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InternLM-Math Base 7B on 7.NS.A.3-fraction

Common Core Standard 7.NS.A.3-fraction

This standard covers the following:

Solve real-world and mathematical problems involving the four operations with rational numbers.

πŸ”— Problem

Problem: Carla has a garden and wants to calculate the amount of cucumbers she will be able to grow. She noticed that the number of cucumbers she could grow per plant was determined by multiplying 22/3 by 22/19. After a few months, she realized that she could grow her production by multiplying the initial amount by 23/17. How many cucumbers is she expecting to grow per plant after adjusting her production method?

InternLM-Math Base 7B:

 Reasoning: The number of cucumbers per plant is determined by 22/3 Γ— 22/19 Γ— 23/17 = <<22/3 Γ— 22/19 Γ— 23/17= 8.8>>8.8.

Expected answer: 11132/969

Correct? No

πŸ”— Problem

Problem: Pierre has 19/4 kg of grapes. One afternoon, he ate 7/25 kg of them. In the evening, his mother gave him 30/9 kg more grapes. How many kilograms of grapes does Pierre have now?

InternLM-Math Base 7B:

 Reasoning: Pierre has 19/4-7/25 = <<19/4-7/25=3/2>>3/2 kilograms of grapes left in the afternoon. In the evening, he got 30/9 kilograms of grapes. He has 3/2+30/9 = <<3/2+30/9=3/2>>3/2 kilograms of grapes now.
### Answer: 3/2

Expected answer: 2341/300

Correct? No

πŸ”— Problem

Problem: King Arthur is calculating the costs for restoring his castle. The wall repairs cost 26/22 of his castle's annual budget. Meanwhile, the moat renovations cost an additional 4/29 of the budget. Finally, installing new defensive catapults takes up an 11/3 portion of the budget. How much (expressed as a fraction of the castle's annual budget) has King Arthur spent on these projects in total?

InternLM-Math Base 7B:

 Reasoning: The sum of 26/22, 4/29, and 11/3 is <<26/22+4/29+11/3=26/22+4/29+11*3/3=26/22+4/29+33/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26/22+4/29+11*3/3=26

Expected answer: 4772/957

Correct? No

πŸ”— Problem

Problem: A giraffe at the local zoo has a peculiar eating habit. When it is fed 25/19 lbs of acacia leaves, it eats 30/26 times more than what it usually does in a day. If the zoo calculates the weekly feeding amount by multiplying the daily intake by itself (making the result "weekly feeding amount squared") and then multiplying that with the regular daily intake, how many pounds of acacia leaves should they prepare for the giraffe for a week? Calculate ((25 / 19) * (30 / 26))^2 * ((25 / 19) * (30 / 26)) and provide your answer.

InternLM-Math Base 7B:

 Reasoning: The weekly feeding amount is: <<(25/19)*(30/26) = 0.8>>0.8 * <<(25/19)*(30/26) = 0.8>>0.8 = 0.8^2 * 0.8 = 0.8^3 = 0.512. The number of pounds of acacia leaves to prepare for the giraffe for a week is 0.512 * 0.8 = 0.4128.
### Answer: 0.4128

Expected answer: 52734375/15069223

Correct? No

πŸ”— Problem

Problem: Lara wants to make a necklace. The necklace requires (11/3) feet of yarn. She also wants to add smaller beads which will extend the length of the necklace by (8/30) feet. How many feet of materials will Lara need to make the necklace?

InternLM-Math Base 7B:

 Reasoning: Lara needs (11/3) + (8/30) = <<(11/3) + (8/30) = 9/2>>9/2 feet of material to make the necklace.
### Answer: 9/2

Expected answer: 59/15

Correct? No

πŸ”— Problem

Problem: Two planes depart from an airport at the exact same time. Plane A is flying at a speed of 24/11 miles per minute and Plane B is flying at a speed of 26/27 miles per minute. How much farther (in miles) did Plane A travel than Plane B after exactly one minute, assuming they keep flying at a stable speed? Calculate the difference and write your answer as a simplified fraction.

InternLM-Math Base 7B:

 Reasoning: Plane A traveled 24/11 = <<24/11=2.18181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818

Expected answer: 362/297

Correct? No

πŸ”— Problem

Problem: In the wild, an adult bear eats about 14/7 pounds of fish per day. A young bear eats about 25/13 pounds of fish per day. Calculate the combined amount that both bears eat per day by multiplying 14/7 by 25/13.

InternLM-Math Base 7B:

 Reasoning: The combined amount of food eaten is 14/7 β‹… 25/13 = <<14/7β‹…25/13=1.4>>1.4 pounds of fish.
### Answer: 1.4

Expected answer: 50/13

Correct? No

πŸ”— Problem

Problem: Toby plays guitar. His first song takes 12/8 hours to play and his second song takes 12/3 hours to play. How long does it take Toby to play both of his songs? Write your answer as a simplified fraction.

InternLM-Math Base 7B:

 Reasoning: Toby takes 12/8+12/3 = <<12/8+12/3=9>>9 hours to play both of his songs.
### Answer: 9

Expected answer: 11/2

Correct? No

πŸ”— Problem

Problem: Suppose you have 28 out of 29 chocolate bars. Then, you found 8 out of 22 more chocolate bars. What fraction represents the total chocolate bars you have now?

InternLM-Math Base 7B:

 Reasoning: 28/29+8/22 = <<28/29+8/22= 8*22/22*29+8*29/22*29>> 8*22/22*29+8*29/22*29 = <<8*22/22*29+8*29/22*29= 8*22*29/22*29*22+8*29*22/22*29*22>> 8*22*29/22*29*22+8*29*22/22*29*22 = <<8*22*29/22*29*22+8*29*22/22*29*22= 8*22*29*22+8*22*29*22/22*29*22*22+22*29*22*22/22*29*22*22>> 8*22*29*22+8*22*29*22/22*29*22*22+22*29*22*22/22*29*22*22 = <<8*22*29*22+8*22*29*22/22*29*22*22+22*29*22*22/22*29*22*22= 8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22*8*22*22*22*22

Expected answer: 424/319

Correct? No

πŸ”— Problem

Problem: A compass maker is creating some specialty compasses. The compass needle is made from a special material. It takes 27/26 of a pound to create one needle. If the maker is trying to produce two identical needles, how much material will he require? After producing the two needles, the maker realizes he needs to produce an additional piece for the compass that requires 27/6 pounds of the material. How much total material will the compass maker need to produce the two needles and the additional piece?

InternLM-Math Base 7B:

 Reasoning: 27/6 = <<27/6=4.5>>4.5. 27/6+27/26 = <<27/6+27/26=4.5+1.04>>5.54. ### Answer: 5.54

Expected answer: 171/26

Correct? No

πŸ”— Problem

Problem: Liam bought a candle that burns at a rate of 6/4 inches per hour. After some time, he bought another candle that burns at a slower rate of 14/16 inches per hour. What is the total rate at which the two candles burn together?

InternLM-Math Base 7B:

 Reasoning: The first candle burns at a rate of 6/4= <<6/4=1.5>>1.5 inches per hour. The second candle burns at a rate of 14/16= <<14/16=0.875>>0.875 inches per hour. The total rate is 1.5+0.875= <<1.5+0.875=2.375>>2.375 inches per hour.
### Answer: 2.375

Expected answer: 19/8

Correct? Yes

πŸ”— Follow-up

Problem: Liam reevaluated and decided to change the second candle he bought, which now burns at a rate of 26/16 inches per hour, instead of the initial slow rate. Considering the rate of the first candle, what is the total rate at which the two candles now burn?

InternLM-Math Base 7B:

  Reasoning: The first candle burns at a rate of 6/4= <<6/4=1.5>>1.5 inches per hour. The second candle burns at a rate of 26/16= <<26/16=1.625>>1.625 inches per hour. The total rate is 1.5+1.625= <<1.5+1.625=3.125>>3.125 inches per hour.
### Answer: 3.125

Expected answer: 25/8

Correct? Yes

πŸ”— Problem

Problem: Sophia has 17/20 of a dollar. Her friend gives her another 1/4 of a dollar. After some time, her brother gives her 1 dollar. How much money does Sophia have now in dollars?

InternLM-Math Base 7B:

 Reasoning: Sophia has 17/20 + 1/4 = <<17/20+1/4= 8/5>>8/5 dollars.

Expected answer: 21/10

Correct? No

πŸ”— Problem

Problem: Imagine you're a music producer who is working on a new song. Your resources are divided into different sections. - First, you dedicate 16/4 hours to composing the music and another 16/29 hours to writing the lyrics. This is your initial time investment for the song (let's call it p). - Then, you spend 28/13 hours for mixing and mastering the song in addition to the initial time investment (let's call this new total time b). - Suddenly, a drummer you hired for a session uses 18/4 hours less because he finished his parts quickly. What is the final time you spent on producing the song, if your total time is expressed as (b - (18 / 4))?

InternLM-Math Base 7B:


        

Expected answer: 1663/754

Correct? No

πŸ”— Problem

Problem: Monica has 21/15 dozens of cookies at her bakery shop. Later in the day, she bakes additional 29/17 dozens of cookies to add into her stock. At the end of the day, she decides to increase her total stock of cookies by a ratio of 7/5 for an upcoming cookie festival. How many dozens of cookies will Monica have for the cookie festival?

InternLM-Math Base 7B:

 Reasoning: Monica's new total of cookies is 21/15+29/17 = 8/9 <<21/15+29/17=8/9>>.
The new total of cookies is increased by 7/5, so 8/9*7/5 = 8/9*7/5 = 8*7/9*5 = 8*7/45 = 8*7/9*5 = 8*7/45 = 56/45 <<8*7/9*5=8*7/45=56/45>>.
Monica will have 56/45 <<56/45>> dozens of cookies for the cookie festival.

Expected answer: 1848/425

Correct? No

πŸ”— Problem

Problem: In a bakery, a certain cake recipe requires 26/24 kg of sugar per cake. If a chef starts with 28 kg of sugar, how many kilograms of sugar will they have left after making one cake and then adding 10/6 kg of sugar to their supply?

InternLM-Math Base 7B:

 Reasoning: The chef will have 28-26/24 = <<28-26/24=0.8>>0.8 kilograms of sugar left after making one cake.
The chef will have 0.8+10/6 = <<0.8+10/6=1.8>>1.8 kilograms of sugar after adding 10/6 kilograms of sugar to their supply.
### Answer: 1.8

Expected answer: 343/12

Correct? No

πŸ”— Problem

Problem: On a plane trip, Emily watched a total of 16 / 4 hours of movies. During this time, she spent 6 / 3 hours watching a comedy film. How many hours did she spend watching movies other than the comedy film?

InternLM-Math Base 7B:

 Reasoning: Emily spent 6/3 = <<6/3=2>>2 hours watching a comedy film. She spent 16-2 = <<16-2=14>>14 hours watching movies other than the comedy film.
### Answer: 14

Expected answer: 2

Correct? No

πŸ”— Problem

Problem: Princess Lily was dining at a finely set table and in front of her, two dishes were placed, one with slices of apple pie and the other with slices of blueberry pie. She can eat pie slices endlessly! She ate 10 out of the 12 slices of the apple pie and 10 out of the 29 slices of the blueberry pie. How much of the pies (combined) did she eat? Represent your answer as a fraction.

InternLM-Math Base 7B:

 Reasoning: Lily ate 10/12 = <<10/12=5/6>>5/6 of the apple pie and 10/29 = <<10/29=1/3>>1/3 of the blueberry pie. The sum of the two fractions is 5/6+1/3 = <<5/6+1/3=7/6>>7/6.
### Answer: 7/6

Expected answer: 205/174

Correct? No

πŸ”— Problem

Problem: Marta has a box of colored pencils. She uses 20 of the colored pencils every 11 days on her art projects. However, she only uses about 23 out of every 26 colored pencils for shading techniques. How many colored pencils does Marta use for shading in her art projects over an 11-day period? Evaluate by performing the operation (20 / 11) * (23 / 26) and write your answer as a simplified fraction.

InternLM-Math Base 7B:

 Reasoning: Marta uses 20/11 = <<20/11=1.818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818181818

Expected answer: 230/143

Correct? No

πŸ”— Problem

Problem: A police investigator is analyzing two evidence specimens. The first specimen has a unique property that decreases its value by 26 out of every 6 units. The second specimen decreases its value by 25 out of every 17 units. The investigator needs to find the ratio of these changes, referred to as indicator i. Additionally, he needs to figure out a set of changes in another pair of evidence specimens. The first one of this pair increases its value by 18 out of every 8 units and the second one increases its value by 17 out of every 23 units. The investigator has to find the difference between these two rates and refer to it as indicator h. He then combines these two indicators (h and i) by multiplying them to get a final evidence factor, referred to as indicator f. This will help determine the likelihood of a particular suspect’s involvement. Calculate the value of f.

InternLM-Math Base 7B:

 Reasoning: The investigator needs to first find the ratio of the two changes. The first change is 26/6 = <<26/6=4.33333333333333>>4.33333333333333. The second change is 25/17 = <<25/17=1.47058823529412>>1.47058823529412. The ratio of these two changes is 4.33333333333333/1.47058823529412 = <<4.33333333333333/1.47058823529412=2.95>><<2.95>>2.95.

The next step is to find the difference of the two changes. The first change is 18/8 = <<18/8=2.25>>2.25. The second change is 17/23 = <<17/23=0.739130434782609>>0.739130434782609. The difference of these two changes is 2.25-0.739130434782609 = <<2.25-0.739130434782609=1.5108>>1.5108.

The last step is to multiply the two values. The value of f is 2.95*1.5108 = <<2.95*1.5108=4.45>>4.45.

Expected answer: 30719/6900

Correct? No

πŸ”— Problem

Problem: In a wildlife park, there are lions and giraffes. During one particular year, the gestation period of a lioness is represented as 20/22 of a year, while a giraffe's gestation period is 15 years. Find the total gestation period of both animals together. Later in the same year, a lioness is pregnant again but this time her gestation period reduces by 15/20 of a year compared to the earlier total gestation period of both animals. How long will it take for the lioness to give birth this second time?

InternLM-Math Base 7B:

 Reasoning: The total gestation period of a lioness and a giraffe is 20/22 + 15 = <<20/22+15= 1.5+15= 16.5>>16.5 years. 
A lioness's gestation period is 16.5 - 15/20 = <<16.5-15/20= 16.5-0.75= 15.75>>15.75 years.
### Answer: 15.75

Expected answer: 667/44

Correct? No

πŸ”— Problem

Problem: A rectangle's length is 30/7 meters and its width is 19/6 meters. The area of the rectangle is found by multiplying the length and the width. If a similar rectangle has an area which is 18/17 times bigger than the original rectangle, what is the area of the similar rectangle?

InternLM-Math Base 7B:

 Reasoning: The area of the first rectangle is 30/7 β‹… 19/6 = <<30/7 β‹… 19/6=285/42>>285/42 = 5 β‹… 7 β‹… 3 β‹… 7 = 105 square meters. The second rectangle is 18/17 times the first rectangle. 18/17 β‹… 105 = β‹… 105 = β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… 

Expected answer: 1710/119

Correct? No

πŸ”— Problem

Problem: A soap factory produces 23/8 tonnes of soap each day. One day, they decided to increase production by an extra 4/20 of a tonne. However, later that same day, they reduce the production by 19/24 of a tonne due to a sudden power cut. How many tonnes of soap does the factory produce that day after these adjustments?

InternLM-Math Base 7B:

 Reasoning: The factory produces 23/8+4/20 = <<23/8+4/20= 8 3/8>>8 3/8 tonnes of soap in the first part of the day.
The factory then produces 8 3/8-19/24 = <<8 3/8-19/24= 8 3/8- 3/4 = 8 3/8- 6/8 = 8 3/8- 0 3/8 = 8 0/8 = 8>>8 tonnes of soap in the second part of the day.
### Answer: 8

Expected answer: 137/60

Correct? No

πŸ”— Problem

Problem: You have a paint mixing machine that creates specific shades of color. The machine starts by mixing 24/8 gallons of red paint. It then pours away 12/8 gallons of the mix. Let 'd' represent the amount of red paint left in the machine. Finally, the machine adds another 1/28 gallon of blue pigment to lighten the color, subtract that from 'd' to find 'x' in gallons, which is the total amount of paint. Find the value of 'x'.

InternLM-Math Base 7B:

 Reasoning: The machine starts with 24/8 = <<24/8=3>>3 gallons of red paint. It then pours away 12/8 = <<12/8=1.5>>1.5 gallons of the mix. The amount of red paint left in the machine is 3-1.5 = <<3-1.5=1.5>>1.5 gallons. The machine then adds 1/28 = <<1/28=0.035714285714285714285714285714286>>0.035714285714285714285714285714286 gallons of blue pigment. The final amount of paint is 1.5-0.035714285714285714285714285714286 = <<1.5-0.035714285714285714285714285714286=1.4642857142857142857142857142857>>1.4642857142857142857142857142857 gallons.
### Answer: 1.4642857142857142857142857142857

Expected answer: 41/28

Correct? Yes

πŸ”— Follow-up

Problem: Suppose, while creating the paint mixture you started with the revised amount of 24/8 gallons of red paint. However, this time instead of adding 1/28 gallon blue pigment, you added 1/21 gallon of blue pigment to adjust the color. Subtract this newer amount of blue pigment from 'd' to find 'x' in gallons, which is the total amount of paint. What is the value of 'x' now?

InternLM-Math Base 7B:

  Reasoning: The machine starts with 24/8 = <<24/8=3>>3 gallons of red paint. It then pours away 12/8 = <<12/8=1.5>>1.5 gallons of the mix. The amount of red paint left in the machine is 3-1.5 = <<3-1.5=1.5>>1.5 gallons. The machine then adds 1/21 = <<1/21=0.04761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904761904

Expected answer: 61/42

Correct? No

πŸ”— Problem

Problem: A banana bread recipe requires you to multiply the fractions (27 / 14) and (17 / 13) together to determine how many ounces of mashed bananas you'll need. Compute the product of these fractions and write your answer as a simplified fraction to find out how many ounces are required.

InternLM-Math Base 7B:

 Reasoning: (27 / 14) * (17 / 13) = <<(27/14) * (17/13) = (27*17) / (14*13) = 459/182>>459/182
### Answer: 459/182

Expected answer: 459/182

Correct? Yes

πŸ”— Follow-up

Problem: After finding out how many ounces of mashed bananas you'll need for the banana bread, you realize that you need to scale up the recipe by the factor represented by the fraction (8 / 4). Compute the product of the original fraction and the scaling factor (8 / 4) to determine the new amount of mashed bananas that will be needed. Write your answer as a simplified fraction.

InternLM-Math Base 7B:

 Reasoning: (27 / 14) * (8 / 4) = <<(27/14) * (8/4) = 27*8 / 14*4 = 216/56 = 27/7>>27/7
### Answer: 27/7

Expected answer: 459/91

Correct? No

πŸ”— Follow-up

Problem: After reevaluating the recipe, you discover that the amount of mashed bananas required is actually determined by multiplying the fractions (27 / 14) and (17 / 15), not (27 / 14) and (17 / 13) as you initially thought. Recompute the product of these fractions to find out the correct amount of mashed bananas needed for the banana bread. Write your answer as a simplified fraction.

InternLM-Math Base 7B:

  Reasoning: (27 / 14) * (17 / 15) = <<(27/14) * (17/15) = (27*17) / (14*15) = 459/210>>459/210
### Answer: 459/210

Expected answer: 153/70

Correct? Yes

πŸ”— Problem

Problem: Sonia uses 21/12 oz of toothpaste to brush her teeth every day. Her brother Anthony uses less toothpaste, just 6/27 oz daily. Add both quantities of toothpaste to get the total daily amount used by Sonia and Anthony. Now, suppose their mom includes an amount of toothpaste for herself to the total - she uses 3/18 oz of toothpaste daily. Add this amount to the total used by Sonia and Anthony to get the final total daily toothpaste usage for the whole family. Solve each fraction separately and give the answer as a simplified fraction.

InternLM-Math Base 7B:

 Reasoning: Sonia and Anthony's total daily toothpaste usage is 21/12+6/27 = <<21/12+6/27= 8/9>>8/9. The final total daily toothpaste usage for the whole family is 8/9+3/18 = <<8/9+3/18= 8/9>>8/9.
### Answer: 8/9

Expected answer: 77/36

Correct? No

πŸ”— Problem

Problem: Let's suppose for a special recipe sandwich, you need to divide a wheel of cheese into 14 equal parts and a pickle jar into 18 equal parts. To make one special sandwich, you need 21 parts of the wheel of cheese and 7 parts from the pickle jar. You've just made these sandwiches and you are down to ((7 / 18) + (21 / 14)) of your original ingredients. Later, you decided to make a simpler version of the sandwich which required half of the wheel of cheese and did not use any pickles. What fraction of the original ingredients do you have left after making the simpler sandwich? Calculate the answer by subtracting (2 / 4) from the fraction you had after making the first sandwich.

InternLM-Math Base 7B:

 Reasoning: The fraction of the original ingredients you have left after making the simpler sandwich is ((7 / 18) + (21 / 14) - 1/2) = <<(7/18+21/14-1/2)=(7/18+21/14-2/4)=(7/18+21/14-1/2-1/2)=(7/18+21/14-1-1/2)=(7/18+21/14-3/2)=(7/18+21/14-3/2-3/2)=(7/18+21/14-3-3/2)=(7/18+21/14-6/2)=(7/18+21/14-3)=(7/18+21/14-3-3/3)=(7/18+21/14-3-1)=(7/18+21/14-4)=(7/18+21/14-4-3/9)=(7/18+21/14-4-1/3)=(7/18+21/14-5/3)=(7/18+21/14-5/3-3/9)=(7/18+21/14-5-1/3)=(7/18+21/14-6/3)=(7/18+21/14-2)=(7/18+21/14-2-3/9)=(7/18+21/14-2-1/3)=(7/18+21/14-3/3)=(7/18+21/14-1)=(7/18+21/14-1-3/9)=(7/18+21/14-1-1/3)=(7/18+21/14-3/9)=(7/18+21/14-3/9-3/9)=(7/18+21/14-3-3/9)=(7/18+21/14-6/9)=(7/18+21/14-2/3)=(7/18+21/14-2/3-3/9)=(7/18+21/14-2-1/3)=(7/18+21/14-3/3)=(7/18+21/14-1)=(7/18+21/14-1-3/9)=(7/18+21/14-1-1/3)=(7/18+21/14-3/9)=(7/18+21/14-3/9-3/9)=(7/18+21/14-3-3/9)=(7/18+21/14-6/9)=(7/18+21/14-2/3)=(7/18+21/14-2/3-3/9)=(7/18+21/14-2-1/3)=(7/18+21/14-3/3)=(7/18+21/14-1)=(7/18+21/14-1-3/9)=(7/18+21/14-1-1/3)=(7/18+21/14-3/9)=(7/18+21/14-3/9-3/9)=(7/18+21/14-3-3/9)=(7/18+21/14-6/9)=(7/18+21/14-2/3)=(7/18+21/14-2/3-3/9)=(7/18+21/14-2-1/3)=(7/18+21/14-3/3)=(7/18+21/14-1)=(7/18+21/14-1-3/9)=(7/18+21/14-1-1/3)=(7/18+21/14-3/9)=(7/18+21/14-3/9-3/9)=(7/18+21/14-3-3/9)=(7/18+21/14-6/9)=(7/18+21/14-2/3)=(7/18+21/14-2/3-3/9)=(7/18+21/14-2-1/3)=(7/18+21/14-3/3)=(7/18+21/14-1)=(7/18+21/14-1-3/9

Expected answer: 25/18

Correct? No

πŸ”— Problem

Problem: A window washer needs to clean two windows in a large building. The first window is 15/6 meters tall while the other one is 7/16 meters tall. How tall are the windows in total?

InternLM-Math Base 7B:


        

Expected answer: 47/16

Correct? No

πŸ”— Problem

Problem: Jan is mixing some fruit juices for a party. She mixes 16/6 liters of apple juice with 20/12 liters of orange juice. To add some tartness, she also adds 2/3 liters of cranberry juice. How many liters of juice does she have in total?

InternLM-Math Base 7B:

 Reasoning: Jan's total amount of juice is 16/6+20/12+2/3 = <<16/6+20/12+2/3= 8 1/3>>8 1/3.
### Answer: 8 1/3

Expected answer: 5

Correct? No

πŸ”— Problem

Problem: In a puzzle game, each level gives you 4/3 points. If you have played 13/10 of these levels, how many points have you earned? Standardize your response as a simplified fraction.

InternLM-Math Base 7B:

 Reasoning: 4/3 Γ— 13/10 = <<4/3 Γ— 13/10=26/15>>26/15
### Answer: 26/15

Expected answer: 26/15

Correct? Yes

πŸ”— Follow-up

Problem: In the same puzzle game, let's say now each level gives you the same amount of points, 4/3, but you've only played the game completely (13/13 of the levels). How many points have you earned now? Write your response as a simplified fraction.

InternLM-Math Base 7B:

  Reasoning: 4/3 Γ— 13/13 = <<4/3 Γ— 13/13=4/3>>4/3
### Answer: 4/3

Expected answer: 4/3

Correct? Yes

πŸ”— Problem

Problem: An astronaut on a mission has a routine where he spends 18/8 hours a day cycling on the spaceship's exercise bike and 26/2 hours a day conducting scientific experiments. The total amount of time spent on these activities in a day makes up what he calls his "work". One day he decides to add another activity to his routine around 30/8 hours of reviewing data from the mission so far. He adds this time to his previous "work" routine. How many hours does the astronaut spend on his whole daily routine now?

InternLM-Math Base 7B:


        

Expected answer: 19

Correct? No

πŸ”— Problem

Problem: Jeremy went to a sandwich shop that slices cheese by weight measured in ounces. He ordered slices of cheese that weighed 30/9 ounces in total. However, upon weighing, he found that there was 17/22 ounces less cheese than he requested. Calculate how much cheese he actually received. Use the equation 'd = n - (17 / 22)' to find the answer.

InternLM-Math Base 7B:

 Reasoning: Jeremy's cheese weighed 30/9 - 17/22 = <<30/9-17/22= 8/9>>8/9 ounces in total.
### Answer: 8/9

Expected answer: 169/66

Correct? No

πŸ”— Problem

Problem: Sophia is a researcher who studies sunglasses. She was examining a batch of sunglasses and trying to calculate the average light blocking efficiency. In the first test, she found that 13 out of every 4 sunglasses blocked all UV rays completely, while in the second test, 20 out of every 18 sunglasses also blocked all UV rays. Sophia decided to add these numbers to her total. Next, she added the additional 21 out of 17 sunglasses from another batch that also blocked all UV rays. Later, she realized she made a mistake and needed to subtract the 16 out of 30 sunglasses that actually did not block all UV rays. What is the final corrected number of sunglasses that blocked all UV rays, according to Sophia's tests and calculations? Please give your answer as a simplified fraction.

InternLM-Math Base 7B:

 Reasoning: Sophia's first test had 13/4 = <<13/4=3.25>>3.25 sunglasses that blocked all UV rays. The second test had 20/18 = <<20/18=1.111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111

Expected answer: 15493/3060

Correct? No

πŸ”— Problem

Problem: Shawn is making sandwiches for a picnic. The recipe for the sandwiches requires different amounts of mayonnaise and sandwich spread. To make a sandwich, Shawn uses 23/28 cups of mayonnaise and 6/9 cups of sandwich spread. How many cups of these two ingredients does Shawn use in total to make a sandwich? While preparing the sandwiches, Shawn realizes that he has to add 18/12 cups of cheese spread to his recipe. Calculate the total amount of ingredients Shawn now needs to make one sandwich which includes mayonnaise, sandwich spread, and cheese spread. Finally, if Shawn has to make an equal number of sandwiches using 4/4 cups of all the ingredients combined, how many cups of ingredients will he use in total to make those sandwiches?

InternLM-Math Base 7B:


        

Expected answer: 251/84

Correct? No

πŸ”— Problem

Problem: Cassandra collected keys for a hobby. At first she had a collection equivalent to 7/6 of a key set. After she lost 1/21 of a key set, how many key sets does she have now?

InternLM-Math Base 7B:

 Reasoning: Cassandra's new collection is 7/6-1/21 = <<7/6-1/21=35/42>>35/42 of a key set.
### Answer: 35/42

Expected answer: 47/42

Correct? No

πŸ”— Problem

Problem: A songwriter is composing a new piece. In the first section, he uses a ratio of 29 notes every 23 measures. In the second section, he uses a ratio of 19 notes every 17 measures. Calculate the difference between the sum of the ratios of the two sections ((29 / 23) + (19 / 17)) and the ratio of a rest, which is equivalent to one whole measure (26/26), used in the third section of his composition.

InternLM-Math Base 7B:


        

Expected answer: 539/391

Correct? No

πŸ”— Problem

Problem: You're trying to solve a puzzle that requires you to multiply two fractions together. The fractions are 22/25 and 22/8. Calculate the product to get the answer you need to advance in the puzzle.

InternLM-Math Base 7B:

 Reasoning: 22/25 * 22/8 = 22*22/25*8 = <<22*22/25*8=22*22/25*2*4=22*2*2*2*2/25*2*4=11*2*2*2*2/25*2*2*2=11*2*2*2/25*2*2=11*2*2/25*2=11*2/25*2=11/25*2=11/25*1*2/1=11*2/25=22/25>>22/25
### Answer: 22/25

Expected answer: 121/50

Correct? No

πŸ”— Problem

Problem: James is making a decorative pillow and would like to add a matching border. He needs to calculate the length of border material he will need. The pillow is 23/9 feet long. He had an additional 22/25 feet of length due to the fluffing of the pillow. The total length is then multiplied by 16/13 to account for overlap and corners. Calculate the length of border material James will need for his pillow.

InternLM-Math Base 7B:

 Reasoning: The total length of the border material is 23/9*16/13+22/25*16/13 = <<23/9*16/13+22/25*16/13= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 8/9+ 8 8/25= 8 

Expected answer: 12368/2925

Correct? No

πŸ”— Problem

Problem: A car travels 21/4 miles every hour. One day, the car was needed to travel an extra 16/13 miles, but due to a detour, it only traveled an additional 1/21 miles. How many more miles was the car supposed to travel in total that day, given that it ran continuously at the same speed? Calculate by multiplying the additional distance needed by the average miles the car travels in an hour.

InternLM-Math Base 7B:

 Reasoning: 16/13-1/21 = <<16/13-1/21= 1/3>>1/3
### Answer: 1/3

Expected answer: 323/52

Correct? No

πŸ”— Problem

Problem: In a book publishing company, the manager has to look after various departments. The editing team takes 20/5 hours to edit a manuscript of a book, while the typesetting team needs 18/17 hours to adjust the layout of a page. Some break delay happens that results in a collective loss of 6/15 hours. After these delays and losses, the manager, to compensate, extended the working hours by the same amount of time as the initial time span of the process. On a particular day, they continue to work. What's the total extended time in hours, if you multiply the time required for the entire process and the extended time after the reduction of the lost hours with the initial total time required?

InternLM-Math Base 7B:

 Reasoning: The total time required for the process is 1.3 hours. The total time extended is 1.3*1.3=1.69 hours.
### Answer: 1.69

Expected answer: 34056/1445

Correct? No

πŸ”— Problem

Problem: Jenny plants 13/11 rows of potatoes in her garden. Each row yields approximately 21/3 bushels. If Jenny sells her yield at the farmer's market where each bushel earns her 21/15 dollars, how many dollars will she make in total by selling all her potatoes?

InternLM-Math Base 7B:


        

Expected answer: 637/55

Correct? No

πŸ”— Problem

Problem: A jeweler uses 14/28 of a kilogram of gold to craft a certain type of rings. Additionally, he uses 13/26 of a kilogram of silver to design another type of rings. What is the sum of the amount of gold and silver used by the jeweler in kilograms?

InternLM-Math Base 7B:

 Reasoning: 14/28+13/26= <<14/28+13/26= 0.5+0.5=1.0>>1.0
### Answer: 1.0

Expected answer: 1

Correct? Yes

πŸ”— Follow-up

Problem: The jeweler decided to use a more expensive gold making process for his rings, which requires a slightly larger amount of gold, specifically 21/28 of a kilogram instead of the original 14/28. Taking this into account, now how much total weight of gold and silver is he using to craft his rings?

InternLM-Math Base 7B:

  Reasoning: 21/28+13/26= <<21/28+13/26= 0.75+0.5=1.25>>1.25
### Answer: 1.25

Expected answer: 5/4

Correct? Yes

πŸ”— Problem

Problem: In a beehive, there are sections for honey storage and bee rearing. Each section is classified into many sub-sections. One day, the beekeeper discovered that each honey storage sub-section had (25 / 9) gallons of honey. He also found the same amount of honey in each bee rearing sub-section. If he combined the honey from both a honey storage sub-section and a bee rearing sub-section, the beekeeper would have a total quantity represented by 'p'. However, one honey storage sub-section had an additional (2 / 26) gallons of honey. So, if the beekeeper was calculating the total amount from this sub-section plus a bee rearing sub-section, the total amount of honey would be defined as 's'. What quantity of honey ('s') would the beekeeper have in total from this scenario?

InternLM-Math Base 7B:

 Reasoning: The beekeeper would have a total of (25/9) + 2/26 = <<(25/9) + 2/26= 8/9>>8/9 gallons of honey. 
### Answer: 8/9

Expected answer: 659/117

Correct? No

πŸ”— Problem

Problem: In prehistoric times, a herbivorous dinosaur eats 16/8 bunches of leaves per hour during the day. But at night, it only eats 6/17 bunches of leaves every hour because of reduced visibility. Calculate the total bunches of leaves the dinosaur eats in an hour if it is eating day and night.

InternLM-Math Base 7B:

 Reasoning: The total number of leaves the dinosaur eats in a 12 hour day and 12 hour night is 12 β‹… 16/8 + 12 β‹… 6/17 = <<12β‹…16/8+12β‹…6/17= β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… β‹… 

Expected answer: 40/17

Correct? No

πŸ”— Problem

Problem: A bear ate 28/6 pounds of fish one day and 21/18 pounds the next day. On the third day, the bear ate 24/22 pounds of fish. How many total pounds of fish did the bear eat in these three days, written as a fraction?

InternLM-Math Base 7B:

 Reasoning: The first day, the bear ate 28/6 = <<28/6=4.6>>4.6 pounds of fish.
The second day, the bear ate 21/18 = <<21/18=1.1>>1.1 pounds of fish.
The third day, the bear ate 24/22 = <<24/22=1.0>>1.0 pounds of fish.
The bear ate 4.6+1.1+1.0 = <<4.6+1.1+1.0=6.7>>6.7 pounds of fish in these three days.
### Answer: 6.7

Expected answer: 457/66

Correct? No

πŸ”— Problem

Problem: Heather was preparing a special three-course dinner for her family. For the first course, she had a bread recipe that required 11/17 of a cup of sugar. In addition, she baked a custard for dessert that required another 6/2 cups of sugar. As her family loves sweet dishes, she decided to increase the total quantity of sugar by a factor of 29/21. How many cups of sugar did Heather use in total?

InternLM-Math Base 7B:

 Reasoning: Heather used 11/17+6/2 = <<11/17+6/2= 8/7>>8/7 cups of sugar for the first and the last course. 

She used 8/7x(29/21) = <<8/7x(29/21) = 29/3>>29/3 cups of sugar in total.

Expected answer: 1798/357

Correct? No

πŸ”— Problem

Problem: Ms. Parker, a math teacher, was grading papers and noticed that a student did the calculation ((7 / 8) + (21 / 18)), but she didn't write down the final answer. What is the result of this calculation as a simplified fraction?

InternLM-Math Base 7B:

 Reasoning: The student's calculation is the same as the following: (7/8) + (3/9) = (7/8) + (1/3) = 3/8 + 8/24 = 3/8 + 1/3 = 9/24 + 8/24 = 17/24.
### Answer: 17/24

Expected answer: 49/24

Correct? No

πŸ”— Problem

Problem: King Arthur is planning a grand feast at his castle. He estimates that each guest will consume 15/7 gallons of water and 15/24 gallons of wine. On the other hand, the royal baker needs 26/20 gallons of milk for each of the cakes he's baking. Calculate the total amount of liquid (v) that will be consumed if the baker's requirement is multiplied by the guests' consumption (i), and then add this to the guests' consumption (v) to find the total amount of liquid (x) needed for the feast.

InternLM-Math Base 7B:

 Reasoning: The baker's requirement is 26/20 gallons of milk, and the guests' consumption is 15/7+15/24 = <<15/7+15/24=15/4>>15/4 gallons of water and wine. 

The total amount of liquid (x) is 26/20*15/4+15/4 = <<26/20*15/4+15/4= 15/2+15/4= 15/2+15/4= 3*15/4= 3*15/4= 45/4>>45/4 gallons of liquid. 

Expected answer: 713/112

Correct? No

πŸ”— Problem

Problem: Teddy is a bear who loves to play with numbers. One day, Teddy was playing with his favorite number, which just so happened to be 30/17. While playing, he saw another number, 18/15, and decided to add it to his favorite number. With this new number in mind, he then saw another, 24/13, and decided to multiply it by his new number. What is Teddy's final number?

InternLM-Math Base 7B:

 Reasoning: Teddy's new number is 30/17+18/15 = <<30/17+18/15= 10/3>>10/3.
Teddy's final number is 10/3*24/13 = <<10/3*24/13= 8/1>>8.

Expected answer: 6048/1105

Correct? No

πŸ”— Problem

Problem: Johnny is building a scooter from scratch. He needs to drill holes into the scooter deck to attach the wheels. The size of each hole should be approximately (20/6) cm in diameter. Unfortunately, his drill bit only has a diameter of (11/21) cm. If he uses his current drill bit, he needs to drill a hole, move it over and drill again to achieve the diameter he needs. If he drills each hole exactly once with his drill bit, calculate what fraction of the desired diameter would each hole have? Don't simplify the fraction, keep as (20/6) * (11 / 21).

InternLM-Math Base 7B:

 Reasoning: (20/6) * (11/21) = <<(20*11)/(6*21) = 220/126 = 10/21>>10/21
### Answer: 10/21

Expected answer: 110/63

Correct? No

πŸ”— Problem

Problem: Aaron has a small model car collection. His favorite car model takes exactly 17/10 hours to assemble. He started assembling a new car model and realized that it was simpler, taking only 12/23 hours to complete. How much less time, in hours, will the second model take than the first one? Write your answer as a simplified fraction or decimal.

InternLM-Math Base 7B:

 Reasoning: The first model took 17/10 = <<17/10=1.7>>1.7 hours to assemble. The second model took 12/23 = <<12/23=0.52>>0.52 hours to assemble. 

The second model took 1.7 – 0.52 = <<1.7-0.52=1.18>>1.18 hours less than the first one.
### Answer: 1.18

Expected answer: 271/230

Correct? No

πŸ”— Problem

Problem: Carlos is very handy, and he decided to start a business making and selling chairs. He usually makes each chair using 20/15 units of wood. For a special order, he decided to design a larger, sturdier chair that uses (24/5) times (7/6) units more wood than usual. In total, how many units of wood would Carlos need to make one of these special chairs? Please give your answer in simplest form.

InternLM-Math Base 7B:

 Reasoning: Carlos needs 20/15 <<20/15=4/3>>4/3 units of wood to make each of his normal chairs. 

The special chair needs 4/3 <<4/3=1 1/3>>1 1/3 units of wood more than a normal chair. 

The special chair needs 4/3+1 <<4/3+1=1 1/3+1=2 1/3>>2 1/3 units of wood more than a normal chair. 

The special chair needs 4/3(2 1/3) <<4/3(2 1/3)=(4/3)(2 1/3)=(4/3)(8/3)=(4x8)/(3x3)=(32/9)>>32/9 units of wood. 
### Answer: 32/9

Expected answer: 104/15

Correct? No

πŸ”— Problem

Problem: Officer Davis was monitoring traffic for speeders. He was measuring the speed of cars passing by him using a radar gun. The gun showed one car was going 13/4 miles per minute. Suddenly, the car slows down and reduces his speed by 14/15 miles per minute. Officer Davis noted down the new speed of the car. Suddenly, the car increased its speed again by 30/15 miles per minute. What was the final speed of the car according to Officer Davis's radar gun?

InternLM-Math Base 7B:

 Answer: 13/4 - 14/15 = <<13/4-14/15= 8/15>>8/15
8/15 + 30/15 = 38/15
### Answer: 38/15

Expected answer: 259/60

Correct? No

πŸ”— Problem

Problem: Jake is trying to figure out how many grapes he can get from a certain vineyard. - The vineyard can usually produce 19/2 baskets of grapes every season. However, due to weather conditions, only 19/29 of the usual amount were produced this season. How many baskets of grapes were produced this season? - But Jake isn't the only one interested in these grapes. He has to share the grapes with others. He gets to keep only 7/11 of the total amount of grapes. How many baskets of grapes does he get? - Out of the grapes that he got, Jake wants to make some grape juice. But he only uses 9/10 of his grapes to make the juice. How many baskets of grapes does he use for the juice?

InternLM-Math Base 7B:

 Reasoning: Jake got <<19/2*19/29=19*9/58=27/29>>27/29 baskets of grapes this season. He only got <<7/11*27/29=7*9/11*29=63/121>>63/121 baskets of grapes. He only used <<9/10*63/121=9*63/10*121=567/1210=27/55>>27/55 baskets of grapes to make the juice.

Expected answer: 22743/6380

Correct? No

πŸ”— Problem

Problem: Joel has a grape farm. One day, he picked 9/2 bushels of red grapes and 10/22 bushels of green grapes from his farm. Calculate the total number of bushels of grapes Joel picked that day.

InternLM-Math Base 7B:

 Reasoning: Joel picked 9/2+10/22 = <<9/2+10/22=9.5>>9.5 bushels of grapes.

Expected answer: 109/22

Correct? No

πŸ”— Problem

Problem: A snowman is constructed by stacking two different sized snowballs on top of each other. The larger snowball at the bottom has a diameter of 17/8 feet, and the smaller snowball on top has a diameter of 1/20 feet. What is the total height of the snowman in feet when these two snowballs are stacked on top of each other?

InternLM-Math Base 7B:

 Reasoning: The height of a snowman is the same as the height of a cone. The height of a cone is 1/3 of the base. The base of a cone is a circle. The base of a circle is the same as the diameter of the circle. The height of a snowman is 1/3 of 17/8+1/20 = <<1/3(17/8+1/20) = 1/3(19/8) = 19/24 = 0.79166666666666666666666666666667>>0.79166666666666666666666666666667 feet.
### Answer: 0.79166666666666666666666666666667

Expected answer: 87/40

Correct? No

πŸ”— Problem

Problem: In a sandbox, a child splits up 24/7 parts of the sand in a fair way. Later on, another child takes away 2/16 part of the sand. Calculate the remaining part of sand in the sandbox.

InternLM-Math Base 7B:

 Reasoning: 24/7 = <<24/7=3.428>>3.428
3.428-2/16 = <<3.428-2/16=3.3>>3.3
### Answer: 3.3

Expected answer: 185/56

Correct? No

πŸ”— Problem

Problem: In the jungle, a lion ate 28/26 of a zebra in one day and 23/9 of a wildebeest the next day. How much less of the zebra did the lion eat compared with the wildebeest? Calculate your answer as a simplified fraction.

InternLM-Math Base 7B:

 Reasoning: The lion ate 28/26 of a zebra in one day and 23/9 of a wildebeest the next day. The lion ate 23/9-28/26 = <<23/9-28/26= β…”>>β…” less of the zebra than the wildebeest.
### Answer: β…”

Expected answer: 173/117

Correct? No

πŸ”— Problem

Problem: A chocolate factory makes a batch of chocolate by combining 14/4 kilograms of cocoa and 21/11 liters of milk for every kilogram. How many kilograms of chocolate will the factory produce by combining these ingredients? Calculate your answer to the following expression, ((14 / 4) * (21 / 11)).

InternLM-Math Base 7B:

 Reasoning: The factory will make <<(14/4) * (21/11) = 3.8>>3.8 kilograms of chocolate.

Expected answer: 147/22

Correct? No

πŸ”— Problem

Problem: In the tropical rainforest, there are two different species of banana trees. One species produces 12 bananas every 29 days, while another species produces 30 bananas every 10 days. If a day is chosen at random, what is the expected number of bananas that the two species together will have produced on that day? Use the formula ((12 / 29) + (30 / 10)) to calculate the answer.

InternLM-Math Base 7B:

 Answer: 8.

Expected answer: 99/29

Correct? No

πŸ”— Problem

Problem: A giraffe needs to eat a total of 11/11 ton of acacia leaves plus 26/14 ton of grasses a day. Calculate the total ton of food the giraffe needs to eat in a day.

InternLM-Math Base 7B:

 Reasoning: The total ton of food the giraffe needs to eat a day is 11/11+26/14 = 1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1

Expected answer: 20/7

Correct? No

πŸ”— Problem

Problem: A bear spends 18 hours of the day sleeping. Given that each day has 24 hours, this bear spends 18/24th of each day asleep. For 27 days of the month, the bear's activity is tracked. Assume that the bear has a regular sleeping pattern. Calculate the fraction of time the bear has spent sleeping over the 27 days assuming each month has 13 weeks. Your answer should be the result of (18 / 24) * (27 / 13). Write your answer as a decimal.

InternLM-Math Base 7B:

 0.8

Expected answer: 81/52

Correct? No

πŸ”— Problem

Problem: In a beautiful forest, the park rangers recorded that 9 out of every 14 trees were pine trees. They also noticed an exceptional occurrence where 19 out of every 2 trees were birches. If you count all the pine trees and birch trees together, what fraction of the trees in the forest are either pine or birch? Use the formula f = ((9 / 14) + (19 / 2)) to solve this.

InternLM-Math Base 7B:

 Reasoning: The fraction of the trees that are either pine or birch is 9/14+19/2 = <<9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/2= 8 9/14+19/

Expected answer: 71/7

Correct? No

πŸ”— Problem

Problem: On planet Zog, aliens use an interesting system to track their energy levels. At the beginning of the day, Zogorian calculates his energy level to be (14 / 2) / (23 / 17) zogs. Later in the day, after harnessing energy from their primary star, his energy level increases by (16 / 24) zogs. Calculate the Zogorian's energy level after the increase.

InternLM-Math Base 7B:

 Reasoning: The Zogorian's new energy level is <<(14/2) / (23/17) + (16/24) = 0.8>>0.8 zogs.
### Answer: 0.8

Expected answer: 403/69

Correct? No

πŸ”— Problem

Problem: Teddy, the bear, loves to play hide and seek with his friends. One day, he decided to play a game where he hides some number of his stuffed animal friends. Teddy hides 18/11 of his friends in the forest and 8/21 of his friends at the beach. First calculate how many more friends Teddy hides in the forest than at the beach. Let's call this number 'f'. Then square 'f' to find 'n', the total number of hiding spots Teddy needs. How many hiding spots does Teddy need?

InternLM-Math Base 7B:

 Reasoning: 18/11 - 8/21 = <<18/11-8/21=2/231>>2/231
n = 2/231 β‹… 2/231 = <<2/231β‹…2/231=4/4851>>4/4851
### Answer: 4/4851

Expected answer: 84100/53361

Correct? No

πŸ”— Problem

Problem: A robot is performing a maintenance task. It starts with 25/10 units of energy. However, it quickly uses 27/23 units of energy to complete a series of complex computations. Calculate how much energy it has left.

InternLM-Math Base 7B:


        

Expected answer: 61/46

Correct? No

πŸ”— Problem

Problem: During rainy weather, a small snail moves at a snail-pace covering 17/21 of a meter in an hour. Another slightly faster snail covers 20/24 of a meter in the same time during such weather. One rainy day, the first snail started an hour earlier than the second. At the time when the second snail began, a third snail that covers 18/17 of a meter per hour also started moving. What is their total distance in meters 1 hour after all three have started moving? Compute the result using the operation ((17 / 21) + (20 / 24)) for the first two snails' distance, and multiply this result by (18 / 17) for the total distance , including the third snail.

InternLM-Math Base 7B:

 Reasoning: The first two snails' distance in 1 hour is ((17/21) + (20/24)) = <<(17/21) + (20/24) = 0.8 + 0.833 = 1.633>>1.633 meters. 

The total distance, including the third snail, is 1.633 * 18/17 = <<1.633 * 18/17 = 1.633 * 1.0588 = 1.73004>>1.73004 meters.

Expected answer: 207/119

Correct? No

πŸ”— Problem

Problem: Johnny had 24/14 of a yard of fabric that he used to make stuffed animals. After creating a few, he found he only had 9/29 of a yard left. He then got a new type of fabric and used 15/2 times the difference of the original and remaining fabric to make more stuffed animals. How many yards of the new fabric did Johnny use?

InternLM-Math Base 7B:

 Reasoning: Johnny had 1-<<9/29=21/29>>21/29 = <<1-21/29=28/29>>28/29 of a yard of the original fabric. He used 1-<<28/29=1/29>>1/29 = <<1-1/29=28/29>>28/29 of a yard of the new fabric.
### Answer: 28/29

Expected answer: 4275/406

Correct? No

πŸ”— Problem

Problem: In a park, there are some kids lining up for the swings. Part of the waiting line consists of 2/10 of the total number of kids in the park, while another part is made up of 21/4 kids. What is the total number of kids waiting for the swing? Add together 2/10 and 21/4 to find your answer.

InternLM-Math Base 7B:


        

Expected answer: 109/20

Correct? No

πŸ”— Problem

Problem: An alien spacecraft has 18 fuel tanks out of a total of 30 fuel tanks filled. Each fuel tank can power the spacecraft for 22/6 hours. How many hours of power does the spacecraft currently have? Calculate (18 / 30) * (22 / 6) to find out.

InternLM-Math Base 7B:

 Reasoning: (18/30) * (22/6) = <<18/30*22/6=8/3>>8/3
The spacecraft has 8/3 = <<8/3=2.6...>>2.6... hours of power.

Expected answer: 11/5

Correct? No

πŸ”— Problem

Problem: A cat is fed twice a day. In the morning, it eats 16/12 of a can of cat food. in the evening, it eats 6/10 of a can. How much of a can in total does the cat eat in one day?

InternLM-Math Base 7B:

 Reasoning: The cat eats <<16/12=4/3>>4/3+<<6/10=3/5>>3/5 = 7/5 = <<7/5*1/1=7/5*1/1=7/5>>7/5 of a can in one day.
### Answer: 7/5

Expected answer: 29/15

Correct? No

πŸ”— Problem

Problem: A starfish laid 12 eggs in 3 nests and 11 eggs in 4 other nests. How much is the difference between the average number of eggs per nest for these two groups of nests?

InternLM-Math Base 7B:


        

Expected answer: 5/4

Correct? No

πŸ”— Problem

Problem: A monkey finds a pile of bananas and ends up eating (22 / 7) times (10 / 25) of the pile. Later, he gives (3 / 28) of the pile to his friend. How much of the pile does the monkey have left?

InternLM-Math Base 7B:

 Reasoning: The monkey has 1 - (22/7) β‹… (10/25) = <<1-22/7*10/25=1-2/7=5/7>>5/7 of the original pile. The monkey then gives (3/28) of the pile to his friend. The amount the monkey has left is 1 - (3/28) = <<1-3/28=25/28>>25/28 of the original pile.
### Answer: 25/28

Expected answer: 23/20

Correct? No

πŸ”— Problem

Problem: A mouse runs at a speed of 24/20 feet per second. If the mouse runs for 23/2 seconds, how many feet does the mouse run?

InternLM-Math Base 7B:

|

Expected answer: 69/5

Correct? No

πŸ”— Problem

Problem: At a party, the drinks are served in glasses that contain 29/9 ounces of beverage each. If 26/25 of them were consumed, how many ounces of beverage were consumed? Now imagine that the party goers then drink an additional 2/19 ounces of beverages. How many total ounces of beverages were consumed at the party in total?

InternLM-Math Base 7B:

 Reasoning: 26/25 of 29/9 = <<26/25 of 29/9 = 26/25*29/9= 26*29/25*9= 26*29/225= 754/225>>754/225 ounces of beverage were consumed.
754/225+2/19 = <<754/225+2/19 = 754*19/225*19= 754*19/4275= 14*19/4275= 266/4275= 266*225/4275*225= 59850/4275= 14>>14 ounces of beverage were consumed in total.
### Answer: 14

Expected answer: 14776/4275

Correct? No

πŸ”— Problem

Problem: You decide to start a toothbrush collection and you add 7/15 of a new set of toothbrushes to your current collection. Suddenly, a friend gifts you 9 more sets. After grouping everything, you realized you can only fit 26/27 of them in your display case. How many sets of toothbrushes can you fit in your display case?

InternLM-Math Base 7B:

 Reasoning: You have 7/15+9 = <<7/15+9=9.6>>9.6 sets of toothbrushes. You can only fit 26/27 of the 9.6 sets in your display case. 26/27 of 9.6 = <<26/27 of 9.6=9.2>>9.2 sets. You can only fit 9.2 sets in your display case.

Expected answer: 3692/405

Correct? No

πŸ”— Problem

Problem: Joan has a backpack which weighs 27/20 kilograms when it's empty. She adds a book which weighs 1/6 kilograms. Calculate the total weight of the backpack in kilograms now. Please write the answer as a simplified fraction.

InternLM-Math Base 7B:

 Reasoning: The backpack weighs 27/20+1/6 = <<27/20+1/6=9/5>>9/5 kilograms.
### Answer: 9/5

Expected answer: 91/60

Correct? No

πŸ”— Problem

Problem: A soda company is changing its bottle design. The new design will change the volume of the bottles so that they become (7 / 7) * (25 / 22) times larger. What will be the multiplier of the new bottle compared to the old one?

InternLM-Math Base 7B:


        

Expected answer: 25/22

Correct? No

πŸ”— Problem

Problem: Turtle Tilly is collecting food for the winter. She has gathered 25/9 kg of sea plants, and she then finds 8/13 kg more. In a close-by rock, she spots another food stash weighing 24/27 kg. After gobbling up these finds, Tilly stumbles upon yet another food source weighing 21/26 kg. If Tilly combines all her found food, how many kilograms does she now have in total? Answer as a simplified fraction.

InternLM-Math Base 7B:

 Reasoning: Tilly has 25/9+8/13+24/27+21/26 = 8/9+8/13+24/27+21/26 = 8/9+8/13+8/27+8/26 = 8(9/9+13/13+27/27+26/26) = 8(1+1+1+1) = 8(4) = 32 <<8(9/9+13/13+27/27+26/26)=8(1+1+1+1)=8(4)=32>> kilograms in total.
### Answer: 32

Expected answer: 397/78

Correct? No

πŸ”— Problem

Problem: Captain Alf undertakes multi-step calculations to ensure the safe navigation of his boat. First, he calculates the difference in his current location and the distance of a nearby island. The distance to the island is 17/2 nautical miles, and his boat is currently 4/2 nautical miles away from the island. Next, Captain Alf adjusts for the tide, which he has estimated to push his boat off course by 14/9 nautical miles. He adds this to his previous calculations. Finally, when considering his fuel efficiency rated at 22/15 nautical miles per gallon, Captain Alf multiplies his adjusted distance by this rate to figure out his fuel requirements. What does Captain Alf’s final calculation come to? Use these steps and corresponding fractions to find your answer.

InternLM-Math Base 7B:

 Reasoning: The distance to the island is 17/2 = <<17/2=8.5>>8.5 nautical miles, and the boat is currently 4/2 = <<4/2=2>>2 nautical miles away. The total distance to the island is 8.5-2 = <<8.5-2=6.5>>6.5 nautical miles. 

The tide is estimated to push the boat off course by 14/9 = <<14/9=1.5>>1.5 nautical miles. The total distance to the island, with the tide, is 6.5+1.5 = <<6.5+1.5=8>>8 nautical miles. 

The fuel efficiency of the boat is 22/15 = <<22/15=1.4>>1.4 nautical miles per gallon. The final calculation is 8 β‹… 1.4 = <<8β‹…1.4=11.2>>11.2. 

### Answer: 11.2

Expected answer: 319/27

Correct? No

πŸ”— Problem

Problem: A forest ranger patrolled 14/3 miles of trails in the morning. In the afternoon, he patrolled 2/18 mile less than what he walked in the morning. How many miles did the forest ranger patrol in the afternoon?

InternLM-Math Base 7B:

 Reasoning: The forest ranger patrolled 2/18 <<14/3-14/3*2/18=8/9>>8/9 miles in the afternoon.
### Answer: 8/9

Expected answer: 41/9

Correct? No

πŸ”— Problem

Problem: Arthur practices piano for 20/21 of an hour every day. On weekends, he practices an additional 11/29 of an hour per day. How many hours in total does Arthur spend practicing the piano each day on the weekend?

InternLM-Math Base 7B:

 Reasoning: Arthur practices 20/21+11/29 = <<20/21+11/29=3.8>>3.8 hours of piano on the weekend.
### Answer: 3.8

Expected answer: 811/609

Correct? No

πŸ”— Problem

Problem: Lucas has a shirt store. Initially, he had 18 shirts which he divided equally among his 3 siblings. Later, he bought 27 more shirts but wanted to sell them at a higher price, so he decided to keep only 1/19 of those shirts for each sibling. How many more or fewer shirts does each sibling now have as compared to before? Calculate the difference using the expression ((18 / 3) - (27 / 19)) and find out the result.

InternLM-Math Base 7B:

 Reasoning: Lucas' siblings are now sharing <<(18/3)-(27/19)=(6-1.5)=(4.5)>>4.5 fewer shirts.
### Answer: 4.5

Expected answer: 87/19

Correct? No

πŸ”— Problem

Problem: A painter mixed 7 gallons of white paint with 2/5 gallon of blue paint to make a light blue paint. After using 18/4 gallons of the light blue paint for a project, how many gallons does the painter have left?

InternLM-Math Base 7B:

 Reasoning: The painter used 18/4 = <<18/4=4.5>>4.5 gallons of the light blue paint for a project.
The painter has 7-4.5 = <<7-4.5=2.5>>2.5 gallons of light blue paint left.
### Answer: 2.5

Expected answer: 29/10

Correct? No

πŸ”— Problem

Problem: Jayson went to the roller rink and spent 24/7 hours skating on the first day. On the second day, he decided to skate for an additional 30/20 hours. How many hours in total did Jayson spend skate skating over the two days?

InternLM-Math Base 7B:

 Reasoning: Jayson skated for 24/7+30/20 = <<24/7+30/20=3.8>>3.8 hours in total.

Expected answer: 69/14

Correct? No

πŸ”— Problem

Problem: Dolphins can leap approximately 18/3 feet out of the water. If a dolphin only manages to jump 3/4 of his usual height one day, how high did the dolphin jump?

InternLM-Math Base 7B:

 Reasoning: The dolphin only managed to jump 3/4 of 18/3, or 3/4 Γ— 18/3 = <<3/4 Γ— 18/3=9/2>>9/2 feet out of the water.
### Answer: 9/2

Expected answer: 9/2

Correct? Yes

πŸ”— Follow-up

Problem: After observing that the dolphin managed to only jump 3/4 of his usual 18/3 feet out of the water, the trainer noted a reduction in his jumping height by 14/25 feet the next day. How high did the dolphin jump this time?

InternLM-Math Base 7B:

  Reasoning: The dolphin managed to only jump 3/4 Γ— 18/3 = <<3/4 Γ— 18/3=9/2>>9/2 feet out of the water the first day, and 9/2 - 14/25 = <<9/2 - 14/25=9/5>>9/5 feet out of the water the next day.
### Answer: 9/5

Expected answer: 197/50

Correct? No

πŸ”— Follow-up

Problem: Previously, we measured the dolphin's jump when it managed to reach 3/4 of his usual height of 18/3 feet. Now let's consider a day when the dolphin jumps to an unusually high 19/4 of his normal height. If the dolphin's usual jump is 18/3 feet, how high does the dolphin jump on this particular day?

InternLM-Math Base 7B:

  Reasoning: The dolphin managed to jump 19/4 of 18/3, or 19/4 Γ— 18/3 = <<19/4 Γ— 18/3=19.5>>19.5 feet out of the water.
### Answer: 19.5

Expected answer: 57/2

Correct? No

πŸ”— Problem

Problem: Callie owns a pen business. Last month, she sold 20 pens for every 15 she produced. At the same time, she sold an additional 16 pens for every 22 she put out for sale. Meanwhile, she found that for every 22 pens she advertised, 27 were interested customers. For each 23 pens she produced this week, she was able to sell 8. What is the result when she multiplies the ratio of last month's sales to production (20/15 + 16/22) and this week's figure for the ratio of interested customers to production (22/27 * 23/8)? Leave your answer as an unsimplified fraction.

InternLM-Math Base 7B:

 Reasoning: The ratio of last month's sales to production is <<20/15+16/22= 20*22*15+16*15*22/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16/15*22*16

Expected answer: 391/81

Correct? No

πŸ”— Problem

Problem: Consider a band practice session in which a musician played a song for exactly 30 minutes. After dividing this time equally between 15 songs, how much time did they spend on each song? From this average time per song, the band reduced the time spent on a particular song by 1/17 of an hour. Can you calculate the final duration of that song?

InternLM-Math Base 7B:

 You can use the following to calculate the time spent on a particular song: <<30/15=2>>2 minutes.

Expected answer: 33/17

Correct? No

πŸ”— Problem

Problem: Josh rented a scooter for a day. He rode the scooter for a total of 18 hours during the first day. The next day, he rode the scooter for an additional 1/12 of an hour. Later that afternoon, his friend Jack also rented a scooter and rode it for 7/17 of an hour. How many hours did they both ride scooters in total (expressed as a fraction)? Combine the hours they both rode and simplify the fraction to get the answer.

InternLM-Math Base 7B:

 Reasoning: Josh rode the scooter for 1/12+1/12 = <<1/12+1/12=1/6>>1/6 of an additional hour.
Josh rode a total of 18+1/6 = <<18+1/6=19 1/6>>19 1/6 hours.
Jack rode 7/17 = <<7/17>>7/17 hours.
The two of them rode 19 1/6+7/17 = <<19 1/6+7/17=19 9/17>>19 9/17 hours in total.
### Answer: 19 9/17

Expected answer: 3773/204

Correct? No

πŸ”— Problem

Problem: A lamp store owner is doing inventory of all the lamps in his store. He found that he has 4/26 of lamps that are floor lamps, 15/11 that are desk lamps, he also discovered he has 23/28 of table lamps and finally 8/19 of lamps that are decorative. What fraction of his total inventory do these lamps constitute?

InternLM-Math Base 7B:

 Answer: 4/26+15/11+23/28+8/19= <<4/26+15/11+23/28+8/19= 8/19+4/26+15/11+23/28= 8/19+8/19+4/26+15/11= 16/19+4/26+15/11= 16/19+8/26+15/11= 16/19+8/26+8/11= 16/19+8/26+8/11= 16/19+8/19= 24/19= 1 5/19>>1 5/19

Expected answer: 209967/76076

Correct? No

πŸ”— Problem

Problem: Oliver has a kite string that is 26/19 meters long and another kite string that is 7/11 meters long. He decides to add these two strings to create an even longer kite string. Later on, he decides to use only 5/8 of this combined string. How long is the kite string that he is using now? Do not simplify your fractions within your calculation.

InternLM-Math Base 7B:


        

Expected answer: 2095/1672

Correct? No

πŸ”— Problem

Problem: In a snow fight, Mike threw 9/19 of his snowballs and his friend, John threw 6/8 of his snowballs. After a while, Mike found 4 more snowballs to throw. The question is, if 'u' represents the number of snowballs thrown by both Mike and John and 'j' is the total number of snowballs Mike had after finding more, how many snowballs did Mike have in total? Solve the following equations to find the variable 'j': u = 9/19 + 6/8 j = u + 4/1

InternLM-Math Base 7B:

 Mike and John threw a total of <<9/19+6/8= 8.9>>8.9 snowballs. Mike found 4 more snowballs, so he has 8.9+4/1 = <<8.9+4=12.9>>12.9 snowballs in total.

Expected answer: 397/76

Correct? No

πŸ”— Problem

Problem: In a chocolate factory, one worker packages 26 pieces of chocolate in 18 minutes, while another worker can package 15 pieces of chocolate every 15 minutes. Find out the total amount of chocolate they can package in one minute.

InternLM-Math Base 7B:

 Reasoning: The first worker can package 26/18 = <<26/18=1.44>>1.44 pieces of chocolate in one minute. The second worker can package 15/15 = <<15/15=1>>1 piece of chocolate in one minute. The first worker can package 1.44+1 = <<1.44+1=2.44>>2.44 pieces of chocolate in one minute. ### Answer: 2.44

Expected answer: 22/9

Correct? No

πŸ”— Problem

Problem: Yesterday, Joanna washed 24/20 batches of small towels and 25/15 batches of large towels. Find the total number of batches of towels she washed.

InternLM-Math Base 7B:

 Reasoning: Joanna washed 24/20*1.25 = <<24/20*1.25=1.2>>1.2*25/15 = <<1.2*25/15=3>>3 batches of towels.

Expected answer: 43/15

Correct? No

πŸ”— Problem

Problem: Debra is baking cookies and she realizes she has two different recipes for the same type of cookie. She's wondering if she combines the ingredients from both, if she will end up with even more cookies or not. The first recipe requires (27 / 3) cups flour and (11 / 7) cups sugar. She determines the ratio of flour to sugar by dividing the amount of flour by the amount of sugar. She then subtracts (21 / 26) from this ratio because that's how many cups of sugar her friend says makes the cookies too sweet. After that, she adds (22 / 9) cups of flour from the second recipe to the new ratio to see how many total cups of flour she will need. How many cups of flour will she have in the end?

InternLM-Math Base 7B:

 Reasoning: Debra's new recipe will have a ratio of flour to sugar of <<(27/3-21/26+22/9)/(11/7-21/26+22/9)=(9/3-3/26+22/9)/(11/7-3/26+22/9)=9/3-3/26+22/9-9/7+3/26-22/9=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-9/7=9/3-9/7-3/26-

Expected answer: 18955/2574

Correct? No

πŸ”— Problem

Problem: There are 26/13 chickens in one farm and 9/16 chickens in another farm. Farmer John calculated the difference between the number of chickens in the two farms. After a week, the number of chickens multiplied by 19/21 due to new chickens born. How many chickens are there now in Farmer John's farm?

InternLM-Math Base 7B:

 Reasoning: The number of chickens in the first farm is 26/13. The number of chickens in the second farm is 9/16. The number of chickens in the first farm is greater than the number of chickens in the second farm by 26/13-9/16 = <<26/13-9/16= 8/24= 1/3>>1/3. The number of chickens in the first farm is 8/3. The number of chickens in the first farm is 8/3*19/21 = <<8/3*19/21= 8*19/3*21= 152/21>>152/21. The number of chickens in the first farm is 152/21.
### Answer: 152/21

Expected answer: 437/336

Correct? No

πŸ”— Problem

Problem: A helicopter traveled a distance of 24/14 miles for a training exercise. During a second exercise, the helicopter flew the same distance. If we let 'w' be the distance flown for each exercise and 't' be the total distance flown for both exercises represented as the product of 'w' times 'w', what is the value of 't'?

InternLM-Math Base 7B:

 Reasoning: The total distance flown for both exercises is 24/14*24/14 = 576/196 = <<576/196=3>>3.
### Answer: 3

Expected answer: 144/49

Correct? No

πŸ”— Problem

Problem: A UFO has made two fuel stops. During the first refuel, the UFO was able to fill 20/16 of its fuel tank. At the second fuel stop, the UFO filled another 24/25 of its tank. Calculate the total fraction of the tank that the UFO was able to refill during these two stops.

InternLM-Math Base 7B:

 Reasoning: The first refuel filled the tank 20/16 = <<20/16=5/4>>5/4 of the way. The second refuel filled the tank 24/25 = <<24/25=24/25>>24/25 of the way. The total refill is 5/4+24/25 = <<5/4+24/25= 9/5+24/25= 9/5+96/25= 9/5+3 21/25= 12 21/25= 12 21/25= 123/25= 123/25= 49/10>>49/10 of the tank.
### Answer: 49/10

Expected answer: 221/100

Correct? No

πŸ”— Problem

Problem: Professor Astro is working on his telescope. He believes the power of his telescope is directly proportional to the sum of two fractions. The first fraction is the light gathering power of the lens, which is 24 out of 27. The second fraction is the zooming potential, which is 30 out of 26. So, Professor Astro calculates the sum of these two fractions ((24 / 27) + (30 / 26)). What does he find?

InternLM-Math Base 7B:


        

Expected answer: 239/117

Correct? No

πŸ”— Problem

Problem: Kiki is a lively little monkey. She loves eating bananas. She ate 11/6 bananas in the morning and the same amount in the afternoon. How many bananas did she eat in total? Express your answer as an improper fraction.

InternLM-Math Base 7B:

 Reasoning: Kiki ate 11/6+11/6 = <<11/6+11/6=22/6>>22/6 bananas in total.
### Answer: 22/6

Expected answer: 11/3

Correct? Yes

πŸ”— Follow-up

Problem: Kiki realized that she miscounted the amount of bananas she ate. Instead of eating 11/6 bananas in the morning, she actually ate 11 whole bananas in the morning and another 11 in the afternoon. Given this new information, how many bananas did Kiki eat in total?

InternLM-Math Base 7B:

  Reasoning: Kiki ate 11/1+11/1 = <<11/1+11/1=22/1>>22/1 bananas in total.
### Answer: 22/1

Expected answer: 22

Correct? Yes

πŸ”— Problem

Problem: Jaden is a dairy farmer who milks his cows twice a day. In the morning, his cows give him 26/14 gallons of milk per cow, and in the evening, they give 28/20 gallons of milk per cow. If he multiplies these two fractions together, how much milk is he getting from one cow in one day?

InternLM-Math Base 7B:

 Reasoning: 1/2 β‹… 1/3 = <<1/2 β‹… 1/3=1/6>>1/6
### Answer: 1/6

Expected answer: 13/5

Correct? No