Problem: The gardener realizes afterwards that he initially miscounted the rose bushes in the field. It turns out there were not 80, but 84 rose bushes instead, each still producing 30 roses, and the storm still managed to blow away 43 roses. How many roses does he actually have remaining in the field after the correction?

Qwen2-Math 7B:

 Reasoning: The gardener has 84*30 = <<84*30=2520>>2520 roses in total.
After the storm, the gardener has 2520-43 = <<2520-43=2477>>2477 roses remaining in the field.
### Answer: 2477

Expected answer: 2477

Correct? Yes

Problem: Continuing from the original scenario, suppose we made a mistake in our measurements and realized that the dolphin, in fact, can leap (41 + 59) feet high instead of (3 + 59) feet. Considering this, if the dolphin still completes 89 jumps in a day, how many feet in total has the dolphin jumped in that day now?

Qwen2-Math 7B:

 Reasoning: The dolphin can leap 41 + 59 = <<41+59=100>>100 feet high.
The dolphin completes 89 jumps in a day, so the total distance jumped is 100 * 89 = <<100*89=8900>>8900 feet.
### Answer: 8900

Expected answer: 8900

Correct? Yes

Problem: Continuing from the original scenario, suppose the candy store started the day with 81 pieces of candy and received a delivery adding 6, but this time, they only sold 7 candies throughout the day. How many pieces of candy does the store now have left?

Qwen2-Math 7B:

 Reasoning: The candy store starts with 81 pieces of candy.
They receive a delivery adding another 6 candies, so they have 81+6 = <<81+6=87>>87 pieces of candy.
They sell 7 throughout the day, so they have 87-7 = <<87-7=80>>80 pieces of candy left.
### Answer: 80

Expected answer: 80

Correct? Yes

Problem: A sports store received a huge shipment of 6806 pairs of ice skates. After reconsideration, they decided to distribute the skates over 61 stores instead of the original 82. How many pairs of ice skates does each store receive now?

Qwen2-Math 7B:

 Reasoning: Each store receives 6806/61 = <<6806/61=111>>111 pairs of ice skates.

Expected answer: 6806/61

Correct? Yes

Problem: Suppose instead that the stationery store had 40 white erasers and 37 pink erasers initially. How many erasers would be there in total in that case?

Qwen2-Math 7B:

 Reasoning: There would be 40+37 = <<40+37=77>>77 erasers in total.
### Answer: 77

Expected answer: 77

Correct? Yes

Problem: The company found an error in their manufacturing record and realized they actually produced 43 batches of pens, not 10. Each batch still contained 39 pens. How many pens did the company actually produce?

Qwen2-Math 7B:

 Reasoning: The company actually produced 43*39 = <<43*39=1677>>1677 pens.
### Answer: 1677

Expected answer: 1677

Correct? Yes

Problem: Suppose that instead of each cow producing (99 + 58) litres of milk per day as previously stated, they actually produce only (5 + 58) litres of milk daily. How many litres of milk would the farm produce from cows in this case?

Qwen2-Math 7B:

 Reasoning: Each cow now produces 5+58 = <<5+58=63>>63 litres of milk per day.
The farm would produce 33*63 = <<33*63=2079>>2079 litres of milk in a day.
### Answer: 2079

Expected answer: 2079

Correct? Yes

Problem: In the original scenario, a grape vine produces 3344 grapes and the farmer has 38 equally productive grape vines. Now consider a new situation. Let's say the farmer had 75 equally productive vines instead of 38. How many grapes would each vine have produced now?

Qwen2-Math 7B:

 Reasoning: The total number of grapes produced by the 75 vines is still 3344.
To find the number of grapes produced by each vine, we divide the total number of grapes by the number of vines: 3344/75 = <<3344/75=44.586666666666664>>44.586666666666664.
Since we cannot have a fraction of a grape, we round the number to the nearest whole number: 45.
### Answer: 45

Expected answer: 3344/75

Correct? No

Problem: Considering the previous problem, suppose the region experienced a heavier snowfall of 90 cm (instead of 29 cm) today, while the 20 cm melt remained the same. How might this change the amount of snow now left?

Qwen2-Math 7B:

 Reasoning: Yesterday, the region received 93+90 = <<93+90=183>>183 cm of snow.
Today, 20 cm of snow has melted, so the total snow left is 183-20 = <<183-20=163>>163 cm.
### Answer: 163

Expected answer: 163

Correct? Yes

Problem: After measuring the giraffe's neck in meters, the zookeeper re-evaluates and discovers that his conversion tool was using an incorrect scale, where one meter actually equals 43 centimeters, not 5 centimeters. Given this new information, what is the length of the giraffe's neck in meters?

Qwen2-Math 7B:

 Reasoning: 275 centimeters is equal to 275/43 = <<275/43=6.395348837209302>>6.395348837209302 meters.
The length of the giraffe's neck is approximately 6.4 meters.
### Answer: 6.4

Expected answer: 275/43

Correct? No

Problem: Following from the previous scenario, consider instead that the furniture store originally had 79 chairs, but this time, they only received a shipment adding 4 more chairs before selling 45 chairs in a single day. How many chairs are now in the store under this altered situation?

Qwen2-Math 7B:

 Reasoning: The store had 79+4 = <<79+4=83>>83 chairs after receiving the shipment.
After selling 45 chairs, the store has 83-45 = <<83-45=38>>38 chairs now.
### Answer: 38

Expected answer: 38

Correct? Yes

Problem: If you can drive 304 miles on a full tank of gas which is divided into 4 equal parts, you've found that you can drive a certain distance on one part of the tank. If you refill this part of the tank 47 times, how many miles in total could you potentially drive?

Qwen2-Math 7B:

 Reasoning: If you can drive 76 miles on one part of the tank, and you refill this part 47 times, you can drive 76 * 47 = <<76*47=3572>>3572 miles in total.
### Answer: 3572

Expected answer: 3572

Correct? Yes

Problem: If instead of a tank which can hold enough gas to drive 304 miles, you have a smaller tank which holds enough gas to drive 304 miles, and you divide the tank into 91 equal parts, how many miles can you drive on one part of the tank?

Qwen2-Math 7B:

 Reasoning: 304 miles / 91 parts = <<304/91=3.3333333333333335>>3.3333333333333335 miles per part.
### Answer: 3.3333333333333335

Expected answer: 304/91

Correct? No

Problem: In the previous scenario, the shop sells ice skates at 25 dollars a pair on sale. After the increase, a pair of ice skates is priced at 33 dollars. If a customer only has 70 dollars, how much money will they have left after buying a pair of ice skates during the sale?

Qwen2-Math 7B:

 Reasoning: The customer will have 70-33 = <<70-33=37>>37 dollars left after buying a pair of ice skates during the sale.
### Answer: 37

Expected answer: 37

Correct? Yes

Problem: In the previous scenario, the price of ice skates was 25 dollars a pair before the price increase. Now, consider a scenario where the original price of the ice skates was 79 dollars a pair instead of 25 dollars. If the price was increased by the same amount, 8 dollars, how much would a pair of ice skates cost now?

Qwen2-Math 7B:

 Reasoning: The sale price of a pair of ice skates is 79+8 = <<79+8=87>>87 dollars.
### Answer: 87

Expected answer: 87

Correct? Yes

Problem: Continuing from the previous problem, if the river also carried a piece of debris that got an additional 94 miles downstream due to the wind in those 31 days, how far would the piece of debris have traveled in total?

Qwen2-Math 7B:

 Reasoning: The piece of debris would have traveled an additional 94 miles downstream due to the wind in those 31 days.
Therefore, the total distance the piece of debris would have traveled is 2976 + 94 = <<2976+94=3070>>3070 miles.
### Answer: 3070

Expected answer: 3070

Correct? Yes

Problem: Continuing from the previous problem, suppose the river flow was less than initially thought. Rather than flowing at a speed of 96 miles per day, it actually flows at a speed of 12 miles per day. How far would the river have traveled in 31 days at this slower speed?

Qwen2-Math 7B:

 Reasoning: The river now travels 12 miles per day, so in 31 days it would have travelled 12*31 = <<12*31=372>>372 miles.
### Answer: 372

Expected answer: 372

Correct? Yes

Problem: Following our previous scenario, let's consider that instead of dividing by 73, the velocity of the star's light was divided by 42. What would be the resulting speed of the light emitted by the star, given this new calculation?

Qwen2-Math 7B:

 Reasoning: The resulting speed of the light emitted by the star would be 1095/42 = <<1095/42=26.071428571428573>>26.071428571428573 miles per second.
### Answer: 26.071428571428573

Expected answer: 365/14

Correct? Yes

Problem: After 40 years instead of 51, a massive wind storm passes through the area removing 84 lemons from the total number of lemons the tree produced. Given this earlier timing of the wind storm, how many lemons did the lemon tree produce after the wind storm?

Qwen2-Math 7B:

 Reasoning: The lemon tree produced 99*40 = <<99*40=3960>>3960 lemons in 40 years.
After the wind storm, the lemon tree produced 3960-84 = <<3960-84=3876>>3876 lemons.
### Answer: 3876

Expected answer: 3876

Correct? Yes

Problem: Instead of the initial 89 blocks in each pack, John found out that 41 blocks were in each of his 4 packs. After losing 72 blocks, how many blocks does John have now?

Qwen2-Math 7B:

 Reasoning: John had 4*41 = <<4*41=164>>164 blocks initially.
After losing 72 blocks, John has 164-72 = <<164-72=92>>92 blocks now.
### Answer: 92

Expected answer: 92

Correct? Yes

Problem: In a revised count, it was discovered that the seashells were actually spread over 92 meters of the beach instead of 72 meters as previously thought. Now, how many seashells are there on average for each meter of the beach?

Qwen2-Math 7B:

 Reasoning: There are 5544/92 = <<5544/92=60.26>>60.26 seashells on average for each meter of the beach.
### Answer: 60.26

Expected answer: 1386/23

Correct? No

Problem: In a revision to the previous count, it turns out there were only 38 birds instead of 67 at the zoo originally. Given this, how many animals in the zoo were not birds?

Qwen2-Math 7B:

 Reasoning: There are 82-38 = <<82-38=44>>44 animals in the zoo that are not birds.
### Answer: 44

Expected answer: 44

Correct? Yes

Problem: In the same construction company's new plan, instead of building 36 houses they are planning to build 75 houses a month. If they managed to keep up this pace for the same period of 46 months, how many houses would they have built in total with this increased productivity?

Qwen2-Math 7B:

 Reasoning: The construction company would have built 75*46 = <<75*46=3450>>3450 houses in total with this increased productivity.
### Answer: 3450

Expected answer: 3450

Correct? Yes

Problem: Continuing from the previous situation, suppose the factory decided to cut down its monthly goal and now aims to produce only 50 windows in a month. Based on this new target, how many windows does the factory need to produce each day if it still operates for 31 days in a month?

Qwen2-Math 7B:

 Reasoning: The factory needs to produce 50/31 = <<50/31=1.6129032258064516>>1.6129032258064516 windows each day to meet its new goal.
### Answer: 1.6129032258064516

Expected answer: 50/31

Correct? Yes

Problem: After the 8 episodes of the 3rd season were aired, the TV series continued to air more episodes. In the remaining part of the 3rd season, they aired 80 episodes. They have also just finished airing all the 82 episodes of the 4th season. How many episodes have aired in total now?

Qwen2-Math 7B:

 Reasoning: The total number of episodes aired is 141+80+82 = <<141+80+82=303>>303.
### Answer: 303

Expected answer: 303

Correct? Yes

Problem: Let's imagine that in the first two seasons of the TV series there were fewer episodes than we initially thought. The 1st season had 66 episodes and the second season only had 8. After 8 more episodes of the 3rd season aired, how many total episodes have aired so far?

Qwen2-Math 7B:

 Reasoning: The total number of episodes aired is 66+8+8 = <<66+8+8=82>>82.
### Answer: 82

Expected answer: 82

Correct? Yes

Problem: Following the previous scenarios, let's reconsider the scenario like this: suppose the amount that John decided to spend on lunch was not 38 dollars, but actually 68 dollars. How much money does he have left in his wallet after this change?

Qwen2-Math 7B:

 Reasoning: John had 133-68 = <<133-68=65>>65 dollars left after buying lunch.
### Answer: 65

Expected answer: 65

Correct? Yes

Problem: In the bottling factory, an upgrade to the machines increases the manufacturing speed by 19 bottles per minute. After the upgrade, how many bottles does the factory fill every minute?

Qwen2-Math 7B:

 Reasoning: The factory fills 64+19 = <<64+19=83>>83 bottles every minute.
### Answer: 83

Expected answer: 83

Correct? Yes

Problem: In the bottling factory, imagine that before the upgrade, the machinery was even slower, filling bottles at a rate of 3840 bottles every 18 hours, instead of 60 minutes. How many bottles were being filled every hour in that case?

Qwen2-Math 7B:

 Reasoning: The factory filled 3840/18 = <<3840/18=213.33333333333334>>213.33333333333334 bottles every hour.
### Answer: 213.33333333333334

Expected answer: 640/3

Correct? Yes

Problem: In the previous scenario, imagine that instead of adding 49 treasures to each gnome's share, the dragon decided to add 79 treasures. How many treasures does each gnome now have?

Qwen2-Math 7B:

 Reasoning: Each gnome initially has 1702/37 = <<1702/37=46>>46 treasures.
After adding 79 more treasures, each gnome has 46+79 = <<46+79=125>>125 treasures.
### Answer: 125

Expected answer: 125

Correct? Yes

Problem: Continuing from the previous scenario, let's say the frog has increased its leaping ability and can now hop 83 inches in total with an average of 6 inches per leap. How many leaps does it take for the frog to complete this new journey?

Qwen2-Math 7B:

 Reasoning: The frog hops 6 inches per single leap.
The frog hops 83/6 = <<83/6=13.833333333333334>>13.833333333333334 times to complete the new journey.
Since the frog cannot make a fraction of a leap, we round up to the nearest whole number.
### Answer: 14

Expected answer: 83/6

Correct? No

Problem: Continuing with the scenario of the cheese factory, let's say the factory now operates 31 days a month rather than 85 days, with the overall cheese production still being 5865 kg. How much cheese would now be produced each day?

Qwen2-Math 7B:

 Reasoning: The factory now produces 5865/31 = <<5865/31=189.19354838709677>>189.19354838709677 kg of cheese each day.
### Answer: 189.19354838709677

Expected answer: 5865/31

Correct? Yes

Problem: In a new scenario, where an exact amount of 1 cucumber is damaged instead of 74 in the section growing 38 plants, how many cucumbers would now be available for sale from that section?

Qwen2-Math 7B:

 Reasoning: The farm yields 2592/54 = <<2592/54=48>>48 cucumbers per plant.
A section of the farm grows 38 plants, so the total yield is 38*48 = <<38*48=1824>>1824 cucumbers.
Subtracting the 1 damaged cucumber, the farm has 1824-1 = <<1824-1=1823>>1823 cucumbers available for sale.
### Answer: 1823

Expected answer: 1823

Correct? Yes

Problem: If you decide to buy a simple keychain from the same craftsman instead, which costs the same as a single installment of your previous purchase, how much does it cost if each installment was 83 dollars divided by 83?

Qwen2-Math 7B:

 Reasoning: The cost of the wallet was 2407 dollars, and it was paid in 83 installments.
Therefore, each installment was 2407/83 = <<2407/83=29>>29 dollars.
If you buy a simple keychain that costs the same as a single installment, it would cost 29 dollars.
### Answer: 29

Expected answer: 1

Correct? No

Problem: In the original problem, the big grizzly bear ate 2726 ounces of salmon over a 58-day summer period. However, what would have been the daily average if the bear had eaten the same total amount of salmon but over a shorter 50-day period instead?

Qwen2-Math 7B:

 Reasoning: If the bear had eaten the same total amount of salmon over a 50-day period, the daily average would be 2726/50 = <<2726/50=54.52>>54.52 ounces of salmon each day.
### Answer: 54.52

Expected answer: 1363/25

Correct? Yes

Problem: Let's consider the farmer's situation again. What if, instead of 77 days, the farmer only collected carrots from his patches of land for a period of 22 days. How many total carrots would he have collected from his patches during this time?

Qwen2-Math 7B:

 Reasoning: The farmer collects 26+16 = <<26+16=42>>42 carrots per day.
The farmer collects 42*22 = <<42*22=924>>924 carrots in total.
### Answer: 924

Expected answer: 924

Correct? Yes

Problem: In the next batch, the chef decided to add an extra 25g of sugar to her special cake recipe to make it sweeter. How much sugar does she use now for each cake?

Qwen2-Math 7B:

 Reasoning: The chef now uses 69+25 = <<69+25=94>>94g of sugar for each cake.
### Answer: 94

Expected answer: 94

Correct? Yes

Problem: After receiving some feedback, the chef used less sugar in her next batch of cakes. She used only 65g for seven cakes. How much sugar does she use now for each cake?

Qwen2-Math 7B:

 Reasoning: The chef now uses 65/7 = <<65/7=9.285714285714286>>9.285714285714286g of sugar for each cake.
### Answer: 9.285714285714286

Expected answer: 65/7

Correct? Yes

Problem: Following up with the earlier situation of the kite maker who had 41 blue, 63 red, and 57 green kites, gave away 98 kites, and created an additional 3 kites: If the kite maker decided to ramp up production and multiply their current inventory by 18, then add the original inventory to this increased production, how many kites would the they have now?

Qwen2-Math 7B:

 Reasoning: The kite maker initially has 41+63+57 = <<41+63+57=161>>161 kites.
After giving away 98 kites, the kite maker has 161-98 = <<161-98=63>>63 kites.
After creating 3 additional kites, the kite maker has 63+3 = <<63+3=66>>66 kites.
If the kite maker multiplies their current inventory by 18, they would have 66*18 = <<66*18=1188>>1188 kites.
If the kite maker adds the original inventory to this increased production, they would have 1188+161 = <<1188+161=1349>>1349 kites.
### Answer: 1349

Expected answer: 1254

Correct? No

Problem: After the kite maker gave away some kites and made new ones, let's change the circumstances a bit. Instead of giving away 98 kites, they only gave away 19 kites. Taking into account that they still made an additional 3 kites, how many kites does the maker have now?

Qwen2-Math 7B:

 Reasoning: The kite maker initially has 41+63+57 = <<41+63+57=161>>161 kites.
After giving away 19 kites, the kite maker has 161-19 = <<161-19=142>>142 kites.
After creating 3 additional kites, the kite maker has 142+3 = <<142+3=145>>145 kites.
### Answer: 145

Expected answer: 145

Correct? Yes

Problem: After reviewing their production numbers, the teddy bear company realized that they actually produce 7644 teddy bears in a span of 50 days, not 91 days. How many teddy bears does the company approximately makes each day now?

Qwen2-Math 7B:

 Reasoning: The company makes 7644/50 = <<7644/50=152.88>>152.88 teddy bears each day.

Expected answer: 3822/25

Correct? Yes

Problem: In the previous question, we considered a speed decrease from 68 mph to 28 mph. For this question, let's assume the train didn't have to slow down that much, but travelled instead at a speed of 56 mph. Over the same 21 hours, calculate the revised total distance travelled by the train.

Qwen2-Math 7B:

 Reasoning: The train would have traveled 56*21 = <<56*21=1176>>1176 miles at 56 mph.
The difference in distance traveled compared to the original 68 mph scenario is 1428-1176 = <<1428-1176=252>>252 miles.

Expected answer: 252

Correct? Yes

Problem: The alien spaceship initially traveled 95 light-years to reach Earth. But let's consider a scenario where they could only stop 60 light-years along the way at a space buoy for refueling instead of 70 light-years. In that case, how many light-years would the spaceship have to travel after refueling to reach Earth?

Qwen2-Math 7B:

 Reasoning: If the spaceship could only stop 60 light-years along the way, it would have traveled 95-60 = <<95-60=35>>35 light-years after refueling to reach Earth.
### Answer: 35

Expected answer: 35

Correct? Yes

Problem: In our previous scenario, the character started with a health value of 82. What if, instead of being attacked and losing 69 health points, he was attacked by a weaker rival character and only lost 33 health points. What would be the character's remaining health value in this new scenario?

Qwen2-Math 7B:

 Reasoning: The character's remaining health value would be 82-33 = <<82-33=49>>49.
### Answer: 49

Expected answer: 49

Correct? Yes

Problem: The skateboard company decides to extend its production over 21 days but had to discard 65 skateboards due to quality issues. How many skateboards did they make in the span of these 21 days after discarding the faulty ones?

Qwen2-Math 7B:

 Reasoning: The company makes 128*21 = <<128*21=2688>>2688 skateboards in 21 days.
After discarding 65 faulty skateboards, the company made 2688-65 = <<2688-65=2623>>2623 skateboards in the span of these 21 days.
### Answer: 2623

Expected answer: 2623

Correct? Yes

Problem: Suppose now the company produces 82 freestyle skateboards instead of 36, while still producing 92 downhill skateboards daily. How many skateboards does it make in total in a day?

Qwen2-Math 7B:

 Reasoning: The company makes 82+92 = <<82+92=174>>174 skateboards in total in a day.
### Answer: 174

Expected answer: 174

Correct? Yes

Problem: The café also has another branch. If the other branch also made the same amount of money from selling hot chocolate and marshmallows in a day, what would be the total revenue from both branches?

Qwen2-Math 7B:

 Reasoning: The total revenue from both branches would be 3334*2 = <<3334*2=6668>>6668 dollars.
### Answer: 6668

Expected answer: 6668

Correct? Yes

Problem: Suppose that on another day, the café priced their hot chocolate differently: they sold it for 42 dollars per cup but only sold 78 cups, and made an additional 24 dollars from selling marshmallows. What would be the total revenue of that day?

Qwen2-Math 7B:

 Reasoning: The café made 42*78 = <<42*78=3276>>3276 dollars from selling hot chocolate.
The café made 3276+24 = <<3276+24=3300>>3300 dollars in total from selling hot chocolate and marshmallows.
### Answer: 3300

Expected answer: 3300

Correct? Yes

Problem: Suppose that the river tour boat could originally only hold 58 adults. It has now been modified to increase its capacity by 3 more adults. Taking this into account, how many total adults can the boat hold now?

Qwen2-Math 7B:

 Reasoning: The boat can now hold 58 adults + 3 more adults = <<58+3=61>>61 adults.
### Answer: 61

Expected answer: 61

Correct? Yes

Problem: If in the next month, the monkey received additional bananas, bringing its total to ((360 bananas / 12 months) + 16 extra bananas + 79 more bananas) but then 67 of them were stolen, how many bananas does the monkey have now?

Qwen2-Math 7B:

 Reasoning: The monkey initially had (360/12) + 16 = <<360/12=30>>30 + 16 = <<30+16=46>>46 bananas.
After receiving 79 more bananas, the monkey had 46 + 79 = <<46+79=125>>125 bananas.
After 67 bananas were stolen, the monkey had 125 - 67 = <<125-67=58>>58 bananas.
### Answer: 58

Expected answer: 58

Correct? Yes

Problem: What if, instead of getting 360 bananas a year, the monkey only got 360 bananas every 20 months? If the monkey also got 16 extra bananas per month, how many bananas would the monkey get in a month?

Qwen2-Math 7B:

 Reasoning: The monkey gets (360/20) + 16 = <<360/20=18>>18 + 16 = <<18+16=34>>34 bananas per month.
### Answer: 34

Expected answer: 34

Correct? Yes

Problem: Continuing from the previous problem, what if the starfish was an unusual species with 17 arms instead of 5? If there were still 360 degrees in a circle, how many degrees would be in each section if it were to be equally divided amongst the starfish's arms?

Qwen2-Math 7B:

 Reasoning: 360/17 = <<360/17=21.176470588235294>>21.176470588235294 degrees in each section.
### Answer: 21.176470588235294

Expected answer: 360/17

Correct? Yes

Problem: The toy store received a special toy order of 1 rare stuffed panda in addition to their previous order. After adding the special order, how many stuffed animals will the toy store have in total?

Qwen2-Math 7B:

 Reasoning: The toy store will have 146+1 = <<146+1=147>>147 stuffed animals in total.
### Answer: 147

Expected answer: 147

Correct? Yes

Problem: On Wednesday, Rachel watched 68 minutes of TV but decided to reduce her screen time by the amount she had watched on Monday. How many total minutes of TV did Rachel watch on Monday, Tuesday and Wednesday after reducing her Wednesday screen time?

Qwen2-Math 7B:

 Reasoning: Rachel watched 68-35 = <<68-35=33>>33 minutes of TV on Wednesday after reducing her screen time.
Rachel watched 35+61+33 = <<35+61+33=129>>129 minutes of TV on Monday, Tuesday and Wednesday after reducing her Wednesday screen time.
### Answer: 129

Expected answer: 129

Correct? Yes

Problem: If on Monday instead of watching 35 minutes of TV, Rachel watched 37 minutes. Then, how many total minutes of TV did she watch on Monday and Tuesday?

Qwen2-Math 7B:

 Reasoning: Rachel watched 37+61 = <<37+61=98>>98 minutes of TV on Monday and Tuesday.
### Answer: 98

Expected answer: 98

Correct? Yes

Problem: Earlier we calculated that a dolphin needs approximately 96 kilograms of fish and 22 kilograms of squid every day to stay healthy. But what if instead, each day the dolphin had 96 kilograms of fish and only 8 kilograms of squid? Then, how much total food in kilograms would the dolphin need if it ate this diet unchanged for 59 days?

Qwen2-Math 7B:

 Reasoning: The dolphin needs 96+8 = <<96+8=104>>104 kilograms of food every day.
The dolphin needs 104*59 = <<104*59=6136>>6136 kilograms of food in total for 59 days.
### Answer: 6136

Expected answer: 6136

Correct? Yes

Problem: Following the previous problem, if Mandy decides to multiply the numbers of the building blocks she ends up with by the result of dividing 215 by 43, how many building blocks would she have then?

Qwen2-Math 7B:

 Reasoning: Mandy has 1098*215/43 = <<1098*215/43=510>>510 building blocks.
### Answer: 510

Expected answer: 5490

Correct? No

Problem: Continuing with the previous problem, suppose Mandy initially had 18 building blocks and received another 55, instead of the original 43. If she then multiplies the total by the initial 18 building blocks she had, how many building blocks would she have now?

Qwen2-Math 7B:

 Reasoning: Mandy has 18+55 = <<18+55=73>>73 building blocks.
Mandy has 73*18 = <<73*18=1314>>1314 building blocks in the end.
### Answer: 1314

Expected answer: 1314

Correct? Yes

Problem: Suppose our ballerina decided to lessen her weekend practices to (28 - 11) hours but increased the frequency to 66 times. How many hours did she practice in total on the weekends now?

Qwen2-Math 7B:

 Reasoning: The ballerina practices (28 - 11) * 66 = <<(28 - 11) * 66=1452>>1452 hours on weekends.
### Answer: 1452

Expected answer: 1122

Correct? No

Problem: After the manufacturer's initial count of the standard cards and the division of premium cards, they discover a miscalculation. Instead of 59 different kinds of cards in the deck, there are actually 90 kinds. If for each kind, there are still 59 cards, how many total standard cards are there in this deck?

Qwen2-Math 7B:

 Reasoning: There are 90*59 = <<90*59=5310>>5310 cards in the deck.
### Answer: 5310

Expected answer: 5310

Correct? Yes

Problem: The farmer reevaluates his count and realizes that he made a mistake in his initial counting. He actually added 65 new vines to his field, instead of 93, then added 73 more vines and had 92 vines die. How many grapevines does he have in his field now with this corrected count?

Qwen2-Math 7B:

 Reasoning: The farmer has 65+73 = <<65+73=138>>138 vines after adding the new ones.
After 92 vines died, the farmer has 138-92 = <<138-92=46>>46 vines left.
### Answer: 46

Expected answer: 46

Correct? Yes

Problem: In the previous problem, we started with the blanket factory making 13 blankets in the morning. Let's consider what would happen if instead, they made 92 blankets in the morning, while still making 81 in the afternoon and returning 59 due to defects. Each blanket is still sold at a price equal to 39 times the total number of good blankets they have, plus the number of good blankets. What's the new total value of the blankets they've sold?

Qwen2-Math 7B:

 Reasoning: The factory makes 92+81 = <<92+81=173>>173 blankets in total.
After returning 59 defective blankets, they have 173-59 = <<173-59=114>>114 good blankets.
The total value of the blankets sold is 39*114 + 114 = <<39*114+114=4482>>4482.
### Answer: 4482

Expected answer: 4560

Correct? No

Problem: In our previous scenario, suppose instead of covering the distance in 20 equal stages, the bus decided to only stop 4 times, dividing the journey into equal parts. In that case, how many miles would the bus need to travel per stage?

Qwen2-Math 7B:

 Reasoning: The bus would need to travel 1300/4 = <<1300/4=325>>325 miles per stage.
### Answer: 325

Expected answer: 325

Correct? Yes

Problem: Suppose the region actually usually receives 69 inches of rain each year, instead of 53 as we previously thought. If it still received 7 inches less than the usual amount in the year we're considering, how many inches of rain did it receive that year?

Qwen2-Math 7B:

 Reasoning: The region received 69-7 = <<69-7=62>>62 inches of rain that year.
### Answer: 62

Expected answer: 62

Correct? Yes

Problem: Originally, the watchmaker removed 80 gears from the watch, leaving a certain number of gears. But what if the watchmaker only removed 8 gears instead of 80 from the total of 98 gears in the main mechanism and 61 gears in a side mechanism? How many gears would remain in the watch?

Qwen2-Math 7B:

 Reasoning: The total number of gears in the watch before service is 98+61 = <<98+61=159>>159.
If the watchmaker only removed 8 gears, the number of gears left in the watch would be 159-8 = <<159-8=151>>151.
### Answer: 151

Expected answer: 151

Correct? Yes

Problem: In addition to the binoculars already distributed, each store received an additional shipment of binoculars from a second manufacturing facility. The second facility produced 4104 binoculars and divided them equally among 57 stores. After accounting for this additional shipment, how many binoculars does each store end up with in total?

Qwen2-Math 7B:

 Reasoning: The second facility produced 4104/57 = <<4104/57=72>>72 binoculars per store.
After accounting for the additional shipment, each store ends up with 9+72 = <<9+72=81>>81 binoculars.
### Answer: 81

Expected answer: 81

Correct? Yes

Problem: In a revision to the initial report, it turns out that 19 defective pieces were found in each store's binocular stock, rather than the originally believed 25. After making this correction, how many binoculars does each store end up with from the initial shipment?

Qwen2-Math 7B:

 Reasoning: Each store gets 1462/43 = <<1462/43=34>>34 binoculars.
After subtracting 19 defective pieces, each store ends up with 34-19 = <<34-19=15>>15 binoculars.
### Answer: 15

Expected answer: 15

Correct? Yes

Problem: Following the previous scenario, let's revisit the promotional event. Suppose this time the shop had decided to multiply the total number of cameras by 56 instead of 77 after receiving the same initial stock of 71 new DSLR cameras. How many cameras would the shop have had for promotion in this case?

Qwen2-Math 7B:

 Reasoning: The shop has 25+71 = <<25+71=96>>96 cameras after receiving the delivery.
The shop would have 96*56 = <<96*56=5376>>5376 cameras for promotion.
### Answer: 5376

Expected answer: 5376

Correct? Yes

Problem: In a similar situation as before, the farmer started his day with a different quantity of 95 tomatoes in his basket. Just like the previous day, by midday, he managed to harvest some more, bringing the total to 95 + 82 tomatoes in the basket. Unfortunately, he found that 37 of these tomatoes were not ripe enough to sell. How many ripe tomatoes did the farmer have left in his basket after this day?

Qwen2-Math 7B:

 Reasoning: The farmer has 95 + 82 = <<95+82=177>>177 tomatoes in total.
After removing the unsellable ones, the farmer has 177 - 37 = <<177-37=140>>140 tomatoes left that are ready to sell.
### Answer: 140

Expected answer: 140

Correct? Yes

Problem: Continuing from the initial situation in the soap manufacturing factory, suppose now they have decided to cut the large soap blocks into smaller bars such that each block can now be cut into 1424 bars of soap. However, this time they plan to package the soap in bundles of 36 bars each instead of 16. How many packages can they make from one large block of soap under this new arrangement?

Qwen2-Math 7B:

 Reasoning: 1424/36 = <<1424/36=39.555555555555555>>39.555555555555555 packages can be made from one large block of soap.
However, since we cannot have a fraction of a package, we round down to the nearest whole number.
### Answer: 39

Expected answer: 356/9

Correct? No

Problem: Continuing from the previous scenario, what if the printer only printed 2 sheets of paper with 4 letters each second instead of 37. Keeping the same printing duration of 95 seconds, how many letters would have been printed then?

Qwen2-Math 7B:

 Reasoning: The printer prints 2*4 = <<2*4=8>>8 letters per second.
In 95 seconds, the printer will print 8*95 = <<8*95=760>>760 letters.
### Answer: 760

Expected answer: 760

Correct? Yes

Problem: After reviewing the plane's logbook, the crew realizes there was a mistake in their calculations. Instead of covering 360,000 miles to travel around the world, it actually only took them 81,000 miles. Given this, how many days would it have taken them to travel around the world at a rate of 72,000 miles per day?

Qwen2-Math 7B:

 Reasoning: The plane traveled 81,000 miles, which is 81,000/72,000 = <<81000/72000=1.125>>1.125 days.
### Answer: 1.125

Expected answer: 9/8

Correct? Yes

Problem: After re-counting the initial logs at the start of the camping trip, there were actually 48 logs, not 56. After using up 15 logs, with this new count, how many logs are now left for the rest of the trip?

Qwen2-Math 7B:

 Reasoning: There are 48-15 = <<48-15=33>>33 logs left for the rest of the trip.
### Answer: 33

Expected answer: 33

Correct? Yes

Problem: After paying the tax and buying the 23 pairs of binoculars, the store owner decides to purchase an additional single pair of binoculars that has a discount of $95. What is the total amount the store owner will need to pay now?

Qwen2-Math 7B:

 Reasoning: The cost of the additional pair of binoculars after the discount is 27-95 = <<27-95=-68>>-68 dollars.
The total amount the store owner will need to pay is 630-68 = <<630-68=562>>562 dollars.
### Answer: 562

Expected answer: 562

Correct? Yes

Problem: After the store owner's last transaction, a new shipment of binoculars came in with a lower price. This time, each pair costs $27 and there's a fixed tax of $9. If the store owner decides to buy 13 pairs from the new shipment, how much would the total cost be now?

Qwen2-Math 7B:

 Reasoning: The total cost of the binoculars is 13*27 = <<13*27=351>>351 dollars.
The total cost after tax is 351+9 = <<351+9=360>>360 dollars.
### Answer: 360

Expected answer: 360

Correct? Yes

Problem: Following on from the previous problem: The pirate made a mistake while counting his treasure. He originally thought that he had found 91 gold coins on another island, but it turned out there were only 9 gold coins. With the 22 coins he found on an island, 9 on another island, and 33 hidden in a chest, how many coins does the pirate have now?

Qwen2-Math 7B:

 Reasoning: The pirate now has 22+9+33 = <<22+9+33=64>>64 gold coins in total.
### Answer: 64

Expected answer: 64

Correct? Yes

Problem: In our previous scenario, instead of adding 13 phones, suppose the phone manufacturer adds an additional 80 phones after producing phones for 33 hours. How many phones are produced in total at this time now?

Qwen2-Math 7B:

 Reasoning: The phone manufacturer produces 990/22 = <<990/22=45>>45 phones per hour.
After 33 hours, they have produced 45*33 = <<45*33=1485>>1485 phones.
After adding 80 more phones, the total production is 1485+80 = <<1485+80=1565>>1565 phones.
### Answer: 1565

Expected answer: 1565

Correct? Yes

Problem: After figuring out the total number of windows the maintenance team cleaned in a day, let's consider a different scenario. What if the building had originally been built with 704 windows spread over 71 floors instead of 8? How many windows would there be on each floor then?

Qwen2-Math 7B:

 Reasoning: The building has 704 windows in total and 71 floors. To find the number of windows on each floor, we divide the total number of windows by the number of floors: 704/71 = <<704/71=9.91>>9.91.
Since we can't have a fraction of a window, we round down to the nearest whole number, which is 9.
### Answer: 9

Expected answer: 704/71

Correct? No

Problem: In a small town, each household owns an average of 77 cats. If there are 69 households in the town, there would be a certain number of cats in total. However, due to some circumstances, 91 of these cats had to be moved to another town. How many cats are left in the town now?

Qwen2-Math 7B:

 Reasoning: There are 77*69 = <<77*69=5313>>5313 cats in total.
After moving 91 cats to another town, there are 5313-91 = <<5313-91=5222>>5222 cats left in the town.
### Answer: 5222

Expected answer: 5222

Correct? Yes

Problem: Originally, the chocolate bar factory had 87 machines running every day instead of 28. If 2 of the machines break down, as it happened in the previous scenario, how many machines would still be producing chocolate bars?

Qwen2-Math 7B:

 Reasoning: The factory originally had 87 machines, and 2 machines break down. Therefore, the number of machines still producing chocolate bars is 87-2 = <<87-2=85>>85.
### Answer: 85

Expected answer: 85

Correct? Yes

Problem: After creating and combining his different candle types, the candlemaker's friend gifted him an additional 7 candles they made. Now, how many candles does the candlemaker have in total?

Qwen2-Math 7B:

 Reasoning: The candlemaker now has 77+7 = <<77+7=84>>84 candles in total.
### Answer: 84

Expected answer: 84

Correct? Yes

Problem: The candlemaker originally thought he had made 6 vanilla-scented candles, but he actually made 8 instead. Given this correction, with everything else the same, how many candles does the candlemaker have in total now?

Qwen2-Math 7B:

 Reasoning: The candlemaker originally thought he had 6 vanilla-scented candles, but he actually made 8 instead.
This means he has 77-6+8 = <<77-6+8=81>>81 candles in total now.
### Answer: 81

Expected answer: 79

Correct? No

Problem: After finding the sum of 12, 4, and 71, add 15 to the result. What is the new total?

Qwen2-Math 7B:

 Reasoning: The sum of 12, 4, and 71 is 87. Adding 15 to 87 gives 87+15 = <<87+15=102>>102.
### Answer: 102

Expected answer: 102

Correct? Yes

Problem: Imagine that initially instead of 12, you started with 53. Now, what would be the result of adding the numbers 53, 4, and 71 together?

Qwen2-Math 7B:

 Reasoning: 53+4+71 = <<53+4+71=128>>128
### Answer: 128

Expected answer: 128

Correct? Yes

Problem: In the same puzzle game, consider that to complete a level, a player now requires 3795 points but the points are gained in increments of 19 instead of 69. How many increments of 19 points are now needed to gather the required points to complete the level?

Qwen2-Math 7B:

 Reasoning: The player needs to gain 3795/19 = <<3795/19=199>>199 increments to gain the points required to complete the level.
### Answer: 199

Expected answer: 3795/19

Correct? No

Problem: Suppose the pirate initially found a smaller chest with only 6 gemstones, each still worth 57 gold coins, along with an additional 42 gold coins. How many gold coins would be the total worth of this smaller chest?

Qwen2-Math 7B:

 Reasoning: The total worth of the gemstones is 6*57 = <<6*57=342>>342 gold coins.
The total worth of the smaller chest is 342+42 = <<342+42=384>>384 gold coins.
### Answer: 384

Expected answer: 384

Correct? Yes

Problem: If the pet store decides to double its quantity of each species of mouse – the white mice, brown mice, and black mice, how many mice will the store have then?

Qwen2-Math 7B:

 Reasoning: The pet store will have 2*35 = <<2*35=70>>70 white mice, 2*86 = <<2*86=172>>172 brown mice, and 2*39 = <<2*39=78>>78 black mice.
The pet store will have 70+172+78 = <<70+172+78=320>>320 mice in total.
### Answer: 320

Expected answer: 320

Correct? Yes

Problem: If the pet store actually had 31 black mice instead of 39 black mice along with the 35 white mice and 86 brown mice, how many mice in total would the pet store then have?

Qwen2-Math 7B:

 Reasoning: The pet store would have 35+86+31 = <<35+86+31=152>>152 mice in total.
### Answer: 152

Expected answer: 152

Correct? Yes

Problem: The soap factory realized that instead of producing 97 bars of soap per batch, they had actually been producing only 43 bars per batch due to a measuring error. Given this new information, how many bars of soap were actually produced over the 94 batches made on the first day?

Qwen2-Math 7B:

 Reasoning: The factory produced 43*94 = <<43*94=4042>>4042 bars of soap in one day.
### Answer: 4042

Expected answer: 4042

Correct? Yes

Problem: After reviewing the production data, the toy car factory realized there was a mistake in their calculation. They actually produce only 4 toy cars every minute instead of 5. If they continue to produce for 76 minutes and add another batch of 49 toy cars as before, how many toy cars will the factory have now?

Qwen2-Math 7B:

 Reasoning: The factory produces 4*76 = <<4*76=304>>304 toy cars in 76 minutes.
The factory has 304+49 = <<304+49=353>>353 toy cars now.
### Answer: 353

Expected answer: 353

Correct? Yes

Problem: In a similar situation, another farmer currently owns 25 km of farmland. They also decided to expand by 77 km, but like the previous farmer, had to give back 71 km due to legal issues. How many kilometers does this second farmer have left after this expansion and subsequent decrease?

Qwen2-Math 7B:

 Reasoning: The second farmer expanded his property by 77 km, so he had 25+77 = <<25+77=102>>102 km.
However, he had to return 71 km due to legal issues, so he had 102-71 = <<102-71=31>>31 km left.
### Answer: 31

Expected answer: 31

Correct? Yes

Problem: A paint company is preparing 8930 liters of a specific color. If they can fill up a paint bucket with 95 liters of paint, how many buckets will they be able to fill up completely? After the initial sales, the company realized they were missing 73 paint buckets. But soon they found 59 buckets in the warehouse. After adding these found buckets, how many buckets does the company have in total now?

Qwen2-Math 7B:

 Reasoning: The company initially had 8930/95 = <<8930/95=94>>94 buckets.
After finding 59 more buckets, the company now has 94+59 = <<94+59=153>>153 buckets in total.
### Answer: 153

Expected answer: 80

Correct? No

Problem: Suppose the bubble machine was actually more efficient and could produce 3654 bubbles with just 47 ounces of bubble fluid. With this rate, how many bubbles can it make with 1 ounce of bubble fluid?

Qwen2-Math 7B:

 Reasoning: The bubble machine can make 3654/47 = <<3654/47=78>>78 bubbles with 1 ounce of bubble fluid.
### Answer: 78

Expected answer: 3654/47

Correct? No

Problem: Considering the previous scenario, if instead of using 13 apples daily for the fruit salads, they started using 55 apples, how many apples did they use in total when they made fruit salads for 30 days?

Qwen2-Math 7B:

 Reasoning: The juice bar used 55*30 = <<55*30=1650>>1650 apples to make fruit salads for 30 days.
### Answer: 1650

Expected answer: 1650

Correct? Yes

Problem: Following the previous scenario, suppose the paleontologists revised their calculations and found that the dinosaur species was actually laying eggs every 47 minutes, not 60 as originally thought. In that case, how many total eggs would the dinosaur have laid if it had been laying eggs for 1620 minutes straight?

Qwen2-Math 7B:

 Reasoning: If the dinosaur species was laying eggs every 47 minutes, then in 1620 minutes, they would have laid 1620/47 = <<1620/47=34.468085106382975>>34.468085106382975 eggs. Since we can't have a fraction of an egg, we round down to the nearest whole number, which is 34 eggs.
### Answer: 34

Expected answer: 1620/47

Correct? No

Problem: In the original shipment to the library, suppose there were 95 science fiction novels instead of 67. With the 55 romance novels and 43 mystery novels remaining the same, how many new books did the library receive now?

Qwen2-Math 7B:

 Reasoning: The library received 55+43+95 = <<55+43+95=193>>193 new books.
### Answer: 193

Expected answer: 193

Correct? Yes

Problem: Building on our beachcomber's tale, after counting his 42-day collection of seashells, he accidentally loses one seashell down a seaside crevice. Disappointed but not defeated, he decides to collect 32 more seashells the next day. How many seashells does he have in total after adding the new batch and accounting for the lost seashell?

Qwen2-Math 7B:

 Reasoning: The beachcomber had 3164 seashells after 42 days.
After losing one seashell, he had 3164-1 = <<3164-1=3163>>3163 seashells.
After adding 32 more seashells, he had 3163+32 = <<3163+32=3195>>3195 seashells in total.
### Answer: 3195

Expected answer: 3195

Correct? Yes

Problem: Let's revisit our beachcomber. After reconsidering his collection habit, he realizes he has been actually collecting an average of 89 seashells per day instead of 74, over the same 42 day period. He still found that additional 56 seashells hidden in the sand. Now, how many seashells does he have in total after 42 days?

Qwen2-Math 7B:

 Reasoning: The beachcomber collected 89*42 = <<89*42=3738>>3738 seashells in 42 days.
The beachcomber had 3738+56 = <<3738+56=3794>>3794 seashells in total after 42 days.
### Answer: 3794

Expected answer: 3794

Correct? Yes