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Gemma 2B on 7.NS.A.3-decimal

Common Core Standard 7.NS.A.3-decimal

This standard covers the following:

Solve real-world and mathematical problems involving the four operations with rational numbers.

πŸ”— Problem

Problem: A teacher has a stack of papers that is 12.7 cm high. She adds another stack of papers that is 4.2 cm high to the existing pile. Afterwards, she distributes 2.144 cm worth of papers to her students. How tall is the stack of papers now?

Gemma 2B:

Reasoning: The total height of the stack of papers is 12.7 cm + 4.2 cm = <<12.7+4.2=16.9>>16.9 cm.
After distributing the papers, the stack of papers is 12.7 cm + 4.2 cm - 2.144 cm = <<12.7+4.2-2.144=16.9>>16.9 cm tall.

Expected answer: 14.7560000000000

Correct? No

πŸ”— Problem

Problem: A dragon flew a total distance of 24.02 km in a day. However, it had to backtrack 1.3 km due to a severe storm. How many kilometers did the dragon travel in the end?

Gemma 2B:

Reasoning: The dragon flew 24.02 km. However, it had to backtrack 1.3 km, so the total distance traveled was 24.02 - 1.3 = <<24.02-1.3=22.72>>22.72 km.

Expected answer: 22.7200000000000

Correct? Yes

πŸ”— Problem

Problem: An elephant weighs 12.1 tons in the morning and gains 15.68 tons throughout the day from eating. What is the elephant's total weight by the end of the day?

Gemma 2B:

Reasoning: The elephant weighs 12.1 + 15.68 = <<12.1+15.68=27.78>>27.78 tons by the end of the day.
### Answer: 27.78

Expected answer: 27.7800000000000

Correct? Yes

πŸ”— Follow-up

Problem: The elephant from the previous question then burns off 5.935 tons of weight. What is the elephant's weight now?

Gemma 2B:

Reasoning: The elephant weighs 27.78 - 5.935 = <<27.78-5.935=21.85>>21.85 tons by the end of the day.
### Answer: 21.85

Expected answer: 21.8450000000000

Correct? Yes

πŸ”— Problem

Problem: A certain breed of mouse can eat up to 29.573 grams of food a day. However, one day it only eats 4.62 grams less than what it usually eats. How much does it eat on that day?

Gemma 2B:

Reasoning: The mouse ate 29.573 - 4.62 = <<29.573-4.62=25.953>>25.953 grams of food on that day.
### Answer: 25.953

Expected answer: 24.9530000000000

Correct? No

πŸ”— Problem

Problem: In a zoo, there’s a baby giraffe that is 1.4 meters tall. If it grows another 5.7 meters, how tall will the giraffe be?

Gemma 2B:

Reasoning: The baby giraffe will be 1.4 + 5.7 = <<1.4+5.7=7.1>>7.1 meters tall after it grows 5.7 meters.
### Answer: 7.1

Expected answer: 7.10000000000000

Correct? Yes

πŸ”— Follow-up

Problem: In a zoo, there’s a baby giraffe that is 1.4 meters tall. If it grows another 5.7 meters, it will reach a certain height. Now, if this grown giraffe stretches its neck further and adds another 12.608 meters to its height, how tall will the giraffe be then?

Gemma 2B:

Reasoning: The giraffe will be 1.4 + 5.7 + 12.608 = <<1.4+5.7+12.608=19.908>>19.908 meters tall then.
### Answer: 19.908

Expected answer: 19.7080000000000

Correct? No

πŸ”— Follow-up

Problem: In another zoo, there is a full-grown giraffe that measures an impressive 23 meters. If the giraffe stretches its neck and grows another 5.7 meters, how tall will the giraffe be then?

Gemma 2B:

Reasoning: The giraffe will be 23 + 5.7 = <<23+5.7=28.7>>28.7 meters tall after it stretches its neck.
### Answer: 28.7

Expected answer: 28.7000000000000

Correct? Yes

πŸ”— Problem

Problem: An astronaut is floating in space and generates an isotopic energy reading of 24.178 units per second. If he keeps this energy level constant for 1.0 second, how much energy does he generate in total?

Gemma 2B:

Reasoning: The energy generated in 1.0 second is equal to the energy generated in 1/1000th of a second, which is 0.001 seconds.
Therefore, the total energy generated is 24.178 * 0.001 = <<0.24178>>0.24178> energy units.
### Answer: 0.24178

Expected answer: 24.1780000000000

Correct? No

πŸ”— Problem

Problem: A treasure chest holds 25.84 kilograms of gold. However, 2.876 kilograms of it is stolen. How much gold is left in the chest?

Gemma 2B:

Reasoning: 25.84 - 2.876 = <<25.84-2.876=23.96>>23.96 kilograms of gold is left in the chest.
### Answer: 23.96

Expected answer: 22.9640000000000

Correct? No

πŸ”— Problem

Problem: A breed of dog grows 15.7 inches tall and a different breed grows 4.9 inches more. How tall is the taller dog?

Gemma 2B:

Reasoning: The taller dog is 15.7 + 4.9 = <<15.7+4.9=20.6>>20.6 inches tall.

Expected answer: 20.6000000000000

Correct? Yes

πŸ”— Problem

Problem: A ball weighs 21.985 grams. If another identical ball weighs 25.3 grams but has lost some weight to become equal to the first ball, how much weight has the second ball lost? If we add 8.0 grams to the lost weight, what will be the total?

Gemma 2B:

Reasoning: The second ball lost 25.3 - 21.985 = <<25.3-21.985=3.315>>3.315 grams of weight.
If we add 8.0 grams to the lost weight, we get 3.315 + 8.0 = <<11.315>>11.315 grams of weight.
### Answer: 11.315

Expected answer: 11.3150000000000

Correct? Yes

πŸ”— Problem

Problem: At the beginning of his shift, a firefighter checks the fuel levels for two firetrucks. One truck has 9.155 gallons of fuel and the other has 5.540 gallons of fuel. After refueling both trucks, he adds an additional 9.03 gallons. What is the total amount of fuel in gallons after the firefighter refueled both trucks?

Gemma 2B:

Reasoning: After refueling, the first truck has 9.155 + 9.03 = <<18.185>>18.185 gallons of fuel.
The second truck has 5.540 + 9.03 = <<14.57>>14.57 gallons of fuel.
The total amount of fuel in gallons after the firefighter refueled both trucks is 18.185 + 14.57 = <<32.75>>32.75.
### Answer: 32.75

Expected answer: 23.7250000000000

Correct? No

πŸ”— Problem

Problem: A sunflower stem measures 23.57 cm at its longest but due to insufficient sunlight it shrunk to 11.58 cm. How much did the sunflower stem shrink?

Gemma 2B:

Reasoning: The sunflower stem shrunk from 23.57 cm to 11.58 cm.
The difference between the two measurements is 23.57-11.58 = <<23.57-11.58=12.09>>12.09 cm.
The sunflower stem shrunk by 12.09 cm.

Expected answer: 11.9900000000000

Correct? No

πŸ”— Problem

Problem: A scented candle is usually priced at $18.77 but today it is discounted by $4.016. What is the current price of the scented candle?

Gemma 2B:

Reasoning: The discounted price is 18.77 - 4.016 = <<18.77-4.016=14.75>>14.75.
The current price of the scented candle is $14.75.

Expected answer: 14.7540000000000

Correct? Yes

πŸ”— Problem

Problem: In a forest, there are 3.9km of northern trails and 7.4km of southern trails. If the total distance of all trails in the forest is 17.9km, how many kilometres of trails are not part of the northern or southern trails?

Gemma 2B:

Reasoning: 17.9 - 3.9 = <<17.9-3.9=14.0>>14.0 km of trails are not part of the northern or southern trails.

Expected answer: 6.60000000000000

Correct? No

πŸ”— Problem

Problem: A baby weighed 4.8 pounds at birth. After a few weeks, the baby gained 15.67 pounds. The baby's weight increased again by 6.5 pounds a few months later. What is the baby's weight now?

Gemma 2B:

Reasoning: The baby gained 15.67 + 6.5 = <<15.67+6.5=22.17>>22.17 pounds after birth.
The baby's weight now is 4.8 + 15.67 + 22.17 = <<4.8+15.67+22.17=42.64>>42.64 pounds.

Expected answer: 26.9700000000000

Correct? No

πŸ”— Problem

Problem: Astronomer Tom has a powerful telescope with a focal length of 22.5 centimeters. He uses an eyepiece that extends the focal length by another 1.832 centimeters. What is the total length of his telescope?

Gemma 2B:

Reasoning: The total length of the telescope is equal to the focal length plus the extension.
Total length = Focal length + Extension = 22.5 cm + 1.832 cm = <<22.5 cm + 1.832 cm=24.33 cm>>24.33 cm.
### Answer: 24.33 cm

Expected answer: 24.3320000000000

Correct? Yes

πŸ”— Follow-up

Problem: With further calibration, Astronomer Tom realized the eyepiece only extends the telescope's focal length by an additional 2 centimeters, instead of the previous 1.832 centimeters. Considering this, what would be the new total focal length of his telescope?

Gemma 2B:

### Answer: 22.5 cm + 2 cm = 24.5 cm

Expected answer: 24.5000000000000

Correct? Yes

πŸ”— Problem

Problem: A window has a width of 17.9 inches and an additional length of 1.5 inches for the frame. What is the total width of the window including the frame?

Gemma 2B:

Reasoning: The total width is the width of the window plus the frame, which is 17.9 + 1.5 = <<17.9+1.5=19.4>>19.4 inches.
### Answer: 19.4

Expected answer: 19.4000000000000

Correct? Yes

πŸ”— Follow-up

Problem: After installing the window, the builder realizes he made an error and the opening for the window is actually 13.48 inches smaller than the total width of the window including the frame. What is the excess length of the window that couldn't fit into the opening?

Gemma 2B:

### Answer: 4.52

Expected answer: 5.92000000000000

Correct? No

πŸ”— Follow-up

Problem: Suppose the builder made a new window, this time with a width of 28 inches, plus an additional length of 1.5 inches for the frame, how long is the window including the frame this time?

Gemma 2B:

Reasoning: The total length is the width of the window plus the frame, which is 28 + 1.5 = <<28+1.5=29.5>>29.5 inches.
### Answer: 29.5

Expected answer: 29.5000000000000

Correct? Yes

πŸ”— Problem

Problem: Your pen has 5.1ml of ink when it's new. If you add 22.4ml of ink into the pen, how much ink does the pen have in total?

Gemma 2B:

Reasoning: 5.1ml + 22.4ml = <<5.1+22.4=27.5>>27.5ml of ink in the pen.
### Answer: 27.5

Expected answer: 27.5000000000000

Correct? Yes

πŸ”— Follow-up

Problem: Suppose instead of starting with 5.1ml of ink in your pen, you started with 2ml of ink and then added 22.4ml of ink. How much ink does your pen have in total now?

Gemma 2B:

Reasoning: 2ml + 22.4ml = <<2+22.4=24>>24ml of ink in the pen.
### Answer: 24

Expected answer: 24.4000000000000

Correct? No

πŸ”— Problem

Problem: The perimeter of a square is found by adding the lengths of all its sides. If three sides of a square measure 15.4 cm in total, and the length of the remaining side is 1.828 cm, what is the total perimeter of the square?

Gemma 2B:

### Answer: 43.24 cm

Expected answer: 17.2280000000000

Correct? No

πŸ”— Problem

Problem: In a document, a paragraph has 12.244 words. If we add the number of words in this paragraph to a similar one, then how many words do the two paragraphs have in total?

Gemma 2B:

Reasoning: The number of words in the first paragraph is 12.244. The number of words in the second paragraph is also 12.244.
Therefore, the two paragraphs have the same number of words, which is 12.244.

Expected answer: 24.4880000000000

Correct? No

πŸ”— Problem

Problem: In a letter writing competition, one of the participants wrote a letter having a length of 29.82 pages. However, the rules require only a maximum of 24.2 pages. How many extra pages did the participant write compared to the maximum limit?

Gemma 2B:

Reasoning: 29.82 - 24.2 = <<29.82-24.2=5.62>>5.62 extra pages were written.
### Answer: 5.62

Expected answer: 5.62000000000000

Correct? Yes

πŸ”— Follow-up

Problem: Following the previous scenario, imagine if the participant had initially written 29.82 pages, but this time he decided to reduce it down to 28 pages. How many pages did he have to exclude from his letter in this scenario?

Gemma 2B:

### Answer: 1.82

Expected answer: 1.82000000000000

Correct? Yes

πŸ”— Problem

Problem: At the zoo, a lion weights 28.32 pounds but loses 21.88 pounds. After gaining 3.4 pounds, what is the lion's new weight?

Gemma 2B:

Reasoning: The lion lost 21.88 pounds, so 28.32 - 21.88 = <<28.32-21.88=6.44>>6.44 pounds.
The lion's new weight is 28.32 + 6.44 = <<28.32+6.44=34.76>>34.76 pounds.

Expected answer: 9.84000000000000

Correct? No

πŸ”— Problem

Problem: Last month, it rained an average of 3.645 inches per day. Today's rainfall is increased by 3.741 inches. How much rain was there in inches today?

Gemma 2B:

Reasoning: Today's rain is 3.741 inches more than yesterday's rain.
3.645 + 3.741 = <<3.645+3.741=7.386>>7.386 inches of rain today.

Expected answer: 7.38600000000000

Correct? Yes

πŸ”— Problem

Problem: A window has a length of 1.7 meters and a height of 9.448 meters. A larger window has its length equal to the length and height of the smaller window combined and an extra height of 7.619 meters. What is the total length and height of the larger window?

Gemma 2B:

Reasoning: The total length is equal to the sum of the length and height of the smaller window, which is 1.7 m and 9.448 m, respectively.
The total height is the sum of the height of the smaller window and the extra height, which is 7.619 m.
Therefore, the total length and height of the larger window are:
### Answer: 1.7 m + 9.448 m + 7.619 m = 19.758 m

Expected answer: 18.7670000000000

Correct? No

πŸ”— Problem

Problem: A pair of glasses at an optometrist's store cost $14.8. A special sturdy case for these glasses costs an additional $2.22. How much will it cost to buy the glasses and the case together?

Gemma 2B:

Reasoning: The cost of the glasses is 14.8, and the case costs 2.22.
The total cost is 14.8 + 2.22 = <<14.8+2.22=17.02>>17.02.
### Answer: 17.02

Expected answer: 17.0200000000000

Correct? Yes

πŸ”— Follow-up

Problem: In addition to the glasses and the special case, the eye checkup costs $3.0. How much would it cost in total to have an eye checkup, buy the glasses and special case together?

Gemma 2B:

Reasoning: The cost of the glasses is 14.8, the case costs 2.22, and the eye checkup costs 3.0.
The total cost is 14.8 + 2.22 + 3.0 = <<14.8+2.22+3.0=19.02>>19.02.
### Answer: 19.02

Expected answer: 20.0200000000000

Correct? No

πŸ”— Follow-up

Problem: Suppose that a different pair of glasses costs $25, but the special sturdy case still costs an additional $2.22. How much will it cost in total to buy this new pair of glasses and the case together?

Gemma 2B:

Reasoning: The cost of the new glasses is 25, and the case costs 2.22.
The total cost is 25 + 2.22 = <<25+2.22=27.22>>27.22.
### Answer: 27.22

Expected answer: 27.2200000000000

Correct? Yes

πŸ”— Problem

Problem: A roller skate normally costs $17.9, but is currently on sale with a discount of $8.069. How much does the sale price of the roller skate cost?

Gemma 2B:

Reasoning: The sale price is 17.9 - 8.069 = <<17.9-8.069=9.831>>9.831 dollars.
### Answer: 9.831

Expected answer: 9.83100000000000

Correct? Yes

πŸ”— Follow-up

Problem: After finding the sale price of the roller skate, let's say that you also decide to purchase a special set of roller skate guards that cost $3.53. How much would you need to pay in total for the discounted roller skate and the set of roller skate guards?

Gemma 2B:

Reasoning: The total cost would be 9.831 + 3.53 = <<9.831+3.53=13.361>>13.361 dollars.
### Answer: 13.361

Expected answer: 13.3610000000000

Correct? Yes

πŸ”— Follow-up

Problem: Let's consider a different scenario for the roller skate sale. If the discount on the roller skate was instead $6 from its original price of $17.9, how much would the roller skate cost after this new discount?

Gemma 2B:

Reasoning: The new discount is 17.9 - 6 = <<17.9-6=11.9>>11.9 dollars.
### Answer: 11.9

Expected answer: 11.9000000000000

Correct? Yes

πŸ”— Problem

Problem: In a sandbox, average weight of a single toy is 1.18 pounds. If a child put 23 toys in the sandbox, and added a castle mold that weighed 2.04 pounds, what would be the total weight of the items in the sandbox?

Gemma 2B:

Reasoning: Total weight = weight of toys = 23 toys * 1.18 pounds/toy = <<23*1.18=26.04>>26.04 pounds.
### Answer: 26.04

Expected answer: 29.1800000000000

Correct? No

πŸ”— Problem

Problem: At a campfire gathering, each person uses about 1.217 kg of firewood. If there are 18.89 people, approximately how much firewood will be used in total?

Gemma 2B:

Reasoning: Each person uses 1.217 kg/person, so 18.89 people use 18.89 * 1.217 = <<22.24 kg>>22.24 kg of firewood in total.
### Answer: 22.24

Expected answer: 22.9891300000000

Correct? No

πŸ”— Problem

Problem: A big marshmallow contains 6.1 grams of sugar. A small one has 4.64 grams. What is the total grams of sugar if you were to consume both types of marshmallows?

Gemma 2B:

Reasoning: The total weight of sugar in the big and small marshmallows is equal to the weight of the big marshmallow minus the weight of the small marshmallow.
6.1 + 4.64 = <<6.1+4.64=10.74>>10.74 grams of sugar.

Expected answer: 10.7400000000000

Correct? Yes

πŸ”— Problem

Problem: The weight of a toy car and a toy robot are 8.011 and 2.7 kilograms respectively. If we discount the collective weight by 9.526 kilograms, what is the resulting weight?

Gemma 2B:

Reasoning: The weight of the toy car and the toy robot is 8.011 + 2.7 = 10.711 kilograms.
After discounting the collective weight by 9.526 kg, the resulting weight is 10.711 - 9.526 = <<1.185>>1.185 kilograms.

Expected answer: 1.18500000000000

Correct? Yes

πŸ”— Problem

Problem: A dog's meal should weigh 28.207 grams. If you already fed your dog 5.801 grams, how much more do you need to feed it if it needs to consume an additional 1.59 grams after this meal?

Gemma 2B:

Reasoning: 28.207 - 5.801 = <<28.207-5.801=22.306>>22.306 grams of food should be fed to the dog.
### Answer: 22.306

Expected answer: 23.9960000000000

Correct? No

πŸ”— Problem

Problem: A dolphin can leap a maximum of 9.8 feet out of the water. If it jumps an additional 11.484 feet during an extraordinary display, what is the total distance the dolphin covered?

Gemma 2B:

Reasoning: The dolphin covered 9.8 + 11.484 = <<9.8+11.484=21.284>>21.284 feet during its extraordinary display.
### Answer: 21.284

Expected answer: 21.2840000000000

Correct? Yes

πŸ”— Follow-up

Problem: After the remarkable display, it was noticed that the dolphin only returned 9.8 feet back to the water level. What was the remaining distance the dolphin covered in mid-air?

Gemma 2B:

### Answer: 11.484

Expected answer: 11.4840000000000

Correct? Yes

πŸ”— Follow-up

Problem: In another remarkable leap, instead of rising an additional 11.484 feet, the dolphin soared an extra 20 feet above the initial 9.8 feet. What is the total distance the dolphin covered in this jump?

Gemma 2B:

Reasoning: The dolphin covered 9.8 + 20 = <<9.8+20=29.8>>29.8 feet during this jump.
### Answer: 29.8

Expected answer: 29.8000000000000

Correct? Yes

πŸ”— Problem

Problem: A water bottle holds 7.55 liters of water initially. If you add 17.4 more liters of water, how many liters are in the water bottle?

Gemma 2B:

Reasoning: We add 17.4 to 7.55 = <<7.55+17.4=25.9>>25.9 liters of water in the water bottle.
### Answer: 25.9

Expected answer: 24.9500000000000

Correct? No

πŸ”— Problem

Problem: If the eastern direction on a compass is represented by 25.348 degrees, and the southeastern direction is represented by 15.313 degrees. What is the difference between these two directions in degrees?

Gemma 2B:

Reasoning: The difference between these two directions is 25.348 - 15.313 = <<25.348-15.313=10.035>>10.035 degrees.
### Answer: 10.035

Expected answer: 10.0350000000000

Correct? Yes

πŸ”— Follow-up

Problem: Now consider a new scenario, where the eastern direction on a compass is represented by 28 degrees instead of 25.348. What is the difference between this new eastern direction and the previous southeastern direction in degrees?

Gemma 2B:

### Answer: 3.035

Expected answer: 12.6870000000000

Correct? No

πŸ”— Problem

Problem: A specific computer model costs $20.7. The store offers an upgrade that costs an additional $6.18. What will be the total cost for the upgraded computer model?

Gemma 2B:

Reasoning: The total cost is equal to the original price plus the upgrade price.
$20.7 + $6.18 = <<$20.7+$6.18=26.88>>26.88.
The total cost for the upgraded computer model is $26.88.

Expected answer: 26.8800000000000

Correct? Yes

πŸ”— Problem

Problem: The weight of a teddy bear is 29.2 grams. It loses 9.1 grams of its stuffing. Together with it, a small ribbon weighing 6.62 grams is attached to it. How much does the teddy bear with missing stuffing and a ribbon weigh now?

Gemma 2B:

Reasoning: The weight of the teddy bear after losing stuffing and a ribbon is 29.2 - 9.1 = <<29.2-9.1=19.1>>19.1 grams.
### Answer: 19.1

Expected answer: 26.7200000000000

Correct? No

πŸ”— Problem

Problem: A blanket has a temperature of 17.8Β°C. However, if it is used for a period of time, the temperature drops to 7.24Β°C. How many degrees Celsius does the temperature of the blanket drop by?

Gemma 2B:

Reasoning: The temperature drops by 17.8Β°C - 7.24Β°C = <<17.8Β°C-7.24Β°C=10.56Β°C>>10.56Β°C.
Therefore, the temperature of the blanket drops by 10.56Β°C.

Expected answer: 10.5600000000000

Correct? Yes

πŸ”— Problem

Problem: A jacket initially costs $13.3. However, there is a discount that reduces the price by $4.971. What is the cost of the jacket after the discount?

Gemma 2B:

Reasoning: After the discount, the jacket costs $13.3 - $4.971 = <<$8.329>>$8.329.
### Answer: $8.329

Expected answer: 8.32900000000000

Correct? Yes

πŸ”— Follow-up

Problem: After paying for the discounted jacket, how much money did you actually save from the original price?

Gemma 2B:

Reasoning: After the discount, the jacket costs $8.329, which is less than the original price of $13.3. Therefore, the person saved $13.3 - $8.329 = <<$4.971>>$4.971 from the original price.
### Answer: $4.971

Expected answer: 4.97100000000000

Correct? Yes

πŸ”— Follow-up

Problem: Suppose instead of the original price being $13.3, the jacket initially costs $30, how much would the jacket cost after applying the same discount of $4.971?

Gemma 2B:

Reasoning: After the discount, the jacket costs $30 - $4.971 = <<$25.029>>$25.029.
### Answer: $25.029

Expected answer: 25.0290000000000

Correct? Yes

πŸ”— Problem

Problem: Charlie has a unique ball that weighs 3.9 lbs. He adds two materials to the ball, first material weighing 14.2 lbs and the second material weighing 2.642 lbs. What is the total weight of the ball after adding both materials?

Gemma 2B:

Reasoning: The total weight of the ball after adding the two materials is 3.9 + 14.2 + 2.642 = <<3.9+14.2+2.642=20.542>>20.542 lbs.
### Answer: 20.542

Expected answer: 20.7420000000000

Correct? No

πŸ”— Problem

Problem: The distance from the earth to the sun is 26.6 million miles. If a spacecraft has already traveled 15.818 million miles, how much farther does it need to travel? If it needs to stop at a station that is 10.5 million miles away from its current position, what is the total distance the spacecraft has to travel? If after the stop, it has to detour another 4.27 million miles because of space debris, what will be the final total distance the spacecraft has to travel to reach the sun?

Gemma 2B:

### Answer: 26.6 million miles

Expected answer: 25.5520000000000

Correct? No

πŸ”— Problem

Problem: An eraser company makes two types of erasers: Type A weighs 12.2 grams and Type B weighs 15.0 grams. What is the total weight of one Type A eraser and one Type B eraser?

Gemma 2B:

Reasoning: The total weight of one Type A eraser and one Type B eraser is 12.2 + 15.0 = <<12.2+15.0=27.2>>27.2 grams.

Expected answer: 27.2000000000000

Correct? Yes

πŸ”— Problem

Problem: A coffee shop sells hot chocolate that is prepared with 11.07 grams of chocolate mix and 18.213 grams of sugar. How many grams are there in total in the hot chocolate mix?

Gemma 2B:

Reasoning: The total weight of the chocolate mix is 11.07 + 18.213 = <<11.07+18.213=29.28>>29.28 grams.
### Answer: 29.28

Expected answer: 29.2830000000000

Correct? Yes

πŸ”— Follow-up

Problem: After preparing the hot chocolate mix with 11.07 grams of chocolate mix and 18.213 grams of sugar, a barista decides to remove 13.93 grams of the mix to make it less sweet. How many grams are left in the hot chocolate mix now?

Gemma 2B:

Reasoning: After removing 13.93 grams of the mix, there are 11.07 + 18.213 - 13.93 = <<11.07+18.213-13.93=12.15>>12.15 grams left in the hot chocolate mix.
### Answer: 12.15

Expected answer: 15.3530000000000

Correct? No

πŸ”— Follow-up

Problem: If instead of 11.07 grams of chocolate mix, the coffee shop decides to add only 2 grams of chocolate mix to the 18.213 grams of sugar, how many grams would there be in total in the hot chocolate mix?

Gemma 2B:

Reasoning: The total weight of the chocolate mix would be 18.213 - 2 = <<18.213-2=18.193>>18.193 grams.
### Answer: 18.193

Expected answer: 20.2130000000000

Correct? No

πŸ”— Problem

Problem: A bookstore had 16.551 books and sold 2.8 books in the morning. In the afternoon, an additional 7.268 books were sold. How many books are left in the bookstore after this?

Gemma 2B:

Reasoning: After the morning sale, the bookstore had 16.551 - 2.8 = <<16.551-2.8=13.751>>13.751 books.
After the afternoon sale, the bookstore had 13.751 + 7.268 = <<13.751+7.268=21.019>>21.019 books.
The bookstore had 16.551 - 2.8 + 7.268 = <<16.551-2.8+7.268=13.751>>13.751 books left in the bookstore after the afternoon sale.

Expected answer: 6.48300000000000

Correct? No

πŸ”— Problem

Problem: In searching for hidden treasure in an old shipwreck, you found a treasure chest weighing 14.755650000000001 kilograms. If the maritime version of gold's worth is 10.81 kilograms per seashell, how many seashells is the treasure chest worth? If you could sell each seashell for $7.19, how much could you earn from selling all the seashells represented by the weight of the treasure chest?

Gemma 2B:

 
Reasoning: The weight of the treasure chest is 14.755650000000001 kg. The value of 10.81 kg per seashell is equivalent to 10.81 kg/shell. Therefore, the number of seashells in the treasure chest is equal to 14.755650000000001/10.81 = <<14.755650000000001/10.81>> 16 seashells.
 
The total amount of money earned from selling all the seashells represented by the weight of the treasure chest is 16 seashells * $7.19 = <<$115.12>> $115.12.
### Answer: $115.12

Expected answer: 9.81435000000000

Correct? No

πŸ”— Problem

Problem: A baby's birth weight is typically around 18.4 ounces. If a particular baby gains 6.97 ounces more than this average weight during the first month, what is the baby's weight then?

Gemma 2B:

Reasoning: The baby's weight is 18.4+6.97 = <<18.4+6.97=25.37>>25.37 ounces.
### Answer: 25.37

Expected answer: 25.3700000000000

Correct? Yes

πŸ”— Follow-up

Problem: A baby's birth weight is typically around 18.4 ounces. If a particular baby gains 6.97 ounces more than this average weight during the first month, what is the baby's weight then? If this baby then loses 21.754 ounces, what will be the baby's new weight?

Gemma 2B:

Reasoning: The baby's weight is 18.4+6.97 = <<18.4+6.97=25.37>>25.37 ounces.
If this baby then loses 21.754 ounces, the baby's new weight will be 18.4-21.754 = <<18.4-21.754=6.646>>6.646 ounces.

Expected answer: 3.61600000000000

Correct? No

πŸ”— Follow-up

Problem: A baby's birth weight is typically around 18.4 ounces. If a particular baby gains 7 ounces more than the average weight during the first month rather than the previous 6.97 ounces scenario, what is the baby's new weight then?

Gemma 2B:

Reasoning: The baby's weight is 18.4+7 = <<18.4+7=25.47>>25.47 ounces.
### Answer: 25.47

Expected answer: 25.4000000000000

Correct? Yes

πŸ”— Problem

Problem: An eraser is 1.4 cm long and 6.7 cm wide. Calculate the surface area of the eraser.

Gemma 2B:

Reasoning: The surface area of an eraser can be calculated by multiplying its length and width.
Surface area = length x width = 1.4 cm x 6.7 cm = <<1.4 cm x 6.7 cm=9.2 cm^2>>9.2 cm^2.
### Answer: 9.2 cm^2

Expected answer: 9.38000000000000

Correct? Yes

πŸ”— Follow-up

Problem: In addition to the first eraser, Carl buys an identical eraser. Calculate the total surface area of the two erasers together.

Gemma 2B:

Reasoning: The total surface area of the two erasers is the same as the surface area of the first eraser.
Total surface area = 9.2 cm^2 = <<9.2 cm^2>>
### Answer: 9.2 cm^2

Expected answer: 18.7600000000000

Correct? No

πŸ”— Follow-up

Problem: Suppose the original eraser is actually 1.4 cm long but 18 cm wide instead. What would be the new surface area of this eraser?

Gemma 2B:

Reasoning: The new width of the eraser is 1.4 cm x 3 = 4.2 cm.
The new surface area of the eraser would be:
New surface area = length x width = 1.4 cm x 4.2 cm = <<1.4 cm x 4.2 cm=5.8 cm^2>>5.8 cm^2.
### Answer: 5.8 cm^2

Expected answer: 25.2000000000000

Correct? No

πŸ”— Problem

Problem: A UFO is spotted at an altitude of 28.571 miles. It descends by 14.06 miles. Then it descends another 12.7 miles. Shortly after, it rises by 16.4 miles. What is the altitude of the UFO now?

Gemma 2B:

Reasoning: The UFO descends 14.06 miles, then 12.7 miles, and then rises 16.4 miles.
Therefore, the UFO's altitude is 28.571 - 14.06 - 12.7 + 16.4 = 14.07 miles above its original altitude.
### Answer: 14.07

Expected answer: 18.2110000000000

Correct? No

πŸ”— Problem

Problem: A woman bought a skirt where the cost of the fabric is $3.935 and the cost of the workmanship is $6.78. What is the total cost for the skirt?

Gemma 2B:

Reasoning: The cost of the fabric is 3.935, and the cost of the workmanship is 6.78. The total cost is 3.935 + 6.78 = <<3.935+6.78=10.71>>10.71.
### Answer: 10.71

Expected answer: 10.7150000000000

Correct? Yes

πŸ”— Follow-up

Problem: In addition to the cost of the skirt's fabric and workmanship which was $3.935 and $6.78 respectively, there was an extra cost for specific design elements of $1.803. What is the total cost of the skirt now?

Gemma 2B:

### Answer: 10.71+1.803 = 12.513

Expected answer: 12.5180000000000

Correct? Yes

πŸ”— Follow-up

Problem: If instead of $6.78, the cost of the workmanship for the skirt was $25 while the cost of the fabric remained at $3.935, what would be the total cost for the skirt?

Gemma 2B:

Reasoning: If the cost of the workmanship had been $25, the total cost would have been 3.935 + 25 = <<3.935+25=38.93>>38.93.
### Answer: 38.93

Expected answer: 28.9350000000000

Correct? No

πŸ”— Problem

Problem: A top and bottom combo of a dress set is sold separately. The top costs $5.9 and the bottom costs $5.5. What is the total price of the entire dress set?

Gemma 2B:

Reasoning: The total cost is the sum of the top and bottom costs, which is $5.9 + $5.5 = $11.4.
### Answer: 11.4

Expected answer: 11.4000000000000

Correct? Yes

πŸ”— Follow-up

Problem: Considering the price of the top and bottom combo of the dress set, if a customer also decides to buy a matching coat priced at $17.58 to complete her outfit, what is the total cost of her purchase?

Gemma 2B:

### Answer: 11.4 + 17.58 = 29.08

Expected answer: 28.9800000000000

Correct? No

πŸ”— Follow-up

Problem: If the price of the top part of the dress set is actually $3 instead of $5.9, and the bottom still costs $5.5, what would be the new total price of the dress set?

Gemma 2B:

Reasoning: The total cost is now $3 + $5.5 = $8.5.
### Answer: 8.5

Expected answer: 8.50000000000000

Correct? Yes

πŸ”— Problem

Problem: Captain Jack has a treasure chest with 22.83 gold coins. He spends 10.198 coins on a new pirate map. How many gold coins does he have left?

Gemma 2B:

Reasoning: 22.83 - 10.198 = <<22.83-10.198=12.63>>12.63 coins.
### Answer: 12.63

Expected answer: 12.6320000000000

Correct? Yes

πŸ”— Follow-up

Problem: Following the previous question, what if the treasure chest originally had 14 gold coins instead of 22.83 gold coins? After spending 10.198 coins on a new pirate map, how many gold coins would Captain Jack have left?

Gemma 2B:

### Answer: 14

Expected answer: 3.80200000000000

Correct? No

πŸ”— Problem

Problem: Princess Mia has a particular type of magical gemstone that powers her kingdom. Each gemstone weighs 6.7 grams. One day, she decides to gather two of these gemstones. But disaster strikes! A mischievous goblin steals 9.483 grams worth of gemstones from Mia. How many grams of gemstones does Princess Mia have left after the goblin's mischievous act?

Gemma 2B:

Reasoning: After the goblin took 9.483 grams, Mia has 6.7 - 9.483 = <<6.7-9.483=<<-2.783>>-2.783 grams of gemstones left.
### Answer: 6.7-2.783=<<4.217>>4.217 grams of gemstones left

Expected answer: 3.91700000000000

Correct? No

πŸ”— Problem

Problem: A zoo has 22.8 kilograms of food for the animals. The lion is fed 5.0 kilograms of food. How much food is left in the zoo after feeding the lion?

Gemma 2B:

Reasoning: After feeding the lion, there are 22.8 - 5 = <<22.8-5=17.8>>17.8 kilograms of food left in the zoo.
### Answer: 17.8

Expected answer: 17.8000000000000

Correct? Yes

πŸ”— Follow-up

Problem: After feeding the lion, the zookeepers realize that a delivery of an additional 6.91 kilograms of food has arrived. What is the total amount of food for the animals in the zoo after the additional food delivery?

Gemma 2B:

### Answer: 29.71

Expected answer: 24.7100000000000

Correct? No

πŸ”— Follow-up

Problem: Earlier, the zoo had 23 kilograms of food for the animals, but they fed 5.0 kilograms of it to the lion. Now, how much food is left in the zoo after feeding the lion under these new circumstances?

Gemma 2B:

### Answer: 18 kilograms

Expected answer: 18.0000000000000

Correct? Yes

πŸ”— Problem

Problem: At a party, each guest is offered 1.625 ounces of a party mix snack. If there are 14.149 guests, how many ounces of party mix will be eaten in total?

Gemma 2B:

Reasoning: Each guest will be offered 1.625 ounces of party mix, so 14.149 guests will be offered 14.149 * 1.625 = <<24.125>>24.125 ounces of party mix.
### Answer: 24.125

Expected answer: 22.9921250000000

Correct? No

πŸ”— Problem

Problem: Linda noticed her favourite doll was initially priced at $26.63 in a store. However, it was marked down by $16.41 during a sale. How much does the doll cost after the discount?

Gemma 2B:

Reasoning: The discount is 26.63-16.41 = <<26.63-16.41=10.22>>10.22 dollars.
### Answer: $10.22

Expected answer: 10.2200000000000

Correct? Yes

πŸ”— Follow-up

Problem: After Linda noticed the discount and purchased the favorite doll, she also found a cute dress for the doll that costs $10.52. How much will Linda spend in total for the doll and the dress?

Gemma 2B:

Reasoning: The total cost is 10.22+10.52 = <<10.22+10.52=20.74>>20.74 dollars.
### Answer: $20.74

Expected answer: 20.7400000000000

Correct? Yes

πŸ”— Problem

Problem: A pair of pants have a length of 9.8 inches and an extra material of 7.7 inches is added for adjustments. After the adjustment, an additional cloth of 6.757 inches was added for the design. What is the overall length of the pants including the adjustments and design?

Gemma 2B:

Reasoning: The length of the pants after adjustments = 9.8 + 7.7 = <<9.8+7.7=17.5>>17.5 inches.
The design cloth added = 6.757 inches.
Therefore, the overall length of the pants including the adjustments and design = 9.8 + 7.7 + 6.757 = <<9.8+7.7+6.757=24.25>>24.25 inches.

Expected answer: 24.2570000000000

Correct? Yes

πŸ”— Problem

Problem: A specific pen has an initial weight of 13.964 grams. After using it for a while, the weight is reduced to 11.59 grams. If the weight of the pen case is 24.0 grams, what is the total weight of the pen and its case after using the pen for some time?

Gemma 2B:

Reasoning: The weight of the pen and its case is reduced by the weight of the used pen.
13.964 - 11.59 = <<13.964-11.59=2.374>>2.374 grams.
The total weight of the pen and its case after using the pen for some time is 13.964 - 2.374 = <<13.964-2.374=11.59>>11.59 grams.
### Answer: 11.59

Expected answer: 26.3740000000000

Correct? No

πŸ”— Problem

Problem: The bed of a small truck is 2.06 meters long and 1.32 meters wide. What is the area of the truck bed in square meters?

Gemma 2B:

Reasoning: The area of the bed is 2.06 x 1.32 = <<2.06 x 1.32=2.78>>2.78 square meters.
### Answer: 2.78

Expected answer: 2.71920000000000

Correct? Yes

πŸ”— Follow-up

Problem: Given that the bed of a small truck is 2.06 meters long and 1.32 meters wide, and the additional space outside the truck bed for placing items is 5.1 square meters, what is the total area available for placing items in square meters?

Gemma 2B:

### Answer: 7.12

Expected answer: 7.81920000000000

Correct? No

πŸ”— Problem

Problem: In a marine study, a particular species of starfish has an average weight of 2.967 grams. A researcher finds a group of 6.52 starfish on average in a certain area. However, a starfish weighs 7.36 grams less than the total weight of the group starfish found in that area. What is the weight of this starfish in grams?

Gemma 2B:

Reasoning: The weight of the starfish in the group is 6.52*2.967 = <<6.52*2.967=18.004>>18.004 grams.
The weight of the starfish in the group is 18.004 - 7.36 = <<18.004-7.36=10.644>>10.644 grams.

Expected answer: 11.9848400000000

Correct? No

πŸ”— Problem

Problem: A monkey jumps 1.627 meters high in one jump. If he manages to jump 11.0 meters further in his second jump, how high does he jump altogether?

Gemma 2B:

Reasoning: The monkey jumped 1.627 + 11.0 = <<1.627+11.0=12.627>>12.627 meters high in his second jump.
### Answer: 12.627

Expected answer: 12.6270000000000

Correct? Yes

πŸ”— Follow-up

Problem: After his second jump, the monkey ate some bananas and his strength increased, making him able to jump 5.1 meters less than his previous combined heights. How high is the new jump?

Gemma 2B:

### Answer: 12.627-5.1 = 7.527 meters high

Expected answer: 7.52700000000000

Correct? Yes

πŸ”— Follow-up

Problem: After some rest, the energetic monkey did another jump which was 1.627 meters high. The monkey's second jump this time was only 7 meters further than first jump. How high in total did the monkey jump in these two jumps?

Gemma 2B:

### Answer: 1.627+7 = <<1.627+7=2.327>>2.327 meters high in total.

Expected answer: 8.62700000000000

Correct? No

πŸ”— Problem

Problem: The height of a club sandwich is 1.61 inches. Find the square of the height of the sandwich.

Gemma 2B:

Reasoning: The square of the height is 1.61^2 = <<1.61^2=2.56>>2.56 square inches.
### Answer: 2.56

Expected answer: 2.59210000000000

Correct? Yes

πŸ”— Follow-up

Problem: In addition to knowing the square of the height of the club sandwich, what would be the volume if the sandwich was shaped like a cube?

Gemma 2B:

### Answer: 1.61^3 = 2.56 square inches

Expected answer: 4.17328100000000

Correct? No

πŸ”— Follow-up

Problem: If the height of the club sandwich was actually 2 inches instead of 1.61 inches, what would be the new square of the height of the sandwich?

Gemma 2B:

### Answer: 4 square inches

Expected answer: 4

Correct? Yes

πŸ”— Problem

Problem: A clock ticks 6.645 second per cycle after midnight and adds an additional 13.52 seconds for the hourly chime. How long, in seconds, does it take for one full cycle of the clock, including the hourly chime?

Gemma 2B:

Reasoning: One full cycle of the clock takes 6.645 + 13.52 = <<6.645+13.52=20.165>>20.165 seconds.
### Answer: 20.165

Expected answer: 20.1650000000000

Correct? Yes

πŸ”— Follow-up

Problem: After the one full cycle of the clock, the clockmaker adjusted the clock by taking off 1.6 seconds from the cycle time. How long, in seconds, does the clock take for one full cycle after the clockmaker's adjustment?

Gemma 2B:

### Answer: 20.165-1.6 = 18.565 seconds

Expected answer: 18.5650000000000

Correct? Yes

πŸ”— Follow-up

Problem: In a new adjustment, the clockmaker changes the hourly chime to add an additional 20 seconds to the clock's cycle time instead of the previous 13.52 seconds. How long, in seconds, does it take for one full cycle of the clock, including the new hourly chime, after this adjustment?

Gemma 2B:

Reasoning: One full cycle of the clock takes 6.645 + 20 = <<6.645+20=26.645>>26.645 seconds.
### Answer: 26.645

Expected answer: 26.6450000000000

Correct? Yes

πŸ”— Problem

Problem: John originally had $13.079 in his wallet. After buying a pack of pens, he was left with $11.967. How much did the pens cost?

Gemma 2B:

Reasoning: The cost of the pens can be found by subtracting the initial amount from the final amount.
$13.079 - $11.967 = <<$13.079-$11.967=$1.112>>$1.112.
Therefore, the pens cost $1.112.

Expected answer: 1.11200000000000

Correct? No

πŸ”— Problem

Problem: A type of strawberry is sold at a weight of 23.21g. If an apple that has a weight of 3.759g is added, what is the total weight of them both?

Gemma 2B:

Reasoning: The total weight is 23.21g + 3.759g = <<23.21g+3.759g=27.96g>>27.96g.
### Answer: 27.96

Expected answer: 26.9690000000000

Correct? No

πŸ”— Problem

Problem: You bought a gaming mouse that cost $11.57. You also purchased an additional gaming accessory that was $16.99 more expensive than the mouse. How much did the gaming accessory cost?

Gemma 2B:

Reasoning: The additional accessory cost 16.99 - 11.57 = <<16.99-11.57=5.42>>5.42 more than the mouse.
Therefore, the gaming accessory cost $11.57 + 5.42 = <<11.57+5.42=16.99>>$16.99.

Expected answer: 28.5600000000000

Correct? No

πŸ”— Problem

Problem: If a pen costs $18.33 and additionally $10.727 for its fancy pen case, how much money will the full set cost you?

Gemma 2B:

Reasoning: The total cost of the pen and its case is 18.33 + 10.727 = <<18.33+10.727=29.057>>29.057 dollars.

Expected answer: 29.0570000000000

Correct? Yes

πŸ”— Problem

Problem: At the zoo, an elephant eats 4.36 kilograms of food every meal. If it eats two meals, how many kilograms of food does the elephant eat in total?

Gemma 2B:

Reasoning: The elephant eats 4.36 x 2 = <<4.36 x 2= 8.72>>8.72 kilograms of food in total in two meals.
### Answer: 8.72

Expected answer: 8.72000000000000

Correct? Yes

πŸ”— Follow-up

Problem: The zookeeper needs to add 7.71 kilograms of fruits and vegetables to the elephant's diet after its two meals. How many kilograms of food in total does the elephant eat including the two meals and the added fruits and vegetables?

Gemma 2B:

### Answer: 15.41

Expected answer: 16.4300000000000

Correct? No

πŸ”— Follow-up

Problem: Instead of the 4.36 kilograms of food at each meal, what if the zoo had to feed the elephant 8 kilograms of food at each meal? How many kilograms of food would the elephant eat in total over two meals?

Gemma 2B:

### Answer: 16

Expected answer: 16

Correct? Yes

πŸ”— Problem

Problem: A specific stuffed animal weighs 1.2 pounds. If we multiply that weight by a packaging factor of 2.663, we get a new weight. If the transportation fee for shipping the stuffed animal is $4.67 per pound, what will be the total transportation fee for this stuffed animal?

Gemma 2B:

Reasoning: The total weight is 1.2 x 2.663 = <<1.2 x 2.663=3.196>>3.196 pounds.
The total transportation fee is 3.196 x 4.67 = <<3.196 x 4.67=$14.88>>$14.88.
### Answer: $14.88

Expected answer: 14.9234520000000

Correct? No

πŸ”— Problem

Problem: In a cafΓ©, a cup of hot chocolate costs $6.84. After seeing the high demand for this beverage, the cafΓ© owner decides to increase the price by 239%. However, due to feedback from regular customers, the owner decides to decrease the new price by $1.766. What is the new price of a cup of hot chocolate at the cafΓ©?

Gemma 2B:

Reasoning: The new price is 6.84 * 123/100 = <<6.84*123/100=80.32>>80.32.
### Answer: $80.32

Expected answer: 14.5816000000000

Correct? No

πŸ”— Problem

Problem: At the campfire, James gathered 12.291 kilograms of firewood while Ruby brought in 6.48 kilograms of firewood. What is the total weight of the firewood?

Gemma 2B:

Reasoning: James gathered 12.291 kg and Ruby brought in 6.48 kg, so the total weight is 12.291 + 6.48 = <<12.291+6.48=18.77>>18.77 kg.
### Answer: 18.77

Expected answer: 18.7710000000000

Correct? Yes

πŸ”— Follow-up

Problem: At the campfire, suppose James gathered 6 kilograms of firewood instead of 12.291 kilograms, while Ruby still brought in 6.48 kilograms of firewood. Now, what would be the total weight of the firewood?

Gemma 2B:

Reasoning: If James had gathered 6 kg, then he would have 12.291 - 6 = <<6-12.291=6.291>>6.291 kg of firewood.
If Ruby had brought in 6.48 kg, then she would have 6.48 + 6 = <<6.48+6=12.48>>12.48 kg of firewood.
The total weight of the firewood is 6.291 + 12.48 = <<6.291+12.48=18.77>>18.77 kg.
### Answer: 18.77

Expected answer: 12.4800000000000

Correct? No

πŸ”— Problem

Problem: The compass reads that the initial direction is 4.0 degrees, but there is a shift of 17.56 degrees to the east. How many degrees is the final direction?

Gemma 2B:

Reasoning: The final direction is 4.0 + 17.56 = <<4.0+17.56=21.56>>21.56 degrees.
### Answer: 21.56

Expected answer: 21.5600000000000

Correct? Yes

πŸ”— Follow-up

Problem: After the initial movement, the compass reads another directional shift this time 18.1 degrees to the west. What would be the final directional reading after this shift?

Gemma 2B:

### Answer: 42.66 degrees

Expected answer: 3.46000000000000

Correct? No

πŸ”— Follow-up

Problem: The compass originally pointed 10 degrees east, but then it shifted an additional 17.56 degrees further. What will be the compass's new direction in degrees after this additional shift?

Gemma 2B:

### Answer: 21.56

Expected answer: 27.5600000000000

Correct? No

πŸ”— Problem

Problem: A large cake costs $17.3. The cake shop is having a special offer where you get a pack of candles for $3.57 along with the cake. How much are you going to pay in total?

Gemma 2B:

Reasoning: The price of the cake is $17.3. The price of the candles is $3.57. So, the total cost is $17.3 + $3.57 = <<$17.3+$3.57=$20.87>>$20.87.
### Answer: $20.87

Expected answer: 20.8700000000000

Correct? Yes

πŸ”— Follow-up

Problem: The cake shop offers a special discount of $3.327 on the total cost. How much do you have to pay after applying the discount?

Gemma 2B:

Reasoning: The total cost is $17.3. The discount is $3.327. So, the final cost is $17.3 - $3.327 = <<$17.3-$3.327=$14.97>>$14.97.
### Answer: $14.97

Expected answer: 17.5430000000000

Correct? No

πŸ”— Follow-up

Problem: Suppose the cake's price was increased to $19 due to additional decorations. How much is the total cost, together with the pack of candles worth $3.57?

Gemma 2B:

Reasoning: The price of the cake increased from $17.3 to $19. The price of the candles is $3.57. So, the total cost is $17.3 + $3.57 = <<$17.3+$3.57=$20.87>>$20.87.
### Answer: $20.87

Expected answer: 22.5700000000000

Correct? No

πŸ”— Problem

Problem: A sleeping bag has a length of 12.2 feet and a width of 10.95 feet. What's the sum of the sleeping bag's length and width?

Gemma 2B:

Reasoning: The sum of the length and width is 12.2 + 10.95 = <<12.2+10.95=23.15>>23.15 feet.

Expected answer: 23.1500000000000

Correct? Yes

πŸ”— Problem

Problem: A storm is coming in and the wind speed was initially 15.1 km/hr. It then increases by 7.79 km/hr. Simultaneously, another storm was hitting from the opposite direction with wind speed of 18.002 km/hr but it decreases by 11.8 km/hr. What is the total wind speed now?

Gemma 2B:

Reasoning: The total wind speed now is the sum of the two wind speeds: 15.1 + 7.79 = 22.89 km/hr.
### Answer: 22.89

Expected answer: 29.0920000000000

Correct? No

πŸ”— Problem

Problem: On Joe's mountain hike, he drinks 11.2 liters of water each day. If Joe hikes for 2 days, how much water is left from a 29.99-liter water jug he carried?

Gemma 2B:

Reasoning: 11.2 x 2 = <<11.2 x 2=22.4>>22.4 liters of water are left from the jug after 2 days.
### Answer: 22.4

Expected answer: 7.59000000000000

Correct? No

πŸ”— Problem

Problem: A pillow costs $25.997. If you have a discount code that takes off $3.685, how much will the pillow cost after the discount?

Gemma 2B:

Reasoning: The discount code takes off 3.685 from $25.997, which is equivalent to $22.302.
The final price is $25.997 - $22.302 = <<$25.997-$22.302=$3.69>>$3.69.
### Answer: $3.69

Expected answer: 22.3120000000000

Correct? No

πŸ”— Problem

Problem: An ice skate weighs 8.38 pounds. If we add changeable blades to the skate, which weighs 1.16 pounds, how much does the ice skate weigh in total?

Gemma 2B:

Reasoning: The total weight is 8.38 + 1.16 = <<8.38+1.16=9.54>>9.54 pounds.
### Answer: 9.54

Expected answer: 9.54000000000000

Correct? Yes

πŸ”— Problem

Problem: A police officer is investigating two crime scenes. The first crime scene is 11.183 kilometers from the police station, and the second crime scene is 4.46 kilometers away from the first crime scene. What is the total distance the officer needs to travel to investigate both crime scenes?

Gemma 2B:

Reasoning: The total distance is 11.183 + 4.46 = <<11.183+4.46=15.64>>15.64 kilometers.
### Answer: 15.64

Expected answer: 15.6430000000000

Correct? Yes

πŸ”— Follow-up

Problem: Previously, the police officer's first crime scene was 11.183 kilometers away, and the second was an additional 4.46 kilometers. But what if the first crime scene had instead been 14 kilometers away from the station but still 4.46 kilometers away from the second crime scene? What would then be the total distance the cop needs to travel to investigate both crime scenes?

Gemma 2B:

### Answer: 19.64

Expected answer: 18.4600000000000

Correct? No

πŸ”— Problem

Problem: An alien named Zyko has 24.06 kryptonite units. However, a space villain has stolen 8.49 units from him. Zyko then discovers another hero alien has a total of 27.7 units. After Zyko's loss, how much more kryptonite does this hero have in comparison to Zyko?

Gemma 2B:

Reasoning: Zyko lost 8.49 units, so he has 24.06 - 8.49 = <<24.06-8.49=15.57>>15.57 units more than the hero.
### Answer: 15.57

Expected answer: 12.1300000000000

Correct? No

πŸ”— Problem

Problem: A cloud is at 27.53 kilometers above the surface of the Earth. If it drops 2.411 kilometers lower, how high is the cloud from the surface of the Earth now?

Gemma 2B:

Reasoning: The cloud will be 27.53 - 2.411 = <<27.53-2.411=25.12>>25.12 kilometers above the surface of the Earth now.

Expected answer: 25.1190000000000

Correct? Yes

πŸ”— Problem

Problem: A piano tuning session costs normally $25.3. Today, there is a special offer and you can get it done for $5.433 less than the normal price! How much will the piano tuning session cost after the discount?

Gemma 2B:

Reasoning: The discount is $25.3 - $5.433 = <<$25.3-$5.433=$20.867>>$20.867.
The final price of the piano tuning session is $25.3 - $20.867 = <<$25.3-$20.867=$4.43>>$4.43.
### Answer: $4.43

Expected answer: 19.8670000000000

Correct? No

πŸ”— Problem

Problem: A swing moves forward 17.6 meters. If it swings back 8.325 meters, what is the total distance travel by the swing?

Gemma 2B:

Reasoning: The total distance traveled by the swing is the sum of the forward and backward travel.
Distance forward = 17.6 m
Distance backward = 8.325 m
Total distance = 17.6 + 8.325 = <<26.925>>26.925 m.

Expected answer: 25.9250000000000

Correct? No

πŸ”— Problem

Problem: A candle maker uses 8.0 ounces of wax for one candle and tops it with 1.3 ounces of decorative wax. What is the total weight of the completed candle?

Gemma 2B:

Reasoning: The total weight of the completed candle is 8.0 + 1.3 = <<8.0+1.3=9.3>>9.3 ounces.
### Answer: 9.3

Expected answer: 9.30000000000000

Correct? Yes

πŸ”— Follow-up

Problem: The candle maker decides to make another candle of the same size. What is the total weight of both candles?

Gemma 2B:

Reasoning: The total weight of both candles is 8.0 + 9.3 = <<8.0+9.3=17.3>>17.3 ounces.
### Answer: 17.3

Expected answer: 18.6000000000000

Correct? No

πŸ”— Follow-up

Problem: If the candle maker decides to use 21 ounces of wax for a candle instead of 8 ounces, but keeps the weight of decorative wax the same, what would be the total weight of the new candle?

Gemma 2B:

Reasoning: The total weight of the new candle would be 8.0 + 21 = <<8.0+21=29>>29 ounces.
### Answer: 29

Expected answer: 22.3000000000000

Correct? No

πŸ”— Problem

Problem: The length of a jumbo eraser is 29.0 cm. However, it is then cut down to 19.078 cm. Another piece measuring 8.197 cm is also cut off from it. If you then add a piece measuring 14.4 cm to it, what is the new length of the eraser?

Gemma 2B:

Reasoning: The total length of the eraser is 29.0 cm. If 8.197 cm is cut off, the remaining length is 29.0-8.197 = <<29.0-8.197=20.803>>20.803 cm.
The new length of the eraser is 20.803 cm.

Expected answer: 16.1250000000000

Correct? No

πŸ”— Problem

Problem: A snowman was made on a snowy day. At first, it was 12.903 feet high. But, after a couple of hours, due to the heat from the sun, it had melted down to 2.624 feet. How much height did the snowman lose?

Gemma 2B:

Reasoning: The snowman lost 12.903 - 2.624 = <<12.903-2.624=10.279>>10.279 feet of height.
### Answer: 10.279

Expected answer: 10.2790000000000

Correct? Yes

πŸ”— Follow-up

Problem: After the snowman melted to 2.624 feet, a fresh layer of snow fell overnight and added the exact amount of height that the snowman lost back onto it. What is the height of the snowman the next morning?

Gemma 2B:

### Answer: 12.903 feet

Expected answer: 12.9030000000000

Correct? Yes

πŸ”— Problem

Problem: In a sandbox, children have poured 17.985 kilograms of sand into different playing areas. If they want to divide the sand equally into 5.45 areas, how much sand will each area get?

Gemma 2B:

Reasoning: Each area will get 17.985 Γ· 5.45 β‰ˆ <<17.985 Γ· 5.45 β‰ˆ 3.32>>3.32 kilograms of sand.
### Answer: 3.32

Expected answer: 3.30000000000000

Correct? Yes

πŸ”— Follow-up

Problem: In the same sandbox, the children have decided instead to divide the original 17.985 kilograms of sand equally into 11 different play areas. How much sand would each area get now?

Gemma 2B:

Reasoning: Each area will get 17.985 Γ· 11 β‰ˆ <<17.985 Γ· 11 = 1.68>>1.68 kilograms of sand.
### Answer: 1.68

Expected answer: 1.63500000000000

Correct? Yes

πŸ”— Problem

Problem: If a gift's initial price was $24.17, and they added $3.802 for gift wrapping, how much would the final cost of the gift be?

Gemma 2B:

Reasoning: The final cost would be the initial price plus the gift wrapping cost.
Final cost = $24.17 + $3.802 = <<$24.17+$3.802=$27.97>>$27.97.
### Answer: $27.97

Expected answer: 27.9720000000000

Correct? Yes

πŸ”— Follow-up

Problem: If a gift's initial price was $24.17, and they added $3.802 for gift wrapping, how much would the final cost of the gift be? Additionally, if the customer used a discount coupon worth $10.7, what would be the total cost of the gift after applying the discount?

Gemma 2B:

Reasoning: The final cost would be the initial price minus the discount amount.
Final cost = $24.17 - $10.7 = <<$13.47>>$13.47.
### Answer: $13.47

Expected answer: 17.2720000000000

Correct? No

πŸ”— Follow-up

Problem: If instead of the original price being $24.17, the gift only cost $4, and they still added $3.802 for gift wrapping, what would the final cost of the gift then be?

Gemma 2B:

Reasoning: The final cost would be the original price minus the gift wrapping cost.
Final cost = $24.17 - $3.802 = <<$24.17-$3.802=$20.36>>$20.36.
### Answer: $20.36

Expected answer: 7.80200000000000

Correct? No

πŸ”— Problem

Problem: A baker has 15.643 kilograms of sugar and 10.24 kilograms of flour. If they use 8.8 kilograms of the total ingredients for baking a cake, how many kilograms of ingredients are left?

Gemma 2B:

Reasoning: 15.643 - 10.24 = <<15.643-10.24=5.403>>5.403 kg of ingredients are left.

Expected answer: 17.0830000000000

Correct? No

πŸ”— Problem

Problem: Inside your wallet, you have $13.32. But you decided to buy a wallet organizer that costs $7.612. After purchasing, you find $22.013 inside the pocket of the organizer. How much money do you have in total now?

Gemma 2B:

Reasoning: You bought a wallet organizer for $7.612, and you found $22.013 inside the organizer.
So, you have $13.32 + $7.612 + $22.013 = <<13.32+7.612+22.013=43.94>>43.94 dollars in total.
### Answer: 43.94

Expected answer: 27.7210000000000

Correct? No

πŸ”— Problem

Problem: A luxury pillow costs $25.15. However, there's a sale that reduces the price by $5.1. What is the price of the pillow after the discount?

Gemma 2B:

Reasoning: After the discount, the price is 25.15 - 5.1 = <<25.15-5.1=20.05>>20.05 dollars.
### Answer: $20.05

Expected answer: 20.0500000000000

Correct? Yes

πŸ”— Follow-up

Problem: After purchasing the discounted pillow, Carl decided to buy an additional decorative pillow cover that cost $7. If the original discounted price of the pillow was $25.15 - $5.10, how much did Carl pay in total for the pillow and the cover?

Gemma 2B:

Reasoning: The total cost is 25.15 - 5.10 = <<25.15-5.10=20.05>>20.05 dollars.
### Answer: $20.05

Expected answer: 27.0500000000000

Correct? No

πŸ”— Follow-up

Problem: If the original price of the pillow before the sale was instead $8.00 but the discount was still $5.10, what would be the new price of the discounted pillow?

Gemma 2B:

Reasoning: After the discount, the price is 8.00 - 5.10 = <<8.00-5.10=2.90>>2.90 dollars.
### Answer: $2.90

Expected answer: 2.90000000000000

Correct? Yes

πŸ”— Problem

Problem: A pirate has found a treasure chest weighing 15.5 kg! But the chest's lock weights 3.8 kg. How much does the actual treasure inside the chest weigh?

Gemma 2B:

Reasoning: The actual treasure weight is 15.5 - 3.8 = <<15.5-3.8=11.7>>11.7 kg.
### Answer: 11.7

Expected answer: 11.7000000000000

Correct? Yes

πŸ”— Follow-up

Problem: The pirate actually counted his treasure wrong and there were 29 kg of treasure instead of 15.5 kg initially. After subtracting the 3.8 kg the lock on the chest weighs, how much does the corrected weight of the treasure inside the chest come to?

Gemma 2B:

### Answer: 11.7

Expected answer: 25.2000000000000

Correct? No

πŸ”— Problem

Problem: The length of Slide A in the park is 16.638 meters while Slide B is shorter measuring 6.45 meters. What is the total length of both slides?

Gemma 2B:

Reasoning: The total length of both slides is the sum of their individual lengths.
Slide A + Slide B = 16.638 + 6.45 = <<16.638+6.45=23.088>>23.088 meters.

Expected answer: 23.0880000000000

Correct? Yes

πŸ”— Problem

Problem: The train ticket for a one-way trip from City A to City B costs $13.868. If a passenger wants to buy a round-trip ticket from City A to City B and back to City A, how much does it cost?

Gemma 2B:

Reasoning: A round-trip ticket would be twice the price of a one-way ticket, so $13.868 x 2 = $27.736.
### Answer: $27.736

Expected answer: 27.7360000000000

Correct? Yes

πŸ”— Follow-up

Problem: Now consider that train tickets for a one-way trip from City A to City B are revised and cost $2 instead of $13.868. If a passenger wants to buy a round-trip ticket from City A to City B and back to City A, what is the new cost?

Gemma 2B:

Reasoning: A round-trip ticket would be twice the price of a one-way ticket, so $2 x 2 = $4.
### Answer: $4

Expected answer: 4

Correct? Yes

πŸ”— Problem

Problem: A box of colored pencils costs $14.93. If Kai buys 2 boxes of colored pencils, how much does he spend?

Gemma 2B:

Reasoning: Kai bought 2 boxes of colored pencils for $14.93 each, which is 2 * 14.93 = $29.86.
### Answer: $29.86

Expected answer: 29.8600000000000

Correct? Yes

πŸ”— Follow-up

Problem: If a box of colored pencils actually costs $6 instead of $14.93, how much would Kai spend to buy 2 boxes?

Gemma 2B:

Reasoning: If a box of colored pencils costs $6 instead of $14.93, then 2 boxes would cost 2 * 6 = $12.
### Answer: $12

Expected answer: 12

Correct? Yes

πŸ”— Problem

Problem: A robot needs precisely 21.3 volts to work perfectly. If there is only 15.433 volts left in the battery, how many more volts are required to make the robot function ideally?

Gemma 2B:

Reasoning: We need to find the difference between the desired voltage (21.3) and the available voltage (15.433).
21.3 - 15.433 = <<21.3-15.433=5.867>>5.867 volts.
Therefore, the robot needs 5.867 more volts to function ideally.

Expected answer: 5.86700000000000

Correct? Yes

πŸ”— Problem

Problem: A jar of turquoise paint costs $7.949, while a jar of navy blue paint costs $20.16. If you have a discount coupon that subtracts $8.405 from your total cost, what is the final price for purchasing both jars of paint?

Gemma 2B:

Reasoning: After the discount, the price of the turquoise paint is 7.949 - 8.405 = <<7.949-8.405=$0.054>>0.054, and the price of the navy blue paint is 20.16 - 8.405 = <<20.16-8.405=$11.755>>11.755.
Therefore, the final price for purchasing both jars of paint is 0.054 + 11.755 = <<0.054+11.755=$11.799>>11.799.

Expected answer: 19.7040000000000

Correct? No

πŸ”— Problem

Problem: A scooter initially travels 3.566 km before making a stop. After the brief stop, it goes on for another 19.63 km. How many kilometers did the scooter travel in total?

Gemma 2B:

Reasoning: The scooter traveled 3.566 km before stopping, and then it traveled another 19.63 km after the stop.
Total distance = 3.566 + 19.63 = <<3.566+19.63=23.19>>23.19 km.

Expected answer: 23.1960000000000

Correct? Yes

πŸ”— Problem

Problem: In a party, John noticed that he has 24.644 ounces of juice left. If he remembers that he started with 19.226 ounces, how many ounces of juice did he have to add?

Gemma 2B:

Reasoning: John started with 19.226 ounces and added 24.644 - 19.226 = <<24.644-19.226=5.42>>5.42 ounces of juice.
### Answer: 5.42

Expected answer: 5.41800000000000

Correct? Yes

πŸ”— Follow-up

Problem: In the same party, after John found out how much juice he added, he decided to add an additional 13.9 ounces of juice. How much juice does he currently have now?

Gemma 2B:

Reasoning: After adding 13.9 ounces, John has 19.226 + 13.9 = <<19.226+13.9=33.126>>33.126 ounces of juice.
### Answer: 33.126

Expected answer: 19.3180000000000

Correct? No

πŸ”— Follow-up

Problem: In the same party, what if John initially had 20 ounces of juice instead of 24.644 ounces before he added more? How much juice would he have added to reach 24.644 ounces?

Gemma 2B:

### Answer: 4.644

Expected answer: 4.64400000000000

Correct? Yes

πŸ”— Problem

Problem: The intensity of the sun's radiation outside of Earth's atmosphere is approximately 19.4 kilowatts per square meter. If you further absorb an additional 2.38 kilowatts per square meter due to a scientific experiment, what is the total intensity of the absorbed solar radiation in kilowatts per square meter?

Gemma 2B:

Reasoning: The total intensity of the absorbed solar radiation is 19.4 + 2.38 = <<19.4+2.38=21.78>>21.78 kilowatts per square meter.
### Answer: 21.78

Expected answer: 21.7800000000000

Correct? Yes

πŸ”— Follow-up

Problem: Suppose in a new experiment, the intensity of the sun's radiation outside of Earth's atmosphere is slightly stronger, and is now 21 kilowatts per square meter. If you further absorb an additional 2.38 kilowatts per square meter due to this experiment, what is the total intensity of the absorbed solar radiation now in kilowatts per square meter?

Gemma 2B:

### Answer: 23.38

Expected answer: 23.3800000000000

Correct? Yes

πŸ”— Problem

Problem: At noon, the sun's temperature is 18.22 million degrees Fahrenheit. But as the afternoon progresses, the temperature drops to 14.558 million degrees Fahrenheit. What is the decrease in the sun's temperature?

Gemma 2B:

Reasoning: The temperature decreased by 18.22 - 14.558 = <<18.22-14.558=3.662>>3.662 million degrees Fahrenheit.
### Answer: 3.662

Expected answer: 3.66200000000000

Correct? Yes

πŸ”— Follow-up

Problem: Following the decrease in the sun's temperature, scientists observe that for every degree decrease, solar energy reaching Earth reduces by 7.6%. How much has the solar energy reduced by, when the sun's temperature dropped from 18.22 million degrees Fahrenheit to 14.558 million degrees Fahrenheit?

Gemma 2B:

### Answer: 7.6%

Expected answer: 27.8312000000000

Correct? No

πŸ”— Follow-up

Problem: Given the previous scenario about the sun's temperature decreasing from 18.22 million degrees Fahrenheit in the afternoon, imagine instead that the temperature reduced more drastically to 6 million degrees. What would then be the decrease in the sun's temperature?

Gemma 2B:

### Answer: 14.268 million degrees Fahrenheit

Expected answer: 12.2200000000000

Correct? No

πŸ”— Problem

Problem: A farmer has a banana tree that typically yields 1.6 kg of bananas. One day, there is an additional 3.443 kg increase in the weight of bananas. How much does the banana tree yield now?

Gemma 2B:

Reasoning: The banana tree now yields 1.6 kg + 3.443 kg = <<1.6+3.443=5.043>>5.043 kg of bananas.
### Answer: 5.043

Expected answer: 5.04300000000000

Correct? Yes

πŸ”— Follow-up

Problem: If instead of the initial yield being 1.6 kg, it was 6 kg and the same 3.443 kg increase occurs, how much would the banana tree yield then?

Gemma 2B:

Reasoning: The banana tree now yields 6 kg + 3.443 kg = <<6+3.443=9.443>>9.443 kg of bananas.
### Answer: 9.443

Expected answer: 9.44300000000000

Correct? Yes

πŸ”— Problem

Problem: A giraffe eats 22.3 pounds of leaves in the morning and 6.1 pounds later in the afternoon. If 7.58 pounds of the eaten leaves were not digested, how many pounds were digested?

Gemma 2B:

Reasoning: 22.3 + 6.1 - 7.58 = <<22.3+6.1-7.58=10.72>>10.72 pounds were digested.

Expected answer: 20.8200000000000

Correct? No