MathCAMPS Logo

Claude-3 Haiku on 8.EE.C.8

Common Core Standard 8.EE.C.8

This standard covers the following:

Analyze and solve pairs of simultaneous linear equations.

🔗 Problem

Problem: Let's find the values of variables q and s by solving the following system of equations: 1. (40 * s) - (91 * q) = 37 2. (30 * s) + (12 * q) = 121

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve for q in the second equation.
(30 * s) + (12 * q) = 121
12 * q = 121 - (30 * s)
q = (121 - (30 * s)) / 12

Step 2: Substitute the expression for q into the first equation.
(40 * s) - (91 * ((121 - (30 * s)) / 12)) = 37
(40 * s) - (91 * (121 / 12) - (91 * (30 * s) / 12)) = 37
(40 * s) - (7,533 - (227.5 * s)) = 37
(40 * s) - 7,533 + 227.5 * s = 37
267.5 * s - 7,533 = 37
267.5 * s = 7,570
s = 28.3

Step 3: Substitute the value of s into the expression for q.
q = (121 - (30 * 28.3)) / 12
q = (121 - 849) / 12
q = -728 / 12
q = -60.67

Therefore, the values of the variables are:
q = -60.67
s = 28.3

### Answer: q = -60.67, s = 28.3

Expected answer: {q: 373/321, s: 2291/642}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of b and m: 4 * b + 44 * m = 180 and 79 * m - 6 * b = 48.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Given equations:
4 * b + 44 * m = 180
79 * m - 6 * b = 48

Step 1: Solve for b in the second equation.
79 * m - 6 * b = 48
6 * b = 79 * m - 48
b = (79 * m - 48) / 6

Step 2: Substitute the expression for b in the first equation.
4 * b + 44 * m = 180
4 * ((79 * m - 48) / 6) + 44 * m = 180
(316 * m - 192) / 6 + 44 * m = 180
(316 * m - 192 + 264 * m) / 6 = 180
580 * m / 6 = 180
m = 180 * 6 / 580
m = 1.8571

Step 3: Substitute the value of m in the expression for b.
b = (79 * 1.8571 - 48) / 6
b = (146.3321 - 48) / 6
b = 98.3321 / 6
b = 16.3887

Therefore, the values of b and m are:
b = 16.3887
m = 1.8571

### Answer: b = 16.3887, m = 1.8571

Expected answer: {b: 3027/145, m: 318/145}

Correct? No

🔗 Problem

Problem: Solve the following system of equations to find the values of o and g: 42 * o - 15 * g = 28 47 * o + 29 * g = 141.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Given equations:
42 * o - 15 * g = 28
47 * o + 29 * g = 141

Step 1: Solve for o in the first equation.
42 * o - 15 * g = 28
42 * o = 28 + 15 * g
o = (28 + 15 * g) / 42

Step 2: Substitute the expression for o in the second equation.
47 * o + 29 * g = 141
47 * ((28 + 15 * g) / 42) + 29 * g = 141
(47 * 28 + 47 * 15 * g) / 42 + 29 * g = 141
(1316 + 705 * g) / 42 + 29 * g = 141
(1316 + 705 * g + 1218 * g) / 42 = 141
(1316 + 1923 * g) / 42 = 141
1316 + 1923 * g = 5922
1923 * g = 4606
g = 2.4

Step 3: Substitute the value of g in the expression for o.
o = (28 + 15 * g) / 42
o = (28 + 15 * 2.4) / 42
o = (28 + 36) / 42
o = 64 / 42
o = 1.52

Therefore, the values of o and g are:
o = 1.52
g = 2.4

### Answer: o = 1.52, g = 2.4

Expected answer: {g: 4606/1923, o: 2927/1923}

Correct? No

🔗 Problem

Problem: Given the following system of equations, determine the values of v and o: The first equation is: ((12 * v) - (6 * o)) = 21 The second equation is: ((76 * v) - (45 * o)) = 50.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve the first equation for v.
(12 * v) - (6 * o) = 21
12v - 6o = 21
v = (21 + 6o) / 12

Step 2: Substitute the expression for v in the second equation.
(76 * v) - (45 * o) = 50
76 * ((21 + 6o) / 12) - 45 * o = 50
(76 * (21 + 6o) / 12) - 45 * o = 50
(1596 + 456o) / 12 - 45 * o = 50
(2052 - 540o) / 12 = 50
2052 - 540o = 600
-540o = -1452
o = 2.7

Step 3: Substitute the value of o in the first equation to find the value of v.
v = (21 + 6o) / 12
v = (21 + 6 * 2.7) / 12
v = (21 + 16.2) / 12
v = 37.2 / 12
v = 3.1

Therefore, the values of v and o are:
v = 3.1
o = 2.7

### Answer: v = 3.1, o = 2.7

Expected answer: {o: 83/7, v: 215/28}

Correct? No

🔗 Problem

Problem: Find the values of f and g in the following system of equations: 75 * f + 25 * g = 138 and 2 * f + 90 * g = 143.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Let's start by solving the first equation for f:
75 * f + 25 * g = 138
75 * f = 138 - 25 * g
f = (138 - 25 * g) / 75

Now, let's substitute this expression for f into the second equation:
2 * f + 90 * g = 143
2 * (138 - 25 * g) / 75 + 90 * g = 143
276 - 50 * g + 6750 * g = 10725
6700 * g = 10449
g = 10449 / 6700
g = 1.56

Now, let's substitute the value of g back into the first equation to find the value of f:
f = (138 - 25 * 1.56) / 75
f = (138 - 39) / 75
f = 99 / 75
f = 1.32

Therefore, the values of f and g are:
f = 1.32
g = 1.56

### Answer: f = 1.32, g = 1.56

Expected answer: {f: 1769/1340, g: 10449/6700}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for variables y and n: the first equation is 194 = 4 * y + 14 * n and the second equation is 7 = 65 * n - 79 * y.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

First, let's solve the second equation for y:
7 = 65 * n - 79 * y
79 * y = 65 * n - 7
y = (65 * n - 7) / 79

Now, we can substitute this expression for y into the first equation:
194 = 4 * y + 14 * n
194 = 4 * ((65 * n - 7) / 79) + 14 * n
194 = 260 * n / 79 - 28 / 79 + 14 * n
194 = (260 * n + 14 * 79 - 28) / 79
194 * 79 = 260 * n + 1106 - 28
15326 = 260 * n + 1078
14248 = 260 * n
n = 54.8

Now, we can substitute the value of n into the expression for y:
y = (65 * 54.8 - 7) / 79
y = 3562 / 79
y = 45

### Answer: y = 45, n = 54.8

Expected answer: {n: 7677/683, y: 6256/683}

Correct? No

🔗 Problem

Problem: Find the values of l and g that satisfy these two equations: The first equation is 146 = 28 * g + 26 * l. The second equation is 6 = 41 * l - 53 * g.

Claude-3 Haiku:

To solve this problem, we need to find the values of l and g that satisfy the two given equations.

Let's start with the first equation:
146 = 28 * g + 26 * l

Rearranging the terms, we get:
26 * l = 146 - 28 * g
l = (146 - 28 * g) / 26

Now, let's substitute this expression for l into the second equation:
6 = 41 * ((146 - 28 * g) / 26) - 53 * g
6 = (41 * (146 - 28 * g)) / 26 - 53 * g
156 = 41 * (146 - 28 * g) - 1378 * g
156 = 5986 - 1148 * g - 1378 * g
156 = 5986 - 2526 * g
2370 = 2526 * g
g = 2370 / 2526
g = 0.9382

Now, let's substitute the value of g into the first equation to find the value of l:
l = (146 - 28 * 0.9382) / 26
l = (146 - 26.2696) / 26
l = 119.7304 / 26
l = 4.6058

Therefore, the values of l and g that satisfy the two equations are:
l = 4.6058
g = 0.9382

### Answer: l = 4.6058, g = 0.9382

Expected answer: {g: 2915/1263, l: 3953/1263}

Correct? No

🔗 Problem

Problem: Consider the following system of equations: 1) 20 * p + 56 * y = 90 2) 89 * p + 7 * y = 98 Resolve this system and find the values of p and y.

Claude-3 Haiku:

To solve this system of linear equations, we can use the elimination method.

Step 1: Multiply the first equation by 7 and the second equation by 56 to eliminate the variable y.

7 * (20 * p + 56 * y = 90)
140 * p + 392 * y = 630

56 * (89 * p + 7 * y = 98)
4984 * p + 392 * y = 5488

Step 2: Subtract the second equation from the first equation to eliminate the variable y.

140 * p + 392 * y = 630
-4984 * p - 392 * y = -5488
-4844 * p = -4858

Step 3: Solve for the variable p.

-4844 * p = -4858
p = -4858 / -4844
p = 1

Step 4: Substitute the value of p into one of the original equations to find the value of y.

Using the first equation:
20 * 1 + 56 * y = 90
20 + 56 * y = 90
56 * y = 70
y = 70 / 56
y = 5/4 = 1.25

Therefore, the values of p and y are:
p = 1
y = 1.25

### Answer: p = 1, y = 1.25

Expected answer: {p: 347/346, y: 3025/2422}

Correct? No

🔗 Problem

Problem: Given the system of equations: 72*k - 22*d = 17 and 6*d +69*k = 96, find the values of variables k and d.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve for d in the first equation.
72*k - 22*d = 17
-22*d = 17 - 72*k
d = (17 - 72*k) / (-22)
d = (17 - 72*k) / 22

Step 2: Substitute the expression for d into the second equation.
6*d + 69*k = 96
6*((17 - 72*k) / 22) + 69*k = 96
(102 - 432*k) / 22 + 69*k = 96
102 - 432*k + 1518*k = 2112
1518*k - 432*k = 2112 - 102
1086*k = 2010
k = 2010 / 1086
k = 1.85

Step 3: Substitute the value of k into the expression for d.
d = (17 - 72*k) / 22
d = (17 - 72*1.85) / 22
d = (17 - 133.2) / 22
d = -116.2 / 22
d = -5.28

Therefore, the values of the variables are:
k = 1.85
d = -5.28

### Answer: k = 1.85, d = -5.28

Expected answer: {d: 1913/650, k: 369/325}

Correct? No

🔗 Problem

Problem: Solve the following system of equations to find the values of d and h: 73 * h - 33 * d = 48 10 * d + 14 * h = 91

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Step 1: Solve the first equation for d.
73 * h - 33 * d = 48
33 * d = 73 * h - 48
d = (73 * h - 48) / 33

Step 2: Substitute the expression for d in the second equation.
10 * d + 14 * h = 91
10 * ((73 * h - 48) / 33) + 14 * h = 91
(730 * h - 480) / 33 + 14 * h = 91
730 * h - 480 + 462 * h = 3003
1192 * h = 3483
h = 3483 / 1192
h = <<3483/1192=2.92>>2.92

Step 3: Substitute the value of h in the first equation to find the value of d.
73 * 2.92 - 33 * d = 48
213.16 - 33 * d = 48
-33 * d = -165.16
d = <<-165.16/-33=5>>5

Therefore, the values of d and h are:
d = 5
h = 2.92

### Answer: d = 5, h = 2.92

Expected answer: {d: 5971/1192, h: 3483/1192}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of q and e: 1) 43 * q - 44 * e = 29 2) 30 * q + 43 * e = 130

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Step 1: Rearrange the first equation to solve for q.
43 * q - 44 * e = 29
43 * q = 29 + 44 * e
q = (29 + 44 * e) / 43

Step 2: Substitute the expression for q in the second equation.
30 * q + 43 * e = 130
30 * ((29 + 44 * e) / 43) + 43 * e = 130
(870 + 1320 * e) / 43 + 43 * e = 130
870 + 1320 * e + 1290 * e = 5590
2610 * e = 4720
e = 4720 / 2610
e = 1.8

Step 3: Substitute the value of e back into the first equation to find the value of q.
43 * q - 44 * 1.8 = 29
43 * q - 79.2 = 29
43 * q = 108.2
q = 108.2 / 43
q = 2.52

Therefore, the values of q and e are:
q = 2.52
e = 1.8

### Answer: q = 2.52, e = 1.8

Expected answer: {e: 4720/3169, q: 6967/3169}

Correct? No

🔗 Problem

Problem: Find the values of r and a in the following system of equations: 53 = ((89 * r) - (74 * a)) 109 = ((37 * a) + (6 * r))

Claude-3 Haiku:

To solve this system of equations, we need to find the values of the variables r and a.

Given the system of equations:
53 = ((89 * r) - (74 * a))
109 = ((37 * a) + (6 * r))

Step 1: Solve for r in the first equation.
53 = ((89 * r) - (74 * a))
53 + (74 * a) = 89 * r
r = (53 + (74 * a)) / 89

Step 2: Substitute the expression for r into the second equation.
109 = ((37 * a) + (6 * r))
109 = ((37 * a) + (6 * ((53 + (74 * a)) / 89)))
109 = ((37 * a) + (318 + (444 * a)) / 89)
109 * 89 = (37 * a * 89) + (318 + (444 * a))
9,701 = (3,293 * a) + (318 + (444 * a))
9,701 - 318 = (3,293 * a) + (444 * a)
9,383 = (3,737 * a)
a = 9,383 / 3,737
a ≈ 2.51

Step 3: Substitute the value of a into the expression for r.
r = (53 + (74 * a)) / 89
r = (53 + (74 * 2.51)) / 89
r = (53 + 185.74) / 89
r = 238.74 / 89
r ≈ 2.68

Therefore, the values of r and a are:
r ≈ 2.68
a ≈ 2.51

### Answer: r ≈ 2.68, a ≈ 2.51

Expected answer: {a: 9383/3737, r: 271/101}

Correct? No

🔗 Problem

Problem: Given the following pair of equations where 'g' and 'q' represent the quantities of two different types of grains in a mix, solve for 'g' and 'q': 1. The sum of the weights of 42 units of 'g' and 12 units of 'q' equals 169 kg. 2. The weight of 12 units of 'q' minus the weight of 50 units of 'g' results in 19 kg.

Claude-3 Haiku:

To solve for 'g' and 'q', we can use the given equations and set up a system of linear equations.

Let's define the variables:
- 'g' represents the quantity of one type of grain
- 'q' represents the quantity of the other type of grain

Given information:
1. The sum of the weights of 42 units of 'g' and 12 units of 'q' equals 169 kg.
2. The weight of 12 units of 'q' minus the weight of 50 units of 'g' results in 19 kg.

Step 1: Set up the first equation.
42g + 12q = 169

Step 2: Set up the second equation.
12q - 50g = 19

Step 3: Solve the system of equations using substitution or elimination method.
From the second equation, we can solve for 'q':
12q - 50g = 19
12q = 19 + 50g
q = (19 + 50g) / 12

Substituting the value of 'q' into the first equation:
42g + 12((19 + 50g) / 12) = 169
42g + (19 + 50g) = 169
92g + 19 = 169
92g = 150
g = 150 / 92
g ≈ 1.63 units

Substituting the value of 'g' into the second equation to find 'q':
12q - 50(1.63) = 19
12q - 81.5 = 19
12q = 100.5
q = 100.5 / 12
q ≈ 8.38 units

### Answer: g ≈ 1.63 units, q ≈ 8.38 units

Expected answer: {g: 75/46, q: 578/69}

Correct? No

🔗 Problem

Problem: Find the values of s and v for the following system of equations: 37 * s - 11 * v = 54 82 * s - 62 * v = 41

Claude-3 Haiku:

To solve this system of equations, we can use the elimination method.

Step 1: Multiply the first equation by 62 and the second equation by 11 to eliminate the variable v.

62 * (37 * s - 11 * v = 54)
2294 * s - 682 * v = 3348

11 * (82 * s - 62 * v = 41)
902 * s - 682 * v = 451

Step 2: Subtract the second equation from the first equation to eliminate the variable v.

2294 * s - 3348 = 902 * s - 451
1392 * s = 2897
s = 2897 / 1392
s = 2.08

Step 3: Substitute the value of s into either equation to find the value of v.

Using the first equation:
37 * 2.08 - 11 * v = 54
77.96 - 11 * v = 54
-11 * v = -23.96
v = 2.18

Therefore, the values of s and v are:
s = 2.08
v = 2.18

### Answer: s = 2.08, v = 2.18

Expected answer: {s: 2897/1392, v: 2911/1392}

Correct? No

🔗 Problem

Problem: Based on the following two equations, find the values for c and z: The first equation is 41 * c + 65 * z = 151 The second equation is 78 * z - 48 * c = 48.

Claude-3 Haiku:

To solve for the values of c and z, we can use the system of linear equations provided.

The first equation is:
41 * c + 65 * z = 151

The second equation is:
78 * z - 48 * c = 48

We can solve this system of equations using the substitution method.

Step 1: Solve for c in the second equation.
78 * z - 48 * c = 48
-48 * c = 78 * z - 48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) / -48
c = (78 * z - 48) /

Expected answer: {c: 37/27, z: 512/351}

Correct? No

🔗 Problem

Problem: Given the following system of equations: 60 * c - 91 * i = 7 7 * i + 76 * c = 148 What are the values of c and i?

Claude-3 Haiku:

To solve this system of linear equations, we can use the substitution method.

Step 1: Solve the first equation for i.
60 * c - 91 * i = 7
91 * i = 60 * c - 7
i = (60 * c - 7) / 91

Step 2: Substitute the expression for i into the second equation.
7 * i + 76 * c = 148
7 * (60 * c - 7) / 91 + 76 * c = 148
420 * c - 49 + 6,916 * c = 13,388
7,336 * c = 13,437
c = 13,437 / 7,336
c = 1.83

Step 3: Substitute the value of c into the first equation to find the value of i.
60 * 1.83 - 91 * i = 7
109.8 - 91 * i = 7
-91 * i = -102.8
i = 1.13

Therefore, the values of c and i are:
c = 1.83
i = 1.13

### Answer: c = 1.83, i = 1.13

Expected answer: {c: 1931/1048, i: 2087/1834}

Correct? No

🔗 Problem

Problem: Find the values of e and v that satisfy the following two simultaneous linear equations: 1) 71*v - 37*e = 69 2) 41*e + 76*v = 184

Claude-3 Haiku:

To solve this system of two simultaneous linear equations, we can use the elimination method.

Step 1: Multiply the first equation by 76 and the second equation by 71 to eliminate one of the variables.

76(71*v - 37*e = 69)
5396*v - 2812*e = 5244

71(41*e + 76*v = 184)
2911*e + 5396*v = 13064

Step 2: Subtract the second equation from the first equation to eliminate the variable v.

5396*v - 2812*e = 5244
-2911*e - 5396*v = -13064
---------------------------------------------------------------------------
-8723*e = -7820

Step 3: Solve for e.

-8723*e = -7820
e = -7820/-8723
e = 0.9

Step 4: Substitute the value of e into one of the original equations to solve for v.

Using the first equation:
71*v - 37*e = 69
71*v - 37*0.9 = 69
71*v - 33.3 = 69
71*v = 102.3
v = 102.3/71
v = 1.44

Therefore, the values of e and v that satisfy the given system of linear equations are:
e = 0.9
v = 1.44

### Answer: e = 0.9, v = 1.44

Expected answer: {e: 7820/5723, v: 9637/5723}

Correct? No

🔗 Problem

Problem: What are the values of 'd' and 'v' in the following system of equations? The sum of 25 times 'v' and 69 times 'd' equals 113. The sum of 26 times 'd' and 42 times 'v' equals 85.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Let's start by solving for 'd' in the second equation:

26d + 42v = 85
26d = 85 - 42v
d = (85 - 42v) / 26

Now, we can substitute this expression for 'd' into the first equation:

25v + 69((85 - 42v) / 26) = 113
25v + 2205 - 1803v / 26 = 113
25v - 1803v / 26 = -2092
-1778v / 26 = -2092
v = 26 * (-2092) / -1778
v = 31

Now that we have the value of 'v', we can substitute it back into the second equation to find the value of 'd':

26d + 42(31) = 85
26d + 1302 = 85
26d = -1217
d = -46.81

Therefore, the values of 'd' and 'v' are:
### Answer: d = -46.81, v = 31

Expected answer: {d: 2621/2248, v: 2927/2248}

Correct? No

🔗 Problem

Problem: Solve the following equations for g and z: 43 * z - 91 * g = 33 72 * g - 3 * z = 68

Claude-3 Haiku:

To solve the given system of linear equations for g and z, we can use the substitution method.

Step 1: Solve the first equation for z.
43 * z - 91 * g = 33
43 * z = 91 * g + 33
z = (91 * g + 33) / 43

Step 2: Substitute the expression for z in the second equation.
72 * g - 3 * z = 68
72 * g - 3 * (91 * g + 33) / 43 = 68
72 * g - 273 * g / 43 - 99 / 43 = 68
72 * g - 6.349 * g - 2.302 = 68
65.651 * g = 70.302
g = 1.072

Step 3: Substitute the value of g back into the first equation to find the value of z.
43 * z - 91 * 1.072 = 33
43 * z - 97.552 = 33
43 * z = 130.552
z = 3.035

Therefore, the solutions to the system of equations are:
g = 1.072
z = 3.035

### Answer: g = 1.072, z = 3.035

Expected answer: {g: 3023/2823, z: 8564/2823}

Correct? No

🔗 Problem

Problem: Alex's and Brad's baskets contained c cherries and f figs respectively. From an old recipe book, it stated that cherries multiplied by 50 multiplied by the quantity of figs that multiplied by 12, which altogether would weigh about 92 grams. Another recipe book stated that cherries multiplied by 36 minus figs multiplied by 21 should weigh about 34 grams. Can you find the quantity of cherries (c) and figs (f)? Use the following system of equations to solve: 50c + 12f = 92 36c - 21f = 34.

Claude-3 Haiku:

To solve this problem, we need to use the system of equations provided:

50c + 12f = 92
36c - 21f = 34

Step 1: Multiply the second equation by 12 and the first equation by 36 to eliminate the variable c.
36(50c + 12f) = 36(92)
36c - 21f = 34
432c + 432f = 3312
36c - 21f = 34

Subtracting the second equation from the first equation:
432c + 432f - 36c + 21f = 3312 - 34
396c + 453f = 3278

Step 2: Multiply the first equation by 21 and the second equation by 50 to eliminate the variable f.
21(50c + 12f) = 21(92)
36c - 21f = 34
1050c + 252f = 1932
1800c - 1050f = 1700

Subtracting the second equation from the first equation:
1050c + 252f - 1800c + 1050f = 1932 - 1700
-750c = 232
c = -232/750 = -0.3093

Step 3: Substitute the value of c into the first equation to find the value of f.
50c + 12f = 92
50(-0.3093) + 12f = 92
-15.465 + 12f = 92
12f = 107.465
f = 107.465/12 = 8.9555

Therefore, the quantity of cherries (c) is -0.3093, and the quantity of figs (f) is 8.9555.

### Answer: c = -0.3093, f = 8.9555

Expected answer: {c: 30/19, f: 62/57}

Correct? No

🔗 Problem

Problem: Here are the equations you'll need to solve (remember, the goal is to find the values of u and d): 1) 87u - 75d = 7 2) 85d - 82u = 54

Claude-3 Haiku:

Okay, let's solve this system of linear equations to find the values of u and d.

First, we'll use the substitution method to solve for u in terms of d.

From equation 1:
87u - 75d = 7
87u = 75d + 7
u = (75d + 7) / 87

Now, we'll substitute this expression for u into equation 2:
85d - 82((75d + 7) / 87) = 54
85d - (6150d + 574) / 87 = 54
(7395d - 6150d - 574) / 87 = 54
(1245d - 574) / 87 = 54
1245d - 574 = 4698
1245d = 5272
d = 4.23

Now that we have the value of d, we can plug it back into the first equation to solve for u:
87u - 75(4.23) = 7
87u - 318.25 = 7
87u = 325.25
u = 3.74

Therefore, the values of u and d are:
u = 3.74
d = 4.23

### Answer: u = 3.74, d = 4.23

Expected answer: {d: 5272/1245, u: 929/249}

Correct? No

🔗 Problem

Problem: Bill is trying to decipher a secret code. He manages to translate two sentences into the following mathematical expressions: (75 * his unknown number a) - (4 * his unknown number i) equals 42, and (10 * i) + (13 * a) equals 160. Using these equations, can you figure out the values of i and a for him?

Claude-3 Haiku:

Okay, let's solve this step-by-step:

1) We have two equations:
(75 * a) - (4 * i) = 42
(10 * i) + (13 * a) = 160

2) First, let's solve for i in the second equation:
(10 * i) + (13 * a) = 160
10 * i = 160 - 13 * a
i = (160 - 13 * a) / 10

3) Now, let's substitute this expression for i into the first equation:
(75 * a) - (4 * (160 - 13 * a) / 10) = 42
(75 * a) - (64 - 5.2 * a) = 42
75 * a - 64 + 5.2 * a = 42
80.2 * a = 106
a = 106 / 80.2
a = 1.32

4) Now that we have the value of a, we can plug it back into the second equation to solve for i:
(10 * i) + (13 * 1.32) = 160
10 * i = 160 - 17.16
i = (160 - 17.16) / 10
i = 14.28

### Answer: i = 14.28, a = 1.32

Expected answer: {a: 530/401, i: 5727/401}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of p and c: 37 * p + 74 * c = 183 27 * c - 18 * p = 13

Claude-3 Haiku:

To solve the given system of equations for the values of p and c, we can use the substitution method.

Step 1: Solve the first equation for p.
37 * p + 74 * c = 183
37 * p = 183 - 74 * c
p = (183 - 74 * c) / 37

Step 2: Substitute the expression for p in the second equation.
27 * c - 18 * p = 13
27 * c - 18 * (183 - 74 * c) / 37 = 13
27 * c - 3294 + 1332 * c / 37 = 13
27 * c - 3294 + 36 * c = 481
63 * c = 3775
c = 60

Step 3: Substitute the value of c in the first equation to find the value of p.
37 * p + 74 * 60 = 183
37 * p + 4440 = 183
37 * p = 183 - 4440
37 * p = -4257
p = -115

Therefore, the values of p and c are:
p = -115
c = 60

### Answer: p = -115, c = 60

Expected answer: {c: 3775/2331, p: 3979/2331}

Correct? No

🔗 Problem

Problem: Determine the values of k and p from the following system of equations: (48 * k) - (30 * p) = 37 (16 * p) + (33 * k) = 105.

Claude-3 Haiku:

To solve this system of equations, we need to use the substitution method.

Let's start by solving the first equation for k:
(48 * k) - (30 * p) = 37
48k - 30p = 37
k = (37 + 30p) / 48

Now, let's substitute this expression for k into the second equation:
(16 * p) + (33 * k) = 105
(16 * p) + (33 * (37 + 30p) / 48) = 105
(16 * p) + (1221 + 990p) / 48 = 105
(16 * p) + 2211 / 48 = 105
(16 * p) + 46.0625 = 105
16p = 59.9375
p = 3.74609375

Now, let's substitute the value of p back into the first equation to find the value of k:
(48 * k) - (30 * 3.74609375) = 37
48k - 112.3828125 = 37
48k = 149.3828125
k = 3.11630859375

Therefore, the values of k and p are:
k = 3.11630859375
p = 3.74609375

### Answer: k = 3.11630859375, p = 3.74609375

Expected answer: {k: 1871/879, p: 1273/586}

Correct? No

🔗 Problem

Problem: Consider the following pair of equations. 1. 75v - 69f = 14 2. 46f + 53v = 110 Determine the values for v and f that satisfy these simultaneous equations.

Claude-3 Haiku:

To solve this system of simultaneous equations, we can use the elimination method.

Step 1: Multiply the first equation by 53 and the second equation by 75 to eliminate one of the variables.

Multiplying the first equation by 53:
53(75v - 69f = 14)
3,975v - 3,657f = 742

Multiplying the second equation by 75:
75(46f + 53v = 110)
3,450f + 3,975v = 8,250

Step 2: Subtract the first equation from the second equation to eliminate the variable v.
3,450f + 3,975v = 8,250
-3,975v - 3,657f = -742
-----------------
-207f = 7,508

Step 3: Solve for the variable f.
-207f = 7,508
f = -7,508/207
f = -36.25

Step 4: Substitute the value of f into one of the original equations to solve for the variable v.
Using the first equation:
75v - 69f = 14
75v - 69(-36.25) = 14
75v + 2,501.25 = 14
75v = -2,487.25
v = -33.165

Therefore, the values of the variables that satisfy the system of equations are:
v = -33.165
f = -36.25

### Answer: v = -33.165, f = -36.25

Expected answer: {f: 7508/7107, v: 358/309}

Correct? No

🔗 Problem

Problem: Determine the values of o and g from the following system of equations: 7 * o + 13 * g = 131 89 * g - 70 * o = 37.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Given the system of equations:
7 * o + 13 * g = 131
89 * g - 70 * o = 37

Step 1: Solve for o in the first equation.
7 * o + 13 * g = 131
7 * o = 131 - 13 * g
o = (131 - 13 * g) / 7

Step 2: Substitute the expression for o in the second equation.
89 * g - 70 * o = 37
89 * g - 70 * (131 - 13 * g) / 7 = 37
89 * g - 70 * (131 / 7 - 13 * g / 7) = 37
89 * g - 70 * (18.71 - 1.86 * g) = 37
89 * g - 1309.7 + 130.2 * g = 37
219.2 * g = 1346.7
g = 6.15

Step 3: Substitute the value of g in the expression for o.
o = (131 - 13 * g) / 7
o = (131 - 13 * 6.15) / 7
o = (131 - 79.95) / 7
o = 51.05 / 7
o = 7.29

Therefore, the values of o and g are:
o = 7.29
g = 6.15

### Answer: o = 7.29, g = 6.15

Expected answer: {g: 449/73, o: 3726/511}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of d and k: 88 * d - 60 * k = 38 33 * k - 11 * d = 46.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Step 1: Solve the first equation for d.
88 * d - 60 * k = 38
88 * d = 38 + 60 * k
d = (38 + 60 * k) / 88

Step 2: Substitute the expression for d in the second equation.
33 * k - 11 * d = 46
33 * k - 11 * (38 + 60 * k) / 88 = 46
33 * k - 418 / 88 - 660 * k / 88 = 46
33 * k - 4.75 - 7.5 * k = 46
25.5 * k = 50.75
k = 50.75 / 25.5
k = 2

Step 3: Substitute the value of k in the expression for d.
d = (38 + 60 * k) / 88
d = (38 + 60 * 2) / 88
d = (38 + 120) / 88
d = 158 / 88
d = 1.8

Therefore, the values of d and k are:
d = 1.8
k = 2

### Answer: d = 1.8, k = 2

Expected answer: {d: 669/374, k: 203/102}

Correct? No

🔗 Problem

Problem: Consider the following system of equations, calculate the values of y and z: 24 * z + 72 * y = 139, 2 * z + 82 * y = 96.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve the first equation for z.
24 * z + 72 * y = 139
24 * z = 139 - 72 * y
z = (139 - 72 * y) / 24

Step 2: Substitute the expression for z into the second equation.
2 * z + 82 * y = 96
2 * (139 - 72 * y) / 24 + 82 * y = 96
(278 - 144 * y) / 24 + 82 * y = 96
278 - 144 * y + 1968 * y = 2304
1824 * y = 2026
y = 2026 / 1824
y = 1.11

Step 3: Substitute the value of y back into the first equation to find the value of z.
z = (139 - 72 * 1.11) / 24
z = (139 - 79.92) / 24
z = 59.08 / 24
z = 2.46

Therefore, the values of y and z are:
y = 1.11
z = 2.46

### Answer: y = 1.11, z = 2.46

Expected answer: {y: 1013/912, z: 2243/912}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the variables v and o: (87 * o) - (29 * v) = 1 and (8 * v) + (30 * o) = 91.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Given equations:
(87 * o) - (29 * v) = 1
(8 * v) + (30 * o) = 91

Step 1: Solve for v in the second equation.
(8 * v) + (30 * o) = 91
8 * v = 91 - (30 * o)
v = (91 - 30 * o) / 8

Step 2: Substitute the expression for v in the first equation.
(87 * o) - (29 * ((91 - 30 * o) / 8)) = 1
(87 * o) - (29 * (91 - 30 * o) / 8) = 1
(87 * o) - (29 * 91 / 8) + (29 * 30 * o / 8) = 1
(87 * o) - 333.375 + 112.5 * o = 1
199.5 * o - 333.375 = 1
199.5 * o = 334.375
o = 334.375 / 199.5
o = <<o = 1.675>>1.675

Step 3: Substitute the value of o in the expression for v.
v = (91 - 30 * 1.675) / 8
v = (91 - 50.25) / 8
v = 40.75 / 8
v = <<v = 5.09>>5.09

### Answer: v = 5.09, o = 1.675

Expected answer: {o: 2647/1566, v: 2629/522}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for h and p: The first equation is (23 * h) - (46 * p) = 58 The second equation is (11 * p) + (23 * h) = 124.

Claude-3 Haiku:

To solve the given system of equations for h and p, we can use the substitution method.

Step 1: Rearrange the second equation to express h in terms of p.
(11 * p) + (23 * h) = 124
23 * h = 124 - (11 * p)
h = (124 - (11 * p)) / 23

Step 2: Substitute the expression for h in the first equation.
(23 * h) - (46 * p) = 58
(23 * ((124 - (11 * p)) / 23)) - (46 * p) = 58
(124 - (11 * p)) - (46 * p) = 58
124 - 11 * p - 46 * p = 58
124 - 57 * p = 58
-57 * p = -66
p = 1.16

Step 3: Substitute the value of p in the expression for h to find the value of h.
h = (124 - (11 * p)) / 23
h = (124 - (11 * 1.16)) / 23
h = (124 - 12.76) / 23
h = 111.24 / 23
h = 4.84

Therefore, the solution to the system of equations is:
h = 4.84
p = 1.16

### Answer: h = 4.84, p = 1.16

Expected answer: {h: 2114/437, p: 22/19}

Correct? No

🔗 Problem

Problem: If the following system of equations represents the relationship between integers d and f, determine their values: 1) 19d + 6f = 120, 2) 90d - 42f = 69.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve the first equation for d.
19d + 6f = 120
19d = 120 - 6f
d = (120 - 6f) / 19

Step 2: Substitute the expression for d into the second equation.
90d - 42f = 69
90 * (120 - 6f) / 19 - 42f = 69
(90 * 120 - 90 * 6f) / 19 - 42f = 69
(10800 - 540f) / 19 - 42f = 69
10800 - 540f - 798f = 1311
-1338f = -9489
f = 7

Step 3: Substitute the value of f into the first equation to find d.
19d + 6(7) = 120
19d + 42 = 120
19d = 78
d = 4

Therefore, the values of the integers d and f are:
d = 4
f = 7

### Answer: d = 4, f = 7

Expected answer: {d: 909/223, f: 3163/446}

Correct? No

🔗 Problem

Problem: Here's a problem: A system of linear equations is given by the following formulas: 1) 42 * m + 55 * r = 127 2) 66 * m - 52 * r = 44 Can you solve this system to find the values of 'r' and 'm'?

Claude-3 Haiku:

To solve this system of linear equations, we can use the substitution method or the elimination method.

Using the substitution method:

From the first equation, we can solve for m:
42m + 55r = 127
42m = 127 - 55r
m = (127 - 55r) / 42

Substituting this expression for m into the second equation:
66((127 - 55r) / 42) - 52r = 44
(66/42)(127 - 55r) - 52r = 44
(66/42)127 - (66/42)55r - 52r = 44
(66/42)127 - 118r = 44
118r = (66/42)127 - 44
r = ((66/42)127 - 44) / 118
r = 1

Substituting r = 1 back into the first equation to find m:
42m + 55(1) = 127
42m + 55 = 127
42m = 72
m = 72/42
m = 12/7

Therefore, the solution to the system of linear equations is:
r = 1
m = 12/7

### Answer: r = 1, m = 12/7

Expected answer: {m: 1504/969, r: 363/323}

Correct? No

🔗 Problem

Problem: Determine the values of n and w that satisfy the following system of linear equations simultaneously: 31n + 64w = 120 57w + 71n = 173

Claude-3 Haiku:

To solve this system of linear equations, we can use the elimination method.

Step 1: Multiply the first equation by 71 and the second equation by 31 to eliminate the variable n.

71(31n + 64w = 120)
2201n + 4544w = 8520

31(57w + 71n = 173)
1767w + 2201n = 5363

Step 2: Subtract the second equation from the first equation to eliminate the variable n.

2201n + 4544w = 8520
1767w + 2201n = 5363
--------------
2777w = 3157

Step 3: Solve for w.

w = 3157 / 2777
w = <<3157/2777=1.14>>1.14

Step 4: Substitute the value of w into the first equation to solve for n.

31n + 64(1.14) = 120
31n + 72.96 = 120
31n = 47.04
n = <<47.04/31=1.52>>1.52

Therefore, the values of n and w that satisfy the system of linear equations are:
n = 1.52
w = 1.14

### Answer: n = 1.52, w = 1.14

Expected answer: {n: 4232/2777, w: 3157/2777}

Correct? No

🔗 Problem

Problem: Determine the values of u and a from the following system of linear equations: 1) 72 * a + 26 * u = 112 2) 76 * u - 77 * a = 31.

Claude-3 Haiku:

To solve this system of linear equations, we can use the substitution method.

From the first equation, we can solve for u:
72 * a + 26 * u = 112
26 * u = 112 - 72 * a
u = (112 - 72 * a) / 26

Now, we can substitute this expression for u into the second equation:
76 * ((112 - 72 * a) / 26) - 77 * a = 31
(76 * (112 - 72 * a)) / 26 - 77 * a = 31
(8,512 - 5,472 * a) / 26 - 77 * a = 31
(3,040 - 5,472 * a) / 26 = 31 + 77 * a
3,040 - 5,472 * a = 806 + 2,002 * a
-7,474 * a = -2,234
a = 0.2985 (rounded to 4 decimal places)

Now, we can substitute the value of a back into the first equation to find the value of u:
72 * 0.2985 + 26 * u = 112
21.492 + 26 * u = 112
26 * u = 112 - 21.492
u = 3.4577 (rounded to 4 decimal places)

### Answer: u = 3.4577, a = 0.2985

Expected answer: {a: 3853/3737, u: 5428/3737}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of b and n: the first equation is 54n + 18b = 143 and the second equation is 87n - 93b = 48.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

First, let's solve for n in the first equation:
54n + 18b = 143
54n = 143 - 18b
n = (143 - 18b) / 54

Now, let's substitute the expression for n into the second equation:
87n - 93b = 48
87 * (143 - 18b) / 54 - 93b = 48
(7761 - 1566b) / 54 - 93b = 48
7761 - 1566b - 5022b = 2592
-6588b = -5169
b = 0.785

Now, let's substitute the value of b back into the first equation to find the value of n:
54n + 18(0.785) = 143
54n + 14.13 = 143
54n = 128.87
n = 2.39

### Answer: b = 0.785, n = 2.39

Expected answer: {b: 3283/2196, n: 4721/2196}

Correct? No

🔗 Problem

Problem: Given the following system of equations about a company's production economics, where e represents the cost of electricity and p is the cost of petroleum: 53 * e + 7 * p = 103 69 * e - 88 * p = 6 What are the costs of electricity (e) and petroleum (p)?

Claude-3 Haiku:

To solve this system of linear equations, we can use the substitution method.

Step 1: Solve for e in the first equation.
53 * e + 7 * p = 103
53 * e = 103 - 7 * p
e = (103 - 7 * p) / 53

Step 2: Substitute the expression for e in the second equation.
69 * e - 88 * p = 6
69 * ((103 - 7 * p) / 53) - 88 * p = 6
(69 * 103 - 69 * 7 * p) / 53 - 88 * p = 6
(7107 - 483 * p) / 53 - 88 * p = 6
7107 - 483 * p - 4664 * p = 318
-5147 * p = -6789
p = 1.32

Step 3: Substitute the value of p in the first equation to find the value of e.
53 * e + 7 * 1.32 = 103
53 * e + 9.24 = 103
53 * e = 93.76
e = 1.77

Therefore, the cost of electricity (e) is $1.77, and the cost of petroleum (p) is $1.32.

### Answer: Electricity cost (e) = $1.77, Petroleum cost (p) = $1.32

Expected answer: {e: 9106/5147, p: 6789/5147}

Correct? No

🔗 Problem

Problem: Consider the following pair of linear equations. First equation: ((18 * p) - (7 * s)) = 21 Second equation: ((51 * s) - (24 * p)) = 14 Find the values of p and s that satisfy both equations.

Claude-3 Haiku:

To solve this problem, we need to use the method of substitution or elimination to find the values of p and s that satisfy both linear equations.

Let's start by rearranging the first equation to solve for p:
(18 * p) - (7 * s) = 21
18 * p = 21 + (7 * s)
p = (21 + 7 * s) / 18

Now, we can substitute this expression for p into the second equation:
(51 * s) - (24 * ((21 + 7 * s) / 18)) = 14
(51 * s) - (24 * (21 + 7 * s) / 18) = 14
(51 * s) - (24 * 21 / 18) - (24 * 7 * s / 18) = 14
(51 * s) - 28 - (28 * s / 6) = 14
(51 * s) - 28 - (4.67 * s) = 14
(46.33 * s) - 28 = 14
46.33 * s = 42
s = 0.91

Now, we can substitute the value of s back into the first equation to find the value of p:
p = (21 + 7 * 0.91) / 18
p = (21 + 6.37) / 18
p = 27.37 / 18
p = 1.52

Therefore, the values of p and s that satisfy both equations are:
p = 1.52
s = 0.91

### Answer: p = 1.52, s = 0.91

Expected answer: {p: 1169/750, s: 126/125}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for c and w: The first equation is 59 times c minus 34 times w is equal to 84. The second equation is 11 times c plus 42 times w is equal to 98.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Given equations:
59c - 34w = 84
11c + 42w = 98

Step 1: Solve for c in the first equation.
59c - 34w = 84
59c = 84 + 34w
c = (84 + 34w) / 59

Step 2: Substitute the expression for c in the second equation.
11c + 42w = 98
11((84 + 34w) / 59) + 42w = 98
(924 + 374w) / 59 + 42w = 98
924 + 374w + 2478w = 5782
2852w = 4858
w = 4858 / 2852
w = 1.7

Step 3: Substitute the value of w back into the first equation to find c.
59c - 34(1.7) = 84
59c - 57.8 = 84
59c = 141.8
c = 141.8 / 59
c = 2.4

Therefore, the solution to the system of equations is:
c = 2.4
w = 1.7

### Answer: c = 2.4, w = 1.7

Expected answer: {c: 1715/713, w: 2429/1426}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of f and z: First equation is 45 * f + 42 * z = 101, Second equation is 60 * z - 42 * f = 13.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

First equation: 45 * f + 42 * z = 101
Rearranging the first equation to solve for f:
45 * f = 101 - 42 * z
f = (101 - 42 * z) / 45

Substituting the expression for f into the second equation:
60 * z - 42 * ((101 - 42 * z) / 45) = 13
60 * z - (4242 - 1764 * z) / 45 = 13
60 * z - 2478 / 45 + 39.2 * z = 13
99.2 * z - 2478 / 45 = 13
99.2 * z = 2491 / 45
z = 25

Substituting the value of z back into the first equation to find the value of f:
45 * f + 42 * 25 = 101
45 * f + 1050 = 101
45 * f = -949
f = -21.09

Rounding the values to two decimal places:
f = -21.09
z = 25.00

### Answer: f = -21.09, z = 25.00

Expected answer: {f: 919/744, z: 1609/1488}

Correct? No

🔗 Problem

Problem: Calculate the values of p and u from the following system of equations: 26 * p - 21 * u = 6 15 * p + 58 * u = 83.

Claude-3 Haiku:

To solve for the values of p and u, we can use the system of linear equations provided.

Given:
26 * p - 21 * u = 6
15 * p + 58 * u = 83

Step 1: Solve for p in the first equation.
26 * p - 21 * u = 6
26 * p = 6 + 21 * u
p = (6 + 21 * u) / 26

Step 2: Substitute the expression for p in the second equation.
15 * p + 58 * u = 83
15 * ((6 + 21 * u) / 26) + 58 * u = 83
(90 + 315 * u) / 26 + 58 * u = 83
(90 + 315 * u + 1508 * u) / 26 = 83
(90 + 1823 * u) / 26 = 83
90 + 1823 * u = 2158
1823 * u = 2068
u = 2068 / 1823
u = <<u = 1.13>>1.13

Step 3: Substitute the value of u in the expression for p.
p = (6 + 21 * u) / 26
p = (6 + 21 * 1.13) / 26
p = (6 + 23.73) / 26
p = 29.73 / 26
p = <<p = 1.14>>1.14

### Answer: p = 1.14, u = 1.13

Expected answer: {p: 2091/1823, u: 2068/1823}

Correct? No

🔗 Problem

Problem: Solve for the values of n and s using these two simultaneous equations: 1) 92 * n - 38 * s = 62 2) 59 * n + 8 * s = 75

Claude-3 Haiku:

To solve for the values of n and s using the given simultaneous equations, we can use the substitution method.

Equation 1: 92 * n - 38 * s = 62
Equation 2: 59 * n + 8 * s = 75

Step 1: Solve for s in terms of n using Equation 1.
92 * n - 38 * s = 62
38 * s = 92 * n - 62
s = (92 * n - 62) / 38

Step 2: Substitute the expression for s in Equation 2.
59 * n + 8 * ((92 * n - 62) / 38) = 75
59 * n + 8 * (92 * n - 62) / 38 = 75
59 * n + 736 * n - 496 / 38 = 75
795 * n - 496 / 38 = 75
795 * n - 13 = 75
795 * n = 88
n = 88 / 795
n = 0.1107

Step 3: Substitute the value of n in the expression for s to find the value of s.
s = (92 * n - 62) / 38
s = (92 * 0.1107 - 62) / 38
s = (10.1044 - 62) / 38
s = -51.8956 / 38
s = -1.3657

Therefore, the values of n and s are:
### Answer: n = 0.1107, s = -1.3657

Expected answer: {n: 1673/1489, s: 1621/1489}

Correct? No

🔗 Problem

Problem: Solving the following pairs of simultaneous equations, what would be the values for e and z? The equations are: 87 * z - 35 * e = 63 and 81 * z + 58 * e = 154.

Claude-3 Haiku:

To solve the given system of simultaneous equations, we can use the substitution method.

Given equations:
87 * z - 35 * e = 63
81 * z + 58 * e = 154

Step 1: Solve for e in the first equation.
87 * z - 35 * e = 63
35 * e = 87 * z - 63
e = (87 * z - 63) / 35

Step 2: Substitute the expression for e in the second equation.
81 * z + 58 * ((87 * z - 63) / 35) = 154
81 * z + 58 * (87 * z - 63) / 35 = 154
81 * z + 58 * (87 * z - 63) / 35 = 154
81 * z + 4986 * z - 3654 / 35 = 154
5067 * z - 3654 / 35 = 154
5067 * z - 104 = 154
5067 * z = 258
z = 258 / 5067
z = 0.051

Step 3: Substitute the value of z in the expression for e.
e = (87 * 0.051 - 63) / 35
e = (4.437 - 63) / 35
e = -58.563 / 35
e = -1.673

Therefore, the values for e and z are:
e = -1.673
z = 0.051

### Answer: e = -1.673, z = 0.051

Expected answer: {e: 2765/2627, z: 9044/7881}

Correct? No

🔗 Problem

Problem: To find the values of h and t, solve the following system of simultaneous linear equations: (11 * t) + (44 * h) = 110 (98 * t) - (36 * h) = 18.

Claude-3 Haiku:

To solve the given system of simultaneous linear equations, we can use the substitution method or the elimination method.

Using the substitution method:

From the first equation, we can express t in terms of h:
(11 * t) + (44 * h) = 110
11 * t = 110 - 44 * h
t = (110 - 44 * h) / 11

Substituting the expression for t in the second equation:
(98 * (110 - 44 * h) / 11) - (36 * h) = 18
(1078 - 4312 * h) / 11 - 36 * h = 18
1078 - 4312 * h - 396 * h = 198 * 11
-4708 * h = 2178
h = -2178 / 4708
h = -0.4625

Substituting the value of h in the expression for t:
t = (110 - 44 * (-0.4625)) / 11
t = (110 + 204.5) / 11
t = 314.5 / 11
t = 28.59

Therefore, the values of h and t are:
h = -0.4625
t = 28.59

### Answer: h = -0.4625, t = 28.59

Expected answer: {h: 481/214, t: 108/107}

Correct? No

🔗 Problem

Problem: Solve the following system of linear equations to find the values of b and o: ((69 * b) - (50 * o)) = 55 ((41 * o) + (18 * b)) = 85.

Claude-3 Haiku:

To solve the given system of linear equations, we can use the substitution method.

Step 1: Rearrange the first equation to solve for b.
(69 * b) - (50 * o) = 55
69b - 50o = 55
b = (55 + 50o) / 69

Step 2: Substitute the expression for b in the second equation.
(41 * o) + (18 * ((55 + 50o) / 69)) = 85
(41 * o) + (990 + 900o) / 69 = 85
(41 * o) + (1890 + 900o) / 69 = 85
(41 * o + 1890 + 900o) / 69 = 85
(941 * o + 1890) / 69 = 85
941 * o + 1890 = 5865
941 * o = 3975
o = 4.22

Step 3: Substitute the value of o in the expression for b.
b = (55 + 50 * 4.22) / 69
b = (55 + 211) / 69
b = 266 / 69
b = 3.85

Therefore, the values of b and o are:
b = 3.85
o = 4.22

### Answer: b = 3.85, o = 4.22

Expected answer: {b: 6505/3729, o: 1625/1243}

Correct? No

🔗 Problem

Problem: Solve the following system of equations to find the values of p and q: 67 * q - 80 * p = 65, and 6 * q + 5 * p = 177.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Given equations:
67 * q - 80 * p = 65
6 * q + 5 * p = 177

Step 1: Solve for p in the second equation.
6 * q + 5 * p = 177
5 * p = 177 - 6 * q
p = (177 - 6 * q) / 5

Step 2: Substitute the expression for p in the first equation.
67 * q - 80 * ((177 - 6 * q) / 5) = 65
67 * q - 80 * (177 / 5 - 6 * q / 5) = 65
67 * q - 80 * (35.4 - 1.2 * q) = 65
67 * q - 2832 + 96 * q = 65
163 * q = 2897
q = 2897 / 163
q = 17.77 (rounded to two decimal places)

Step 3: Substitute the value of q in the expression for p.
p = (177 - 6 * 17.77) / 5
p = (177 - 106.62) / 5
p = 70.38 / 5
p = 14.08 (rounded to two decimal places)

### Answer: p = 14.08, q = 17.77

Expected answer: {p: 11469/815, q: 2897/163}

Correct? No

🔗 Problem

Problem: Find the values of k and f that satisfy the following system of equations: 10 * k + 48 * f = 161 33 * k - 41 * f = 31.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve the first equation for f.
10 * k + 48 * f = 161
48 * f = 161 - 10 * k
f = (161 - 10 * k) / 48

Step 2: Substitute the expression for f into the second equation.
33 * k - 41 * ((161 - 10 * k) / 48) = 31
33 * k - (41 * 161 - 410 * k) / 48 = 31
33 * k - (6601 - 410 * k) / 48 = 31
33 * k - 137.52 + 8.54 * k = 31
41.54 * k = 168.52
k = 4

Step 3: Substitute the value of k into the first equation to find the value of f.
10 * 4 + 48 * f = 161
40 + 48 * f = 161
48 * f = 121
f = 121 / 48
f = 2.52

Therefore, the values of k and f that satisfy the given system of equations are:
k = 4
f = 2.52

### Answer: k = 4, f = 2.52

Expected answer: {f: 5003/1994, k: 8089/1994}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of l and n: The first equation is 31 = 58 * l - n The second equation is 103 = n + 73 * l

Claude-3 Haiku:

To solve the given system of equations, we need to find the values of l and n.

Given equations:
31 = 58 * l - n
103 = n + 73 * l

Step 1: Solve for n in the first equation.
31 = 58 * l - n
n = 58 * l - 31

Step 2: Substitute the expression for n in the second equation.
103 = n + 73 * l
103 = (58 * l - 31) + 73 * l
103 = 131 * l - 31

Step 3: Solve for l.
103 = 131 * l - 31
134 = 131 * l
l = 134 / 131
l = 1.0229

Step 4: Substitute the value of l in the first equation to find the value of n.
n = 58 * l - 31
n = 58 * 1.0229 - 31
n = 59.3282 - 31
n = 28.3282

Therefore, the values of l and n are:
l = 1.0229
n = 28.3282

### Answer: l = 1.0229, n = 28.3282

Expected answer: {l: 134/131, n: 3711/131}

Correct? No

🔗 Problem

Problem: Find the values of y and j that satisfy the following system of equations: 29y - 28j = 39 25y + 37j = 116

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve the first equation for j.
29y - 28j = 39
28j = 29y - 39
j = (29y - 39) / 28

Step 2: Substitute the expression for j into the second equation.
25y + 37j = 116
25y + 37((29y - 39) / 28) = 116
25y + (1033y - 1443) / 28 = 116
25y + 1033y / 28 - 1443 / 28 = 116
1058y / 28 - 1443 / 28 = 116
1058y - 1443 = 3248
1058y = 4691
y = 4.44

Step 3: Substitute the value of y into the first equation to find the value of j.
29(4.44) - 28j = 39
128.76 - 28j = 39
-28j = -89.76
j = 3.2

Therefore, the values of y and j that satisfy the system of equations are:
y = 4.44
j = 3.2

### Answer: y = 4.44, j = 3.2

Expected answer: {j: 2389/1773, y: 4691/1773}

Correct? No

🔗 Problem

Problem: Given the following system of equations, solve for u and a: The first equation is 93u - 85a = 74 The second equation is 96u + 17a = 186.

Claude-3 Haiku:

To solve for u and a, we can use the substitution method.

Step 1: Solve the first equation for a.
93u - 85a = 74
-85a = 74 - 93u
a = (74 - 93u) / -85
a = (74 - 93u) / -85
a = (93u - 74) / 85

Step 2: Substitute the expression for a into the second equation.
96u + 17a = 186
96u + 17((93u - 74) / 85) = 186
96u + (1581u - 1258) / 85 = 186
96u + 1581u / 85 - 1258 / 85 = 186
96u + 18.6u - 14.8 = 186
114.6u - 14.8 = 186
114.6u = 200.8
u = 200.8 / 114.6
u = 1.75

Step 3: Substitute the value of u into the expression for a.
a = (93u - 74) / 85
a = (93(1.75) - 74) / 85
a = (162.75 - 74) / 85
a = 88.75 / 85
a = 1.04

Therefore, the solution to the system of equations is:
u = 1.75
a = 1.04

### Answer: u = 1.75, a = 1.04

Expected answer: {a: 3398/3247, u: 1004/573}

Correct? No

🔗 Problem

Problem: Given the following pair of simultaneous equations, please find out the values of u and g: 97 * u - 61 * g = 15 85 * u + 23 * g = 186

Claude-3 Haiku:

To solve for the values of u and g, we can use the method of substitution or elimination.

Let's use the method of elimination.

Step 1: Multiply the first equation by 23 and the second equation by 61 to eliminate the variable g.

23 * (97 * u - 61 * g = 15)
2231 * u - 1403 * g = 345

61 * (85 * u + 23 * g = 186)
5185 * u + 1403 * g = 11346

Step 2: Subtract the first equation from the second equation to eliminate the variable g.

5185 * u + 1403 * g = 11346
-2231 * u + 1403 * g = -345
-----------------
2954 * u = 11691

Step 3: Solve for the variable u.

u = 11691 / 2954
u = 3.96

Step 4: Substitute the value of u into one of the original equations to find the value of g.

Let's use the first equation:
97 * u - 61 * g = 15
97 * 3.96 - 61 * g = 15
384.12 - 61 * g = 15
-61 * g = -369.12
g = 6.05

### Answer: u = 3.96, g = 6.05

Expected answer: {g: 1863/824, u: 1299/824}

Correct? No

🔗 Problem

Problem: Determine the values of r and b that satisfy the following system of equations. The first equation is (17 * r) + (67 * b) = 103. The second equation is (85 * r) + (67 * b) = 187.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Let's start by solving the first equation for r:

(17 * r) + (67 * b) = 103
17r + 67b = 103
r = (103 - 67b) / 17

Now, we can substitute this expression for r into the second equation:

(85 * r) + (67 * b) = 187
85 * ((103 - 67b) / 17) + 67b = 187
(85 * 103 - 85 * 67b) / 17 + 67b = 187
(8755 - 5795b) / 17 + 67b = 187
(2960 - 5795b) / 17 = 120
2960 - 5795b = 2040
-5795b = -920
b = 0.159

Now, we can substitute the value of b back into the first equation to find the value of r:

r = (103 - 67b) / 17
r = (103 - 67 * 0.159) / 17
r = (103 - 10.653) / 17
r = 92.347 / 17
r = 5.432

Therefore, the values of r and b that satisfy the given system of equations are:
r = 5.432
b = 0.159

### Answer: r = 5.432, b = 0.159

Expected answer: {b: 82/67, r: 21/17}

Correct? No

🔗 Problem

Problem: Given the following system of equations, solve for the values of t and n: 1. (85 * n) - (54 * t) = 41 2. (38 * t) + (30 * n) = 126.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve the first equation for t.
(85 * n) - (54 * t) = 41
54 * t = (85 * n) - 41
t = ((85 * n) - 41) / 54

Step 2: Substitute the expression for t in the second equation.
(38 * ((85 * n) - 41) / 54) + (30 * n) = 126
(3230 * n - 1558) / 54 + (30 * n) = 126
(3230 * n - 1558 + 1620 * n) / 54 = 126
4850 * n / 54 = 126
n = 126 * 54 / 4850
n = 1.4

Step 3: Substitute the value of n in the first equation to find the value of t.
t = ((85 * 1.4) - 41) / 54
t = (119 - 41) / 54
t = 78 / 54
t = 1.44

Therefore, the values of t and n are:
t = 1.44
n = 1.4

### Answer: t = 1.44, n = 1.4

Expected answer: {n: 4181/2425, t: 948/485}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of u and q: 1) The result of multiplying 75 by u and subtracting the product of 69 and q is equal to 5. 2) The sum of the product of 48 and u and the product of 25 and q is 140.

Claude-3 Haiku:

To solve this system of equations, we need to use the substitution method.

Given equations:
1) 75u - 69q = 5
2) 48u + 25q = 140

Step 1: Solve for u in the second equation.
48u + 25q = 140
48u = 140 - 25q
u = (140 - 25q) / 48

Step 2: Substitute the expression for u in the first equation.
75u - 69q = 5
75 * (140 - 25q) / 48 - 69q = 5
(75 * 140 - 75 * 25q) / 48 - 69q = 5
(10500 - 1875q) / 48 - 69q = 5
10500 - 1875q - 3312q = 240
-5187q = -10260
q = 2

Step 3: Substitute the value of q in the expression for u to find its value.
u = (140 - 25q) / 48
u = (140 - 25 * 2) / 48
u = (140 - 50) / 48
u = 90 / 48
u = 1.875

### Answer: u = 1.875, q = 2

Expected answer: {q: 180/91, u: 515/273}

Correct? No

🔗 Problem

Problem: Determine the values of v and x from the following system of equations: ((20 * v) + (17 * x)) = 149 and ((24 * x) - (49 * v)) = 22.

Claude-3 Haiku:

To solve this system of equations, we need to find the values of v and x.

Given the system of equations:
((20 * v) + (17 * x)) = 149
((24 * x) - (49 * v)) = 22

Step 1: Solve for v in the first equation.
((20 * v) + (17 * x)) = 149
20v + 17x = 149
20v = 149 - 17x
v = (149 - 17x) / 20

Step 2: Substitute the expression for v into the second equation.
((24 * x) - (49 * v)) = 22
((24 * x) - (49 * (149 - 17x) / 20)) = 22
24x - (7351 - 833x) / 20 = 22
24x - 7351 / 20 + 833x / 20 = 22
857x / 20 - 7351 / 20 = 22
857x - 7351 = 440
857x = 7791
x = 9

Step 3: Substitute the value of x into the expression for v.
v = (149 - 17x) / 20
v = (149 - 17(9)) / 20
v = (149 - 153) / 20
v = -4 / 20
v = -0.2

Therefore, the values of v and x are:
v = -0.2
x = 9

### Answer: v = -0.2, x = 9

Expected answer: {v: 3202/1313, x: 7741/1313}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of t and g: 39 * t + 41 * g = 147 94 * t - 91 * g = 42.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Given equations:
39 * t + 41 * g = 147
94 * t - 91 * g = 42

Step 1: Solve for t in the first equation.
39 * t + 41 * g = 147
39 * t = 147 - 41 * g
t = (147 - 41 * g) / 39

Step 2: Substitute the expression for t in the second equation.
94 * t - 91 * g = 42
94 * ((147 - 41 * g) / 39) - 91 * g = 42
(94 * 147 - 94 * 41 * g) / 39 - 91 * g = 42
(13818 - 3854 * g) / 39 - 91 * g = 42
13818 - 3854 * g - 3549 * g = 1638
-7403 * g = -12180
g = 1.65

Step 3: Substitute the value of g in the expression for t to find the value of t.
t = (147 - 41 * g) / 39
t = (147 - 41 * 1.65) / 39
t = (147 - 67.65) / 39
t = 79.35 / 39
t = 2.03

Therefore, the values of t and g are:
t = 2.03
g = 1.65

### Answer: t = 2.03, g = 1.65

Expected answer: {g: 12180/7403, t: 15099/7403}

Correct? No

🔗 Problem

Problem: Determine the values of c and o that satisfy the following system of equations: 6c + 55o = 112, and 55c - 48o = 36.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

First, let's solve for c in the first equation:
6c + 55o = 112
6c = 112 - 55o
c = (112 - 55o) / 6

Now, let's substitute this expression for c into the second equation:
55c - 48o = 36
55 * ((112 - 55o) / 6) - 48o = 36
(55 * 112 - 55 * 55o) / 6 - 48o = 36
(6160 - 3025o) / 6 - 48o = 36
(1027 - 504o) - 288o = 216
1027 - 792o = 216
-792o = -811
o = 1.025

Now, let's substitute the value of o back into the first equation to find the value of c:
6c + 55(1.025) = 112
6c + 56.375 = 112
6c = 55.625
c = 9.271

Therefore, the values of c and o that satisfy the system of equations are:
c = 9.271
o = 1.025

### Answer: c = 9.271, o = 1.025

Expected answer: {c: 7356/3313, o: 5944/3313}

Correct? No

🔗 Problem

Problem: Determine the values of u and w that satisfy the following system of equations: 8w + 68u = 170, 71w - 94u = 8.

Claude-3 Haiku:

To solve this system of linear equations, we can use the substitution method.

Step 1: Solve for u in the first equation.
8w + 68u = 170
68u = 170 - 8w
u = (170 - 8w) / 68

Step 2: Substitute the expression for u into the second equation.
71w - 94u = 8
71w - 94((170 - 8w) / 68) = 8
71w - (94 * 170 - 8 * 94w) / 68 = 8
71w - (16,180 - 752w) / 68 = 8
71w - 238 + 11w = 8
82w = 246
w = 3

Step 3: Substitute the value of w into the expression for u to find the value of u.
u = (170 - 8w) / 68
u = (170 - 8 * 3) / 68
u = (170 - 24) / 68
u = 146 / 68
u = 2.15

Therefore, the values of u and w that satisfy the given system of equations are:
u = 2.15
w = 3

### Answer: u = 2.15, w = 3

Expected answer: {u: 667/310, w: 459/155}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of r and f: 68*r + 8*f = 92 97*f + 38*r = 182

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Step 1: Solve for one variable in terms of the other.
From the first equation:
68*r + 8*f = 92
8*f = 92 - 68*r
f = (92 - 68*r)/8

Step 2: Substitute the expression for f into the second equation.
97*f + 38*r = 182
97*((92 - 68*r)/8) + 38*r = 182
(97*92 - 97*68*r)/8 + 38*r = 182
(8924 - 6596*r)/8 + 38*r = 182
1128 - 824.5*r + 304*r = 1456
-520.5*r = 328
r = -0.63

Step 3: Substitute the value of r back into the first equation to find the value of f.
68*r + 8*f = 92
68*(-0.63) + 8*f = 92
-42.84 + 8*f = 92
8*f = 134.84
f = 16.85

Therefore, the values of r and f are:
r = -0.63
f = 16.85

### Answer: r = -0.63, f = 16.85

Expected answer: {f: 2220/1573, r: 1867/1573}

Correct? No

🔗 Problem

Problem: Given the equations below, find the values of r and d: For the first equation, consider 67 apples, each worth d dollars, and 37 ragdolls, each worth r dollars. If the total value of all these items is $50, you can represent this situation with the equation 67d - 37r = 50. In another case, consider 39 ragdolls, each worth r dollars, and 21 apples, each worth d dollars. If the total value of all these items is $16, you can also represent this situation with the equation 39r - 21d = 16. From these two equations, find the values of d (the cost of each apple) and r (the cost of each ragdoll).

Claude-3 Haiku:

To solve this problem, we need to use the two given equations to find the values of r and d.

Given equations:
1. 67d - 37r = 50
2. 39r - 21d = 16

Step 1: Solve for r in the second equation.
39r - 21d = 16
39r = 16 + 21d
r = (16 + 21d) / 39

Step 2: Substitute the expression for r into the first equation.
67d - 37r = 50
67d - 37((16 + 21d) / 39) = 50
67d - (592 + 777d) / 39 = 50
2639d - 592 - 777d = 1950
1862d = 2542
d = 1.37

Step 3: Substitute the value of d into the expression for r to find the value of r.
r = (16 + 21d) / 39
r = (16 + 21(1.37)) / 39
r = (16 + 28.77) / 39
r = 44.77 / 39
r = 1.15

Therefore, the values of d (the cost of each apple) and r (the cost of each ragdoll) are:
d = $1.37
r = $1.15

### Answer: d = $1.37, r = $1.15

Expected answer: {d: 1271/918, r: 1061/918}

Correct? No

🔗 Problem

Problem: To find the values of x and a, solve the following system of simultaneous linear equations: First equation: 163 equals 50 times x plus a Second equation: 24 equals 98 times x minus 84 times a.

Claude-3 Haiku:

To solve this system of simultaneous linear equations, we need to find the values of x and a.

Given:
First equation: 163 = 50x + a
Second equation: 24 = 98x - 84a

Step 1: Solve for a in the second equation.
24 = 98x - 84a
84a = 98x - 24
a = (98x - 24) / 84

Step 2: Substitute the expression for a into the first equation.
163 = 50x + (98x - 24) / 84
163 = 50x + 98x / 84 - 24 / 84
163 = 148x / 84 - 24 / 84
163 = (148x - 24) / 84
13,684 = 148x - 24
13,708 = 148x
x = 92.5

Step 3: Substitute the value of x into the expression for a.
a = (98x - 24) / 84
a = (98 × 92.5 - 24) / 84
a = (9,065 - 24) / 84
a = 9,041 / 84
a = 107.5

Therefore, the values of x and a are:
x = 92.5
a = 107.5

### Answer: x = 92.5, a = 107.5

Expected answer: {a: 7387/2149, x: 6858/2149}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of p and b: 67 * p + 18 * b = 110 82 * b - 44 * p = 58.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Step 1: Solve the first equation for p.
67 * p + 18 * b = 110
67 * p = 110 - 18 * b
p = (110 - 18 * b) / 67

Step 2: Substitute the expression for p in the second equation.
82 * b - 44 * p = 58
82 * b - 44 * (110 - 18 * b) / 67 = 58
82 * b - 4400 + 792 * b = 3886
874 * b = 8286
b = 9.5

Step 3: Substitute the value of b in the expression for p.
p = (110 - 18 * 9.5) / 67
p = (110 - 171) / 67
p = -61 / 67

Therefore, the values of p and b are:
p = -61 / 67
b = 9.5

### Answer: p = -61 / 67, b = 9.5

Expected answer: {b: 4363/3143, p: 3988/3143}

Correct? No

🔗 Problem

Problem: Determine the values of c and e from the following simultaneous equations: The difference between 63 times c and 36 times e equals 27, and 8 times c added to 32 times e equals 69.

Claude-3 Haiku:

To solve this problem, we need to set up a system of two linear equations with two unknowns, c and e, and then solve for the values of c and e.

Given information:
- The difference between 63 times c and 36 times e equals 27.
- 8 times c added to 32 times e equals 69.

Let's represent the equations as follows:
Equation 1: 63c - 36e = 27
Equation 2: 8c + 32e = 69

Step 1: Solve for c in terms of e using Equation 2.
8c + 32e = 69
8c = 69 - 32e
c = (69 - 32e) / 8

Step 2: Substitute the expression for c into Equation 1 and solve for e.
63c - 36e = 27
63((69 - 32e) / 8) - 36e = 27
(4347 - 2016e) / 8 - 36e = 27
4347 - 2016e - 288e = 216
4347 - 2304e = 216
-2304e = -4131
e = 1.8

Step 3: Substitute the value of e into the expression for c to find the value of c.
c = (69 - 32e) / 8
c = (69 - 32(1.8)) / 8
c = (69 - 57.6) / 8
c = 11.4 / 8
c = 1.425

Therefore, the values of c and e are:
c = 1.425
e = 1.8

### Answer: c = 1.425, e = 1.8

Expected answer: {c: 93/64, e: 459/256}

Correct? No

🔗 Problem

Problem: Solve the following system of linear equations to find the values of x and p: 26 * x + 29 * p = 107 61 * x - 51 * p = 4

Claude-3 Haiku:

To solve the given system of linear equations, we can use the elimination method.

Step 1: Multiply the first equation by 51 and the second equation by 29 to eliminate the variable p.

51 * (26x + 29p = 107)
=> 1326x + 1479p = 5457

29 * (61x - 51p = 4)
=> 1769x - 1479p = 116

Step 2: Subtract the second equation from the first equation to eliminate the variable p.

1326x + 1479p = 5457
- (1769x - 1479p = 116)
-443x = 5341

Step 3: Solve for x.

-443x = 5341
x = -5341/443
x = -12

Step 4: Substitute the value of x into one of the original equations to find the value of p.

Using the first equation: 26x + 29p = 107
26(-12) + 29p = 107
-312 + 29p = 107
29p = 419
p = 419/29
p = 14.4482758620689

Therefore, the values of x and p are:
x = -12
p = 14.4482758620689

### Answer: x = -12, p = 14.4482758620689

Expected answer: {p: 6423/3095, x: 5573/3095}

Correct? No

🔗 Problem

Problem: Find the values for g and l from the system of equations below. The first equation is: ((29 * l) + (17 * g)) = 68. The second equation is: ((31 * g) - (10 * l)) = 17.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve the first equation for one of the variables, let's say l.
(29 * l) + (17 * g) = 68
29 * l = 68 - 17 * g
l = (68 - 17 * g) / 29

Step 2: Substitute the expression for l into the second equation.
(31 * g) - (10 * l) = 17
(31 * g) - (10 * (68 - 17 * g) / 29) = 17
(31 * g) - (680 - 170 * g) / 29 = 17
(31 * g - 680 + 170 * g) / 29 = 17
(201 * g - 680) / 29 = 17
201 * g - 680 = 493
201 * g = 1173
g = 5.83

Step 3: Substitute the value of g into the expression for l to find the value of l.
l = (68 - 17 * g) / 29
l = (68 - 17 * 5.83) / 29
l = (68 - 99.11) / 29
l = -31.11 / 29
l = -1.07

Therefore, the values for g and l are:
g = 5.83
l = -1.07

### Answer: g = 5.83, l = -1.07

Expected answer: {g: 1173/1069, l: 1819/1069}

Correct? No

🔗 Problem

Problem: Given the following system of equations, what are the values for a and c? 33*a - 54*c = 20 24*a - 26*c = 29.

Claude-3 Haiku:

To solve for the values of a and c, we can use the method of substitution or elimination.

Let's use the method of elimination.

First, we will multiply the first equation by 26 and the second equation by 54 to eliminate the variable c.

Multiplying the first equation by 26:
26(33*a - 54*c = 20)
858*a - 1404*c = 520

Multiplying the second equation by 54:
54(24*a - 26*c = 29)
1296*a - 1404*c = 1566

Now, we subtract the two equations to eliminate the variable c:
1296*a - 1404*c - 858*a + 1404*c = 1566 - 520
438*a = 1046
a = 1046/438
a = 2.39

Now, we can substitute the value of a into either of the original equations to solve for c.

Using the first equation:
33*2.39 - 54*c = 20
78.87 - 54*c = 20
-54*c = -58.87
c = 1.09

Therefore, the values for a and c are:
a = 2.39
c = 1.09

### Answer: a = 2.39, c = 1.09

Expected answer: {a: 523/219, c: 159/146}

Correct? No

🔗 Problem

Problem: Kat found herself stuck solving the following system of equations with two variables, d and j. Can you help her resolve it? 71d + 9j = 132 43j - 84d = 91.

Claude-3 Haiku:

Okay, let's solve this system of equations with two variables, d and j.

To solve this system, we can use the elimination method.

First, let's multiply the first equation by 84 and the second equation by 71 to eliminate one of the variables.

Multiplying the first equation by 84:
84(71d + 9j) = 84(132)
5964d + 756j = 11088

Multiplying the second equation by 71:
71(43j - 84d) = 71(91)
3053j - 5964d = 6461

Now, we can subtract the second equation from the first equation to eliminate the variable d.

5964d + 756j = 11088
-3053j + 5964d = -6461
--------------
756j = 17549

Solving for j:
j = 17549 / 756
j = 23.2

Now, we can substitute the value of j into either of the original equations to solve for d.

Let's use the first equation:
71d + 9(23.2) = 132
71d + 208.8 = 132
71d = -76.8
d = -1.08

Therefore, the solution to the system of equations is:
d = -1.08
j = 23.2

### Answer: d = -1.08, j = 23.2

Expected answer: {d: 4857/3809, j: 17549/3809}

Correct? No

🔗 Problem

Problem: Determine the values of o and n by solving this system of equations: (81 * o) + (26 * n) = 163 (87 * n) + (23 * o) = 143.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Given the system of equations:
(81 * o) + (26 * n) = 163
(87 * n) + (23 * o) = 143

Step 1: Solve for o in the first equation.
(81 * o) + (26 * n) = 163
81 * o = 163 - 26 * n
o = (163 - 26 * n) / 81

Step 2: Substitute the expression for o in the second equation.
(87 * n) + (23 * o) = 143
(87 * n) + (23 * (163 - 26 * n) / 81) = 143
(87 * n) + (3739 - 598 * n) / 81 = 143
(87 * n) + 3739 - 598 * n = 143 * 81
(87 * n) - 598 * n + 3739 = 11583
-511 * n + 3739 = 11583
-511 * n = 7844
n = -7844 / 511
n = -15.35

Step 3: Substitute the value of n in the expression for o.
o = (163 - 26 * n) / 81
o = (163 - 26 * (-15.35)) / 81
o = (163 + 398.1) / 81
o = 561.1 / 81
o = 6.93

Therefore, the values of o and n are:
o = 6.93
n = -15.35

### Answer: o = 6.93, n = -15.35

Expected answer: {n: 7834/6449, o: 10463/6449}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for w and s: 46 * s - 61 * w = 2 61 * s + 67 * w = 178.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Step 1: Solve the first equation for s.
46 * s - 61 * w = 2
46 * s = 61 * w + 2
s = (61 * w + 2) / 46

Step 2: Substitute the expression for s in the second equation.
61 * s + 67 * w = 178
61 * ((61 * w + 2) / 46) + 67 * w = 178
(61^2 * w + 122) / 46 + 67 * w = 178
(3721 * w + 122) / 46 + 67 * w = 178
3721 * w + 122 + 2082 * w = 8228
5803 * w = 8106
w = 1.4

Step 3: Substitute the value of w in the first equation to find the value of s.
46 * s - 61 * 1.4 = 2
46 * s - 85.4 = 2
46 * s = 87.4
s = 1.9

Therefore, the solution to the system of equations is:
w = 1.4
s = 1.9

### Answer: w = 1.4, s = 1.9

Expected answer: {s: 10992/6803, w: 8066/6803}

Correct? No

🔗 Problem

Problem: In the following system of equations, calculate the values of i and k. System of equations: 51*k - 8*i = 86 39*i + 8*k = 193.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve for i in the first equation.
51*k - 8*i = 86
8*i = 51*k - 86
i = (51*k - 86)/8

Step 2: Substitute the expression for i in the second equation.
39*i + 8*k = 193
39*((51*k - 86)/8) + 8*k = 193
(39*51*k - 39*86)/8 + 8*k = 193
(1989*k - 3354)/8 + 8*k = 193
1989*k - 3354 + 64*k = 1544
2053*k = 4898
k = 2.39

Step 3: Substitute the value of k in the expression for i.
i = (51*k - 86)/8
i = (51*2.39 - 86)/8
i = (122.89 - 86)/8
i = 36.89/8
i = 4.61

### Answer: i = 4.61, k = 2.39

Expected answer: {i: 9155/2053, k: 4898/2053}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of l and m: 26m + 17l = 146 93m + l = 126

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Step 1: Solve the second equation for l.
93m + l = 126
l = 126 - 93m

Step 2: Substitute the expression for l in the first equation.
26m + 17(126 - 93m) = 146
26m + 2142 - 1581m = 146
-1555m + 2142 = 146
-1555m = -1996
m = 1.28

Step 3: Substitute the value of m in the second equation to find the value of l.
l = 126 - 93(1.28)
l = 126 - 119.04
l = 6.96

Therefore, the values of l and m are:
l = 6.96
m = 1.28

### Answer: l = 6.96, m = 1.28

Expected answer: {l: 10302/1555, m: 1996/1555}

Correct? No

🔗 Problem

Problem: Determine the values of 'h' and 'f' by solving the following system of equations: 1) (8 * f) + (39 * h) = 66 2) (29 * f) + (46 * h) = 119

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve for 'f' in the first equation.
(8 * f) + (39 * h) = 66
8 * f = 66 - (39 * h)
f = (66 - 39 * h) / 8

Step 2: Substitute the expression for 'f' into the second equation.
(29 * f) + (46 * h) = 119
(29 * (66 - 39 * h) / 8) + (46 * h) = 119
(1914 - 1131 * h) / 8 + 46 * h = 119
1914 - 1131 * h + 368 * h = 952
-763 * h = -962
h = 1.26

Step 3: Substitute the value of 'h' into the expression for 'f' to find its value.
f = (66 - 39 * h) / 8
f = (66 - 39 * 1.26) / 8
f = (66 - 49.14) / 8
f = 16.86 / 8
f = 2.11

Therefore, the values of 'h' and 'f' are:
h = 1.26
f = 2.11

### Answer: h = 1.26, f = 2.11

Expected answer: {f: 1605/763, h: 962/763}

Correct? No

🔗 Problem

Problem: Find the values of k and b that satisfy the following system of equations: 22 * b + 23 * k = 109 and 62 * k - 69 * b = 14.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

First, let's solve the first equation for b:
22 * b + 23 * k = 109
22 * b = 109 - 23 * k
b = (109 - 23 * k) / 22

Now, let's substitute this expression for b into the second equation:
62 * k - 69 * b = 14
62 * k - 69 * ((109 - 23 * k) / 22) = 14
62 * k - 69 * (109 / 22 - 23 * k / 22) = 14
62 * k - 69 * (4.95 - 1.045 * k) = 14
62 * k - 341.55 + 72.105 * k = 14
134.105 * k = 355.55
k = 2.65

Now, let's substitute the value of k back into the first equation to find the value of b:
22 * b + 23 * 2.65 = 109
22 * b + 61.45 = 109
22 * b = 47.55
b = 2.16

Therefore, the values of k and b that satisfy the system of equations are:
k = 2.65
b = 2.16

### Answer: k = 2.65, b = 2.16

Expected answer: {b: 6436/2951, k: 7829/2951}

Correct? No

🔗 Problem

Problem: Solve the following system of linear equations for the values of m and s: 1. 84m - 55s = 1 2. 63m - 2s = 98.

Claude-3 Haiku:

To solve the given system of linear equations, we can use the substitution method.

Given equations:
1. 84m - 55s = 1
2. 63m - 2s = 98

Step 1: Solve for s in the second equation.
63m - 2s = 98
2s = 63m - 98
s = (63m - 98) / 2

Step 2: Substitute the expression for s in the first equation.
84m - 55[(63m - 98) / 2] = 1
84m - (55/2)(63m - 98) = 1
84m - (27.5m - 53.9) = 1
84m - 27.5m + 53.9 = 1
56.5m = -52.9
m = -52.9 / 56.5
m = -0.936

Step 3: Substitute the value of m in the expression for s to find the value of s.
s = (63m - 98) / 2
s = (63(-0.936) - 98) / 2
s = (-58.968 - 98) / 2
s = -156.968 / 2
s = -78.484

Therefore, the values of m and s are:
m = -0.936
s = -78.484

### Answer: m = -0.936, s = -78.484

Expected answer: {m: 1796/1099, s: 389/157}

Correct? No

🔗 Problem

Problem: Given the following system of equations, find the values of b and k: 1. (6 * b) + (5 * k) = 105 2. (95 * k) - (51 * b) = 67.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve the first equation for b.
(6 * b) + (5 * k) = 105
6b + 5k = 105
b = (105 - 5k) / 6

Step 2: Substitute the expression for b into the second equation.
(95 * k) - (51 * b) = 67
(95 * k) - (51 * (105 - 5k) / 6) = 67
(95 * k) - (5355 - 255k) / 6 = 67
(95 * k) - 892.5 + 42.5k = 67
137.5k = 960
k = 7

Step 3: Substitute the value of k into the first equation to find the value of b.
b = (105 - 5k) / 6
b = (105 - 5 * 7) / 6
b = (105 - 35) / 6
b = 70 / 6
b = 11.67 (rounded to two decimal places)

Therefore, the values of b and k are:
b = 11.67
k = 7

### Answer: b = 11.67, k = 7

Expected answer: {b: 1928/165, k: 1919/275}

Correct? No

🔗 Problem

Problem: Determine the values of d and u from the following pair of simultaneous linear equations: 33d + 62u = 114 and 32u + 40d = 83.

Claude-3 Haiku:

To solve this system of simultaneous linear equations, we can use the substitution method.

Step 1: Solve for d in the first equation.
33d + 62u = 114
33d = 114 - 62u
d = (114 - 62u) / 33

Step 2: Substitute the expression for d into the second equation.
32u + 40d = 83
32u + 40((114 - 62u) / 33) = 83
32u + (4560 - 2480u) / 33 = 83
32u + 2080 / 33 - 75.15u = 83
-43.15u = 83 - 2080 / 33
-43.15u = 83 - 63.03
-43.15u = 19.97
u = -19.97 / 43.15
u = -0.46

Step 3: Substitute the value of u into the expression for d to find the value of d.
d = (114 - 62u) / 33
d = (114 - 62(-0.46)) / 33
d = (114 + 28.52) / 33
d = 142.52 / 33
d = 4.32

Therefore, the values of d and u are:
d = 4.32
u = -0.46

### Answer: d = 4.32, u = -0.46

Expected answer: {d: 749/712, u: 1821/1424}

Correct? No

🔗 Problem

Problem: There are two equations below that contain the variables c and p. Can you solve this system of equations to find the values of c and p? 5 * c + 28 * p = 102 20 * c - 67 * p = 13

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve the first equation for c.
5 * c + 28 * p = 102
5 * c = 102 - 28 * p
c = (102 - 28 * p) / 5

Step 2: Substitute the expression for c into the second equation.
20 * c - 67 * p = 13
20 * ((102 - 28 * p) / 5) - 67 * p = 13
(2040 - 560 * p) / 5 - 67 * p = 13
2040 - 560 * p - 335 * p = 65
2040 - 895 * p = 65
-895 * p = -1975
p = 2.21

Step 3: Substitute the value of p back into the first equation to find the value of c.
c = (102 - 28 * 2.21) / 5
c = (102 - 61.88) / 5
c = 40.12 / 5
c = 8.024

### Answer: c = 8.024, p = 2.21

Expected answer: {c: 7198/895, p: 395/179}

Correct? No

🔗 Problem

Problem: Given the following system of linear equations, determine the value of r and q. The system of equations is: 58 * r + 12 * q = 147 97 * q - 76 * r = 76.

Claude-3 Haiku:

To solve this system of linear equations, we can use the substitution method.

Step 1: Solve for r in the first equation.
58 * r + 12 * q = 147
58 * r = 147 - 12 * q
r = (147 - 12 * q) / 58

Step 2: Substitute the expression for r in the second equation.
97 * q - 76 * r = 76
97 * q - 76 * (147 - 12 * q) / 58 = 76
97 * q - 11172 + 912 * q = 4408
1009 * q = 15580
q = 15580 / 1009
q = 15.45

Step 3: Substitute the value of q back into the expression for r.
r = (147 - 12 * 15.45) / 58
r = (147 - 185.4) / 58
r = -38.4 / 58
r = -0.66

Therefore, the values of r and q are:
r = -0.66
q = 15.45

### Answer: r = -0.66, q = 15.45

Expected answer: {q: 7790/3269, r: 13347/6538}

Correct? No

🔗 Problem

Problem: Resolve the provided system of simultaneous linear equations for v and k: 47 * v - 3 * k = 10 73 * v + 2 * k = 128.

Claude-3 Haiku:

To solve the system of simultaneous linear equations, we can use the elimination method.

Given equations:
47 * v - 3 * k = 10
73 * v + 2 * k = 128

Step 1: Multiply the first equation by 2 and the second equation by 3 to eliminate the variable k.
94 * v - 6 * k = 20
219 * v + 6 * k = 384

Step 2: Subtract the first equation from the second equation to eliminate the variable k.
125 * v = 364

Step 3: Solve for the variable v.
v = 364 / 125
v = 2.912

Step 4: Substitute the value of v into one of the original equations to solve for the variable k.
Let's use the first equation: 47 * v - 3 * k = 10
47 * 2.912 - 3 * k = 10
137.064 - 3 * k = 10
-3 * k = -127.064
k = 42.355

Therefore, the solution to the system of equations is:
v = 2.912
k = 42.355

### Answer: v = 2.912, k = 42.355

Expected answer: {k: 5286/313, v: 404/313}

Correct? No

🔗 Problem

Problem: You are given the following system of equations: The result of 89 multiplied by p minus 41 multiplied by q equals 60. The result of 27 multiplied by p plus 91 multiplied by q equals 124. What are the values of p and q?

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Let's start by solving the first equation for p:
89p - 41q = 60
p = (60 + 41q) / 89

Now, we can substitute this expression for p into the second equation:
27(60 + 41q) / 89 + 91q = 124
1620 + 1107q + 2457q = 11,036
3564q = 9,416
q = 2.64

Now, we can substitute the value of q back into the first equation to find the value of p:
p = (60 + 41(2.64)) / 89
p = (60 + 108.24) / 89
p = 168.24 / 89
p = 1.89

### Answer: p = 1.89, q = 2.64

Expected answer: {p: 5272/4603, q: 4708/4603}

Correct? No

🔗 Problem

Problem: Find the values of u and d that make these equations true: The first equation is: (88 * u) - (96 * d) = 12 The second equation is: (27 * u) + (36 * d) = 71

Claude-3 Haiku:

To find the values of u and d that make the given equations true, we need to solve the system of linear equations.

Let's start with the first equation:
(88 * u) - (96 * d) = 12

Rearranging the terms, we get:
88u - 96d = 12

Now, let's look at the second equation:
(27 * u) + (36 * d) = 71

Solving the system of equations:

From the first equation, we can express d in terms of u:
d = (88u - 12) / 96

Substituting this expression for d in the second equation, we get:
27u + 36((88u - 12) / 96) = 71
27u + 33.6u - 12.6 = 71
60.6u = 83.6
u = 83.6 / 60.6
u = 1.38

Now, we can substitute the value of u back into the first equation to find the value of d:
d = (88 * 1.38 - 12) / 96
d = (121.44 - 12) / 96
d = 109.44 / 96
d = 1.14

Therefore, the values of u and d that make the equations true are:
u = 1.38
d = 1.14

### Answer: u = 1.38, d = 1.14

Expected answer: {d: 1481/1440, u: 151/120}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of f and n: 20 * n - 18 * f = 9 and 3 * n - 2 * f = 70.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Given equations:
20 * n - 18 * f = 9
3 * n - 2 * f = 70

Step 1: Solve for f in the second equation.
3 * n - 2 * f = 70
2 * f = 3 * n - 70
f = (3 * n - 70) / 2

Step 2: Substitute the expression for f in the first equation.
20 * n - 18 * ((3 * n - 70) / 2) = 9
20 * n - 27 * n + 630 = 9
-7 * n + 630 = 9
-7 * n = -621
n = 89

Step 3: Substitute the value of n in the expression for f to find the value of f.
f = (3 * 89 - 70) / 2
f = (267 - 70) / 2
f = 197 / 2
f = 98.5

Therefore, the values of f and n are:
f = 98.5
n = 89

### Answer: f = 98.5, n = 89

Expected answer: {f: 1373/14, n: 621/7}

Correct? No

🔗 Problem

Problem: Determine the values of j and l from the following system of equations: 7 * l + 97 * j = 133 22 * j + 37 * l = 76.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

First, let's solve for j in the second equation:
22 * j + 37 * l = 76
22 * j = 76 - 37 * l
j = (76 - 37 * l) / 22

Now, let's substitute this expression for j into the first equation:
7 * l + 97 * ((76 - 37 * l) / 22) = 133
7 * l + 97 * (76 / 22 - 37 * l / 22) = 133
7 * l + 97 * (3.45 - 1.68 * l) = 133
7 * l + 335.65 - 163.16 * l = 133
-156.16 * l = -202.65
l = 1.3

Now, let's substitute the value of l into the expression for j:
j = (76 - 37 * 1.3) / 22
j = (76 - 48.1) / 22
j = 27.9 / 22
j = 1.27

### Answer: j = 1.27, l = 1.3

Expected answer: {j: 1463/1145, l: 1482/1145}

Correct? No

🔗 Problem

Problem: Determine the values of d and f from the following system of equations: 21d - 46f = 53 8d + 84f = 133.

Claude-3 Haiku:

To solve this system of equations, we can use the elimination method.

Step 1: Multiply the first equation by 8 and the second equation by 21 to eliminate the variable d.

8(21d - 46f = 53)
168d - 368f = 424

21(8d + 84f = 133)
168d + 1764f = 2793

Step 2: Subtract the first equation from the second equation to eliminate the variable d.

1764f - 368f = 2793 - 424
1396f = 2369

Step 3: Solve for the variable f.

f = 2369 / 1396
f = 1.7

Step 4: Substitute the value of f into one of the original equations to solve for the variable d.

Let's use the first equation: 21d - 46f = 53

Substituting f = 1.7, we get:
21d - 46(1.7) = 53
21d - 78.2 = 53
21d = 131.2
d = 6.25

Therefore, the values of d and f are:
d = 6.25
f = 1.7

### Answer: d = 6.25, f = 1.7

Expected answer: {d: 5285/1066, f: 2369/2132}

Correct? No

🔗 Problem

Problem: Determine the values of u and w that satisfy the following system of equations: 74u + 11w = 116 66u - 68w = 21.

Claude-3 Haiku:

To solve this system of linear equations, we can use the elimination method.

Step 1: Multiply the first equation by 66 and the second equation by 74 to eliminate one of the variables.
66(74u + 11w = 116)
4,884u + 726w = 7,656
74(66u - 68w = 21)
4,884u - 5,032w = 1,554

Step 2: Subtract the second equation from the first equation to eliminate the u variable.
4,884u + 726w = 7,656
4,884u - 5,032w = 1,554
---------------------------------------------------------------------------
1,758w = 6,102

Step 3: Solve for w.
w = 6,102 / 1,758
w = 3.47

Step 4: Substitute the value of w into one of the original equations to solve for u.
Let's use the first equation: 74u + 11w = 116
74u + 11(3.47) = 116
74u + 38.17 = 116
74u = 77.83
u = 1.05

Therefore, the values of u and w that satisfy the given system of equations are:
u = 1.05
w = 3.47

### Answer: u = 1.05, w = 3.47

Expected answer: {u: 8119/5758, w: 3051/2879}

Correct? No

🔗 Problem

Problem: Find the values of f and j that will satisfy the following system of equations: 76 * f - 42 * j = 96 47 * j + 34 * f = 136.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve the first equation for f.
76 * f - 42 * j = 96
76 * f = 96 + 42 * j
f = (96 + 42 * j) / 76

Step 2: Substitute the expression for f into the second equation.
47 * j + 34 * f = 136
47 * j + 34 * ((96 + 42 * j) / 76) = 136
47 * j + 34 * (96 / 76 + 42 * j / 76) = 136
47 * j + 3264 / 76 + 1428 * j / 76 = 136
47 * j + 4692 / 76 = 136
47 * j + 61.7 = 136
47 * j = 74.3
j = 1.58

Step 3: Substitute the value of j into the expression for f.
f = (96 + 42 * j) / 76
f = (96 + 42 * 1.58) / 76
f = (96 + 66.36) / 76
f = 162.36 / 76
f = 2.14

Therefore, the values of f and j that satisfy the system of equations are:
f = 2.14
j = 1.58

### Answer: f = 2.14, j = 1.58

Expected answer: {f: 1278/625, j: 884/625}

Correct? No

🔗 Problem

Problem: Consider the following system of equations. Find the values of u and e: 68u + 32e = 174 63e - 69u = 1.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve for u in the first equation.
68u + 32e = 174
68u = 174 - 32e
u = (174 - 32e) / 68

Step 2: Substitute the expression for u into the second equation.
63e - 69u = 1
63e - 69((174 - 32e) / 68) = 1
63e - (174 - 32e) = 68
63e - 174 + 32e = 68
95e = 242
e = 242 / 95
e = <<242/95>>2.54

Step 3: Substitute the value of e into the expression for u to find the value of u.
u = (174 - 32e) / 68
u = (174 - 32(2.54)) / 68
u = (174 - 81.28) / 68
u = 92.72 / 68
u = <<92.72/68>>1.36

Therefore, the values of u and e are:
u = 1.36
e = 2.54

### Answer: u = 1.36, e = 2.54

Expected answer: {e: 6037/3246, u: 5465/3246}

Correct? No

🔗 Problem

Problem: Find the values of p and n that satisfy the following system of linear equations: 57p + 4n = 129 and 24p + 39n = 154.

Claude-3 Haiku:

To solve this system of linear equations, we can use the elimination method.

Step 1: Multiply the first equation by 24 and the second equation by 57 to eliminate one of the variables.

24(57p + 4n = 129)
1368p + 96n = 3096

57(24p + 39n = 154)
1368p + 2223n = 8778

Step 2: Subtract the second equation from the first equation to eliminate the p variable.

(1368p + 96n = 3096) - (1368p + 2223n = 8778)
-2127n = -5682
n = 2.67

Step 3: Substitute the value of n into one of the original equations to find the value of p.

Using the first equation: 57p + 4(2.67) = 129
57p + 10.68 = 129
57p = 118.32
p = 2.08

Therefore, the values of p and n that satisfy the given system of linear equations are:
p = 2.08
n = 2.67

### Answer: p = 2.08, n = 2.67

Expected answer: {n: 1894/709, p: 4415/2127}

Correct? No

🔗 Problem

Problem: Determine the values of y and z from the given system of equations: 66 * z - 44 * y = 32 60 * y + 14 * z = 116.

Claude-3 Haiku:

To solve for the values of y and z, we can use the given system of linear equations.

Given equations:
66 * z - 44 * y = 32
60 * y + 14 * z = 116

Step 1: Solve for y in the second equation.
60 * y + 14 * z = 116
60 * y = 116 - 14 * z
y = (116 - 14 * z) / 60

Step 2: Substitute the expression for y into the first equation.
66 * z - 44 * ((116 - 14 * z) / 60) = 32
66 * z - 44 * (116 / 60 - 14 * z / 60) = 32
66 * z - 44 * (1.933 - 0.233 * z) = 32
66 * z - 85.052 + 10.252 * z = 32
76.252 * z - 85.052 = 32
76.252 * z = 117.052
z = 117.052 / 76.252
z = 1.536

Step 3: Substitute the value of z into the expression for y to find the value of y.
y = (116 - 14 * 1.536) / 60
y = (116 - 21.504) / 60
y = 94.496 / 60
y = 1.575

Therefore, the values of y and z are:
y = 1.575
z = 1.536

### Answer: y = 1.575, z = 1.536

Expected answer: {y: 901/572, z: 439/286}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the variables t and h: The first equation is 83 * t - 58 * h = 45. The second equation is 69 * h + 11 * t = 124.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

First, let's solve the first equation for t:
83 * t - 58 * h = 45
83 * t = 45 + 58 * h
t = (45 + 58 * h) / 83

Now, let's substitute this expression for t into the second equation:
69 * h + 11 * (45 + 58 * h) / 83 = 124
69 * h + 11 * (45 / 83 + 58 * h / 83) = 124
69 * h + 11 * (45 / 83 + 58 * h / 83) = 124
69 * h + 11 * (45 / 83) + 11 * (58 * h / 83) = 124
69 * h + 11 * (45 / 83) + 638 * h / 83 = 124
69 * h + 11 * (45 / 83) + 638 * h / 83 - 124 = 0
(69 + 638 / 83) * h + 11 * (45 / 83) - 124 = 0
707 * h / 83 + 495 / 83 - 124 = 0
707 * h / 83 = 124 - 495 / 83
707 * h / 83 = -371 / 83
h = -371 / (707 / 83)
h = -371 / 8.5
h = -43.6

Now, let's substitute the value of h into the first equation to find the value of t:
83 * t - 58 * (-43.6) = 45
83 * t + 2528.8 = 45
83 * t = 45 - 2528.8
t = (45 - 2528.8) / 83
t = -29.9

### Answer: t = -29.9, h = -43.6

Expected answer: {h: 9797/6365, t: 10297/6365}

Correct? No

🔗 Problem

Problem: Given the system of equations ((79 * h) - (61 * o)) = 9 and ((16 * h) - (12 * o)) = 9, what are the values of o and h?

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Let's start by solving for h in the second equation:
(16 * h) - (12 * o) = 9
16h - 12o = 9
h = (9 + 12o) / 16

Now, let's substitute this expression for h into the first equation:
(79 * ((9 + 12o) / 16)) - (61 * o) = 9
(79 * (9 + 12o) / 16) - (61 * o) = 9
(711 + 948o) / 16 - 61o = 9
711 + 948o - 976o = 144
948o - 976o = -567
-28o = -567
o = 20.25

Now, let's substitute the value of o back into the expression for h:
h = (9 + 12o) / 16
h = (9 + 12 * 20.25) / 16
h = (9 + 243) / 16
h = 252 / 16
h = 15.75

### Answer: o = 20.25, h = 15.75

Expected answer: {h: 63/4, o: 81/4}

Correct? No

🔗 Problem

Problem: Solve for variables s and y when the following system of equations is satisfied: 4 * y + 56 * s = 139 65 * y - 90 * s = 16

Claude-3 Haiku:

To solve for the variables s and y, we need to use the given system of equations and solve for them.

Given equations:
4 * y + 56 * s = 139
65 * y - 90 * s = 16

Step 1: Solve for s in the first equation.
4 * y + 56 * s = 139
56 * s = 139 - 4 * y
s = (139 - 4 * y) / 56

Step 2: Substitute the expression for s in the second equation.
65 * y - 90 * s = 16
65 * y - 90 * (139 - 4 * y) / 56 = 16
65 * y - 90 * (139 / 56 - 4 * y / 56) = 16
65 * y - 90 * (2.482142857 - 0.0714285714 * y) = 16
65 * y - 223.3928571 + 6.428571429 * y = 16
71.42857143 * y = 239.3928571
y = 3.35

Step 3: Substitute the value of y in the expression for s.
s = (139 - 4 * y) / 56
s = (139 - 4 * 3.35) / 56
s = (139 - 13.4) / 56
s = 125.6 / 56
s = 2.25

Therefore, the values of the variables s and y are:
s = 2.25
y = 3.35

### Answer: s = 2.25, y = 3.35

Expected answer: {s: 8971/4000, y: 6703/2000}

Correct? No

🔗 Problem

Problem: Solve the following pair of simultaneous equations: 42 * d - 4 * z = 75 40 * d + 45 * z = 162 Find the values of d and z.

Claude-3 Haiku:

To solve the given pair of simultaneous equations, we can use the elimination method.

Step 1: Multiply the first equation by 40 and the second equation by 42 to eliminate the variable d.

40 * (42 * d - 4 * z = 75)
1680 * d - 160 * z = 3000

42 * (40 * d + 45 * z = 162)
1680 * d + 1890 * z = 6804

Step 2: Subtract the first equation from the second equation to eliminate the variable d.

1890 * z - (-160 * z) = 6804 - 3000
2050 * z = 3804
z = 3804 / 2050
z = 1.86

Step 3: Substitute the value of z into one of the original equations to find the value of d.

Let's use the first equation:
42 * d - 4 * 1.86 = 75
42 * d - 7.44 = 75
42 * d = 82.44
d = 82.44 / 42
d = 1.96

Therefore, the values of d and z are:
d = 1.96
z = 1.86

### Answer: d = 1.96, z = 1.86

Expected answer: {d: 4023/2050, z: 1902/1025}

Correct? No

🔗 Problem

Problem: Determine the values of 'a' and 'o' from the following system of equations: (42 * o) + (24 * a) = 142 (42 * a) + (6 * o) = 75.

Claude-3 Haiku:

To solve this system of equations, we need to find the values of 'a' and 'o'.

Given equations:
(42 * o) + (24 * a) = 142
(42 * a) + (6 * o) = 75

Step 1: Solve for 'o' in the first equation.
(42 * o) + (24 * a) = 142
42 * o = 142 - 24 * a
o = (142 - 24 * a) / 42

Step 2: Substitute the expression for 'o' into the second equation.
(42 * a) + (6 * ((142 - 24 * a) / 42)) = 75
(42 * a) + (6 * (142 / 42 - 24 * a / 42)) = 75
(42 * a) + (6 * (3.38 - 0.57 * a)) = 75
(42 * a) + (20.28 - 3.42 * a) = 75
38.58 * a = 54.72
a = 54.72 / 38.58
a = 1.42

Step 3: Substitute the value of 'a' into the expression for 'o' to find its value.
o = (142 - 24 * a) / 42
o = (142 - 24 * 1.42) / 42
o = (142 - 34.08) / 42
o = 107.92 / 42
o = 2.57

Therefore, the values of 'a' and 'o' are:
a = 1.42
o = 2.57

### Answer: a = 1.42, o = 2.57

Expected answer: {a: 383/270, o: 347/135}

Correct? No

🔗 Problem

Problem: Given the following system of equations, find the values of p and r: 39*r - 2*p = 45 and 16*p - 84*r = 36.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

First, let's solve the first equation for p:
39*r - 2*p = 45
2*p = 39*r - 45
p = (39*r - 45)/2

Now, let's substitute this expression for p into the second equation:
16*p - 84*r = 36
16*((39*r - 45)/2) - 84*r = 36
(16*39*r - 16*45)/2 - 84*r = 36
(624*r - 720)/2 - 84*r = 36
312*r - 360 - 168*r = 72
144*r = 432
r = 3

Now, let's substitute the value of r back into the first equation to find the value of p:
39*3 - 2*p = 45
117 - 2*p = 45
-2*p = -72
p = 36

Therefore, the values of p and r are:
p = 36
r = 3

### Answer: p = 36, r = 3

Expected answer: {p: 216/19, r: 33/19}

Correct? No

🔗 Problem

Problem: Given the following system of equations, solve for the values of 'd' and 'w': 1. (23 * d) - (52 * w) = 7 2. (64 * w) - (8 * d) = 58

Claude-3 Haiku:

To solve for the values of 'd' and 'w', we can use the substitution method.

Step 1: Rearrange the second equation to solve for 'd' in terms of 'w'.
(64 * w) - (8 * d) = 58
8 * d = (64 * w) - 58
d = ((64 * w) - 58) / 8

Step 2: Substitute the expression for 'd' into the first equation.
(23 * ((64 * w) - 58) / 8) - (52 * w) = 7
(23 * (64 * w - 58)) / 8 - (52 * w) = 7
(1472 * w - 1334) / 8 - (52 * w) = 7
(1472 * w - 1334 - 416 * w) / 8 = 7
(1056 * w - 1334) / 8 = 7
1056 * w - 1334 = 56
1056 * w = 1390
w = 1.32

Step 3: Substitute the value of 'w' into the expression for 'd' to find the value of 'd'.
d = ((64 * 1.32) - 58) / 8
d = (84.48 - 58) / 8
d = 26.48 / 8
d = 3.31

Therefore, the values of 'd' and 'w' are:
d = 3.31
w = 1.32

### Answer: d = 3.31, w = 1.32

Expected answer: {d: 433/132, w: 695/528}

Correct? No

🔗 Problem

Problem: Solve the following system of equations for the values of n and z: (71 * z) + (60 * n) = 184 (52 * z) - (47 * n) = 19.

Claude-3 Haiku:

To solve the given system of equations, we can use the substitution method.

Given equations:
(71 * z) + (60 * n) = 184
(52 * z) - (47 * n) = 19

Step 1: Solve for n in the second equation.
(52 * z) - (47 * n) = 19
-47 * n = (52 * z) - 19
n = ((52 * z) - 19) / -47
n = ((52 * z) - 19) / 47

Step 2: Substitute the expression for n in the first equation.
(71 * z) + (60 * ((52 * z) - 19) / 47) = 184
(71 * z) + (3120 * z - 1140) / 47 = 184
(71 * z) + (3120 * z - 1140) / 47 = 184
(71 * z) + (66.38 * z - 24.26) = 184
137.38 * z - 24.26 = 184
137.38 * z = 208.26
z = 208.26 / 137.38
z = 1.52

Step 3: Substitute the value of z in the expression for n.
n = ((52 * 1.52) - 19) / 47
n = (79.04 - 19) / 47
n = 60.04 / 47
n = 1.28

Therefore, the values of n and z are:
n = 1.28
z = 1.52

### Answer: n = 1.28, z = 1.52

Expected answer: {n: 8219/6457, z: 9788/6457}

Correct? No

🔗 Problem

Problem: Given the following system of equations, find the values of e and z: 70 * e + 90 * z = 189 99 * z - 84 * e = 20

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve the first equation for e.
70 * e + 90 * z = 189
70 * e = 189 - 90 * z
e = (189 - 90 * z) / 70

Step 2: Substitute the expression for e into the second equation.
99 * z - 84 * e = 20
99 * z - 84 * ((189 - 90 * z) / 70) = 20
99 * z - (2646 - 7560 * z) / 70 = 20
99 * z - 37.8571 * (189 - 90 * z) = 20
99 * z - 7143.4286 + 3402.8571 * z = 20
4.5714 * z - 7143.4286 = 20
4.5714 * z = 7163.4286
z = 1565

Step 3: Substitute the value of z into the first equation to find the value of e.
70 * e + 90 * 1565 = 189
70 * e + 141,850 = 189
70 * e = 189 - 141,850
e = -2,023.5714

Therefore, the values of e and z are:
e = -2,023.5714
z = 1565

### Answer: e = -2,023.5714, z = 1565

Expected answer: {e: 1879/1610, z: 1234/1035}

Correct? No

🔗 Problem

Problem: Find the values of o and f that satisfy the following system of equations: 1) 26o - 44f = 95 2) 87f + 11o = 169.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

Step 1: Solve the first equation for o.
26o - 44f = 95
26o = 95 + 44f
o = (95 + 44f) / 26

Step 2: Substitute the expression for o into the second equation.
87f + 11o = 169
87f + 11((95 + 44f) / 26) = 169
87f + 1045 + 484f = 4394
571f = 3349
f = 5.86

Step 3: Substitute the value of f into the first equation to find the value of o.
o = (95 + 44f) / 26
o = (95 + 44(5.86)) / 26
o = (95 + 257.84) / 26
o = 352.84 / 26
o = 13.57

Therefore, the values of o and f that satisfy the system of equations are:
o = 13.57
f = 5.86

### Answer: o = 13.57, f = 5.86

Expected answer: {f: 3349/2746, o: 15701/2746}

Correct? No

🔗 Problem

Problem: Calculate the values of z and p using the following system of equations: 40*z - 20*p = 51 6*z + 58*p = 165.

Claude-3 Haiku:

To solve this system of equations, we can use the substitution method.

First, let's solve for z in the first equation:
40*z - 20*p = 51
40*z = 51 + 20*p
z = (51 + 20*p) / 40

Now, let's substitute this expression for z in the second equation:
6*z + 58*p = 165
6*((51 + 20*p) / 40) + 58*p = 165
(306 + 120*p) / 40 + 58*p = 165
306 + 120*p + 2320*p = 6600
2440*p = 6294
p = 6294 / 2440
p = 2.58

Now, let's substitute the value of p back into the first equation to find the value of z:
z = (51 + 20*p) / 40
z = (51 + 20*2.58) / 40
z = (51 + 51.6) / 40
z = 102.6 / 40
z = 2.565

### Answer: z = 2.565, p = 2.58

Expected answer: {p: 3147/1220, z: 3129/1220}

Correct? No

🔗 Problem

Problem: Find the values of s and f from the given system of equations: (71 * s) - (89 * f) = 5 (3 * f) + (10 * s) = 93.

Claude-3 Haiku:

To find the values of s and f, we need to solve the given system of linear equations.

Given equations:
(71 * s) - (89 * f) = 5
(3 * f) + (10 * s) = 93

Step 1: Solve for s in the second equation.
(3 * f) + (10 * s) = 93
10 * s = 93 - (3 * f)
s = (93 - 3 * f) / 10

Step 2: Substitute the expression for s in the first equation.
(71 * s) - (89 * f) = 5
(71 * (93 - 3 * f) / 10) - (89 * f) = 5
(6603 - 213 * f) / 10 - (89 * f) = 5
6603 - 213 * f - 890 * f = 50
6603 - 1103 * f = 50
-1103 * f = -6553
f = 5.94

Step 3: Substitute the value of f in the expression for s.
s = (93 - 3 * f) / 10
s = (93 - 3 * 5.94) / 10
s = (93 - 17.82) / 10
s = 7.52

Therefore, the values of s and f are:
s = 7.52
f = 5.94

### Answer: s = 7.52, f = 5.94

Expected answer: {f: 6553/1103, s: 8292/1103}

Correct? No