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DeepSeek 67B on 5.NF.A.2

Common Core Standard 5.NF.A.2

This standard covers the following:

Solve word problems involving addition and subtraction of fractions referring to the same whole, including cases of unlike denominators, e.g., by using visual fraction models or equations to represent the problem. Use benchmark fractions and number sense of fractions to estimate mentally and assess the reasonableness of answers.

🔗 Problem

Problem: In their game, Kyle threw a ball for a distance of 18/4 yards, while Lisa threw the same ball for a distance of 19/9 yards. How many yards did the ball travel in total?

DeepSeek 67B:

Reasoning:
To find the total distance the ball traveled, we need to add the distances Kyle and Lisa threw the ball.

Kyle threw the ball for 18/4 yards, which is equivalent to 4.5 yards.
Lisa threw the ball for 19/9 yards, which is equivalent to 2.1111 yards.

Total distance = 4.5 + 2.1111 = 6.6111 yards.

### Answer: 6.6111

Expected answer: 119/18

Correct? No

🔗 Problem

Problem: Johnnie the monkey was given 18/7 bananas by the zookeeper in the morning, and 12/14 bananas in the afternoon. In total, how many bananas were given to Johnnie the monkey?

DeepSeek 67B:

Reasoning:
To find the total number of bananas given to Johnnie, we need to add the number of bananas given in the morning and the number of bananas given in the afternoon.

In the morning, Johnnie was given 18/7 bananas.
In the afternoon, Johnnie was given 12/14 bananas.

To add these fractions, we need a common denominator. The least common multiple of 7 and 14 is 14. So, we can rewrite the fractions with a denominator of 14:

18/7 = (18 * 2) / (7 * 2) = 36/14
12/14

Now, we can add the fractions:

36/14 + 12/14 = (36 + 12) / 14 = 48/14

To simplify the fraction, we can divide the numerator and denominator by their greatest common divisor, which is 14:

48/14 = (48/14) / (14/14) = 48/14 = 3

So, Johnnie was given a total of 3 bananas.

Expected answer: 24/7

Correct? No

🔗 Problem

Problem: The bottom of a door measures 4/19 inches from the floor, and the top of the door measures 9/10 inches from the ceiling. What is the total distance of the bottom and top of the door from the floor and ceiling, respectively?

DeepSeek 67B:

Reasoning: The total distance of the bottom and top of the door from the floor and ceiling is 4/19 + 9/10 = <<4/19+9/10=1.26>>1.26 inches.
### Answer: 1.26

Expected answer: 211/190

Correct? No

🔗 Problem

Problem: Ralph's juice recipe requires 17/3 liters of apple juice. However, he only uses 15/11 liters of it. How many liters of apple juice are left unused?

DeepSeek 67B:

Reasoning:
To find out how many liters of apple juice are left unused, we need to subtract the amount used from the total amount required.

Total amount required = 17/3 liters
Amount used = 15/11 liters

Unused amount = Total amount required - Amount used
Unused amount = (17/3) - (15/11)

To subtract these fractions, we need a common denominator. The least common multiple of 3 and 11 is 33. So, we rewrite the fractions with the common denominator:

(17/3) = (17 * 11/3 * 11) = 205/33
(15/11) = (15 * 3/11 * 3) = 45/33

Now, we can subtract the fractions:

Unused amount = (205/33) - (45/33) = 160/33

So, 160/33 liters of apple juice are left unused.

### Answer: 160/33

Expected answer: 142/33

Correct? No

🔗 Problem

Problem: Billy is trying to roller skate in an empty parking lot. He initially travels 4 miles, but rolls back for 17/20 of a mile after spotting a pothole. How many miles did he ultimately travel forward?

DeepSeek 67B:

Reasoning:
Billy initially traveled 4 miles.
He then rolled back for 17/20 of a mile.
To find the total distance he traveled forward, we need to subtract the distance he rolled back from the initial distance he traveled.
The total distance he traveled forward is 4 - 17/20 = 4 - 0.85 = 3.15 miles.
### Answer: 3.15

Expected answer: 63/20

Correct? Yes

🔗 Problem

Problem: A rocket was launched into orbit. On the first day, it traveled 15/3 light years. On the second day, it traveled an additional 2/7 light years. How far has the rocket traveled in total?

DeepSeek 67B:

Reasoning: The rocket traveled 15/3 + 2/7 = 5 + 1 = <<15/3+2/7=6>>6 light years in total.
### Answer: 6

Expected answer: 37/7

Correct? No

🔗 Problem

Problem: Captain Silverbeard found 10/13 of a treasure map at one shipwreck site and 16/19 of the same treasure map at another site. What is the total portion of the treasure map that he found?

DeepSeek 67B:

Reasoning:
To find the total portion of the treasure map that Captain Silverbeard found, we need to add the portions he found at each site.

The portion of the treasure map that Captain Silverbeard found at the first site is 10/13.
The portion of the treasure map that Captain Silverbeard found at the second site is 16/19.

To add these fractions, we need a common denominator. The least common multiple of 13 and 19 is 247.

So, we rewrite the fractions with the common denominator:
10/13 = (10 * 19) / (13 * 19) = 190/247
16/19 = (16 * 13) / (19 * 13) = 208/247

Now, we can add the fractions:
190/247 + 208/247 = 398/247

The total portion of the treasure map that Captain Silverbeard found is 398/247.

### Answer: 398/247

Expected answer: 398/247

Correct? Yes

🔗 Follow-up

Problem: After Captain Silverbeard finds the portions of the treasure map, he discovers another piece on a third site which is 15/17 of the total map. What is the total portion of the treasure map that Captain Silverbeard has now?

DeepSeek 67B:

Reasoning:
To find the total portion of the treasure map that Captain Silverbeard has now, we need to add the portions he found at each site.

The portion of the treasure map that Captain Silverbeard found at the first site is 10/13.
The portion of the treasure map that Captain Silverbeard found at the second site is 16/19.
The portion of the treasure map that Captain Silverbeard found at the third site is 15/17.

To add these fractions, we need a common denominator. The least common multiple of 13, 19, and 17 is 51.

So, we rewrite the fractions with the common denominator:
10/13 = (10 * 4) / (13 * 4) = 40/52
16/19 = (16 * 2) / (19 * 2) = 32/38
15/17 = (15 * 3) / (17 * 3) = 45/51

Now, we can add the fractions:
40/52 + 32/38 + 45/51 = 1170/51

The total portion of the treasure map that Captain Silverbeard has now is 1170/51.

### Answer: 1170/51

Expected answer: 10471/4199

Correct? No

🔗 Follow-up

Problem: Suppose instead of finding 10/13 of the treasure map at the first shipwreck site, Captain Silverbeard found a larger piece which was 10/9 of the total map. Keeping the second portion from the other shipwreck site the same at 16/19, what is the total portion of the treasure map that he found now?

DeepSeek 67B:

Reasoning:
To find the total portion of the treasure map that Captain Silverbeard found, we need to add the portions he found at each site.

The portion of the treasure map that Captain Silverbeard found at the first site is 10/9.
The portion of the treasure map that Captain Silverbeard found at the second site is 16/19.

To add these fractions, we need a common denominator. The least common multiple of 9 and 19 is 171.

So, we rewrite the fractions with the common denominator:
10/9 = (10 * 19) / (9 * 19) = 190/171
16/19 = (16 * 9) / (19 * 9) = 144/171

Now, we can add the fractions:
190/171 + 144/171 = 334/171

The total portion of the treasure map that Captain Silverbeard found is 334/171.

### Answer: 334/171

Expected answer: 334/171

Correct? Yes

🔗 Problem

Problem: A hiker decides to walk 9/6 miles North before walking 2/16 miles East. How many miles has the hiker traveled in total?

DeepSeek 67B:

Reasoning: The hiker walked 9/6 + 2/16 = 18/16 + 2/16 = 20/16 = 1 4/16 miles in total.
### Answer: 1 4/16

Expected answer: 13/8

Correct? No

🔗 Problem

Problem: In Jessica's sandbox, she has a pile of sand that is 16/9 cubic feet. She then removes 4/13 cubic feet of sand from the sandbox. How much sand does she have left in her sandbox?

DeepSeek 67B:

Reasoning: Jessica removes 4/13 cubic feet of sand from the sandbox.
The amount of sand left in the sandbox is 16/9 - 4/13 = 16/9 * 13/13 - 4/13 = 208/117 - 4/13 = 208 - 4 * 9 = 208 - 36 = 172/117 cubic feet.
### Answer: 172/117

Expected answer: 172/117

Correct? Yes

🔗 Follow-up

Problem: Jessica decided to add more sand to her sandbox. She adds an extra 19/15 cubic feet of sand to it. After this, how much sand does she now have in her sandbox?

DeepSeek 67B:

Reasoning: Jessica adds 19/15 cubic feet of sand to the sandbox.
The total amount of sand in the sandbox is 172/117 + 19/15 = 172/117 * 15/15 + 19/15 = 2580/1755 + 19/15 = 2580 + 19 * 117/15 = 2580 + 2163/15 = 4743/15 cubic feet.
### Answer: 4743/15

Expected answer: 1601/585

Correct? No

🔗 Follow-up

Problem: In our previous scenario, let's say that Jessica initially had a smaller pile of sand that was 16/9 cubic feet. If she still removed 4/8 cubic feet of sand as before, how much sand does she now have left in her sandbox?

DeepSeek 67B:

Reasoning: Jessica removes 4/8 cubic feet of sand from the sandbox.
The amount of sand left in the sandbox is 16/9 - 4/8 = 16/9 * 8/8 - 4/8 = 128/72 - 4/8 = 128 - 4 * 9 = 128 - 36 = 92/72 cubic feet.
### Answer: 92/72

Expected answer: 23/18

Correct? Yes

🔗 Problem

Problem: Jacob has a piece of rope that is 15/12 meters long and he adds a piece that is 17/17 meters long to it. What is the total length of the rope now?

DeepSeek 67B:

Reasoning:
To find the total length of the rope, we need to add the lengths of the two pieces of rope.
The first piece of rope is 15/12 meters long, which is equivalent to 1 3/12 meters.
The second piece of rope is 17/17 meters long, which is equivalent to 1 meter.
To add the lengths of the two pieces of rope, we need to convert them to the same unit.
Since 15/12 meters is equivalent to 1 3/12 meters, we can rewrite it as 1 + 3/12 meters.
Now we can add the lengths of the two pieces of rope:
1 + 3/12 + 1 = 2 + 3/12 = 2 3/12 meters.
To simplify the fraction, we can divide both the numerator and denominator by 3:
2 3/12 = 2 1/4 meters.
Therefore, the total length of the rope is 2 1/4 meters.
The answer is: 2\frac{1}{4}

Expected answer: 9/4

Correct? No

🔗 Problem

Problem: Mark has 1 full pair of pants and another 13/4 pairs from various incomplete sets. How many pairs of pants does he have in total?

DeepSeek 67B:

Reasoning:
Mark has 1 full pair of pants.
He also has 13/4 pairs from various incomplete sets.
To find the total number of pairs of pants, we need to add the full pair and the incomplete pairs.
The total number of pairs of pants is 1 + 13/4 = 1 + 3.25 = 4.25 pairs.
### Answer: 4.25

Expected answer: 17/4

Correct? Yes

🔗 Problem

Problem: Miss Jenny stayed after school to grade papers. She spent 8/8 hours on one subject and an additional 20/19 hours on another subject. How long did she spend grading papers in total?

DeepSeek 67B:

Reasoning:
Miss Jenny spent 8/8 + 20/19 = 160/19 + 20/19 = 180/19 hours grading papers in total.
### Answer: 180/19

Expected answer: 39/19

Correct? No

🔗 Problem

Problem: A cloud was observed at a height of 12/3 kms, it later ascended by 15/12 kms. What was the resultant height of the cloud from the ground?

DeepSeek 67B:

Reasoning:
The initial height of the cloud was 12/3 kms.
The cloud ascended by 15/12 kms.
To find the resultant height, we need to add the initial height and the distance it ascended.

Calculating the resultant height:
Resultant height = Initial height + Distance ascended
Resultant height = (12/3) + (15/12)

To add these fractions, we need a common denominator. The least common multiple of 3 and 12 is 12. So, we rewrite the fractions with a denominator of 12:

Resultant height = (4/1) + (15/12)

Now, we can add the fractions:

Resultant height = (4*12)/12 + (15/12)
Resultant height = (48/12) + (15/12)
Resultant height = (48+15)/12
Resultant height = 63/12

The resultant height of the cloud from the ground is 63/12 kms.

### Answer: 63/12

Expected answer: 21/4

Correct? Yes

🔗 Follow-up

Problem: Let's now consider this scenario: the cloud was initially at a height of 12/3 kms, then later it ascended by 7/12 kms instead of the previous 15/12 kms. What would be the resultant height of the cloud from the ground in this case?

DeepSeek 67B:

Reasoning:
The initial height of the cloud was 12/3 kms.
The cloud ascended by 7/12 kms.
To find the resultant height, we need to add the initial height and the distance it ascended.

Calculating the resultant height:
Resultant height = Initial height + Distance ascended
Resultant height = (12/3) + (7/12)

To add these fractions, we need a common denominator. The least common multiple of 3 and 12 is 12. So, we rewrite the fractions with a denominator of 12:

Resultant height = (4/1) + (7/12)

Now, we can add the fractions:

Resultant height = (4*12)/12 + (7/12)
Resultant height = (48/12) + (7/12)
Resultant height = (48+7)/12
Resultant height = 55/12

The resultant height of the cloud from the ground is 55/12 kms.

### Answer: 55/12

Expected answer: 55/12

Correct? Yes

🔗 Problem

Problem: Jack rides his scooter 3/9 of a mile to the library. After leaving, he scoots another 17/15 of a mile to his grandparents' house. How many miles does Jack ride his scooter in total?

DeepSeek 67B:

Reasoning: Jack rides his scooter 3/9 + 17/15 = 45/135 + 102/135 = 147/135 = 1.0866666666666667 miles in total.
### Answer: 1.0866666666666667

Expected answer: 22/15

Correct? No

🔗 Problem

Problem: There are 4 logs in a pile that each burn for 1/16 of an hour. The fire burns out and Tom brings 16 twigs, each of which burns for 1/12 of an hour. What is the total burn time for the logs and twigs?

DeepSeek 67B:

Reasoning:
The total burn time for the logs is 4 * (1/16) = 1/4 of an hour.
The total burn time for the twigs is 16 * (1/12) = 4/3 of an hour.
The total burn time for the logs and twigs is 1/4 + 4/3 = 3/12 + 16/12 = 19/12 of an hour.
### Answer: 19/12

Expected answer: 19/12

Correct? Yes

🔗 Follow-up

Problem: After the logs and twigs burn out, Tom adds 8 pieces of charcoal, each of which burns for 1/5 of an hour. What is the total burn time for the logs, twigs, and charcoal?

DeepSeek 67B:

Reasoning:
The total burn time for the logs and twigs is 19/12 of an hour.
The total burn time for the charcoal is 8 * (1/5) = 8/5 of an hour.
The total burn time for the logs, twigs, and charcoal is 19/12 + 8/5 = 153/60 + 96/60 = 249/60 = 49/10 of an hour.
### Answer: 49/10

Expected answer: 191/60

Correct? No

🔗 Follow-up

Problem: In the original scenario, consider that there were actually 4 logs that each burn for 1/16 of an hour, but Tom only added 15 twigs that each burn for 1/12 of an hour instead. What would be the total burn time for the logs and twigs in this situation?

DeepSeek 67B:

Reasoning:
The total burn time for the logs is 4 * (1/16) = 1/4 of an hour.
The total burn time for the twigs is 15 * (1/12) = 5/4 of an hour.
The total burn time for the logs and twigs is 1/4 + 5/4 = 6/4 = 3/2 of an hour.
### Answer: 3/2

Expected answer: 3/2

Correct? Yes

🔗 Problem

Problem: If a ring maker uses 12/16 ounces of a silver for the base of the ring and 16/2 ounces to make the rest of the ring, how many ounces of silver did the ring maker use in total?

DeepSeek 67B:

Reasoning:
The ring maker used 12/16 ounces of silver for the base of the ring and 16/2 ounces to make the rest of the ring.
To find the total amount of silver used, we need to add the amount used for the base and the amount used for the rest of the ring.
12/16 + 16/2 = 12/16 + 8/1 = 12/16 + 80/16 = 92/16 = 5.75 ounces
The ring maker used 5.75 ounces of silver in total.
### Answer: 5.75

Expected answer: 35/4

Correct? No

🔗 Problem

Problem: A farmer has an apple tree that produced 10/11 bushels of apples in the morning and 17/11 bushels in the afternoon. How many bushels of apples did the tree produce in total?

DeepSeek 67B:

Reasoning: The farmer's apple tree produced 10/11 + 17/11 = <<10/11+17/11=27/11=2.45>>2.45 bushels of apples in total.
### Answer: 2.45

Expected answer: 27/11

Correct? No

🔗 Problem

Problem: If Sam's binoculars increase his range of sight by 3/14 of a mile and Joe's binoculars increase his range of sight by exactly 1 mile (16/16), what is their combined range increase when they use the binoculars one after the other?

DeepSeek 67B:

Reasoning:
Sam's binoculars increase his range of sight by 3/14 of a mile.
Joe's binoculars increase his range of sight by exactly 1 mile.
When they use the binoculars one after the other, the combined range increase is the sum of the individual range increases.
So, the combined range increase is 3/14 + 16/16 = 49/16 miles.
### Answer: 49/16

Expected answer: 17/14

Correct? No

🔗 Problem

Problem: Maria uses 15/10 yards of fabric for a section of a blanket and 9/18 more yards for another section. What is the total length of fabric Maria uses for these two sections?

DeepSeek 67B:

Reasoning:
Maria uses 15/10 + 9/18 = 3/2 + 3/18 = 9/6 + 3/18 = 18/18 + 3/18 = 21/18 = 1.1667 yards of fabric for these two sections.
### Answer: 1.1667

Expected answer: 2

Correct? No

🔗 Problem

Problem: A turtle walks 10/5 miles forward, then walks backward 5/16 mile. How many miles has the turtle actually covered from its starting point?

DeepSeek 67B:

Reasoning: The turtle walks 10/5 - 5/16 = 80/80 - 25/80 = 55/80 miles from its starting point.
### Answer: 55/80

Expected answer: 27/16

Correct? No

🔗 Problem

Problem: A painter uses 18/11 liters of blue paint and 1/8 liters of white paint to mix a shade of sky blue. How much paint in liters did he use in total?

DeepSeek 67B:

Reasoning:
The painter used 18/11 + 1/8 liters of paint in total.
To add these fractions, we need a common denominator. The least common multiple of 11 and 8 is 88.
So, we rewrite the fractions with the common denominator:
18/11 = (18*8)/(11*8) = 144/88
1/8 = 1/8
Now, we can add the fractions:
144/88 + 1/8 = 145/88
The painter used 145/88 liters of paint in total.
### Answer: 145/88

Expected answer: 155/88

Correct? No

🔗 Problem

Problem: A computer program executed 8 tasks in 4 minutes and then executed another 20 tasks in 14 minutes. What is the total number of tasks it executed per minute?

DeepSeek 67B:

Reasoning:
The computer program executed 8 tasks in 4 minutes, so it executed 8/4 = 2 tasks per minute.
Then, it executed another 20 tasks in 14 minutes, so it executed 20/14 = 1.42857 tasks per minute.
To find the total number of tasks executed per minute, we add the tasks per minute from both parts: 2 + 1.42857 = 3.42857 tasks per minute.
### Answer: 3.42857

Expected answer: 24/7

Correct? No

🔗 Problem

Problem: At the end of a rainbow, there are pots filled with magical gold coins. One pot contains 12/13 of a pound of gold coins while another contains 3/2 pounds of gold coins. How much gold is there in total?

DeepSeek 67B:

Reasoning:
To find the total amount of gold, we need to add the amount of gold in each pot.
The first pot contains 12/13 pounds of gold, and the second pot contains 3/2 pounds of gold.
To add these fractions, we need a common denominator. The least common multiple of 13 and 2 is 26.
So, we can rewrite the fractions as 20/26 and 33/26.
Now, we can add the fractions: 20/26 + 33/26 = 53/26.
To simplify the fraction, we divide the numerator and denominator by their greatest common divisor, which is 1.
So, the fraction simplifies to 53/26.
Therefore, there is a total of 53/26 pounds of gold in the pots.
### Answer: 53/26

Expected answer: 63/26

Correct? No

🔗 Problem

Problem: In space, an alien named Zorg receives a video message from earth that is divided into parts. The first part of the message is 4/4 hours long, and the second part is 11/1 hour long. How long in total is the message Zorg received?

DeepSeek 67B:

Reasoning: The first part of the message is 4/4 = <<4/4=1>>1 hour long.
The second part of the message is 11/1 = <<11/1=11>>11 hours long.
The total length of the message is 1+11 = <<1+11=12>>12 hours.
### Answer: 12

Expected answer: 12

Correct? Yes

🔗 Follow-up

Problem: After watching the original message, Zorg receives an additional part of the message from earth that is 7/8 hours long. What is the total length of all parts of the message that Zorg received?

DeepSeek 67B:

Reasoning: The additional part of the message is 7/8 hours long.
The total length of all parts of the message is 12+7/8 = <<12+7/8=12.875>>12.875 hours.
### Answer: 12.875

Expected answer: 103/8

Correct? Yes

🔗 Follow-up

Problem: Upon reviewing the original video message, Zorg realised that the first part of the video message was actually half as long at 4/8 hours instead of 4/4. The second part of the message still remains 11/1 hour long. What is the total length of the message that Zorg has corrected?

DeepSeek 67B:

Reasoning: The first part of the message is 4/8 = <<4/8=0.5>>0.5 hours long.
The second part of the message is 11/1 = <<11/1=11>>11 hours long.
The total length of the message is 0.5+11 = <<0.5+11=11.5>>11.5 hours.
### Answer: 11.5

Expected answer: 23/2

Correct? Yes

🔗 Problem

Problem: In a park, 10 ducks are equally distributed among 5 ponds, implying each pond has 10 / 5 ducks. In the same park, 8 fish are distributed among 10 small pools, with each pool having 8 / 10 fish. How many animals are there in each pond and pool combined?

DeepSeek 67B:

Reasoning:
There are 10 ducks distributed among 5 ponds, so each pond has 10 / 5 = <<10/5=2>>2 ducks.
There are 8 fish distributed among 10 small pools, so each pool has 8 / 10 = <<8/10=0.8>>0.8 fish.
Since each pool has 0.8 fish, there are 0.8 * 10 = <<0.8*10=8>>8 fish in total in the pools.
In total, there are 2 ducks per pond * 5 ponds = <<2*5=10>>10 ducks in the ponds.
Therefore, there are 10 ducks + 8 fish = <<10+8=18>>18 animals in the ponds and pools combined.
### Answer: 18

Expected answer: 14/5

Correct? No

🔗 Problem

Problem: On a map, 15/11 inches represents the distance between Town A and Town B, and 16/15 inches represents the distance between Town B and Town C. What is the total distance between Town A and Town C on the map?

DeepSeek 67B:

Reasoning:
To find the total distance between Town A and Town C on the map, we need to add the distances between Town A and Town B and Town B and Town C.
The distance between Town A and Town B is 15/11 inches, and the distance between Town B and Town C is 16/15 inches.
To add these fractions, we need a common denominator. The least common multiple of 11 and 15 is 165.
So, we rewrite the fractions with the common denominator:
15/11 = (15 * 15) / (11 * 15) = 225/165
16/15 = (16 * 11) / (15 * 11) = 176/165
Now, we can add the fractions:
225/165 + 176/165 = 401/165
So, the total distance between Town A and Town C on the map is 401/165 inches.
### Answer: 401/165

Expected answer: 401/165

Correct? Yes

🔗 Follow-up

Problem: On a map, 15/11 inches represents the distance between Town A and Town B, and 16/15 inches represents the distance between Town B and Town C. After measuring the distance between Town C and Town D, which was found to be 20/5 inches. What is the total distance between Town A and Town D on the map?

DeepSeek 67B:

Reasoning:
To find the total distance between Town A and Town D on the map, we need to add the distances between Town A and Town B, Town B and Town C, and Town C and Town D.
The distance between Town A and Town B is 15/11 inches, the distance between Town B and Town C is 16/15 inches, and the distance between Town C and Town D is 20/5 inches.
To add these fractions, we need a common denominator. The least common multiple of 11, 15, and 5 is 165.
So, we rewrite the fractions with the common denominator:
15/11 = (15 * 15) / (11 * 15) = 225/165
16/15 = (16 * 11) / (15 * 11) = 176/165
20/5 = (20 * 33) / (5 * 33) = 660/165
Now, we can add the fractions:
225/165 + 176/165 + 660/165 = 1061/165
So, the total distance between Town A and Town D on the map is 1061/165 inches.
### Answer: 1061/165

Expected answer: 1061/165

Correct? Yes

🔗 Follow-up

Problem: On the same map, suppose the distance between Town A and Town B is not 15/11 but 15/11 inches, and 16/7 inches represents the distance between Town B and Town C. Now, what would be the total distance on the map from Town A to Town C?

DeepSeek 67B:

Reasoning:
To find the total distance between Town A and Town C on the map, we need to add the distances between Town A and Town B and Town B and Town C.
The distance between Town A and Town B is 15/11 inches, and the distance between Town B and Town C is 16/7 inches.
To add these fractions, we need a common denominator. The least common multiple of 11 and 7 is 77.
So, we rewrite the fractions with the common denominator:
15/11 = (15 * 7) / (11 * 7) = 105/77
16/7 = (16 * 11) / (7 * 11) = 176/77
Now, we can add the fractions:
105/77 + 176/77 = 281/77
So, the total distance between Town A and Town C on the map is 281/77 inches.
### Answer: 281/77

Expected answer: 281/77

Correct? Yes

🔗 Problem

Problem: A soap company produces 13/18 tons of Soap A and 4/6 tons of Soap B in a day. How many tons of soap do they produce in total each day?

DeepSeek 67B:

Reasoning:
To find the total amount of soap produced each day, we need to add the amount of Soap A and Soap B produced.

Soap A: 13/18 tons
Soap B: 4/6 tons

To add these fractions, we need a common denominator. The least common multiple of 18 and 6 is 18. So, we can rewrite the fractions with a denominator of 18:

Soap A: 13/18
Soap B: 4/6 = 8/18

Now, we can add the fractions:

Total soap produced = (13/18) + (8/18) = (13+8)/18 = 21/18

To simplify the fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 3:

21 � 3 = 7
18 � 3 = 6

So, the total soap produced each day is 7/6 tons. However, since we cannot have a fraction of a ton, we need to convert this to a mixed number:

7/6 = 1 1/6 tons

Therefore, the soap company produces 1 1/6 tons of soap in total each day.

Expected answer: 25/18

Correct? No

🔗 Problem

Problem: Mark bought a sleeping bag that was 19/2 feet long. However, he decides to cut off 13/12 feet from it to fit his height. How long is his sleeping bag now?

DeepSeek 67B:

Reasoning:
Mark's sleeping bag was initially 19/2 feet long.
He cut off 13/12 feet from it.
To find the length of the sleeping bag now, we subtract the length he cut off from the initial length.
The length of the sleeping bag now is 19/2 - 13/12 feet.
To subtract these fractions, we need a common denominator.
The least common multiple of 2 and 12 is 12.
So, we rewrite the fractions with a denominator of 12:
19/2 = (19*6)/(2*6) = 114/12
13/12
Now we can subtract the fractions:
114/12 - 13/12 = 101/12
So, Mark's sleeping bag is now 101/12 feet long.
### Answer: 101/12

Expected answer: 101/12

Correct? Yes

🔗 Follow-up

Problem: After tailoring, Mark finds the sleeping bag is still too long for his comfort. He decides to cut off another 13/14 feet from his sleeping bag. What is the length of his sleeping bag now?

DeepSeek 67B:

Reasoning:
Mark's sleeping bag was initially 19/2 feet long.
He cut off 13/12 feet from it, making it 101/12 feet long.
Now, he decides to cut off another 13/14 feet from it.
To find the length of the sleeping bag now, we subtract the length he cut off from the previous length.
The length of the sleeping bag now is 101/12 - 13/14 feet.
To subtract these fractions, we need a common denominator.
The least common multiple of 12 and 14 is 84.
So, we rewrite the fractions with a denominator of 84:
101/12 = (101*7)/(12*7) = 707/84
13/14 = (13*6)/(14*6) = 78/84
Now we can subtract the fractions:
707/84 - 78/84 = 629/84
So, Mark's sleeping bag is now 629/84 feet long.
### Answer: 629/84

Expected answer: 629/84

Correct? Yes

🔗 Follow-up

Problem: Originally, Mark bought a sleeping bag that was 8/2 feet long instead of 19/2 feet. He still cuts off 13/12 feet from it to fit his height. How long is his sleeping bag now?

DeepSeek 67B:

Reasoning:
Mark's sleeping bag was initially 8/2 feet long.
He cut off 13/12 feet from it.
To find the length of the sleeping bag now, we subtract the length he cut off from the initial length.
The length of the sleeping bag now is 8/2 - 13/12 feet.
To subtract these fractions, we need a common denominator.
The least common multiple of 2 and 12 is 12.
So, we rewrite the fractions with a denominator of 12:
8/2 = (8*6)/(2*6) = 48/12
13/12
Now we can subtract the fractions:
48/12 - 13/12 = 35/12
So, Mark's sleeping bag is now 35/12 feet long.
### Answer: 35/12

Expected answer: 35/12

Correct? Yes

🔗 Problem

Problem: At the zoo, Mary feeds 6/20 pounds of food to the monkeys, and 18/15 pounds of food to the giraffes. How many pounds of food in total has she given to the monkeys and giraffes?

DeepSeek 67B:

Reasoning: Mary feeds 6/20 + 18/15 = 18/30 + 18/15 = 36/60 + 36/60 = 72/60 = 1.2 pounds of food to the monkeys and giraffes.
### Answer: 1.2

Expected answer: 3/2

Correct? No

🔗 Problem

Problem: Albert has a deck of 20/17 full sets of cards to start. He then collects another full set of 4/1 cards. How many full sets of cards does he have now?

DeepSeek 67B:

Reasoning: Albert has 20/17 + 4/1 = <<20/17+4/1=20/17+4=20/17+4*17/17=20/17+68/17=88/17>>88/17 full sets of cards.
### Answer: 88/17

Expected answer: 88/17

Correct? Yes

🔗 Follow-up

Problem: Instead of collecting a full set of 4/1 cards, what if Albert had only managed to find 4/11 of a full set? Adding this to his initial 20/17 full sets, how many full sets of cards does he have now?

DeepSeek 67B:

Reasoning: Albert has 20/17 + 4/11 = <<20/17+4/11=20/17+4/11*17/17=20/17+68/187=20*187+68*17/17*187=3740+1156/187*17=4896/187>>4896/187 full sets of cards.
### Answer: 4896/187

Expected answer: 288/187

Correct? No

🔗 Problem

Problem: A jeweler has 5/14 pound of silver and adds 18/19 pounds more to the supply. How many pounds of silver does the jeweler have now to make rings?

DeepSeek 67B:

Reasoning: The jeweler has 5/14 + 18/19 = <<5/14+18/19=187/196>>187/196 pounds of silver.
The jeweler has 187/196 = <<187/196=1>>1 pound of silver.
### Answer: 1

Expected answer: 347/266

Correct? No

🔗 Problem

Problem: A turtle starts at a point and moves 11 meters northward. Then, it moves 15/15 of a meter back towards the starting point. How many meters is the turtle from its starting point after these two movement?

DeepSeek 67B:

Reasoning:
The turtle moves 11 meters northward and then moves 15/15 = 1 meter back towards the starting point.
So, the turtle is 11 - 1 = <<11-1=10>>10 meters from its starting point after these two movements.
### Answer: 10

Expected answer: 10

Correct? Yes

🔗 Follow-up

Problem: Continuing from the prior situation, the turtle then decided to move further, walking an additional 15/20 of a meter towards the same direction. How many meters is the turtle from its original starting point now?

DeepSeek 67B:

Reasoning:
The turtle is initially 10 meters from its starting point.
It then moves an additional 15/20 = 0.75 meters towards the same direction.
So, the turtle is now 10 - 0.75 = <<10-0.75=9.25>>9.25 meters from its original starting point.
### Answer: 9.25

Expected answer: 43/4

Correct? No

🔗 Follow-up

Problem: Reconsider the previous scenario, but this time the turtle returns 15/8 of a meter back towards the starting point instead of the former 15/15 meters. Now, how many meters is the turtle from its starting point after these two movements?

DeepSeek 67B:

Reasoning:
The turtle moves 11 meters northward and then moves 15/8 = 1.875 meters back towards the starting point.
So, the turtle is 11 - 1.875 = <<11-1.875=9.125>>9.125 meters from its starting point after these two movements.
### Answer: 9.125

Expected answer: 73/8

Correct? Yes

🔗 Problem

Problem: Chloe has a chocolate bar that is 19/2 ounces. If she eats a piece that is 17/2 ounces, how many ounces of chocolate does she have left?

DeepSeek 67B:

Reasoning: Chloe has a chocolate bar that is 19/2 ounces.
If she eats a piece that is 17/2 ounces, she has 19/2 - 17/2 = 1 ounce of chocolate left.
### Answer: 1

Expected answer: 1

Correct? Yes

🔗 Follow-up

Problem: After Chloe eats a piece of the chocolate bar, she decides to add a piece from another chocolate bar. The piece from the other bar weighs 4/14 ounces. How many ounces of chocolate does Chloe have now?

DeepSeek 67B:

Reasoning: Chloe has 1 ounce of chocolate left from the first bar.
She adds a piece from another bar that weighs 4/14 ounces.
So, Chloe now has 1 + 4/14 = 14/14 + 4/14 = 18/14 = 9/7 ounces of chocolate.
### Answer: 9/7

Expected answer: 9/7

Correct? Yes

🔗 Follow-up

Problem: Originally, Chloe had a chocolate bar that was 19/2 ounces. What if instead, at the beginning she had eaten a piece that was 9/2 ounces? How many ounces of chocolate would she have had left then?

DeepSeek 67B:

Reasoning: Chloe originally had a chocolate bar that was 19/2 ounces.
If she had eaten a piece that was 9/2 ounces, she would have had 19/2 - 9/2 = 5 ounces of chocolate left.
### Answer: 5

Expected answer: 5

Correct? Yes

🔗 Problem

Problem: Sammy has a backpack with a capacity of 20/9 liters. If he adds another pouch to the backpack that can hold 8/4 more liters, what will be the total capacity of his backpack?

DeepSeek 67B:

Reasoning: Sammy's backpack has a capacity of 20/9 liters.
If he adds another pouch that can hold 8/4 more liters, the total capacity of his backpack will be 20/9 + 8/4 liters.
To add these fractions, we need a common denominator, which is 36.
So, 20/9 + 8/4 = (20/9) * (4/4) + (8/4) * (9/9) = 80/36 + 72/36 = 152/36.
The total capacity of Sammy's backpack is 152/36 liters.
### Answer: 152/36

Expected answer: 38/9

Correct? Yes

🔗 Follow-up

Problem: In addition to his already expanded backpack, Sammy finds another tiny side pocket that can carry an extra 3/8 of a liter. What is the total capacity of his backpack now?

DeepSeek 67B:

Reasoning: Sammy's backpack has a capacity of 152/36 liters.
If he adds another tiny side pocket that can carry an extra 3/8 of a liter, the total capacity of his backpack will be 152/36 + 3/8 liters.
To add these fractions, we need a common denominator, which is 24.
So, 152/36 + 3/8 = (152/36) * (8/8) + (3/8) * (3/3) = 1216/288 + 9/288 = 1225/288.
The total capacity of Sammy's backpack is 1225/288 liters.
### Answer: 1225/288

Expected answer: 331/72

Correct? No

🔗 Follow-up

Problem: Instead of the backpack having an initial capacity of 20/9 liters, let's say it could only carry 20/12 liters. If Sammy still adds the same extra pouch of 8/4 liters, what would the total capacity of his backpack be then?

DeepSeek 67B:

Reasoning: Sammy's backpack has a capacity of 20/12 liters.
If he adds another pouch that can hold 8/4 more liters, the total capacity of his backpack will be 20/12 + 8/4 liters.
To add these fractions, we need a common denominator, which is 12.
So, 20/12 + 8/4 = (20/12) * (1/1) + (8/4) * (3/3) = 20/12 + 24/12 = 44/12.
The total capacity of Sammy's backpack is 44/12 liters.
### Answer: 44/12

Expected answer: 11/3

Correct? Yes

🔗 Problem

Problem: Captain Hook has 11/8 ounces of gold. He finds an additional 5/5 ounces of gold on his latest treasure hunt. What is the total weight of the gold Captain Hook now has?

DeepSeek 67B:

Reasoning:
To find the total weight of the gold Captain Hook now has, we need to add the weight of the gold he initially had to the weight of the gold he found on his latest treasure hunt.

Captain Hook initially had 11/8 ounces of gold.
He found an additional 5/5 ounces of gold on his latest treasure hunt.

To add these fractions, we need a common denominator. The least common multiple of 8 and 5 is 40. So, we can rewrite the fractions with a denominator of 40:

11/8 = 55/40
5/5 = 40/40

Now, we can add the fractions:

55/40 + 40/40 = 95/40

To simplify the fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 5:

95/40 = 19/8

So, the total weight of the gold Captain Hook now has is 19/8 ounces.

### Answer: 19/8

Expected answer: 19/8

Correct? Yes

🔗 Follow-up

Problem: After counting his newly found gold, Captain Hook discovers an additional 7/11 ounces of gold hidden in a small pouch he had forgotten about. What is the total weight of all the gold Captain Hook now has?

DeepSeek 67B:

Reasoning:
To find the total weight of all the gold Captain Hook now has, we need to add the weight of the gold he initially had, the weight of the gold he found on his latest treasure hunt, and the weight of the gold he found in the small pouch.

Captain Hook initially had 11/8 ounces of gold.
He found an additional 5/5 ounces of gold on his latest treasure hunt.
He found an additional 7/11 ounces of gold in the small pouch.

To add these fractions, we need a common denominator. The least common multiple of 8, 40, and 11 is 440. So, we can rewrite the fractions with a denominator of 440:

11/8 = 575/440
5/5 = 440/440
7/11 = 308/440

Now, we can add the fractions:

575/440 + 440/440 + 308/440 = 1323/440

To simplify the fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 1:

1323/440 = 1323/440

So, the total weight of all the gold Captain Hook now has is 1323/440 ounces.

### Answer: 1323/440

Expected answer: 265/88

Correct? No

🔗 Follow-up

Problem: In the previous treasure hunt, Captain Hook had originally found 11/8 ounces of gold. But let's say, instead of finding 5/5 ounces of gold as he did in his latest treasure hunt, he discovered 7/5 ounces of gold. How much total weight of gold would Captain Hook have had then?

DeepSeek 67B:

Reasoning:
To find the total weight of the gold Captain Hook would have had, we need to add the weight of the gold he initially had to the weight of the gold he found on his previous treasure hunt.

Captain Hook initially had 11/8 ounces of gold.
He found an additional 7/5 ounces of gold on his previous treasure hunt.

To add these fractions, we need a common denominator. The least common multiple of 8 and 5 is 40. So, we can rewrite the fractions with a denominator of 40:

11/8 = 55/40
7/5 = 56/40

Now, we can add the fractions:

55/40 + 56/40 = 111/40

To simplify the fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 11:

111/40 = 10/4

So, the total weight of the gold Captain Hook would have had is 10/4 ounces.

### Answer: 10/4

Expected answer: 111/40

Correct? No

🔗 Problem

Problem: If Jake originally had 9/10 of a dollar and then received an additional 20/15 of a dollar, how much money does he have in his wallet now?

DeepSeek 67B:

Reasoning:
Jake originally had 9/10 of a dollar, which is equal to 9/10 = 0.9 dollars.
He then received an additional 20/15 of a dollar, which is equal to 20/15 = 4/3 dollars.
To find out how much money Jake has in his wallet now, we need to add the two amounts together.
0.9 + 4/3 = 2.7/3 = 1.2 dollars.
Therefore, Jake has 1.2 dollars in his wallet now.
### Answer: 1.2

Expected answer: 67/30

Correct? No

🔗 Problem

Problem: Paul has built the front half of a chair that measures 5/2 feet high. He also constructs the back portion of the chair that measures 20/14 feet. What is the combined height of the front and back portions of the chair that Paul has constructed?

DeepSeek 67B:

Reasoning:
The combined height of the front and back portions of the chair is the sum of the height of the front half and the height of the back portion.
The height of the front half is 5/2 feet, and the height of the back portion is 20/14 feet.
To find the combined height, we add the two heights:
5/2 + 20/14 = 14/2 + 20/14 = 70/14 + 20/14 = 90/14 = 6 6/7 feet.
### Answer: 6 6/7

Expected answer: 55/14

Correct? No

🔗 Problem

Problem: John has 5 shirts and he donated 12/9 of them to charity. How many shirts does he have left?

DeepSeek 67B:

Reasoning: John donated 12/9*5 = <<12/9*5=6.67>>6.67 shirts to charity.
John has 5-6.67 = <<5-6.67= -1.67>>-1.67 shirts left.
### Answer: -1.67

Expected answer: 11/3

Correct? No

🔗 Problem

Problem: Bob has a jacket that measures 14/3 meters in length. However, he finds the jacket is slightly too long for him so he decides to cut off 14/16 meter from the original length. What is the length of Bob's jacket after the alteration?

DeepSeek 67B:

Reasoning:
Bob's jacket originally measured 14/3 meters.
He cut off 14/16 meters from the original length.
To find the length of the jacket after the alteration, we need to subtract the length cut off from the original length.

Length of jacket after alteration = Original length - Length cut off
Length of jacket after alteration = (14/3) - (14/16)

To subtract these fractions, we need a common denominator. The least common multiple of 3 and 16 is 48. So, we convert both fractions to have a denominator of 48:

(14/3) = (14 * 16) / (3 * 16) = (224/48)
(14/16) = (14 * 3) / (16 * 3) = (42/48)

Now, we can subtract the fractions:

Length of jacket after alteration = (224/48) - (42/48) = (224 - 42) / 48 = 182/48

To simplify the fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 2:

Length of jacket after alteration = (182/2) / (48/2) = 91/24

So, the length of Bob's jacket after the alteration is 91/24 meters.

Expected answer: 91/24

Correct? Yes

🔗 Problem

Problem: Officer Max spends 2/6 part of an hour completing paperwork. Then, he spends 14/7 parts of an hour patrolling the neighborhood. How much time, in parts of an hour, does Officer Max use for these two tasks?

DeepSeek 67B:

Reasoning:
Officer Max spends 2/6 + 14/7 = 1/3 + 2 parts of an hour for these two tasks.
### Answer: 1/3 + 2

Expected answer: 7/3

Correct? Yes

🔗 Problem

Problem: John watched a movie for 10/12 of an hour and then watched a TV show for another 3/8 of an hour. What is the total time he spent watching in hours?

DeepSeek 67B:

Reasoning:
John watched a movie for 10/12 of an hour, which is equal to 5/6 of an hour.
He then watched a TV show for another 3/8 of an hour.
To find the total time he spent watching, we need to add these two fractions together.
The common denominator for 6 and 8 is 24, so we can rewrite the fractions as:
5/6 = 15/24
3/8 = 9/24
Now we can add the fractions:
15/24 + 9/24 = 24/24 = 1
So, John spent a total of 1 hour watching.
### Answer: 1

Expected answer: 29/24

Correct? No

🔗 Problem

Problem: Mr. Carpenter makes crafting chairs a meticulous process. He takes 5/3 hours to build the frame and additional 10/13 hours to upholster it. How long does it take for him to build a chair from start to finish?

DeepSeek 67B:

Reasoning:
To find the total time it takes for Mr. Carpenter to build a chair, we need to add the time it takes to build the frame and the time it takes to upholster it.

The time it takes to build the frame is 5/3 hours.
The time it takes to upholster it is 10/13 hours.

To add these fractions, we need a common denominator. The least common multiple of 3 and 13 is 39. So, we rewrite the fractions with the common denominator of 39:

5/3 = (5 * 13) / (3 * 13) = 65/39
10/13 = (10 * 3) / (13 * 3) = 30/39

Now, we can add the fractions:

65/39 + 30/39 = 95/39

So, it takes Mr. Carpenter 95/39 hours to build a chair from start to finish.

To express this as a mixed number, we divide the numerator by the denominator:

95 � 39 = 2 remainder 13

So, the mixed number is 2 13/39.

Therefore, it takes Mr. Carpenter 2 13/39 hours to build a chair from start to finish.

Expected answer: 95/39

Correct? No

🔗 Problem

Problem: Anna has a bracelet that consists of small and large beads. The small beads are each 8/4 mm in diameter and the large beads are each 15/2 mm in diameter. If she adds a small and a large bead to her bracelet, what would be the total added diameter in mm?

DeepSeek 67B:

Reasoning:
The diameter of a small bead is 8/4 mm = 2 mm.
The diameter of a large bead is 15/2 mm = 7.5 mm.
If Anna adds a small and a large bead to her bracelet, the total added diameter would be 2 mm + 7.5 mm = 9.5 mm.
### Answer: 9.5

Expected answer: 19/2

Correct? Yes

🔗 Problem

Problem: A rocket travels 11/18 light-years to an alien planet, then travels another 8/2 light-years towards a distant star. What is the total distance covered by the rocket?

DeepSeek 67B:

Reasoning: The total distance covered by the rocket is the sum of the distances covered in the two trips.
The total distance covered by the rocket is 11/18 + 8/2 = <<11/18+8/2=1>>1 light-year.
### Answer: 1

Expected answer: 83/18

Correct? No

🔗 Problem

Problem: Johnathan needs 12/14 yards of one fabric to make a sleeping bag, and another 8/5 yards of a different fabric to create the liner. How many yards of fabric does he need in total to create his sleeping bag?

DeepSeek 67B:

Reasoning:
To find the total amount of fabric Johnathan needs, we need to add the amount of fabric needed for the sleeping bag and the liner.

The amount of fabric needed for the sleeping bag is 12/14 yards.
The amount of fabric needed for the liner is 8/5 yards.

To add these fractions, we need a common denominator. The least common multiple of 14 and 5 is 70.

So, we rewrite the fractions with the common denominator of 70:

12/14 = (12 * 5) / (14 * 5) = 60/70
8/5 = (8 * 14) / (5 * 14) = 112/70

Now, we can add the fractions:

60/70 + 112/70 = 172/70

To simplify the fraction, we divide the numerator and denominator by their greatest common divisor, which is 2:

172/70 = (172/2) / (70/2) = 86/35

So, Johnathan needs a total of 86/35 yards of fabric to create his sleeping bag.

### Answer: 86/35

Expected answer: 86/35

Correct? Yes

🔗 Follow-up

Problem: After calculating the total fabrics Jonathan needed for the sleeping bag, he remembered that he had bought 17 yards of fabric in total. How many yards does he have left after using the necessary fabric to create his sleeping bag?

DeepSeek 67B:

Reasoning:
To find out how many yards of fabric Johnathan has left, we need to subtract the total amount of fabric needed for the sleeping bag from the amount of fabric he bought.

Johnathan bought 17 yards of fabric in total.
The total amount of fabric needed for the sleeping bag is 86/35 yards.

To subtract these fractions, we need a common denominator. The least common multiple of 35 and 1 is 35.

So, we rewrite the fractions with the common denominator of 35:

17 = 17 * 1 = 17/1
86/35 = 86/35

Now, we can subtract the fractions:

17/1 - 86/35 = (17 * 35) / (1 * 35) - 86/35 = 595/35 - 86/35 = 509/35

To simplify the fraction, we divide the numerator and denominator by their greatest common divisor, which is 1:

509/35 = 509/35

So, Johnathan has 509/35 yards of fabric left after using the necessary fabric to create his sleeping bag.

### Answer: 509/35

Expected answer: 509/35

Correct? Yes

🔗 Follow-up

Problem: In the previous problem, Johnathan originally thought he needed 12/14 yards of one fabric to create the sleeping bag. But after rechecking his measurements, he realized he only needed 12/17 yards of that fabric. The liner fabric remained the same at 8/5 yards. How many total yards of fabric does he actually need to make the sleeping bag?

DeepSeek 67B:

Reasoning:
To find the total amount of fabric Johnathan actually needs, we need to add the amount of fabric needed for the sleeping bag and the liner.

The amount of fabric needed for the sleeping bag is 12/17 yards.
The amount of fabric needed for the liner is 8/5 yards.

To add these fractions, we need a common denominator. The least common multiple of 17 and 5 is 85.

So, we rewrite the fractions with the common denominator of 85:

12/17 = (12 * 5) / (17 * 5) = 60/85
8/5 = (8 * 17) / (5 * 17) = 136/85

Now, we can add the fractions:

60/85 + 136/85 = 196/85

To simplify the fraction, we divide the numerator and denominator by their greatest common divisor, which is 1:

196/85 = 196/85

So, Johnathan actually needs a total of 196/85 yards of fabric to make the sleeping bag.

### Answer: 196/85

Expected answer: 196/85

Correct? Yes

🔗 Problem

Problem: In a forest, there are 5/4 acres of pine trees and 1/2 acre of oak trees. What is the total acreage of pine and oak trees in the forest?

DeepSeek 67B:

Reasoning:
To find the total acreage of pine and oak trees in the forest, we need to add the acreage of pine trees and the acreage of oak trees.
The total acreage of pine trees is 5/4 acres.
The total acreage of oak trees is 1/2 acre.
To add these fractions, we need a common denominator. The least common multiple of 4 and 2 is 4.
So, we rewrite the fractions with a denominator of 4:
5/4 acres + 2/4 acres = 7/4 acres.
Therefore, the total acreage of pine and oak trees in the forest is 7/4 acres.
### Answer: 7/4

Expected answer: 7/4

Correct? Yes

🔗 Follow-up

Problem: After further research, it is found that the forest actually had 5/3 acres of pine trees instead of 5/4 acres. Keeping the acreage of oak trees the same, what is the new total acreage of pine and oak trees in the forest?

DeepSeek 67B:

Reasoning:
To find the new total acreage of pine and oak trees in the forest, we need to add the new acreage of pine trees and the acreage of oak trees.
The new total acreage of pine trees is 5/3 acres.
The total acreage of oak trees is still 1/2 acre.
To add these fractions, we need a common denominator. The least common multiple of 3 and 2 is 6.
So, we rewrite the fractions with a denominator of 6:
5/3 acres + 3/6 acres = 10/6 acres.
Therefore, the new total acreage of pine and oak trees in the forest is 10/6 acres.
### Answer: 10/6

Expected answer: 13/6

Correct? No

🔗 Problem

Problem: Jake has 12/7 of a yard of fabric. He finds another piece that measures 2/14 of a yard. If he combines both pieces, how much fabric does he have to make his shirt?

DeepSeek 67B:

Reasoning:
Jake has 12/7 + 2/14 = 12/7 + 1/7 = 13/7 = 1 6/7 yards of fabric.
### Answer: 1 6/7

Expected answer: 13/7

Correct? Yes

🔗 Follow-up

Problem: After making his shirt, Jake realizes he needs to remove 4/16 of a yard of fabric for the shirt to fit perfectly. How much fabric will he have left after making this adjustment?

DeepSeek 67B:

Reasoning:
Jake has 1 6/7 - 4/16 = 1 6/7 - 1/4 = 1 2/7 yards of fabric left.
### Answer: 1 2/7

Expected answer: 45/28

Correct? No

🔗 Follow-up

Problem: Let's say Jake originally had less fabric, only 12/6 yards instead of 12/7 yards. He still finds an additional piece of fabric that measures 2/14 of a yard. If he combines both these pieces now, then how much fabric does he have altogether for his shirt?

DeepSeek 67B:

Reasoning:
Jake has 12/6 + 2/14 = 2 + 1/7 = 2 1/7 yards of fabric.
### Answer: 2 1/7

Expected answer: 15/7

Correct? Yes

🔗 Problem

Problem: At a park, a special tree produces on average 10/4 kilograms of fruit every summer. In the winter, it loses some of its fruit, amounting to 12/20 kg. What is the difference in kilograms of the fruit from summer to winter?

DeepSeek 67B:

Reasoning:
The difference in kilograms of the fruit from summer to winter is 10/4 - 12/20 = 5/2 - 3/10 = 25/10 - 6/10 = 19/10 = 1.9 kg.
### Answer: 1.9

Expected answer: 19/10

Correct? Yes

🔗 Problem

Problem: A ballerina starts with a routine that lasts 13/5 minutes but decides to shorten it by 15/16 minutes. How long is her routine after shortening it?

DeepSeek 67B:

Reasoning: The ballerina's routine is shortened by 15/16 minutes, so the remaining time is 13/5 - 15/16 minutes.
To subtract these fractions, we need a common denominator, which is 80.
So, 13/5 - 15/16 = (13*16)/5 - 15/16 = 208/80 - 15/80 = 193/80 minutes.
### Answer: 193/80

Expected answer: 133/80

Correct? No

🔗 Problem

Problem: Miss Daisy has 19/6 kg of fertilizers for her flowers. If she uses 17/20 kg on her roses, how much fertilizers does she have left to use on her other flowers?

DeepSeek 67B:

Reasoning:
Miss Daisy has 19/6 kg of fertilizers.
She uses 17/20 kg on her roses.
To find out how much fertilizers she has left, we need to subtract the amount she used from the total amount she has.
19/6 - 17/20 = ?
To subtract these fractions, we need a common denominator. The least common multiple of 6 and 20 is 60.
So, we rewrite the fractions with the common denominator:
19/6 = 190/60
17/20 = 85/60
Now, we can subtract the fractions:
190/60 - 85/60 = 105/60
To simplify the fraction, we divide the numerator and denominator by their greatest common divisor, which is 15:
105/60 = 7/4
So, Miss Daisy has 7/4 kg of fertilizers left to use on her other flowers.
### Answer: 7/4

Expected answer: 139/60

Correct? No

🔗 Problem

Problem: Scientists have discovered that the moon is slowly moving away from Earth. If the distance increases by 4/16 meters every year, and unexpectedly there was an additional increase of 20/6 meters this year, what is the total change in distance this year?

DeepSeek 67B:

Reasoning:
The total change in distance this year is the sum of the regular increase and the unexpected increase.
The regular increase is 4/16 meters per year.
The unexpected increase is 20/6 meters this year.
So, the total change in distance this year is (4/16) + (20/6) = 24/48 + 80/48 = 104/48 = 26/12 = 13/6 meters.
### Answer: 13/6

Expected answer: 43/12

Correct? No

🔗 Problem

Problem: Bob has 11/3 dollars in one pocket of his wallet and 12/19 dollars in another pocket. How much money does he have in total in his wallet?

DeepSeek 67B:

Reasoning:
To find the total amount of money Bob has in his wallet, we need to add the amount of money in each pocket.

The amount of money in the first pocket is 11/3 dollars.
The amount of money in the second pocket is 12/19 dollars.

To add these fractions, we need a common denominator. The least common multiple of 3 and 19 is 57. So, we can rewrite the fractions with the common denominator of 57:

11/3 = (11 * 19) / (3 * 19) = 209/57
12/19 = (12 * 3) / (19 * 3) = 36/57

Now, we can add the fractions:

209/57 + 36/57 = 245/57

So, Bob has 245/57 dollars in total in his wallet.

### Answer: 245/57

Expected answer: 245/57

Correct? Yes

🔗 Follow-up

Problem: Bob has 11/3 dollars in one pocket of his wallet and 12/19 dollars in another pocket. How much money does he have in total in his wallet? Now, if Bob duplicates the total amount of money in his wallet, how much money will he have then?

DeepSeek 67B:

Reasoning:

To find the total amount of money Bob has in his wallet, we need to add the amount of money in each pocket.

The amount of money in the first pocket is 11/3 dollars.
The amount of money in the second pocket is 12/19 dollars.

To add these fractions, we need a common denominator. The least common multiple of 3 and 19 is 57. So, we can rewrite the fractions with the common denominator of 57:

11/3 = (11 * 19) / (3 * 19) = 209/57
12/19 = (12 * 3) / (19 * 3) = 36/57

Now, we can add the fractions:

209/57 + 36/57 = 245/57

So, Bob has 245/57 dollars in total in his wallet.

If Bob duplicates the total amount of money in his wallet, he will have:

2 * (245/57) = 490/57 dollars

### Answer: 490/57

Expected answer: 490/57

Correct? Yes

🔗 Follow-up

Problem: Suppose Bob starts out with 3/3 (or 1) dollar in one pocket of his wallet instead of 11/3 dollars, and still has 12/19 dollars in another pocket. Now how much money does he have in total in his wallet?

DeepSeek 67B:

Reasoning:
To find the total amount of money Bob has in his wallet, we need to add the amount of money in each pocket.

The amount of money in the first pocket is 3/3 (or 1) dollar.
The amount of money in the second pocket is 12/19 dollars.

To add these fractions, we need a common denominator. The least common multiple of 3 and 19 is 57. So, we can rewrite the fractions with the common denominator of 57:

1 = (1 * 19) / (3 * 19) = 19/57
12/19 = (12 * 3) / (19 * 3) = 36/57

Now, we can add the fractions:

19/57 + 36/57 = 55/57

So, Bob has 55/57 dollars in total in his wallet.

### Answer: 55/57

Expected answer: 31/19

Correct? No

🔗 Problem

Problem: In an ocean, a shark swims a distance of 5/5 miles in the morning and adds an additional 12/18 miles in the afternoon. How many miles in total did the shark swim that day?

DeepSeek 67B:

Reasoning: The shark swam 5/5 + 12/18 = 9/18 + 12/18 = 21/18 = 1 3/18 miles in total.
### Answer: 1 3/18

Expected answer: 5/3

Correct? No

🔗 Problem

Problem: Jim types 20 words in 16 seconds and Mary types 9 words in 4 seconds. How many words per second do Jim and Mary type in total?

DeepSeek 67B:

Reasoning:
Jim types 20/16 = <<20/16=1.25>>1.25 words per second.
Mary types 9/4 = <<9/4=2.25>>2.25 words per second.
Jim and Mary type 1.25+2.25 = <<1.25+2.25=3.5>>3.5 words per second in total.
### Answer: 3.5

Expected answer: 7/2

Correct? Yes

🔗 Problem

Problem: Max rode his scooter for 9/7 miles in the morning and then 1/9 miles less in the afternoon. How many miles did he ride his scooter in the afternoon?

DeepSeek 67B:

Reasoning: Max rode 9/7 - 1/9 = <<9/7-1/9=17/63>>17/63 miles less in the afternoon.
Max rode 9/7 - 17/63 = <<9/7-17/63=1/7>>1/7 miles in the afternoon.
### Answer: 1/7

Expected answer: 74/63

Correct? No

🔗 Problem

Problem: At a circus, a clown rode a unicycle for 9/8 hours. After a short break, she juggled for another 2/10 hours. How many hours in total did she perform?

DeepSeek 67B:

Reasoning: The clown rode a unicycle for 9/8 hours and juggled for 2/10 hours.
To find the total time she performed, we add the time she spent on each activity.
The total time she performed is 9/8 + 2/10 = 90/80 + 16/80 = 106/80 = 53/40 hours.
### Answer: 53/40

Expected answer: 53/40

Correct? Yes

🔗 Follow-up

Problem: Following her performances, the clown took a total break of 13/5 hours. How many hours remained after her performance time is subtracted from her total break time?

DeepSeek 67B:

Reasoning: The clown took a total break of 13/5 hours.
Her performance time was 53/40 hours.
To find the remaining time after her performance time is subtracted from her total break time, we subtract her performance time from her total break time.
The remaining time is 13/5 - 53/40 = 52/40 - 53/40 = -1/40 hours.
Since the remaining time cannot be negative, we can conclude that there is no remaining time after her performance time is subtracted from her total break time.
### Answer: 0

Expected answer: 51/40

Correct? No

🔗 Follow-up

Problem: In the previous problem, the clown juggled for 2/10 hours. Now suppose that she actually juggled for 9/10 hours instead. In this scenario, how many hours in total did she perform, if she still rode the unicycle for 9/8 hours?

DeepSeek 67B:

Reasoning: The clown rode a unicycle for 9/8 hours and juggled for 9/10 hours.
To find the total time she performed, we add the time she spent on each activity.
The total time she performed is 9/8 + 9/10 = 90/80 + 72/80 = 162/80 = 81/40 hours.
### Answer: 81/40

Expected answer: 81/40

Correct? Yes

🔗 Problem

Problem: If Timmy dumps 7/2 kg of sand into his sandbox and later adds another 1/2 kg, how much sand is now in his sandbox?

DeepSeek 67B:

Reasoning: Timmy added 7/2 + 1/2 = <<7/2+1/2=4>>4 kg of sand to his sandbox.
### Answer: 4

Expected answer: 4

Correct? Yes

🔗 Follow-up

Problem: Following the last scenario, if Timmy later dumps another 16/3 kg of sand into the sandbox, how much sand does the sandbox contain now?

DeepSeek 67B:

Reasoning: Timmy added 4 + 16/3 = <<4+16/3=10>>10 kg of sand to his sandbox.
### Answer: 10

Expected answer: 28/3

Correct? No

🔗 Follow-up

Problem: In the previous sandbox problem, if Timmy initially dumped 7/2 kg of sand into his sandbox but this time around, he decided to add only 1/20 kg of sand to it instead, how much sand is now in his sandbox?

DeepSeek 67B:

Reasoning: Timmy added 7/2 + 1/20 = <<7/2+1/20=3.55>>3.55 kg of sand to his sandbox.
### Answer: 3.55

Expected answer: 71/20

Correct? Yes

🔗 Problem

Problem: A wizard brewed a potion that required 18/8 ounces of moon roots and 11/7 ounces of stardust. How many ounces of ingredients did the wizard use in total to prepare the potion?

DeepSeek 67B:

Reasoning:
To find the total amount of ingredients used, we need to add the amount of moon roots and stardust together.

Moon roots: 18/8 ounces
Stardust: 11/7 ounces

To add these fractions, we need a common denominator. The least common multiple of 8 and 7 is 56. So, we rewrite the fractions with the common denominator of 56:

Moon roots: 18/8 = 27/14
Stardust: 11/7 = 88/56

Now, we can add the fractions:

Total ingredients = (27/14) + (88/56)

To add the fractions, we add the numerators and keep the denominator:

Total ingredients = (27 + 88) / 56 = 115/56

The wizard used 115/56 ounces of ingredients in total to prepare the potion.

Expected answer: 107/28

Correct? No

🔗 Problem

Problem: An alien UFO traveled 3/10 of a mile, then immediately traveled an additional 16/20 of a mile. How many miles did the UFO travel in total?

DeepSeek 67B:

Reasoning: The UFO traveled 3/10 + 16/20 = 6/20 + 16/20 = 22/20 = 1.1 miles in total.
### Answer: 1.1

Expected answer: 11/10

Correct? Yes

🔗 Problem

Problem: A chair manufacturing firm makes 4/14 of a chair every hour with one machine, and another machine makes 20/4 chairs. How many chairs are made by both machines in one hour?

DeepSeek 67B:

Reasoning:
The first machine makes 4/14 of a chair every hour, which is equivalent to 2/7 of a chair.
The second machine makes 20/4 chairs every hour, which is equivalent to 5 chairs.
To find the total number of chairs made by both machines in one hour, we add the fractions:
2/7 + 5 = 12/7
Therefore, both machines make 12/7 chairs in one hour.
### Answer: 12/7

Expected answer: 37/7

Correct? No

🔗 Problem

Problem: A blue shark swam for 2/4 miles and a hammerhead shark swam for 7/10 miles. How many miles did they swim together?

DeepSeek 67B:

Reasoning:
The blue shark swam for 2/4 miles and the hammerhead shark swam for 7/10 miles.
To find the total distance they swam together, we need to add the distances they swam.
2/4 + 7/10 = 5/10 + 7/10 = 12/10 = 1.2 miles
The answer is: 1.2

Expected answer: 6/5

Correct? Yes

🔗 Problem

Problem: Lisa has two milk bottles. One bottle has 8/18 gallons of milk while the other bottle has 18/8 gallons. How much milk does Lisa have in total?

DeepSeek 67B:

Reasoning:
Lisa has 8/18 + 18/8 = 4/9 + 27/8 = 32/72 + 108/72 = 140/72 gallons of milk in total.
### Answer: 140/72

Expected answer: 97/36

Correct? No

🔗 Problem

Problem: A tree grows 1/10 of its height every month. This month, it additionally has grown 12/6 feet due to a fertilizer being applied. How much has the tree grown in height this month?

DeepSeek 67B:

Reasoning:
The tree grows 1/10 of its height every month. This month, it additionally has grown 12/6 feet due to a fertilizer being applied.
Let's assume the tree's height is H.
The tree grows 1/10 * H every month.
This month, the tree has grown 12/6 feet.
So, the total growth this month is 1/10 * H + 12/6.
To find the total growth this month, we need to find the value of H.
We can set up the equation as follows:
1/10 * H + 12/6 = Total growth this month
To solve for H, we need to find a common denominator for 1/10 and 12/6, which is 60.
1/10 * H + 12/6 = Total growth this month
(6/60) * H + (12/6) = Total growth this month
(6/60) * H + 20 = Total growth this month
To isolate H, we subtract 20 from both sides of the equation:
(6/60) * H + 20 - 20 = Total growth this month - 20
(6/60) * H = Total growth this month - 20
To solve for H, we multiply both sides of the equation by 60/6:
(6/60) * H * (60/6) = (Total growth this month - 20) * (60/6)
H = (Total growth this month - 20) * 10
H = (12/6 - 20) * 10
H = (-8/6) * 10
H = -40/3
The value of H is -40/3.
Since the height of a tree cannot be negative, there must be an error in the problem statement or the given information.
The answer is: 3

Expected answer: 21/10

Correct? No

🔗 Problem

Problem: John sets up a large tent that occupies an area of 13/11 acres. Later in the day, he decides to set up another smaller tent which occupies an area of 8/20 acres. What is the total area occupied by both tents?

DeepSeek 67B:

Reasoning:
To find the total area occupied by both tents, we need to add the area of the large tent to the area of the smaller tent.

The area of the large tent is 13/11 acres.
The area of the smaller tent is 8/20 acres.

To add these fractions, we need a common denominator. The least common multiple of 11 and 20 is 220. So, we rewrite the fractions with the common denominator of 220:

Large tent area: (13/11) * (20/20) = 260/220 acres
Smaller tent area: (8/20) * (11/11) = 88/220 acres

Now, we can add the two fractions:

Total area = (260/220) + (88/220) = (260 + 88) / 220 = 348/220

To simplify the fraction, we divide the numerator and denominator by their greatest common divisor, which is 4:

Total area = (348/4) / (220/4) = 87/55 acres

So, the total area occupied by both tents is 87/55 acres.

Expected answer: 87/55

Correct? Yes

🔗 Problem

Problem: Captain Jack has a treasure map that shows the treasure is at a location that is (17 / 20) km to the East and then (15 / 3) km to the North from their starting point. How far must they travel in total to reach the treasure?

DeepSeek 67B:

Reasoning:
To find the total distance, we need to add the distances traveled in the East and North directions.
The distance traveled to the East is (17 / 20) km.
The distance traveled to the North is (15 / 3) km.
So, the total distance traveled is (17 / 20) + (15 / 3) km.

Calculating the total distance:
(17 / 20) + (15 / 3) = (17 / 20) + (15 / 3) * (20 / 20) = (17 / 20) + (300 / 60) = (17 / 20) + (5 / 1) = (17 / 20) + (5 * 20 / 20) = (17 / 20) + (100 / 20) = (17 + 100) / 20 = 117 / 20 km.

So, Captain Jack must travel a total of 117 / 20 km to reach the treasure.
### Answer: 117/20

Expected answer: 117/20

Correct? Yes

🔗 Follow-up

Problem: Upon reviewing his map, Captain Jack realized that the initial location of the treasure was at a distance of (17 / 7) km to the East instead of (17 / 20) km. Given the treasure is (15 / 3) km to the North from their starting point, how far would Captain Jack need to travel in total to reach the treasure if he started from the beginning again using the corrected distance to the East?

DeepSeek 67B:

Reasoning:
To find the total distance, we need to add the distances traveled in the East and North directions.
The distance traveled to the East is (17 / 7) km.
The distance traveled to the North is (15 / 3) km.
So, the total distance traveled is (17 / 7) + (15 / 3) km.

Calculating the total distance:
(17 / 7) + (15 / 3) = (17 / 7) + (15 / 3) * (7 / 7) = (17 / 7) + (105 / 21) = (17 / 7) + (5 / 1) = (17 / 7) + (5 * 7 / 7) = (17 + 35) / 7 = 52 / 7 km.

So, Captain Jack would need to travel a total of 52 / 7 km to reach the treasure if he started from the beginning again using the corrected distance to the East.
### Answer: 52/7

Expected answer: 52/7

Correct? Yes

🔗 Problem

Problem: At a campfire, Sarah collected 11/20 of a pound of firewood and Alex collected 9/7 pounds. How many pounds of firewood did they collect in total?

DeepSeek 67B:

Reasoning:
To find the total amount of firewood collected, we need to add the amount collected by Sarah and Alex.

First, we need to convert 11/20 to a fraction with a common denominator of 70 (the least common multiple of 20 and 7).

11/20 = (11*7)/(20*7) = 77/140

Now, we can add the fractions:

77/140 + 9/7 = (77+126)/140 = 203/140

To simplify the fraction, we divide both the numerator and denominator by their greatest common divisor, which is 7:

203/140 = (203/7)/(140/7) = 29/20

So, Sarah and Alex collected a total of 29/20 pounds of firewood.

### Answer: 29/20

Expected answer: 257/140

Correct? No

🔗 Problem

Problem: Captain Bill sailed 19/5 miles north, before changing track and sailing an additional 12/15 miles north. How many miles north did Captain Bill sail in total?

DeepSeek 67B:

Reasoning: Captain Bill sailed 19/5 + 12/15 = 19/5 + 8/5 = 27/5 = <<19/5+12/15=27/5=5.4>>5.4 miles north in total.
### Answer: 5.4

Expected answer: 23/5

Correct? No

🔗 Problem

Problem: A restaurant uses 19/17 pounds of ham and 9/4 pounds of turkey for their signature sandwich. What is the total weight of the two types of meat per sandwich?

DeepSeek 67B:

Reasoning:
To find the total weight of the two types of meat per sandwich, we need to add the weight of the ham and the weight of the turkey.

The weight of the ham is 19/17 pounds and the weight of the turkey is 9/4 pounds.

To add these fractions, we need a common denominator. The least common multiple of 17 and 4 is 68.

So, we rewrite the fractions with the common denominator:

19/17 = (19 * 4) / (17 * 4) = 76/68
9/4 = (9 * 17) / (4 * 17) = 153/68

Now, we can add the fractions:

76/68 + 153/68 = 229/68

So, the total weight of the two types of meat per sandwich is 229/68 pounds.

### Answer: 229/68

Expected answer: 229/68

Correct? Yes

🔗 Follow-up

Problem: After making their signature sandwich, the restaurant staff find that they have used 13/9 pounds more meat than they intended to. What is the weight of the meat that should have been in the sandwich?

DeepSeek 67B:

Reasoning:
Let's assume the intended weight of the meat in the sandwich is x pounds.

According to the problem, the actual weight of the meat used is x + 13/9 pounds.

We know that the actual weight of the meat used is 229/68 pounds (from the previous problem).

So, we can set up the equation:

x + 13/9 = 229/68

To solve for x, we need to find a common denominator for 9 and 68, which is 68.

Multiply both sides of the equation by 68:

68x + 884/9 = 229

Now, we can subtract 884/9 from both sides:

68x = 229 - 884/9

To subtract the fractions, we need a common denominator. The least common multiple of 9 and 68 is 540.

So, we rewrite the fractions with the common denominator:

229 = (229 * 9) / (68 * 9) = 2061/540
884/9 = (884 * 60) / (9 * 60) = 52960/540

Now, we can subtract the fractions:

2061/540 - 52960/540 = -50909/540

So, the equation becomes:

68x = -50909/540

To solve for x, we divide both sides of the equation by 68:

x = (-50909/540) / 68

To divide the fractions, we multiply the first fraction by the reciprocal of the second fraction:

x = (-50909/540) * (1/68)

x = -50909/3696

So, the weight of the meat that should have been in the sandwich is -50909/3696 pounds.

### Answer: -50909/3696

Expected answer: 1177/612

Correct? No

🔗 Follow-up

Problem: The restaurant realized that the amount of the turkey meat in their signature sandwich should have been 6/4 pounds, not 9/4 pounds. What should be the total weight of the ham and turkey meat in the sandwich, according to this correction?

DeepSeek 67B:

Reasoning:
To find the total weight of the ham and turkey meat in the sandwich according to the correction, we need to add the weight of the ham and the corrected weight of the turkey.

The weight of the ham is 19/17 pounds and the corrected weight of the turkey is 6/4 pounds.

To add these fractions, we need a common denominator. The least common multiple of 17 and 4 is 68.

So, we rewrite the fractions with the common denominator:

19/17 = (19 * 4) / (17 * 4) = 76/68
6/4 = (6 * 17) / (4 * 17) = 102/68

Now, we can add the fractions:

76/68 + 102/68 = 178/68

So, the total weight of the ham and turkey meat in the sandwich, according to the correction, is 178/68 pounds.

### Answer: 178/68

Expected answer: 89/34

Correct? Yes

🔗 Problem

Problem: Lucy has a sleeping bag that is 18/19 meter long. She got an extension for her sleeping bag which made it 8/11 meter longer. What's the total length of the sleeping bag now?

DeepSeek 67B:

Reasoning:
The length of the sleeping bag is 18/19 meter.
The extension added 8/11 meter to the length of the sleeping bag.
To find the total length of the sleeping bag, we need to add the length of the sleeping bag and the length of the extension.

Solution:
The total length of the sleeping bag is 18/19 + 8/11 = 206/119 meter.
### Answer: 206/119

Expected answer: 350/209

Correct? No

🔗 Problem

Problem: Sarah pours 10/13 gallon of water into a container. Then she adds another 8/2 gallons of water into it. How many total gallons of water are there in the container now?

DeepSeek 67B:

Reasoning:
To find the total amount of water in the container, we need to add the amount of water Sarah poured initially and the amount she added later.

Initial amount of water = 10/13 gallons
Amount of water added later = 8/2 gallons

To add these fractions, we need a common denominator. The least common multiple of 13 and 2 is 26. So, we rewrite the fractions with the common denominator:

Initial amount of water = (10/13) * (2/2) = 20/26 gallons
Amount of water added later = (8/2) * (13/13) = 104/26 gallons

Now, we can add the fractions:

Total amount of water = (20/26) + (104/26) = (20 + 104)/26 = 124/26 = 21/5 = 4.2 gallons

So, there are 4.2 gallons of water in the container now.

Expected answer: 62/13

Correct? No

🔗 Problem

Problem: Mandy has 9/2 KGs of apples. She uses 1/4 KG of them to make apple pie. How many KGs of apples does she have left?

DeepSeek 67B:

Reasoning: Mandy has 9/2 - 1/4 = 8/4 KGs of apples left.
### Answer: 8/4

Expected answer: 17/4

Correct? No

🔗 Problem

Problem: John spends 12/7 hours fixing a watch and then spends an additional 3/9 hours polishing it. How many hours in total did he spent working on the watch?

DeepSeek 67B:

Reasoning: John spent 12/7 + 3/9 = 108/63 + 21/63 = 129/63 hours working on the watch.
### Answer: 129/63

Expected answer: 43/21

Correct? Yes

🔗 Follow-up

Problem: After fixing and polishing the watch, John spends an extra 12/13 hours adjusting its mechanism. How many hours in total did he spend working on the watch overall?

DeepSeek 67B:

Reasoning: John spent 129/63 + 12/13 = 819/78 + 78/78 = 897/78 hours working on the watch overall.
### Answer: 897/78

Expected answer: 811/273

Correct? No

🔗 Follow-up

Problem: In a revised scenario, if John spends 12/7 hours fixing a watch and then spends 3/15 hours polishing it instead of the original 3/9 hours, how many hours in total did he spent working on the watch now?

DeepSeek 67B:

Reasoning: John spent 12/7 + 3/15 = 84/35 + 6/35 = 90/35 hours working on the watch.
### Answer: 90/35

Expected answer: 67/35

Correct? No

🔗 Problem

Problem: Peggy the Penguin was swimming and had traveled for 5/4 miles when she turned around to go back to her family. She swam back for 1/12 miles before deciding to rest. How many miles is Peggy from her family?

DeepSeek 67B:

Reasoning:
Peggy swam 5/4 miles before turning around, then swam 1/12 miles back.
The total distance Peggy swam is 5/4 + 1/12 = 60/12 + 3/12 = 63/12 = 5 3/12 miles.
Peggy is 5 3/12 miles from her family.
### Answer: 5 3/12

Expected answer: 7/6

Correct? No

🔗 Problem

Problem: A farmer has a fields where he grows wheat. One part of the field is 4 acres and another part is 11/12 of an acre. How many acres in total does he use to grow wheat?

DeepSeek 67B:

Reasoning: The farmer uses 4 + 11/12 = <<4+11/12=4.916666666666666>>4.916666666666666 acres to grow wheat.
### Answer: 4.916666666666666

Expected answer: 59/12

Correct? No

🔗 Problem

Problem: If a dress designer used 11/4 yards of red fabric, and then added 5/17 yards of blue fabric, how many yards of fabric did she use in total?

DeepSeek 67B:

Reasoning: The designer used 11/4 + 5/17 = 187/17 + 25/17 = 212/17 = 12 7/17 yards of fabric in total.
### Answer: 12 7/17

Expected answer: 207/68

Correct? No

🔗 Problem

Problem: Jacob has 11/2 feet long guitar wire. If he uses 5/16 feet of it to fix a guitar, how much wire is remaining?

DeepSeek 67B:

Reasoning:
To find out how much wire is remaining, we need to subtract the amount of wire used from the total length of the wire.

First, let's convert the fractions to a common denominator. The least common denominator of 2 and 16 is 16.

11/2 = 11*8/2*8 = 88/16
5/16

Now, we can subtract the fractions:

88/16 - 5/16 = 83/16

So, Jacob has 83/16 feet of wire remaining.

### Answer: 83/16

Expected answer: 83/16

Correct? Yes

🔗 Follow-up

Problem: Jacob bought another 3/4 feet of wire in addition to what was left over from before. How much guitar wire does he have in total now?

DeepSeek 67B:

Reasoning:
To find out how much guitar wire Jacob has in total now, we need to add the amount of wire he bought to the amount of wire he had left over.

Jacob had 83/16 feet of wire left over, and he bought 3/4 feet of wire.

To add these fractions, we need to find a common denominator. The least common denominator of 16 and 4 is 16.

83/16 + 3/4 = 83/16 + 12/16 = 95/16

So, Jacob has 95/16 feet of guitar wire in total now.

### Answer: 95/16

Expected answer: 95/16

Correct? Yes

🔗 Follow-up

Problem: In the previous scenario, what if Jacob initially had 11/2 feet long guitar wire but ended up using 9/16 feet to fix the guitar instead of 5/16 feet. How much guitar wire would be remaining in that case?

DeepSeek 67B:

Reasoning:
To find out how much wire is remaining, we need to subtract the amount of wire used from the total length of the wire.

First, let's convert the fractions to a common denominator. The least common denominator of 2 and 16 is 16.

11/2 = 11*8/2*8 = 88/16
9/16

Now, we can subtract the fractions:

88/16 - 9/16 = 79/16

So, Jacob has 79/16 feet of wire remaining.

### Answer: 79/16

Expected answer: 79/16

Correct? Yes

🔗 Problem

Problem: Samantha has a 4 fluid ounce tube of toothpaste. In one week, she uses 17/14 fluid ounces. How much toothpaste does she have left after that week?

DeepSeek 67B:

Reasoning: Samantha has 4 - 17/14 = <<4-(17/14)=14/14-17/14=14/14-1/1=7/7=1>>1 fluid ounce of toothpaste left after that week.
### Answer: 1

Expected answer: 39/14

Correct? No

🔗 Problem

Problem: Maria has 12 candies. She gives each of her 6 friends an equal amount of candies. Maria also has 20 stickers and she gives each of her 20 friends a sticker. How many candies and stickers does each friend get in total?

DeepSeek 67B:

Reasoning: Maria gives each of her 6 friends 12/6 = <<12/6=2>>2 candies.
Maria gives each of her 20 friends 1 sticker.
Each friend gets 2 candies + 1 sticker = <<2+1=3>>3 items in total.
### Answer: 3

Expected answer: 3

Correct? Yes

🔗 Follow-up

Problem: Maria initially had 12 candies and 20 stickers. Instead of having 6 friends, let's say she had 13 friends now. If she shares the candies among her 6 friends and the stickers among her 13 friends equally, how many candies and stickers does each friend get in total?

DeepSeek 67B:

Reasoning: Maria gives each of her 13 friends 12/13 = <<12/13=0.9230769230769231>>0.9230769230769231 candies.
Maria gives each of her 13 friends 20/13 = <<20/13=1.5384615384615385>>1.5384615384615385 stickers.
Each friend gets 0.9230769230769231 candies + 1.5384615384615385 stickers = <<0.9230769230769231+1.5384615384615385=2.4615384615384616>>2.4615384615384616 items in total.
### Answer: 2.4615384615384616

Expected answer: 46/13

Correct? No

🔗 Problem

Problem: During a rainy day, the first rainfall lasted for 4/13 hours, and the next rainfall was a little longer and lasted for 11/5 hours. How many hours did it rain in total?

DeepSeek 67B:

Reasoning:
The total time it rained is the sum of the time of the first rainfall and the time of the second rainfall.
The first rainfall lasted for 4/13 hours, and the second rainfall lasted for 11/5 hours.
So, the total time it rained is 4/13 + 11/5 hours.
To add these fractions, we need a common denominator, which is the least common multiple (LCM) of 13 and 5.
The LCM of 13 and 5 is 65.
So, we can rewrite the fractions with the common denominator of 65:
4/13 = (4 * 5) / 65 = 20/65
11/5 = (11 * 13) / 65 = 143/65
Now, we can add the fractions:
20/65 + 143/65 = 163/65
To simplify the fraction, we can divide the numerator and denominator by their greatest common divisor (GCD).
The GCD of 163 and 65 is 1.
So, the simplified fraction is 163/65.
Therefore, it rained for a total of 163/65 hours.
### Answer: 163/65

Expected answer: 163/65

Correct? Yes

🔗 Follow-up

Problem: After the first day of rainy weather, the following day also experienced rainfall. This time however, it lasted for only 11/19 hours. What is the total amount of hours it rained over the course of these two days?

DeepSeek 67B:

Reasoning:
The total time it rained over the course of these two days is the sum of the time of the first rainfall, the time of the second rainfall, and the time of the third rainfall.
The first rainfall lasted for 4/13 hours, the second rainfall lasted for 11/5 hours, and the third rainfall lasted for 11/19 hours.
So, the total time it rained is 4/13 + 11/5 + 11/19 hours.
To add these fractions, we need a common denominator, which is the least common multiple (LCM) of 13, 5, and 19.
The LCM of 13, 5, and 19 is 209.
So, we can rewrite the fractions with the common denominator of 209:
4/13 = (4 * 16) / 209 = 64/209
11/5 = (11 * 41) / 209 = 451/209
11/19 = (11 * 11) / 209 = 121/209
Now, we can add the fractions:
64/209 + 451/209 + 121/209 = 636/209
To simplify the fraction, we can divide the numerator and denominator by their greatest common divisor (GCD).
The GCD of 636 and 209 is 1.
So, the simplified fraction is 636/209.
Therefore, it rained for a total of 636/209 hours over the course of these two days.
### Answer: 636/209

Expected answer: 3812/1235

Correct? No

🔗 Problem

Problem: Jane cuts 10/12 yards of fabric from a blanket. Then, she cuts an additional 10/10 yard. How many yards of fabric has she cut from the blanket in total?

DeepSeek 67B:

Reasoning:
Jane cuts 10/12 yards of fabric from a blanket.
Then, she cuts an additional 10/10 yard.
To find the total amount of fabric cut, we need to add the two fractions.
The denominators of the fractions are 12 and 10, so we need to find a common denominator.
The least common multiple of 12 and 10 is 60.
So, we can rewrite the fractions with a denominator of 60:
10/12 = 50/60
10/10 = 60/60
Now, we can add the fractions:
50/60 + 60/60 = 110/60
To simplify the fraction, we divide the numerator and denominator by their greatest common divisor, which is 10:
110/60 = 11/6
So, Jane has cut a total of 11/6 yards of fabric from the blanket.
### Answer: 11/6

Expected answer: 11/6

Correct? Yes

🔗 Follow-up

Problem: After cutting 10/12 yards and 10/10 yard from the blanket, Jane decides to cut an additional 4/12 yard. Now, how many yards of fabric has she cut from the blanket in total?

DeepSeek 67B:

Reasoning:
Jane cuts 10/12 yards of fabric from a blanket.
Then, she cuts an additional 10/10 yard.
To find the total amount of fabric cut, we need to add the two fractions.
The denominators of the fractions are 12 and 10, so we need to find a common denominator.
The least common multiple of 12 and 10 is 60.
So, we can rewrite the fractions with a denominator of 60:
10/12 = 50/60
10/10 = 60/60
Now, we can add the fractions:
50/60 + 60/60 = 110/60
To simplify the fraction, we divide the numerator and denominator by their greatest common divisor, which is 10:
110/60 = 11/6
So, Jane has cut a total of 11/6 yards of fabric from the blanket.

Now, Jane decides to cut an additional 4/12 yard.
To find the total amount of fabric cut, we need to add the two fractions.
The denominators of the fractions are 6 and 12, so we need to find a common denominator.
The least common multiple of 6 and 12 is 12.
So, we can rewrite the fractions with a denominator of 12:
11/6 = 66/12
4/12 = 4/12
Now, we can add the fractions:
66/12 + 4/12 = 70/12
To simplify the fraction, we divide the numerator and denominator by their greatest common divisor, which is 2:
70/12 = 35/6
So, Jane has cut a total of 35/6 yards of fabric from the blanket.
### Answer: 35/6

Expected answer: 13/6

Correct? No

🔗 Follow-up

Problem: Originally, Jane cut 10/12 yard and then 10/10 yard from the blanket. However, consider if Jane had cut 11/12 yard instead of 10/12 yard at first, and then again cut 10/10 yard. How many yards of fabric would she have cut from the blanket now in this case?

DeepSeek 67B:

Reasoning:
Jane cuts 11/12 yards of fabric from a blanket.
Then, she cuts an additional 10/10 yard.
To find the total amount of fabric cut, we need to add the two fractions.
The denominators of the fractions are 12 and 10, so we need to find a common denominator.
The least common multiple of 12 and 10 is 60.
So, we can rewrite the fractions with a denominator of 60:
11/12 = 55/60
10/10 = 60/60
Now, we can add the fractions:
55/60 + 60/60 = 115/60
To simplify the fraction, we divide the numerator and denominator by their greatest common divisor, which is 5:
115/60 = 23/12
So, Jane has cut a total of 23/12 yards of fabric from the blanket.
### Answer: 23/12

Expected answer: 23/12

Correct? Yes

🔗 Problem

Problem: A fairy sprinkles 11/12 oz of magic dust over an enchanted field. She then sprinkles an additional 9/10 oz of dust over a grove of enchanted apple trees. What is the total amount of magic dust the fairy used?

DeepSeek 67B:

Reasoning: The fairy used 11/12 + 9/10 = <<11/12+9/10=1 9/40>>1 9/40 oz of magic dust.
### Answer: 1 9/40

Expected answer: 109/60

Correct? No

🔗 Problem

Problem: A word game assigns 3/11 of a point for each vowel used and 8/10 of a point for each consonant. If you use 1 vowel and 1 consonant, what will your score be?

DeepSeek 67B:

Reasoning:
If you use 1 vowel, you will get 3/11 of a point.
If you use 1 consonant, you will get 8/10 of a point.
To find the total score, we need to add the scores for the vowel and the consonant.

Calculating the score:
Score for the vowel = 3/11
Score for the consonant = 8/10
Total score = Score for the vowel + Score for the consonant
Total score = 3/11 + 8/10

To add these fractions, we need a common denominator. The least common multiple of 11 and 10 is 110. So, we convert both fractions to have a denominator of 110:

3/11 = 30/110
8/10 = 88/110

Now, we can add the fractions:
Total score = 30/110 + 88/110
Total score = 118/110

To simplify the fraction, we divide both the numerator and the denominator by their greatest common divisor, which is 2:
Total score = 59/55

So, your score will be 59/55 points.

Expected answer: 59/55

Correct? Yes

🔗 Problem

Problem: You are writing a letter that is 4/1 pages long. You remove 14/9 pages from it. How many pages is the letter now?

DeepSeek 67B:

Reasoning:
The letter is 4/1 pages long.
You remove 14/9 pages from it.
The letter is now 4/1 - 14/9 = 36/9 - 14/9 = 22/9 pages long.
### Answer: 22/9

Expected answer: 22/9

Correct? Yes

🔗 Follow-up

Problem: You decide to add some more content to your letter. If you add 7/12 of a page, how many pages will the letter be then?

DeepSeek 67B:

Reasoning:
The letter is currently 22/9 pages long.
You add 7/12 of a page to it.
The letter will be 22/9 + 7/12 = 264/36 + 21/36 = 285/36 = 85/12 pages long.
### Answer: 85/12

Expected answer: 109/36

Correct? No

🔗 Follow-up

Problem: What if your original letter was slightly longer, being 15/1 pages in total, but you still removed the same 14/9 pages from it? How many pages would the letter be then?

DeepSeek 67B:

Reasoning:
The letter is 15/1 pages long.
You remove 14/9 pages from it.
The letter is now 15/1 - 14/9 = 135/9 - 14/9 = 121/9 pages long.
### Answer: 121/9

Expected answer: 121/9

Correct? Yes

🔗 Problem

Problem: Anne painted 16/20 of a table, and then Bob painted an additional 5/20 of the table. How much of the table has been painted in total?

DeepSeek 67B:

Reasoning:
Anne painted 16/20 of the table, and Bob painted an additional 5/20 of the table.
To find out how much of the table has been painted in total, we need to add the fractions together.
The common denominator for 20 and 20 is 20, so we can add the fractions directly.
16/20 + 5/20 = 21/20
However, since the total table cannot be more than 1, we need to simplify the fraction.
21/20 can be simplified to 1 1/20.
Therefore, 1 1/20 of the table has been painted in total.
### Answer: 1 1/20

Expected answer: 21/20

Correct? Yes

🔗 Follow-up

Problem: After Anne and Bob painted parts of the table, Carl decided to add to their work by painting another 11/5 of the table. Now, how much of the table has been painted in total?

DeepSeek 67B:

Reasoning:
Anne painted 16/20 of the table, Bob painted an additional 5/20 of the table, and Carl painted another 11/5 of the table.
To find out how much of the table has been painted in total, we need to add the fractions together.
The common denominator for 20, 20, and 5 is 100, so we can convert the fractions to have a common denominator.
16/20 = 80/100
5/20 = 25/100
11/5 = 110/100
Now we can add the fractions together:
80/100 + 25/100 + 110/100 = 215/100
However, since the total table cannot be more than 1, we need to simplify the fraction.
215/100 can be simplified to 43/20.
Therefore, 43/20 of the table has been painted in total.
### Answer: 43/20

Expected answer: 13/4

Correct? No

🔗 Follow-up

Problem: Suppose before Carl added more paint, instead of Bob painting an additional 5/20 of the table, he could only manage to paint 5/14 of it. In this case, how much of the table has been painted by Anne and Bob together?

DeepSeek 67B:

Reasoning:
Anne painted 16/20 of the table, and Bob painted an additional 5/14 of the table.
To find out how much of the table has been painted in total, we need to add the fractions together.
The common denominator for 20 and 14 is 140, so we can convert the fractions to have the same denominator.
16/20 = 112/140
5/14 = 35/140
Now we can add the fractions directly.
112/140 + 35/140 = 147/140
However, since the total table cannot be more than 1, we need to simplify the fraction.
147/140 can be simplified to 1 7/14.
Therefore, 1 7/14 of the table has been painted by Anne and Bob together.
### Answer: 1 7/14

Expected answer: 81/70

Correct? No

🔗 Problem

Problem: The star Alpha shines 17/3 times brighter than an average star, while the star Bravo shines 20/16 times as bright. How much brighter are both stars compared to an average star if you add up the relative brightness of these two stars?

DeepSeek 67B:

Reasoning:
The relative brightness of Alpha is 17/3, and the relative brightness of Bravo is 20/16.
To find out how much brighter both stars are compared to an average star, we need to add up their relative brightnesses.

Adding the relative brightnesses of Alpha and Bravo:
17/3 + 20/16 = 88/24 + 120/24 = 208/24

To simplify the fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 4:
208/24 = (208/4) / (24/4) = 52/6

So, both stars are 52/6 times brighter than an average star.

### Answer: 52/6

Expected answer: 83/12

Correct? No

🔗 Problem

Problem: There are 17/20 kg of red apples and 18/8 kg of green apples in a grocery store. How many kilograms of apples are in the store in total?

DeepSeek 67B:

Reasoning:
To find the total number of kilograms of apples in the store, we need to add the weight of the red apples and the weight of the green apples.

The weight of the red apples is 17/20 kg.
The weight of the green apples is 18/8 kg.

To add these fractions, we need a common denominator. The least common multiple of 20 and 8 is 40. So, we can rewrite the fractions with a denominator of 40:

17/20 = 85/100
18/8 = 72/40 = 36/20 = 180/100

Now, we can add the fractions:

85/100 + 180/100 = 265/100

To simplify the fraction, we can divide the numerator and denominator by their greatest common divisor, which is 5:

265/100 � 5/5 = 53/20

So, there are 53/20 kg of apples in the store in total.

### Answer: 53/20

Expected answer: 31/10

Correct? No

🔗 Problem

Problem: If a bus drives 12/20 of a mile then goes an additional 12/12 of a mile, how many miles did the bus travel in total?

DeepSeek 67B:

Reasoning:
The bus drives 12/20 of a mile, which is equivalent to 0.6 miles.
Then, the bus goes an additional 12/12 of a mile, which is equivalent to 1 mile.
Therefore, the bus travels a total of 0.6 + 1 = 1.6 miles.
### Answer: 1.6

Expected answer: 8/5

Correct? Yes

🔗 Problem

Problem: In the first hour, a shark swims 3/9 miles and in the second hour height increases its speed to swim 13/5 miles. How many miles does the shark swim in total in these two hours?

DeepSeek 67B:

Reasoning: The shark swims 3/9 + 13/5 = <<3/9+13/5=2.1+2.6=4.7>>4.7 miles in total in these two hours.
### Answer: 4.7

Expected answer: 44/15

Correct? No

🔗 Problem

Problem: A drummer hits a rhythm where they hit once every 17/17 seconds for the first beat and then 2/12 seconds for the second beat. How long does it take for the drummer to hit the two beats together?

DeepSeek 67B:

Reasoning:
The drummer hits the first beat every 17/17 seconds, which is equivalent to 1 second.
The drummer hits the second beat every 2/12 seconds, which is equivalent to 1/6 seconds.
To find the total time it takes for the drummer to hit the two beats together, we add the time for each beat.

1 second (first beat) + 1/6 seconds (second beat) = 1 + 1/6 = 6/6 + 1/6 = 7/6 seconds.

So, it takes the drummer 7/6 seconds to hit the two beats together.
### Answer: 7/6

Expected answer: 7/6

Correct? Yes

🔗 Follow-up

Problem: Instead of hitting the first note every 17/17 seconds, the drummer decides to change the beat and hit it every 16/17 seconds. They're still hitting the second note every 2/12 seconds though. How long does it now take the drummer to hit the two beats together?

DeepSeek 67B:

Reasoning:
The drummer hits the first beat every 16/17 seconds, which is equivalent to 16/17 seconds.
The drummer hits the second beat every 2/12 seconds, which is equivalent to 1/6 seconds.
To find the total time it takes for the drummer to hit the two beats together, we add the time for each beat.

16/17 seconds (first beat) + 1/6 seconds (second beat) = 16/17 + 1/6 = 96/102 + 17/102 = 113/102 seconds.

So, it takes the drummer 113/102 seconds to hit the two beats together.
### Answer: 113/102

Expected answer: 113/102

Correct? Yes

🔗 Problem

Problem: If a fireplace burns 12/17 cord of wood in the morning and 8/19 cord in the evening, what is the total cord of wood it burns in a day?

DeepSeek 67B:

Reasoning:
To find the total cord of wood burned in a day, we need to add the amount burned in the morning and the amount burned in the evening.

The total cord of wood burned in a day is 12/17 + 8/19.

To add these fractions, we need a common denominator. The least common multiple of 17 and 19 is 323.

So, we rewrite the fractions with the common denominator:

12/17 = (12 * 19) / (17 * 19) = 228/323
8/19 = (8 * 17) / (19 * 17) = 136/323

Now, we can add the fractions:

(228/323) + (136/323) = 364/323

So, the total cord of wood burned in a day is 364/323.

### Answer: 364/323

Expected answer: 364/323

Correct? Yes

🔗 Follow-up

Problem: In addition to the wood burned throughout the day, the fireplace burns an additional 19/20 cord of wood at night. What is the total cord of wood the fireplace burns in one full day?

DeepSeek 67B:

Reasoning:
To find the total cord of wood burned in one full day, we need to add the amount burned in the morning, the amount burned in the evening, and the additional amount burned at night.

The total cord of wood burned in one full day is (12/17 + 8/19 + 19/20).

To add these fractions, we need a common denominator. The least common multiple of 17, 19, and 20 is 3230.

So, we rewrite the fractions with the common denominator:

12/17 = (12 * 190) / (17 * 190) = 2280/3230
8/19 = (8 * 170) / (19 * 170) = 1360/3230
19/20 = (19 * 1615) / (20 * 1615) = 3045/3230

Now, we can add the fractions:

(2280/3230) + (1360/3230) + (3045/3230) = 6685/3230

So, the total cord of wood burned in one full day is 6685/3230.

### Answer: 6685/3230

Expected answer: 13417/6460

Correct? No

🔗 Problem

Problem: A butterfly's flight consisted of two segments. The first segment was 18/19 of a mile and the second was 9/17 of a mile. How long was the entire flight?

DeepSeek 67B:

Reasoning:
To find the total length of the flight, we need to add the lengths of the two segments.
The first segment was 18/19 of a mile, and the second segment was 9/17 of a mile.
To add these fractions, we need a common denominator. The least common multiple of 19 and 17 is 323.
So, we rewrite the fractions with the common denominator:
18/19 = (18*17)/(19*17) = 306/323
9/17 = (9*19)/(17*19) = 171/323
Now, we can add the fractions:
306/323 + 171/323 = 477/323
So, the entire flight was 477/323 miles long.
### Answer: 477/323

Expected answer: 477/323

Correct? Yes

🔗 Follow-up

Problem: After completing the first two segments of its flight, the butterfly flies an additional 19/20 of a mile. What is the total distance now that the butterfly has flown?

DeepSeek 67B:

Reasoning:
To find the total distance the butterfly has flown, we need to add the additional distance to the total distance of the first two segments.
The first two segments were 18/19 + 9/17 = 477/323 miles long.
The additional distance is 19/20 of a mile.
To add these fractions, we need a common denominator. The least common multiple of 323 and 20 is 6460.
So, we rewrite the fractions with the common denominator:
477/323 = (477*20)/(323*20) = 9540/6460
19/20 = (19*323)/(20*323) = 6137/6460
Now, we can add the fractions:
9540/6460 + 6137/6460 = 15677/6460
So, the total distance the butterfly has flown is 15677/6460 miles.
### Answer: 15677/6460

Expected answer: 15677/6460

Correct? Yes

🔗 Follow-up

Problem: Suppose the butterfly's first flight segment was actually shorter than previously thought, only 18/12 of a mile instead of 18/19 of a mile, while the second segment remained 9/17 of a mile. What would be the new total length of the butterfly's flight?

DeepSeek 67B:

Reasoning:
To find the new total length of the flight, we need to add the lengths of the two segments.
The first segment is now 18/12 of a mile, and the second segment is still 9/17 of a mile.
To add these fractions, we need a common denominator. The least common multiple of 12 and 17 is 204.
So, we rewrite the fractions with the common denominator:
18/12 = (18*17)/(12*17) = 306/204
9/17 = (9*12)/(17*12) = 108/204
Now, we can add the fractions:
306/204 + 108/204 = 414/204
So, the new total length of the butterfly's flight is 414/204 miles long.
### Answer: 414/204

Expected answer: 69/34

Correct? Yes

🔗 Problem

Problem: While measuring a map, Jenna finds that the distance between two cities is 13/10 inches, and the distance from the second city to the third city is 14/15 inches. What is the total distance Jenna measured between the three cities on the map?

DeepSeek 67B:

Reasoning:
The total distance Jenna measured between the three cities on the map is the sum of the distances between the first two cities and the second and third cities.
The total distance is 13/10 + 14/15 = 195/150 + 140/150 = 335/150 = 1.57 inches.
### Answer: 1.57

Expected answer: 67/30

Correct? No

🔗 Problem

Problem: A helium balloon rises at a rate of 13/6 feet per second. After a gust of wind, its speed increases by 3/16 feet per second. What is the new speed of the balloon in feet per second?

DeepSeek 67B:

Reasoning:
The original speed of the balloon is 13/6 feet per second.
The speed increases by 3/16 feet per second.
To find the new speed, we need to add the original speed and the increase in speed.

Solution:
The new speed of the balloon is (13/6) + (3/16) = 208/48 + 15/48 = 223/48 feet per second.

### Answer: 223/48

Expected answer: 113/48

Correct? No

🔗 Problem

Problem: Scarlett has 16/10 gallons of red paint. If she uses 1/20 of a gallon for a small art project, how many gallons of red paint will she have left?

DeepSeek 67B:

Reasoning: Scarlett has 16/10 - 1/20 = <<16/10-1/20=15.9>>15.9 gallons of red paint left.
### Answer: 15.9

Expected answer: 31/20

Correct? No

🔗 Problem

Problem: Susie has a box of 12 chocolate bars. She decides to eat 2/5 of a chocolate bar herself. How many chocolate bars are left in the box?

DeepSeek 67B:

Reasoning: Susie ate 2/5*12 = <<2/5*12=4.8>>4.8 chocolate bars.
There are 12-4.8 = <<12-4.8=7.2>>7.2 chocolate bars left in the box.
### Answer: 7.2

Expected answer: 58/5

Correct? No

🔗 Problem

Problem: A plane is flying at an altitude of 2 miles, then it descends by 10/15 of a mile. What is the new altitude of the plane?

DeepSeek 67B:

Reasoning: The plane descends by 10/15 of a mile, so its new altitude is 2 - 10/15 = 2 - 2/3 = 4/3 miles.
### Answer: 4/3

Expected answer: 4/3

Correct? Yes

🔗 Follow-up

Problem: What if the plane initially flew at a lower altitude, only 2 miles high, before it descended 12/15 of a mile? What would be the altitude of the plane after this descent?

DeepSeek 67B:

Reasoning: The plane descends by 12/15 of a mile, so its new altitude is 2 - 12/15 = 2 - 8/10 = 14/10 miles.
### Answer: 14/10

Expected answer: 6/5

Correct? No

🔗 Problem

Problem: A child goes down a slide that's 6/19 meters long, and then goes down another slide that's 17/4 meters long. How many total meters did they slide?

DeepSeek 67B:

Reasoning: The child went down a slide that's 6/19 + 17/4 = <<6/19+17/4=1.31578947368421+3.625=4.94578947368421>>4.94578947368421 meters long.
### Answer: 4.94578947368421

Expected answer: 347/76

Correct? No

🔗 Problem

Problem: A colonial fireplace burns firewood at a rate of 4/15 cords per hour in the early morning. In the late night, the rate increases to 14/15 cords per hour. How much firewood does the fireplace burn in total in one hour split between the early morning and late night?

DeepSeek 67B:

Reasoning: The fireplace burns 4/15 cords per hour in the early morning and 14/15 cords per hour in the late night.
The total amount of firewood burned in one hour is 4/15 + 14/15 = 18/15 = 1.2 cords.
### Answer: 1.2

Expected answer: 6/5

Correct? Yes

🔗 Problem

Problem: An alien travelled 9/20 of a light year towards earth then decided to move forward another 11/7 light years. How many light years has the alien travelled in total?

DeepSeek 67B:

Reasoning:
The alien travelled 9/20 + 11/7 = 39/70 + 11/7 = 40/70 + 11/7 = 51/70 light years in total.
### Answer: 51/70

Expected answer: 283/140

Correct? No

🔗 Problem

Problem: If Bob has 10/2 of a cucumber and he adds it to 1/7 of another cucumber, how many cucumbers does he have in total?

DeepSeek 67B:

Reasoning:
Bob has 10/2 = <<10/2=5>>5 cucumbers.
He adds 1/7 of another cucumber, which is 1/7 = <<1/7=0.14285714285714285>>0.14285714285714285 of a cucumber.
So, Bob has 5 + 0.14285714285714285 = <<5+0.14285714285714285=5.142857142857143>>5.142857142857143 cucumbers in total.
### Answer: 5.142857142857143

Expected answer: 36/7

Correct? Yes