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Llama 3 8B on 5.NF.A.2

Common Core Standard 5.NF.A.2

This standard covers the following:

Solve word problems involving addition and subtraction of fractions referring to the same whole, including cases of unlike denominators, e.g., by using visual fraction models or equations to represent the problem. Use benchmark fractions and number sense of fractions to estimate mentally and assess the reasonableness of answers.

๐Ÿ”— Problem

Problem: In their game, Kyle threw a ball for a distance of 18/4 yards, while Lisa threw the same ball for a distance of 19/9 yards. How many yards did the ball travel in total?

Llama 3 8B:

Reasoning: Kyle threw the ball for a distance of 18/4 yards, which can be simplified to 4.5 yards.
Lisa threw the ball for a distance of 19/9 yards, which can be simplified to 2.11 yards.
The total distance the ball traveled is the sum of Kyle's and Lisa's throws: 4.5 + 2.11 = 6.61 yards.
### Answer: 6.61

Expected answer: 119/18

Correct? No

๐Ÿ”— Problem

Problem: Johnnie the monkey was given 18/7 bananas by the zookeeper in the morning, and 12/14 bananas in the afternoon. In total, how many bananas were given to Johnnie the monkey?

Llama 3 8B:

Reasoning: To find the number of bananas given to Johnnie in the morning, we need to simplify the fraction 18/7. We can do this by dividing both the numerator and the denominator by their greatest common divisor, which is 3. This gives us 6/1, or simply 6. So, Johnnie was given 6 bananas in the morning.

In the afternoon, Johnnie was given 12/14 bananas. To simplify this fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 2. This gives us 6/7. So, Johnnie was given 6/7 bananas in the afternoon.

To find the total number of bananas given to Johnnie, we add the number of bananas given in the morning and the number of bananas given in the afternoon. This gives us 6 + 6/7 = 6 + 0.86 = 6.86 bananas.
### Answer: 6.86

Expected answer: 24/7

Correct? No

๐Ÿ”— Problem

Problem: The bottom of a door measures 4/19 inches from the floor, and the top of the door measures 9/10 inches from the ceiling. What is the total distance of the bottom and top of the door from the floor and ceiling, respectively?

Llama 3 8B:

Reasoning: The distance from the floor to the bottom of the door is 4/19 inches.
The distance from the ceiling to the top of the door is 1 - 9/10 = 1/10 inches.
The total distance is the sum of these two distances: 4/19 + 1/10 = <<(4*5+1*19)/(19*10)=23/190+19/190=42/190=7/38>>7/38 inches.
### Answer: 7/38

Expected answer: 211/190

Correct? No

๐Ÿ”— Problem

Problem: Ralph's juice recipe requires 17/3 liters of apple juice. However, he only uses 15/11 liters of it. How many liters of apple juice are left unused?

Llama 3 8B:

Reasoning: Ralph's recipe requires 17/3 liters of apple juice, but he only uses 15/11 liters. To find the difference, we need to subtract the amount used from the amount required:

(17/3) - (15/11) = ?

To subtract fractions, we need to find a common denominator, which is 33. So, we can rewrite the fractions as:

(17/3) = (187/33)
(15/11) = (165/33)

Now, we can subtract:

(187/33) - (165/33) = (22/33)

So, Ralph has 22/33 liters of apple juice left unused.

### Answer: 22/33

Expected answer: 142/33

Correct? No

๐Ÿ”— Problem

Problem: Billy is trying to roller skate in an empty parking lot. He initially travels 4 miles, but rolls back for 17/20 of a mile after spotting a pothole. How many miles did he ultimately travel forward?

Llama 3 8B:

Reasoning: Billy initially travels 4 miles, but then rolls back 17/20 of a mile. To find the distance he rolled back, we can convert the fraction to a decimal: 17/20 = 0.85. So, he rolled back 0.85 miles. To find the distance he traveled forward, we subtract the distance he rolled back from the initial distance: 4 - 0.85 = 3.15 miles.
### Answer: 3.15

Expected answer: 63/20

Correct? Yes

๐Ÿ”— Follow-up

Problem: Suppose instead of travelling 4 miles initially, Billy actually traveled 6 miles before rolling back 17/20 of a mile to avoid the pothole. With this change in initial distance, how many miles did Billy ultimately travel forward?

Llama 3 8B:

Reasoning: Billy initially travels 6 miles, but then rolls back 17/20 of a mile. To find the distance he rolled back, we can convert the fraction to a decimal: 17/20 = 0.85. So, he rolled back 0.85 miles. To find the distance he traveled forward, we subtract the distance he rolled back from the initial distance: 6 - 0.85 = 5.15 miles.
### Answer: 5.15

Expected answer: 103/20

Correct? No

๐Ÿ”— Problem

Problem: A rocket was launched into orbit. On the first day, it traveled 15/3 light years. On the second day, it traveled an additional 2/7 light years. How far has the rocket traveled in total?

Llama 3 8B:

Reasoning: The rocket traveled 15/3 light years on the first day, which can be simplified to 5 light years.
The rocket traveled an additional 2/7 light years on the second day.
To find the total distance traveled, we add the distances: 5 + 2/7 = 41/7 + 2/7 = 43/7 = 6 1/7 light years.
### Answer: 6 1/7 light years.

Expected answer: 37/7

Correct? No

๐Ÿ”— Problem

Problem: Captain Silverbeard found 10/13 of a treasure map at one shipwreck site and 16/19 of the same treasure map at another site. What is the total portion of the treasure map that he found?

Llama 3 8B:

Reasoning: Captain Silverbeard found 10/13 of the treasure map at one site and 16/19 of the treasure map at another site.
To find the total portion of the treasure map that he found, we need to add the fractions.
First, we need to find the least common multiple (LCM) of 13 and 19, which is 247.
Then, we convert both fractions to have the same denominator, which is 247:
10/13 = (10 x 19)/(13 x 19) = 190/247
16/19 = (16 x 13)/(19 x 13) = 208/247
Now, we add the fractions:
190/247 + 208/247 = 398/247
### Answer: 398/247

Expected answer: 398/247

Correct? Yes

๐Ÿ”— Follow-up

Problem: After Captain Silverbeard finds the portions of the treasure map, he discovers another piece on a third site which is 15/17 of the total map. What is the total portion of the treasure map that Captain Silverbeard has now?

Llama 3 8B:

Reasoning: Captain Silverbeard already found 398/247 of the treasure map.
He finds another piece which is 15/17 of the total map.
To find the total portion of the treasure map that he has now, we need to add the new piece to the portion he already found.
First, we need to find the least common multiple (LCM) of 247 and 17, which is 247.
Then, we convert the new fraction to have the same denominator, which is 247:
15/17 = (15 x 14)/(17 x 14) = 210/247
Now, we add the fractions:
398/247 + 210/247 = 608/247
### Answer: 608/247

Expected answer: 10471/4199

Correct? No

๐Ÿ”— Follow-up

Problem: Suppose instead of finding 10/13 of the treasure map at the first shipwreck site, Captain Silverbeard found a larger piece which was 10/9 of the total map. Keeping the second portion from the other shipwreck site the same at 16/19, what is the total portion of the treasure map that he found now?

Llama 3 8B:

Reasoning: Captain Silverbeard found 10/9 of the treasure map at one site and 16/19 of the treasure map at another site.
To find the total portion of the treasure map that he found, we need to add the fractions.
First, we need to find the least common multiple (LCM) of 9 and 19, which is 171.
Then, we convert both fractions to have the same denominator, which is 171:
10/9 = (10 x 19)/(9 x 19) = 190/171
16/19 = (16 x 9)/(19 x 9) = 144/171
Now, we add the fractions:
190/171 + 144/171 = 334/171
### Answer: 334/171

Expected answer: 334/171

Correct? Yes

๐Ÿ”— Problem

Problem: A hiker decides to walk 9/6 miles North before walking 2/16 miles East. How many miles has the hiker traveled in total?

Llama 3 8B:

Reasoning: The hiker walks 9/6 = 3/2 = 1.5 miles North.
The hiker walks 2/16 = 1/8 miles East.
The hiker travels a total distance of โˆš(1.5^2 + 1/8^2) = โˆš(2.25 + 0.0625) = โˆš2.3125 โ‰ˆ 1.51 miles.
### Answer: โ‰ˆ 1.51

Expected answer: 13/8

Correct? No

๐Ÿ”— Problem

Problem: In Jessica's sandbox, she has a pile of sand that is 16/9 cubic feet. She then removes 4/13 cubic feet of sand from the sandbox. How much sand does she have left in her sandbox?

Llama 3 8B:

Reasoning: Jessica has 16/9 cubic feet of sand initially.
She removes 4/13 cubic feet of sand, which is equal to 16/9 * 4/13 = 16/39 cubic feet.
So, she has 16/9 - 16/39 = 16/39 * 39/39 - 16/39 = 16/39 * (39/39 - 1) = 16/39 * (-16/39) = -16/39 cubic feet left.
### Answer: -16/39

Expected answer: 172/117

Correct? No

๐Ÿ”— Problem

Problem: Jacob has a piece of rope that is 15/12 meters long and he adds a piece that is 17/17 meters long to it. What is the total length of the rope now?

Llama 3 8B:

Reasoning: Jacob's original rope is 15/12 meters long. To convert this to a decimal, we can divide the numerator by the denominator: 15 รท 12 = 1.25 meters.
He adds a piece that is 17/17 meters long, which is equal to 1 meter (since 17 รท 17 = 1).
The total length of the rope now is the sum of the original length and the added length: 1.25 + 1 = 2.25 meters.
### Answer: 2.25

Expected answer: 9/4

Correct? Yes

๐Ÿ”— Follow-up

Problem: Jacob now wants to double the total length of the rope he has. If Jacob starts with the rope that is ((15 / 12) + (17 / 17)) meters long, and then adds another piece of the same length to it, what will be the total length of the combined ropes?

Llama 3 8B:

Reasoning: Jacob's original rope is ((15/12) + (17/17)) meters long, which we calculated earlier to be 2.25 meters.
He adds another piece of the same length to it, so the total length of the combined ropes is 2.25 + 2.25 = 4.5 meters.
### Answer: 4.5

Expected answer: 9/2

Correct? No

๐Ÿ”— Follow-up

Problem: Now, suppose Jacob starts with a piece of rope that is 7/12 meters long instead of 15/12 meters. If he still adds the rope piece that is 17/17 meters long to it, what is the total length of the rope now?

Llama 3 8B:

Reasoning: Jacob's original rope is 7/12 meters long. To convert this to a decimal, we can divide the numerator by the denominator: 7 รท 12 = 0.583333... meters (approximately).
He adds a piece that is 17/17 meters long, which is equal to 1 meter (since 17 รท 17 = 1).
The total length of the rope now is the sum of the original length and the added length: 0.583333... + 1 = 1.583333... meters (approximately).
### Answer: 1.583333...

Expected answer: 19/12

Correct? No

๐Ÿ”— Problem

Problem: Mark has 1 full pair of pants and another 13/4 pairs from various incomplete sets. How many pairs of pants does he have in total?

Llama 3 8B:

Reasoning: Mark has 1 full pair of pants, which is equal to 2 pairs.
He also has 13/4 pairs from various incomplete sets. To convert this to a decimal, we can divide the numerator by the denominator: 13 รท 4 = 3.25.
So, Mark has 3.25 pairs from various incomplete sets. Since you can't have a fraction of a pair, we'll round this to 3 pairs.
In total, Mark has 2 (full pair) + 3 (from incomplete sets) = 5 pairs of pants.
### Answer: 5

Expected answer: 17/4

Correct? No

๐Ÿ”— Problem

Problem: Miss Jenny stayed after school to grade papers. She spent 8/8 hours on one subject and an additional 20/19 hours on another subject. How long did she spend grading papers in total?

Llama 3 8B:

Reasoning: Miss Jenny spent 8 hours on one subject. She spent an additional 20/19 hours on another subject. To find the total hours spent on the second subject, we need to convert the mixed number to an improper fraction: 20/19 = 1 1/19. Then, we add the hours spent on both subjects: 8 + 1 1/19 = 9 1/19. To convert this mixed number to a decimal, we divide the numerator by the denominator: 1/19 = 0.0526. Then, we add this decimal to the whole number part: 9 + 0.0526 = 9.0526. Since we can't spend a fraction of an hour, we round this decimal to the nearest tenth: 9.1 hours. Therefore, Miss Jenny spent 8 + 9.1 = <<8+9.1=17.1>>17.1 hours grading papers in total.
### Answer: 17.1

Expected answer: 39/19

Correct? No

๐Ÿ”— Problem

Problem: A cloud was observed at a height of 12/3 kms, it later ascended by 15/12 kms. What was the resultant height of the cloud from the ground?

Llama 3 8B:

Reasoning: The initial height of the cloud is 12/3 = 4 kms.
The cloud ascended by 15/12 = 1.25 kms.
So, the resultant height of the cloud from the ground is 4 + 1.25 = 5.25 kms.
### Answer: 5.25

Expected answer: 21/4

Correct? Yes

๐Ÿ”— Follow-up

Problem: Let's now consider this scenario: the cloud was initially at a height of 12/3 kms, then later it ascended by 7/12 kms instead of the previous 15/12 kms. What would be the resultant height of the cloud from the ground in this case?

Llama 3 8B:

Reasoning: The initial height of the cloud is still 12/3 = 4 kms.
The cloud ascended by 7/12 = 0.5833 (approximately) kms.
So, the resultant height of the cloud from the ground is 4 + 0.5833 = 4.5833 (approximately) kms.
### Answer: 4.5833

Expected answer: 55/12

Correct? No

๐Ÿ”— Problem

Problem: Jack rides his scooter 3/9 of a mile to the library. After leaving, he scoots another 17/15 of a mile to his grandparents' house. How many miles does Jack ride his scooter in total?

Llama 3 8B:

Reasoning: To find the total distance Jack rides his scooter, we need to add the distance he rides to the library and the distance he rides to his grandparents' house.

The distance he rides to the library is 3/9 of a mile. To simplify this fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 3.

3 รท 3 = 1
9 รท 3 = 3

So, the distance he rides to the library is 1/3 of a mile.

The distance he rides to his grandparents' house is 17/15 of a mile. To simplify this fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 1.

17 รท 1 = 17
15 รท 1 = 15

So, the distance he rides to his grandparents' house is 17/15 of a mile.

To add these distances, we can convert both to decimal form:

1/3 = 0.33
17/15 = 1.13

Now, we can add these decimal values:

0.33 + 1.13 = 1.46

Therefore, Jack rides his scooter a total of 1.46 miles.
### Answer: 1.46

Expected answer: 22/15

Correct? No

๐Ÿ”— Problem

Problem: There are 4 logs in a pile that each burn for 1/16 of an hour. The fire burns out and Tom brings 16 twigs, each of which burns for 1/12 of an hour. What is the total burn time for the logs and twigs?

Llama 3 8B:

Reasoning: The logs burn for 4 x 1/16 = 1/4 of an hour.
The twigs burn for 16 x 1/12 = 4/3 of an hour.
The total burn time is the sum of the burn times for the logs and twigs, which is 1/4 + 4/3 = 5/12 + 4/3 = 5/12 + 20/12 = 25/12 of an hour.
### Answer: 25/12

Expected answer: 19/12

Correct? No

๐Ÿ”— Problem

Problem: If a ring maker uses 12/16 ounces of a silver for the base of the ring and 16/2 ounces to make the rest of the ring, how many ounces of silver did the ring maker use in total?

Llama 3 8B:

Reasoning: The ring maker uses 12/16 ounces for the base of the ring, which is equal to 0.75 ounces (12/16 = 0.75).
The ring maker uses 16/2 ounces for the rest of the ring, which is equal to 8 ounces (16/2 = 8).
The total amount of silver used is the sum of the base and the rest, which is 0.75 + 8 = 8.75 ounces.
### Answer: 8.75

Expected answer: 35/4

Correct? Yes

๐Ÿ”— Follow-up

Problem: The ring maker decides to add an ornamental filigree to the ring, which requires an additional 18/20 ounces of silver. How many total ounces of silver did the ring maker use including the filigree?

Llama 3 8B:

Reasoning: The ring maker used 8.75 ounces of silver initially.
The ring maker adds an additional 18/20 ounces of silver for the filigree, which is equal to 0.9 ounces (18/20 = 0.9).
The total amount of silver used, including the filigree, is the sum of the initial amount and the additional amount, which is 8.75 + 0.9 = 9.65 ounces.
### Answer: 9.65

Expected answer: 193/20

Correct? No

๐Ÿ”— Follow-up

Problem: If initially, the ring maker used 10/16 ounces of a silver for the base of the ring instead of 12/16 ounces, while still using 16/2 ounces to make the rest of the ring, how many total ounces of silver did the ring maker use then?

Llama 3 8B:

Reasoning: The ring maker uses 10/16 ounces for the base of the ring, which is equal to 0.625 ounces (10/16 = 0.625).
The ring maker uses 16/2 ounces for the rest of the ring, which is equal to 8 ounces (16/2 = 8).
The total amount of silver used is the sum of the base and the rest, which is 0.625 + 8 = 8.625 ounces.
### Answer: 8.625

Expected answer: 69/8

Correct? No

๐Ÿ”— Problem

Problem: A farmer has an apple tree that produced 10/11 bushels of apples in the morning and 17/11 bushels in the afternoon. How many bushels of apples did the tree produce in total?

Llama 3 8B:

Reasoning: The farmer's apple tree produced 10/11 bushels of apples in the morning and 17/11 bushels in the afternoon. To find the total number of bushels produced, we can add the two fractions together:

(10/11) + (17/11) = ?

To add these fractions, we need to have the same denominator, which is 11. So, we can rewrite the fractions with the same denominator:

(10/11) + (17/11) = (10+17)/11 = 27/11

So, the apple tree produced 27/11 bushels of apples in total.

### Answer: 27/11

Expected answer: 27/11

Correct? Yes

๐Ÿ”— Follow-up

Problem: Now assume the farmer's first apple tree produced 10/9 bushels instead of 10/11 bushels in the morning. With the same amount of apples in the afternoon, how many bushels of apples did this tree produce in one day?

Llama 3 8B:

Reasoning: The farmer's apple tree produced 10/9 bushels of apples in the morning and 17/11 bushels in the afternoon. To find the total number of bushels produced, we can add the two fractions together:

(10/9) + (17/11) = ?

To add these fractions, we need to have the same denominator, which is the least common multiple (LCM) of 9 and 11, which is 99. So, we can rewrite the fractions with the same denominator:

(10/9) = (110/99) and (17/11) = (51/99)

Now we can add the fractions:

(110/99) + (51/99) = 161/99

So, the apple tree produced 161/99 bushels of apples in total.

### Answer: 161/99

Expected answer: 263/99

Correct? No

๐Ÿ”— Problem

Problem: If Sam's binoculars increase his range of sight by 3/14 of a mile and Joe's binoculars increase his range of sight by exactly 1 mile (16/16), what is their combined range increase when they use the binoculars one after the other?

Llama 3 8B:

Reasoning: Sam's binoculars increase his range of sight by 3/14 of a mile, which can be written as 3/14 * 1 mile. Joe's binoculars increase his range of sight by 1 mile, which is 16/16 * 1 mile. When they use the binoculars one after the other, the total increase in range is the sum of the two: (3/14 + 16/16) * 1 mile. To add these fractions, we need a common denominator, which is 56. So, we can rewrite the fractions as 24/56 + 16/16. The 16/16 simplifies to 1, so the total increase in range is (24/56 + 1) * 1 mile. This simplifies to (25/56) * 1 mile, which is 25/56 mile.
### Answer: 25/56

Expected answer: 17/14

Correct? No

๐Ÿ”— Problem

Problem: Maria uses 15/10 yards of fabric for a section of a blanket and 9/18 more yards for another section. What is the total length of fabric Maria uses for these two sections?

Llama 3 8B:

Reasoning: Maria uses 15/10 yards of fabric for the first section. To find the equivalent fraction with a denominator of 18, we can multiply both the numerator and denominator by 2, getting 30/20 yards. For the second section, Maria uses 9/18 yards. To find the equivalent fraction with a denominator of 20, we can multiply both the numerator and denominator by 1, getting 9/18 yards. Now we can add the two sections together: 30/20 + 9/18 = 30/20 + 9/20 = 39/20 yards.
### Answer: 39/20

Expected answer: 2

Correct? No

๐Ÿ”— Problem

Problem: A turtle walks 10/5 miles forward, then walks backward 5/16 mile. How many miles has the turtle actually covered from its starting point?

Llama 3 8B:

Reasoning: The turtle walks 10/5 = 2 miles forward, then walks backward 5/16 = 0.3125 miles.
The turtle has actually covered 2 - 0.3125 = 1.6875 miles from its starting point.
### Answer: 1.6875

Expected answer: 27/16

Correct? Yes

๐Ÿ”— Follow-up

Problem: In the previous question, we considered the turtle walking forward 10/5 miles and walking backward 5/16 mile. Now, assume instead that the turtle walks backward a distance of 5/6 miles instead of 5/16 mile after walking forward. Now, how far is the turtle from its starting point?

Llama 3 8B:

Reasoning: The turtle walks 10/5 = 2 miles forward, then walks backward 5/6 = 0.8333 miles.
The turtle has actually covered 2 - 0.8333 = 1.1667 miles from its starting point.
### Answer: 1.1667

Expected answer: 7/6

Correct? No

๐Ÿ”— Problem

Problem: A painter uses 18/11 liters of blue paint and 1/8 liters of white paint to mix a shade of sky blue. How much paint in liters did he use in total?

Llama 3 8B:

Reasoning: The painter uses 18/11 liters of blue paint and 1/8 liters of white paint. To find the total amount of paint used, we need to add these two amounts together.

First, we can simplify the fractions by finding the common denominator, which is 88.

18/11 = 72/88
1/8 = 11/88

Now we can add the two amounts:

72/88 + 11/88 = 83/88

So, the painter used 83/88 liters of paint in total.

### Answer: 83/88

Expected answer: 155/88

Correct? No

๐Ÿ”— Problem

Problem: A computer program executed 8 tasks in 4 minutes and then executed another 20 tasks in 14 minutes. What is the total number of tasks it executed per minute?

Llama 3 8B:

Reasoning: The computer program executed 8 tasks in 4 minutes, so it executed 8/4 = 2 tasks per minute.
Then, it executed 20 tasks in 14 minutes, so it executed 20/14 = 10/7 tasks per minute.
The total number of tasks it executed per minute is 2 + 10/7 = 14/7 = 2 tasks per minute.
### Answer: 2

Expected answer: 24/7

Correct? No

๐Ÿ”— Problem

Problem: At the end of a rainbow, there are pots filled with magical gold coins. One pot contains 12/13 of a pound of gold coins while another contains 3/2 pounds of gold coins. How much gold is there in total?

Llama 3 8B:

Reasoning: To find the total amount of gold, we need to convert both fractions to a common denominator, which is 26 in this case.

12/13 = 12 ร— (2/2) / 13 = 24/26
3/2 = 3 ร— (13/13) / 2 = 39/26

Now, we can add the two amounts:

24/26 + 39/26 = 63/26

To simplify the fraction, we can divide both numerator and denominator by their greatest common divisor, which is 3:

63 รท 3 = 21
26 รท 3 = 8.67

So, the total amount of gold is 21 8/13 pounds.

### Answer: 21 8/13 pounds.

Expected answer: 63/26

Correct? No

๐Ÿ”— Problem

Problem: In space, an alien named Zorg receives a video message from earth that is divided into parts. The first part of the message is 4/4 hours long, and the second part is 11/1 hour long. How long in total is the message Zorg received?

Llama 3 8B:

Reasoning: The first part of the message is 4/4 hours long, which is equal to 1 hour. The second part is 11/1 hour long, which is equal to 11 hours. To find the total length of the message, we add the lengths of the two parts: 1 hour + 11 hours = 12 hours.
### Answer: 12

Expected answer: 12

Correct? Yes

๐Ÿ”— Follow-up

Problem: After watching the original message, Zorg receives an additional part of the message from earth that is 7/8 hours long. What is the total length of all parts of the message that Zorg received?

Llama 3 8B:

Reasoning: Zorg already received a message that was 12 hours long. The additional part is 7/8 hours long, which is equal to 0.875 hours (since 7/8 can be converted to a decimal by dividing the numerator by the denominator). To find the total length of all parts of the message, we add the lengths of the three parts: 12 hours + 0.875 hours = 12.875 hours.
### Answer: 12.875

Expected answer: 103/8

Correct? Yes

๐Ÿ”— Follow-up

Problem: Upon reviewing the original video message, Zorg realised that the first part of the video message was actually half as long at 4/8 hours instead of 4/4. The second part of the message still remains 11/1 hour long. What is the total length of the message that Zorg has corrected?

Llama 3 8B:

Reasoning: The first part of the message is now 4/8 hours long, which is equal to 1/2 hour or 0.5 hours. The second part is still 11/1 hour long, which is equal to 11 hours. To find the total length of the message, we add the lengths of the two parts: 0.5 hours + 11 hours = 11.5 hours.
### Answer: 11.5

Expected answer: 23/2

Correct? Yes

๐Ÿ”— Problem

Problem: In a park, 10 ducks are equally distributed among 5 ponds, implying each pond has 10 / 5 ducks. In the same park, 8 fish are distributed among 10 small pools, with each pool having 8 / 10 fish. How many animals are there in each pond and pool combined?

Llama 3 8B:

Reasoning: Each pond has 10/5 = 2 ducks.
Each pool has 8/10 = 0.8 fish.
There are 5 ponds and 10 pools, so the total number of ducks is 5 x 2 = 10.
The total number of fish is 10 x 0.8 = 8.
The total number of animals is 10 ducks + 8 fish = 18.
### Answer: 18

Expected answer: 14/5

Correct? No

๐Ÿ”— Problem

Problem: On a map, 15/11 inches represents the distance between Town A and Town B, and 16/15 inches represents the distance between Town B and Town C. What is the total distance between Town A and Town C on the map?

Llama 3 8B:

Reasoning: The distance between Town A and Town B is 15/11 inches. The distance between Town B and Town C is 16/15 inches. To find the total distance between Town A and Town C, we need to add these two distances.

First, we can find a common denominator for both fractions, which is 165. Then, we can convert both fractions to have a denominator of 165:

15/11 = 165/143
16/15 = 176/143

Now, we can add these two fractions:

165/143 + 176/143 = 341/143

So, the total distance between Town A and Town C on the map is 341/143 inches.

### Answer: 341/143

Expected answer: 401/165

Correct? No

๐Ÿ”— Problem

Problem: A soap company produces 13/18 tons of Soap A and 4/6 tons of Soap B in a day. How many tons of soap do they produce in total each day?

Llama 3 8B:

Reasoning: To find the total amount of soap produced, we need to add the amount of Soap A and Soap B.

First, we need to convert both fractions to have the same denominator, which is 18.

Soap A: 13/18
Soap B: (4/6) ร— (3/3) = 12/18

Now we can add them:

13/18 + 12/18 = 25/18

So, the company produces 25/18 tons of soap in total each day.

### Answer: 25/18

Expected answer: 25/18

Correct? Yes

๐Ÿ”— Follow-up

Problem: The soap company plans to double their daily production. After producing 13/18 tons of Soap A and 4/6 tons of Soap B each day, how many tons of soap will they produce in total when they double their production?

Llama 3 8B:

Reasoning: Since the company plans to double their daily production, they will produce twice the amount of soap they currently produce.

Currently, they produce:

Soap A: 13/18 tons
Soap B: 4/6 tons = 12/18 tons (converted to have the same denominator)

Total soap produced: 13/18 + 12/18 = 25/18 tons

To double their production, they will produce:

Soap A: 2 ร— 13/18 = 26/18 tons
Soap B: 2 ร— 12/18 = 24/18 tons

Total soap produced when doubled: 26/18 + 24/18 = 50/18 tons

### Answer: 50/18

Expected answer: 25/9

Correct? Yes

๐Ÿ”— Follow-up

Problem: The soap company decided to increase the production of Soap A to 17/18 tons a day while maintaining the production of Soap B at 4/6 tons a day. How many tons of soap do they produce in total each day after this change?

Llama 3 8B:

Reasoning: The company is still producing Soap B at the same rate, which is 4/6 tons a day. To find the total amount of soap produced, we need to add the new amount of Soap A and Soap B.

First, we need to convert both fractions to have the same denominator, which is 18.

Soap A: 17/18
Soap B: (4/6) ร— (3/3) = 12/18

Now we can add them:

17/18 + 12/18 = 29/18

So, the company produces 29/18 tons of soap in total each day after this change.

### Answer: 29/18

Expected answer: 29/18

Correct? Yes

๐Ÿ”— Problem

Problem: Mark bought a sleeping bag that was 19/2 feet long. However, he decides to cut off 13/12 feet from it to fit his height. How long is his sleeping bag now?

Llama 3 8B:

Reasoning: Mark's sleeping bag was originally 19/2 = 9.5 feet long.
He cut off 13/12 = 1.0833... feet from it.
So, the new length of his sleeping bag is 9.5 - 1.0833... = 8.4166... feet.
### Answer: 8.4166... feet (approximately 8.42 feet)

Expected answer: 101/12

Correct? No

๐Ÿ”— Problem

Problem: At the zoo, Mary feeds 6/20 pounds of food to the monkeys, and 18/15 pounds of food to the giraffes. How many pounds of food in total has she given to the monkeys and giraffes?

Llama 3 8B:

Reasoning: First, we need to simplify the fractions. 6/20 can be simplified to 3/10, and 18/15 can be simplified to 6/5. So, Mary feeds 3/10 pounds of food to the monkeys, and 6/5 pounds of food to the giraffes.
To find the total amount of food given, we need to add the amounts given to the monkeys and giraffes. 3/10 + 6/5 can be rewritten as (3/10) + (12/10) = (15/10) = 1 1/2 pounds.
### Answer: 1 1/2 pounds.

Expected answer: 3/2

Correct? Yes

๐Ÿ”— Follow-up

Problem: After feeding the monkeys and giraffes, Mary then feeds the elephants 19/11 pounds of food. How many pounds of food in total has she given to the monkeys, giraffes, and elephants at the zoo?

Llama 3 8B:

Reasoning: We already found that Mary gave 1 1/2 pounds of food to the monkeys and giraffes. Now, she gives 19/11 pounds of food to the elephants. To find the total amount of food given, we add the amounts given to the monkeys and giraffes, and the amount given to the elephants: 1 1/2 + 19/11 = (3/2) + (19/11) = (33/22) + (38/22) = (71/22) = 3 1/22 pounds.
### Answer: 3 1/22 pounds.

Expected answer: 71/22

Correct? No

๐Ÿ”— Follow-up

Problem: Originally, Mary had given the monkeys 6/20 pounds of food and the giraffes 18/15 pounds of food. But what if she had made a mistake, and she actually gave the giraffes 18/19 pounds of food instead? How many pounds of food in total did she then give to the monkeys and giraffes?

Llama 3 8B:

Reasoning: If Mary gave the giraffes 18/19 pounds of food instead of 18/15 pounds, we need to simplify the new fraction. 18/19 can be simplified to 18/19.
Now, we need to find the total amount of food given to the monkeys and giraffes. Mary gave the monkeys 6/20 pounds of food, which can be simplified to 3/10 pounds. She gave the giraffes 18/19 pounds of food.
To find the total amount of food given, we add the amounts given to the monkeys and giraffes: 3/10 + 18/19. To add these fractions, we need a common denominator, which is 190. So, we rewrite the fractions with a denominator of 190: (38/190) + (18/19). We can simplify 18/19 to 171/190. Now, we can add the fractions: (38/190) + (171/190) = (209/190).
### Answer: 209/190.

Expected answer: 237/190

Correct? No

๐Ÿ”— Problem

Problem: Albert has a deck of 20/17 full sets of cards to start. He then collects another full set of 4/1 cards. How many full sets of cards does he have now?

Llama 3 8B:

Reasoning: Albert starts with 20/17 full sets of cards, which is equivalent to 20/17 = 1.17647... (approximately 1.18) full sets. He then collects another full set of 4/1 cards, which is 4 full sets.
In total, Albert has 1.18 + 4 = 5.18 full sets of cards, which is approximately 5 full sets.
### Answer: 5

Expected answer: 88/17

Correct? No

๐Ÿ”— Problem

Problem: A jeweler has 5/14 pound of silver and adds 18/19 pounds more to the supply. How many pounds of silver does the jeweler have now to make rings?

Llama 3 8B:

Reasoning: The jeweler initially has 5/14 pounds of silver.
Adding 18/19 pounds more, the jeweler now has 5/14 + 18/19 = 95/238 pounds of silver.
### Answer: 95/238

Expected answer: 347/266

Correct? No

๐Ÿ”— Problem

Problem: A turtle starts at a point and moves 11 meters northward. Then, it moves 15/15 of a meter back towards the starting point. How many meters is the turtle from its starting point after these two movement?

Llama 3 8B:

Reasoning: The turtle moves 11 meters northward, so it is 11 meters away from the starting point.
Then, it moves 15/15 of a meter back towards the starting point, which is equivalent to 1 meter back towards the starting point.
So, the turtle is now 11 - 1 = 10 meters away from the starting point.
### Answer: 10

Expected answer: 10

Correct? Yes

๐Ÿ”— Follow-up

Problem: Continuing from the prior situation, the turtle then decided to move further, walking an additional 15/20 of a meter towards the same direction. How many meters is the turtle from its original starting point now?

Llama 3 8B:

Reasoning: The turtle is currently 10 meters away from the starting point.
It then moves 15/20 of a meter further, which is equivalent to 3/4 of a meter further.
So, the turtle is now 10 + 3/4 = 10.75 meters away from the starting point.
### Answer: 10.75

Expected answer: 43/4

Correct? Yes

๐Ÿ”— Follow-up

Problem: Reconsider the previous scenario, but this time the turtle returns 15/8 of a meter back towards the starting point instead of the former 15/15 meters. Now, how many meters is the turtle from its starting point after these two movements?

Llama 3 8B:

Reasoning: The turtle moves 11 meters northward, so it is 11 meters away from the starting point.
Then, it moves 15/8 of a meter back towards the starting point. To convert this to a decimal, we can divide 15 by 8, which gives us 1.875.
So, the turtle moves 1.875 meters back towards the starting point.
To find the new distance from the starting point, we subtract the distance moved back from the original distance: 11 - 1.875 = 9.125 meters.
### Answer: 9.125

Expected answer: 73/8

Correct? Yes

๐Ÿ”— Problem

Problem: Chloe has a chocolate bar that is 19/2 ounces. If she eats a piece that is 17/2 ounces, how many ounces of chocolate does she have left?

Llama 3 8B:

Reasoning: Chloe has 19/2 ounces of chocolate initially.
She eats 17/2 ounces, so she is left with 19/2 - 17/2 = 2/2 = 1 ounces.
### Answer: 1

Expected answer: 1

Correct? Yes

๐Ÿ”— Follow-up

Problem: After Chloe eats a piece of the chocolate bar, she decides to add a piece from another chocolate bar. The piece from the other bar weighs 4/14 ounces. How many ounces of chocolate does Chloe have now?

Llama 3 8B:

Reasoning: Chloe has 1 ounce of chocolate left from the initial bar.
She adds 4/14 ounces from the other bar, so she now has 1 + 4/14 = 1 + 2/7 = 7/7 = 1 ounces.
### Answer: 1

Expected answer: 9/7

Correct? No

๐Ÿ”— Follow-up

Problem: Originally, Chloe had a chocolate bar that was 19/2 ounces. What if instead, at the beginning she had eaten a piece that was 9/2 ounces? How many ounces of chocolate would she have had left then?

Llama 3 8B:

Reasoning: Chloe has 19/2 ounces of chocolate initially.
She eats 9/2 ounces, so she is left with 19/2 - 9/2 = 10/2 = 5 ounces.
### Answer: 5

Expected answer: 5

Correct? Yes

๐Ÿ”— Problem

Problem: Sammy has a backpack with a capacity of 20/9 liters. If he adds another pouch to the backpack that can hold 8/4 more liters, what will be the total capacity of his backpack?

Llama 3 8B:

Reasoning: The original capacity of the backpack is 20/9 liters. The additional pouch can hold 8/4 = 2 liters. The total capacity of the backpack will be the original capacity plus the additional capacity, which is 20/9 + 2 = 20/9 + 2*1/4 = 20/9 + 1/2 = 40/9 + 1/2 = 40/9 + 1/2*9/9 = 40/9 + 9/18 = 40/9 + 5/9 = 45/9 = 5.
### Answer: 5 liters.

Expected answer: 38/9

Correct? No

๐Ÿ”— Problem

Problem: Captain Hook has 11/8 ounces of gold. He finds an additional 5/5 ounces of gold on his latest treasure hunt. What is the total weight of the gold Captain Hook now has?

Llama 3 8B:

Reasoning: Captain Hook initially has 11/8 ounces of gold.
He finds an additional 5/5 ounces of gold, which can be simplified to 1 ounce.
The total weight of the gold Captain Hook now has is 11/8 + 1 = 11/8 + 8/8 = 19/8 ounces.
### Answer: 19/8 ounces.

Expected answer: 19/8

Correct? Yes

๐Ÿ”— Follow-up

Problem: After counting his newly found gold, Captain Hook discovers an additional 7/11 ounces of gold hidden in a small pouch he had forgotten about. What is the total weight of all the gold Captain Hook now has?

Llama 3 8B:

Reasoning: Captain Hook already had 19/8 ounces of gold.
He finds an additional 7/11 ounces of gold.
To add these fractions, we need a common denominator, which is 88. So, we convert both fractions to have a denominator of 88:
19/8 = 209/88
7/11 = 56/88
The total weight of the gold Captain Hook now has is 209/88 + 56/88 = 265/88 ounces.
### Answer: 265/88 ounces.

Expected answer: 265/88

Correct? Yes

๐Ÿ”— Follow-up

Problem: In the previous treasure hunt, Captain Hook had originally found 11/8 ounces of gold. But let's say, instead of finding 5/5 ounces of gold as he did in his latest treasure hunt, he discovered 7/5 ounces of gold. How much total weight of gold would Captain Hook have had then?

Llama 3 8B:

Reasoning: Captain Hook initially had 11/8 ounces of gold.
He finds an additional 7/5 ounces of gold.
To add these fractions, we need a common denominator, which is 40. So, we can rewrite the fractions as:
11/8 = 22/16
7/5 = 28/20
Adding these fractions, we get:
22/16 + 28/20 = 110/80
Simplifying the fraction, we get:
11/8 + 7/5 = 11/8 + 14/8 = 25/8 ounces
### Answer: 25/8 ounces.

Expected answer: 111/40

Correct? No

๐Ÿ”— Problem

Problem: If Jake originally had 9/10 of a dollar and then received an additional 20/15 of a dollar, how much money does he have in his wallet now?

Llama 3 8B:

Reasoning: Jake originally had 9/10 of a dollar, which is equal to 0.9 dollars.
He received an additional 20/15 of a dollar, which is equal to 4/3 dollars.
To find the total amount of money Jake has, we add the two amounts together: 0.9 + 4/3 = 0.9 + 1.33 = 2.23.
### Answer: 2.23

Expected answer: 67/30

Correct? No

๐Ÿ”— Problem

Problem: Paul has built the front half of a chair that measures 5/2 feet high. He also constructs the back portion of the chair that measures 20/14 feet. What is the combined height of the front and back portions of the chair that Paul has constructed?

Llama 3 8B:

Reasoning: The front portion of the chair is 5/2 feet high. To find the height of the front portion in decimal form, we can convert the fraction to a decimal: 5/2 = 2.5 feet.
The back portion of the chair is 20/14 feet high. To find the height of the back portion in decimal form, we can convert the fraction to a decimal: 20/14 = 1.42857142857143 feet (approximately).
The combined height of the front and back portions of the chair is 2.5 + 1.42857142857143 = 3.92857142857143 feet (approximately).
### Answer: 3.93 feet (approximately).

Expected answer: 55/14

Correct? No

๐Ÿ”— Problem

Problem: John has 5 shirts and he donated 12/9 of them to charity. How many shirts does he have left?

Llama 3 8B:

Reasoning: John has 5 shirts initially.
He donated 12/9 of them, which is equivalent to 4/3 of them (since 12/9 = 4/3).
So, he donated 4/3 * 5 = 20/3 shirts.
He has 5 - 20/3 = 5 - 2 2/3 = 5 - 2.67 = 2.33 shirts left.
### Answer: 2.33

Expected answer: 11/3

Correct? No

๐Ÿ”— Problem

Problem: Bob has a jacket that measures 14/3 meters in length. However, he finds the jacket is slightly too long for him so he decides to cut off 14/16 meter from the original length. What is the length of Bob's jacket after the alteration?

Llama 3 8B:

Reasoning: Bob's original jacket length is 14/3 meters. He cuts off 14/16 meter from the original length. To find the length of the jacket after the alteration, we need to subtract 14/16 from 14/3.

First, we need to find a common denominator for 3 and 16, which is 48. So, we can rewrite the fractions as:

14/3 = 56/48
14/16 = 7/48

Now, we can subtract:

56/48 - 7/48 = 49/48

So, the length of Bob's jacket after the alteration is 49/48 meters.

### Answer: 49/48

Expected answer: 91/24

Correct? No

๐Ÿ”— Problem

Problem: Officer Max spends 2/6 part of an hour completing paperwork. Then, he spends 14/7 parts of an hour patrolling the neighborhood. How much time, in parts of an hour, does Officer Max use for these two tasks?

Llama 3 8B:

Reasoning: Officer Max spends 2/6 = 1/3 part of an hour completing paperwork.
Officer Max spends 14/7 = 2 parts of an hour patrolling the neighborhood.
Officer Max uses 1/3 + 2 = <<1/3+2=5/3>>5/3 parts of an hour for these two tasks.
### Answer: 5/3

Expected answer: 7/3

Correct? No

๐Ÿ”— Problem

Problem: John watched a movie for 10/12 of an hour and then watched a TV show for another 3/8 of an hour. What is the total time he spent watching in hours?

Llama 3 8B:

Reasoning: To convert the fractions to hours, we can divide the numerator by the denominator: 10/12 = 5/6 and 3/8 = 3/8.
John watched a movie for 5/6 of an hour and then watched a TV show for another 3/8 of an hour.
To find the total time, we can add the two fractions: 5/6 + 3/8 = 5/6 + 1.5/6 = 6.5/6 = 1 1/6.
### Answer: 1 1/6 hours.

Expected answer: 29/24

Correct? No

๐Ÿ”— Problem

Problem: Mr. Carpenter makes crafting chairs a meticulous process. He takes 5/3 hours to build the frame and additional 10/13 hours to upholster it. How long does it take for him to build a chair from start to finish?

Llama 3 8B:

Reasoning: Mr. Carpenter takes 5/3 hours to build the frame and 10/13 hours to upholster it. To find the total time, we need to add these two times together.

First, we can find a common denominator for the fractions by multiplying both the numerator and denominator of 5/3 by 13 and multiplying both the numerator and denominator of 10/13 by 3. This gives us:

5/3 = 65/39
10/13 = 30/39

Now we can add the two times together:

65/39 + 30/39 = 95/39

To simplify this fraction, we can divide both the numerator and denominator by their greatest common divisor, which is 5:

95/39 = 19/7.7

So, it takes Mr. Carpenter 19/7.7 hours to build a chair from start to finish.

### Answer: 19/7.7 hours

Expected answer: 95/39

Correct? No

๐Ÿ”— Problem

Problem: Anna has a bracelet that consists of small and large beads. The small beads are each 8/4 mm in diameter and the large beads are each 15/2 mm in diameter. If she adds a small and a large bead to her bracelet, what would be the total added diameter in mm?

Llama 3 8B:

Reasoning: The diameter of a small bead is 8/4 = 2 mm. The diameter of a large bead is 15/2 = 7.5 mm. The total added diameter is the sum of the diameters of the small and large beads, which is 2 + 7.5 = 9.5 mm.
### Answer: 9.5

Expected answer: 19/2

Correct? Yes

๐Ÿ”— Follow-up

Problem: Suppose instead of the large bead of 15/2 mm diameter, Anna adds a different large bead to her bracelet that is 5/2 mm in diameter. Now, what would be the total added diameter if she adds this new large bead and the small bead to her bracelet?

Llama 3 8B:

Reasoning: The diameter of a small bead is still 8/4 = 2 mm. The diameter of the new large bead is 5/2 = 2.5 mm. The total added diameter is the sum of the diameters of the small and large beads, which is 2 + 2.5 = 4.5 mm.
### Answer: 4.5

Expected answer: 9/2

Correct? No

๐Ÿ”— Problem

Problem: A rocket travels 11/18 light-years to an alien planet, then travels another 8/2 light-years towards a distant star. What is the total distance covered by the rocket?

Llama 3 8B:

Reasoning: The rocket travels 11/18 light-years to the alien planet. To convert this to a decimal, we can divide the numerator by the denominator: 11 รท 18 = 0.6111... (repeating). So, the rocket travels 0.6111... light-years to the alien planet.

Then, the rocket travels another 8/2 light-years towards the distant star. To simplify this fraction, we can divide the numerator by the denominator: 8 รท 2 = 4. So, the rocket travels 4 light-years towards the distant star.

To find the total distance covered by the rocket, we add the distances traveled to the alien planet and towards the distant star: 0.6111... + 4 = 4.6111... (repeating).

### Answer: 4.6111... (repeating) light-years.

Expected answer: 83/18

Correct? No

๐Ÿ”— Problem

Problem: Johnathan needs 12/14 yards of one fabric to make a sleeping bag, and another 8/5 yards of a different fabric to create the liner. How many yards of fabric does he need in total to create his sleeping bag?

Llama 3 8B:

Reasoning: To find the total amount of fabric needed, we need to add the amount of fabric needed for the outer layer and the liner.

For the outer layer, Johnathan needs 12/14 yards of fabric. To simplify this fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 2.

12 รท 2 = 6
14 รท 2 = 7

So, the simplified fraction is 6/7 yards of fabric.

For the liner, Johnathan needs 8/5 yards of fabric. To simplify this fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 1.

8 รท 1 = 8
5 รท 1 = 5

So, the simplified fraction is 8/5 yards of fabric.

Now, we can add the simplified fractions to find the total amount of fabric needed:

6/7 + 8/5

To add these fractions, we need to find a common denominator, which is 35.

6/7 = (6 ร— 5) / (7 ร— 5) = 30/35
8/5 = (8 ร— 7) / (5 ร— 7) = 56/35

Now, we can add the fractions:

30/35 + 56/35 = 86/35

So, Johnathan needs 86/35 yards of fabric in total to create his sleeping bag.

### Answer: 86/35

Expected answer: 86/35

Correct? Yes

๐Ÿ”— Follow-up

Problem: After calculating the total fabrics Jonathan needed for the sleeping bag, he remembered that he had bought 17 yards of fabric in total. How many yards does he have left after using the necessary fabric to create his sleeping bag?

Llama 3 8B:

Reasoning: Jonathan needs 86/35 yards of fabric in total to create his sleeping bag. He has 17 yards of fabric in total. To find out how many yards he has left after using the necessary fabric, we need to subtract the amount of fabric needed from the total amount of fabric he has.

17 - 86/35

To subtract these values, we need to convert the mixed number 86/35 to an improper fraction:

86/35 = 246/35

Now, we can subtract:

17 - 246/35

To subtract these fractions, we need to find a common denominator, which is 35.

17 = 17 ร— 1 = 17/1

Now, we can subtract:

17/1 - 246/35

To subtract these fractions, we need to subtract the numerators and keep the same denominator:

17 - 246 = -229

So, the result is -229/35. Since we cannot have a negative amount of fabric, we can convert this mixed number to an improper fraction:

-229/35 = -229 รท 35 = -6 29/35

So, Jonathan has -6 29/35 yards of fabric left after using the necessary fabric to create his sleeping bag.

### Answer: -6 29/35

Expected answer: 509/35

Correct? No

๐Ÿ”— Follow-up

Problem: In the previous problem, Johnathan originally thought he needed 12/14 yards of one fabric to create the sleeping bag. But after rechecking his measurements, he realized he only needed 12/17 yards of that fabric. The liner fabric remained the same at 8/5 yards. How many total yards of fabric does he actually need to make the sleeping bag?

Llama 3 8B:

Reasoning: Johnathan originally thought he needed 12/14 yards of fabric, but now he realizes he only needs 12/17 yards. To find the difference, we can subtract the new amount from the original amount:

12/14 - 12/17

To subtract these fractions, we need to find a common denominator, which is 238.

12/14 = (12 ร— 17) / (14 ร— 17) = 204/238
12/17 = (12 ร— 14) / (17 ร— 14) = 168/238

Now, we can subtract the fractions:

204/238 - 168/238 = 36/238

So, Johnathan actually needs 36/238 yards less of the outer layer fabric.

The liner fabric remains the same at 8/5 yards.

To find the total amount of fabric needed, we can add the amount of fabric needed for the outer layer and the liner:

(12/17) + (8/5)

To add these fractions, we need to find a common denominator, which is 85.

12/17 = (12 ร— 5) / (17 ร— 5) = 60/85
8/5 = (8 ร— 17) / (5 ร— 17) = 136/85

Now, we can add the fractions:

60/85 + 136/85 = 196/85

So, Johnathan actually needs 196/85 yards of fabric in total to create his sleeping bag.

### Answer: 196/85

Expected answer: 196/85

Correct? Yes

๐Ÿ”— Problem

Problem: In a forest, there are 5/4 acres of pine trees and 1/2 acre of oak trees. What is the total acreage of pine and oak trees in the forest?

Llama 3 8B:

Reasoning: To find the total acreage, we need to add the acreage of pine trees and oak trees.

The acreage of pine trees is 5/4 acres, which can be converted to a decimal by dividing the numerator by the denominator: 5 รท 4 = 1.25 acres.

The acreage of oak trees is 1/2 acre, which can also be converted to a decimal: 1 รท 2 = 0.5 acres.

Now, we can add the two decimals: 1.25 + 0.5 = 1.75 acres.

### Answer: 1.75 acres

Expected answer: 7/4

Correct? No

๐Ÿ”— Problem

Problem: Jake has 12/7 of a yard of fabric. He finds another piece that measures 2/14 of a yard. If he combines both pieces, how much fabric does he have to make his shirt?

Llama 3 8B:

Reasoning: Jake has 12/7 of a yard of fabric initially.
He finds another piece that measures 2/14 of a yard.
To combine both pieces, we need to convert them to a common denominator, which is 14.
12/7 = 12*2/7*2 = 24/14
So, Jake has 24/14 + 2/14 = 26/14 of a yard of fabric.
### Answer: 26/14

Expected answer: 13/7

Correct? Yes

๐Ÿ”— Follow-up

Problem: After making his shirt, Jake realizes he needs to remove 4/16 of a yard of fabric for the shirt to fit perfectly. How much fabric will he have left after making this adjustment?

Llama 3 8B:

Reasoning: Jake has 26/14 of a yard of fabric initially.
He needs to remove 4/16 of a yard of fabric.
To find the common denominator, we multiply the numerator and denominator of 4/16 by 2, getting 8/32.
Now, we can subtract 8/32 from 26/14:
26/14 - 8/32 = 26/14 - 2/14 = 24/14
So, Jake will have 24/14 of a yard of fabric left after making the adjustment.
### Answer: 24/14

Expected answer: 45/28

Correct? No

๐Ÿ”— Follow-up

Problem: Let's say Jake originally had less fabric, only 12/6 yards instead of 12/7 yards. He still finds an additional piece of fabric that measures 2/14 of a yard. If he combines both these pieces now, then how much fabric does he have altogether for his shirt?

Llama 3 8B:

Reasoning: Jake has 12/6 = 2 of a yard of fabric initially.
He finds another piece that measures 2/14 of a yard.
To combine both pieces, we need to convert them to a common denominator, which is 14.
2 = 2*7/7 = 14/7
So, Jake has 14/7 + 2/14 = 14/7 + 1/7 = 15/7 of a yard of fabric.
### Answer: 15/7

Expected answer: 15/7

Correct? Yes

๐Ÿ”— Problem

Problem: At a park, a special tree produces on average 10/4 kilograms of fruit every summer. In the winter, it loses some of its fruit, amounting to 12/20 kg. What is the difference in kilograms of the fruit from summer to winter?

Llama 3 8B:

Reasoning: The tree produces 10/4 = 2.5 kg of fruit in the summer.
The tree loses 12/20 = 0.6 kg of fruit in the winter.
The difference in kilograms of fruit from summer to winter is 2.5 - 0.6 = 1.9 kg.
### Answer: 1.9

Expected answer: 19/10

Correct? Yes

๐Ÿ”— Follow-up

Problem: Continuing from the first scenario, suppose that this special tree only produces 10/4 kilograms of fruit in the summer, but it only loses 11/20 kilograms of its fruit in the winter, instead of 12/20 kilograms. What is now the difference in kilograms of the fruit from summer to winter?

Llama 3 8B:

Reasoning: The tree produces 10/4 = 2.5 kg of fruit in the summer.
The tree loses 11/20 = 0.55 kg of fruit in the winter.
The difference in kilograms of fruit from summer to winter is 2.5 - 0.55 = 1.95 kg.
### Answer: 1.95

Expected answer: 39/20

Correct? No

๐Ÿ”— Problem

Problem: A ballerina starts with a routine that lasts 13/5 minutes but decides to shorten it by 15/16 minutes. How long is her routine after shortening it?

Llama 3 8B:

Reasoning: The ballerina's original routine is 13/5 minutes long. To shorten it by 15/16 minutes, we need to subtract 15/16 from 13/5.

First, we need to find a common denominator for 5 and 16, which is 80. So, we can rewrite the fractions as:

13/5 = 104/80
15/16 = 75/80

Now, we can subtract:

104/80 - 75/80 = 29/80

So, the ballerina's routine is shortened by 29/80 minutes. To find the new length of the routine, we subtract this from the original length:

13/5 - 29/80 = 13/5 - 29/80 = 104/80 - 29/80 = 75/80 = 3/4

The ballerina's routine is now 3/4 minutes long.

### Answer: 3/4

Expected answer: 133/80

Correct? No

๐Ÿ”— Problem

Problem: Miss Daisy has 19/6 kg of fertilizers for her flowers. If she uses 17/20 kg on her roses, how much fertilizers does she have left to use on her other flowers?

Llama 3 8B:

Reasoning: Miss Daisy has 19/6 kg of fertilizers initially.
She uses 17/20 kg on her roses. To find the fraction of kg used, we need to find the common denominator, which is 60. So, 17/20 = 51/60 and 19/6 = 95/60.
She uses 51/60 kg on her roses, leaving her with 95/60 - 51/60 = 44/60 kg.
### Answer: 44/60 kg

Expected answer: 139/60

Correct? No

๐Ÿ”— Problem

Problem: Scientists have discovered that the moon is slowly moving away from Earth. If the distance increases by 4/16 meters every year, and unexpectedly there was an additional increase of 20/6 meters this year, what is the total change in distance this year?

Llama 3 8B:

Reasoning: The distance increases by 4/16 meters every year. This means that the distance increases by 1/4 meters every year. This year, there was an additional increase of 20/6 meters. To find the total change in distance, we add the two increases together: 1/4 + 20/6 = 3/12 + 20/6 = 1/4 + 10/6 = 1/4 + 5/3 = 7/12.
### Answer: 7/12

Expected answer: 43/12

Correct? No

๐Ÿ”— Problem

Problem: Bob has 11/3 dollars in one pocket of his wallet and 12/19 dollars in another pocket. How much money does he have in total in his wallet?

Llama 3 8B:

Reasoning: To find the total amount of money Bob has, we need to add the amount in each pocket. First, we need to convert the fractions to decimals: 11/3 = 3.67 and 12/19 = 0.63.
Then, we add the two amounts: 3.67 + 0.63 = 4.30.
### Answer: 4.30

Expected answer: 245/57

Correct? No

๐Ÿ”— Problem

Problem: In an ocean, a shark swims a distance of 5/5 miles in the morning and adds an additional 12/18 miles in the afternoon. How many miles in total did the shark swim that day?

Llama 3 8B:

Reasoning: The shark swims 5/5 miles in the morning, which is equal to 1 mile. Then, it swims an additional 12/18 miles in the afternoon. To find the value of 12/18, we can simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 6. This gives us 2/3 miles. Therefore, the shark swims a total of 1 + 2/3 = 5/3 miles.
### Answer: 5/3

Expected answer: 5/3

Correct? Yes

๐Ÿ”— Follow-up

Problem: Following the previous problem, if the shark decides to swim an additional 18/9 miles in the evening, what is the total distance the shark would have swam by the end of the day?

Llama 3 8B:

Reasoning: The shark already swam 5/3 miles in the morning and afternoon. To find the value of 18/9, we can simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 9. This gives us 2 miles. Therefore, the shark swims an additional 2 miles in the evening, making the total distance swum by the end of the day 5/3 + 2 = 11/3 miles.
### Answer: 11/3

Expected answer: 11/3

Correct? Yes

๐Ÿ”— Follow-up

Problem: Continuing from the last problem, suppose the shark had only swam 5/12 miles in the morning instead of 5/5 miles, but still swam the additional 12/18 miles in the afternoon. How many miles would the shark have swam in the morning and afternoon combined?

Llama 3 8B:

Reasoning: The shark swims 5/12 miles in the morning. Then, it swims an additional 12/18 miles in the afternoon. To find the value of 12/18, we can simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 6. This gives us 2/3 miles. Therefore, the shark swims a total of 5/12 + 2/3 = 5/12 + 4/12 = 9/12 = 3/4 miles.
### Answer: 3/4

Expected answer: 13/12

Correct? No

๐Ÿ”— Problem

Problem: Jim types 20 words in 16 seconds and Mary types 9 words in 4 seconds. How many words per second do Jim and Mary type in total?

Llama 3 8B:

Reasoning: Jim types 20 words in 16 seconds, so his rate is 20/16 = 5/4 = 1.25 words per second.
Mary types 9 words in 4 seconds, so her rate is 9/4 = 2.25 words per second.
The total rate is 1.25 + 2.25 = 3.5 words per second.
### Answer: 3.5

Expected answer: 7/2

Correct? Yes

๐Ÿ”— Follow-up

Problem: After typing together, Jim and Mary decide to slow down their pace and reduce their combined typing speed by 2 words every 11 seconds. What becomes their new combined typing speed?

Llama 3 8B:

Reasoning: Initially, Jim and Mary type at a combined rate of 3.5 words per second.
They reduce their combined typing speed by 2 words every 11 seconds, which means they reduce their rate by 2/11 words per second.
To find their new combined typing speed, subtract this reduction from their initial rate: 3.5 - (2/11) = 3.5 - 0.1818... = 3.3182... โ‰ˆ 3.32 words per second.
### Answer: 3.32

Expected answer: 73/22

Correct? No

๐Ÿ”— Problem

Problem: Max rode his scooter for 9/7 miles in the morning and then 1/9 miles less in the afternoon. How many miles did he ride his scooter in the afternoon?

Llama 3 8B:

Reasoning: Let's first find the distance Max rode in the afternoon. He rode 1/9 miles less than in the morning, so we can set up an equation:

Afternoon distance = Morning distance - 1/9

We know the morning distance is 9/7 miles, so we can substitute:

Afternoon distance = (9/7) - 1/9

To simplify the fraction, we can find a common denominator, which is 63:

Afternoon distance = (63/7) - (7/9)
= (63 - 7)/9
= 56/9

So Max rode his scooter 56/9 miles in the afternoon.

### Answer: 56/9

Expected answer: 74/63

Correct? No

๐Ÿ”— Problem

Problem: At a circus, a clown rode a unicycle for 9/8 hours. After a short break, she juggled for another 2/10 hours. How many hours in total did she perform?

Llama 3 8B:

Reasoning: To convert the fractions to decimals, we can divide the numerator by the denominator: 9/8 = 1.125 and 2/10 = 0.2.
The clown rode the unicycle for 1.125 hours and juggled for 0.2 hours.
To find the total time, we add the two times: 1.125 + 0.2 = 1.325 hours.
### Answer: 1.325

Expected answer: 53/40

Correct? Yes

๐Ÿ”— Follow-up

Problem: Following her performances, the clown took a total break of 13/5 hours. How many hours remained after her performance time is subtracted from her total break time?

Llama 3 8B:

Reasoning: The clown took a total break of 13/5 hours. To convert the fraction to a decimal, we can divide the numerator by the denominator: 13/5 = 2.6 hours.
The clown performed for 1.325 hours. To find the remaining break time, we subtract the performance time from the total break time: 2.6 - 1.325 = 1.275 hours.
### Answer: 1.275

Expected answer: 51/40

Correct? No

๐Ÿ”— Follow-up

Problem: In the previous problem, the clown juggled for 2/10 hours. Now suppose that she actually juggled for 9/10 hours instead. In this scenario, how many hours in total did she perform, if she still rode the unicycle for 9/8 hours?

Llama 3 8B:

Reasoning: The clown rode the unicycle for 9/8 = 1.125 hours.
She juggled for 9/10 = 0.9 hours.
To find the total time, we add the two times: 1.125 + 0.9 = 1.925 hours.
### Answer: 1.925

Expected answer: 81/40

Correct? No

๐Ÿ”— Problem

Problem: If Timmy dumps 7/2 kg of sand into his sandbox and later adds another 1/2 kg, how much sand is now in his sandbox?

Llama 3 8B:

Reasoning: Timmy initially dumps 7/2 kg of sand into his sandbox. To find the initial amount of sand, we can multiply 7 by 1/2, which gives us 3.5 kg.
Later, Timmy adds another 1/2 kg of sand. To find the total amount of sand, we can add the initial amount to the additional amount: 3.5 + 1/2 = 4.
### Answer: 4 kg

Expected answer: 4

Correct? Yes

๐Ÿ”— Follow-up

Problem: Following the last scenario, if Timmy later dumps another 16/3 kg of sand into the sandbox, how much sand does the sandbox contain now?

Llama 3 8B:

Reasoning: Timmy already has 4 kg of sand in the sandbox. He adds another 16/3 kg of sand. To find the total amount of sand, we can add the initial amount to the additional amount: 4 + 16/3 = 4 + 5.33 (approximately) = 9.33 kg.
### Answer: 9.33 kg

Expected answer: 28/3

Correct? No

๐Ÿ”— Follow-up

Problem: In the previous sandbox problem, if Timmy initially dumped 7/2 kg of sand into his sandbox but this time around, he decided to add only 1/20 kg of sand to it instead, how much sand is now in his sandbox?

Llama 3 8B:

Reasoning: Timmy initially dumps 7/2 kg of sand into his sandbox. To find the initial amount of sand, we can multiply 7 by 1/2, which gives us 3.5 kg.
Later, Timmy adds another 1/20 kg of sand. To find the total amount of sand, we can add the initial amount to the additional amount: 3.5 + 1/20 = 3.5 + 0.05 = 3.55.
### Answer: 3.55 kg

Expected answer: 71/20

Correct? No

๐Ÿ”— Problem

Problem: A wizard brewed a potion that required 18/8 ounces of moon roots and 11/7 ounces of stardust. How many ounces of ingredients did the wizard use in total to prepare the potion?

Llama 3 8B:

Reasoning: To find the total amount of moon roots used, we can multiply the number of ounces required by the number of times it is used: 18/8 * 1 = 9/4 ounces.
To find the total amount of stardust used, we can multiply the number of ounces required by the number of times it is used: 11/7 * 1 = 11/7 ounces.
To find the total amount of ingredients used, we can add the amount of moon roots and stardust: 9/4 + 11/7 = 33/28 + 22/28 = 55/28 ounces.
### Answer: 55/28 ounces.

Expected answer: 107/28

Correct? No

๐Ÿ”— Problem

Problem: An alien UFO traveled 3/10 of a mile, then immediately traveled an additional 16/20 of a mile. How many miles did the UFO travel in total?

Llama 3 8B:

Reasoning: The UFO traveled 3/10 of a mile, which can be converted to a decimal by dividing the numerator by the denominator: 3 รท 10 = 0.3 miles.
Then, it traveled an additional 16/20 of a mile, which can be converted to a decimal by dividing the numerator by the denominator: 16 รท 20 = 0.8 miles.
To find the total distance traveled, add the two distances: 0.3 + 0.8 = 1.1 miles.
### Answer: 1.1

Expected answer: 11/10

Correct? Yes

๐Ÿ”— Follow-up

Problem: Originally, the alien UFO traveled 3/10 of a mile, then an additional 16/20 of a mile. But what if, instead, the UFO initially only traveled 3/10 of a mile, before traveling an extra 16/18 of a mile. How much distance did UFO cover in total this time?

Llama 3 8B:

Reasoning: The UFO initially traveled 3/10 of a mile, which can be converted to a decimal by dividing the numerator by the denominator: 3 รท 10 = 0.3 miles.
Then, it traveled an additional 16/18 of a mile, which can be converted to a decimal by dividing the numerator by the denominator: 16 รท 18 = 0.89 (approximately) miles.
To find the total distance traveled, add the two distances: 0.3 + 0.89 = 1.19 miles.
### Answer: 1.19

Expected answer: 107/90

Correct? No

๐Ÿ”— Problem

Problem: A chair manufacturing firm makes 4/14 of a chair every hour with one machine, and another machine makes 20/4 chairs. How many chairs are made by both machines in one hour?

Llama 3 8B:

Reasoning: The first machine makes 4/14 of a chair every hour, which is equivalent to 4/14 * 1 = 4/14 chairs.
The second machine makes 20/4 chairs every hour.
Total chairs made by both machines in one hour = 4/14 + 20/4 = 4/14 * 1 + 20/4 * 1 = 4/14 + 5 = 9/14 + 5 = 9/14 + 5*14/14 = 9/14 + 70/14 = 79/14 = 5 11/14.
### Answer: 5 11/14

Expected answer: 37/7

Correct? No

๐Ÿ”— Problem

Problem: A blue shark swam for 2/4 miles and a hammerhead shark swam for 7/10 miles. How many miles did they swim together?

Llama 3 8B:

Reasoning: To find the total distance swum, we need to add the distances swum by each shark.

The blue shark swam 2/4 miles, which can be simplified to 1/2 miles.

The hammerhead shark swam 7/10 miles.

To add these distances, we need to find a common denominator, which is 20. So, we can rewrite the distances as:

Blue shark: 10/20 miles
Hammerhead shark: 14/20 miles

Now, we can add the distances:

10/20 + 14/20 = 24/20

This can be simplified to 6/5 miles.

### Answer: 6/5 miles

Expected answer: 6/5

Correct? Yes

๐Ÿ”— Follow-up

Problem: After the blue shark and the hammerhead shark swam their respective distances, a great white shark joined them and swam 9/14 miles. What is the total combined distance that the three sharks swam together?

Llama 3 8B:

Reasoning: We already found the total distance swum by the blue shark and the hammerhead shark, which is 6/5 miles.

The great white shark swam 9/14 miles.

To add this distance to the total, we need to find a common denominator, which is 70. So, we can rewrite the distances as:

Blue shark and hammerhead shark: 42/70 miles
Great white shark: 63/70 miles

Now, we can add the distances:

42/70 + 63/70 = 105/70

This can be simplified to 21/14 miles.

### Answer: 21/14 miles

Expected answer: 129/70

Correct? No

๐Ÿ”— Follow-up

Problem: In the previous situation, let's imagine that the blue shark actually swam for only 2/4 miles and the hammerhead shark swam for 7/11 miles. In this case, how many miles did the blue and hammerhead sharks swim in total?

Llama 3 8B:

Reasoning: To find the total distance swum, we need to add the distances swum by each shark.

The blue shark swam 2/4 miles, which can be simplified to 1/2 miles.

The hammerhead shark swam 7/11 miles.

To add these distances, we need to find a common denominator, which is 44. So, we can rewrite the distances as:

Blue shark: 22/44 miles
Hammerhead shark: 28/44 miles

Now, we can add the distances:

22/44 + 28/44 = 50/44

This can be simplified to 25/22 miles.

### Answer: 25/22 miles

Expected answer: 25/22

Correct? Yes

๐Ÿ”— Problem

Problem: Lisa has two milk bottles. One bottle has 8/18 gallons of milk while the other bottle has 18/8 gallons. How much milk does Lisa have in total?

Llama 3 8B:

Reasoning: The first bottle has 8/18 gallons of milk, which can be simplified to 4/9 gallons. The second bottle has 18/8 gallons, which can be simplified to 9/4 gallons. To find the total amount of milk, we can add the two fractions:

(4/9) + (9/4) = ?

To add these fractions, we need a common denominator, which is 36. So, we can convert both fractions to have a denominator of 36:

(4/9) = (16/36)
(9/4) = (27/36)

Now we can add:

(16/36) + (27/36) = 43/36

So, Lisa has 43/36 gallons of milk in total.

### Answer: 43/36

Expected answer: 97/36

Correct? No

๐Ÿ”— Problem

Problem: A tree grows 1/10 of its height every month. This month, it additionally has grown 12/6 feet due to a fertilizer being applied. How much has the tree grown in height this month?

Llama 3 8B:

Reasoning: The tree grows 1/10 of its height every month. This means that the tree grows 1/10 of its current height, not a fixed amount.
The tree has grown 12/6 = 2 feet due to the fertilizer. This is an additional growth, not a part of the regular monthly growth.
### Answer: 2 feet.

Expected answer: 21/10

Correct? No

๐Ÿ”— Problem

Problem: John sets up a large tent that occupies an area of 13/11 acres. Later in the day, he decides to set up another smaller tent which occupies an area of 8/20 acres. What is the total area occupied by both tents?

Llama 3 8B:

Reasoning: The area occupied by the large tent is 13/11 acres. To find the decimal equivalent, we can divide the numerator by the denominator: 13 รท 11 = 1.18.
The area occupied by the smaller tent is 8/20 acres. To find the decimal equivalent, we can divide the numerator by the denominator: 8 รท 20 = 0.4.
The total area occupied by both tents is the sum of the areas: 1.18 + 0.4 = 1.58.
### Answer: 1.58

Expected answer: 87/55

Correct? No

๐Ÿ”— Problem

Problem: Captain Jack has a treasure map that shows the treasure is at a location that is (17 / 20) km to the East and then (15 / 3) km to the North from their starting point. How far must they travel in total to reach the treasure?

Llama 3 8B:

Reasoning: To find the total distance, we need to find the distance from the starting point to the treasure. The distance to the East is (17 / 20) km, and the distance to the North is (15 / 3) km. We can use the Pythagorean theorem to find the total distance:

โˆš((17/20)^2 + (15/3)^2) = โˆš((289/400) + (225/9)) = โˆš((289+225)/400) = โˆš(514/400) = โˆš(257/200) = โˆš(1.2857) โ‰ˆ 1.13 km

So, Captain Jack must travel approximately 1.13 km to reach the treasure.

### Answer: โ‰ˆ 1.13 km

Expected answer: 117/20

Correct? No

๐Ÿ”— Problem

Problem: At a campfire, Sarah collected 11/20 of a pound of firewood and Alex collected 9/7 pounds. How many pounds of firewood did they collect in total?

Llama 3 8B:

Reasoning: To find the total amount of firewood collected, we need to add the amounts collected by Sarah and Alex.

First, we need to convert both amounts to a common denominator, which is 140 (the least common multiple of 20 and 7).

Sarah collected 11/20 of a pound, which is equivalent to 77/140 pounds.

Alex collected 9/7 pounds, which is equivalent to 108/140 pounds.

Now, we can add the two amounts:

77/140 + 108/140 = 185/140

So, Sarah and Alex collected a total of 185/140 pounds of firewood.

### Answer: 185/140

Expected answer: 257/140

Correct? No

๐Ÿ”— Problem

Problem: Captain Bill sailed 19/5 miles north, before changing track and sailing an additional 12/15 miles north. How many miles north did Captain Bill sail in total?

Llama 3 8B:

Reasoning: Captain Bill sailed 19/5 = 3.8 miles north initially.
He then sailed an additional 12/15 = 0.8 miles north.
The total distance sailed north is 3.8 + 0.8 = 4.6 miles.
### Answer: 4.6

Expected answer: 23/5

Correct? Yes

๐Ÿ”— Follow-up

Problem: After traveling north for a total distance, Captain Bill decided to backtrack and went 20/17 miles south. How many miles away from the original starting point was Captain Bill located then?

Llama 3 8B:

Reasoning: Captain Bill traveled 4.6 miles north initially, so he was 4.6 miles away from the starting point.
Then, he traveled 20/17 = 1.17647... miles south.
The total distance traveled south is 4.6 - 1.17647... = 3.42353... miles.
### Answer: 3.42353...

Expected answer: 291/85

Correct? No

๐Ÿ”— Follow-up

Problem: After reconsidering the calculations, Captain Bill realized that he actually sailed 19/18 miles north initially instead of 19/5 miles before changing track and sailing an additional 12/15 miles north. In light of this new information, how many miles north did Captain Bill sail in total now?

Llama 3 8B:

Reasoning: Captain Bill sailed 19/18 = 1.06 miles north initially.
He then sailed an additional 12/15 = 0.8 miles north.
The total distance sailed north is 1.06 + 0.8 = 1.86 miles.
### Answer: 1.86

Expected answer: 167/90

Correct? No

๐Ÿ”— Problem

Problem: A restaurant uses 19/17 pounds of ham and 9/4 pounds of turkey for their signature sandwich. What is the total weight of the two types of meat per sandwich?

Llama 3 8B:

Reasoning: To find the total weight of the two types of meat per sandwich, we need to add the weight of ham and turkey.

First, we need to find the common denominator of the fractions. The least common multiple of 17 and 4 is 68. So, we can convert both fractions to have a denominator of 68:

Ham: 19/17 = (19 ร— 4)/(17 ร— 4) = 76/68
Turkey: 9/4 = (9 ร— 17)/(4 ร— 17) = 153/68

Now, we can add the weights:

Total weight = 76/68 + 153/68 = (76 + 153)/68 = 229/68

### Answer: 229/68

Expected answer: 229/68

Correct? Yes

๐Ÿ”— Follow-up

Problem: After making their signature sandwich, the restaurant staff find that they have used 13/9 pounds more meat than they intended to. What is the weight of the meat that should have been in the sandwich?

Llama 3 8B:

Reasoning: Let's first find the total weight of the meat used in the sandwich. We already calculated that:

Total weight = 229/68 pounds

Since they used 13/9 pounds more meat than intended, the intended weight is:

Intended weight = Total weight - 13/9
= 229/68 - 13/9
= (229 ร— 9 - 13 ร— 68) / (68 ร— 9)
= (2057 - 884) / 612
= 1173 / 612
= 193/102

### Answer: 193/102

Expected answer: 1177/612

Correct? No

๐Ÿ”— Follow-up

Problem: The restaurant realized that the amount of the turkey meat in their signature sandwich should have been 6/4 pounds, not 9/4 pounds. What should be the total weight of the ham and turkey meat in the sandwich, according to this correction?

Llama 3 8B:

Reasoning: Since the amount of turkey meat was incorrect, we need to recalculate the total weight of the ham and turkey meat.

First, we need to find the correct weight of turkey meat:

6/4 pounds of turkey meat

Now, we can add the weight of ham and turkey:

Ham: 19/17 pounds = (19 ร— 4)/(17 ร— 4) = 76/68 pounds
Turkey: 6/4 pounds = (6 ร— 17)/(4 ร— 17) = 102/68 pounds

Total weight = 76/68 + 102/68 = (76 + 102)/68 = 178/68

### Answer: 178/68

Expected answer: 89/34

Correct? Yes

๐Ÿ”— Problem

Problem: Lucy has a sleeping bag that is 18/19 meter long. She got an extension for her sleeping bag which made it 8/11 meter longer. What's the total length of the sleeping bag now?

Llama 3 8B:

Reasoning: The original length of the sleeping bag is 18/19 meters. The extension is 8/11 meters. To find the total length, we need to add the original length and the extension.

First, we need to convert the extension to the same denominator as the original length. To do this, we can multiply the numerator and denominator of the extension by 19:

8/11 = (8 ร— 19)/(11 ร— 19) = 152/209

Now we can add the original length and the extension:

18/19 + 152/209 = (18 ร— 209) + (152 ร— 19) / (19 ร— 209) = 3756 + 2888 / 3611 = 6644/3611

### Answer: 6644/3611

Expected answer: 350/209

Correct? No

๐Ÿ”— Problem

Problem: Sarah pours 10/13 gallon of water into a container. Then she adds another 8/2 gallons of water into it. How many total gallons of water are there in the container now?

Llama 3 8B:

Reasoning: Sarah pours 10/13 gallon of water initially.
Then she adds another 8/2 = 4 gallons of water.
Total gallons of water = 10/13 + 4 = 10/13 + 40/13 = 50/13 = 3 7/13.
### Answer: 3 7/13

Expected answer: 62/13

Correct? No

๐Ÿ”— Problem

Problem: Mandy has 9/2 KGs of apples. She uses 1/4 KG of them to make apple pie. How many KGs of apples does she have left?

Llama 3 8B:

Reasoning: Mandy has 9/2 = 4.5 KGs of apples initially.
She uses 1/4 = 0.25 KGs of apples to make apple pie.
So, she has 4.5 - 0.25 = 4.25 KGs of apples left.
### Answer: 4.25

Expected answer: 17/4

Correct? Yes

๐Ÿ”— Follow-up

Problem: Mandy has 9/2 KGs of apples. She uses 1/4 KG of them to make apple pie. Afterwards, she finds 3/19 more KGs of apples in her refrigerator. How many KGs of apples does she have total now?

Llama 3 8B:

Reasoning: Mandy has 9/2 = 4.5 KGs of apples initially.
She uses 1/4 = 0.25 KGs of apples to make apple pie.
So, she has 4.5 - 0.25 = 4.25 KGs of apples left.
Then, she finds 3/19 = 0.1584 KGs of apples in her refrigerator.
So, she has 4.25 + 0.1584 = 4.4084 KGs of apples now.
### Answer: 4.4084

Expected answer: 335/76

Correct? No

๐Ÿ”— Follow-up

Problem: In the scenario where Mandy initially had 9/7 KGs of apples instead, and she still uses 1/4 KG of them for her apple pie, how many KGs of apples would she have left?

Llama 3 8B:

Reasoning: Mandy has 9/7 = 1.2857 (approximately) KGs of apples initially.
She uses 1/4 = 0.25 KGs of apples to make apple pie.
So, she has 1.2857 - 0.25 = 1.0357 (approximately) KGs of apples left.
### Answer: 1.0357 (approximately)

Expected answer: 29/28

Correct? No

๐Ÿ”— Problem

Problem: John spends 12/7 hours fixing a watch and then spends an additional 3/9 hours polishing it. How many hours in total did he spent working on the watch?

Llama 3 8B:

Reasoning: John spent 12/7 hours fixing the watch. To convert this to a decimal, we can divide the numerator by the denominator: 12 รท 7 = 1.714285714... (rounded to 1.71). So, John spent approximately 1.71 hours fixing the watch.

John then spent an additional 3/9 hours polishing the watch. To convert this to a decimal, we can divide the numerator by the denominator: 3 รท 9 = 0.333333333... (rounded to 0.33). So, John spent approximately 0.33 hours polishing the watch.

In total, John spent 1.71 + 0.33 = 2.04 hours working on the watch.

### Answer: 2.04

Expected answer: 43/21

Correct? No

๐Ÿ”— Problem

Problem: Peggy the Penguin was swimming and had traveled for 5/4 miles when she turned around to go back to her family. She swam back for 1/12 miles before deciding to rest. How many miles is Peggy from her family?

Llama 3 8B:

Reasoning: Peggy swam 5/4 miles initially, then swam 1/12 miles back. So, she is 5/4 - 1/12 = 11/12 miles away from her family.
### Answer: 11/12

Expected answer: 7/6

Correct? No

๐Ÿ”— Problem

Problem: A farmer has a fields where he grows wheat. One part of the field is 4 acres and another part is 11/12 of an acre. How many acres in total does he use to grow wheat?

Llama 3 8B:

Reasoning: The farmer has a field that is 4 acres, and another part that is 11/12 of an acre. To find the total area, we need to convert the fraction to a decimal: 11/12 = 0.9167 (approximately).

Then, we add the two areas together: 4 acres + 0.9167 acres = 4.9167 acres

### Answer: 4.9167 acres

Expected answer: 59/12

Correct? No

๐Ÿ”— Problem

Problem: If a dress designer used 11/4 yards of red fabric, and then added 5/17 yards of blue fabric, how many yards of fabric did she use in total?

Llama 3 8B:

Reasoning: To find the total amount of fabric used, we need to add the amount of red fabric and the amount of blue fabric.

First, we can simplify the fraction of red fabric by dividing both the numerator and the denominator by their greatest common divisor, which is 1:

11/4 = 11/4

Next, we can add the simplified fraction of red fabric and the fraction of blue fabric:

11/4 + 5/17 = ?

To add these fractions, we need to find a common denominator, which is 68 (the least common multiple of 4 and 17). Then, we can convert both fractions to have a denominator of 68:

11/4 = 187/68
5/17 = 130/68

Now we can add the fractions:

187/68 + 130/68 = 317/68

So, the total amount of fabric used is 317/68 yards.

### Answer: 317/68

Expected answer: 207/68

Correct? No

๐Ÿ”— Problem

Problem: Jacob has 11/2 feet long guitar wire. If he uses 5/16 feet of it to fix a guitar, how much wire is remaining?

Llama 3 8B:

Reasoning: Jacob has 11/2 = 5.5 feet of guitar wire initially.
He uses 5/16 = 0.3125 feet of it to fix a guitar.
So, the remaining wire is 5.5 - 0.3125 = 5.1875 feet.
### Answer: 5.1875

Expected answer: 83/16

Correct? Yes

๐Ÿ”— Follow-up

Problem: Jacob bought another 3/4 feet of wire in addition to what was left over from before. How much guitar wire does he have in total now?

Llama 3 8B:

Reasoning: Jacob had 5.1875 feet of wire remaining initially.
He bought 3/4 = 0.75 feet of wire.
So, the total wire he has now is 5.1875 + 0.75 = 5.9375 feet.
### Answer: 5.9375

Expected answer: 95/16

Correct? No

๐Ÿ”— Follow-up

Problem: In the previous scenario, what if Jacob initially had 11/2 feet long guitar wire but ended up using 9/16 feet to fix the guitar instead of 5/16 feet. How much guitar wire would be remaining in that case?

Llama 3 8B:

Reasoning: Jacob has 11/2 = 5.5 feet of guitar wire initially.
He uses 9/16 = 0.5625 feet of it to fix a guitar.
So, the remaining wire is 5.5 - 0.5625 = 5.0375 feet.
### Answer: 5.0375

Expected answer: 79/16

Correct? No

๐Ÿ”— Problem

Problem: Samantha has a 4 fluid ounce tube of toothpaste. In one week, she uses 17/14 fluid ounces. How much toothpaste does she have left after that week?

Llama 3 8B:

Reasoning: Samantha has 4 fluid ounces initially.
She uses 17/14 fluid ounces in one week.
To find the amount used, we can convert the fraction to a decimal: 17/14 = 1.214285714... (repeating decimal).
So, she uses approximately 1.214 fluid ounces.
To find the amount left, we subtract the amount used from the initial amount: 4 - 1.214 = 2.786 fluid ounces.
### Answer: 2.786 fluid ounces.

Expected answer: 39/14

Correct? No

๐Ÿ”— Problem

Problem: Maria has 12 candies. She gives each of her 6 friends an equal amount of candies. Maria also has 20 stickers and she gives each of her 20 friends a sticker. How many candies and stickers does each friend get in total?

Llama 3 8B:

Reasoning: Maria gives each of her 6 friends an equal amount of candies, so each friend gets 12/6 = 2 candies.
Maria gives each of her 20 friends a sticker, so each friend gets 1 sticker.
Each friend gets 2 candies + 1 sticker = 3 candies and stickers in total.
### Answer: 3

Expected answer: 3

Correct? Yes

๐Ÿ”— Follow-up

Problem: Maria initially had 12 candies and 20 stickers. Instead of having 6 friends, let's say she had 13 friends now. If she shares the candies among her 6 friends and the stickers among her 13 friends equally, how many candies and stickers does each friend get in total?

Llama 3 8B:

Reasoning: Maria gives each of her 6 friends an equal amount of candies, so each friend gets 12/6 = 2 candies.
Maria gives each of her 13 friends a sticker, so each friend gets 20/13 = 1.5384615384615384 (approximately 1 with a remainder) sticker.
Each friend gets 2 candies + 1.5384615384615384 stickers = 2.5384615384615384 (approximately 2 with a remainder) candies and stickers in total.
### Answer: approximately 2 with a remainder

Expected answer: 46/13

Correct? No

๐Ÿ”— Problem

Problem: During a rainy day, the first rainfall lasted for 4/13 hours, and the next rainfall was a little longer and lasted for 11/5 hours. How many hours did it rain in total?

Llama 3 8B:

Reasoning: The first rainfall lasted for 4/13 hours, and the next rainfall was a little longer and lasted for 11/5 hours. To find the total time it rained, we add the two times together:

4/13 + 11/5 = (4 ร— 5) / (13 ร— 5) + 11/5 = 20/65 + 11/5 = (20 + 33) / 65 = 53/65

So, it rained for 53/65 hours in total.

### Answer: 53/65

Expected answer: 163/65

Correct? No

๐Ÿ”— Problem

Problem: Jane cuts 10/12 yards of fabric from a blanket. Then, she cuts an additional 10/10 yard. How many yards of fabric has she cut from the blanket in total?

Llama 3 8B:

Reasoning: Jane cuts 10/12 yards of fabric initially, which is equivalent to 5/6 yards (since 10/12 = 5/6).
Then, she cuts an additional 10/10 yard, which is equal to 1 yard.
In total, Jane cuts 5/6 + 1 = 11/6 yards of fabric.
### Answer: 11/6

Expected answer: 11/6

Correct? Yes

๐Ÿ”— Follow-up

Problem: After cutting 10/12 yards and 10/10 yard from the blanket, Jane decides to cut an additional 4/12 yard. Now, how many yards of fabric has she cut from the blanket in total?

Llama 3 8B:

Reasoning: Jane has already cut 5/6 yards (10/12) and 1 yard (10/10), which is a total of 5/6 + 1 = 11/6 yards.
She then cuts an additional 4/12 yard, which is equivalent to 1/3 yard (since 4/12 = 1/3).
In total, Jane has cut 11/6 + 1/3 = 13/6 yards of fabric.
### Answer: 13/6

Expected answer: 13/6

Correct? Yes

๐Ÿ”— Follow-up

Problem: Originally, Jane cut 10/12 yard and then 10/10 yard from the blanket. However, consider if Jane had cut 11/12 yard instead of 10/12 yard at first, and then again cut 10/10 yard. How many yards of fabric would she have cut from the blanket now in this case?

Llama 3 8B:

Reasoning: If Jane cuts 11/12 yards initially, she would have cut 11/12 yards.
Then, she cuts an additional 10/10 yard, which is equal to 1 yard.
In total, Jane would have cut 11/12 + 1 = 13/12 yards of fabric.
### Answer: 13/12

Expected answer: 23/12

Correct? No

๐Ÿ”— Problem

Problem: A fairy sprinkles 11/12 oz of magic dust over an enchanted field. She then sprinkles an additional 9/10 oz of dust over a grove of enchanted apple trees. What is the total amount of magic dust the fairy used?

Llama 3 8B:

Reasoning: The fairy sprinkles 11/12 oz of magic dust over the enchanted field. To find the decimal equivalent, we can divide the numerator by the denominator: 11 รท 12 = 0.9166666666666667 oz. Then, she sprinkles an additional 9/10 oz of dust over the grove of enchanted apple trees. To find the decimal equivalent, we can divide the numerator by the denominator: 9 รท 10 = 0.9 oz. The total amount of magic dust the fairy used is the sum of the amounts she used for the field and the trees: 0.9166666666666667 oz + 0.9 oz = 1.8166666666666667 oz.
### Answer: 1.8166666666666667 oz.

Expected answer: 109/60

Correct? No

๐Ÿ”— Problem

Problem: A word game assigns 3/11 of a point for each vowel used and 8/10 of a point for each consonant. If you use 1 vowel and 1 consonant, what will your score be?

Llama 3 8B:

Reasoning: For each vowel, you get 3/11 of a point. Since you use 1 vowel, you get 3/11 of a point.
For each consonant, you get 8/10 of a point. Since you use 1 consonant, you get 8/10 of a point.
Total score = 3/11 + 8/10 = <<(3/11) + (8/10)>>= <<(30+88)/110>>= <<118/110>>= 1 8/110.
### Answer: 1 8/110.

Expected answer: 59/55

Correct? Yes

๐Ÿ”— Follow-up

Problem: After earning points from using 1 vowel and 1 consonant, you played another round and scored 19/7 points. What is your total score now?

Llama 3 8B:

Reasoning: Your initial score was 1 8/110.
You scored 19/7 points in the next round.
Total score = 1 8/110 + 19/7 = <<(110+2097)/1107>>= <<2207/1107>>= 2 0/7.
### Answer: 2 0/7.

Expected answer: 1458/385

Correct? No

๐Ÿ”— Follow-up

Problem: In the same word game, now we assign 5/11 of a point for each vowel used instead of 3/11, while the points given for each consonant remain 8/10. If you use 1 vowel and 1 consonant with this new scoring system, what will your score be?

Llama 3 8B:

Reasoning: For each vowel, you get 5/11 of a point. Since you use 1 vowel, you get 5/11 of a point.
For each consonant, you get 8/10 of a point. Since you use 1 consonant, you get 8/10 of a point.
Total score = 5/11 + 8/10 = <<(5/11) + (8/10)>>= <<(50+88)/110>>= <<138/110>>= 1 28/110.
### Answer: 1 28/110.

Expected answer: 69/55

Correct? Yes

๐Ÿ”— Problem

Problem: You are writing a letter that is 4/1 pages long. You remove 14/9 pages from it. How many pages is the letter now?

Llama 3 8B:

Reasoning: The original letter is 4/1 pages long, which is equivalent to 4 + 1/4 = 4.25 pages. After removing 14/9 pages, the letter is left with 4.25 - 14/9 pages.

To find the decimal equivalent of 14/9, we can divide the numerator by the denominator: 14 รท 9 = 1.555...

So, the letter is left with 4.25 - 1.555... = 2.695... pages.

Since we can't have a fraction of a page, we round down to the nearest whole number, which is 2 pages.

### Answer: 2

Expected answer: 22/9

Correct? No

๐Ÿ”— Problem

Problem: Anne painted 16/20 of a table, and then Bob painted an additional 5/20 of the table. How much of the table has been painted in total?

Llama 3 8B:

Reasoning: Anne painted 16/20 of the table, which is equal to 0.8 or 80%.
Bob painted an additional 5/20 of the table, which is equal to 0.25 or 25%.
The total amount of the table that has been painted is the sum of the amounts painted by Anne and Bob, which is 80% + 25% = 105%.
### Answer: 105%

Expected answer: 21/20

Correct? No

๐Ÿ”— Problem

Problem: The star Alpha shines 17/3 times brighter than an average star, while the star Bravo shines 20/16 times as bright. How much brighter are both stars compared to an average star if you add up the relative brightness of these two stars?

Llama 3 8B:

Reasoning: Alpha shines 17/3 times brighter than an average star, which means it shines 17/3 - 1 = 5.67 times brighter than an average star.
Bravo shines 20/16 times as bright, which means it shines 20/16 - 1 = 1.25 times brighter than an average star.
Adding the relative brightness of both stars, we get 5.67 + 1.25 = 6.92 times brighter than an average star.
### Answer: 6.92

Expected answer: 83/12

Correct? No

๐Ÿ”— Problem

Problem: There are 17/20 kg of red apples and 18/8 kg of green apples in a grocery store. How many kilograms of apples are in the store in total?

Llama 3 8B:

Reasoning: To find the total weight of red apples, we can convert the fraction to a decimal by dividing the numerator by the denominator: 17/20 = 0.85 kg.
To find the total weight of green apples, we can convert the fraction to a decimal by dividing the numerator by the denominator: 18/8 = 2.25 kg.
The total weight of apples is the sum of the red and green apples: 0.85 kg + 2.25 kg = 3.1 kg.
### Answer: 3.1

Expected answer: 31/10

Correct? Yes

๐Ÿ”— Follow-up

Problem: The grocery store owner also received an additional batch of yellow apples that weighs 17/15 kg. So, now how many total kilograms of apples are in the store?

Llama 3 8B:

Reasoning: We already calculated the total weight of red and green apples: 3.1 kg.
The additional batch of yellow apples weighs 17/15 kg, which we can convert to a decimal by dividing the numerator by the denominator: 17/15 = 1.13 kg.
The total weight of apples in the store is the sum of the red and green apples and the yellow apples: 3.1 kg + 1.13 kg = 4.23 kg.
### Answer: 4.23

Expected answer: 127/30

Correct? No

๐Ÿ”— Follow-up

Problem: Instead of having 17/20 kg of red apples as stated in the original problem, suppose the store only had 3/20 kg of red apples. Along with the 18/8 kg of green apples, how many kilograms of apples would be in the store now?

Llama 3 8B:

Reasoning: To find the total weight of red apples, we can convert the fraction to a decimal by dividing the numerator by the denominator: 3/20 = 0.15 kg.
To find the total weight of green apples, we can convert the fraction to a decimal by dividing the numerator by the denominator: 18/8 = 2.25 kg.
The total weight of apples is the sum of the red and green apples: 0.15 kg + 2.25 kg = 2.4 kg.
### Answer: 2.4

Expected answer: 12/5

Correct? No

๐Ÿ”— Problem

Problem: If a bus drives 12/20 of a mile then goes an additional 12/12 of a mile, how many miles did the bus travel in total?

Llama 3 8B:

Reasoning: The bus drives 12/20 of a mile, which can be simplified to 3/5 of a mile.
The bus then drives an additional 12/12 of a mile, which is equal to 1 mile.
The total distance traveled by the bus is the sum of these two distances: 3/5 + 1 = 8/5 miles.
### Answer: 8/5

Expected answer: 8/5

Correct? Yes

๐Ÿ”— Follow-up

Problem: After the bus has traveled 12/20 of a mile, then an additional 12/12 of a mile, it makes the same journey back. How many miles did the bus travel in total?

Llama 3 8B:

Reasoning: The bus drives 12/20 of a mile, which can be simplified to 3/5 of a mile.
The bus then drives an additional 12/12 of a mile, which is equal to 1 mile.
The total distance traveled by the bus in one direction is 3/5 + 1 = 8/5 miles.
Since the bus makes the same journey back, it travels the same distance, which is also 8/5 miles.
The total distance traveled by the bus is the sum of the distances traveled in both directions: 8/5 + 8/5 = 16/5 miles.
### Answer: 16/5

Expected answer: 16/5

Correct? Yes

๐Ÿ”— Follow-up

Problem: If instead of driving 12/20 of a mile initially, the bus drives 14/20 of a mile in the beginning and then goes an additional 12/12 of a mile, how many miles did the bus travel in total?

Llama 3 8B:

Reasoning: The bus drives 14/20 of a mile, which can be simplified to 7/10 of a mile.
The bus then drives an additional 12/12 of a mile, which is equal to 1 mile.
The total distance traveled by the bus is the sum of these two distances: 7/10 + 1 = 17/10 miles.
### Answer: 17/10

Expected answer: 17/10

Correct? Yes

๐Ÿ”— Problem

Problem: In the first hour, a shark swims 3/9 miles and in the second hour height increases its speed to swim 13/5 miles. How many miles does the shark swim in total in these two hours?

Llama 3 8B:

Reasoning: The shark swims 3/9 miles in the first hour. To find the total distance swum in the first hour, we can multiply the distance by the number of hours: 3/9 ร— 1 = 1/3 miles.
The shark swims 13/5 miles in the second hour. To find the total distance swum in the second hour, we can multiply the distance by the number of hours: 13/5 ร— 1 = 13/5 miles.
The total distance swum by the shark in two hours is the sum of the distances swum in each hour: 1/3 + 13/5 = 15/15 + 26/15 = 41/15 miles.
### Answer: 41/15

Expected answer: 44/15

Correct? No

๐Ÿ”— Problem

Problem: A drummer hits a rhythm where they hit once every 17/17 seconds for the first beat and then 2/12 seconds for the second beat. How long does it take for the drummer to hit the two beats together?

Llama 3 8B:

Reasoning: The time it takes for the drummer to hit the first beat is 17/17 seconds, which simplifies to 1 second.
The time it takes for the drummer to hit the second beat is 2/12 seconds, which simplifies to 1/6 seconds.
The total time it takes for the drummer to hit both beats together is 1 + 1/6 = 1 1/6 seconds.
### Answer: 1 1/6 seconds.

Expected answer: 7/6

Correct? Yes

๐Ÿ”— Follow-up

Problem: Instead of hitting the first note every 17/17 seconds, the drummer decides to change the beat and hit it every 16/17 seconds. They're still hitting the second note every 2/12 seconds though. How long does it now take the drummer to hit the two beats together?

Llama 3 8B:

Reasoning: The time it takes for the drummer to hit the first beat is now 16/17 seconds, which simplifies to 16/17 seconds.
The time it takes for the drummer to hit the second beat is still 2/12 seconds, which simplifies to 1/6 seconds.
The total time it takes for the drummer to hit both beats together is 16/17 + 1/6 = 32/51 seconds.
### Answer: 32/51 seconds.

Expected answer: 113/102

Correct? No

๐Ÿ”— Problem

Problem: If a fireplace burns 12/17 cord of wood in the morning and 8/19 cord in the evening, what is the total cord of wood it burns in a day?

Llama 3 8B:

Reasoning: The fireplace burns 12/17 cord of wood in the morning and 8/19 cord in the evening. To find the total cord of wood burned in a day, we need to add these two fractions.

First, we need to find a common denominator for the two fractions. The least common multiple of 17 and 19 is 323. So, we can convert both fractions to have a denominator of 323:

12/17 = 228/323
8/19 = 152/323

Now, we can add the two fractions:

228/323 + 152/323 = 380/323

So, the total cord of wood burned in a day is 380/323 cord.

### Answer: 380/323

Expected answer: 364/323

Correct? No

๐Ÿ”— Problem

Problem: A butterfly's flight consisted of two segments. The first segment was 18/19 of a mile and the second was 9/17 of a mile. How long was the entire flight?

Llama 3 8B:

Reasoning: To find the total length of the flight, we need to add the lengths of the two segments. The first segment is 18/19 of a mile, and the second segment is 9/17 of a mile.

To add these fractions, we need to find a common denominator, which is 19*17 = 323. So, we can rewrite the fractions as:

18/19 = 342/323
9/17 = 171/323

Now we can add the numerators:

342 + 171 = 513

So, the total length of the flight is 513/323 of a mile.

### Answer: 513/323

Expected answer: 477/323

Correct? No

๐Ÿ”— Problem

Problem: While measuring a map, Jenna finds that the distance between two cities is 13/10 inches, and the distance from the second city to the third city is 14/15 inches. What is the total distance Jenna measured between the three cities on the map?

Llama 3 8B:

Reasoning: The distance between the first and second city is 13/10 inches. The distance between the second and third city is 14/15 inches. To find the total distance, we add these two distances together: 13/10 + 14/15 = 169/150.
### Answer: 169/150

Expected answer: 67/30

Correct? No

๐Ÿ”— Problem

Problem: A helium balloon rises at a rate of 13/6 feet per second. After a gust of wind, its speed increases by 3/16 feet per second. What is the new speed of the balloon in feet per second?

Llama 3 8B:

Reasoning: The initial speed of the balloon is 13/6 feet per second. After the gust of wind, its speed increases by 3/16 feet per second. To find the new speed, we add the initial speed and the increase in speed:

(13/6) + (3/16) = (52/24) + (3/16) = (52 + 3)/24 = 55/24

### Answer: 55/24 feet per second.

Expected answer: 113/48

Correct? No

๐Ÿ”— Problem

Problem: Scarlett has 16/10 gallons of red paint. If she uses 1/20 of a gallon for a small art project, how many gallons of red paint will she have left?

Llama 3 8B:

Reasoning: Scarlett has 16/10 = 1.6 gallons of red paint initially.
She uses 1/20 = 0.05 gallons for the art project.
To find the amount of paint left, subtract the amount used from the initial amount: 1.6 - 0.05 = 1.55 gallons.
### Answer: 1.55

Expected answer: 31/20

Correct? Yes

๐Ÿ”— Follow-up

Problem: After finishing the small art project, Scarlett decides to mix the remaining red paint with 5/7 gallons of yellow paint to make orange paint. How many gallons of paint does she have now?

Llama 3 8B:

Reasoning: Scarlett has 1.55 gallons of red paint left.
She mixes it with 5/7 = 0.71 (approximately) gallons of yellow paint.
To find the total amount of paint, add the amounts of red and yellow paint: 1.55 + 0.71 = 2.26 gallons.
### Answer: 2.26

Expected answer: 317/140

Correct? No

๐Ÿ”— Follow-up

Problem: Suppose Scarlett initially had 16/10 gallons of red paint. But this time, she uses 2/20 of a gallon for her small project instead. How many gallons of red paint does she have left now?

Llama 3 8B:

Reasoning: Scarlett has 16/10 = 1.6 gallons of red paint initially.
She uses 2/20 = 0.1 gallons for the art project.
To find the amount of paint left, subtract the amount used from the initial amount: 1.6 - 0.1 = 1.5 gallons.
### Answer: 1.5

Expected answer: 3/2

Correct? No

๐Ÿ”— Problem

Problem: Susie has a box of 12 chocolate bars. She decides to eat 2/5 of a chocolate bar herself. How many chocolate bars are left in the box?

Llama 3 8B:

Reasoning: Susie eats 2/5 of a chocolate bar, which is equivalent to 0.4 chocolate bars (since 2/5 = 0.4).
She has 12 chocolate bars initially, and eats 0.4 chocolate bars, so she has 12 - 0.4 = 11.6 chocolate bars left.
Since you can't have a fraction of a chocolate bar, we round down to the nearest whole number, which is 11.
### Answer: 11

Expected answer: 58/5

Correct? No

๐Ÿ”— Problem

Problem: A plane is flying at an altitude of 2 miles, then it descends by 10/15 of a mile. What is the new altitude of the plane?

Llama 3 8B:

Reasoning: The plane is initially at an altitude of 2 miles. It descends by 10/15 of a mile, which is equivalent to 2/3 of a mile (since 10/15 = 2/3).

New altitude = Initial altitude - Descended altitude
= 2 miles - (2/3) mile
= 2 miles - 0.666... miles (approximately)
= 1.333... miles (approximately)

### Answer: 1.33 miles

Expected answer: 4/3

Correct? No

๐Ÿ”— Problem

Problem: A child goes down a slide that's 6/19 meters long, and then goes down another slide that's 17/4 meters long. How many total meters did they slide?

Llama 3 8B:

Reasoning: The child slid 6/19 meters on the first slide, and 17/4 meters on the second slide. To find the total distance, we can add the two distances together:

6/19 + 17/4

To add these fractions, we need to find a common denominator, which is 76. So, we can rewrite the fractions as:

3/38 + 17/4

Now we can add:

3/38 + 17/4 = (3*19) / (38*4) + 17/4 = 57/152 + 17/4

To add these fractions, we need to find a common denominator, which is 152. So, we can rewrite the fractions as:

57/152 + 76/152

Now we can add:

57/152 + 76/152 = 133/152

So, the total distance the child slid is 133/152 meters.

### Answer: 133/152

Expected answer: 347/76

Correct? No

๐Ÿ”— Problem

Problem: A colonial fireplace burns firewood at a rate of 4/15 cords per hour in the early morning. In the late night, the rate increases to 14/15 cords per hour. How much firewood does the fireplace burn in total in one hour split between the early morning and late night?

Llama 3 8B:

Reasoning: The fireplace burns 4/15 cords per hour in the early morning, and 14/15 cords per hour in the late night.
The total amount of firewood burned in one hour is the sum of the amount burned in the early morning and the late night: 4/15 + 14/15 = 18/15 = 1 3/15 = 1.2/1 = 1 2/10 = 1.2.
### Answer: 1.2

Expected answer: 6/5

Correct? Yes

๐Ÿ”— Follow-up

Problem: If the colonial fireplace burns firewood at a combined rate of 4/15 cords per hour in the early morning and 14/15 cords per hour in the late night, and during the peak hours, it burns an additional 6/5 cords per hour. Then how much total firewood does the fireplace burn in one hour considering early morning, late night, and peak hours?

Llama 3 8B:

Reasoning: The fireplace burns 4/15 cords per hour in the early morning, and 14/15 cords per hour in the late night. The combined rate is 4/15 + 14/15 = 18/15 = 1 3/15 = 1.2/1 = 1 2/10 = 1.2.
During the peak hours, it burns an additional 6/5 cords per hour.
The total amount of firewood burned in one hour is the sum of the amount burned in the early morning, late night, and peak hours: 1.2 + 6/5 = 1.2 + 1.2/1 = 1.2 + 1.2 = 2.4.
### Answer: 2.4

Expected answer: 12/5

Correct? No

๐Ÿ”— Follow-up

Problem: Continuing from the previous scenario, let's suppose the colonial fireplace in the early morning burns firewood at a slightly different rate of 8/15 cords per hour instead of 4/15 cords per hour. The late night burning rate remains the same at 14/15 cords per hour. Given these new circumstances, how much firewood does the fireplace burn in total in one hour split between the early morning and late night?

Llama 3 8B:

Reasoning: The fireplace burns 8/15 cords per hour in the early morning, and 14/15 cords per hour in the late night.
The total amount of firewood burned in one hour is the sum of the amount burned in the early morning and the late night: 8/15 + 14/15 = 22/15 = 1 7/15 = 1.46/1 = 1 7/10 = 1.46.
### Answer: 1.46

Expected answer: 22/15

Correct? No

๐Ÿ”— Problem

Problem: An alien travelled 9/20 of a light year towards earth then decided to move forward another 11/7 light years. How many light years has the alien travelled in total?

Llama 3 8B:

Reasoning: The alien travelled 9/20 of a light year initially. To find the total distance travelled, we can multiply this by the fraction of a light year: 9/20 ร— 1 = 9/20 light year.
The alien then travelled another 11/7 light years. To find the total distance travelled, we can add this to the initial distance: 9/20 + 11/7 = 63/140 + 110/140 = 173/140 light year.
### Answer: 173/140

Expected answer: 283/140

Correct? No

๐Ÿ”— Problem

Problem: If Bob has 10/2 of a cucumber and he adds it to 1/7 of another cucumber, how many cucumbers does he have in total?

Llama 3 8B:

Reasoning: Bob has 10/2 = 5/2 = 2.5/1 = 2 1/2 of a cucumber.
Bob adds 1/7 of another cucumber, which is 1/7 = 0.14 (approximately).
Bob has 2.5 + 0.14 = 2.64 (approximately) of a cucumber.
### Answer: 2 2/7

Expected answer: 36/7

Correct? No