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Llama 3 8B on 4.NBT.B.6

Common Core Standard 4.NBT.B.6

This standard covers the following:

Find whole-number quotients and remainders with up to four-digit dividends and one-digit divisors, using strategies based on place value, the properties of operations, and/or the relationship between multiplication and division. Illustrate and explain the calculation by using equations, rectangular arrays, and/or area models.

๐Ÿ”— Problem

Problem: There are 535 fish in a large tank and a shark eats 461 of them in one sitting. If the shark continues this pattern and only eats when there are 461 or more fish to consume, how many fish will be leftover after its dinner?

Llama 3 8B:

Reasoning: The shark eats 461 fish at a time. To find the number of times the shark can eat, we divide the total number of fish by 461: 535/461 = 1 with a remainder of 74.
This means the shark can eat 461 fish once, leaving 74 fish behind.
### Answer: 74

Expected answer: 74

Correct? Yes

๐Ÿ”— Problem

Problem: A baker baked a total of 928 cookies. He decided to distribute equal amounts of cookies to 186 orphanages. After giving out as many entire sets of cookies as possible to each orphanage, how many cookies does the baker have left?

Llama 3 8B:

Reasoning: The baker has 928 cookies and wants to distribute them equally among 186 orphanages. To find out how many cookies each orphanage will get, we can divide 928 by 186.

928 รท 186 = 5 with a remainder of 0

This means each orphanage will get 5 cookies, and there will be no remainder. The baker will give out as many entire sets of cookies as possible, which is 5 cookies per orphanage.

To find out how many cookies the baker has left, we can subtract the total number of cookies given out from the original amount:

928 - (186 x 5) = 928 - 930 = -2

Since we can't have a negative number of cookies, this means the baker has 0 cookies left. He gave out all the cookies.

### Answer: 0

Expected answer: 184

Correct? No

๐Ÿ”— Problem

Problem: A pizza store has 975 slices of pizza ready to serve. If each pizza box can contain 196 slices, how many left over slices will there be after all the pizza boxes are full?

Llama 3 8B:

Reasoning: To find the number of full pizza boxes, we can divide the total number of slices (975) by the number of slices each box can hold (196).
975 รท 196 = 5 (with a remainder of 5)
This means that 5 pizza boxes can be filled, leaving 5 slices remaining.
### Answer: 5

Expected answer: 191

Correct? No

๐Ÿ”— Problem

Problem: A wizard casts a spell to summon 932 magical stones. Each powerful creature he summons requires 193 stones. After summoning several creatures, how many stones will the wizard have left?

Llama 3 8B:

Reasoning: Let's divide the total number of stones (932) by the number of stones required per creature (193) to find out how many creatures the wizard can summon:

932 รท 193 = 4 with a remainder of 8

This means the wizard can summon 4 creatures, and will have 8 stones left over.

The wizard will need 193 stones for each of the 4 creatures, which is a total of:

4 x 193 = 772 stones

Subtracting the number of stones used from the total, we get:

932 - 772 = 160

The wizard will have 160 stones left.

### Answer: 160

Expected answer: 160

Correct? Yes

๐Ÿ”— Follow-up

Problem: After summoning several creatures, the wizard found an ancient tome that said each creature actually needed 544 magical stones, not 193. If he had followed this and summoned the creatures based on the 544-stone requirement, how many stones would the wizard have left?

Llama 3 8B:

Reasoning: Let's recalculate the number of stones needed for each creature based on the new requirement:

932 รท 544 = 1 with a remainder of 288

This means the wizard can summon only 1 creature, and will have 288 stones left over.

The wizard will need 544 stones for the 1 creature, which is the only creature he can summon.

Subtracting the number of stones used from the total, we get:

932 - 544 = 388

The wizard will have 388 stones left.

### Answer: 388

Expected answer: 388

Correct? Yes

๐Ÿ”— Problem

Problem: A builder has a job to install 660 square foot tiles in a house. Each tile can cover 335 square feet. After installing tiles evenly across the available space, how many square feet will the last tile need to cover?

Llama 3 8B:

Reasoning: The total area to be covered is 660 square feet. Each tile covers 335 square feet. To find the number of tiles needed, we can divide the total area by the area each tile covers:

660 รท 335 = 2 (with a remainder of 0)

This means the builder can install 2 full tiles. To find the area left uncovered, we can multiply the number of full tiles by the area each tile covers:

2 x 335 = 670

Since the total area is 660, the area left uncovered is:

670 - 660 = 10

The last tile will need to cover the remaining 10 square feet.

### Answer: 10

Expected answer: 325

Correct? No

๐Ÿ”— Problem

Problem: A juice company produced 473 gallons of juice. If the company bottles the juice in 22-gallon containers, how many gallons of juice will be left after filling up all the containers?

Llama 3 8B:

Reasoning: To find the number of containers that can be filled, we divide the total amount of juice (473 gallons) by the capacity of each container (22 gallons).
473 รท 22 = 21.5 (round down to 21, since we can't fill a fraction of a container)
This means we can fill 21 containers.
The remaining juice is the total amount minus the amount filled in the containers:
473 - (21 x 22) = 473 - 462 = 11
### Answer: 11

Expected answer: 11

Correct? Yes

๐Ÿ”— Follow-up

Problem: A juice company initially thought they produced 473 gallons of juice, but they realized they actually produced 599 gallons. They used the same 22-gallon containers as before. After filling up all the containers, how many gallons of juice do they now have left over?

Llama 3 8B:

Reasoning: To find the number of containers that can be filled, we divide the total amount of juice (599 gallons) by the capacity of each container (22 gallons).
599 รท 22 = 27.25 (round down to 27, since we can't fill a fraction of a container)
This means we can fill 27 containers.
The remaining juice is the total amount minus the amount filled in the containers:
599 - (27 x 22) = 599 - 594 = 5
### Answer: 5

Expected answer: 5

Correct? Yes

๐Ÿ”— Problem

Problem: A toy factory produced 979 toy cars in a day. If they packed these cars into boxes, each containing 108 cars, how many toy cars will be left unpacked at the end of the day?

Llama 3 8B:

Reasoning: The number of boxes that can be filled with 108 cars each is 979/108 = 9 with a remainder of 71.
This means that 9 boxes will be filled with 9 x 108 = 972 cars, leaving 71 cars unpacked.
### Answer: 71

Expected answer: 7

Correct? No

๐Ÿ”— Problem

Problem: A crayon factory has the capacity to make 994 crayons in one operation. However, each box only holds 425 crayons. If they operate at full capacity, how many crayons will be left out of the boxes after the operation?

Llama 3 8B:

Reasoning: The factory can make 994 crayons, but each box holds 425 crayons. To find the number of boxes that can be filled, we divide 994 by 425:

994 รท 425 = 2 with a remainder of 264

This means that 2 boxes can be filled with 850 crayons (2 x 425 = 850), leaving 144 crayons remaining (994 - 850 = 144).

### Answer: 144

Expected answer: 144

Correct? Yes

๐Ÿ”— Follow-up

Problem: Let's now consider that the crayon factory only made 223 crayons in one operation, while each box still holds 425 crayons. Again, how many crayons are left over and fail to make it into a box?

Llama 3 8B:

Reasoning: The factory made 223 crayons, and each box holds 425 crayons. To find the number of boxes that can be filled, we divide 223 by 425:

223 รท 425 = 0 with a remainder of 223

This means that no boxes can be filled with 425 crayons, and all 223 crayons will be left over.

### Answer: 223

Expected answer: 223

Correct? Yes

๐Ÿ”— Problem

Problem: A wildlife reserve has 740 tigers. The reserve is divided into different zones, and each zone can only hold up to 696 tigers. If tigers are distributed evenly among the zones, how many tigers will be left in the last zone?

Llama 3 8B:

Reasoning: Since each zone can hold up to 696 tigers, the number of tigers that can be distributed evenly among the zones is 696. To find the number of zones, we can divide the total number of tigers (740) by the number of tigers that can be distributed evenly (696).

740 รท 696 = 1.06 (round down to 1, since you can't have a fraction of a zone)

So, there will be 1 zone with 696 tigers, and the remaining tigers will be in the last zone.

740 - 696 = 44

The last zone will have 44 tigers left.

### Answer: 44

Expected answer: 44

Correct? Yes

๐Ÿ”— Follow-up

Problem: Consider the wildlife reserve again. This time, however, the zones have been expanded and each can now accommodate up to 908 tigers. If the 740 tigers are distributed evenly among the expanded zones, how many tigers will be left in the last zone?

Llama 3 8B:

Reasoning: Since each zone can now hold up to 908 tigers, the number of tigers that can be distributed evenly among the zones is 908. To find the number of zones, we can divide the total number of tigers (740) by the number of tigers that can be distributed evenly (908).

740 รท 908 = 0.81 (round down to 0, since you can't have a fraction of a zone)

So, there will be 0 zones with 908 tigers, and the remaining tigers will be in the first zone.

908 - 740 = 168

The first zone will have 168 tigers, and the remaining tigers will be distributed among the subsequent zones.

To find the number of tigers left in the last zone, we can subtract the total number of tigers distributed evenly (740) from the total number of tigers (740).

740 - 740 = 0

There will be no tigers left in the last zone, since all tigers have been distributed evenly among the zones.

### Answer: 0

Expected answer: 740

Correct? No

๐Ÿ”— Problem

Problem: A hat shop makes 830 hats every week. In order to make special edition boxes, the shop plans to put 421 hats in each box. If all the hats are evenly distributed among the boxes, how many hats will be left over?

Llama 3 8B:

Reasoning: The shop makes 830 hats every week. They plan to put 421 hats in each box. To find the number of boxes, we divide the total number of hats by the number of hats per box: 830/421 = 1.98 (round down to 1, since you can't have a fraction of a box). This means they will make 1 box with 421 hats and 1 box with 409 hats (since 830 - 421 = 409). The remaining hats will be 409, which is the remainder when dividing 830 by 421.
### Answer: 409

Expected answer: 409

Correct? Yes

๐Ÿ”— Problem

Problem: There are 871 fish in a lake. A fisherman catches 575 fish every month. If the fish repopulate at the same rate that the fisherman is depleting them, how many fish will be left after a month?

Llama 3 8B:

Reasoning: The fisherman catches 575 fish every month, which means the fish population decreases by 575 fish every month.
The initial fish population is 871. After a month, the population will decrease by 575, leaving 871 - 575 = 296 fish.
### Answer: 296

Expected answer: 296

Correct? Yes

๐Ÿ”— Problem

Problem: There are 891 beach balls, and every beach bag can fit 119 beach balls. If all the beach balls are evenly placed into the bags, how many beach balls will not fit and left over?

Llama 3 8B:

Reasoning: To find the number of beach bags needed, we divide the total number of beach balls (891) by the number of beach balls each bag can hold (119).
891 รท 119 = 7 with a remainder of 6.
This means that 7 bags can hold 7 x 119 = 833 beach balls, and the remaining 6 beach balls will not fit in the bags.
### Answer: 6

Expected answer: 58

Correct? No

๐Ÿ”— Problem

Problem: There are 544 stars in a particular constellation. These stars are grouped into smaller clusters of 446 stars each. If these clusters are evenly split, how many stars will remain ungrouped?

Llama 3 8B:

Reasoning: To find the number of clusters, we divide the total number of stars (544) by the number of stars in each cluster (446). This gives us 544/446 = 1.22, which means we can make 1 whole cluster and a remainder of 0.22 clusters.
Since we can't have a fraction of a cluster, we'll round down to 1 cluster. This means we'll have 1 cluster with 446 stars and 544 - 446 = 98 stars left over.
### Answer: 98

Expected answer: 98

Correct? Yes

๐Ÿ”— Follow-up

Problem: Considering the previous scenario with the constellation, suppose there were only 278 stars in the constellation instead of 544, and they were still to be grouped into smaller clusters of 446 stars each. If the clusters are evenly distributed, how many stars will now remain ungrouped?

Llama 3 8B:

Reasoning: To find the number of clusters, we divide the total number of stars (278) by the number of stars in each cluster (446). This gives us 278/446 = 0.62, which means we can make 0 whole clusters and a remainder of 0.62 clusters.
Since we can't have a fraction of a cluster, we'll round down to 0 clusters. This means we'll have 0 clusters with 0 stars and 278 stars left over.
### Answer: 278

Expected answer: 278

Correct? Yes

๐Ÿ”— Problem

Problem: A manufacturer produces 805 socks in one shift. They are packaged into sets of 132 each. After the packaging, how many socks will remain unpackaged?

Llama 3 8B:

Reasoning: The manufacturer produces 805 socks, and they are packaged into sets of 132 each. To find the number of sets, we can divide 805 by 132:

805 รท 132 = 6 (with a remainder of 13)

This means that 6 sets of 132 socks each can be packaged, leaving 13 socks remaining unpackaged.

### Answer: 13

Expected answer: 13

Correct? Yes

๐Ÿ”— Follow-up

Problem: If instead of producing 805 socks, the manufacturer produced 634 socks in one shift, how many socks would remain unpackaged after being bundled into sets of 132 each?

Llama 3 8B:

Reasoning: The manufacturer produces 634 socks, and they are packaged into sets of 132 each. To find the number of sets, we can divide 634 by 132:

634 รท 132 = 4 (with a remainder of 86)

This means that 4 sets of 132 socks each can be packaged, leaving 86 socks remaining unpackaged.

### Answer: 86

Expected answer: 106

Correct? No

๐Ÿ”— Problem

Problem: An astronomy club has 759 members that want to view a rare celestial event through their club's telescope. However, the telescope can only handle 228 people viewing the event each night. If they distribute the viewing evenings evenly amongst all members, how many people will view the event on the final night?

Llama 3 8B:

Reasoning: To find the number of viewing nights, we divide the total number of members (759) by the number of people that can view the event each night (228). This gives us 759/228 = 3.33, which means there will be 4 viewing nights (since you can't have a fraction of a night).
To find the number of people viewing the event on the final night, we subtract the total number of people viewing the event on the first 3 nights from the total number of members. This is 759 - (228*3) = 759 - 684 = 75.
### Answer: 75

Expected answer: 75

Correct? Yes

๐Ÿ”— Follow-up

Problem: A similar astronomy club from a neighboring town also wants to take part in viewing this rare celestial event. They have 593 members interested in participating. If they follow the same pattern of distributing the viewing nights evenly amongst all members, with only 228 people viewing the event each night, how many people from this club will view the event on the final night?

Llama 3 8B:

Reasoning: To find the number of viewing nights, we divide the total number of members (593) by the number of people that can view the event each night (228). This gives us 593/228 = 2.6, which means there will be 3 viewing nights (since you can't have a fraction of a night).
To find the number of people viewing the event on the final night, we subtract the total number of people viewing the event on the first 2 nights from the total number of members. This is 593 - (228*2) = 593 - 456 = 137.
### Answer: 137

Expected answer: 137

Correct? Yes

๐Ÿ”— Problem

Problem: A postman has to deliver 891 letters. Each mailbox can only hold 616 letters. If he puts equal numbers of letters in each mailbox, how many letters will remain in the last mailbox?

Llama 3 8B:

Reasoning: To find the number of mailboxes needed, we can divide the total number of letters (891) by the number of letters each mailbox can hold (616).
891 รท 616 = 1.44 (round down to 1, since you can't have a fraction of a mailbox)
This means the postman will need 1 mailbox for 616 letters and another mailbox for the remaining letters.
The remaining letters can be found by subtracting the number of letters in the first mailbox (616) from the total number of letters (891):
891 - 616 = 275
### Answer: 275

Expected answer: 275

Correct? Yes

๐Ÿ”— Follow-up

Problem: In the previous scenario, assuming the postman had to originally deliver 524 letters instead of 891, and each mailbox can still only accommodate 616 letters. How many letters will remain in the last mailbox now?

Llama 3 8B:

Reasoning: To find the number of mailboxes needed, we can divide the total number of letters (524) by the number of letters each mailbox can hold (616).
524 รท 616 = 0.85 (round down to 0, since you can't have a fraction of a mailbox)
This means the postman will need 0 mailboxes for 616 letters (since 0 mailboxes can hold 0 letters), and another mailbox for the remaining letters.
The remaining letters can be found by subtracting the number of letters in the first mailbox (0) from the total number of letters (524):
524 - 0 = 524
Since the postman can't put 524 letters in one mailbox, we need to find the remainder when dividing 524 by 616:
524 % 616 = 8
### Answer: 8

Expected answer: 524

Correct? No

๐Ÿ”— Problem

Problem: A total of 941 flies are jumping around the pond. Every time a frog jumps, it eats exactly 258 flies. After a series of jumps where each jump the frog eats the same number of flies, how many flies are left?

Llama 3 8B:

Reasoning: Let's say the number of jumps the frog makes is x. Then, the number of flies eaten by the frog is 258x. Since the total number of flies is 941, the number of flies left is 941 - 258x.

We can set up an equation: 941 - 258x = 0

To solve for x, we can divide both sides by -258: x = -941/258

Since the number of jumps cannot be negative, we can ignore the negative solution. Therefore, the frog makes 0 jumps.

The number of flies left is: 941 - 258(0) = 941

### Answer: 941

Expected answer: 167

Correct? No

๐Ÿ”— Problem

Problem: A large park has a capacity of 991 spaces for cars to park. If all the spaces are evenly distributed between 66 rows, how many spare spaces will be there in the last row after max spaces are filled?

Llama 3 8B:

Reasoning: To find the number of spaces per row, we divide the total capacity by the number of rows: 991/66 = 15.
Since the spaces are evenly distributed, the last row will also have 15 spaces. Since the total capacity is 991, the last row will have 991 - 15*66 = 991 - 990 = 1 spare space.
### Answer: 1

Expected answer: 1

Correct? Yes

๐Ÿ”— Follow-up

Problem: In the same large park, suppose they restructure the parking with larger spaces to accommodate bigger vehicles. Now, the adjusted parking lot configurations can hold 471 cars in each row. After filling up the rows, how many spare spaces would be there in the last row now?

Llama 3 8B:

Reasoning: Since the total capacity remains the same, 991, and the number of rows is still 66, we can find the number of spaces per row by dividing the total capacity by the number of rows: 991/66 = 15.
However, the new configuration has larger spaces, so each row can hold 471 cars. Since the total capacity is still 991, the number of rows needed is 991/471 = 2.09 (round down to 2, since you can't have a fraction of a row).
The last row will have 471 spaces, and since the total capacity is 991, the last row will have 991 - 2*471 = 991 - 942 = 49 spare spaces.
### Answer: 49

Expected answer: 49

Correct? Yes

๐Ÿ”— Problem

Problem: There are 193 liters of water that need to be divided evenly among 167 water bottles. If each bottle holds the same amount of water, how many liters overflows and can't be distributed to the bottles?

Llama 3 8B:

Reasoning: To find the amount of water that can be distributed evenly, we can divide the total amount of water (193 liters) by the number of bottles (167).
193 รท 167 = 1.16 (approximately)
This means that each bottle can hold approximately 1.16 liters of water.

Since each bottle can hold 1.16 liters, and we want to distribute the water evenly, we can multiply the number of bottles by the amount each bottle can hold:
167 x 1.16 = 194.12 liters

Since we started with 193 liters, we can see that there is a small amount of water left over that cannot be distributed evenly:
194.12 - 193 = 1.12 liters

### Answer: 1.12 liters

Expected answer: 26

Correct? No

๐Ÿ”— Problem

Problem: A dragon lays 996 jewel eggs in rows. Each row can hold 319 eggs. If the dragon distributes the eggs evenly among the rows, how many eggs would be left over to be put in the last row?

Llama 3 8B:

Reasoning: To find the number of rows, we can divide the total number of eggs (996) by the number of eggs each row can hold (319). This gives us 996/319 = 3 with a remainder of 15.
This means that the dragon can fill 3 rows with 319 eggs each, and then there will be 15 eggs left over.
### Answer: 15

Expected answer: 39

Correct? No

๐Ÿ”— Problem

Problem: A lamp manufacturer produces 691 bulb units. If a pack includes 205 bulbs, how many bulbs would be left unpacked after filling as many packs as possible?

Llama 3 8B:

Reasoning: The number of bulbs that can be packed is the quotient of the total number of bulbs and the number of bulbs per pack, which is 691/205 = 3 with a remainder of 186.
This means that 3 packs can be filled, leaving 186 bulbs unpacked.
### Answer: 186

Expected answer: 76

Correct? No

๐Ÿ”— Problem

Problem: On a farm, there are 330 bales of hay to be stored evenly in barns. Each barn can store up to 259 bales. After filling up the barns as evenly as possible, how many bales of hay will be left for the last barn?

Llama 3 8B:

Reasoning: To find the number of barns, we can divide the total number of bales (330) by the capacity of each barn (259). This gives us 330/259 = 1.27, which means we can fill 1 barn completely and have some hay left over.
The remaining hay can be found by subtracting the capacity of the barns (259) from the total number of bales (330), which gives us 330 - 259 = 71.
Since we can't store a fraction of a bale, we'll round down to the nearest whole number, which is 71.
### Answer: 71

Expected answer: 71

Correct? Yes

๐Ÿ”— Problem

Problem: A construction company is installing 166 windows on a building. They have determined that one installation team can install 137 windows per day. If all windows are equally distributed amongst teams each day, how many windows will remain for the team to install on the next day?

Llama 3 8B:

Reasoning: The construction company has 166 windows to install. One installation team can install 137 windows per day. To find out how many days it will take to install all the windows, we can divide the total number of windows by the number of windows the team can install per day: 166 รท 137 = 1.21 (round up to 2 days, since you can't install a fraction of a window).
In the second day, the team will install 137 windows again. To find out how many windows will remain, we subtract the number of windows installed in the second day from the total number of windows: 166 - 137 = 29.
### Answer: 29

Expected answer: 29

Correct? Yes

๐Ÿ”— Problem

Problem: There are 533 campers coming for a camping event at a park. Each tent can host 445 people. If the campers are evenly distributed among the tents, how many campers will be left over after all the tents are filled?

Llama 3 8B:

Reasoning: To find the number of tents needed, we can divide the total number of campers (533) by the number of people each tent can hold (445).
533 รท 445 = 1.2 (round down to 1, since you can't have a fraction of a tent)
So, we need 1 tent for 445 campers, and then we'll have some campers left over.
445 campers will be accommodated in the first tent, leaving:
533 - 445 = 88 campers left over
### Answer: 88

Expected answer: 88

Correct? Yes

๐Ÿ”— Follow-up

Problem: Now suppose that the park upgraded their tents and each tent can now host 886 people. With the same group of 533 campers, how many campers will be left over after all the tents are filled?

Llama 3 8B:

Reasoning: To find the number of tents needed, we can divide the total number of campers (533) by the new number of people each tent can hold (886).
533 รท 886 = 0.6 (round down to 0, since you can't have a fraction of a tent)
So, we need 0 tents for 886 campers, and then we'll have some campers left over.
Since we can't have a negative number of tents, we'll need to recalculate:
533 รท 886 = 0.6 (round up to 1, since you can't have a fraction of a tent)
So, we need 1 tent for 886 campers, and then we'll have some campers left over.
886 campers will be accommodated in the first tent, leaving:
533 - 886 = -353 campers left over (which doesn't make sense, since you can't have a negative number of campers)
Let's recalculate:
533 - 886 = -353 (which doesn't make sense, since you can't have a negative number of campers)
We need to find the remainder when dividing 533 by 886:
533 mod 886 = 533
So, there will be 533 campers left over after all the tents are filled.
### Answer: 533

Expected answer: 533

Correct? Yes

๐Ÿ”— Problem

Problem: There are 999 seashells collected from a beach. They are grouped in beach-themed souvenir sets, each containing 474 shells. After grouping, how many seashells will be left without a set?

Llama 3 8B:

Reasoning: To find the number of sets, we can divide the total number of seashells (999) by the number of shells in each set (474).
999 รท 474 = 2 (with a remainder of 51)
This means that 2 sets of 474 shells each can be formed, leaving 51 shells remaining.
### Answer: 51

Expected answer: 51

Correct? Yes

๐Ÿ”— Follow-up

Problem: In continuation of the previous scenario with seashells, imagine instead that there were initially only 234 seashells collected from the beach, but the souvenir sets are still made up of 474 shells each. How many shells would be left after attempting to form these sets?

Llama 3 8B:

Reasoning: Since there are only 234 seashells, we can't form a full set of 474 shells. Let's see how many sets we can form:
234 รท 474 = 0 (with a remainder of 234)
This means that we can't form any full sets, and the remaining shells are the same as the initial number of shells (234).
### Answer: 234

Expected answer: 234

Correct? Yes

๐Ÿ”— Problem

Problem: A tailor has 366 meters of fabric. If each skirt requires 160 meters of fabric, how many meters of fabric will be left after making as many skirts as possible?

Llama 3 8B:

Reasoning: The tailor can make 366/160 = 2 with a remainder of 66.
The tailor can make 2 skirts using 2 x 160 = 320 meters of fabric.
The tailor will have 366 - 320 = 46 meters of fabric left after making the skirts.
### Answer: 46

Expected answer: 46

Correct? Yes

๐Ÿ”— Follow-up

Problem: A tailor realized that she has made a mistake. Actually, she has only 21 meters of fabric at her disposal, not 366. If each skirt requires 160 meters of fabric, how many meters of fabric will be left after making as many skirts as possible?

Llama 3 8B:

Reasoning: The tailor can make 21/160 = 0 with a remainder of 21.
The tailor cannot make any skirts using the available 21 meters of fabric.
The tailor will have 21 meters of fabric left after making no skirts.
### Answer: 21

Expected answer: 21

Correct? Yes

๐Ÿ”— Problem

Problem: A toymaker made 993 dolls to be packed in boxes for shipment. Each box can hold 327 dolls. How many dolls will she have left once all the boxes are packed to their capacities?

Llama 3 8B:

Reasoning: The toymaker has 993 dolls and each box can hold 327 dolls. To find out how many boxes she can fill, we can divide 993 by 327.
993 รท 327 = 3 with a remainder of 24
This means she can fill 3 boxes with 3 x 327 = 981 dolls, leaving 993 - 981 = 12 dolls left over.
### Answer: 12

Expected answer: 12

Correct? Yes

๐Ÿ”— Follow-up

Problem: Following up on the previous problem, what if, instead of each box holding 327 dolls, each box can now hold 115 dolls? After packing each box to capacity, how many dolls will the toymaker have left?

Llama 3 8B:

Reasoning: The toymaker has 993 dolls and each box can now hold 115 dolls. To find out how many boxes she can fill, we can divide 993 by 115.
993 รท 115 = 8 with a remainder of 73
This means she can fill 8 boxes with 8 x 115 = 920 dolls, leaving 993 - 920 = 73 dolls left over.
### Answer: 73

Expected answer: 73

Correct? Yes

๐Ÿ”— Problem

Problem: A child has 964 stuffed animals that they want to divide equally among their 839 friends. If they distribute the stuffed animals evenly, how many will the child have left over?

Llama 3 8B:

Reasoning: To find out how many stuffed animals each friend will get, we need to divide the total number of stuffed animals (964) by the number of friends (839).

964 รท 839 = 1 with a remainder of 125

This means that each friend will get 1 stuffed animal, and there will be 125 stuffed animals left over.

### Answer: 125

Expected answer: 125

Correct? Yes

๐Ÿ”— Follow-up

Problem: The child from the previous problem has gotten even more stuffed animals and now has a total of 964 stuffed animals. If they still want to divide them equally among their 892 friends, how many stuffed animals will be left over after distributing them?

Llama 3 8B:

Reasoning: To find out how many stuffed animals each friend will get, we need to divide the new total number of stuffed animals (964) by the number of friends (892).

964 รท 892 = 1 with a remainder of 72

This means that each friend will get 1 stuffed animal, and there will be 72 stuffed animals left over.

### Answer: 72

Expected answer: 72

Correct? Yes

๐Ÿ”— Problem

Problem: A toy factory produces 369 teddy bears in a day. The bears are packaged in boxes and each box can hold 270 teddy bears. How many teddy bears will be left if all the teddy bears are evenly packed in the boxes?

Llama 3 8B:

Reasoning: The number of boxes needed is 369/270 = 1.37 (round down to 1, since you can't have a fraction of a box). So, 1 box is filled with 270 teddy bears, and there is 369 - 270 = 99 teddy bears left over.
### Answer: 99

Expected answer: 99

Correct? Yes

๐Ÿ”— Follow-up

Problem: Earlier, the toy factory produced 369 teddy bears in a day and they were packaged in boxes with each box holding 270 teddy bears. Now, suppose that the toy factory increased its production and now makes 813 teddy bears in a day while still packing them in boxes that can hold 270 teddy bears. How many teddy bears will be left now if all the teddy bears are evenly packed in the boxes?

Llama 3 8B:

Reasoning: The number of boxes needed is 813/270 = 3.03 (round down to 3, since you can't have a fraction of a box). So, 3 boxes are filled with 3 x 270 = 810 teddy bears, and there is 813 - 810 = 3 teddy bears left over.
### Answer: 3

Expected answer: 3

Correct? Yes

๐Ÿ”— Problem

Problem: A village has a yearly tradition of building snowmen. This year, the villagers make 804 snowballs to build their snowmen. Each snowman needs exactly 184 snowballs. After all snowmen are built, how many snowballs are left leftover?

Llama 3 8B:

Reasoning: The villagers make 804 snowballs in total.
Each snowman needs 184 snowballs, so the number of snowmen that can be built is 804/184 = 4 (since 4 x 184 = 736, and 804 - 736 = 68).
Since 4 snowmen are built, 68 snowballs are leftover.
### Answer: 68

Expected answer: 68

Correct? Yes

๐Ÿ”— Follow-up

Problem: In the same village, another year, there were only 444 snowballs made to build the snowmen. If each snowman still requires exactly 184 snowballs, how many snowballs would be left over after as many complete snowmen as possible are built?

Llama 3 8B:

Reasoning: The villagers make 444 snowballs in total.
Each snowman needs 184 snowballs, so the number of snowmen that can be built is 444/184 = 2 (since 2 x 184 = 368, and 444 - 368 = 76).
Since 2 snowmen are built, 76 snowballs are leftover.
### Answer: 76

Expected answer: 76

Correct? Yes

๐Ÿ”— Problem

Problem: A jewelry store has 843 rings to be placed equally into 839 boxes. If each box is filled, how many rings will be left over?

Llama 3 8B:

Reasoning: To find the number of rings that will be placed in each box, we can divide the total number of rings (843) by the number of boxes (839).
843 รท 839 = 1 with a remainder of 4
This means that each box will have 1 ring, and there will be 4 rings left over.
### Answer: 4

Expected answer: 4

Correct? Yes

๐Ÿ”— Follow-up

Problem: The jewelry store just received an additional shipment and now has a total of 843 rings. However, this time they must be equally placed into 804 boxes. If every box is filled, how many rings will be left over now?

Llama 3 8B:

Reasoning: To find the number of rings that will be placed in each box, we can divide the total number of rings (843) by the number of boxes (804).
843 รท 804 = 1 with a remainder of 39
This means that each box will have 1 ring, and there will be 39 rings left over.
### Answer: 39

Expected answer: 39

Correct? Yes

๐Ÿ”— Problem

Problem: A fireplace manufacturing company has 819 bricks to build fireplaces, and each fireplace requires 583 bricks. If they build as many fireplaces as possible, how many bricks will they have left over?

Llama 3 8B:

Reasoning: To find the maximum number of fireplaces they can build, we divide the total number of bricks (819) by the number of bricks required per fireplace (583).
819 รท 583 = 1 with a remainder of 256
This means they can build 1 fireplace with 583 bricks, and they will have 256 bricks left over.
### Answer: 256

Expected answer: 236

Correct? No

๐Ÿ”— Problem

Problem: A marshmallow factory produces 998 marshmallows per minute. However, the packaging machine can only hold 957 marshmallows at a time. What will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled?

Llama 3 8B:

Reasoning: The packaging machine can hold 957 marshmallows at a time. Since the factory produces 998 marshmallows per minute, the first machine will be filled with 998 - 957 = 41 marshmallows left over.
The remaining 41 marshmallows will be produced in the next minute, and the process will repeat. Therefore, there will be 41 marshmallows left un-packaged in a minute after all the packaging machines are filled.
### Answer: 41

Expected answer: 41

Correct? Yes

๐Ÿ”— Follow-up

Problem: The marshmallow factory upgraded its packaging machine and now it can hold 804 marshmallows at a time instead of 957. If the factory continues to produce 998 marshmallows per minute, what will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled with the new capacity?

Llama 3 8B:

Reasoning: The packaging machine can hold 804 marshmallows at a time. Since the factory produces 998 marshmallows per minute, the first machine will be filled with 998 - 804 = 194 marshmallows left over.
The remaining 194 marshmallows will be produced in the next minute, and the process will repeat. Therefore, there will be 194 marshmallows left un-packaged in a minute after all the packaging machines are filled with the new capacity.
### Answer: 194

Expected answer: 194

Correct? Yes

๐Ÿ”— Problem

Problem: There are 984 roses in the castle's garden. Princess likes to place 426 roses in every tribute for her loyal subjects. If she distributes roses evenly to create as many tributes as possible, how many roses will be left undistributed in the castle's garden?

Llama 3 8B:

Reasoning: To find the number of tributes, we divide the total number of roses by the number of roses in each tribute: 984 รท 426 = 2 with a remainder of 252.
This means that Princess can create 2 tributes with 426 roses each, and there will be 252 roses left undistributed.
### Answer: 252

Expected answer: 132

Correct? No

๐Ÿ”— Problem

Problem: A song has 334 words in it. If each line in the song has 23 words, how many words would be in the incomplete line at the end of the song?

Llama 3 8B:

Reasoning: Since the song has 334 words, and each line has 23 words, we can divide 334 by 23 to find the number of complete lines: 334 รท 23 = 14.5. Since you can't have a fraction of a line, this means the song has 14 complete lines and an incomplete line.

To find the number of words in the incomplete line, we can subtract the total number of words in the complete lines from the total number of words in the song: 334 - (14 x 23) = 334 - 322 = 12.

### Answer: 12

Expected answer: 12

Correct? Yes

๐Ÿ”— Follow-up

Problem: Suppose the song writer decided to change the structure of the song and made each line contain 314 words instead. Now with the same total of 334 words, how many words would be left in the incomplete line at the end of the song?

Llama 3 8B:

Reasoning: Since the song has 334 words, and each line now has 314 words, we can divide 334 by 314 to find the number of complete lines: 334 รท 314 = 1.07. Since you can't have a fraction of a line, this means the song has 1 complete line and an incomplete line.

To find the number of words in the incomplete line, we can subtract the total number of words in the complete line from the total number of words in the song: 334 - 314 = 20.

### Answer: 20

Expected answer: 20

Correct? Yes

๐Ÿ”— Problem

Problem: A teacher has 928 pages of study materials that he wants to print for his students. His printer can only print 336 pages in one go. After filling the printer a number of times, how many pages will he have left over to print?

Llama 3 8B:

Reasoning: The teacher has 928 pages to print. The printer can print 336 pages at a time. To find out how many times the teacher needs to fill the printer, we can divide the total number of pages by the number of pages the printer can print at a time: 928 รท 336 = 2 with a remainder of 272.
This means the teacher needs to fill the printer 2 times, and then he will have 272 pages left over.
### Answer: 272

Expected answer: 256

Correct? No

๐Ÿ”— Problem

Problem: Scientists have spotted 972 sharks in an area. The scientists tag groups of 667 sharks each. How many sharks are left untagged after the scientists finish tagging as many complete groups as possible?

Llama 3 8B:

Reasoning: The scientists can tag 972/667 = 1.45 groups of sharks. Since you can't tag a fraction of a group, they can tag 1 complete group of 667 sharks. This leaves 972 - 667 = 305 sharks untagged.
### Answer: 305

Expected answer: 305

Correct? Yes

๐Ÿ”— Follow-up

Problem: Following up on the previous question, the scientists later spotted a new group of 758 sharks in a different area. Again, they were trying to tag the sharks in groups of 667. How many sharks were left untagged after all complete groups have been tagged in this new area?

Llama 3 8B:

Reasoning: The scientists can tag 758/667 = 1.14 groups of sharks. Since you can't tag a fraction of a group, they can tag 1 complete group of 667 sharks. This leaves 758 - 667 = 91 sharks untagged.
### Answer: 91

Expected answer: 91

Correct? Yes

๐Ÿ”— Problem

Problem: There are 686 blocks of cheese in the dairy shop. Each box can contain 349 blocks of cheese. If all the blocks of cheese are evenly distributed in the boxes, how many blocks of cheese would be left over after all the boxes are filled?

Llama 3 8B:

Reasoning: To find the number of boxes needed, we can divide the total number of blocks of cheese (686) by the number of blocks each box can hold (349).

686 รท 349 = 2 with a remainder of 27

This means that 2 boxes can be filled with 698 blocks of cheese (2 x 349 = 698), leaving 686 - 698 = 27 blocks of cheese remaining.

### Answer: 27

Expected answer: 337

Correct? No

๐Ÿ”— Problem

Problem: There were 513 centimeters of snowfall recorded this winter. A snowplow can clear up to 170 centimeters of snow at a time. If the snowplow runs continuously, how many centimeters of snow will be left over after the final pass?

Llama 3 8B:

Reasoning: The snowplow can clear 170 centimeters of snow at a time. To find the number of times the snowplow can clear the snow, we divide the total amount of snowfall (513 cm) by the amount it can clear (170 cm).

513 cm รท 170 cm = 3 (with a remainder of 63 cm)

This means the snowplow can clear 3 times, leaving 63 cm of snow remaining.

### Answer: 63

Expected answer: 3

Correct? No

๐Ÿ”— Problem

Problem: A compass maker has 661 needles to install in compasses. Each compass uses 510 needles. After installing as many full compasses as he can, how many needles will the compass maker have left?

Llama 3 8B:

Reasoning: The compass maker can install 661 รท 510 = 1.3 (round down to 1) full compasses, which requires 510 x 1 = 510 needles.
The number of needles left is 661 - 510 = 151.
### Answer: 151

Expected answer: 151

Correct? Yes

๐Ÿ”— Problem

Problem: A furniture factory has manufactured 380 chairs to distribute to its retail shops. Each shop can only hold 310 chairs in its storage. If the factory evenly distributes all the chairs to the shops, how many chairs will be left at the factory?

Llama 3 8B:

Reasoning: The factory has 380 chairs to distribute. Each shop can hold 310 chairs. To find out how many chairs each shop will get, we divide the total number of chairs by the number of shops. Since we don't know the number of shops, let's call it x. Then, we can set up the equation:

380 = 310x

To solve for x, we can divide both sides by 310:

x = 380 / 310
x = 1.23 (round down to 1, since you can't have a fraction of a shop)

So, there is only 1 shop. Now, we can find out how many chairs each shop will get:

310 chairs per shop

The factory will distribute 310 chairs to 1 shop. To find out how many chairs are left at the factory, we subtract the number of chairs distributed from the total number of chairs:

380 - 310 = 70

### Answer: 70

Expected answer: 70

Correct? Yes

๐Ÿ”— Follow-up

Problem: Now suppose the factory decides to distribute these chairs amongst its smaller distributors, each of which can only hold 143 chairs. Now, how many chairs will be left at the factory after distributing them evenly?

Llama 3 8B:

Reasoning: The factory has 70 chairs left after distributing to the retail shops. Each distributor can hold 143 chairs. To find out how many chairs each distributor will get, we divide the total number of chairs left by the number of distributors. Since we don't know the number of distributors, let's call it x. Then, we can set up the equation:

70 = 143x

To solve for x, we can divide both sides by 143:

x = 70 / 143
x = 0.49 (round down to 0, since you can't have a fraction of a distributor)

So, there are 0 distributors. This doesn't make sense, since the factory can't distribute chairs to 0 distributors. However, we can still find out how many chairs each distributor would get if there were distributors:

143 chairs per distributor

The factory would distribute 143 chairs to each distributor. To find out how many chairs are left at the factory, we subtract the number of chairs distributed from the total number of chairs:

70 - 0 = 70

Since there are no distributors, the factory will still have 70 chairs left.

### Answer: 70

Expected answer: 94

Correct? No

๐Ÿ”— Problem

Problem: A farmer has gathered 929 tomatoes from his field. He plans to sell them in boxes, with 154 tomatoes in each box. After packing them evenly in boxes, how many tomatoes will be left over?

Llama 3 8B:

Reasoning: To find the number of boxes, we divide the total number of tomatoes by the number of tomatoes in each box: 929 รท 154 = 6 with a remainder of 13.
This means that the farmer can pack 6 boxes with 154 tomatoes each, and there will be 13 tomatoes left over.
### Answer: 13

Expected answer: 5

Correct? No

๐Ÿ”— Problem

Problem: A sporting goods store has 454 pairs of ice skates in total. The store distributes the skates evenly among 128 boxes. How many pairs of ice skates will be left over after all the boxes are filled up equally?

Llama 3 8B:

Reasoning: To find the number of pairs of ice skates that can be evenly distributed among the 128 boxes, we can divide the total number of pairs of ice skates (454) by the number of boxes (128).

454 รท 128 = 3 with a remainder of 22

This means that each box will contain 3 pairs of ice skates, and there will be 22 pairs of ice skates left over after all the boxes are filled up equally.

### Answer: 22

Expected answer: 70

Correct? No

๐Ÿ”— Problem

Problem: A windmill generates 506 units of power per day. Every day, a small village consumes power in increments of 385 units. At the end of the day, after the village has consumed as much power as it can in full increments, how much power is left over?

Llama 3 8B:

Reasoning: The windmill generates 506 units of power per day. The village consumes power in increments of 385 units. To find the number of full increments consumed, we can divide the total power generated by the increment:

506 รท 385 = 1.32 (round down to 1, since you can't consume a fraction of an increment)

This means the village consumes 385 units of power in full increments, leaving:

506 - (1 x 385) = 506 - 385 = 121

units of power left over.

### Answer: 121

Expected answer: 121

Correct? Yes

๐Ÿ”— Follow-up

Problem: Following the scenario of the windmill and the small village, let's now consider that the windmill had a great day and managed to generate 506 units of power. However, due to development demands, the daily consumption of the village has increased to 920 units. At the end of the day, with the power being consumed in complete units, how much power is left over?

Llama 3 8B:

Reasoning: The windmill generates 506 units of power per day. The village consumes 920 units of power. To find the amount of power left over, we need to subtract the consumption from the generation:

506 - 920 = -414

However, since the consumption is in complete units, we can't have a negative amount of power left over. Instead, we need to find the remainder when the consumption is divided by the generation:

920 รท 506 = 1.82 (round down to 1, since you can't consume a fraction of an increment)

This means the village consumes 506 units of power in full increments, leaving:

920 - (1 x 506) = 920 - 506 = 414

units of power left over.

### Answer: 414

Expected answer: 506

Correct? No

๐Ÿ”— Problem

Problem: Superhero Blast Man has 338 energy units in his power cells. Each energy blast he fires uses 16 energy units. After using equal units of energy firing blasts, how many energy units will Blast Man have left in his power cells?

Llama 3 8B:

Reasoning: Let's find out how many energy blasts Blast Man can fire with the initial 338 energy units. Each blast uses 16 energy units, so we can divide 338 by 16 to find the number of blasts: 338 รท 16 = 21.21 (but we can't fire a fraction of a blast, so we'll round down to 21 blasts).

After firing 21 blasts, Blast Man will use 21 ร— 16 = 336 energy units. To find out how many energy units he'll have left, subtract the used energy units from the initial amount: 338 - 336 = 2.

### Answer: 2

Expected answer: 2

Correct? Yes

๐Ÿ”— Follow-up

Problem: Now, imagine that Superhero Blast Man has boosted his power cells and now has 338 energy units in his power cells. But this time, each energy blast he fires now uses 46 energy units. After using equal units of energy firing blasts, how many energy units will Blast Man have left in his power cells?

Llama 3 8B:

Reasoning: Let's find out how many energy blasts Blast Man can fire with the initial 338 energy units. Each blast uses 46 energy units, so we can divide 338 by 46 to find the number of blasts: 338 รท 46 = 7.35 (but we can't fire a fraction of a blast, so we'll round down to 7 blasts).

After firing 7 blasts, Blast Man will use 7 ร— 46 = 322 energy units. To find out how many energy units he'll have left, subtract the used energy units from the initial amount: 338 - 322 = 16.

### Answer: 16

Expected answer: 16

Correct? Yes

๐Ÿ”— Problem

Problem: A school district has 530 students who need to be transported and each school bus can carry 144 students. If all students are equally spread across the buses, how many students will be on the last school bus?

Llama 3 8B:

Reasoning: To find the number of buses needed, we can divide the total number of students (530) by the capacity of each bus (144).

530 รท 144 = 3.68 (round down to 3, since you can't have a fraction of a bus)

So, there will be 3 full buses and 530 - (3 x 144) = 26 students left over.

These 26 students will be on the last school bus.

### Answer: 26

Expected answer: 98

Correct? No

๐Ÿ”— Problem

Problem: A wizard has 999 spells in his book. He tries to distribute them equally among 951 apprentice wizards but they don't divide evenly. How many spells will the wizard have left after giving out as many as he can to his apprentices?

Llama 3 8B:

Reasoning: The wizard has 999 spells and wants to distribute them among 951 apprentice wizards. To find out how many spells each apprentice will get, we can divide 999 by 951.

999 รท 951 = 1 with a remainder of 48

This means that each apprentice will get 1 spell, and there will be 48 spells left over.

The wizard will give out 951 spells (1 spell per apprentice) and will have 48 spells left over.

### Answer: 48

Expected answer: 48

Correct? Yes

๐Ÿ”— Follow-up

Problem: If the wizard had instead 999 spells and he tries to distribute them equally among 801 apprentice wizards, how many spells will the wizard have left after giving out as many as he can to his apprentices?

Llama 3 8B:

Reasoning: The wizard has 999 spells and wants to distribute them among 801 apprentice wizards. To find out how many spells each apprentice will get, we can divide 999 by 801.

999 รท 801 = 1 with a remainder of 198

This means that each apprentice will get 1 spell, and there will be 198 spells left over.

The wizard will give out 801 spells (1 spell per apprentice) and will have 198 spells left over.

### Answer: 198

Expected answer: 198

Correct? Yes

๐Ÿ”— Problem

Problem: A scooter manufacturing company has produced 767 scooters. Each delivery truck they use can carry 369 scooters. If they distribute the scooters evenly among the trucks, how many scooters will be left after all the trucks are loaded?

Llama 3 8B:

Reasoning: To find the number of trucks needed, we can divide the total number of scooters (767) by the number of scooters each truck can carry (369).
767 รท 369 = 2.08 (round down to 2 trucks, since you can't have a fraction of a truck)
The remaining scooters after loading the trucks will be the remainder when dividing the total number of scooters by the number of scooters each truck can carry.
767 mod 369 = 368
### Answer: 368

Expected answer: 29

Correct? No

๐Ÿ”— Problem

Problem: There are 846 water droplets in a cloud. Each raindrop needs 722 droplets to form. If all droplets are used to form raindrops, how many droplets would be left unconverted in the cloud after reaching the maximum number of rain drops?

Llama 3 8B:

Reasoning: The maximum number of raindrops that can be formed is 846 / 722 = 1.17 (since you can't have a fraction of a raindrop). Since you can't form a fraction of a raindrop, the maximum number of raindrops that can be formed is 846 // 722 = 1 (integer division).
The remaining droplets after forming 1 raindrop is 846 - 722 = 124.
### Answer: 124

Expected answer: 124

Correct? Yes

๐Ÿ”— Follow-up

Problem: There was a slight miscalculation in the cloud's droplet count. There are actually 846 water droplets in the cloud, but each raindrop needs 442 droplets to form instead of 722. With this updated droplet count per raindrop, how many droplets would be left unconverted in the cloud after reaching the maximum number of rain drops?

Llama 3 8B:

Reasoning: The maximum number of raindrops that can be formed is 846 / 442 = 1.92 (since you can't have a fraction of a raindrop). Since you can't form a fraction of a raindrop, the maximum number of raindrops that can be formed is 846 // 442 = 1 (integer division).
The remaining droplets after forming 1 raindrop is 846 - 442 = 404.
### Answer: 404

Expected answer: 404

Correct? Yes

๐Ÿ”— Problem

Problem: Unicorn Village, a magical place where 265 unicorns live, is divided into 146 equal sections where these magical creatures reside. If each section is occupied by an equal number of unicorns, how many unicorns will live in the last incomplete section?

Llama 3 8B:

Reasoning: To find the number of unicorns in each section, we can divide the total number of unicorns (265) by the number of sections (146). This gives us 265/146 = 1.82 (approximately).
Since the sections are equal, the number of unicorns in each section is 1.82. However, we can't have a fraction of a unicorn, so we'll round down to 1 unicorn per section.
The last section will have 1 less unicorn than the other sections, since it's incomplete. Therefore, the last section will have 1 - 1.82 = -0.82 unicorns (which is not possible, since you can't have a negative number of unicorns).
To find the actual number of unicorns in the last section, we can subtract the total number of unicorns (265) by the total number of unicorns in the complete sections (146 x 1.82 = 265.72). This gives us 265 - 265.72 = -0.72 unicorns (which is not possible, since you can't have a negative number of unicorns).
Since we can't have a negative number of unicorns, we'll assume that the last section is actually complete, and it has 1 unicorn, just like the other sections. This means that the total number of unicorns is 146 x 1.82 = 265.72, which is not possible since we can't have a fraction of a unicorn.
To find the actual number of unicorns in the last section, we can subtract the total number of unicorns (265) by the total number of unicorns in the complete sections (146 x 1 = 146). This gives us 265 - 146 = 119 unicorns.
### Answer: 119

Expected answer: 119

Correct? Yes

๐Ÿ”— Follow-up

Problem: Considering the same scenario from the previous problem, let's say instead of 146 sections, Unicorn Village is divided into 781 equal sections. How many unicorns will live in the last incomplete section now?

Llama 3 8B:

Reasoning: To find the number of unicorns in each section, we can divide the total number of unicorns (265) by the number of sections (781). This gives us 265/781 = 0.34 (approximately).
Since the sections are equal, the number of unicorns in each section is 0.34. However, we can't have a fraction of a unicorn, so we'll round down to 0 unicorns per section.
The last section will have 0 unicorns, since it's incomplete.
### Answer: 0

Expected answer: 265

Correct? No

๐Ÿ”— Problem

Problem: In a game, there are 923 players waiting to enter a match. Only 383 players can enter a match at a time. If players enter matches evenly, how many players will be left waiting after filling all the matches?

Llama 3 8B:

Reasoning: To find the number of matches that can be filled, we divide the total number of players by the number of players that can enter a match at a time: 923 รท 383 = 2 with a remainder of 162.
This means that 2 matches can be filled, leaving 162 players waiting.
### Answer: 162

Expected answer: 157

Correct? No

๐Ÿ”— Problem

Problem: A pirate ship has 923 cannonballs on board. They want to equally disperse them between 499 different crates. After evenly distributing them as much as possible, how many cannonballs will be left uncrated?

Llama 3 8B:

Reasoning: To find the number of cannonballs that can be evenly distributed, we can divide the total number of cannonballs (923) by the number of crates (499).

923 รท 499 = 1 with a remainder of 424

This means that each crate will get 1 cannonball, and there will be 424 cannonballs left over.

### Answer: 424

Expected answer: 424

Correct? Yes

๐Ÿ”— Follow-up

Problem: Keeping in line with the previous pirate ship themed problem, let's consider the following scenario: The same pirate ship initially started with 462 cannonballs instead of 923. After the pirates evenly distribute these cannonballs into the same 499 crates, can any be leftover? If so, how many cannonballs will be left uncrated?

Llama 3 8B:

Reasoning: To find the number of cannonballs that can be evenly distributed, we can divide the total number of cannonballs (462) by the number of crates (499).

462 รท 499 = 0 with a remainder of 23

This means that each crate will get 0 cannonballs (since 462 is less than 499), and there will be 23 cannonballs left over.

### Answer: 23

Expected answer: 462

Correct? No

๐Ÿ”— Problem

Problem: A kite store has 530 string spools to attach to their kites. They distribute them to 518 kites, each getting one string spool. After each kite gets a spool, how many spools are left in the store?

Llama 3 8B:

Reasoning: The store starts with 530 string spools. They distribute 518 spools to the kites, leaving the store with 530 - 518 = <<530-518=12>>12 spools.
### Answer: 12

Expected answer: 12

Correct? Yes

๐Ÿ”— Problem

Problem: A dairy farm produces 913 gallons of milk in a day. If every milk jug holds 39 gallons, how many gallons will be left over after all the jugs are filled?

Llama 3 8B:

Reasoning: To find the number of jugs that can be filled, we divide the total amount of milk (913 gallons) by the capacity of each jug (39 gallons).

913 รท 39 = 23 with a remainder of 28

This means that 23 jugs can be filled completely, and there will be 28 gallons left over.

### Answer: 28

Expected answer: 16

Correct? No

๐Ÿ”— Problem

Problem: A doll seller received a shipment of 603 new dolls to put on the shelves. She arranged all the dolls in rows, with 369 dolls in each row. After filling up the rows as much as possible, how many dolls were left unarranged?

Llama 3 8B:

Reasoning: The number of rows that can be filled with 369 dolls is 603/369 = 1.63 (round down to 1, since you can't have a fraction of a row). This means 1 row was not filled completely.
The number of dolls in the 1 row that was not filled completely is 603 - (369 * 1) = 603 - 369 = 234.
### Answer: 234

Expected answer: 234

Correct? Yes

๐Ÿ”— Follow-up

Problem: In the previous doll problem, if the doll seller initially received a shipment of 44 new dolls instead of 603, and still arranged them in rows of 369 dolls, how many dolls would be left unarranged after filling up the rows as much as possible?

Llama 3 8B:

Reasoning: The number of rows that can be filled with 369 dolls is 44/369 = 0.12 (round down to 0, since you can't have a fraction of a row). This means no rows can be filled.
The number of dolls left unarranged is the same as the initial number of dolls, which is 44.
### Answer: 44

Expected answer: 44

Correct? Yes

๐Ÿ”— Problem

Problem: A jewelry maker has 850 beads to make necklaces. They use 631 beads for each necklace. After using as many beads as possible, how many beads will the jewelry maker have left over?

Llama 3 8B:

Reasoning: The jewelry maker uses 631 beads for each necklace. To find out how many necklaces they can make, we can divide the total number of beads (850) by the number of beads used per necklace (631).

850 รท 631 = 1.35 (round down to 1, since you can't make a fraction of a necklace)

So, the jewelry maker can make 1 necklace with 631 beads. To find out how many beads are left over, we subtract the number of beads used (631) from the total number of beads (850):

850 - 631 = 219

The jewelry maker will have 219 beads left over.

### Answer: 219

Expected answer: 219

Correct? Yes

๐Ÿ”— Follow-up

Problem: The jewelry maker decides to change the design and now each necklace uses only 150 beads instead of 631 beads. After they distribute the 850 beads as equally as possible among the new necklaces, how many beads will the jewelry maker have left over?

Llama 3 8B:

Reasoning: The jewelry maker uses 150 beads for each necklace. To find out how many necklaces they can make, we can divide the total number of beads (850) by the number of beads used per necklace (150).

850 รท 150 = 5.67 (round down to 5, since you can't make a fraction of a necklace)

So, the jewelry maker can make 5 necklaces with 150 beads each. To find out how many beads are left over, we subtract the number of beads used (5 x 150 = 750) from the total number of beads (850):

850 - 750 = 100

The jewelry maker will have 100 beads left over.

### Answer: 100

Expected answer: 100

Correct? Yes

๐Ÿ”— Problem

Problem: A gardener has 952 grapes that he wants to package into boxes. If each box can hold 380 grapes, how many grapes will be left after the gardener has filled as many boxes as possible?

Llama 3 8B:

Reasoning: The gardener can fill 952/380 = 2 with a remainder of 232.
The gardener can fill 2 boxes with 2 x 380 = 760 grapes.
There will be 952 - 760 = 232 grapes left after filling the boxes.
### Answer: 232

Expected answer: 192

Correct? No

๐Ÿ”— Problem

Problem: On a treasure map, there are 236 steps mentioned on the guide. If every 44 steps I make leads me to a significant place or clue, how many steps will be left after I reach the last significant place or clue?

Llama 3 8B:

Reasoning: To find the number of significant places or clues, we can divide the total number of steps (236) by the number of steps leading to each significant place or clue (44).
236 รท 44 = 5.36 (round down to 5, since you can't have a fraction of a place or clue)
This means there are 5 significant places or clues.
To find the number of steps left after reaching the last significant place or clue, we subtract the total number of steps leading to each significant place or clue (44 ร— 5 = 220) from the total number of steps (236).
236 - 220 = 16
### Answer: 16

Expected answer: 16

Correct? Yes

๐Ÿ”— Problem

Problem: Sarah blew 932 bubbles using her new bubble machine. The machine is designed to form groups of 507 bubbles each before releasing them. After forming complete groups, how many bubbles does it make in its final, incomplete group?

Llama 3 8B:

Reasoning: Since the machine forms groups of 507 bubbles each, we can divide the total number of bubbles (932) by 507 to find the number of complete groups: 932 รท 507 = 1 with a remainder of 437.
This means that the machine forms 1 complete group of 507 bubbles, and then has 437 bubbles left over in the final, incomplete group.
### Answer: 437

Expected answer: 425

Correct? No

๐Ÿ”— Problem

Problem: At the park, there are 931 kids who want to use the swings. Each swing set can accommodate 34 kids at a time. If all the swing sets are filled continuously, how many kids will be waiting for their turn after all the swing sets are occupied?

Llama 3 8B:

Reasoning: The number of kids who can use the swings at any given time is equal to the number of swing sets multiplied by the capacity of each swing set, which is 34. So, the number of kids who can use the swings is 34 x 27 = 918.
The number of kids waiting for their turn is the total number of kids minus the number of kids who can use the swings, which is 931 - 918 = 13.
### Answer: 13

Expected answer: 13

Correct? Yes

๐Ÿ”— Follow-up

Problem: In the previous scenario, let's say that some of the kids finished their swinging and left the park. Now, there are only 708 kids waiting to use the swings. Each swing set can still accommodate 34 kids at a time. Given this new number, how many children will be waiting for their turn after all the swing sets are occupied?

Llama 3 8B:

Reasoning: The number of kids who can use the swings at any given time is still equal to the number of swing sets multiplied by the capacity of each swing set, which is 34. So, the number of kids who can use the swings is 34 x 21 = 714.
The number of kids waiting for their turn is the total number of kids minus the number of kids who can use the swings, which is 708 - 714 = -6.
However, since you can't have a negative number of kids waiting, it means that there are actually 6 kids who are already using the swings. So, the number of kids waiting for their turn is 708 - 714 + 6 = 0.
### Answer: 0

Expected answer: 28

Correct? No

๐Ÿ”— Problem

Problem: John has 943 dollar bills in his possession. He tries to stuff them in wallets that can each contain 433 dollar bills. After fully loading as many wallets as he can, how many dollar bills does he have left?

Llama 3 8B:

Reasoning: John can fit 943/433 = 2 with a remainder of 2 in the wallets.
This means he can fit 2 x 433 = 866 dollar bills in the wallets.
He has 943 - 866 = 77 dollar bills left.
### Answer: 77

Expected answer: 77

Correct? Yes

๐Ÿ”— Follow-up

Problem: Suppose John originally had 586 dollar bills instead of 943. He still tries to stuff them in wallets that can each contain 433 dollar bills. After fully loading as many wallets as he can, how many dollar bills does he have left now?

Llama 3 8B:

Reasoning: John can fit 586/433 = 1 with a remainder of 149 in the wallets.
This means he can fit 1 x 433 = 433 dollar bills in the wallets.
He has 586 - 433 = 153 dollar bills left.
### Answer: 153

Expected answer: 153

Correct? Yes

๐Ÿ”— Problem

Problem: A helicopter pilot plans to transport 240 passengers over several trips. He can carry 177 passengers in one trip. How many passengers will be left behind after the helicopter makes the first full trip?

Llama 3 8B:

Reasoning: The helicopter can carry 177 passengers in one trip. If it makes one full trip, it will transport 177 passengers.
The number of passengers left behind will be the total number of passengers minus the number of passengers transported in the first trip.
240 - 177 = <<240-177=63>>63 passengers will be left behind after the helicopter makes the first full trip.
### Answer: 63

Expected answer: 63

Correct? Yes

๐Ÿ”— Problem

Problem: A gardener has 982 flowers to plant in flowerbeds. Each flowerbed can fit 555 flowers. After filling up as many flowerbeds as possible, how many flowers will the gardener have left to plant?

Llama 3 8B:

Reasoning: The gardener can fill up 982/555 = 1.76 flowerbeds (since you can't have a fraction of a flowerbed, we'll round down to 1 flowerbed).
The gardener can fill up 1 flowerbed, which means they'll use 555 flowers.
The gardener will have 982 - 555 = 427 flowers left to plant.
### Answer: 427

Expected answer: 427

Correct? Yes

๐Ÿ”— Follow-up

Problem: The gardener received an additional shipment, bringing the total number of flowers up to 867. If he continues to plant the flowers in flowerbeds of 555 each, how many flowers will he have left to plant after filling up as many flowerbeds as possible?

Llama 3 8B:

Reasoning: The gardener can fill up 867/555 = 1.56 flowerbeds (since you can't have a fraction of a flowerbed, we'll round down to 1 flowerbed).
The gardener can fill up 1 flowerbed, which means they'll use 555 flowers.
The gardener will have 867 - 555 = 312 flowers left to plant.
### Answer: 312

Expected answer: 312

Correct? Yes

๐Ÿ”— Problem

Problem: A farmer grows 203 strawberry plants. She wants to divide her plants into groups of 5 to sell. How many plants will be remaining if she divides them equally?

Llama 3 8B:

Reasoning: To find the number of groups of 5, we can divide the total number of plants (203) by 5.
203 รท 5 = 40 with a remainder of 3.
This means that the farmer can make 40 groups of 5 plants each, and there will be 3 plants left over.
### Answer: 3

Expected answer: 3

Correct? Yes

๐Ÿ”— Follow-up

Problem: The farmer harvested another field and got an additional 76 strawberry plants. Again, she wants to divide the new plants into groups of 5 to sell. How many plants will be remaining if she divides these new strawberries equally?

Llama 3 8B:

Reasoning: The farmer already has 203 strawberry plants. She adds 76 more, making a total of 203 + 76 = 279 plants.
To find the number of groups of 5, we can divide the total number of plants (279) by 5.
279 รท 5 = 55 with a remainder of 4.
This means that the farmer can make 55 groups of 5 plants each, and there will be 4 plants left over.
### Answer: 4

Expected answer: 1

Correct? No

๐Ÿ”— Problem

Problem: A gardener has 355 carrots. He wants to create bundles of 16. After creating as many bundles as he can, how many carrots will he have left?

Llama 3 8B:

Reasoning: The gardener can create bundles of 16 carrots, so he can create 355/16 = 22.1875 bundles (since you can't create a fraction of a bundle, we'll round down to 22 bundles).
22 bundles x 16 carrots/bundle = 352 carrots
The gardener will have 355 - 352 = 3 carrots left.
### Answer: 3

Expected answer: 3

Correct? Yes

๐Ÿ”— Problem

Problem: A total rainfall of 612 inches fell over a certain city in 29 consecutive days. If the rain fell in the same amount every day, how many inches of rain would be left to make the days evenly rainy?

Llama 3 8B:

Reasoning: If the rain fell in the same amount every day, then the amount of rain per day is 612/29 = 21 inches.
To make the days evenly rainy, we need to find the remainder when 612 is divided by 29. This can be done by subtracting 29 times the quotient from 612, which is 612 - 29*21 = 612 - 609 = 3 inches.
### Answer: 3

Expected answer: 3

Correct? Yes

๐Ÿ”— Follow-up

Problem: Suppose instead of 612 inches, a total rainfall of 505 inches fell over the city in those same 29 consecutive days. If the rain fell in the same amount every day, how many inches of rain would be left to make the days evenly rainy?

Llama 3 8B:

Reasoning: If the rain fell in the same amount every day, then the amount of rain per day is 505/29 = 17.41 inches (approximately).
To make the days evenly rainy, we need to find the remainder when 505 is divided by 29. This can be done by subtracting 29 times the quotient from 505, which is 505 - 29*17 = 505 - 493 = 12 inches.
### Answer: 12

Expected answer: 12

Correct? Yes

๐Ÿ”— Problem

Problem: A truck company has got 514 boxes for delivery. Each truck can hold up to 371 boxes. If each truck is loaded to its full capacity, how many boxes will be left over?

Llama 3 8B:

Reasoning: The number of boxes that can be loaded onto the trucks is equal to the number of trucks multiplied by the capacity of each truck. Since each truck can hold up to 371 boxes, the total number of boxes that can be loaded is 371 * (number of trucks).

Let's calculate the number of trucks needed to load all the boxes:

Number of trucks = Total number of boxes / Capacity of each truck
= 514 / 371
= 1.39 (round down to 1, since you can't have a fraction of a truck)

So, 1 truck can be loaded with 371 boxes, leaving:

514 - 371 = 143

boxes left over.

### Answer: 143

Expected answer: 143

Correct? Yes

๐Ÿ”— Problem

Problem: In a large sandbox, children create 684 sandcastles over the summer. The sandcastles were grouped into sets of 230 for a photography contest. After all the sets were completed, how many sandcastles were left that didn't form a complete set?

Llama 3 8B:

Reasoning: The number of sandcastles that formed complete sets is equal to the number of sets multiplied by the number of sandcastles in each set. Since there are 684 sandcastles and each set has 230 sandcastles, the number of complete sets is 684/230 = 3 (with a remainder of 0).

This means that 3 complete sets were formed, leaving 684 - (3 x 230) = 684 - 690 = 6 sandcastles that didn't form a complete set.

### Answer: 6

Expected answer: 224

Correct? No

๐Ÿ”— Problem

Problem: A toy manufacturer has a production run of 735 toy cars. They package the cars in packs of 348 for bulk shipments. If all the toy cars are divided equally among packs, how many toy cars will be left over after all full packs have been filled?

Llama 3 8B:

Reasoning: To find the number of full packs, we divide the total number of toy cars (735) by the number of toy cars per pack (348).
735 รท 348 = 2 with a remainder of 35
This means that 2 packs will be filled with 348 toy cars each, and there will be 35 toy cars left over.
### Answer: 35

Expected answer: 39

Correct? No

๐Ÿ”— Problem

Problem: In a forest, there are 386 animals. Each woodlands territory can support 95 animals. If the existing animals are evenly distributed among the territories, how many animals will be left in the last not fully occupied territory?

Llama 3 8B:

Reasoning: To find the number of territories, we divide the total number of animals by the number of animals each territory can support: 386/95 = 4.04 (round down to 4, since you can't have a fraction of a territory).
This means there will be 4 fully occupied territories, and 2 animals left over (since 4 x 95 = 380, and 386 - 380 = 6, but we round down to 2 since we can't have a fraction of an animal).
The last not fully occupied territory will have 95 - 2 = 93 animals.
### Answer: 93

Expected answer: 6

Correct? No

๐Ÿ”— Problem

Problem: A forest has 801 trees. A tree disease starts to spread and is expected to affect 646 trees. If all the diseased trees have to be cut down evenly, how many trees are likely to stay healthy after the disease has affected all possible trees?

Llama 3 8B:

Reasoning: The disease is expected to affect 646 trees. To find the number of trees that will stay healthy, we subtract the number of diseased trees from the total number of trees.

801 (total trees) - 646 (diseased trees) = 155

So, 155 trees are likely to stay healthy after the disease has affected all possible trees.

### Answer: 155

Expected answer: 155

Correct? Yes

๐Ÿ”— Problem

Problem: A rope manufacturer has made a rope of 934 meters in length. This rope is supposed to be cut into smaller pieces, each piece being 902 meters in length. After cutting into the maximum possible number of equal pieces, how many meters will the last piece of the rope be?

Llama 3 8B:

Reasoning: The rope is 934 meters long and each piece is 902 meters long. To find the maximum number of pieces, we can divide the length of the rope by the length of each piece:

934 รท 902 = 1.03 (with a remainder of 30)

This means that we can cut the rope into 934 รท 902 = 1.03 (approximately 1) pieces, with a remainder of 30 meters.

The last piece will be the remainder, which is 30 meters.

### Answer: 30

Expected answer: 32

Correct? No

๐Ÿ”— Problem

Problem: A dairy farm produces 561 liters of milk each day. The milk is packaged into 550-liter containers. How many liters of milk are left over each day after filling the containers?

Llama 3 8B:

Reasoning: The dairy farm produces 561 liters of milk each day. The containers can hold 550 liters of milk. To find the leftover milk, subtract the capacity of the containers from the total milk produced: 561 - 550 = 11.
### Answer: 11

Expected answer: 11

Correct? Yes

๐Ÿ”— Follow-up

Problem: If the dairy farm increased its production and started producing 729 liters of milk each day instead of 561 liters, how many liters of milk would be left over each day after filling the 550-liter containers?

Llama 3 8B:

Reasoning: The dairy farm now produces 729 liters of milk each day. The containers can hold 550 liters of milk. To find the leftover milk, subtract the capacity of the containers from the total milk produced: 729 - 550 = 179.
### Answer: 179

Expected answer: 179

Correct? Yes

๐Ÿ”— Problem

Problem: Jon has 259 puzzle pieces. If each puzzle requires 258 pieces, how many pieces will be left over once he completes a full puzzle?

Llama 3 8B:

Reasoning: Jon has 259 puzzle pieces and each puzzle requires 258 pieces. To find the number of puzzle pieces left over, we can subtract the number of pieces required for a full puzzle from the total number of pieces Jon has.

259 - 258 = 1

So, Jon will have 1 piece left over once he completes a full puzzle.

### Answer: 1

Expected answer: 1

Correct? Yes

๐Ÿ”— Follow-up

Problem: In the previous problem, Jon had 259 puzzle pieces and each puzzle requires 258 pieces. Suppose instead each puzzle needs 542 pieces. How many pieces would Jon have left over after finishing as many full puzzles as possible with his 259 pieces?

Llama 3 8B:

Reasoning: Jon has 259 puzzle pieces and each puzzle requires 542 pieces. To find the number of puzzle pieces left over, we can divide the total number of pieces Jon has by the number of pieces required for a full puzzle and find the remainder.

259 รท 542 = 0 with a remainder of 259

Since Jon can't make a full puzzle with 259 pieces, he will have 259 pieces left over.

### Answer: 259

Expected answer: 259

Correct? Yes

๐Ÿ”— Problem

Problem: A jewelry maker has 673 beads. She plans to use exactly 49 beads for each bracelet. How many beads will she have left after creating as many bracelets as possible with the exact number of beads?

Llama 3 8B:

Reasoning: The jewelry maker can create 673/49 = 13 with a remainder of 28 bracelets.
She will use 49*13 = 637 beads for the bracelets.
She will have 673 - 637 = 36 beads left after creating the bracelets.
### Answer: 36

Expected answer: 36

Correct? Yes

๐Ÿ”— Follow-up

Problem: The jewelry maker received an additional shipment, and now she has a total of 673 beads. This time, she wants to make larger bracelets which use exactly 545 beads each. After creating as many large bracelets as possible, how many beads will she have left over?

Llama 3 8B:

Reasoning: The jewelry maker can create 673/545 = 1 with a remainder of 128 large bracelets.
She will use 545*1 = 545 beads for the large bracelets.
She will have 673 - 545 = 128 beads left after creating the large bracelets.
### Answer: 128

Expected answer: 128

Correct? Yes

๐Ÿ”— Problem

Problem: A police station received 927 calls within a week. They have 311 operators who can handle the same number of calls each week. However, when the calls are divided equally, how many calls will the last operator handle?

Llama 3 8B:

Reasoning: To find the number of calls each operator will handle, we need to divide the total number of calls (927) by the number of operators (311).
927 รท 311 = 3 with a remainder of 0
This means that each operator will handle 3 calls, except for the last one.
To find the number of calls the last operator will handle, we need to subtract the number of calls each operator will handle (3) from the remainder (0), since the last operator will not handle a full 3 calls.
0 - 3 = -3
Since we can't have a negative number of calls, we can add the total number of calls (927) to the remainder to get the correct answer.
0 + 927 = 927
So, the last operator will handle 927 - (3 x 310) = 927 - 930 = -3 calls.
### Answer: 0

Expected answer: 305

Correct? No

๐Ÿ”— Problem

Problem: John has 764 pieces for his jigsaw puzzle, and every package should contain 589 pieces. If he separates these pieces into full packages, how many pieces will be left outside without a package?

Llama 3 8B:

Reasoning: To find the number of full packages, we divide the total number of pieces by the number of pieces per package: 764 รท 589 = 1 R 175.
This means John can make 1 full package with 589 pieces, and there will be 175 pieces left over.
### Answer: 175

Expected answer: 175

Correct? Yes

๐Ÿ”— Follow-up

Problem: If John had originally only 404 puzzle pieces, and each package can still only contain 589, how many pieces will be left outside the package now?

Llama 3 8B:

Reasoning: To find the number of full packages, we divide the total number of pieces by the number of pieces per package: 404 รท 589 = 0 R 115.
This means John can make 0 full packages with 589 pieces, and there will be 115 pieces left over.
### Answer: 115

Expected answer: 404

Correct? No

๐Ÿ”— Problem

Problem: A dressmaker has 984 meters of fabric. She uses 217 meters of fabric to make each dress. After using all the fabric she can to make as many dresses as possible, how many meters of fabric will she have left?

Llama 3 8B:

Reasoning: The dressmaker can make 984/217 = 4 with a remainder of 12 (since 217 x 4 = 868 and 984 - 868 = 12).
She will use 217 x 4 = 868 meters of fabric to make 4 dresses.
She will have 12 meters of fabric left.
### Answer: 12

Expected answer: 116

Correct? No

๐Ÿ”— Problem

Problem: A company donates 639 sleeping bags for a camping event. Each campsite is supplied with 374 sleeping bags. If all the sleeping bags are divided equally among the campsites, how many sleeping bags will there be left?

Llama 3 8B:

Reasoning: The total number of sleeping bags is 639. Each campsite is supplied with 374 sleeping bags. To find the number of campsites, we can divide the total number of sleeping bags by the number of sleeping bags per campsite: 639 รท 374 = 1.71 (round down to 1, since you can't have a fraction of a campsite). This means there will be 1 campsite with 374 sleeping bags and 265 sleeping bags left over (639 - 374 = 265).
### Answer: 265

Expected answer: 265

Correct? Yes

๐Ÿ”— Follow-up

Problem: The same company from our previous question receives an updated request for sleeping bags. Now instead of 639, they only need to donate 613. If each campsite is still supplied with 374 sleeping bags, how many sleeping bags will be left after all the campsites are filled?

Llama 3 8B:

Reasoning: The total number of sleeping bags is 613. Each campsite is supplied with 374 sleeping bags. To find the number of campsites, we can divide the total number of sleeping bags by the number of sleeping bags per campsite: 613 รท 374 = 1.63 (round down to 1, since you can't have a fraction of a campsite). This means there will be 1 campsite with 374 sleeping bags and 239 sleeping bags left over (613 - 374 = 239).
### Answer: 239

Expected answer: 239

Correct? Yes

๐Ÿ”— Problem

Problem: A pizza restaurant made 620 pizzas today. They package up the pizzas in boxes that hold 578 each for delivery. If the pizzas are evenly distributed into these boxes, how many pizzas will be left over that don't fit into a box?

Llama 3 8B:

Reasoning: To find the number of pizzas that fit into the boxes, we can divide the total number of pizzas (620) by the number of pizzas each box can hold (578).

620 รท 578 = 1.07 (approximately)

Since we can't put a fraction of a pizza in a box, we'll round down to the nearest whole number, which means we can fit 578 pizzas into the boxes.

To find the number of pizzas left over, we'll subtract the number of pizzas that fit into the boxes from the total number of pizzas:

620 - 578 = 42

### Answer: 42

Expected answer: 42

Correct? Yes

๐Ÿ”— Follow-up

Problem: The owner of the pizza restaurant decides to make 74 more pizzas tomorrow, bringing the total to 694 pizzas. If they are again distributed into boxes that hold 578 pizzas each, how many pizzas will be left out without a box this time?

Llama 3 8B:

Reasoning: First, let's calculate the number of boxes needed to hold the total number of pizzas (694):

694 รท 578 = 1.20 (approximately)

Since we can't put a fraction of a pizza in a box, we'll round down to the nearest whole number, which means we can fit 578 pizzas into 1 box and 116 pizzas into the next box.

The remaining pizzas will be:

694 - (578 + 578) = 694 - 1156 = 538

Since we already used 578 pizzas in the first box, we'll subtract 578 from the remaining pizzas:

538 - 578 = -40

This means we have 40 pizzas more than the number of pizzas that can fit into the boxes. Since we can't put a negative number of pizzas in a box, we'll ignore the negative result and focus on the remaining pizzas.

### Answer: 40

Expected answer: 116

Correct? No

๐Ÿ”— Problem

Problem: A factory made a total of 820 robots. It can store 684 robots in one storage unit. If the robots are evenly stored, how many robots will not fit and remain outside of the storage units?

Llama 3 8B:

Reasoning: The factory made a total of 820 robots. It can store 684 robots in one storage unit. To find out how many robots will not fit, we need to subtract the number of robots that can fit from the total number of robots.

820 - 684 = 136

So, 136 robots will not fit and remain outside of the storage units.

### Answer: 136

Expected answer: 136

Correct? Yes

๐Ÿ”— Follow-up

Problem: In the same factory, another production run is completed, this time manufacturing a total of 820 upgraded robots. However, the storage units for these new models can only hold 625 robots each. If the robots are evenly stored, how many upgraded robots will not fit and remain outside the storage units now?

Llama 3 8B:

Reasoning: The factory produced a total of 820 upgraded robots. Each storage unit can hold 625 robots. To find out how many robots will not fit, we need to subtract the number of robots that can fit from the total number of robots.

820 - 625 = 195

So, 195 upgraded robots will not fit and remain outside the storage units.

### Answer: 195

Expected answer: 195

Correct? Yes

๐Ÿ”— Problem

Problem: A cloud changes its shape by reducing its water droplets. Initially, there were 516 droplets in the cloud. If the cloud loses water droplets at an equal rate and becomes entirely dry after every 289 droplets, how many droplets will be left when the cloud is dry after the final cycle?

Llama 3 8B:

Reasoning: The cloud loses water droplets at an equal rate, which means it loses 289 droplets in each cycle. Since the cloud becomes entirely dry after every 289 droplets, it will go through 516/289 = 1 with a remainder of 227 cycles.
In the final cycle, the cloud will lose 289 droplets, leaving 227 droplets.
### Answer: 227

Expected answer: 227

Correct? Yes

๐Ÿ”— Follow-up

Problem: If initially, there were only 175 droplets in the cloud instead of 516. If the cloud loses water droplets at an equal rate and becomes entirely dry after every 289 droplets, how many droplets will be left when the cloud is dry after the final cycle?

Llama 3 8B:

Reasoning: The cloud loses water droplets at an equal rate, which means it loses 289 droplets in each cycle. Since the cloud becomes entirely dry after every 289 droplets, it will go through 175/289 = 0 with a remainder of 175 cycles.
In the final cycle, the cloud will lose 175 droplets, leaving 0 droplets.
### Answer: 0

Expected answer: 175

Correct? No

๐Ÿ”— Problem

Problem: A transport company needs to load 330 boxes into trucks. Each truck can hold exactly 4 boxes. After filling each truck to its full capacity, how many boxes will be left unloaded?

Llama 3 8B:

Reasoning: Since each truck can hold exactly 4 boxes, we can divide the total number of boxes (330) by 4 to find the number of trucks needed:

330 รท 4 = 82.5

Since you can't have a fraction of a truck, we'll round down to 82 trucks. This means we'll use 82 trucks, and each truck will be filled with 4 boxes.

To find the number of boxes left unloaded, we'll subtract the total number of boxes loaded (82 trucks x 4 boxes/truck = 328 boxes) from the original total:

330 - 328 = 2

So, there will be 2 boxes left unloaded.

### Answer: 2

Expected answer: 2

Correct? Yes

๐Ÿ”— Follow-up

Problem: The transport company now needs to load a new batch of 274 boxes into trucks. Again, each truck can hold exactly 4 boxes. After filling each truck to its full capacity, how many boxes will be left unloaded this time?

Llama 3 8B:

Reasoning: Since each truck can hold exactly 4 boxes, we can divide the total number of boxes (274) by 4 to find the number of trucks needed:

274 รท 4 = 68.5

Since you can't have a fraction of a truck, we'll round down to 68 trucks. This means we'll use 68 trucks, and each truck will be filled with 4 boxes.

To find the number of boxes left unloaded, we'll subtract the total number of boxes loaded (68 trucks x 4 boxes/truck = 272 boxes) from the original total:

274 - 272 = 2

So, there will be 2 boxes left unloaded.

### Answer: 2

Expected answer: 2

Correct? Yes

๐Ÿ”— Problem

Problem: A farmer harvested 649 potatoes this season. He decides to pack them into crates each containing 183 potatoes. How many potatoes will be left after all crates are filled to their maximum capacity?

Llama 3 8B:

Reasoning: The farmer has 649 potatoes and each crate can hold 183 potatoes. To find out how many crates he can fill, we divide the total number of potatoes by the number of potatoes per crate:

649 รท 183 = 3.56

Since you can't fill a fraction of a crate, the farmer can fill 3 crates. This means he will use 3 x 183 = 549 potatoes.

To find out how many potatoes will be left, we subtract the number of potatoes used from the total number of potatoes:

649 - 549 = 100

### Answer: 100

Expected answer: 100

Correct? Yes

๐Ÿ”— Follow-up

Problem: The farmer realized that he actually only harvested 238 potatoes this season instead of 649. If he still packs them into crates each holding 183 potatoes, how many potatoes will be left after all crates are filled to their maximum capacity?

Llama 3 8B:

Reasoning: The farmer has 238 potatoes and each crate can hold 183 potatoes. To find out how many crates he can fill, we divide the total number of potatoes by the number of potatoes per crate:

238 รท 183 = 1.3

Since you can't fill a fraction of a crate, the farmer can fill 1 crate. This means he will use 183 potatoes.

To find out how many potatoes will be left, we subtract the number of potatoes used from the total number of potatoes:

238 - 183 = 55

### Answer: 55

Expected answer: 55

Correct? Yes

๐Ÿ”— Problem

Problem: A t-shirt company has a batch of 258 shirts in production. Each box can pack 67 shirts. If all the shirts are evenly distributed in the boxes, how many shirts would be left outside the boxes?

Llama 3 8B:

Reasoning: To find the number of boxes needed, we can divide the total number of shirts (258) by the number of shirts that can fit in each box (67).

258 รท 67 = 3 with a remainder of 57

This means that 3 boxes can be filled with 3 x 67 = 201 shirts, leaving 57 shirts remaining.

### Answer: 57

Expected answer: 57

Correct? Yes

๐Ÿ”— Follow-up

Problem: Suppose the t-shirt company actually had a batch of 258 shirts, but this time each box can pack 828 shirts. If all the shirts are evenly distributed in the boxes, how many shirts would be left outside the boxes?

Llama 3 8B:

Reasoning: To find the number of boxes needed, we can divide the total number of shirts (258) by the number of shirts that can fit in each box (828).

258 รท 828 = 0 with a remainder of 258

This means that the number of shirts (258) is less than the capacity of each box (828), so the shirts can be evenly distributed in a single box. There would be no shirts left outside the box.

### Answer: 0

Expected answer: 258

Correct? No

๐Ÿ”— Problem

Problem: On a pirate ship, there are 995 gold coins that need to be evenly divided among the 267 pirates. If they split the gold up as evenly as possible, how many gold coins will be left over?

Llama 3 8B:

Reasoning: To find the number of gold coins each pirate will get, we need to divide the total number of gold coins (995) by the number of pirates (267).
995 รท 267 = 3 with a remainder of 32
This means that each pirate will get 3 gold coins, and there will be 32 gold coins left over.
### Answer: 32

Expected answer: 194

Correct? No

๐Ÿ”— Problem

Problem: There are 776 snails all lined up in a row. If you group them in bunches of 375 snails, how many snails will be left in the final group?

Llama 3 8B:

Reasoning: To find the number of groups, we can divide the total number of snails (776) by the number of snails in each group (375).

776 รท 375 = 2 (with a remainder)

This means that we can make 2 groups of 375 snails each, and there will be a remainder of snails left over.

To find the number of snails left over, we can multiply the number of groups (2) by the number of snails in each group (375), and then subtract the total number of snails from the result.

2 x 375 = 750
750 - 776 = -26

However, since we can't have a negative number of snails, this means that there will be 26 snails left over in the final group.

### Answer: 26

Expected answer: 26

Correct? Yes

๐Ÿ”— Follow-up

Problem: Originally, you had grouped the snails in bunches of 375 snails each. Now, think about what would happen if each bunch had 18 snails instead. How many snails would be left in the final group then?

Llama 3 8B:

Reasoning: Let's recalculate the number of groups and the remainder:

776 รท 18 = 43 (with a remainder)

This means that we can make 43 groups of 18 snails each, and there will be a remainder of snails left over.

To find the number of snails left over, we can multiply the number of groups (43) by the number of snails in each group (18), and then subtract the total number of snails from the result.

43 x 18 = 774
774 - 776 = 2

So, if each bunch had 18 snails instead, there would be 2 snails left in the final group.

### Answer: 2

Expected answer: 2

Correct? Yes

๐Ÿ”— Problem

Problem: A pillow factory produces 589 pillows per day. They package these pillows in boxes, and each box holds 198 pillows. If they pack as many full boxes as possible, how many pillows will be left outside the boxes at the end of the day?

Llama 3 8B:

Reasoning: The factory produces 589 pillows per day. Each box holds 198 pillows, so the number of full boxes that can be packed is 589/198 = 3 (since 3 x 198 = 594, which is less than 589).
The number of pillows left outside the boxes is the remaining pillows after packing 3 full boxes, which is 589 - 594 = -5 (since 594 is more than 589, there are actually 5 pillows left over, not 5 less).
Since you can't have a negative number of pillows, the factory will have 589 - 594 = 5 pillows left outside the boxes at the end of the day.
### Answer: 5

Expected answer: 193

Correct? No

๐Ÿ”— Problem

Problem: A jewelry maker has 633 beads. If she uses beads to make necklaces, with each necklace using exactly 30 beads, how many beads will she have left after making as many necklaces as she can?

Llama 3 8B:

Reasoning: To find out how many necklaces the jewelry maker can make, we need to divide the total number of beads (633) by the number of beads used per necklace (30).
633 รท 30 = 21 (with a remainder of 3)
This means she can make 21 complete necklaces, using up 21 x 30 = 630 beads.
The remaining beads will be the total number of beads minus the number of beads used to make the necklaces: 633 - 630 = 3
### Answer: 3

Expected answer: 3

Correct? Yes

๐Ÿ”— Follow-up

Problem: The jewelry maker found an additional box of beads in her storage, increasing her total number of beads to 588. Now, if she uses these beads to make necklaces, with each necklace using exactly 30 beads, how many beads will she have left after making as many necklaces as she can?

Llama 3 8B:

Reasoning: To find out how many necklaces the jewelry maker can make, we need to divide the total number of beads (588) by the number of beads used per necklace (30).
588 รท 30 = 19 (with a remainder of 18)
This means she can make 19 complete necklaces, using up 19 x 30 = 570 beads.
The remaining beads will be the total number of beads minus the number of beads used to make the necklaces: 588 - 570 = 18
### Answer: 18

Expected answer: 18

Correct? Yes

๐Ÿ”— Problem

Problem: John has collected 365 coins. He decided to put equal numbers of them in his 140 wallets. However, he found out he would still have some coins left after evenly distributing them into these wallets. How many coins will John have left?

Llama 3 8B:

Reasoning: John has 365 coins and 140 wallets. To find out how many coins he can put in each wallet, we can divide 365 by 140.
365 รท 140 = 2 with a remainder of 85
This means John can put 2 coins in each wallet, and he will have 85 coins left over.
### Answer: 85

Expected answer: 85

Correct? Yes

๐Ÿ”— Follow-up

Problem: Now, suppose John comes across additional coins and his collection increases to 739 coins. He again tries to evenly distribute these coins among his 140 wallets. How many coins will John have left after this distribution?

Llama 3 8B:

Reasoning: John has 739 coins and 140 wallets. To find out how many coins he can put in each wallet, we can divide 739 by 140.
739 รท 140 = 5 with a remainder of 39
This means John can put 5 coins in each wallet, and he will have 39 coins left over.
### Answer: 39

Expected answer: 39

Correct? Yes

๐Ÿ”— Problem

Problem: A sock manufacturer produces 743 socks in a single production run. The socks are packed into cartons, each containing 451 socks. After filling up as many cartons as possible, how many socks are left unpacked?

Llama 3 8B:

Reasoning: The number of cartons that can be filled is the integer division of the total number of socks (743) by the number of socks per carton (451).
743 รท 451 = 1 with a remainder of 743 mod 451 = 32
This means that 1 carton can be filled with 451 socks, leaving 32 socks unpacked.
### Answer: 32

Expected answer: 292

Correct? No

๐Ÿ”— Problem

Problem: A total of 923 children want to slide down a slide at an amusement park. If 771 children can go down the slide without rest, how many children will be left waiting for their turn?

Llama 3 8B:

Reasoning: If 771 children can go down the slide without rest, that means they will all go down the slide. The number of children left waiting for their turn will be the total number of children minus the number of children who can go down the slide.
923 - 771 = <<923-771=152>>152 children will be left waiting for their turn.
### Answer: 152

Expected answer: 152

Correct? Yes

๐Ÿ”— Follow-up

Problem: After the first 771 children go down the slide, another wave of children arrives and now there are 923 children in total waiting again. If 881 children can go down the slide without any break this time, how many children will be left waiting for their turn?

Llama 3 8B:

Reasoning: First, we need to find out how many children went down the slide in the second wave. Since 771 children went down the slide initially, and now there are 923 children waiting, the number of children who arrived in the second wave is:
923 - 771 = <<923-771=152>>152 children arrived in the second wave.

Now, 881 children can go down the slide without any break this time. Since 771 children went down the slide initially, the number of children who went down the slide in the second wave is:
881 - 771 = <<881-771=110>>110 children went down the slide in the second wave.

The total number of children who went down the slide is the sum of the initial 771 children and the 110 children who went down the slide in the second wave:
771 + 110 = <<771+110=881>>881 children went down the slide.

The number of children left waiting for their turn is the total number of children minus the number of children who went down the slide:
923 - 881 = <<923-881=42>>42 children will be left waiting for their turn.
### Answer: 42

Expected answer: 42

Correct? Yes

๐Ÿ”— Problem

Problem: Superhero Iron Punch has to save 442 people from a collapsing building. He can teleport a maximum of 104 people at a time to safety. After teleporting as many full groups as he can, how many people will be left in the building for his last round of rescue?

Llama 3 8B:

Reasoning: Iron Punch can teleport 104 people at a time. To find out how many full groups he can teleport, we divide the total number of people (442) by the number of people he can teleport (104).

442 รท 104 = 4 (with a remainder of 42)

This means Iron Punch can teleport 4 full groups of 104 people each, which is a total of 4 x 104 = 416 people.

To find out how many people will be left in the building for his last round of rescue, we subtract the number of people he teleported (416) from the total number of people (442).

442 - 416 = 26

### Answer: 26

Expected answer: 26

Correct? Yes

๐Ÿ”— Follow-up

Problem: What if there were actually 512 people in the collapsing building instead of 442? After Superhero Iron Punch teleports as many full groups of 104 people as he can to safety, how many people will be left in the building for his last round of rescue now?

Llama 3 8B:

Reasoning: Iron Punch can teleport 104 people at a time. To find out how many full groups he can teleport, we divide the total number of people (512) by the number of people he can teleport (104).

512 รท 104 = 4 (with a remainder of 88)

This means Iron Punch can teleport 4 full groups of 104 people each, which is a total of 4 x 104 = 416 people.

To find out how many people will be left in the building for his last round of rescue, we subtract the number of people he teleported (416) from the total number of people (512).

512 - 416 = 96

### Answer: 96

Expected answer: 96

Correct? Yes

๐Ÿ”— Problem

Problem: A card game manufacturer creates a deck of cards with 569 cards. Each card pack has 68 cards. After creating as many packs as possible, how many cards will the manufacturer have left over?

Llama 3 8B:

Reasoning: The manufacturer can create 569/68 = 8 with a remainder of 13 packs.
The manufacturer will have 13 cards left over.
### Answer: 13

Expected answer: 25

Correct? No

๐Ÿ”— Problem

Problem: A stationery store received a shipment of 842 erasers. The store owner wants to display them in boxes, with each box containing 719 erasers. After filling as many boxes as possible, how many erasers will be left over?

Llama 3 8B:

Reasoning: The store owner can fill 842/719 = 1.17 boxes, which means they can fill 1 box with 719 erasers and have 842 - 719 = 123 erasers left over.
### Answer: 123

Expected answer: 123

Correct? Yes

๐Ÿ”— Follow-up

Problem: Suppose the stationery store owner later decided to display the erasers in smaller boxes, with each box containing 420 erasers instead. After filling as many boxes as possible, how many erasers will be left over now?

Llama 3 8B:

Reasoning: The store owner can fill 842/420 = 2 boxes, which means they can fill 2 boxes with 420 erasers each, and have 842 - 2*420 = 2 erasers left over.
### Answer: 2

Expected answer: 2

Correct? Yes

๐Ÿ”— Problem

Problem: A farmer harvested 461 carrots from his garden. He packs them into boxes, each box can hold up to 244 carrots. After packing as many full boxes as possible, how many carrots will be left unpacked?

Llama 3 8B:

Reasoning: The farmer can pack 461/244 = 1 remainder 217 carrots into boxes.
The remainder 217 carrots will be left unpacked.
### Answer: 217

Expected answer: 217

Correct? Yes

๐Ÿ”— Follow-up

Problem: The farmer found out that he had initially miscounted and he actually only harvested 11 carrots. After he tries to pack these into the boxes which each can hold up to 244 carrots, how many carrots will be left unpacked now?

Llama 3 8B:

Reasoning: The farmer can pack 11/244 = 0 remainder 11 carrots into boxes.
The remainder 11 carrots will be left unpacked.
### Answer: 11

Expected answer: 11

Correct? Yes

๐Ÿ”— Problem

Problem: A penguin scientist counts 309 penguins in a colony. She decides to tag them in groups of 293 for easier tracking. How many penguins will be in the final, possibly incomplete, group?

Llama 3 8B:

Reasoning: The penguin scientist can tag 309 penguins in groups of 293. To find the number of groups, we can divide 309 by 293.
309 รท 293 = 1 with a remainder of 16
This means that 1 group of 293 penguins can be tagged, and there will be 16 penguins left over.
### Answer: 16

Expected answer: 16

Correct? Yes

๐Ÿ”— Follow-up

Problem: The penguin scientist realizes she made a mistake and there were actually only 262 penguins in each group. How many penguins will be in the final, possibly incomplete, group now?

Llama 3 8B:

Reasoning: The penguin scientist can tag 309 penguins in groups of 262. To find the number of groups, we can divide 309 by 262.
309 รท 262 = 1 with a remainder of 47
This means that 1 group of 262 penguins can be tagged, and there will be 47 penguins left over.
### Answer: 47

Expected answer: 47

Correct? Yes

๐Ÿ”— Problem

Problem: A sandwich shop has 580 slices of bread. They use 18 slices of bread for each sandwich-making batch. After using up the bread in these batches, how many slices will they have left?

Llama 3 8B:

Reasoning: The sandwich shop has 580 slices of bread initially.
They use 18 slices of bread for each sandwich-making batch.
To find the number of batches, we divide the total slices by the slices used per batch: 580 รท 18 = 32.22 (round down to 32, since you can't make a fraction of a batch).
So, they make 32 batches, using up 32 ร— 18 = 576 slices of bread.
The remaining slices of bread are: 580 - 576 = 4.
### Answer: 4

Expected answer: 4

Correct? Yes

๐Ÿ”— Follow-up

Problem: The sandwich shop's supplier delivered an additional batch of bread, bringing their total to 580 slices. If the shop still makes sandwiches using 477 slices of bread per batch, how many slices will they have left after the latest batch of sandwiches is made?

Llama 3 8B:

Reasoning: The sandwich shop has 580 slices of bread initially.
They use 477 slices of bread for each sandwich-making batch.
To find the number of batches, we divide the total slices by the slices used per batch: 580 รท 477 = 1.21 (round down to 1, since you can't make a fraction of a batch).
So, they make 1 batch, using up 477 slices of bread.
The remaining slices of bread are: 580 - 477 = 103.
### Answer: 103

Expected answer: 103

Correct? Yes

๐Ÿ”— Problem

Problem: A tailor has 925 meters of fabric. The tailor uses 529 meters of fabric to make each dress. If the tailor uses the fabric evenly for each dress, how many meters of fabric will be left over after completing the dresses?

Llama 3 8B:

Reasoning: The tailor has 925 meters of fabric initially.
The tailor uses 529 meters of fabric for each dress.
To find the number of dresses the tailor can make, we divide the total fabric by the amount used per dress: 925 รท 529 = 1.75 (round down to 1, since you can't make a fraction of a dress).
The tailor can make 1 dress with 529 meters of fabric, leaving 925 - 529 = 396 meters of fabric unused.
### Answer: 396

Expected answer: 396

Correct? Yes

๐Ÿ”— Follow-up

Problem: After making some dresses, the tailor now only has 62 meters of fabric left. If the tailor continues to use 529 meters of fabric to make each dress, how many meters of fabric will be left over after making the dresses?

Llama 3 8B:

Reasoning: The tailor has 62 meters of fabric initially.
The tailor uses 529 meters of fabric for each dress.
To find the number of dresses the tailor can make, we divide the total fabric by the amount used per dress: 62 รท 529 = 0.117 (round down to 0, since you can't make a fraction of a dress).
The tailor can make 0 dresses with 62 meters of fabric, leaving 62 meters of fabric unused.
### Answer: 62

Expected answer: 62

Correct? Yes

๐Ÿ”— Problem

Problem: There are 976 tourists wanting to explore a castle. Each tour group throughout the day accommodates up to 530 people. After all the groups have taken off, how many tourists will be left for the last group of the day?

Llama 3 8B:

Reasoning: The maximum capacity of each tour group is 530 people. Since there are 976 tourists, we can divide 976 by 530 to find the number of groups that can be accommodated:

976 รท 530 = 1.84 (round down to 1, since you can't have a fraction of a group)

This means that 1 group of 530 people can be accommodated, leaving:

976 - 530 = 446

tourists for the last group of the day.
### Answer: 446

Expected answer: 446

Correct? Yes

๐Ÿ”— Follow-up

Problem: What would happen if the number of tourists wanting to explore the castle was still 976, but this time each group could accommodate up to 726 people? How many tourists would be left for the last group of the day now?

Llama 3 8B:

Reasoning: The maximum capacity of each tour group is now 726 people. Since there are still 976 tourists, we can divide 976 by 726 to find the number of groups that can be accommodated:

976 รท 726 = 1.35 (round down to 1, since you can't have a fraction of a group)

This means that 1 group of 726 people can be accommodated, leaving:

976 - 726 = 250

tourists for the last group of the day.
### Answer: 250

Expected answer: 250

Correct? Yes