InternLM-Math Base 20B on 5.OA.A.1
Common Core Standard 5.OA.A.1
This standard covers the following:
Use parentheses, brackets, or braces in numerical expressions, and evaluate expressions with these symbols.
Problem: A sock company packages their socks in sets of 40. They have 2840 socks to package, and they currently have 93 packs already made. How many packs of socks will they have in total once all the socks have been packaged? Afterward, they received an another shipment of 70 packs of socks, but had to return 8 due to quality issues. How many packs of socks does the company have now?
InternLM-Math Base 20B:
Reasoning: 2840/40 = <<2840/40=71>>71 packs of socks will be made. 71+93 = <<71+93=164>>164 packs of socks will be made in total. Reasoning: 70-8 = <<70-8=62>>62 packs of socks were received. 164+62 = <<164+62=226>>226 packs of socks are now available. ### Answer: 226
Expected answer: 226
Correct? Yes
Problem: A gardener has a field where he planted 80 rose bushes, with each bush producing 30 roses. Before he is able to gather them, a storm blows away 43 roses. How many roses are remaining in the field?
InternLM-Math Base 20B:
Reasoning: The gardener has 80 rose bushes, and each bush produces 30 roses. So, he has 80*30 = <<80*30=2400>>2400 roses in total. The storm blows away 43 roses. So, he has 2400-43 = <<2400-43=2357>>2357 roses remaining in the field. ### Answer: 2357
Expected answer: 2357
Correct? Yes
Problem: The gardener realizes afterwards that he initially miscounted the rose bushes in the field. It turns out there were not 80, but 84 rose bushes instead, each still producing 30 roses, and the storm still managed to blow away 43 roses. How many roses does he actually have remaining in the field after the correction?
InternLM-Math Base 20B:
Reasoning: The gardener has 84 rose bushes, and each bush produces 30 roses. So, he has 84*30 = <<84*30=2520>>2520 roses in total. The storm blows away 43 roses. So, he has 2520-43 = <<2520-43=2477>>2477 roses remaining in the field. ### Answer: 2477
Expected answer: 2477
Correct? Yes
Problem: A dolphin can leap (3 + 59) feet high. If a dolphin completes 89 jumps in a day, how many feet in total has the dolphin jumped in that day?
InternLM-Math Base 20B:
Reasoning: 3 + 59 = <<3+59=62>>62 feet is the height of a dolphin's jump. 89 × 62 = <<89*62=5518>>5518 feet is the total height of the dolphin's jumps. ### Answer: 5518
Expected answer: 5518
Correct? Yes
Problem: Continuing from the original scenario, suppose we made a mistake in our measurements and realized that the dolphin, in fact, can leap (41 + 59) feet high instead of (3 + 59) feet. Considering this, if the dolphin still completes 89 jumps in a day, how many feet in total has the dolphin jumped in that day now?
InternLM-Math Base 20B:
Reasoning: 41 + 59 = <<41+59=100>>100 feet is the height of a dolphin's jump. 89 × 100 = <<89*100=8900>>8900 feet is the total height of the dolphin's jumps. ### Answer: 8900
Expected answer: 8900
Correct? Yes
Problem: A candy store starts the day with 81 pieces of candy. They receive a delivery adding another 6 candies, but they sell 61 throughout the day. How many pieces of candy does the store have left?
InternLM-Math Base 20B:
Reasoning: The store has 81+6 = <<81+6=87>>87 pieces of candy at the end of the day. They sell 61 of them, so they have 87-61 = <<87-61=26>>26 pieces of candy left. ### Answer: 26
Expected answer: 26
Correct? Yes
Problem: Continuing from the original scenario, suppose the candy store started the day with 81 pieces of candy and received a delivery adding 6, but this time, they only sold 7 candies throughout the day. How many pieces of candy does the store now have left?
InternLM-Math Base 20B:
Reasoning: The store has 81+6 = <<81+6=87>>87 pieces of candy at the end of the day. They sell 7 of them, so they have 87-7 = <<87-7=80>>80 pieces of candy left. ### Answer: 80
Expected answer: 80
Correct? Yes
Problem: A sports store received a huge shipment of 6806 pairs of ice skates. If they evenly distribute the skates over 82 separate stores, how many pairs of ice skates does each store receive?
InternLM-Math Base 20B:
Reasoning: 6806/82 = <<6806/82=83>>83 pairs of ice skates. Each store receives 83 pairs of ice skates. ### Answer: 83
Expected answer: 83
Correct? Yes
Problem: A sports store received a huge shipment of 6806 pairs of ice skates. After reconsideration, they decided to distribute the skates over 61 stores instead of the original 82. How many pairs of ice skates does each store receive now?
InternLM-Math Base 20B:
Reasoning: 6806/61 = <<6806/61=111>>111 pairs of ice skates. Each store receives 111 pairs of ice skates. ### Answer: 111
Expected answer: 6806/61
Correct? No
Problem: If a stationery store has 40 white erasers and 74 pink erasers, how many erasers are there in total?
InternLM-Math Base 20B:
Reasoning: 40+74 = <<40+74=114>>114 ### Answer: 114
Expected answer: 114
Correct? Yes
Problem: Suppose instead that the stationery store had 40 white erasers and 37 pink erasers initially. How many erasers would be there in total in that case?
InternLM-Math Base 20B:
Reasoning: 40+37 = <<40+37=77>>77 ### Answer: 77
Expected answer: 77
Correct? Yes
Problem: A company manufactures a batch of pens, with each batch containing 39 pens. If the company has produced 10 such batches, how many pens does the company have now?
InternLM-Math Base 20B:
Reasoning: The company has 39×10 = <<39*10=390>>390 pens. ### Answer: 390
Expected answer: 390
Correct? Yes
Problem: The company found an error in their manufacturing record and realized they actually produced 43 batches of pens, not 10. Each batch still contained 39 pens. How many pens did the company actually produce?
InternLM-Math Base 20B:
Reasoning: The company has 39×43 = <<39*43=1677>>1677 pens. ### Answer: 1677
Expected answer: 1677
Correct? Yes
Problem: A dairy farm has 33 cows. Each cow gives (99 + 58) litres of milk per day. How many litres of milk does the farm produce in a day?
InternLM-Math Base 20B:
Reasoning: 33 × (99 + 58) = <<33*(99+58)=33*157=5101>>5101 The farm produces 5101 litres of milk in a day. ### Answer: 5101
Expected answer: 5181
Correct? No
Problem: A farmer's grape vine produces 3344 grapes, and he has 38 equally productive grape vines. How many grapes does each vine produce?
InternLM-Math Base 20B:
Reasoning: The farmer has 38 grape vines, and each grape vine produces 3344/38 = <<3344/38=88>>88 grapes. ### Answer: 88
Expected answer: 88
Correct? Yes
Problem: In the original scenario, a grape vine produces 3344 grapes and the farmer has 38 equally productive grape vines. Now consider a new situation. Let's say the farmer had 75 equally productive vines instead of 38. How many grapes would each vine have produced now?
InternLM-Math Base 20B:
Reasoning: The farmer has 75 grape vines, and each grape vine produces 3344/75 = <<3344/75=44>>44 grapes. ### Answer: 44
Expected answer: 3344/75
Correct? No
Problem: Yesterday, a region experienced a heavy snowfall of 93 cm and today it received additional 29 cm of snow. However, 20 cm of snow has melted. How much snow is now left?
InternLM-Math Base 20B:
Reasoning: 93+29 = <<93+29=122>>122 cm of snow fell in total. 20 cm of snow melted, so 122-20 = <<122-20=102>>102 cm of snow is left. ### Answer: 102
Expected answer: 102
Correct? Yes
Problem: Considering the previous problem, suppose the region experienced a heavier snowfall of 90 cm (instead of 29 cm) today, while the 20 cm melt remained the same. How might this change the amount of snow now left?
InternLM-Math Base 20B:
Reasoning: 93+90 = <<93+90=183>>183 cm of snow fell in total. 20 cm of snow melted, so 183-20 = <<183-20=163>>163 cm of snow is left. ### Answer: 163
Expected answer: 163
Correct? Yes
Problem: A farmer has 3069 grapes. If he decides to put 33 grapes in each bag, he will have a certain number of bags. However, the farmer eats 13 bags of grapes and also gives away 50 bags of grapes. How many bags of grapes does the farmer have left?
InternLM-Math Base 20B:
Reasoning: The farmer has 3069/33 = <<3069/33=92>>92 bags of grapes. He eats 13 bags of grapes and gives away 50 bags of grapes. He has 92-13-50 = <<92-13-50=39>>39 bags of grapes left. ### Answer: 39
Expected answer: 30
Correct? No
Problem: A giraffe's neck has a length of 275 centimeters. If one meter is made up of 5 centimeters, what is the length of the giraffe's neck in meters?
InternLM-Math Base 20B:
Reasoning: 275/5 = <<275/5=55>>55 ### Answer: 55
Expected answer: 55
Correct? Yes
Problem: After measuring the giraffe's neck in meters, the zookeeper re-evaluates and discovers that his conversion tool was using an incorrect scale, where one meter actually equals 43 centimeters, not 5 centimeters. Given this new information, what is the length of the giraffe's neck in meters?
InternLM-Math Base 20B:
Reasoning: 275/43 = <<275/43=6.4>>6.4 ### Answer: 6.4
Expected answer: 275/43
Correct? No
Problem: A furniture store had 79 chairs in stock. They received a shipment adding 9 more chairs, but then sold 45 chairs in a single day. How many chairs are now in the store?
InternLM-Math Base 20B:
Reasoning: The store now has 79+9-45 = <<79+9-45=73>>73 chairs. ### Answer: 73
Expected answer: 43
Correct? No
Problem: A teddy bear factory can usually produce 91 teddy bears per day. However, today their capacity increased by 1 due to new equipment. A charity has also just donated materials to produce 15 additional teddy bears. How many total teddy bears can the factory produce today?
InternLM-Math Base 20B:
Reasoning: The factory can produce 91+1 = <<91+1=92>>92 teddy bears per day. The factory can also produce 15 additional teddy bears. Therefore, the factory can produce 92+15 = <<92+15=107>>107 teddy bears today. ### Answer: 107
Expected answer: 107
Correct? Yes
Problem: A giraffe needs 67 leaves to eat at breakfast and 33 more in the afternoon. How many leaves does the giraffe need for a single day?
InternLM-Math Base 20B:
Reasoning: The giraffe needs 67+33 = <<67+33=100>>100 leaves for a single day. ### Answer: 100
Expected answer: 100
Correct? Yes
Problem: If you can drive 304 miles on a tank of gas and the tank is divided into 4 equal parts, how many miles can you drive on one part of the tank?
InternLM-Math Base 20B:
Reasoning: 304/4 = <<304/4=76>>76 miles can be driven on one part of the tank. ### Answer: 76
Expected answer: 76
Correct? Yes
Problem: If you can drive 304 miles on a full tank of gas which is divided into 4 equal parts, you've found that you can drive a certain distance on one part of the tank. If you refill this part of the tank 47 times, how many miles in total could you potentially drive?
InternLM-Math Base 20B:
Reasoning: 304/4 = <<304/4=76>>76 miles can be driven on one part of the tank. 47*76 = <<47*76=3572>>3572 miles can be driven in total. ### Answer: 3572
Expected answer: 3572
Correct? Yes
Problem: If instead of a tank which can hold enough gas to drive 304 miles, you have a smaller tank which holds enough gas to drive 304 miles, and you divide the tank into 91 equal parts, how many miles can you drive on one part of the tank?
InternLM-Math Base 20B:
Reasoning: 304/91 = <<304/91=3.3>>3.3 miles can be driven on one part of the tank. ### Answer: 3.3
Expected answer: 304/91
Correct? No
Problem: A shop sells ice skates at 25 dollars a pair. They are having a sale where all ice skates are increased by 8 dollars. How much would a pair of ice skates cost during the sale?
InternLM-Math Base 20B:
Reasoning: The cost of a pair of ice skates during the sale is 25+8 = <<25+8=33>>33 dollars. ### Answer: 33
Expected answer: 33
Correct? Yes
Problem: In the previous scenario, the shop sells ice skates at 25 dollars a pair on sale. After the increase, a pair of ice skates is priced at 33 dollars. If a customer only has 70 dollars, how much money will they have left after buying a pair of ice skates during the sale?
InternLM-Math Base 20B:
Reasoning: The customer will have 70-33 = <<70-33=37>>37 dollars left after buying a pair of ice skates during the sale. ### Answer: 37
Expected answer: 37
Correct? Yes
Problem: In the previous scenario, the price of ice skates was 25 dollars a pair before the price increase. Now, consider a scenario where the original price of the ice skates was 79 dollars a pair instead of 25 dollars. If the price was increased by the same amount, 8 dollars, how much would a pair of ice skates cost now?
InternLM-Math Base 20B:
Reasoning: The cost of a pair of ice skates during the sale is 79+8 = <<79+8=87>>87 dollars. ### Answer: 87
Expected answer: 87
Correct? Yes
Problem: A river flows at a speed of 96 miles per day. How far would it have travelled in 31 days?
InternLM-Math Base 20B:
Reasoning: 96 × 31 = <<96*31=2976>>2976 The river would have travelled 2976 miles in 31 days. ### Answer: 2976
Expected answer: 2976
Correct? Yes
Problem: Continuing from the previous problem, if the river also carried a piece of debris that got an additional 94 miles downstream due to the wind in those 31 days, how far would the piece of debris have traveled in total?
InternLM-Math Base 20B:
Reasoning: 2976 + 94 = <<2976+94=3070>>3070 The piece of debris would have travelled 3070 miles in total. ### Answer: 3070
Expected answer: 3070
Correct? Yes
Problem: Continuing from the previous problem, suppose the river flow was less than initially thought. Rather than flowing at a speed of 96 miles per day, it actually flows at a speed of 12 miles per day. How far would the river have traveled in 31 days at this slower speed?
InternLM-Math Base 20B:
Reasoning: 12 × 31 = <<12*31=372>>372 The river would have travelled 372 miles in 31 days. ### Answer: 372
Expected answer: 372
Correct? Yes
Problem: A manufacturer produces 46 blankets each day. After 43 days, an additional 42 blankets were donated to the manufacturer. How many blankets does the manufacturer now have in total?
InternLM-Math Base 20B:
Reasoning: The manufacturer has 46*43 = <<46*43=1978>>1978 blankets after 43 days. The manufacturer now has 1978+42 = <<1978+42=2019>>2019 blankets in total. ### Answer: 2019
Expected answer: 2020
Correct? No
Problem: A particular star emits light at a velocity of 1095 miles per second. If this velocity were divided by 73, what would be the resulting speed of the light emitted by the star?
InternLM-Math Base 20B:
Reasoning: 1095/73 = <<1095/73=15>>15 ### Answer: 15
Expected answer: 15
Correct? Yes
Problem: Following our previous scenario, let's consider that instead of dividing by 73, the velocity of the star's light was divided by 42. What would be the resulting speed of the light emitted by the star, given this new calculation?
InternLM-Math Base 20B:
Reasoning: 1095/42 = <<1095/42=26>>26 ### Answer: 26
Expected answer: 365/14
Correct? No
Problem: A lemon tree produces 99 lemons every year. After 51 years, a massive wind storm passes through the area and removes 84 lemons from the total number of lemons the tree produced. How many lemons did the lemon tree produce after the wind storm?
InternLM-Math Base 20B:
Reasoning: The tree produced 99 lemons every year. After 51 years, the tree produced 99*51 = <<99*51=5049>>5049 lemons. After the wind storm, the tree produced 5049-84 = <<5049-84=4965>>4965 lemons. ### Answer: 4965
Expected answer: 4965
Correct? Yes
Problem: After 40 years instead of 51, a massive wind storm passes through the area removing 84 lemons from the total number of lemons the tree produced. Given this earlier timing of the wind storm, how many lemons did the lemon tree produce after the wind storm?
InternLM-Math Base 20B:
Reasoning: The tree produced 99 lemons every year. After 40 years, the tree produced 99*40 = <<99*40=3960>>3960 lemons. After the wind storm, the tree produced 3960-84 = <<3960-84=3876>>3876 lemons. ### Answer: 3876
Expected answer: 3876
Correct? Yes
Problem: John had 4 packs of building blocks and each pack contains 89 blocks. After losing 72 blocks while playing, how many blocks does John have now?
InternLM-Math Base 20B:
Reasoning: John had 4*89 = <<4*89=356>>356 blocks in total. After losing 72 blocks, he has 356-72 = <<356-72=284>>284 blocks now. ### Answer: 284
Expected answer: 284
Correct? Yes
Problem: Instead of the initial 89 blocks in each pack, John found out that 41 blocks were in each of his 4 packs. After losing 72 blocks, how many blocks does John have now?
InternLM-Math Base 20B:
Reasoning: John had 4*41 = <<4*41=164>>164 blocks in total. After losing 72 blocks, he has 164-72 = <<164-72=92>>92 blocks now. ### Answer: 92
Expected answer: 92
Correct? Yes
Problem: On a particular beach, 5544 seashells are evenly distributed across 72 meters of sand. How many seashells are there on average for every meter of the beach?
InternLM-Math Base 20B:
Reasoning: 5544/72 = <<5544/72=77>>77 There are 77 seashells on average for every meter of the beach. ### Answer: 77
Expected answer: 77
Correct? Yes
Problem: In a revised count, it was discovered that the seashells were actually spread over 92 meters of the beach instead of 72 meters as previously thought. Now, how many seashells are there on average for each meter of the beach?
InternLM-Math Base 20B:
Reasoning: 5544/92 = <<5544/92=60>>60 There are 60 seashells on average for every meter of the beach. ### Answer: 60
Expected answer: 1386/23
Correct? No
Problem: There are 82 animals in the zoo. If 67 animals are birds, how many animals in the zoo are not birds?
InternLM-Math Base 20B:
Reasoning: 82-67 = <<82-67=15>>15 animals in the zoo are not birds. ### Answer: 15
Expected answer: 15
Correct? Yes
Problem: In a revision to the previous count, it turns out there were only 38 birds instead of 67 at the zoo originally. Given this, how many animals in the zoo were not birds?
InternLM-Math Base 20B:
Reasoning: 82-38 = <<82-38=44>>44 animals in the zoo are not birds. ### Answer: 44
Expected answer: 44
Correct? Yes
Problem: A construction company builds 36 houses every month. If they kept this pace up for 46 months, how many houses would they have built over this time?
InternLM-Math Base 20B:
Reasoning: 36 × 46 = <<36*46=1656>>1656 The construction company would have built 1656 houses over this time. ### Answer: 1656
Expected answer: 1656
Correct? Yes
Problem: In the same construction company's new plan, instead of building 36 houses they are planning to build 75 houses a month. If they managed to keep up this pace for the same period of 46 months, how many houses would they have built in total with this increased productivity?
InternLM-Math Base 20B:
Reasoning: 75 × 46 = <<75*46=3450>>3450 The construction company would have built 3450 houses over this time. ### Answer: 3450
Expected answer: 3450
Correct? Yes
Problem: A window factory has a goal to produce 1767 windows within a month. If the factory operates 31 days a month, how many windows does it need to produce each day to meet its goal?
InternLM-Math Base 20B:
Reasoning: The factory needs to produce 1767/31 = <<1767/31=56.7>>56.7 windows each day to meet its goal. ### Answer: 56.7
Expected answer: 57
Correct? No
Problem: A TV series has just been renewed for its third season. The 1st season had 66 episodes, the 2nd season had 67 episodes, and now 8 episodes of the 3rd season have been aired. How many episodes have aired in total?
InternLM-Math Base 20B:
Reasoning: The 3rd season has 8 episodes. The 1st and 2nd seasons have 66+67 = <<66+67=133>>133 episodes. The total number of episodes is 133+8 = <<133+8=141>>141. ### Answer: 141
Expected answer: 141
Correct? Yes
Problem: After the 8 episodes of the 3rd season were aired, the TV series continued to air more episodes. In the remaining part of the 3rd season, they aired 80 episodes. They have also just finished airing all the 82 episodes of the 4th season. How many episodes have aired in total now?
InternLM-Math Base 20B:
Reasoning: The 3rd season has 8+80 = <<8+80=88>>88 episodes. The 4th season has 82 episodes. The total number of episodes is 88+82 = <<88+82=170>>170. ### Answer: 170
Expected answer: 303
Correct? No
Problem: Let's imagine that in the first two seasons of the TV series there were fewer episodes than we initially thought. The 1st season had 66 episodes and the second season only had 8. After 8 more episodes of the 3rd season aired, how many total episodes have aired so far?
InternLM-Math Base 20B:
Reasoning: The 3rd season has 8 episodes. The 1st and 2nd seasons have 66+8 = <<66+8=74>>74 episodes. The total number of episodes is 74+8 = <<74+8=82>>82. ### Answer: 82
Expected answer: 82
Correct? Yes
Problem: At the end of a rainbow, a leprechaun is guarding a pot of gold coins. He adds 39 gold coins to the pot, then another 47. However, while he is distracted, a fairy takes away 8 gold coins from the pot. The new total of coins becomes a code to a magical lock. The code must be enhanced by adding 48 to it only once, and then multiplied by 24. What is the final value to unlock the magical lock?
InternLM-Math Base 20B:
Reasoning: The leprechaun added 39+47 = <<39+47=86>>86 gold coins to the pot. The fairy took away 8 gold coins from the pot. The new total of coins is 86-8 = <<86-8=78>>78. The final value to unlock the magical lock is 78+48 = <<78+48=126>>126*24 = <<126*24=3024>>3024. ### Answer: 3024
Expected answer: 3024
Correct? Yes
Problem: The leprechaun realizes that there was a mistake in the first part of his magical lock code. Instead of multiplying the initial set of gold coin count by 24 after adding 48, he should have multiplied it by 29. Given this new information, what should be the correct initial value to unlock the magical lock?
InternLM-Math Base 20B:
Reasoning: The final value to unlock the magical lock is 3024/29 = <<3024/29=104>>104. The initial value to unlock the magical lock is 104-48 = <<104-48=56>>56. ### Answer: 56
Expected answer: 3654
Correct? No
Problem: John has 98 dollars in his wallet. He found a 35-dollar bill on the ground and added it to his wallet. However, he then spent 38 dollars on lunch. How much money does he have left in his wallet now?
InternLM-Math Base 20B:
Reasoning: John has 98+35 = <<98+35=133>>133 dollars in his wallet. He then spent 38 dollars on lunch. He has 133-38 = <<133-38=95>>95 dollars left in his wallet. ### Answer: 95
Expected answer: 95
Correct? Yes
Problem: Following the previous scenarios, let's reconsider the scenario like this: suppose the amount that John decided to spend on lunch was not 38 dollars, but actually 68 dollars. How much money does he have left in his wallet after this change?
InternLM-Math Base 20B:
Reasoning: John has 98+35 = <<98+35=133>>133 dollars in his wallet. He then spent 68 dollars on lunch. He has 133-68 = <<133-68=65>>65 dollars left in his wallet. ### Answer: 65
Expected answer: 65
Correct? Yes
Problem: A bottling factory fills 3840 bottles every hour. How many bottles does it fill every minute?
InternLM-Math Base 20B:
Reasoning: 3840/60 = <<3840/60=64>>64 bottles every minute. ### Answer: 64
Expected answer: 64
Correct? Yes
Problem: In the bottling factory, an upgrade to the machines increases the manufacturing speed by 19 bottles per minute. After the upgrade, how many bottles does the factory fill every minute?
InternLM-Math Base 20B:
Reasoning: 64+19 = <<64+19=83>>83 bottles every minute. ### Answer: 83
Expected answer: 83
Correct? Yes
Problem: In the bottling factory, imagine that before the upgrade, the machinery was even slower, filling bottles at a rate of 3840 bottles every 18 hours, instead of 60 minutes. How many bottles were being filled every hour in that case?
InternLM-Math Base 20B:
Reasoning: 3840/18 = <<3840/18=216>>216 bottles every hour. ### Answer: 216
Expected answer: 640/3
Correct? No
Problem: In a mystical world, a dragon has 1702 treasures in his cave. If he divides these treasures among his 37 faithful gnomes and then decides to add another 49 treasures to each one, how many treasures does each gnome now have?
InternLM-Math Base 20B:
Reasoning: The dragon divides 1702/37 = <<1702/37=46>>46 treasures among his 37 faithful gnomes. Then he adds 49 treasures to each one. So each gnome now has 46+49 = <<46+49=95>>95 treasures. ### Answer: 95
Expected answer: 95
Correct? Yes
Problem: In the previous scenario, imagine that instead of adding 49 treasures to each gnome's share, the dragon decided to add 79 treasures. How many treasures does each gnome now have?
InternLM-Math Base 20B:
Reasoning: The dragon divides 1702/37 = <<1702/37=46>>46 treasures among his 37 faithful gnomes. Then he adds 79 treasures to each one. So each gnome now has 46+79 = <<46+79=125>>125 treasures. ### Answer: 125
Expected answer: 125
Correct? Yes
Problem: If a frog can hop 192 inches in total and on average, hops 6 inches per single leap, how many leaps does it take for the frog to reach the end of its journey?
InternLM-Math Base 20B:
Reasoning: 192/6 = <<192/6=32>>32 leaps. ### Answer: 32
Expected answer: 32
Correct? Yes
Problem: Continuing from the previous scenario, let's say the frog has increased its leaping ability and can now hop 83 inches in total with an average of 6 inches per leap. How many leaps does it take for the frog to complete this new journey?
InternLM-Math Base 20B:
Reasoning: 83/6 = <<83/6=13.8333>>13.8333 leaps. ### Answer: 13.8333
Expected answer: 83/6
Correct? No
Problem: A cheese factory produces 5865 kg of cheese evenly over 85 days. How much cheese does the factory produce each day?
InternLM-Math Base 20B:
Reasoning: 5865/85 = <<5865/85=69>>69 kg of cheese is produced each day. ### Answer: 69
Expected answer: 69
Correct? Yes
Problem: Continuing with the scenario of the cheese factory, let's say the factory now operates 31 days a month rather than 85 days, with the overall cheese production still being 5865 kg. How much cheese would now be produced each day?
InternLM-Math Base 20B:
Reasoning: 5865/31 = <<5865/31=188>>188 kg of cheese is produced each day. ### Answer: 188
Expected answer: 5865/31
Correct? No
Problem: A cucumber farm yields 2592 cucumbers per 54 plants. If a section of the farm grows 38 plants, subtracting the 74 cucumbers that were damaged, how many cucumbers are available for sale?
InternLM-Math Base 20B:
Reasoning: 2592/54 = <<2592/54=48>>48 cucumbers per plant. 38 plants yield 38*48 = <<38*48=1824>>1824 cucumbers. 1824 - 74 = <<1824-74=1750>>1750 cucumbers are available for sale. ### Answer: 1750
Expected answer: 1750
Correct? Yes
Problem: In a new scenario, where an exact amount of 1 cucumber is damaged instead of 74 in the section growing 38 plants, how many cucumbers would now be available for sale from that section?
InternLM-Math Base 20B:
Reasoning: 2592/54 = <<2592/54=48>>48 cucumbers per plant. 38 plants yield 38*48 = <<38*48=1824>>1824 cucumbers. 1824 - 1 = <<1824-1=1823>>1823 cucumbers are available for sale. ### Answer: 1823
Expected answer: 1823
Correct? Yes
Problem: A toy car battery lasts 16 hours. However, if the car's lights are used, the battery life decreases by the equivalent of 36 divided by 9 hours. Assuming the toy car is run with the lights on for 12 full weeks, each week considered to be 60 hours, how long did the battery last?
InternLM-Math Base 20B:
Reasoning: The toy car's battery lasts 16 hours. However, if the car's lights are used, the battery life decreases by the equivalent of 36/9 = <<36/9=4>>4 hours. Therefore, the battery lasts 16-4 = <<16-4=12>>12 hours with the lights on. The toy car is run with the lights on for 12 full weeks, each week considered to be 60 hours. Therefore, the toy car is run with the lights on for 12*60 = <<12*60=720>>720 hours. The battery lasts 720/12 = <<720/12=60>>60 weeks. Therefore, the battery lasted 60 weeks. ### Answer: 60
Expected answer: 8640
Correct? No
Problem: A hand-crafted leather wallet costs 2407 dollars. If you can pay this in 83 installments, how much money would each installment be?
InternLM-Math Base 20B:
Reasoning: 2407/83 = <<2407/83=29>>29 Each installment would be 29 dollars. ### Answer: 29
Expected answer: 29
Correct? Yes
Problem: If you decide to buy a simple keychain from the same craftsman instead, which costs the same as a single installment of your previous purchase, how much does it cost if each installment was 83 dollars divided by 83?
InternLM-Math Base 20B:
Reasoning: 29/83 = <<29/83=0.35>>0.35 The keychain costs 0.35 dollars. ### Answer: 0.35
Expected answer: 1
Correct? No
Problem: A big grizzly bear feasts on 2726 ounces of salmon during a 58-day summer period. How much salmon does the bear eat each day on average?
InternLM-Math Base 20B:
Reasoning: The bear eats 2726/58 = <<2726/58=47>>47 ounces of salmon each day on average. ### Answer: 47
Expected answer: 47
Correct? Yes
Problem: In the original problem, the big grizzly bear ate 2726 ounces of salmon over a 58-day summer period. However, what would have been the daily average if the bear had eaten the same total amount of salmon but over a shorter 50-day period instead?
InternLM-Math Base 20B:
Reasoning: The bear eats 2726/50 = <<2726/50=54.52>>54.52 ounces of salmon each day on average. ### Answer: 54.52
Expected answer: 1363/25
Correct? Yes
Problem: A farmer has two patches of land. One patch yields 26 carrots and the other yields 16 carrots. If every day for 77 days, the farmer collects the same amount of carrots, how many carrots has the farmer collected in total?
InternLM-Math Base 20B:
Reasoning: The farmer collects 26+16 = <<26+16=42>>42 carrots per day. The farmer collects 42*77 = <<42*77=3234>>3234 carrots in total. ### Answer: 3234
Expected answer: 3234
Correct? Yes
Problem: Let's consider the farmer's situation again. What if, instead of 77 days, the farmer only collected carrots from his patches of land for a period of 22 days. How many total carrots would he have collected from his patches during this time?
InternLM-Math Base 20B:
Reasoning: The farmer collects 42 carrots per day. The farmer collects 42*22 = <<42*22=924>>924 carrots in total. ### Answer: 924
Expected answer: 924
Correct? Yes
Problem: A clothes store had 71 pairs of pants in stock at the beginning of the week. They received an additional shipment of 39 pairs, but then sold 54 pairs. How many pairs of pants does the store have in stock now?
InternLM-Math Base 20B:
Reasoning: The store has 71+39 = <<71+39=110>>110 pairs of pants in stock at the beginning of the week. The store sold 54 pairs of pants, so they have 110-54 = <<110-54=56>>56 pairs of pants in stock now. ### Answer: 56
Expected answer: 56
Correct? Yes
Problem: A chef uses 483g of sugar to make 7 of her special cakes. How much sugar does she use for each cake?
InternLM-Math Base 20B:
Reasoning: The chef uses 483/7 = <<483/7=69>>69g of sugar for each cake. ### Answer: 69
Expected answer: 69
Correct? Yes
Problem: In the next batch, the chef decided to add an extra 25g of sugar to her special cake recipe to make it sweeter. How much sugar does she use now for each cake?
InternLM-Math Base 20B:
Reasoning: The chef uses 69+25 = <<69+25=94>>94g of sugar for each cake. ### Answer: 94
Expected answer: 94
Correct? Yes
Problem: After receiving some feedback, the chef used less sugar in her next batch of cakes. She used only 65g for seven cakes. How much sugar does she use now for each cake?
InternLM-Math Base 20B:
Reasoning: The chef uses 65/7 = <<65/7=9.285714285714286>>9.285714285714286g of sugar for each cake. ### Answer: 9.285714285714286
Expected answer: 65/7
Correct? Yes
Problem: A kite maker has 41 blue, 63 red, and 57 green kites. If they give away 98 kites and create an additional 3 kites, how many kites does the maker have now?
InternLM-Math Base 20B:
Reasoning: The kite maker has 41+63+57 = <<41+63+57=161>>161 kites. They give away 98 kites, so they have 161-98 = <<161-98=63>>63 kites. They create 3 kites, so they have 63+3 = <<63+3=66>>66 kites. ### Answer: 66
Expected answer: 66
Correct? Yes
Problem: Following up with the earlier situation of the kite maker who had 41 blue, 63 red, and 57 green kites, gave away 98 kites, and created an additional 3 kites: If the kite maker decided to ramp up production and multiply their current inventory by 18, then add the original inventory to this increased production, how many kites would the they have now?
InternLM-Math Base 20B:
Reasoning: The kite maker has 41+63+57 = <<41+63+57=161>>161 kites. They give away 98 kites, so they have 161-98 = <<161-98=63>>63 kites. They create 3 kites, so they have 63+3 = <<63+3=66>>66 kites. ### Answer: 66
Expected answer: 1254
Correct? No
Problem: After the kite maker gave away some kites and made new ones, let's change the circumstances a bit. Instead of giving away 98 kites, they only gave away 19 kites. Taking into account that they still made an additional 3 kites, how many kites does the maker have now?
InternLM-Math Base 20B:
Reasoning: The kite maker has 41+63+57 = <<41+63+57=161>>161 kites. They give away 19 kites, so they have 161-19 = <<161-19=142>>142 kites. They create 3 kites, so they have 142+3 = <<142+3=145>>145 kites. ### Answer: 145
Expected answer: 145
Correct? Yes
Problem: A teddy bear company produces 7644 teddy bears in a span of 91 days. How many teddy bears does the company approximately makes each day?
InternLM-Math Base 20B:
Reasoning: 7644/91 = <<7644/91=84>>84 teddy bears are made each day. ### Answer: 84
Expected answer: 84
Correct? Yes
Problem: After reviewing their production numbers, the teddy bear company realized that they actually produce 7644 teddy bears in a span of 50 days, not 91 days. How many teddy bears does the company approximately makes each day now?
InternLM-Math Base 20B:
Reasoning: 7644/50 = <<7644/50=152>>152 teddy bears are made each day. ### Answer: 152
Expected answer: 3822/25
Correct? No
Problem: A train travels at a speed of 68 mph but due to certain restrictions, it had to slow down to 28 mph. Considering the travel time of 21 hours, calculate the impact on the total distance traveled by the train.
InternLM-Math Base 20B:
Reasoning: The train traveled at 68 mph for 21 hours. The train traveled at 28 mph for 21 hours. The total distance traveled by the train is 68*21 + 28*21 = <<68*21+28*21=1528>>1528 miles. ### Answer: 1528
Expected answer: 840
Correct? No
Problem: An alien spacecraft traveled 95 light-years to reach Earth, but had to stop 70 light-years along the way at a space buoy for refueling. How many light-years did it travel after refueling to reach Earth?
InternLM-Math Base 20B:
Reasoning: The spacecraft traveled 95-70 = <<95-70=25>>25 light-years after refueling to reach Earth. ### Answer: 25
Expected answer: 25
Correct? Yes
Problem: The alien spaceship initially traveled 95 light-years to reach Earth. But let's consider a scenario where they could only stop 60 light-years along the way at a space buoy for refueling instead of 70 light-years. In that case, how many light-years would the spaceship have to travel after refueling to reach Earth?
InternLM-Math Base 20B:
Reasoning: The spacecraft would have traveled 95-60 = <<95-60=35>>35 light-years after refueling to reach Earth. ### Answer: 35
Expected answer: 35
Correct? Yes
Problem: In a popular game, a character starts with a health value of 82. After being attacked by a rival character, his health value decreases by 69. What is the character's remaining health value?
InternLM-Math Base 20B:
Reasoning: The character's remaining health value is 82-69 = <<82-69=13>>13. ### Answer: 13
Expected answer: 13
Correct? Yes
Problem: In our previous scenario, the character started with a health value of 82. What if, instead of being attacked and losing 69 health points, he was attacked by a weaker rival character and only lost 33 health points. What would be the character's remaining health value in this new scenario?
InternLM-Math Base 20B:
Reasoning: The character's remaining health value is 82-33 = <<82-33=49>>49. ### Answer: 49
Expected answer: 49
Correct? Yes
Problem: A designer creates 77 dresses in a week and sells them for $16 each. After a week, he subtracts a cost of $27 for fabric damage. How much did the designer earn after accounting for the fabric damage?
InternLM-Math Base 20B:
Reasoning: The designer earns $16 × 77 = <<16*77=1232>>1232 dollars in a week. After subtracting the cost of $27, the designer earns $1232 − $27 = <<1232-27=1205>>1205 dollars. ### Answer: 1205
Expected answer: 1205
Correct? Yes
Problem: A snail travels 66 inches in a day. In addition to that, the snail extracted energy from 704 lettuce leaves over 22 days, allowing it to move an additional inch per day. How far in inches does the snail travel in a day with the additional energy?
InternLM-Math Base 20B:
Reasoning: The snail travels 66+22 = <<66+22=88>>88 inches in a day with the additional energy. ### Answer: 88
Expected answer: 98
Correct? No
Problem: A cake recipe calls for using 65 grams of sugar. If a bakery prepares 29 such cakes and then adds 46 more grams for frosting, how many grams of sugar did they use in total?
InternLM-Math Base 20B:
Reasoning: The bakery used 65*29 = <<65*29=1885>>1885 grams of sugar for the 29 cakes. The bakery used 1885+46 = <<1885+46=1931>>1931 grams of sugar in total. ### Answer: 1931
Expected answer: 1931
Correct? Yes
Problem: A skateboard company makes 36 freestyle skateboards and 92 downhill skateboards in a day. How many skateboards does it make in total in a day?
InternLM-Math Base 20B:
Reasoning: The company makes 36+92 = <<36+92=128>>128 skateboards in total in a day. ### Answer: 128
Expected answer: 128
Correct? Yes
Problem: The skateboard company decides to extend its production over 21 days but had to discard 65 skateboards due to quality issues. How many skateboards did they make in the span of these 21 days after discarding the faulty ones?
InternLM-Math Base 20B:
Reasoning: The company makes 128*21 = <<128*21=2688>>2688 skateboards in total in 21 days. The company discards 65 skateboards. The company makes 2688-65 = <<2688-65=2623>>2623 skateboards in total in 21 days. ### Answer: 2623
Expected answer: 2623
Correct? Yes
Problem: Suppose now the company produces 82 freestyle skateboards instead of 36, while still producing 92 downhill skateboards daily. How many skateboards does it make in total in a day?
InternLM-Math Base 20B:
Reasoning: The company makes 82+92 = <<82+92=174>>174 skateboards in total in a day. ### Answer: 174
Expected answer: 174
Correct? Yes
Problem: A café sells hot chocolate for 42 dollars per cup. One day, they sold 78 cups of hot chocolate and made an extra 58 dollars from selling marshmallows. What is the total revenue of that day from selling hot chocolate and marshmallows?
InternLM-Math Base 20B:
Reasoning: The café made 42*78 = <<42*78=3156>>3156 dollars from selling hot chocolate. The café made 3156+58 = <<3156+58=3214>>3214 dollars from selling hot chocolate and marshmallows. ### Answer: 3214
Expected answer: 3334
Correct? No
Problem: A river tour boat can hold 58 adults. If an additional 4 children can also board the boat, what is the total number of passengers the boat can carry?
InternLM-Math Base 20B:
Reasoning: 58+4 = <<58+4=62>>62 ### Answer: 62
Expected answer: 62
Correct? Yes
Problem: Suppose that the river tour boat could originally only hold 58 adults. It has now been modified to increase its capacity by 3 more adults. Taking this into account, how many total adults can the boat hold now?
InternLM-Math Base 20B:
Reasoning: 58+3 = <<58+3=61>>61 ### Answer: 61
Expected answer: 61
Correct? Yes
Problem: If a monkey gets ((360 bananas / 12 months) + 16 extra bananas) per month, how many bananas does the monkey get in a month?
InternLM-Math Base 20B:
Reasoning: ((360 bananas / 12 months) + 16 extra bananas) = <<(360 bananas / 12 months) + 16 extra bananas=(360/12)+16=30+16=46>>46 bananas per month. ### Answer: 46
Expected answer: 46
Correct? Yes
Problem: If in the next month, the monkey received additional bananas, bringing its total to ((360 bananas / 12 months) + 16 extra bananas + 79 more bananas) but then 67 of them were stolen, how many bananas does the monkey have now?
InternLM-Math Base 20B:
Reasoning: ((360 bananas / 12 months) + 16 extra bananas + 79 more bananas) = <<(360 bananas / 12 months) + 16 extra bananas + 79 more bananas=(360/12)+16+79=30+16+79=125>>125 bananas. 125 - 67 = <<125-67=58>>58 bananas. ### Answer: 58
Expected answer: 58
Correct? Yes
Problem: What if, instead of getting 360 bananas a year, the monkey only got 360 bananas every 20 months? If the monkey also got 16 extra bananas per month, how many bananas would the monkey get in a month?
InternLM-Math Base 20B:
Reasoning: ((360 bananas / 20 months) + 16 extra bananas) = <<(360 bananas / 20 months) + 16 extra bananas=(360 bananas / 20 months) + 16 extra bananas=(360/20)+16=18+16=34>>34 bananas per month. ### Answer: 34
Expected answer: 34
Correct? Yes
Problem: A starfish has 5 arms. If there were 360 degrees in a circle, how many degrees would be in each section if it were to be equally divided amongst the starfish's arms?
InternLM-Math Base 20B:
Reasoning: 360/5 = <<360/5=72>>72 ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: Continuing from the previous problem, what if the starfish was an unusual species with 17 arms instead of 5? If there were still 360 degrees in a circle, how many degrees would be in each section if it were to be equally divided amongst the starfish's arms?
InternLM-Math Base 20B:
Reasoning: 360/17 = <<360/17=21.18>>21.18 ### Answer: 21.18
Expected answer: 360/17
Correct? No
Problem: There's a toy store that has 26 stuffed rabbits. If they decide to order an additional 84 stuffed rabbits and 36 stuffed bears, how many stuffed animals will they have in total?
InternLM-Math Base 20B:
Reasoning: 26+84+36 = <<26+84+36=146>>146 ### Answer: 146
Expected answer: 146
Correct? Yes
Problem: The toy store received a special toy order of 1 rare stuffed panda in addition to their previous order. After adding the special order, how many stuffed animals will the toy store have in total?
InternLM-Math Base 20B:
Reasoning: 146+1 = <<146+1=147>>147 ### Answer: 147
Expected answer: 147
Correct? Yes
Problem: On Monday, Rachel watched 35 minutes of TV. On Tuesday, she watched 48 minutes in the morning and 13 more in the evening. How many minutes of TV did Rachel watch on both days?
InternLM-Math Base 20B:
Reasoning: Rachel watched 48+13 = <<48+13=61>>61 minutes of TV on Tuesday. Rachel watched 35+61 = <<35+61=96>>96 minutes of TV on both days. ### Answer: 96
Expected answer: 96
Correct? Yes
Problem: On Wednesday, Rachel watched 68 minutes of TV but decided to reduce her screen time by the amount she had watched on Monday. How many total minutes of TV did Rachel watch on Monday, Tuesday and Wednesday after reducing her Wednesday screen time?
InternLM-Math Base 20B:
Reasoning: Rachel watched 35+61 = <<35+61=96>>96 minutes of TV on Monday and Tuesday. Rachel watched 68-35 = <<68-35=33>>33 minutes of TV on Wednesday. Rachel watched 96+33 = <<96+33=129>>129 minutes of TV on Monday, Tuesday and Wednesday. ### Answer: 129
Expected answer: 129
Correct? Yes
Problem: If on Monday instead of watching 35 minutes of TV, Rachel watched 37 minutes. Then, how many total minutes of TV did she watch on Monday and Tuesday?
InternLM-Math Base 20B:
Reasoning: Rachel watched 37+61 = <<37+61=98>>98 minutes of TV on Monday and Tuesday. ### Answer: 98
Expected answer: 98
Correct? Yes
Problem: A door manufacturing company can produce 2340 doors over a 90-day period. How many doors can the company produce in one day?
InternLM-Math Base 20B:
Reasoning: The company can produce 2340/90 = <<2340/90=26>>26 doors in one day. ### Answer: 26
Expected answer: 26
Correct? Yes
Problem: A little mouse had stored 91 pieces of cheese for winter, but a thief mouse stole 77 pieces. The little mouse found 22 more pieces and a kind mouse gave him 12 more. How many pieces of cheese does the little mouse have now?
InternLM-Math Base 20B:
Reasoning: The little mouse has 91-77 = <<91-77=14>>14 pieces of cheese left. Then he found 22 more pieces, so he has 14+22 = <<14+22=36>>36 pieces of cheese. The kind mouse gave him 12 more, so he has 36+12 = <<36+12=48>>48 pieces of cheese now. ### Answer: 48
Expected answer: 48
Correct? Yes
Problem: A dolphin needs to have approximately 96 kilograms of fish and 22 kilograms of squid every day to stay healthy. If a dolphin's diet remained unchanged for 59 days, how much fish and squid in total, in kilograms, would the dolphin need?
InternLM-Math Base 20B:
Reasoning: The dolphin needs 96/59 = <<96/59=1.6>>1.6 kilograms of fish and 22/59 = <<22/59=0.4>>0.4 kilograms of squid every day. The dolphin needs 1.6*59 = <<1.6*59=94.4>>94.4 kilograms of fish and 0.4*59 = <<0.4*59=23.6>>23.6 kilograms of squid in total in 59 days. ### Answer: 94.4 kilograms of fish and 23.6 kilograms of squid
Expected answer: 6962
Correct? No
Problem: If Mandy has 18 building blocks and she received another 43, then decided to multiply the total by the initial number she had, how many building blocks would she have in the end?
InternLM-Math Base 20B:
Reasoning: Mandy has 18+43 = <<18+43=61>>61 building blocks in the end. ### Answer: 61
Expected answer: 1098
Correct? No
Problem: A ballerina practices for (28 - 11) hours a day, and she practices 10 times more on weekends. How much does she practice on weekends?
InternLM-Math Base 20B:
Reasoning: The ballerina practices for (28 - 11) = <<28-11=17>>17 hours a day. She practices 10 times more on weekends, so she practices 10*17 = <<10*17=170>>170 hours on weekends. ### Answer: 170
Expected answer: 170
Correct? Yes
Problem: Suppose our ballerina decided to lessen her weekend practices to (28 - 11) hours but increased the frequency to 66 times. How many hours did she practice in total on the weekends now?
InternLM-Math Base 20B:
Reasoning: The ballerina practices for (28 - 11) = <<28-11=17>>17 hours a day. She practices 66 times, so she practices 66*17 = <<66*17=1122>>1122 hours on weekends. ### Answer: 1122
Expected answer: 1122
Correct? Yes
Problem: A deck of special cards contains 59 different kinds of cards, and for each kind, there are 49 cards. How many total cards are there in this deck?
InternLM-Math Base 20B:
Reasoning: There are 59*49 = <<59*49=2891>>2891 cards in the deck. ### Answer: 2891
Expected answer: 2891
Correct? Yes
Problem: After the manufacturer's initial count of the standard cards and the division of premium cards, they discover a miscalculation. Instead of 59 different kinds of cards in the deck, there are actually 90 kinds. If for each kind, there are still 59 cards, how many total standard cards are there in this deck?
InternLM-Math Base 20B:
Reasoning: There are 90*59 = <<90*59=5271>>5271 cards in the deck. ### Answer: 5271
Expected answer: 5310
Correct? No
Problem: A farmer has a field where he grows grapevines. He has added 93 new vines to his field and 73 more after that. Unfortunately, 92 of the vines have died. How many vines does he have now?
InternLM-Math Base 20B:
Reasoning: The farmer has 93+73-92 = <<93+73-92=84>>84 vines now. ### Answer: 84
Expected answer: 74
Correct? No
Problem: A blanket factory makes 13 blankets in the morning and 81 in the afternoon, but returns 59 due to defects. Each blanket is sold at a price equal to 39 times the total number of good blankets they have, plus the number of good blankets. What's the total value of the blankets they've sold?
InternLM-Math Base 20B:
Reasoning: The factory makes 13+81 = <<13+81=94>>94 blankets in total, but returns 59, so they have 94-59 = <<94-59=35>>35 good blankets. The value of the blankets they've sold is 39*35+35 = <<39*35+35=1430>>1430. ### Answer: 1430
Expected answer: 1400
Correct? No
Problem: A bus travels a distance of 1300 miles. If it does so in 20 equal stages, how many miles does the bus travel per stage?
InternLM-Math Base 20B:
Reasoning: The bus travels 1300/20 = <<1300/20=65>>65 miles per stage. ### Answer: 65
Expected answer: 65
Correct? Yes
Problem: In our previous scenario, suppose instead of covering the distance in 20 equal stages, the bus decided to only stop 4 times, dividing the journey into equal parts. In that case, how many miles would the bus need to travel per stage?
InternLM-Math Base 20B:
Reasoning: The bus would need to travel 1300/4 = <<1300/4=325>>325 miles per stage. ### Answer: 325
Expected answer: 325
Correct? Yes
Problem: A region usually receives 53 inches of rain each year. However, in a certain year, it only received 7 inches less than the usual amount. How many inches of rain did it receive that year?
InternLM-Math Base 20B:
Reasoning: 53-7 = <<53-7=46>>46 ### Answer: 46
Expected answer: 46
Correct? Yes
Problem: Suppose the region actually usually receives 69 inches of rain each year, instead of 53 as we previously thought. If it still received 7 inches less than the usual amount in the year we're considering, how many inches of rain did it receive that year?
InternLM-Math Base 20B:
Reasoning: 69-7 = <<69-7=62>>62 ### Answer: 62
Expected answer: 62
Correct? Yes
Problem: In a complicated mechanical watch, there are 98 gears in the main mechanism and 61 gears in a side mechanism. After service, a watchmaker removed 80 gears from the watch. How many gears are there left in the watch now?
InternLM-Math Base 20B:
Reasoning: The watchmaker removed 80 gears from the main mechanism and 80 gears from the side mechanism. The watchmaker removed 80+80 = <<80+80=160>>160 gears from the watch. There are 98-80 = <<98-80=18>>18 gears left in the main mechanism and 61-80 = <<61-80=-19>>-19 gears left in the side mechanism. There are 18+(-19) = <<18+(-19)=-1>>-1 gears left in the watch. ### Answer: -1
Expected answer: 79
Correct? No
Problem: A company manufactures 1462 binoculars and distributes them equally among 43 stores. After subtracting 25 defective pieces from each store's stock, how many binoculars does each store end up with?
InternLM-Math Base 20B:
Reasoning: Each store gets 1462/43 = <<1462/43=34>>34 binoculars. Each store ends up with 34-25 = <<34-25=9>>9 binoculars. ### Answer: 9
Expected answer: 9
Correct? Yes
Problem: In addition to the binoculars already distributed, each store received an additional shipment of binoculars from a second manufacturing facility. The second facility produced 4104 binoculars and divided them equally among 57 stores. After accounting for this additional shipment, how many binoculars does each store end up with in total?
InternLM-Math Base 20B:
Reasoning: Each store gets 4104/57 = <<4104/57=72>>72 binoculars. Each store ends up with 72+9 = <<72+9=81>>81 binoculars. ### Answer: 81
Expected answer: 81
Correct? Yes
Problem: In a revision to the initial report, it turns out that 19 defective pieces were found in each store's binocular stock, rather than the originally believed 25. After making this correction, how many binoculars does each store end up with from the initial shipment?
InternLM-Math Base 20B:
Reasoning: Each store gets 1462/43 = <<1462/43=34>>34 binoculars. Each store ends up with 34-19 = <<34-19=15>>15 binoculars. ### Answer: 15
Expected answer: 15
Correct? Yes
Problem: A camera shop stocks 25 DSLR cameras. They receive a delivery of 71 new DSLR cameras and for promotional reasons, the shop decides to multiply the total number of cameras by 77. How many cameras does the shop have for promotion?
InternLM-Math Base 20B:
Reasoning: The shop has 71+25 = <<71+25=96>>96 cameras. The shop has 96*77 = <<96*77=7392>>7392 cameras for promotion. ### Answer: 7392
Expected answer: 7392
Correct? Yes
Problem: Following the previous scenario, let's revisit the promotional event. Suppose this time the shop had decided to multiply the total number of cameras by 56 instead of 77 after receiving the same initial stock of 71 new DSLR cameras. How many cameras would the shop have had for promotion in this case?
InternLM-Math Base 20B:
Reasoning: The shop has 71+25 = <<71+25=96>>96 cameras. The shop has 96*56 = <<96*56=5376>>5376 cameras for promotion. ### Answer: 5376
Expected answer: 5376
Correct? Yes
Problem: On average, a construction company can build 1425 square feet of a house in 19 days. If they worked for 14 days, how many square feet would they have built?
InternLM-Math Base 20B:
Reasoning: 1425/19 = <<1425/19=75>>75 square feet per day. 1425/19 × 14 = <<1425/19 × 14=1050>>1050 square feet in 14 days. ### Answer: 1050
Expected answer: 1050
Correct? Yes
Problem: A farmer starts the day with 18 tomatoes in his basket. By midday, he manages to harvest some more, bringing the total to 18 + 82 tomatoes in the basket. Unfortunately, 37 of these tomatoes are deemed unsellable because they are not ripe enough. How many tomatoes does the farmer have left in the basket that are ready to sell?
InternLM-Math Base 20B:
Reasoning: The farmer has 18+82 = <<18+82=100>>100 tomatoes in the basket. 37 of these are not ripe enough, so the farmer has 100-37 = <<100-37=63>>63 tomatoes left in the basket that are ready to sell. ### Answer: 63
Expected answer: 63
Correct? Yes
Problem: In a similar situation as before, the farmer started his day with a different quantity of 95 tomatoes in his basket. Just like the previous day, by midday, he managed to harvest some more, bringing the total to 95 + 82 tomatoes in the basket. Unfortunately, he found that 37 of these tomatoes were not ripe enough to sell. How many ripe tomatoes did the farmer have left in his basket after this day?
InternLM-Math Base 20B:
Reasoning: The farmer has 95+82 = <<95+82=177>>177 tomatoes in the basket. 37 of these are not ripe enough, so the farmer has 177-37 = <<177-37=140>>140 tomatoes left in the basket that are ready to sell. ### Answer: 140
Expected answer: 140
Correct? Yes
Problem: In a soap manufacturing factory, they create soap in large blocks that are then cut into smaller bars. If each large block can be cut into 1424 bars of soap, but they package the soap in bundles of 16 bars each, how many packages can they make from one large block of soap?
InternLM-Math Base 20B:
Reasoning: 1424 = <<1424=14*24=336>>336, so 336/16 = <<336/16=21>>21 packages can be made from one large block of soap. ### Answer: 21
Expected answer: 89
Correct? No
Problem: A printer prints 2 sheets of paper with 37 letters each second. If it continues to print at this rate for 95 seconds, how many letters will be printed?
InternLM-Math Base 20B:
Reasoning: 2 sheets of paper with 37 letters each = 2*37 = <<2*37=74>>74 letters. 74 letters are printed in 1 second. 74*95 = <<74*95=7030>>7030 letters are printed in 95 seconds. ### Answer: 7030
Expected answer: 7030
Correct? Yes
Problem: Continuing from the previous scenario, what if the printer only printed 2 sheets of paper with 4 letters each second instead of 37. Keeping the same printing duration of 95 seconds, how many letters would have been printed then?
InternLM-Math Base 20B:
Reasoning: 2 sheets of paper with 4 letters each = 2*4 = <<2*4=8>>8 letters. 8 letters are printed in 1 second. 8*95 = <<8*95=760>>760 letters are printed in 95 seconds. ### Answer: 760
Expected answer: 760
Correct? Yes
Problem: A potato farm produces 12 tons of potatoes per acre. They have a 3 acre plot of land which they use for growing potatoes. After the harvest, they found out that 71 tons were rotten, but they could salvage 44 tons. How many tons of potatoes do they have left?
InternLM-Math Base 20B:
Reasoning: The farm produces 12*3 = <<12*3=36>>36 tons of potatoes per acre. They have 71-44 = <<71-44=27>>27 tons of rotten potatoes. They have 36-27 = <<36-27=9>>9 tons of potatoes left. ### Answer: 9
Expected answer: 9
Correct? Yes
Problem: If the potato farm had initially produced 56 tons of potatoes per acre instead of 12, how many tons of potatoes would they have left after considering the rotten and salvageable ones?
InternLM-Math Base 20B:
Reasoning: The farm produces 56*3 = <<56*3=168>>168 tons of potatoes per acre. They have 71-44 = <<71-44=27>>27 tons of rotten potatoes. They have 168-27 = <<168-27=141>>141 tons of potatoes left. ### Answer: 141
Expected answer: 141
Correct? Yes
Problem: A plane travels around the world, covering a distance of 360,000 miles. If it covers 72,000 miles per day, how many days does it take for the plane to travel around the world?
InternLM-Math Base 20B:
Reasoning: The plane travels 360,000/72,000 = <<360,000/72,000=5>>5 days to travel around the world. ### Answer: 5
Expected answer: 5
Correct? Yes
Problem: After reviewing the plane's logbook, the crew realizes there was a mistake in their calculations. Instead of covering 360,000 miles to travel around the world, it actually only took them 81,000 miles. Given this, how many days would it have taken them to travel around the world at a rate of 72,000 miles per day?
InternLM-Math Base 20B:
Reasoning: The plane travels 81,000/72,000 = <<81,000/72,000=1.125>>1.125 days to travel around the world. ### Answer: 1.125
Expected answer: 9/8
Correct? Yes
Problem: A fairy sprinkles magical dust at a rate of 4332 milligrams every 76 minutes. If she reduces her sprinkling rate by 44 milligrams and continues at this reduced rate for 52 minutes, how much magical dust will she sprinkle in that time?
InternLM-Math Base 20B:
Reasoning: The fairy sprinkles 4332/76 = <<4332/76=57>>57 milligrams per minute. She sprinkles 57-44 = <<57-44=13>>13 milligrams per minute at the reduced rate. She sprinkles 13*52 = <<13*52=676>>676 milligrams in 52 minutes. ### Answer: 676
Expected answer: 676
Correct? Yes
Problem: After sprinkling magical dust at the reduced rate for 52 minutes, the fairy finds an additional 49 milligrams of magical dust. How much total magical dust did she use in that time?
InternLM-Math Base 20B:
Reasoning: The fairy sprinkles 4332/76 = <<4332/76=57>>57 milligrams per minute. She sprinkles 57-44 = <<57-44=13>>13 milligrams per minute at the reduced rate. She sprinkles 13*52 = <<13*52=676>>676 milligrams in 52 minutes. She sprinkles 676+49 = <<676+49=725>>725 milligrams in 52 minutes. ### Answer: 725
Expected answer: 725
Correct? Yes
Problem: If the fairy had initially reduced her sprinkling rate to 22 minutes instead of 52 minutes, how much magical dust would she have sprinkled in that time with the reduced rate of 44 milligrams?
InternLM-Math Base 20B:
Reasoning: The fairy sprinkles 4332/76 = <<4332/76=57>>57 milligrams per minute. She sprinkles 57-44 = <<57-44=13>>13 milligrams per minute at the reduced rate. She sprinkles 13*22 = <<13*22=286>>286 milligrams in 22 minutes. ### Answer: 286
Expected answer: 286
Correct? Yes
Problem: At the start of the camping trip, there were 56 logs to fuel the campfire. But after some time, the campers had used up 15 logs. How many logs are left for the rest of the trip?
InternLM-Math Base 20B:
Reasoning: 56-15 = <<56-15=41>>41 logs are left for the rest of the trip. ### Answer: 41
Expected answer: 41
Correct? Yes
Problem: After re-counting the initial logs at the start of the camping trip, there were actually 48 logs, not 56. After using up 15 logs, with this new count, how many logs are now left for the rest of the trip?
InternLM-Math Base 20B:
Reasoning: 48-15 = <<48-15=33>>33 logs are left for the rest of the trip. ### Answer: 33
Expected answer: 33
Correct? Yes
Problem: John took 30 pictures with his new camera, but then he accidentally deleted 81 pictures. Fortunately, he was able to recover 61 of the deleted pictures. How many pictures does he have now?
InternLM-Math Base 20B:
Reasoning: John took 30 pictures with his new camera, but then he accidentally deleted 81 pictures. He was able to recover 61 of the deleted pictures. John has 30+61-81 = <<30+61-81=10>>10 pictures now. ### Answer: 10
Expected answer: 10
Correct? Yes
Problem: In the previous scenario, let's consider that instead of taking 30 pictures, John only took 21 pictures with his new camera before accidentally deleting 81 pictures. Like before, he was able to recover 61 of those deleted pictures. How many pictures does he have now?
InternLM-Math Base 20B:
Reasoning: John took 21 pictures with his new camera, but then he accidentally deleted 81 pictures. He was able to recover 61 of the deleted pictures. John has 21+61-81 = <<21+61-81=-1>>-1 pictures now. ### Answer: -1
Expected answer: 1
Correct? Yes
Problem: A tailor uses 20 square feet of fabric to make one teddy bear. If they use the same amount of fabric for every teddy bear, how much fabric will they need to make 20 teddy bears?
InternLM-Math Base 20B:
Reasoning: The tailor uses 20 square feet of fabric to make one teddy bear. They will need 20 × 20 = <<20*20=400>>400 square feet of fabric to make 20 teddy bears. ### Answer: 400
Expected answer: 400
Correct? Yes
Problem: If each pair of binoculars costs $27 and a store adds a tax of $9 after buying 23 pairs, how much will the total cost be?
InternLM-Math Base 20B:
Reasoning: The cost of 23 pairs of binoculars is 23*27 = <<23*27=621>>621. The total cost is 621+9 = <<621+9=630>>630. ### Answer: 630
Expected answer: 630
Correct? Yes
Problem: After paying the tax and buying the 23 pairs of binoculars, the store owner decides to purchase an additional single pair of binoculars that has a discount of $95. What is the total amount the store owner will need to pay now?
InternLM-Math Base 20B:
Reasoning: The cost of 24 pairs of binoculars is 24*27 = <<24*27=648>>648. The total cost is 648-95 = <<648-95=553>>553. ### Answer: 553
Expected answer: 562
Correct? No
Problem: After the store owner's last transaction, a new shipment of binoculars came in with a lower price. This time, each pair costs $27 and there's a fixed tax of $9. If the store owner decides to buy 13 pairs from the new shipment, how much would the total cost be now?
InternLM-Math Base 20B:
Reasoning: The cost of 13 pairs of binoculars is 13*27 = <<13*27=351>>351. The total cost is 351+9 = <<351+9=360>>360. ### Answer: 360
Expected answer: 360
Correct? Yes
Problem: A pirate found 22 gold coins on an island. On his ship, he remembered that he had found 91 gold coins on another island, and 33 gold coins hidden in a chest. How many gold coins does the pirate have in total?
InternLM-Math Base 20B:
Reasoning: The pirate has 22+91+33 = <<22+91+33=146>>146 gold coins in total. ### Answer: 146
Expected answer: 146
Correct? Yes
Problem: Following on from the previous problem: The pirate made a mistake while counting his treasure. He originally thought that he had found 91 gold coins on another island, but it turned out there were only 9 gold coins. With the 22 coins he found on an island, 9 on another island, and 33 hidden in a chest, how many coins does the pirate have now?
InternLM-Math Base 20B:
Reasoning: The pirate has 22+9+33 = <<22+9+33=64>>64 gold coins now. ### Answer: 64
Expected answer: 64
Correct? Yes
Problem: A magical unicorn has (54 - 24) + 25 numbers of rainbow apples. If each rainbow apple can be traded for 51 sparkly diamonds, how many sparkly diamonds can the unicorn get in return?
InternLM-Math Base 20B:
Reasoning: The unicorn has (54 - 24) + 25 = <<54-24+25=85>>85 rainbow apples. Each rainbow apple can be traded for 51 sparkly diamonds. The unicorn can get 85 × 51 = <<85*51=4335>>4335 sparkly diamonds in return. ### Answer: 4335
Expected answer: 2805
Correct? No
Problem: A phone manufacturer is capable of producing 990 phones every 22 hours. After 33 hours, they add an additional 13 phones to the production batch. How many phones are produced in total at this time?
InternLM-Math Base 20B:
Reasoning: The phone manufacturer produces 990/22 = <<990/22=45>>45 phones per hour. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45=1485>>1485 phones. In 33 hours, they produce 33*45 = <<33*45
Expected answer: 1498
Correct? No
Problem: A tall building has 704 windows in total. If each floor has the same number of windows and the building is 8 floors high, how many windows are there on each floor?
InternLM-Math Base 20B:
Reasoning: 704/8 = <<704/8=88>>88 windows on each floor. ### Answer: 88
Expected answer: 88
Correct? Yes
Problem: After figuring out the total number of windows the maintenance team cleaned in a day, let's consider a different scenario. What if the building had originally been built with 704 windows spread over 71 floors instead of 8? How many windows would there be on each floor then?
InternLM-Math Base 20B:
Reasoning: 704/71 = <<704/71=9.9...>>9.9... windows on each floor. ### Answer: 9.9...
Expected answer: 704/71
Correct? No
Problem: In a small town, each household owns an average of 77 cats. If there are 69 households in the town, how many cats are there in total?
InternLM-Math Base 20B:
Reasoning: 77*69 = <<77*69=5,313>>5,313 There are 5,313 cats in total. ### Answer: 5,313
Expected answer: 5313
Correct? Yes
Problem: In a small town, each household owns an average of 77 cats. If there are 69 households in the town, there would be a certain number of cats in total. However, due to some circumstances, 91 of these cats had to be moved to another town. How many cats are left in the town now?
InternLM-Math Base 20B:
Reasoning: 77*69 = <<77*69=5,313>>5,313 There are 5,313 cats in total. However, 91 of these cats had to be moved to another town. Therefore, there are 5,313-91 = <<5,313-91=5,222>>5,222 cats left in the town now. ### Answer: 5,222
Expected answer: 5222
Correct? Yes
Problem: A chocolate bar factory has 28 machines running every day. If 2 machines break down and stop producing, how many machines are still producing chocolate bars?
InternLM-Math Base 20B:
Reasoning: 28-2 = <<28-2=26>>26 machines are still producing chocolate bars. ### Answer: 26
Expected answer: 26
Correct? Yes
Problem: Originally, the chocolate bar factory had 87 machines running every day instead of 28. If 2 of the machines break down, as it happened in the previous scenario, how many machines would still be producing chocolate bars?
InternLM-Math Base 20B:
Reasoning: 87-2 = <<87-2=85>>85 machines are still producing chocolate bars. ### Answer: 85
Expected answer: 85
Correct? Yes
Problem: A candlemaker has 37 lavender-scented candles and makes 10 more. He then makes another 24 candles, combines them with the ones he already has, and finally adds 6 vanilla-scented candles to his collection. How many candles does he have in total?
InternLM-Math Base 20B:
Reasoning: The candlemaker has 37+10+24+6 = <<37+10+24+6=73>>73 candles in total. ### Answer: 73
Expected answer: 77
Correct? No
Problem: What is the result of adding the numbers 12, 4, and 71 together?
InternLM-Math Base 20B:
Reasoning: 12+4+71 = <<12+4+71=87>>87 ### Answer: 87
Expected answer: 87
Correct? Yes
Problem: After finding the sum of 12, 4, and 71, add 15 to the result. What is the new total?
InternLM-Math Base 20B:
Reasoning: 12+4+71+15 = <<12+4+71+15=102>>102 ### Answer: 102
Expected answer: 102
Correct? Yes
Problem: Imagine that initially instead of 12, you started with 53. Now, what would be the result of adding the numbers 53, 4, and 71 together?
InternLM-Math Base 20B:
Reasoning: 53+4+71 = <<53+4+71=128>>128 ### Answer: 128
Expected answer: 128
Correct? Yes
Problem: John's cucumber plant produces 59 cucumbers. Mary's cucumber plant, on the other hand, produces as many cucumbers as John's but minus the difference between John's cucumbers and 9. How many cucumbers did Mary's plant produce?
InternLM-Math Base 20B:
Reasoning: John's cucumber plant produces 59 cucumbers. Mary's cucumber plant produces 59-9 = <<59-9=50>>50 cucumbers. ### Answer: 50
Expected answer: 9
Correct? No
Problem: A puzzle game requires 3795 points to complete a level, but a player can only gain points in increments of 69. How many increments are needed to gain the points required to complete the level?
InternLM-Math Base 20B:
Reasoning: 3795/69 = <<3795/69=54.98...>>54.98...
Expected answer: 55
Correct? No
Problem: A pirate found a treasure chest with 35 gemstones each worth 57 gold coins. The chest also had an additional 42 gold coins. How many gold coins is the total worth of the treasure chest?
InternLM-Math Base 20B:
Reasoning: The total value of the gemstones is 35*57 = <<35*57=1995>>1995 gold coins. The total value of the treasure chest is 1995+42 = <<1995+42=2037>>2037 gold coins. ### Answer: 2037
Expected answer: 2037
Correct? Yes
Problem: Suppose the pirate initially found a smaller chest with only 6 gemstones, each still worth 57 gold coins, along with an additional 42 gold coins. How many gold coins would be the total worth of this smaller chest?
InternLM-Math Base 20B:
Reasoning: The total value of the gemstones is 6*57 = <<6*57=342>>342 gold coins. The total value of the smaller chest is 342+42 = <<342+42=384>>384 gold coins. ### Answer: 384
Expected answer: 384
Correct? Yes
Problem: A pet store has 35 white mice, 86 brown mice, and 39 black mice. How many mice does the store have in total?
InternLM-Math Base 20B:
Reasoning: 35+86+39 = <<35+86+39=160>>160 mice. ### Answer: 160
Expected answer: 160
Correct? Yes
Problem: If the pet store decides to double its quantity of each species of mouse – the white mice, brown mice, and black mice, how many mice will the store have then?
InternLM-Math Base 20B:
Reasoning: 2*35+2*86+2*39 = <<2*35+2*86+2*39=320>>320 mice. ### Answer: 320
Expected answer: 320
Correct? Yes
Problem: If the pet store actually had 31 black mice instead of 39 black mice along with the 35 white mice and 86 brown mice, how many mice in total would the pet store then have?
InternLM-Math Base 20B:
Reasoning: 35+86+31 = <<35+86+31=152>>152 mice. ### Answer: 152
Expected answer: 152
Correct? Yes
Problem: A soap making factory produces 97 bars of soap in one batch. If they made 94 batches in one day, how many bars of soap did they produce that day?
InternLM-Math Base 20B:
Reasoning: 97 × 94 = <<97*94=9118>>9118 The factory produced 9118 bars of soap that day. ### Answer: 9118
Expected answer: 9118
Correct? Yes
Problem: The soap factory realized that instead of producing 97 bars of soap per batch, they had actually been producing only 43 bars per batch due to a measuring error. Given this new information, how many bars of soap were actually produced over the 94 batches made on the first day?
InternLM-Math Base 20B:
Reasoning: 43 × 94 = <<43*94=4042>>4042 The factory actually produced 4042 bars of soap that day. ### Answer: 4042
Expected answer: 4042
Correct? Yes
Problem: A toy factory produces 5 toy cars every minute. After 76 minutes, they add another batch of 49 toy cars. How many toy cars does the factory have now?
InternLM-Math Base 20B:
Reasoning: The factory produces 5 toy cars every minute. After 76 minutes, they add another batch of 49 toy cars. So, the factory has 5*76+49 = <<5*76+49=469>>469 toy cars now. ### Answer: 469
Expected answer: 429
Correct? No
Problem: A piece of farmland spans across 9 km. The owner decided to expand his property by 77 km. However, he had to return 71 km due to some legal issues. How many km does the farmer have left after his expansion and subsequent decrease?
InternLM-Math Base 20B:
Reasoning: The farmer has 9+77-71 = <<9+77-71=97>>97 km of farmland. ### Answer: 97
Expected answer: 15
Correct? No
Problem: A paint company is preparing 8930 liters of a specific color. If they can fill up a paint bucket with 95 liters of paint, how many buckets will they be able to fill up completely?
InternLM-Math Base 20B:
Reasoning: 8930/95 = <<8930/95=94.1052>>94 buckets. ### Answer: 94
Expected answer: 94
Correct? Yes
Problem: A paint company is preparing 8930 liters of a specific color. If they can fill up a paint bucket with 95 liters of paint, how many buckets will they be able to fill up completely? After the initial sales, the company realized they were missing 73 paint buckets. But soon they found 59 buckets in the warehouse. After adding these found buckets, how many buckets does the company have in total now?
InternLM-Math Base 20B:
Reasoning: 8930/95 = <<8930/95=94.1052>>94 buckets. ### Answer: 94
Expected answer: 80
Correct? No
Problem: A bubble machine can make 3654 bubbles with 87 ounces of bubble fluid. How many bubbles can it make with 1 ounce of bubble fluid?
InternLM-Math Base 20B:
Reasoning: 1/87 = <<1/87=0.01147541>>0.01147541 3654 * 0.01147541 = <<3654*0.01147541=41.8>>41.8 ### Answer: 41.8
Expected answer: 42
Correct? No
Problem: A juice bar uses 13 apples to make a jug of apple juice. If they made 30 jugs in one day, how many apples did they use?
InternLM-Math Base 20B:
Reasoning: 30 × 13 = <<30*13=390>>390. They used 390 apples. ### Answer: 390
Expected answer: 390
Correct? Yes
Problem: Considering the previous scenario, if instead of using 13 apples daily for the fruit salads, they started using 55 apples, how many apples did they use in total when they made fruit salads for 30 days?
InternLM-Math Base 20B:
Reasoning: 30 × 55 = <<30*55=1650>>1650. They used 1650 apples. ### Answer: 1650
Expected answer: 1650
Correct? Yes
Problem: A certain dinosaur species laid eggs every 60 minutes. If they had been laying eggs for 1620 minutes straight, how many total eggs would they have laid?
InternLM-Math Base 20B:
Reasoning: 1620/60 = <<1620/60=27>>27. ### Answer: 27
Expected answer: 27
Correct? Yes
Problem: Following the previous scenario, suppose the paleontologists revised their calculations and found that the dinosaur species was actually laying eggs every 47 minutes, not 60 as originally thought. In that case, how many total eggs would the dinosaur have laid if it had been laying eggs for 1620 minutes straight?
InternLM-Math Base 20B:
Reasoning: 1620/47 = <<1620/47=34.680851>>34.680851. ### Answer: 34.680851
Expected answer: 1620/47
Correct? No
Problem: A library received a shipment of new books. There were 55 romance novels, 43 mystery novels, and 67 science fiction novels. How many new books did the library receive?
InternLM-Math Base 20B:
Reasoning: The library received 55+43+67 = <<55+43+67=165>>165 new books. ### Answer: 165
Expected answer: 165
Correct? Yes
Problem: In the original shipment to the library, suppose there were 95 science fiction novels instead of 67. With the 55 romance novels and 43 mystery novels remaining the same, how many new books did the library receive now?
InternLM-Math Base 20B:
Reasoning: The library received 55+43+95 = <<55+43+95=193>>193 new books. ### Answer: 193
Expected answer: 193
Correct? Yes
Problem: On a particular beach, there is a tendency for 74 seashells to appear every day. After 42 days of collection, a beachcomber also discovered an additional 56 seashells that had been hidden in the sand. How many seashells did the beachcomber have in total after 42 days?
InternLM-Math Base 20B:
Reasoning: The beachcomber had 74 × 42 = <<74*42=3028>>3028 seashells after 42 days. The beachcomber had 3028 + 56 = <<3028+56=3084>>3084 seashells after 42 days. ### Answer: 3084
Expected answer: 3164
Correct? No