Common Core Standard 8.EE.C.8
This standard covers the following:
Analyze and solve pairs of simultaneous linear equations.
Problem: Let's find the values of variables q and s by solving the following system of equations: 1. (40 * s) - (91 * q) = 37 2. (30 * s) + (12 * q) = 121
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the second equation for s: s = (121 - 12q) / 30 Now, substitute this expression for s into the first equation: (40 * ((121 - 12q) / 30)) - (91 * q) = 37 Simplify the equation: (40 * 121 / 30) - (40 * 12q / 30) - 91q = 37 Simplify further: 808/30 - 16q/30 - 91q = 37 Combine like terms: (808 - 16 - 2730) / 30 - 91q = 37 Simplify: -1862/30 - 91q = 37 Multiply both sides by 30 to eliminate the fraction: -1862 - 2730q = 1110 Add 1862 to both sides: -2730q = 2872 Divide both sides by -2730: q = -2872 / 2730 q = -1.05 Now that we have the value of q, we can find the value of s: s = (121 - 12(-1.05)) / 30 s = (121 + 12.6) / 30 s = 133.6 / 30 s = 4.45 ### Answer: q = -1.05, s = 4.45
Expected answer: {q: 373/321, s: 2291/642}
Correct? No
Problem: Solve the following system of equations for the values of b and m: 4 * b + 44 * m = 180 and 79 * m - 6 * b = 48.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the second equation for m: 79m - 6b = 48 79m = 6b + 48 m = (6b + 48) / 79 Now, substitute this expression for m into the first equation: 4b + 44((6b + 48) / 79) = 180 Multiply both sides by 79 to eliminate the fraction: 316b + 2112 = 14280 Subtract 2112 from both sides: 316b = 12168 Divide both sides by 316: b = 12168 / 316 b = 38.5 Now that we have found b, we can substitute it back into one of the original equations to find m. We'll use the second equation: 79m - 6(38.5) = 48 Simplify: 79m - 231 = 48 Add 231 to both sides: 79m = 279 Divide both sides by 79: m = 279 / 79 m = 3.5 ### Answer: b = 38.5, m = 3.5
Expected answer: {b: 3027/145, m: 318/145}
Correct? No
Problem: Solve the following system of equations to find the values of o and g: 42 * o - 15 * g = 28 47 * o + 29 * g = 141.
Llama 3 8B:
To solve this system of equations, we can use the method of substitution or elimination. Here, we will use the elimination method. First, we will multiply both equations by necessary multiples such that the coefficients of o's in both equations are the same: 1) Multiply the first equation by 29: 42 * o - 15 * g = 28 29 * (42 * o - 15 * g) = 29 * 28 1162 * o - 435 * g = 812 2) Multiply the second equation by 15: 47 * o + 29 * g = 141 15 * (47 * o + 29 * g) = 15 * 141 705 * o + 435 * g = 2115 Now, subtract the first equation from the second equation to eliminate o: (705 * o + 435 * g) - (1162 * o - 435 * g) = 2115 - 812 -457 * o = 1303 o = -1303/457 Now that we have the value of o, substitute it into one of the original equations to find the value of g. We will use the first equation: 42 * o - 15 * g = 28 42 * (-1303/457) - 15 * g = 28 -1094/11 - 15 * g = 28 -1094/11 - 15 * g + 1094/11 = 28 + 1094/11 -15 * g = 140/11 g = -140/165 ### Answer: o = -1303/457, g = -140/165
Expected answer: {g: 4606/1923, o: 2927/1923}
Correct? No
Problem: Given the following system of equations, determine the values of v and o: The first equation is: ((12 * v) - (6 * o)) = 21 The second equation is: ((76 * v) - (45 * o)) = 50.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can simplify the first equation by distributing the multiplication: 12v - 6o = 21 Next, we can simplify the second equation by distributing the multiplication: 76v - 45o = 50 Now, we can try to eliminate one of the variables by multiplying the two equations by necessary multiples such that the coefficients of o's in both equations are the same. Let's multiply the first equation by 5 and the second equation by 6: 60v - 30o = 105 456v - 270o = 300 Now, we can subtract the first equation from the second equation to eliminate o: 456v - 60v = 300 - 105 396v = 195 Now, we can solve for v: v = 195 / 396 v = 0.5 Now that we have the value of v, we can substitute it into one of the original equations to solve for o. Let's use the first equation: 12v - 6o = 21 12(0.5) - 6o = 21 6 - 6o = 21 Now, we can subtract 6 from both sides: -6o = 15 Finally, we can divide both sides by -6 to solve for o: o = -15 / 6 o = -2.5 ### Answer: v = 0.5, o = -2.5
Expected answer: {o: 83/7, v: 215/28}
Correct? No
Problem: Find the values of f and g in the following system of equations: 75 * f + 25 * g = 138 and 2 * f + 90 * g = 143.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the second equation for g: 90g = 143 - 2f g = (143 - 2f) / 90 Now, substitute this expression for g into the first equation: 75f + 25((143 - 2f) / 90) = 138 Multiply both sides by 90 to eliminate the fraction: 675f + 25(143 - 2f) = 138 * 90 Expand and simplify: 675f + 3575 - 50f = 12420 Combine like terms: 625f = 8865 Divide by 625: f = 8865 / 625 f = 14.24 Now that we have found f, we can find g by substituting f into the expression we found earlier: g = (143 - 2(14.24)) / 90 g = (143 - 28.48) / 90 g = 114.52 / 90 g = 1.27 ### Answer: f = 14.24, g = 1.27
Expected answer: {f: 1769/1340, g: 10449/6700}
Correct? No
Problem: Solve the following system of equations for variables y and n: the first equation is 194 = 4 * y + 14 * n and the second equation is 7 = 65 * n - 79 * y.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can rewrite the second equation to isolate y: 79y = 65n - 7 Now, divide both sides by 79: y = (65n - 7) / 79 Next, substitute this expression for y into the first equation: 194 = 4((65n - 7) / 79) + 14n Multiply both sides by 79 to eliminate the fraction: 15244 = 260n - 28 + 14n Combine like terms: 15244 = 274n - 28 Add 28 to both sides: 15272 = 274n Divide both sides by 274: n = 15272 / 274 n = 56 Now that we have found n, we can substitute it back into one of the original equations to find y. We'll use the second equation: 79y = 65(56) - 7 79y = 3643 - 7 79y = 3636 Divide both sides by 79: y = 3636 / 79 y = 46 ### Answer: y = 46, n = 56
Expected answer: {n: 7677/683, y: 6256/683}
Correct? No
Problem: Find the values of l and g that satisfy these two equations: The first equation is 146 = 28 * g + 26 * l. The second equation is 6 = 41 * l - 53 * g.
Llama 3 8B:
Let's solve the system of equations step by step. From the second equation, we can express l in terms of g: 6 = 41 * l - 53 * g 41 * l = 6 + 53 * g l = (6 + 53 * g) / 41 Now, substitute this expression for l into the first equation: 146 = 28 * g + 26 * ((6 + 53 * g) / 41) Multiply both sides by 41 to eliminate the fraction: 6024 = 28 * 41 * g + 26 * (6 + 53 * g) Expand and simplify: 6024 = 1148 * g + 156 + 1378 * g Combine like terms: 6024 = 2516 * g + 156 Subtract 156 from both sides: 5868 = 2516 * g Divide both sides by 2516: g = 5868 / 2516 g = 2.33 Now that we have found g, we can find l by substituting g into one of the original equations. We'll use the second equation: 6 = 41 * l - 53 * g 6 = 41 * l - 53 * 2.33 6 = 41 * l - 123.69 41 * l = 6 + 123.69 41 * l = 129.69 l = 129.69 / 41 l = 3.18 ### Answer: l = 3.18, g = 2.33
Expected answer: {g: 2915/1263, l: 3953/1263}
Correct? No
Problem: Consider the following system of equations: 1) 20 * p + 56 * y = 90 2) 89 * p + 7 * y = 98 Resolve this system and find the values of p and y.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply equation (1) by 7 and equation (2) by 56 to make the coefficients of y in both equations the same: 1) 140p + 392y = 630 2) 496p + 7y = 546 Now, we can subtract equation (2) from equation (1) to eliminate y: (140p + 392y) - (496p + 7y) = 630 - 546 140p - 496p = 630 - 546 - 392y + 7y -356p = 84 p = -84/356 Now that we have the value of p, we can substitute it into one of the original equations to find the value of y. Let's use equation (1): 20p + 56y = 90 20(-84/356) + 56y = 90 -1680/356 + 56y = 90 56y = 90 + 1680/356 56y = 90 + 48 56y = 138 y = 138/56 y = 123/48 So, the values of p and y are: p = -84/356 y = 123/48 ### Answer: p = -84/356, y = 123/48
Expected answer: {p: 347/346, y: 3025/2422}
Correct? No
Problem: Given the system of equations: 72*k - 22*d = 17 and 6*d +69*k = 96, find the values of variables k and d.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the second equation by 2 to make the coefficients of d in both equations the same: 12*d + 138*k = 192 Now we can subtract the first equation from the modified second equation: (12*d + 138*k) - (72*k - 22*d) = 192 - 17 12*d + 138*k - 72*k + 22*d = 192 - 17 34*d + 66*k = 175 Now we can solve for d: 34*d = 175 - 66*k d = (175 - 66*k) / 34 Now we can substitute this expression for d into one of the original equations. Let's use the first equation: 72*k - 22*(175 - 66*k) / 34 = 17 Multiply both sides by 34 to eliminate the fraction: 2488*k - 22*(175 - 66*k) = 578 Expand and simplify: 2488*k - 3850 + 1452*k = 578 33340*k - 3850 = 578 33340*k = 4428 Now we can solve for k: k = 4428 / 33340 k = 0.132 Now that we have the value of k, we can find the value of d: d = (175 - 66*0.132) / 34 d = (175 - 8.712) / 34 d = 166.288 / 34 d = 4.89 So, the values of variables k and d are: k = 0.132 d = 4.89 ### Answer: k = 0.132, d = 4.89
Expected answer: {d: 1913/650, k: 369/325}
Correct? No
Problem: Solve the following system of equations to find the values of d and h: 73 * h - 33 * d = 48 10 * d + 14 * h = 91
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of d's in both equations are the same: 1) Multiply the first equation by 10: 730h - 330d = 480 2) Multiply the second equation by 33: 330d + 462h = 2973 Now, subtract the first equation from the second equation to eliminate the d term: 462h - 730h = 2973 - 480 -268h = 2493 Now, divide both sides by -268: h = -2493/268 h = -9.25 Now that we have the value of h, substitute it into one of the original equations to find the value of d. We'll use the first equation: 73h - 33d = 48 73(-9.25) - 33d = 48 -675 - 33d = 48 Add 675 to both sides: -33d = 723 d = -723/33 d = -22 So, the values of d and h are: d = -22 h = -9.25 ### Answer: d = -22, h = -9.25
Expected answer: {d: 5971/1192, h: 3483/1192}
Correct? No
Problem: Solve the following system of equations for the values of q and e: 1) 43 * q - 44 * e = 29 2) 30 * q + 43 * e = 130
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply both equations by necessary multiples such that the coefficients of e's in both equations are the same: 1) 43q - 44e = 29 Multiply equation (1) by 43 and equation (2) by 44: 172q - 1932e = 1253 132q + 1932e = 5720 Now, we can subtract equation (2) from equation (1) to eliminate e: (172q - 132q) - (1932e - 1932e) = 1253 - 5720 40q = -4467 Now, divide by 40: q = -4467/40 q = -111.675 Now that we have the value of q, we can substitute it into one of the original equations to find the value of e. We'll use equation (1): 43q - 44e = 29 43(-111.675) - 44e = 29 -4829.725 - 44e = 29 Add 4829.725 to both sides: -44e = 4829.725 + 29 -44e = 4858.725 Divide by -44: e = -4858.725/44 e = 110.205 ### Answer: q = -111.675, e = 110.205
Expected answer: {e: 4720/3169, q: 6967/3169}
Correct? No
Problem: Find the values of r and a in the following system of equations: 53 = ((89 * r) - (74 * a)) 109 = ((37 * a) + (6 * r))
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the first equation for r: r = (53 + 74a) / 89 Now, substitute this expression for r into the second equation: 109 = (37a + 6((53 + 74a) / 89)) Multiply both sides of the equation by 89 to eliminate the fraction: 9697 = 37a + 6(53 + 74a) Expand and simplify the right-hand side: 9697 = 37a + 318 + 444a Combine like terms: 9697 = 481a + 318 Subtract 318 from both sides: 9379 = 481a Divide both sides by 481: a = 9379 / 481 a = 19.5 Now that we have found a, we can substitute this value back into one of the original equations to find r. We'll use the first equation: r = (53 + 74(19.5)) / 89 r = (53 + 1443) / 89 r = 1496 / 89 r = 16.8 ### Answer: r = 16.8, a = 19.5
Expected answer: {a: 9383/3737, r: 271/101}
Correct? No
Problem: Given the following pair of equations where 'g' and 'q' represent the quantities of two different types of grains in a mix, solve for 'g' and 'q': 1. The sum of the weights of 42 units of 'g' and 12 units of 'q' equals 169 kg. 2. The weight of 12 units of 'q' minus the weight of 50 units of 'g' results in 19 kg.
Llama 3 8B:
Let's start by using the information from equation (2) to express the weight of 'q' in terms of 'g': 12q - 50g = 19 Now, we can use equation (1) to express the weight of 'g' in terms of 'q': 42g + 12q = 169 Substitute the expression for 'q' from equation (2) into equation (1): 42g + 12(19 + 50g) = 169 Expand and simplify: 42g + 228 + 600g = 169 Combine like terms: 642g = -59 Divide by 642: g = -59/642 Now that we have the value of 'g', we can find the value of 'q' by substituting it into equation (2): 12q = 19 + 50(-59/642) Simplify: 12q = -19 Divide by 12: q = -19/12 ### Answer: g = -59/642, q = -19/12
Expected answer: {g: 75/46, q: 578/69}
Correct? No
Problem: Find the values of s and v for the following system of equations: 37 * s - 11 * v = 54 82 * s - 62 * v = 41
Llama 3 8B:
Let's solve the system of equations using the method of substitution or elimination. First, let's multiply both equations by necessary multiples such that the coefficients of v's in both equations are the same: 1) Multiply the first equation by 62: 37s - 11v = 54 37s - 11v = 54 148s - 62v = 332 2) Multiply the second equation by 11: 82s - 62v = 41 82s - 62v = 41 914s - 682v = 451 Now, subtract the first equation from the second equation to eliminate v: 914s - 148s = 451 - 332 766s = 119 Now, divide by 766: s = 119/766 s = 0.155 Now that we have the value of s, substitute it into one of the original equations to find the value of v. We'll use the first equation: 37s - 11v = 54 37(0.155) - 11v = 54 5.71 - 11v = 54 Add 11v to both sides: 5.71 = 54 + 11v 11v = 54 - 5.71 11v = 48.29 Divide by 11: v = 48.29/11 v = 4.39 ### Answer: s = 0.155, v = 4.39
Expected answer: {s: 2897/1392, v: 2911/1392}
Correct? No
Problem: Based on the following two equations, find the values for c and z: The first equation is 41 * c + 65 * z = 151 The second equation is 78 * z - 48 * c = 48.
Llama 3 8B:
Let's solve the system of equations. First, we can multiply the two equations by necessary multiples such that the coefficients of c's in both equations are the same: 1) Multiply the first equation by 48 and the second equation by 65: 48 * 41 * c + 65 * 48 * z = 151 * 48 65 * 78 * z - 65 * 48 * c = 65 * 48 2) Now, we can subtract the second equation from the first equation: (48 * 41 - 65 * 48) * c = 151 * 48 - 65 * 48 -208 * c = 6048 - 65 * 48 -208 * c = 6048 - 65 * 48 -208 * c = 6048 - 3120 -208 * c = 2928 c = -2928/208 c = -14 Now that we have the value of c, we can substitute it into one of the original equations to find the value of z. We'll use the first equation: 41 * c + 65 * z = 151 41 * (-14) + 65 * z = 151 -574 + 65 * z = 151 65 * z = 725 z = 725/65 z = 11 ### Answer: c = -14, z = 11
Expected answer: {c: 37/27, z: 512/351}
Correct? No
Problem: Given the following system of equations: 60 * c - 91 * i = 7 7 * i + 76 * c = 148 What are the values of c and i?
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of c's in both equations are the same: 1) Multiply the first equation by 76 and the second equation by 91: 4560c - 6876i = 532 637i + 6968c = 13528 2) Subtract the first equation from the second equation to eliminate c: 637i + 6968c - (4560c - 6876i) = 13528 - 532 637i + 6968c - 4560c + 6876i = 13528 - 532 1197i = 13496 3) Divide both sides by 1197: i = 13496/1197 i = 11.25 4) Now that we have the value of i, substitute it into one of the original equations to find the value of c. We'll use the first equation: 60c - 91(11.25) = 7 60c - 1031.25 = 7 60c = 1031.25 + 7 60c = 1038.25 c = 1038.25/60 c = 17.305 ### Answer: c = 17.305, i = 11.25
Expected answer: {c: 1931/1048, i: 2087/1834}
Correct? No
Problem: Find the values of e and v that satisfy the following two simultaneous linear equations: 1) 71*v - 37*e = 69 2) 41*e + 76*v = 184
Llama 3 8B:
Let's solve the system of linear equations. We can solve the first equation for v: v = (69 + 37*e) / 71 Now, substitute this expression for v into the second equation: 41*e + 76*((69 + 37*e) / 71) = 184 Multiply both sides by 71 to eliminate the fraction: 2871*e + 10676 = 12964 Subtract 12964 from both sides: 2871*e = 2288 Divide both sides by 2871: e = 2288 / 2871 e ≈ 0.80 Now that we have found e, we can find v by substituting e back into one of the original equations. We'll use the first equation: 71*v - 37*0.80 = 69 71*v - 29.6 = 69 Add 29.6 to both sides: 71*v = 98.6 Divide both sides by 71: v = 98.6 / 71 v ≈ 1.39 ### Answer: e ≈ 0.80, v ≈ 1.39
Expected answer: {e: 7820/5723, v: 9637/5723}
Correct? No
Problem: What are the values of 'd' and 'v' in the following system of equations? The sum of 25 times 'v' and 69 times 'd' equals 113. The sum of 26 times 'd' and 42 times 'v' equals 85.
Llama 3 8B:
Let's solve the system of equations step by step. From the first equation, we can write: 25v + 69d = 113 From the second equation, we can write: 26d + 42v = 85 Now, we can multiply the first equation by 2 and the second equation by 1 to make the coefficients of 'd' the same: 50v + 138d = 226 26d + 42v = 85 Subtract the second equation from the first equation to eliminate 'v': 138d - 26d = 226 - 85 112d = 141 Now, divide both sides by 112: d = 141/112 d = 1.265625 Now that we have the value of 'd', we can substitute it into one of the original equations to find the value of 'v'. We'll use the first equation: 25v + 69(1.265625) = 113 Simplify the right-hand side: 25v + 88.4375 = 113 Subtract 88.4375 from both sides: 25v = 24.5625 Divide both sides by 25: v = 24.5625/25 v = 0.9825 ### Answer: d = 1.265625, v = 0.9825
Expected answer: {d: 2621/2248, v: 2927/2248}
Correct? No
Problem: Solve the following equations for g and z: 43 * z - 91 * g = 33 72 * g - 3 * z = 68
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply both sides of the first equation by 91 to get: 3917z - 8281g = 2973 Now, we can multiply both sides of the second equation by 3 to get: 216g - 9z = 204 Now, we can add the two equations to eliminate the z variable: 3917z - 8281g + 216g - 9z = 2973 + 204 Combine like terms: 3908z - 8065g = 3177 Now, we can divide both sides by 3908 to get: z = (3177 + 8065g) / 3908 Now, substitute this expression for z into one of the original equations. Let's use the first equation: 43z - 91g = 33 Substitute the expression for z: 43((3177 + 8065g) / 3908) - 91g = 33 Multiply both sides by 3908 to eliminate the fraction: 16141 + 34835g - 8281g = 12916 Combine like terms: -4806g = -3215 Divide both sides by -4806: g = 3215 / 4806 g = 0.668 Now that we have found g, we can substitute this value back into one of the original equations to find z. Let's use the first equation again: 43z - 91g = 33 Substitute the value of g: 43z - 91(0.668) = 33 Multiply both sides by 100 to eliminate the decimal: 4300z - 9132 = 3300 Add 9132 to both sides: 4300z = 9432 Divide both sides by 4300: z = 9432 / 4300 z = 2.2 ### Answer: g = 0.668, z = 2.2
Expected answer: {g: 3023/2823, z: 8564/2823}
Correct? No
Problem: Alex's and Brad's baskets contained c cherries and f figs respectively. From an old recipe book, it stated that cherries multiplied by 50 multiplied by the quantity of figs that multiplied by 12, which altogether would weigh about 92 grams. Another recipe book stated that cherries multiplied by 36 minus figs multiplied by 21 should weigh about 34 grams. Can you find the quantity of cherries (c) and figs (f)? Use the following system of equations to solve: 50c + 12f = 92 36c - 21f = 34.
Llama 3 8B:
Let's solve the system of equations. First, we can multiply both sides of the second equation by 12 to make the coefficients of f equal: 432c - 252f = 408 Now, we can subtract the first equation from the modified second equation to eliminate f: 432c - 50c - 252f + 12f = 408 - 92 382c = 316 Now, we can divide both sides by 382 to solve for c: c = 316/382 c = 8 Now that we have found c, we can substitute it into one of the original equations to find f. We'll use the first equation: 50c + 12f = 92 50(8) + 12f = 92 400 + 12f = 92 Subtract 400 from both sides: 12f = -308 Divide both sides by -12: f = 308/12 f = 25.67 Since f cannot be a fraction, we can round it to the nearest whole number. In this case, f = 26. ### Answer: c = 8, f = 26.
Expected answer: {c: 30/19, f: 62/57}
Correct? No
Problem: Here are the equations you'll need to solve (remember, the goal is to find the values of u and d): 1) 87u - 75d = 7 2) 85d - 82u = 54
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the first equation for u: u = (7 + 75d) / 87 Now, substitute this expression for u into the second equation: 85d - 82((7 + 75d) / 87) = 54 Multiply both sides of the equation by 87 to eliminate the fraction: 7535d - 82(7 + 75d) = 4716 Expand and simplify: 7535d - 574 - 6150d = 4716 Combine like terms: -8615d = -1028 Divide both sides by -8615: d = 1028 / 8615 d = 0.12 Now that we have found d, we can substitute this value back into one of the original equations to find u. We'll use the first equation: 87u - 75(0.12) = 7 87u - 9 = 7 Add 9 to both sides: 87u = 16 Divide both sides by 87: u = 16 / 87 u = 0.184 ### Answer: u = 0.184, d = 0.12.
Expected answer: {d: 5272/1245, u: 929/249}
Correct? No
Problem: Bill is trying to decipher a secret code. He manages to translate two sentences into the following mathematical expressions: (75 * his unknown number a) - (4 * his unknown number i) equals 42, and (10 * i) + (13 * a) equals 160. Using these equations, can you figure out the values of i and a for him?
Llama 3 8B:
Let's start by solving the first equation: (75 * a) - (4 * i) = 42 We can add (4 * i) to both sides to get: (75 * a) = 42 + (4 * i) Now, we can subtract 42 from both sides to get: 75a = 42 + 4i Next, we can subtract 4i from both sides to get: 75a - 4i = 42 Now, we can divide both sides by 75 to get: a - (4/75)i = 42/75 Now, let's move on to the second equation: (10 * i) + (13 * a) = 160 We can subtract (13 * a) from both sides to get: (10 * i) = 160 - (13 * a) Now, we can divide both sides by 10 to get: i = (160 - 13a) / 10 Now, we can substitute this expression for i into the first equation: (75 * a) - (4 * ((160 - 13a) / 10)) = 42 We can multiply both sides by 10 to get rid of the fraction: (750 * a) - (4 * (160 - 13a)) = 420 Now, we can expand the right-hand side: (750 * a) - 640 + 52a = 420 Now, we can add 640 to both sides to get: (750 * a) + 52a = 1060 Now, we can combine like terms: 802a = 1060 Now, we can divide both sides by 802 to get: a = 1060/802 a = 1.32 Now that we have found a, we can substitute it into one of the original equations to find i. Let's use the second equation: (10 * i) + (13 * 1.32) = 160 We can simplify the right-hand side: (10 * i) + 17.16 = 160 Now, we can subtract 17.16 from both sides to get: (10 * i) = 142.84 Now, we can divide both sides by 10 to get: i = 14.284 So, the values of i and a are: i = 14.284 a = 1.32 ### Answer: i = 14.284, a = 1.32
Expected answer: {a: 530/401, i: 5727/401}
Correct? No
Problem: Solve the following system of equations for the values of p and c: 37 * p + 74 * c = 183 27 * c - 18 * p = 13
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of p's in both equations are the same: 1) Multiply the first equation by 18: 666p + 1332c = 3276 2) Multiply the second equation by 74: 198c - 324p = 962 Now, we can subtract the second equation from the first equation to eliminate the p variable: 666p + 1332c - (198c - 324p) = 3276 - 962 666p + 1332c - 198c + 324p = 2314 690p + 1134c = 2314 Now, we can solve for p: 690p = 2314 - 1134c p = (2314 - 1134c) / 690 Now, substitute the expression for p into one of the original equations, say the first equation: 37 * ((2314 - 1134c) / 690) + 74c = 183 Simplify the equation: 37 * (2314 - 1134c) / 690 + 74c = 183 1373 - 4263c / 19 + 74c = 183 Multiply both sides by 19 to eliminate the fraction: 26067 - 4263c + 1414c = 3483 12494 - 285c = 3483 Now, subtract 3483 from both sides: 12494 - 285c - 3483 = 0 90011 - 285c = 0 Now, divide both sides by -285: c = 90011 / 285 c = 316 Now that we have the value of c, we can find the value of p: p = (2314 - 1134c) / 690 p = (2314 - 1134 * 316) / 690 p = (2314 - 357624) / 690 p = -356310 / 690 p = -516 ### Answer: p = -516, c = 316
Expected answer: {c: 3775/2331, p: 3979/2331}
Correct? No
Problem: Determine the values of k and p from the following system of equations: (48 * k) - (30 * p) = 37 (16 * p) + (33 * k) = 105.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the first equation for k: 48k - 30p = 37 48k = 30p + 37 k = (30p + 37) / 48 Now, substitute this expression for k into the second equation: 16p + 33((30p + 37) / 48) = 105 Multiply both sides by 48 to eliminate the fraction: 768p + 33(30p + 37) = 5040 Expand and simplify: 768p + 990p + 1217 = 5040 2058p + 1217 = 5040 Subtract 1217 from both sides: 2058p = 3823 Divide both sides by 2058: p = 3823 / 2058 p = 1.86 (approximately) Now that we have found p, we can substitute it back into one of the original equations to find k. We'll use the first equation: 48k - 30p = 37 48k - 30(1.86) = 37 Multiply 30(1.86) = 56.8: 48k - 56.8 = 37 Add 56.8 to both sides: 48k = 93.8 Divide both sides by 48: k = 93.8 / 48 k = 1.96 (approximately) So, the values of k and p are approximately: k ≈ 1.96 p ≈ 1.86 ### Answer: k ≈ 1.96, p ≈ 1.86.
Expected answer: {k: 1871/879, p: 1273/586}
Correct? No
Problem: Consider the following pair of equations. 1. 75v - 69f = 14 2. 46f + 53v = 110 Determine the values for v and f that satisfy these simultaneous equations.
Llama 3 8B:
Let's solve the system of equations using the method of substitution or elimination. First, let's multiply equation (1) by 46 to make the coefficients of f in both equations the same: 46(75v - 69f = 14) 3465v - 3186f = 686 Now, add equation (2) to the modified equation (1): 3465v - 3186f = 686 46f + 53v = 110 ------------------- 3511v - 3186f = 796 Now, divide both sides by -3186: v = (796 + 3186f) / 3511 Substitute this expression for v into one of the original equations, say equation (1): 75((796 + 3186f) / 3511) - 69f = 14 Multiply both sides by 3511 to eliminate the fraction: 267750 + 239610f - 47565f = 15186 Combine like terms: 219285 + 960f = 15186 Subtract 219285 from both sides: 960f = -70799 Divide both sides by -960: f = 73.75 Now that we have found f, we can find v by substituting f into the expression we found earlier: v = (796 + 3186(73.75)) / 3511 v = (796 + 23625) / 3511 v = 24021 / 3511 v = 6.85 ### Answer: v = 6.85, f = 73.75
Expected answer: {f: 7508/7107, v: 358/309}
Correct? No
Problem: Determine the values of o and g from the following system of equations: 7 * o + 13 * g = 131 89 * g - 70 * o = 37.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the second equation for g: g = (37 + 70o) / 89 Now, substitute this expression for g into the first equation: 7o + 13((37 + 70o) / 89) = 131 Multiply both sides by 89 to eliminate the fraction: 637o + 13(37 + 70o) = 11693 Expand and simplify: 637o + 481 + 910o = 11693 Combine like terms: 1547o = 11112 Divide both sides by 1547: o = 11112 / 1547 o = 7.2 Now that we have found o, we can find g by substituting o into one of the original equations. We'll use the second equation: 89g - 70(7.2) = 37 89g - 504 = 37 Add 504 to both sides: 89g = 541 Divide both sides by 89: g = 541 / 89 g = 6.1 ### Answer: o = 7.2, g = 6.1
Expected answer: {g: 449/73, o: 3726/511}
Correct? No
Problem: Solve the following system of equations for the values of d and k: 88 * d - 60 * k = 38 33 * k - 11 * d = 46.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply both equations by necessary multiples such that the coefficients of d's in both equations are the same: 1) Multiply the first equation by 11: 968d - 660k = 418 2) Multiply the second equation by 60: 1980k - 660d = 2760 Now, we can subtract the first equation from the second equation to eliminate d: (1980k - 660d) - (968d - 660k) = 2760 - 418 1980k - 660d - 968d + 660k = 2342 2012k - 1320d = 2342 Now, we can solve for k: k = (2342 + 1320d) / 2012 Now, substitute this expression for k into one of the original equations. We'll use the first equation: 88d - 60((2342 + 1320d) / 2012) = 38 Multiply both sides by 2012 to eliminate the fraction: 176,960d - 140,320 = 76,544 Now, subtract 76,544 from both sides: 176,960d = 64,416 Now, divide both sides by 176,960: d = 64,416 / 176,960 d = 0.364 Now that we have the value of d, we can find the value of k: k = (2342 + 1320d) / 2012 k = (2342 + 1320(0.364)) / 2012 k = (2342 + 480.48) / 2012 k = 2822.48 / 2012 k = 1.405 ### Answer: d = 0.364, k = 1.405
Expected answer: {d: 669/374, k: 203/102}
Correct? No
Problem: Consider the following system of equations, calculate the values of y and z: 24 * z + 72 * y = 139, 2 * z + 82 * y = 96.
Llama 3 8B:
Let's solve the system of equations using the method of elimination. First, we can multiply the two equations by necessary multiples such that the coefficients of y's in both equations are the same: 1) Multiply the first equation by 41 (which is the coefficient of y in the second equation): 24z + 72y = 139 41(24z + 72y) = 41(139) 576z + 2952y = 5671 2) Multiply the second equation by 1 (no need to multiply): 2z + 82y = 96 Now, subtract the second equation from the first equation: (576z + 2952y) - (2z + 82y) = 5671 - 96 574z + 2870y = 5575 Now, simplify the equation: 574z = 5575 - 2870y z = (5575 - 2870y) / 574 Now, substitute the value of z in one of the original equations. We'll use the first equation: 24z + 72y = 139 24((5575 - 2870y) / 574) + 72y = 139 Simplify the equation: 13920 - 103800y + 72y = 139 13920 - 103728y = 139 103728y = 13920 + 139 103728y = 13959 y = 13959 / 103728 y ≈ 0.134 Now that we have the value of y, we can find the value of z: z = (5575 - 2870y) / 574 z = (5575 - 2870(0.134)) / 574 z = (5575 - 383.32) / 574 z = 5191.68 / 574 z ≈ 9.03 ### Answer: y ≈ 0.134, z ≈ 9.03
Expected answer: {y: 1013/912, z: 2243/912}
Correct? No
Problem: Solve the following system of equations for the variables v and o: (87 * o) - (29 * v) = 1 and (8 * v) + (30 * o) = 91.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can rewrite the equations in a more convenient form: 1) 87o - 29v = 1 2) 8v + 30o = 91 Now, we can solve the first equation for o: o = (1 + 29v) / 87 Substitute this expression for o into the second equation: 8v + 30((1 + 29v) / 87) = 91 Multiply both sides by 87 to eliminate the fraction: 8v * 87 + 30(1 + 29v) = 91 * 87 Expand and simplify: 696v + 30 + 870v = 7937 Combine like terms: 1566v + 30 = 7937 Subtract 30 from both sides: 1566v = 7907 Divide both sides by 1566: v = 7907 / 1566 v = 5 Now that we have found v, we can find o by substituting v into one of the original equations. We'll use the first equation: o = (1 + 29(5)) / 87 o = (1 + 145) / 87 o = 146 / 87 o = 2 So, the values of v and o are: v = 5 o = 2 ### Answer: v = 5, o = 2
Expected answer: {o: 2647/1566, v: 2629/522}
Correct? No
Problem: Solve the following system of equations for h and p: The first equation is (23 * h) - (46 * p) = 58 The second equation is (11 * p) + (23 * h) = 124.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can simplify the first equation by multiplying both sides by 1 to get rid of the parentheses: 23h - 46p = 58 Next, we can simplify the second equation by multiplying both sides by 1 to get rid of the parentheses: 11p + 23h = 124 Now, we can solve for h in the first equation: 23h = 58 + 46p Divide both sides by 23: h = (58 + 46p) / 23 Now, substitute this expression for h into the second equation: 11p + 23((58 + 46p) / 23) = 124 Simplify the equation: 11p + 58 + 46p = 124 Combine like terms: 57p + 58 = 124 Subtract 58 from both sides: 57p = 66 Divide both sides by 57: p = 66 / 57 p = 1.16 (approximately) Now that we have found p, we can substitute it back into one of the original equations to find h. We'll use the first equation: 23h - 46(1.16) = 58 Simplify: 23h - 53.36 = 58 Add 53.36 to both sides: 23h = 111.36 Divide both sides by 23: h = 111.36 / 23 h = 4.84 (approximately) ### Answer: h ≈ 4.84, p ≈ 1.16.
Expected answer: {h: 2114/437, p: 22/19}
Correct? No
Problem: If the following system of equations represents the relationship between integers d and f, determine their values: 1) 19d + 6f = 120, 2) 90d - 42f = 69.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply equation (2) by 2 to make the coefficients of f in both equations the same: 2) 180d - 84f = 138 Now, we can add equation (1) and equation (2) to eliminate the f term: (19d + 6f = 120) + (180d - 84f = 138) This gives us: 199d = 258 Now, we can solve for d: d = 258/199 = 1.3 (not an integer, so we'll try to eliminate the fraction) d = 129/99 = 1 1/3 (not an integer, so we'll try to eliminate the fraction) d = 128/98 = 1 1/7 (not an integer, so we'll try to eliminate the fraction) d = 127/97 = 1 1/9 (not an integer, so we'll try to eliminate the fraction) d = 126/96 = 1 1/2 (integer!) So, d = 1 1/2 = 3/2 = 1.5 (not an integer, so we'll try to eliminate the fraction) d = 1 Now that we have the value of d, we can substitute it into one of the original equations to solve for f. We'll use equation (1): 19d + 6f = 120 19(1) + 6f = 120 6f = 120 - 19 = 101 f = 101/6 = 16 5/6 (not an integer, so we'll try to eliminate the fraction) f = 16 So, the values of d and f are: d = 1 f = 16 ### Answer: d = 1, f = 16.
Expected answer: {d: 909/223, f: 3163/446}
Correct? No
Problem: Here's a problem: A system of linear equations is given by the following formulas: 1) 42 * m + 55 * r = 127 2) 66 * m - 52 * r = 44 Can you solve this system to find the values of 'r' and 'm'?
Llama 3 8B:
Let's solve the system of linear equations step by step. First, we can multiply equation (1) by 2 and equation (2) by 1 to make the coefficients of 'r' in both equations the same: 1) 84 * m + 110 * r = 254 2) 66 * m - 52 * r = 44 Now, we can subtract equation (2) from equation (1) to eliminate 'm': (84 * m + 110 * r) - (66 * m - 52 * r) = 254 - 44 84 * m + 110 * r - 66 * m + 52 * r = 210 18 * m + 162 * r = 210 Next, we can subtract 162 * r from both sides to get: 18 * m = 210 - 162 * r 18 * m = 48 - 162 * r Now, we can divide both sides by 18 to solve for 'm': m = (48 - 162 * r) / 18 Now that we have the expression for 'm', we can substitute it into one of the original equations to solve for 'r'. Let's use equation (1): 42 * m + 55 * r = 127 42 * ((48 - 162 * r) / 18) + 55 * r = 127 Simplifying the equation, we get: 24 + 55 * r = 127 55 * r = 103 r = 103 / 55 r = 1.87 Now that we have the value of 'r', we can substitute it back into the expression for 'm' to find the value of 'm': m = (48 - 162 * 1.87) / 18 m = (48 - 303.54) / 18 m = -255.54 / 18 m = -14.23 ### Answer: m = -14.23, r = 1.87
Expected answer: {m: 1504/969, r: 363/323}
Correct? No
Problem: Determine the values of n and w that satisfy the following system of linear equations simultaneously: 31n + 64w = 120 57w + 71n = 173
Llama 3 8B:
To solve this system of linear equations, we can use the method of substitution or elimination. Here, we will use the elimination method. First, we will multiply the two equations by necessary multiples such that the coefficients of n's in both equations are the same: 1) Multiply the first equation by 71 and the second equation by 31: 2177n + 4480w = 8480 1771w + 5041n = 5373 2) Subtract the second equation from the first equation to eliminate n: 4480w - 1771w = 8480 - 5373 2711w = 3107 3) Divide both sides by 2711: w = 3107/2711 w = 1.15 4) Now that we have the value of w, substitute it into one of the original equations to find the value of n. We will use the first equation: 31n + 64(1.15) = 120 5) Simplify the equation: 31n + 76.4 = 120 6) Subtract 76.4 from both sides: 31n = 43.6 7) Divide both sides by 31: n = 43.6/31 n = 1.41 ### Answer: n = 1.41, w = 1.15.
Expected answer: {n: 4232/2777, w: 3157/2777}
Correct? No
Problem: Determine the values of u and a from the following system of linear equations: 1) 72 * a + 26 * u = 112 2) 76 * u - 77 * a = 31.
Llama 3 8B:
Let's solve the system of linear equations step by step. We have two equations: 1) 72a + 26u = 112 2) 76u - 77a = 31 We can solve this system using substitution or elimination. Let's use elimination. First, we can multiply equation (1) by 77 and equation (2) by 72 to make the coefficients of a in both equations the same: 1) 5548a + 1972u = 8656 2) 5472u - 5516a = 2184 Now, we can subtract equation (2) from equation (1) to eliminate a: (5548a + 1972u) - (5472u - 5516a) = 8656 - 2184 5548a + 1972u - 5472u + 5516a = 8656 - 2184 11064a = 6472 Now, we can solve for a: a = 6472 / 11064 a = 0.58 Now that we have the value of a, we can substitute it into one of the original equations to solve for u. Let's use equation (1): 72a + 26u = 112 72(0.58) + 26u = 112 41.76 + 26u = 112 Subtract 41.76 from both sides: 26u = 70.24 Divide both sides by 26: u = 70.24 / 26 u = 2.7 ### Answer: u = 2.7, a = 0.58
Expected answer: {a: 3853/3737, u: 5428/3737}
Correct? No
Problem: Solve the following system of equations for the values of b and n: the first equation is 54n + 18b = 143 and the second equation is 87n - 93b = 48.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of b's in both equations are the same: 1) Multiply the first equation by 93: 93(54n + 18b = 143) => 5493n + 1674b = 13331 2) Multiply the second equation by 18: 18(87n - 93b = 48) => 1566n - 1674b = 864 Now, we can subtract the second equation from the first equation to eliminate the term with b: (5493n + 1674b = 13331) - (1566n - 1674b = 864) => 6937n = 12467 Now, we can solve for n: 6937n = 12467 n = 12467/6937 n = 1.8 Now that we have the value of n, we can substitute it into one of the original equations to find the value of b. We'll use the first equation: 54n + 18b = 143 54(1.8) + 18b = 143 97.2 + 18b = 143 Subtract 97.2 from both sides: 18b = 45.8 Divide both sides by 18: b = 45.8/18 b = 2.55 ### Answer: b = 2.55, n = 1.8
Expected answer: {b: 3283/2196, n: 4721/2196}
Correct? No
Problem: Given the following system of equations about a company's production economics, where e represents the cost of electricity and p is the cost of petroleum: 53 * e + 7 * p = 103 69 * e - 88 * p = 6 What are the costs of electricity (e) and petroleum (p)?
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of p's in both equations are the same: 1) Multiply the first equation by 88: 53 * e + 7 * p = 103 53 * e + 7 * p = 103 88 * 53 * e + 88 * 7 * p = 88 * 103 2) Multiply the second equation by 7: 69 * e - 88 * p = 6 7 * 69 * e - 7 * 88 * p = 7 * 6 Now, we can subtract the second equation from the first equation: (88 * 53 * e + 88 * 7 * p) - (7 * 69 * e - 7 * 88 * p) = (88 * 103) - (7 * 6) 88 * 53 * e + 88 * 7 * p - 7 * 69 * e + 7 * 88 * p = 88 * 103 - 7 * 6 (88 * 53 - 7 * 69) * e = 88 * 103 - 7 * 6 + 88 * 7 * p - 7 * 88 * p (88 * 53 - 7 * 69) * e = 88 * 103 - 7 * 6 + 88 * (7 * p - 7 * p) (88 * 53 - 7 * 69) * e = 88 * 103 - 7 * 6 + 88 * 0 (88 * 53 - 7 * 69) * e = 88 * 103 - 7 * 6 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103 - 42 (88 * 53 - 7 * 69) * e = 88 * 103
Expected answer: {e: 9106/5147, p: 6789/5147}
Correct? No
Problem: Consider the following pair of linear equations. First equation: ((18 * p) - (7 * s)) = 21 Second equation: ((51 * s) - (24 * p)) = 14 Find the values of p and s that satisfy both equations.
Llama 3 8B:
Let's solve the system of linear equations. First, we can multiply the first equation by 24 to make the coefficients of p in both equations the same: 24((18 * p) - (7 * s)) = 24 * 21 432p - 168s = 504 Now, we can subtract the second equation from the modified first equation: 432p - 168s = 504 -(51s - 24p) = 14 Combine like terms: 432p - 168s - 51s + 24p = 504 - 14 432p - 219s = 490 Now, we can solve for p: 432p = 490 + 219s p = (490 + 219s) / 432 Now, substitute this expression for p into the original first equation: ((18 * ((490 + 219s) / 432)) - (7 * s)) = 21 Simplify and solve for s: (18 * (490 + 219s) / 432) - 7s = 21 (1710 + 3918s) / 432 - 7s = 21 3918s - 7s = 21 * 432 - 1710 3911s = 9261 - 1710 3911s = 7551 s = 7551 / 3911 s = 1.94 (approximately) Now that we have the value of s, we can find the value of p: p = (490 + 219 * 1.94) / 432 p = (490 + 423.66) / 432 p = 913.66 / 432 p = 2.11 (approximately) ### Answer: p ≈ 2.11, s ≈ 1.94.
Expected answer: {p: 1169/750, s: 126/125}
Correct? No
Problem: Solve the following system of equations for c and w: The first equation is 59 times c minus 34 times w is equal to 84. The second equation is 11 times c plus 42 times w is equal to 98.
Llama 3 8B:
Let's solve the system of equations step by step. We have two equations: 1) 59c - 34w = 84 2) 11c + 42w = 98 We can solve this system of equations using the method of substitution or elimination. Here, we'll use the elimination method. First, we'll multiply both equations by necessary multiples such that the coefficients of w's in both equations are the same: 1) 59c - 34w = 84 Multiply equation (1) by 3 and equation (2) by 2: 3(59c - 34w = 84) => 177c - 102w = 252 2) 11c + 42w = 98 Multiply equation (2) by 3: 3(11c + 42w = 98) => 33c + 126w = 294 Now, subtract equation (2) from equation (1): (177c - 102w = 252) - (33c + 126w = 294) => 144c - 228w = -42 Now, we have a new equation: 144c - 228w = -42 Now, we'll multiply equation (1) by 1 and equation (2) by 2: 1(59c - 34w = 84) => 59c - 34w = 84 2(11c + 42w = 98) => 22c + 84w = 196 Now, add equation (1) and equation (2): (59c - 34w = 84) + (22c + 84w = 196) => 81c + 50w = 280 Now, we have a new equation: 81c + 50w = 280 Now, we'll solve the system of equations by solving the above two equations: 144c - 228w = -42 81c + 50w = 280 Now, multiply equation (2) by 3: 3(81c + 50w = 280) => 243c + 150w = 840 Now, subtract equation (1) from equation (2): (243c + 150w = 840) - (144c - 228w = -42) => 387c + 378w = 882 Now, divide both sides by 387: c = 882/387 c = 2.28 Now, substitute the value of c in one of the original equations, say equation (1): 59c - 34w = 84 59(2.28) - 34w = 84 133.32 - 34w = 84 Now, subtract 133.32 from both sides: -34w = -49.32 Now, divide both sides by -34: w = 49.32/34 w = 1.45 ### Answer: c = 2.28, w = 1.45
Expected answer: {c: 1715/713, w: 2429/1426}
Correct? No
Problem: Solve the following system of equations for the values of f and z: First equation is 45 * f + 42 * z = 101, Second equation is 60 * z - 42 * f = 13.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of f's in both equations are the same: 1) Multiply the first equation by 42 and the second equation by 45: 1) 1890f + 1764z = 4282 2) 2700z - 1890f = 585 Now, we can subtract the second equation from the first equation to eliminate the f variable: 1890f + 1764z = 4282 - (2700z - 1890f = 585) This gives us: 3800z = 3697 Now, we can solve for z: z = 3697/3800 z = 0.9755 Now that we have the value of z, we can substitute it into one of the original equations to solve for f. We'll use the first equation: 45f + 42z = 101 45f + 42(0.9755) = 101 Simplifying the equation: 45f + 41.71 = 101 Subtracting 41.71 from both sides: 45f = 59.29 Dividing both sides by 45: f = 59.29/45 f = 1.315 ### Answer: f = 1.315, z = 0.9755
Expected answer: {f: 919/744, z: 1609/1488}
Correct? No
Problem: Calculate the values of p and u from the following system of equations: 26 * p - 21 * u = 6 15 * p + 58 * u = 83.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the first equation for p: 26p - 21u = 6 26p = 6 + 21u p = (6 + 21u) / 26 Now, substitute this expression for p into the second equation: 15((6 + 21u) / 26) + 58u = 83 Multiply both sides by 26 to eliminate the fraction: 15(6 + 21u) + 58u * 26 = 83 * 26 Expand and simplify: 90 + 315u + 1492u = 2158 Combine like terms: 2507u = 2068 Divide by 2507: u = 2068 / 2507 u = 0.826 Now that we have found u, we can substitute it back into one of the original equations to find p. We'll use the first equation: 26p - 21u = 6 26p - 21(0.826) = 6 Simplify: 26p - 17.346 = 6 Add 17.346 to both sides: 26p = 23.346 Divide by 26: p = 23.346 / 26 p = 0.900 ### Answer: p = 0.900, u = 0.826.
Expected answer: {p: 2091/1823, u: 2068/1823}
Correct? No
Problem: Solve for the values of n and s using these two simultaneous equations: 1) 92 * n - 38 * s = 62 2) 59 * n + 8 * s = 75
Llama 3 8B:
Let's solve the system of equations. We can start by multiplying equation (1) by 8 and equation (2) by 38 to make the coefficients of s in both equations the same: 1) 736n - 304s = 496 2) 2236n + 304s = 2860 Now, we can subtract equation (1) from equation (2) to eliminate the s term: 2236n - 736n = 2860 - 496 1500n = 2364 Now, we can solve for n: n = 2364/1500 n = 1.576 Now that we have the value of n, we can substitute it into one of the original equations to solve for s. We'll use equation (1): 92n - 38s = 62 92(1.576) - 38s = 62 148.352 - 38s = 62 Now, we can solve for s: -38s = -86.352 s = 86.352/38 s = 2.272 ### Answer: n = 1.576, s = 2.272
Expected answer: {n: 1673/1489, s: 1621/1489}
Correct? No
Problem: Solving the following pairs of simultaneous equations, what would be the values for e and z? The equations are: 87 * z - 35 * e = 63 and 81 * z + 58 * e = 154.
Llama 3 8B:
Let's solve the system of equations step by step. We have: 1) 87z - 35e = 63 2) 81z + 58e = 154 First, we can multiply equation (1) by 58 and equation (2) by 35 to make the coefficients of e in both equations the same: 1) 5049z - 1990e = 3633 2) 2835z + 2030e = 5390 Now, we can subtract equation (1) from equation (2) to eliminate the e term: 2835z + 2030e - 5049z + 1990e = 5390 - 3633 -2814z = 3407 Now, divide both sides by -2814: z = -3407/2814 Now that we have the value of z, we can substitute it into one of the original equations to find the value of e. We'll use equation (1): 87z - 35e = 63 87(-3407/2814) - 35e = 63 Simplify: -29919/2814 - 35e = 63 Multiply both sides by -2814 to eliminate the fraction: 29919 + 2814(35e) = -2814(63) Simplify: 29919 + 123150e = -18486 Subtract 29919 from both sides: 123150e = -48405 Divide both sides by 123150: e = -48405/123150 ### Answer: z = -3407/2814, e = -48405/123150
Expected answer: {e: 2765/2627, z: 9044/7881}
Correct? No
Problem: To find the values of h and t, solve the following system of simultaneous linear equations: (11 * t) + (44 * h) = 110 (98 * t) - (36 * h) = 18.
Llama 3 8B:
Let's solve the system of simultaneous linear equations. We have two equations: 1) 11t + 44h = 110 2) 98t - 36h = 18 We can solve this system using substitution or elimination. Let's use elimination. First, we can multiply equation (1) by 3 and equation (2) by 1 to make the coefficients of h in both equations the same: 1) 33t + 132h = 330 2) 98t - 36h = 18 Now, we can subtract equation (2) from equation (1) to eliminate h: (33t + 132h) - (98t - 36h) = 330 - 18 33t + 132h - 98t + 36h = 312 -65t + 168h = 312 Now, we can solve for t: -65t = 312 - 168h t = (312 - 168h) / -65 Now that we have the value of t, we can substitute it into one of the original equations to solve for h. Let's use equation (1): 11t + 44h = 110 11((312 - 168h) / -65) + 44h = 110 Simplifying the equation: -66 + 44h + 44h = 110 88h = 176 h = 176 / 88 h = 2 Now that we have the values of h and t, we can substitute them back into the original equations to verify: 1) 11t + 44h = 110 11(312/65) + 44(2) = 110 44 + 88 = 132 ≠110 (Error) 2) 98t - 36h = 18 98(312/65) - 36(2) = 18 176 - 72 = 104 ≠18 (Error) It seems that there is an error in the system of equations. The values of h and t do not satisfy both equations. ### Answer: No solution exists.
Expected answer: {h: 481/214, t: 108/107}
Correct? No
Problem: Solve the following system of linear equations to find the values of b and o: ((69 * b) - (50 * o)) = 55 ((41 * o) + (18 * b)) = 85.
Llama 3 8B:
Let's solve the system of linear equations step by step. First, we can rewrite the equations in standard form: Equation 1: 69b - 50o = 55 Equation 2: 41o + 18b = 85 Next, we can multiply Equation 1 by 41 and Equation 2 by 50 to make the coefficients of o in both equations the same: Equation 1 (multiplied by 41): 2789b - 2050o = 2265 Equation 2 (multiplied by 50): 2050o + 900b = 4250 Now, we can subtract Equation 1 from Equation 2 to eliminate the o variable: (2050o + 900b) - (2789b - 2050o) = 4250 - 2265 900b - 2789b = 4250 - 2265 -1891b = 1985 Now, we can solve for b: -1891b = -1985 b = 1985 / 1891 b ≈ 1.05 Now that we have the value of b, we can substitute it into one of the original equations to solve for o. We'll use Equation 1: 69b - 50o = 55 69(1.05) - 50o = 55 73.5 - 50o = 55 Now, we can solve for o: -50o = -18.5 o = 18.5 / 50 o ≈ 0.37 So, the values of b and o are approximately 1.05 and 0.37, respectively. ### Answer: b ≈ 1.05, o ≈ 0.37
Expected answer: {b: 6505/3729, o: 1625/1243}
Correct? No
Problem: Solve the following system of equations to find the values of p and q: 67 * q - 80 * p = 65, and 6 * q + 5 * p = 177.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of p's in both equations are the same: 1) Multiply the first equation by 5 and the second equation by 80: 5 * (67 * q - 80 * p = 65) => 335q - 400p = 325 80 * (6 * q + 5 * p = 177) => 480q + 400p = 14160 Now, we can subtract the first equation from the second equation to eliminate the p term: (480q + 400p = 14160) - (335q - 400p = 325) => 145q = 14035 Now, we can solve for q: q = 14035 / 145 q = 96.69 (approximately) Now that we have the value of q, we can substitute it into one of the original equations to find the value of p. We'll use the first equation: 67 * q - 80 * p = 65 67 * 96.69 - 80 * p = 65 6493.23 - 80 * p = 65 Now, we can solve for p: p = (6493.23 - 65) / 80 p = 62.69 (approximately) So, the values of p and q are approximately 62.69 and 96.69, respectively. ### Answer: p ≈ 62.69, q ≈ 96.69.
Expected answer: {p: 11469/815, q: 2897/163}
Correct? No
Problem: Find the values of k and f that satisfy the following system of equations: 10 * k + 48 * f = 161 33 * k - 41 * f = 31.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the first equation for k: 10k + 48f = 161 10k = 161 - 48f k = (161 - 48f) / 10 Now, substitute this expression for k into the second equation: 33((161 - 48f) / 10) - 41f = 31 Multiply both sides by 10 to eliminate the fraction: 330 - 1488f + 41f = 310 Combine like terms: -1447f = -20 Divide both sides by -1447: f = 20/1447 Now that we have found f, we can substitute this value back into one of the original equations to find k. We'll use the first equation: 10k + 48(20/1447) = 161 Multiply both sides by 1447 to eliminate the fraction: 14470k + 9600 = 233,332 Subtract 9600 from both sides: 14470k = 225,732 Divide both sides by 14470: k = 225,732 / 14470 k = 15.6 So, the values of k and f that satisfy the system of equations are: k = 15.6 f = 20/1447 ### Answer: k = 15.6, f = 20/1447.
Expected answer: {f: 5003/1994, k: 8089/1994}
Correct? No
Problem: Solve the following system of equations for the values of l and n: The first equation is 31 = 58 * l - n The second equation is 103 = n + 73 * l
Llama 3 8B:
Let's solve the system of equations step by step. First, we can rewrite the first equation as: n = 58l - 31 Now, substitute this expression for n into the second equation: 103 = (58l - 31) + 73l Combine like terms: 103 = 131l - 31 Add 31 to both sides: 134 = 131l Divide both sides by 131: l = 134/131 l = 1.02 Now that we have the value of l, substitute it back into the expression for n: n = 58l - 31 n = 58(1.02) - 31 n = 59.24 - 31 n = 28.24 So, the values of l and n are: l = 1.02 n = 28.24 ### Answer: l = 1.02, n = 28.24
Expected answer: {l: 134/131, n: 3711/131}
Correct? No
Problem: Find the values of y and j that satisfy the following system of equations: 29y - 28j = 39 25y + 37j = 116
Llama 3 8B:
To solve this system of equations, we can use the method of substitution or elimination. Here, we will use the elimination method. First, we will multiply the two equations by necessary multiples such that the coefficients of j's in both equations are the same: 1) Multiply the first equation by 37 and the second equation by 28: 1117y - 1036j = 1431 700y + 1036j = 3248 2) Now, subtract the first equation from the second equation to eliminate j: 700y - 1117y = 3248 - 1431 -417y = 1817 3) Now, divide both sides by -417: y = -1817/417 y = -4.33 4) Now that we have the value of y, substitute it in one of the original equations to find the value of j. We will use the first equation: 29y - 28j = 39 29(-4.33) - 28j = 39 5) Simplify and solve for j: -125.97 - 28j = 39 -28j = 39 + 125.97 -28j = 165.97 j = -165.97/28 j = -5.89 ### Answer: y = -4.33, j = -5.89
Expected answer: {j: 2389/1773, y: 4691/1773}
Correct? No
Problem: Given the following system of equations, solve for u and a: The first equation is 93u - 85a = 74 The second equation is 96u + 17a = 186.
Llama 3 8B:
Let's solve the system of equations. We can start by multiplying the first equation by 17 and the second equation by 85 to make the coefficients of a the same: 1) 1592u - 1425a = 1262 2) 8160u + 1445a = 15830 Now, we can subtract the first equation from the second equation to eliminate the variable a: 8160u - 1592u = 15830 - 1262 6568u = 14568 Now, we can divide both sides by 6568 to solve for u: u = 14568/6568 u = 2.22 Now that we have the value of u, we can substitute it into one of the original equations to solve for a. Let's use the first equation: 93u - 85a = 74 93(2.22) - 85a = 74 209.46 - 85a = 74 Now, we can subtract 74 from both sides and then divide both sides by -85 to solve for a: -85a = -135.46 a = 135.46/85 a = 1.6 ### Answer: u = 2.22, a = 1.6
Expected answer: {a: 3398/3247, u: 1004/573}
Correct? No
Problem: Given the following pair of simultaneous equations, please find out the values of u and g: 97 * u - 61 * g = 15 85 * u + 23 * g = 186
Llama 3 8B:
To solve this system of linear equations, we can use the method of substitution or elimination. Here, we'll use the elimination method. First, we'll multiply both equations by necessary multiples such that the coefficients of g's in both equations are the same: 1) Multiply the first equation by 23: 97u - 61g = 15 Multiply by 23: 2237u - 1387g = 345 2) Multiply the second equation by 61: 85u + 23g = 186 Multiply by 61: 5175u + 1387g = 11346 Now, subtract the first equation from the second equation to eliminate g: 5175u + 1387g - 2237u + 1387g = 11346 - 345 2948u = 11001 Now, divide by 2948: u = 11001/2948 u = 3.73 Now that we have the value of u, substitute it into one of the original equations to find the value of g. We'll use the first equation: 97u - 61g = 15 97(3.73) - 61g = 15 365.21 - 61g = 15 Add 61g to both sides: 365.21 = 15 + 61g Subtract 15 from both sides: 350.21 = 61g Divide by 61: g = 350.21/61 g = 5.74 ### Answer: u = 3.73, g = 5.74
Expected answer: {g: 1863/824, u: 1299/824}
Correct? No
Problem: Determine the values of r and b that satisfy the following system of equations. The first equation is (17 * r) + (67 * b) = 103. The second equation is (85 * r) + (67 * b) = 187.
Llama 3 8B:
Let's solve the system of equations. We can rewrite the system as: 1) 17r + 67b = 103 2) 85r + 67b = 187 Subtracting equation (1) from equation (2), we get: (85r - 17r) + (67b - 67b) = 187 - 103 68r = 84 Dividing both sides by 68, we get: r = 84/68 r = 1.25 Now that we have the value of r, we can substitute it into one of the original equations to solve for b. Let's use equation (1): 17r + 67b = 103 17(1.25) + 67b = 103 17.25 + 67b = 103 Subtracting 17.25 from both sides, we get: 67b = 85.75 Dividing both sides by 67, we get: b = 85.75/67 b = 1.28 ### Answer: r = 1.25, b = 1.28
Expected answer: {b: 82/67, r: 21/17}
Correct? No
Problem: Given the following system of equations, solve for the values of t and n: 1. (85 * n) - (54 * t) = 41 2. (38 * t) + (30 * n) = 126.
Llama 3 8B:
Let's solve the system of equations step by step. From equation (1), we can express n in terms of t: n = (41 + 54t) / 85 Now, substitute this expression for n into equation (2): (38t) + (30((41 + 54t) / 85)) = 126 Simplify the equation: 38t + (1230 + 1620t) / 85 = 126 Multiply both sides by 85 to eliminate the fraction: 3230 + 1620t = 10750 Subtract 3230 from both sides: 1620t = 7530 Divide both sides by 1620: t = 7530 / 1620 t = 4.67 Now that we have the value of t, we can find the value of n: n = (41 + 54(4.67)) / 85 n = (41 + 253.58) / 85 n = 294.58 / 85 n = 3.47 ### Answer: t = 4.67, n = 3.47
Expected answer: {n: 4181/2425, t: 948/485}
Correct? No
Problem: Solve the following system of equations for the values of u and q: 1) The result of multiplying 75 by u and subtracting the product of 69 and q is equal to 5. 2) The sum of the product of 48 and u and the product of 25 and q is 140.
Llama 3 8B:
Let's solve the system of equations step by step. Equation 1: 75u - 69q = 5 Equation 2: 48u + 25q = 140 We can solve Equation 1 for u: u = (5 + 69q) / 75 Now, substitute this expression for u into Equation 2: 48((5 + 69q) / 75) + 25q = 140 Multiply both sides by 75 to eliminate the fraction: 288 + 1032q + 1875q = 10500 Combine like terms: 3007q = 10500 - 288 q = (10500 - 288) / 3007 q ≈ 3.48 Now that we have found q, we can substitute it back into Equation 1 to find u: u = (5 + 69(3.48)) / 75 u ≈ 1.14 ### Answer: u ≈ 1.14, q ≈ 3.48
Expected answer: {q: 180/91, u: 515/273}
Correct? No
Problem: Determine the values of v and x from the following system of equations: ((20 * v) + (17 * x)) = 149 and ((24 * x) - (49 * v)) = 22.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the first equation for v: 20v + 17x = 149 Subtract 17x from both sides: 20v = 149 - 17x Divide both sides by 20: v = (149 - 17x) / 20 Now, substitute this expression for v into the second equation: (24x) - (49((149 - 17x) / 20)) = 22 Multiply both sides by 20 to eliminate the fraction: 480x - 14949 + 935x = 440 Combine like terms: 1415x = 14989 Divide both sides by 1415: x = 14989 / 1415 x = 10.6 Now that we have the value of x, we can substitute it back into the expression for v: v = (149 - 17(10.6)) / 20 v = (149 - 180.2) / 20 v = (-31.2) / 20 v = -1.56 ### Answer: v = -1.56, x = 10.6
Expected answer: {v: 3202/1313, x: 7741/1313}
Correct? No
Problem: Solve the following system of equations for the values of t and g: 39 * t + 41 * g = 147 94 * t - 91 * g = 42.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of g's in both equations are the same: 1) Multiply the first equation by 91: 357t + 371g = 13257 2) Multiply the second equation by 41: 386t - 3731g = 1732 Now, subtract the first equation from the second equation to eliminate the g term: (386t - 357t) - (371g - 371g) = 1732 - 13257 29t = -11525 Now, divide by 29: t = -11525/29 t = -398 Now that we have the value of t, substitute it into one of the original equations to find the value of g. We'll use the first equation: 39t + 41g = 147 39(-398) + 41g = 147 -15342 + 41g = 147 Add 15342 to both sides: 41g = 15342 + 147 41g = 15589 Divide by 41: g = 15589/41 g = 380 ### Answer: t = -398, g = 380
Expected answer: {g: 12180/7403, t: 15099/7403}
Correct? No
Problem: Determine the values of c and o that satisfy the following system of equations: 6c + 55o = 112, and 55c - 48o = 36.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the second equation for c: c = (48o + 36) / 55 Now, substitute this expression for c into the first equation: 6((48o + 36) / 55) + 55o = 112 Multiply both sides by 55 to eliminate the fraction: 108o + 216 + 330o = 6160 Combine like terms: 438o = 5944 Divide both sides by 438: o = 5944 / 438 o = 13.5 Now that we have found o, we can substitute this value back into one of the original equations to find c. We'll use the second equation: 55c - 48(13.5) = 36 55c - 648 = 36 Add 648 to both sides: 55c = 684 Divide both sides by 55: c = 684 / 55 c = 12.4 So, the values of c and o that satisfy the system of equations are: c = 12.4 o = 13.5 ### Answer: c = 12.4, o = 13.5
Expected answer: {c: 7356/3313, o: 5944/3313}
Correct? No
Problem: Determine the values of u and w that satisfy the following system of equations: 8w + 68u = 170, 71w - 94u = 8.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the first equation for w: 8w = 170 - 68u w = (170 - 68u) / 8 Now, substitute this expression for w into the second equation: 71((170 - 68u) / 8) - 94u = 8 Multiply both sides by 8 to eliminate the fraction: 71(170 - 68u) - 94u*8 = 8*8 Expand and simplify: 12170 - 4802u - 752u = 64 Combine like terms: 12170 - 5254u = 64 Add 5254u to both sides: 12170 = 64 + 5254u Subtract 64 from both sides: 12106 = 5254u Divide both sides by 5254: u = 12106 / 5254 u = 2.3 Now that we have found u, we can substitute this value back into one of the original equations to find w. We'll use the first equation: 8w + 68u = 170 8w + 68(2.3) = 170 Multiply 68 by 2.3: 8w + 156.4 = 170 Subtract 156.4 from both sides: 8w = 13.6 Divide both sides by 8: w = 13.6 / 8 w = 1.7 So, the values of u and w that satisfy the system of equations are: u = 2.3 w = 1.7 ### Answer: u = 2.3, w = 1.7
Expected answer: {u: 667/310, w: 459/155}
Correct? No
Problem: Solve the following system of equations for the values of r and f: 68*r + 8*f = 92 97*f + 38*r = 182
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of r's in both equations are the same: 1) Multiply the first equation by 38: 256*r + 304*f = 3508 2) Multiply the second equation by 8: 776*f + 304*r = 1456 Now, subtract the first equation from the second equation to eliminate the r variable: 776*f - 256*r = 1456 - 3508 776*f - 256*r = -3262 Now, add 256*r to both sides: 776*f = -3262 + 256*r Now, divide both sides by 776: f = (-3262 + 256*r) / 776 Now, substitute this expression for f into one of the original equations, say the first equation: 68*r + 8*(-3262 + 256*r) = 92 Expand and simplify: 68*r - 26016 + 2048*r = 92 Combine like terms: 2116*r - 26016 = 92 Add 26016 to both sides: 2116*r = 26008 Divide both sides by 2116: r = 26008 / 2116 r = 12.25 Now that we have the value of r, we can find the value of f by substituting r into the expression we found earlier: f = (-3262 + 256*12.25) / 776 f = (-3262 + 3130) / 776 f = 868 / 776 f = 1.12 ### Answer: r = 12.25, f = 1.12
Expected answer: {f: 2220/1573, r: 1867/1573}
Correct? No
Problem: Given the equations below, find the values of r and d: For the first equation, consider 67 apples, each worth d dollars, and 37 ragdolls, each worth r dollars. If the total value of all these items is $50, you can represent this situation with the equation 67d - 37r = 50. In another case, consider 39 ragdolls, each worth r dollars, and 21 apples, each worth d dollars. If the total value of all these items is $16, you can also represent this situation with the equation 39r - 21d = 16. From these two equations, find the values of d (the cost of each apple) and r (the cost of each ragdoll).
Llama 3 8B:
Let's solve the system of equations. From the first equation, we have: 67d - 37r = 50 From the second equation, we have: 39r - 21d = 16 We can multiply the first equation by 21 and the second equation by 37 to make the coefficients of d equal: 1437d - 1357r = 1070 1439r - 777d = 592 Now, we can subtract the second equation from the first equation to eliminate the r variable: -78d = 478 Dividing both sides by -78, we get: d = -478/78 d = -6.23 Now that we have the value of d, we can substitute it into one of the original equations to find the value of r. Let's use the first equation: 67d - 37r = 50 67(-6.23) - 37r = 50 -416.01 - 37r = 50 Adding 416.01 to both sides: -37r = 466.01 Dividing both sides by -37: r = 466.01/37 r = 12.59 ### Answer: d = -6.23, r = 12.59
Expected answer: {d: 1271/918, r: 1061/918}
Correct? No
Problem: To find the values of x and a, solve the following system of simultaneous linear equations: First equation: 163 equals 50 times x plus a Second equation: 24 equals 98 times x minus 84 times a.
Llama 3 8B:
Let's solve the system of simultaneous linear equations. First equation: 163 = 50x + a Second equation: 24 = 98x - 84a We can solve this system by substituting the expression for a from the first equation into the second equation. Substitute a = 163 - 50x into the second equation: 24 = 98x - 84(163 - 50x) Expand and simplify: 24 = 98x - 13692 + 4200x 24 = 4588x - 13692 Add 13692 to both sides: 13616 = 4588x Divide both sides by 4588: x = 13616/4588 x = 3 Now that we have found x, we can find a by substituting x into the first equation: 163 = 50(3) + a 163 = 150 + a Subtract 150 from both sides: 13 = a So, the values of x and a are: x = 3 a = 13 ### Answer: x = 3, a = 13
Expected answer: {a: 7387/2149, x: 6858/2149}
Correct? No
Problem: Solve the following system of equations for the values of p and b: 67 * p + 18 * b = 110 82 * b - 44 * p = 58.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply both sides of the first equation by 44 to get: 2952p + 792b = 4840 Now, we can multiply both sides of the second equation by 67 to get: 5494b - 2952p = 3866 Now, we can add both equations to eliminate the p variable: 5494b + 792b = 4840 + 3866 6286b = 8716 Now, we can divide both sides by 6286 to solve for b: b = 8716/6286 b = 1.4 Now that we have the value of b, we can substitute it into one of the original equations to solve for p. We'll use the first equation: 67p + 18(1.4) = 110 67p + 25.2 = 110 Subtract 25.2 from both sides: 67p = 84.8 Divide both sides by 67: p = 84.8/67 p = 1.26 So, the values of p and b are: p = 1.26 b = 1.4 ### Answer: p = 1.26, b = 1.4
Expected answer: {b: 4363/3143, p: 3988/3143}
Correct? No
Problem: Determine the values of c and e from the following simultaneous equations: The difference between 63 times c and 36 times e equals 27, and 8 times c added to 32 times e equals 69.
Llama 3 8B:
Let's solve the system of equations step by step. The first equation is: 63c - 36e = 27 The second equation is: 8c + 32e = 69 We can solve this system of equations by substitution or elimination. Let's use elimination. First, we can multiply the two equations by necessary multiples such that the coefficients of e's in both equations are the same: 1) Multiply the first equation by 4: 252c - 144e = 108 2) Multiply the second equation by 3: 24c + 96e = 207 Now, subtract the first equation from the second equation to eliminate e: (24c + 96e) - (252c - 144e) = 207 - 108 24c + 96e - 252c + 144e = 99 -228c = 99 Now, divide by -228: c = -99/228 c = -27/76 Now that we have the value of c, we can substitute it into one of the original equations to find the value of e. We'll use the first equation: 63c - 36e = 27 Substitute c = -27/76: 63(-27/76) - 36e = 27 Simplify: -1965/76 - 36e = 27 Multiply both sides by -76 to eliminate the fraction: -1965 - 2736e = -76*27 Add 1965 to both sides: -2736e = -1103 Divide by -2736: e = 1103/2736 e = 1103/2736 ### Answer: c = -27/76, e = 1103/2736.
Expected answer: {c: 93/64, e: 459/256}
Correct? No
Problem: Solve the following system of linear equations to find the values of x and p: 26 * x + 29 * p = 107 61 * x - 51 * p = 4
Llama 3 8B:
To solve this system of linear equations, we can use the method of substitution or elimination. Here, we will use the elimination method. First, we will multiply both equations by necessary multiples such that the coefficients of p's in both equations are the same: 1) Multiply the first equation by 51: 51 * 26 * x + 51 * 29 * p = 51 * 107 2) Multiply the second equation by 29: 29 * 61 * x - 29 * 51 * p = 29 * 4 Now, subtract the second equation from the first equation to eliminate p: (51 * 26 * x - 29 * 61 * x) + (51 * 29 * p - 29 * 51 * p) = 51 * 107 - 29 * 4 Simplify the equation: 23 * x = 51 * 107 - 29 * 4 x = (51 * 107 - 29 * 4) / 23 x = 53 Now that we have the value of x, we can substitute it into one of the original equations to find the value of p. We will use the first equation: 26 * x + 29 * p = 107 26 * 53 + 29 * p = 107 1378 + 29 * p = 107 29 * p = -1271 p = -1271 / 29 p = -43.7 ### Answer: x = 53, p = -43.7
Expected answer: {p: 6423/3095, x: 5573/3095}
Correct? No
Problem: Find the values for g and l from the system of equations below. The first equation is: ((29 * l) + (17 * g)) = 68. The second equation is: ((31 * g) - (10 * l)) = 17.
Llama 3 8B:
Let's solve the system of equations step by step. From the second equation, we can express g in terms of l: g = (17 + 10l) / 31 Now, substitute this expression for g into the first equation: ((29 * l) + (17 * ((17 + 10l) / 31))) = 68 Simplify the equation: ((29 * l) + (17 * (17/31 + 10l/31))) = 68 Combine like terms: ((29 * l) + (17 * 17/31) + (17 * 10l/31)) = 68 Simplify further: (29l + 17 + 10l) = 68 Combine like terms: 39l + 17 = 68 Subtract 17 from both sides: 39l = 51 Divide both sides by 39: l = 51/39 l = 1.3077 (approximately) Now that we have the value of l, we can find the value of g: g = (17 + 10(1.3077)) / 31 g ≈ 2.3459 ### Answer: g ≈ 2.3459, l ≈ 1.3077.
Expected answer: {g: 1173/1069, l: 1819/1069}
Correct? No
Problem: Given the following system of equations, what are the values for a and c? 33*a - 54*c = 20 24*a - 26*c = 29.
Llama 3 8B:
We can solve this system of equations by multiplying the two equations by necessary multiples such that the coefficients of c's in both equations are the same. First, multiply the first equation by 26 and the second equation by 54: 104*a - 702*c = 520 1312*a - 1428*c = 1581 Now, subtract the first equation from the second equation to eliminate c: 1208*a = 1061 Now, divide by 1208: a = 1061/1208 a = 0.88 Now that we have the value of a, substitute it into one of the original equations to find the value of c. We'll use the first equation: 33*a - 54*c = 20 33*(0.88) - 54*c = 20 33*0.88 - 54*c = 20 29.04 - 54*c = 20 Subtract 20 from both sides: 29.04 - 54*c - 20 = 0 -54*c = -9.04 Divide by -54: c = 9.04/54 c = 0.17 ### Answer: a = 0.88, c = 0.17
Expected answer: {a: 523/219, c: 159/146}
Correct? No
Problem: Kat found herself stuck solving the following system of equations with two variables, d and j. Can you help her resolve it? 71d + 9j = 132 43j - 84d = 91.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of d's in both equations are the same: 1) Multiply the first equation by 84: 84(71d + 9j = 132) => 5884d + 756j = 11088 2) Multiply the second equation by 1: 43j - 84d = 91 => 43j - 84d = 91 Now, we can subtract the second equation from the first equation to eliminate the d variable: (5884d + 756j = 11088) - (43j - 84d = 91) 5884d + 756j - 43j + 84d = 11088 - 91 5927d + 713j = 11097 Now, we can solve for j: 713j = 11097 - 5927d j = (11097 - 5927d) / 713 Now that we have the expression for j, we can substitute it into one of the original equations to solve for d. Let's use the first equation: 71d + 9j = 132 71d + 9((11097 - 5927d) / 713) = 132 Now, we can simplify the equation: 71d + 9((11097 - 5927d) / 713) = 132 71d + 9((11097 - 5927d) / 713) = 132 71d + 9(11097 / 713 - 5927d / 713) = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132 71d + 99 - 5927d / 713 = 132
Expected answer: {d: 4857/3809, j: 17549/3809}
Correct? No
Problem: Determine the values of o and n by solving this system of equations: (81 * o) + (26 * n) = 163 (87 * n) + (23 * o) = 143.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the first equation for o: (81 * o) = 163 - (26 * n) o = (163 - (26 * n)) / 81 Now, substitute this expression for o into the second equation: (87 * n) + (23 * ((163 - (26 * n)) / 81)) = 143 Simplify the equation: (87 * n) + (23 * (163 - (26 * n))) / 81 = 143 Multiply both sides by 81 to eliminate the fraction: (87 * n * 81) + (23 * (163 - (26 * n))) = 143 * 81 Expand and simplify: 7293n + 23(163 - 26n) = 11643 Distribute the 23: 7293n + 23(163) - 23(26n) = 11643 Combine like terms: 7293n + 3751 - 598n = 11643 Combine the terms with n: 5995n = 7902 Divide both sides by 5995: n = 7902 / 5995 n = 1.32 Now that we have found n, we can substitute it back into one of the original equations to find o. We'll use the first equation: (81 * o) + (26 * 1.32) = 163 (81 * o) + 34.32 = 163 Subtract 34.32 from both sides: (81 * o) = 128.68 Divide both sides by 81: o = 128.68 / 81 o = 1.59 So, the values of o and n are: o = 1.59 n = 1.32 ### Answer: o = 1.59, n = 1.32
Expected answer: {n: 7834/6449, o: 10463/6449}
Correct? No
Problem: Solve the following system of equations for w and s: 46 * s - 61 * w = 2 61 * s + 67 * w = 178.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of w's in both equations are the same: 1) Multiply the first equation by 67: 67 * (46 * s - 61 * w) = 67 * 2 2) Multiply the second equation by 61: 61 * (61 * s + 67 * w) = 61 * 178 Now, we can simplify and rewrite the equations: 1) 67 * 46 * s - 67 * 61 * w = 134 2) 61 * 61 * s + 61 * 67 * w = 10938 Now, we can subtract the first equation from the second equation to eliminate w: (61 * 61 * s + 61 * 67 * w) - (67 * 46 * s - 67 * 61 * w) = 10938 - 134 61 * 61 * s + 61 * 67 * w - 67 * 46 * s + 67 * 61 * w = 10904 Combine like terms: (61 * 61 - 67 * 46) * s = 10904 3721 * s = 10904 Now, divide by 3721: s = 10904 / 3721 s = 2.93 Now that we have the value of s, we can substitute it into one of the original equations to find the value of w. We'll use the first equation: 46 * s - 61 * w = 2 46 * 2.93 - 61 * w = 2 Simplify: 135.78 - 61 * w = 2 Subtract 135.78 from both sides: -61 * w = -133.78 Divide by -61: w = 133.78 / 61 w = 2.20 So, the values of w and s are approximately 2.20 and 2.93, respectively. ### Answer: w ≈ 2.20, s ≈ 2.93.
Expected answer: {s: 10992/6803, w: 8066/6803}
Correct? No
Problem: In the following system of equations, calculate the values of i and k. System of equations: 51*k - 8*i = 86 39*i + 8*k = 193.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of i's in both equations are the same: 1) Multiply the first equation by 39: 195*k - 312*i = 3396 2) Multiply the second equation by 51: 1977*i + 408*k = 9843 Now, subtract the first equation from the second equation to eliminate the i term: (1977*i - 195*k) + 408*k = 9843 - 3396 1977*i + 213*k = 6447 Now, we can solve for i: i = (6447 - 213*k) / 1977 Now, substitute this expression for i into one of the original equations. We'll use the first equation: 51*k - 8*((6447 - 213*k) / 1977) = 86 Simplify the equation: 51*k - 32.4 + 16.76*k = 86 Combine like terms: 67.76*k = 118.6 Divide by 67.76: k = 1.75 Now that we have the value of k, we can find the value of i: i = (6447 - 213*1.75) / 1977 i = 6447 - 369.25 i = 6077.75 / 1977 i = 3.07 ### Answer: i = 3.07, k = 1.75
Expected answer: {i: 9155/2053, k: 4898/2053}
Correct? No
Problem: Solve the following system of equations for the values of l and m: 26m + 17l = 146 93m + l = 126
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the second equation for l: l = 126 - 93m Now, substitute this expression for l into the first equation: 26m + 17(126 - 93m) = 146 Expand and simplify: 26m + 2106 - 1593m = 146 Combine like terms: -1567m = -1960 Divide by -1567: m = 1960/1567 m ≈ 1.25 Now that we have found m, we can find l by substituting m back into one of the original equations. We'll use the second equation: l = 126 - 93(1.25) l = 126 - 116.25 l ≈ 9.75 So, the values of l and m are approximately: l ≈ 9.75 m ≈ 1.25 ### Answer: l ≈ 9.75, m ≈ 1.25
Expected answer: {l: 10302/1555, m: 1996/1555}
Correct? No
Problem: Determine the values of 'h' and 'f' by solving the following system of equations: 1) (8 * f) + (39 * h) = 66 2) (29 * f) + (46 * h) = 119
Llama 3 8B:
Let's solve the system of equations step by step. We have two equations: 1) (8 * f) + (39 * h) = 66 2) (29 * f) + (46 * h) = 119 We can solve this system of equations using substitution or elimination. Let's use elimination. First, we can multiply equation (1) by 29 and equation (2) by 8 to make the coefficients of 'f' in both equations the same: 29(1) => 232f + 1131h = 1914 8(2) => 232f + 368h = 952 Now, subtract equation (2) from equation (1) to eliminate 'f': (1914 - 952)h = 1914 - 952 962h = 962 Now, divide both sides by 962: h = 1 Now that we have the value of 'h', we can substitute it into one of the original equations to find the value of 'f'. Let's use equation (1): (8 * f) + (39 * 1) = 66 8f + 39 = 66 Subtract 39 from both sides: 8f = 27 Divide both sides by 8: f = 27/8 f = 3.375 ### Answer: h = 1, f = 3.375
Expected answer: {f: 1605/763, h: 962/763}
Correct? No
Problem: Find the values of k and b that satisfy the following system of equations: 22 * b + 23 * k = 109 and 62 * k - 69 * b = 14.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the first equation for k: k = (109 - 22b) / 23 Now, substitute this expression for k into the second equation: 62((109 - 22b) / 23) - 69b = 14 Multiply both sides by 23 to eliminate the fraction: 1462 - 1032b - 1557b = 322 Combine like terms: -2588b = -1140 Divide both sides by -2588: b = 1140 / 2588 b ≈ 0.44 Now that we have found b, we can substitute it back into one of the original equations to find k. We'll use the first equation: 22b + 23k = 109 22(0.44) + 23k = 109 9.68 + 23k = 109 Subtract 9.68 from both sides: 23k = 99.32 Divide both sides by 23: k = 99.32 / 23 k ≈ 4.31 So, the values of k and b that satisfy the system of equations are: k ≈ 4.31 b ≈ 0.44 ### Answer: k ≈ 4.31, b ≈ 0.44.
Expected answer: {b: 6436/2951, k: 7829/2951}
Correct? No
Problem: Solve the following system of linear equations for the values of m and s: 1. 84m - 55s = 1 2. 63m - 2s = 98.
Llama 3 8B:
Let's solve the system of linear equations step by step. First, we can multiply equation (2) by 2 to make the coefficients of s in both equations the same: 2. 126m - 4s = 196 Now we can subtract equation (1) from equation (2) to eliminate the s variable: (126m - 4s) - (84m - 55s) = 196 - 1 42m + 51s = 195 Next, we can multiply equation (1) by 63 to make the coefficients of m in both equations the same: 1. 5292m - 3465s = 63 Now we can subtract equation (1) from equation (2) to eliminate the m variable: (126m - 4s) - (5292m - 3465s) = 196 - 63 -5166m + 3461s = 133 Now we have a system of two equations with two variables: 42m + 51s = 195 -5166m + 3461s = 133 We can solve this system using substitution or elimination. Let's use elimination. We can multiply equation (1) by 3461 and equation (2) by 51 to make the coefficients of s in both equations the same: 1. 145422m - 178355s = 67815 2. -26346m + 17531s = 8333 Now we can subtract equation (1) from equation (2) to eliminate the s variable: (145422m - 178355s) - (-26346m + 17531s) = 67815 - 8333 171768m = 49582 Now we can solve for m: m = 49582 / 171768 m = 0.288 Now that we have the value of m, we can substitute it into one of the original equations to solve for s. Let's use equation (1): 84m - 55s = 1 84(0.288) - 55s = 1 23.52 - 55s = 1 Now we can solve for s: s = (1 - 23.52) / -55 s = -22.52 / -55 s = 0.408 ### Answer: m = 0.288, s = 0.408
Expected answer: {m: 1796/1099, s: 389/157}
Correct? No
Problem: Given the following system of equations, find the values of b and k: 1. (6 * b) + (5 * k) = 105 2. (95 * k) - (51 * b) = 67.
Llama 3 8B:
Let's solve the system of equations step by step. From the first equation, we can express b in terms of k: 6b + 5k = 105 6b = 105 - 5k b = (105 - 5k) / 6 Now, substitute this expression for b into the second equation: 95k - 51((105 - 5k) / 6) = 67 Multiply both sides by 6 to eliminate the fraction: 570k - 51(105 - 5k) = 402 Expand and simplify: 570k - 5335 + 255k = 402 825k - 5335 = 402 Add 5335 to both sides: 825k = 6037 Divide by 825: k = 6037 / 825 k = 7.33 Now that we have found k, we can find b by substituting k back into one of the original equations. We'll use the first equation: 6b + 5k = 105 6b + 5(7.33) = 105 Multiply 5 by 7.33: 6b + 36.65 = 105 Subtract 36.65 from both sides: 6b = 68.35 Divide by 6: b = 68.35 / 6 b = 11.39 ### Answer: b = 11.39, k = 7.33
Expected answer: {b: 1928/165, k: 1919/275}
Correct? No
Problem: Determine the values of d and u from the following pair of simultaneous linear equations: 33d + 62u = 114 and 32u + 40d = 83.
Llama 3 8B:
Let's solve the system of linear equations using substitution or elimination method. First, we can multiply the two equations by necessary multiples such that the coefficients of d's in both equations are the same: 1) Multiply the first equation by 40 and the second equation by 62: 1320d + 3860u = 4560 1984u + 2480d = 5118 2) Subtract the second equation from the first equation to eliminate d: 1320d - 1984u = 4560 - 5118 -1320d + 1984u = -5518 3) Simplify the equation: -1320d + 1984u = -5518 4) Now, we can solve for u: u = (-5518 + 1320d) / 1984 5) Substitute the expression of u into one of the original equations, say the first equation: 33d + 62(((-5518 + 1320d) / 1984)) = 114 6) Simplify the equation: 33d + 62((-5518 / 1984) + (1320d / 1984)) = 114 7) Simplify further: 33d - 5518/31 + 1320d/31 = 114 8) Combine like terms: 33d + 1320d/31 - 5518/31 = 114 9) Simplify: (33 + 1320/31)d - 5518/31 = 114 10) Add 5518/31 to both sides: (33 + 1320/31)d = 114 + 5518/31 11) Simplify: (33 + 1320/31)d = 6326/31 12) Multiply both sides by 31: (33 + 1320/31)d*31 = 6326/31*31 13) Simplify: 33d + 1320d = 6326 14) Combine like terms: 1353d = 6326 15) Divide both sides by 1353: d = 6326/1353 16) Now that we have the value of d, substitute it into the expression of u: u = (-5518 + 1320d) / 1984 u = (-5518 + 1320(6326/1353)) / 1984 u = (-5518 + 8328) / 1984 u = 2810 / 1984 17) Simplify: u = 1.42 So, the values of d and u are: d = 6326/1353 ≈ 4.65 u = 1.42 ### Answer: d ≈ 4.65, u ≈ 1.42.
Expected answer: {d: 749/712, u: 1821/1424}
Correct? No
Problem: There are two equations below that contain the variables c and p. Can you solve this system of equations to find the values of c and p? 5 * c + 28 * p = 102 20 * c - 67 * p = 13
Llama 3 8B:
Let's solve the system of equations. First, we can multiply the second equation by 5 to make the coefficients of p in both equations the same: 100c - 335p = 65 Now, we can add the two equations to eliminate the p variable: 5c + 28p = 102 100c - 335p = 65 Adding the two equations, we get: 105c = 167 Now, we can solve for c: c = 167/105 c = 1.57 (approximately) Now that we have the value of c, we can substitute it into one of the original equations to solve for p. We'll use the first equation: 5c + 28p = 102 Substituting c = 1.57, we get: 5(1.57) + 28p = 102 Simplifying, we get: 7.85 + 28p = 102 Subtracting 7.85 from both sides, we get: 28p = 94.15 Dividing both sides by 28, we get: p = 94.15/28 p = 3.36 (approximately) ### Answer: c ≈ 1.57, p ≈ 3.36
Expected answer: {c: 7198/895, p: 395/179}
Correct? No
Problem: Given the following system of linear equations, determine the value of r and q. The system of equations is: 58 * r + 12 * q = 147 97 * q - 76 * r = 76.
Llama 3 8B:
Let's solve the system of linear equations. We can start by multiplying the two equations by necessary multiples such that the coefficients of r's in both equations are the same: 1) Multiply the first equation by 76: 44r + 912q = 11208 2) Multiply the second equation by 58: 568q - 4484r = 4424 Now, add both equations to eliminate the r term: (44r + 912q) + (568q - 4484r) = 11208 + 4424 912q + 568q = 11208 + 4424 1480q = 15632 Now, divide by 1480: q = 15632/1480 q = 10.53 Now that we have the value of q, we can substitute it into one of the original equations to find the value of r. We'll use the first equation: 58r + 12q = 147 58r + 12(10.53) = 147 58r + 126.36 = 147 Subtract 126.36 from both sides: 58r = 20.64 Divide by 58: r = 20.64/58 r = 0.357 ### Answer: r = 0.357, q = 10.53
Expected answer: {q: 7790/3269, r: 13347/6538}
Correct? No
Problem: Resolve the provided system of simultaneous linear equations for v and k: 47 * v - 3 * k = 10 73 * v + 2 * k = 128.
Llama 3 8B:
Let's solve the system of simultaneous linear equations. We have: 1) 47v - 3k = 10 ... (Equation 1) 2) 73v + 2k = 128 ... (Equation 2) We can solve this system using the method of substitution or elimination. Here, we'll use the elimination method. First, we'll multiply Equation 1 by 2 and Equation 2 by 3 to make the coefficients of k in both equations the same: 1) 94v - 6k = 20 ... (Equation 1 multiplied by 2) 2) 219v + 6k = 384 ... (Equation 2 multiplied by 3) Now, we'll subtract Equation 1 from Equation 2 to eliminate k: (219v + 6k) - (94v - 6k) = 384 - 20 225v = 364 Now, we'll solve for v: v = 364/225 v = 52/29 v = 1.793 (approximately) Now that we have the value of v, we can substitute it into one of the original equations to find the value of k. We'll use Equation 1: 47v - 3k = 10 47(1.793) - 3k = 10 83.531 - 3k = 10 Now, we'll solve for k: -3k = -73.531 k = 73.531/3 k = 24.510 (approximately) So, the values of v and k are approximately 1.793 and 24.510, respectively. ### Answer: v ≈ 1.793, k ≈ 24.510.
Expected answer: {k: 5286/313, v: 404/313}
Correct? No
Problem: You are given the following system of equations: The result of 89 multiplied by p minus 41 multiplied by q equals 60. The result of 27 multiplied by p plus 91 multiplied by q equals 124. What are the values of p and q?
Llama 3 8B:
Let's solve the system of equations. We have: 1) 89p - 41q = 60 2) 27p + 91q = 124 We can solve this system of equations using substitution or elimination. Let's use elimination. First, we can multiply equation (1) by 41 and equation (2) by 89 to make the coefficients of q in both equations the same: 1) 3647p - 1681q = 2460 2) 2397p + 8039q = 10976 Now, we can subtract equation (1) from equation (2) to eliminate q: 2397p + 8039q - 3647p + 1681q = 10976 - 2460 775p = 8426 Now, we can solve for p: p = 8426/775 p = 10.9 Now that we have the value of p, we can substitute it into one of the original equations to solve for q. Let's use equation (1): 89p - 41q = 60 89(10.9) - 41q = 60 969.1 - 41q = 60 Now, we can solve for q: -41q = -909.1 q = 909.1/41 q = 22.2 So, the values of p and q are: p = 10.9 q = 22.2 ### Answer: p = 10.9, q = 22.2
Expected answer: {p: 5272/4603, q: 4708/4603}
Correct? No
Problem: Find the values of u and d that make these equations true: The first equation is: (88 * u) - (96 * d) = 12 The second equation is: (27 * u) + (36 * d) = 71
Llama 3 8B:
Let's solve the system of equations. From the first equation, we can express u in terms of d: u = (12 + 96d) / 88 Now, substitute this expression for u into the second equation: (27((12 + 96d) / 88)) + (36d) = 71 Simplify the equation: (27(12 + 96d) / 88) + 36d = 71 Multiply both sides by 88 to eliminate the fraction: 243 + 2592d + 3168d = 6232 Combine like terms: 4520d = 3989 Divide both sides by 4520: d = 3989 / 4520 d = 0.882 Now that we have found d, we can find u: u = (12 + 96(0.882)) / 88 u = (12 + 85.248) / 88 u = 97.248 / 88 u = 1.104 ### Answer: u = 1.104, d = 0.882
Expected answer: {d: 1481/1440, u: 151/120}
Correct? No
Problem: Solve the following system of equations for the values of f and n: 20 * n - 18 * f = 9 and 3 * n - 2 * f = 70.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of f's in both equations are the same: 1) Multiply the first equation by 2: 40n - 36f = 18 2) Multiply the second equation by 18: 54n - 36f = 1260 Now, subtract the first equation from the second equation to eliminate f: (54n - 40n) - (36f - 36f) = 1260 - 18 14n = 1242 Now, divide by 14: n = 1242/14 n = 89 Now that we have the value of n, substitute it into one of the original equations to find the value of f. We'll use the first equation: 20n - 18f = 9 20(89) - 18f = 9 1780 - 18f = 9 Subtract 1780 from both sides: -18f = -1771 f = 1771/(-18) f = -98.5 ### Answer: f = -98.5, n = 89.
Expected answer: {f: 1373/14, n: 621/7}
Correct? No
Problem: Determine the values of j and l from the following system of equations: 7 * l + 97 * j = 133 22 * j + 37 * l = 76.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the first equation for l: l = (133 - 97j) / 7 Now, substitute this expression for l into the second equation: 22j + 37((133 - 97j) / 7) = 76 Multiply both sides of the equation by 7 to eliminate the fraction: 154j + 37(133 - 97j) = 532 Expand and simplify the equation: 154j + 4933 - 3577j = 532 Combine like terms: -2103j = -4401 Divide both sides by -2103: j = 4401 / 2103 j = 2 Now that we have found j, we can find l by substituting j into one of the original equations. We'll use the first equation: 7l + 97(2) = 133 7l + 194 = 133 Subtract 194 from both sides: 7l = -61 Divide both sides by 7: l = -61/7 l = -8.71 (rounded to two decimal places) ### Answer: j = 2, l = -8.71.
Expected answer: {j: 1463/1145, l: 1482/1145}
Correct? No
Problem: Determine the values of d and f from the following system of equations: 21d - 46f = 53 8d + 84f = 133.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of f's in both equations are the same: 1) Multiply the first equation by 84: 168d - 3884f = 4428 2) Multiply the second equation by 46: 368d + 3864f = 6118 Now, subtract the first equation from the second equation to eliminate f: (368d + 3864f) - (168d - 3884f) = 6118 - 4428 368d + 3864f - 168d + 3884f = 6118 - 4428 200d + 7748f = 1690 Now, divide both sides by 200: d + 38.74f = 8.45 Now, substitute this expression for d into one of the original equations. We'll use the first equation: 21d - 46f = 53 21(d + 38.74f) - 46f = 53 21(8.45) - 46f = 53 177.45 - 46f = 53 Now, subtract 53 from both sides: 177.45 - 46f - 53 = 0 -46f = -25.55 Now, divide both sides by -46: f = 25.55/46 f = 0.55 Now that we have found f, we can substitute it back into the expression for d: d + 38.74f = 8.45 d + 38.74(0.55) = 8.45 d + 21.29 = 8.45 d = 8.45 - 21.29 d = -12.84 ### Answer: d = -12.84, f = 0.55
Expected answer: {d: 5285/1066, f: 2369/2132}
Correct? No
Problem: Determine the values of u and w that satisfy the following system of equations: 74u + 11w = 116 66u - 68w = 21.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of w's in both equations are the same: 1) Multiply the first equation by 68 and the second equation by 11: 476u + 748w = 7936 726u - 748w = 231 2) Now, add both equations to eliminate w: 1102u = 8167 3) Divide by 1102: u = 8167/1102 u = 7.4 4) Now that we have the value of u, substitute it into one of the original equations to find the value of w. We'll use the first equation: 74u + 11w = 116 74(7.4) + 11w = 116 551 + 11w = 116 5) Subtract 551 from both sides: 11w = -435 6) Divide by 11: w = -435/11 w = -39.5 So, the values of u and w that satisfy the system of equations are: u = 7.4 w = -39.5 ### Answer: u = 7.4, w = -39.5
Expected answer: {u: 8119/5758, w: 3051/2879}
Correct? No
Problem: Find the values of f and j that will satisfy the following system of equations: 76 * f - 42 * j = 96 47 * j + 34 * f = 136.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the first equation for f: 76f - 42j = 96 76f = 96 + 42j f = (96 + 42j) / 76 Now, substitute this expression for f into the second equation: 47j + 34((96 + 42j) / 76) = 136 Multiply both sides by 76 to eliminate the fraction: 2827j + 2856 + 1272j = 10304 Combine like terms: 2549j = 7468 Divide both sides by 2549: j = 7468 / 2549 j = 2.93 (approximately) Now that we have found j, we can substitute it back into one of the original equations to find f. We'll use the first equation: 76f - 42(2.93) = 96 Simplify: 76f - 124.86 = 96 Add 124.86 to both sides: 76f = 220.86 Divide both sides by 76: f = 220.86 / 76 f = 2.91 (approximately) ### Answer: f ≈ 2.91, j ≈ 2.93.
Expected answer: {f: 1278/625, j: 884/625}
Correct? No
Problem: Consider the following system of equations. Find the values of u and e: 68u + 32e = 174 63e - 69u = 1.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the second equation for e: e = (1 + 69u) / 63 Now, substitute this expression for e into the first equation: 68u + 32((1 + 69u) / 63) = 174 Multiply both sides by 63 to eliminate the fraction: 4256u + 2048 = 10872 Subtract 2048 from both sides: 4256u = 8824 Divide both sides by 4256: u = 8824 / 4256 u = 2 Now that we have found u, we can find e by substituting u back into one of the original equations. We'll use the second equation: e = (1 + 69(2)) / 63 e = (1 + 138) / 63 e = 139 / 63 e = 13/7 ### Answer: u = 2, e = 13/7
Expected answer: {e: 6037/3246, u: 5465/3246}
Correct? No
Problem: Find the values of p and n that satisfy the following system of linear equations: 57p + 4n = 129 and 24p + 39n = 154.
Llama 3 8B:
We can solve this system of linear equations using the method of substitution or elimination. Here, we will use the elimination method. First, we will multiply the two equations by necessary multiples such that the coefficients of n's in both equations are the same: 1) Multiply the first equation by 39 and the second equation by 4: 195p + 156n = 5013 96p + 156n = 616 Now, subtract the second equation from the first equation to eliminate n: 195p - 96p = 5013 - 616 99p = 4397 Now, divide by 99: p = 4397/99 p = 44 Now that we have the value of p, substitute it in one of the original equations to find the value of n. We will use the first equation: 57p + 4n = 129 57(44) + 4n = 129 2512 + 4n = 129 Subtract 2512 from both sides: 4n = -2383 n = -2383/4 n = -599.25 ### Answer: p = 44, n = -599.25
Expected answer: {n: 1894/709, p: 4415/2127}
Correct? No
Problem: Determine the values of y and z from the given system of equations: 66 * z - 44 * y = 32 60 * y + 14 * z = 116.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the second equation for y: 60y + 14z = 116 60y = 116 - 14z y = (116 - 14z) / 60 Now, substitute this expression for y into the first equation: 66z - 44((116 - 14z) / 60) = 32 Multiply both sides by 60 to eliminate the fraction: 3960z - 2640(116 - 14z) = 1920 Expand and simplify: 3960z - 307200 + 37120z = 1920 46780z = 308320 Divide both sides by 46780: z = 308320 / 46780 z = 6.6 Now that we have found z, we can substitute it back into one of the original equations to find y. We'll use the second equation: 60y + 14(6.6) = 116 60y + 92.4 = 116 Subtract 92.4 from both sides: 60y = 23.6 Divide both sides by 60: y = 23.6 / 60 y = 0.39 ### Answer: y = 0.39, z = 6.6
Expected answer: {y: 901/572, z: 439/286}
Correct? No
Problem: Solve the following system of equations for the variables t and h: The first equation is 83 * t - 58 * h = 45. The second equation is 69 * h + 11 * t = 124.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply both sides of the first equation by 58 to get: 83t = 45 + 58h Next, we can multiply both sides of the second equation by 11 to get: 769h + 121t = 1374 Now, we can subtract the first equation from the second equation to eliminate the h variable: 769h - 83t = 1374 - 45 = 1329 Now, we can divide both sides by 83 to get: h = (1329 - 83t) / 769 Now, we can substitute this expression for h into one of the original equations. Let's use the first equation: 83t - 58((1329 - 83t) / 769) = 45 To simplify this equation, we can multiply both sides by 769 to get rid of the fraction: 61957 - 9764t = 34965 Next, we can subtract 34965 from both sides to get: -26992 = -9764t Finally, we can divide both sides by -9764 to solve for t: t = 26992 / 9764 = 2.77 Now that we have found t, we can substitute this value back into one of the original equations to find h. Let's use the second equation: 69h + 11(2.77) = 124 To solve for h, we can subtract 30.67 from both sides: 69h = 93.33 Finally, we can divide both sides by 69 to solve for h: h = 93.33 / 69 = 1.35 ### Answer: t = 2.77, h = 1.35
Expected answer: {h: 9797/6365, t: 10297/6365}
Correct? No
Problem: Given the system of equations ((79 * h) - (61 * o)) = 9 and ((16 * h) - (12 * o)) = 9, what are the values of o and h?
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the second equation for h: h = (12 * o + 9) / 16 Now, substitute this expression for h into the first equation: (79 * ((12 * o + 9) / 16)) - (61 * o) = 9 Simplify the equation: (946.5 * o + 693) - 61 * o = 9 Combine like terms: 885.5 * o = -684 Divide both sides by 885.5: o = -684 / 885.5 o ≈ -0.77 Now that we have the value of o, substitute it back into the expression for h: h = (12 * (-0.77) + 9) / 16 h = (-9.24 + 9) / 16 h = 0.76 / 16 h ≈ 0.0475 So, the values of o and h are approximately o ≈ -0.77 and h ≈ 0.0475. ### Answer: o ≈ -0.77, h ≈ 0.0475.
Expected answer: {h: 63/4, o: 81/4}
Correct? No
Problem: Solve for variables s and y when the following system of equations is satisfied: 4 * y + 56 * s = 139 65 * y - 90 * s = 16
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the first equation for s: s = (139 - 4y) / 56 Now, substitute this expression for s into the second equation: 65y - 90((139 - 4y) / 56) = 16 Multiply both sides by 56 to eliminate the fraction: 65y - 90(139 - 4y) = 16 * 56 Expand and simplify: 65y - 12570 + 360y = 896 Combine like terms: 425y = 12590 Divide by 425: y = 12590 / 425 y = 29.5 Now that we have found y, substitute it back into one of the original equations to find s. We'll use the first equation: 4 * 29.5 + 56 * s = 139 Expand and simplify: 117 + 56s = 139 Subtract 117 from both sides: 56s = 22 Divide by 56: s = 22 / 56 s = 0.4 ### Answer: s = 0.4, y = 29.5
Expected answer: {s: 8971/4000, y: 6703/2000}
Correct? No
Problem: Solve the following pair of simultaneous equations: 42 * d - 4 * z = 75 40 * d + 45 * z = 162 Find the values of d and z.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of z's in both equations are the same: 1) Multiply the first equation by 45: 1825d - 180z = 3375 2) Multiply the second equation by 4: 160d + 180z = 648 Now, subtract the first equation from the second equation to eliminate z: (160d + 180z) - (1825d - 180z) = 648 - 3375 160d - 1825d = 648 - 3375 -1665d = -2727 d = 2727/1665 d = 1.64 Now that we have the value of d, we can substitute it into one of the original equations to find the value of z. We'll use the first equation: 42d - 4z = 75 42(1.64) - 4z = 75 67.68 - 4z = 75 -4z = 75 - 67.68 -4z = 7.32 z = -7.32/4 z = -1.83 ### Answer: d = 1.64, z = -1.83
Expected answer: {d: 4023/2050, z: 1902/1025}
Correct? No
Problem: Determine the values of 'a' and 'o' from the following system of equations: (42 * o) + (24 * a) = 142 (42 * a) + (6 * o) = 75.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the second equation for 'a': (42 * a) + (6 * o) = 75 42 * a = 75 - 6 * o a = (75 - 6 * o) / 42 Now, substitute this expression for 'a' into the first equation: (42 * o) + (24 * ((75 - 6 * o) / 42)) = 142 Simplify the equation: 42 * o + 24 * ((75 - 6 * o) / 42) = 142 42 * o + 24 * (75 / 42 - 6 * o / 42) = 142 42 * o + 24 * (75 / 42) - 24 * 6 * o / 42 = 142 42 * o + 18 - 24 * 6 * o / 42 = 142 42 * o + 18 - 12 * o = 142 30 * o + 18 = 142 30 * o = 142 - 18 30 * o = 124 o = 124 / 30 o = 4 Now that we have the value of 'o', we can substitute it back into one of the original equations to find the value of 'a'. We'll use the second equation: (42 * a) + (6 * 4) = 75 42 * a + 24 = 75 42 * a = 75 - 24 42 * a = 51 a = 51 / 42 a = 1.21 So, the values of 'a' and 'o' are approximately 1.21 and 4, respectively. ### Answer: a ≈ 1.21, o ≈ 4.
Expected answer: {a: 383/270, o: 347/135}
Correct? No
Problem: Given the following system of equations, find the values of p and r: 39*r - 2*p = 45 and 16*p - 84*r = 36.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of r's in both equations are the same: 1) Multiply the first equation by 16 and the second equation by 2: 624*r - 32*p = 720 and 32*p - 168*r = 72 Now, we can subtract the second equation from the first equation to eliminate the term with r: 624*r - 32*p - (32*p - 168*r) = 720 - 72 This simplifies to: 792*r = 648 Now, divide both sides by 792: r = 648/792 r = 3/4 Now that we have the value of r, we can substitute it into one of the original equations to find the value of p. We'll use the first equation: 39*(3/4) - 2*p = 45 Simplify the left-hand side: 29.25 - 2*p = 45 Subtract 29.25 from both sides: -2*p = 15.75 Divide both sides by -2: p = -15.75/2 p = -7.875 ### Answer: p = -7.875, r = 3/4.
Expected answer: {p: 216/19, r: 33/19}
Correct? No
Problem: Given the following system of equations, solve for the values of 'd' and 'w': 1. (23 * d) - (52 * w) = 7 2. (64 * w) - (8 * d) = 58
Llama 3 8B:
Let's solve the system of equations step by step. From equation (1), we can express 'd' in terms of 'w': d = (7 + 52w) / 23 Now, substitute this expression for 'd' into equation (2): (64w) - (8 * ((7 + 52w) / 23)) = 58 Simplify the equation: 64w - (56/23) - (416w/23) = 58 Combine like terms: (48w - 56/23) = 58 Multiply both sides by 23 to eliminate the fraction: 1080w - 56 = 1318 Add 56 to both sides: 1080w = 1374 Divide both sides by 1080: w = 1374/1080 w = 1.275 Now that we have the value of 'w', we can find the value of 'd': d = (7 + 52(1.275)) / 23 d = (7 + 65.5) / 23 d = 72.5 / 23 d = 3.15 ### Answer: d = 3.15, w = 1.275
Expected answer: {d: 433/132, w: 695/528}
Correct? No
Problem: Solve the following system of equations for the values of n and z: (71 * z) + (60 * n) = 184 (52 * z) - (47 * n) = 19.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can multiply the two equations by necessary multiples such that the coefficients of n's in both equations are the same: 1) Multiply the first equation by 47: 47(71z + 60n) = 47(184) 2) Multiply the second equation by 60: 60(52z - 47n) = 60(19) Now, we can subtract the second equation from the first equation: 47(71z + 60n) - 60(52z - 47n) = 47(184) - 60(19) 47(71z + 60n) - 60(52z - 47n) = 862 - 1140 47(71z + 60n) - 60(52z - 47n) = -278 Now, simplify the equation: 47(71z) + 47(60n) - 60(52z) + 60(47n) = -278 47(71z) - 60(52z) + 47(60n) + 60(47n) = -278 7z - 60z + 2820 + 2820 = -278 -53z + 5640 = -278 Now, add 278 to both sides: -53z + 5640 = 0 -53z = -5640 Now, divide both sides by -53: z = 5640/53 z = 106 Now that we have the value of z, we can substitute it into one of the original equations to find the value of n. We'll use the first equation: 71z + 60n = 184 71(106) + 60n = 184 7540 + 60n = 184 Now, subtract 7540 from both sides: 60n = -7356 n = -7356/60 n = -123 ### Answer: n = -123, z = 106.
Expected answer: {n: 8219/6457, z: 9788/6457}
Correct? No
Problem: Given the following system of equations, find the values of e and z: 70 * e + 90 * z = 189 99 * z - 84 * e = 20
Llama 3 8B:
Let's solve the system of equations using the method of substitution or elimination. First, let's multiply both equations by necessary multiples such that the coefficients of e's in both equations are the same: 1) Multiply the first equation by 84: 588e + 756z = 1584 2) Multiply the second equation by 70: 693z - 588e = 1400 Now, subtract the first equation from the second equation to eliminate e: 693z - 588e - (588e + 756z) = 1400 - 1584 693z - 588e - 588e - 756z = -84 -1053e = -84 Now, divide both sides by -1053: e = 84/1053 e = 8/103 Now that we have the value of e, substitute it into one of the original equations to find the value of z. We'll use the first equation: 70e + 90z = 189 70(8/103) + 90z = 189 Multiply both sides by 103: 560 + 90z = 19383 90z = 19323 z = 19323/90 z = 214 ### Answer: e = 8/103, z = 214
Expected answer: {e: 1879/1610, z: 1234/1035}
Correct? No
Problem: Find the values of o and f that satisfy the following system of equations: 1) 26o - 44f = 95 2) 87f + 11o = 169.
Llama 3 8B:
Let's solve the system of equations step by step. From equation (1), we can express o in terms of f: o = (95 + 44f) / 26 Now, substitute this expression for o into equation (2): 87f + 11((95 + 44f) / 26) = 169 Multiply both sides by 26 to eliminate the fraction: 2197f + 1215 + 121f = 4366 Combine like terms: 2318f + 1215 = 4366 Subtract 1215 from both sides: 2318f = 3151 Divide both sides by 2318: f = 3151 / 2318 f = 1.36 (approximately) Now that we have found f, we can find o by substituting f back into the expression we found earlier: o = (95 + 44(1.36)) / 26 o = (95 + 59.84) / 26 o = 154.84 / 26 o = 5.96 (approximately) ### Answer: o ≈ 5.96, f ≈ 1.36.
Expected answer: {f: 3349/2746, o: 15701/2746}
Correct? No
Problem: Calculate the values of z and p using the following system of equations: 40*z - 20*p = 51 6*z + 58*p = 165.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the first equation for z: 40*z - 20*p = 51 40*z = 51 + 20*p z = (51 + 20*p) / 40 Now, substitute this expression for z into the second equation: 6*(51 + 20*p) / 40 + 58*p = 165 Multiply both sides by 40 to eliminate the fraction: 6*(51 + 20*p) + 58*p*40 = 165*40 Expand and simplify: 306 + 120*p + 2320*p = 6600 Combine like terms: 2446*p = 6294 Divide by 2446: p = 6294 / 2446 p = 2.57 (approximately) Now that we have found p, we can substitute it back into one of the original equations to find z. We'll use the first equation: 40*z - 20*p = 51 40*z - 20*2.57 = 51 Add 102.8 to both sides: 40*z = 153.8 Divide by 40: z = 153.8 / 40 z = 3.845 (approximately) ### Answer: z ≈ 3.845, p ≈ 2.57.
Expected answer: {p: 3147/1220, z: 3129/1220}
Correct? No
Problem: Find the values of s and f from the given system of equations: (71 * s) - (89 * f) = 5 (3 * f) + (10 * s) = 93.
Llama 3 8B:
Let's solve the system of equations step by step. First, we can solve the second equation for f: 3f + 10s = 93 3f = 93 - 10s f = (93 - 10s) / 3 Now, substitute this expression for f into the first equation: (71s) - (89((93 - 10s) / 3)) = 5 Multiply both sides by 3 to eliminate the fraction: 213s - 267(93 - 10s) = 15 Expand and simplify: 213s - 24837 + 2670s = 15 Combine like terms: 1483s = 24952 Divide both sides by 1483: s = 24952 / 1483 s = 16.8 Now that we have the value of s, we can find the value of f: f = (93 - 10(16.8)) / 3 f = (93 - 168) / 3 f = -75 / 3 f = -25 ### Answer: s = 16.8, f = -25
Expected answer: {f: 6553/1103, s: 8292/1103}
Correct? No