Problem: A songwriter creates a long ballad with many verses. Each verse has 162 words and he divides these into 18 lines per verse. This gives a certain number of words per line. To each line, he adds 34 more words as a refrain. What is the total number of words present in each line now?

InternLM-Math Base 20B:

 Reasoning: The number of words per line is 162/18 = <<162/18=9>>9.
The total number of words per line is 9+34 = <<9+34=43>>43.
### Answer: 43

Expected answer: 43

Correct? Yes

Problem: A penguin biologist counted 35 penguins on a small ice floe. In another part of the Antarctic, she counted a different group of penguins and found there were approximately 598 divided evenly among 26 ice floes. After returning to the first place, she found that the penguin population had increased by 49. Wishing to conduct another survey, she decided to take 33 more penguins into account. However, when she counted them again, she realized she had overestimated and had to subtract 10 from her calculations. Her final step was to add in the penguins she’d left at her base camp, which were 20 adults and 14 chicks. How many penguins did she count in total?

InternLM-Math Base 20B:

 Reasoning: 35+49+33-10+20+14 = <<35+49+33-10+20+14=129>>129
### Answer: 129

Expected answer: 164

Correct? No

Problem: In a local park, a jungle gym has a total of 27 steps. If the top 19 steps are blue and rest along with another 19 steps are red, we get a certain number of colored steps. On another jungle gym, there are 34 green steps. What is the total number of colored steps on the two jungle gyms?

InternLM-Math Base 20B:

 Reasoning: The total number of colored steps on the two jungle gyms is 27+19+19+34 = <<27+19+19+34=99>>99.
### Answer: 99

Expected answer: 61

Correct? No

Problem: If a cloud releases 47 millimeters of rainfall per hour over a one hour period, and the average cloud typically releases 775 millimeters of rainfall over the course of 31 hours, find the amount of rainfall from the following condition. Subtract 22 from the average rainfall of the typical cloud per hour then multiply this by 23. Add this result to a constant cloud factor of 42. Add this new result to the hourly rainfall of the initial cloud and subtract 2 from it. What is the resultant millimeters of rainfall?

InternLM-Math Base 20B:

 Reasoning: 775/31 = <<775/31=25>>25 millimeters of rainfall per hour for the average cloud. 

25 - 22 = <<25-22=3>>3 millimeters of rainfall per hour for the average cloud. 

3 * 23 = <<3*23=69>>69 millimeters of rainfall per hour for the average cloud. 

42 + 69 = <<42+69=111>>111 millimeters of rainfall per hour for the average cloud. 

111 + 47 - 2 = <<111+47-2=148>>148 millimeters of rainfall per hour for the average cloud. 

### Answer: 148

Expected answer: 156

Correct? No

Problem: Nadia likes to practice playing the piano. The other day she practiced for 45 minutes in the morning. In the same day, she also practiced for another 35 minutes in the afternoon and then another 35 minutes in the evening. How long did Nadia practice the piano in total that day?

InternLM-Math Base 20B:

 Reasoning: Nadia practiced for 45+35+35 = <<45+35+35=115>>115 minutes in total that day.
### Answer: 115

Expected answer: 115

Correct? Yes

Problem: A popular clothing store sells dresses for $44 each. During a flash sale, they further reduce prices by a factor of 465 divided by 31. How much does a dress cost during the flash sale?

InternLM-Math Base 20B:

 Reasoning: 44/31 = <<44/31=1.419>>1.419
A dress costs $1.419 during the flash sale.
### Answer: 1.419

Expected answer: 660

Correct? No

Problem: A rope maker made 46 meters of rope on Monday. On Tuesday, he made as many meters of rope as he did on Monday, plus an additional 19 meters. However, by Wednesday, 9 meters of this rope had been damaged and was unusable. How many meters of usable rope does he have after Wednesday?

InternLM-Math Base 20B:

 Reasoning: The rope maker made 46+19 = <<46+19=65>>65 meters of rope on Tuesday.
By Wednesday, 9 meters of this rope had been damaged and was unusable. So, he has 65-9 = <<65-9=56>>56 meters of usable rope after Wednesday.
### Answer: 56

Expected answer: 56

Correct? Yes

Problem: Juliana bought 16 pairs of vintage earrings for a gift. Each pair costs $2. She also chose a special jewelry box that costs $25. In addition, she paid $48 for the gift wrapping service. How much did she spend in total for her gift?

InternLM-Math Base 20B:

 Reasoning: Juliana spent $2 × 16 + $25 + $48 = <<2*16+25+48=89>>$89 in total for her gift.
### Answer: 89

Expected answer: 105

Correct? No

Problem: If Emma takes 60 beads and divides them equally among 3 of her friends, each friend will get a certain number of beads. She then adds 4 more beads to each friend's pile to start making necklaces. How many beads does each friend have now?

InternLM-Math Base 20B:

 Reasoning: Each friend will get 60/3 = <<60/3=20>>20 beads. Then, each friend will have 20+4 = <<20+4=24>>24 beads.
### Answer: 24

Expected answer: 24

Correct? Yes

Problem: A young boy with a creative mind decided to build a kite. He started with 37 paper straws but decided that 4 were unnecessary and removed them. Later, he realized his kite was still too bulky and removed another 23 straws. He multiplied the remaining number of straws by 45, subtracted 49 from that total, and then took out 7 more straws. How many straws did the boy have left?

InternLM-Math Base 20B:

 Reasoning: The boy had 37-4-23 = <<37-4-23=10>>10 straws left after removing 4 and 23 straws. He then multiplied 10 by 45, subtracted 49, and took out 7 more straws. 10*45-49-7 = <<10*45-49-7=399>>399 straws left.
### Answer: 399

Expected answer: 394

Correct? No

Problem: At the zoo, there were 2 trips being hosted. Each trip was allowed to see 2 animals. However, each animal had 3 baby animals with them, making the number of animals seen per trip multiplied by 3. If each baby animal could be photographed 21 times, how many photos could be taken in total? Also, if 34 photos were spoiled and unusable out of the entire batch, but guests were given the opportunity to take an additional 30 photos later, how many usable photos would there be in total?

InternLM-Math Base 20B:

 Reasoning: There were 2 trips, and each trip was allowed to see 2 animals. Each animal had 3 baby animals with them, so the number of animals seen per trip was multiplied by 3. If each baby animal could be photographed 21 times, then the total number of photos that could be taken was 2*2*3*21 = <<2*2*3*21=252>>252.
Out of the entire batch, 34 photos were spoiled and unusable, but guests were given the opportunity to take an additional 30 photos later. Therefore, the total number of usable photos was 252-34+30 = <<252-34+30=244>>244.
### Answer: 244

Expected answer: 248

Correct? No

Problem: In a literacy event, a group of learners were asked to write a word from letters. In the first round, they could form a word with 47 letters, but due to a mistake, they had to remove 30 letters. Then, they figured out they could still add 10 more letters to this word. In the next round, they removed 3 of these letters from the updated word. How many letters were there in the word after this last deletion?

InternLM-Math Base 20B:

 Reasoning: The learners started with 47 letters. They removed 30 letters, so they had 47-30 = <<47-30=17>>17 letters left. They added 10 letters, so they had 17+10 = <<17+10=27>>27 letters. They removed 3 letters, so they had 27-3 = <<27-3=24>>24 letters left.
### Answer: 24

Expected answer: 24

Correct? Yes

Problem: A turtle named Tommy moves at 74/37 miles per hour. If Tommy maintains his current speed for a while then slows down by 3 mph, then speeds up to his initial speed again, what would be his average speed?

InternLM-Math Base 20B:

 Reasoning: Tommy's average speed is 74/37+3+74/37/3 = <<(74/37+3+74/37)/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3+74/37/3=74/37+3

Expected answer: 1

Correct? No

Problem: Liam has 40 sets of building blocks. Each set contains 16 blocks. How many building blocks does Liam have in total?

InternLM-Math Base 20B:

 Reasoning: Liam has 40 × 16 = <<40*16=640>>640 building blocks in total.
### Answer: 640

Expected answer: 640

Correct? Yes

Problem: John has 24 pencils. Then he bought more such that the number of pencils he has now is equal to the number of what he had plus 7. How many pencils does John have now?

InternLM-Math Base 20B:

 Reasoning: John has 24+7 = <<24+7=31>>31 pencils now.
### Answer: 31

Expected answer: 31

Correct? Yes

Problem: The snowfall in City A, which lasts for 50 days, is currently 36 days in. In City B, there is a unique snow pattern where for every 14 days, it snows 98 inches. The total snowfall in inches in City A is expected to be the product of the remaining snowfall days in City A and the average daily snowfall in inches in City B. However, the snow removal has been keeping up and has managed to remove an amount of snow equal to the average daily snowfall in City B. How much snow in inches is left in City A after the snow removal?

InternLM-Math Base 20B:

 Reasoning: The total snowfall in inches in City A is 50*98/2 = <<50*98/2=2450>>2450. The snow removal has removed 98*36/2 = <<98*36/2=1716>>1716 inches of snow. The remaining snow in inches in City A is 2450-1716 = <<2450-1716=734>>734.
### Answer: 734

Expected answer: 91

Correct? No

Problem: A pirate finds 28 rubies on the first day of his treasure hunt. On the second day, he finds another haul of rubies equal to the first day's find plus an additional 21 rubies. How many rubies does the pirate have in total after the second day?

InternLM-Math Base 20B:

 Reasoning: The pirate finds 28+21 = <<28+21=49>>49 rubies on the second day. He has 28+49 = <<28+49=77>>77 rubies in total after the second day.
### Answer: 77

Expected answer: 77

Correct? Yes

Problem: There were 47 inches of snowfall in January and an additional 7 inches in early February. On February 15th, there was an additional 17 inches of snowfall. Then, 48 inches of snow fell in March. In April, we had an additional 31 inches of snowfall early on, but then 27 inches melted by the end of the month. How many inches of snow does this sum up to at the end of April?

InternLM-Math Base 20B:

 Reasoning: 47+7+17+48+31-27 = <<47+7+17+48+31-27=154>>154 inches of snow.
### Answer: 154

Expected answer: 123

Correct? No

Problem: At a fair, a vendor sold balloons. On a particularly busy day, he sold 46 balloons every hour for 11 hours straight. After the fair had closed, he ended up selling an additional 31 balloons to some stragglers. How many balloons did he sell in total that day?

InternLM-Math Base 20B:

 Reasoning: The vendor sold 46*11 = <<46*11=506>>506 balloons during the fair.
The vendor sold 31 balloons to stragglers.
The vendor sold 506+31 = <<506+31=537>>537 balloons in total that day.
### Answer: 537

Expected answer: 537

Correct? Yes

Problem: Mary and John decided to play a game of cards. In the first game, Mary scored 31 points and John scored 39 points. In the second game, their combined score was increased by 35 more points. During a special round, they could multiply their score by the difference between 27 and the number of cards left in the deck, which was 23. What was their final score in the special round?

InternLM-Math Base 20B:

 Reasoning: Mary's score in the second game was 31+35 = <<31+35=66>>66 points. John's score in the second game was 39+35 = <<39+35=74>>74 points. Mary's score in the special round was 66*23 = <<66*23=1518>>1518 points. John's score in the special round was 74*23 = <<74*23=1702>>1702 points. Mary and John's final score in the special round was 1518+1702 = <<1518+1702=3220>>3220 points.
### Answer: 3220

Expected answer: 420

Correct? No

Problem: A furniture company manufactured 17 upholstered seats and 18 wooden seats in the morning, and then produced another 29 in the afternoon. They repeated this production in the evening. Later on, they gave away 48 chairs to charity and used 7 chairs for quality testing. How many chairs are left after these operations?

InternLM-Math Base 20B:

 Reasoning: The company produced 17+18+29 = <<17+18+29=64>>64 chairs in the morning and evening. They gave away 48 chairs to charity and used 7 chairs for quality testing. The number of chairs left is 64-48-7 = <<64-48-7=9>>9.
### Answer: 9

Expected answer: 73

Correct? No

Problem: On a popular jungle gym, there are 46 monkey bars and 18 swinging ropes for the kids to play on. Nearby, a larger jungle gym was recently built to accommodate more kids. The new jungle gym contains 2 extra long zip lines and 20 regular zip lines, each requiring 31 special hooks to install. How many more hooks were used in the new jungle gym compared to the number of play components on the popular jungle gym?

InternLM-Math Base 20B:

 Reasoning: The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra long zip lines and 20 regular zip lines. Each extra long zip line requires 31 special hooks to install. Each regular zip line requires 31 special hooks to install. The new jungle gym has 2 extra

Expected answer: 618

Correct? No

Problem: John has saved $168 and he decides to divide it evenly between 21 days. After doing so, he then gets an additional $47 from his job. He then receives another amount of money which is the sum of $12 and $45. How much money does John have now?

InternLM-Math Base 20B:

 Reasoning: John has $168/21 = <<168/21=8>>8 dollars per day.
John has 8*21 = <<8*21=168>>168 dollars after 21 days.
John has 168+47 = <<168+47=215>>215 dollars after 21 days and his job.
John has 215+12+45 = <<215+12+45=272>>272 dollars after 21 days and his job.
### Answer: 272

Expected answer: 112

Correct? No

Problem: A robot can stack 32 boxes in 1 minute. If it works non-stop for 4 minutes and then picks up 1 extra box, how many boxes will this robot have stacked in total?

InternLM-Math Base 20B:

 Reasoning: The robot can stack 32 boxes in 1 minute.
The robot can stack 32*4 = <<32*4=128>>128 boxes in 4 minutes.
The robot can stack 128+1 = <<128+1=129>>129 boxes in 4 minutes and 1 extra box.
### Answer: 129

Expected answer: 129

Correct? Yes

Problem: A female tiger gave birth to 26 cubs in all her lifetime. Unfortunately, 17 of them did not survive the harsh conditions of the wild. However, after growing up, 6 of the surviving tigers moved to other territories. How many tigers remained in the female tiger's territory?

InternLM-Math Base 20B:

 Reasoning: The number of tigers that remained in the female tiger's territory is 26-17-6 = <<26-17-6=3>>3.
### Answer: 3

Expected answer: 3

Correct? Yes

Problem: A colony of penguins originally started with 44 members. After a while, 39 new penguins join the colony. Later, from that group, 16 penguins leave to start a new colony elsewhere. To supplant the loss, another group of 35 penguins join the colony. How many penguins are in the colony now?

InternLM-Math Base 20B:

 Reasoning: The number of penguins in the colony is 44+39-16+35 = <<44+39-16+35=94>>94.
### Answer: 94

Expected answer: 102

Correct? No

Problem: A helicopter travels 10 miles in one minute. If the helicopter increases its speed by 40 miles, plus another 20 miles, how far will the helicopter travel in 12 minutes at this increased speed?

InternLM-Math Base 20B:

 Reasoning: The helicopter travels 10+40+20 = <<10+40+20=70>>70 miles in one minute.
The helicopter travels 70*12 = <<70*12=840>>840 miles in 12 minutes.
### Answer: 840

Expected answer: 840

Correct? Yes

Problem: A new telescope has a magnification power of 26. To further explore the universe, another telescope is required that needs to be exactly 41 in magnification strength. How much more magnification is required for the new telescope compared to the existing one?

InternLM-Math Base 20B:

 Reasoning: 41-26 = <<41-26=15>>15
The new telescope needs to be 15 more magnification strength.
### Answer: 15

Expected answer: 15

Correct? Yes

Problem: Sophie's parents give her $18 for every hour she works at the family business. On Monday, she worked 2 of those hours. Then she bought a $4 ice cream and another $4 coffee afterwards. She then added Monday's leftover amount to her pay for her next single hour of work. After that, she got an additional $45 as a bonus from her grandmother. How much money does Sophie have in total now?

InternLM-Math Base 20B:

 Reasoning: Sophie worked 2 hours on Monday. She got $18 for every hour, so she got $18*2 = <<18*2=36>>36 dollars for her 2 hours of work. She then spent $4 on an ice cream and $4 on a coffee, so she spent $4+$4 = <<4+4=8>>8 dollars. She then added her leftover amount to her pay for her next single hour of work. She then got a $45 bonus from her grandmother. So, she has $36-$8+$18+$45 = <<36-8+18+45=91>>91 dollars in total now.
### Answer: 91

Expected answer: 91

Correct? Yes

Problem: A towel company initially produced 30 beach towels and 6 hand towels. They then gave away 7 towels for charity, which leaves a certain amount of towels. They then decided to produce 14 more towels to add to their current stock. On the other hand, they made a special batch of 13 towels for every towel left after their charity activity and deducted 19 towels from this special batch, calling it their premium collection. They then noted 20 towels were damaged and removed it from this premium collection. After this, they deducted 3 more towels from the remaining premium collection and combined it with the total they had after their second batch of production. How many towels does the company have now?

InternLM-Math Base 20B:

 Reasoning: The company has 30+6-7+14 = <<30+6-7+14=43>>43 towels after their first batch of production. 

The company has 13-19-20-3 = <<13-19-20-3=-19>>-19 towels after their second batch of production. 

The company has 43-19 = <<43-19=24>>24 towels now.
### Answer: 24

Expected answer: 378

Correct? No

Problem: An extraterrestrial being from the planet Zorkon communicates that they have 50 special energy crystals. Then they explain that they'll get 20 more energy crystals in a few earth days. Additionally, their zorbcraft has a hidden compartment that contains 50 energy crystals and 6 extra lumino-gems, and they plan to add the upcoming energy crystals to this compartment as well. How many items (including both energy crystals and lumino-gems) would be in the zorbcraft's compartment at that time?

InternLM-Math Base 20B:

 Reasoning: The extraterrestrial being will have 50+20 = <<50+20=70>>70 energy crystals in total. The zorbcraft's compartment will contain 50+70 = <<50+70=120>>120 energy crystals and 6 lumino-gems. Therefore, the zorbcraft's compartment will contain 120+6 = <<120+6=126>>126 items in total.
### Answer: 126

Expected answer: 126

Correct? Yes

Problem: A park contains 43 Velociraptors. Then, the park added another set of dinosaurs which numbered 972, but as it so happens, each of these sections contained 27 dinosaurs. This meant the actual number of new dinosaur types added was less. After calculating the new dinosaur types, they found out that the number of Velociraptors was more. They found the difference and multiplied this difference by 7, as each of the Velociraptors laid 7 new eggs that week. How many total eggs were laid by the Velociraptors that week?

InternLM-Math Base 20B:

 Reasoning: The number of new dinosaur types added was 972/27 = <<972/27=36>>36. The number of Velociraptors was 43-36 = <<43-36=7>>7. The number of eggs laid by the Velociraptors was 7*7 = <<7*7=49>>49.
### Answer: 49

Expected answer: 49

Correct? Yes

Problem: There is a bowl containing 46 oranges. After Maria took 16 oranges from that bowl, how many oranges are left?

InternLM-Math Base 20B:

 Reasoning: 46-16 = <<46-16=30>>30 oranges are left.
### Answer: 30

Expected answer: 30

Correct? Yes

Problem: A toothbrush factory produces 37 toothbrushes per minute at the start of its morning shift. A little later, it increases its production to rate to 308 toothbrushes every 7 minutes. If this increased rate of production continued for 16 minutes, how many toothbrushes were produced in total?

InternLM-Math Base 20B:

 Reasoning: The factory produces 308/7 = <<308/7=44>>44 toothbrushes per minute.
In 16 minutes, the factory produces 16*44 = <<16*44=704>>704 toothbrushes.
In the first minute, the factory produces 37 toothbrushes.
The total number of toothbrushes produced is 704+37 = <<704+37=741>>741.
### Answer: 741

Expected answer: 741

Correct? Yes

Problem: A research laboratory has 39 telescopes initially. They added 7 more telescopes in the first month and then 17 more in the second month. Twelve more telescopes arrived in the third month, followed by further add up of 18 in the fourth month. In fifth month, they got exactly the same number of telescopes as they had initially i.e. 39 telescopes and in the sixth month, they received extra 19 telescopes. How many telescopes does the research laboratory have at the end of the sixth month.

InternLM-Math Base 20B:

 Reasoning: The research laboratory has 39+7+17+12+18+39+19 = <<39+7+17+12+18+39+19=175>>175 telescopes at the end of the sixth month.
### Answer: 175

Expected answer: 151

Correct? No

Problem: A table was initially set with 20 forks and 23 knives. Later in the day, 28 more sets of cutlery were added, each set containing 26 utensils. After counting, they found 7 more utensils than expected. However, there were 46 missing utensils, and they had to remove the original set of 20 forks and 23 knives. How many utensils were left on the table?

InternLM-Math Base 20B:

 Reasoning: The number of utensils on the table is 28*26-46 = <<28*26-46=630-46=584>>584.
### Answer: 584

Expected answer: 646

Correct? No

Problem: A magical unicorn has 50 red roses and 36 blue roses in her mystical garden. But then, a storm comes and 25 blue roses are destroyed. How many roses does the unicorn have left in her garden after the storm?

InternLM-Math Base 20B:

 Reasoning: The unicorn has 50+36 = <<50+36=86>>86 roses in her garden before the storm.
The unicorn has 36-25 = <<36-25=11>>11 blue roses left after the storm.
The unicorn has 50+11 = <<50+11=61>>61 roses left after the storm.
### Answer: 61

Expected answer: 61

Correct? Yes

Problem: A factory produces 100 bottles every hour. Half of the hourly production is sent to one warehouse. At another location, triple the amount sent to the first warehouse was marked for shipping, as well as an additional 29 bottles. By the end of the day, 28 more bottles were added to this shipment. How many bottles were marked for shipping in total?

InternLM-Math Base 20B:

 Reasoning: The factory produces 100 bottles every hour. Half of the hourly production is sent to one warehouse. This means that 100/2 = <<100/2=50>>50 bottles are sent to the first warehouse. At another location, triple the amount sent to the first warehouse was marked for shipping, as well as an additional 29 bottles. This means that 3*50+29 = <<3*50+29=149>>149 bottles were marked for shipping. By the end of the day, 28 more bottles were added to this shipment. This means that 149+28 = <<149+28=177>>177 bottles were marked for shipping in total.
### Answer: 177

Expected answer: 207

Correct? No

Problem: The height of a window frame is calculated as the sum of 925 divided by 37 and 26 inches. The width of the window is 11 inches greater than the height. The circumference of the window is calculated as the sum of twice the width and the height. Finally the size of the glass for the window is calculated by subtracting 32 from the circumference. Find the size of the glass required for the window?

InternLM-Math Base 20B:

 Reasoning: The height of the window frame is 925/37+26 = <<(925/37)+26=35>>35 inches.
The width of the window is 11 inches greater than the height, so the width is 35+11 = <<35+11=46>>46 inches.
The circumference of the window is 2*46+35 = <<2*46+35=117>>117 inches.
The size of the glass for the window is 117-32 = <<117-32=85>>85 inches.
### Answer: 85

Expected answer: 143

Correct? No

Problem: A pirate finds treasure with 135 gold coins. He divides these amongst his crew of 9. On another island, they find 323 emeralds which he divides amongst his crew of 19. He then multiplies these two shares to find out the total share per crew member. However, due to a miscount, he later realizes he has overcounted the share by 14. What is the corrected total share per crew member?

InternLM-Math Base 20B:

 Reasoning: The total share per crew member is 135/9*323/19-14 = <<135/9*323/19-14=12.5>>12.5.
### Answer: 12.5

Expected answer: 241

Correct? No

Problem: A chocolatier has decided to make small chocolate bars that weigh 176 grams each. To get the right size, he divides each bar into 8 pieces, which means each piece weighs a certain number of grams. He then decides to make a new batch of chocolate using a special recipe. This recipe calls for a total of 38 grams of cocoa, but subtraction the weight of one piece from the 176g bars, plus an additional 26 grams of sugar. Simultaneously, the chocolatier decides to create another batch of chocolates that needs a total of 38 grams of cocoa and 18 grams of milk. What is the difference in the total weight of ingredients between the second and third batch of chocolates?

InternLM-Math Base 20B:

 Reasoning: The second batch of chocolates needs 38 grams of cocoa, 26 grams of sugar, and 176 grams of chocolate. The third batch of chocolates needs 38 grams of cocoa, 18 grams of milk, and 176 grams of chocolate. The difference in the total weight of ingredients between the second and third batch of chocolates is 26 grams of sugar minus 18 grams of milk, which is 8 grams. ### Answer: 8

Expected answer: 14

Correct? No

Problem: Jenny has 9 red colored pencils in her art box. She also has some green colored pencils which amounts to 38 minus the number of red colored pencils she has. The total number of times she used all the pencils is the product of the number of green and red pencils she has. How many times did she use all her pencils?

InternLM-Math Base 20B:

 Reasoning: Jenny has 9 red colored pencils and 38-9 = <<38-9=29>>29 green colored pencils. The total number of times she used all the pencils is 9*29 = <<9*29=261>>261.
### Answer: 261

Expected answer: 261

Correct? Yes

Problem: A factory has just released a new robot model, where each model has 17 transistors and each transistor may have 16 separate connections. One of the newly manufactured robots by accident was made with one less connection than standard. However, to compensate for the mistake, an extra 41 connections were added elsewhere. What is the total number of connections in the strangely built robot?

InternLM-Math Base 20B:

 Reasoning: The total number of transistors is 17, and each transistor has 16 connections. So the total number of connections is 17*16 = <<17*16=272>>272. However, the robot has one less connection, so the total number of connections is 272-1 = <<272-1=271>>271. However, 41 extra connections were added, so the total number of connections is 271+41 = <<271+41=312>>312.
### Answer: 312

Expected answer: 312

Correct? Yes

Problem: At the local jungle gym, during busy hours, there are usually 24 kids climbing on each of the 31 different attractions. One rainy day, however, there were only 6 kids in total! If you subtract the number of kids on the rainy day from the usual busy day, and then further subtract 12 (the number of squirrels scampering around), how many kids will you have counted in total?

InternLM-Math Base 20B:

 Reasoning: 24×31 = <<24*31=744>>744 kids on the busy day.
744−6 = <<744-6=738>>738 kids on the busy day.
738−12 = <<738-12=726>>726 kids counted in total.
### Answer: 726

Expected answer: 726

Correct? Yes

Problem: There's this mystical ring that, after you perform a special chant, it will grant you powers based on a complex magic formula. If the first step of the magical formula is subtracting 5 from 23 and then multiplying by the number of magical chants you perform, which in this case is 6. After that, the result is multiplied by 7 and again by 1. However, for the final step, you subtract 48 from the result. If you follow these steps, how powerful will the ring's magic be?

InternLM-Math Base 20B:

 Reasoning: 23-5 = <<23-5=18>>18, 18*6 = <<18*6=108>>108, 108*7 = <<108*7=756>>756, 756-48 = <<756-48=708>>708.
The ring's magic will be 708.
### Answer: 708

Expected answer: 708

Correct? Yes

Problem: A child can make 15 cookies in one hour. If the child spends 24 hours making the cookies, how many cookies are made in total?

InternLM-Math Base 20B:

 Reasoning: The child makes 15 cookies in one hour. The child spends 24 hours making the cookies. 15*24 = <<15*24=360>>360 cookies are made in total.
### Answer: 360

Expected answer: 360

Correct? Yes

Problem: A silversmith has 16 silver rings in stock. He decided to create more rings and ended up with 28 silver and 24 gold rings. Then he subtracted from them the number of his original stock of silver rings. He traded some rings and ended up with 21 rings less than what he had after the creation stage. After that, for a special order, he created 26 times the number of rings he had left. In addition, he had made 7 platinum and 47 bronze rings for another order. How many rings does the silversmith have in total now?

InternLM-Math Base 20B:

 Reasoning: The silversmith has 28+24-16 = <<28+24-16=36>>36 rings after the creation stage.
He traded 21 rings, so he has 36-21 = <<36-21=15>>15 rings after the trading stage.
He created 26 times the number of rings he had left, so he has 26*15 = <<26*15=390>>390 rings after the creation stage.
He made 7 platinum and 47 bronze rings, so he has 390+7+47 = <<390+7+47=444>>444 rings in total now.
### Answer: 444

Expected answer: 444

Correct? Yes

Problem: A gardener plants flowers in several rows. Each row contains 40 flowers, but due to the rough soil conditions only half of them grow properly. In total, 19 rows are planted this way. Additionally, the gardener plants another small batch of 18 bulbs in one corner and 48 in another corner of the garden. What is the difference between the total number of flowers in the rows and the small corners?

InternLM-Math Base 20B:

 Reasoning: The gardener plants 19 rows of 40 flowers each. This is 19*40 = <<19*40=760>>760 flowers. Half of them grow properly, so 760/2 = <<760/2=380>>380 flowers grow properly. The gardener also plants 18 and 48 bulbs in two corners. The difference between the total number of flowers in the rows and the small corners is 380 - 18 - 48 = <<380-18-48=314>>314.
### Answer: 314

Expected answer: 314

Correct? Yes

Problem: In the forest, a certain bird lays an average of 11 eggs per month. This month, the bird laid 4 times the average. Due to extreme weather conditions, the forest welcoming committee distributed an additional 40 eggs to various nests to support the bird population. How many eggs are there in the forest this month?

InternLM-Math Base 20B:

 Reasoning: The bird laid 4*11 = <<4*11=44>>44 eggs this month.
The bird laid 44+40 = <<44+40=84>>84 eggs in the forest this month.
### Answer: 84

Expected answer: 84

Correct? Yes

Problem: You are mixing paints to create different shades. In one mixture, you have 41 drops of red paint. You then add 13 drops of white paint and the same amount of red paint as before. You take a sample of this mixture, which is 34 drops, and add that to a new mixture. Then take away the same amount of the 34 drop sample that you took originally. How many drops of paint are there in the new mixture?

InternLM-Math Base 20B:

 Reasoning: You have 41+13+41 = <<41+13+41=95>>95 drops of paint in the first mixture. You take 34 drops of the first mixture and add it to a new mixture. You then take away 34 drops from the new mixture. The number of drops in the new mixture is 95-34-34 = <<95-34-34=27>>27.
### Answer: 27

Expected answer: 95

Correct? No

Problem: A small toy car factory made 32 toy cars on Monday, but only 27 on Tuesday. They multiply the difference by 49 to determine their weekly goal. The staff number in the factory is 12, and every staff member makes 9 toy cars a day. They add 45 to the total number of toy cars prepared by staff members. On Friday, they prepare 31 additional toy cars and add this to the weekly goal and staff prepared cars. How many toy cars in total were made in this process?

InternLM-Math Base 20B:

 Reasoning: The difference between 32 and 27 is 5. 5*49 = <<5*49=245>>245. 245+12*9 = <<245+12*9=381>>381. 381+31 = <<381+31=412>>412.
### Answer: 412

Expected answer: 429

Correct? No

Problem: A farmer harvested 45 carrots in one day from his farm. He noticed that for every carrot over 44 per day, he can earn 29 dollars. How much would the farmer have earned if this continued?

InternLM-Math Base 20B:

 Reasoning: The farmer would have earned 29 dollars for every carrot over 44 per day.
The farmer harvested 45 carrots in one day, which is 1 carrot over 44.
So, the farmer would have earned 29 dollars for 1 carrot.
### Answer: 29

Expected answer: 29

Correct? Yes

Problem: In a sock factory, a worker started with 26 pairs of socks. Unfortunately, 50 pairs got torn and had to be discarded. The worker was able to produce 36 more pairs to replace them. Each pair of socks is sold for $37. After earning from the sock sales, the worker found a $13 bill on the floor. How much money does the worker have in total?

InternLM-Math Base 20B:

 Reasoning: The worker started with 26 pairs of socks. 50 pairs got torn and had to be discarded. The worker was able to produce 36 more pairs to replace them. So, the worker has 26+36 = <<26+36=62>>62 pairs of socks in total. Each pair of socks is sold for $37. So, the worker earns 62*37 = <<62*37=2294>>$2294 from the sock sales. The worker also found a $13 bill on the floor. So, the worker has $2294+$13 = <<2294+13=2307>>$2307 in total.
### Answer: $2307

Expected answer: 457

Correct? No

Problem: A jewelry maker starts with 38 beads to make a bracelet. However, the number of beads was not right, so she removed a number of beads equal to dividing 560 by 40. However, she thinks her initial count may have been wrong and she may have actually started with 15 more beads than she initially thought. After adjusting the count and removing some beads, she adds one more bead, and then 39 more. How many beads does the jewelry maker have now?

InternLM-Math Base 20B:

 Reasoning: The jewelry maker started with 38+15 = <<38+15=53>>53 beads. She removed 560/40 = <<560/40=14>>14 beads. She added 39+1 = <<39+1=40>>40 beads. She has 53-14+40 = <<53-14+40=99>>99 beads now.
### Answer: 99

Expected answer: 79

Correct? No

Problem: In an aquarium, there are initially 30 sharks. But then, 23 of them are moved to a different area of the aquarium. A few days later, an additional 14 sharks are brought in, followed by 3 more being moved to the other area. The number of sharks is then multiplied by 43 for a research study. What is the final figure for the research?

InternLM-Math Base 20B:

 Reasoning: The number of sharks in the aquarium is 30-23+14-3 = <<30-23+14-3=28>>28. The final figure for the research is 28*43 = <<28*43=1204>>1204.
### Answer: 1204

Expected answer: 774

Correct? No

Problem: In a puzzle game, each round you collect 150 points which are then divided by 10 to determine the number of gold coins you earn. After two rounds, you earned some gold coins. In the third round, you collected 28 emeralds and 14 sapphires but you had to sacrifice the same amount of gold coins as you earned in the first two rounds. How many emeralds and sapphires did you have left after the third round?

InternLM-Math Base 20B:

 Reasoning: You collected 28+14 = <<28+14=42>>42 emeralds and sapphires in the third round.
You had 28+14-150/10-150/10 = <<28+14-150/10-150/10=2>>2 emeralds and sapphires left after the third round.
### Answer: 2

Expected answer: 12

Correct? No

Problem: A train gets to carry 15 containers every day. On Fridays, the train gets to carry an extra 12 containers than usual. The following Monday, the train carries an additional 26 containers. However, on Wednesday, the load decreases by 32 containers. For a particular trip, the train is coupled with 2 more containers, and after it makes one stop, an additional 48 containers are loaded onto the train. How many containers is the train carrying at this point?

InternLM-Math Base 20B:

 Reasoning: The train carries 15+12 = <<15+12=27>>27 containers on Fridays. The train carries 27+26 = <<27+26=53>>53 containers on Monday. The train carries 53-32 = <<53-32=21>>21 containers on Wednesday. The train carries 21+2 = <<21+2=23>>23 containers on the first day of the week. The train carries 23+48 = <<23+48=71>>71 containers after the first stop.
### Answer: 71

Expected answer: 71

Correct? Yes

Problem: A lemon farmer had harvested 39 lemons in the morning and 33 in the afternoon. Unfortunately, 12 lemons got spoiled by the end of the day. The next day, the farmer used 23 lemons to make lemonade. How many lemons did he have left after making the lemonade?

InternLM-Math Base 20B:

 Reasoning: The farmer had 39+33 = <<39+33=72>>72 lemons at the end of the first day. 12 lemons got spoiled, so he had 72-12 = <<72-12=60>>60 lemons left. He used 23 lemons to make lemonade, so he had 60-23 = <<60-23=37>>37 lemons left after making the lemonade.
### Answer: 37

Expected answer: 37

Correct? Yes

Problem: A bee lands on 33 flowers in an hour. If the bee is collecting 15 nectar droplets from each flower, how many nectar droplets does it have after an hour if it started with 26 nectar droplets?

InternLM-Math Base 20B:

 Reasoning: The bee collects 33*15 = <<33*15=495>>495 nectar droplets in an hour.
The bee has 495+26 = <<495+26=521>>521 nectar droplets after an hour.
### Answer: 521

Expected answer: 521

Correct? Yes

Problem: A company produces 36 marshmallow packs in an hour. To meet a sudden increase in demand, they decide to increase their production. They add an extra 350 marshmallows to their daily production, which is distributed evenly over 7 hours of their working day. Additionally, they add another 6 marshmallow packs to their hourly production. But, due to some limitations, they end up producing 43 less packs per hour than their goal. How many marshmallow packs per hour are they now producing?

InternLM-Math Base 20B:

 Reasoning: The company produces 350/7 = <<350/7=50>>50 extra marshmallows per hour. They produce 6+50 = <<6+50=56>>56 extra packs per hour. They produce 36-43 = <<36-43=-7>>-7 packs per hour. They produce 36-7 = <<36-7=29>>29 packs per hour.
### Answer: 29

Expected answer: 49

Correct? No

Problem: A wizard casts a spell that produces 882 glimmering lights over a span of 21 days. That's an average of how many lights a day? In comparison, another wizard casts a spell that produces 460 glowing orbs in 20 days. What is the daily average here? Now, let's assume that the difference in their daily averages times the second wizard's daily average is a magical constant represented by 'n'. Can you find out what 'n' is?

InternLM-Math Base 20B:

 Reasoning: 882/21 = <<882/21=42>>42 lights a day.
460/20 = <<460/20=23>>23 orbs a day.
42-23 = <<42-23=19>>19
19*23 = <<19*23=437>>437
### Answer: 437

Expected answer: 437

Correct? Yes

Problem: A candy factory has 20 different flavors of candy. Their bestselling flavors are the Sugar Rush, which has 14 different base ingredients, the Candy Twirl, which has 25 base ingredients, and the Jawbreaker, which has 16 base ingredients. They create a Special Mix which combines all of these bestsellers and adds 43 extra goodies, including sprinkles and marshmallows. To create a limited edition candy, they take a piece of the Special Mix, add 7 uniquely crafted sweets, then combine this with one of each flavor from their 20 different flavored candies (excluding 19 of them so it's not too overwhelming). They then top it all off by removing 3 experimental sweets that didn't taste quite right. What is the count of various components used in creating this limited edition candy?

InternLM-Math Base 20B:

 Reasoning: The limited edition candy has 20-19 = <<20-19=1>>1 flavor, 14+25+16+43+7+3 = <<14+25+16+43+7+3=100>>100 base ingredients, and 43+7+3 = <<43+7+3=53>>53 extra goodies.
### Answer: 1, 100, 53

Expected answer: 103

Correct? No

Problem: In a special operation, 32 police officers were assigned to the north district, 33 were sent to the south district, and 29 officers were held for the downtown district. After the operation, 21 officers from the downtown district were transferred elsewhere. A week later, on a different assignment, 39 officers were added to the remaining duty force. Later that day, another 14 officers joined the force. How many officers were on duty by the end of the day?

InternLM-Math Base 20B:

 Reasoning: 32+33+29 = <<32+33+29=94>>94 officers were on duty at the end of the first day.
21 officers were transferred from the downtown district, so 29-21 = <<29-21=8>>8 officers remained in the downtown district.
39 officers were added to the remaining duty force, so 94+39 = <<94+39=133>>133 officers were on duty at the end of the second day.
14 officers joined the force, so 133+14 = <<133+14=147>>147 officers were on duty by the end of the day.
### Answer: 147

Expected answer: 126

Correct? No

Problem: The distance between the Moon and the Earth changes throughout the month. On one particular day, the distance was 36 million kilometers but decreased by 19 million kilometers later in the month. Then it increased again by 11 million kilometers. If that distance, in millions of kilometers, times 19 minus 27 equals to a certain value, what is the value?

InternLM-Math Base 20B:

 Reasoning: The distance between the Moon and the Earth changed from 36 to 36-19 = <<36-19=17>>17 to 17+11 = <<17+11=28>>28 million kilometers. 19*28-27 = <<19*28-27=513>>513.
### Answer: 513

Expected answer: 505

Correct? No

Problem: A tiger has an average step length of 9 meters. If a tiger took two steps and then leaped 44 meters, it would have covered a certain distance. Another tiger covered a distance combining 23 meters with a leap and a 46-meter run but then retraces the distance equal to the first tiger's steps and the leap. How much distance did the second tiger cover finally?

InternLM-Math Base 20B:

 Reasoning: The first tiger covered a distance of 2*9+44 = <<2*9+44=62>>62 meters.
The second tiger covered a distance of 23+46 = <<23+46=69>>69 meters.
The second tiger covered a distance of 69-62 = <<69-62=7>>7 meters.
### Answer: 7

Expected answer: 7

Correct? Yes

Problem: A toothpaste factory produces 26 tubes of toothpaste every hour. On Sundays, they work for 7 hours and produce additional 8 tubes of toothpaste. So, in one Sunday, they produce ((26 * 7) + 8) tubes. The following Monday, they continue their production by adding another 31 tubes to their Sunday's total. In parallel, in the packaging department, they have 50 empty boxes. They use 19 of them for another department, leaving them with (50 - 19) boxes. The total number of toothpaste tubes ready is calculated by adding the packaged boxes number with Monday's production. On Tuesday, they produced an additional 48 tubes of toothpaste. What is the total number of produced toothpaste tubes until Tuesday, inclusive?

InternLM-Math Base 20B:

 Reasoning: 26 * 7 = <<26*7=182>>182
<<26*7=182>>182 + 8 = <<26*7+8=190>>190
<<26*7+8=190>>190 + 31 = <<26*7+8+31=221>>221
50 - 19 = <<50-19=31>>31
<<50-19=31>>31 + <<26*7+8+31=221>>221 = <<50-19+26*7+8+31=252>>252
<<50-19+26*7+8+31=252>>252 + 48 = <<50-19+26*7+8+31+48=300>>300
### Answer: 300

Expected answer: 300

Correct? Yes

Problem: In a magical forest, a unicorn has 42 rainbow pebbles. A day later, it finds 26 more. It also has a stash of 44 dreamberries. Later on, the unicorn gathers 33 more rainbow pebbles and adds them with its stash of dreamberries. Finally, the unicorn finds 40 magical dandelions and adds them to his stash, but oh no, he loses 14! How many items does the unicorn have altogether after these events?

InternLM-Math Base 20B:

 Reasoning: The unicorn has 42+26+44+33+40-14 = <<42+26+44+33+40-14=165>>165 items altogether.
### Answer: 165

Expected answer: 171

Correct? No

Problem: A pirate captain has a treasure chest containing 23 types of jewels. Each type has 28 jewels. Tired from his adventure, he mistakenly lost 40 jewels on his way back to his ship. The next day, he luckily found 16 jewels from a deserted island. How many jewels does he have now in his treasure chest?

InternLM-Math Base 20B:

 Reasoning: The captain has 23 types of jewels. Each type has 28 jewels. So, he has 23*28 = <<23*28=644>>644 jewels in total.
He lost 40 jewels, so he has 644-40 = <<644-40=604>>604 jewels left.
He found 16 jewels, so he has 604+16 = <<604+16=620>>620 jewels now.
### Answer: 620

Expected answer: 620

Correct? Yes

Problem: In a distant galaxy, a star shines brightly with 38 neutrons. It then gains 4 more. This total number gets multiplied by 18 to create a sensational energy output. During an explosion, it additionally releases the energy equivalent to 6 plus 25. How much total energy does the star emit?

InternLM-Math Base 20B:

 Reasoning: 38+4 = <<38+4=42>>42, 42*18 = <<42*18=756>>756, 756+6+25 = <<756+6+25=777>>777.
### Answer: 777

Expected answer: 787

Correct? No

Problem: A gardener planted 13 Sunflowers in his garden. The next day, he worked out that he needed to plant more, with the number being calculated as 37 times the number of petals on one sunflower, which is 5, minus 18. On the following day, he subtracted 10 flowers from that number, then added his initial sunflowers back, creating a new total. Meanwhile, he figured out that in a special part of his garden, ideal for 92 orchids he had, each spot can hold 23, so he calculated how many spots needed. By the end of the week, he summed up the total number of plants he worked on and the spots needed, then he doubled that total for no particular reason. How many did he end up with?

InternLM-Math Base 20B:

 Reasoning: The gardener planted 13 sunflowers. The next day, he worked out that he needed to plant 37*5-18 = <<37*5-18=122>>122 more. On the following day, he subtracted 10 flowers from that number, then added his initial sunflowers back, creating a new total of 13+122-10 = <<13+122-10=125>>125. Meanwhile, he figured out that in a special part of his garden, ideal for 92 orchids he had, each spot can hold 23, so he calculated that he needed 92/23 = <<92/23=4>>4 spots. By the end of the week, he summed up the total number of plants he worked on and the spots needed, then he doubled that total for no particular reason. He ended up with 125+4*2 = <<125+4*2=133>>133.
### Answer: 133

Expected answer: 348

Correct? No

Problem: In a particular pond, there are 18 frogs. Each frog can catch 21 flies in a day. How many flies do all the frogs catch in a day?

InternLM-Math Base 20B:

 Reasoning: 18*21 = <<18*21=378>>378 flies.
### Answer: 378

Expected answer: 378

Correct? Yes

Problem: A community center has 21 chairs in their main meeting room. They are supplemented with an additional 22 chairs from the storage room for a large event. How many chairs are in the meeting room now for the event?

InternLM-Math Base 20B:

 Reasoning: The number of chairs in the meeting room now for the event is 21+22 = <<21+22=43>>43.
### Answer: 43

Expected answer: 43

Correct? Yes

Problem: There are 14 elephants in a conservation park. This year, 11 new baby elephants were born, and the park received 25 more elephants from various rescues. How many elephants are there in the park now?

InternLM-Math Base 20B:

 Reasoning: There are 14+11+25 = <<14+11+25=50>>50 elephants in the park now.
### Answer: 50

Expected answer: 50

Correct? Yes

Problem: A treasure chest contains 23 emeralds and 30 diamonds. Unfortunately, 39 of the stones are fake and had to be removed. The number of real stones left (y) is multiplied by itself and then 37 is subtracted to get a number (g) that represents the value of the chest. In another chest, there were 540 rubies which have been equally shared amongst 45 pirates, and then 3 are lost in the division. The remaining number (x) is subtracted from the value of the first chest (g) to get a new value. In the same chest as the rubies, there were also 23 pearls and 11 zirconias, but 9 pieces had to be discarded due to damage. The count (s) is subtracted from the new value to determine the value (m) of the remaining treasure. What is the value (m) of the remaining treasure?

InternLM-Math Base 20B:

 Reasoning: The number of real stones left (y) is multiplied by itself and then 37 is subtracted to get a number (g) that represents the value of the chest. 

In another chest, there were 540 rubies which have been equally shared amongst 45 pirates, and then 3 are lost in the division. The remaining number (x) is subtracted from the value of the first chest (g) to get a new value.

In the same chest as the rubies, there were also 23 pearls and 11 zirconias, but 9 pieces had to be discarded due to damage. The count (s) is subtracted from the new value to determine the value (m) of the remaining treasure.

What is the value (m) of the remaining treasure?

Expected answer: 125

Correct? No

Problem: There are 6 confirmed UFO sightings in a small city. After a viral event, sightings increase by a daily average obtained by dividing an additional 504 sightings over the next 14 days. Subtract the initial confirmed sightings from this new daily average. Then, multiply it by the result of taking the maximum number of sightings recorded in one day (9) and subtracting the number you would typically dismiss as random (3). How many sightings are there according to this calculation?

InternLM-Math Base 20B:

 Reasoning: 504/14 = <<504/14=36>>36 sightings per day. 36-6 = <<36-6=30>>30 sightings per day. 9-3 = <<9-3=6>>6 sightings per day. 30*6 = <<30*6=180>>180 sightings.
### Answer: 180

Expected answer: 180

Correct? Yes

Problem: A blanket maker has 5 square patches of blue material. She wants to make an intricate design that requires her to subtract this from 26*25 square patches of red material. Then, she wants to compare this number to her stock of green material, which is 48*21 square patches, by subtracting the number of red patches from the green patches. How many patches is the difference between her stock of green patches and the red patches needed for the design?

InternLM-Math Base 20B:

 Reasoning: The number of red patches is 26*25 = <<26*25=650>>650.
The number of green patches is 48*21 = <<48*21=1008>>1008.
The difference between the number of green patches and the number of red patches is 1008-650 = <<1008-650=358>>358.
### Answer: 358

Expected answer: 363

Correct? No

Problem: Lemonville is a small village known for its lemon trees. One year, the villagers picked 38 baskets of lemons from the trees near the river and 24 baskets from the ones near an old well. From the trees near the school, they picked 16 more baskets and from the trees near the mayor's house, they picked 13 more baskets. They realized that their lemons were heavier and they could extract more juice so they decided to get 35 baskets to make lemonade. If each basket of lemons could produce 14 bottles of lemonade, how many bottles of lemonade would they get from the remaining baskets?

InternLM-Math Base 20B:

 Reasoning: The villagers picked 38+24+16+13 = <<38+24+16+13=91>>91 baskets of lemons. They used 35 baskets to make lemonade. They had 91-35 = <<91-35=56>>56 baskets left. Each basket could produce 14 bottles of lemonade. So, they got 56*14 = <<56*14=784>>784 bottles of lemonade from the remaining baskets.
### Answer: 784

Expected answer: 784

Correct? Yes

Problem: Amy found 21 seashells in the sandbox, but gave 15 of them to her sister. The next day, she found another group of seashells that was 13 more than the amount she had remaining from the previous day. She also found an additional 49. Being a generous sister, she gave 23 to her brother and 27 to her cousin. How many seashells does Amy have left now?

InternLM-Math Base 20B:

 Reasoning: Amy found 21 seashells in the sandbox, but gave 15 of them to her sister. She had 21-15 = <<21-15=6>>6 seashells left. The next day, she found another group of seashells that was 13 more than the amount she had remaining from the previous day. She had 6+13 = <<6+13=19>>19 seashells. She also found an additional 49. She had 19+49 = <<19+49=68>>68 seashells. Being a generous sister, she gave 23 to her brother and 27 to her cousin. She had 68-23-27 = <<68-23-27=18>>18 seashells left now.
### Answer: 18

Expected answer: 18

Correct? Yes

Problem: Princess Anna was playing a numbers game in the kingdom. In the first round of the game, she thought of two numbers: 7 and 10. She added them together. In the second round, she thought of a number 29. She subtracted the result from the first round and then subtracted 8 more from that result. In the final round, Princess Anna added the results from the first and second round and then multiplied the sum by the result from the second round. What was the final result of the Princess's game?

InternLM-Math Base 20B:

 Reasoning: In the first round, Princess Anna added 7 and 10 to get 17.
In the second round, Princess Anna subtracted 17 from 29 to get 12, and then subtracted 8 from 12 to get 4.
In the final round, Princess Anna added 17 and 4 to get 21, and then multiplied 21 by 4 to get 84.
### Answer: 84

Expected answer: 84

Correct? Yes

Problem: Ellen had 15 dollars. Meanwhile, Sam had 48 dollars but then he gave some money to Ellen. After Sam gave his money to Ellen, he had as much money as Ellen originally had. Then, Sam got 24 dollars from his brother. How much money does Sam have now?

InternLM-Math Base 20B:

 Reasoning: Ellen had 15 dollars. Sam had 48 dollars. Sam gave 48-15 = <<48-15=33>>33 dollars to Ellen. Then, Sam got 24 dollars from his brother. So, Sam has 33+24 = <<33+24=57>>57 dollars now.
### Answer: 57

Expected answer: 57

Correct? Yes

Problem: A group of scientists began studying a river and found that it was 33 kilometers long. To be thorough, they decided to also study a connected tributary, which added 19 kilometers to the total length of waterway they needed to investigate. However, they later realized that a 30-kilometer portion of the river was inaccessible and couldn't be studied. How many kilometers of the river were they able to study?

InternLM-Math Base 20B:

 Reasoning: The scientists were able to study 33+19-30 = <<33+19-30=22>>22 kilometers of the river.
### Answer: 22

Expected answer: 22

Correct? Yes

Problem: A photographer took 34 shots at a wedding but decided to remove 19 of them because they were out of focus. The next day he took an additional 21 shots at a different event. Then, he decided to add to this collection, 23 more shots he took on a third event. Similarly, another photographer took 880 shots at a large event and decided to select every 40th shot for his collection. What is the total number of shots in their collections combined?

InternLM-Math Base 20B:

 Reasoning: The first photographer took 34-19 = <<34-19=15>>15 shots at the wedding, 21 shots at the second event, and 23 shots at the third event. The second photographer took 880/40 = <<880/40=22>>22 shots. The total number of shots in their collections combined is 15+21+23+22 = <<15+21+23+22=81>>81.
### Answer: 81

Expected answer: 81

Correct? Yes

Problem: A pirate found a treasure chest containing 3 times the amount of his previous loot of 13 gold coins. After spending 22 of these coins for the crew's rum, he discovered another loot of 47 gold coins. How many gold coins does the pirate have now?

InternLM-Math Base 20B:

 Reasoning: The pirate found 3*13 = <<3*13=39>>39 gold coins.
He spent 22 of these coins, so he has 39-22 = <<39-22=17>>17 gold coins.
He found another loot of 47 gold coins, so he has 17+47 = <<17+47=64>>64 gold coins.
### Answer: 64

Expected answer: 64

Correct? Yes

Problem: A hiker traveled an average of 900 miles in 36 days. One day, he increases his daily average to 16 miles. This reduces his remaining journey by a certain number of days. After that, he finds a shortcut which saves him an additional 4 days, and a friendly traveller advised him of another path that will save him 40 days. If he also saves 21 days due to good weather, how many days in total did he save on his journey?

InternLM-Math Base 20B:

 Reasoning: The hiker traveled 900/36 = <<900/36=25>>25 miles per day. If he increases his daily average to 16 miles, he will save 9 miles per day. This will reduce his remaining journey by 9*36 = <<9*36=324>>324 miles. The hiker will save 324/9 = <<324/9=36>>36 days. The hiker saves 4+40+21 = <<4+40+21=65>>65 days in total.
### Answer: 65

Expected answer: 74

Correct? No

Problem: A pillow manufacturing company produces 33 pillows every hour in round the clock operations. In a day, they realized they had incurred a loss of 43 pillows due to machine errors. What is the total number of pillows the company manufactured in a day after accounting for the losses?

InternLM-Math Base 20B:

 Reasoning: The company produces 33 pillows every hour. In a day, they produced 33*24 = <<33*24=792>>792 pillows. They incurred a loss of 43 pillows. So, the total number of pillows the company manufactured in a day is 792-43 = <<792-43=749>>749.
### Answer: 749

Expected answer: 749

Correct? Yes

Problem: In a Castle, there are 5 rooms in one wing. The other wing has 216 bricks. Nowadays, there's a strange rule: one room is equivalent to 36 bricks. Following this, if we have to calculate the sum of total rooms from both wings by converting the number of bricks to the number of rooms. How many rooms would be considered in total according to this rule?

InternLM-Math Base 20B:

 Reasoning: 216/36 = <<216/36=6>>6 rooms in the other wing.
5+6 = <<5+6=11>>11 rooms in total.
### Answer: 11

Expected answer: 11

Correct? Yes

Problem: A player scored 15 goals each over 31 matches. However, due to an error, 43 of the goals were discounted. Later, the error was rectified and 40 goals were awarded back to the player. Unfortunately, after a reevaluation of the matches, 26 of those goals were deducted from the player again. How many goals does the player end up with?

InternLM-Math Base 20B:

 Reasoning: The player scored 15*31 = <<15*31=465>>465 goals in 31 matches.
43 goals were discounted, so the player scored 465-43 = <<465-43=422>>422 goals.
40 goals were awarded back to the player, so the player scored 422+40 = <<422+40=462>>462 goals.
26 goals were deducted from the player again, so the player scored 462-26 = <<462-26=436>>436 goals.
### Answer: 436

Expected answer: 436

Correct? Yes

Problem: An aquarium has 9 tanks, each with 49 fish. However, 5 of the fish in one tank are relocated. What is the new total number of fish in the aquarium?

InternLM-Math Base 20B:

 Reasoning: 49-5 = <<49-5=44>>44 fish are left in the tank. 9*49 = <<9*49=441>>441 fish are in the other tanks. 44+441 = <<44+441=485>>485 fish are in the aquarium.
### Answer: 485

Expected answer: 436

Correct? No

Problem: In a card game, Jeremy has 14 cards. He then discards 19 of his cards, and then gains 32 more cards from the deck. How many cards does Jeremy have now?

InternLM-Math Base 20B:

 Reasoning: Jeremy has 14-19+32 = <<14-19+32=27>>27 cards now.
### Answer: 27

Expected answer: 27

Correct? Yes

Problem: A clock ticks 504 times in 42 minutes. Similarly, another clock ticks 279 times in 31 minutes. Add 34 to the rate of the second clock's ticks per minute. Multiply the first clock's ticks per minute by 35 and then subtract 41 from it. Finally, subtract the rate of the second clock (after adding 34) from the manipulated rate of the first clock. What is the final value?

InternLM-Math Base 20B:

 Reasoning: The first clock ticks 504/42 = <<504/42=12>>12 times per minute. The second clock ticks 279/31 = <<279/31=9>>9 times per minute. Adding 34 to the second clock's rate gives 9+34 = <<9+34=43>>43 ticks per minute. Multiplying the first clock's rate by 35 gives 12*35 = <<12*35=420>>420 ticks per minute. Subtracting 41 from the first clock's rate gives 420-41 = <<420-41=379>>379 ticks per minute. Subtracting the second clock's rate from the first clock's rate gives 379-43 = <<379-43=336>>336 ticks per minute.
### Answer: 336

Expected answer: 336

Correct? Yes

Problem: Nina has noted down the rainfall of her town in centimeters over the last few days. On Tuesday, there was a rainfall of 39 cm. The rainfall decreased by 6 cm on Wednesday and further decreased by 31 cm on Thursday. How much rainfall did Nina note on Thursday?

InternLM-Math Base 20B:

 Reasoning: The rainfall on Thursday was 39-6-31 = <<39-6-31=-36>>-36 cm.
### Answer: -36

Expected answer: 2

Correct? No

Problem: A UFO-watching enthusiast reported seeing 50 UFOs in a month. However, a later investigation revealed that 36 of these were actually meteors. In the next month, the enthusiast reported seeing 41 UFOs, plus an amount equal to the revised (i.e., actual) number of UFO sightings from the previous month, with an additional 5. How many UFO sightings were reported by the enthusiast in the second month?

InternLM-Math Base 20B:

 Reasoning: The enthusiast reported seeing 50-36 = <<50-36=14>>14 UFOs in the first month. In the second month, the enthusiast reported seeing 41+14+5 = <<41+14+5=60>>60 UFOs.
### Answer: 60

Expected answer: 60

Correct? Yes

Problem: A cat started playing with yarn balls. In her first game, she managed to accumulate 5 yarn balls. In her second game, she got as many balls as the square of what she obtained in the first game plus 8 more. Finally, she lost some of her balls in her third game due to a playful dog. She ended the game with a number of balls which is 25 times the difference between 45 and what she accumulated from the second game. How many yarn balls does the cat have now?

InternLM-Math Base 20B:

 Reasoning: The cat got 5+8 = <<5+8=13>>13 balls in the second game. She lost 25*(45-13) = <<25*(45-13)=800>>800 balls in the third game. She has 5+13-800 = <<5+13-800=-782>>-782 balls now.
### Answer: -782

Expected answer: 300

Correct? No

Problem: A basket contains 41 balls. The balls are split into two types - tennis balls and cricket balls. If we remove 16 balls from the basket, we get cricket balls. When 9 ping pong balls and 21 basketballs are added to the basket, what is the total number of balls in the basket?

InternLM-Math Base 20B:

 Reasoning: The number of balls in the basket is 41. The number of balls removed is 16. The number of balls added is 9+21 = <<9+21=30>>30. The total number of balls in the basket is 41-16+30 = <<41-16+30=55>>55.
### Answer: 55

Expected answer: 55

Correct? Yes

Problem: The design of a classic wall clock dictates that there should be 1 number represented for every 12 around the clock face. However, your quirky modernist clockmaker friend wants to do things differently. They want to represent 37 hours on the clock's face, each hour has an equivalent of 1 square. Your friend has already completed 32 squares. They left their project for a while, and when they came back, they forgot how many squares they needed to fulfill their quirk. So they did some math to figure it out: they subtracted 32 from 37, added 42 to the result, and then subtracted 37 from that total. Suddenly, an idea occurred to them. What if they add 25 more squares for representing minutes on their quirky clock? Plus, they also wanted to add another 28 squares for seconds. Since your friend is a bit forgetful, they forgot how many squares they need again to finish their project. So, they did a little more math - added 41 to 25, followed by another 28, and then added 17 to the result. Because your friend didn't have enough material, they decided that they could reduce the total number of squares by 23. Finally, they added the number they figured out at the beginning (for hours) to this reduced number. Can you help your friend figure out how many squares they would need in total to complete their quirky clock?

InternLM-Math Base 20B:

 Reasoning: The number of squares needed for hours is 37-32 = <<37-32=5>>5. The number of squares needed for minutes is 25. The number of squares needed for seconds is 28. The total number of squares needed is 5+25+28 = <<5+25+28=58>>58. The total number of squares needed is 58-23 = <<58-23=35>>35. The total number of squares needed is 35+5 = <<35+5=40>>40.
### Answer: 40

Expected answer: 98

Correct? No

Problem: An orange farm produced 2 times the 28 pounds of oranges they typically produce in a single day due to a new method. This production also multiplied by the 15 days of the harvest period. If the farm then added 16 pounds of a rare orange variant to this harvest, how much did the farm produce in total?

InternLM-Math Base 20B:

 Reasoning: The farm produced 28*2 = <<28*2=56>>56 pounds of oranges in a single day.
The farm produced 56*15 = <<56*15=840>>840 pounds of oranges in the harvest period.
The farm produced 840+16 = <<840+16=856>>856 pounds of oranges in total.
### Answer: 856

Expected answer: 856

Correct? Yes

Problem: A bus has 37 passengers. At the next stop, 20 more passengers get on. Before the bus reaches to the next stop, 44 passengers get off. Now, suppose this remaining number of passengers each pays an $11 fare, but the bus company also deducts a $14 service fee from the total fare. How much revenue does the bus company get?

InternLM-Math Base 20B:

 Reasoning: The bus has 37+20-44 = <<37+20-44=3>>3 passengers now.
The bus company gets 3*11-14 = <<3*11-14=17>>$17.
### Answer: $17

Expected answer: 129

Correct? No

Problem: A pirate found a treasure chest with 13 emeralds, 42 rubies, and 19 sapphires. He gave away 43 of these precious gems to his crewmates. How many gems did the pirate have left?

InternLM-Math Base 20B:

 Reasoning: The pirate gave away 43/3 = <<43/3=14>>14 gems of each type.
The pirate had 13-14 = <<13-14=-1>>-1 emeralds, 42-14 = <<42-14=28>>28 rubies, and 19-14 = <<19-14=5>>5 sapphires left.
### Answer: -1, 28, 5

Expected answer: 31

Correct? No

Problem: A certain reserve has 16 ginger giraffes. They then bring in the same number of golden giraffes as they had of the ginger ones. Later, they decide to add another group of 46 greyish giraffes. What is the total number of giraffes in the reserve now?

InternLM-Math Base 20B:

 Reasoning: The number of ginger giraffes is 16.
The number of golden giraffes is 16.
The number of greyish giraffes is 46.
The total number of giraffes is 16+16+46 = <<16+16+46=78>>78.
### Answer: 78

Expected answer: 78

Correct? Yes

Problem: A turtle decides to swim. One day, it travels as many leagues as 11 plus 10, then multiplies that by 16 to get the total distance it swam that week. Later, it realized it had over calculated the distance by 41 leagues. What is the real distance it swam that week?

InternLM-Math Base 20B:

 Reasoning: 11+10 = <<11+10=21>>21, 21*16 = <<21*16=336>>336, 336-41 = <<336-41=295>>295.
The real distance it swam that week is 295 leagues.
### Answer: 295

Expected answer: 295

Correct? Yes