InternLM-Math Base 20B on 6.NS.B.3
Common Core Standard 6.NS.B.3
This standard covers the following:
Add, subtract, multiply, and divide decimals to hundredths, using concrete models or drawings and strategies based on place value, properties of operations, and/or the relationship between addition and subtraction; relate the strategy to a written method and explain the reasoning used.
Problem: A window cleaning company charges $533.89 for cleaning the windows of a large building, and this cost is equally shared by 20.3 tenants. How much does each tenant contribute to the window cleaning cost?
InternLM-Math Base 20B:
Reasoning: Each tenant contributes 533.89/20.3 = <<533.89/20.3=26.25>>26.25 dollars to the window cleaning cost. ### Answer: 26.25
Expected answer: 26.3000000000000
Correct? No
Problem: A company distributed 2218.5 kilograms of cucumber equally among 51 grocery stores. How many kilograms of cucumber did each store receive?
InternLM-Math Base 20B:
Reasoning: 2218.5/51 = <<2218.5/51=43.5>>43.5 Each store received 43.5 kilograms of cucumber. ### Answer: 43.5
Expected answer: 43.5000000000000
Correct? Yes
Problem: After the grocery stores received their portions of cucumber, each store decided to use 25.3 kilograms of their share for a special cucumber salad. How many kilograms of cucumber were left at each store after making the salad?
InternLM-Math Base 20B:
Reasoning: 43.5-25.3 = <<43.5-25.3=18.2>>18.2 There were 18.2 kilograms of cucumber left at each store after making the salad. ### Answer: 18.2
Expected answer: 18.2000000000000
Correct? Yes
Problem: A hat maker uses 70.2 grams of wool to make each hat. If they plan on making 39.2 hats, how many grams of wool will they need in total?
InternLM-Math Base 20B:
Reasoning: The hat maker needs 70.2 × 39.2 = <<70.2*39.2=2750.24>>2750.24 grams of wool in total. ### Answer: 2750.24
Expected answer: 2751.84000000000
Correct? No
Problem: A cucumber weighs 1.93 pounds on average. If a farmer collects 18.06 cucumbers from his garden, how many pounds of cucumbers does he have in total?
InternLM-Math Base 20B:
Reasoning: 18.06/1.93 = <<18.06/1.93=9.37>>9.37 cucumbers weigh 1 pound. The farmer has 9.37*1 = <<9.37*1=9.37>>9.37 pounds of cucumbers in total. ### Answer: 9.37
Expected answer: 34.8558000000000
Correct? No
Problem: A mouse starts running from a point, he runs for 10.4 meters towards east, then turns around and runs for another 37.12 meters towards west. What is the total distance the mouse has run?
InternLM-Math Base 20B:
Reasoning: The mouse has run 10.4+37.12 = <<10.4+37.12=47.52>>47.52 meters. ### Answer: 47.52
Expected answer: 47.5200000000000
Correct? Yes
Problem: Continuing from the original problem, if the mouse starts by running a distance of 10.4 meters towards east, then changes his route and only runs 24 meters towards west instead of 37.12 meters, what would be the total distance run by the mouse then?
InternLM-Math Base 20B:
Reasoning: The mouse has run 10.4+24 = <<10.4+24=34.4>>34.4 meters. ### Answer: 34.4
Expected answer: 34.4000000000000
Correct? Yes
Problem: You bought a gold ring weighing 83.07 grams, but after polishing and curving, you lost 3.4 grams of gold from the ring. What is the weight of the finished ring?
InternLM-Math Base 20B:
Reasoning: The weight of the finished ring is 83.07-3.4 = <<83.07-3.4=79.67>>79.67 grams. ### Answer: 79.67
Expected answer: 79.6700000000000
Correct? Yes
Problem: You bought a gold ring weighing 83.07 grams, but after polishing and curving, you lost 3.4 grams of gold from the ring. Afterward, you decided to add 6.8 grams of platinum to the ring. What is the total weight of the ring now?
InternLM-Math Base 20B:
Reasoning: The weight of the finished ring is 83.07-3.4 = <<83.07-3.4=79.67>>79.67 grams. The weight of the ring after adding platinum is 79.67+6.8 = <<79.67+6.8=86.47>>86.47 grams. ### Answer: 86.47
Expected answer: 86.4700000000000
Correct? Yes
Problem: You bought a gold ring weighing 83.07 grams, but after an intricate engraving process, you lost 18 grams of gold from the ring. What is the weight of the engraved ring now?
InternLM-Math Base 20B:
Reasoning: The weight of the finished ring is 83.07-18 = <<83.07-18=65.07>>65.07 grams. ### Answer: 65.07
Expected answer: 65.0700000000000
Correct? Yes
Problem: A forest has 70.3 hectares filled with oak trees. If each hectare can absorb 88.8 tons of carbon dioxide a year, how many tons of carbon dioxide in total can these hectares of oak trees absorb in a year?
InternLM-Math Base 20B:
Reasoning: 70.3 * 88.8 = <<70.3*88.8=6,238.64>>6,238.64 ### Answer: 6,238.64
Expected answer: 6242.64000000000
Correct? No
Problem: There were 81.4 kilograms of cucumbers in the storage room. After selling some of them, the weight dropped to 66.05 kilograms. How many kilograms of cucumbers were sold?
InternLM-Math Base 20B:
Reasoning: The weight of the cucumbers that were sold is 81.4-66.05 = <<81.4-66.05=15.35>>15.35 kilograms. ### Answer: 15.35
Expected answer: 15.3500000000000
Correct? Yes
Problem: Following from the previous problem, let's say initially there were 81.4 kilograms of cucumbers in the storage room but this time, the quantity sold was different, amounting to 44 kilograms instead. How many kilograms of cucumbers were left in the storage room after this sale?
InternLM-Math Base 20B:
Reasoning: The weight of the cucumbers that were left in the storage room is 81.4-44 = <<81.4-44=37.4>>37.4 kilograms. ### Answer: 37.4
Expected answer: 37.4000000000000
Correct? Yes
Problem: A snow machine produces 60.87 pounds of artificial snow per hour. If the machine runs for 27.5 hours, how many pounds of artificial snow will be produced?
InternLM-Math Base 20B:
Reasoning: 60.87 × 27.5 = <<60.87*27.5=1675.425>>1675.425 ### Answer: 1675.425
Expected answer: 1673.92500000000
Correct? No
Problem: A dolphin can travel 1687.56 miles within a certain period. If it travels the same distance in 29.4 days, how many miles does the dolphin travel each day?
InternLM-Math Base 20B:
Reasoning: The dolphin travels 1687.56/29.4 = <<1687.56/29.4=57.5>>57.5 miles each day. ### Answer: 57.5
Expected answer: 57.4000000000000
Correct? Yes
Problem: Following from the previous problem, if a dolphin can travel an additional 57.93 miles per day due to current in its favor, how many total miles does the dolphin travel each day?
InternLM-Math Base 20B:
Reasoning: The dolphin travels 57.5+57.93 = <<57.5+57.93=115.43>>115.43 miles each day. ### Answer: 115.43
Expected answer: 115.330000000000
Correct? No
Problem: Following from the previous problem, what if the dolphin had travelled the same 1687.56 miles, but over a longer period of 91 days. How many miles would the dolphin have travelled each day then?
InternLM-Math Base 20B:
Reasoning: The dolphin travels 1687.56/91 = <<1687.56/91=18.5>>18.5 miles each day. ### Answer: 18.5
Expected answer: 18.5446153846154
Correct? Yes
Problem: A truck was carrying a load of 65.4 tons, but 56.3 tons were delivered. How many tons are still on the truck?
InternLM-Math Base 20B:
Reasoning: 65.4 - 56.3 = <<65.4-56.3=9.1>>9.1 tons are still on the truck. ### Answer: 9.1
Expected answer: 9.10000000000000
Correct? Yes
Problem: After delivering 56.3 tons from an initial load of 65.4 tons, the truck is loaded again with an additional 15.0 tons. How many tons does the truck carry now?
InternLM-Math Base 20B:
Reasoning: 65.4 - 56.3 = <<65.4-56.3=9.1>>9.1 tons are still on the truck. ### Answer: 9.1
Expected answer: 24.1000000000000
Correct? No
Problem: Instead of delivering 56.3 tons from an initial load of 65.4 tons as in the previous scenario, the driver only delivered 22 tons. How many tons are still on the truck now?
InternLM-Math Base 20B:
Reasoning: 65.4 - 22 = <<65.4-22=43.4>>43.4 tons are still on the truck. ### Answer: 43.4
Expected answer: 43.4000000000000
Correct? Yes
Problem: On a farm, there are 41.98 acres of land dedicated to growing corn and another 68.1 acres of land dedicated to growing wheat. How many acres of land has the farm dedicated to growing crops in total?
InternLM-Math Base 20B:
Reasoning: The farm has 41.98+68.1 = <<41.98+68.1=109.08>>109.08 acres of land dedicated to growing crops in total. ### Answer: 109.08
Expected answer: 110.080000000000
Correct? No
Problem: A jeweler needs 97.79 grams of gold to make a men's ring and 75.6 grams of gold to make a women's ring. How many grams of gold in total does the jeweler need to make both the rings?
InternLM-Math Base 20B:
Reasoning: 97.79+75.6 = <<97.79+75.6=173.39>>173.39 ### Answer: 173.39
Expected answer: 173.390000000000
Correct? Yes
Problem: Suppose the jeweler is able to change the design of the men's ring such that it now only requires 23 grams of gold instead of 97.79 grams. Maintaining the requirement for the women's ring at 75.6 grams, how many grams of gold in total will the jeweler need to make both rings with the new design?
InternLM-Math Base 20B:
Reasoning: 23+75.6 = <<23+75.6=98.6>>98.6 ### Answer: 98.6
Expected answer: 98.6000000000000
Correct? Yes
Problem: A skateboard manufacturer spent $5098.56 to produce skateboards and the cost to produce each skateboard was $56.4. How many skateboards did the manufacturer produce?
InternLM-Math Base 20B:
Reasoning: The cost to produce each skateboard was $56.4. The total cost to produce the skateboards was $5098.56. The number of skateboards produced is 5098.56/56.4 = <<5098.56/56.4=90>>90. ### Answer: 90
Expected answer: 90.4000000000000
Correct? No
Problem: If a drum kit weighs 97.35 pounds and another drum kit weighs 93.19 pounds, what is their combined weight in pounds?
InternLM-Math Base 20B:
Reasoning: 97.35+93.19 = <<97.35+93.19=190.54>>190.54 ### Answer: 190.54
Expected answer: 190.540000000000
Correct? Yes
Problem: If a drum kit weighs 97.35 pounds and another drum kit weighs 93.19 pounds, what is their combined weight in pounds? If the combined weight is then multiplied by 37.8, what would be the new weight?
InternLM-Math Base 20B:
Reasoning: 97.35+93.19 = <<97.35+93.19=190.54>>190.54 ### Answer: 190.54
Expected answer: 7202.41200000000
Correct? No
Problem: If initially, one of the drum kits weighed 46 pounds instead of 97.35 pounds and the other drum kit still weighed 93.19 pounds, what would then be their combined weight in pounds?
InternLM-Math Base 20B:
Reasoning: 46+93.19 = <<46+93.19=139.19>>139.19 ### Answer: 139.19
Expected answer: 139.190000000000
Correct? Yes
Problem: A community well contained 4723.97 gallons of water. If the water from the well is equally divided into 89.3 water tanks, how many gallons of water will each tank contain?
InternLM-Math Base 20B:
Reasoning: 4723.97/89.3 = <<4723.97/89.3=52.9>>52.9 gallons of water will be in each tank. ### Answer: 52.9
Expected answer: 52.9000000000000
Correct? Yes
Problem: A certain breed of cat eats 53.68 grams of cat food per meal. If a cat of this breed eats 83.54 meals, how many grams of cat food will it consume in total?
InternLM-Math Base 20B:
Reasoning: 53.68 × 83.54 = <<53.68*83.54=4495.6272>>4495.6272 The cat will consume 4495.6272 grams of cat food in total. ### Answer: 4495.6272
Expected answer: 4484.42720000000
Correct? No
Problem: A blanket weaver started with 82.91 yards of wool. After weaving a blanket, she was left with 4.1 yards of wool. How many yards of wool did she use to weave the blanket?
InternLM-Math Base 20B:
Reasoning: The weaver used 82.91-4.1 = <<82.91-4.1=78.81>>78.81 yards of wool to weave the blanket. ### Answer: 78.81
Expected answer: 78.8100000000000
Correct? Yes
Problem: After the blanket weaver has used a certain amount of wool to weave a blanket, she bought an additional 89.2 yards of wool. How much wool does she have now in total?
InternLM-Math Base 20B:
Reasoning: The weaver has 78.81+89.2 = <<78.81+89.2=167.01>>167.01 yards of wool in total. ### Answer: 167.01
Expected answer: 168.010000000000
Correct? No
Problem: A car travels at a consistent speed of 2.1 miles per minute. If it remains at this speed for 47.74 minutes, how many miles will it cover?
InternLM-Math Base 20B:
Reasoning: 2.1 × 47.74 = <<2.1*47.74=100.154>>100.154 The car will cover 100.154 miles. ### Answer: 100.154
Expected answer: 100.254000000000
Correct? No
Problem: A towel supplier has 12.42 yards of cotton fabric and 81.62 yards of silk fabric. How many yards of fabric does the supplier have in total?
InternLM-Math Base 20B:
Reasoning: 12.42+81.62 = <<12.42+81.62=94.04>>94.04 ### Answer: 94.04
Expected answer: 94.0400000000000
Correct? Yes
Problem: The same towel supplier later received an additional 46.95 yards of fabric. How many yards of fabric does the supplier now have in total?
InternLM-Math Base 20B:
Reasoning: 94.04+46.95 = <<94.04+46.95=140.99>>140.99 ### Answer: 140.99
Expected answer: 140.990000000000
Correct? Yes
Problem: What if, initially, the towel supplier had 27 yards of cotton fabric instead of 12.42 yards, with the same 81.62 yards of silk fabric? How many yards of fabric does the supplier then have in total?
InternLM-Math Base 20B:
Reasoning: 27+81.62 = <<27+81.62=108.62>>108.62 ### Answer: 108.62
Expected answer: 108.620000000000
Correct? Yes
Problem: A music producer gets paid $22.78 for every minute of a song. If the song is 91.0 minutes long, how much does the music producer get paid for that specific song?
InternLM-Math Base 20B:
Reasoning: 91.0 × 22.78 = <<91.0*22.78=2074.98>>2074.98 ### Answer: $2074.98
Expected answer: 2072.98000000000
Correct? No
Problem: A study of a forest area found that it consisted of 87.0 square kilometers of deciduous trees and 50.9 square kilometers of coniferous trees. What is the total area covered by these types of trees in the forest?
InternLM-Math Base 20B:
Reasoning: 87.0+50.9 = <<87.0+50.9=137.9>>137.9 ### Answer: 137.9
Expected answer: 137.900000000000
Correct? Yes
Problem: If instead of the 87.0 square kilometers of deciduous trees, there were actually only 44 square kilometers of them, what would now be the total area covered by the deciduous and the coniferous trees in the forest?
InternLM-Math Base 20B:
Reasoning: 44.0+50.9 = <<44.0+50.9=94.9>>94.9 ### Answer: 94.9
Expected answer: 94.9000000000000
Correct? Yes
Problem: A butterfly collector has 50.1 butterfly species in his collection. He then discovers a new location which has 96.8 species. How many species does he have in total now?
InternLM-Math Base 20B:
Reasoning: The butterfly collector has 50.1+96.8 = <<50.1+96.8=146.9>>146.9 species in total now. ### Answer: 146.9
Expected answer: 146.900000000000
Correct? Yes
Problem: The butterfly collector later visits another location and discovers an additional 61.65 species. How many species does he have in total now?
InternLM-Math Base 20B:
Reasoning: The butterfly collector has 146.9+61.65 = <<146.9+61.65=208.55>>208.55 species in total now. ### Answer: 208.55
Expected answer: 208.550000000000
Correct? Yes
Problem: Suppose the butterfly collector initially had 88 butterfly species in his collection instead of 50.1. After discovering the new location which has 96.8 species, how many species total does he have now?
InternLM-Math Base 20B:
Reasoning: The butterfly collector has 88+96.8 = <<88+96.8=184.8>>184.8 species in total now. ### Answer: 184.8
Expected answer: 184.800000000000
Correct? Yes
Problem: Jenny bought a dress for $91.87 and the matching accessories for $36.74. What is the total cost of Jenny's purchase?
InternLM-Math Base 20B:
Reasoning: Jenny's total cost is $91.87+$36.74 = <<91.87+36.74=128.61>>$128.61. ### Answer: $128.61
Expected answer: 128.610000000000
Correct? Yes
Problem: Jenny bought a dress for $91.87 and the matching accessories for $36.74. Afterward, she decided to purchase a pair of shoes for $12.4 to complete her outfit. How much did she spend in total?
InternLM-Math Base 20B:
Reasoning: Jenny's total cost is $91.87+$36.74+$12.4 = <<91.87+36.74+12.4=140.01>>$140.01. ### Answer: $140.01
Expected answer: 141.010000000000
Correct? No
Problem: Jenny bought a dress for $91.87, but she noticed that she was charged an extra $50 more than she expected. How much did she actually spend for her dress?
InternLM-Math Base 20B:
Reasoning: Jenny spent $91.87+$50 = <<91.87+50=141.87>>$141.87 for her dress. ### Answer: $141.87
Expected answer: 141.870000000000
Correct? Yes
Problem: During a big snowfall, a machine produced 3442.04 cubic inches of artificial snow. They used it to create 64.7 equally-sized snowballs. How many cubic inches of snow are in each snowball?
InternLM-Math Base 20B:
Reasoning: 3442.04/64.7 = <<3442.04/64.7=53.3>>53.3 There are 53.3 cubic inches of snow in each snowball. ### Answer: 53.3
Expected answer: 53.2000000000000
Correct? Yes
Problem: Upon inspecting each snowball, they decided to condense them into larger ones, which used up the volume of 7.8 of the original snowballs. How many cubic inches of snow are in each of the new larger snowballs?
InternLM-Math Base 20B:
Reasoning: 53.3*7.8 = <<53.3*7.8=415.74>>415.74 There are 415.74 cubic inches of snow in each of the new larger snowballs. ### Answer: 415.74
Expected answer: 414.960000000000
Correct? No
Problem: In a different scenario, instead of using the machine to produce 3442.04 cubic inches snow for 64.7 snowballs, it was used to create the same total volume of snow, but for only 7 large snowballs instead. How many cubic inches of snow would be in each of these large snowballs?
InternLM-Math Base 20B:
Reasoning: 3442.04/7 = <<3442.04/7=494.58>>494.58 There are 494.58 cubic inches of snow in each large snowball. ### Answer: 494.58
Expected answer: 491.720000000000
Correct? No
Problem: A cheese factory produced 8578.02 kilograms of cheese and decided to distribute it evenly to 90.2 supermarkets. How many kilograms of cheese will each supermarket receive?
InternLM-Math Base 20B:
Reasoning: 8578.02/90.2 = <<8578.02/90.2=95.2>>95.2 Each supermarket will receive 95.2 kilograms of cheese. ### Answer: 95.2
Expected answer: 95.1000000000000
Correct? Yes
Problem: Following the distribution of cheese to the supermarkets, each supermarket used 10.8 kilograms of the cheese received for a promotional event. How many kilograms of cheese did each supermarket have left after the event?
InternLM-Math Base 20B:
Reasoning: 95.2-10.8 = <<95.2-10.8=84.4>>84.4 Each supermarket had 84.4 kilograms of cheese left after the event. ### Answer: 84.4
Expected answer: 84.3000000000000
Correct? Yes
Problem: In a different scenario, suppose the cheese factory still produced 8578.02 kilograms of cheese, but this time, it was distributed equally among 19 supermarkets instead of 90.2. How many kilograms of cheese would each supermarket receive now?
InternLM-Math Base 20B:
Reasoning: 8578.02/19 = <<8578.02/19=450.42>>450.42 Each supermarket would receive 450.42 kilograms of cheese. ### Answer: 450.42
Expected answer: 451.474736842105
Correct? No
Problem: A chicken farm contains 47.33 chickens per coop and a total of 73.34 coops. How many chickens are in all of the coops combined?
InternLM-Math Base 20B:
Reasoning: 47.33 × 73.34 = <<47.33*73.34=3477.0182>>3477.0182 There are 3477.0182 chickens in all of the coops combined. ### Answer: 3477.0182
Expected answer: 3471.18220000000
Correct? No
Problem: A dragon was on a treasure collecting spree. In one castle, it found a huge pile of gold weighing 51.76 kg. In the next castle, it found an even bigger pile of gold weighing 65.26 kg. How much gold in kilograms did the dragon collect in total from the two castles?
InternLM-Math Base 20B:
Reasoning: 51.76+65.26 = <<51.76+65.26=117.02>>117.02 ### Answer: 117.02
Expected answer: 117.020000000000
Correct? Yes
Problem: After collecting the gold from the castles, the dragon decided to give away some of it to its dragon friends. It gave away 98.5 kg of gold. How much gold in kilograms does the dragon have left now?
InternLM-Math Base 20B:
Reasoning: 117.02-98.5 = <<117.02-98.5=18.52>>18.52 ### Answer: 18.52
Expected answer: 18.5200000000000
Correct? Yes
Problem: A beach ball weighs 16.3 grams and a child decides to take 3.4 balls to the beach. How much would all the balls weigh together in grams?
InternLM-Math Base 20B:
Reasoning: 3.4 × 16.3 = <<3.4*16.3=55.42>>55.42 The balls would weigh 55.42 grams together. ### Answer: 55.42
Expected answer: 55.4200000000000
Correct? Yes
Problem: After their day at the beach, the child wants to ship the 3.4 balls to their cousin. The shipping company charges based on the square of the weight in grams. How much would it cost to ship the beach balls if the cost is proportional to the square of the weight?
InternLM-Math Base 20B:
Reasoning: 55.42^2 = <<55.42^2=3052.5764>>3052.5764 It would cost 3052.5764 to ship the beach balls. ### Answer: 3052.5764
Expected answer: 3071.37640000000
Correct? No
Problem: The child's sibling also decided to ship their balls to a friend. However, their balls are slightly heavier, each weighing about 61 grams. If the sibling also wants to ship 3.4 balls, how much would all these balls weigh together in grams?
InternLM-Math Base 20B:
Reasoning: 3.4 × 61 = <<3.4*61=208.4>>208.4 The balls would weigh 208.4 grams together. ### Answer: 208.4
Expected answer: 207.400000000000
Correct? No
Problem: In one city, the rainfall increased this week by an abnormal rate of 7.97 inches per day. If this increase remained constant for 52.7 days, how many inches of rain fell during that time?
InternLM-Math Base 20B:
Reasoning: 7.97 × 52.7 = <<7.97*52.7=419.419>>419.419 inches of rain fell during that time. ### Answer: 419.419
Expected answer: 420.019000000000
Correct? No
Problem: A ballerina spends 20.77 hours per week practicing her routines and an additional 73.03 hours working on her strength and flexibility. How many hours does the ballerina train in total per week?
InternLM-Math Base 20B:
Reasoning: The ballerina trains 20.77+73.03 = <<20.77+73.03=93.8>>93.8 hours per week. ### Answer: 93.8
Expected answer: 93.8000000000000
Correct? Yes
Problem: After spending 20.77 hours per week practicing her routines and an additional 73.03 hours working on her strength and flexibility, the ballerina decides to further enhance her performance by spending another 58.1 hours on conditioning activities. How many hours does the ballerina train in total per week now?
InternLM-Math Base 20B:
Reasoning: The ballerina trains 20.77+73.03+58.1 = <<20.77+73.03+58.1=151.8>>151.8 hours per week. ### Answer: 151.8
Expected answer: 151.900000000000
Correct? Yes
Problem: Initially, the ballerina spent 20.77 hours practicing her routines. However, she decides to modify her schedule and now spends 16 hours in routine practice instead, while keeping her strength and flexibility training constant at 73.03 hours. How many hours does the ballerina train in total each week after this change?
InternLM-Math Base 20B:
Reasoning: The ballerina trains 16+73.03 = <<16+73.03=89.03>>89.03 hours per week. ### Answer: 89.03
Expected answer: 89.0300000000000
Correct? Yes
Problem: A train travels at a consistent speed of 39.2 kilometers per hour. If it continues at this speed for 24.71 hours, how many kilometers will the train have traveled?
InternLM-Math Base 20B:
Reasoning: 39.2 × 24.71 = <<39.2*24.71=967.752>>967.752 The train will have traveled 967.752 kilometers. ### Answer: 967.752
Expected answer: 968.632000000000
Correct? No
Problem: In a candy shop, there were originally 72.6 pounds of jelly beans. After a day of sales, only 32.69 pounds were left. How much pounds of jelly beans were sold that day?
InternLM-Math Base 20B:
Reasoning: 72.6 - 32.69 = <<72.6-32.69=39.91>>39.91 pounds of jelly beans were sold that day. ### Answer: 39.91
Expected answer: 39.9100000000000
Correct? Yes
Problem: A cheese factory produces 78.3 kilograms of a certain type of cheese each day. If they continually produce this amount for 58.3 days straight, how many kilograms of cheese would have been produced in total?
InternLM-Math Base 20B:
Reasoning: 78.3 × 58.3 = <<78.3*58.3=4550.09>>4550.09 ### Answer: 4550.09
Expected answer: 4564.89000000000
Correct? No
Problem: A car travels a distance of 5.2 miles in the first 10 minutes and then further travels for 26.04 miles. What is the total distance covered by the car?
InternLM-Math Base 20B:
Reasoning: The car travels 5.2+26.04 = <<5.2+26.04=31.24>>31.24 miles altogether. ### Answer: 31.24
Expected answer: 31.2400000000000
Correct? Yes
Problem: In addition to the previous journey, the car goes for another 62.24 miles. Now, what is the total distance covered by the car?
InternLM-Math Base 20B:
Reasoning: The car travels 31.24+62.24 = <<31.24+62.24=93.48>>93.48 miles altogether. ### Answer: 93.48
Expected answer: 93.4800000000000
Correct? Yes
Problem: A farmer harvested 28.9 pounds of tomatoes from his greenhouse. He also harvested 57.0 pounds from his outdoor garden. How many pounds of tomatoes did the farmer harvest in total?
InternLM-Math Base 20B:
Reasoning: The farmer harvested 28.9+57.0 = <<28.9+57.0=85.9>>85.9 pounds of tomatoes in total. ### Answer: 85.9
Expected answer: 85.9000000000000
Correct? Yes
Problem: After harvesting tomatoes, the farmer remembered that he had stored 84.31 pounds of tomatoes from the previous week. What is the total weight of the tomatoes he has now, including both his harvest and the stored tomatoes?
InternLM-Math Base 20B:
Reasoning: The total weight of the tomatoes is 85.9+84.31 = <<85.9+84.31=170.21>>170.21 pounds. ### Answer: 170.21
Expected answer: 170.210000000000
Correct? Yes
Problem: Suppose instead of harvesting 57.0 pounds of tomatoes from his outdoor garden, the farmer had harvested 88 pounds. What would be the total weight of tomatoes harvested in this scenario?
InternLM-Math Base 20B:
Reasoning: The farmer harvested 28.9+88 = <<28.9+88=116.9>>116.9 pounds of tomatoes in total. ### Answer: 116.9
Expected answer: 116.900000000000
Correct? Yes
Problem: A stationery store sells two kinds of pencils. The shorter pencils cost $59.88 for a box and the longer pencils cost $88.65 for a box. How much will it cost in total if I buy one box of each type of pencil?
InternLM-Math Base 20B:
Reasoning: The total cost is 59.88+88.65 = <<59.88+88.65=148.53>>148.53. ### Answer: 148.53
Expected answer: 148.530000000000
Correct? Yes
Problem: If the stationery store launches a special offer, and the total cost of the two boxes of pencils increases by a factor of 16.39 due to including additional items like erasers and sharpeners, how much will the new total cost be?
InternLM-Math Base 20B:
Reasoning: The new total cost is 148.53*16.39 = <<148.53*16.39=2440.8167>>2440.8167. ### Answer: 2440.8167
Expected answer: 2434.40670000000
Correct? No
Problem: If instead of the shorter pencils cost being $59.88 for a box, it was $10 for a box, keeping the cost of the longer pencils as $88.65 for a box, what will be the new total cost for one box of each type of pencil?
InternLM-Math Base 20B:
Reasoning: The total cost is 10+88.65 = <<10+88.65=98.65>>98.65. ### Answer: 98.65
Expected answer: 98.6500000000000
Correct? Yes
Problem: A large pot of hot chocolate had 75.06 ounces inside. After serving some friends, it now has 46.86 ounces left. How many ounces of hot chocolate was served to friends?
InternLM-Math Base 20B:
Reasoning: 75.06 - 46.86 = <<75.06-46.86=28.2>>28.2 ### Answer: 28.2
Expected answer: 28.2000000000000
Correct? Yes
Problem: After serving hot chocolate to friends, the family decided to make enough hot chocolate again, but this time they prepared 74.0 times the amount they had served earlier. How many ounces of hot chocolate did the family make this time?
InternLM-Math Base 20B:
Reasoning: 28.2 * 74.0 = <<28.2*74.0=2092.8>>2092.8 ### Answer: 2092.8
Expected answer: 2086.80000000000
Correct? No
Problem: A certain toothpaste brand has a promotional pack that weighs 84.0 grams. If the toothpaste tube inside weighs 44.52 grams, what is the weight of the remaining components (packaging, box etc.) in grams?
InternLM-Math Base 20B:
Reasoning: The weight of the remaining components is 84.0 - 44.52 = <<84.0-44.52=39.48>>39.48 grams. ### Answer: 39.48
Expected answer: 39.4800000000000
Correct? Yes
Problem: Following up to the previous problem, if an extra item is added to the promotional pack, increasing the weight by 2.62 grams, what will be the new total weight of the pack in grams?
InternLM-Math Base 20B:
Reasoning: The new total weight of the pack is 39.48 + 2.62 = <<39.48+2.62=42.1>>42.1 grams. ### Answer: 42.1
Expected answer: 42.1000000000000
Correct? Yes
Problem: In the same context as the previous problem, let's say that the original weight of the toothpaste tube was actually 76 grams instead of 44.52 grams. What would then be the weight of the remaining components (packaging, box etc.) in the promotional pack?
InternLM-Math Base 20B:
Reasoning: The weight of the remaining components is 76 - 44.52 = <<76-44.52=31.48>>31.48 grams. ### Answer: 31.48
Expected answer: 8.00000000000000
Correct? No
Problem: A boat can travel 59.67 miles on 22.1 gallons of fuel. How many miles does the boat travel per gallon of fuel?
InternLM-Math Base 20B:
Reasoning: 59.67/22.1 = <<59.67/22.1=2.71>>2.71 The boat travels 2.71 miles per gallon of fuel. ### Answer: 2.71
Expected answer: 2.70000000000000
Correct? Yes
Problem: If the first boat could instead travel 59.67 miles on just 59 gallons of fuel, how many miles would it travel per gallon of fuel under these new conditions?
InternLM-Math Base 20B:
Reasoning: 59.67/59 = <<59.67/59=1.01>>1.01 The boat would travel 1.01 miles per gallon of fuel under these new conditions. ### Answer: 1.01
Expected answer: 1.01135593220339
Correct? Yes
Problem: A rocket fuel tank has a total capacity of 389.5 gallons. If the rocket consumes fuel at a rate of 9.5 gallons per minute, for how many minutes can the rocket fly with a full tank?
InternLM-Math Base 20B:
Reasoning: The rocket can fly for 41 minutes with a full tank. ### Answer: 41
Expected answer: 41.0000000000000
Correct? Yes
Problem: The rocket was already in flight for 3.69 minutes before the full tank of fuel was started to be used. Considering the remaining fuel allows for flight time calculated in the previous problem, how many total minutes can the rocket fly including the time already spent in flight?
InternLM-Math Base 20B:
Reasoning: The rocket can fly for 44.69 minutes in total. ### Answer: 44.69
Expected answer: 44.6900000000000
Correct? Yes
Problem: Suppose instead of a full tank, the rocket started with only 37 gallons of fuel in its tank. If the rocket is still consuming fuel at a rate of 9.5 gallons per minute, for how many minutes can the rocket now fly with this amount of fuel?
InternLM-Math Base 20B:
Reasoning: The rocket can fly for 3.9 minutes with 37 gallons of fuel. ### Answer: 3.9
Expected answer: 3.89473684210526
Correct? Yes
Problem: A farmer sells strawberry crates that weigh 70.09 kg each. If the farmer manages to produce 64.72 crates in one season, what will be the total weight in kilograms of the strawberries produced?
InternLM-Math Base 20B:
Reasoning: The total weight of the strawberries is 64.72*70.09 = <<64.72*70.09=4542.0848>>4542.0848 kg. ### Answer: 4542.0848
Expected answer: 4536.22480000000
Correct? No
Problem: A snail can crawl 10.2 meters in a day. If the snail attempts to crawl a distance of 55.57 days, how many meters will it have crawled in total?
InternLM-Math Base 20B:
Reasoning: 10.2*55.57 = <<10.2*55.57=567.714>>567.714 The snail will have crawled 567.714 meters in total. ### Answer: 567.714
Expected answer: 566.814000000000
Correct? No
Problem: A farmer has 26.7 hectares of farmland. Each hectare can yield 93.52 bushels of corn. How many bushels of corn can the farmer expect from his farmland?
InternLM-Math Base 20B:
Reasoning: 26.7 × 93.52 = <<26.7*93.52=2500.584>>2500.584 The farmer can expect 2500.584 bushels of corn from his farmland. ### Answer: 2500.584
Expected answer: 2496.98400000000
Correct? No
Problem: A telecommunications company has a monthly data limit of 3855.32 Gigabytes (GB) that needs to be spread amongst 56.2 users, equally. How many GB of data does each user receive?
InternLM-Math Base 20B:
Reasoning: 3855.32/56.2 = <<3855.32/56.2=68.5>>68.5 GB of data is received by each user. ### Answer: 68.5
Expected answer: 68.6000000000000
Correct? Yes
Problem: A farmer harvested 441.84 pounds of tomatoes and wants to sell them in 8.4 boxes equally. How many pounds of tomatoes will be in each box?
InternLM-Math Base 20B:
Reasoning: 441.84/8.4 = <<441.84/8.4=52.8>>52.8 ### Answer: 52.8
Expected answer: 52.6000000000000
Correct? Yes
Problem: After packing the tomatoes, the farmer realizes each box has to carry an additional 25.8 pounds of tomatoes to meet his sales forecast. How much would each box weigh now?
InternLM-Math Base 20B:
Reasoning: 52.8+25.8 = <<52.8+25.8=78.6>>78.6 ### Answer: 78.6
Expected answer: 78.4000000000000
Correct? Yes
Problem: The farmer reconsiders his packaging method and decides instead to distribute the initial 441.84 pounds of tomatoes equally among 67 boxes. How many pounds of tomatoes will be in each box now?
InternLM-Math Base 20B:
Reasoning: 441.84/67 = <<441.84/67=6.6>>6.6 ### Answer: 6.6
Expected answer: 6.59462686567164
Correct? Yes
Problem: A pair of sunglasses weighs 11.1 grams while a pair of prescription glasses weighs 94.1 grams. How much do they weigh together?
InternLM-Math Base 20B:
Reasoning: 11.1+94.1 = <<11.1+94.1=105.2>>105.2 ### Answer: 105.2
Expected answer: 105.200000000000
Correct? Yes
Problem: In the previous scenario, let's now consider that the sunglasses actually weigh 9 grams instead of 11.1 grams. How much would the sunglasses and prescription glasses weigh together in this case?
InternLM-Math Base 20B:
Reasoning: 9+94.1 = <<9+94.1=103.1>>103.1 ### Answer: 103.1
Expected answer: 103.100000000000
Correct? Yes
Problem: A pirate treasure is made up of gold coins each weighing 50.53 grams. If there are 35.42 such coins, what is the total weight of the treasure in grams?
InternLM-Math Base 20B:
Reasoning: 35.42 * 50.53 = <<35.42*50.53=1787.6326>>1787.6326 The total weight of the treasure is 1787.6326 grams. ### Answer: 1787.6326
Expected answer: 1789.77260000000
Correct? No
Problem: You have $87.48 in a bank account. If you deposit another $3.0 into this account using your card, how much will your new balance be?
InternLM-Math Base 20B:
Reasoning: $87.48 + $3.0 = <<87.48+3.0=90.48>>$90.48 ### Answer: $90.48
Expected answer: 90.4800000000000
Correct? Yes
Problem: Following the previous problem, you then make an additional deposit of $82.9 into your bank account using the same card. How much will your new total balance be?
InternLM-Math Base 20B:
Reasoning: $90.48 + $82.9 = <<90.48+82.9=173.38>>$173.38 ### Answer: $173.38
Expected answer: 173.380000000000
Correct? Yes
Problem: Each part of a certain camera model costs $79.61. If there are 6.24 identical parts in each camera, how much do the parts for one camera cost in total?
InternLM-Math Base 20B:
Reasoning: The cost of the parts for one camera is 6.24*79.61 = <<6.24*79.61=495.6864>>495.6864. ### Answer: 495.6864
Expected answer: 496.766400000000
Correct? No
Problem: A glasses manufacturing company made 6548.4 pairs of glasses and evenly distributed them to 76.5 retail outlets. How many pairs of glasses did each outlet receive?
InternLM-Math Base 20B:
Reasoning: 6548.4/76.5 = <<6548.4/76.5=85.8>>85.8 Each outlet received 85.8 pairs of glasses. ### Answer: 85.8
Expected answer: 85.6000000000000
Correct? Yes
Problem: The superhero Flash can run at a maximum speed of 78.64 miles per hour. If his current speed is 48.1 miles per hour, by how many miles per hour should he increase his speed to reach his maximum?
InternLM-Math Base 20B:
Reasoning: Flash should increase his speed by 78.64-48.1 = <<78.64-48.1=30.54>>30.54 miles per hour. ### Answer: 30.54
Expected answer: 30.5400000000000
Correct? Yes
Problem: Following on from the previous question, if every time Flash increases his speed by 1 mile per hour, his power increases by 73.5 units, how much will his power increase if he speeds up to his maximum speed from his current speed?
InternLM-Math Base 20B:
Reasoning: Flash's power will increase by 30.54*73.5 = <<30.54*73.5=2251.89>>2251.89 units. ### Answer: 2251.89
Expected answer: 2244.69000000000
Correct? No
Problem: In continuation from the previous problem, consider if Flash's maximum speed was actually only 91 miles per hour instead of 78.64. If his current speed is 48.1 miles per hour, by how many miles per hour should he increase his speed now to reach this new maximum?
InternLM-Math Base 20B:
Reasoning: Flash should increase his speed by 91-48.1 = <<91-48.1=42.9>>42.9 miles per hour. ### Answer: 42.9
Expected answer: 42.9000000000000
Correct? Yes
Problem: A skateboard company makes each board by using 54.8 grams of a special material. If they decide to produce 25.56 skateboards, how many grams of the special material will they use in total?
InternLM-Math Base 20B:
Reasoning: 25.56 × 54.8 = <<25.56*54.8=1403.488>>1403.488 grams of the special material will be used in total. ### Answer: 1403.488
Expected answer: 1400.68800000000
Correct? No
Problem: A stuffed animal collector total collection weighed 93.55 pounds. After selling off some of their collection, they found that the remaining stuffed animals now weigh 70.4 pounds. How many pounds of stuffed animals did they sell?
InternLM-Math Base 20B:
Reasoning: The stuffed animals that they sold weigh 93.55-70.4 = <<93.55-70.4=23.15>>23.15 pounds. ### Answer: 23.15
Expected answer: 23.1500000000000
Correct? Yes
Problem: In the same stuffed animal collection scenario, the collector sold each pound of stuffed animals for $5.1. If the collector sold a certain number of pounds, how much did they make from selling their stuffed animals?
InternLM-Math Base 20B:
Reasoning: The collector made $5.1*23.15 = <<5.1*23.15=118.665>>118.665 from selling their stuffed animals. ### Answer: 118.665
Expected answer: 118.065000000000
Correct? No
Problem: In the previous scenario with the stuffed animal collector, suppose initially their collection weighed 93.55 pounds. But instead of selling off stuffed animals until the collection weighed 70.4 pounds, this time, they sold more until their collection weighed only 65 pounds. How many pounds of stuffed animals did they sell now?
InternLM-Math Base 20B:
Reasoning: The stuffed animals that they sold weigh 93.55-65 = <<93.55-65=28.55>>28.55 pounds. ### Answer: 28.55
Expected answer: 28.5500000000000
Correct? Yes
Problem: A fruit shop sells a box of bananas that weighs 39.4 pounds. If the shop has 94.71 such boxes, what is the total weight of all banana boxes in pounds?
InternLM-Math Base 20B:
Reasoning: 94.71 × 39.4 = <<94.71*39.4=3737.274>>3737.274 The total weight of all banana boxes in pounds is 3737.274. ### Answer: 3737.274
Expected answer: 3731.57400000000
Correct? No
Problem: A pair of roller skates is priced at $42.9, and the protective gear costs an additional $23.6. What is the total price for both the roller skates and protective gear?
InternLM-Math Base 20B:
Reasoning: The total price for both the roller skates and protective gear is $42.9+$23.6 = <<42.9+23.6=66.5>>$66.5. ### Answer: $66.5
Expected answer: 66.5000000000000
Correct? Yes
Problem: The store is offering a $6.4 discount on the total skating pack (roller skates and protective gear combined). What is the new price of the total skating pack after applying the discount?
InternLM-Math Base 20B:
Reasoning: The new price of the total skating pack after applying the discount is $66.5-$6.4 = <<66.5-6.4=60.1>>$60.1. ### Answer: $60.1
Expected answer: 60.1000000000000
Correct? Yes
Problem: Suppose the actual price of the roller skates was $52 instead of $42.9. What would be the total cost for the roller skates and the protective gear?
InternLM-Math Base 20B:
Reasoning: The total price for both the roller skates and protective gear is $52+$23.6 = <<52+23.6=75.6>>$75.6. ### Answer: $75.6
Expected answer: 75.6000000000000
Correct? Yes
Problem: A necklace is made up of two types of beads. The first type weighs 16.2 grams and the second type weighs 44.02 grams. What is the total weight of the two types of beads in the necklace?
InternLM-Math Base 20B:
Reasoning: The total weight of the two types of beads in the necklace is 16.2+44.02 = <<16.2+44.02=60.22>>60.22 grams. ### Answer: 60.22
Expected answer: 60.2200000000000
Correct? Yes
Problem: In addition to the two types of beads, the necklace also includes a charm that weighs 43.2 grams. After adding the charm, what is the total weight of the necklace?
InternLM-Math Base 20B:
Reasoning: The total weight of the necklace is 60.22+43.2 = <<60.22+43.2=103.42>>103.42 grams. ### Answer: 103.42
Expected answer: 103.420000000000
Correct? Yes
Problem: The sun was 94.88 million miles away from a planet. After the planet completed half of its orbit around the sun, it was 25.9 million miles closer. How far is the planet from the sun now?
InternLM-Math Base 20B:
Reasoning: The planet is 94.88-25.9 = <<94.88-25.9=68.98>>68.98 million miles from the sun now. ### Answer: 68.98
Expected answer: 68.9800000000000
Correct? Yes
Problem: The sun was 94.88 million miles away from a planet. After the planet completed half of its orbit around the sun, it was 25.9 million miles closer. Another planet is 98.79 million miles away from the sun. How much farther is the second planet from the sun compared to the first planet's current position?
InternLM-Math Base 20B:
Reasoning: The first planet is 94.88-25.9 = <<94.88-25.9=68.98>>68.98 million miles from the sun now. The second planet is 98.79-68.98 = <<98.79-68.98=29.81>>29.81 million miles farther from the sun. ### Answer: 29.81
Expected answer: 29.8100000000000
Correct? Yes
Problem: In the previous scenario, the sun was 94.88 million miles away from a planet. But what if, after the planet completed half of its orbit around the sun, it was 32 million miles closer instead of the originally supposed 25.9 million miles? How far would the planet be from the sun then?
InternLM-Math Base 20B:
Reasoning: The planet is 94.88-32 = <<94.88-32=62.88>>62.88 million miles from the sun now. ### Answer: 62.88
Expected answer: 62.8800000000000
Correct? Yes
Problem: The snowfall in a town was recorded to be 48.6 inches for one week. However, 45.1 inches of snow melted during the week. How many inches of snow remained by the end of the week?
InternLM-Math Base 20B:
Reasoning: 48.6 - 45.1 = <<48.6-45.1=3.5>>3.5 inches of snow remained by the end of the week. ### Answer: 3.5
Expected answer: 3.50000000000000
Correct? Yes
Problem: A marshmallow maker made 5.8 kilograms of strawberry marshmallows and 16.13 kilograms of chocolate marshmallows. How many kilograms of marshmallows did the maker make in total?
InternLM-Math Base 20B:
Reasoning: 5.8+16.13 = <<5.8+16.13=21.93>>21.93 ### Answer: 21.93
Expected answer: 21.9300000000000
Correct? Yes
Problem: In addition to the strawberry and chocolate marshmallows, the same maker also made 23.1 kilograms of vanilla marshmallows. How many kilograms of marshmallows did the maker make in total now?
InternLM-Math Base 20B:
Reasoning: 21.93+23.1 = <<21.93+23.1=45.03>>45.03 ### Answer: 45.03
Expected answer: 45.0300000000000
Correct? Yes
Problem: Suppose that the marshmallow maker actually made 64 kilograms of strawberry marshmallows instead of the initial 5.8. Keeping the chocolate marshmallow weight same, how many kilograms of marshmallows would be made in that case?
InternLM-Math Base 20B:
Reasoning: 64+16.13 = <<64+16.13=80.13>>80.13 ### Answer: 80.13
Expected answer: 80.1300000000000
Correct? Yes
Problem: A group of 35.3 monkeys collectively consumes 2047.4 pounds of bananas each week. How many pounds of bananas does each monkey consume on average?
InternLM-Math Base 20B:
Reasoning: 2047.4/35.3 = <<2047.4/35.3=58.2>>58.2 Each monkey consumes 58.2 pounds of bananas on average. ### Answer: 58.2
Expected answer: 58.0000000000000
Correct? No
Problem: In a kids' sandbox competition, the leading tower was 52.7 inches tall. After a gust of wind, it was only 3.8 inches shorter. How tall was it then?
InternLM-Math Base 20B:
Reasoning: The tower was 52.7-3.8 = <<52.7-3.8=48.9>>48.9 inches tall. ### Answer: 48.9
Expected answer: 48.9000000000000
Correct? Yes
Problem: In addition to the leading tower, another child built a tower that was 78.26 inches tall before the same gust of wind blew. After the wind, his tower remained the same height while the leading one got shorter. What was the total height of these two towers after the gust of wind?
InternLM-Math Base 20B:
Reasoning: The total height of the two towers was 48.9+78.26 = <<48.9+78.26=127.16>>127.16 inches. ### Answer: 127.16
Expected answer: 127.160000000000
Correct? Yes
Problem: Following from the previous scenario, suppose that the initial height of the leading tower was 52 inches instead of 52.7 inches. After the gust of wind, it lost 3.8 inches in height. How tall was the leading tower after the gust?
InternLM-Math Base 20B:
Reasoning: The tower was 52-3.8 = <<52-3.8=48.2>>48.2 inches tall. ### Answer: 48.2
Expected answer: 48.2000000000000
Correct? Yes
Problem: A doctor was monitoring a patient's temperature. At noon, the patient's temperature was 21.0°C. By 8 p.m., the temperature had fallen by 3.08°C. What was the patient's temperature at 8 p.m.?
InternLM-Math Base 20B:
Reasoning: The patient's temperature at 8 p.m. was 21.0-3.08 = <<21.0-3.08=17.92>>17.92°C. ### Answer: 17.92
Expected answer: 17.9200000000000
Correct? Yes
Problem: After the doctor had recorded the patient's temperature at 8 p.m., the patient was given some treatment which increased the temperature by 6.06°C. What was the patient's temperature after the treatment?
InternLM-Math Base 20B:
Reasoning: The patient's temperature after the treatment was 17.92+6.06 = <<17.92+6.06=24.98>>24.98°C. ### Answer: 24.98
Expected answer: 23.9800000000000
Correct? No
Problem: In the previous scenario, assume that the patient's original temperature at noon was 34°C instead of 21°C. If the temperature fell by the same amount, 3.08°C, by 8 p.m., what would the patient's temperature be at 8 p.m.?
InternLM-Math Base 20B:
Reasoning: The patient's temperature at 8 p.m. would be 34.0-3.08 = <<34.0-3.08=30.92>>30.92°C. ### Answer: 30.92
Expected answer: 30.9200000000000
Correct? Yes
Problem: A zoo has 75.0 monkeys in one enclosure and 72.9 monkeys in another. How many monkeys are there in total at the zoo?
InternLM-Math Base 20B:
Reasoning: 75.0+72.9 = <<75.0+72.9=147.9>>147.9 ### Answer: 147.9
Expected answer: 147.900000000000
Correct? Yes
Problem: You found out that there are 75.0 monkeys in one enclosure and 72.9 monkeys in another. However, later in the day, an additional 46.96 monkeys arrive at the zoo. After these monkeys join, how many monkeys are there in total at the zoo?
InternLM-Math Base 20B:
Reasoning: 75.0+72.9+46.96 = <<75.0+72.9+46.96=194.86>>194.86 ### Answer: 194.86
Expected answer: 194.860000000000
Correct? Yes
Problem: A wind farm generates 3081.8 MWh of energy that is distributed evenly among 38.0 cities. How much energy in MWh does each city receive from the wind farm?
InternLM-Math Base 20B:
Reasoning: 3081.8/38.0 = <<3081.8/38.0=81.1>>81.1 MWh of energy is distributed to each city. ### Answer: 81.1
Expected answer: 81.1000000000000
Correct? Yes
Problem: Following up on the energy distribution, if each of the cities decided to double their energy received from the wind farm, how much energy in MWh would each city receive now?
InternLM-Math Base 20B:
Reasoning: 2*81.1 = <<2*81.1=162.2>>162.2 MWh of energy is distributed to each city. ### Answer: 162.2
Expected answer: 162.200000000000
Correct? Yes
Problem: At a party, 22.12 people are in the living room and 63.1 people are in the dining room. How many people are at the party in total?
InternLM-Math Base 20B:
Reasoning: 22.12+63.1 = <<22.12+63.1=85.22>>85.22 ### Answer: 85.22
Expected answer: 85.2200000000000
Correct? Yes
Problem: A certain book weighs 68.0 grams. If a bookstore wants to stock up 52.01 copies of the same book, how many grams would that amount to?
InternLM-Math Base 20B:
Reasoning: 68.0 × 52.01 = <<68.0*52.01=3537.68>>3537.68 grams. ### Answer: 3537.68 grams
Expected answer: 3536.68000000000
Correct? No
Problem: A farmer has a particular breed of chicken that each weighs 41.92 kilograms on average. If the farmer has 11.1 chickens of this breed, what is the total weight in kilograms of these chickens?
InternLM-Math Base 20B:
Reasoning: 11.1 chickens weigh 41.92 kilograms on average. 11.1 chickens weigh 11.1 × 41.92 = <<11.1*41.92=462.912>>462.912 kilograms in total. ### Answer: 462.912
Expected answer: 465.312000000000
Correct? No
Problem: Princess Olivia has 120.54 meters of royal fabric. She decided to divide it equally to make dresses for her 29.4 favorite dolls. How many meters of fabric will each doll's dress receive?
InternLM-Math Base 20B:
Reasoning: Princess Olivia will divide 120.54 by 29.4. 120.54/29.4 = <<120.54/29.4=4.10>>4.10 ### Answer: 4.10
Expected answer: 4.10000000000000
Correct? Yes
Problem: Princess Olivia realized that she had another batch of fabric, but this time it was only 74 meters long. If she still wants to divide this batch equally for the dresses of her 29.4 dolls, how many meters of fabric will each doll's dress receive now?
InternLM-Math Base 20B:
Reasoning: Princess Olivia will divide 74 by 29.4. 74/29.4 = <<74/29.4=2.51>>2.51 ### Answer: 2.51
Expected answer: 2.51700680272109
Correct? Yes
Problem: A certain variety of fish weighs on average 86.7 kilograms. If a fisherman catches 30.4 of these fish, what is the total weight of his catch in kilograms?
InternLM-Math Base 20B:
Reasoning: 30.4 × 86.7 = <<30.4*86.7=2624.48>>2624.48 The total weight of the fisherman's catch is 2624.48 kilograms. ### Answer: 2624.48
Expected answer: 2635.68000000000
Correct? No
Problem: A superhero needs to rescue people from two locations. He needs to travel 56.6 miles to reach the first location and an additional 29.15 miles to reach the second location. How many miles does the superhero need to travel in total to reach both locations?
InternLM-Math Base 20B:
Reasoning: The superhero needs to travel 56.6+29.15 = <<56.6+29.15=85.75>>85.75 miles in total to reach both locations. ### Answer: 85.75
Expected answer: 85.7500000000000
Correct? Yes
Problem: The previous scenario mentioned that the superhero needs to travel 56.6 miles to reach the first location and then an additional 29.15 miles to reach the second location. However, suppose there is a new scenario where the distance to the second location is increased to 87 miles instead of 29.15 miles while the distance to first location remains the same. How many miles does the superhero need to travel in total to reach both locations in this new scenario?
InternLM-Math Base 20B:
Reasoning: The superhero needs to travel 56.6+87 = <<56.6+87=143.6>>143.6 miles in total to reach both locations in the new scenario. ### Answer: 143.6
Expected answer: 143.600000000000
Correct? Yes
Problem: A princess possesses 3054.4 precious gems which she wants to equally distribute amongst her 33.2 loyal knights. How many precious gems does each knight receive?
InternLM-Math Base 20B:
Reasoning: 3054.4/33.2 = <<3054.4/33.2=92>>92. Each knight receives 92 precious gems. ### Answer: 92
Expected answer: 92.0000000000000
Correct? Yes
Problem: Suppose the princess made another mistake and actually had to distribute the same total number of 3054.4 precious gems amongst not 33.2, but 76 knights instead. How many precious gems does each knight now receive?
InternLM-Math Base 20B:
Reasoning: 3054.4/76 = <<3054.4/76=40>>40. Each knight receives 40 precious gems. ### Answer: 40
Expected answer: 40.1894736842105
Correct? No
Problem: A jeweler uses 27.2 grams of gold to make each ring. If the jeweler plans to make 89.73 rings, how many grams of gold will be needed in total?
InternLM-Math Base 20B:
Reasoning: The jeweler needs 27.2 × 89.73 = <<27.2*89.73=2440.056>>2440.056 grams of gold in total. ### Answer: 2440.056
Expected answer: 2440.65600000000
Correct? No
Problem: A specific species of shark usually grows 3.2 feet longer each year. If a certain shark of this species has been alive for 89.57 years, how much total length has it gained since it was born?
InternLM-Math Base 20B:
Reasoning: The shark has gained 3.2 × 89.57 = <<3.2*89.57=1042.24>>1042.24 feet in length since it was born. ### Answer: 1042.24
Expected answer: 286.624000000000
Correct? No
Problem: In a playful snowball fight, Jason threw a snowball that went 50.23 meters before hitting the ground. However, it first had to travel past a tree that was 24.6 meters away. How much distance did the snowball cover past the tree before it hit the ground?
InternLM-Math Base 20B:
Reasoning: The snowball traveled 50.23-24.6 = <<50.23-24.6=25.63>>25.63 meters past the tree before it hit the ground. ### Answer: 25.63
Expected answer: 25.6300000000000
Correct? Yes
Problem: After hitting the ground, the snowball rolled an additional 4.4 meters. What was the total distance that the snowball travelled from Jason's hand to its final stopping point?
InternLM-Math Base 20B:
Reasoning: The snowball traveled 50.23+4.4 = <<50.23+4.4=54.63>>54.63 meters from Jason's hand to its final stopping point. ### Answer: 54.63
Expected answer: 30.0300000000000
Correct? No
Problem: Jason decided to have another snowball fight but this time the snowball went 78 meters before hitting the ground, still having to travel past the same tree that was 24.6 meters away. How much distance did the snowball cover past the tree before it hit the ground this time?
InternLM-Math Base 20B:
Reasoning: The snowball traveled 78-24.6 = <<78-24.6=53.4>>53.4 meters past the tree before it hit the ground. ### Answer: 53.4
Expected answer: 53.4000000000000
Correct? Yes
Problem: A beach ball manufacturer produces 3792.28 beach balls which are distributed equally amongst 45.2 beach stores. How many beach balls does each store receive?
InternLM-Math Base 20B:
Reasoning: 3792.28/45.2 = <<3792.28/45.2=83.8>>83.8 Each store receives 83.8 beach balls. ### Answer: 83.8
Expected answer: 83.9000000000000
Correct? Yes
Problem: If each of the beach stores received an additional shipment of beach balls equal to the amount they originally received, how many beach balls does each store now have in total?
InternLM-Math Base 20B:
Reasoning: 83.8+83.8 = <<83.8+83.8=167.6>>167.6 Each store now has 167.6 beach balls in total. ### Answer: 167.6
Expected answer: 167.800000000000
Correct? Yes
Problem: If the beach ball manufacturer had initially produced 3792.28 beach balls which were distributed equally amongst 48 beach stores instead of 45.2, how many beach balls would each store have received originally?
InternLM-Math Base 20B:
Reasoning: 3792.28/48 = <<3792.28/48=78.8>>78.8 Each store would have received 78.8 beach balls originally. ### Answer: 78.8
Expected answer: 79.0058333333333
Correct? No
Problem: A fishing company has caught 1303.12 pounds of fish, which they want to divide equally among 18.2 of their stores. How many pounds of fish will each store receive?
InternLM-Math Base 20B:
Reasoning: 1303.12/18.2 = <<1303.12/18.2=71.9>>71.9 Each store will receive 71.9 pounds of fish. ### Answer: 71.9
Expected answer: 71.6000000000000
Correct? Yes
Problem: Following the last question, suppose the fishing company initially caught 35 pounds of fish instead of 1303.12 pounds and it still had to be divided equally among 18.2 stores. How many pounds of fish will each store receive now?
InternLM-Math Base 20B:
Reasoning: 35/18.2 = <<35/18.2=1.9>>1.9 Each store will receive 1.9 pounds of fish. ### Answer: 1.9
Expected answer: 1.92307692307692
Correct? Yes
Problem: A luxurious watch brand has two different models. The first model weighs 68.7 grams, and the second one weighs 49.3 grams. What is the total weight of both watch models in grams?
InternLM-Math Base 20B:
Reasoning: The total weight of both watch models is 68.7+49.3 = <<68.7+49.3=118>>118 grams. ### Answer: 118
Expected answer: 118.000000000000
Correct? Yes
Problem: Following the previous question: If an artist decides to decorate each gram of both watch models with 75.6 milligrams of gold, how many milligrams of gold will he need in total to decorate all the watches?
InternLM-Math Base 20B:
Reasoning: The total weight of both watch models is 68.7+49.3 = <<68.7+49.3=118>>118 grams. The artist will need 118*75.6 = <<118*75.6=8860.8>>8860.8 milligrams of gold to decorate all the watches. ### Answer: 8860.8
Expected answer: 8920.80000000000
Correct? No
Problem: Following the previous question: If the first watch model actually weighed 68.7 grams and a second, lighter model only weighed 1 gram, what would be the total weight of both watch models in grams?
InternLM-Math Base 20B:
Reasoning: The total weight of both watch models is 68.7+1 = <<68.7+1=69.7>>69.7 grams. ### Answer: 69.7
Expected answer: 69.7000000000000
Correct? Yes
Problem: A snowman is built with a large base snowball that weighs 42.8 pounds and a smaller top snowball that weighs 6.3 pounds. How much does the snowman weigh in total?
InternLM-Math Base 20B:
Reasoning: 42.8+6.3 = <<42.8+6.3=49.1>>49.1 ### Answer: 49.1
Expected answer: 49.1000000000000
Correct? Yes
Problem: Given the total weight of the previously built snowman, an even larger snowman is to be made that is 91.92 times heavier than the first. How heavy is this new snowman?
InternLM-Math Base 20B:
Reasoning: 49.1*91.92 = <<49.1*91.92=4532.272>>4532.272 ### Answer: 4532.272
Expected answer: 4513.27200000000
Correct? No
Problem: Previously, a snowman was built with a base snowball that weighed 42.8 pounds and a top snowball that weighed 6.3 pounds. Now, consider a scenario where the top snowball is much larger and weighs 51 pounds instead. How much does the snowman weigh in this case?
InternLM-Math Base 20B:
Reasoning: 42.8+51 = <<42.8+51=93.8>>93.8 ### Answer: 93.8
Expected answer: 93.8000000000000
Correct? Yes
Problem: A factory produced 24.91 pencils per minute for a consecutive period of 46.98 minutes. How many pencils were produced in total?
InternLM-Math Base 20B:
Reasoning: 24.91 × 46.98 = <<24.91*46.98=1160.8118>>1160.8118 ### Answer: 1160.8118
Expected answer: 1170.27180000000
Correct? No
Problem: A farmer has 26.0 chickens, each laying 22.0 eggs. How many eggs in total do the chickens lay?
InternLM-Math Base 20B:
Reasoning: 26.0 * 22.0 = <<26.0*22.0=572.0>>572.0 ### Answer: 572.0
Expected answer: 572.000000000000
Correct? Yes
Problem: The farmer decides to sell the eggs in the market. Each egg sells for $10.11. How much money in total does the farmer earn from the sale of the eggs?
InternLM-Math Base 20B:
Reasoning: 572.0 * 10.11 = <<572.0*10.11=5785.92>>5785.92 ### Answer: 5785.92
Expected answer: 5782.92000000000
Correct? No
Problem: In a new scenario, the farmer has 26.0 chickens, but now, each chicken lays 49 eggs instead of 22. How many eggs in total do the chickens lay in this scenario?
InternLM-Math Base 20B:
Reasoning: 26.0 * 49.0 = <<26.0*49.0=1274.0>>1274.0 ### Answer: 1274.0
Expected answer: 1274.00000000000
Correct? Yes
Problem: A bus consumes 18.5 liters of fuel per trip. If the bus completes 62.38 trips, how many liters of fuel will it have consumed in total?
InternLM-Math Base 20B:
Reasoning: 18.5 × 62.38 = <<18.5*62.38=1152.13>>1152.13 The bus will have consumed 1152.13 liters of fuel in total. ### Answer: 1152.13
Expected answer: 1154.03000000000
Correct? No
Problem: A jacket costs $14.97 and a person wants to buy 5.9 jackets. What will be the total cost of the jackets?
InternLM-Math Base 20B:
Reasoning: 5.9 × 14.97 = <<5.9*14.97=88.423>>88.423 The total cost of the jackets is $88.423. ### Answer: $88.423
Expected answer: 88.3230000000000
Correct? No
Problem: A bookstore initially has 74.46 books. After selling some of them, only 52.19 books are left. How many books did the bookstore sell?
InternLM-Math Base 20B:
Reasoning: The bookstore sold 74.46-52.19 = <<74.46-52.19=22.27>>22.27 books. ### Answer: 22.27
Expected answer: 22.2700000000000
Correct? Yes
Problem: Given the same situation, suppose initially the bookstore actually had 74.46 books and they sold some books to a point where their stock was reduced to 57 books. How many books did the bookstore sell in this case?
InternLM-Math Base 20B:
Reasoning: The bookstore sold 74.46-57 = <<74.46-57=17.46>>17.46 books. ### Answer: 17.46
Expected answer: 17.4600000000000
Correct? Yes
Problem: A chair production company produces 95.0 chairs every day. If each chair uses 20.7 kilograms of wood, how many kilograms of wood does the company use in one day?
InternLM-Math Base 20B:
Reasoning: 95.0*20.7 = <<95.0*20.7=1966.5>>1966.5 The company uses 1966.5 kilograms of wood in one day. ### Answer: 1966.5
Expected answer: 1966.50000000000
Correct? Yes
Problem: Following up on the previous question, if the chair company managed to save 98.83 kilograms of wood after a day's production, how many kilograms of wood did they actually use in making the chairs?
InternLM-Math Base 20B:
Reasoning: 1966.5-98.83 = <<1966.5-98.83=1867.67>>1867.67 The company used 1867.67 kilograms of wood in making the chairs. ### Answer: 1867.67
Expected answer: 1867.67000000000
Correct? Yes
Problem: Following up on the original question, suppose the chair production company instead produces 32 chairs per day, still using the same 20.7 kilograms of wood per chair. How many kilograms of wood does the company use in this case?
InternLM-Math Base 20B:
Reasoning: 32*20.7 = <<32*20.7=661.4>>661.4 The company uses 661.4 kilograms of wood in one day. ### Answer: 661.4
Expected answer: 662.400000000000
Correct? No
Problem: A jeweler is creating a ring that combines two metals. The first metal weighs 63.2 grams and the second metal weighs 62.95 grams. How much will the ring weigh in grams when both metals are combined?
InternLM-Math Base 20B:
Reasoning: 63.2+62.95 = <<63.2+62.95=126.15>>126.15 ### Answer: 126.15
Expected answer: 126.150000000000
Correct? Yes
Problem: After creating the ring that combines two metals weighing 63.2 grams and 62.95 grams respectively, the jeweler decides to remove 41.42 grams of the material for fine-tuning the design. What would be the new weight of the ring in grams after this removal?
InternLM-Math Base 20B:
Reasoning: 126.15-41.42 = <<126.15-41.42=84.73>>84.73 ### Answer: 84.73
Expected answer: 84.7300000000000
Correct? Yes
Problem: In a modified design, the jeweler decides to use a different first metal that weighs 26 grams instead of 63.2 grams but keeps the second metal that weighs 62.95 grams. In this modified design, what will the new total weight of the ring be with the two metals combined?
InternLM-Math Base 20B:
Reasoning: 26+62.95 = <<26+62.95=88.95>>88.95 ### Answer: 88.95
Expected answer: 88.9500000000000
Correct? Yes
Problem: A star is 3480.66 light years away from Earth. If the star's light is seen from 36.6 different sighting points on Earth, what is the average distance in light years of the star from each sighting point?
InternLM-Math Base 20B:
Reasoning: The average distance of the star from each sighting point is 3480.66/36.6 = <<3480.66/36.6=95.2>>95.2 light years. ### Answer: 95.2
Expected answer: 95.1000000000000
Correct? Yes
Problem: A pizza place sold 84.3 pepperoni pizzas today. They also sold 47.9 more mushroom pizzas. How many pizzas did they sell in total today?
InternLM-Math Base 20B:
Reasoning: The pizza place sold 84.3+47.9 = <<84.3+47.9=132.2>>132.2 pizzas in total today. ### Answer: 132.2
Expected answer: 132.200000000000
Correct? Yes
Problem: In addition to the pizzas sold previously, the pizza place also sold 95.5 margherita pizzas today. Altogether, how many pizzas did they sell today?
InternLM-Math Base 20B:
Reasoning: The pizza place sold 132.2+95.5 = <<132.2+95.5=227.7>>227.7 pizzas in total today. ### Answer: 227.7
Expected answer: 227.700000000000
Correct? Yes
Problem: A castle has a height of 68.4 meters. If a scale model of this castle is made where 1 meter of the original castle corresponds to 27.69 mm of the model, how many millimeters tall will the model of the castle be?
InternLM-Math Base 20B:
Reasoning: The model of the castle will be 68.4/27.69 = <<68.4/27.69=2.47>>2.47 millimeters tall. ### Answer: 2.47
Expected answer: 1893.99600000000
Correct? No
Problem: A wizard has a collection of 17.7 magical ingredients. Recently, he found another spot that contained 34.1 magical items. How many magical ingredients does the wizard have in total now?
InternLM-Math Base 20B:
Reasoning: The wizard has 17.7+34.1 = <<17.7+34.1=51.8>>51.8 magical ingredients in total now. ### Answer: 51.8
Expected answer: 51.8000000000000
Correct? Yes
Problem: In the previous scenario, what if the wizard initially had only 17.7 magical items and he found a new spot that contained 83 magical items? How many magical items would the wizard have in total then?
InternLM-Math Base 20B:
Reasoning: The wizard has 17.7+83 = <<17.7+83=100.7>>100.7 magical ingredients in total then. ### Answer: 100.7
Expected answer: 100.700000000000
Correct? Yes
Problem: A fleet of camping tents has a combined weight of 1448.37 pounds. If there are 69.3 tents in this fleet, how much does each tent weigh in pounds?
InternLM-Math Base 20B:
Reasoning: 1448.37/69.3 = <<1448.37/69.3=20.8>>20.8 Each tent weighs 20.8 pounds. ### Answer: 20.8
Expected answer: 20.9000000000000
Correct? Yes
Problem: Following up on the previous question, the standard weight for this type of tent is set at 85.4 pounds. After working out the actual weight of each tent, how much do the tents differ from the standard weight?
InternLM-Math Base 20B:
Reasoning: 85.4-20.8 = <<85.4-20.8=64.6>>64.6 The tents differ from the standard weight by 64.6 pounds. ### Answer: 64.6
Expected answer: 64.5000000000000
Correct? Yes
Problem: Following up on the previous question, what if there were actually 45 tents in the fleet instead of 69.3? With the same total weight of 1448.37 pounds, how much would each tent weigh then?
InternLM-Math Base 20B:
Reasoning: 1448.37/45 = <<1448.37/45=32.18>>32.18 Each tent would weigh 32.18 pounds. ### Answer: 32.18
Expected answer: 32.1860000000000
Correct? Yes
Problem: A monkey collected 52.7 bananas in the morning and 88.17 bananas in the afternoon. How many bananas did the monkey collect in total?
InternLM-Math Base 20B:
Reasoning: The monkey collected 52.7+88.17 = <<52.7+88.17=140.87>>140.87 bananas in total. ### Answer: 140.87
Expected answer: 140.870000000000
Correct? Yes
Problem: Each bubble has a volume of 55.9 cubic centimeters. If a child blows 77.8 such bubbles, what would be the total volume of the bubbles in cubic centimeters?
InternLM-Math Base 20B:
Reasoning: 77.8 x 55.9 = <<77.8*55.9=4352.02>>4352.02 ### Answer: 4352.02
Expected answer: 4349.02000000000
Correct? No
Problem: A dinosaur eats 19.45 kilograms of vegetation every hour. If it eats for 48.71 hours straight without stopping, how many kilograms of vegetation will it have consumed in total?
InternLM-Math Base 20B:
Reasoning: The dinosaur eats 19.45 kilograms of vegetation every hour. It eats for 48.71 hours straight without stopping. So, it eats 19.45 × 48.71 = <<19.45*48.71=940.5495>>940.5495 kilograms of vegetation in total. ### Answer: 940.5495
Expected answer: 947.409500000000
Correct? No
Problem: A dragon has hoarded 65.4 kilograms of gold and 28.5 kilograms of gems. How much total weight has the dragon hoarded in kilograms?
InternLM-Math Base 20B:
Reasoning: 65.4+28.5 = <<65.4+28.5=93.9>>93.9 ### Answer: 93.9
Expected answer: 93.9000000000000
Correct? Yes
Problem: After the dragon has hoarded 65.4 kilograms of gold and 28.5 kilograms of gems, he decides to add some silver to his hoard. If the dragon's total hoard is decreased by 6.74 kilograms after adding the silver, what will be the new total weight of the dragon's hoard?
InternLM-Math Base 20B:
Reasoning: 65.4+28.5-6.74 = <<65.4+28.5-6.74=90.16>>90.16 ### Answer: 90.16
Expected answer: 87.1600000000000
Correct? No
Problem: Each teddy bear in a toy shop weighs 96.8 grams. If there are 93.3 teddy bears in the shop, what is the total weight of the teddy bears in grams?
InternLM-Math Base 20B:
Reasoning: 96.8 × 93.3 = <<96.8*93.3=9025.44>>9025.44 The total weight of the teddy bears is 9025.44 grams. ### Answer: 9025.44
Expected answer: 9031.44000000000
Correct? No
Problem: A UFO is found to travel 2.46 light years every month. How far, in light years, would the UFO have travelled after 3.5 months?
InternLM-Math Base 20B:
Reasoning: 2.46*3.5 = <<2.46*3.5=8.61>>8.61 light years. ### Answer: 8.61
Expected answer: 8.61000000000000
Correct? Yes
Problem: Following from the previous scenario, after travelling 2.46 light years every month for 3.5 months, the UFO then continued travelling for an additional 33.17 light years. How far did the UFO travel in total?
InternLM-Math Base 20B:
Reasoning: 2.46*3.5 + 33.17 = <<2.46*3.5+33.17=42.27>>42.27 light years. ### Answer: 42.27
Expected answer: 41.7800000000000
Correct? No
Problem: In the previous situation, the UFO was assumed to travel 2.46 light years every month for 3.5 months. Now assume that the UFO has instead been traveling at that speed for 68 months. How far in light years would the UFO have traveled this time?
InternLM-Math Base 20B:
Reasoning: 2.46*68 = <<2.46*68=170.28>>170.28 light years. ### Answer: 170.28
Expected answer: 167.280000000000
Correct? No
Problem: In a park, there is a rectangular field with an area of 36.82 square meters. If there are 57.5 such fields in the park, what is the total area, in square meters, of all these fields?
InternLM-Math Base 20B:
Reasoning: 36.82 × 57.5 = <<36.82*57.5=2108.15>>2108.15 The total area of all the fields is 2108.15 square meters. ### Answer: 2108.15
Expected answer: 2117.15000000000
Correct? No
Problem: A herd of giraffes collectively eats 2571.29 kilograms of leaves each day. If there are 38.9 giraffes in the herd, how many kilograms of leaves does each giraffe eat daily?
InternLM-Math Base 20B:
Reasoning: 2571.29/38.9 = <<2571.29/38.9=66.1>>66.1 kilograms of leaves does each giraffe eat daily. ### Answer: 66.1
Expected answer: 66.1000000000000
Correct? Yes
Problem: Following on from the previous problem, suppose the number of giraffes in the herd were halved to 19 instead of 38.9. Assuming the same total amount of leaf consumption as before (2571.29 kilograms), how many kilograms of leaves would each giraffe in this smaller herd consume daily?
InternLM-Math Base 20B:
Reasoning: 2571.29/19 = <<2571.29/19=135.9>>135.9 kilograms of leaves does each giraffe eat daily. ### Answer: 135.9
Expected answer: 135.331052631579
Correct? Yes
Problem: A unicorn needs 217.35 units of magic energy to teleport to another location. If one rainbow provides 20.7 units of magic energy, how many rainbows will it consume for the unicorn to teleport once?
InternLM-Math Base 20B:
Reasoning: 217.35/20.7 = <<217.35/20.7=10.5>>10.5 The unicorn will consume 11 rainbows to teleport once. ### Answer: 11
Expected answer: 10.5000000000000
Correct? No