Qwen2-Math 7B on 4.NBT.B.6
Common Core Standard 4.NBT.B.6
This standard covers the following:
Find whole-number quotients and remainders with up to four-digit dividends and one-digit divisors, using strategies based on place value, the properties of operations, and/or the relationship between multiplication and division. Illustrate and explain the calculation by using equations, rectangular arrays, and/or area models.
Problem: There are 535 fish in a large tank and a shark eats 461 of them in one sitting. If the shark continues this pattern and only eats when there are 461 or more fish to consume, how many fish will be leftover after its dinner?
Qwen2-Math 7B:
Reasoning: The shark eats 461 fish, leaving 535-461 = <<535-461=74>>74 fish. The shark will not eat any more fish because there are not 461 or more fish left. ### Answer: 74
Expected answer: 74
Correct? Yes
Problem: A baker baked a total of 928 cookies. He decided to distribute equal amounts of cookies to 186 orphanages. After giving out as many entire sets of cookies as possible to each orphanage, how many cookies does the baker have left?
Qwen2-Math 7B:
Reasoning: The baker can give out 928/186 = <<928/186=5>>5 cookies to each orphanage. The baker has 928-5*186 = <<928-5*186=138>>138 cookies left. ### Answer: 138
Expected answer: 184
Correct? No
Problem: A pizza store has 975 slices of pizza ready to serve. If each pizza box can contain 196 slices, how many left over slices will there be after all the pizza boxes are full?
Qwen2-Math 7B:
Reasoning: 975/196 = <<975/196=4.974489795918367>>4.974489795918367 Since we can't have a fraction of a pizza box, we round down to the nearest whole number, which is 4. 4 * 196 = <<4*196=784>>784 975 - 784 = <<975-784=191>>191 There will be 191 left over slices. ### Answer: 191
Expected answer: 191
Correct? Yes
Problem: A wizard casts a spell to summon 932 magical stones. Each powerful creature he summons requires 193 stones. After summoning several creatures, how many stones will the wizard have left?
Qwen2-Math 7B:
Reasoning: The wizard has 932-193 = <<932-193=739>>739 stones left after summoning the first creature. The wizard has 739-193 = <<739-193=546>>546 stones left after summoning the second creature. The wizard has 546-193 = <<546-193=353>>353 stones left after summoning the third creature. The wizard has 353-193 = <<353-193=160>>160 stones left after summoning the fourth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the fifth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the sixth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the seventh creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the eighth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the ninth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the tenth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the eleventh creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the twelfth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the thirteenth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the fourteenth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the fifteenth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the sixteenth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the seventeenth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the eighteenth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the nineteenth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the twentieth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the twenty-first creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the twenty-second creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the twenty-third creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the twenty-fourth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the twenty-fifth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the twenty-sixth creature. The wizard has 160-193 = <<160-193=-33>>-33 stones left after summoning the twenty-seventh creature. The
Expected answer: 160
Correct? No
Problem: A builder has a job to install 660 square foot tiles in a house. Each tile can cover 335 square feet. After installing tiles evenly across the available space, how many square feet will the last tile need to cover?
Qwen2-Math 7B:
Reasoning: The builder can install 660/335 = <<660/335=1.9705882352941176>>1.9705882352941176 tiles evenly across the available space. Since the builder can't install a fraction of a tile, the last tile will need to cover 660 - 335*1 = <<660-335*1=325>>325 square feet. ### Answer: 325
Expected answer: 325
Correct? Yes
Problem: A builder realizes that he made a mistake and the tiles can actually cover 337 square feet instead of 335 square feet. Given the same total area of 660 square feet, how many square feet will the last tile now need to cover?
Qwen2-Math 7B:
Reasoning: The builder can install 660/337 = <<660/337=1.96046511627907>>1.96046511627907 tiles evenly across the available space. Since the builder can't install a fraction of a tile, the last tile will need to cover 660 - 337*1 = <<660-337*1=323>>323 square feet. ### Answer: 323
Expected answer: 323
Correct? Yes
Problem: A juice company produced 473 gallons of juice. If the company bottles the juice in 22-gallon containers, how many gallons of juice will be left after filling up all the containers?
Qwen2-Math 7B:
Reasoning: The company can fill 473/22 = <<473/22=21.5>>21.5 containers. Since the company can only fill whole containers, they can fill 21 containers. The company will have 473 - 21*22 = <<473-21*22=11>>11 gallons of juice left. ### Answer: 11
Expected answer: 11
Correct? Yes
Problem: A juice company initially thought they produced 473 gallons of juice, but they realized they actually produced 599 gallons. They used the same 22-gallon containers as before. After filling up all the containers, how many gallons of juice do they now have left over?
Qwen2-Math 7B:
Reasoning: The company can fill 599/22 = <<599/22=27.2>>27.2 containers. Since the company can only fill whole containers, they can fill 27 containers. The company will have 599 - 27*22 = <<599-27*22=11>>11 gallons of juice left. ### Answer: 11
Expected answer: 5
Correct? No
Problem: A toy factory produced 979 toy cars in a day. If they packed these cars into boxes, each containing 108 cars, how many toy cars will be left unpacked at the end of the day?
Qwen2-Math 7B:
Reasoning: The toy factory produced 979 toy cars in a day. If they packed these cars into boxes, each containing 108 cars, then the number of boxes that can be filled is 979/108 = <<979/108=9>>9. The number of toy cars left unpacked at the end of the day is 979 - (9 * 108) = <<979-(9*108)=11>>11. ### Answer: 11
Expected answer: 7
Correct? No
Problem: A crayon factory has the capacity to make 994 crayons in one operation. However, each box only holds 425 crayons. If they operate at full capacity, how many crayons will be left out of the boxes after the operation?
Qwen2-Math 7B:
Reasoning: The number of crayons that will be left out of the boxes is 994-425 = <<994-425=569>>569. ### Answer: 569
Expected answer: 144
Correct? No
Problem: A wildlife reserve has 740 tigers. The reserve is divided into different zones, and each zone can only hold up to 696 tigers. If tigers are distributed evenly among the zones, how many tigers will be left in the last zone?
Qwen2-Math 7B:
Reasoning: The number of tigers in the last zone is the remainder when 740 is divided by 696. 740 % 696 = <<740 % 696=44>>44 There will be 44 tigers left in the last zone. ### Answer: 44
Expected answer: 44
Correct? Yes
Problem: Consider the wildlife reserve again. This time, however, the zones have been expanded and each can now accommodate up to 908 tigers. If the 740 tigers are distributed evenly among the expanded zones, how many tigers will be left in the last zone?
Qwen2-Math 7B:
Reasoning: The number of tigers in the last zone is the remainder when 740 is divided by 908. 740 % 908 = <<740 % 908=0>>0 There will be 0 tigers left in the last zone. ### Answer: 0
Expected answer: 740
Correct? No
Problem: A hat shop makes 830 hats every week. In order to make special edition boxes, the shop plans to put 421 hats in each box. If all the hats are evenly distributed among the boxes, how many hats will be left over?
Qwen2-Math 7B:
Reasoning: The number of hats left over is the remainder when 830 is divided by 421. 830 ÷ 421 = <<830%421=109>>109 remainder 109. Therefore, there will be 109 hats left over. ### Answer: 109
Expected answer: 409
Correct? No
Problem: There are 871 fish in a lake. A fisherman catches 575 fish every month. If the fish repopulate at the same rate that the fisherman is depleting them, how many fish will be left after a month?
Qwen2-Math 7B:
Reasoning: The fisherman catches 575 fish every month, so the number of fish left after a month is 871 - 575 = <<871-575=296>>296. ### Answer: 296
Expected answer: 296
Correct? Yes
Problem: There are 891 beach balls, and every beach bag can fit 119 beach balls. If all the beach balls are evenly placed into the bags, how many beach balls will not fit and left over?
Qwen2-Math 7B:
Reasoning: 891/119 = <<891/119=7.467532467532468>>7.467532467532468 Since we can't have a fraction of a beach ball, we round down to the nearest whole number, which is 7. Therefore, 7 beach balls will not fit and left over. ### Answer: 7
Expected answer: 58
Correct? No
Problem: There are 544 stars in a particular constellation. These stars are grouped into smaller clusters of 446 stars each. If these clusters are evenly split, how many stars will remain ungrouped?
Qwen2-Math 7B:
Reasoning: 544/446 = <<544/446=1.219>>1.219 Since we can't have a fraction of a cluster, we round down to the nearest whole number, which is 1. 544 - (1 * 446) = <<544 - (1 * 446)=98>>98 Therefore, 98 stars will remain ungrouped. ### Answer: 98
Expected answer: 98
Correct? Yes
Problem: Considering the previous scenario with the constellation, suppose there were only 278 stars in the constellation instead of 544, and they were still to be grouped into smaller clusters of 446 stars each. If the clusters are evenly distributed, how many stars will now remain ungrouped?
Qwen2-Math 7B:
Reasoning: 278/446 = <<278/446=0.622>>0.622 Since we can't have a fraction of a cluster, we round down to the nearest whole number, which is 0. 278 - (0 * 446) = <<278 - (0 * 446)=278>>278 Therefore, 278 stars will remain ungrouped. ### Answer: 278
Expected answer: 278
Correct? Yes
Problem: A manufacturer produces 805 socks in one shift. They are packaged into sets of 132 each. After the packaging, how many socks will remain unpackaged?
Qwen2-Math 7B:
Reasoning: The manufacturer can package 805/132 = <<805/132=6>>6 sets of socks. After packaging, there will be 805 - 6*132 = <<805-6*132=13>>13 socks remaining. ### Answer: 13
Expected answer: 13
Correct? Yes
Problem: If instead of producing 805 socks, the manufacturer produced 634 socks in one shift, how many socks would remain unpackaged after being bundled into sets of 132 each?
Qwen2-Math 7B:
Reasoning: The manufacturer can package 634/132 = <<634/132=4>>4 sets of socks. After packaging, there will be 634 - 4*132 = <<634-4*132=106>>106 socks remaining. ### Answer: 106
Expected answer: 106
Correct? Yes
Problem: An astronomy club has 759 members that want to view a rare celestial event through their club's telescope. However, the telescope can only handle 228 people viewing the event each night. If they distribute the viewing evenings evenly amongst all members, how many people will view the event on the final night?
Qwen2-Math 7B:
Reasoning: 759/228 = <<759/228=3.31>>3.31 Since we can't have a fraction of a person, we round down to the nearest whole number, which is 3. Therefore, 3 people will view the event on the final night. ### Answer: 3
Expected answer: 75
Correct? No
Problem: A postman has to deliver 891 letters. Each mailbox can only hold 616 letters. If he puts equal numbers of letters in each mailbox, how many letters will remain in the last mailbox?
Qwen2-Math 7B:
Reasoning: The postman can put 891/616 = <<891/616=1.449>>1.449 letters in each mailbox. Since the number of letters in each mailbox must be a whole number, the postman can put 1 letter in each mailbox. The postman will have 891-616 = <<891-616=275>>275 letters left. ### Answer: 275
Expected answer: 275
Correct? Yes
Problem: In the previous scenario, assuming the postman had to originally deliver 524 letters instead of 891, and each mailbox can still only accommodate 616 letters. How many letters will remain in the last mailbox now?
Qwen2-Math 7B:
Reasoning: The postman can put 524/616 = <<524/616=0.851>>0.851 letters in each mailbox. Since the number of letters in each mailbox must be a whole number, the postman can put 0 letters in each mailbox. The postman will have 524-0 = <<524-0=524>>524 letters left. ### Answer: 524
Expected answer: 524
Correct? Yes
Problem: A total of 941 flies are jumping around the pond. Every time a frog jumps, it eats exactly 258 flies. After a series of jumps where each jump the frog eats the same number of flies, how many flies are left?
Qwen2-Math 7B:
Reasoning: The number of flies left is 941 - (258 * number of jumps). Since the number of jumps is not specified, we cannot provide a specific answer. However, the formula to calculate the remaining flies is 941 - (258 * number of jumps). ### Answer: 941 - (258 * number of jumps)
Expected answer: 167
Correct? No
Problem: A large park has a capacity of 991 spaces for cars to park. If all the spaces are evenly distributed between 66 rows, how many spare spaces will be there in the last row after max spaces are filled?
Qwen2-Math 7B:
Reasoning: 991/66 = <<991/66=15>>15 with a remainder of <<991%66=1>>1. There will be 1 spare space in the last row after max spaces are filled. ### Answer: 1
Expected answer: 1
Correct? Yes
Problem: In the same large park, suppose they restructure the parking with larger spaces to accommodate bigger vehicles. Now, the adjusted parking lot configurations can hold 471 cars in each row. After filling up the rows, how many spare spaces would be there in the last row now?
Qwen2-Math 7B:
Reasoning: 991/471 = <<991/471=2>>2 with a remainder of <<991%471=149>>149. There will be 149 spare spaces in the last row after filling up the rows. ### Answer: 149
Expected answer: 49
Correct? No
Problem: There are 193 liters of water that need to be divided evenly among 167 water bottles. If each bottle holds the same amount of water, how many liters overflows and can't be distributed to the bottles?
Qwen2-Math 7B:
Reasoning: 193/167 = <<193/167=1.15488>>1.15488 liters per bottle. 193 - (167 * 1.15488) = <<193 - (167 * 1.15488)=0.00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
Expected answer: 26
Correct? No
Problem: A dragon lays 996 jewel eggs in rows. Each row can hold 319 eggs. If the dragon distributes the eggs evenly among the rows, how many eggs would be left over to be put in the last row?
Qwen2-Math 7B:
Reasoning: 996/319 = <<996/319=3>>3 remainder <<996%319=149>>149. The dragon would have 149 eggs left over to be put in the last row. ### Answer: 149
Expected answer: 39
Correct? No
Problem: A lamp manufacturer produces 691 bulb units. If a pack includes 205 bulbs, how many bulbs would be left unpacked after filling as many packs as possible?
Qwen2-Math 7B:
Reasoning: The number of packs that can be filled is 691/205 = <<691/205=3>>3. The number of bulbs left unpacked is 691 - 3*205 = <<691-3*205=76>>76. ### Answer: 76
Expected answer: 76
Correct? Yes
Problem: If the lamp manufacturer produced 739 bulb units instead of 691, how many bulbs would be left unpacked after filling as many packs as possible with 205 bulbs each?
Qwen2-Math 7B:
Reasoning: The number of packs that can be filled is 739/205 = <<739/205=3>>3. The number of bulbs left unpacked is 739 - 3*205 = <<739-3*205=134>>134. ### Answer: 134
Expected answer: 124
Correct? No
Problem: On a farm, there are 330 bales of hay to be stored evenly in barns. Each barn can store up to 259 bales. After filling up the barns as evenly as possible, how many bales of hay will be left for the last barn?
Qwen2-Math 7B:
Reasoning: 330/259 = <<330/259=1.27>>1.27 Since each barn can store up to 259 bales, the first barn will store 259 bales. The second barn will store 330-259 = <<330-259=71>>71 bales. Therefore, there will be 71 bales of hay left for the last barn. ### Answer: 71
Expected answer: 71
Correct? Yes
Problem: A construction company is installing 166 windows on a building. They have determined that one installation team can install 137 windows per day. If all windows are equally distributed amongst teams each day, how many windows will remain for the team to install on the next day?
Qwen2-Math 7B:
Reasoning: 166 windows / 137 windows per day = <<166/137=1.2119205298013245>>1.2119205298013245 days. Since we can't have a fraction of a day, we round down to the nearest whole number, which is 1 day. Therefore, the team will have 166 - 137 = <<166-137=29>>29 windows remaining to install on the next day. ### Answer: 29
Expected answer: 29
Correct? Yes
Problem: There are 533 campers coming for a camping event at a park. Each tent can host 445 people. If the campers are evenly distributed among the tents, how many campers will be left over after all the tents are filled?
Qwen2-Math 7B:
Reasoning: 533/445 = <<533/445=1.195>>1.195 Since we can't have a fraction of a person, we round down to the nearest whole number, which is 1. Therefore, 533 - (445 * 1) = <<533-(445*1)=88>>88 campers will be left over. ### Answer: 88
Expected answer: 88
Correct? Yes
Problem: Now suppose that the park upgraded their tents and each tent can now host 886 people. With the same group of 533 campers, how many campers will be left over after all the tents are filled?
Qwen2-Math 7B:
Reasoning: 533/886 = <<533/886=0.600>>0.600 Since we can't have a fraction of a person, we round down to the nearest whole number, which is 0. Therefore, 533 - (886 * 0) = <<533-(886*0)=533>>533 campers will be left over. ### Answer: 533
Expected answer: 533
Correct? Yes
Problem: There are 999 seashells collected from a beach. They are grouped in beach-themed souvenir sets, each containing 474 shells. After grouping, how many seashells will be left without a set?
Qwen2-Math 7B:
Reasoning: 999/474 = <<999/474=2>>2 sets with 474 shells each. 999 - (2 * 474) = <<999 - (2 * 474)=45>>45 seashells left without a set. ### Answer: 45
Expected answer: 51
Correct? No
Problem: A tailor has 366 meters of fabric. If each skirt requires 160 meters of fabric, how many meters of fabric will be left after making as many skirts as possible?
Qwen2-Math 7B:
Reasoning: The tailor can make 366/160 = <<366/160=2.2875>>2.2875 skirts, but since the tailor can't make a fraction of a skirt, they can only make 2 skirts. The tailor will have 366 - 160*2 = <<366-160*2=46>>46 meters of fabric left after making as many skirts as possible. ### Answer: 46
Expected answer: 46
Correct? Yes
Problem: A tailor realized that she has made a mistake. Actually, she has only 21 meters of fabric at her disposal, not 366. If each skirt requires 160 meters of fabric, how many meters of fabric will be left after making as many skirts as possible?
Qwen2-Math 7B:
Reasoning: The tailor can make 21/160 = <<21/160=0.13125>>0.13125 skirts, but since the tailor can't make a fraction of a skirt, they can only make 0 skirts. The tailor will have 21 - 160*0 = <<21-160*0=21>>21 meters of fabric left after making as many skirts as possible. ### Answer: 21
Expected answer: 21
Correct? Yes
Problem: A toymaker made 993 dolls to be packed in boxes for shipment. Each box can hold 327 dolls. How many dolls will she have left once all the boxes are packed to their capacities?
Qwen2-Math 7B:
Reasoning: The toymaker will have 993-327 = <<993-327=666>>666 dolls left after packing the first box. The toymaker will have 666-327 = <<666-327=339>>339 dolls left after packing the second box. The toymaker will have 339-327 = <<339-327=12>>12 dolls left after packing the third box. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: Following up on the previous problem, what if, instead of each box holding 327 dolls, each box can now hold 115 dolls? After packing each box to capacity, how many dolls will the toymaker have left?
Qwen2-Math 7B:
Reasoning: The toymaker will have 993-115 = <<993-115=878>>878 dolls left after packing the first box. The toymaker will have 878-115 = <<878-115=763>>763 dolls left after packing the second box. The toymaker will have 763-115 = <<763-115=648>>648 dolls left after packing the third box. The toymaker will have 648-115 = <<648-115=533>>533 dolls left after packing the fourth box. The toymaker will have 533-115 = <<533-115=418>>418 dolls left after packing the fifth box. The toymaker will have 418-115 = <<418-115=303>>303 dolls left after packing the sixth box. The toymaker will have 303-115 = <<303-115=188>>188 dolls left after packing the seventh box. The toymaker will have 188-115 = <<188-115=73>>73 dolls left after packing the eighth box. The toymaker will have 73-115 = <<73-115=-42>>-42 dolls left after packing the ninth box. Since the number of dolls left cannot be negative, the toymaker will have 0 dolls left after packing the ninth box. ### Answer: 0
Expected answer: 73
Correct? No
Problem: A child has 964 stuffed animals that they want to divide equally among their 839 friends. If they distribute the stuffed animals evenly, how many will the child have left over?
Qwen2-Math 7B:
Reasoning: The child will have 964 mod 839 = <<964 mod 839=125>>125 stuffed animals left over.
Expected answer: 125
Correct? Yes
Problem: The child from the previous problem has gotten even more stuffed animals and now has a total of 964 stuffed animals. If they still want to divide them equally among their 892 friends, how many stuffed animals will be left over after distributing them?
Qwen2-Math 7B:
Reasoning: The child will have 964 mod 892 = <<964 mod 892=72>>72 stuffed animals left over.
Expected answer: 72
Correct? Yes
Problem: A toy factory produces 369 teddy bears in a day. The bears are packaged in boxes and each box can hold 270 teddy bears. How many teddy bears will be left if all the teddy bears are evenly packed in the boxes?
Qwen2-Math 7B:
Reasoning: The number of teddy bears left is 369 mod 270 = <<369 mod 270=99>>99. ### Answer: 99
Expected answer: 99
Correct? Yes
Problem: Earlier, the toy factory produced 369 teddy bears in a day and they were packaged in boxes with each box holding 270 teddy bears. Now, suppose that the toy factory increased its production and now makes 813 teddy bears in a day while still packing them in boxes that can hold 270 teddy bears. How many teddy bears will be left now if all the teddy bears are evenly packed in the boxes?
Qwen2-Math 7B:
Reasoning: The number of teddy bears left is 813 mod 270 = <<813 mod 270=103>>103. ### Answer: 103
Expected answer: 3
Correct? No
Problem: A village has a yearly tradition of building snowmen. This year, the villagers make 804 snowballs to build their snowmen. Each snowman needs exactly 184 snowballs. After all snowmen are built, how many snowballs are left leftover?
Qwen2-Math 7B:
Reasoning: 804/184 = <<804/184=4.375>>4.375 Since we can't have a fraction of a snowman, we can only build 4 snowmen. 804 - (4 * 184) = <<804 - (4 * 184)=124>>124 There are 124 snowballs left leftover. ### Answer: 124
Expected answer: 68
Correct? No
Problem: A jewelry store has 843 rings to be placed equally into 839 boxes. If each box is filled, how many rings will be left over?
Qwen2-Math 7B:
Reasoning: 843 divided by 839 is 1 with a remainder of <<843%839=4>>4. Therefore, there will be 4 rings left over. ### Answer: 4
Expected answer: 4
Correct? Yes
Problem: The jewelry store just received an additional shipment and now has a total of 843 rings. However, this time they must be equally placed into 804 boxes. If every box is filled, how many rings will be left over now?
Qwen2-Math 7B:
Reasoning: 843 divided by 804 is 1 with a remainder of <<843%804=39>>39. Therefore, there will be 39 rings left over. ### Answer: 39
Expected answer: 39
Correct? Yes
Problem: A fireplace manufacturing company has 819 bricks to build fireplaces, and each fireplace requires 583 bricks. If they build as many fireplaces as possible, how many bricks will they have left over?
Qwen2-Math 7B:
Reasoning: The company can build 819/583 = <<819/583=1>>1 fireplace. They will have 819-583 = <<819-583=236>>236 bricks left over. ### Answer: 236
Expected answer: 236
Correct? Yes
Problem: The company received a new delivery of bricks, now they have 486 bricks in total. If they continue making fireplaces, each requiring 583 bricks as before, how many bricks will they have left after building as many full fireplaces as they can?
Qwen2-Math 7B:
Reasoning: The company can build 486/583 = <<486/583=0>>0 fireplaces. They will have 486-0 = <<486-0=486>>486 bricks left over. ### Answer: 486
Expected answer: 486
Correct? Yes
Problem: A marshmallow factory produces 998 marshmallows per minute. However, the packaging machine can only hold 957 marshmallows at a time. What will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled?
Qwen2-Math 7B:
Reasoning: The packaging machine can only hold 957 marshmallows at a time, so the number of marshmallows left un-packaged in a minute is 998-957 = <<998-957=41>>41. ### Answer: 41
Expected answer: 41
Correct? Yes
Problem: The marshmallow factory upgraded its packaging machine and now it can hold 804 marshmallows at a time instead of 957. If the factory continues to produce 998 marshmallows per minute, what will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled with the new capacity?
Qwen2-Math 7B:
Reasoning: The packaging machine can now hold 804 marshmallows at a time, so the number of marshmallows left un-packaged in a minute is 998-804 = <<998-804=194>>194. ### Answer: 194
Expected answer: 194
Correct? Yes
Problem: There are 984 roses in the castle's garden. Princess likes to place 426 roses in every tribute for her loyal subjects. If she distributes roses evenly to create as many tributes as possible, how many roses will be left undistributed in the castle's garden?
Qwen2-Math 7B:
Reasoning: The number of tributes that can be created is 984/426 = <<984/426=2>>2. The number of roses left undistributed is 984 - 426*2 = <<984-426*2=132>>132. ### Answer: 132
Expected answer: 132
Correct? Yes
Problem: In the same castle's garden, there were originally 984 roses, but the princess has decided to use only 730 roses for each tribute to her loyal subjects instead of the previous 426. Now, if she distributes roses evenly to create as many tributes as possible, how many roses will be left undistributed in the castle's garden?
Qwen2-Math 7B:
Reasoning: The number of tributes that can be created is 984/730 = <<984/730=1>>1. The number of roses left undistributed is 984 - 730*1 = <<984-730*1=254>>254. ### Answer: 254
Expected answer: 254
Correct? Yes
Problem: A song has 334 words in it. If each line in the song has 23 words, how many words would be in the incomplete line at the end of the song?
Qwen2-Math 7B:
Reasoning: 334/23 = <<334/23=14.521739130434783>>14.521739130434783 There would be 14 full lines and an incomplete line with 18 words. ### Answer: 18
Expected answer: 12
Correct? No
Problem: A teacher has 928 pages of study materials that he wants to print for his students. His printer can only print 336 pages in one go. After filling the printer a number of times, how many pages will he have left over to print?
Qwen2-Math 7B:
Reasoning: The teacher can print 336 pages at a time. To find out how many pages he will have left over, we need to find the remainder when 928 is divided by 336. 928 ÷ 336 = 2 remainder <<928%336=224>>224 The teacher will have 224 pages left over to print. ### Answer: 224
Expected answer: 256
Correct? No
Problem: Scientists have spotted 972 sharks in an area. The scientists tag groups of 667 sharks each. How many sharks are left untagged after the scientists finish tagging as many complete groups as possible?
Qwen2-Math 7B:
Reasoning: The scientists can tag 972/667 = <<972/667=1>>1 complete group of sharks. After tagging 1 group, there are 972-667 = <<972-667=305>>305 sharks left untagged. ### Answer: 305
Expected answer: 305
Correct? Yes
Problem: Following up on the previous question, the scientists later spotted a new group of 758 sharks in a different area. Again, they were trying to tag the sharks in groups of 667. How many sharks were left untagged after all complete groups have been tagged in this new area?
Qwen2-Math 7B:
Reasoning: The scientists can tag 758/667 = <<758/667=1>>1 complete group of sharks. After tagging 1 group, there are 758-667 = <<758-667=91>>91 sharks left untagged. ### Answer: 91
Expected answer: 91
Correct? Yes
Problem: There are 686 blocks of cheese in the dairy shop. Each box can contain 349 blocks of cheese. If all the blocks of cheese are evenly distributed in the boxes, how many blocks of cheese would be left over after all the boxes are filled?
Qwen2-Math 7B:
Reasoning: 686/349 = <<686/349=1>>1 with a remainder of <<686%349=337>>337. There would be 337 blocks of cheese left over after all the boxes are filled. ### Answer: 337
Expected answer: 337
Correct? Yes
Problem: In the previous scenario, say the dairy shop initially had 239 blocks of cheese instead of 686. Using the same boxes which can contain 349 blocks of cheese, how many blocks of cheese would be left over after all the boxes are filled?
Qwen2-Math 7B:
Reasoning: 239/349 = <<239/349=0>>0 with a remainder of <<239%349=239>>239. There would be 239 blocks of cheese left over after all the boxes are filled. ### Answer: 239
Expected answer: 239
Correct? Yes
Problem: There were 513 centimeters of snowfall recorded this winter. A snowplow can clear up to 170 centimeters of snow at a time. If the snowplow runs continuously, how many centimeters of snow will be left over after the final pass?
Qwen2-Math 7B:
Reasoning: The snowplow can clear 170 centimeters of snow at a time. After the final pass, there will be 513-170 = <<513-170=343>>343 centimeters of snow left over. ### Answer: 343
Expected answer: 3
Correct? No
Problem: A compass maker has 661 needles to install in compasses. Each compass uses 510 needles. After installing as many full compasses as he can, how many needles will the compass maker have left?
Qwen2-Math 7B:
Reasoning: The compass maker can install 661/510 = <<661/510=1>>1 full compass. After installing the full compass, the compass maker will have 661-510 = <<661-510=151>>151 needles left. ### Answer: 151
Expected answer: 151
Correct? Yes
Problem: A furniture factory has manufactured 380 chairs to distribute to its retail shops. Each shop can only hold 310 chairs in its storage. If the factory evenly distributes all the chairs to the shops, how many chairs will be left at the factory?
Qwen2-Math 7B:
Reasoning: The factory can evenly distribute 380/310 = <<380/310=1.2258064516129032>>1.2258064516129032 chairs to each shop, which is not possible since we cannot distribute a fraction of a chair. Therefore, the factory can only distribute 1 chair to each shop, leaving 380 - 310 = <<380-310=70>>70 chairs at the factory. ### Answer: 70
Expected answer: 70
Correct? Yes
Problem: Now suppose the factory decides to distribute these chairs amongst its smaller distributors, each of which can only hold 143 chairs. Now, how many chairs will be left at the factory after distributing them evenly?
Qwen2-Math 7B:
Reasoning: The factory can evenly distribute 380/143 = <<380/143=2.6593406593406593>>2.6593406593406593 chairs to each distributor, which is not possible since we cannot distribute a fraction of a chair. Therefore, the factory can only distribute 2 chairs to each distributor, leaving 380 - 2*143 = <<380-2*143=94>>94 chairs at the factory. ### Answer: 94
Expected answer: 94
Correct? Yes
Problem: A farmer has gathered 929 tomatoes from his field. He plans to sell them in boxes, with 154 tomatoes in each box. After packing them evenly in boxes, how many tomatoes will be left over?
Qwen2-Math 7B:
Reasoning: The farmer can pack 929/154 = <<929/154=6>>6 boxes with 154 tomatoes each, leaving a remainder of 929 - (6 * 154) = <<929 - (6 * 154)=109>>109 tomatoes. ### Answer: 109
Expected answer: 5
Correct? No
Problem: A sporting goods store has 454 pairs of ice skates in total. The store distributes the skates evenly among 128 boxes. How many pairs of ice skates will be left over after all the boxes are filled up equally?
Qwen2-Math 7B:
Reasoning: 454/128 = <<454/128=3.546875>>3.546875 Since we can't have a fraction of a pair of skates, we round down to the nearest whole number, which is 3. 454 - (128 * 3) = <<454 - (128 * 3)=454 - 384=70>>70 There will be 70 pairs of ice skates left over after all the boxes are filled up equally. ### Answer: 70
Expected answer: 70
Correct? Yes
Problem: If the sporting goods store originally had 976 pairs of ice skates instead of 454, and they still distribute the skates evenly among 128 boxes as before, how many pairs of ice skates will be left over after all the boxes are filled equally?
Qwen2-Math 7B:
Reasoning: 976/128 = <<976/128=7.625>>7.625 Since we can't have a fraction of a pair of skates, we round down to the nearest whole number, which is 7. 976 - (128 * 7) = <<976 - (128 * 7)=976 - 896=80>>80 There will be 80 pairs of ice skates left over after all the boxes are filled up equally. ### Answer: 80
Expected answer: 80
Correct? Yes
Problem: A windmill generates 506 units of power per day. Every day, a small village consumes power in increments of 385 units. At the end of the day, after the village has consumed as much power as it can in full increments, how much power is left over?
Qwen2-Math 7B:
Reasoning: The windmill generates 506 units of power per day. The village consumes power in increments of 385 units. To find out how much power is left over, we need to find the remainder when 506 is divided by 385. 506 ÷ 385 = 1 remainder <<506%385=121>>121 Therefore, 121 units of power are left over at the end of the day. ### Answer: 121
Expected answer: 121
Correct? Yes
Problem: Following the scenario of the windmill and the small village, let's now consider that the windmill had a great day and managed to generate 506 units of power. However, due to development demands, the daily consumption of the village has increased to 920 units. At the end of the day, with the power being consumed in complete units, how much power is left over?
Qwen2-Math 7B:
Reasoning: The windmill generates 506 units of power per day. The village now consumes power in increments of 920 units. To find out how much power is left over, we need to find the remainder when 506 is divided by 920. 506 ÷ 920 = 0 remainder <<506%920=506>>506 Therefore, 506 units of power are left over at the end of the day. ### Answer: 506
Expected answer: 506
Correct? Yes
Problem: Superhero Blast Man has 338 energy units in his power cells. Each energy blast he fires uses 16 energy units. After using equal units of energy firing blasts, how many energy units will Blast Man have left in his power cells?
Qwen2-Math 7B:
Reasoning: Blast Man can fire 338/16 = <<338/16=21.125>>21.125 energy blasts. Since Blast Man can't fire a fraction of a blast, he can fire 21 blasts. After firing 21 blasts, Blast Man will have 338 - 21*16 = <<338-21*16=102>>102 energy units left in his power cells. ### Answer: 102
Expected answer: 2
Correct? No
Problem: A school district has 530 students who need to be transported and each school bus can carry 144 students. If all students are equally spread across the buses, how many students will be on the last school bus?
Qwen2-Math 7B:
Reasoning: 530/144 = <<530/144=3.673611111111111>>3.673611111111111 Since we can't have a fraction of a student, we round down to the nearest whole number, which is 3. Therefore, 3 students will be on the last school bus. ### Answer: 3
Expected answer: 98
Correct? No
Problem: A wizard has 999 spells in his book. He tries to distribute them equally among 951 apprentice wizards but they don't divide evenly. How many spells will the wizard have left after giving out as many as he can to his apprentices?
Qwen2-Math 7B:
Reasoning: The wizard can give out 999/951 = <<999/951=1>>1 spell to each apprentice, with 999 - (951 * 1) = <<999 - (951 * 1)=48>>48 spells left. ### Answer: 48
Expected answer: 48
Correct? Yes
Problem: If the wizard had instead 999 spells and he tries to distribute them equally among 801 apprentice wizards, how many spells will the wizard have left after giving out as many as he can to his apprentices?
Qwen2-Math 7B:
Reasoning: The wizard can give out 999/801 = <<999/801=1>>1 spell to each apprentice, with 999 - (801 * 1) = <<999 - (801 * 1)=198>>198 spells left. ### Answer: 198
Expected answer: 198
Correct? Yes
Problem: A scooter manufacturing company has produced 767 scooters. Each delivery truck they use can carry 369 scooters. If they distribute the scooters evenly among the trucks, how many scooters will be left after all the trucks are loaded?
Qwen2-Math 7B:
Reasoning: The company can load 767/369 = <<767/369=2>>2 trucks with 369 scooters each, leaving 767-2*369 = <<767-2*369=339>>339 scooters. ### Answer: 339
Expected answer: 29
Correct? No
Problem: There are 846 water droplets in a cloud. Each raindrop needs 722 droplets to form. If all droplets are used to form raindrops, how many droplets would be left unconverted in the cloud after reaching the maximum number of rain drops?
Qwen2-Math 7B:
Reasoning: The maximum number of raindrops that can be formed is 846/722 = <<846/722=1>>1. The number of droplets left unconverted is 846 - 722 = <<846-722=124>>124. ### Answer: 124
Expected answer: 124
Correct? Yes
Problem: There was a slight miscalculation in the cloud's droplet count. There are actually 846 water droplets in the cloud, but each raindrop needs 442 droplets to form instead of 722. With this updated droplet count per raindrop, how many droplets would be left unconverted in the cloud after reaching the maximum number of rain drops?
Qwen2-Math 7B:
Reasoning: The maximum number of raindrops that can be formed is 846/442 = <<846/442=1>>1. The number of droplets left unconverted is 846 - 442 = <<846-442=404>>404. ### Answer: 404
Expected answer: 404
Correct? Yes
Problem: Unicorn Village, a magical place where 265 unicorns live, is divided into 146 equal sections where these magical creatures reside. If each section is occupied by an equal number of unicorns, how many unicorns will live in the last incomplete section?
Qwen2-Math 7B:
Reasoning: 265 unicorns divided by 146 sections equals <<265/146=1.8157894736842105>>1.8157894736842105 unicorns per section. Since we can't have a fraction of a unicorn, we round down to 1 unicorn per section. Therefore, 146 sections will have 1 unicorn each, leaving 265 - 146 = <<265-146=119>>119 unicorns for the last incomplete section. ### Answer: 119
Expected answer: 119
Correct? Yes
Problem: Considering the same scenario from the previous problem, let's say instead of 146 sections, Unicorn Village is divided into 781 equal sections. How many unicorns will live in the last incomplete section now?
Qwen2-Math 7B:
Reasoning: 265 unicorns divided by 781 sections equals <<265/781=0.33933933933933935>>0.33933933933933935 unicorns per section. Since we can't have a fraction of a unicorn, we round down to 0 unicorns per section. Therefore, 781 sections will have 0 unicorns each, leaving 265 unicorns for the last incomplete section. ### Answer: 265
Expected answer: 265
Correct? Yes
Problem: In a game, there are 923 players waiting to enter a match. Only 383 players can enter a match at a time. If players enter matches evenly, how many players will be left waiting after filling all the matches?
Qwen2-Math 7B:
Reasoning: 923/383 = <<923/383=2>>2 remainder <<923%383=157>>157. Therefore, 157 players will be left waiting after filling all the matches. ### Answer: 157
Expected answer: 157
Correct? Yes
Problem: In the same game, a new day dawns with 456 players waiting to join a match. The match capacity remains the same, permitting 383 players at a time. If players are allocated evenly across the matches, how many players will be left waiting after all available matches are filled?
Qwen2-Math 7B:
Reasoning: 456/383 = <<456/383=1>>1 remainder <<456%383=73>>73. Therefore, 73 players will be left waiting after filling all the matches. ### Answer: 73
Expected answer: 73
Correct? Yes
Problem: A pirate ship has 923 cannonballs on board. They want to equally disperse them between 499 different crates. After evenly distributing them as much as possible, how many cannonballs will be left uncrated?
Qwen2-Math 7B:
Reasoning: 923/499 = <<923/499=1.8496993984984985>>1.8496993984984985 The number of cannonballs left uncrated is 923 - (499 * 1) = <<923 - (499 * 1)=424>>424. ### Answer: 424
Expected answer: 424
Correct? Yes
Problem: Keeping in line with the previous pirate ship themed problem, let's consider the following scenario: The same pirate ship initially started with 462 cannonballs instead of 923. After the pirates evenly distribute these cannonballs into the same 499 crates, can any be leftover? If so, how many cannonballs will be left uncrated?
Qwen2-Math 7B:
Reasoning: 462/499 = <<462/499=0.925851706679449>>0.925851706679449 The number of cannonballs left uncrated is 462 - (499 * 0) = <<462 - (499 * 0)=462>>462. ### Answer: 462
Expected answer: 462
Correct? Yes
Problem: A kite store has 530 string spools to attach to their kites. They distribute them to 518 kites, each getting one string spool. After each kite gets a spool, how many spools are left in the store?
Qwen2-Math 7B:
Reasoning: The store has 530-518 = <<530-518=12>>12 spools left. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: A dairy farm produces 913 gallons of milk in a day. If every milk jug holds 39 gallons, how many gallons will be left over after all the jugs are filled?
Qwen2-Math 7B:
Reasoning: 913/39 = <<913/39=23.384615384615385>>23.384615384615385 Since we can't have a fraction of a jug, we round down to the nearest whole number, which is 23 jugs. 913 - (23 * 39) = <<913-(23*39)=20>>20 There will be 20 gallons left over after all the jugs are filled. ### Answer: 20
Expected answer: 16
Correct? No
Problem: A doll seller received a shipment of 603 new dolls to put on the shelves. She arranged all the dolls in rows, with 369 dolls in each row. After filling up the rows as much as possible, how many dolls were left unarranged?
Qwen2-Math 7B:
Reasoning: The number of dolls left unarranged is 603 - (369 * <<603-369=234>>234) = <<603-369=234>>234 dolls.
Expected answer: 234
Correct? Yes
Problem: In the previous doll problem, if the doll seller initially received a shipment of 44 new dolls instead of 603, and still arranged them in rows of 369 dolls, how many dolls would be left unarranged after filling up the rows as much as possible?
Qwen2-Math 7B:
Reasoning: The number of dolls left unarranged is 44 - (369 * <<44-369=-325>>-325) = <<44-369=-325>>-325 dolls. However, since the number of dolls cannot be negative, this means that all 44 dolls were used to fill up the rows, and no dolls were left unarranged.
Expected answer: 44
Correct? Yes
Problem: A jewelry maker has 850 beads to make necklaces. They use 631 beads for each necklace. After using as many beads as possible, how many beads will the jewelry maker have left over?
Qwen2-Math 7B:
Reasoning: The jewelry maker can make 850/631 = <<850/631=1>>1 necklace with 850-631 = <<850-631=219>>219 beads left over. ### Answer: 219
Expected answer: 219
Correct? Yes
Problem: The jewelry maker decides to change the design and now each necklace uses only 150 beads instead of 631 beads. After they distribute the 850 beads as equally as possible among the new necklaces, how many beads will the jewelry maker have left over?
Qwen2-Math 7B:
Reasoning: The jewelry maker can make 850/150 = <<850/150=5>>5 necklaces with 850-150*5 = <<850-150*5=100>>100 beads left over. ### Answer: 100
Expected answer: 100
Correct? Yes
Problem: A gardener has 952 grapes that he wants to package into boxes. If each box can hold 380 grapes, how many grapes will be left after the gardener has filled as many boxes as possible?
Qwen2-Math 7B:
Reasoning: The gardener can fill 952/380 = <<952/380=2>>2 boxes. The gardener will have 952-380*2 = <<952-380*2=192>>192 grapes left after filling the boxes. ### Answer: 192
Expected answer: 192
Correct? Yes
Problem: The gardener's friend gave him an additional 183 grapes from his own garden. If the gardener decides to package these grapes as well into boxes with each box holding 380 grapes, how many grapes will remain after packaging the new grapes into as many boxes as possible?
Qwen2-Math 7B:
Reasoning: The gardener can fill 183/380 = <<183/380=0>>0 boxes. The gardener will have 183-380*0 = <<183-380*0=183>>183 grapes left after packaging the new grapes into boxes. ### Answer: 183
Expected answer: 183
Correct? Yes
Problem: On a treasure map, there are 236 steps mentioned on the guide. If every 44 steps I make leads me to a significant place or clue, how many steps will be left after I reach the last significant place or clue?
Qwen2-Math 7B:
Reasoning: 236/44 = <<236/44=5.363636363636364>>5.363636363636364 Since we can't have a fraction of a step, we round down to the nearest whole number, which is 5. 5 * 44 = <<5*44=220>>220 236 - 220 = <<236-220=16>>16 There will be 16 steps left after reaching the last significant place or clue. ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: Sarah blew 932 bubbles using her new bubble machine. The machine is designed to form groups of 507 bubbles each before releasing them. After forming complete groups, how many bubbles does it make in its final, incomplete group?
Qwen2-Math 7B:
Reasoning: The machine forms complete groups of 507 bubbles each. The number of complete groups is 932/507 = <<932/507=1>>1. The number of bubbles in the final, incomplete group is 932 - (1 * 507) = <<932-(1*507)=425>>425. ### Answer: 425
Expected answer: 425
Correct? Yes
Problem: Suppose Sarah uses her bubble machine again, this time to blow 904 bubbles. The machine is still designed to form groups of 507 bubbles each before releasing them. After forming complete groups, how many bubbles does it make in its final, incomplete group?
Qwen2-Math 7B:
Reasoning: The machine forms complete groups of 507 bubbles each. The number of complete groups is 904/507 = <<904/507=1>>1. The number of bubbles in the final, incomplete group is 904 - (1 * 507) = <<904-(1*507)=397>>397. ### Answer: 397
Expected answer: 397
Correct? Yes
Problem: At the park, there are 931 kids who want to use the swings. Each swing set can accommodate 34 kids at a time. If all the swing sets are filled continuously, how many kids will be waiting for their turn after all the swing sets are occupied?
Qwen2-Math 7B:
Reasoning: The number of kids that can use the swing sets at a time is 34 * <<34*3=102>>102. The number of kids waiting for their turn is 931 - 102 = <<931-102=829>>829. ### Answer: 829
Expected answer: 13
Correct? No
Problem: John has 943 dollar bills in his possession. He tries to stuff them in wallets that can each contain 433 dollar bills. After fully loading as many wallets as he can, how many dollar bills does he have left?
Qwen2-Math 7B:
Reasoning: John can fully load 943/433 = <<943/433=2>>2 wallets. After fully loading as many wallets as he can, he has 943-2*433 = <<943-2*433=7>>7 dollar bills left. ### Answer: 7
Expected answer: 77
Correct? No
Problem: A helicopter pilot plans to transport 240 passengers over several trips. He can carry 177 passengers in one trip. How many passengers will be left behind after the helicopter makes the first full trip?
Qwen2-Math 7B:
Reasoning: The helicopter can carry 177 passengers in one trip. After the first full trip, there will be 240-177 = <<240-177=63>>63 passengers left behind. ### Answer: 63
Expected answer: 63
Correct? Yes
Problem: A gardener has 982 flowers to plant in flowerbeds. Each flowerbed can fit 555 flowers. After filling up as many flowerbeds as possible, how many flowers will the gardener have left to plant?
Qwen2-Math 7B:
Reasoning: The gardener can fill up 982/555 = <<982/555=1>>1 flowerbed completely. The gardener will have 982-555 = <<982-555=427>>427 flowers left to plant. ### Answer: 427
Expected answer: 427
Correct? Yes
Problem: The gardener received an additional shipment, bringing the total number of flowers up to 867. If he continues to plant the flowers in flowerbeds of 555 each, how many flowers will he have left to plant after filling up as many flowerbeds as possible?
Qwen2-Math 7B:
Reasoning: The gardener can fill up 867/555 = <<867/555=1>>1 flowerbed completely. The gardener will have 867-555 = <<867-555=312>>312 flowers left to plant. ### Answer: 312
Expected answer: 312
Correct? Yes
Problem: A farmer grows 203 strawberry plants. She wants to divide her plants into groups of 5 to sell. How many plants will be remaining if she divides them equally?
Qwen2-Math 7B:
Reasoning: 203/5 = <<203/5=40.6>>40.6 Since we can't have a fraction of a plant, we round down to the nearest whole number, which is 40. The farmer will have 203 - (40 * 5) = <<203-(40*5)=3>>3 plants remaining. ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: The farmer harvested another field and got an additional 76 strawberry plants. Again, she wants to divide the new plants into groups of 5 to sell. How many plants will be remaining if she divides these new strawberries equally?
Qwen2-Math 7B:
Reasoning: 76/5 = <<76/5=15.2>>15.2 Since we can't have a fraction of a plant, we round down to the nearest whole number, which is 15. The farmer will have 76 - (15 * 5) = <<76-(15*5)=1>>1 plants remaining. ### Answer: 1
Expected answer: 1
Correct? Yes
Problem: A gardener has 355 carrots. He wants to create bundles of 16. After creating as many bundles as he can, how many carrots will he have left?
Qwen2-Math 7B:
Reasoning: The gardener can create 355/16 = <<355/16=22.1875>>22 bundles with 16 carrots each. After creating 22 bundles, the gardener will have 355 - 22*16 = <<355-22*16=3>>3 carrots left. ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: A total rainfall of 612 inches fell over a certain city in 29 consecutive days. If the rain fell in the same amount every day, how many inches of rain would be left to make the days evenly rainy?
Qwen2-Math 7B:
Reasoning: 612/29 = <<612/29=21.103448275862068>>21.103448275862068 inches of rain fell each day. To find the total inches of rain left to make the days evenly rainy, we need to find the remainder when 612 is divided by 29. 612 % 29 = <<612%29=13>>13 inches of rain would be left to make the days evenly rainy. ### Answer: 13
Expected answer: 3
Correct? No
Problem: A truck company has got 514 boxes for delivery. Each truck can hold up to 371 boxes. If each truck is loaded to its full capacity, how many boxes will be left over?
Qwen2-Math 7B:
Reasoning: 514 - 371 = <<514-371=143>>143 boxes will be left over. ### Answer: 143
Expected answer: 143
Correct? Yes
Problem: In a large sandbox, children create 684 sandcastles over the summer. The sandcastles were grouped into sets of 230 for a photography contest. After all the sets were completed, how many sandcastles were left that didn't form a complete set?
Qwen2-Math 7B:
Reasoning: 684/230 = <<684/230=2>>2 sets of sandcastles were completed. 684 - (230*2) = <<684-(230*2)=224>>224 sandcastles were left that didn't form a complete set. ### Answer: 224
Expected answer: 224
Correct? Yes
Problem: Continuing from the prior problem, suppose that in another large sandbox, children now create 533 sandcastles over the summer instead of 684. If they still group the sandcastles in sets of 230 for a photography contest, how many sandcastles will be left now that don't form a complete set?
Qwen2-Math 7B:
Reasoning: 533/230 = <<533/230=2>>2 sets of sandcastles were completed. 533 - (230*2) = <<533-(230*2)=73>>73 sandcastles were left that didn't form a complete set. ### Answer: 73
Expected answer: 73
Correct? Yes
Problem: A toy manufacturer has a production run of 735 toy cars. They package the cars in packs of 348 for bulk shipments. If all the toy cars are divided equally among packs, how many toy cars will be left over after all full packs have been filled?
Qwen2-Math 7B:
Reasoning: 735/348 = <<735/348=2>>2 with a remainder of <<735%348=41>>41. There will be 41 toy cars left over after all full packs have been filled. ### Answer: 41
Expected answer: 39
Correct? No
Problem: In a forest, there are 386 animals. Each woodlands territory can support 95 animals. If the existing animals are evenly distributed among the territories, how many animals will be left in the last not fully occupied territory?
Qwen2-Math 7B:
Reasoning: 386/95 = <<386/95=4.063157894736842>>4.063157894736842 territories. Since we can't have a fraction of a territory, we round down to 4 territories. 4 territories * 95 animals/territory = <<4*95=380>>380 animals. 386 animals - 380 animals = <<386-380=6>>6 animals left in the last not fully occupied territory. ### Answer: 6
Expected answer: 6
Correct? Yes
Problem: In the same forest, a new report finds that there were actually 497 animals instead of the initially thought 386. If these animals were evenly distributed among the territories, each still supporting 95 animals, how many animals would be in the last not fully occupied territory now?
Qwen2-Math 7B:
Reasoning: 497/95 = <<497/95=5.231578947368421>>5.231578947368421 territories. Since we can't have a fraction of a territory, we round down to 5 territories. 5 territories * 95 animals/territory = <<5*95=475>>475 animals. 497 animals - 475 animals = <<497-475=22>>22 animals in the last not fully occupied territory. ### Answer: 22
Expected answer: 22
Correct? Yes
Problem: A forest has 801 trees. A tree disease starts to spread and is expected to affect 646 trees. If all the diseased trees have to be cut down evenly, how many trees are likely to stay healthy after the disease has affected all possible trees?
Qwen2-Math 7B:
Reasoning: If all the diseased trees have to be cut down evenly, then the number of trees that are likely to stay healthy after the disease has affected all possible trees is 801-646 = <<801-646=155>>155. ### Answer: 155
Expected answer: 155
Correct? Yes
Problem: A rope manufacturer has made a rope of 934 meters in length. This rope is supposed to be cut into smaller pieces, each piece being 902 meters in length. After cutting into the maximum possible number of equal pieces, how many meters will the last piece of the rope be?
Qwen2-Math 7B:
Reasoning: The maximum number of pieces that can be cut from the rope is 934/902 = <<934/902=1>>1. The length of the last piece of the rope will be 934 - 902 = <<934-902=32>>32 meters. ### Answer: 32
Expected answer: 32
Correct? Yes
Problem: Continuing from the previous scenario, suppose that the manufacturer only made a rope of 202 meters in length initially. Applying the same method of cutting rope into pieces that are each 902 meters long, how many meters would the piece of the rope be now?
Qwen2-Math 7B:
Reasoning: The maximum number of pieces that can be cut from the rope is 202/902 = <<202/902=0>>0. The length of the last piece of the rope will be 202 - 0 = <<202-0=202>>202 meters. ### Answer: 202
Expected answer: 202
Correct? Yes
Problem: A dairy farm produces 561 liters of milk each day. The milk is packaged into 550-liter containers. How many liters of milk are left over each day after filling the containers?
Qwen2-Math 7B:
Reasoning: The dairy farm produces 561 liters of milk each day. Each container holds 550 liters of milk. The number of liters of milk left over each day is 561-550 = <<561-550=11>>11 liters. ### Answer: 11
Expected answer: 11
Correct? Yes
Problem: If the dairy farm increased its production and started producing 729 liters of milk each day instead of 561 liters, how many liters of milk would be left over each day after filling the 550-liter containers?
Qwen2-Math 7B:
Reasoning: The dairy farm now produces 729 liters of milk each day. Each container still holds 550 liters of milk. The number of liters of milk left over each day is 729-550 = <<729-550=179>>179 liters. ### Answer: 179
Expected answer: 179
Correct? Yes
Problem: Jon has 259 puzzle pieces. If each puzzle requires 258 pieces, how many pieces will be left over once he completes a full puzzle?
Qwen2-Math 7B:
Reasoning: Jon has 259 - 258 = <<259-258=1>>1 piece left over once he completes a full puzzle. ### Answer: 1
Expected answer: 1
Correct? Yes
Problem: In the previous problem, Jon had 259 puzzle pieces and each puzzle requires 258 pieces. Suppose instead each puzzle needs 542 pieces. How many pieces would Jon have left over after finishing as many full puzzles as possible with his 259 pieces?
Qwen2-Math 7B:
Reasoning: Jon can complete 259/542 = <<259/542=0>>0 full puzzles with his 259 pieces. Jon will have 259 - 0*542 = <<259-0*542=259>>259 pieces left over after finishing as many full puzzles as possible with his 259 pieces. ### Answer: 259
Expected answer: 259
Correct? Yes
Problem: A jewelry maker has 673 beads. She plans to use exactly 49 beads for each bracelet. How many beads will she have left after creating as many bracelets as possible with the exact number of beads?
Qwen2-Math 7B:
Reasoning: The jewelry maker can make 673/49 = <<673/49=13.73469387755102>>13.73469387755102 bracelets, but since she can only make whole bracelets, she can make 13 bracelets. After making 13 bracelets, she will have 673 - (13 * 49) = <<673-(13*49)=673-637=36>>36 beads left. ### Answer: 36
Expected answer: 36
Correct? Yes
Problem: The jewelry maker received an additional shipment, and now she has a total of 673 beads. This time, she wants to make larger bracelets which use exactly 545 beads each. After creating as many large bracelets as possible, how many beads will she have left over?
Qwen2-Math 7B:
Reasoning: The jewelry maker can make 673/545 = <<673/545=1.2357723577235772>>1.2357723577235772 bracelets, but since she can only make whole bracelets, she can make 1 large bracelet. After making 1 large bracelet, she will have 673 - 545 = <<673-545=128>>128 beads left over. ### Answer: 128
Expected answer: 128
Correct? Yes
Problem: A police station received 927 calls within a week. They have 311 operators who can handle the same number of calls each week. However, when the calls are divided equally, how many calls will the last operator handle?
Qwen2-Math 7B:
Reasoning: 927/311 = <<927/311=3>>3 with a remainder of <<927%311=294>>294. The last operator will handle 3 + 1 = <<3+1=4>>4 calls. ### Answer: 4
Expected answer: 305
Correct? No
Problem: John has 764 pieces for his jigsaw puzzle, and every package should contain 589 pieces. If he separates these pieces into full packages, how many pieces will be left outside without a package?
Qwen2-Math 7B:
Reasoning: John can separate 764/589 = <<764/589=1>>1 full package. John will have 764-589 = <<764-589=175>>175 pieces left outside without a package. ### Answer: 175
Expected answer: 175
Correct? Yes
Problem: If John had originally only 404 puzzle pieces, and each package can still only contain 589, how many pieces will be left outside the package now?
Qwen2-Math 7B:
Reasoning: John can separate 404/589 = <<404/589=0>>0 full package. John will have 404-0 = <<404-0=404>>404 pieces left outside the package. ### Answer: 404
Expected answer: 404
Correct? Yes
Problem: A dressmaker has 984 meters of fabric. She uses 217 meters of fabric to make each dress. After using all the fabric she can to make as many dresses as possible, how many meters of fabric will she have left?
Qwen2-Math 7B:
Reasoning: The dressmaker can make 984/217 = <<984/217=4.54>>4.54 dresses, but since she can't make a fraction of a dress, she can only make 4 dresses. She will have 984 - (4 * 217) = <<984 - (4 * 217)=100>>100 meters of fabric left. ### Answer: 100
Expected answer: 116
Correct? No
Problem: A company donates 639 sleeping bags for a camping event. Each campsite is supplied with 374 sleeping bags. If all the sleeping bags are divided equally among the campsites, how many sleeping bags will there be left?
Qwen2-Math 7B:
Reasoning: The total number of sleeping bags is 639. If each campsite is supplied with 374 sleeping bags, then the number of campsites is 639/374 = <<639/374=1.7083>>1.7083. Since the number of campsites must be a whole number, we round down to 1 campsite. Therefore, there will be 639 - 374 = <<639-374=265>>265 sleeping bags left. ### Answer: 265
Expected answer: 265
Correct? Yes
Problem: The same company from our previous question receives an updated request for sleeping bags. Now instead of 639, they only need to donate 613. If each campsite is still supplied with 374 sleeping bags, how many sleeping bags will be left after all the campsites are filled?
Qwen2-Math 7B:
Reasoning: The total number of sleeping bags is 613. If each campsite is supplied with 374 sleeping bags, then the number of campsites is 613/374 = <<613/374=1.6399>>1.6399. Since the number of campsites must be a whole number, we round down to 1 campsite. Therefore, there will be 613 - 374 = <<613-374=239>>239 sleeping bags left. ### Answer: 239
Expected answer: 239
Correct? Yes
Problem: A pizza restaurant made 620 pizzas today. They package up the pizzas in boxes that hold 578 each for delivery. If the pizzas are evenly distributed into these boxes, how many pizzas will be left over that don't fit into a box?
Qwen2-Math 7B:
Reasoning: 620 - 578 = <<620-578=42>>42 pizzas will be left over that don't fit into a box. ### Answer: 42
Expected answer: 42
Correct? Yes
Problem: The owner of the pizza restaurant decides to make 74 more pizzas tomorrow, bringing the total to 694 pizzas. If they are again distributed into boxes that hold 578 pizzas each, how many pizzas will be left out without a box this time?
Qwen2-Math 7B:
Reasoning: 694 - 578 = <<694-578=116>>116 pizzas will be left out without a box this time. ### Answer: 116
Expected answer: 116
Correct? Yes
Problem: A factory made a total of 820 robots. It can store 684 robots in one storage unit. If the robots are evenly stored, how many robots will not fit and remain outside of the storage units?
Qwen2-Math 7B:
Reasoning: The factory can store 684 robots in one storage unit. If the robots are evenly stored, then the number of robots that will not fit and remain outside of the storage units is 820-684 = <<820-684=136>>136. ### Answer: 136
Expected answer: 136
Correct? Yes
Problem: In the same factory, another production run is completed, this time manufacturing a total of 820 upgraded robots. However, the storage units for these new models can only hold 625 robots each. If the robots are evenly stored, how many upgraded robots will not fit and remain outside the storage units now?
Qwen2-Math 7B:
Reasoning: The factory can store 625 robots in one storage unit. If the robots are evenly stored, then the number of robots that will not fit and remain outside of the storage units is 820-625 = <<820-625=95>>95. ### Answer: 95
Expected answer: 195
Correct? No
Problem: A cloud changes its shape by reducing its water droplets. Initially, there were 516 droplets in the cloud. If the cloud loses water droplets at an equal rate and becomes entirely dry after every 289 droplets, how many droplets will be left when the cloud is dry after the final cycle?
Qwen2-Math 7B:
Reasoning: The cloud loses droplets at a rate of 516-289 = <<516-289=227>>227 droplets per cycle. After the first cycle, there will be 516-227 = <<516-227=289>>289 droplets left. After the second cycle, there will be 289-227 = <<289-227=62>>62 droplets left. After the third cycle, there will be 62-227 = -165 droplets left, which is not possible. Therefore, the cloud will be dry after the second cycle, and there will be 62 droplets left. ### Answer: 62
Expected answer: 227
Correct? No
Problem: A transport company needs to load 330 boxes into trucks. Each truck can hold exactly 4 boxes. After filling each truck to its full capacity, how many boxes will be left unloaded?
Qwen2-Math 7B:
Reasoning: 330 boxes / 4 boxes per truck = <<330/4=82.5>>82.5 trucks. Since we can't have half a truck, we need to round down to the nearest whole number, which is 82 trucks. 330 boxes - (82 trucks * 4 boxes per truck) = 330 - <<82*4=328>>328 = <<330-328=2>>2 boxes left unloaded. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: The transport company now needs to load a new batch of 274 boxes into trucks. Again, each truck can hold exactly 4 boxes. After filling each truck to its full capacity, how many boxes will be left unloaded this time?
Qwen2-Math 7B:
Reasoning: 274 boxes / 4 boxes per truck = <<274/4=68.5>>68.5 trucks. Rounding down to the nearest whole number, we have 68 trucks. 274 boxes - (68 trucks * 4 boxes per truck) = 274 - <<68*4=272>>272 = <<274-272=2>>2 boxes left unloaded. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: A farmer harvested 649 potatoes this season. He decides to pack them into crates each containing 183 potatoes. How many potatoes will be left after all crates are filled to their maximum capacity?
Qwen2-Math 7B:
Reasoning: The farmer can pack 649/183 = <<649/183=3>>3 crates, with 649-3*183 = <<649-3*183=140>>140 potatoes left over. ### Answer: 140
Expected answer: 100
Correct? No
Problem: A t-shirt company has a batch of 258 shirts in production. Each box can pack 67 shirts. If all the shirts are evenly distributed in the boxes, how many shirts would be left outside the boxes?
Qwen2-Math 7B:
Reasoning: 258/67 = <<258/67=3.835820895522388>>3.835820895522388 Since we can't have a fraction of a shirt, we round down to the nearest whole number, which is 3. 258 - (3 * 67) = <<258-(3*67)=258-201=57>>57 Therefore, there would be 57 shirts left outside the boxes. ### Answer: 57
Expected answer: 57
Correct? Yes
Problem: Suppose the t-shirt company actually had a batch of 258 shirts, but this time each box can pack 828 shirts. If all the shirts are evenly distributed in the boxes, how many shirts would be left outside the boxes?
Qwen2-Math 7B:
Reasoning: 258/828 = <<258/828=0.3111111111111111>>0.3111111111111111 Since we can't have a fraction of a shirt, we round down to the nearest whole number, which is 0. 258 - (0 * 828) = <<258-(0*828)=258-0=258>>258 Therefore, there would be 258 shirts left outside the boxes. ### Answer: 258
Expected answer: 258
Correct? Yes
Problem: On a pirate ship, there are 995 gold coins that need to be evenly divided among the 267 pirates. If they split the gold up as evenly as possible, how many gold coins will be left over?
Qwen2-Math 7B:
Reasoning: 995/267 = <<995/267=3.72>>3.72 Since the number of gold coins must be a whole number, we can't have a fraction of a coin. Therefore, we need to find the remainder when 995 is divided by 267. 995 mod 267 = <<995 mod 267=154>>154 So, there will be 154 gold coins left over. ### Answer: 154
Expected answer: 194
Correct? No
Problem: There are 776 snails all lined up in a row. If you group them in bunches of 375 snails, how many snails will be left in the final group?
Qwen2-Math 7B:
Reasoning: 776/375 = <<776/375=2>>2 remainder <<776%375=61>>61. There will be 61 snails left in the final group. ### Answer: 61
Expected answer: 26
Correct? No
Problem: A pillow factory produces 589 pillows per day. They package these pillows in boxes, and each box holds 198 pillows. If they pack as many full boxes as possible, how many pillows will be left outside the boxes at the end of the day?
Qwen2-Math 7B:
Reasoning: 589 pillows / 198 pillows per box = <<589/198=2>>2 boxes with 589 - (2 * 198) = <<589 - (2 * 198)=193>>193 pillows left over. ### Answer: 193
Expected answer: 193
Correct? Yes
Problem: The pillow factory has made an adjustment to the packaging process and recently upgraded their boxes so that each can now hold 810 pillows. If they still produce 589 pillows per day and pack as many full boxes as possible, how many pillows will be left outside the boxes at the end of the day?
Qwen2-Math 7B:
Reasoning: 589 pillows / 810 pillows per box = <<589/810=0>>0 boxes with 589 pillows left over. ### Answer: 589
Expected answer: 589
Correct? Yes
Problem: A jewelry maker has 633 beads. If she uses beads to make necklaces, with each necklace using exactly 30 beads, how many beads will she have left after making as many necklaces as she can?
Qwen2-Math 7B:
Reasoning: The jewelry maker can make 633/30 = <<633/30=21.1>>21.1 necklaces. Since she can't make a fraction of a necklace, she can make 21 necklaces. After making 21 necklaces, she will have 633 - (21 * 30) = <<633-(21*30)=3>>3 beads left. ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: The jewelry maker found an additional box of beads in her storage, increasing her total number of beads to 588. Now, if she uses these beads to make necklaces, with each necklace using exactly 30 beads, how many beads will she have left after making as many necklaces as she can?
Qwen2-Math 7B:
Reasoning: The jewelry maker can make 588/30 = <<588/30=19.6>>19.6 necklaces. Since she can't make a fraction of a necklace, she can make 19 necklaces. After making 19 necklaces, she will have 588 - (19 * 30) = <<588-(19*30)=18>>18 beads left. ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: John has collected 365 coins. He decided to put equal numbers of them in his 140 wallets. However, he found out he would still have some coins left after evenly distributing them into these wallets. How many coins will John have left?
Qwen2-Math 7B:
Reasoning: John can put 365/140 = <<365/140=2>>2 coins in each wallet. John will have 365-140*2 = <<365-140*2=85>>85 coins left. ### Answer: 85
Expected answer: 85
Correct? Yes
Problem: Now, suppose John comes across additional coins and his collection increases to 739 coins. He again tries to evenly distribute these coins among his 140 wallets. How many coins will John have left after this distribution?
Qwen2-Math 7B:
Reasoning: John can put 739/140 = <<739/140=5>>5 coins in each wallet. John will have 739-140*5 = <<739-140*5=39>>39 coins left. ### Answer: 39
Expected answer: 39
Correct? Yes
Problem: A sock manufacturer produces 743 socks in a single production run. The socks are packed into cartons, each containing 451 socks. After filling up as many cartons as possible, how many socks are left unpacked?
Qwen2-Math 7B:
Reasoning: The number of cartons that can be filled is 743/451 = <<743/451=1>>1. The number of socks left unpacked is 743 - 451 = <<743-451=292>>292. ### Answer: 292
Expected answer: 292
Correct? Yes
Problem: Now suppose the sock manufacturer changes their packaging method and each carton contains 179 socks instead of 451 socks. After filling up as many cartons as possible with 743 socks, how many socks are left unpacked?
Qwen2-Math 7B:
Reasoning: The number of cartons that can be filled is 743/179 = <<743/179=4>>4. The number of socks left unpacked is 743 - 4*179 = <<743-4*179=107>>107. ### Answer: 107
Expected answer: 27
Correct? No
Problem: A total of 923 children want to slide down a slide at an amusement park. If 771 children can go down the slide without rest, how many children will be left waiting for their turn?
Qwen2-Math 7B:
Reasoning: 923-771 = <<923-771=152>>152 children will be left waiting for their turn. ### Answer: 152
Expected answer: 152
Correct? Yes
Problem: After the first 771 children go down the slide, another wave of children arrives and now there are 923 children in total waiting again. If 881 children can go down the slide without any break this time, how many children will be left waiting for their turn?
Qwen2-Math 7B:
Reasoning: 923-881 = <<923-881=42>>42 children will be left waiting for their turn. ### Answer: 42
Expected answer: 42
Correct? Yes
Problem: Superhero Iron Punch has to save 442 people from a collapsing building. He can teleport a maximum of 104 people at a time to safety. After teleporting as many full groups as he can, how many people will be left in the building for his last round of rescue?
Qwen2-Math 7B:
Reasoning: Iron Punch can teleport 442/104 = <<442/104=4>>4 full groups of people. After teleporting 4 full groups, there will be 442-4*104 = <<442-4*104=46>>46 people left in the building for his last round of rescue. ### Answer: 46
Expected answer: 26
Correct? No
Problem: A card game manufacturer creates a deck of cards with 569 cards. Each card pack has 68 cards. After creating as many packs as possible, how many cards will the manufacturer have left over?
Qwen2-Math 7B:
Reasoning: The manufacturer can create 569/68 = <<569/68=8.33>>8.33 packs. The manufacturer will have 569-68*8 = <<569-68*8=13>>13 cards left over. ### Answer: 13
Expected answer: 25
Correct? No
Problem: A stationery store received a shipment of 842 erasers. The store owner wants to display them in boxes, with each box containing 719 erasers. After filling as many boxes as possible, how many erasers will be left over?
Qwen2-Math 7B:
Reasoning: The store owner can fill 842/719 = <<842/719=1>>1 box with 719 erasers. After filling the box, there will be 842-719 = <<842-719=123>>123 erasers left over. ### Answer: 123
Expected answer: 123
Correct? Yes
Problem: Suppose the stationery store owner later decided to display the erasers in smaller boxes, with each box containing 420 erasers instead. After filling as many boxes as possible, how many erasers will be left over now?
Qwen2-Math 7B:
Reasoning: The store owner can fill 842/420 = <<842/420=2>>2 boxes with 420 erasers. After filling the boxes, there will be 842-840 = <<842-840=2>>2 erasers left over. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: A farmer harvested 461 carrots from his garden. He packs them into boxes, each box can hold up to 244 carrots. After packing as many full boxes as possible, how many carrots will be left unpacked?
Qwen2-Math 7B:
Reasoning: The farmer can pack 461/244 = <<461/244=1>>1 full box. After packing 1 full box, there will be 461-244 = <<461-244=217>>217 carrots left unpacked. ### Answer: 217
Expected answer: 217
Correct? Yes
Problem: The farmer found out that he had initially miscounted and he actually only harvested 11 carrots. After he tries to pack these into the boxes which each can hold up to 244 carrots, how many carrots will be left unpacked now?
Qwen2-Math 7B:
Reasoning: The farmer can pack 11/244 = <<11/244=0>>0 full boxes. After packing 0 full boxes, there will be 11-0 = <<11-0=11>>11 carrots left unpacked. ### Answer: 11
Expected answer: 11
Correct? Yes
Problem: A penguin scientist counts 309 penguins in a colony. She decides to tag them in groups of 293 for easier tracking. How many penguins will be in the final, possibly incomplete, group?
Qwen2-Math 7B:
Reasoning: The scientist will tag 309/293 = <<309/293=1>>1 group of penguins, with 309-293 = <<309-293=16>>16 penguins in the final, possibly incomplete, group. ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: The penguin scientist realizes she made a mistake and there were actually only 262 penguins in each group. How many penguins will be in the final, possibly incomplete, group now?
Qwen2-Math 7B:
Reasoning: The scientist will tag 262/293 = <<262/293=0>>0 groups of penguins, with 262-0 = <<262-0=262>>262 penguins in the final, possibly incomplete, group. ### Answer: 262
Expected answer: 47
Correct? No
Problem: A sandwich shop has 580 slices of bread. They use 18 slices of bread for each sandwich-making batch. After using up the bread in these batches, how many slices will they have left?
Qwen2-Math 7B:
Reasoning: The shop can make 580/18 = <<580/18=32.22222222222222>>32.22222222222222 batches of sandwiches. Since they can't make a fraction of a batch, they can make 32 batches. After making 32 batches, they will have 580 - (32 * 18) = <<580 - (32 * 18)=16>>16 slices of bread left.
Expected answer: 4
Correct? No
Problem: A tailor has 925 meters of fabric. The tailor uses 529 meters of fabric to make each dress. If the tailor uses the fabric evenly for each dress, how many meters of fabric will be left over after completing the dresses?
Qwen2-Math 7B:
Reasoning: The tailor will have 925-529 = <<925-529=396>>396 meters of fabric left over after completing the dresses.
Expected answer: 396
Correct? Yes
Problem: After making some dresses, the tailor now only has 62 meters of fabric left. If the tailor continues to use 529 meters of fabric to make each dress, how many meters of fabric will be left over after making the dresses?
Qwen2-Math 7B:
Reasoning: The tailor will have 62-529 = <<62-529=-467>>-467 meters of fabric left over after making the dresses. However, since the tailor cannot have a negative amount of fabric, this means that the tailor does not have enough fabric to make any more dresses.
Expected answer: 62
Correct? Yes
Problem: There are 976 tourists wanting to explore a castle. Each tour group throughout the day accommodates up to 530 people. After all the groups have taken off, how many tourists will be left for the last group of the day?
Qwen2-Math 7B:
Reasoning: The number of tourists left for the last group of the day is 976-530 = <<976-530=446>>446. ### Answer: 446
Expected answer: 446
Correct? Yes
Problem: What would happen if the number of tourists wanting to explore the castle was still 976, but this time each group could accommodate up to 726 people? How many tourists would be left for the last group of the day now?
Qwen2-Math 7B:
Reasoning: The number of tourists left for the last group of the day is 976-726 = <<976-726=250>>250. ### Answer: 250
Expected answer: 250
Correct? Yes