Common Core Standard 3.OA.A.3
This standard covers the following:
Use multiplication and division within 100 to solve word problems in situations involving equal groups, arrays, and measurement quantities, e.g., by using drawings and equations with a symbol for the unknown number to represent the problem.
Problem: John has 12 tables. Each table requires 8 chairs. How many chairs does John need to accommodate all the tables?
InternLM-Math Base 7B:
Reasoning: John needs 12x8= <<12x8=96>>96 chairs to accommodate all the tables. ### Answer: 96
Expected answer: 96
Correct? Yes
Problem: Suppose now, John only has 2 tables instead of 12. Using the same number of chairs per table, how many chairs would John need now to accommodate these tables?
InternLM-Math Base 7B:
Reasoning: John needs 2x8= <<2x8=16>>16 chairs to accommodate the 2 tables. ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: In a magical fairy world, there are 4 fairies per house and 3 houses in a cluster. Each fairy creates 5 magic dust particles a day. How many magic dust particles are created in one day by all the fairies in a cluster?
InternLM-Math Base 7B:
Reasoning: There are 3 <<3>>3 houses in a cluster. Each house has 4 <<4>>4 fairies. Each fairy makes 5 <<5>>5 magic dust particles. So, 3 â‹… 4 â‹… 5 = 3â‹…4â‹…5= <<3â‹…4â‹…5=60>>60 ### Answer: 60
Expected answer: 60
Correct? Yes
Problem: In the magical fairy world, each magic dust particle created lasts for 1 whole week. How many magic dust particles will be available in a cluster of houses after a week?
InternLM-Math Base 7B:
Reasoning: There are 3 <<3>>3 houses in a cluster. Each house has 4 <<4>>4 fairies. Each fairy makes 5 <<5>>5 magic dust particles. So, 3â‹…4â‹…5=3â‹…4â‹…5= <<3â‹…4â‹…5=60>>60 There are 7 <<7>>7 days in a week. So, 60â‹…7=60â‹…7= <<60â‹…7=420>>420 ### Answer: 420
Expected answer: 60
Correct? No
Problem: Previously, we discovered that each fairy creates 5 magic dust particles a day. But what happens if instead, each fairy creates 8 magic dust particles a day? How many magic dust particles are then created in one day by all the fairies in a cluster?
InternLM-Math Base 7B:
Reasoning: 3 â‹… 4 â‹… 8 = 3â‹…4â‹…8= <<3â‹…4â‹…8=96>>96 ### Answer: 96
Expected answer: 96
Correct? Yes
Problem: Harry has 9 sets of building blocks, each set contains 7 blocks. How many building blocks does Harry have in total?
InternLM-Math Base 7B:
Reasoning: 9*7= <<9*7=63>>63 ### Answer: 63
Expected answer: 63
Correct? Yes
Problem: In the zoo, there are 12 peacocks in every enclosure. If there are 4 enclosures, how many peacocks are in the zoo in total?
InternLM-Math Base 7B:
Reasoning: 12*4 = <<12*4=48>>48 ### Answer: 48
Expected answer: 48
Correct? Yes
Problem: Let's imagine that instead of 4 enclosures, the zoo originally had 7 enclosures. The same rule was followed: 12 peacocks were placed in each enclosure. How many peacocks would there be in the zoo in this scenario?
InternLM-Math Base 7B:
Reasoning: 12*7 = <<12*7=84>>84 ### Answer: 84
Expected answer: 84
Correct? Yes
Problem: There are 24 children at the park and want to play on the jungle gym. If each jungle gym can accommodate 12 children at a time, how many turns must they take so that everyone gets a chance to play?
InternLM-Math Base 7B:
Reasoning: 12/24 = <<12/24=1/2>>1/2. 1/2 of 24 = <<1/2*24=12>>12. 24-12 = <<24-12=12>>12. 12/12 = <<12/12=1>>1. 1 turn is required for all 24 children to get a turn on the jungle gym. ### Answer: 1
Expected answer: 2
Correct? No
Problem: On the farm, there are 7 groups of chicks. Each group consists of just 1 chick. The farmer then brought 9 times that amount of chicks. How many chicks did the farmer bring?
InternLM-Math Base 7B:
Reasoning: 7 groups of 1 = <<7x1=7>>7 9x7 = <<9x7=63>>63 ### Answer: 63
Expected answer: 63
Correct? Yes
Problem: Initially, there were around 7 groups of chicks on the farm, with each group consisting of just 1 chick. But what if the farmer's original flock was smaller? Let's say he initially started with 4 times that amount of chicks. How many chicks would he have started with then?
InternLM-Math Base 7B:
Reasoning: 4x7 = <<4x7=28>>28 ### Answer: 28
Expected answer: 28
Correct? Yes
Problem: Mr. Hansen, a very organized teacher, likes to keep ten copies of each handout for his class. If he is preparing a new handout for the next class, how many copies will he make?
InternLM-Math Base 7B:
Expected answer: 10
Correct? No
Problem: A snowman has a top hat that is 5 inches tall. The snowman himself, without his hat, is 4 times as tall as his hat. How tall is the snowman without his hat?
InternLM-Math Base 7B:
Reasoning: The top hat of the snowman is 5 inches tall. The snowman, without his hat, is 4 times as tall as his hat. 4x5=20, so the snowman, without his hat, is 20 inches tall. ### Answer: 20
Expected answer: 20
Correct? Yes
Problem: In the initial scenario, the snowman without his hat was 4 times as tall as his 5-inch hat, giving us a snowman's height of 20 inches. Now, in our revised scenario, let's consider that the snowman without his hat is instead only 4 times as tall as a 2-inch hat. How tall is the snowman without his hat in this new scenario?
InternLM-Math Base 7B:
Reasoning: The top hat of the snowman is 2 inches tall. The snowman, without his hat, is 4 times as tall as his hat. 4x2=8, so the snowman, without his hat, is 8 inches tall. ### Answer: 8
Expected answer: 8
Correct? Yes
Problem: In a video game, Susan collected 45 diamonds. If she divided those diamonds evenly among her 9 game characters, how many diamonds does each character get?
InternLM-Math Base 7B:
Reasoning: 45/9 = <<45/9=5>>5 Each character gets 5 diamonds. ### Answer: 5
Expected answer: 5
Correct? Yes
Problem: Suppose initially, Susan had only found 12 diamonds instead of 45. If she still divided those diamonds evenly among her 9 game characters, how many diamonds would each character receive then?
InternLM-Math Base 7B:
Reasoning: 12/9 = <<12/9=1.3...>>1.3... Each character would receive 1.3... diamonds. ### Answer: 1.3
Expected answer: 4/3
Correct? No
Problem: Jim has 12 guitar picks. He divided them equally among his 12 bandmates. How many guitar picks did each bandmate get?
InternLM-Math Base 7B:
Reasoning: 12/12 = 1 Each bandmate got 1 pick. ### Answer: 1
Expected answer: 1
Correct? Yes
Problem: After dividing his guitar picks among his bandmates, Jim got a package from a fan. In the package, there were 11 more sets of guitar picks, each set having the same number of picks as each bandmate initially received. How many guitar picks were there in the package?
InternLM-Math Base 7B:
Reasoning: 1x11 = 1+1+1+1+1+1+1+1+1+1+1=11 There were 11 guitar picks in the package. ### Answer: 11
Expected answer: 11
Correct? Yes
Problem: Considering the scenario when Jim initially had 12 guitar picks but instead of dividing them among 12 bandmates, he divided them among 6 bandmates. How many guitar picks did each bandmate get?
InternLM-Math Base 7B:
Reasoning: 12/6 = 2 Each bandmate got 2 picks. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: Suzie has 5 aquariums. Each aquarium has 12 fish. How many fish does Suzie have in total?
InternLM-Math Base 7B:
Reasoning: Suzie has 5*12 = <<5*12=60>>60 fish in total. ### Answer: 60
Expected answer: 60
Correct? Yes
Problem: After buying the new batch, Suzie realized her first count was wrong. She actually started with 4 aquariums, not 5, before she bought the new fish. With each aquarium having 12 fish, how many fish did Suzie initially have?
InternLM-Math Base 7B:
Reasoning: Suzie had 4*12 = <<4*12=48>>48 fish in total. ### Answer: 48
Expected answer: 48
Correct? Yes
Problem: A pirate found a treasure map. The map indicated that the treasure chest was buried at a spot marked by 2 stones multiplied by 9. How many stones mark the hiding place of the treasure chest?
InternLM-Math Base 7B:
Reasoning: 2 × 9 = <<2 × 9=18>>18. The hiding place of the treasure chest is marked by 18 stones. ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: The pirate, now intrigued, discovered a third map in the larger treasure chest. This map was slightly different, indicating that the next treasure chest was marked by a spot identified not by 2 stones multiplied by 9, but by 3 stones multiplied by 9. How many stones mark the hiding spot of this third treasure chest?
InternLM-Math Base 7B:
Reasoning: 3 × 9 = <<3 × 9=27>>27. The third treasure chest is hidden at a spot identified by 27 stones. ### Answer: 27
Expected answer: 27
Correct? Yes
Problem: A special type of butterfly lays eggs in batches of 6. If a butterfly lays 4 batches of eggs, how many eggs does she lay in total?
InternLM-Math Base 7B:
Reasoning: 4*6 = <<4*6=24>>24 ### Answer: 24
Expected answer: 24
Correct? Yes
Problem: After further research, it was discovered that the butterfly was actually laying eggs in batches of 4 instead of 6 as previously thought. If there were still 4 batches of eggs, how many eggs would the butterfly have laid in total then?
InternLM-Math Base 7B:
Reasoning: 4*4 = <<4*4=16>>16 ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: Anna has 54 feathers she wants to use to stuff some pillows. If each pillow needs 9 feathers, how many pillows can she stuff?
InternLM-Math Base 7B:
Reasoning: 54/9 = <<54/9=6>>6 She can make 6 pillows.
Expected answer: 6
Correct? Yes
Problem: Following from the previous problem, Anna managed to stuff the pillows with the 54 feathers. If each stuffed pillow now needs to be sewn with 8 buttons, how many buttons will Anna need in total?
InternLM-Math Base 7B:
Reasoning: 6 â‹… 8 = <<6â‹…8=48>>48 She will need 48 buttons in total.
Expected answer: 48
Correct? Yes
Problem: Tom has 1 strawberry plant. Each strawberry plant can produce 9 strawberries. How many strawberries can Tom's plant produce?
InternLM-Math Base 7B:
Reasoning: 9x1 = <<9x1=9>>9 ### Answer: 9
Expected answer: 9
Correct? Yes
Problem: Continuing from the earlier problem, let's say now Tom decides to increase his strawberry plant count to 5 plants. Given that each plant can produce 9 strawberries without any fertilizer, how many strawberries can all of Tom's plants now produce together?
InternLM-Math Base 7B:
Reasoning: 9x5 = <<9x5=45>>45 ### Answer: 45
Expected answer: 45
Correct? Yes
Problem: In a large mansion, each room has 8 fireplaces. If there are 96 fireplaces in total, how many rooms are there in the mansion?
InternLM-Math Base 7B:
Reasoning: 8 fireplaces in each room. 96/8 = <<96/8=12>>12 rooms.
Expected answer: 12
Correct? Yes
Problem: Following the last question, if each room in the mansion requires 7 workers to clean all of the fireplaces, how many workers are needed in total to clean all the fireplaces in the mansion?
InternLM-Math Base 7B:
Reasoning: 7 workers in each room. 12x7 = <<12x7=84>>84 workers.
Expected answer: 84
Correct? Yes
Problem: John has 10 boxes he needs to transport in a truck. However, his truck can only hold 5 boxes at a time. How many trips does he need to make to transport all the boxes?
InternLM-Math Base 7B:
Reasoning: John can only transport 5 boxes at a time. The number of trips he needs to make to transport 10 boxes is 10/5 = <<10/5=2>>2.
Expected answer: 2
Correct? Yes
Problem: John has finished his trips and transported all the boxes. However, he realizes that each round trip he makes consumes 6 liters of fuel. How many liters of fuel has he used to make all of his trips?
InternLM-Math Base 7B:
Reasoning: John has made 2 round trips. The number of liters of fuel he has used to make all of his trips is 2x6 = <<2x6=12>>12.
Expected answer: 12
Correct? Yes
Problem: Charlie has a total of 63 toy cars. If he groups them equally into 9 big boxes, how many toy cars will be in each box?
InternLM-Math Base 7B:
|user| If Charlie groups 63/9 = <<63/9=7>>7 toy cars into each box, there will be 9 big boxes.
Expected answer: 7
Correct? Yes
Problem: Let's reconsider the organization of Charlie's toy cars. This time, instead of grouping them into 9 boxes, imagine he grouped the original 63 toy cars into only 5 boxes. How many toy cars will be in each box now?
InternLM-Math Base 7B:
|user| If Charlie groups 63/5 = <<63/5=12>>12 cars into each box, there will be 5 big boxes.
Expected answer: 63/5
Correct? Yes
Problem: On the farm, there are 24 hens. Each coop holds 12 hens. How many coops are needed to house all the hens?
InternLM-Math Base 7B:
Reasoning: 24/12 = <<24/12=2>>2 ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: After reconsidering, the farmer decides to place the hens into larger coops where each coop can hold 8 hens. How many coops would he need now to house all the hens?
InternLM-Math Base 7B:
Reasoning: 24/8 = <<24/8=3>>3 ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: If 3 large postcards are placed in 1 envelope, how many large postcards are in each envelope?
InternLM-Math Base 7B:
Reasoning: 3/3 = <<3/3=1>>1 large postcard in each envelope. ### Answer: 1
Expected answer: 3
Correct? No
Problem: Tommy is going camping and he needs sleeping bags. He took 12 sleeping bags from the storage and he remembered that he needs twice as many. How many sleeping bags does he need in total?
InternLM-Math Base 7B:
Reasoning: Tommy needs 2*12 = <<2*12=24>>24 sleeping bags in total. ### Answer: 24
Expected answer: 24
Correct? Yes
Problem: Tommy remembered that he actually only had 6 sleeping bags in storage, not 12 as he had previously thought. He still needs twice as many sleeping bags as originally counted. How many sleeping bags does he need in total now?
InternLM-Math Base 7B:
Reasoning: Tommy needs 2*6 = <<2*6=12>>12 sleeping bags in total. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: In a new game, Tina earns 3 points per level. If she successfully completes 5 levels, how many total points does she earn?
InternLM-Math Base 7B:
Tina earns 3x5 = <<3x5=15>>15 total points. ### Answer: 15
Expected answer: 15
Correct? Yes
Problem: In the same game, Tina decides to convert her points into game coins. If the current rate of conversion is 1 coin per point, how many game coins will she have after the conversion?
InternLM-Math Base 7B:
Tina will have 15x1 = <<15x1=15>>15 game coins. ### Answer: 15
Expected answer: 15
Correct? Yes
Problem: In a video game, Tim needs 4 points to advance to the next level. If there are 9 levels in total, how many points does Tim need in total to finish the game?
InternLM-Math Base 7B:
Reasoning: 4 points to advance to the next level, 9 levels, 9*4 = 36 points ### Answer: 36
Expected answer: 36
Correct? Yes
Problem: In the new season of the video game, the number of points needed to advance to the next level increased. Now, Tim needs 4 points to advance each of the 11 levels. What is the total number of points Tim needs now to finish the game?
InternLM-Math Base 7B:
Reasoning: 4 points to advance to the next level, 11 levels, 11*4 = 44 points ### Answer: 44
Expected answer: 44
Correct? Yes
Problem: Sophie has a bubble blowing machine. The machine blows bubbles at a rate of 2 bubbles per second. How many bubbles will be blown in one second?
InternLM-Math Base 7B:
Reasoning: 2/1 = <<2/1=2>>2 bubbles will be blown in one second. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: Sophie lets her bubble blowing machine run for another 9 seconds. How many more bubbles does the machine blow?
InternLM-Math Base 7B:
Reasoning: 9*2 = <<9*2=18>>18 bubbles will be blown in 9 seconds. ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: Sophie changes the setting on her bubble blowing machine so that it now blows 7 bubbles per second instead of 2. How many bubbles will now be blown in one second?
InternLM-Math Base 7B:
Reasoning: 7/1 = <<7/1=7>>7 bubbles will be blown in one second. ### Answer: 7
Expected answer: 7
Correct? Yes
Problem: Farmer Mike has 6 cows. Each of them gives 12 liters of milk every day. How many liters of milk does Farmer Mike get in a day?
InternLM-Math Base 7B:
Reasoning: 6x12= <<6x12=72>>72 ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: Farmer Mike decided to buy an additional cow, increasing his herd to 7 cows. If each cow still produces 12 liters of milk every day, how many liters of milk does Farmer Mike get in a day now?
InternLM-Math Base 7B:
Reasoning: 7x12= <<7x12=84>>84 ### Answer: 84
Expected answer: 84
Correct? Yes
Problem: John has 9 sunglasses in a line. He decided to divide his collection into equal parts. If each part contains 9 sunglasses, how many parts would he get?
InternLM-Math Base 7B:
Reasoning: 9/9 = <<9/9=1>>1 ### Answer: 1
Expected answer: 1
Correct? Yes
Problem: After assigning sunglasses to the group, John considers dividing his original collection differently. If he divides the initial 9 sunglasses by 1 instead of 9, how many sunglasses would he have in each group?
InternLM-Math Base 7B:
Reasoning: 9/1 = <<9/1=9>>9 ### Answer: 9
Expected answer: 9
Correct? Yes
Problem: A rocket scientist needs to calculate the fuel consumption of his rocket. Each second, the rocket uses 9 units of fuel. After 11 seconds of flight, how much fuel has been consumed?
InternLM-Math Base 7B:
Reasoning: 9*11 = <<9*11=99>>99 units of fuel have been consumed. ### Answer: 99
Expected answer: 99
Correct? Yes
Problem: In the park, there are 4 swings available. Every swing can seat 3 children. How many children can the swings in the park seat altogether?
InternLM-Math Base 7B:
Reasoning: 4 x 3 = <<4x3=12>>12 ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: In reconsideration, the first park actually only has 1 swing that can seat 3 children, not 4 swings. Given this new information, how many children can the swings in the first park seat now?
InternLM-Math Base 7B:
Reasoning: 1 x 3 = <<1x3=3>>3 ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: There are 3 magical fairies in Fairyland. Each fairy has a unique ability to create triplets of herself. How many fairies will there be after each of them uses their ability?
InternLM-Math Base 7B:
Reasoning: The first fairy creates 3 fairies. The second fairy creates 9 fairies. The third fairy creates 27 fairies. There are 3+9+27 = <<3+9+27=39>>39 fairies.
Expected answer: 9
Correct? No
Problem: James, a songwriter, loves to include the word "love" in his songs. In one song, he mentioned the word "love" 4 times in each verse. How many times did he mention "love" if the song has 3 verses?
InternLM-Math Base 7B:
Reasoning: James mentioned the word "love" 4x3= <<4x3=12>>12 times in the song. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: Following the last problem, after James wrote his song, he decided to dedicate four performances to his beloved. In each performance, he sings the song once. How many times will the word "love" be mentioned if he sings the song in all four performances?
InternLM-Math Base 7B:
Reasoning: James sings the song 4x1= <<4x1=4>>4 times in the four performances. He mentions the word "love" 4x4= <<4x4=16>>16 times in the four performances. ### Answer: 16
Expected answer: 48
Correct? No
Problem: Continuing from the previous scenarios, James decided to rewrite his song. Now, he included the word "love" 4 times in each verse, but this time he expanded his song to include 10 verses. How many times does he mention "love" in this new version of his song?
InternLM-Math Base 7B:
Reasoning: James mentioned the word "love" 4x10= <<4x10=40>>40 times in the new version of his song. ### Answer: 40
Expected answer: 40
Correct? Yes
Problem: Mark has 48 apps on his phone. He likes to organize his apps into folders, and he can fit exactly 8 apps in each folder. How many folders does he need to organize all of his apps?
InternLM-Math Base 7B:
| |assistant| Reasoning: Mark can put 8/8 = 1 app in each folder. He needs 48/8 = <<48/8=6>>6 folders to organize all of his apps. ### Answer: 6
Expected answer: 6
Correct? Yes
Problem: Mark realized that he could fit more apps into each folder. If he reorganizes his apps so that each folder contains 6 apps instead of 8, how many folders will he need now to store all of his 48 apps?
InternLM-Math Base 7B:
| |assistant| | |assistant| Reasoning: Mark can put 6/6 = 1 app in each folder. He needs 48/6 = <<48/6=8>>8 folders to organize all of his apps. ### Answer: 8
Expected answer: 8
Correct? Yes
Problem: If Johnny wants to distribute candies to his friends at school and he decides to give each friend 12 candies, and there are 3 friends, how many candies does he need in total?
InternLM-Math Base 7B:
Reasoning: Johnny should have 3*12 = <<3*12=36>>36 candies in total. ### Answer: 36
Expected answer: 36
Correct? Yes
Problem: After distributing candies to his friends at school, Johnny decides to double the amount of candies he gave for the next day. How many candies will he need in total for the next day?
InternLM-Math Base 7B:
Reasoning: Johnny should have 3*2*12 = <<3*2*12=72>>72 candies in total. ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: Tommy has a racetrack that he plans to race his toy cars on. If he can race 10 cars in total and he races 5 cars at a time, how many turns does it take for him to race all his cars?
InternLM-Math Base 7B:
Reasoning: Tommy can race 10/5 = <<10/5=2>>2 cars in 1 turn. He can race 10 cars in 5/2 = <<5/2=2.5>>2.5 turns. ### Answer: 2.5
Expected answer: 2
Correct? No
Problem: Sally has 40 feathers from her chickens. If she arranged the feathers in groups of 10, how many groups would she have?
InternLM-Math Base 7B:
Reasoning: 40/10 = <<40/10=4>>4 Sally would have 4 groups of 10 feathers. ### Answer: 4
Expected answer: 4
Correct? Yes
Problem: Sally sorts her 40 chicken feathers into groups of 10. Then, she decided to double the number of groups. How many groups does she have now?
InternLM-Math Base 7B:
Reasoning: 2x4= <<2x4=8>>8 Sally has 8 groups of 10 feathers. ### Answer: 8
Expected answer: 8
Correct? Yes
Problem: Sally originally thought she had sorted her 40 chicken feathers into groups of 10, but then she realized she actually sorted them into groups of 11 instead. How many groups does she have now?
InternLM-Math Base 7B:
Reasoning: 40/11 = <<40/11=3.6363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636363636
Expected answer: 40/11
Correct? Yes
Problem: Fairy Lily is 1 inch tall. However, when she uses her magical fairy dust, she can become 11 times her original size. How tall is Fairy Lily when she uses her magical dust?
InternLM-Math Base 7B:
Reasoning: 1x11 = <<1x11=11>>11 ### Answer: 11
Expected answer: 11
Correct? Yes
Problem: After using her magical dust to grow 11 times her original size, Fairy Lily decides to add another element to her spells. She casts a spell that multiplies her height by 7. How tall is Fairy Lily now?
InternLM-Math Base 7B:
Reasoning: 11x7 = <<11x7=77>>77 ### Answer: 77
Expected answer: 77
Correct? Yes
Problem: In a different scenario, if Fairy Lily only grows to 6 times her original size rather than 11 times using her magical dust, how tall would she become then?
InternLM-Math Base 7B:
Reasoning: 1x6 = <<1x6=6>>6 ### Answer: 6
Expected answer: 6
Correct? Yes
Problem: In a beehive, one female bee can produce 5 new bees every day. How many bees would she produce in 1 day?
InternLM-Math Base 7B:
Reasoning: 1 female bee produces 5 new bees a day. 1 female bee would produce 5 new bees in 1 day. ### Answer: 5
Expected answer: 5
Correct? Yes
Problem: Following the previous problem, if this female bee continues to produce bees at the same rate, how many bees will she have produced after 11 days?
InternLM-Math Base 7B:
Reasoning: 1 female bee produces 5 new bees a day. 1 female bee would produce 5*11 = <<5*11=55>>55 new bees in 11 days. ### Answer: 55
Expected answer: 55
Correct? Yes
Problem: Following the previous problems, consider if the female bee instead produced new bees at a slower rate, making only 5 bees every 3 days. How many bees would she produce in one day at this new rate?
InternLM-Math Base 7B:
Reasoning: 1 female bee produces 5/3 = <<5/3=1.6666...>>1.6 new bees a day. 1 female bee would produce 1.6 new bees in 1 day at this new rate. ### Answer: 1.6
Expected answer: 5/3
Correct? No
Problem: Thomas has 35 piano sheets in his music stand. If he wants to evenly distribute his music sheets into 7 piano books, how many sheets will each book have?
InternLM-Math Base 7B:
Reasoning: 35/7 = <<35/7=5>>5 Thomas will have 5 sheets in each of his 7 books. ### Answer: 5
Expected answer: 5
Correct? Yes
Problem: After arranging his music sheets into the piano books, Thomas decided to purchase 8 more books, each with the same number of sheets as the books he has now. How many more piano sheets did he buy?
InternLM-Math Base 7B:
Reasoning: 8x5= <<8x5=40>>40 Thomas bought 40 more sheets. ### Answer: 40
Expected answer: 40
Correct? Yes
Problem: Instead, suppose originally Thomas had 9 piano sheets. If he evenly distributes his music sheets into 7 piano books as before, how many sheets will each book have now?
InternLM-Math Base 7B:
Reasoning: 9/7 = <<9/7=1>>1 Thomas will have 1 sheet in each of his 7 books. ### Answer: 1
Expected answer: 9/7
Correct? No
Problem: Mom baked 2 batches of cookies. Each batch contains 8 cookies. How many cookies did mom bake in total?
InternLM-Math Base 7B:
Reasoning: 2x8 = <<2x8=16>>16 ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: Earth has 3 natural satellites. If the number of moon rocks collected each year is triple the total number of these satellites, how many moon rocks would be collected in one year?
InternLM-Math Base 7B:
Reasoning: The number of moon rocks collected each year is 3*3 = <<3*3=9>>9. ### Answer: 9
Expected answer: 9
Correct? Yes
Problem: Following the previous scenario, if each moon rock collected in a year is stored in a separate storage bin, how many storage bins would be needed to store all the rocks collected in one year?
InternLM-Math Base 7B:
Reasoning: 9*1 = <<9*1=9>>9 ### Answer: 9
Expected answer: 9
Correct? Yes
Problem: Continuing from the previous scenario, suppose that instead of 3, the Earth had 5 natural satellites. In this case, if the number of moon rocks collected each year is triple the total number of these satellites, how many moon rocks would be collected in one year?
InternLM-Math Base 7B:
Reasoning: The number of moon rocks collected each year is 5*3 = <<5*3=15>>15. ### Answer: 15
Expected answer: 15
Correct? Yes
Problem: Doctor Thomas needs to visit 10 patients. He spends 5 minutes with each patient. How many minutes does he spend with all of his patients?
InternLM-Math Base 7B:
Reasoning: Doctor Thomas spends 5x10 = <<5x10=50>>50 minutes with all 10 patients. ### Answer: 50
Expected answer: 50
Correct? Yes
Problem: After visiting his patients, Doctor Thomas then spends twice the amount of time he spent with his patients on paperwork. How many minutes does he spend on paperwork?
InternLM-Math Base 7B:
Reasoning: Twice the amount of time he spent with his patients is 2x50 = <<2x50=100>>100. ### Answer: 100
Expected answer: 100
Correct? Yes
Problem: In a different scenario, Doctor Thomas spends 6 minutes with each patient instead of 5 minutes. If he still has the same number of patients to visit, how many minutes will he spend with all his patients?
InternLM-Math Base 7B:
Reasoning: Doctor Thomas spends 6x10 = <<6x10=60>>60 minutes with all 10 patients. ### Answer: 60
Expected answer: 60
Correct? Yes
Problem: Jerry was thinking of purchasing new pants and he noticed a special offer. The shop was selling 11 pants for $55. After calculating the price for each pant, he decided to buy 12. How much would he spend?
InternLM-Math Base 7B:
Reasoning: Jerry can get 12 pants for 12*8.5 = <<12*8.5=102>>102.
Expected answer: 60
Correct? No
Problem: Molly has 8 bottles of apple juice. She decides to multiply her collection of apple juice bottles by the same number she has. How many bottles of apple juice does Molly have now?
InternLM-Math Base 7B:
Reasoning: Molly has 8 bottles of apple juice. Molly has 8x8 = <<8x8=64>>64 bottles of apple juice now. ### Answer: 64
Expected answer: 64
Correct? Yes
Problem: Molly later decided that 8 bottles of apple juice were too many. So, she reduced her collection to 6 bottles. Then, she once again decided to increase her apple juice collection by multiplying the number of bottles she has by the same number. How many bottles of apple juice does Molly have now?
InternLM-Math Base 7B:
Reasoning: Molly has 8 bottles of apple juice. Molly has 8x8 = <<8x8=64>>64 bottles of apple juice. Molly has 64x6 = <<64x6=384>>384 bottles of apple juice now. ### Answer: 384
Expected answer: 36
Correct? No
Problem: There are few craters on one of the sections of the moon. If that section is divided into 8 equal parts and we count 32 craters in total, how many craters are there in each part?
InternLM-Math Base 7B:
Reasoning: 32/8 = <<32/8=4>>4 ### Answer: 4
Expected answer: 4
Correct? Yes
Problem: Let's think back to the moon section with craters we discussed earlier. Suppose instead that the moon's section was divided into 5 equal parts with a total of 32 craters. How many craters would there be in each part then?
InternLM-Math Base 7B:
Reasoning: 32/5 = <<32/5=6.4>>6.4 ### Answer: 6.4
Expected answer: 32/5
Correct? Yes
Problem: There are 4 monkeys in the jungle. Each monkey has 7 bananas. How many bananas do the monkeys have in total?
InternLM-Math Base 7B:
Reasoning: 4 monkeys × 7 bananas = <<4*7=28>>28 bananas ### Answer: 28
Expected answer: 28
Correct? Yes
Problem: Let's imagine that originally there were 9 monkeys instead of 4. If each monkey has 7 bananas, how many bananas do all the monkeys have in total now?
InternLM-Math Base 7B:
Reasoning: 9 monkeys × 7 bananas = <<9*7=63>>63 bananas ### Answer: 63
Expected answer: 63
Correct? Yes
Problem: Fiona has a block of cheese that weighs 32 ounces. If she wants to divide it into equal pieces which each weigh 4 ounces, how many pieces of cheese will she have?
InternLM-Math Base 7B:
Reasoning: 32/4 = <<32/4=8>>8 Fiona will have 8 equal pieces of cheese. ### Answer: 8
Expected answer: 8
Correct? Yes
Problem: Fiona later found a smaller block of cheese that weighs 32 ounces. If she wants to cut this one into equal pieces which each weigh 9 ounces, how many pieces of cheese will she get from this block?
InternLM-Math Base 7B:
Reasoning: 32/9 = <<32/9=3.555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555
Expected answer: 32/9
Correct? Yes
Problem: Bob has 6 cups. If he wants to fill each cup with 1 glass of milk, how many glasses of milk does he need?
InternLM-Math Base 7B:
Reasoning: Bob needs 6 <<1=1>>1 glasses of milk. ### Answer: 6
Expected answer: 6
Correct? Yes
Problem: Bob just realized he only has 2 cups instead of 6. If he still wants to fill each cup with 1 glass of milk, how many glasses of milk does he need now?
InternLM-Math Base 7B:
Reasoning: Bob needs 2 <<1=1>>1 glasses of milk. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: In the zoo, there are 36 new-born rabbits divided evenly into 9 cages. Each cage is then assigned to two caretakers. How many caretakers are assigned per cage?
InternLM-Math Base 7B:
Reasoning: 36/9 = <<36/9=4>>4 new-born rabbits are in each cage. 2 caretakers are assigned to each cage. ### Answer: 2
Expected answer: 8
Correct? No
Problem: Farmer Brown has made 42 blocks of cheese. Each wheel of cheese requires 7 blocks to make. How many whole wheels of cheese can he make with the current blocks he has?
InternLM-Math Base 7B:
Reasoning: 42/7 = 6 <<42/7=6>>. Farmer Brown can make 6 whole wheels of cheese with the 42 blocks of cheese he has. ### Answer: 6
Expected answer: 6
Correct? Yes
Problem: After making the cheese wheels, Farmer Brown decides to double his production in order to have enough for the upcoming village fair. Based on his current production rate, how many cheese wheels will he have after doubling his output?
InternLM-Math Base 7B:
Reasoning: 2x6= <<2x6=12>>12. Farmer Brown will have 12 cheese wheels after he has doubled his output. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: John has a square kite. Each side of the kite is 4 feet long. What is the total length of two sides of the kite in feet?
InternLM-Math Base 7B:
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Expected answer: 8
Correct? No
Problem: Anna has 4 bags of candy, each containing 3 candies. How many candies does she have in total?
InternLM-Math Base 7B:
Reasoning: 3*4 = <<3*4=12>>12 ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: In the previous situation, what if Anna initially had only 1 bag of candy, each containing 3 candies? How many candies would she have initially?
InternLM-Math Base 7B:
Reasoning: 3*1 = <<3*1=3>>3 ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: A garden has 6 patches of flowers. Each patch attracts 3 butterflies. How many butterflies are there in total in the garden?
InternLM-Math Base 7B:
Reasoning: 3*6 = <<3*6=18>>18 ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: In a similar situation, imagine if initially there were 8 patches of flowers instead of 6 and each patch still attracts 3 butterflies. How many butterflies would there be in total then?
InternLM-Math Base 7B:
Reasoning: 8*3= <<8*3=24>>24 ### Answer: 24
Expected answer: 24
Correct? Yes
Problem: Sophia is having a party. She wants to divide 72 cookies evenly among her 8 friends, giving them an equal number. She then decides to gift each friend 5 times the amount they initially received. How many cookies will each friend get in total?
InternLM-Math Base 7B:
Reasoning: 8*1 = <<8*1=8>>8 cookies to each friend in the first round. 8*5 = <<8*5=40>>40 cookies to each friend in the second round. Each friend will get 8+40 = <<8+40=48>>48 cookies in total. ### Answer: 48
Expected answer: 45
Correct? No
Problem: John has 3 cameras. Each camera can take 1 picture per second. If John uses all his cameras to take pictures for 5 seconds, how many pictures will he have taken in total?
InternLM-Math Base 7B:
Reasoning: John can take 3*5 = <<3*5=15>>15 pictures in 5 seconds. ### Answer: 15
Expected answer: 15
Correct? Yes
Problem: Tommy has 3 boxes of toys. Each box contains 9 toys. How many toys does Tommy have in total?
InternLM-Math Base 7B:
Reasoning: 9*3 = <<9*3=27>>27 ### Answer: 27
Expected answer: 27
Correct? Yes
Problem: Tommy realized he made a mistake when counting his toys. Instead of having 3 boxes of toys, he actually had 10 boxes. Each box still contains 9 toys. Now, how many toys does Tommy really have?
InternLM-Math Base 7B:
Reasoning: 9*10 = <<9*10=90>>90 ### Answer: 90
Expected answer: 90
Correct? Yes
Problem: Joanna has a clothing store and packs 10 shirts into 5 boxes. How many shirts does each box contain?
InternLM-Math Base 7B:
Reasoning: Each box contains 10/5 = <<10/5=2>>2 shirts. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: What if Joanna originally had 7 shirts instead of 10 and she still wants to distribute them evenly into 5 boxes? How many shirts will each box contain then?
InternLM-Math Base 7B:
Reasoning: Each box will contain 7/5 = <<7/5=1.4>>1.4 shirts. ### Answer: 1.4
Expected answer: 7/5
Correct? Yes
Problem: Jack has 9 scooters. Harry, seeing Jack's love for scooters, decided to give him seven times as many scooters for his birthday. How many scooters did Harry give to Jack?
InternLM-Math Base 7B:
Reasoning: 9x7 = <<9x7=63>>63 ### Answer: 63
Expected answer: 63
Correct? Yes
Problem: Suppose instead of having 9 scooters originally, Jack started with 6 scooters. How many scooters would Harry give to Jack now, following Harry's original plan of giving seven times as many scooters as Jack initially had?
InternLM-Math Base 7B:
Reasoning: 6x7 = <<6x7=42>>42 ### Answer: 42
Expected answer: 42
Correct? Yes
Problem: There are 7 hours on a clock. Each hour has 4 quarters. How many quarters are there in three clocks?
InternLM-Math Base 7B:
Reasoning: 3*4*7 = 84 ### Answer: 84
Expected answer: 84
Correct? Yes
Problem: Liam has 35 scoops of ice cream. If he puts an equal amount of ice cream into 5 cones, how many scoops of ice cream does each cone get?
InternLM-Math Base 7B:
Reasoning: 35/5 = <<35/5=7>>7 Liam puts 7 scoops of ice cream into each cone. ### Answer: 7
Expected answer: 7
Correct? Yes
Problem: In the previous problem, we had 35 scoops of ice cream to start with. But what if we start with only 8 scoops of ice cream, and we are still trying to divide it equally into 5 cones? How many scoops of ice cream would each cone hold then?
InternLM-Math Base 7B:
Reasoning: 8/5 = <<8/5=1.6>>1.6 Each cone would have 1.6 scoops of ice cream. ### Answer: 1.6
Expected answer: 8/5
Correct? Yes
Problem: Billy has 8 toy trains at his house. He went to a train festival and got 9 times more trains than he originally had. How many trains did Billy get at the festival?
InternLM-Math Base 7B:
Reasoning: 8x9= <<8x9=72>>72 Billy got 72 trains at the festival. ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: If Billy originally had 8 toy trains, but at the train festival, he was able to gather 8 times more trains than he originally had instead of 9, how many trains did Billy get at the festival?
InternLM-Math Base 7B:
Reasoning: 8x8= <<8x8=64>>64 Billy got 64 trains at the festival. ### Answer: 64
Expected answer: 64
Correct? Yes
Problem: A librarian decided to arrange books on a shelf. She placed 8 books in a row and made sure every row had the same number of books. How many books were there if the arrangement was square (i.e., the same number of rows as there were books in a row)?
InternLM-Math Base 7B:
Answer: 8
Expected answer: 64
Correct? No
Problem: Lisa had 10 yards of fabric. If it takes 1 yard of fabric to make a skirt, how many skirts can Lisa make?
InternLM-Math Base 7B:
Reasoning: Lisa can make 10/1 = <<10/1=10>>10 skirts. ### Answer: 10
Expected answer: 10
Correct? Yes
Problem: Sarah receives 12 phone calls every day on her work phone. But, she only answers a quarter of those phone calls. How many phone calls does she answer a day?
InternLM-Math Base 7B:
Reasoning: Sarah only answers 12/4 = <<12/4=3>>3 of the phone calls that she receives.
Expected answer: 3
Correct? Yes
Problem: Following up on the previous problem, if for each phone call Sarah answered, she received 11 more calls as a response, how many additional calls did she receive in a day?
InternLM-Math Base 7B:
Reasoning: <<12/4=3>>3 phone calls that Sarah received were answered. For each of these 3 phone calls, she received 11 more phone calls. 3*11 = <<3*11=33>>33 ### Answer: 33
Expected answer: 33
Correct? Yes
Problem: Melanie is planning for a camping trip and she needs 3 sleeping bags for each of her 4 friends. How many sleeping bags does Melanie need in total?
InternLM-Math Base 7B:
Reasoning: Melanie needs 3*4 = <<3*4=12>>12 sleeping bags in total. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: Suppose Melanie originally planned to bring 3 sleeping bags for each of her 6 friends instead of 4, for the camping trip. How many sleeping bags would Melanie need in total for the camping trip now?
InternLM-Math Base 7B:
Reasoning: Melanie needs 3*6 = <<3*6=18>>18 sleeping bags in total. ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: Johnny has 3 times the amount of snowballs that Billy does. If Billy has 6 snowballs, how many snowballs does Johnny have?
InternLM-Math Base 7B:
Answer: 18
Expected answer: 18
Correct? Yes
Problem: Consider now that initially, Johnny had 3 times the amount of snowballs that Billy does, not 5 times. If Billy still has 11 snowballs, how many snowballs does Johnny have now?
InternLM-Math Base 7B:
Answer: 33
Expected answer: 33
Correct? Yes
Problem: In a game, each star is equivalent to 5 points. If Tom collected 1 star, how many points does he have?
InternLM-Math Base 7B:
Reasoning: 1*5= <<1*5=5>>5 ### Answer: 5
Expected answer: 5
Correct? Yes
Problem: Tom decided to play more of the game and managed to collect 4 more stars. Considering that each star is equivalent to 5 points, how many additional points has he earned now?
InternLM-Math Base 7B:
Reasoning: 5*4= <<5*4=20>>20 ### Answer: 20
Expected answer: 20
Correct? Yes
Problem: In the game, what if initially each star was equivalent to 7 points instead of 5? If Tom collected 1 star as before, how many points would he have now?
InternLM-Math Base 7B:
Reasoning: 1*7= <<1*7=7>>7 ### Answer: 7
Expected answer: 7
Correct? Yes
Problem: Captain Jack has 4 cannons on his pirate ship. If each cannon fires 12 cannonballs, how many cannonballs were fired in total?
InternLM-Math Base 7B:
Reasoning: 4 â‹… 12 = <<4â‹…12=48>>48 ### Answer: 48
Expected answer: 48
Correct? Yes
Problem: Given that Captain Jack actually had 4 cannons, but each can fire only 3 cannonballs, how many cannonballs were fired in total now?
InternLM-Math Base 7B:
Reasoning: 4 â‹… 3 = <<4â‹…3=12>>12 ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: Emma has a pack of 10 colored pencils. She wants to have as many colored pencils as the square of the number she currently has. How many colored pencils will she have then?
InternLM-Math Base 7B:
Reasoning: Emma will have 10*10 = <<10*10=100>>100 colored pencils.
Expected answer: 100
Correct? Yes
Problem: Now consider if Emma had started with a pack of only 4 colored pencils instead. If she still wants to have as many colored pencils as the square of the number she currently has, how many colored pencils will she have then?
InternLM-Math Base 7B:
Reasoning: Emma will have 4*4 = <<4*4=16>>16 colored pencils.
Expected answer: 16
Correct? Yes
Problem: Emily had 70 cookies. She decided to pack them in bags with each bag containing 7 cookies. After getting the number of bags, she decided to multiply it by 6 for a camping trip. How many cookies does she need for her intended number of sleeping bag sets?
InternLM-Math Base 7B:
Reasoning: Emily needs 6x7=<<6x7=42>>42 cookies for her intended number of sleeping bag sets.
Expected answer: 60
Correct? No
Problem: Captain Redbeard has 6 cannons on one side of his pirate ship. Each cannon fires 4 cannonballs at a time when the ship goes into battle. During a sea fight, with one shot from each of the cannons on one side of the ship, how many cannonballs are fired in total?
InternLM-Math Base 7B:
Reasoning: 4 cannonballs are fired from each of 6 cannons. 4x6 = <<4x6=24>>24 cannonballs are fired in total. ### Answer: 24
Expected answer: 24
Correct? Yes
Problem: In a different battle, Captain Redbeard decided to increase his firepower and loaded each cannon with 11 cannonballs. With one shot from each of the 6 cannons on one side of his ship, how many cannonballs would be fired in total from that side?
InternLM-Math Base 7B:
Reasoning: 11 cannonballs are fired from each of 6 cannons. 11x6 = <<11x6=66>>66 cannonballs are fired in total. ### Answer: 66
Expected answer: 66
Correct? Yes
Problem: A magical unicorn walks 72 miles every day. If it takes the unicorn 12 hours to cover that distance. How many miles does the unicorn cover every hour?
InternLM-Math Base 7B:
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Expected answer: 6
Correct? No
Problem: Sue has 3 potato plants and each plant yields 10 potatoes. How many potatoes does Sue have in total?
InternLM-Math Base 7B:
Reasoning: <<3*10=30>>Sue has 3*10 = 30 potatoes in total. ### Answer: 30
Expected answer: 30
Correct? Yes
Problem: Suppose that Sue originally planted 3 potato plants instead of 10, and each of those plants still produced 3 potatoes. How many potatoes would Sue have harvested from her original planting?
InternLM-Math Base 7B:
Reasoning: <<3*3=9>>Sue has 3*3 = 9 potatoes in total. ### Answer: 9
Expected answer: 9
Correct? Yes
Problem: An astronaut walks a distance of 20 kilometers per day on the lunar surface. If they decide to only walk for 1/5 of the day, how many kilometers do they cover?
InternLM-Math Base 7B:
Reasoning: The astronaut walks 1/5 of 20/1 = <<1/5 20/1=4>>4 kilometers. ### Answer: 4
Expected answer: 4
Correct? Yes
Problem: Following up on the previous problem, let's say on a particular day, the astronaut decides to increase their walking duration from 1/5 of a day to 12/5 of a day. How many kilometers would they cover on that day?
InternLM-Math Base 7B:
Reasoning: The astronaut walks 12/5 of 20/1 = <<12/5 20/1=24>>24 kilometers. ### Answer: 24
Expected answer: 48
Correct? No
Problem: In a new scenario, let's say the astronaut now walks a distance of 20 kilometers per day on the lunar surface but decides to walk for only 1/6 of the day instead of 1/5. How many kilometers would they cover in this case?
InternLM-Math Base 7B:
Reasoning: The astronaut would now walk 1/6 of 20/1 = <<1/6 20/1=3 1/3>>3 1/3 kilometers. ### Answer: 3 1/3
Expected answer: 10/3
Correct? Yes
Problem: Mr. Lemon has 10 lemons and he wants to evenly distribute them into 5 boxes. How many lemons will there be in each box?
InternLM-Math Base 7B:
Answer: 2
Expected answer: 2
Correct? Yes
Problem: Mr. Lemon decides to add 2 more lemons to each box, because he wants to share more lemons with his friends. How many lemons will there be in each box now?
InternLM-Math Base 7B:
Answer: 4
Expected answer: 4
Correct? Yes
Problem: After some thought, Mr. Lemon considers distributing the ten lemons among six boxes instead of five. How many lemons would there be in each box if he decides to distribute them in this way?
InternLM-Math Base 7B:
Answer: 1.66
Expected answer: 5/3
Correct? No
Problem: A helicopter pad can hold 4 helicopters at a time. The city has decided to build 11 new helicopter pads. How many helicopters can all of the helicopter pads hold when combined?
InternLM-Math Base 7B:
Reasoning: 4 helicopters can be held on each of 11 new helicopter pads. 4*11 = <<4*11=44>>44 helicopters can be held on the 11 new helicopter pads. ### Answer: 44
Expected answer: 44
Correct? Yes
Problem: If each of the helicopters that the city's helicopter pads can hold requires just one helipad to park, how many helipads will be occupied when all the helicopters are parked?
InternLM-Math Base 7B:
Reasoning: 4*11 = <<4*11=44>>44 helicopters can be held on the 11 new helicopter pads. 4*11 = <<4*11=44>>44 helipads will be occupied when all the helicopters are parked. ### Answer: 44
Expected answer: 44
Correct? Yes
Problem: John decided to re-arrange his room and he has a single bed that takes the space of 1 large carpet tile. If his room size requires 12 such carpet tiles fully side by side, how many bed spaces does John's room have?
InternLM-Math Base 7B:
Reasoning: 12-1 = 11. John's room has 11 bed spaces.
Expected answer: 12
Correct? Yes
Problem: In a different layout, John realized he could fit 3 beds in the space currently occupied by 1 large carpet tile due to the smaller size of new bunk beds he purchased. If his room size still requires 12 large carpet tiles side by side, then, how many new bunk beds can he fit in his room now?
InternLM-Math Base 7B:
Reasoning: 12-3 = 9. John can fit 9 new bunk beds in his room.
Expected answer: 36
Correct? No
Problem: Sophie has 8 flowerpots. In each flowerpot, she plans to plant 3 flowers. How many flowers will Sophie plant in total?
InternLM-Math Base 7B:
Reasoning: 8*3 = <<8*3=24>>24 ### Answer: 24
Expected answer: 24
Correct? Yes
Problem: After successfully planting flowers in her 8 flowerpots, Sophie decided to double the total number of flowers she planted. How many flowers does she have now?
InternLM-Math Base 7B:
Reasoning: 2*24 = <<2*24=48>>48 ### Answer: 48
Expected answer: 48
Correct? Yes
Problem: Now imagine if Sophie originally had 12 flowerpots instead of 8. How many flowers would she have planted if she still planted 3 flowers per flowerpot?
InternLM-Math Base 7B:
Reasoning: 12*3 = <<12*3=36>>36 ### Answer: 36
Expected answer: 36
Correct? Yes
Problem: Shawn has 12 gift boxes and each box contains 6 presents inside. How many presents does Shawn have in total?
InternLM-Math Base 7B:
Reasoning: Shawn has 12*6 = <<12*6=72>>72 presents in total. ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: What if Shawn had only 2 gift boxes instead of 12 and each box still contained 6 presents. How many presents does Shawn have in total now?
InternLM-Math Base 7B:
Reasoning: Shawn has 2*6 = <<2*6=12>>12 presents in total. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: In the factory, each RoboFalcon assembler can build 8 robots per hour. How many robots can it build in 12 hours?
InternLM-Math Base 7B:
Reasoning: 8*12 = <<8*12=96>>96 ### Answer: 96
Expected answer: 96
Correct? Yes
Problem: Suppose the RoboFalcon assembler had a minor update and the efficiency slightly reduced. Now, it can only build 6 robots per hour. How many robots can it build in 12 hours now?
InternLM-Math Base 7B:
Reasoning: 6*12 = <<6*12=72>>72 ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: Tom has setup 2 tents and each tent has 8 poles. If each pole has 6 strengths attached, how many strings are there in total?
InternLM-Math Base 7B:
Reasoning: 8 poles in 1 tent. 2 tents. 8*2 = <<8*2=16>>16 16 poles. 6 strength in 1 pole. 6*16 = <<6*16=96>>96 ### Answer: 96
Expected answer: 96
Correct? Yes
Problem: Let's change the scenario a bit. What if Tom had set up only 2 tents but each tent had 3 poles instead of 8. If each pole still has 6 strings attached, how many strings are there in total now?
InternLM-Math Base 7B:
3 poles in 1 tent. 2 tents. 3*2 = <<3*2=6>>6 6 poles. 6 strength in 1 pole. 6*6 = <<6*6=36>>36 ### Answer: 36
Expected answer: 36
Correct? Yes
Problem: Jane received a set of 10 camera filters as a gift. She decided to equally distribute these between her 5 cameras. How many filters would each camera get?
InternLM-Math Base 7B:
Expected answer: 2
Correct? No
Problem: An elephant takes 1 hour to drink 1 gallon of water. If the elephant spends 1 hour by the waterhole, how many gallons of water did the elephant drink?
InternLM-Math Base 7B:
Reasoning: The elephant drinks 1/1 = 1gallon of water in 1 hour. The elephant drinks 1*1 = 1gallon of water in 1 hour.
Expected answer: 1
Correct? Yes
Problem: Given that each gallon of water weighs approximately 1 pound, if the elephant drank 1 gallon of water, how many pounds did the elephant gain from drinking?
InternLM-Math Base 7B:
Reasoning: The elephant gained 1pound from drinking 1gallon of water.
Expected answer: 1
Correct? Yes
Problem: If instead of spending 1 hour by the waterhole, the elephant spent 5 hours there, how many gallons of water would the elephant have drank?
InternLM-Math Base 7B:
Reasoning: The elephant would have drunk 1*5=5gallons of water in 5 hours.
Expected answer: 5
Correct? Yes
Problem: If one gallon of milk can fill up 2 large containers, how many gallons of milk will be needed to fill 4 large containers?
InternLM-Math Base 7B:
Reasoning: 1/2 = <<1/2=0.5>>0.5, so 4*0.5 = <<4*0.5=2>>2.
Expected answer: 2
Correct? Yes
Problem: Now, instead of having 4 large containers to fill with milk, imagine if we had 11 containers instead. Given the same rate of 2 containers per gallon, how many gallons of milk will we need to fill all 11 containers?
InternLM-Math Base 7B:
Reasoning: 1/2 = <<1/2=0.5>>0.5, so 11*0.5 = <<11*0.5=5.5>>5.5.
Expected answer: 11/2
Correct? Yes
Problem: Eddy the pirate has 3 pieces of gold. For every gold coin he has, he gets a matching emerald from the captain. How many emeralds does Eddy have now?
InternLM-Math Base 7B:
Reasoning: Eddy has 3/3 = <<3/3=1>>1 emerald for every gold coin. Eddy has 3*1 = <<3*1=3>>3 emeralds.
Expected answer: 3
Correct? Yes
Problem: Eddy was very happy with his emerald collection. Seeing this, the captain decided to award him with 4 rubies for each emerald he had. How many rubies did Eddy get from the captain?
InternLM-Math Base 7B:
Reasoning: Eddy has 3/3 = <<3/3=1>>1 emerald for every gold coin. Eddy has 3*1 = <<3*1=3>>3 emeralds. Eddy has 3*4 = <<3*4=12>>12 rubies.
Expected answer: 12
Correct? Yes
Problem: A dolphin can jump 20 feet above water. Given that every 10 feet is considered a level, what level does the dolphin reach when it jumps?
InternLM-Math Base 7B:
Reasoning: 20/10 = <<20/10=2>>2 ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: After observing the dolphin's jumping level, researchers discovered that dolphins can increase their jump level by 11 times when aided by a strong wave. What would be the dolphin's level if it gets help from a strong wave?
InternLM-Math Base 7B:
Reasoning: 2*11 = <<2*11=22>>22 ### Answer: 22
Expected answer: 22
Correct? Yes
Problem: In light winds, the jumping level of the dolphin decreases to 20 feet instead of the usual 20 feet per level. Given that every 11 feet is still considered a level, what level does the dolphin now reach when it jumps in light winds?
InternLM-Math Base 7B:
Reasoning: 20/11 = <<20/11=1.8>>1.8 The jumping level of the dolphin in light winds is 1.8. ### Answer: 1.8
Expected answer: 20/11
Correct? No
Problem: Jill has 28 balls which she wants to distribute equally among her 7 friends. How many balls will each friend get?
InternLM-Math Base 7B:
Reasoning: 28/7 = <<28/7=4>>4. Each friend will get 4 balls. ### Answer: 4
Expected answer: 4
Correct? Yes
Problem: In the previous problem, Jill divided her 28 balls equally among her 7 friends. But what if Jill decided to divide the 28 balls equally among 10 friends instead? How many balls will each friend get then?
InternLM-Math Base 7B:
Reasoning: 28/10 = <<28/10=2.8>>2.8. Each friend will get 2.8 balls. ### Answer: 2.8
Expected answer: 14/5
Correct? Yes
Problem: In a robotic factory, there are 8 machines on the assembly line. Each of these machines can manufacture the same number of robots per day as there are machines. How many robots can the entire factory produce in one day?
InternLM-Math Base 7B:
|user||system|
Expected answer: 64
Correct? No
Problem: In a geometry class, Maya was given a task to divide a line segment into smaller segments. Initially, the line segment was 15 cm long. She decided to cut it into equal parts each 5 cm long. How many segments did Maya get in the end?
InternLM-Math Base 7B:
Reasoning: 15/5 = <<15/5=3>>3 Maya got 3 segments in the end. ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: Maya realized that if she had divided the original 15 cm line segment into 7 cm pieces, the number of segments would have been different. If she cut the 15 cm line into equal pieces of 7 cm each, how many segments would she have obtained then?
InternLM-Math Base 7B:
Reasoning: 15/7 = <<15/7=2.1...>>2.1 Maya would have got 2.1... segments in the end. ### Answer: 2.1
Expected answer: 15/7
Correct? No
Problem: Tommy has 5 types of cheese. He multiplies this by 5 to provide variety on his cheese platter for a party. How many types of cheese does Tommy have for his cheese platter now?
InternLM-Math Base 7B:
Reasoning: Tommy has 5*5 = <<5*5=25>>25 types of cheese for his cheese platter. ### Answer: 25
Expected answer: 25
Correct? Yes
Problem: If Tommy originally had 7 types of cheese instead of 5, and he still intended to multiply this by 5 to provide variety on his cheese platter, how many types of cheese would Tommy have for his cheese platter then?
InternLM-Math Base 7B:
Reasoning: Tommy has 7*5 = <<7*5=35>>35 types of cheese for his cheese platter. ### Answer: 35
Expected answer: 35
Correct? Yes
Problem: The width of a river increases by 10 feet every year. After 9 years, how much has the width of the river increased?
InternLM-Math Base 7B:
Reasoning: The width of the river has increased 9 â‹… 10 = <<9â‹…10=90>>90 feet. ### Answer: 90
Expected answer: 90
Correct? Yes
Problem: If the width of the river only increases by 10 feet every 3 years instead of every year, how much does the river's width increase after 9 years?
InternLM-Math Base 7B:
Reasoning: The width of the river has increased 9 â‹… 3 = <<9â‹…3=27>>27 feet. ### Answer: 27
Expected answer: 30
Correct? No
Problem: Jessica has a collection of stuffed animals. She currently groups them in sets of 4. If she has 20 stuffed animals in total, how many groups does she have?
InternLM-Math Base 7B:
Reasoning: 20/4 = <<20/4=5>>5 ### Answer: 5
Expected answer: 5
Correct? Yes
Problem: Originally, Jessica decided to group her collection of 20 stuffed animals into sets of 4. But what if she had originally decided to group her stuffed animals into sets of 4, but she only had 9 stuffed animals instead of 20? How many groups would she have then?
InternLM-Math Base 7B:
Reasoning: 9/4 = <<9/4=2.25>>2.25 ### Answer: 2.25
Expected answer: 9/4
Correct? Yes
Problem: Tom has a set of 5 drums. Each of the drums has a length of 8 inches. Find out, How long would it be if he put all of his drums side by side?
InternLM-Math Base 7B:
You are a mathematics teacher that solves all problems correctly and explains your reasoning. Write your final answer in the last line of your response. The last line should always be formatted as follows: "### Answer: <<your final answer here.>>".
Expected answer: 40
Correct? No
Problem: Jack has 5 apples and decides to multiply it by 6 to get the total number of oranges he can trade them for. How many oranges can he get?
InternLM-Math Base 7B:
Reasoning: 5x6=30 ### Answer: 30
Expected answer: 30
Correct? Yes
Problem: Now consider if Jack started with 12 apples instead of 5. He decides to multiply it by 6 again to see how many oranges he can get. How many oranges can he now get?
InternLM-Math Base 7B:
Reasoning: 12x6=72 ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: A set of marker pens come with 6 different colors. If a whole pack contains 72 marker pens, how many sets of different colors are there in it?
InternLM-Math Base 7B:
Reasoning: 6*12=<<6*12=72>>72 ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: A dragon guards a cave that contains 80 pieces of gold. The dragon decided to equally distribute the gold into 8 separate piles. How many pieces of gold does each pile contain?
InternLM-Math Base 7B:
The dragon distributed 80/8 = <<80/8=10>>10 pieces of gold in each pile. ### Answer: 10
Expected answer: 10
Correct? Yes
Problem: After dividing the gold into 8 piles, the dragon decided to protect the most important treasure trove, which contains 4 times the number of gold pieces in each pile. How much gold is in the dragon's special pile?
InternLM-Math Base 7B:
The dragon's special pile contains 4 × 10 = <<4 × 10=40>>40 gold pieces. ### Answer: 40
Expected answer: 40
Correct? Yes
Problem: Let's reconsider the original situation. Suppose the dragon initially had 80 pieces of gold but decided to divide them into 11 piles instead of 8. How many pieces of gold would each pile contain in this scenario?
InternLM-Math Base 7B:
The dragon distributed 80/11 = <<80/11=7.272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727272727
Expected answer: 80/11
Correct? Yes
Problem: John wants to divide his camping area of 44 square meters into 11 equal sections. Each of these sections would host a tent. If each tent can accommodate 12 campers, how many campers can camp in total?
InternLM-Math Base 7B:
Reasoning: 11/12 = <<11/12=0.9>>0.9 John can accommodate 0.9*44 = <<0.9*44=39.6>>39.6 campers in total. ### Answer: 39.6
Expected answer: 48
Correct? No
Problem: A tiger can travel 6 miles in an hour. How far can it travel in 3 hours?
InternLM-Math Base 7B:
Reasoning: 3*6= <<3*6=18>>18 ### Answer: 18
Expected answer: 18
Correct? Yes
Problem: In the previous problem we found out that a tiger can travel 6 miles in an hour. But what if the tiger could cover more ground in the same time span? If the tiger can travel 7 times as far in an hour, how far can it travel then?
InternLM-Math Base 7B:
Reasoning: 6*7= <<6*7=42>>42 ### Answer: 42
Expected answer: 42
Correct? Yes
Problem: A number sets of 6 are multiplied by 7. What is the resulting product?
InternLM-Math Base 7B:
Reasoning: 6*7= <<6*7=42>>42 ### Answer: 42
Expected answer: 42
Correct? Yes
Problem: Following the previous problem. Consider that instead of multiplying 6 sets by 7, we multiply 4 sets by 7. What is the resulting product now?
InternLM-Math Base 7B:
Reasoning: 4*7= <<4*7=28>>28 ### Answer: 28
Expected answer: 28
Correct? Yes
Problem: A doctor works double shift every day. If one shift is 6 hours, for how many hours does the doctor work each day?
InternLM-Math Base 7B:
Reasoning: 6*2=<<6*2=12>>12 ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: Following his extra shifts, the doctor wants to reduce his workload. He decides to work 11 hours a day instead. How many hours does he work in a two-day period now?
InternLM-Math Base 7B:
Reasoning: 11*2=<<11*2=22>>22 ### Answer: 22
Expected answer: 22
Correct? Yes
Problem: A farmer plants 6 seeds in each row of his field. If he has 11 rows total, how many seeds did he plant?
InternLM-Math Base 7B:
Reasoning: 6*11 = <<6*11=66>>66 ### Answer: 66
Expected answer: 66
Correct? Yes
Problem: Mommy has a tradition that for every month, she buys 5 new toys for her baby. If the baby is 10 months old, how many toys has Mommy bought in total?
InternLM-Math Base 7B:
Reasoning: Mommy has bought 5x10 = <<5x10=50>>50 toys in total. ### Answer: 50
Expected answer: 50
Correct? Yes
Problem: After reflecting on her toy buying habits, Mommy realizes that she bought too many toys in the beginning. Instead of buying 5 new toys every month for 10 months, she now remembers that there was a month when she didn't buy any toys. Therefore, she only bought 5 toys per month for 9 months. How many toys did she actually buy during that period?
InternLM-Math Base 7B:
Reasoning: Mommy has bought 5x9 = <<5x9=45>>45 toys in total. ### Answer: 45
Expected answer: 45
Correct? Yes