Problem: What would the result be if instead of raising 5 to the 4th power, you raised the number 4 to the 4th power?

InternLM-Math Base 7B:

  Reasoning: 4*4*4*4= <<4*4*4*4=256>>256
### Answer: 256

Expected answer: 256

Correct? Yes

Problem: What would the outcome be if we raise 6 to the power of 3, instead of 9?

InternLM-Math Base 7B:

  Reasoning: 6^3 = 6*6*6 = <<6*6*6=216>>216
### Answer: 216

Expected answer: 216

Correct? Yes

Problem: What is the value if we are cubing 7 instead of 5?

InternLM-Math Base 7B:

  Reasoning: 7*7*7=7^3=<<7^3=343>>343
### Answer: 343

Expected answer: 343

Correct? Yes

Problem: What would be the result if we raise 8 to the power of 2 instead of 9?

InternLM-Math Base 7B:

  Reasoning: 8^2 = 8*8 = <<8*8=64>>64
### Answer: 64

Expected answer: 64

Correct? Yes

Problem: In the previous problem, you found the value of 3 to the power of 3. Now, consider what would happen if the base was 5 instead of 3. What is the value of 5 to the power of 3?

InternLM-Math Base 7B:

  Reasoning: 5 to the power of 3 is 5 × 5 × 5 = 125.

Expected answer: 125

Correct? Yes

Problem: Considering our previous problem, if instead of 9 we raise 4 to the power of 2, what would be the value?

InternLM-Math Base 7B:

  Reasoning: 4^2 = <<4^2=16>>16
### Answer: 16

Expected answer: 16

Correct? Yes

Problem: After learning about the calculation of 9^2, can you now tell me what is the result of 7^2?

InternLM-Math Base 7B:

  Reasoning: 7^2 = <<7*7=49>>49
### Answer: 49

Expected answer: 49

Correct? Yes

Problem: If we changed the base in the previous question to 4 while keeping the exponent as 3, what value would we get for 4^3?

InternLM-Math Base 7B:

  Reasoning: 4^3 = 4x4x4 = <<4x4x4=64>>64
### Answer: 64

Expected answer: 64

Correct? Yes

Problem: What would the value be if instead of 6, we have 4 squared or 4^2?

InternLM-Math Base 7B:

  Reasoning: 4^2 = <<4*4=16>>16
### Answer: 16

Expected answer: 16

Correct? Yes

Problem: In the previous problem, we found the cube of 3. Now, what would be the value if we raise 6 to the power of 3 instead?

InternLM-Math Base 7B:

  Reasoning: 6^3 = <<6^3=216>>216
### Answer: 216

Expected answer: 216

Correct? Yes

Problem: What happens if we instead consider 4 raised to the power of 2?

InternLM-Math Base 7B:

  Reasoning: 4x4 = <<4x4=16>>16.

Expected answer: 16

Correct? Yes

Problem: Earlier, we found out the value for 9 raised to the third power, right? Now, considering the same scenario, what would be the value if you raise 5 instead of 9 to the power of 3?

InternLM-Math Base 7B:

 5^3 = <<5^3=125>>125
### Answer: 125

Expected answer: 125

Correct? Yes

Problem: In the previous situation we evaluated the square of 2. Now, consider what would the value be if instead of 2, we needed to evaluate the square of 5?

InternLM-Math Base 7B:

  Reasoning: 5^2 = <<5*5=25>>25
### Answer: 25

Expected answer: 25

Correct? Yes

Problem: Following the previous question, what would be the value if we raised the number 2 to the power of 2 instead of 7?

InternLM-Math Base 7B:

  Reasoning: 2^2 = <<2*2=4>>4
### Answer: 4

Expected answer: 4

Correct? Yes

Problem: In the previous problem, we evaluated 8 raised to the power of 3. What if we changed the base and considered 7 instead of 8? What is the value of 7 raised to the power of 3?

InternLM-Math Base 7B:

  Reasoning: 7^3 = 7x7x7 = <<7x7x7=343>>343
### Answer: 343

Expected answer: 343

Correct? Yes

Problem: Now, what if instead you were to calculate the square of 8? What would be the value of 8^2?

InternLM-Math Base 7B:

  Reasoning: 8^2 = <<8*8=64>>64
### Answer: 64

Expected answer: 64

Correct? Yes

Problem: What would be the result if instead of raising 9 to the power of 2, we raised 6 to the power of 2?

InternLM-Math Base 7B:

  Reasoning: 6^2 = <<6^2=36>>36
### Answer: 36

Expected answer: 36

Correct? Yes

Problem: What is the value if we consider a cube with a side length of 8 units instead of 5 units?

InternLM-Math Base 7B:

  Reasoning: 8^3 = <<8*8*8=512>>512
### Answer: 512

Expected answer: 512

Correct? Yes

Problem: What is the outcome when 4 is raised to the power of 2, instead of 5?

InternLM-Math Base 7B:

  Reasoning: 4^2 = <<4^2=16>>16
### Answer: 16

Expected answer: 16

Correct? Yes

Problem: Following from the previous problem, what would be the value if we raised 8 to the power of 2 instead of 5?

InternLM-Math Base 7B:

  Reasoning: 8*8 = <<8*8=64>>64
### Answer: 64

Expected answer: 64

Correct? Yes

Problem: You previously calculated 2 raised to the power of 3. Now, what would be the result if we raise 10 to the power of 3 instead?

InternLM-Math Base 7B:

  Reasoning: 10 raised to the power of 3 = 10 × 10 × 10 = 1,000.

Expected answer: 1000

Correct? Yes

Problem: Given what you have learned, what happens if you take the new number 3 and raise it to the power of 3 instead?

InternLM-Math Base 7B:

  Reasoning: 3^3 = 3*3*3 = 9
### Answer: 9

Expected answer: 27

Correct? No

Problem: What would the result be if we change the exponent from 9 to 6 and compute the value of 1 raised to the power of 6 instead?

InternLM-Math Base 7B:

  Reasoning: 1^6 = <<1^6=1>>1
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: Previously, we raised 8 to the power of 3. Now, what if we raise 5 to the power of 3, what would be the result?

InternLM-Math Base 7B:

  Reasoning: 5^3 = 5*5*5 = 125
### Answer: 125

Expected answer: 125

Correct? Yes

Problem: Given the understanding that 1 raised to the power of 2 gives us 1, what would be the result if we raised 4 to the power of 2 instead?

InternLM-Math Base 7B:

  Reasoning: 4<<4=2>>2 to the power of 2 = 4
### Answer: 4

Expected answer: 16

Correct? No

Problem: Previously, you evaluated 2^2. Now, what's the result of performing an identical operation, but instead of squared (2^2), it is raised to the 7th power (2^7)?

InternLM-Math Base 7B:

  Reasoning: 2^7 = <<2*2*2*2*2*2*2=128>>128
### Answer: 128

Expected answer: 128

Correct? Yes

Problem: What would be the result if we took one instead of eight and raised it to the power of 2?

InternLM-Math Base 7B:

  Reasoning: 1^2 = 1
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: What would the result be if you raised 7 to the power of 3 instead of 2 in the previous problem?

InternLM-Math Base 7B:

  Reasoning: 7 raised to the power of 3 = 7 × 7 × 7 = 343.

Expected answer: 343

Correct? Yes

Problem: What would be the value if you squared 1 instead of 8?

InternLM-Math Base 7B:

  Reasoning: 1^2 = 1
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: Following the previous problem, what would be the result if we evaluate 6 to the power of 1 instead of 3?

InternLM-Math Base 7B:

  Reasoning: 6 to the power of 1 = 6x1 = 6
### Answer: 6

Expected answer: 6

Correct? Yes

Problem: Now, consider what will be the value when 7 is not just raised to the power of 1, but to the power of 3 instead?

InternLM-Math Base 7B:

  Reasoning: 7^3 = <<7^3=343>>343
### Answer: 343

Expected answer: 343

Correct? Yes

Problem: In the previous problem, you found the result of 2 raised to the power of 2. Now, what is the result of 4 raised to the power of 2?

InternLM-Math Base 7B:

  Reasoning: 4 raised to the power of 2 = 4x4 = 16.
### Answer: 16

Expected answer: 16

Correct? Yes

Problem: Following up on our previous question, what would be the result if we raised 10, instead of 4, to the power of 2?

InternLM-Math Base 7B:

  Reasoning: 10^2 = <<10*10=100>>100
### Answer: 100

Expected answer: 100

Correct? Yes

Problem: What would be the value if instead of 9^2, we calculated 4^2?

InternLM-Math Base 7B:

  Reasoning: 4^2 = <<4*4=16>>16
### Answer: 16

Expected answer: 16

Correct? Yes

Problem: What is the value if we consider raising 7 to the power of 3 instead of 5^3?

InternLM-Math Base 7B:

  Reasoning: 7*7*7= <<7*7*7=343>> 343
### Answer: 343

Expected answer: 343

Correct? Yes

Problem: What would be the result if instead of raising 7 to the power of 3, you raised 9 to the power of 3?

InternLM-Math Base 7B:

  Reasoning: 9^3=9*9*9= <<9*9*9=729>>729
### Answer: 729

Expected answer: 729

Correct? Yes

Problem: Suppose instead of 2 units, you only had a single unit. What would be the result if you squared that single unit (1^2)?

InternLM-Math Base 7B:

  Reasoning: 1^2 = 1*1 = <<1*1=1>>1
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: Now imagine if we raised 3 to the power of 3 instead, what would be the result?

InternLM-Math Base 7B:

  Reasoning: 3^3 = <<3^3=27>>27
### Answer: 27

Expected answer: 27

Correct? Yes

Problem: In the previous problem, we evaluated 2^3. Now consider if it were 3^3 instead. What value would that give?

InternLM-Math Base 7B:

  Reasoning: 3^3 = <<3*3*3=27>>27
### Answer: 27

Expected answer: 27

Correct? Yes

Problem: What would the value be if we have 6^3 instead of 7^3?

InternLM-Math Base 7B:

  Reasoning: 6*6*6= <<6*6*6=216>>216
### Answer: 216

Expected answer: 216

Correct? Yes

Problem: What is the result if we have 8 groups, not 10, of spiders, each group having a power of 2?

InternLM-Math Base 7B:

  Reasoning: 8^2 = <<8*8=64>>64
### Answer: 64

Expected answer: 64

Correct? Yes

Problem: What if, instead of 1, the base was changed to 6? What would be the result of 6 raised to the power of 2?

InternLM-Math Base 7B:

  Reasoning: 6^2 = 6*6 = 36
### Answer: 36

Expected answer: 36

Correct? Yes

Problem: Now consider this: What would be the result if we were to raise 7 to the power of 3 instead of 9? Calculate 7^3.

InternLM-Math Base 7B:

  Reasoning: 7^3 = <<7*7*7=343>>343
### Answer: 343

Expected answer: 343

Correct? Yes

Problem: What is 3^2? In other words, if now you're considering 3 instances of a number being multiplied by itself instead of the single instance we previously evaluated, what would the new result be?

InternLM-Math Base 7B:

  Reasoning: 3^2 = 3*3 = 9
### Answer: 9

Expected answer: 9

Correct? Yes

Problem: What would the result be if we now consider 1 raised to the power 2 instead of 2 raised to the power 2?

InternLM-Math Base 7B:

  Reasoning: 1 raised to the power 2 = 1 ⋅ 1 = 1
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: What happens to the result when instead of squaring 4, you square 7?

InternLM-Math Base 7B:

  Reasoning: 7 squared = <<7^2=7*7=49>>49
### Answer: 49

Expected answer: 49

Correct? Yes

Problem: What would be the result if we raise 8 instead of 7 to the power of 3?

InternLM-Math Base 7B:

  Reasoning: 8*8*8= <<8*8*8=512>>512
### Answer: 512

Expected answer: 512

Correct? Yes

Problem: Following the previous question, consider that instead of taking 4^3, we take 5^3. What is now the value?

InternLM-Math Base 7B:

  Reasoning: 5^3 = <<5^3=125>>125
### Answer: 125

Expected answer: 125

Correct? Yes

Problem: What would be the value if you raised 7 to the power of 2 instead of 1?

InternLM-Math Base 7B:

  Reasoning: 7^2 = 7*7 = 49
### Answer: 49

Expected answer: 49

Correct? Yes

Problem: Suppose you originally had 3 square blocks instead of 6. What is the result of squaring the number of these blocks now, i.e., what is 3^2?

InternLM-Math Base 7B:

  Reasoning: 3*3 = <<3*3=9>>9
### Answer: 9

Expected answer: 9

Correct? Yes

Problem: In the previous problem, we calculated the square of 2. But what if we had 3 instead of 2 to begin with? What would be the result of 3 raised to the power of 2?

InternLM-Math Base 7B:

  Reasoning: 3 raised to the power of 2 = 3x3 = 9.
### Answer: 9

Expected answer: 9

Correct? Yes

Problem: Now, consider what will be the value if instead of 4, we square 9? What will 9^2 be?

InternLM-Math Base 7B:

  Reasoning: 9^2 = <<9*9=81>>81
### Answer: 81

Expected answer: 81

Correct? Yes

Problem: Following the previous problem, what if, instead of 3, we raised 8 to the power of 2? What would be the value?

InternLM-Math Base 7B:

  Reasoning: 8^2 = <<8*8=64>>64
### Answer: 64

Expected answer: 64

Correct? Yes

Problem: What would be the result if we change the base number from 10 to 9, and compute 9 raised to the power of 3?

InternLM-Math Base 7B:

  Reasoning: 9^3 = 729
### Answer: 729

Expected answer: 729

Correct? Yes

Problem: Following our previous calculation, let's change the numbers a bit. What's the value now if we evaluate 10^1?

InternLM-Math Base 7B:

  Reasoning: 10^1 = <<10^1=10>>10
### Answer: 10

Expected answer: 10

Correct? Yes

Problem: What if instead of elevating 7 to the power of 3, we changed the base and elevated 2 to the power of 3? What would be the result then?

InternLM-Math Base 7B:

  Reasoning: 2^3 = 2*2*2 = <<2*2*2=8>>8
### Answer: 8

Expected answer: 8

Correct? Yes

Problem: What happens if we consider 6 instead of 2 and raise it to the power of 2?

InternLM-Math Base 7B:

  Reasoning: 6 raised to the power of 2 = 6x6 = 36.
### Answer: 36

Expected answer: 36

Correct? Yes

Problem: Consider the original finding where we raised 5 to the power of 4. Now, what would be the result if we raised 1 to the power of 4 instead?

InternLM-Math Base 7B:

  Reasoning: 1^4=1*1*1*1=1
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: Considering the previous problem where we calculated 3^5, what would be the result if we instead calculated 2^5?

InternLM-Math Base 7B:

  Reasoning: 2^5 = 2x2x2x2x2 = <<2x2x2x2x2=32>>32
### Answer: 32

Expected answer: 32

Correct? Yes

Problem: What would be the result if we raised 5 to the power of 2 instead of 2?

InternLM-Math Base 7B:

  Reasoning: 2^2 = 2*2=4
5^2 = 5*5=25
### Answer: 25

Expected answer: 25

Correct? Yes

Problem: What would be the value if originally, instead of 4^2, it was calculated as 9^2?

InternLM-Math Base 7B:

  Reasoning: 9^2 = <<9*9=81>>81
### Answer: 81

Expected answer: 81

Correct? Yes

Problem: What would be the value if we considered 7^2 instead of 6^2?

InternLM-Math Base 7B:

  Reasoning: 7^2 = <<7*7=7^2=49>>49
### Answer: 49

Expected answer: 49

Correct? Yes

Problem: What is the result if we replace the base number from the previous problem (which was 10), with 7? In other words, what is the value of 7^3?

InternLM-Math Base 7B:

  Reasoning: 7^3 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7*7 = 7*7

Expected answer: 343

Correct? Yes

Problem: Following up from your last computation, how would the outcome change if you raised 6 to the power of 2 instead of 4?

InternLM-Math Base 7B:

  Reasoning: 6^2 = <<6^2=6*6=36>>36
### Answer: 36

Expected answer: 36

Correct? Yes

Problem: What would be the outcome if instead of 10, we raised 1 to the power of 3?

InternLM-Math Base 7B:

  Reasoning: 1^3 = 1
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: Following up from the previous question, what would the result be if we raised 3 to the power of 3 instead of 7?

InternLM-Math Base 7B:

  Reasoning: 3*3*3= <<3*3*3=27>>27
### Answer: 27

Expected answer: 27

Correct? Yes

Problem: What would the result be if instead of raising 8 to the power of 2, we raised 7 to the power of 2?

InternLM-Math Base 7B:

  Reasoning: 7^2 = <<7*7=49>>49
### Answer: 49

Expected answer: 49

Correct? Yes

Problem: What would be the result if instead of cubing 7, you cubed 6?

InternLM-Math Base 7B:

  Reasoning: 6^3 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6*6 = 6*6

Expected answer: 216

Correct? Yes

Problem: Considering the same calculation, what is the result if we raise 6 to the power of 2 instead of 8?

InternLM-Math Base 7B:

  Reasoning: 6^2 = <<6*6=36>>36
### Answer: 36

Expected answer: 36

Correct? Yes

Problem: Previously, you computed the value of 2 raised to the power 3. Now, calculate what happens if you raise 5 to the power 3 instead.

InternLM-Math Base 7B:

  Reasoning: 5 raised to the power 3 = 5⋅5⋅5 = 125
### Answer: 125

Expected answer: 125

Correct? Yes

Problem: In continuation of the previous problem, now calculate the value of 4 raised to the power of 2.

InternLM-Math Base 7B:

  Reasoning: 4^2 = <<4^2=4*4=16>>16
### Answer: 16

Expected answer: 16

Correct? Yes

Problem: What would happen if instead of 7, we raised 10 to the power of 2?

InternLM-Math Base 7B:

  Reasoning: 10^2=10x10=100
### Answer: 100

Expected answer: 100

Correct? Yes

Problem: Now consider what happens if instead of raising 10 to the power of 2, we instead raise 2 to the power of 2. What would be the value?

InternLM-Math Base 7B:

  Reasoning: 2^2 = <<2^2=4>>4
### Answer: 4

Expected answer: 4

Correct? Yes

Problem: What would be the value if you raise 9 to the power of 2 instead of 6?

InternLM-Math Base 7B:

  Reasoning: 9^2 = <<9*9=9^2=81>>81
### Answer: 81

Expected answer: 81

Correct? Yes

Problem: What would be the result if, instead of 3, we raised 5 to the power of 3?

InternLM-Math Base 7B:

  Reasoning: 5^3 = 5x5x5 = 125
### Answer: 125

Expected answer: 125

Correct? Yes

Problem: What would be the result if we raised 9 to the power of 3 instead of 1?

InternLM-Math Base 7B:

  Reasoning: 9^3 = 9*9*9 = 729
### Answer: 729

Expected answer: 729

Correct? Yes

Problem: What would be the value if we instead raised 3 to the power of 1?

InternLM-Math Base 7B:

  Reasoning: 3^1 = 3
### Answer: 3

Expected answer: 3

Correct? Yes

Problem: Following the previous problem, what would be the result if we consider 3 raised to the power of 1?

InternLM-Math Base 7B:

  Reasoning: 3^1 = <<3^1=3>>3
### Answer: 3

Expected answer: 3

Correct? Yes

Problem: What is the result if instead of cubic value of 8, we calculate the cubic value of 1, expressed as 1^3?

InternLM-Math Base 7B:

  Reasoning: 1^3 = 1 × 1 × 1 = 1
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: Following our previous calculation of 9^2, let's change the number. What is the value of 5^2?

InternLM-Math Base 7B:

  Reasoning: 5^2 = <<5*5=25>>25
### Answer: 25

Expected answer: 25

Correct? Yes

Problem: What is the result if the base 2 is raised to the power of 1 instead of 2?

InternLM-Math Base 7B:

  Reasoning: 2^1 = <<2*1=2>>2
### Answer: 2

Expected answer: 2

Correct? Yes

Problem: If we reconsider the previous concept but instead use 3 as the base, what would be the value of 3 squared?

InternLM-Math Base 7B:

  Reasoning: 3 squared = 3*3 = 9
### Answer: 9

Expected answer: 9

Correct? Yes

Problem: What is the square of 7?

InternLM-Math Base 7B:

  Reasoning: The square of 7 = 7x7 = 49
### Answer: 49

Expected answer: 49

Correct? Yes

Problem: In the previous problem, you calculated the value when 8 was raised to the power of 3. What would the value be if instead we raise 7 to the power of 3?

InternLM-Math Base 7B:

  Reasoning: 7^3 = 7 ⋅ 7 ⋅ 7 = <<7 ⋅ 7 ⋅ 7=343>>343
### Answer: 343

Expected answer: 343

Correct? Yes

Problem: What happens if we change the situation a bit and instead of 3, we use 2 and raise it to the power of 3? What would be the result?

InternLM-Math Base 7B:

  Reasoning: 2^3 = <<2^3=8>>8
### Answer: 8

Expected answer: 8

Correct? Yes

Problem: What would the cube be if we considered 3 instead of 9?

InternLM-Math Base 7B:

  Reasoning: 3*3*3= <<3*3*3=27>>27
### Answer: 27

Expected answer: 27

Correct? Yes

Problem: In the previous problem, you found the result of raising 9 to the third power. Now, what if instead of raising 9, you raise 3 to the third power? What would be the result then?

InternLM-Math Base 7B:

  Reasoning: 3 to the 3 power is 3x3x3. 3x3x3 = 9. ### Answer: 9

Expected answer: 27

Correct? No

Problem: "What would be the result if instead of raising 6 to the power of 3, we raised 10 to the power of 3?"

InternLM-Math Base 7B:

  Reasoning: 10*10*10=<<10*10*10=1000>>1000
### Answer: 1000

Expected answer: 1000

Correct? Yes

Problem: What would the result be if we squared a smaller number, like 4^2?

InternLM-Math Base 7B:

  Reasoning: 4^2 = <<4*4=16>>16
### Answer: 16

Expected answer: 16

Correct? Yes

Problem: Continuing from the previous question, what would be the value if instead of 8 raised to the power of 2, we now have 10 raised to the power of 2?

InternLM-Math Base 7B:

  Reasoning: 10 raised to the power of 2 is 10*10 = <<10*10=100>>100.
### Answer: 100

Expected answer: 100

Correct? Yes

Problem: Based on the previous problem, let's consider a different scenario. What will be the value when 2 raised to the power of 3 instead of 10?

InternLM-Math Base 7B:

  Reasoning: 2^3 = 8
### Answer: 8

Expected answer: 8

Correct? Yes

Problem: Now reflect on the previous problem but this time think about what would happen if it was 7 that was raised to the power of 3. What would be the value then?

InternLM-Math Base 7B:

  Reasoning: 7^3 = <<7^3=343>>343
### Answer: 343

Expected answer: 343

Correct? Yes

Problem: What would be the result if there was only 1 number instead of 7, and it was raised to the power of 3?

InternLM-Math Base 7B:

  Reasoning: 1*1*1= 1
### Answer: 1

Expected answer: 1

Correct? Yes

Problem: Following on from the previous question, what would the outcome be if we replaced 7 with 9 in our exponent calculation? In other words, what is the value of 9^3?

InternLM-Math Base 7B:

  Reasoning: 9*9*9= <<9*9*9=729>>729
### Answer: 729

Expected answer: 729

Correct? Yes

Problem: What would be the result if 1 is raised to the 9th power instead of the 5th power?

InternLM-Math Base 7B:

  Reasoning: 1^9 = <<1^9=1>>1
### Answer: 1

Expected answer: 1

Correct? Yes