Problem: If the dragon initially planned to fly 13 km in the day instead of 24.02 km, but still had to backtrack 1.3 km due to the severe storm, how many kilometers would the dragon have traveled then?

InternLM-Math Base 20B:

  Reasoning: The dragon would have traveled 13 - 1.3 = <<13-1.3=11.7>>11.7 km in the end.
### Answer: 11.7

Expected answer: 11.7000000000000

Correct? Yes

Problem: The elephant from the previous question then burns off 5.935 tons of weight. What is the elephant's weight now?

InternLM-Math Base 20B:

  Reasoning: 27.78-5.935 = <<27.78-5.935=21.845>>21.845
The elephant's weight now is 21.845 tons.
### Answer: 21.845

Expected answer: 21.8450000000000

Correct? Yes

Problem: Given the same situation, if the mouse initially tends to eat 27 grams of food, but on that particular day, it eats 4.62 grams less than its usual intake. How much food does it eat on that day?

InternLM-Math Base 20B:

  Reasoning: The mouse eats 27-4.62 = <<27-4.62=22.38>>22.38 grams of food on that day.
### Answer: 22.38

Expected answer: 22.3800000000000

Correct? Yes

Problem: In a zoo, there’s a baby giraffe that is 1.4 meters tall. If it grows another 5.7 meters, it will reach a certain height. Now, if this grown giraffe stretches its neck further and adds another 12.608 meters to its height, how tall will the giraffe be then?

InternLM-Math Base 20B:

  Reasoning: 1.4+5.7+12.608 = <<1.4+5.7+12.608=19.708>>19.708
### Answer: 19.708

Expected answer: 19.7080000000000

Correct? Yes

Problem: In another zoo, there is a full-grown giraffe that measures an impressive 23 meters. If the giraffe stretches its neck and grows another 5.7 meters, how tall will the giraffe be then?

InternLM-Math Base 20B:

  Reasoning: 23+5.7 = <<23+5.7=28.7>>28.7
### Answer: 28.7

Expected answer: 28.7000000000000

Correct? Yes

Problem: After generating an isotopic energy reading of 24.178 units for 1.0 second, the astronaut decides to boost his energy output by an additional 4.995 units. What is the new total amount of energy he generates?

InternLM-Math Base 20B:

  Reasoning: 24.178 + 4.995 = <<24.178+4.995=29.173>>29.173
The astronaut generates 29.173 units of energy in total.
### Answer: 29.173

Expected answer: 29.1730000000000

Correct? Yes

Problem: If instead of generating an isotopic energy reading of 24.178 units per second, the astronaut was initially generating 23 units per second for 1.0 second, what would the total energy output be then?

InternLM-Math Base 20B:

  Reasoning: 23 * 1.0 = <<23*1.0=23>>23
The astronaut generates 23 units of energy in total.
### Answer: 23

Expected answer: 23.0000000000000

Correct? Yes

Problem: After some recalculations, it was discovered that the treasure chest initially held 17 kilograms of gold instead of 25.84 kilograms. With 2.876 kilograms stolen, how much gold is left in the chest now?

InternLM-Math Base 20B:

  Reasoning: 17 - 2.876 = <<17-2.876=14.124>>14.124
### Answer: 14.124

Expected answer: 14.1240000000000

Correct? Yes

Problem: In addition to the previous question: The taller dog then bends over to pick up a toy, at which point its height decreases by 2.865 inches. How tall is the dog when it is bending over?

InternLM-Math Base 20B:

  Reasoning: The dog is 20.6-2.865 = <<20.6-2.865=17.735>>17.735 inches tall when it is bending over.
### Answer: 17.735

Expected answer: 17.7350000000000

Correct? Yes

Problem: If instead of growing 4.9 inches more, the different breed of dog only grew 1 inch more than the 15.7 inches tall dog, how tall would this different breed of dog be?

InternLM-Math Base 20B:

  Reasoning: The different breed of dog would be 15.7+1 = <<15.7+1=16.7>>16.7 inches tall.
### Answer: 16.7

Expected answer: 16.7000000000000

Correct? Yes

Problem: After a few hours, one of the firetrucks responds to a call and uses 15.7 gallons of its fuel. How many gallons of fuel are left across both firetrucks after this call?

InternLM-Math Base 20B:

  Reasoning: The firefighter added 9.03 gallons to the 9.155 gallons and 5.540 gallons of fuel.
The total amount of fuel in gallons after the firefighter refueled both trucks is 9.155+5.540+9.03 = <<9.155+5.540+9.03=23.725>>23.725 gallons.
### Answer: 23.725

Expected answer: 8.02500000000000

Correct? No

Problem: In a reassessment of the fuel levels, it was determined that one of the firetrucks originally had 8 gallons of fuel instead of 9.155 gallons. Keeping everything else constant, what would have been the total amount of fuel in gallons after the firefighter refueled both trucks in this case?

InternLM-Math Base 20B:

  Reasoning: The firefighter added 9.03 gallons to the 8 gallons and 5.540 gallons of fuel.
The total amount of fuel in gallons after the firefighter refueled both trucks is 8+5.540+9.03 = <<8+5.540+9.03=22.57>>22.57 gallons.
### Answer: 22.57

Expected answer: 22.5700000000000

Correct? Yes

Problem: After buying the discounted candle, Helen realized she had a coupon that subtracts another $8.49 from her total payment. How much is the final price she has to pay for the candle after applying the coupon?

InternLM-Math Base 20B:

  Reasoning: The final price Helen has to pay for the candle is $14.754 - $8.49 = <<14.754-8.49=6.264>>$6.264.
### Answer: $6.264

Expected answer: 6.26400000000000

Correct? Yes

Problem: Recalling the previous scenario, let's imagine that initially, the scented candle was priced at $18.77, but today it's on a bigger discount of $9 instead of $4.016. What would be the current price of the scented candle with the bigger discount?

InternLM-Math Base 20B:

  Reasoning: The current price of the scented candle is $18.77 - $9 = <<18.77-9=9.77>>$9.77.
### Answer: $9.77

Expected answer: 9.77000000000000

Correct? Yes

Problem: Upon reevaluating the forest trails, it was found that the length of the southern trails was actually 11km instead of 7.4km. Keeping the length of the northern trails and the total distance of all trails the same, how many kilometres of trails are not part of the northern or southern trails now?

InternLM-Math Base 20B:

  Reasoning: 3.9+11 = <<3.9+11=14.9>>14.9km of trails are part of the northern or southern trails.
17.9-14.9 = <<17.9-14.9=3>>3km of trails are not part of the northern or southern trails.
### Answer: 3

Expected answer: 3.00000000000000

Correct? Yes

Problem: Previously, the baby's weight increased by 15.67 pounds a few weeks after birth. Suppose instead, the baby gained 11 pounds after a few weeks. The baby's weight still increased by 6.5 pounds a few months later. What would be the baby's weight now in this scenario?

InternLM-Math Base 20B:

  Reasoning: The baby's weight increased by 11 pounds after a few weeks.
The baby's weight increased again by 6.5 pounds a few months later.
The baby's weight increased by 11+6.5 = <<11+6.5=17.5>>17.5 pounds in total.
The baby's weight now is 4.8+17.5 = <<4.8+17.5=22.3>>22.3 pounds.
### Answer: 22.3

Expected answer: 22.3000000000000

Correct? Yes

Problem: With further calibration, Astronomer Tom realized the eyepiece only extends the telescope's focal length by an additional 2 centimeters, instead of the previous 1.832 centimeters. Considering this, what would be the new total focal length of his telescope?

InternLM-Math Base 20B:

  Reasoning: The total length of the telescope is 22.5+2 = <<22.5+2=24.5>>24.5 centimeters.
### Answer: 24.5

Expected answer: 24.5000000000000

Correct? Yes

Problem: After installing the window, the builder realizes he made an error and the opening for the window is actually 13.48 inches smaller than the total width of the window including the frame. What is the excess length of the window that couldn't fit into the opening?

InternLM-Math Base 20B:

  Reasoning: The excess length of the window is 19.4-13.48 = <<19.4-13.48=5.92>>5.92 inches.
### Answer: 5.92

Expected answer: 5.92000000000000

Correct? Yes

Problem: Suppose the builder made a new window, this time with a width of 28 inches, plus an additional length of 1.5 inches for the frame, how long is the window including the frame this time?

InternLM-Math Base 20B:

  Reasoning: The total width of the window is 28+1.5 = <<28+1.5=29.5>>29.5 inches.
### Answer: 29.5

Expected answer: 29.5000000000000

Correct? Yes

Problem: Suppose instead of starting with 5.1ml of ink in your pen, you started with 2ml of ink and then added 22.4ml of ink. How much ink does your pen have in total now?

InternLM-Math Base 20B:

  Reasoning: 2+22.4 = <<2+22.4=24.4>>24.4
### Answer: 24.4

Expected answer: 24.4000000000000

Correct? Yes

Problem: Having considered the paragraph with 12.244 words, let's say that instead, a paragraph contains 7 words. If we add these words to a similar paragraph, then how many words do the two paragraphs have in total?

InternLM-Math Base 20B:

  Reasoning: 7+7 = <<7+7=14>>14
### Answer: 14

Expected answer: 14

Correct? Yes

Problem: Following the previous scenario, imagine if the participant had initially written 29.82 pages, but this time he decided to reduce it down to 28 pages. How many pages did he have to exclude from his letter in this scenario?

InternLM-Math Base 20B:

  Reasoning: The participant had to exclude 29.82-28 = <<29.82-28=1.82>>1.82 pages from his letter.
### Answer: 1.82

Expected answer: 1.82000000000000

Correct? Yes

Problem: In addition to the lion's new weight, a baby lion weighs 16.97 pounds. What is the total weight of both the lion and the baby lion?

InternLM-Math Base 20B:

  Reasoning: The total weight of both the lion and the baby lion is 9.84+16.97 = <<9.84+16.97=26.81>>26.81 pounds.
### Answer: 26.81

Expected answer: 26.8100000000000

Correct? Yes

Problem: In the previous scenario, if the lion initially weighed 28.32 pounds but loses 14 pounds instead, and still gains 3.4 pounds afterwards, what would be the lion's new weight then?

InternLM-Math Base 20B:

  Reasoning: The lion's new weight is 28.32-14+3.4 = <<28.32-14+3.4=17.72>>17.72 pounds.
### Answer: 17.72

Expected answer: 17.7200000000000

Correct? Yes

Problem: Continuing from the last scenario: After the increase in the daily rainfall today, an additional 4.51 inches of rain fell tonight. How much total rainfall was there today in inches?

InternLM-Math Base 20B:

  Reasoning: 7.386+4.51 = <<7.386+4.51=11.896>>11.896
### Answer: 11.896

Expected answer: 11.8960000000000

Correct? Yes

Problem: In addition to the glasses and the special case, the eye checkup costs $3.0. How much would it cost in total to have an eye checkup, buy the glasses and special case together?

InternLM-Math Base 20B:

  Reasoning: The cost of the eye checkup, the glasses and the case together is $3.0+17.02 = <<3.0+17.02=20.02>>20.02.
### Answer: 20.02

Expected answer: 20.0200000000000

Correct? Yes

Problem: Suppose that a different pair of glasses costs $25, but the special sturdy case still costs an additional $2.22. How much will it cost in total to buy this new pair of glasses and the case together?

InternLM-Math Base 20B:

  Reasoning: The cost of the new pair of glasses and the case together is $25+$2.22 = <<25+2.22=27.22>>27.22.
### Answer: 27.22

Expected answer: 27.2200000000000

Correct? Yes

Problem: After finding the sale price of the roller skate, let's say that you also decide to purchase a special set of roller skate guards that cost $3.53. How much would you need to pay in total for the discounted roller skate and the set of roller skate guards?

InternLM-Math Base 20B:

  Reasoning: The total cost of the roller skate and the set of roller skate guards is 9.831+3.53 = <<9.831+3.53=13.361>>13.361.
### Answer: 13.361

Expected answer: 13.3610000000000

Correct? Yes

Problem: Let's consider a different scenario for the roller skate sale. If the discount on the roller skate was instead $6 from its original price of $17.9, how much would the roller skate cost after this new discount?

InternLM-Math Base 20B:

  Reasoning: The new sale price of the roller skate is 17.9-6 = <<17.9-6=11.9>>11.9.
### Answer: 11.9

Expected answer: 11.9000000000000

Correct? Yes

Problem: Continuing from the previous scenario, think about what would happen if each person at the campfire gathering used only 1 kg of firewood instead of 1.217 kg. With 18.89 people, how much firewood will be used in total now?

InternLM-Math Base 20B:

  Reasoning: 1 × 18.89 = <<1*18.89=18.89>>18.89
Approximately 18.89 kg of firewood will be used in total.
### Answer: 18.89

Expected answer: 18.8900000000000

Correct? Yes

Problem: Following the previous question, if you were to consume another marshmallow containing 10.045 grams of sugar, along with the big and small marshmallow, what would be the total grams of sugar you would consume?

InternLM-Math Base 20B:

  Reasoning: 6.1+4.64+10.045 = <<6.1+4.64+10.045=20.185>>20.185
### Answer: 20.185

Expected answer: 20.7850000000000

Correct? No

Problem: Following the previous question, if the amount of sugar in the big marshmallow was actually 6.1 grams and the small marshmallow contained only 2 grams of sugar, what would be the total grams of sugar you would consume from both marshmallows?

InternLM-Math Base 20B:

  Reasoning: 6.1+2 = <<6.1+2=8.1>>8.1
### Answer: 8.1

Expected answer: 8.10000000000000

Correct? Yes

Problem: Continuing from the previous question, if the resulting weight is translated to Newtons by multiplying each kilogram by 17.5, what will be the total weight in Newtons of the toy car and robot after the discount?

InternLM-Math Base 20B:

  Reasoning: 1.185*17.5 = <<1.185*17.5=20.7375>>20.7375
### Answer: 20.7375

Expected answer: 20.7375000000000

Correct? Yes

Problem: In the previous question, suppose the weight of the toy robot was actually 21 kilograms instead of 2.7 kilograms. After taking into account the 9.526 kilograms discount, what would be the new combined weight of the toy car and robot?

InternLM-Math Base 20B:

  Reasoning: 8.011+21 = <<8.011+21=29.011>>29.011
29.011-9.526 = <<29.011-9.526=19.485>>19.485
### Answer: 19.485

Expected answer: 19.4850000000000

Correct? Yes

Problem: After the remarkable display, it was noticed that the dolphin only returned 9.8 feet back to the water level. What was the remaining distance the dolphin covered in mid-air?

InternLM-Math Base 20B:

  Reasoning: The dolphin covered 21.284-9.8 = <<21.284-9.8=11.484>>11.484 feet in mid-air.
### Answer: 11.484

Expected answer: 11.4840000000000

Correct? Yes

Problem: In another remarkable leap, instead of rising an additional 11.484 feet, the dolphin soared an extra 20 feet above the initial 9.8 feet. What is the total distance the dolphin covered in this jump?

InternLM-Math Base 20B:

  Reasoning: The dolphin leaps 9.8+20 = <<9.8+20=29.8>>29.8 feet.
### Answer: 29.8

Expected answer: 29.8000000000000

Correct? Yes

Problem: In the previous scenario, let's reconsider the amount of water initially in the bottle. Imagine instead that the water bottle initially held 7.55 liters, but you only added 4 liters more. Now, how many liters of water are in the bottle?

InternLM-Math Base 20B:

  Reasoning: 7.55+4 = <<7.55+4=11.55>>11.55
### Answer: 11.55

Expected answer: 11.5500000000000

Correct? Yes

Problem: After purchasing the upgraded computer model, the buyer realizes that he has a voucher which gives a $17.29 discount on his next purchase. How much will the final cost of his purchase be after applying the voucher?

InternLM-Math Base 20B:

  Reasoning: The final cost of the purchase is $26.88-$17.29 = <<26.88-17.29=9.59>>9.59.
### Answer: 9.59

Expected answer: 9.59000000000000

Correct? Yes

Problem: Instead of the original computer model costing $20.7, consider if the computer model costs only $4. With the same upgrade cost of $6.18, what would be the total cost for the upgraded computer model now?

InternLM-Math Base 20B:

  Reasoning: The total cost for the upgraded computer model is $4+$6.18 = <<4+6.18=10.18>>10.18.
### Answer: 10.18

Expected answer: 10.1800000000000

Correct? Yes

Problem: After the adjustments mentioned in the previous problem, the teddy bear is then placed in a box which weighs 2.55 grams less than the teddy bear's total weight. What does the box weigh?

InternLM-Math Base 20B:

  Reasoning: The box weighs 2.55 grams less than the teddy bear's total weight. The box weighs 26.72-2.55 = <<26.72-2.55=24.17>>24.17 grams.
### Answer: 24.17

Expected answer: 24.1700000000000

Correct? Yes

Problem: Suppose the blanket initially had a temperature of 12°C instead of 17.8°C before it dropped to 7.24°C. How many degrees Celsius does the temperature of the blanket drop by now?

InternLM-Math Base 20B:

  Reasoning: The temperature of the blanket drops by 12-7.24 = <<12-7.24=4.76>>4.76°C.
### Answer: 4.76

Expected answer: 4.76000000000000

Correct? Yes

Problem: After paying for the discounted jacket, how much money did you actually save from the original price?

InternLM-Math Base 20B:

  Reasoning: You saved $13.3 - $8.329 = <<13.3-8.329=4.971>>4.971.
### Answer: 4.971

Expected answer: 4.97100000000000

Correct? Yes

Problem: Suppose instead of the original price being $13.3, the jacket initially costs $30, how much would the jacket cost after applying the same discount of $4.971?

InternLM-Math Base 20B:

  Reasoning: The cost of the jacket after the discount is $30 - $4.971 = <<30-4.971=25.029>>25.029.
### Answer: 25.029

Expected answer: 25.0290000000000

Correct? Yes

Problem: Considering the same scenario as before, but suppose the distance from the earth to the sun is now 18 million miles instead of 26.6 million miles. With the spacecraft still having traveled 15.818 million miles, how much further does it need to go? If it still needs to stop at a station that is 10.5 million miles away from its current position, what is the new total distance the spacecraft has to travel? And if it still has to detour another 4.27 million miles because of space debris, what will be the new final total distance the spacecraft has to travel to reach the sun?

InternLM-Math Base 20B:

  Reasoning: The spacecraft has to travel 18-15.818 = <<18-15.818=2.182>>2.182 million miles to reach the sun.
The spacecraft has to travel 2.182+10.5 = <<2.182+10.5=12.682>>12.682 million miles to reach the sun after the stop.
The spacecraft has to travel 12.682+4.27 = <<12.682+4.27=16.952>>16.952 million miles to reach the sun after the detour.
### Answer: 16.952

Expected answer: 16.9520000000000

Correct? Yes

Problem: Following up on the previous problem, suppose that after production, the company found that the Type A erasers are having an excess weight amounting to 1.49 grams which needs to be trimmed off each eraser. What will then be the new combined weight of one Type A and Type B eraser after the excess weight from Type A is trimmed off?

InternLM-Math Base 20B:

  Reasoning: The new weight of one Type A eraser is 12.2-1.49 = <<12.2-1.49=10.71>>10.71 grams. The new combined weight of one Type A and Type B eraser is 10.71+15.0 = <<10.71+15.0=25.71>>25.71 grams.
### Answer: 25.71

Expected answer: 25.7100000000000

Correct? Yes

Problem: Considering the previous scenario, what will be the total weight if, instead of a type A eraser, the company decides to pair two Type B erasers, each weighing 15 grams?

InternLM-Math Base 20B:

  Reasoning: The total weight of two Type B erasers is 15.0+15.0 = <<15.0+15.0=30.0>>30.0 grams.
### Answer: 30.0

Expected answer: 30.0000000000000

Correct? Yes

Problem: After preparing the hot chocolate mix with 11.07 grams of chocolate mix and 18.213 grams of sugar, a barista decides to remove 13.93 grams of the mix to make it less sweet. How many grams are left in the hot chocolate mix now?

InternLM-Math Base 20B:

  Reasoning: 11.07+18.213-13.93 = <<11.07+18.213-13.93=24.29>>24.29
### Answer: 24.29

Expected answer: 15.3530000000000

Correct? No

Problem: If instead of 11.07 grams of chocolate mix, the coffee shop decides to add only 2 grams of chocolate mix to the 18.213 grams of sugar, how many grams would there be in total in the hot chocolate mix?

InternLM-Math Base 20B:

  Reasoning: 2+18.213 = <<2+18.213=20.213>>20.213
### Answer: 20.213

Expected answer: 20.2130000000000

Correct? Yes

Problem: In the same bookstore, there were originally 25 books instead of 16.551. After selling the same number of books in the morning and afternoon as before (2.8 and 7.268), how many books would now be left in the bookstore?

InternLM-Math Base 20B:

  Reasoning: In the same bookstore, there were originally 25 books instead of 16.551. After selling the same number of books in the morning and afternoon as before (2.8 and 7.268), the bookstore sold 2.8+7.268 = <<2.8+7.268=10.068>>10.068 books in total. The bookstore has 25-10.068 = <<25-10.068=14.932>>14.932 books left.
### Answer: 14.932

Expected answer: 14.9320000000000

Correct? Yes

Problem: A baby's birth weight is typically around 18.4 ounces. If a particular baby gains 6.97 ounces more than this average weight during the first month, what is the baby's weight then? If this baby then loses 21.754 ounces, what will be the baby's new weight?

InternLM-Math Base 20B:

  Reasoning: The baby's weight is 18.4+6.97 = <<18.4+6.97=25.37>>25.37 ounces.
### Answer: 25.37

Expected answer: 3.61600000000000

Correct? No

Problem: A baby's birth weight is typically around 18.4 ounces. If a particular baby gains 7 ounces more than the average weight during the first month rather than the previous 6.97 ounces scenario, what is the baby's new weight then?

InternLM-Math Base 20B:

  Reasoning: The baby's weight is 18.4+7 = <<18.4+7=25.4>>25.4 ounces.
### Answer: 25.4

Expected answer: 25.4000000000000

Correct? Yes

Problem: In addition to the first eraser, Carl buys an identical eraser. Calculate the total surface area of the two erasers together.

InternLM-Math Base 20B:

  Reasoning: The total surface area of the two erasers is 2*9.38 = <<2*9.38=18.76>>18.76 cm^2.
### Answer: 18.76

Expected answer: 18.7600000000000

Correct? Yes

Problem: Suppose the original eraser is actually 1.4 cm long but 18 cm wide instead. What would be the new surface area of this eraser?

InternLM-Math Base 20B:

  Reasoning: The surface area of the eraser is 1.4*18 = <<1.4*18=25.2>>25.2 cm^2.
### Answer: 25.2

Expected answer: 25.2000000000000

Correct? Yes

Problem: In addition to the cost of the skirt's fabric and workmanship which was $3.935 and $6.78 respectively, there was an extra cost for specific design elements of $1.803. What is the total cost of the skirt now?

InternLM-Math Base 20B:

  Reasoning: The total cost for the skirt is $3.935+$6.78+$1.803 = <<3.935+6.78+1.803=12.518>>$12.518.
### Answer: $12.518

Expected answer: 12.5180000000000

Correct? Yes

Problem: If instead of $6.78, the cost of the workmanship for the skirt was $25 while the cost of the fabric remained at $3.935, what would be the total cost for the skirt?

InternLM-Math Base 20B:

  Reasoning: The total cost for the skirt is $3.935+$25 = <<3.935+25=28.935>>$28.935.
### Answer: $28.935

Expected answer: 28.9350000000000

Correct? Yes

Problem: Considering the price of the top and bottom combo of the dress set, if a customer also decides to buy a matching coat priced at $17.58 to complete her outfit, what is the total cost of her purchase?

InternLM-Math Base 20B:

  Reasoning: The total cost of her purchase is $11.4+$17.58 = <<11.4+17.58=28.98>>$28.98.
### Answer: 28.98

Expected answer: 28.9800000000000

Correct? Yes

Problem: If the price of the top part of the dress set is actually $3 instead of $5.9, and the bottom still costs $5.5, what would be the new total price of the dress set?

InternLM-Math Base 20B:

  Reasoning: The new total price of the dress set is $3+$5.5 = <<3+5.5=8.5>>$8.5.
### Answer: 8.5

Expected answer: 8.50000000000000

Correct? Yes

Problem: Following the previous question, what if the treasure chest originally had 14 gold coins instead of 22.83 gold coins? After spending 10.198 coins on a new pirate map, how many gold coins would Captain Jack have left?

InternLM-Math Base 20B:

  Reasoning: Captain Jack has 14-10.198 = <<14-10.198=3.802>>3.802 gold coins left.
### Answer: 3.802

Expected answer: 3.80200000000000

Correct? Yes

Problem: After realizing that Princess Mia's gemstones have been partially stolen, her loyal subjects present her with an additional gemstone weighing 6.5 grams as a gift to help make up for her loss. How many grams of gemstones does Princess Mia have now after receiving this gift?

InternLM-Math Base 20B:

  Reasoning: Princess Mia has 3.917 grams of gemstones left after the goblin's mischievous act.

She receives a gift of an additional gemstone weighing 6.5 grams. So, Princess Mia now has 3.917 + 6.5 = <<3.917+6.5=10.417>>10.417 grams of gemstones.

### Answer: 10.417

Expected answer: 10.4170000000000

Correct? Yes

Problem: Suppose that instead of the goblin stealing 9.483 grams of gemstones, he was only able to steal 7 grams worth of gemstones. In that case, how many grams of gemstones would Princess Mia have then?

InternLM-Math Base 20B:

  Reasoning: Princess Mia has 2 gemstones, each weighing 6.7 grams. So, she has 2*6.7 = <<2*6.7=13.4>>13.4 grams of gemstones in total.

The goblin steals 7 grams of gemstones. So, Princess Mia has 13.4 - 7 = <<13.4-7=6.4>>6.4 grams of gemstones left.

### Answer: 6.4

Expected answer: 6.40000000000000

Correct? Yes

Problem: After feeding the lion, the zookeepers realize that a delivery of an additional 6.91 kilograms of food has arrived. What is the total amount of food for the animals in the zoo after the additional food delivery?

InternLM-Math Base 20B:

  Reasoning: 17.8+6.91 = <<17.8+6.91=24.71>>24.71
### Answer: 24.71

Expected answer: 24.7100000000000

Correct? Yes

Problem: Earlier, the zoo had 23 kilograms of food for the animals, but they fed 5.0 kilograms of it to the lion. Now, how much food is left in the zoo after feeding the lion under these new circumstances?

InternLM-Math Base 20B:

  Reasoning: 23-5.0 = <<23-5.0=18>>18
### Answer: 18

Expected answer: 18.0000000000000

Correct? Yes

Problem: After Linda noticed the discount and purchased the favorite doll, she also found a cute dress for the doll that costs $10.52. How much will Linda spend in total for the doll and the dress?

InternLM-Math Base 20B:

  Reasoning: Linda will spend $10.22 + $10.52 = <<10.22+10.52=20.74>>$20.74 in total for the doll and the dress.
### Answer: $20.74

Expected answer: 20.7400000000000

Correct? Yes

Problem: Let's consider a new pair of pants. Initially, this pair has a length of 11 inches. An extra material of 7.7 inches is added for adjustments, similar to the previous pair. Then, again, an additional cloth of 6.757 inches is added for the design. What is the overall length of this new pair of pants including the adjustments and design?

InternLM-Math Base 20B:

  Reasoning: The length of the pants is 11+7.7+6.757 = <<11+7.7+6.757=25.457>>25.457 inches.
### Answer: 25.457

Expected answer: 25.4570000000000

Correct? Yes

Problem: Given that the bed of a small truck is 2.06 meters long and 1.32 meters wide, and the additional space outside the truck bed for placing items is 5.1 square meters, what is the total area available for placing items in square meters?

InternLM-Math Base 20B:

  Reasoning: The total area available for placing items is 2.7192 + 5.1 = <<2.7192+5.1=7.8192>>7.8192 square meters.
### Answer: 7.8192

Expected answer: 7.81920000000000

Correct? Yes

Problem: After his second jump, the monkey ate some bananas and his strength increased, making him able to jump 5.1 meters less than his previous combined heights. How high is the new jump?

InternLM-Math Base 20B:

  Reasoning: The monkey jumps 12.627-5.1 = <<12.627-5.1=7.527>>7.527 meters.
### Answer: 7.527

Expected answer: 7.52700000000000

Correct? Yes

Problem: After some rest, the energetic monkey did another jump which was 1.627 meters high. The monkey's second jump this time was only 7 meters further than first jump. How high in total did the monkey jump in these two jumps?

InternLM-Math Base 20B:

  Reasoning: The monkey jumps 1.627+7.0 = <<1.627+7.0=8.627>>8.627 meters altogether.
### Answer: 8.627

Expected answer: 8.62700000000000

Correct? Yes

Problem: In addition to the pens, John also bought a notebook for $4.7. How much total did John spend on the pens and the notebook?

InternLM-Math Base 20B:

  Reasoning: John spent $1.112 + $4.7 = <<1.112+4.7=5.812>>$5.812 on the pens and the notebook.
### Answer: 5.812

Expected answer: 5.81200000000000

Correct? Yes

Problem: Following the previous problem, if the total weight of the strawberry and the apple is subtracted by the weight of a small blueberry that weighs 2.22g, what is the net weight of the remaining apple and strawberry?

InternLM-Math Base 20B:

  Reasoning: 26.969-2.22 = <<26.969-2.22=24.749>>24.749
### Answer: 24.749

Expected answer: 24.7490000000000

Correct? Yes

Problem: Following on from the previous problems, suppose the weight of the strawberry is still 23.21g, but instead of an apple, now a cherry of 2g is added to the strawberry. What is the total weight of the strawberry and cherry combined?

InternLM-Math Base 20B:

  Reasoning: 23.21+2 = <<23.21+2=25.21>>25.21
### Answer: 25.21

Expected answer: 25.2100000000000

Correct? Yes

Problem: Following your previous purchases, you found a desirable mousepad that costs $5.10 less than the cost of the gaming accessory you acquired. How much does the mousepad cost?

InternLM-Math Base 20B:

  Reasoning: The mousepad costs $28.56-5.10 = <<28.56-5.10=23.46>>$23.46.
### Answer: 23.46

Expected answer: 23.4600000000000

Correct? Yes

Problem: Suppose instead of the gaming accessory that was $16.99 more expensive than the gaming mouse, you saw another accessory that was $13 more expensive than the gaming mouse. How much does this new accessory cost?

InternLM-Math Base 20B:

  Reasoning: The new accessory cost $11.57+13 = <<11.57+13=24.57>>$24.57.
### Answer: 24.57

Expected answer: 24.5700000000000

Correct? Yes

Problem: Following the previous problem, if you then applied a coupon worth $17.79 to your purchase, how much money would you need to buy the full set then?

InternLM-Math Base 20B:

  Reasoning: The full set will cost 29.057-17.79 = <<29.057-17.79=11.267>>11.267 dollars.
### Answer: 11.267

Expected answer: 11.2670000000000

Correct? Yes

Problem: Considering the previous scenario, what would be the price of the full set if the pen only cost $6 instead of $18.33?

InternLM-Math Base 20B:

  Reasoning: The full set will cost 6+10.727 = <<6+10.727=16.727>>16.727 dollars.
### Answer: 16.727

Expected answer: 16.7270000000000

Correct? Yes

Problem: The zookeeper needs to add 7.71 kilograms of fruits and vegetables to the elephant's diet after its two meals. How many kilograms of food in total does the elephant eat including the two meals and the added fruits and vegetables?

InternLM-Math Base 20B:

  Reasoning: The elephant eats 8.72+7.71 = <<8.72+7.71=16.43>>16.43 kilograms of food in total.
### Answer: 16.43

Expected answer: 16.4300000000000

Correct? Yes

Problem: Instead of the 4.36 kilograms of food at each meal, what if the zoo had to feed the elephant 8 kilograms of food at each meal? How many kilograms of food would the elephant eat in total over two meals?

InternLM-Math Base 20B:

  Reasoning: The elephant eats 8+8 = <<8+8=16>>16 kilograms of food in total.
### Answer: 16

Expected answer: 16

Correct? Yes

Problem: In the previous scenario, let's say the packaging factor now changes to 3 times the weight of the stuffed animal which is still 1.2 pounds. If the transportation fee is still $4.67 per pound, what now is the total transportation fee for this stuffed animal?

InternLM-Math Base 20B:

  Reasoning: The new weight is 1.2 × 3 = <<1.2*3=3.6>>3.6 pounds.
The total transportation fee is 3.6 × 4.67 = <<3.6*4.67=16.9>>16.9 dollars.
### Answer: 16.9

Expected answer: 16.8120000000000

Correct? Yes

Problem: At the campfire, suppose James gathered 6 kilograms of firewood instead of 12.291 kilograms, while Ruby still brought in 6.48 kilograms of firewood. Now, what would be the total weight of the firewood?

InternLM-Math Base 20B:

  Reasoning: 6+6.48 = <<6+6.48=12.48>>12.48
### Answer: 12.48

Expected answer: 12.4800000000000

Correct? Yes

Problem: After the initial movement, the compass reads another directional shift this time 18.1 degrees to the west. What would be the final directional reading after this shift?

InternLM-Math Base 20B:

  Reasoning: The final direction is 21.56-18.1 = <<21.56-18.1=3.46>>3.46 degrees.
### Answer: 3.46

Expected answer: 3.46000000000000

Correct? Yes

Problem: The compass originally pointed 10 degrees east, but then it shifted an additional 17.56 degrees further. What will be the compass's new direction in degrees after this additional shift?

InternLM-Math Base 20B:

  Reasoning: The compass's new direction is 10+17.56 = <<10+17.56=27.56>>27.56 degrees.
### Answer: 27.56

Expected answer: 27.5600000000000

Correct? Yes

Problem: The cake shop offers a special discount of $3.327 on the total cost. How much do you have to pay after applying the discount?

InternLM-Math Base 20B:

  Reasoning: The total cost is $20.87-$3.327 = <<20.87-3.327=17.543>>$17.543.
### Answer: $17.543

Expected answer: 17.5430000000000

Correct? Yes

Problem: Suppose the cake's price was increased to $19 due to additional decorations. How much is the total cost, together with the pack of candles worth $3.57?

InternLM-Math Base 20B:

  Reasoning: The total cost is $19+$3.57 = <<19+3.57=22.57>>$22.57.
### Answer: $22.57

Expected answer: 22.5700000000000

Correct? Yes

Problem: After buying the sleeping bag, it shrunk slightly in the wash, reducing both the length and the width by a total of 1.464 feet. What is the new combined length and width of the sleeping bag after washing?

InternLM-Math Base 20B:

  Reasoning: 23.15-1.464 = <<23.15-1.464=21.686>>21.686
### Answer: 21.686

Expected answer: 21.6860000000000

Correct? Yes

Problem: After the wash, you realize the width of the sleeping bag is not 10.95 feet but originally it was 8 feet. Now, what is the new total of the sleeping bag's length and width?

InternLM-Math Base 20B:

  Reasoning: 12.2+8 = <<12.2+8=20.2>>20.2
### Answer: 20.2

Expected answer: 20.2000000000000

Correct? Yes

Problem: Following his hike, Joe then visits a natural spring where he adds 7.9 liters of fresh water to his water jug. How much water does he have in his jug now?

InternLM-Math Base 20B:

  Reasoning: Joe has 7.59+7.9 = <<7.59+7.9=15.49>>15.49 liters of water in his water jug.
### Answer: 15.49

Expected answer: 15.4900000000000

Correct? Yes

Problem: What if, instead of drinking 11.2 liters of water each day, Joe only drank 9 liters a day? After hiking for 2 days, how much water would be left from his 29.99-liter water jug?

InternLM-Math Base 20B:

  Reasoning: Joe drinks 9+9 = <<9+9=18>>18 liters of water in 2 days.
Joe drinks 29.99-18 = <<29.99-18=11.99>>11.99 liters of water from the water jug.
### Answer: 11.99

Expected answer: 11.9900000000000

Correct? Yes

Problem: After applying the discount to the pillow, you decide to purchase an additional cushion cover that costs $3.91. How much will the total cost be for both the pillow and the cushion cover?

InternLM-Math Base 20B:

  Reasoning: The total cost is $22.312 + $3.91 = <<22.312+3.91=26.222>>$26.222.
### Answer: 26.222

Expected answer: 26.2220000000000

Correct? Yes

Problem: In the previous problem, we had mentioned how much the pillow cost after a discount. But what if the original price of the pillow had been $27 instead of $25.997 before applying the discount of $3.685? What would be the cost of the pillow then?

InternLM-Math Base 20B:

  Reasoning: The pillow costs $27 - $3.685 = <<27-3.685=23.315>>$23.315 after the discount.
### Answer: 23.315

Expected answer: 23.3150000000000

Correct? Yes

Problem: Previously, the police officer's first crime scene was 11.183 kilometers away, and the second was an additional 4.46 kilometers. But what if the first crime scene had instead been 14 kilometers away from the station but still 4.46 kilometers away from the second crime scene? What would then be the total distance the cop needs to travel to investigate both crime scenes?

InternLM-Math Base 20B:

  Reasoning: The total distance the officer needs to travel is 14+4.46 = <<14+4.46=18.46>>18.46 kilometers.
### Answer: 18.46

Expected answer: 18.4600000000000

Correct? Yes

Problem: Following his first discovery, Zyko learns that another friendly alien has 3.87 units more kryptonite than the hero alien. After he takes into account the kryptonite stolen from him, how much kryptonite does this second friendly alien have compared to Zyko?

InternLM-Math Base 20B:

  Reasoning: The second friendly alien has 12.13+3.87 = <<12.13+3.87=16>>16 units more kryptonite than Zyko.
### Answer: 16

Expected answer: 16.0000000000000

Correct? Yes

Problem: In a new development, it turns out the space villain only managed to steal 1 unit of kryptonite from Zyko, not 8.49 units as initially believed. With this new revelation, how much more kryptonite does the hero alien have in comparison to Zyko?

InternLM-Math Base 20B:

  Reasoning: Zyko has 24.06-1 = <<24.06-1=23.06>>23.06 kryptonite units left. The hero has 27.7-23.06 = <<27.7-23.06=4.64>>4.64 more units of kryptonite.
### Answer: 4.64

Expected answer: 4.64000000000000

Correct? Yes

Problem: Following the previous questions, now consider if the cloud was originally at 19 kilometers above the surface of the Earth instead of 27.53 and it drops 2.411 kilometers lower as before. How high is the cloud from the surface of the Earth now?

InternLM-Math Base 20B:

  Reasoning: 19-2.411 = <<19-2.411=16.589>>16.589
### Answer: 16.589

Expected answer: 16.5890000000000

Correct? Yes

Problem: Suppose the normal cost of the piano tuning was actually $13 instead of $25.3. With the same special offer of $5.433 off, how much will the piano tuning session cost after the discount?

InternLM-Math Base 20B:

  Reasoning: The piano tuning session costs $13 - $5.433 = <<13-5.433=7.567>>$7.567.
### Answer: $7.567

Expected answer: 7.56700000000000

Correct? Yes

Problem: Revisiting the previous scenario, what if the swing initially moved only 5 meters forward but still swung back 8.325 meters? What would be the total distance travelled by the swing?

InternLM-Math Base 20B:

  Reasoning: 5+8.325 = <<5+8.325=13.325>>13.325
### Answer: 13.325

Expected answer: 13.3250000000000

Correct? Yes

Problem: The candle maker decides to make another candle of the same size. What is the total weight of both candles?

InternLM-Math Base 20B:

  Reasoning: The total weight of both candles is 9.3+9.3 = <<9.3+9.3=18.6>>18.6 ounces.
### Answer: 18.6

Expected answer: 18.6000000000000

Correct? Yes

Problem: If the candle maker decides to use 21 ounces of wax for a candle instead of 8 ounces, but keeps the weight of decorative wax the same, what would be the total weight of the new candle?

InternLM-Math Base 20B:

  Reasoning: The total weight of the new candle is 21+1.3 = <<21+1.3=22.3>>22.3 ounces.
### Answer: 22.3

Expected answer: 22.3000000000000

Correct? Yes

Problem: After the snowman melted to 2.624 feet, a fresh layer of snow fell overnight and added the exact amount of height that the snowman lost back onto it. What is the height of the snowman the next morning?

InternLM-Math Base 20B:

  Reasoning: The height of the snowman the next morning is 2.624+10.279 = <<2.624+10.279=12.903>>12.903 feet.
### Answer: 12.903

Expected answer: 12.9030000000000

Correct? Yes

Problem: If a gift's initial price was $24.17, and they added $3.802 for gift wrapping, how much would the final cost of the gift be? Additionally, if the customer used a discount coupon worth $10.7, what would be the total cost of the gift after applying the discount?

InternLM-Math Base 20B:

  Reasoning: The final cost of the gift is $24.17+$3.802 = <<24.17+3.802=27.972>>$27.972.
### Answer: 27.972

Expected answer: 17.2720000000000

Correct? No

Problem: If instead of the original price being $24.17, the gift only cost $4, and they still added $3.802 for gift wrapping, what would the final cost of the gift then be?

InternLM-Math Base 20B:

  Reasoning: The final cost of the gift is $4+$3.802 = <<4+3.802=7.802>>$7.802.
### Answer: 7.802

Expected answer: 7.80200000000000

Correct? Yes

Problem: Now, consider if the baker has a smaller amount of sugar, 7 kilograms instead of 15.643 kilograms. Given the same amount of flour (10.24 kilograms) and the same amount of total ingredients used for the cake (8.8 kilograms), how many kilograms of ingredients are left now?

InternLM-Math Base 20B:

  Reasoning: The total amount of ingredients is 7+10.24 = <<7+10.24=17.24>>17.24 kilograms.
The amount of ingredients left is 17.24-8.8 = <<17.24-8.8=8.44>>8.44 kilograms.
### Answer: 8.44

Expected answer: 8.44000000000000

Correct? Yes

Problem: After purchasing the discounted pillow, Carl decided to buy an additional decorative pillow cover that cost $7. If the original discounted price of the pillow was $25.15 - $5.10, how much did Carl pay in total for the pillow and the cover?

InternLM-Math Base 20B:

  Reasoning: The total cost of the pillow and the cover is $20.05 + $7 = <<20.05+7=27.05>>$27.05.
### Answer: $27.05

Expected answer: 27.0500000000000

Correct? Yes

Problem: If the original price of the pillow before the sale was instead $8.00 but the discount was still $5.10, what would be the new price of the discounted pillow?

InternLM-Math Base 20B:

  Reasoning: The new price of the discounted pillow is $8.00 - $5.10 = <<8.00-5.10=2.90>>$2.90.
### Answer: $2.90

Expected answer: 2.90000000000000

Correct? Yes

Problem: The pirate actually counted his treasure wrong and there were 29 kg of treasure instead of 15.5 kg initially. After subtracting the 3.8 kg the lock on the chest weighs, how much does the corrected weight of the treasure inside the chest come to?

InternLM-Math Base 20B:

  Reasoning: The treasure weighs 29-3.8 = <<29-3.8=25.2>>25.2 kg.
### Answer: 25.2

Expected answer: 25.2000000000000

Correct? Yes

Problem: Suppose they now added another Slide C in the park with a length of 21 meters while the length of Slide B remains at 6.45 meters. What would be the total length of both slides now?

InternLM-Math Base 20B:

  Reasoning: 21+6.45 = <<21+6.45=27.45>>27.45
### Answer: 27.45

Expected answer: 27.4500000000000

Correct? Yes

Problem: Now consider that train tickets for a one-way trip from City A to City B are revised and cost $2 instead of $13.868. If a passenger wants to buy a round-trip ticket from City A to City B and back to City A, what is the new cost?

InternLM-Math Base 20B:

  Reasoning: The cost of a round-trip ticket is twice the cost of a one-way ticket.
The cost of a round-trip ticket is 2*2 = <<2*2=4>>4.
### Answer: 4

Expected answer: 4

Correct? Yes

Problem: If a box of colored pencils actually costs $6 instead of $14.93, how much would Kai spend to buy 2 boxes?

InternLM-Math Base 20B:

  Reasoning: 2*6 = <<2*6=12>>12
### Answer: 12

Expected answer: 12

Correct? Yes

Problem: In the previous scenario, the robot needed 21.3 volts to operate perfectly. Suppose now the battery already has 13 volts. How many more volts are required now to make the robot function ideally?

InternLM-Math Base 20B:

  Reasoning: 21.3-13 = <<21.3-13=8.3>>8.3 volts are required to make the robot function ideally.
### Answer: 8.3

Expected answer: 8.30000000000000

Correct? Yes

Problem: Assuming that the price of the jar of turquoise paint was actually $4 instead of $7.949, the cost of the two jars of paint would be different. If you still apply the discount coupon that subtracts $8.405 from your total cost, what is the final price now for purchasing both the jar of turquoise paint and the jar of navy blue paint?

InternLM-Math Base 20B:

  Reasoning: The total cost of the two jars of paint is $4 + $20.16 = <<4+20.16=24.16>>$24.16.
The final price for purchasing both jars of paint is $24.16 - $8.405 = <<24.16-8.405=15.755>>$15.755.
### Answer: 15.755

Expected answer: 15.7550000000000

Correct? Yes

Problem: After travelling a combined total of 3.566 km and 19.63 km, the scooter then reverses its direction and goes back 5.364 km. How many kilometers is the scooter now from its original starting position?

InternLM-Math Base 20B:

  Reasoning: The scooter is now 3.566+19.63-5.364 = <<3.566+19.63-5.364=17.256>>17.256 km from its original starting position.
### Answer: 17.256

Expected answer: 17.8320000000000

Correct? No

Problem: After considering the initial 3.566 km the scooter had travelled, suppose it only travelled an additional 5 km instead of 19.63 km before making the stop. What is the new total distance the scooter travelled?

InternLM-Math Base 20B:

  Reasoning: The scooter traveled 3.566+5 = <<3.566+5=8.566>>8.566 km in total.
### Answer: 8.566

Expected answer: 8.56600000000000

Correct? Yes

Problem: In the same party, after John found out how much juice he added, he decided to add an additional 13.9 ounces of juice. How much juice does he currently have now?

InternLM-Math Base 20B:

  Reasoning: John currently has 5.418+13.9 = <<5.418+13.9=19.318>>19.318 ounces of juice.
### Answer: 19.318

Expected answer: 19.3180000000000

Correct? Yes

Problem: In the same party, what if John initially had 20 ounces of juice instead of 24.644 ounces before he added more? How much juice would he have added to reach 24.644 ounces?

InternLM-Math Base 20B:

  Reasoning: John added 24.644-20 = <<24.644-20=4.644>>4.644 ounces of juice.
### Answer: 4.644

Expected answer: 4.64400000000000

Correct? Yes

Problem: Suppose in a new experiment, the intensity of the sun's radiation outside of Earth's atmosphere is slightly stronger, and is now 21 kilowatts per square meter. If you further absorb an additional 2.38 kilowatts per square meter due to this experiment, what is the total intensity of the absorbed solar radiation now in kilowatts per square meter?

InternLM-Math Base 20B:

  Reasoning: 21+2.38 = <<21+2.38=23.38>>23.38
### Answer: 23.38

Expected answer: 23.3800000000000

Correct? Yes

Problem: Following the decrease in the sun's temperature, scientists observe that for every degree decrease, solar energy reaching Earth reduces by 7.6%. How much has the solar energy reduced by, when the sun's temperature dropped from 18.22 million degrees Fahrenheit to 14.558 million degrees Fahrenheit?

InternLM-Math Base 20B:

  Reasoning: 3.662 * 7.6% = <<3.662*7.6%=0.0278>>0.0278
### Answer: 0.0278

Expected answer: 27.8312000000000

Correct? No

Problem: Given the previous scenario about the sun's temperature decreasing from 18.22 million degrees Fahrenheit in the afternoon, imagine instead that the temperature reduced more drastically to 6 million degrees. What would then be the decrease in the sun's temperature?

InternLM-Math Base 20B:

 Reasoning: 18.22-6 = <<18.22-6=12.22>>12.22
### Answer: 12.22

Expected answer: 12.2200000000000

Correct? Yes

Problem: If instead of the initial yield being 1.6 kg, it was 6 kg and the same 3.443 kg increase occurs, how much would the banana tree yield then?

InternLM-Math Base 20B:

  Reasoning: The banana tree yields 6+3.443 = <<6+3.443=9.443>>9.443 kg of bananas.
### Answer: 9.443

Expected answer: 9.44300000000000

Correct? Yes

Problem: If instead of 6.1 pounds, the giraffe only ate 4 pounds of leaves in the afternoon, and still, 7.58 pounds were not digested, how many pounds were now digested?

InternLM-Math Base 20B:

  Reasoning: 22.3+4 = <<22.3+4=26.3>>26.3 pounds of leaves were eaten.
26.3-7.58 = <<26.3-7.58=18.72>>18.72 pounds of leaves were digested.
### Answer: 18.72

Expected answer: 18.7200000000000

Correct? Yes