Common Core Standard 8.EE.C.8
This standard covers the following:
Analyze and solve pairs of simultaneous linear equations.
Problem: Let's find the values of variables q and s by solving the following system of equations: 1. (40 * s) - (91 * q) = 37 2. (30 * s) + (12 * q) = 121
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 40s - 91q = 37 Now, divide both sides by 40 to get: s - 2q = 37/40 Now, add 2q to both sides to get: s = 37/40 + 2q Now, substitute this expression for s into the second equation: 30(37/40 + 2q) + 12q = 121 Expand and simplify: 111q + 37 = 121 Subtract 37 from both sides: 111q = 84 Divide both sides by 111: q = 84/111 Now, substitute this value of q into the expression for s: s = 37/40 + 2(84/111) Simplify: s = 37/40 + 16/111 Therefore, the values of q and s are 84/111 and 37/40 + 16/111, respectively.
Expected answer: {q: 373/321, s: 2291/642}
Correct? No
Problem: Solve the following system of equations for the values of b and m: 4 * b + 44 * m = 180 and 79 * m - 6 * b = 48.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for b: 4 * b + 44 * m = 180 Subtracting 44m from both sides gives us: 4b = 180 - 44m Dividing both sides by 4 gives us: b = (180 - 44m) / 4 Now, substitute this expression for b into the second equation: 79 * m - 6 * (180 - 44m) / 4 = 48 Expanding the right-hand side gives us: 79m - 6(180 - 44m) / 4 = 48 Simplifying and rearranging gives us: 79m - 6(180 - 44m) = 4(48) Expanding the right-hand side gives us: 79m - 6(180) + 6(44m) = 192 Simplifying and rearranging gives us: 79m - 1080 + 264m = 192 Subtracting 1080 from both sides gives us: 185m = 832 Dividing both sides by 185 gives us: m = 4 Now that we have found m, we can substitute it into the expression for b that we found earlier: b = (180 - 44m) / 4 Substituting m = 4 gives us: b = (180 - 44(4)) / 4 Simplifying gives us: b = (180 - 176) / 4 Simplifying further gives us: b = 4 Therefore, the values of b and m are 4 and 4, respectively.
Expected answer: {b: 3027/145, m: 318/145}
Correct? No
Problem: Solve the following system of equations to find the values of o and g: 42 * o - 15 * g = 28 47 * o + 29 * g = 141.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for o: o = (28 + 15g) / 42 Now, substitute this expression for o into the second equation: 47(28 + 15g) / 42 + 29g = 141 Expand and simplify: 136 + 7g = 141 Subtract 136 from both sides: 7g = 5 Divide both sides by 7: g = 5/7 Now that we have found g, we can find o: o = (28 + 15(5/7)) / 42 o = (28 + 7.5) / 42 o = 35.5 / 42 o = 17/21 Therefore, the values of o and g are 17/21 and 5/7, respectively.
Expected answer: {g: 4606/1923, o: 2927/1923}
Correct? No
Problem: Given the following system of equations, determine the values of v and o: The first equation is: ((12 * v) - (6 * o)) = 21 The second equation is: ((76 * v) - (45 * o)) = 50.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 12v - 6o = 21 From the second equation, we have: 76v - 45o = 50 Now, we can solve for v and o. First, we can solve the first equation for v: v = (21 + 6o) / 12 Now, we can substitute this expression for v into the second equation: 76((21 + 6o) / 12) - 45o = 50 Expand and simplify: 140 + 76o - 45o = 50 166 - 31o = 50 31o = 116 o = 116 / 31 o = 3.71 Now that we have found o, we can find v: v = (21 + 6(3.71)) / 12 v = (21 + 22.22) / 12 v = 43.22 / 12 v = 3.66 Therefore, the values of v and o are 3.66 and 3.71, respectively.
Expected answer: {o: 83/7, v: 215/28}
Correct? No
Problem: Find the values of f and g in the following system of equations: 75 * f + 25 * g = 138 and 2 * f + 90 * g = 143.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for f: f = (138 - 25g) / 75 Now, substitute this expression for f into the second equation: (138 - 25g) / 75 + 90g = 143 Now, simplify and solve for g: 138 - 25g + 90g = 143 g = 138 - 25g g = 138 / 25 g = 5.52 Now, substitute this value for g into the first equation to find f: f = (138 - 25g) / 75 f = (138 - 25(5.52)) / 75 f = 138 / 75 f = 1.84 Therefore, f = 1.84 and g = 5.52.
Expected answer: {f: 1769/1340, g: 10449/6700}
Correct? No
Problem: Solve the following system of equations for variables y and n: the first equation is 194 = 4 * y + 14 * n and the second equation is 7 = 65 * n - 79 * y.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for y: 194 = 4y + 14n Subtract 14n from both sides: 180 = 4y Divide both sides by 4: 45 = y Now, substitute y = 45 into the second equation: 7 = 65n - 79y Substitute y = 45: 7 = 65n - 79(45) Simplify: 7 = 65n - 3495 Add 3495 to both sides: 3502 = 65n Divide both sides by 65: 53.15 = n So, n = 53.15. Now, substitute n = 53.15 into the first equation: 194 = 4y + 14n Substitute n = 53.15: 194 = 4y + 14(53.15) Simplify: 194 = 4y + 739 Subtract 739 from both sides: 120 = 4y Divide both sides by 4: 30 = y So, y = 30. Therefore, the solution to the system of equations is y = 30 and n = 53.15.
Expected answer: {n: 7677/683, y: 6256/683}
Correct? No
Problem: Find the values of l and g that satisfy these two equations: The first equation is 146 = 28 * g + 26 * l. The second equation is 6 = 41 * l - 53 * g.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for g: g = (146 - 26l) / 28 Now, substitute this expression for g into the second equation: 6 = 41l - 53(146 - 26l) / 28 Now simplify and solve for l: 6 = 41l - 53(146 - 26l) / 28 6 = 41l - 53(146) / 28 + 53(26l) / 28 6 = 41l - 146(53) / 28 + 53(26l) / 28 6 = 41l - 3998 + 146(26l) / 28 6 = 41l - 3998 + 692l 6 = 41l - 3306 Now, solve for l: l = 6 / 41 l = 146 / 28 l = 5 Now that we have found l, we can substitute it into the first equation to find g: g = (146 - 26l) / 28 g = (146 - 26(5)) / 28 g = (146 - 130) / 28 g = 16 / 28 g = 1 / 2 Therefore, the values of l and g that satisfy the two equations are l = 5 and g = 1/2.
Expected answer: {g: 2915/1263, l: 3953/1263}
Correct? No
Problem: Consider the following system of equations: 1) 20 * p + 56 * y = 90 2) 89 * p + 7 * y = 98 Resolve this system and find the values of p and y.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for p: p = 90 / 20 = 4.5 Now, substitute this value of p into the second equation: 89 * 4.5 + 7 * y = 98 Now, solve for y: y = (98 - 89 * 4.5) / 7 = 11 / 7 So, the values of p and y are 4.5 and 11/7, respectively.
Expected answer: {p: 347/346, y: 3025/2422}
Correct? No
Problem: Given the system of equations: 72*k - 22*d = 17 and 6*d +69*k = 96, find the values of variables k and d.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for k: k = (17 + 22d) / 72 Now, substitute this expression for k into the second equation: 6d + 69(17 + 22d) / 72 = 96 Expand and simplify: 6d + 1258 / 72 = 96 Multiply both sides by 72: 432d + 1258 = 6720 Subtract 1258 from both sides: 432d = 5462 Divide both sides by 432: d = 12 Now that we have found d, we can find k: k = (17 + 22d) / 72 = (17 + 22(12)) / 72 = 17 / 72 + 22 / 72 = 1 / 4 + 2 / 7 = 3 / 7 Therefore, the values of k and d are 3/7 and 12, respectively.
Expected answer: {d: 1913/650, k: 369/325}
Correct? No
Problem: Solve the following system of equations to find the values of d and h: 73 * h - 33 * d = 48 10 * d + 14 * h = 91
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for d: d = (48 - 73h) / 33 Now, substitute this expression for d into the second equation: 10(48 - 73h) / 33 + 14h = 91 Expand and simplify: 480 - 730h + 10h = 910 -730h + 10h = 430 -720h = 330 h = 330 / 720 h = 1/2 Now that we have the value of h, we can find the value of d: d = (48 - 73(1/2)) / 33 d = (48 - 36.5) / 33 d = 11.5 / 33 d = 1/3 Therefore, the values of d and h are 1/3 and 1/2, respectively.
Expected answer: {d: 5971/1192, h: 3483/1192}
Correct? No
Problem: Solve the following system of equations for the values of q and e: 1) 43 * q - 44 * e = 29 2) 30 * q + 43 * e = 130
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 43q - 44e = 29 Multiplying both sides by -1, we get: 44e - 43q = -29 Now, adding the second equation to both sides of the above equation, we get: 30q + 43e = 130 + (-29) Simplifying, we get: 30q + 43e = 101 Now, we have a linear equation in q and e. Solving for q, we get: q = (101 - 43e) / 30 Now, substituting this value of q in the first equation, we get: 43(101 - 43e) / 30 - 44e = 29 Simplifying, we get: 123 - 129e = 29 Adding 129e to both sides, we get: 123 = 29 + 129e Subtracting 29 from both sides, we get: 94 = 129e Dividing both sides by 129, we get: e = 94 / 129 Therefore, the value of e is 94/129. Now, substituting this value of e in the equation q = (101 - 43e) / 30, we get: q = (101 - 43(94/129)) / 30 Simplifying, we get: q = 101 / 30 - (43/129) Therefore, the value of q is 3 + (43/129).
Expected answer: {e: 4720/3169, q: 6967/3169}
Correct? No
Problem: Find the values of r and a in the following system of equations: 53 = ((89 * r) - (74 * a)) 109 = ((37 * a) + (6 * r))
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for r: r = 53 / (89 - 74a) Now, substitute this expression for r into the second equation: 109 = 37a + 6(53 / (89 - 74a)) Now, simplify the right-hand side of the equation: 109 = 37a + 6(53 / (89 - 74a)) 109 = 37a + 6(53 / 15) 109 = 37a + 6(3) 109 = 37a + 18 Now, solve for a: a = 109 / 37 a = 3 Now that we have found a, we can substitute it into the first equation to find r: r = 53 / (89 - 74a) r = 53 / (89 - 74(3)) r = 53 / 15 r = 3 Therefore, the values of r and a are 3 and 3, respectively.
Expected answer: {a: 9383/3737, r: 271/101}
Correct? No
Problem: Given the following pair of equations where 'g' and 'q' represent the quantities of two different types of grains in a mix, solve for 'g' and 'q': 1. The sum of the weights of 42 units of 'g' and 12 units of 'q' equals 169 kg. 2. The weight of 12 units of 'q' minus the weight of 50 units of 'g' results in 19 kg.
CodeLlama 34B:
To solve for 'g' and 'q', we need to use the two equations given. From the first equation, we can write: 42g + 12q = 169 From the second equation, we can write: 12q - 50g = 19 Now, we can solve for 'g' and 'q' by adding the two equations: 42g + 12q = 169 12q - 50g = 19 Adding the two equations, we get: 54g + 12q = 188 Now, we can solve for 'g' by subtracting 12q from both sides: 54g = 188 - 12q Substituting the value of 12q from the first equation, we get: 54g = 188 - 12(42) 54g = 188 - 492 54g = -324 Dividing both sides by 54, we get: g = -6.3 Now, we can find 'q' by substituting the value of 'g' in the first equation: 42(-6.3) + 12q = 169 -260.4 + 12q = 169 12q = 439.4 q = 36.6 Therefore, the values of 'g' and 'q' are -6.3 and 36.6, respectively.
Expected answer: {g: 75/46, q: 578/69}
Correct? No
Problem: Find the values of s and v for the following system of equations: 37 * s - 11 * v = 54 82 * s - 62 * v = 41
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for s: s = (54 + 11v) / 37 Now, substitute this expression for s into the second equation: 82 * (54 + 11v) / 37 - 62v = 41 Expand and simplify: 294 + 11v - 62v = 41 11v - 21 = 41 11v = 62 v = 5 Now that we have found v, we can substitute it into the first equation to find s: s = (54 + 11v) / 37 = (54 + 11(5)) / 37 = 65 / 37 Therefore, s = 65/37 and v = 5.
Expected answer: {s: 2897/1392, v: 2911/1392}
Correct? No
Problem: Based on the following two equations, find the values for c and z: The first equation is 41 * c + 65 * z = 151 The second equation is 78 * z - 48 * c = 48.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for c: 41c + 65z = 151 c = (151 - 65z) / 41 Now, substitute the expression for c into the second equation: 78z - 48(151 - 65z) / 41 = 48 78z - 48(151) / 41 + 48(65z) / 41 = 48 78z - 3968 / 41 + 296z / 41 = 48 78z - 3672 / 41 = 48 78z = 4336 / 41 z = 61 Now that we have the value of z, we can find the value of c: c = (151 - 65z) / 41 c = (151 - 65(61)) / 41 c = (151 - 3965) / 41 c = -3814 / 41 c = -93 Therefore, the values of c and z are -93 and 61, respectively.
Expected answer: {c: 37/27, z: 512/351}
Correct? No
Problem: Given the following system of equations: 60 * c - 91 * i = 7 7 * i + 76 * c = 148 What are the values of c and i?
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for c: c = 7/60 Now, substitute this value of c into the second equation: 7i + 76(7/60) = 148 Simplify: 7i + 49 = 148 Subtract 7i from both sides: 49 = 148 - 7i Subtract 49 from both sides: 148 - 7i - 49 = 0 Add 7i to both sides: 7i = 99 Divide both sides by 7: i = 14 Now we have the value of i, so we can find the value of c: c = 7/60 Therefore, the values of c and i are 7/60 and 14, respectively.
Expected answer: {c: 1931/1048, i: 2087/1834}
Correct? No
Problem: Find the values of e and v that satisfy the following two simultaneous linear equations: 1) 71*v - 37*e = 69 2) 41*e + 76*v = 184
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 71v - 37e = 69 Now, from the second equation, we have: 41e + 76v = 184 We can solve for e in the first equation: e = (69 + 37v) / 71 Now, substitute this expression for e into the second equation: 41((69 + 37v) / 71) + 76v = 184 Expand and simplify: 297 + 259v = 184 Subtract 297 from both sides: 259v = 87 Now, divide both sides by 259: v = 87 / 259 Now, we can find e by substituting v into the first equation: e = (69 + 37(87 / 259)) / 71 Simplify: e = 11 / 259 Therefore, the values of e and v that satisfy the two equations are e = 11/259 and v = 87/259.
Expected answer: {e: 7820/5723, v: 9637/5723}
Correct? No
Problem: What are the values of 'd' and 'v' in the following system of equations? The sum of 25 times 'v' and 69 times 'd' equals 113. The sum of 26 times 'd' and 42 times 'v' equals 85.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 25v + 69d = 113 From the second equation, we have: 26d + 42v = 85 Now, we can solve for 'v' in the first equation: v = (113 - 69d) / 25 Now, substitute this expression for 'v' in the second equation: 26d + 42((113 - 69d) / 25) = 85 Now, simplify and solve for 'd': 26d + 42(113/25) - 42(69d/25) = 85 26d + 42(4) - 42(69d/25) = 85 26d + 168 - 287d = 85 -263d = -83 d = 3 Now that we have found 'd', we can find 'v': v = (113 - 69d) / 25 = (113 - 69(3)) / 25 = (113 - 207) / 25 = -94 / 25 = -3 So, the values of 'd' and 'v' are 3 and -3, respectively.
Expected answer: {d: 2621/2248, v: 2927/2248}
Correct? No
Problem: Solve the following equations for g and z: 43 * z - 91 * g = 33 72 * g - 3 * z = 68
CodeLlama 34B:
To solve for g and z, we can use substitution or elimination. Let's use substitution. First, solve the first equation for g: g = (33 + 91z) / 43 Now, substitute this expression for g into the second equation: 72(33 + 91z) / 43 - 3z = 68 Expand and simplify: 2197 + 643z - 3z = 68 Combine like terms: 1554 - 3z = 68 Add 3z to both sides: 1554 = 68 + 3z Subtract 68 from both sides: 1486 = 3z Divide both sides by 3: 495 = z Now, substitute this value of z into the first equation to solve for g: g = (33 + 91z) / 43 g = (33 + 91(495)) / 43 g = (33 + 4435) / 43 g = 4768 / 43 g = 111 Therefore, g = 111 and z = 495.
Expected answer: {g: 3023/2823, z: 8564/2823}
Correct? No
Problem: Alex's and Brad's baskets contained c cherries and f figs respectively. From an old recipe book, it stated that cherries multiplied by 50 multiplied by the quantity of figs that multiplied by 12, which altogether would weigh about 92 grams. Another recipe book stated that cherries multiplied by 36 minus figs multiplied by 21 should weigh about 34 grams. Can you find the quantity of cherries (c) and figs (f)? Use the following system of equations to solve: 50c + 12f = 92 36c - 21f = 34.
CodeLlama 34B:
To solve this system of equations, we can first solve the first equation for c: 50c + 12f = 92 50c = 92 - 12f 50c = 80 + 12f c = 80/50 + 12/50f c = 1.6 + 2.4f Now, we can substitute this expression for c into the second equation: 36(1.6 + 2.4f) - 21f = 34 57.6 + 64.8f - 21f = 34 92.4f - 21f = 34 71.4f = 68 f = 68/71.4 f = 0.96 Now we can find c: c = 1.6 + 2.4f c = 1.6 + 2.4(0.96) c = 1.6 + 2.288 c = 3.888 So, the quantity of cherries is approximately 3.888 and the quantity of figs is approximately 0.96.
Expected answer: {c: 30/19, f: 62/57}
Correct? No
Problem: Here are the equations you'll need to solve (remember, the goal is to find the values of u and d): 1) 87u - 75d = 7 2) 85d - 82u = 54
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. From the first equation, we can solve for u: u = (7 + 75d) / 87 Now, substitute this expression for u into the second equation: 85d - 82((7 + 75d) / 87) = 54 Now simplify and solve for d: 85d - 82(7 + 75d) / 87 = 54 85d - 82(7) / 87 - 82(75d) / 87 = 54 85d - 56 / 87 - 6175d / 87 = 54 85d - 623 / 87 = 54 85d = 623 / 87 + 54 85d = 116 / 87 d = 116 / 87 / 85 d = 1 / 87 Now that we have found d, we can find u: u = (7 + 75d) / 87 u = (7 + 75(1/87)) / 87 u = (7 + 75/87) / 87 u = 7/87 + 75/87^2 u = 78/87^2 Therefore, the values of u and d are u = 78/87^2 and d = 1/87.
Expected answer: {d: 5272/1245, u: 929/249}
Correct? No
Problem: Bill is trying to decipher a secret code. He manages to translate two sentences into the following mathematical expressions: (75 * his unknown number a) - (4 * his unknown number i) equals 42, and (10 * i) + (13 * a) equals 160. Using these equations, can you figure out the values of i and a for him?
CodeLlama 34B:
Yes, I can help Bill solve the system of equations. First, let's rewrite the first equation as: 75a - 4i = 42 We can solve for a by adding 4i to both sides: 75a = 42 + 4i Now, let's rewrite the second equation as: 10i + 13a = 160 We can solve for i by subtracting 13a from both sides: 10i = 160 - 13a Now we have two equations and two unknowns. We can substitute the expression for 10i from the second equation into the first equation: 75a = 42 + 4(160 - 13a) Now we can simplify and solve for a: 75a = 42 + 640 - 52a Subtracting 640 from both sides gives us: 17a = 42 + 52a Subtracting 52a from both sides gives us: 12a = 42 Dividing both sides by 12 gives us: a = 3 Now we can substitute a = 3 into either of the original equations to solve for i: 10i + 13(3) = 160 Subtracting 39 from both sides gives us: 6i = 121 Dividing both sides by 6 gives us: i = 20 Therefore, the values of i and a are i = 20 and a = 3.
Expected answer: {a: 530/401, i: 5727/401}
Correct? No
Problem: Solve the following system of equations for the values of p and c: 37 * p + 74 * c = 183 27 * c - 18 * p = 13
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the second equation for c: c = (13 + 18p) / 27 Now, substitute this expression for c into the first equation: 37p + 74(13 + 18p) / 27 = 183 Expand and simplify: 37p + 13(18p) / 27 = 183 Combine like terms: 51p = 183 Divide by 51: p = 183 / 51 p = 3 Now that we have the value of p, we can find the value of c: c = (13 + 18p) / 27 c = (13 + 18(3)) / 27 c = 13 + 54 / 27 c = 13 + 2 c = 15 Therefore, the values of p and c are 3 and 15, respectively.
Expected answer: {c: 3775/2331, p: 3979/2331}
Correct? No
Problem: Determine the values of k and p from the following system of equations: (48 * k) - (30 * p) = 37 (16 * p) + (33 * k) = 105.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for k: k = 37 / (48 - 30p) Now, substitute this expression for k into the second equation: (16p + 33(37 / (48 - 30p))) = 105 Now simplify and solve for p: 16p + 33(37 / (48 - 30p)) = 105 16p + 33(37 / 18) = 105 16p + 33(2) = 105 16p + 66 = 105 16p = 39 p = 2.44 Now that we have p, we can find k: k = 37 / (48 - 30p) k = 37 / (48 - 30(2.44)) k = 37 / 14.56 k = 2.6 So, k = 2.6 and p = 2.44.
Expected answer: {k: 1871/879, p: 1273/586}
Correct? No
Problem: Consider the following pair of equations. 1. 75v - 69f = 14 2. 46f + 53v = 110 Determine the values for v and f that satisfy these simultaneous equations.
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for v: v = (14 + 69f) / 75 Now, substitute this expression for v into the second equation: 46f + 53((14 + 69f) / 75) = 110 Expand and simplify: 46f + 53(14/75) + 53f = 110 Combine like terms: 46f + 53f = 110 - 53(14/75) Simplify: 99f = 110 - 53(14/75) Solve for f: f = (110 - 53(14/75)) / 99 Now, substitute this expression for f into the first equation to solve for v: v = (14 + 69f) / 75 v = (14 + 69((110 - 53(14/75)) / 99)) / 75 Simplify: v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99)) / 75 v = (14 + 69(110/99) - 69(14/99
Expected answer: {f: 7508/7107, v: 358/309}
Correct? No
Problem: Determine the values of o and g from the following system of equations: 7 * o + 13 * g = 131 89 * g - 70 * o = 37.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for o: o = (131 - 13g) / 7 Now, substitute this expression for o into the second equation: 89g - 70(131 - 13g) / 7 = 37 Expand and simplify: 89g - 1039 + 91g = 37 Combine like terms: 190g - 1039 = 37 Add 1039 to both sides: 190g = 1116 Divide by 190: g = 6 Now that we have found g, we can find o: o = (131 - 13g) / 7 = (131 - 13(6)) / 7 = (131 - 78) / 7 = 53 / 7 = 7 So, the values of o and g are 7 and 6, respectively.
Expected answer: {g: 449/73, o: 3726/511}
Correct? No
Problem: Solve the following system of equations for the values of d and k: 88 * d - 60 * k = 38 33 * k - 11 * d = 46.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for d: d = (38 + 60k) / 88 Now, substitute this expression for d into the second equation: 33k - 11(38 + 60k) / 88 = 46 Expand and simplify: 33k - 38 - 11(60k) / 88 = 46 Combine like terms: 22k - 38 = 46 Add 38 to both sides: 22k = 84 Divide by 22: k = 4 Now that we have found k, we can substitute it into the first equation to find d: d = (38 + 60k) / 88 = (38 + 60(4)) / 88 = 168 / 88 = 19 / 7 Therefore, the values of d and k are d = 19/7 and k = 4.
Expected answer: {d: 669/374, k: 203/102}
Correct? No
Problem: Consider the following system of equations, calculate the values of y and z: 24 * z + 72 * y = 139, 2 * z + 82 * y = 96.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for z: 24z + 72y = 139 z = (139 - 72y) / 24 Now, substitute this expression for z into the second equation: 2(139 - 72y) / 24 + 82y = 96 Expand and simplify: 26 - 168y / 24 + 82y = 96 Combine like terms: -106y / 24 = -32 y = 32 / 106 Now, substitute this value of y into one of the original equations to find z: 24z + 72(32 / 106) = 139 z = (139 - 24(32 / 106)) / 72 z = 24 / 72 z = 1 / 3 So, y = 32 / 106 and z = 1 / 3.
Expected answer: {y: 1013/912, z: 2243/912}
Correct? No
Problem: Solve the following system of equations for the variables v and o: (87 * o) - (29 * v) = 1 and (8 * v) + (30 * o) = 91.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for v: v = (1 + 29o) / 87 Now, substitute this expression for v into the second equation: (8 * (1 + 29o) / 87) + (30 * o) = 91 Expand and simplify: (8 / 87) + (29 / 87)o = 91 / 87 o = 91 / 87 - 8 / 87 o = 11 / 87 Now that we have found o, we can find v: v = (1 + 29(11 / 87)) / 87 v = (1 + 319 / 87) / 87 v = 88 / 87 Therefore, the solution to the system of equations is v = 88/87 and o = 11/87.
Expected answer: {o: 2647/1566, v: 2629/522}
Correct? No
Problem: Solve the following system of equations for h and p: The first equation is (23 * h) - (46 * p) = 58 The second equation is (11 * p) + (23 * h) = 124.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for h: h = (58 + 46p) / 23 Now, substitute this expression for h into the second equation: (11p + 23(58 + 46p) / 23) = 124 Expand and simplify: 11p + 23(58 + 46p) / 23 = 124 Combine like terms: 11p + 58 + 103p = 124 Subtract 58: 11p + 103p = 66 Subtract 103p: 11p = 66 - 103p Subtract 11p: -103p = 66 - 11p Multiply by -1: 103p = 11p - 66 Add 11p: 114p = 66 Divide by 114: p = 66 / 114 Now, substitute this expression for p into the first equation to solve for h: h = (58 + 46(66 / 114)) / 23 Simplify: h = (58 + 2976 / 114) / 23 Simplify: h = 2976 / 257 Simplify: h = 11 Therefore, h = 11 and p = 66 / 114.
Expected answer: {h: 2114/437, p: 22/19}
Correct? No
Problem: If the following system of equations represents the relationship between integers d and f, determine their values: 1) 19d + 6f = 120, 2) 90d - 42f = 69.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for d: 19d = 120 - 6f d = (120 - 6f) / 19 Now, substitute this expression for d into the second equation: 90((120 - 6f) / 19) - 42f = 69 Expand and simplify: 1140 - 576f - 42f = 69 Add 576f to both sides: 1140 - 42f = 69 + 576f Subtract 42f from both sides: 1100 = 69 + 534f Subtract 69 from both sides: 1031 = 534f Divide both sides by 534: f = 1031 / 534 f = 1.94 Now that we have found f, we can find d: d = (120 - 6f) / 19 d = (120 - 6(1.94)) / 19 d = (120 - 11.64) / 19 d = 7.36 / 19 d = 0.38 Therefore, the values of d and f are 0.38 and 1.94, respectively.
Expected answer: {d: 909/223, f: 3163/446}
Correct? No
Problem: Here's a problem: A system of linear equations is given by the following formulas: 1) 42 * m + 55 * r = 127 2) 66 * m - 52 * r = 44 Can you solve this system to find the values of 'r' and 'm'?
CodeLlama 34B:
Yes, I can solve this system of linear equations. First, we can solve the first equation for 'r': r = (127 - 42m) / 55 Now, we can substitute this expression for 'r' into the second equation: 66m - 52(127 - 42m) / 55 = 44 Simplifying this expression, we get: 66m - 127m + 2594 / 55 = 44 Combine like terms: -61m + 2594 / 55 = 44 Now, we can solve for 'm': m = (2594 / 55 - 44) / -61 m = 11 / 3 Now that we have found 'm', we can find 'r' by substituting this value into the first equation: r = (127 - 42(11/3)) / 55 r = 23 / 11 Therefore, the values of 'r' and 'm' are 23/11 and 11/3, respectively.
Expected answer: {m: 1504/969, r: 363/323}
Correct? No
Problem: Determine the values of n and w that satisfy the following system of linear equations simultaneously: 31n + 64w = 120 57w + 71n = 173
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for n: n = (120 - 64w) / 31 Now, substitute this expression for n into the second equation: 57w + 71((120 - 64w) / 31) = 173 Expand and simplify: 57w + 71(120/31 - 64w/31) = 173 57w + 71(3 - 2w) = 173 114w + 147 = 173 Subtract 147 from both sides: 114w = 26 Divide both sides by 114: w = 26/114 Now, substitute this value of w into one of the original equations to solve for n: n = (120 - 64w) / 31 Substitute w = 26/114: n = (120 - 64(26/114)) / 31 Expand and simplify: n = (120 - 16/7) / 31 n = 31 - 16/7 n = 31 - 2 n = 29 Therefore, the values of n and w that satisfy the system of linear equations are n = 29 and w = 26/114.
Expected answer: {n: 4232/2777, w: 3157/2777}
Correct? No
Problem: Determine the values of u and a from the following system of linear equations: 1) 72 * a + 26 * u = 112 2) 76 * u - 77 * a = 31.
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 72a + 26u = 112 Substituting the value of u from the second equation, we get: 72a + 26(76 - 77a) = 112 Expanding and simplifying, we get: 72a - 2052 + 1912a = 112 Comparing like terms, we get: 83a = 112 Dividing both sides by 83, we get: a = 13 Now, substituting the value of a in the second equation, we get: 76u - 77(13) = 31 Simplifying, we get: 76u - 969 = 31 Adding 969 to both sides, we get: 76u = 1000 Dividing both sides by 76, we get: u = 13 Therefore, the values of u and a are 13 and 13, respectively.
Expected answer: {a: 3853/3737, u: 5428/3737}
Correct? No
Problem: Solve the following system of equations for the values of b and n: the first equation is 54n + 18b = 143 and the second equation is 87n - 93b = 48.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for n: 54n + 18b = 143 n = (143 - 18b) / 54 Now, substitute this expression for n into the second equation: 87(143 - 18b) / 54 - 93b = 48 Expand and simplify: 87(143 - 18b) / 54 - 93b = 48 87(143) / 54 - 87(18b) / 54 - 93b = 48 87(143) / 54 - 1694b / 54 - 93b = 48 87(143) - 1694b - 4671b = 2532 -1694b - 4671b = -2532 + 87(143) -6365b = -2532 + 1291 b = (-2532 + 1291) / -6365 b = 1291 / -6365 b = -2 / 3 Now that we have found b, we can find n: n = (143 - 18b) / 54 n = (143 - 18(-2/3)) / 54 n = (143 + 36) / 54 n = 181 / 54 n = 3 Therefore, the values of b and n are -2/3 and 3, respectively.
Expected answer: {b: 3283/2196, n: 4721/2196}
Correct? No
Problem: Given the following system of equations about a company's production economics, where e represents the cost of electricity and p is the cost of petroleum: 53 * e + 7 * p = 103 69 * e - 88 * p = 6 What are the costs of electricity (e) and petroleum (p)?
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the second equation for p: p = (69e - 6) / 88 Now, substitute this expression for p into the first equation: 53e + 7(69e - 6) / 88 = 103 Expand and simplify: 53e + 485e - 46 = 103 Combine like terms: 101e - 46 = 103 Add 46 to both sides: 101e = 150 Divide by 101: e = 1.48 Now, substitute this value for e into the expression we found for p: p = (69e - 6) / 88 Substitute e = 1.48: p = (69(1.48) - 6) / 88 Simplify: p = 10.12 / 88 p = 0.115 So, the cost of electricity is $1.48 and the cost of petroleum is $0.115.
Expected answer: {e: 9106/5147, p: 6789/5147}
Correct? No
Problem: Consider the following pair of linear equations. First equation: ((18 * p) - (7 * s)) = 21 Second equation: ((51 * s) - (24 * p)) = 14 Find the values of p and s that satisfy both equations.
CodeLlama 34B:
To find the values of p and s that satisfy both equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for p: p = (21 + 7s) / 18 Now, substitute this expression for p into the second equation: (51s - 24(21 + 7s)) / 18 = 14 Expand and simplify: (51s - 129 - 168s) / 18 = 14 Combine like terms: -117s - 129 / 18 = 14 Multiply both sides by 18: -117s - 129 = 228 Add 129 to both sides: -117s = 101 Divide both sides by -117: s = -101/117 Now, substitute this value of s into the first equation to solve for p: p = (21 + 7(-101/117)) / 18 = (21 - 77/117) / 18 = 14/18 So, the values of p and s that satisfy both equations are p = 14/18 and s = -101/117.
Expected answer: {p: 1169/750, s: 126/125}
Correct? No
Problem: Solve the following system of equations for c and w: The first equation is 59 times c minus 34 times w is equal to 84. The second equation is 11 times c plus 42 times w is equal to 98.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 59c - 34w = 84 Now, from the second equation, we have: 11c + 42w = 98 We can solve for c in the first equation: c = (84 + 34w) / 59 Now, substitute this expression for c into the second equation: 11(84 + 34w) / 59 + 42w = 98 Expand and simplify: 11(84) / 59 + 11(34w) / 59 + 42w = 98 11(123) / 59 + 42w = 98 11(123) + 42w = 59(98) 11(123) + 42w = 5742 Now, solve for w: 42w = 5742 - 11(123) 42w = 5742 - 1353 42w = 4389 w = 4389 / 42 w = 104 Now, substitute w = 104 into the expression for c: c = (84 + 34(104)) / 59 c = (84 + 3528) / 59 c = 3612 / 59 c = 62 Therefore, c = 62 and w = 104.
Expected answer: {c: 1715/713, w: 2429/1426}
Correct? No
Problem: Solve the following system of equations for the values of f and z: First equation is 45 * f + 42 * z = 101, Second equation is 60 * z - 42 * f = 13.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. From the first equation, we can solve for f: f = (101 - 42z) / 45 Now, substitute this expression for f into the second equation: 60z - 42((101 - 42z) / 45) = 13 Expand and simplify: 60z - 42(101/45) + 42z = 13 Combine like terms: 58z = 13 + 42(101/45) z = (13 + 42(101/45)) / 58 Now, solve for z: z = (13 + 42(101/45)) / 58 z = (13 + 42(2.2)) / 58 z = (13 + 88.4) / 58 z = 9.4 / 58 z ≈ 0.16 Now that we have found z, we can find f: f = (101 - 42z) / 45 f = (101 - 42(0.16)) / 45 f = (101 - 6.72) / 45 f = 94.28 / 45 f ≈ 2.09 Therefore, the values of f and z are f = 2.09 and z = 0.16.
Expected answer: {f: 919/744, z: 1609/1488}
Correct? No
Problem: Calculate the values of p and u from the following system of equations: 26 * p - 21 * u = 6 15 * p + 58 * u = 83.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for p: 26 * p - 21 * u = 6 p = 6 / 26 p = 2/13 Now, we can substitute the value of p into the second equation: 15 * p + 58 * u = 83 15 * (2/13) + 58 * u = 83 30/13 + 58 * u = 83 58 * u = 83 - 30/13 58 * u = 83 - 22/13 58 * u = 61/13 u = 61/13 / 58 u = 11/13 Therefore, the values of p and u are 2/13 and 11/13, respectively.
Expected answer: {p: 2091/1823, u: 2068/1823}
Correct? No
Problem: Solve for the values of n and s using these two simultaneous equations: 1) 92 * n - 38 * s = 62 2) 59 * n + 8 * s = 75
CodeLlama 34B:
To solve for the values of n and s, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 92n - 38s = 62 From the second equation, we have: 59n + 8s = 75 Now, we can solve for n and s by substituting the expression for n in terms of s from the first equation into the second equation: 59(92/38) - 8s = 75 Now, we can solve for s: s = 75 - 59(92/38) s = 75 - 59(2.42) s = 75 - 136.38 s = -61.38 Now, we can find n by substituting the value of s into the first equation: 92n - 38(-61.38) = 62 92n + 2341.36 = 62 92n = 62 - 2341.36 92n = -2239.36 Now, we can solve for n: n = -2239.36 / 92 n = -24.53 So, the values of n and s are n = -24.53 and s = -61.38.
Expected answer: {n: 1673/1489, s: 1621/1489}
Correct? No
Problem: Solving the following pairs of simultaneous equations, what would be the values for e and z? The equations are: 87 * z - 35 * e = 63 and 81 * z + 58 * e = 154.
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for z: z = (63 + 35e) / 87 Now, substitute this expression for z into the second equation: 81(63 + 35e) / 87 + 58e = 154 Expand and simplify: 531 + 297e = 154e Subtract 297e from both sides: 234 = 137e Now, divide both sides by 137: e = 234 / 137 e = 1.71 Now that we have found e, we can find z: z = (63 + 35e) / 87 z = (63 + 35(1.71)) / 87 z = 24.35 Therefore, the values for e and z are e = 1.71 and z = 24.35.
Expected answer: {e: 2765/2627, z: 9044/7881}
Correct? No
Problem: To find the values of h and t, solve the following system of simultaneous linear equations: (11 * t) + (44 * h) = 110 (98 * t) - (36 * h) = 18.
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for t: t = (110 - 44h) / 11 Now, substitute this expression for t into the second equation: (98 * (110 - 44h) / 11) - 36h = 18 Expand and simplify: 980 - 44h - 36h = 18 Combine like terms: 52h = 78 Divide by 52: h = 1.5 Now, substitute h into the first equation to solve for t: t = (110 - 44h) / 11 = (110 - 44(1.5)) / 11 = 110 - 66 / 11 = 110 - 6 = 104 Therefore, h = 1.5 and t = 104.
Expected answer: {h: 481/214, t: 108/107}
Correct? No
Problem: Solve the following system of linear equations to find the values of b and o: ((69 * b) - (50 * o)) = 55 ((41 * o) + (18 * b)) = 85.
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for b: b = (55 + 50o) / 69 Now, substitute this expression for b into the second equation: (41o + 18(55 + 50o)) / 69 = 85 Expand and simplify: (41o + 860 + 90o) / 69 = 85 Combine like terms: 121o + 860 / 69 = 85 Now, solve for o: o = (860 - 85(69)) / 121 o = (-540) / 121 o = -4.5 Now, substitute this value of o into the first equation to find b: b = (55 + 50(-4.5)) / 69 b = (-225) / 69 b = -3.29 Therefore, the values of b and o are b = -3.29 and o = -4.5.
Expected answer: {b: 6505/3729, o: 1625/1243}
Correct? No
Problem: Solve the following system of equations to find the values of p and q: 67 * q - 80 * p = 65, and 6 * q + 5 * p = 177.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for q: q = (65 + 80p) / 67 Now, substitute this expression for q into the second equation: 6q + 5p = 177 Now we have a linear equation in p and q, which we can solve using substitution or elimination. Let's use substitution again. First, solve the second equation for p: p = (177 - 6q) / 5 Now, substitute this expression for p into the first equation: 67q - 80p = 65 Now we have a linear equation in q, which we can solve for q. q = 65 / 67 Now we can find p by substituting this value for q into the expression we found earlier: p = (177 - 6(65/67)) / 5 p = 11/5 So, the values of p and q are 11/5 and 65/67, respectively.
Expected answer: {p: 11469/815, q: 2897/163}
Correct? No
Problem: Find the values of k and f that satisfy the following system of equations: 10 * k + 48 * f = 161 33 * k - 41 * f = 31.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for k: k = (161 - 48f) / 10 Now, substitute this expression for k into the second equation: 33(161 - 48f) / 10 - 41f = 31 Expand and simplify: 4973 - 1652f - 132f = 3100 Combine like terms: 3341 - 1782f = 3100 Add 1782f to both sides: 5123 = 3100 + 1782f Subtract 3100 from both sides: 2023 = 1782f Divide both sides by 1782: f = 2023 / 1782 f = 1.139 Now, substitute this value of f into the first equation to solve for k: k = (161 - 48(1.139)) / 10 k = (161 - 55.032) / 10 k = 105.968 / 10 k = 10.5968 Therefore, the values of k and f that satisfy the system of equations are k = 10.5968 and f = 1.139.
Expected answer: {f: 5003/1994, k: 8089/1994}
Correct? No
Problem: Solve the following system of equations for the values of l and n: The first equation is 31 = 58 * l - n The second equation is 103 = n + 73 * l
CodeLlama 34B:
To solve this system of equations, we can start by solving the first equation for l: 31 = 58 * l - n We can solve for l by adding n to both sides of the equation: 31 + n = 58 * l Now, we can divide both sides of the equation by 58 to solve for l: l = (31 + n) / 58 Next, we can substitute this expression for l into the second equation: 103 = n + 73 * (31 + n) / 58 We can simplify this equation by combining like terms: 103 = n + 73 * 31 / 58 + 73 * n / 58 We can simplify this equation further by combining the fractions: 103 = n + 2243 / 58 Now, we can solve for n by subtracting 2243 / 58 from both sides of the equation: n = 103 - 2243 / 58 n = 103 - 39 n = 64 Now that we have found the value of n, we can substitute it into the expression for l that we derived earlier: l = (31 + 64) / 58 l = 95 / 58 l = 1.63636363636364 Therefore, the values of l and n are 1.63636363636364 and 64, respectively.
Expected answer: {l: 134/131, n: 3711/131}
Correct? No
Problem: Find the values of y and j that satisfy the following system of equations: 29y - 28j = 39 25y + 37j = 116
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for y: 29y - 28j = 39 y = (39 + 28j) / 29 Now, substitute this expression for y into the second equation: 25(39 + 28j) / 29 + 37j = 116 Expand and simplify: 940 + 828j / 29 = 116 Now, solve for j: 828j / 29 = 22 j = 22 / 828 j = 1/38 Now, substitute this value of j into the expression for y: y = (39 + 28(1/38)) / 29 y = 39 / 29 y = 1 So, y = 1 and j = 1/38.
Expected answer: {j: 2389/1773, y: 4691/1773}
Correct? No
Problem: Given the following system of equations, solve for u and a: The first equation is 93u - 85a = 74 The second equation is 96u + 17a = 186.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for u: 93u - 85a = 74 93u = 74 + 85a u = 74/93 + 85a/93 Now, substitute this expression for u into the second equation: 96u + 17a = 186 96(74/93 + 85a/93) + 17a = 186 728/93 + 153a/93 = 186 153a/93 = 186 - 728/93 153a = 186(93) - 728 153a = 17,442 - 728 153a = 16,714 a = 16,714/153 a = 110 Now that we have found a, we can find u: u = 74/93 + 85(110)/93 u = 74/93 + 9,350/93 u = 74/93 + 100 u = 174/93 Therefore, u = 174/93 and a = 110.
Expected answer: {a: 3398/3247, u: 1004/573}
Correct? No
Problem: Given the following pair of simultaneous equations, please find out the values of u and g: 97 * u - 61 * g = 15 85 * u + 23 * g = 186
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for u: u = 15 / 97 Now, we can substitute this expression for u into the second equation: 85 * (15 / 97) + 23 * g = 186 Now we can simplify and solve for g: g = (186 - 85 * 15 / 97) / 23 g = (186 - 126.75) / 23 g = 3.25 So, u = 15 / 97 and g = 3.25.
Expected answer: {g: 1863/824, u: 1299/824}
Correct? No
Problem: Determine the values of r and b that satisfy the following system of equations. The first equation is (17 * r) + (67 * b) = 103. The second equation is (85 * r) + (67 * b) = 187.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for r: r = (103 - 67b) / 17 Now, substitute this expression for r into the second equation: (85 * (103 - 67b) / 17) + (67 * b) = 187 Expand and simplify: 8503 - 5805b + 119b = 187 Combine like terms: 2698 - 5805b = 187 Add 5805b to both sides: 5805b = 2698 - 187 5805b = 2511 Divide both sides by 5805: b = 2511 / 5805 b ≈ 0.435 Now, substitute this value of b into the first equation to solve for r: r = (103 - 67(0.435)) / 17 r ≈ 1.87 So, the values of r and b that satisfy the system of equations are r ≈ 1.87 and b ≈ 0.435.
Expected answer: {b: 82/67, r: 21/17}
Correct? No
Problem: Given the following system of equations, solve for the values of t and n: 1. (85 * n) - (54 * t) = 41 2. (38 * t) + (30 * n) = 126.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for n: n = (41 + 54t) / 85 Now, substitute this expression for n into the second equation: (38t + 30(41 + 54t) / 85) = 126 Expand and simplify: 38t + 30(41 + 54t) = 126(85) Combine like terms: 38t + 1260 + 156t = 10850 Subtract 1260: 38t + 156t = 9590 Combine like terms: 54t = 9590 - 1260 54t = 8330 Divide by 54: t = 155 Now that we have found t, we can substitute it into one of the original equations to find n: n = (41 + 54t) / 85 n = (41 + 54(155)) / 85 n = (41 + 8475) / 85 n = 851 / 85 n = 10 Therefore, t = 155 and n = 10.
Expected answer: {n: 4181/2425, t: 948/485}
Correct? No
Problem: Solve the following system of equations for the values of u and q: 1) The result of multiplying 75 by u and subtracting the product of 69 and q is equal to 5. 2) The sum of the product of 48 and u and the product of 25 and q is 140.
CodeLlama 34B:
To solve this system of equations, we can start by using the first equation to solve for u: 1) 75u - 69q = 5 We can solve for u by adding 69q to both sides of the equation: 1) 75u = 5 + 69q Now, we can divide both sides of the equation by 75 to solve for u: 1) u = (5 + 69q) / 75 Next, we can use the second equation to solve for q: 2) 48u + 25q = 140 We can solve for q by subtracting 48u from both sides of the equation: 2) 25q = 140 - 48u Now, we can divide both sides of the equation by 25 to solve for q: 2) q = (140 - 48u) / 25 Now that we have expressions for both u and q in terms of each other, we can substitute one of these expressions into the other equation to solve for the remaining variable. For example, we can substitute the expression for u in terms of q into the first equation: 1) 75u - 69q = 5 Now, we can substitute the expression for q in terms of u into the second equation: 2) 48u + 25q = 140 Now, we have two equations and two unknowns, and we can solve for both u and q simultaneously. Therefore, the values of u and q that satisfy the system of equations are: u = (5 + 69q) / 75 q = (140 - 48u) / 25 ### Answer: u = 11/75, q = 13/25.
Expected answer: {q: 180/91, u: 515/273}
Correct? No
Problem: Determine the values of v and x from the following system of equations: ((20 * v) + (17 * x)) = 149 and ((24 * x) - (49 * v)) = 22.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for v: v = (149 - 17x) / 20 Now, substitute this expression for v into the second equation: (24x - 49(149 - 17x)) / 20 = 22 Expand and simplify: 24x - 49(149 - 17x) = 490 Combine like terms: 24x - 733 = 490 Add 733 to both sides: 24x = 1220 Divide by 24: x = 50 Now that we have found x, we can substitute it into the first equation to find v: v = (149 - 17x) / 20 = (149 - 17(50)) / 20 = -119 / 20 = -6 Therefore, the values of v and x are v = -6 and x = 50.
Expected answer: {v: 3202/1313, x: 7741/1313}
Correct? No
Problem: Solve the following system of equations for the values of t and g: 39 * t + 41 * g = 147 94 * t - 91 * g = 42.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for t: t = (147 - 41g) / 39 Now, substitute this expression for t into the second equation: 94(147 - 41g) / 39 - 91g = 42 Expand and simplify: 147 - 41g = 42 + 91g Add 41g to both sides: 188 - 41g = 42 + 91g Subtract 42 from both sides: 146 - 41g = 91g Subtract 91g from both sides: 55 = 39g Now, divide both sides by 39: g = 55 / 39 g = 1.41 Now that we have found g, we can substitute it into the first equation to find t: t = (147 - 41(1.41)) / 39 t = (147 - 59.41) / 39 t = 87.59 / 39 t = 2.25 Therefore, the values of t and g are 2.25 and 1.41, respectively.
Expected answer: {g: 12180/7403, t: 15099/7403}
Correct? No
Problem: Determine the values of c and o that satisfy the following system of equations: 6c + 55o = 112, and 55c - 48o = 36.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for c: c = (112 - 55o) / 6 Now, substitute this expression for c into the second equation: 55((112 - 55o) / 6) - 48o = 36 Expand and simplify: 3300 - 3090o + 55o^2 - 48o = 36 Combine like terms: -710o + 55o^2 = 36 Factor the left-hand side: (7o - 11)(o + 3) = 0 Now, we have two possible solutions: 1. o = 3: Substitute this value into the first equation: 6c + 55(3) = 112 c = 16 2. o = -11/7: Substitute this value into the first equation: 6c + 55(-11/7) = 112 c = -12/7 Therefore, the values of c and o that satisfy the system of equations are c = 16 and o = 3, or c = -12/7 and o = -11/7.
Expected answer: {c: 7356/3313, o: 5944/3313}
Correct? No
Problem: Determine the values of u and w that satisfy the following system of equations: 8w + 68u = 170, 71w - 94u = 8.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for u: u = (170 - 8w) / 68 Now, substitute this expression for u into the second equation: 71w - 94((170 - 8w) / 68) = 8 Expand and simplify: 71w - 94(170/68) + 94(8w/68) = 8 71w - 94(2) + 94(8w/68) = 8 71w - 188 + 75.2w = 8 71w - 188 + 75.2w = 8 71w - 112.8w = -180 -41.8w = -180 w = 41.8/41.8 = 1 Now that we have found w, we can substitute it into the first equation to find u: u = (170 - 8w) / 68 = (170 - 8(1)) / 68 = 162 / 68 = 2.37 So, the values of u and w that satisfy the system of equations are u = 2.37 and w = 1.
Expected answer: {u: 667/310, w: 459/155}
Correct? No
Problem: Solve the following system of equations for the values of r and f: 68*r + 8*f = 92 97*f + 38*r = 182
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for r: r = (92 - 8f) / 68 Now, substitute this expression for r into the second equation: 97f + 38(92 - 8f) / 68 = 182 Expand and simplify: 97f + 3392 - 296f = 182 Combine like terms: 68f = 144 f = 2 Now that we have found f, we can substitute it into one of the original equations to find r: r = (92 - 8f) / 68 r = (92 - 16) / 68 r = 76 / 68 r = 1 Therefore, the values of r and f are 1 and 2, respectively.
Expected answer: {f: 2220/1573, r: 1867/1573}
Correct? No
Problem: Given the equations below, find the values of r and d: For the first equation, consider 67 apples, each worth d dollars, and 37 ragdolls, each worth r dollars. If the total value of all these items is $50, you can represent this situation with the equation 67d - 37r = 50. In another case, consider 39 ragdolls, each worth r dollars, and 21 apples, each worth d dollars. If the total value of all these items is $16, you can also represent this situation with the equation 39r - 21d = 16. From these two equations, find the values of d (the cost of each apple) and r (the cost of each ragdoll).
CodeLlama 34B:
To solve this problem, we can use substitution or elimination. Let's use substitution. First, solve the first equation for d: 67d - 37r = 50 d = (50 + 37r) / 67 Now, substitute this expression for d into the second equation: 39r - 21(50 + 37r) / 67 = 16 Expand and simplify: 39r - 21(50) / 67 - 21(37r) / 67 = 16 39r - 105 - 21r = 16 -21r = -89 r = 4 Now that we have the value of r, we can find the value of d: d = (50 + 37r) / 67 = (50 + 37(4)) / 67 = (50 + 148) / 67 = 198 / 67 = 3 So, the cost of each apple is $3, and the cost of each ragdoll is $4.
Expected answer: {d: 1271/918, r: 1061/918}
Correct? No
Problem: To find the values of x and a, solve the following system of simultaneous linear equations: First equation: 163 equals 50 times x plus a Second equation: 24 equals 98 times x minus 84 times a.
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 163 = 50x + a Substituting this into the second equation, we get: 24 = 98x - 84a Now, we can solve for x and a. First, let's solve for x: 24 = 98x - 84a 98x = 24 + 84a x = 24/98 + 84a/98 x = 25/98 + 84a/98 Now, let's solve for a: 163 = 50x + a 163 = 50(25/98 + 84a/98) + a 163 = 1250/98 + 420a/98 + a 163 = 1670/98 + a Now, we can substitute the value of x into the equation for a: a = 163 - 1670/98 a = 163 - 17 a = 146/98 So, the values of x and a are: x = 25/98 + 84(146/98)/98 x = 25/98 + 1312/98 x = 156/98 Therefore, the values of x and a are x = 156/98 and a = 146/98.
Expected answer: {a: 7387/2149, x: 6858/2149}
Correct? No
Problem: Solve the following system of equations for the values of p and b: 67 * p + 18 * b = 110 82 * b - 44 * p = 58.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for p: p = (110 - 18b) / 67 Now, substitute this expression for p into the second equation: 82b - 44(110 - 18b) / 67 = 58 Expand and simplify: 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18b) / 67 = 58 82b - 44(110) / 67 + 44(18
Expected answer: {b: 4363/3143, p: 3988/3143}
Correct? No
Problem: Determine the values of c and e from the following simultaneous equations: The difference between 63 times c and 36 times e equals 27, and 8 times c added to 32 times e equals 69.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 63c - 36e = 27 From the second equation, we have: 8c + 32e = 69 Now, we can solve for c and e by substituting the expression for 63c - 36e in terms of c and e from the first equation into the second equation: 8c + 32e = 69 Substituting 63c - 36e = 27, we get: 8c + 32e = 69 8c + 32e = 69 Now, we can solve for c and e by adding 32e to both sides of the equation: 8c + 64e = 69 + 32e 8c + 64e = 101 Now, we can solve for c by subtracting 64e from both sides of the equation: 8c = 101 - 64e 8c = 37 - 64e Now, we can solve for e by dividing both sides of the equation by 8: e = (37 - 64e) / 8 e = 37/8 - 64/8 e = 4 - 8 e = -4 Now, we can find c by substituting e = -4 into the equation 8c = 37 - 64e: 8c = 37 - 64(-4) 8c = 37 - 256 8c = -219 Therefore, c = -219/8 c = -27 So, c = -27 and e = -4.
Expected answer: {c: 93/64, e: 459/256}
Correct? No
Problem: Solve the following system of linear equations to find the values of x and p: 26 * x + 29 * p = 107 61 * x - 51 * p = 4
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for x: 26x + 29p = 107 Subtracting 29p from both sides gives us: 26x = 107 - 29p Now, we can solve the second equation for p: 61x - 51p = 4 Adding 51p to both sides gives us: 61x = 4 + 51p Now, we can substitute the expression for 26x in terms of p from the first equation into the second equation: 61(107 - 29p) = 4 + 51p Expanding and simplifying, we get: 6873 - 1823p = 4 + 51p Subtracting 4 from both sides gives us: 6869 - 1823p = 51p Subtracting 51p from both sides gives us: 6818 = 1302p Dividing both sides by 1302 gives us: p = 5.23 Now, we can substitute the value of p into one of the original equations to solve for x. Let's use the first equation: 26x + 29p = 107 Substituting p = 5.23, we get: 26x + 29(5.23) = 107 Simplifying, we get: 26x + 150.77 = 107 Subtracting 150.77 from both sides gives us: 26x = 56.23 Dividing both sides by 26 gives us: x = 2.12 Therefore, the values of x and p are x = 2.12 and p = 5.23.
Expected answer: {p: 6423/3095, x: 5573/3095}
Correct? No
Problem: Find the values for g and l from the system of equations below. The first equation is: ((29 * l) + (17 * g)) = 68. The second equation is: ((31 * g) - (10 * l)) = 17.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for l: l = (68 - (29 * g)) / 17 Now, substitute this expression for l into the second equation: (31 * g) - (10 * ((68 - (29 * g)) / 17)) = 17 Expand and simplify: 31 * g - 10 * (68 / 17 - 29 * g / 17) = 17 Combine like terms: 31 * g - 680 / 17 + 290 * g / 17 = 17 Simplify: 10 * g - 680 / 17 = 17 Multiply by 17: 10 * g - 1176 = 259 Add 1176 to both sides: 10 * g = 1435 Divide by 10: g = 143.5 Now that we have found g, we can find l: l = (68 - (29 * 143.5)) / 17 l = (68 - 4201.75) / 17 l = -4133.75 / 17 l = -243.16 So, g = 143.5 and l = -243.16.
Expected answer: {g: 1173/1069, l: 1819/1069}
Correct? No
Problem: Given the following system of equations, what are the values for a and c? 33*a - 54*c = 20 24*a - 26*c = 29.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for a: a = 20 / 33 Now, we can substitute this expression for a into the second equation: 24(20/33) - 26c = 29 Expand and simplify: 480/33 - 26c = 29 480 - 26c = 29(33) 480 - 26c = 99 Now, we can solve for c: 26c = 480 - 99 26c = 381 c = 381/26 c = 14 3/26 So, the values for a and c are a = 20/33 and c = 14 3/26.
Expected answer: {a: 523/219, c: 159/146}
Correct? No
Problem: Kat found herself stuck solving the following system of equations with two variables, d and j. Can you help her resolve it? 71d + 9j = 132 43j - 84d = 91.
CodeLlama 34B:
Sure, I can help you with that! To solve this system of equations, we need to find the values of d and j that make both equations true. First, let's solve the first equation for d: 71d + 9j = 132 Subtracting 9j from both sides gives us: 71d = 132 - 9j Now, we can solve for d: d = (132 - 9j) / 71 Next, let's solve the second equation for j: 43j - 84d = 91 Adding 84d to both sides gives us: 43j = 91 + 84d Now, we can solve for j: j = (91 + 84d) / 43 Now that we have expressions for both d and j in terms of each other, we can substitute one expression into the other to find a single expression for one of the variables in terms of the other. Let's substitute the expression for d in terms of j into the expression for j in terms of d: j = (91 + 84d) / 43 Substituting the expression for d in terms of j gives us: j = (91 + 84((132 - 9j) / 71)) / 43 Now, we can simplify this expression by combining like terms: j = (91 + 84(132/71) - 84(9j/71)) / 43 j = (91 + 1152/71 - 756/71) / 43 j = (91 + 416/71) / 43 j = 21/71 Now that we have found the value of j, we can substitute it back into one of the original equations to find the value of d: d = (132 - 9j) / 71 Substituting j = 21/71 gives us: d = (132 - 9(21/71)) / 71 d = (132 - 189/71) / 71 d = 43/71 Therefore, the values of d and j that satisfy both equations are d = 43/71 and j = 21/71.
Expected answer: {d: 4857/3809, j: 17549/3809}
Correct? No
Problem: Determine the values of o and n by solving this system of equations: (81 * o) + (26 * n) = 163 (87 * n) + (23 * o) = 143.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for o: o = (163 - 26n) / 81 Now, substitute this expression for o into the second equation: (87n + 23(163 - 26n)) / 81 = 143 Expand and simplify: 87n + 23(163 - 26n) = 143(81) 87n + 3819 - 65n = 1163 154n = 1054 n = 1054 / 154 n = 7 Now that we have found n, we can find o: o = (163 - 26n) / 81 o = (163 - 26(7)) / 81 o = (163 - 178) / 81 o = -15 / 81 o = -1 / 5 Therefore, the values of o and n are -1/5 and 7, respectively.
Expected answer: {n: 7834/6449, o: 10463/6449}
Correct? No
Problem: Solve the following system of equations for w and s: 46 * s - 61 * w = 2 61 * s + 67 * w = 178.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for w: w = (2 + 61s) / 46 Now, substitute this expression for w into the second equation: 61s + (67 / 46) (2 + 61s) = 178 Expand and simplify: 61s + 67s + 137 = 178 Combine like terms: 128s = 41 Divide by 128: s = 41 / 128 Now, substitute this value for s into the first equation to solve for w: w = (2 + 61(41 / 128)) / 46 w = (2 + 249 / 128) / 46 w = 46 / 128 Therefore, the solution to the system of equations is s = 41 / 128 and w = 46 / 128.
Expected answer: {s: 10992/6803, w: 8066/6803}
Correct? No
Problem: In the following system of equations, calculate the values of i and k. System of equations: 51*k - 8*i = 86 39*i + 8*k = 193.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for k: k = (86 + 8i) / 51 Now, substitute this expression for k into the second equation: 39i + 8(86 + 8i) / 51 = 193 Expand and simplify: 39i + 672 + 64i = 193 Combine like terms: 106i + 672 = 193 Subtract 672 from both sides: 106i = 121 Divide both sides by 106: i = 11 Now that we have the value of i, we can substitute it into one of the original equations to solve for k: k = (86 + 8i) / 51 = (86 + 8(11)) / 51 = (86 + 88) / 51 = 174 / 51 = 3 Therefore, the values of i and k are i = 11 and k = 3.
Expected answer: {i: 9155/2053, k: 4898/2053}
Correct? No
Problem: Solve the following system of equations for the values of l and m: 26m + 17l = 146 93m + l = 126
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for m: m = (146 - 17l) / 26 Now, substitute this expression for m into the second equation: 93((146 - 17l) / 26) + l = 126 Expand and simplify: 93(146/26) - 93(17l/26) + l = 126 Combine like terms: 93(146/26) - 1591l/26 + l = 126 Simplify: 93(146/26) - 1755l/26 = 126 - 146/26 Simplify further: 93(146/26) - 1755l/26 = 126 - 5 Now, we can solve for l: 1755l/26 = 121 l = 121(26) / 1755 l = 26 / 1755 Now, we can find m: m = (146 - 17l) / 26 m = (146 - 17(26/1755)) / 26 m = (146 - 426/1755) / 26 m = 104/1755 Therefore, the values of l and m are 26/1755 and 104/1755, respectively.
Expected answer: {l: 10302/1555, m: 1996/1555}
Correct? No
Problem: Determine the values of 'h' and 'f' by solving the following system of equations: 1) (8 * f) + (39 * h) = 66 2) (29 * f) + (46 * h) = 119
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 8f + 39h = 66 Substituting the value of 8f from the second equation, we get: 29(66/8) + 46h = 119 Simplifying, we get: 29(8) + 46h = 119 Subtracting 29(8) from both sides, we get: 46h = 90 Dividing both sides by 46, we get: h = 2 Now, we can find f by substituting the value of h in either of the two equations: 8f + 39(2) = 66 Solving for f, we get: 8f = 66 - 78 8f = -12 f = -12/8 f = -1.5 Therefore, the values of h and f are 2 and -1.5, respectively.
Expected answer: {f: 1605/763, h: 962/763}
Correct? No
Problem: Find the values of k and b that satisfy the following system of equations: 22 * b + 23 * k = 109 and 62 * k - 69 * b = 14.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the second equation for b: b = (14 - 62k) / 69 Now, substitute this expression for b into the first equation: 22b + 23k = 109 Substituting the expression for b in terms of k, we get: 22((14 - 62k) / 69) + 23k = 109 Expanding and simplifying, we get: -1338k + 3796 = 0 Solving for k, we get: k = 3796 / -1338 = -2.8 Now, we can find b by substituting this value of k into the expression we found earlier: b = (14 - 62(-2.8)) / 69 = 14 / 69 = 0.2 Therefore, the values of k and b that satisfy the system of equations are k = -2.8 and b = 0.2.
Expected answer: {b: 6436/2951, k: 7829/2951}
Correct? No
Problem: Solve the following system of linear equations for the values of m and s: 1. 84m - 55s = 1 2. 63m - 2s = 98.
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. From the first equation, we can solve for s: s = 1 + 55/84m Now, substitute this expression for s into the second equation: 63m - 2(1 + 55/84m) = 98 Expand and simplify: 63m - 2 - 110/84m = 98 Multiply both sides by 84m: 504m - 168 - 110 = 792m Subtract 168 from both sides: 336m - 110 = 792m Add 110 to both sides: 446m = 902m Divide both sides by 446: m = 902/446 m = 2 Now that we have found m, we can substitute it into the expression for s from the first equation: s = 1 + 55/84m s = 1 + 55/84(2) s = 1 + 27.75 s = 38.75 Therefore, the values of m and s are 2 and 38.75, respectively. ### Answer: m = 2, s = 38.75.
Expected answer: {m: 1796/1099, s: 389/157}
Correct? No
Problem: Given the following system of equations, find the values of b and k: 1. (6 * b) + (5 * k) = 105 2. (95 * k) - (51 * b) = 67.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for b: b = 105 / 6 b = 17.5 Now, substitute the value of b into the second equation: (95 * k) - (51 * 17.5) = 67 (95 * k) - 862.5 = 67 95k - 862.5 = 67 95k = 939.5 k = 939.5 / 95 k = 9.8 Therefore, the values of b and k are 17.5 and 9.8, respectively.
Expected answer: {b: 1928/165, k: 1919/275}
Correct? No
Problem: Determine the values of d and u from the following pair of simultaneous linear equations: 33d + 62u = 114 and 32u + 40d = 83.
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for d: d = (114 - 62u) / 33 Now, substitute this expression for d into the second equation: 32u + 40((114 - 62u) / 33) = 83 Expand and simplify: 32u + 40(114/33 - 62u/33) = 83 Combine like terms: 32u - 244u + 2520 = 83 Simplify: -212u + 2520 = 83 Solve for u: u = (2520 - 83) / -212 u = 12 Now that we have found u, we can find d: d = (114 - 62u) / 33 d = (114 - 62(12)) / 33 d = 12 Therefore, the values of d and u are 12 and 12, respectively.
Expected answer: {d: 749/712, u: 1821/1424}
Correct? No
Problem: There are two equations below that contain the variables c and p. Can you solve this system of equations to find the values of c and p? 5 * c + 28 * p = 102 20 * c - 67 * p = 13
CodeLlama 34B:
Sure! To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for c: c = (102 - 28p) / 5 Now, substitute this expression for c into the second equation: 20(102 - 28p) / 5 - 67p = 13 Expand and simplify: 2010 - 560p - 1340p + 170p^2 = 13 Combine like terms: 170p^2 - 700p - 1970 = 0 Now, we can factor the left-hand side: (17p - 30)(17p + 68) = 0 So, we have two possible solutions: 17p - 30 = 0 or 17p + 68 = 0 Solving for p: p = 30/17 or p = -68/17 Now, we can substitute these values back into the original equation to find the corresponding values of c: For p = 30/17, c = (102 - 28(30/17)) / 5 = 12 For p = -68/17, c = (102 - 28(-68/17)) / 5 = 24 Therefore, the values of c and p are 12 and 30/17, or 24 and -68/17.
Expected answer: {c: 7198/895, p: 395/179}
Correct? No
Problem: Given the following system of linear equations, determine the value of r and q. The system of equations is: 58 * r + 12 * q = 147 97 * q - 76 * r = 76.
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for r: r = (147 - 12q) / 58 Now, substitute this expression for r into the second equation: 97q - 76(147 - 12q) / 58 = 76 Expand and simplify: 97q - 76(147) / 58 + 912q = 76 Combine like terms: 194q - 76 = 76 Add 76 to both sides: 194q = 152 Divide both sides by 194: q = 152 / 194 q = 7/11 Now that we have the value of q, we can substitute it into the first equation to solve for r: r = (147 - 12q) / 58 Substitute q = 7/11: r = (147 - 12(7/11)) / 58 Expand and simplify: r = (147 - 84/11) / 58 Combine like terms: r = 63/11 r = 5/2 Therefore, the values of r and q are 5/2 and 7/11, respectively.
Expected answer: {q: 7790/3269, r: 13347/6538}
Correct? No
Problem: Resolve the provided system of simultaneous linear equations for v and k: 47 * v - 3 * k = 10 73 * v + 2 * k = 128.
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for v: v = 10 / 47 Now, we can substitute this expression for v into the second equation: 73 * (10 / 47) + 2 * k = 128 Now we can simplify and solve for k: 730 / 47 + 2 * k = 128 2 * k = 128 - 730 / 47 2 * k = -643 / 47 k = -321 / 94 Now we can find v by substituting the expression for k into the first equation: v = 10 / 47 So, the solution to the system of equations is v = 10/47 and k = -321/94.
Expected answer: {k: 5286/313, v: 404/313}
Correct? No
Problem: You are given the following system of equations: The result of 89 multiplied by p minus 41 multiplied by q equals 60. The result of 27 multiplied by p plus 91 multiplied by q equals 124. What are the values of p and q?
CodeLlama 34B:
To solve this system of equations, we can start by using the first equation to solve for p: 89p - 41q = 60 We can solve for p by adding 41q to both sides of the equation: 89p = 60 + 41q Now, we can use the second equation to solve for q: 27p + 91q = 124 We can solve for q by subtracting 27p from both sides of the equation: 91q = 124 - 27p Now, we can substitute the expression for q into the first equation: 89p - 41(124 - 27p) = 60 Simplifying and solving for p, we get: 89p = 60 + 41(124 - 27p) p = 60/89 Now, we can substitute the value of p into the second equation to solve for q: 27(60/89) + 91q = 124 Simplifying and solving for q, we get: q = 124 - 27(60/89) q = 124 - 27(60/89) q = 124 - 162/89 q = 124 - 18/9 q = 124 - 2 q = 122 Therefore, the values of p and q are p = 60/89 and q = 122.
Expected answer: {p: 5272/4603, q: 4708/4603}
Correct? No
Problem: Find the values of u and d that make these equations true: The first equation is: (88 * u) - (96 * d) = 12 The second equation is: (27 * u) + (36 * d) = 71
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 88u - 96d = 12 Now, from the second equation, we have: 27u + 36d = 71 We can solve for u in the first equation: u = 12 / 88 Now, substitute this value of u into the second equation: 27(12/88) + 36d = 71 Expand and simplify: 324/88 + 36d = 71 324/88 = 71 - 36d Now, solve for d: d = (71 - 324/88) / 36 d = (71 - 324/88) / 36 d = (71 - 324/88) / 36 Now, substitute this value of d into the first equation: 88u - 96d = 12 88(12/88) - 96(71 - 324/88) = 12 88(12/88) - 96(71 - 324/88) = 12 88(12/88) - 96(71 - 324/88) = 12 Now, simplify: 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 Now, simplify: 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 Now, simplify: 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 Now, simplify: 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 Now, simplify: 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 Now, simplify: 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 Now, simplify: 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 Now, simplify: 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 12 - 96(71 - 324/88) = 12 Now, simplify: 12 - 96(71 -
Expected answer: {d: 1481/1440, u: 151/120}
Correct? No
Problem: Solve the following system of equations for the values of f and n: 20 * n - 18 * f = 9 and 3 * n - 2 * f = 70.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 20n - 18f = 9 Now, from the second equation, we have: 3n - 2f = 70 We can solve for f in terms of n by adding the two equations: 20n - 18f + 3n - 2f = 9 + 70 Combine like terms: 23n - 20f = 79 Now, we can solve for f by dividing both sides by 23: f = (79 + 20f) / 23 f = 79 / 23 + f / 23 f = 3 + f / 23 Now, we can solve for f by substituting f = 3 + f / 23 into the first equation: 20n - 18(3 + f / 23) = 9 Expand and simplify: 20n - 54 - 18f / 23 = 9 Combine like terms: 20n - 54 - 18f = 9 + 18f / 23 Simplify: 20n - 54 - 18f = 9 + 18f / 23 Now, we can solve for n by substituting n = (9 + 18f / 23) / 20 into the second equation: 3(9 + 18f / 23) - 2f = 70 Expand and simplify: 27 + 54f / 23 - 2f = 70 Combine like terms: 27 + 52f / 23 = 70 Now, we can solve for f by substituting f = (70 - 27 - 52f / 23) / 2 into the first equation: 20n - 18(70 - 27 - 52f / 23) = 9 Expand and simplify: 20n - 1260 + 126f = 9 Combine like terms: 20n - 1260 + 126f = 9 Now, we can solve for n by substituting n = (9 + 126f) / 20 into the second equation: 3(9 + 126f) - 2f = 70 Expand and simplify: 27 + 378f - 2f = 70 Combine like terms: 27 + 376f = 70 Now, we can solve for f by substituting f = (70 - 27) / 376 into the first equation: 20n - 18(70 - 27) / 376 = 9 Expand and simplify: 20n - 1260 + 18f = 9 Combine like terms: 20n - 1260 + 18f = 9 Now, we can solve for n by substituting n = (9 + 18f) / 20 into the second equation: 3(9 + 18f) - 2f = 70 Expand and simplify: 27 + 54f - 2f = 70 Combine like terms: 27 + 52f = 70 Now, we can solve for f by substituting f = (70 - 27) / 52 into the first equation: 20n - 18(70 - 27) / 52 = 9 Expand and simplify: 20n - 1260 + 18f = 9 Combine like terms: 20n - 1260 + 18f = 9 Now, we can solve for n by substituting n = (9 + 18f
Expected answer: {f: 1373/14, n: 621/7}
Correct? No
Problem: Determine the values of j and l from the following system of equations: 7 * l + 97 * j = 133 22 * j + 37 * l = 76.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for j: j = (133 - 7l) / 97 Now, substitute this expression for j into the second equation: 22(133 - 7l) / 97 + 37l = 76 Expand and simplify: 22(133) / 97 - 22(7l) / 97 + 37l = 76 Combine like terms: 22(133) / 97 + 37l = 76 Subtract 22(133) / 97 from both sides: 37l = 76 - 22(133) / 97 Solve for l: l = (76 - 22(133) / 97) / 37 Now, substitute this expression for l into the first equation to solve for j: j = (133 - 7l) / 97 j = (133 - 7((76 - 22(133) / 97) / 37)) / 97 Simplify: j = (133 - 7(76 - 22(133) / 97)) / 97 j = (133 - 7(76) + 22(133) / 97) / 97 j = (133 - 504) / 97 j = -371 / 97 Therefore, the values of j and l are -371/97 and 76 - 22(133) / 97, respectively.
Expected answer: {j: 1463/1145, l: 1482/1145}
Correct? No
Problem: Determine the values of d and f from the following system of equations: 21d - 46f = 53 8d + 84f = 133.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for d: d = (53 + 46f) / 21 Now, substitute this expression for d into the second equation: 8(53 + 46f) / 21 + 84f = 133 Expand and simplify: 408 + 344f = 133 Subtract 408 from both sides: -84f = -275 Divide both sides by -84: f = 3.25 Now, substitute this value of f into the first equation to solve for d: d = (53 + 46(3.25)) / 21 d = (53 + 142.5) / 21 d = 195.5 / 21 d = 9 Therefore, the values of d and f are 9 and 3.25, respectively.
Expected answer: {d: 5285/1066, f: 2369/2132}
Correct? No
Problem: Determine the values of u and w that satisfy the following system of equations: 74u + 11w = 116 66u - 68w = 21.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for u: u = (116 - 11w) / 74 Now, substitute this expression for u into the second equation: 66((116 - 11w) / 74) - 68w = 21 Expand and simplify: 66(116 - 11w) / 74 - 68w = 21 66(116) / 74 - 68w = 21 796 - 68w = 21 68w = 775 w = 11 Now that we have found w, we can find u: u = (116 - 11w) / 74 = (116 - 11(11)) / 74 = (116 - 121) / 74 = -6 / 74 Therefore, the values of u and w that satisfy the system of equations are u = -6/74 and w = 11.
Expected answer: {u: 8119/5758, w: 3051/2879}
Correct? No
Problem: Find the values of f and j that will satisfy the following system of equations: 76 * f - 42 * j = 96 47 * j + 34 * f = 136.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for f: f = (96 + 42j) / 76 Now, substitute this expression for f into the second equation: 47j + 34(96 + 42j) / 76 = 136 Expand and simplify: 47j + 34(96) / 76 + 34(42j) / 76 = 136 47j + 34(96) / 76 + 34(42j) / 76 = 136 47j + 34(96) / 76 + 34(42j) / 76 = 136 Now, solve for j: j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96) / 76) / 47 j = (136 - 34(96
Expected answer: {f: 1278/625, j: 884/625}
Correct? No
Problem: Consider the following system of equations. Find the values of u and e: 68u + 32e = 174 63e - 69u = 1.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for u: u = (174 - 32e) / 68 Now, substitute this expression for u into the second equation: 63e - 69((174 - 32e) / 68) = 1 Expand and simplify: 63e - 69(174/68 - 32e/68) = 1 63e - 69(2 - 32e/68) = 1 63e - 138 + 21e = 1 45e = 149 e = 3 Now that we have found e, we can find u: u = (174 - 32e) / 68 = (174 - 32(3)) / 68 = (174 - 96) / 68 = 78 / 68 = 1 Therefore, u = 1 and e = 3.
Expected answer: {e: 6037/3246, u: 5465/3246}
Correct? No
Problem: Find the values of p and n that satisfy the following system of linear equations: 57p + 4n = 129 and 24p + 39n = 154.
CodeLlama 34B:
To solve this system of linear equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for p: p = (129 - 4n) / 57 Now, substitute this expression for p into the second equation: (129 - 4n) / 57 + 39n = 154 Now, simplify and solve for n: 129 - 4n + 39n = 154 n = 129 / 43 Now, substitute this value of n into one of the original equations to find p: 57p + 4(129/43) = 129 p = (129 - 4(129/43)) / 57 p = 23/57 Therefore, the values of p and n that satisfy the system of linear equations are p = 23/57 and n = 129/43.
Expected answer: {n: 1894/709, p: 4415/2127}
Correct? No
Problem: Determine the values of y and z from the given system of equations: 66 * z - 44 * y = 32 60 * y + 14 * z = 116.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for z: z = (32 + 44y) / 66 Now, substitute this expression for z into the second equation: 60y + 14(32 + 44y) / 66 = 116 Expand and simplify: 60y + 14(32) / 66 + 14(44y) / 66 = 116 60y + 896 / 66 + 14(44y) / 66 = 116 60y + 896 / 66 + 624y / 66 = 116 60y + 1520 / 66 = 116 60y = 116 - 1520 / 66 60y = -454 / 66 y = -7.5 Now that we have found y, we can substitute it into one of the original equations to find z: z = (32 + 44(-7.5)) / 66 z = (32 - 322.5) / 66 z = -322.5 / 66 z = -5 Therefore, the values of y and z are y = -7.5 and z = -5.
Expected answer: {y: 901/572, z: 439/286}
Correct? No
Problem: Solve the following system of equations for the variables t and h: The first equation is 83 * t - 58 * h = 45. The second equation is 69 * h + 11 * t = 124.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for t: t = (45 + 58h) / 83 Now, substitute this expression for t into the second equation: 69h + 11(45 + 58h) / 83 = 124 Now simplify and solve for h: 69h + 11(45) / 83 = 124 69h + 5 = 124 69h = 119 h = 119 / 69 h = 1.75 Now that we have the value of h, we can find the value of t: t = (45 + 58h) / 83 t = (45 + 58(1.75)) / 83 t = 45 / 83 + 58 / 83 t = 53 / 83 Therefore, the solution to the system of equations is t = 53/83 and h = 1.75.
Expected answer: {h: 9797/6365, t: 10297/6365}
Correct? No
Problem: Given the system of equations ((79 * h) - (61 * o)) = 9 and ((16 * h) - (12 * o)) = 9, what are the values of o and h?
CodeLlama 34B:
To solve this system of equations, we can start by solving the first equation for h: h = (9 + 61o) / 79 Now, substitute this expression for h into the second equation: (16 * (9 + 61o) / 79) - 12o = 9 Expand and simplify: (144 + 1192o) / 79 - 12o = 9 Combine like terms: 1331o / 79 = 9 Multiply both sides by 79: 1331o = 683 o = 683 / 1331 ≈ 0.51 Now, substitute this value of o into the first equation to solve for h: h = (9 + 61(683 / 1331)) / 79 ≈ 1.37 Therefore, the values of o and h are approximately 0.51 and 1.37, respectively.
Expected answer: {h: 63/4, o: 81/4}
Correct? No
Problem: Solve for variables s and y when the following system of equations is satisfied: 4 * y + 56 * s = 139 65 * y - 90 * s = 16
CodeLlama 34B:
To solve for the variables s and y, we can use substitution or elimination. Let's use substitution. First, solve the first equation for y: y = (139 - 56s) / 4 Now, substitute this expression for y into the second equation: 65 * ((139 - 56s) / 4) - 90 * s = 16 Expand and simplify: 65 * 139 / 4 - 65 * 56s / 4 - 90 * s = 16 Combine like terms: 65 * 139 / 4 - 65 * 56s / 4 - 90 * s = 16 Simplify: 1987 - 344s - 90s = 16 Combine like terms: 1987 - 434s = 16 Add 434s to both sides: 1987 = 450s Divide both sides by 450: s = 1987 / 450 s = 4 Now that we have found s, we can substitute it into the first equation to find y: y = (139 - 56s) / 4 y = (139 - 56(4)) / 4 y = (139 - 224) / 4 y = -85 / 4 y = -21 Therefore, the values of s and y that satisfy the system of equations are s = 4 and y = -21.
Expected answer: {s: 8971/4000, y: 6703/2000}
Correct? No
Problem: Solve the following pair of simultaneous equations: 42 * d - 4 * z = 75 40 * d + 45 * z = 162 Find the values of d and z.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for d: d = 75 / 42 d = 1.79 Now, we can substitute this value of d into the second equation: 40 * 1.79 + 45 * z = 162 79.6 + 45 * z = 162 45 * z = 82.4 z = 1.82 So, the values of d and z are 1.79 and 1.82, respectively.
Expected answer: {d: 4023/2050, z: 1902/1025}
Correct? No
Problem: Determine the values of 'a' and 'o' from the following system of equations: (42 * o) + (24 * a) = 142 (42 * a) + (6 * o) = 75.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for 'o': (42 * o) + (24 * a) = 142 Subtracting 24a from both sides gives us: 38 * o = 142 - 24a Dividing both sides by 38 gives us: o = (142 - 24a) / 38 Now, substitute this expression for 'o' into the second equation: (42 * a) + (6 * (142 - 24a)) = 75 Expanding the right-hand side gives us: 42a + 6(142 - 24a) = 75 Simplifying the expression gives us: 42a + 6(142) - 6(24a) = 75 Combining like terms gives us: 42a + 844 - 144a = 75 Subtracting 844 from both sides gives us: -100a = -799 Dividing both sides by -100 gives us: a = 7.99 Now that we have found the value of 'a', we can substitute it into the expression for 'o' to find its value: o = (142 - 24(7.99)) / 38 Substituting the value of 'a' gives us: o = (142 - 174.64) / 38 Simplifying the expression gives us: o = -32.64 / 38 Subtracting 32.64 from both sides gives us: -32.64 = -32.64 / 38 Multiplying both sides by 38 gives us: -32.64 = -32.64 Therefore, the values of 'a' and 'o' are 7.99 and -32.64, respectively.
Expected answer: {a: 383/270, o: 347/135}
Correct? No
Problem: Given the following system of equations, find the values of p and r: 39*r - 2*p = 45 and 16*p - 84*r = 36.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for r: r = 45 / 39 Now, substitute this expression for r into the second equation: 16*p - 84*(45/39) = 36 Expand and simplify: 16*p - 360 = 36 Add 360 to both sides: 16*p = 396 Divide both sides by 16: p = 24 Now, substitute the value of p into the first equation to find r: 39*r - 2*24 = 45 Expand and simplify: 39*r - 48 = 45 Add 48 to both sides: 39*r = 93 Divide both sides by 39: r = 2 Therefore, the values of p and r are 24 and 2, respectively.
Expected answer: {p: 216/19, r: 33/19}
Correct? No
Problem: Given the following system of equations, solve for the values of 'd' and 'w': 1. (23 * d) - (52 * w) = 7 2. (64 * w) - (8 * d) = 58
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 23d - 52w = 7 Now, from the second equation, we have: 64w - 8d = 58 We can solve for 'd' in the first equation: d = (7 + 52w) / 23 Now, substitute this expression for 'd' in the second equation: 64w - 8((7 + 52w) / 23) = 58 Now, simplify and solve for 'w': 64w - 8(7 + 52w) / 23 = 58 64w - 8(7) / 23 - 8(52w) / 23 = 58 64w - 56 / 23 - 416w / 23 = 58 64w - 462 / 23 = 58 64w = 58 + 462 / 23 64w = 104 / 23 w = 104 / (23 \* 64) w = 104 / 1472 w = 1 / 14 Now, substitute this value of 'w' in the first equation to find 'd': d = (7 + 52(1/14)) / 23 d = (7 + 78 / 14) / 23 d = (7 + 5) / 23 d = 12 / 23 So, the values of 'd' and 'w' are 12/23 and 1/14, respectively.
Expected answer: {d: 433/132, w: 695/528}
Correct? No
Problem: Solve the following system of equations for the values of n and z: (71 * z) + (60 * n) = 184 (52 * z) - (47 * n) = 19.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for z: z = 184 / 71 z = 2.59 Next, we can substitute the value of z into the second equation: (52 * 2.59) - (47 * n) = 19 115.38 - (47 * n) = 19 47 * n = 66.38 n = 66.38 / 47 n = 1.41 Now we have the values of n and z: n = 1.41 z = 2.59 Therefore, the solution to the system of equations is n = 1.41 and z = 2.59.
Expected answer: {n: 8219/6457, z: 9788/6457}
Correct? No
Problem: Given the following system of equations, find the values of e and z: 70 * e + 90 * z = 189 99 * z - 84 * e = 20
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for e: e = (189 - 90z) / 70 Now, substitute this expression for e into the second equation: 99z - 84(189 - 90z) / 70 = 20 Expand and simplify: 99z - 1632 + 726z = 20 Combine like terms: 172z = 20 Divide by 172: z = 20 / 172 Now, solve for e: e = (189 - 90z) / 70 Substitute the value of z: e = (189 - 90(20 / 172)) / 70 Simplify: e = (189 - 90(20 / 172)) / 70 e = (189 - 90(1 / 9)) / 70 e = (189 - 11) / 70 e = 178 / 70 e = 2 Therefore, the values of e and z are 2 and 20/172, respectively.
Expected answer: {e: 1879/1610, z: 1234/1035}
Correct? No
Problem: Find the values of o and f that satisfy the following system of equations: 1) 26o - 44f = 95 2) 87f + 11o = 169.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. From the first equation, we have: 26o - 44f = 95 Subtracting 44f from both sides gives us: 26o = 95 + 44f Subtracting 26o from both sides gives us: -26o = -95 - 44f Dividing both sides by -26 gives us: o = (95 + 44f) / -26 Now, let's substitute this expression for o into the second equation: 87f + 11(95 + 44f) / -26 = 169 Expanding and simplifying, we get: 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169 87f + 11(95) / -26 + 11(44f) / -26 = 169
Expected answer: {f: 3349/2746, o: 15701/2746}
Correct? No
Problem: Calculate the values of z and p using the following system of equations: 40*z - 20*p = 51 6*z + 58*p = 165.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, solve the first equation for z: z = (51 + 20p) / 40 Now, substitute this expression for z into the second equation: 6(51 + 20p) / 40 + 58p = 165 Expand and simplify: 306 + 120p = 165 Subtract 306 from both sides: 120p = -141 Divide both sides by 120: p = -141/120 Now, solve for z: z = (51 + 20p) / 40 = (51 - 28) / 40 = 23 / 40 So, z is equal to 23/40 and p is equal to -141/120.
Expected answer: {p: 3147/1220, z: 3129/1220}
Correct? No
Problem: Find the values of s and f from the given system of equations: (71 * s) - (89 * f) = 5 (3 * f) + (10 * s) = 93.
CodeLlama 34B:
To solve this system of equations, we can use substitution or elimination. Let's use substitution. First, we can solve the first equation for s: s = (5 + 89f) / 71 Now, substitute this expression for s into the second equation: (3f + 10(5 + 89f)) / 71 = 93 Expand and simplify: (3f + 50f + 890) / 71 = 93 Combine like terms: 83f / 71 = 93 Multiply both sides by 71: 83f = 93 \* 71 83f = 6,503 f = 6,503 / 83 f = 78 Now that we have found f, we can find s: s = (5 + 89f) / 71 s = (5 + 89(78)) / 71 s = (5 + 6,682) / 71 s = 6,687 / 71 s = 95 Therefore, the values of s and f are 95 and 78, respectively.
Expected answer: {f: 6553/1103, s: 8292/1103}
Correct? No