CodeLlama 7B on 4.MD.A.3
Common Core Standard 4.MD.A.3
This standard covers the following:
Apply the area and perimeter formulas for rectangles in real world and mathematical problems.
Problem: A rectangle has a length of 21m and a width of 37m. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 21m and the width is 37m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m + 21m + 37m + 37m Perimeter = 21m
Expected answer: 116
Correct? No
Problem: A rectangular garden has a length of 50 feet and a width of 20 feet. What is the perimeter of the garden?
CodeLlama 7B:
The perimeter of a rectangular garden can be found by adding the lengths of all four sides. The length of the garden is 50 feet, and the width is 20 feet. Perimeter = 2(l + w) Perimeter = 2(50 + 20) Perimeter = 2(70) Perimeter = 140 feet Therefore, the perimeter of the garden is 140 feet.
Expected answer: 140
Correct? Yes
Problem: A rectangle has a width of 7m and a length of 26m. What is the area of this rectangle?
CodeLlama 7B:
The area of a rectangle can be found by multiplying the width by the length. Area = width x length = 7 x 26 = 184 square meters Therefore, the area of the rectangle is 184 square meters.
Expected answer: 182
Correct? No
Problem: A rectangle has a length of 50m and a width of 15m. What is its perimeter?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, which is the sum of the lengths of all its sides. In this case, the length of the rectangle is 50m and the width is 15m. To find the perimeter, we need to add the lengths of all the sides: Perimeter = 2(length + width) Perimeter = 2(50 + 15) Perimeter = 2(65) Perimeter = 130m Therefore, the perimeter of the rectangle is 130m.
Expected answer: 130
Correct? Yes
Problem: A rectangular fence has a side length of 5m and another side of 19m. What is the total distance, in meters, around the fence (perimeter)?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the outside of the rectangle. To find the perimeter of the fence, we need to add the lengths of all four sides. The length of one side of the fence is 5m, and the length of the other side is 19m. Therefore, the total distance around the fence is: 5m + 5m + 19m + 19m = 39m So, the perimeter of the fence is 39m.
Expected answer: 48
Correct? No
Problem: A rectangle has sides of length 49m and 6m. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the sum of the lengths of all its sides. In this case, the perimeter of the rectangle is 49 + 6 + 49 + 6 = 134m. ### Answer: 134
Expected answer: 110
Correct? No
Problem: Joshua plans to lay a wire around his rectangular garden. If the garden is 7m wide and 26m long, how much wire will Joshua need to enclose the garden completely?
CodeLlama 7B:
To enclose the garden completely, Joshua will need to lay a wire that is 7m wide and 26m long. Therefore, the total length of wire needed is: 7m x 26m = 186m So, Joshua will need 186m of wire to enclose his rectangular garden completely.
Expected answer: 66
Correct? No
Problem: A rectangle has a length of 18 meters and a width of 11 meters. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all the sides. In this case, the length of the rectangle is 18 meters and the width is 11 meters. To find the perimeter, we need to add up the lengths of all the sides: Perimeter = 2(length + width) Perimeter = 2(18 + 11) Perimeter = 2(29) Perimeter = 58 meters Therefore, the perimeter of the rectangle is 58 meters.
Expected answer: 58
Correct? Yes
Problem: The dimensions of a rectangle are 22 feet by 39 feet. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the perimeter of the rectangle is: 22 + 22 + 39 + 39 = 22 + 22 + 78 + 78 = 22 + 22 + 156 + 156 = 22 + 22 + 308 + 308 = 22 + 22 + 616 + 616 = 22 + 22 + 1232 + 1232 = 22 + 22 + 2464 + 2464 = 22 + 22 + 4928 + 4928 = 22 + 22 + 9856 + 9856 = 22 + 22 + 19712 + 19712 = 22 + 22 + 39424 + 39424 = 22 + 22 + 78848 + 78848 = 22 + 22 + 157696 + 157696 = 22 + 22 + 315392 + 315392 = 22 + 22 + 630784 + 630784 = 22 + 22 + 1261568 + 1261568 = 22 + 22 + 2523136 + 2523136 = 22 + 22 + 5046272 + 5046272 = 22 + 22 + 10092544 + 10092544 = 22 + 22 + 20185088 + 20185088 = 22 + 22 + 40360176 + 40360176 = 22 + 22 + 80720352 + 80720352 = 22 + 22 + 161440704 + 161440704 = 22 + 22 + 322881408 + 322881408 = 22 + 22 + 645762816 + 645762816 = 22 + 22 + 1291525728 + 1291525728 = 22 + 22 + 2583041456 + 2583041456 = 22 + 22 + 5166082912 + 5166082912 = 22 + 22 + 10332165824 + 10332165824 = 22 + 22 + 20664321648 + 20664321648 = 22 + 22 + 41328643296 + 41328643296 = 22 + 22 + 82657286512 + 82657286512 = 22 + 22 + 165314573024 + 165314573024 = 22 + 22 + 330629146048 + 330629146048 = 22 + 22 + 661258292096 + 661258292096 = 22 + 22 + 1322516584192 + 132251658
Expected answer: 122
Correct? No
Problem: A rectangle has two sides measuring 45m and the other two sides measuring 25m each. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the sum of the lengths of all four sides. In this case, the perimeter of the rectangle is 45 + 25 + 25 + 45 = 125 meters. ### Answer: 125
Expected answer: 140
Correct? No
Problem: A rectangular garden has a length of 8m and a width of 5m. What is the perimeter of this garden?
CodeLlama 7B:
The perimeter of a rectangular garden can be found by adding the lengths of all four sides. The length of the garden is 8m, and the width is 5m. Perimeter = 2(8+5) = 2(13) = 26m Therefore, the perimeter of the rectangular garden is 26m.
Expected answer: 26
Correct? Yes
Problem: In a rectangle, the length is 19 units and the width is 17 units. What is the area of this rectangle?
CodeLlama 7B:
The area of a rectangle can be found by multiplying the length by the width. In this case, the area of the rectangle is: 19 x 17 = 323 So the area of the rectangle is 323 square units.
Expected answer: 323
Correct? Yes
Problem: A rectangle has a length of 42 meters and a width of 8 meters. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all the sides. In this case, the length of the rectangle is 42 meters and the width is 8 meters. To find the perimeter, we need to add up the lengths of all the sides: Perimeter = 42 + 42 + 8 + 8 = 108 So, the perimeter of the rectangle is 108 meters.
Expected answer: 100
Correct? No
Problem: A rectangle has a width of 16m and a length of 38m. What is the area of this rectangle?
CodeLlama 7B:
The area of the rectangle can be found by multiplying the width by the length: Area = width x length = 16 x 38 = 648 m^2 Therefore, the area of the rectangle is 648 m^2.
Expected answer: 608
Correct? No
Problem: Consider a rectangular plot of land. The plot has a length of 28m and a width of 17m. What is the area of the plot?
CodeLlama 7B:
The area of the plot can be found by multiplying the length and width of the plot. Area = Length x Width Area = 28 x 17 Area = 494 Therefore, the area of the plot is 494 square meters.
Expected answer: 476
Correct? No
Problem: A rectangle has a length of 43m and a width of 41m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 43m and the width is 41m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(43 + 41) Perimeter = 2(84) Perimeter = 168m Therefore, the perimeter of the rectangle is 168m.
Expected answer: 168
Correct? Yes
Problem: A rectangle has one side that measures 44m, and the other side that measures 17m. What is the perimeter of the rectangle?
CodeLlama 7B:
To find the perimeter of the rectangle, we need to add up the lengths of all four sides. The length of one side is 44m, and the length of the other side is 17m. Therefore, the perimeter of the rectangle is: 44 + 17 + 44 + 17 = 91m So, the perimeter of the rectangle is 91m.
Expected answer: 122
Correct? No
Problem: A rectangle's perimeter is twice the sum of its width and length. If the rectangle's width is 2m and its length is 20m, what is its perimeter?
CodeLlama 7B:
The perimeter of a rectangle is twice the sum of its width and length. In this case, the width is 2m and the length is 20m, so the perimeter is twice the sum of these two values. Perimeter = 2(2m + 20m) Perimeter = 2(22m) Perimeter = 44m Therefore, the perimeter of the rectangle is 44m.
Expected answer: 44
Correct? Yes
Problem: A rectangle has a length of 4 meters and a width of 5 meters. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle. To find the perimeter of the rectangle, you need to add the lengths of all four sides. The length of the rectangle is 4 meters, and the width is 5 meters. To find the perimeter, you need to add the length and width: Perimeter = length + width Perimeter = 4 + 5 Perimeter = 9 meters Therefore, the perimeter of the rectangle is 9 meters.
Expected answer: 18
Correct? No
Problem: A rectangle has a length of 45m and a width of 37m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 45m and the width is 37m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(45 + 37) Perimeter = 2(82) Perimeter = 164m Therefore, the perimeter of the rectangle is 164m.
Expected answer: 164
Correct? Yes
Problem: A rectangle has a length of 27m and a width of 21m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 27m and the width is 21m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m + 21m + 27m + 21m Perimeter = 27m
Expected answer: 96
Correct? No
Problem: A rectangular garden has a length of 30m and a width of 20m. What is the perimeter of the garden?
CodeLlama 7B:
The perimeter of a rectangular garden can be found by adding the lengths of all four sides. The length of the garden is 30m, and the width is 20m. Perimeter = 2(30+20) = 2(50) = 100m Therefore, the perimeter of the garden is 100m.
Expected answer: 100
Correct? Yes
Problem: A rectangle has a length of 30m and a width of 27m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 30m and the width is 27m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 30m + 30m + 27m + 27m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m + 27m + 27m + 30m Perimeter = 30m
Expected answer: 114
Correct? Yes
Problem: A rectangle has a length of 23m and a width of 11m. What is the area of this rectangle?
CodeLlama 7B:
The area of the rectangle can be found by multiplying the length and width: Area = length x width Area = 23 x 11 Area = 263 m^2 Therefore, the area of the rectangle is 263 m^2.
Expected answer: 253
Correct? No
Problem: A rectangle has a length of 3m and a width of 9m. What would be the total perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the sum of the lengths of all its sides. In this case, the length of the rectangle is 3m and the width is 9m, so the perimeter is: 3m + 3m + 9m + 9m = 18m Therefore, the total perimeter of the rectangle is 18m.
Expected answer: 24
Correct? No
Problem: A rectangle has a length of 31m and a width of 6m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, which is the sum of the lengths of all its sides. In this case, the length of the rectangle is 31m and the width is 6m. To find the perimeter, we need to add the lengths of all the sides: Perimeter = 31m + 6m + 31m + 6m Perimeter = 2(31m) + 2(6m) Perimeter = 62m Therefore, the perimeter of the rectangle is 62m.
Expected answer: 74
Correct? No
Problem: A rectangle has a length of 12m and a width of 33m. What is the area of this rectangle?
CodeLlama 7B:
The area of the rectangle can be found by multiplying the length and width: Area = length x width Area = 12 x 33 Area = 408 square meters Therefore, the area of the rectangle is 408 square meters.
Expected answer: 396
Correct? No
Problem: A rectangle has a length of 20m and all of its sides are of equal length. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the sum of the lengths of all its sides. Since all the sides of the rectangle are of equal length, we can find the perimeter by multiplying the length of one side by 4. The length of one side of the rectangle is 20m, so the perimeter is: Perimeter = 4 x 20 = 80m Therefore, the perimeter of the rectangle is 80m.
Expected answer: 80
Correct? Yes
Problem: A rectangular playground has a length of 35m and a width of 9m. What is the perimeter of the playground?
CodeLlama 7B:
The perimeter of a rectangular playground can be found by adding the lengths of all four sides. The length of the playground is 35m, and the width is 9m. Perimeter = 2(length + width) = 2(35 + 9) = 2(44) = 88m Therefore, the perimeter of the playground is 88m.
Expected answer: 88
Correct? Yes
Problem: A rectangle has a length of 9m and a width of 25m. What is the area of the rectangle?
CodeLlama 7B:
The area of the rectangle can be found by multiplying the length and width: Area = length x width Area = 9 x 25 Area = 225 m^2 Therefore, the area of the rectangle is 225 m^2.
Expected answer: 225
Correct? Yes
Problem: A rectangle has a length of 13m and a width of 43m. What is the area of the rectangle?
CodeLlama 7B:
The area of the rectangle can be found by multiplying the length and width: Area = length x width Area = 13 x 43 Area = 569 square meters Therefore, the area of the rectangle is 569 square meters.
Expected answer: 559
Correct? No
Problem: A rectangle has a width of 27m and a length of 47m. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of one side of the rectangle is 47m, and the width of the rectangle is 27m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2 x (47 + 27) = 2 x 74 = 148m Therefore, the perimeter of the rectangle is 148m.
Expected answer: 148
Correct? Yes
Problem: A rectangular football field has an area of 21m * 42m, calculate the area of the football field.
CodeLlama 7B:
The area of the football field is given by the product of the length and width, which are both given as 21m and 42m, respectively. Therefore, the area of the football field is: Area = Length x Width Area = 21m x 42m Area = 884m^2 So, the area of the football field is 884m^2.
Expected answer: 882
Correct? No
Problem: A rectangle's area is found by multiplying its length by its width. If the width of a certain rectangle is 27m and the length is 25m, what is the area of the rectangle?
CodeLlama 7B:
The area of a rectangle can be found by multiplying its length by its width. If the width of a certain rectangle is 27m and the length is 25m, then the area of the rectangle is 27m x 25m = 675m^2. ### Answer: 675m^2
Expected answer: 675
Correct? Yes
Problem: Suppose the width of the rectangle in the previous problem was not 27m, but was instead 11m, with the length remaining at 25m. What would then be the new area of the rectangle?
CodeLlama 7B:
If the width of the rectangle is 11m and the length is 25m, then the area of the rectangle is 11m x 25m = 275m^2. ### Answer: 275m^2
Expected answer: 275
Correct? Yes
Problem: A rectangle has a length of 45m and a width of 48m. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 45m and the width is 48m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(45 + 48) Perimeter = 2(93) Perimeter = 186m Therefore, the perimeter of the rectangle is 186m.
Expected answer: 186
Correct? Yes
Problem: A rectangle has a length of 11 meters and a width of 7 meters. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all the sides. In this case, the length of the rectangle is 11 meters and the width is 7 meters. To find the perimeter, we need to add up the lengths of all the sides: Perimeter = 2(length + width) Perimeter = 2(11 + 7) Perimeter = 2(18) Perimeter = 36 meters Therefore, the perimeter of the rectangle is 36 meters.
Expected answer: 36
Correct? Yes
Problem: A rectangular field has a length of 30m and a width of 2m. Can you calculate the perimeter of the field?
CodeLlama 7B:
Yes, I can calculate the perimeter of the field. The perimeter of a rectangle is found by adding the lengths of all four sides. In this case, the length of the field is 30m and the width is 2m, so the perimeter is: 30 + 2 + 30 + 2 = 74m Therefore, the perimeter of the field is 74m.
Expected answer: 64
Correct? No
Problem: A rectangle has one side that is 7m long and another side that is 8m long. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the sum of the lengths of all its sides. In this case, the perimeter of the rectangle is 7 + 8 = 15m. ### Answer: 15
Expected answer: 30
Correct? No
Problem: A rectangle has a length of 14m and a width of 18m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 14m and the width is 18m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(14 + 18) Perimeter = 2(32) Perimeter = 64m Therefore, the perimeter of the rectangle is 64m.
Expected answer: 64
Correct? Yes
Problem: A rectangle has a length of 43 units and a width of 3 units. Calculate the perimeter of this rectangle.
CodeLlama 7B:
The perimeter of a rectangle is the sum of the lengths of all its sides. In this case, the length of the rectangle is 43 units and the width is 3 units, so the perimeter is: 43 + 43 + 3 + 3 = 123 Therefore, the perimeter of the rectangle is 123 units.
Expected answer: 92
Correct? No
Problem: A rectangle has one side that measures 36 meters and another side that measures 42 meters. What is the perimeter of this rectangle?
CodeLlama 7B:
To find the perimeter of the rectangle, we need to add up the lengths of all four sides. The length of one side is 36 meters, and the length of the other side is 42 meters. Therefore, the perimeter of the rectangle is: 36 + 36 + 42 + 42 = 162 meters So, the perimeter of the rectangle is 162 meters.
Expected answer: 156
Correct? No
Problem: A rectangle has a length of 1m and a width of 6m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, which is the sum of the lengths of all its sides. In this case, the length of the rectangle is 1m and the width is 6m. To find the perimeter, we need to add the lengths of all the sides: Perimeter = 2(length + width) Perimeter = 2(1m + 6m) Perimeter = 2(7m) Perimeter = 14m Therefore, the perimeter of the rectangle is 14m.
Expected answer: 14
Correct? Yes
Problem: A rectangle has two sides measuring 45m and two sides measuring 8m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the sum of the lengths of all four sides. In this case, the perimeter of the rectangle is 45 + 45 + 8 + 8 = 128 meters. ### Answer: 128
Expected answer: 106
Correct? No
Problem: A rectangular garden has a length of 25 meters and a width of 37 meters. What is the perimeter of the garden?
CodeLlama 7B:
The perimeter of a rectangular garden can be found by adding the lengths of all four sides. The length of the garden is 25 meters, and the width is 37 meters. Perimeter = 2 sides x length + 2 sides x width = 2 x 25 + 2 x 37 = 50 + 74 = 124 meters Therefore, the perimeter of the garden is 124 meters.
Expected answer: 124
Correct? Yes
Problem: A rectangle has length 36m and width 3m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, which is equal to the sum of the lengths of all four sides. In this case, the length of the rectangle is 36m and the width is 3m. To find the perimeter, we need to add the length and width together: Perimeter = length + width Perimeter = 36m + 3m Perimeter = 39m Therefore, the perimeter of the rectangle is 39m.
Expected answer: 78
Correct? No
Problem: A rectangular garden has a length of 45 meters and a width of 50 meters. Calculate the perimeter of the garden.
CodeLlama 7B:
The perimeter of a rectangular garden can be calculated using the formula: perimeter = 2(length + width). In this case, the length of the garden is 45 meters and the width is 50 meters, so the perimeter can be calculated as follows: perimeter = 2(45 + 50) perimeter = 2(95) perimeter = 190 Therefore, the perimeter of the rectangular garden is 190 meters.
Expected answer: 190
Correct? Yes
Problem: A rectangle has a length of 44m and a width of 34m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 44m and the width is 34m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(44 + 34) Perimeter = 2(78) Perimeter = 156m Therefore, the perimeter of the rectangle is 156m.
Expected answer: 156
Correct? Yes
Problem: A rectangle has a length of 42 m and a width of 29 m. Calculate the perimeter of the rectangle.
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all the sides. In this case, the length of the rectangle is 42 m and the width is 29 m. To find the perimeter, we need to add up the lengths of all the sides. Perimeter = 2(length + width) Perimeter = 2(42 + 29) Perimeter = 2(61) Perimeter = 122 m Therefore, the perimeter of the rectangle is 122 m.
Expected answer: 142
Correct? No
Problem: A rectangle has a length of 44 meters and a width of 35 meters. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 44 meters and the width is 35 meters. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(44 + 35) Perimeter = 2(89) Perimeter = 178 meters Therefore, the perimeter of the rectangle is 178 meters.
Expected answer: 158
Correct? No
Problem: A rectangle has a length of 44m and a width of 45m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 44m and the width is 45m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(44 + 45) Perimeter = 2(89) Perimeter = 178 Therefore, the perimeter of the rectangle is 178 meters.
Expected answer: 178
Correct? Yes
Problem: A rectangle has a length of 3 meters and a width of 39 meters. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 3 meters and the width is 39 meters. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 3 + 3 + 39 + 39 = 75 meters Therefore, the perimeter of the rectangle is 75 meters.
Expected answer: 84
Correct? No
Problem: A rectangular garden has sides that measure 32m and 12m. What is the perimeter of this garden?
CodeLlama 7B:
The perimeter of a rectangular garden is the distance around the outside of the garden, and it is calculated by adding the lengths of all four sides. In this case, the garden has two sides that are 32m long, and two sides that are 12m long. To find the perimeter, we add the two 32m sides together, and then add the two 12m sides together. Perimeter = 32m + 32m + 12m + 12m Perimeter = 64m + 12m Perimeter = 76m Therefore, the perimeter of the rectangular garden is 76m.
Expected answer: 88
Correct? No
Problem: A rectangular swimming pool has a length of 24 feet and a width of 6 feet. What is the perimeter of the swimming pool?
CodeLlama 7B:
The perimeter of a rectangular swimming pool can be found by adding the lengths of all four sides. The length of the pool is 24 feet, and the width is 6 feet. Perimeter = 2 x (length + width) Perimeter = 2 x (24 + 6) Perimeter = 2 x 30 Perimeter = 60 feet Therefore, the perimeter of the rectangular swimming pool is 60 feet.
Expected answer: 60
Correct? Yes
Problem: A rectangle has a length of 27m and a width of 21m. What is the area of this rectangle?
CodeLlama 7B:
The area of the rectangle can be found by multiplying the length and width: Area = length x width Area = 27 x 21 Area = 549 square meters Therefore, the area of the rectangle is 549 square meters.
Expected answer: 567
Correct? No
Problem: A rectangle has twice the length of a square. If the square's side is 49m, what is the length of the rectangle?
CodeLlama 7B:
The length of the rectangle is twice the length of the square, so the length of the rectangle is 2 x 49 = 98 meters.
Expected answer: 98
Correct? Yes
Problem: A rectangle has a length of 50m and a width of 36m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 50m and the width is 36m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(50 + 36) Perimeter = 2(86) Perimeter = 172 Therefore, the perimeter of the rectangle is 172 meters.
Expected answer: 172
Correct? Yes
Problem: A rectangle has a length of 8m and a width of 44m. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 8m and the width is 44m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(8m + 44m) Perimeter = 2(52m) Perimeter = 104m Therefore, the perimeter of the rectangle is 104m.
Expected answer: 104
Correct? Yes
Problem: If a rectangle has a length of 47 feet and a width of 21 feet, what is the area of the rectangle?
CodeLlama 7B:
The area of the rectangle can be found by multiplying the length and width: Area = length x width Area = 47 x 21 Area = 997 square feet Therefore, the area of the rectangle is 997 square feet.
Expected answer: 987
Correct? No
Problem: A rectangle has a length of 19m and a breadth of 28m. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 19m and the breadth is 28m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(19 + 28) = 2(47) = 94m Therefore, the perimeter of the rectangle is 94m.
Expected answer: 94
Correct? Yes
Problem: One side of a rectangle is four times the length of the other side. If the longer side measures 39 meters, what is the area of the rectangle when the shorter side is 10 meters?
CodeLlama 7B:
The area of the rectangle can be found by multiplying the length of the longer side by the length of the shorter side. The area of the rectangle is 39 meters x 10 meters = 390 square meters. ### Answer: 390 square meters
Expected answer: 390
Correct? Yes
Problem: Suppose we discovered an error in the original measurements of the rectangle. The longer side is actually 37 meters instead of 39 meters. With the shorter side still at 10 meters, what is the new area of the rectangle?
CodeLlama 7B:
The area of the rectangle can be found by multiplying the length of the longer side by the length of the shorter side. The area of the rectangle is 37 meters x 10 meters = 370 square meters. ### Answer: 370 square meters
Expected answer: 370
Correct? Yes
Problem: A rectangle has identical sides, each measuring 19 meters. What is the total perimeter of the rectangle?
CodeLlama 7B:
The total perimeter of the rectangle is 4 times the length of the sides, which is 19 meters. Therefore, the total perimeter of the rectangle is 4 x 19 = 76 meters.
Expected answer: 76
Correct? Yes
Problem: The area of a rectangle is given by the equation length * width. If the length is 9m and the width is 26m, what is the area of the rectangle?
CodeLlama 7B:
The area of the rectangle can be found by multiplying the length and width: Area = length * width Area = 9m * 26m Area = 246m^2 Therefore, the area of the rectangle is 246m^2.
Expected answer: 234
Correct? No
Problem: A rectangle has one side measuring 19cm and another side measuring 7cm. What is the perimeter of the rectangle?
CodeLlama 7B:
To find the perimeter of the rectangle, we need to add up the lengths of all four sides. The length of one side is 19cm, and the length of the other side is 7cm. Therefore, the perimeter of the rectangle is: 19 + 7 + 19 + 7 = 55 cm So, the perimeter of the rectangle is 55 cm.
Expected answer: 52
Correct? No
Problem: A shutter is in the shape of a rectangle. Its length is 10m and its width is 6m. What is the total area of the shutter?
CodeLlama 7B:
The total area of the shutter can be found by multiplying the length and width of the rectangle. Length = 10m Width = 6m Total area = length x width = 10 x 6 = 60m^2 Therefore, the total area of the shutter is 60 square meters.
Expected answer: 60
Correct? Yes
Problem: A rectangle has a length of 24 units and a width of 15 units. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all the sides. In this case, the length of the rectangle is 24 units and the width is 15 units. To find the perimeter, we need to add up the lengths of all the sides. The length of the sides are: * Left side: 0 units * Right side: 24 units * Top side: 24 units * Bottom side: 0 units The perimeter of the rectangle is the sum of these lengths: 0 + 24 + 24 + 0 = 48 Therefore, the perimeter of the rectangle is 48 units.
Expected answer: 78
Correct? No
Problem: If a rectangular plot of land has a length of 32m and a width of 27m, what is the area of the plot in square meters?
CodeLlama 7B:
To find the area of the plot, we need to multiply the length and width of the plot. Length = 32m Width = 27m Area = Length x Width = 32 x 27 = 928m^2 Therefore, the area of the plot is 928 square meters.
Expected answer: 864
Correct? No
Problem: A rectangle has one side that measures 15m and another side that measures 10m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the sum of the lengths of all four sides. Since we are given two sides, we can use the formula for the perimeter of a rectangle: Perimeter = 2(side1 + side2) In this case, side1 = 15m and side2 = 10m, so the perimeter is: Perimeter = 2(15m + 10m) = 2(25m) = 50m Therefore, the perimeter of the rectangle is 50m.
Expected answer: 50
Correct? Yes
Problem: A rectangle has a length of 44m and a width of 37m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 44m and the width is 37m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(44 + 37) Perimeter = 2(81) Perimeter = 162m Therefore, the perimeter of the rectangle is 162m.
Expected answer: 162
Correct? Yes
Problem: A rectangle has length of 14 cm and width 8 cm. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, which is the sum of the lengths of all its sides. In this case, the length of the rectangle is 14 cm and the width is 8 cm. To find the perimeter, we need to add the lengths of all the sides: Perimeter = 2(length + width) = 2(14 + 8) = 2(22) = 44 cm Therefore, the perimeter of the rectangle is 44 cm.
Expected answer: 44
Correct? Yes
Problem: A rectangle has a length of 26m and a width of 28m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 26m and the width is 28m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m + 28m + 26m + 28m Perimeter = 26m
Expected answer: 108
Correct? No
Problem: A rectangle has a length of 15m and a width of 37m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 15m and the width is 37m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(15 + 37) Perimeter = 2(52) Perimeter = 104m Therefore, the perimeter of the rectangle is 104m.
Expected answer: 104
Correct? Yes
Problem: A rectangle has a length of 42m and a width of 40m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 42m and the width is 40m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(42 + 40) Perimeter = 2(82) Perimeter = 164m Therefore, the perimeter of the rectangle is 164m.
Expected answer: 164
Correct? Yes
Problem: A rectangular garden has one side that measures 21 feet and another side that measures 30 feet. What is the perimeter of the garden?
CodeLlama 7B:
The perimeter of the garden is the sum of the lengths of all four sides. Since we know the length of two sides, we can use the formula for the perimeter of a rectangle to find the perimeter: Perimeter = 2(side1 + side2) In this case, side1 = 21 feet and side2 = 30 feet, so the perimeter is: Perimeter = 2(21 + 30) = 2(51) = 102 feet Therefore, the perimeter of the rectangular garden is 102 feet.
Expected answer: 102
Correct? Yes
Problem: A certain playground is in the shape of a rectangle. The area of the playground is given as the product of 17 and 44. How many square meters is the playground?
CodeLlama 7B:
The area of the playground is given as the product of 17 and 44, which is equal to 17 x 44 = 708 square meters.
Expected answer: 748
Correct? No
Problem: Rectangle ABCD has a width of 47m and a length of 50m. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle can be found by adding the lengths of all its sides. In this case, the perimeter of the rectangle ABCD is: 47 + 47 + 50 + 50 = 194 So, the perimeter of the rectangle ABCD is 194 meters.
Expected answer: 194
Correct? Yes
Problem: A rectangle has a length of 11m and a width of 31m. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 11m and the width is 31m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(11 + 31) Perimeter = 2(42) Perimeter = 84m Therefore, the perimeter of the rectangle is 84m.
Expected answer: 84
Correct? Yes
Problem: A rectangular garden has a length of 39m and a width of 19m. What is the area of this garden?
CodeLlama 7B:
The area of the garden can be found by multiplying the length and width: Area = length x width Area = 39 x 19 Area = 739 square meters Therefore, the area of the rectangular garden is 739 square meters.
Expected answer: 741
Correct? No
Problem: A carpenter wants to install a wooden floor in a rectangular hallway. The wooden plank has a width of 29 cm and the carpenter has cut it to a length of 11 cm. How many square centimeters of area does one cut wooden plank cover?
CodeLlama 7B:
To find the area of one cut wooden plank, we need to first find the length of the plank. Since the plank has a length of 11 cm, we can use the formula for the area of a rectangle, which is: Area = length x width In this case, the length of the plank is 11 cm, and the width of the plank is 29 cm. So, we can plug these values into the formula to find the area of one cut wooden plank: Area = 11 cm x 29 cm Area = 349 cm^2 Therefore, one cut wooden plank covers an area of 349 square centimeters.
Expected answer: 319
Correct? No
Problem: A rectangle has a length of 25m and a width of 11m. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all the sides. In this case, the length of the rectangle is 25m and the width is 11m. To find the perimeter, we need to add up the lengths of all the sides: Perimeter = 25m + 11m + 25m + 11m Perimeter = 25m + 26m Perimeter = 51m Therefore, the perimeter of the rectangle is 51m.
Expected answer: 72
Correct? No
Problem: A rectangle has a length of 49m and a breadth of 9m. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, which is the sum of the lengths of all its sides. In this case, the length of the rectangle is 49m and the breadth is 9m. To find the perimeter, we need to add the lengths of all the sides: Perimeter = 49m + 9m + 49m + 9m Perimeter = 49m + 2x9m Perimeter = 49m + 18m Perimeter = 67m Therefore, the perimeter of the rectangle is 67m.
Expected answer: 116
Correct? No
Problem: A rectangle has a length of 16m and a width of 7m. What is the area of this rectangle?
CodeLlama 7B:
The area of the rectangle can be found by multiplying the length and width: Area = length x width Area = 16 x 7 Area = 112 So the area of the rectangle is 112 square meters.
Expected answer: 112
Correct? Yes
Problem: The perimeter of a rectangular playground is found by the formula 2*(Length + Breadth). If the length of the playground is 14m and the breadth is 2m, what is the perimeter of the playground?
CodeLlama 7B:
The perimeter of a rectangular playground is found by the formula 2*(Length + Breadth). In this case, the length of the playground is 14m and the breadth is 2m. So, the perimeter of the playground is 2*(14m + 2m) = 2*(16m) = 32m. Therefore, the perimeter of the playground is 32m.
Expected answer: 32
Correct? Yes
Problem: A square has a side length of 16 units. What is the perimeter of the square?
CodeLlama 7B:
The perimeter of a square is the sum of the lengths of all its sides. Since a square has four sides of equal length, the perimeter of the square is 4 times the length of one side. In this case, the side length of the square is 16 units, so the perimeter of the square is: 4 x 16 = 64 units Therefore, the perimeter of the square is 64 units.
Expected answer: 64
Correct? Yes
Problem: A rectangular garden has a width of 7 meters and a length of 21 meters. What is the perimeter of this garden?
CodeLlama 7B:
The perimeter of a rectangular garden can be found by adding the lengths of all four sides. The length of the garden is 21 meters, and the width is 7 meters. Perimeter = 2 sides x length + 2 sides x width = 2 x 21 + 2 x 7 = 42 + 14 = 56 meters Therefore, the perimeter of the rectangular garden is 56 meters.
Expected answer: 56
Correct? Yes
Problem: A rectangle has a length of 20 meters and a width of 5 meters. What is the area of the rectangle?
CodeLlama 7B:
The area of the rectangle can be found by multiplying the length and width: Area = length x width Area = 20 x 5 Area = 100 square meters Therefore, the area of the rectangle is 100 square meters.
Expected answer: 100
Correct? Yes
Problem: A rectangle has a length of 37m and a width of 43m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 37m and the width is 43m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(37 + 43) Perimeter = 2(70) Perimeter = 140m Therefore, the perimeter of the rectangle is 140m.
Expected answer: 160
Correct? No
Problem: A rectangle has a length of 9m. If the width of the rectangle is 1m, what is the area?
CodeLlama 7B:
The area of the rectangle can be found by multiplying the length and width: Area = length x width Area = 9 x 1 Area = 9 So the area of the rectangle is 9 square meters.
Expected answer: 9
Correct? Yes
Problem: In the previous problem, we considered a rectangle with a length of 9m and a width of 1m. Now, consider if the width of the rectangle was actually 40m instead of 1m. What would be the new area of the rectangle?
CodeLlama 7B:
If the width of the rectangle was 40m instead of 1m, the new area of the rectangle would be: Area = length x width Area = 9 x 40 Area = 360 So the new area of the rectangle would be 360 square meters.
Expected answer: 360
Correct? Yes
Problem: A rectangle's area is the product of 22m and 23m. What is the area of the rectangle?
CodeLlama 7B:
The area of the rectangle is 22m x 23m = 498m^2.
Expected answer: 506
Correct? No
Problem: A rectangle has one side that measures 14 cm and another side that measures 21 cm. What is the perimeter of this rectangle?
CodeLlama 7B:
To find the perimeter of the rectangle, we need to add up the lengths of all four sides. The length of one side is 14 cm, and the length of the other side is 21 cm. Therefore, the perimeter of the rectangle is: 14 + 14 + 21 + 21 = 64 cm So, the perimeter of the rectangle is 64 cm.
Expected answer: 70
Correct? No
Problem: In Clara's backyard, there is a rectangular swimming pool. The length of the pool is 23 meters, while the width is 12 meters. What is the area of the swimming pool in Clara's backyard?
CodeLlama 7B:
The area of the swimming pool can be found by multiplying the length and width of the pool. Length = 23 meters Width = 12 meters Area = Length x Width = 23 x 12 = 276 square meters Therefore, the area of the swimming pool in Clara's backyard is 276 square meters.
Expected answer: 276
Correct? Yes
Problem: A rectangle has a length of 39 meters and a width of 8 meters. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 39 meters and the width is 8 meters. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 39 + 39 + 8 + 8 = 146 meters Therefore, the perimeter of the rectangle is 146 meters.
Expected answer: 94
Correct? No
Problem: A rectangle has a width of 27m and a length of 40m. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of one side of the rectangle is 40m, and the width of the rectangle is 27m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2 x (40 + 27) = 2 x 67 = 134 m Therefore, the perimeter of the rectangle is 134 meters.
Expected answer: 134
Correct? Yes
Problem: A rectangle's length is 35m and its width is 9m. What is the perimeter of the rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the sum of the lengths of all its sides. In this case, the perimeter of the rectangle is 35m + 35m + 9m + 9m = 35m + 35m + 18m = 76m. Therefore, the perimeter of the rectangle is 76m.
Expected answer: 88
Correct? No
Problem: A rectangle has a length of 38m and a width of 11m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, which is the sum of the lengths of all its sides. In this case, the length of the rectangle is 38m and the width is 11m. To find the perimeter, we need to add the lengths of all the sides: Perimeter = 2(length + width) Perimeter = 2(38 + 11) Perimeter = 2(59) Perimeter = 118 Therefore, the perimeter of the rectangle is 118m.
Expected answer: 98
Correct? No
Problem: One side of a rectangle is 28m long, and the other side is 29m long. What is the area of this rectangle?
CodeLlama 7B:
To find the area of the rectangle, we need to multiply the length of one side by the length of the other side. In this case, the length of one side is 28m and the length of the other side is 29m. So, the area of the rectangle is: 28m x 29m = 828m^2 Therefore, the area of the rectangle is 828m^2.
Expected answer: 812
Correct? No
Problem: A square has a side length of 9m. What is the total length of fencing needed to enclose the square's perimeter?
CodeLlama 7B:
The perimeter of a square is equal to the sum of the lengths of all its sides. Since the side length of the square is 9m, the perimeter is 4(9) = 36m. Therefore, the total length of fencing needed to enclose the square's perimeter is 36m.
Expected answer: 36
Correct? Yes
Problem: A rectangle has a length of 38m and a width of 29m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 38m and the width is 29m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 2(length + width) Perimeter = 2(38 + 29) Perimeter = 2(67) Perimeter = 134m Therefore, the perimeter of the rectangle is 134m.
Expected answer: 134
Correct? Yes
Problem: A rectangle has one side of length 45m and another side of length 47m. Find the perimeter of the rectangle.
CodeLlama 7B:
To find the perimeter of the rectangle, we need to add the lengths of all four sides. The length of one side is 45m, and the length of the other side is 47m. Therefore, the perimeter of the rectangle is: 45 + 47 = 92m So, the perimeter of the rectangle is 92m.
Expected answer: 184
Correct? No
Problem: Given a rectangle where the length is 24m and the width is 20m, what is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the distance around the rectangle, and it is calculated by adding up the lengths of all four sides. In this case, the length of the rectangle is 24m and the width is 20m. To find the perimeter, we need to add up the lengths of all four sides: Perimeter = 24m + 20m + 24m + 20m Perimeter = 24m + 40m Perimeter = 64m Therefore, the perimeter of the rectangle is 64m.
Expected answer: 88
Correct? No
Problem: The length and width of a rectangle are both 32m. What is the perimeter of this rectangle?
CodeLlama 7B:
The perimeter of a rectangle is the sum of the lengths of all its sides. Since the length and width of the rectangle are both 32m, the perimeter can be calculated as follows: Perimeter = 2(length + width) = 2(32 + 32) = 2(64) = 128m Therefore, the perimeter of the rectangle is 128m.
Expected answer: 128
Correct? Yes