InternLM-Math Base 20B on 3.OA.A.3
Common Core Standard 3.OA.A.3
This standard covers the following:
Use multiplication and division within 100 to solve word problems in situations involving equal groups, arrays, and measurement quantities, e.g., by using drawings and equations with a symbol for the unknown number to represent the problem.
Problem: John has 12 tables. Each table requires 8 chairs. How many chairs does John need to accommodate all the tables?
InternLM-Math Base 20B:
Reasoning: John needs 12*8 = <<12*8=96>>96 chairs to accommodate all the tables. ### Answer: 96
Expected answer: 96
Correct? Yes
Problem: Suppose now, John only has 2 tables instead of 12. Using the same number of chairs per table, how many chairs would John need now to accommodate these tables?
InternLM-Math Base 20B:
Reasoning: John needs 2*8 = <<2*8=16>>16 chairs to accommodate all the tables. ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: In a magical fairy world, there are 4 fairies per house and 3 houses in a cluster. Each fairy creates 5 magic dust particles a day. How many magic dust particles are created in one day by all the fairies in a cluster?
InternLM-Math Base 20B:
Reasoning: There are 4 fairies per house and 3 houses in a cluster. So, there are 4*3 = <<4*3=12>>12 fairies in a cluster. Each fairy creates 5 magic dust particles a day. So, all the fairies in a cluster create 12*5 = <<12*5=60>>60 magic dust particles a day. ### Answer: 60
Expected answer: 60
Correct? Yes
Problem: In the magical fairy world, each magic dust particle created lasts for 1 whole week. How many magic dust particles will be available in a cluster of houses after a week?
InternLM-Math Base 20B:
Reasoning: There are 60 magic dust particles created in a day. So, there will be 60 magic dust particles available in a cluster of houses after a week. ### Answer: 60
Expected answer: 60
Correct? Yes
Problem: Previously, we discovered that each fairy creates 5 magic dust particles a day. But what happens if instead, each fairy creates 8 magic dust particles a day? How many magic dust particles are then created in one day by all the fairies in a cluster?
InternLM-Math Base 20B:
Reasoning: There are 4 fairies per house and 3 houses in a cluster. So, there are 4*3 = <<4*3=12>>12 fairies in a cluster. Each fairy creates 8 magic dust particles a day. So, all the fairies in a cluster create 12*8 = <<12*8=96>>96 magic dust particles a day. ### Answer: 96
Expected answer: 96
Correct? Yes
Problem: Harry has 9 sets of building blocks, each set contains 7 blocks. How many building blocks does Harry have in total?
InternLM-Math Base 20B:
Reasoning: Harry has 9 × 7 = <<9*7=63>>63 blocks in total. ### Answer: 63
Expected answer: 63
Correct? Yes
Problem: In the zoo, there are 12 peacocks in every enclosure. If there are 4 enclosures, how many peacocks are in the zoo in total?
InternLM-Math Base 20B:
Reasoning: There are 12 peacocks in every enclosure. There are 4 enclosures. So, there are 12*4 = <<12*4=48>>48 peacocks in the zoo in total. ### Answer: 48
Expected answer: 48
Correct? Yes
Problem: Let's imagine that instead of 4 enclosures, the zoo originally had 7 enclosures. The same rule was followed: 12 peacocks were placed in each enclosure. How many peacocks would there be in the zoo in this scenario?
InternLM-Math Base 20B:
Reasoning: There are 12 peacocks in every enclosure. There are 7 enclosures. So, there are 12*7 = <<12*7=84>>84 peacocks in the zoo in total. ### Answer: 84
Expected answer: 84
Correct? Yes
Problem: There are 24 children at the park and want to play on the jungle gym. If each jungle gym can accommodate 12 children at a time, how many turns must they take so that everyone gets a chance to play?
InternLM-Math Base 20B:
Reasoning: 24/12 = <<24/12=2>>2 turns. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: Suppose now that there are 24 children at the park, but the jungle gym has been upgraded and can now accommodate 2 children at a time. How many turns would they now need to make sure everyone gets a chance to play?
InternLM-Math Base 20B:
Reasoning: 24/2 = <<24/2=12>>12 turns. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: On the farm, there are 7 groups of chicks. Each group consists of just 1 chick. The farmer then brought 9 times that amount of chicks. How many chicks did the farmer bring?
InternLM-Math Base 20B:
Reasoning: The farmer brought 9*1 = <<9*1=9>>9 chicks. ### Answer: 9
Expected answer: 63
Correct? No
Problem: Mr. Hansen, a very organized teacher, likes to keep ten copies of each handout for his class. If he is preparing a new handout for the next class, how many copies will he make?
InternLM-Math Base 20B:
Reasoning: Mr. Hansen will make 10 copies of the new handout. ### Answer: 10
Expected answer: 10
Correct? Yes
Problem: Following the first problem, let's assume that Mr. Hansen changed his mind and decided to make only four copies of each handout instead of ten for his next class. How many copies of the handout will he now prepare?
InternLM-Math Base 20B:
Reasoning: Mr. Hansen will make 4 copies of the new handout. ### Answer: 4
Expected answer: 4
Correct? Yes
Problem: A snowman has a top hat that is 5 inches tall. The snowman himself, without his hat, is 4 times as tall as his hat. How tall is the snowman without his hat?
InternLM-Math Base 20B:
Reasoning: The snowman is 4*5 = <<4*5=20>>20 inches tall without his hat. ### Answer: 20
Expected answer: 20
Correct? Yes
Problem: In the initial scenario, the snowman without his hat was 4 times as tall as his 5-inch hat, giving us a snowman's height of 20 inches. Now, in our revised scenario, let's consider that the snowman without his hat is instead only 4 times as tall as a 2-inch hat. How tall is the snowman without his hat in this new scenario?
InternLM-Math Base 20B:
Reasoning: The snowman is 4*2 = <<4*2=8>>8 inches tall without his hat. ### Answer: 8
Expected answer: 8
Correct? Yes
Problem: In a video game, Susan collected 45 diamonds. If she divided those diamonds evenly among her 9 game characters, how many diamonds does each character get?
InternLM-Math Base 20B:
Reasoning: Susan divided 45/9 = <<45/9=5>>5 diamonds among her 9 game characters. Each character got 5 diamonds. ### Answer: 5
Expected answer: 5
Correct? Yes
Problem: Suppose initially, Susan had only found 12 diamonds instead of 45. If she still divided those diamonds evenly among her 9 game characters, how many diamonds would each character receive then?
InternLM-Math Base 20B:
Reasoning: Susan divided 12/9 = <<12/9=1.333...>>1.333... diamonds among her 9 game characters. Each character got 1.333... diamonds. ### Answer: 1.333...
Expected answer: 4/3
Correct? No
Problem: Jim has 12 guitar picks. He divided them equally among his 12 bandmates. How many guitar picks did each bandmate get?
InternLM-Math Base 20B:
Reasoning: Jim divided 12 guitar picks among 12 bandmates. 12/12 = <<12/12=1>>1 Each bandmate got 1 guitar pick. ### Answer: 1
Expected answer: 1
Correct? Yes
Problem: After dividing his guitar picks among his bandmates, Jim got a package from a fan. In the package, there were 11 more sets of guitar picks, each set having the same number of picks as each bandmate initially received. How many guitar picks were there in the package?
InternLM-Math Base 20B:
Reasoning: Jim got 11 more sets of guitar picks, each set having the same number of picks as each bandmate initially received. Each bandmate got 1 guitar pick. 11 x 1 = <<11*1=11>>11 There were 11 guitar picks in the package. ### Answer: 11
Expected answer: 11
Correct? Yes
Problem: Considering the scenario when Jim initially had 12 guitar picks but instead of dividing them among 12 bandmates, he divided them among 6 bandmates. How many guitar picks did each bandmate get?
InternLM-Math Base 20B:
Reasoning: Jim divided 12 guitar picks among 6 bandmates. 12/6 = <<12/6=2>>2 Each bandmate got 2 guitar picks. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: Suzie has 5 aquariums. Each aquarium has 12 fish. How many fish does Suzie have in total?
InternLM-Math Base 20B:
Reasoning: Suzie has 5*12 = <<5*12=60>>60 fish in total. ### Answer: 60
Expected answer: 60
Correct? Yes
Problem: After buying the new batch, Suzie realized her first count was wrong. She actually started with 4 aquariums, not 5, before she bought the new fish. With each aquarium having 12 fish, how many fish did Suzie initially have?
InternLM-Math Base 20B:
Reasoning: Suzie had 4*12 = <<4*12=48>>48 fish initially. ### Answer: 48
Expected answer: 48
Correct? Yes
Problem: A pirate found a treasure map. The map indicated that the treasure chest was buried at a spot marked by 2 stones multiplied by 9. How many stones mark the hiding place of the treasure chest?
InternLM-Math Base 20B:
Reasoning: 2 stones multiplied by 9 is 2*9 = <<2*9=18>>18 stones. ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: The pirate, now intrigued, discovered a third map in the larger treasure chest. This map was slightly different, indicating that the next treasure chest was marked by a spot identified not by 2 stones multiplied by 9, but by 3 stones multiplied by 9. How many stones mark the hiding spot of this third treasure chest?
InternLM-Math Base 20B:
Reasoning: 3 stones multiplied by 9 is 3*9 = <<3*9=27>>27 stones. ### Answer: 27
Expected answer: 27
Correct? Yes
Problem: A special type of butterfly lays eggs in batches of 6. If a butterfly lays 4 batches of eggs, how many eggs does she lay in total?
InternLM-Math Base 20B:
Reasoning: A butterfly lays 4*6 = <<4*6=24>>24 eggs in total. ### Answer: 24
Expected answer: 24
Correct? Yes
Problem: After further research, it was discovered that the butterfly was actually laying eggs in batches of 4 instead of 6 as previously thought. If there were still 4 batches of eggs, how many eggs would the butterfly have laid in total then?
InternLM-Math Base 20B:
Reasoning: A butterfly lays 4*4 = <<4*4=16>>16 eggs in total. ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: Anna has 54 feathers she wants to use to stuff some pillows. If each pillow needs 9 feathers, how many pillows can she stuff?
InternLM-Math Base 20B:
Reasoning: Anna can stuff 54/9 = <<54/9=6>>6 pillows. ### Answer: 6
Expected answer: 6
Correct? Yes
Problem: Following from the previous problem, Anna managed to stuff the pillows with the 54 feathers. If each stuffed pillow now needs to be sewn with 8 buttons, how many buttons will Anna need in total?
InternLM-Math Base 20B:
Reasoning: Anna will need 6*8 = <<6*8=48>>48 buttons in total. ### Answer: 48
Expected answer: 48
Correct? Yes
Problem: Tom has 1 strawberry plant. Each strawberry plant can produce 9 strawberries. How many strawberries can Tom's plant produce?
InternLM-Math Base 20B:
Reasoning: Tom's plant can produce 9 strawberries. ### Answer: 9
Expected answer: 9
Correct? Yes
Problem: Continuing from the earlier problem, let's say now Tom decides to increase his strawberry plant count to 5 plants. Given that each plant can produce 9 strawberries without any fertilizer, how many strawberries can all of Tom's plants now produce together?
InternLM-Math Base 20B:
Reasoning: Tom's plants can produce 9*5 = <<9*5=45>>45 strawberries. ### Answer: 45
Expected answer: 45
Correct? Yes
Problem: In a large mansion, each room has 8 fireplaces. If there are 96 fireplaces in total, how many rooms are there in the mansion?
InternLM-Math Base 20B:
Reasoning: There are 96/8 = <<96/8=12>>12 rooms in the mansion. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: Following the last question, if each room in the mansion requires 7 workers to clean all of the fireplaces, how many workers are needed in total to clean all the fireplaces in the mansion?
InternLM-Math Base 20B:
Reasoning: There are 12*7 = <<12*7=84>>84 workers needed in total. ### Answer: 84
Expected answer: 84
Correct? Yes
Problem: John has 10 boxes he needs to transport in a truck. However, his truck can only hold 5 boxes at a time. How many trips does he need to make to transport all the boxes?
InternLM-Math Base 20B:
Reasoning: John needs to make 10/5 = <<10/5=2>>2 trips to transport all the boxes. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: John has finished his trips and transported all the boxes. However, he realizes that each round trip he makes consumes 6 liters of fuel. How many liters of fuel has he used to make all of his trips?
InternLM-Math Base 20B:
Reasoning: John has made 2 round trips, so he has used 2*6 = <<2*6=12>>12 liters of fuel. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: Charlie has a total of 63 toy cars. If he groups them equally into 9 big boxes, how many toy cars will be in each box?
InternLM-Math Base 20B:
Reasoning: Charlie has 63/9 = <<63/9=7>>7 toy cars in each box. ### Answer: 7
Expected answer: 7
Correct? Yes
Problem: Let's reconsider the organization of Charlie's toy cars. This time, instead of grouping them into 9 boxes, imagine he grouped the original 63 toy cars into only 5 boxes. How many toy cars will be in each box now?
InternLM-Math Base 20B:
Reasoning: Charlie has 63/5 = <<63/5=12>>12 toy cars in each box. ### Answer: 12
Expected answer: 63/5
Correct? No
Problem: On the farm, there are 24 hens. Each coop holds 12 hens. How many coops are needed to house all the hens?
InternLM-Math Base 20B:
Reasoning: 24/12 = <<24/12=2>>2 coops are needed to house all the hens. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: After reconsidering, the farmer decides to place the hens into larger coops where each coop can hold 8 hens. How many coops would he need now to house all the hens?
InternLM-Math Base 20B:
Reasoning: 24/8 = <<24/8=3>>3 coops are needed to house all the hens. ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: If 3 large postcards are placed in 1 envelope, how many large postcards are in each envelope?
InternLM-Math Base 20B:
Reasoning: 3 large postcards are placed in 1 envelope. 3/1 = <<3/1=3>>3 large postcards are in each envelope. ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: Following the previous question - if 3 large postcards are placed in 1 envelope, and Macy decided to distribute 6 envelopes of the same kind, how many large postcards did she distribute in total?
InternLM-Math Base 20B:
Reasoning: 3 large postcards are placed in 1 envelope. Macy decided to distribute 6 envelopes of the same kind. 3*6 = <<3*6=18>>18 large postcards did she distribute in total. ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: Following the previous question - suppose that instead of placing 3 large postcards in each envelope, Macy starts to put only 2 large postcards in each envelope. How many large postcards are there in each envelope now?
InternLM-Math Base 20B:
Reasoning: 2 large postcards are placed in 1 envelope. 2/1 = <<2/1=2>>2 large postcards are in each envelope. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: Tommy is going camping and he needs sleeping bags. He took 12 sleeping bags from the storage and he remembered that he needs twice as many. How many sleeping bags does he need in total?
InternLM-Math Base 20B:
Reasoning: Tommy needs 12/2 = <<12/2=6>>6 more sleeping bags. Tommy needs 12+6 = <<12+6=18>>18 sleeping bags in total. ### Answer: 18
Expected answer: 24
Correct? No
Problem: In a new game, Tina earns 3 points per level. If she successfully completes 5 levels, how many total points does she earn?
InternLM-Math Base 20B:
Reasoning: Tina earns 3 points per level. She successfully completes 5 levels. Tina earns 3*5 = <<3*5=15>>15 points. ### Answer: 15
Expected answer: 15
Correct? Yes
Problem: In the same game, Tina decides to convert her points into game coins. If the current rate of conversion is 1 coin per point, how many game coins will she have after the conversion?
InternLM-Math Base 20B:
Reasoning: Tina has 15 points. She converts her points into game coins. Tina has 15 coins. ### Answer: 15
Expected answer: 15
Correct? Yes
Problem: In a video game, Tim needs 4 points to advance to the next level. If there are 9 levels in total, how many points does Tim need in total to finish the game?
InternLM-Math Base 20B:
Reasoning: Tim needs 4 points to advance to the next level. There are 9 levels in total. So, Tim needs 4*9 = <<4*9=36>>36 points in total to finish the game. ### Answer: 36
Expected answer: 36
Correct? Yes
Problem: In the new season of the video game, the number of points needed to advance to the next level increased. Now, Tim needs 4 points to advance each of the 11 levels. What is the total number of points Tim needs now to finish the game?
InternLM-Math Base 20B:
Reasoning: Tim needs 4 points to advance to the next level. There are 11 levels in total. So, Tim needs 4*11 = <<4*11=44>>44 points in total to finish the game. ### Answer: 44
Expected answer: 44
Correct? Yes
Problem: Sophie has a bubble blowing machine. The machine blows bubbles at a rate of 2 bubbles per second. How many bubbles will be blown in one second?
InternLM-Math Base 20B:
Reasoning: 2/1 = <<2/1=2>>2 bubbles will be blown in one second. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: Sophie lets her bubble blowing machine run for another 9 seconds. How many more bubbles does the machine blow?
InternLM-Math Base 20B:
Reasoning: 2*9 = <<2*9=18>>18 bubbles will be blown in 9 seconds. ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: Sophie changes the setting on her bubble blowing machine so that it now blows 7 bubbles per second instead of 2. How many bubbles will now be blown in one second?
InternLM-Math Base 20B:
Reasoning: 7/1 = <<7/1=7>>7 bubbles will be blown in one second. ### Answer: 7
Expected answer: 7
Correct? Yes
Problem: Farmer Mike has 6 cows. Each of them gives 12 liters of milk every day. How many liters of milk does Farmer Mike get in a day?
InternLM-Math Base 20B:
Reasoning: Farmer Mike gets 6*12 = <<6*12=72>>72 liters of milk in a day. ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: Farmer Mike decided to buy an additional cow, increasing his herd to 7 cows. If each cow still produces 12 liters of milk every day, how many liters of milk does Farmer Mike get in a day now?
InternLM-Math Base 20B:
Reasoning: Farmer Mike gets 7*12 = <<7*12=84>>84 liters of milk in a day. ### Answer: 84
Expected answer: 84
Correct? Yes
Problem: John has 9 sunglasses in a line. He decided to divide his collection into equal parts. If each part contains 9 sunglasses, how many parts would he get?
InternLM-Math Base 20B:
Reasoning: John would get 9/9 = <<9/9=1>>1 parts. ### Answer: 1
Expected answer: 1
Correct? Yes
Problem: After assigning sunglasses to the group, John considers dividing his original collection differently. If he divides the initial 9 sunglasses by 1 instead of 9, how many sunglasses would he have in each group?
InternLM-Math Base 20B:
Reasoning: John would have 9/1 = <<9/1=9>>9 sunglasses in each group. ### Answer: 9
Expected answer: 9
Correct? Yes
Problem: A rocket scientist needs to calculate the fuel consumption of his rocket. Each second, the rocket uses 9 units of fuel. After 11 seconds of flight, how much fuel has been consumed?
InternLM-Math Base 20B:
Reasoning: The rocket used 9×11 = <<9*11=99>>99 units of fuel. ### Answer: 99
Expected answer: 99
Correct? Yes
Problem: In the park, there are 4 swings available. Every swing can seat 3 children. How many children can the swings in the park seat altogether?
InternLM-Math Base 20B:
Reasoning: 4 swings can seat 3 children each. 4*3 = <<4*3=12>>12 children can be seated altogether. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: In reconsideration, the first park actually only has 1 swing that can seat 3 children, not 4 swings. Given this new information, how many children can the swings in the first park seat now?
InternLM-Math Base 20B:
Reasoning: 1 swing can seat 3 children. 1*3 = <<1*3=3>>3 children can be seated altogether. ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: There are 3 magical fairies in Fairyland. Each fairy has a unique ability to create triplets of herself. How many fairies will there be after each of them uses their ability?
InternLM-Math Base 20B:
Reasoning: Each fairy creates 3 fairies. So, there will be 3*3 = <<3*3=9>>9 fairies after each of them uses their ability. ### Answer: 9
Expected answer: 9
Correct? Yes
Problem: James, a songwriter, loves to include the word "love" in his songs. In one song, he mentioned the word "love" 4 times in each verse. How many times did he mention "love" if the song has 3 verses?
InternLM-Math Base 20B:
Reasoning: James mentioned the word "love" 4*3 = <<4*3=12>>12 times in the song. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: Following the last problem, after James wrote his song, he decided to dedicate four performances to his beloved. In each performance, he sings the song once. How many times will the word "love" be mentioned if he sings the song in all four performances?
InternLM-Math Base 20B:
Reasoning: James will sing the song 4 times in each performance. He will sing the song 4*4 = <<4*4=16>>16 times in all four performances. He will mention the word "love" 16*12 = <<16*12=192>>192 times in all four performances. ### Answer: 192
Expected answer: 48
Correct? No
Problem: Continuing from the previous scenarios, James decided to rewrite his song. Now, he included the word "love" 4 times in each verse, but this time he expanded his song to include 10 verses. How many times does he mention "love" in this new version of his song?
InternLM-Math Base 20B:
Reasoning: James mentioned the word "love" 4*10 = <<4*10=40>>40 times in the new version of his song. ### Answer: 40
Expected answer: 40
Correct? Yes
Problem: Mark has 48 apps on his phone. He likes to organize his apps into folders, and he can fit exactly 8 apps in each folder. How many folders does he need to organize all of his apps?
InternLM-Math Base 20B:
Reasoning: Mark needs 48/8 = <<48/8=6>>6 folders to organize all of his apps. ### Answer: 6
Expected answer: 6
Correct? Yes
Problem: Mark realized that he could fit more apps into each folder. If he reorganizes his apps so that each folder contains 6 apps instead of 8, how many folders will he need now to store all of his 48 apps?
InternLM-Math Base 20B:
Reasoning: Mark needs 48/6 = <<48/6=8>>8 folders to organize all of his apps. ### Answer: 8
Expected answer: 8
Correct? Yes
Problem: If Johnny wants to distribute candies to his friends at school and he decides to give each friend 12 candies, and there are 3 friends, how many candies does he need in total?
InternLM-Math Base 20B:
Reasoning: Johnny needs 3*12 = <<3*12=36>>36 candies in total. ### Answer: 36
Expected answer: 36
Correct? Yes
Problem: After distributing candies to his friends at school, Johnny decides to double the amount of candies he gave for the next day. How many candies will he need in total for the next day?
InternLM-Math Base 20B:
Reasoning: Johnny needs 2*36 = <<2*36=72>>72 candies in total for the next day. ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: Tommy has a racetrack that he plans to race his toy cars on. If he can race 10 cars in total and he races 5 cars at a time, how many turns does it take for him to race all his cars?
InternLM-Math Base 20B:
Reasoning: Tommy can race 5 cars at a time. He can race 10 cars in total. So, he can race 2 times. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: Following the previous scenario, Tommy decided to organize multiple rounds of races. If he performs 8 rounds of races, with each round involving the same number of turns as before, how many turns in total will he need to complete all the rounds?
InternLM-Math Base 20B:
Reasoning: Tommy can race 5 cars at a time. He can race 10 cars in total. So, he can race 2 times. ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: Sally has 40 feathers from her chickens. If she arranged the feathers in groups of 10, how many groups would she have?
InternLM-Math Base 20B:
Reasoning: 40/10 = <<40/10=4>>4 Sally would have 4 groups. ### Answer: 4
Expected answer: 4
Correct? Yes
Problem: Sally sorts her 40 chicken feathers into groups of 10. Then, she decided to double the number of groups. How many groups does she have now?
InternLM-Math Base 20B:
Reasoning: 40/10 = <<40/10=4>>4 Sally has 4 groups of 10 feathers. Sally doubles the number of groups to 8. ### Answer: 8
Expected answer: 8
Correct? Yes
Problem: Sally originally thought she had sorted her 40 chicken feathers into groups of 10, but then she realized she actually sorted them into groups of 11 instead. How many groups does she have now?
InternLM-Math Base 20B:
Reasoning: 40/11 = <<40/11=3.636...>>3.636... Sally has 3 groups. ### Answer: 3
Expected answer: 40/11
Correct? No
Problem: Fairy Lily is 1 inch tall. However, when she uses her magical fairy dust, she can become 11 times her original size. How tall is Fairy Lily when she uses her magical dust?
InternLM-Math Base 20B:
Reasoning: 1*11 = <<1*11=11>>11 Fairy Lily is 11 inches tall when she uses her magical dust. ### Answer: 11
Expected answer: 11
Correct? Yes
Problem: After using her magical dust to grow 11 times her original size, Fairy Lily decides to add another element to her spells. She casts a spell that multiplies her height by 7. How tall is Fairy Lily now?
InternLM-Math Base 20B:
Reasoning: 11*7 = <<11*7=77>>77 Fairy Lily is 77 inches tall now. ### Answer: 77
Expected answer: 77
Correct? Yes
Problem: In a different scenario, if Fairy Lily only grows to 6 times her original size rather than 11 times using her magical dust, how tall would she become then?
InternLM-Math Base 20B:
Reasoning: 1*6 = <<1*6=6>>6 Fairy Lily is 6 inches tall when she uses her magical dust. ### Answer: 6
Expected answer: 6
Correct? Yes
Problem: In a beehive, one female bee can produce 5 new bees every day. How many bees would she produce in 1 day?
InternLM-Math Base 20B:
Reasoning: 1 bee produces 5 bees every day. 1 bee produces 5 bees every day. ### Answer: 5
Expected answer: 5
Correct? Yes
Problem: Following the previous problem, if this female bee continues to produce bees at the same rate, how many bees will she have produced after 11 days?
InternLM-Math Base 20B:
Reasoning: 1 bee produces 5 bees every day. 1 bee produces 5 bees every day. ### Answer: 55
Expected answer: 55
Correct? Yes
Problem: Following the previous problems, consider if the female bee instead produced new bees at a slower rate, making only 5 bees every 3 days. How many bees would she produce in one day at this new rate?
InternLM-Math Base 20B:
Reasoning: 1 bee produces 5 bees every 3 days. 1 bee produces 5 bees every 3 days. ### Answer: 5/3
Expected answer: 5/3
Correct? Yes
Problem: Thomas has 35 piano sheets in his music stand. If he wants to evenly distribute his music sheets into 7 piano books, how many sheets will each book have?
InternLM-Math Base 20B:
Reasoning: Thomas will have 35/7 = <<35/7=5>>5 sheets in each book. ### Answer: 5
Expected answer: 5
Correct? Yes
Problem: After arranging his music sheets into the piano books, Thomas decided to purchase 8 more books, each with the same number of sheets as the books he has now. How many more piano sheets did he buy?
InternLM-Math Base 20B:
Reasoning: Thomas bought 8*5 = <<8*5=40>>40 sheets. ### Answer: 40
Expected answer: 40
Correct? Yes
Problem: Instead, suppose originally Thomas had 9 piano sheets. If he evenly distributes his music sheets into 7 piano books as before, how many sheets will each book have now?
InternLM-Math Base 20B:
Reasoning: Thomas will have 9/7 = <<9/7=1>>1 sheet in each book. ### Answer: 1
Expected answer: 9/7
Correct? No
Problem: Mom baked 2 batches of cookies. Each batch contains 8 cookies. How many cookies did mom bake in total?
InternLM-Math Base 20B:
Reasoning: 2*8 = <<2*8=16>>16 ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: Earth has 3 natural satellites. If the number of moon rocks collected each year is triple the total number of these satellites, how many moon rocks would be collected in one year?
InternLM-Math Base 20B:
Reasoning: The number of moon rocks collected each year is 3*3 = <<3*3=9>>9. ### Answer: 9
Expected answer: 9
Correct? Yes
Problem: Following the previous scenario, if each moon rock collected in a year is stored in a separate storage bin, how many storage bins would be needed to store all the rocks collected in one year?
InternLM-Math Base 20B:
Reasoning: 9 storage bins would be needed to store all the rocks collected in one year. ### Answer: 9
Expected answer: 9
Correct? Yes
Problem: Continuing from the previous scenario, suppose that instead of 3, the Earth had 5 natural satellites. In this case, if the number of moon rocks collected each year is triple the total number of these satellites, how many moon rocks would be collected in one year?
InternLM-Math Base 20B:
Reasoning: The number of moon rocks collected each year is 5*3 = <<5*3=15>>15. ### Answer: 15
Expected answer: 15
Correct? Yes
Problem: Doctor Thomas needs to visit 10 patients. He spends 5 minutes with each patient. How many minutes does he spend with all of his patients?
InternLM-Math Base 20B:
Reasoning: Doctor Thomas spends 10*5 = <<10*5=50>>50 minutes with all of his patients. ### Answer: 50
Expected answer: 50
Correct? Yes
Problem: After visiting his patients, Doctor Thomas then spends twice the amount of time he spent with his patients on paperwork. How many minutes does he spend on paperwork?
InternLM-Math Base 20B:
Reasoning: Doctor Thomas spends 2*10*5 = <<2*10*5=100>>100 minutes on paperwork. ### Answer: 100
Expected answer: 100
Correct? Yes
Problem: In a different scenario, Doctor Thomas spends 6 minutes with each patient instead of 5 minutes. If he still has the same number of patients to visit, how many minutes will he spend with all his patients?
InternLM-Math Base 20B:
Reasoning: Doctor Thomas spends 10*6 = <<10*6=60>>60 minutes with all of his patients. ### Answer: 60
Expected answer: 60
Correct? Yes
Problem: Jerry was thinking of purchasing new pants and he noticed a special offer. The shop was selling 11 pants for $55. After calculating the price for each pant, he decided to buy 12. How much would he spend?
InternLM-Math Base 20B:
Reasoning: The price of 12 pants is 12/11 = <<12/11=1.0909090909090909>>1.0909090909090909 times the price of 11 pants. The price of 12 pants is 12/11 * 55 = <<12/11*55=60.90909090909091>>60.90909090909091 dollars. ### Answer: 60.90909090909091
Expected answer: 60
Correct? No
Problem: Molly has 8 bottles of apple juice. She decides to multiply her collection of apple juice bottles by the same number she has. How many bottles of apple juice does Molly have now?
InternLM-Math Base 20B:
Reasoning: Molly has 8*8 = <<8*8=64>>64 bottles of apple juice. ### Answer: 64
Expected answer: 64
Correct? Yes
Problem: Molly later decided that 8 bottles of apple juice were too many. So, she reduced her collection to 6 bottles. Then, she once again decided to increase her apple juice collection by multiplying the number of bottles she has by the same number. How many bottles of apple juice does Molly have now?
InternLM-Math Base 20B:
Reasoning: Molly has 6*6 = <<6*6=36>>36 bottles of apple juice. ### Answer: 36
Expected answer: 36
Correct? Yes
Problem: There are few craters on one of the sections of the moon. If that section is divided into 8 equal parts and we count 32 craters in total, how many craters are there in each part?
InternLM-Math Base 20B:
Reasoning: 32/8 = <<32/8=4>>4 There are 4 craters in each part. ### Answer: 4
Expected answer: 4
Correct? Yes
Problem: Let's think back to the moon section with craters we discussed earlier. Suppose instead that the moon's section was divided into 5 equal parts with a total of 32 craters. How many craters would there be in each part then?
InternLM-Math Base 20B:
Reasoning: 32/5 = <<32/5=6.4>>6.4 There are 6.4 craters in each part. ### Answer: 6.4
Expected answer: 32/5
Correct? Yes
Problem: There are 4 monkeys in the jungle. Each monkey has 7 bananas. How many bananas do the monkeys have in total?
InternLM-Math Base 20B:
Reasoning: 4*7 = <<4*7=28>>28 ### Answer: 28
Expected answer: 28
Correct? Yes
Problem: Let's imagine that originally there were 9 monkeys instead of 4. If each monkey has 7 bananas, how many bananas do all the monkeys have in total now?
InternLM-Math Base 20B:
Reasoning: 9*7 = <<9*7=63>>63 ### Answer: 63
Expected answer: 63
Correct? Yes
Problem: Fiona has a block of cheese that weighs 32 ounces. If she wants to divide it into equal pieces which each weigh 4 ounces, how many pieces of cheese will she have?
InternLM-Math Base 20B:
Reasoning: Fiona will have 32/4 = <<32/4=8>>8 pieces of cheese. ### Answer: 8
Expected answer: 8
Correct? Yes
Problem: Fiona later found a smaller block of cheese that weighs 32 ounces. If she wants to cut this one into equal pieces which each weigh 9 ounces, how many pieces of cheese will she get from this block?
InternLM-Math Base 20B:
Reasoning: Fiona will have 32/9 = <<32/9=3.5555555555555556>>3.5555555555555556 pieces of cheese. ### Answer: 3.5555555555555556
Expected answer: 32/9
Correct? No
Problem: Bob has 6 cups. If he wants to fill each cup with 1 glass of milk, how many glasses of milk does he need?
InternLM-Math Base 20B:
Reasoning: Bob needs 6/1 = <<6/1=6>>6 glasses of milk. ### Answer: 6
Expected answer: 6
Correct? Yes
Problem: Bob just realized he only has 2 cups instead of 6. If he still wants to fill each cup with 1 glass of milk, how many glasses of milk does he need now?
InternLM-Math Base 20B:
Reasoning: Bob needs 2/1 = <<2/1=2>>2 glasses of milk. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: In the zoo, there are 36 new-born rabbits divided evenly into 9 cages. Each cage is then assigned to two caretakers. How many caretakers are assigned per cage?
InternLM-Math Base 20B:
Reasoning: There are 9 cages, and each cage is assigned to two caretakers. Therefore, there are 9*2 = <<9*2=18>>18 caretakers assigned per cage. ### Answer: 18
Expected answer: 8
Correct? No
Problem: Farmer Brown has made 42 blocks of cheese. Each wheel of cheese requires 7 blocks to make. How many whole wheels of cheese can he make with the current blocks he has?
InternLM-Math Base 20B:
Reasoning: Farmer Brown can make 42/7 = <<42/7=6>>6 whole wheels of cheese. ### Answer: 6
Expected answer: 6
Correct? Yes
Problem: After making the cheese wheels, Farmer Brown decides to double his production in order to have enough for the upcoming village fair. Based on his current production rate, how many cheese wheels will he have after doubling his output?
InternLM-Math Base 20B:
Reasoning: Farmer Brown will have 2*6 = <<2*6=12>>12 cheese wheels after doubling his output. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: John has a square kite. Each side of the kite is 4 feet long. What is the total length of two sides of the kite in feet?
InternLM-Math Base 20B:
Reasoning: The total length of two sides of the kite is 2*4 = <<2*4=8>>8 feet. ### Answer: 8
Expected answer: 8
Correct? Yes
Problem: John wants to make another identical kite. How many feet of string will he need for the two sides of both kites?
InternLM-Math Base 20B:
Reasoning: John will need 2*4*2 = <<2*4*2=16>>16 feet of string for the two sides of both kites. ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: Suppose that John decides to make a very small kite with each side only 1 foot long. What is the total length of two sides of this smaller kite in feet?
InternLM-Math Base 20B:
Reasoning: The total length of two sides of the kite is 2*1 = <<2*1=2>>2 feet. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: Anna has 4 bags of candy, each containing 3 candies. How many candies does she have in total?
InternLM-Math Base 20B:
Reasoning: Anna has 4 bags of candy, each containing 3 candies. She has 4*3 = <<4*3=12>>12 candies in total. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: In the previous situation, what if Anna initially had only 1 bag of candy, each containing 3 candies? How many candies would she have initially?
InternLM-Math Base 20B:
Reasoning: Anna has 1 bag of candy, each containing 3 candies. She has 1*3 = <<1*3=3>>3 candies in total. ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: A garden has 6 patches of flowers. Each patch attracts 3 butterflies. How many butterflies are there in total in the garden?
InternLM-Math Base 20B:
Reasoning: 6*3 = <<6*3=18>>18 butterflies are in the garden. ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: In a similar situation, imagine if initially there were 8 patches of flowers instead of 6 and each patch still attracts 3 butterflies. How many butterflies would there be in total then?
InternLM-Math Base 20B:
Reasoning: 8*3 = <<8*3=24>>24 butterflies are in the garden. ### Answer: 24
Expected answer: 24
Correct? Yes
Problem: Sophia is having a party. She wants to divide 72 cookies evenly among her 8 friends, giving them an equal number. She then decides to gift each friend 5 times the amount they initially received. How many cookies will each friend get in total?
InternLM-Math Base 20B:
Reasoning: Each friend will get 5*<<72/8=9>>9 = <<5*9=45>>45 cookies in total. ### Answer: 45
Expected answer: 45
Correct? Yes
Problem: Sophia revisited her party plans and decided to invite two more friends, resulting in a total of 10 friends. Now she wants to divide the same 72 cookies evenly among all her friends, and again, give each friend 5 times the initial amount. How many cookies will each friend get in total now?
InternLM-Math Base 20B:
Reasoning: Each friend will get 5*<<72/10=7.2>>7.2 = <<5*7.2=36>>36 cookies in total. ### Answer: 36
Expected answer: 36
Correct? Yes
Problem: John has 3 cameras. Each camera can take 1 picture per second. If John uses all his cameras to take pictures for 5 seconds, how many pictures will he have taken in total?
InternLM-Math Base 20B:
Reasoning: John has 3 cameras. Each camera can take 1 picture per second. If John uses all his cameras to take pictures for 5 seconds, he will have taken 3*5 = <<3*5=15>>15 pictures in total. ### Answer: 15
Expected answer: 15
Correct? Yes
Problem: Tommy has 3 boxes of toys. Each box contains 9 toys. How many toys does Tommy have in total?
InternLM-Math Base 20B:
Reasoning: Tommy has 9+9+9 = <<9+9+9=27>>27 toys in total. ### Answer: 27
Expected answer: 27
Correct? Yes
Problem: Tommy realized he made a mistake when counting his toys. Instead of having 3 boxes of toys, he actually had 10 boxes. Each box still contains 9 toys. Now, how many toys does Tommy really have?
InternLM-Math Base 20B:
Reasoning: Tommy has 9+9+9+9+9+9+9+9+9+9 = <<9+9+9+9+9+9+9+9+9+9=90>>90 toys in total. ### Answer: 90
Expected answer: 90
Correct? Yes
Problem: Joanna has a clothing store and packs 10 shirts into 5 boxes. How many shirts does each box contain?
InternLM-Math Base 20B:
Reasoning: 10/5 = <<10/5=2>>2 shirts per box. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: What if Joanna originally had 7 shirts instead of 10 and she still wants to distribute them evenly into 5 boxes? How many shirts will each box contain then?
InternLM-Math Base 20B:
Reasoning: 7/5 = <<7/5=1.4>>1.4 shirts per box. ### Answer: 1.4
Expected answer: 7/5
Correct? Yes
Problem: Jack has 9 scooters. Harry, seeing Jack's love for scooters, decided to give him seven times as many scooters for his birthday. How many scooters did Harry give to Jack?
InternLM-Math Base 20B:
Reasoning: Jack has 9 scooters. Harry gave him 9*7 = <<9*7=63>>63 scooters. ### Answer: 63
Expected answer: 63
Correct? Yes
Problem: Suppose instead of having 9 scooters originally, Jack started with 6 scooters. How many scooters would Harry give to Jack now, following Harry's original plan of giving seven times as many scooters as Jack initially had?
InternLM-Math Base 20B:
Reasoning: Jack has 6 scooters. Harry gave him 6*7 = <<6*7=42>>42 scooters. ### Answer: 42
Expected answer: 42
Correct? Yes
Problem: There are 7 hours on a clock. Each hour has 4 quarters. How many quarters are there in three clocks?
InternLM-Math Base 20B:
Reasoning: There are 3*7 = <<3*7=21>>21 hours in three clocks. There are 3*7*4 = <<3*7*4=84>>84 quarters in three clocks. ### Answer: 84
Expected answer: 84
Correct? Yes
Problem: Liam has 35 scoops of ice cream. If he puts an equal amount of ice cream into 5 cones, how many scoops of ice cream does each cone get?
InternLM-Math Base 20B:
Reasoning: Liam puts 35/5 = <<35/5=7>>7 scoops of ice cream into each cone. ### Answer: 7
Expected answer: 7
Correct? Yes
Problem: In the previous problem, we had 35 scoops of ice cream to start with. But what if we start with only 8 scoops of ice cream, and we are still trying to divide it equally into 5 cones? How many scoops of ice cream would each cone hold then?
InternLM-Math Base 20B:
Reasoning: We have 8/5 = <<8/5=1.6>>1.6 scoops of ice cream in each cone. ### Answer: 1.6
Expected answer: 8/5
Correct? Yes
Problem: Billy has 8 toy trains at his house. He went to a train festival and got 9 times more trains than he originally had. How many trains did Billy get at the festival?
InternLM-Math Base 20B:
Reasoning: Billy got 8*9 = <<8*9=72>>72 trains at the festival. ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: If Billy originally had 8 toy trains, but at the train festival, he was able to gather 8 times more trains than he originally had instead of 9, how many trains did Billy get at the festival?
InternLM-Math Base 20B:
Reasoning: Billy got 8*8 = <<8*8=64>>64 trains at the festival. ### Answer: 64
Expected answer: 64
Correct? Yes
Problem: A librarian decided to arrange books on a shelf. She placed 8 books in a row and made sure every row had the same number of books. How many books were there if the arrangement was square (i.e., the same number of rows as there were books in a row)?
InternLM-Math Base 20B:
Reasoning: The librarian placed 8 books in a row. She made sure every row had the same number of books. The arrangement was square. The number of rows is the same as the number of books in a row. The number of books in a row is 8. The number of rows is 8. The number of books is 8*8 = <<8*8=64>>64. ### Answer: 64
Expected answer: 64
Correct? Yes
Problem: Following the previous problem about the librarian, let's consider a different scenario. This time, she decides to arrange a smaller square of books with only 4 books in a row. Each row still has the same number of books. So, how many books does she need for this smaller square arrangement?
InternLM-Math Base 20B:
Reasoning: The librarian decided to arrange a smaller square of books. She placed 4 books in a row. Each row has the same number of books. The number of books in a row is 4. The number of rows is 4. The number of books is 4*4 = <<4*4=16>>16. ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: Lisa had 10 yards of fabric. If it takes 1 yard of fabric to make a skirt, how many skirts can Lisa make?
InternLM-Math Base 20B:
Reasoning: Lisa can make 10/1 = <<10/1=10>>10 skirts. ### Answer: 10
Expected answer: 10
Correct? Yes
Problem: Sarah receives 12 phone calls every day on her work phone. But, she only answers a quarter of those phone calls. How many phone calls does she answer a day?
InternLM-Math Base 20B:
Reasoning: Sarah answers 12/4 = <<12/4=3>>3 phone calls a day. ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: Following up on the previous problem, if for each phone call Sarah answered, she received 11 more calls as a response, how many additional calls did she receive in a day?
InternLM-Math Base 20B:
Reasoning: Sarah received 3*11 = <<3*11=33>>33 additional calls a day. ### Answer: 33
Expected answer: 33
Correct? Yes
Problem: Melanie is planning for a camping trip and she needs 3 sleeping bags for each of her 4 friends. How many sleeping bags does Melanie need in total?
InternLM-Math Base 20B:
Reasoning: Melanie needs 3*4 = <<3*4=12>>12 sleeping bags in total. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: Suppose Melanie originally planned to bring 3 sleeping bags for each of her 6 friends instead of 4, for the camping trip. How many sleeping bags would Melanie need in total for the camping trip now?
InternLM-Math Base 20B:
Reasoning: Melanie needs 3*6 = <<3*6=18>>18 sleeping bags in total. ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: Johnny has 3 times the amount of snowballs that Billy does. If Billy has 6 snowballs, how many snowballs does Johnny have?
InternLM-Math Base 20B:
Reasoning: 3*6 = <<3*6=18>>18 ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: Consider now that initially, Johnny had 3 times the amount of snowballs that Billy does, not 5 times. If Billy still has 11 snowballs, how many snowballs does Johnny have now?
InternLM-Math Base 20B:
Reasoning: 3*11 = <<3*11=33>>33 ### Answer: 33
Expected answer: 33
Correct? Yes
Problem: In a game, each star is equivalent to 5 points. If Tom collected 1 star, how many points does he have?
InternLM-Math Base 20B:
Reasoning: 1 star = 5 points. Tom has 1*5 = <<1*5=5>>5 points. ### Answer: 5
Expected answer: 5
Correct? Yes
Problem: Tom decided to play more of the game and managed to collect 4 more stars. Considering that each star is equivalent to 5 points, how many additional points has he earned now?
InternLM-Math Base 20B:
Reasoning: 4 stars = 4*5 = <<4*5=20>>20 points. Tom has earned 20 additional points. ### Answer: 20
Expected answer: 20
Correct? Yes
Problem: In the game, what if initially each star was equivalent to 7 points instead of 5? If Tom collected 1 star as before, how many points would he have now?
InternLM-Math Base 20B:
Reasoning: 1 star = 7 points. Tom has 1*7 = <<1*7=7>>7 points. ### Answer: 7
Expected answer: 7
Correct? Yes
Problem: Captain Jack has 4 cannons on his pirate ship. If each cannon fires 12 cannonballs, how many cannonballs were fired in total?
InternLM-Math Base 20B:
Reasoning: Captain Jack has 4 cannons, and each cannon fires 12 cannonballs. 4*12 = <<4*12=48>>48 cannonballs were fired in total. ### Answer: 48
Expected answer: 48
Correct? Yes
Problem: Given that Captain Jack actually had 4 cannons, but each can fire only 3 cannonballs, how many cannonballs were fired in total now?
InternLM-Math Base 20B:
Reasoning: Captain Jack has 4 cannons, and each cannon fires 3 cannonballs. 4*3 = <<4*3=12>>12 cannonballs were fired in total. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: Emma has a pack of 10 colored pencils. She wants to have as many colored pencils as the square of the number she currently has. How many colored pencils will she have then?
InternLM-Math Base 20B:
Reasoning: Emma will have 10^2 = <<10^2=100>>100 colored pencils. ### Answer: 100
Expected answer: 100
Correct? Yes
Problem: Now consider if Emma had started with a pack of only 4 colored pencils instead. If she still wants to have as many colored pencils as the square of the number she currently has, how many colored pencils will she have then?
InternLM-Math Base 20B:
Reasoning: Emma will have 4^2 = <<4^2=16>>16 colored pencils. ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: Emily had 70 cookies. She decided to pack them in bags with each bag containing 7 cookies. After getting the number of bags, she decided to multiply it by 6 for a camping trip. How many cookies does she need for her intended number of sleeping bag sets?
InternLM-Math Base 20B:
Reasoning: Emily had 70/7 = <<70/7=10>>10 bags of cookies. She needs 10*6 = <<10*6=60>>60 bags of cookies for her intended number of sleeping bag sets. ### Answer: 60
Expected answer: 60
Correct? Yes
Problem: Let's consider a different scenario. Emily originally had 9 cookies instead of 70. She still wants to pack them in bags, with each bag containing 7 cookies. She still wants to multiply the number of bags by 6 for a camping trip. How many cookies does she need now for her intended number of sleeping bag sets?
InternLM-Math Base 20B:
Reasoning: Emily had 9/7 = <<9/7=1.2857142857142858>>1.2857142857142858 bags of cookies. She needs 1.2857142857142858*6 = <<1.2857142857142858*6=7.714285714285714>>7.714285714285714 bags of cookies for her intended number of sleeping bag sets. ### Answer: 7.714285714285714
Expected answer: 54/7
Correct? Yes
Problem: Captain Redbeard has 6 cannons on one side of his pirate ship. Each cannon fires 4 cannonballs at a time when the ship goes into battle. During a sea fight, with one shot from each of the cannons on one side of the ship, how many cannonballs are fired in total?
InternLM-Math Base 20B:
Reasoning: Captain Redbeard has 6 cannons on one side of his pirate ship. Each cannon fires 4 cannonballs at a time when the ship goes into battle. During a sea fight, with one shot from each of the cannons on one side of the ship, how many cannonballs are fired in total?
Expected answer: 24
Correct? Yes
Problem: In a different battle, Captain Redbeard decided to increase his firepower and loaded each cannon with 11 cannonballs. With one shot from each of the 6 cannons on one side of his ship, how many cannonballs would be fired in total from that side?
InternLM-Math Base 20B:
Reasoning: In a different battle, Captain Redbeard decided to increase his firepower and loaded each cannon with 11 cannonballs. With one shot from each of the 6 cannons on one side of his ship, how many cannonballs would be fired in total from that side?
Expected answer: 66
Correct? Yes
Problem: A magical unicorn walks 72 miles every day. If it takes the unicorn 12 hours to cover that distance. How many miles does the unicorn cover every hour?
InternLM-Math Base 20B:
Reasoning: The unicorn covers 72/12 = <<72/12=6>>6 miles every hour. ### Answer: 6
Expected answer: 6
Correct? Yes
Problem: In a magical turn of events, the unicorn's speed is tripled for an enchanting hour. Given the unicorn's new pace, how many miles would it cover in that enchanted hour?
InternLM-Math Base 20B:
Reasoning: The unicorn's new speed is 6*3 = <<6*3=18>>18 miles per hour. The unicorn covers 18*1 = <<18*1=18>>18 miles in that enchanted hour. ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: Sue has 3 potato plants and each plant yields 10 potatoes. How many potatoes does Sue have in total?
InternLM-Math Base 20B:
Reasoning: Sue has 3*10 = <<3*10=30>>30 potatoes in total. ### Answer: 30
Expected answer: 30
Correct? Yes
Problem: Suppose that Sue originally planted 3 potato plants instead of 10, and each of those plants still produced 3 potatoes. How many potatoes would Sue have harvested from her original planting?
InternLM-Math Base 20B:
Reasoning: Sue would have harvested 3*3 = <<3*3=9>>9 potatoes. ### Answer: 9
Expected answer: 9
Correct? Yes
Problem: An astronaut walks a distance of 20 kilometers per day on the lunar surface. If they decide to only walk for 1/5 of the day, how many kilometers do they cover?
InternLM-Math Base 20B:
Reasoning: The astronaut walks 20/5 = <<20/5=4>>4 kilometers per hour. They walk 4*1 = <<4*1=4>>4 kilometers in 1/5 of the day. ### Answer: 4
Expected answer: 4
Correct? Yes
Problem: Following up on the previous problem, let's say on a particular day, the astronaut decides to increase their walking duration from 1/5 of a day to 12/5 of a day. How many kilometers would they cover on that day?
InternLM-Math Base 20B:
Reasoning: The astronaut walks 20/5 = <<20/5=4>>4 kilometers per hour. They walk 4*12 = <<4*12=48>>48 kilometers in 12/5 of the day. ### Answer: 48
Expected answer: 48
Correct? Yes
Problem: In a new scenario, let's say the astronaut now walks a distance of 20 kilometers per day on the lunar surface but decides to walk for only 1/6 of the day instead of 1/5. How many kilometers would they cover in this case?
InternLM-Math Base 20B:
Reasoning: The astronaut walks 20/6 = <<20/6=3.3333333333333335>>3.3333333333333335 kilometers per hour. They walk 3.3333333333333335*1 = <<3.3333333333333335*1=3.3333333333333335>>3.3333333333333335 kilometers in 1/6 of the day. ### Answer: 3.3333333333333335
Expected answer: 10/3
Correct? Yes
Problem: Mr. Lemon has 10 lemons and he wants to evenly distribute them into 5 boxes. How many lemons will there be in each box?
InternLM-Math Base 20B:
Reasoning: 10/5 = <<10/5=2>>2 There will be 2 lemons in each box. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: Mr. Lemon decides to add 2 more lemons to each box, because he wants to share more lemons with his friends. How many lemons will there be in each box now?
InternLM-Math Base 20B:
Reasoning: 2+2 = <<2+2=4>>4 There will be 4 lemons in each box. ### Answer: 4
Expected answer: 4
Correct? Yes
Problem: After some thought, Mr. Lemon considers distributing the ten lemons among six boxes instead of five. How many lemons would there be in each box if he decides to distribute them in this way?
InternLM-Math Base 20B:
Reasoning: 10/6 = <<10/6=1.6666666666666667>>1.6666666666666667 There will be 1.6666666666666667 lemons in each box. ### Answer: 1.6666666666666667
Expected answer: 5/3
Correct? Yes
Problem: A helicopter pad can hold 4 helicopters at a time. The city has decided to build 11 new helicopter pads. How many helicopters can all of the helicopter pads hold when combined?
InternLM-Math Base 20B:
Reasoning: 4 × 11 = <<4*11=44>>44 helicopters. ### Answer: 44
Expected answer: 44
Correct? Yes
Problem: If each of the helicopters that the city's helicopter pads can hold requires just one helipad to park, how many helipads will be occupied when all the helicopters are parked?
InternLM-Math Base 20B:
Reasoning: 44/4 = <<44/4=11>>11 helipads will be occupied. ### Answer: 11
Expected answer: 44
Correct? No
Problem: John decided to re-arrange his room and he has a single bed that takes the space of 1 large carpet tile. If his room size requires 12 such carpet tiles fully side by side, how many bed spaces does John's room have?
InternLM-Math Base 20B:
Reasoning: John's room has 12/1 = <<12/1=12>>12 bed spaces. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: In a different layout, John realized he could fit 3 beds in the space currently occupied by 1 large carpet tile due to the smaller size of new bunk beds he purchased. If his room size still requires 12 large carpet tiles side by side, then, how many new bunk beds can he fit in his room now?
InternLM-Math Base 20B:
Reasoning: John's room can fit 12*3 = <<12*3=36>>36 new bunk beds. ### Answer: 36
Expected answer: 36
Correct? Yes
Problem: Sophie has 8 flowerpots. In each flowerpot, she plans to plant 3 flowers. How many flowers will Sophie plant in total?
InternLM-Math Base 20B:
Reasoning: Sophie will plant 8*3 = <<8*3=24>>24 flowers in total. ### Answer: 24
Expected answer: 24
Correct? Yes
Problem: After successfully planting flowers in her 8 flowerpots, Sophie decided to double the total number of flowers she planted. How many flowers does she have now?
InternLM-Math Base 20B:
Reasoning: Sophie has 2*24 = <<2*24=48>>48 flowers now. ### Answer: 48
Expected answer: 48
Correct? Yes
Problem: Now imagine if Sophie originally had 12 flowerpots instead of 8. How many flowers would she have planted if she still planted 3 flowers per flowerpot?
InternLM-Math Base 20B:
Reasoning: Sophie would have planted 12*3 = <<12*3=36>>36 flowers in total. ### Answer: 36
Expected answer: 36
Correct? Yes
Problem: Shawn has 12 gift boxes and each box contains 6 presents inside. How many presents does Shawn have in total?
InternLM-Math Base 20B:
Reasoning: Shawn has 12 × 6 = <<12*6=72>>72 presents in total. ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: What if Shawn had only 2 gift boxes instead of 12 and each box still contained 6 presents. How many presents does Shawn have in total now?
InternLM-Math Base 20B:
Reasoning: Shawn has 2 × 6 = <<2*6=12>>12 presents in total. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: In the factory, each RoboFalcon assembler can build 8 robots per hour. How many robots can it build in 12 hours?
InternLM-Math Base 20B:
Reasoning: 8*12 = <<8*12=96>>96 ### Answer: 96
Expected answer: 96
Correct? Yes
Problem: Suppose the RoboFalcon assembler had a minor update and the efficiency slightly reduced. Now, it can only build 6 robots per hour. How many robots can it build in 12 hours now?
InternLM-Math Base 20B:
Reasoning: 6*12 = <<6*12=72>>72 ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: Tom has setup 2 tents and each tent has 8 poles. If each pole has 6 strengths attached, how many strings are there in total?
InternLM-Math Base 20B:
Reasoning: Tom has 2 tents and each tent has 8 poles. So, he has 2*8 = <<2*8=16>>16 poles in total. Each pole has 6 strings attached. So, he has 16*6 = <<16*6=96>>96 strings in total. ### Answer: 96
Expected answer: 96
Correct? Yes
Problem: Let's change the scenario a bit. What if Tom had set up only 2 tents but each tent had 3 poles instead of 8. If each pole still has 6 strings attached, how many strings are there in total now?
InternLM-Math Base 20B:
Reasoning: Tom has 2 tents and each tent has 3 poles. So, he has 2*3 = <<2*3=6>>6 poles in total. Each pole has 6 strings attached. So, he has 6*6 = <<6*6=36>>36 strings in total. ### Answer: 36
Expected answer: 36
Correct? Yes
Problem: Jane received a set of 10 camera filters as a gift. She decided to equally distribute these between her 5 cameras. How many filters would each camera get?
InternLM-Math Base 20B:
Reasoning: Jane would give 10/5 = <<10/5=2>>2 filters to each camera. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: In retrospect, Jane realized that she had initially given 6 filters to each camera instead of 10. If she continued to distribute the filters equally between her 5 cameras, how many filters would each camera get initially?
InternLM-Math Base 20B:
Reasoning: Jane would give 6/5 = <<6/5=1.2>>1.2 filters to each camera. ### Answer: 1.2
Expected answer: 6/5
Correct? Yes
Problem: An elephant takes 1 hour to drink 1 gallon of water. If the elephant spends 1 hour by the waterhole, how many gallons of water did the elephant drink?
InternLM-Math Base 20B:
Reasoning: The elephant drinks 1 gallon of water in 1 hour. The elephant drinks <<1*1=1>>1 gallon of water in 1 hour. ### Answer: 1
Expected answer: 1
Correct? Yes
Problem: Given that each gallon of water weighs approximately 1 pound, if the elephant drank 1 gallon of water, how many pounds did the elephant gain from drinking?
InternLM-Math Base 20B:
Reasoning: 1 gallon of water weighs 1 pound. The elephant gained <<1*1=1>>1 pound from drinking 1 gallon of water. ### Answer: 1
Expected answer: 1
Correct? Yes
Problem: If instead of spending 1 hour by the waterhole, the elephant spent 5 hours there, how many gallons of water would the elephant have drank?
InternLM-Math Base 20B:
Reasoning: The elephant drinks 1 gallon of water in 1 hour. The elephant drinks <<1*5=5>>5 gallons of water in 5 hours. ### Answer: 5
Expected answer: 5
Correct? Yes
Problem: If one gallon of milk can fill up 2 large containers, how many gallons of milk will be needed to fill 4 large containers?
InternLM-Math Base 20B:
Reasoning: 1 gallon of milk can fill up 2 large containers. 4 large containers will need 2*4 = <<2*4=8>>8 gallons of milk. ### Answer: 8
Expected answer: 2
Correct? No
Problem: Eddy the pirate has 3 pieces of gold. For every gold coin he has, he gets a matching emerald from the captain. How many emeralds does Eddy have now?
InternLM-Math Base 20B:
Reasoning: Eddy has 3 gold coins, so he gets 3 emeralds. ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: Eddy was very happy with his emerald collection. Seeing this, the captain decided to award him with 4 rubies for each emerald he had. How many rubies did Eddy get from the captain?
InternLM-Math Base 20B:
Reasoning: Eddy has 3 emeralds, so he gets 3*4 = <<3*4=12>>12 rubies. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: A dolphin can jump 20 feet above water. Given that every 10 feet is considered a level, what level does the dolphin reach when it jumps?
InternLM-Math Base 20B:
Reasoning: 20/10 = <<20/10=2>>2 The dolphin reaches the <<2>>2nd level. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: After observing the dolphin's jumping level, researchers discovered that dolphins can increase their jump level by 11 times when aided by a strong wave. What would be the dolphin's level if it gets help from a strong wave?
InternLM-Math Base 20B:
Reasoning: 2*11 = <<2*11=22>>22 The dolphin's level would be <<22>>22. ### Answer: 22
Expected answer: 22
Correct? Yes
Problem: In light winds, the jumping level of the dolphin decreases to 20 feet instead of the usual 20 feet per level. Given that every 11 feet is still considered a level, what level does the dolphin now reach when it jumps in light winds?
InternLM-Math Base 20B:
Reasoning: 20/11 = <<20/11=1.818181818181818>>1.818181818181818 The dolphin reaches the <<1.818181818181818>>1.818181818181818nd level. ### Answer: 1.818181818181818
Expected answer: 20/11
Correct? No
Problem: Jill has 28 balls which she wants to distribute equally among her 7 friends. How many balls will each friend get?
InternLM-Math Base 20B:
Reasoning: Jill will give 28/7 = <<28/7=4>>4 balls to each of her friends. ### Answer: 4
Expected answer: 4
Correct? Yes
Problem: In the previous problem, Jill divided her 28 balls equally among her 7 friends. But what if Jill decided to divide the 28 balls equally among 10 friends instead? How many balls will each friend get then?
InternLM-Math Base 20B:
Reasoning: Jill will give 28/10 = <<28/10=2.8>>2.8 balls to each of her friends. ### Answer: 2.8
Expected answer: 14/5
Correct? Yes
Problem: In a robotic factory, there are 8 machines on the assembly line. Each of these machines can manufacture the same number of robots per day as there are machines. How many robots can the entire factory produce in one day?
InternLM-Math Base 20B:
Reasoning: There are 8 machines in the factory. Each machine can produce 8 robots per day. So, the factory can produce 8*8 = <<8*8=64>>64 robots per day. ### Answer: 64
Expected answer: 64
Correct? Yes
Problem: After assessing the weekly production, the robotic factory's management decided to replace one of the machines with a maintenance station, bringing the total number of machines down to 7. Now, if each of these 7 machines can manufacture the same number of robots per day as there are machines, how many robots would the factory produce in a day?
InternLM-Math Base 20B:
Reasoning: There are 7 machines in the factory. Each machine can produce 7 robots per day. So, the factory can produce 7*7 = <<7*7=49>>49 robots per day. ### Answer: 49
Expected answer: 49
Correct? Yes
Problem: In a geometry class, Maya was given a task to divide a line segment into smaller segments. Initially, the line segment was 15 cm long. She decided to cut it into equal parts each 5 cm long. How many segments did Maya get in the end?
InternLM-Math Base 20B:
Reasoning: Maya cut the line segment into 15/5 = <<15/5=3>>3 segments. ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: Maya realized that if she had divided the original 15 cm line segment into 7 cm pieces, the number of segments would have been different. If she cut the 15 cm line into equal pieces of 7 cm each, how many segments would she have obtained then?
InternLM-Math Base 20B:
Reasoning: Maya cut the line segment into 15/7 = <<15/7=2.1428571428571428571428571428571>>2.1428571428571428571428571428571 segments. ### Answer: 2.1428571428571428571428571428571
Expected answer: 15/7
Correct? Yes
Problem: Tommy has 5 types of cheese. He multiplies this by 5 to provide variety on his cheese platter for a party. How many types of cheese does Tommy have for his cheese platter now?
InternLM-Math Base 20B:
Reasoning: Tommy has 5*5 = <<5*5=25>>25 types of cheese for his cheese platter. ### Answer: 25
Expected answer: 25
Correct? Yes
Problem: If Tommy originally had 7 types of cheese instead of 5, and he still intended to multiply this by 5 to provide variety on his cheese platter, how many types of cheese would Tommy have for his cheese platter then?
InternLM-Math Base 20B:
Reasoning: Tommy has 7*5 = <<7*5=35>>35 types of cheese for his cheese platter. ### Answer: 35
Expected answer: 35
Correct? Yes
Problem: The width of a river increases by 10 feet every year. After 9 years, how much has the width of the river increased?
InternLM-Math Base 20B:
Reasoning: The width of the river increases by 10 feet every year. After 9 years, the width of the river increases by 9*10 = <<9*10=90>>90 feet. ### Answer: 90
Expected answer: 90
Correct? Yes
Problem: If the width of the river only increases by 10 feet every 3 years instead of every year, how much does the river's width increase after 9 years?
InternLM-Math Base 20B:
Reasoning: The width of the river increases by 10 feet every 3 years. After 9 years, the width of the river increases by 9/3*10 = <<9/3*10=30>>30 feet. ### Answer: 30
Expected answer: 30
Correct? Yes
Problem: Jessica has a collection of stuffed animals. She currently groups them in sets of 4. If she has 20 stuffed animals in total, how many groups does she have?
InternLM-Math Base 20B:
Reasoning: Jessica has 20 stuffed animals. She groups them in sets of 4. 20/4 = <<20/4=5>>5. So, she has 5 groups. ### Answer: 5
Expected answer: 5
Correct? Yes
Problem: Originally, Jessica decided to group her collection of 20 stuffed animals into sets of 4. But what if she had originally decided to group her stuffed animals into sets of 4, but she only had 9 stuffed animals instead of 20? How many groups would she have then?
InternLM-Math Base 20B:
Reasoning: Jessica has 9 stuffed animals. She groups them in sets of 4. 9/4 = <<9/4=2>>2. So, she has 2 groups. ### Answer: 2
Expected answer: 9/4
Correct? No
Problem: Tom has a set of 5 drums. Each of the drums has a length of 8 inches. Find out, How long would it be if he put all of his drums side by side?
InternLM-Math Base 20B:
Reasoning: 5*8 = <<5*8=40>>40 ### Answer: 40
Expected answer: 40
Correct? Yes
Problem: Following the last question, Tom decided to add a second row of drums beneath the first. If he maintains the same length of 8 inches per drum and the same number of 5 drums per row, how long will the two rows of drums combined be if placed side by side?
InternLM-Math Base 20B:
Reasoning: 2*5*8 = <<2*5*8=80>>80 ### Answer: 80
Expected answer: 80
Correct? Yes
Problem: Following the previous question, let's consider a different scenario. Suppose, initially, each of Tom's 5 drums were 11 inches long instead of 8. How long would it be if he put all of his drums side by side?
InternLM-Math Base 20B:
Reasoning: 5*11 = <<5*11=55>>55 ### Answer: 55
Expected answer: 55
Correct? Yes
Problem: Jack has 5 apples and decides to multiply it by 6 to get the total number of oranges he can trade them for. How many oranges can he get?
InternLM-Math Base 20B:
Reasoning: 5*6 = <<5*6=30>>30 Jack can get 30 oranges. ### Answer: 30
Expected answer: 30
Correct? Yes
Problem: Now consider if Jack started with 12 apples instead of 5. He decides to multiply it by 6 again to see how many oranges he can get. How many oranges can he now get?
InternLM-Math Base 20B:
Reasoning: 12*6 = <<12*6=72>>72 Jack can get 72 oranges. ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: A set of marker pens come with 6 different colors. If a whole pack contains 72 marker pens, how many sets of different colors are there in it?
InternLM-Math Base 20B:
Reasoning: 72/6 = <<72/6=12>>12 There are 12 sets of different colors in it. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: A dragon guards a cave that contains 80 pieces of gold. The dragon decided to equally distribute the gold into 8 separate piles. How many pieces of gold does each pile contain?
InternLM-Math Base 20B:
Reasoning: 80/8 = <<80/8=10>>10 Each pile contains 10 pieces of gold. ### Answer: 10
Expected answer: 10
Correct? Yes
Problem: After dividing the gold into 8 piles, the dragon decided to protect the most important treasure trove, which contains 4 times the number of gold pieces in each pile. How much gold is in the dragon's special pile?
InternLM-Math Base 20B:
Reasoning: 4*10 = <<4*10=40>>40 The dragon's special pile contains 40 pieces of gold. ### Answer: 40
Expected answer: 40
Correct? Yes
Problem: Let's reconsider the original situation. Suppose the dragon initially had 80 pieces of gold but decided to divide them into 11 piles instead of 8. How many pieces of gold would each pile contain in this scenario?
InternLM-Math Base 20B:
Reasoning: 80/11 = <<80/11=7.272727272727273>>7.272727272727273 Each pile contains 7.272727272727273 pieces of gold. ### Answer: 7.272727272727273
Expected answer: 80/11
Correct? No
Problem: John wants to divide his camping area of 44 square meters into 11 equal sections. Each of these sections would host a tent. If each tent can accommodate 12 campers, how many campers can camp in total?
InternLM-Math Base 20B:
Reasoning: John wants to divide his camping area of 44/11 = <<44/11=4>>4 square meters into 11 equal sections. Each of these sections would host a tent. If each tent can accommodate 12 campers, John can host 12*11 = <<12*11=132>>132 campers in total. ### Answer: 132
Expected answer: 48
Correct? No
Problem: A tiger can travel 6 miles in an hour. How far can it travel in 3 hours?
InternLM-Math Base 20B:
Reasoning: 6*3 = <<6*3=18>>18 miles. ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: In the previous problem we found out that a tiger can travel 6 miles in an hour. But what if the tiger could cover more ground in the same time span? If the tiger can travel 7 times as far in an hour, how far can it travel then?
InternLM-Math Base 20B:
Reasoning: 6*7 = <<6*7=42>>42 miles. ### Answer: 42
Expected answer: 42
Correct? Yes
Problem: A number sets of 6 are multiplied by 7. What is the resulting product?
InternLM-Math Base 20B:
Reasoning: 6 × 7 = <<6*7=42>>42 ### Answer: 42
Expected answer: 42
Correct? Yes
Problem: Following the previous problem. Consider that instead of multiplying 6 sets by 7, we multiply 4 sets by 7. What is the resulting product now?
InternLM-Math Base 20B:
Reasoning: 4 × 7 = <<4*7=28>>28 ### Answer: 28
Expected answer: 28
Correct? Yes
Problem: A doctor works double shift every day. If one shift is 6 hours, for how many hours does the doctor work each day?
InternLM-Math Base 20B:
Reasoning: The doctor works 2 shifts each day. Each shift is 6 hours long. 2*6 = <<2*6=12>>12 hours. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: Following his extra shifts, the doctor wants to reduce his workload. He decides to work 11 hours a day instead. How many hours does he work in a two-day period now?
InternLM-Math Base 20B:
Reasoning: The doctor works 11 hours a day. 11*2 = <<11*2=22>>22 hours. ### Answer: 22
Expected answer: 22
Correct? Yes
Problem: A farmer plants 6 seeds in each row of his field. If he has 11 rows total, how many seeds did he plant?
InternLM-Math Base 20B:
Reasoning: The farmer plants 6 seeds in each row. He has 11 rows total. 6 × 11 = <<6*11=66>>66 seeds. ### Answer: 66
Expected answer: 66
Correct? Yes
Problem: Mommy has a tradition that for every month, she buys 5 new toys for her baby. If the baby is 10 months old, how many toys has Mommy bought in total?
InternLM-Math Base 20B:
Reasoning: Mommy buys 5 toys for her baby every month. So, she buys 5*10 = <<5*10=50>>50 toys in total. ### Answer: 50
Expected answer: 50
Correct? Yes
Problem: After reflecting on her toy buying habits, Mommy realizes that she bought too many toys in the beginning. Instead of buying 5 new toys every month for 10 months, she now remembers that there was a month when she didn't buy any toys. Therefore, she only bought 5 toys per month for 9 months. How many toys did she actually buy during that period?
InternLM-Math Base 20B:
Reasoning: Mommy bought 5 toys per month for 9 months. So, she bought 5*9 = <<5*9=45>>45 toys in total. ### Answer: 45
Expected answer: 45
Correct? Yes