Therefore, James now has 9 + 45 = <<9+45=54>>54 robot toys.
### Answer: 54

Expected answer: 54

Correct? Yes

Problem: The farmer from the previous problem sells each egg for 1 dollar. How much money does the farmer make in a week by selling all the eggs?

Qwen2-Math 7B:

 Reasoning: The farmer makes 77*1 = <<77*1=77>>77 dollars in a week by selling all the eggs.
### Answer: 77

Expected answer: 77

Correct? Yes

Problem: In the previous problem, if the farmer only had 2 chickens instead of 11, and each chicken still lays 7 eggs in a week, how many eggs would the chickens lay in total in a week?

Qwen2-Math 7B:

 Reasoning: The chickens lay 2*7 = <<2*7=14>>14 eggs in total in a week.
### Answer: 14

Expected answer: 14

Correct? Yes

Problem: The enchanted tree that has been growing in the forest doesn't stop there. Overnight, it grows half of its daily growth rate, which is 4 cm. If this overnight height is multiplied by 10, how long is the final growth of the tree over these 10 nights?

Qwen2-Math 7B:

 Reasoning: The tree grows 4/2 = <<4/2=2>>2 centimeters overnight.
Over 10 nights, the tree grows 2*10 = <<2*10=20>>20 centimeters.
### Answer: 20

Expected answer: 20

Correct? Yes

Problem: The enchanted tree that was previously growing at an overnight rate of 4 cm changes its growth pattern. Now, it starts to grow at a rate of 10 centimeters each day, but it still grows only half of this amount each night. How many centimeters does the tree now grow overnight?

Qwen2-Math 7B:

 Reasoning: The tree now grows 10/2 = <<10/2=5>>5 centimeters overnight.
### Answer: 5

Expected answer: 5

Correct? Yes

Problem: After having divided the mice among the 11 cages, the scientist realized that she made a mistake and originally there were only 77 mice but some of them were counted twice. After correcting for this mistake, she realized that she actually only had 77 / 2 mice. How many mice did the scientist have originally?

Qwen2-Math 7B:

 Reasoning: 77/2 = <<77/2=38.5>>38.5 mice.
Since the number of mice must be a whole number, the scientist originally had 38 mice.
### Answer: 38

Expected answer: 77/2

Correct? No

Problem: Sally realizes that she made a mistake in her calculations for making earrings. Instead of needing 35 beads for a set of earrings, she only needs 35 beads for a display of five earrings. Therefore, she recalculates and finds that to make each earring she only needs to divide this new amount by five. If she wants to make just 2 earrings, how many beads will she need now?

Qwen2-Math 7B:

 Reasoning: Sally now needs 35/5 = <<35/5=7>>7 beads for each earring.
For 2 earrings, she will need 7*2 = <<7*2=14>>14 beads in total.
### Answer: 14

Expected answer: 14

Correct? Yes

Problem: In a new scenario, Brenda has 9 apples but this time she only wants to divide them evenly among her 2 closest friends. Given this change, how many apples will each friend receive now?

Qwen2-Math 7B:

 Reasoning: Brenda has 9 apples and 2 friends, so each friend will get 9/2 = <<9/2=4.5>>4.5 apples.
### Answer: 4.5

Expected answer: 9/2

Correct? Yes

Problem: After completing his daring stunt, the tightrope walker decides to challenge himself further and wants to perform the same stunt on a tightrope that's only 1 foot off the ground. Now, how far would he need to walk considering the tightrope is still five times the height above the ground?

Qwen2-Math 7B:

 Reasoning: The tightrope is 5 times the height above the ground, so it is 5*1 = <<5*1=5>>5 feet off the ground. The stuntman needs to walk the length of the tightrope, which is 5 feet.
### Answer: 5

Expected answer: 5

Correct? Yes

Problem: The length of one side of a square is equal to the result of dividing 30 by 6. The total area of the square is found by multiplying the length of one side by itself. Now, if we multiply this area by 3, what will be the new value?

Qwen2-Math 7B:

 Reasoning: The length of one side of the square is 30/6 = <<30/6=5>>5.
The total area of the square is 5*5 = <<5*5=25>>25.
If we multiply this area by 3, the new value will be 25*3 = <<25*3=75>>75.
### Answer: 75

Expected answer: 75

Correct? Yes

Problem: In the original problem, the length of one side of the square was found by dividing 30 by 6. Now consider a new scenario where the length of the square is instead found by dividing number 12 by 6. What would be the total area of this new square?

Qwen2-Math 7B:

 Reasoning: The length of one side of the new square is 12/6 = <<12/6=2>>2.
The total area of the new square is 2*2 = <<2*2=4>>4.
### Answer: 4

Expected answer: 4

Correct? Yes

Problem: If the first star, instead of emitting particles for 8 seconds, only emits particles for 5 seconds, how many particles will then it emit?

Qwen2-Math 7B:

 Reasoning: The star emits 7*5 = <<7*5=35>>35 particles in total.
### Answer: 35

Expected answer: 35

Correct? Yes

Problem: The shoe factory increased its production time from five hours to ten hours. Now, how many shoes will the factory produce if it's still able to create 24 shoes every three hours?

Qwen2-Math 7B:

 Reasoning: The factory produces 24/3 = <<24/3=8>>8 shoes per hour.
In ten hours, the factory will produce 10*8 = <<10*8=80>>80 shoes.
### Answer: 80

Expected answer: 80

Correct? Yes

Problem: Considering the same unique species of butterfly, but now in a different region it only lives for 5 days each week instead of per month. How many days total does the butterfly species live in a 7-week span?

Qwen2-Math 7B:

 Reasoning: The butterfly species lives for 5 days in each week, and there are 7 weeks in a 7-week span.
Therefore, the butterfly species lives for 5*7 = <<5*7=35>>35 days in a 7-week span.
### Answer: 35

Expected answer: 35

Correct? Yes

Problem: In fairy land, change the original number of fairies an ordinary mushroom can feed from 10 to 11. With this change, how many fairies can a magic mushroom, which can provide food as 4 ordinary mushrooms, feed for a day?

Qwen2-Math 7B:

 Reasoning: If one ordinary mushroom provides food for 11 fairies for a day, then 4 ordinary mushrooms can provide food for 4*11 = <<4*11=44>>44 fairies for a day.
Since a magic mushroom can provide food as 4 ordinary mushrooms, a magic mushroom can feed 44 fairies for a day.
### Answer: 44

Expected answer: 44

Correct? Yes

Problem: If the speed of the river were instead 4 kilometers per hour for 2 hours, how far would the river flow within these 2 hours?

Qwen2-Math 7B:

 Reasoning: The river can flow 4*2 = <<4*2=8>>8 kilometers in 2 hours.
### Answer: 8

Expected answer: 8

Correct? Yes

Problem: Following up on the last problem: If Ava decides to triple the height of the slide that is double her height, how high will the new slide be?

Qwen2-Math 7B:

 Reasoning: The original slide is 24 feet tall. If Ava triples the height of the slide, the new height will be 24*3 = <<24*3=72>>72 feet.
### Answer: 72

Expected answer: 72

Correct? Yes

Problem: In the previous problem, Ava was initially considering a slide double her height when she was 12 feet tall. However, let's say Ava is actually 11 feet tall. In that case, how high would the slide be if it was still double her height?

Qwen2-Math 7B:

 Reasoning: If Ava is 11 feet tall, the slide would be 2*11 = <<2*11=22>>22 feet tall.
### Answer: 22

Expected answer: 22

Correct? Yes

Problem: What if the tap was turned on for 7 minutes instead of 9 minutes? How much water would the tap fill in the tank in that case?

Qwen2-Math 7B:

 Reasoning: The tank will have 2*7 = <<2*7=14>>14 liters of water after 7 minutes.
### Answer: 14

Expected answer: 14

Correct? Yes

Problem: Fred received 11 letters in one week instead of 12. If he still reads them evenly over 3 days, how many letters does he read per day now?

Qwen2-Math 7B:

 Reasoning: Fred received 11/3 = <<11/3=3.6666666666666665>>3.6666666666666665 letters per day.
### Answer: 3.6666666666666665

Expected answer: 11/3

Correct? Yes

Problem: After the shifts mentioned in the previous problem, the toy car factory decides to change its production rate. Now, instead of producing 8 cars per hour as before, it produces 5 cars per hour. If the factory continues to run for 12 hours a day, how many cars will it produce in one day now?

Qwen2-Math 7B:

 Reasoning: The factory now produces 5*12 = <<5*12=60>>60 cars in one day.
### Answer: 60

Expected answer: 60

Correct? Yes

Problem: If instead Baby Lily originally got 44 toys but this time, she divided them evenly among her 11 friends, each friend would get 'i' number of toys. If we multiply 'i' by 5, how many toys would that represent?

Qwen2-Math 7B:

 Reasoning: If baby Lily got 44 toys divided evenly among her 11 friends, each friend would get 44/11 = <<44/11=4>>4 toys.
If we multiply 'i' by 5, that would represent 4*5 = <<4*5=20>>20 toys.
### Answer: 20

Expected answer: 20

Correct? Yes

Problem: If each of Mike's children decided to save the money they received from their father every month for a year, how much money would each child have saved by the end of the year?

Qwen2-Math 7B:

 Reasoning: Each child will save $3 per month for 12 months.
Each child will save $3*12 = <<3*12=36>>36.
### Answer: 36

Expected answer: 36

Correct? Yes

Problem: If Mike had $11 instead of $9 and he still decided to divide it equally among his 3 children, how much money would each child receive now?

Qwen2-Math 7B:

 Reasoning: Mike will divide $11 by 3.
Each child will recieve $11/3 = <<11/3=3.6666666666666665>>3.6666666666666665.
### Answer: 3.6666666666666665

Expected answer: 11/3

Correct? Yes

Problem: If instead the cow produced 72 liters of milk in 10 days, and you still wanted to find out how much milk it would produce in 12 days, how much would that be?

Qwen2-Math 7B:

 Reasoning: The cow produces 72/10 = <<72/10=7.2>>7.2 liters of milk in a day.
The cow will produce 7.2*12 = <<7.2*12=86.4>>86.4 liters of milk in 12 days.
### Answer: 86.4

Expected answer: 432/5

Correct? Yes

Problem: If the scale of the map is adjusted so that instead of 30 miles being represented by 10 inches, it is now represented by 12 inches, how many miles would 1 inch represent on the new map?

Qwen2-Math 7B:

 Reasoning: If 30 miles is represented by 12 inches, then 1 inch represents 30/12 = <<30/12=2.5>>2.5 miles on the new map.
### Answer: 2.5

Expected answer: 5/2

Correct? Yes

Problem: If the truck with all the tires fully loaded is carrying cargo weighing the same as the total load the tires can handle, what would be the total weight being carried by the truck?

Qwen2-Math 7B:

 Reasoning: The total weight being carried by the truck is the same as the total load the tires can handle, which is 64 tons.
### Answer: 64

Expected answer: 64

Correct? Yes

Problem: In the previous scenario, each tire was capable of carrying a load of 8 tons. But what if each tire was only capable of carrying a load of 3 tons? How much total load could the truck carry then when all tires are fully loaded?

Qwen2-Math 7B:

 Reasoning: The truck can carry a total load of 8 * 3 = <<8*3=24>>24 tons when all tires are fully loaded.
### Answer: 24

Expected answer: 24

Correct? Yes

Problem: If instead you started with just 1 fruit, how many cups of juice would you be able to make?

Qwen2-Math 7B:

 Reasoning: If you started with just 1 fruit, you would be able to make 1*1 = <<1*1=1>>1 cup of juice.
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: Sara decided to duplicate her complete set of colored pencils and she bought exactly the same amount as she had. Now, how many colored pencils does Sara have in total?

Qwen2-Math 7B:

 Reasoning: Sara has 25 colored pencils, and she duplicated her set. Therefore, Sara has 25*2 = <<25*2=50>>50 colored pencils in total.
### Answer: 50

Expected answer: 50

Correct? Yes

Problem: Sara suddenly realized that she had miscalculated; she actually has 11 of each type of colored pencil, not 5. With this correction, how many colored pencils does Sara really have?

Qwen2-Math 7B:

 Reasoning: Sara has 11 colors, and she has 11 of each type. Therefore, Sara has 11*11 = <<11*11=121>>121 colored pencils in total.
### Answer: 121

Expected answer: 55

Correct? No

Problem: You have decided to play 8 rounds of the same game. If you continue to use the same 12-letter word in each round, how many points will you accumulate in total from all the rounds?

Qwen2-Math 7B:

 Reasoning: Since each round you get 12 points, and you play 8 rounds, the total points would be 12 * 8 = <<12*8=96>>96.
### Answer: 96

Expected answer: 96

Correct? Yes

Problem: You decide to change your strategy in the next game and instead use a 9-letter word. If each letter still corresponds to 1 point, how many points will you get in this game?

Qwen2-Math 7B:

 Reasoning: Since each letter corresponds to 1 point, and the word is 9 letters long, the total points for the word would be 9 * 1 = <<9*1=9>>9.
### Answer: 9

Expected answer: 9

Correct? Yes

Problem: Jake decided to not drink any of the water just yet and stored all the bottles in his garage. After leaving the bottles in the garage untouched, how many bottles does Jake still have?

Qwen2-Math 7B:

 Reasoning: Jake still has 49 bottles of water.
### Answer: 49

Expected answer: 49

Correct? Yes

Problem: Considering from the previous question, what if each piano only had 3 legs instead of 4. With 2 pianos in the music room, how many legs would there be in total?

Qwen2-Math 7B:

 Reasoning: If each piano had 3 legs instead of 4, then there would be 3*2 = <<3*2=6>>6 legs in total.
### Answer: 6

Expected answer: 6

Correct? Yes

Problem: Following the previous scenario, if there are 11 keyrings in total, how many keys does each person get?

Qwen2-Math 7B:

 Reasoning: Each person gets 11/2 = <<11/2=5.5>>5.5 keys.
### Answer: 5.5

Expected answer: 11

Correct? No

Problem: In the previous scenario, suppose now that each keyring holds 3 keys, but still has to be split amongst two people. How many keys does each person get now?

Qwen2-Math 7B:

 Reasoning: Each person gets 3/2 = <<3/2=1.5>>1.5 keys.
### Answer: 1.5

Expected answer: 3/2

Correct? Yes

Problem: Javier decided to pack more bottles into his crates. Now, each crate contains 8 bottles instead of 6. How many bottles does Javier have now with his 9 crates?

Qwen2-Math 7B:

 Reasoning: Javier has 9*8 = <<9*8=72>>72 bottles.
### Answer: 72

Expected answer: 72

Correct? Yes

Problem: Following the previous question: if the exchange rate changes and now 1 euro equals 1 dollar, how much will the shirt cost in dollars now?

Qwen2-Math 7B:

 Reasoning: The shirt costs 10 euros, and now 1 euro equals 1 dollar. Therefore, the shirt will cost 10 dollars now.
### Answer: 10

Expected answer: 10

Correct? Yes

Problem: After the price changes, the shirt now costs 9 dollars. If 1 dollar equals 1 euro, how much does the shirt cost in euros now?

Qwen2-Math 7B:

 Reasoning: The shirt now costs 9 dollars, and 1 dollar equals 1 euro. Therefore, the shirt now costs 9 euros.
### Answer: 9

Expected answer: 9

Correct? Yes

Problem: Suppose the original size of the beach ball was actually 5 feet in diameter, not 3 feet as previously stated. If it is still being blown up to be twice its original size, what will be the diameter of the beach ball after it is blown up now?

Qwen2-Math 7B:

 Reasoning: The beach ball will be twice the size of its original size, so the diameter will be 5*2 = <<5*2=10>>10 feet.
### Answer: 10

Expected answer: 10

Correct? Yes

Problem: The farmer then decides to combine all the tomatoes from the 4 boxes back into one large container. How many tomatoes will there be in the large container?

Qwen2-Math 7B:

 Reasoning: The farmer has 4 boxes with 6 tomatoes each. To find the total number of tomatoes in the large container, we multiply the number of boxes by the number of tomatoes in each box: 4 × 6 = <<4×6=24>>24.
### Answer: 24

Expected answer: 24

Correct? Yes

Problem: In a different scenario, if the farmer had decided to equally divide the 24 tomatoes between only 2 boxes instead of 4, how many tomatoes would have been in each box then?

Qwen2-Math 7B:

 Reasoning: If the farmer divides the 24 tomatoes equally between 2 boxes, we divide the total number of tomatoes by the number of boxes: 24 ÷ 2 = <<24÷2=12>>12.
### Answer: 12

Expected answer: 12

Correct? Yes

Problem: In the previous situation, John multiplied the distance he traveled with 6. But this time, he decides to ride his scooter for a bit longer. Instead of multiplying by 6, he now multiplies the same initial half of 16, distance "B", by 8 to find out the new total distance "X" he traveled back and forth. What is the new total distance "X" he traveled?

Qwen2-Math 7B:

 Reasoning: John traveled B = <<16/2=8>>8 units.
John traveled X = <<8*8=64>>64 units in total.
### Answer: 64

Expected answer: 64

Correct? Yes

Problem: Now, imagine Lisa spent 5 days over the course of a week doing the same routine of watching 2 episodes back-to-back of her favorite TV show, which is 8 minutes per episode. How long in total did she spend watching her TV show over those 5 days?

Qwen2-Math 7B:

 Reasoning: If Lisa watches 2 episodes back-to-back, she will be watching for 8*2 = <<8*2=16>>16 minutes in total per day.
Over 5 days, she will be watching for 16*5 = <<16*5=80>>80 minutes in total.
### Answer: 80

Expected answer: 80

Correct? Yes

Problem: In a twist, one day Lisa decided to watch a different TV show, which is 12 minutes long per episode. If she watches 2 episodes of this show back-to-back without any breaks, how long will she be watching this different TV show in total?

Qwen2-Math 7B:

 Reasoning: If Lisa watches 2 episodes of the different TV show back-to-back, she will be watching for 12*2 = <<12*2=24>>24 minutes in total.
### Answer: 24

Expected answer: 24

Correct? Yes

Problem: Consider the starting point of the previous problem where Jane had 1 blanket and John had 3 times as many blankets as Jane. Now, suppose that Jane initially has 6 blankets instead of 1. In this new scenario, how many blankets does John have initially?

Qwen2-Math 7B:

 Reasoning: In the new scenario, Jane has 6 blankets. Since John has 3 times as many blankets as Jane, John has 6*3 = <<6*3=18>>18 blankets.
### Answer: 18

Expected answer: 18

Correct? Yes

Problem: If John originally had $10 instead of $28, and he still wanted to divide it equally among his 7 children, how much would each child receive now?

Qwen2-Math 7B:

 Reasoning: John will divide $10 by 7 to find the amount each child will receive.
$10/7 = <<10/7=1.42857142857>>1.42857142857
Each child will receive approximately $1.43.
### Answer: 1.43

Expected answer: 10/7

Correct? No

Problem: Continuing from the previous situation, after selling 1 scooter a day for 8 days, Kate decides to hold a grand sale for 8 more days where she sells the same number of scooters she sold in the previous 8 days every day. How many additional scooters will she sell during this grand sale?

Qwen2-Math 7B:

 Reasoning: Kate sells 1 scooter every day.
During the grand sale, she will sell 1*8 = <<1*8=8>>8 scooters every day.
Over 8 days, she will sell 8*8 = <<8*8=64>>64 additional scooters.
### Answer: 64

Expected answer: 64

Correct? Yes

Problem: Let's revise the original situation. Instead of selling 1 scooter a day, let's say Kate was actually selling 7 scooters a day for 8 days. How many scooters did she sell in this period?

Qwen2-Math 7B:

 Reasoning: Kate sells 7 scooters every day.
After 8 days, Kate will sell 7*8 = <<7*8=56>>56 scooters.
### Answer: 56

Expected answer: 56

Correct? Yes

Problem: Now imagine that the tree actually produces 12 seeds each year instead of 10. How many seeds does the tree produce in 1 year?

Qwen2-Math 7B:

 Reasoning: The tree produces 12 seeds each year.
### Answer: 12

Expected answer: 12

Correct? Yes

Problem: Following the same scenario where the friends were divided into groups, if each group decided to buy 7 pizzas, how many pizzas would be bought in total?

Qwen2-Math 7B:

 Reasoning: To find the total number of pizzas, we multiply the number of groups by the number of pizzas each group buys.
4*7 = <<4*7=28>>28
There will be 28 pizzas bought in total.
### Answer: 28

Expected answer: 28

Correct? Yes

Problem: Continuing from our previous scenario, let's say that instead of having 12 friends, there were actually only 6 friends to begin with. If they still want to divide themselves into groups with 3 friends each, how many group will there be?

Qwen2-Math 7B:

 Reasoning: To find the number of groups, we divide the total number of friends by the number of friends in each group.
6/3 = <<6/3=2>>2
There will be 2 groups.
### Answer: 2

Expected answer: 2

Correct? Yes

Problem: Continuing from the previous situation, Emma and her friends decide to make their sandcastles stronger. They pour a layer of seawater on each shovel used in their sandcastles. If each shovel full of sand requires 1 bottle of seawater, how many bottles of seawater will they need in total?

Qwen2-Math 7B:

 Reasoning: Emma and her friends use 72 shovels of sand in total.
They will need 72 bottles of seawater in total.
### Answer: 72

Expected answer: 72

Correct? Yes

Problem: Following the previous situation with Emma and her friends building sandcastles, imagine that they had originally started with 5 sandcastles instead of 6. Each of these 5 sandcastles still uses 4 buckets of sand and each of these buckets contains 3 shovels of sand. How many shovels of sand would they have used then?

Qwen2-Math 7B:

 Reasoning: Emma and her friends would have used 5*4 = <<5*4=20>>20 buckets of sand in total.
They would have used 20*3 = <<20*3=60>>60 shovels of sand in total.
### Answer: 60

Expected answer: 60

Correct? Yes

Problem: After reconsidering, Jenna decided to only make 7 bracelets instead of 8. Now, how many beads will Jenna need to make the bracelets?

Qwen2-Math 7B:

 Reasoning: Jenna needs 12*7 = <<12*7=84>>84 beads in total.
### Answer: 84

Expected answer: 84

Correct? Yes

Problem: If Penny started using 9 milliliters of toothpaste for each brushing instead of 11, how many times could she brush her teeth with the new tube of toothpaste?

Qwen2-Math 7B:

 Reasoning: Penny can brush her teeth 66/9 = <<66/9=7.333333333333333>>7.333333333333333 times with the new tube of toothpaste.
### Answer: 7.333333333333333

Expected answer: 22/3

Correct? Yes

Problem: If Vanessa only had 4 bunches of grapes and each bunch had 5 grapes instead of 11, how many grapes would Vanessa have in total then?

Qwen2-Math 7B:

 Reasoning: Vanessa would have 4*5 = <<4*5=20>>20 grapes in total.
### Answer: 20

Expected answer: 20

Correct? Yes

Problem: Mary used her 6 yards of fabric to make a skirt. Each skirt she makes, requires 6 yards of fabric. She decides to make as many skirts as skirts she already made (i.e., she wants to multiply the number of skirts by the number of skirts she already made). How many skirts will Mary have made in total?

Qwen2-Math 7B:

 Reasoning: Mary will have made 1*1 = <<1*1=1>>1 skirt in total.
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: Mary now has a new length of fabric that's 7 yards long. Keeping in mind that each skirt requires 6 yards of fabric, how many skirts can Mary make with the new fabric she has?

Qwen2-Math 7B:

 Reasoning: Mary can make 7/6 = <<7/6=1.1666666666666667>>1.1666666666666667 skirts with the new fabric she has.
Since Mary cannot make a fraction of a skirt, she can only make 1 skirt with the new fabric she has.
### Answer: 1

Expected answer: 7/6

Correct? No

Problem: Following up from the previous question, if Jordan decides to again double the total number of cards he has, how many cards will Jordan end up with at that point?

Qwen2-Math 7B:

 Reasoning: Jordan has 18*2 = <<18*2=36>>36 cards.
If he doubles the total number of his cards again, he will have 36*2 = <<36*2=72>>72 cards.
### Answer: 72

Expected answer: 36

Correct? No

Problem: Following up from the previous question, if originally Jordan had 5 card packs instead of 9, and he still decided to double the total number of his cards, how many cards would Jordan have then?

Qwen2-Math 7B:

 Reasoning: Jordan has 5*1 = <<5*1=5>>5 cards.
If he doubles the total number of his cards, he will have 5*2 = <<5*2=10>>10 cards.
### Answer: 10

Expected answer: 10

Correct? Yes

Problem: In the magical world, a donezal is a unit of time equal to 10 wizard staff channeling periods. If every wizard staff channeling period lasts as long as the spell in the previous problem, how much time does one donezal represent?

Qwen2-Math 7B:

 Reasoning: A donezal is equal to 10 periods of the spell, and each period lasts 10 minutes. Therefore, one donezal represents 10*10 = <<10*10=100>>100 minutes.
### Answer: 100

Expected answer: 100

Correct? Yes

Problem: In a new experiment, the wizard decided to divide the same 60-minute spell into only 4 equal periods before the wizard staff needs to take a break. How long does each period of casting last now?

Qwen2-Math 7B:

 Reasoning: The total time the spell lasts is 60 minutes. The staff can channel the spell for 4 equal periods before needing a 1-minute break. Therefore, each period of the spell is 60/4 = <<60/4=15>>15 minutes long.
### Answer: 15

Expected answer: 15

Correct? Yes

Problem: In the previous problem, the drummer was hitting his drum 11 times per minute. But what if his rhythm slows down and he now hits the drum only 2 times per minute. How many times will he hit the drum in 8 minutes then?

Qwen2-Math 7B:

 Reasoning: The drummer hits the drum 2 times per minute.
In 8 minutes, the drummer hits the drum 2*8 = <<2*8=16>>16 times.
### Answer: 16

Expected answer: 16

Correct? Yes

Problem: Now, John is reconsidering his packing strategy. Instead of packing two pairs of socks per pair of pants, he thinks he only needs to pack two socks for every pair of pants. If he sticks to this new strategy, how many pairs of pants should he pack for his 4 pairs of socks?

Qwen2-Math 7B:

 Reasoning: John needs 4/2 = <<4/2=2>>2 pairs of pants.
John should pack 2 pairs of pants.
### Answer: 2

Expected answer: 2

Correct? Yes

Problem: If, instead of 8 pens per pack, there were 6 pens per pack, how many pens would John have in total with his 5 packs?

Qwen2-Math 7B:

 Reasoning: If there were 6 pens per pack, John would have 6*5 = <<6*5=30>>30 pens in total.
### Answer: 30

Expected answer: 30

Correct? Yes

Problem: Suppose there are more guards available and Captain Blackbeard decided to split the total time into 12 shifts instead of 6. How many hours will each guard now have to protect the ship under this new arrangement?

Qwen2-Math 7B:

 Reasoning: 60/12 = <<60/12=5>>5
Each guard will now have to protect the ship for 5 hours.
### Answer: 5

Expected answer: 5

Correct? Yes

Problem: Going further from the previous problem, John now realizes he needs twice as much rope! How much will it cost him to buy 12 meters of rope in all?

Qwen2-Math 7B:

 Reasoning: If John needs twice as much rope, he will need 12 meters of rope. The cost of the rope is $5 per meter. Therefore, the total cost for a 12-meter long rope is 12 * $5 = <<12*5=60>>$60.
### Answer: $60

Expected answer: 60

Correct? Yes

Problem: After considering his needs again, John realized that he actually needs 7 meters of rope, not 6. How much will it cost him to buy this new length of rope?

Qwen2-Math 7B:

 Reasoning: The cost of the rope is $5 per meter. Therefore, the total cost for a 7-meter long rope is 7 * $5 = <<7*5=35>>$35.
### Answer: $35

Expected answer: 35

Correct? Yes

Problem: In the previous scenario, Amelia was distributing gifts among 7 of her friends. But what if Amelia instead planned to distribute her 42 gifts equally among only 6 friends instead? How many gifts would each friend receive in this case?

Qwen2-Math 7B:

 Reasoning: Amelia will give each friend 42/6 = <<42/6=7>>7 gifts.
Each friend will receive 7 gifts.
### Answer: 7

Expected answer: 7

Correct? Yes

Problem: If the mother bear had only 40 honey pots and wanted to evenly distribute them among her 10 cubs instead, how many honey pots would each cub receive now?

Qwen2-Math 7B:

 Reasoning: Each cub will receive 40/10 = <<40/10=4>>4 honey pots.
### Answer: 4

Expected answer: 4

Correct? Yes

Problem: In the previous situation, what if instead of eating 4kg of food per hour, the elephant ate only 3kg of food per hour? How much food would the elephant eat in 4 hours then?

Qwen2-Math 7B:

 Reasoning: An elephant can eat 3kg food per hour.
An elephant can eat 3*4 = <<3*4=12>>12kg food in 4 hours.
### Answer: 12

Expected answer: 12

Correct? Yes

Problem: In addition to the 3-headed dragon, another dragon of the same kind joins it. Between the two dragons, how many eyes are there in total?

Qwen2-Math 7B:

 Reasoning: The second dragon also has 3*8 = <<3*8=24>>24 eyes.
Between the two dragons, there are 24+24 = <<24+24=48>>48 eyes in total.
### Answer: 48

Expected answer: 48

Correct? Yes

Problem: Suppose that each dragon instead had 11 eyes per head, not 8. How many eyes would one three-headed dragon have then?

Qwen2-Math 7B:

 Reasoning: The dragon would have 3*11 = <<3*11=33>>33 eyes in total.
### Answer: 33

Expected answer: 33

Correct? Yes

Problem: Following from the last problem, Charlie then takes the amount of chocolates he has and decides to multiply it by 9 for a birthday party. How many chocolates does Charlie have now?

Qwen2-Math 7B:

 Reasoning: Charlie has 4 chocolates and multiplies them by 9, so he has 4*9 = <<4*9=36>>36 chocolates now.
### Answer: 36

Expected answer: 36

Correct? Yes

Problem: Following from the previous problems, let's consider a new scenario. This time, suppose Charlie only had 2 chocolates and again decided to share half of them with his sister. Then, he counts his remaining chocolates and decides to double the amount. How many chocolates does Charlie have now in this scenario?

Qwen2-Math 7B:

 Reasoning: Charlie shared 2/2 = <<2/2=1>>1 chocolate with his sister, leaving him with 2-1 = <<2-1=1>>1 chocolate.
Charlie then doubled his remaining chocolate, so he has 1*2 = <<1*2=2>>2 chocolates now.
### Answer: 2

Expected answer: 2

Correct? Yes

Problem: Suppose the number of walls in the castle was incorrectly counted before, and there are actually 10 walls instead of 6. If the castle still has a total of 36 towers, how many towers would be on each wall in that case?

Qwen2-Math 7B:

 Reasoning: If there are 10 walls, then the number of towers on each wall would be 36/10 = <<36/10=3.6>>3.6.
However, since the number of towers must be a whole number, this scenario is not possible.
### Answer: Not possible

Expected answer: 18/5

Correct? No