Common Core Standard 4.NBT.B.6
This standard covers the following:
Find whole-number quotients and remainders with up to four-digit dividends and one-digit divisors, using strategies based on place value, the properties of operations, and/or the relationship between multiplication and division. Illustrate and explain the calculation by using equations, rectangular arrays, and/or area models.
Problem: There are 535 fish in a large tank and a shark eats 461 of them in one sitting. If the shark continues this pattern and only eats when there are 461 or more fish to consume, how many fish will be leftover after its dinner?
Mistral 7B:
Reasoning: The shark eats all the fish when there are 461 or more. Since there are initially 535 fish, the shark eats all of them because 535 > 461. ### Answer: There will be no fish left over.
Expected answer: 74
Correct? No
Problem: A baker baked a total of 928 cookies. He decided to distribute equal amounts of cookies to 186 orphanages. After giving out as many entire sets of cookies as possible to each orphanage, how many cookies does the baker have left?
Mistral 7B:
Reasoning: First, let's find out how many sets of cookies the baker can give to each orphanage. To do this, we divide the total number of cookies by the number of orphanages: 928 / 186 = <<928/186=4.9748275862069>>4.97 sets per orphanage. Since we cannot give a fraction of a set, we round down to the nearest whole number, which is 4 sets per orphanage. Now, let's calculate the number of cookies given to each orphanage: 4 * 186 = <<4*186=744>>744 cookies. Finally, let's find out how many cookies the baker has left: 928 - 744 = <<928-744=184>>184 cookies. ### Answer: 184
Expected answer: 184
Correct? Yes
Problem: In the previously mentioned scenario, consider that the baker only baked 173 cookies instead of 928. He still plans on distributing equal amounts of cookies to the 186 orphanages. After giving out as many full sets as possible to each orphanage, how many cookies will the baker have left over this time?
Mistral 7B:
Reasoning: First, let's find out how many sets of cookies the baker can give to each orphanage. To do this, we divide the total number of cookies by the number of orphanages: 173 / 186 = <<173/186=0.92857142857143>>0.93 sets per orphanage. Since we cannot give a fraction of a set, we round down to the nearest whole number, which is 0 sets per orphanage. Since the baker cannot give any cookies to the orphanages, he will have all 173 cookies left over. ### Answer: 173
Expected answer: 173
Correct? Yes
Problem: A pizza store has 975 slices of pizza ready to serve. If each pizza box can contain 196 slices, how many left over slices will there be after all the pizza boxes are full?
Mistral 7B:
Reasoning: First, we find out how many full boxes can be made with 975 slices: 975 / 196 = <<975/196=5>>5 full boxes. Since each box can contain 196 slices, the total number of slices in the 5 full boxes is 5 * 196 = <<5*196=980>>980 slices. Now, we subtract the number of slices in the full boxes from the total number of slices: 975 - 980 = <<975-980=-5>>-5. However, since it's not possible to have a negative number of slices, we know that there must be an error in the information provided. The number of slices should be less than 980 for all the pizza boxes to be full. ### Answer: There is an error in the information provided. The number of slices should be less than 980 for all the pizza boxes to be full.
Expected answer: 191
Correct? No
Problem: A wizard casts a spell to summon 932 magical stones. Each powerful creature he summons requires 193 stones. After summoning several creatures, how many stones will the wizard have left?
Mistral 7B:
Reasoning: Let's find out how many creatures the wizard summoned first. The wizard summoned <<932/193=4.832421908849556>>4 creatures (rounded down to 4 since the wizard cannot summon a fraction of a creature). Since the wizard used 193*4 = <<193*4=772>>772 stones for summoning these 4 creatures, he will have 932-772 = <<932-772=160>>160 stones left. ### Answer: 160
Expected answer: 160
Correct? Yes
Problem: After summoning several creatures, the wizard found an ancient tome that said each creature actually needed 544 magical stones, not 193. If he had followed this and summoned the creatures based on the 544-stone requirement, how many stones would the wizard have left?
Mistral 7B:
Reasoning: Let's find out how many creatures the wizard could have summoned if he had followed the 544-stone requirement. The wizard could have summoned <<932/544=1.7357576271186443>>2 creatures (rounded down to 1 since the wizard cannot summon a fraction of a creature). Since the wizard used 544*1 = <<544*1=544>>544 stones for summoning these 1 creature, he would have 932-544 = <<932-544=388>>388 stones left. ### Answer: 388
Expected answer: 388
Correct? Yes
Problem: A builder has a job to install 660 square foot tiles in a house. Each tile can cover 335 square feet. After installing tiles evenly across the available space, how many square feet will the last tile need to cover?
Mistral 7B:
Reasoning: First, let's find out how many tiles the builder needs to install. Number of tiles = Total square feet / Square feet per tile = 660 / 335 = <<660/335=1.9724871794871796>>1.97 (approximately) Since the builder cannot install a fraction of a tile, we'll round up to the nearest whole number, which is 2 tiles. Now, let's find the remaining square feet that need to be covered by the last two tiles. Remaining square feet = Total square feet - (Number of tiles * Square feet per tile) = 660 - (2 * 335) = 660 - 670 = -10 (negative value indicates that there is not enough space for the last two tiles) However, since the question asks for the square feet the last tile needs to cover, we'll divide the remaining square feet by 2 to find the square feet for the last tile. Square feet for the last tile = Remaining square feet / 2 = -10 / 2 = -5 (negative value indicates that the last tile cannot cover the remaining space) Since it's impossible for the last tile to cover the remaining space, the builder will need to adjust the tile layout or order more tiles. ### Answer: The last tile cannot cover the remaining space.
Expected answer: 325
Correct? No
Problem: A juice company produced 473 gallons of juice. If the company bottles the juice in 22-gallon containers, how many gallons of juice will be left after filling up all the containers?
Mistral 7B:
Reasoning: The company can fill up 473/22 = <<473/22=21.5>>21 containers with 22-gallon containers. Since a 22-gallon container can hold 22 gallons, the remaining juice will be 473 - (21*22) = <<473-(21*22)=11>>11 gallons. ### Answer: 11
Expected answer: 11
Correct? Yes
Problem: A juice company initially thought they produced 473 gallons of juice, but they realized they actually produced 599 gallons. They used the same 22-gallon containers as before. After filling up all the containers, how many gallons of juice do they now have left over?
Mistral 7B:
Reasoning: The company can fill up 599/22 = <<599/22=27.181818181818183>>27 containers with 22-gallon containers. Since a 22-gallon container can hold 22 gallons, the remaining juice will be 599 - (27*22) = <<599-(27*22)=18>>18 gallons. ### Answer: 18
Expected answer: 5
Correct? No
Problem: A toy factory produced 979 toy cars in a day. If they packed these cars into boxes, each containing 108 cars, how many toy cars will be left unpacked at the end of the day?
Mistral 7B:
Reasoning: First, we find out how many full boxes can be made with 979 cars: 979/108 = <<979/108=9>>9 full boxes. Since there are 108 cars in each box, the number of cars in the 9 full boxes is 9*108 = <<9*108=972>>972 cars. Now, we subtract the number of cars in the full boxes from the total number of cars produced: 979 - 972 = <<979-972=7>>7 cars. ### Answer: 7
Expected answer: 7
Correct? Yes
Problem: The toy factory now produced 979 toy cars in a day and decided to package these cars into larger boxes, each containing 684 cars. After all the cars have been packed into the larger boxes, how many toy cars would be left unpacked at the end of the day?
Mistral 7B:
Reasoning: First, we find out how many full boxes can be made with 979 cars: 979/684 = <<979/684=1.4359220572727273>>1.4359220572727273 (approximately). Since we cannot have a fraction of a box, we round down to the nearest whole number, which is 1. So, there is 1 full box, and the number of cars in the 1 full box is 684 cars. Now, we subtract the number of cars in the full box from the total number of cars produced: 979 - 684 = <<979-684=295>>295 cars. ### Answer: 295
Expected answer: 295
Correct? Yes
Problem: A crayon factory has the capacity to make 994 crayons in one operation. However, each box only holds 425 crayons. If they operate at full capacity, how many crayons will be left out of the boxes after the operation?
Mistral 7B:
Reasoning: The factory can make 994 crayons in one operation. Each box holds 425 crayons, so the factory can fill 994/425 = <<994/425=2.3142857142857143>>2 boxes and have 994 - (2*425) = <<994-(2*425)=149>>149 crayons left over. ### Answer: 149
Expected answer: 144
Correct? No
Problem: A wildlife reserve has 740 tigers. The reserve is divided into different zones, and each zone can only hold up to 696 tigers. If tigers are distributed evenly among the zones, how many tigers will be left in the last zone?
Mistral 7B:
Reasoning: First, let's find out how many zones there are by dividing the total number of tigers by the maximum capacity of each zone: 740 / 696 = <<740/696=1.0617977528089887>>1 (rounded down to 1 since we cannot have a fraction of a zone). Since there is only one zone left, the remaining tigers will be the difference between the total number of tigers and the number of tigers that can fit in the other zones: 740 - (696 * (number of zones - 1)) = 740 - (696 * (1 - 1)) = 740 - 0 = <<740-0=740>>740 tigers will be left in the last zone. ### Answer: 740
Expected answer: 44
Correct? No
Problem: A hat shop makes 830 hats every week. In order to make special edition boxes, the shop plans to put 421 hats in each box. If all the hats are evenly distributed among the boxes, how many hats will be left over?
Mistral 7B:
Reasoning: The shop makes 830 hats every week, and they plan to put 421 hats in each box. To find out how many boxes they can make, we divide the total number of hats by the number of hats per box: 830 / 421 = <<830/421≈1.9724>>1.9724 (approximately). Since it's not possible to have a fraction of a box, we round down to the nearest whole number, which is 1. So, the shop can make 1 box with 421 hats, and there will be 830 - 421 = <<830-421=409>>409 hats left over. ### Answer: 409
Expected answer: 409
Correct? Yes
Problem: There are 871 fish in a lake. A fisherman catches 575 fish every month. If the fish repopulate at the same rate that the fisherman is depleting them, how many fish will be left after a month?
Mistral 7B:
Reasoning: The fisherman catches 575 fish every month, so the number of fish left in the lake after one month is 871 - 575 = <<871-575=296>>296 fish. ### Answer: 296
Expected answer: 296
Correct? Yes
Problem: There are 891 beach balls, and every beach bag can fit 119 beach balls. If all the beach balls are evenly placed into the bags, how many beach balls will not fit and left over?
Mistral 7B:
Reasoning: To find out how many bags are needed, we divide the total number of beach balls by the number of beach balls each bag can hold: 891 / 119 = <<891/119=7.481481481481481>>7 (rounded down to the nearest whole number). Since 7 bags can hold 7 * 119 = <<7*119=833>>833 beach balls, there will be 891 - 833 = <<891-833=58>>58 beach balls left over. ### Answer: 58
Expected answer: 58
Correct? Yes
Problem: If instead there were 901 beach balls and every beach bag can fit 119 beach balls. After evenly placing the balls into bags, how many beach balls would be left over now?
Mistral 7B:
Reasoning: To find out how many bags are needed, we divide the total number of beach balls by the number of beach balls each bag can hold: 901 / 119 = <<901/119=7.636363636363636>>7 (rounded up to the nearest whole number). Since 8 bags can hold 8 * 119 = <<8*119=952>>952 beach balls, there will be 901 - 952 = <<901-952=-51>>-51 beach balls left over. ### Answer: -51 (Note that negative number of beach balls does not make sense in this context, so we can say that there are no beach balls left over.)
Expected answer: 68
Correct? No
Problem: There are 544 stars in a particular constellation. These stars are grouped into smaller clusters of 446 stars each. If these clusters are evenly split, how many stars will remain ungrouped?
Mistral 7B:
Reasoning: First, let's find out how many clusters there are by dividing the total number of stars by the number of stars per cluster: 544 / 446 ≈ 1.22. Since we cannot have a fraction of a cluster, we round down to 1 cluster. Now, let's find out how many stars are in the clusters: 446 * 1 = 446. Finally, let's subtract the number of stars in the clusters from the total number of stars to find the number of ungrouped stars: 544 - 446 = <<544-446=98>>98. ### Answer: 98
Expected answer: 98
Correct? Yes
Problem: Considering the previous scenario with the constellation, suppose there were only 278 stars in the constellation instead of 544, and they were still to be grouped into smaller clusters of 446 stars each. If the clusters are evenly distributed, how many stars will now remain ungrouped?
Mistral 7B:
Reasoning: First, let's find out how many clusters there are by dividing the new total number of stars by the number of stars per cluster: 278 / 446 ≈ 0.62. Since we cannot have a fraction of a cluster, we round down to 0 clusters. This means that all the stars will be ungrouped. ### Answer: All the stars will remain ungrouped.
Expected answer: 278
Correct? No
Problem: A manufacturer produces 805 socks in one shift. They are packaged into sets of 132 each. After the packaging, how many socks will remain unpackaged?
Mistral 7B:
Reasoning: The manufacturer can package 805/132 = <<805/132=6.051282051282051>>6 full sets of 132 socks each. Since there are only whole sets, we can say that 6 sets were packaged, leaving 805 - (6*132) = <<805-(6*132)=14>>14 socks unpackaged. ### Answer: 14
Expected answer: 13
Correct? No
Problem: An astronomy club has 759 members that want to view a rare celestial event through their club's telescope. However, the telescope can only handle 228 people viewing the event each night. If they distribute the viewing evenings evenly amongst all members, how many people will view the event on the final night?
Mistral 7B:
Reasoning: First, let's find out how many viewing nights are needed to accommodate all members. Number of viewing nights = Total members / Members per night = 759 / 228 = <<759/228=3.3174603174603175>>3 (rounded up to 4 since we can't have a fraction of a night). Now, let's find out how many members will view the event on the final night: Members on the final night = Total members - (Number of viewing nights - 1) * Members per night Members on the final night = 759 - (4 - 1) * 228 = 759 - 892 = <<759-892=-133>>-133 ### Answer: -133 (Since it's not possible to have a negative number of people, this means that all members have already viewed the event before the final night.)
Expected answer: 75
Correct? No
Problem: A postman has to deliver 891 letters. Each mailbox can only hold 616 letters. If he puts equal numbers of letters in each mailbox, how many letters will remain in the last mailbox?
Mistral 7B:
Reasoning: First, let's find out how many full mailboxes the postman can fill. Number of full mailboxes = Total letters / Letters per mailbox = 891 / 616 ≈ 1.44 Since the postman cannot have a fraction of a mailbox, he can fill 1 complete mailbox and have 144 letters left. Now, let's find out how many more letters can fit in the second-to-last mailbox. Let x be the number of letters in the second-to-last mailbox. 616 - x = 616 - (616 - 144) = 144 + x Solving for x, we get 2x = 760, so x = 380 The postman puts 380 letters in the second-to-last mailbox, leaving 891 - (616*1 + 380) = 891 - 996 = -95 letters in the last mailbox. However, since it's impossible to have a negative number of letters, the postman will have to make multiple trips or use larger mailboxes to deliver all the letters. ### Answer: The postman cannot determine the number of letters left in the last mailbox with the given information.
Expected answer: 275
Correct? No
Problem: A total of 941 flies are jumping around the pond. Every time a frog jumps, it eats exactly 258 flies. After a series of jumps where each jump the frog eats the same number of flies, how many flies are left?
Mistral 7B:
Reasoning: The frog eats 258 flies at a time. To find out how many times the frog jumps, we divide the total number of flies by the number of flies eaten per jump: 941/258 = <<941/258=3.6546875>>3 (since the frog cannot eat a fraction of a fly). Since the frog eats 258 flies each time, the total number of flies left is 941 - (3*258) = <<941-(3*258)=125>>125. ### Answer: 125
Expected answer: 167
Correct? No
Problem: A large park has a capacity of 991 spaces for cars to park. If all the spaces are evenly distributed between 66 rows, how many spare spaces will be there in the last row after max spaces are filled?
Mistral 7B:
Reasoning: First, let's find out how many spaces are in each row. To do this, we divide the total number of spaces by the number of rows: 991 / 66 = <<991/66=15>>15 spaces per row. Since the last row will have fewer spaces than the others, we need to find the maximum number of spaces that can fit in the last row without leaving any spare spaces. To do this, we can subtract the number of spaces in the previous rows from the total number of spaces: 991 - (15 * (66 - 1)) = 991 - (15 * 65) = 991 - 975 = <<991-975=16>>16 ### Answer: 16
Expected answer: 1
Correct? No
Problem: There are 193 liters of water that need to be divided evenly among 167 water bottles. If each bottle holds the same amount of water, how many liters overflows and can't be distributed to the bottles?
Mistral 7B:
Reasoning: To find the amount of water per bottle, we divide the total amount of water by the number of bottles: 193/167. Since the water can't overflow, we round down to the nearest whole number: 193/167 ≈ 1.15 liters/bottle. Now, we multiply the amount of water per bottle by the number of bottles: 1.15 * 167 = <<1.15*167=198.05>>198.05 liters. However, since we rounded down earlier, there is an overflow of 193 - 198.05 = <<193-198.05=-5.05>>5.05 liters. ### Answer: 5.05 liters overflow.
Expected answer: 26
Correct? No
Problem: A dragon lays 996 jewel eggs in rows. Each row can hold 319 eggs. If the dragon distributes the eggs evenly among the rows, how many eggs would be left over to be put in the last row?
Mistral 7B:
Reasoning: To find out how many complete rows the dragon can make, we divide the total number of eggs by the number of eggs per row: 996 / 319 = <<996/319=3.1020408163265306>>3 (rounded down to 3 complete rows). Since the dragon can't have a fraction of a row, it can only make 3 complete rows. The remaining eggs are the total number of eggs minus the number of eggs in the 3 complete rows: 996 - (3 * 319) = <<996-(3*319)=16>>16 eggs. ### Answer: 16
Expected answer: 39
Correct? No
Problem: A lamp manufacturer produces 691 bulb units. If a pack includes 205 bulbs, how many bulbs would be left unpacked after filling as many packs as possible?
Mistral 7B:
Reasoning: First, let's find out how many packs can be filled with 691 bulbs: Number of packs = Total bulbs / Bulbs per pack = 691 / 205 ≈ 3.35 Since we cannot have a fraction of a pack, we can only fill 3 packs completely and have 3.35 * 205 - 605 bulbs left. ### Answer: 96 bulbs would be left unpacked.
Expected answer: 76
Correct? No
Problem: On a farm, there are 330 bales of hay to be stored evenly in barns. Each barn can store up to 259 bales. After filling up the barns as evenly as possible, how many bales of hay will be left for the last barn?
Mistral 7B:
Reasoning: First, let's find out how many full barns can be filled with 330 bales: 330 / 259 = <<330/259=1.262962962962963>>1 (rounded down to 1 since we cannot have a fraction of a barn). Now, let's find out how many bales are left after filling up the first barn: 259 - (330 % 259) = <<259-(330%259)=259-1>>258 bales. Since we have already filled up 1 barn with 259 bales, we can now fill up the remaining barns with the remaining 258 bales. ### Answer: 0 (since all bales are used up after filling up the barns evenly)
Expected answer: 71
Correct? No
Problem: A construction company is installing 166 windows on a building. They have determined that one installation team can install 137 windows per day. If all windows are equally distributed amongst teams each day, how many windows will remain for the team to install on the next day?
Mistral 7B:
Reasoning: The number of windows installed per day by one team is 137. To find out how many days it takes to install all 166 windows, we divide the total number of windows by the number of windows installed per day: 166/137 = <<166/137≈1.2042>>1 (approximately). Since the installation takes approximately 1 day, there will be no windows left for the team to install on the next day. ### Answer: 0
Expected answer: 29
Correct? No
Problem: There are 533 campers coming for a camping event at a park. Each tent can host 445 people. If the campers are evenly distributed among the tents, how many campers will be left over after all the tents are filled?
Mistral 7B:
Reasoning: To find out how many tents are needed, we divide the total number of campers by the number of people each tent can host: 533 / 445 = <<533/445=1.2' (cannot divide exactly)>>1 (with a remainder of 128). Since we cannot divide exactly, we need to round up to 2 tents. Each tent can host 445 people, so 2 tents can host 2 * 445 = <<2*445=890>>890 people. The number of campers left over is the total number of campers minus the number of campers that can be accommodated by the tents: 533 - 890 = <<533-890=-357 (negative value indicates a deficit)>>-357. However, since it's not possible to have a negative number of campers, this question has an error. The number of campers should be less than or equal to the number of people that can be accommodated by the tents. ### Answer: The question has an error. The number of campers should be less than or equal to the number of people that can be accommodated by the tents.
Expected answer: 88
Correct? No
Problem: There are 999 seashells collected from a beach. They are grouped in beach-themed souvenir sets, each containing 474 shells. After grouping, how many seashells will be left without a set?
Mistral 7B:
Reasoning: First, let's find out how many sets can be made with the given number of shells: 999 / 474 = <<999/474=2>>2 sets. Since each set contains 474 shells, the total number of shells in the sets is 2 * 474 = <<2*474=948>>948 shells. Now, let's find the number of shells left without a set: 999 - 948 = <<999-948=51>>51 shells. ### Answer: 51
Expected answer: 51
Correct? Yes
Problem: In continuation of the previous scenario with seashells, imagine instead that there were initially only 234 seashells collected from the beach, but the souvenir sets are still made up of 474 shells each. How many shells would be left after attempting to form these sets?
Mistral 7B:
Reasoning: First, let's find out how many sets can be made with the given number of shells: 234 / 474 = <<234/474=0.492847123450244>>0 sets (since the number of sets cannot be a fraction, we round down to 0 sets). Since no sets can be formed, all 234 shells will be left without a set. ### Answer: 234
Expected answer: 234
Correct? Yes
Problem: A tailor has 366 meters of fabric. If each skirt requires 160 meters of fabric, how many meters of fabric will be left after making as many skirts as possible?
Mistral 7B:
Reasoning: The number of skirts that can be made is 366/160 = <<366/160=2.2875>>2 skirts with a remainder of 0.2875. Since it is not possible to make a fraction of a skirt, the tailor can make 2 skirts, and there will be 366 - (2 * 160) = <<366-(2*160)=46>>46 meters of fabric left. ### Answer: 46
Expected answer: 46
Correct? Yes
Problem: A tailor realized that she has made a mistake. Actually, she has only 21 meters of fabric at her disposal, not 366. If each skirt requires 160 meters of fabric, how many meters of fabric will be left after making as many skirts as possible?
Mistral 7B:
Reasoning: The number of skirts that can be made is 21/160 = <<21/160=0.13125>>0 skirts with a remainder of 0.13125. Since it is not possible to make a fraction of a skirt, the tailor cannot make any skirts with the given amount of fabric. ### Answer: 0 0 meters of fabric will be left.
Expected answer: 21
Correct? No
Problem: A toymaker made 993 dolls to be packed in boxes for shipment. Each box can hold 327 dolls. How many dolls will she have left once all the boxes are packed to their capacities?
Mistral 7B:
Reasoning: The number of boxes that can be filled is 993/327 = <<993/327=3>>3 (rounded down). Since each box can hold 327 dolls, the total number of dolls in the 3 boxes is 3*327 = <<3*327=981>>981. The number of dolls left is 993-981 = <<993-981=12>>12. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: Following up on the previous problem, what if, instead of each box holding 327 dolls, each box can now hold 115 dolls? After packing each box to capacity, how many dolls will the toymaker have left?
Mistral 7B:
Reasoning: The number of boxes that can be filled is 993/115 = <<993/115=8.666666666666667>>9 (rounded up). Since each box can hold 115 dolls, the total number of dolls in the 9 boxes is 9*115 = <<9*115=1035>>1035. The number of dolls left is 993-1035 = <<993-1035=-42>>-42 (negative number indicates more dolls than initially available). This is not possible, so the initial assumption that each box can hold 115 dolls is incorrect. ### Answer: The initial assumption that each box can hold 115 dolls is incorrect.
Expected answer: 73
Correct? No
Problem: A child has 964 stuffed animals that they want to divide equally among their 839 friends. If they distribute the stuffed animals evenly, how many will the child have left over?
Mistral 7B:
Reasoning: To find out how many stuffed animals each friend gets, we divide the total number of stuffed animals by the number of friends: 964/839. Since the child wants to distribute all the stuffed animals, the remainder will be 0. ### Answer: 0 (The child will have no stuffed animals left over.)
Expected answer: 125
Correct? No
Problem: A toy factory produces 369 teddy bears in a day. The bears are packaged in boxes and each box can hold 270 teddy bears. How many teddy bears will be left if all the teddy bears are evenly packed in the boxes?
Mistral 7B:
Reasoning: First, let's find out how many complete boxes can be filled with 369 teddy bears: 369 / 270 = <<369/270=1.3666666666666667>>1 (since we cannot have a fraction of a box). Since we cannot have a fraction of a box, we will need to pack the remaining 69 teddy bears in the next box. So, the total number of boxes needed is 1 + (69 / 270) = <<1+(69/270)=1.2571428571428572>>1 (since we cannot have a fraction of a box). Since we cannot have a fraction of a box, we will need to pack the remaining 69 teddy bears in the next box. However, since each box can hold only 270 teddy bears, the last box will be filled with 270 - 69 = <<270-69=201>>201 teddy bears. The remaining 69 teddy bears will not be packed in any box. ### Answer: 201 teddy bears will be left.
Expected answer: 99
Correct? No
Problem: A village has a yearly tradition of building snowmen. This year, the villagers make 804 snowballs to build their snowmen. Each snowman needs exactly 184 snowballs. After all snowmen are built, how many snowballs are left leftover?
Mistral 7B:
Reasoning: The number of snowballs used for building snowmen is equal to the number of snowmen multiplied by the number of snowballs per snowman. Number of snowballs used = Snowmen * Snowballs per snowman Number of snowballs used = 804 = 804/184 = <<804/184=4.368421052631579>>4 (since we cannot have a fraction of a snowball) ### Answer: 4 snowballs are left leftover.
Expected answer: 68
Correct? No
Problem: A jewelry store has 843 rings to be placed equally into 839 boxes. If each box is filled, how many rings will be left over?
Mistral 7B:
Reasoning: To find out how many rings can fit into each box, we divide the total number of rings by the number of boxes. Number of rings per box = Total rings / Number of boxes = 843 / 839 ≈ 1.013 Since it is not possible to have a fraction of a ring, we round down to the nearest whole number, which is 1 ring per box. Since each box is filled, there will be no rings left over. ### Answer: 0 Alternatively, if we want to find out how many rings are left over if we fill all but one box, we can calculate the number of rings in the last box and subtract it from the total number of rings. Number of rings in the last box = Number of rings per box * 1 = 1.013 * 1 ≈ 1 Since we rounded down earlier, we need to add 1 to account for the rounding error. Number of rings left over = Total rings - (Number of rings per box * Number of boxes - Number of rings in the last box) = 843 - (1 * 839 - 1) = 843 - 838 + 1 = 5 ### Answer: 5 (if we fill all but one box)
Expected answer: 4
Correct? No
Problem: A fireplace manufacturing company has 819 bricks to build fireplaces, and each fireplace requires 583 bricks. If they build as many fireplaces as possible, how many bricks will they have left over?
Mistral 7B:
Reasoning: To find out how many fireplaces can be built, we divide the total number of bricks by the number of bricks required for each fireplace: 819/583 = <<819/583≈1.3917>>1 (approximately). However, since it's not possible to build a fraction of a fireplace, the company can only build 1 whole fireplace. Since 1 fireplace requires 583 bricks, the remaining bricks will be 819 - 583 = <<819-583=236>>236. ### Answer: 236
Expected answer: 236
Correct? Yes
Problem: The company received a new delivery of bricks, now they have 486 bricks in total. If they continue making fireplaces, each requiring 583 bricks as before, how many bricks will they have left after building as many full fireplaces as they can?
Mistral 7B:
Reasoning: First, let's find out how many fireplaces they can build with the additional 486 bricks: 486/583 = <<486/583≈0.8333>>0 (approximately). Again, since it's not possible to build a fraction of a fireplace, they can build 0 fireplaces. Since they didn't build any fireplaces, they will have the same number of bricks left as they started with: 486 bricks. ### Answer: 486
Expected answer: 486
Correct? Yes
Problem: A marshmallow factory produces 998 marshmallows per minute. However, the packaging machine can only hold 957 marshmallows at a time. What will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled?
Mistral 7B:
Reasoning: The factory produces 998 marshmallows per minute. Since the packaging machine can only hold 957 marshmallows at a time, there will be 998 - 957 = <<998-957=41>>41 marshmallows left un-packaged in a minute after all the packaging machines are filled. ### Answer: 41
Expected answer: 41
Correct? Yes
Problem: The marshmallow factory upgraded its packaging machine and now it can hold 804 marshmallows at a time instead of 957. If the factory continues to produce 998 marshmallows per minute, what will be the number of marshmallows left un-packaged in a minute after all the packaging machines are filled with the new capacity?
Mistral 7B:
Reasoning: The factory produces 998 marshmallows per minute. With the new capacity, the packaging machine can hold 804 marshmallows at a time. The number of marshmallows left un-packaged in a minute after all the packaging machines are filled is: 998 - (number of machines * 804) Since the factory has only one packaging machine, the number of marshmallows left un-packaged is: 998 - 804 = <<998-804=194>>194 ### Answer: 194
Expected answer: 194
Correct? Yes
Problem: There are 984 roses in the castle's garden. Princess likes to place 426 roses in every tribute for her loyal subjects. If she distributes roses evenly to create as many tributes as possible, how many roses will be left undistributed in the castle's garden?
Mistral 7B:
Reasoning: First, let's find out how many tributes Princess can create with the given number of roses. 984 roses / 426 roses per tribute = <<984/426=2.3011224489795917>>2 tributes (rounded down to 2 tributes since you can't have a fraction of a tribute). Since there are only 2 tributes, there will be no roses left undistributed in the castle's garden. ### Answer: 0
Expected answer: 132
Correct? No
Problem: A song has 334 words in it. If each line in the song has 23 words, how many words would be in the incomplete line at the end of the song?
Mistral 7B:
Reasoning: The number of words in the incomplete line is the total number of words in the song minus the number of words in the complete lines. Since there are 334 words in total and each line has 23 words, there are 334/23 = <<334/23=14.521739130434783>>14 complete lines. The incomplete line would have 23 - (334 mod 23) = 23 - 10 = <<23-10=13>>13 words. ### Answer: 13
Expected answer: 12
Correct? No
Problem: A teacher has 928 pages of study materials that he wants to print for his students. His printer can only print 336 pages in one go. After filling the printer a number of times, how many pages will he have left over to print?
Mistral 7B:
Reasoning: The teacher can print 336 pages at a time. To find out how many times he needs to fill the printer, we divide the total number of pages by the number of pages the printer can print in one go: 928 / 336 = <<928/336=2.75625>>2 (rounded down to 2 because you can't print a fraction of a page). Since the printer can print 336 pages each time, the teacher will fill the printer 2 times. After filling the printer twice, the teacher will have printed 2 * 336 = <<2*336=672>>672 pages. The teacher has 928 - 672 = <<928-672=256>>256 pages left over to print. ### Answer: 256
Expected answer: 256
Correct? Yes
Problem: In the same scenario, suppose the teacher decides to use a different printer that can print 409 pages in one go. After filling this printer a number of times, how many pages will he have left over to print?
Mistral 7B:
Reasoning: The teacher can print 409 pages at a time with the new printer. To find out how many times he needs to fill the printer, we divide the total number of pages by the number of pages the printer can print in one go: 928 / 409 = <<928/409=2.263157894736842>>2 (rounded down to 2 because you can't print a fraction of a page). Since the new printer can print 409 pages each time, the teacher will fill the printer 2 times. After filling the printer twice, the teacher will have printed 2 * 409 = <<2*409=818>>818 pages. The teacher has 928 - 818 = <<928-818=110>>110 pages left over to print. ### Answer: 110
Expected answer: 110
Correct? Yes
Problem: Scientists have spotted 972 sharks in an area. The scientists tag groups of 667 sharks each. How many sharks are left untagged after the scientists finish tagging as many complete groups as possible?
Mistral 7B:
Reasoning: First, let's find out how many complete groups of 667 sharks the scientists can tag: 972 sharks / 667 sharks per group = <<972/667=1.4649444944494448>>1 (approximately 1 complete group). Since the scientists can only tag one complete group, there are no sharks left untagged. ### Answer: 0
Expected answer: 305
Correct? No
Problem: There are 686 blocks of cheese in the dairy shop. Each box can contain 349 blocks of cheese. If all the blocks of cheese are evenly distributed in the boxes, how many blocks of cheese would be left over after all the boxes are filled?
Mistral 7B:
Reasoning: To find out how many boxes can be filled, divide the total number of blocks by the number of blocks per box: 686/349 = <<686/349≈1.9662843137254903>>1.966 (approximately). Since we cannot have a fraction of a box, we round down to the nearest whole number, which is 1. Now, we know that 1 box can hold 349 blocks, so the number of blocks left over after filling 1 box is 686 - 349 = <<686-349=337>>337 blocks. ### Answer: 337
Expected answer: 337
Correct? Yes
Problem: In the previous scenario, say the dairy shop initially had 239 blocks of cheese instead of 686. Using the same boxes which can contain 349 blocks of cheese, how many blocks of cheese would be left over after all the boxes are filled?
Mistral 7B:
Reasoning: To find out how many boxes can be filled, divide the total number of blocks by the number of blocks per box: 239/349 = <<239/349≈0.6849979462068965>>0.685 (approximately). Since we cannot have a fraction of a box, we round down to the nearest whole number, which is 0. Since no boxes can be filled, there would be no blocks left over. ### Answer: 0
Expected answer: 239
Correct? No
Problem: There were 513 centimeters of snowfall recorded this winter. A snowplow can clear up to 170 centimeters of snow at a time. If the snowplow runs continuously, how many centimeters of snow will be left over after the final pass?
Mistral 7B:
Reasoning: First, we need to find out how many times the snowplow can clear the snow. We do this by dividing the total snowfall by the maximum amount of snow the snowplow can clear at a time: 513 cm / 170 cm = <<513/170=3>>3 times. Since the snowplow runs continuously, there will be no snow left over after the final pass. ### Answer: 0
Expected answer: 3
Correct? No
Problem: A compass maker has 661 needles to install in compasses. Each compass uses 510 needles. After installing as many full compasses as he can, how many needles will the compass maker have left?
Mistral 7B:
Reasoning: First, let's find out how many full compasses the compass maker can make with the given number of needles. To do this, we divide the total number of needles by the number of needles per compass: 661 / 510 = <<661/510=1.2941176470588236>>1.2941176470588236 (approximately). Since the compass maker cannot make a fraction of a compass, he can make 1 full compass. After making 1 full compass, the compass maker will have 661 - 510 = <<661-510=151>>151 needles left. ### Answer: 151
Expected answer: 151
Correct? Yes
Problem: A furniture factory has manufactured 380 chairs to distribute to its retail shops. Each shop can only hold 310 chairs in its storage. If the factory evenly distributes all the chairs to the shops, how many chairs will be left at the factory?
Mistral 7B:
Reasoning: The factory needs to divide 380 chairs by the number of shops that can hold 310 chairs each. Let's find out how many shops can be filled with 310 chairs each: Number of shops = Total chairs / Chairs per shop Number of shops = 380 / 310 Number of shops ≈ 1.2258 Since it's not possible to have a fraction of a shop, we'll round down to the nearest whole number, which is 1 shop left over. Now, let's find out how many chairs are left at the factory after distributing to 1 shop: Chairs left at the factory = Total chairs - (Chairs per shop * Number of shops) Chairs left at the factory = 380 - (310 * 1) Chairs left at the factory = 380 - 310 Chairs left at the factory = 70 ### Answer: 70
Expected answer: 70
Correct? Yes
Problem: Now suppose the factory decides to distribute these chairs amongst its smaller distributors, each of which can only hold 143 chairs. Now, how many chairs will be left at the factory after distributing them evenly?
Mistral 7B:
Reasoning: First, let's find out how many distributors can be filled with 143 chairs each: Number of distributors = Total chairs / Chairs per distributor Number of distributors = 380 / 143 Number of distributors ≈ 2.6758 Since it's not possible to have a fraction of a distributor, we'll round down to the nearest whole number, which is 2 distributors left over. Now, let's find out how many chairs are left at the factory after distributing to 2 distributors: Chairs left at the factory = Total chairs - (Chairs per distributor * Number of distributors) Chairs left at the factory = 380 - (143 * 2) Chairs left at the factory = 380 - 286 Chairs left at the factory = 94 ### Answer: 94
Expected answer: 94
Correct? Yes
Problem: A farmer has gathered 929 tomatoes from his field. He plans to sell them in boxes, with 154 tomatoes in each box. After packing them evenly in boxes, how many tomatoes will be left over?
Mistral 7B:
Reasoning: The number of boxes needed is 929/154 = <<929/154=6>>6 boxes. Since there are 154 tomatoes in each box, the total number of tomatoes packed is 6*154 = <<6*154=924>>924 tomatoes. The number of tomatoes left over is 929 - 924 = <<929-924=5>>5 tomatoes. ### Answer: 5
Expected answer: 5
Correct? Yes
Problem: The farmer realized he made an error and actually collected 929 tomatoes from his field, but this time he wants to sell them in bigger boxes that can accommodate 834 tomatoes each. After packing these tomatoes evenly in these larger boxes, how many tomatoes will be left over?
Mistral 7B:
Reasoning: The number of boxes needed is 929/834 = <<929/834=1.1142857142857143>>1 box and a fraction of a box. Since the boxes can only be filled whole numbers of tomatoes, the farmer will need to round up to 2 boxes. The total number of tomatoes packed in 2 boxes is 2*834 = <<2*834=1668>>1668 tomatoes. The number of tomatoes left over is 929 - 1668 = <<929-1668=-739>>-739 tomatoes (which is not possible, as the number of tomatoes cannot be negative). This means that the farmer cannot pack all the tomatoes in the larger boxes and will have to use the smaller boxes instead. ### Answer: The farmer cannot pack all the tomatoes in the larger boxes and will have to use the smaller boxes instead.
Expected answer: 95
Correct? No
Problem: A sporting goods store has 454 pairs of ice skates in total. The store distributes the skates evenly among 128 boxes. How many pairs of ice skates will be left over after all the boxes are filled up equally?
Mistral 7B:
Reasoning: To find out how many pairs of ice skates each box will contain, we divide the total number of ice skates by the number of boxes: 454/128 = <<454/128=3.575>>3 pairs and 50/128 pairs left over. Since we cannot have a fraction of a pair, we round down to the nearest whole number, which is 0 pairs left over. ### Answer: 0
Expected answer: 70
Correct? No
Problem: A windmill generates 506 units of power per day. Every day, a small village consumes power in increments of 385 units. At the end of the day, after the village has consumed as much power as it can in full increments, how much power is left over?
Mistral 7B:
Reasoning: The village consumes power in increments of 385 units. So, the number of full increments the village can consume is 506/385 = <<506/385=1.3162277660168373>>1 (rounded down to 1). The remaining power after the village has consumed 1 full increment is 506 - (1*385) = <<506-(1*385)=121>>121 units. ### Answer: 121
Expected answer: 121
Correct? Yes
Problem: Following the scenario of the windmill and the small village, let's now consider that the windmill had a great day and managed to generate 506 units of power. However, due to development demands, the daily consumption of the village has increased to 920 units. At the end of the day, with the power being consumed in complete units, how much power is left over?
Mistral 7B:
Reasoning: The village consumes power in increments of 920 units. So, the number of full increments the village can consume is 506/920 = <<506/920=0.5483870967741935>>0 (rounded down to 0). The remaining power after the village has consumed 0 full increments is 506 units. ### Answer: 506
Expected answer: 506
Correct? Yes
Problem: Superhero Blast Man has 338 energy units in his power cells. Each energy blast he fires uses 16 energy units. After using equal units of energy firing blasts, how many energy units will Blast Man have left in his power cells?
Mistral 7B:
Reasoning: Let x be the number of energy blasts Blast Man fires. Then, the equation to represent the remaining energy units is: 338 - 16x = 0 Solving for x: 338 = 16x x = 338 / 16 x = 21.125 Since Blast Man cannot fire a fraction of a blast, he will fire 21 blasts and have 0 energy units left in his power cells. ### Answer: 0 (after firing 21 blasts)
Expected answer: 2
Correct? No
Problem: A school district has 530 students who need to be transported and each school bus can carry 144 students. If all students are equally spread across the buses, how many students will be on the last school bus?
Mistral 7B:
Reasoning: To find out how many full buses can be filled, we divide the total number of students by the capacity of each bus: 530 / 144 = <<530/144=3.640625>>3 (rounded down to 3 because we cannot have a fraction of a student). Since there are 3 full buses, the remaining students will be on the last bus: 530 - (3 * 144) = <<530-(3*144)=14>>14 students. ### Answer: 14
Expected answer: 98
Correct? No
Problem: A wizard has 999 spells in his book. He tries to distribute them equally among 951 apprentice wizards but they don't divide evenly. How many spells will the wizard have left after giving out as many as he can to his apprentices?
Mistral 7B:
Reasoning: The wizard can give each apprentice 1 spell, leaving 48 spells (999 - 951) for himself. ### Answer: 48
Expected answer: 48
Correct? Yes
Problem: If the wizard had instead 999 spells and he tries to distribute them equally among 801 apprentice wizards, how many spells will the wizard have left after giving out as many as he can to his apprentices?
Mistral 7B:
Reasoning: The wizard can give each apprentice 1 spell, leaving 198 spells (999 - 801) for himself. ### Answer: 198
Expected answer: 198
Correct? Yes
Problem: A scooter manufacturing company has produced 767 scooters. Each delivery truck they use can carry 369 scooters. If they distribute the scooters evenly among the trucks, how many scooters will be left after all the trucks are loaded?
Mistral 7B:
Reasoning: First, we need to find out how many full trucks can be loaded with the given number of scooters. Number of full trucks = Total scooters / Scooters per truck = 767 / 369 ≈ 2.08 (rounded to 2) Since we cannot have a fraction of a truck, we will have 2 full trucks and some scooters left. Now, let's find out how many scooters are left after loading the 2 full trucks: Scooters left = Total scooters - (Number of full trucks * Scooters per truck) = 767 - (2 * 369) = 767 - 738 = 29 ### Answer: 29
Expected answer: 29
Correct? Yes
Problem: There are 846 water droplets in a cloud. Each raindrop needs 722 droplets to form. If all droplets are used to form raindrops, how many droplets would be left unconverted in the cloud after reaching the maximum number of rain drops?
Mistral 7B:
Reasoning: To find the number of raindrops that can be formed, we divide the total number of water droplets by the number of droplets needed for each raindrop. Number of raindrops = Total number of water droplets / Droplets per raindrop Number of raindrops = 846 / 722 Number of raindrops ≈ 1.184 (rounded to two decimal places) Since we cannot have a fraction of a raindrop, we round down to the nearest whole number, which is 1. This means that only 1 raindrop can be formed from the given number of water droplets. The remaining water droplets that are left unconverted are: 846 - (Number of raindrops * Droplets per raindrop) 846 - (1 * 722) = 124 ### Answer: 124
Expected answer: 124
Correct? Yes
Problem: There was a slight miscalculation in the cloud's droplet count. There are actually 846 water droplets in the cloud, but each raindrop needs 442 droplets to form instead of 722. With this updated droplet count per raindrop, how many droplets would be left unconverted in the cloud after reaching the maximum number of rain drops?
Mistral 7B:
Reasoning: To find the number of raindrops that can be formed, we divide the total number of water droplets by the number of droplets needed for each raindrop. Number of raindrops = Total number of water droplets / Droplets per raindrop Number of raindrops = 846 / 442 Number of raindrops ≈ 1.958 (rounded to two decimal places) Since we cannot have a fraction of a raindrop, we round down to the nearest whole number, which is 2. This means that 2 raindrops can be formed from the given number of water droplets. The remaining water droplets that are left unconverted are: 846 - (Number of raindrops * Droplets per raindrop) 846 - (2 * 442) = 0 ### Answer: 0
Expected answer: 404
Correct? No
Problem: Unicorn Village, a magical place where 265 unicorns live, is divided into 146 equal sections where these magical creatures reside. If each section is occupied by an equal number of unicorns, how many unicorns will live in the last incomplete section?
Mistral 7B:
Reasoning: First, let's find out how many unicorns live in one section: 265 unicorns / 146 sections = <<265/146=1.8181818181818183>>1.82 unicorns per section (approximately). Since the number of unicorns in each section must be an integer, we round up to the nearest whole number, which is 2 unicorns per section. Now, let's find out how many sections are occupied: 146 sections - 1 (the last incomplete section) = <<146-1=145>>145 sections. The total number of unicorns in the 145 complete sections is: 145 sections * 2 unicorns/section = <<145*2=290>>290 unicorns. Since there are 265 unicorns in total, the number of unicorns in the last incomplete section is: 265 unicorns - 290 unicorns = <<265-290=-25>>-25 unicorns (since the number of unicorns must be positive, there are no unicorns in the last incomplete section). ### Answer: 0 unicorns (since the number of unicorns must be positive, there are no unicorns in the last incomplete section)
Expected answer: 119
Correct? No
Problem: In a game, there are 923 players waiting to enter a match. Only 383 players can enter a match at a time. If players enter matches evenly, how many players will be left waiting after filling all the matches?
Mistral 7B:
Reasoning: The number of matches that can be filled is 923/383 = <<923/383=2.4242424242424245>>2 (rounded up to 3) matches. Since each match can hold 383 players, the total number of players that can be accommodated is 3*383 = <<3*383=1149>>1149 players. The number of players left waiting is 923 - 1149 = <<923-1149=-226>>-226 (negative means more players left than can be accommodated, so there will be no players left waiting). ### Answer: -226 (There will be no players left waiting)
Expected answer: 157
Correct? No
Problem: A pirate ship has 923 cannonballs on board. They want to equally disperse them between 499 different crates. After evenly distributing them as much as possible, how many cannonballs will be left uncrated?
Mistral 7B:
Reasoning: To find out how many cannonballs each crate will hold, we divide the total number of cannonballs by the number of crates: 923 / 499 = <<923/499=1.8421052631578947>>1.8421 cannonballs per crate. Since we cannot have a fraction of a cannonball, we round down to the nearest whole number, which is 1 cannonball per crate. Now, we multiply the number of crates by the number of cannonballs per crate to find out how many cannonballs can fit in all the crates: 499 * 1 = <<499*1=499>>499. Since there are 923 cannonballs in total, the number of cannonballs left uncrated is 923 - 499 = <<923-499=424>>424. ### Answer: 424
Expected answer: 424
Correct? Yes
Problem: Keeping in line with the previous pirate ship themed problem, let's consider the following scenario: The same pirate ship initially started with 462 cannonballs instead of 923. After the pirates evenly distribute these cannonballs into the same 499 crates, can any be leftover? If so, how many cannonballs will be left uncrated?
Mistral 7B:
Reasoning: To find out how many cannonballs each crate will hold, we divide the total number of cannonballs by the number of crates: 462 / 499 = <<462/499=0.9248148148148148>>0.9248 cannonballs per crate. Since we cannot have a fraction of a cannonball, we round down to the nearest whole number, which is 1 cannonball per crate. Now, we multiply the number of crates by the number of cannonballs per crate to find out how many cannonballs can fit in all the crates: 499 * 1 = <<499*1=499>>499. Since there are 462 cannonballs in total, the number of cannonballs left uncrated is 462 - 499 = <<462-499=-37>>-37. However, since it's not possible to have a negative number of cannonballs, we know that there must be an error in the given information or our calculations. In this case, the pirates cannot evenly distribute the cannonballs into the given number of crates without leaving some uncrated. ### Answer: There will be uncrated cannonballs.
Expected answer: 462
Correct? No
Problem: A kite store has 530 string spools to attach to their kites. They distribute them to 518 kites, each getting one string spool. After each kite gets a spool, how many spools are left in the store?
Mistral 7B:
Reasoning: Each kite gets one string spool, so 518 kites get 518 spools. The store has 530 - 518 = <<530-518=12>>12 string spools left in the store. ### Answer: 12
Expected answer: 12
Correct? Yes
Problem: A dairy farm produces 913 gallons of milk in a day. If every milk jug holds 39 gallons, how many gallons will be left over after all the jugs are filled?
Mistral 7B:
Reasoning: The number of jugs needed to hold 913 gallons is 913/39 = <<913/39=23.41>>23 jugs (with a remainder of 13 gallons). Since each jug holds 39 gallons, 23 jugs will hold 23*39 = <<23*39=907>>907 gallons. The remaining 13 gallons will be left over. ### Answer: 13
Expected answer: 16
Correct? No
Problem: A doll seller received a shipment of 603 new dolls to put on the shelves. She arranged all the dolls in rows, with 369 dolls in each row. After filling up the rows as much as possible, how many dolls were left unarranged?
Mistral 7B:
Reasoning: First, let's find out how many complete rows the seller made with 603 dolls. Number of complete rows = Total dolls / Dolls per row = 603 / 369 = 1.62 (rounded down to 1 because you can't have a fraction of a row) Since there is only 1 complete row, the remaining dolls will be the total number of dolls minus the number of dolls in that complete row: Unarranged dolls = Total dolls - Dolls in complete row = 603 - 369 = <<603-369=234>>234 dolls. ### Answer: 234
Expected answer: 234
Correct? Yes
Problem: In the previous doll problem, if the doll seller initially received a shipment of 44 new dolls instead of 603, and still arranged them in rows of 369 dolls, how many dolls would be left unarranged after filling up the rows as much as possible?
Mistral 7B:
Reasoning: First, let's find out how many complete rows the seller can make with 44 dolls. Number of complete rows = Total dolls / Dolls per row = 44 / 369 = 0.12 (rounded down to 0 because you can't have a fraction of a row) Since there are no complete rows, all 44 dolls will be left unarranged. ### Answer: 44
Expected answer: 44
Correct? Yes
Problem: A jewelry maker has 850 beads to make necklaces. They use 631 beads for each necklace. After using as many beads as possible, how many beads will the jewelry maker have left over?
Mistral 7B:
Reasoning: The jewelry maker can make 850/631 = <<850/631=1.3456712745192983>>1.3456712745192983 necklaces. Since the jewelry maker cannot make a fraction of a necklace, they will make 1 whole necklace and have 850 - (631*1) = <<850-631=219>>219 beads left over. ### Answer: 219
Expected answer: 219
Correct? Yes
Problem: The jewelry maker decides to change the design and now each necklace uses only 150 beads instead of 631 beads. After they distribute the 850 beads as equally as possible among the new necklaces, how many beads will the jewelry maker have left over?
Mistral 7B:
Reasoning: The jewelry maker can now make 850/150 = <<850/150=5.6666666666666664>>5.6666666666666664 necklaces. Since the jewelry maker cannot make a fraction of a necklace, they will make 5 whole necklaces and have 850 - (150*5) = <<850-750=100>>100 beads left over. ### Answer: 100
Expected answer: 100
Correct? Yes
Problem: A gardener has 952 grapes that he wants to package into boxes. If each box can hold 380 grapes, how many grapes will be left after the gardener has filled as many boxes as possible?
Mistral 7B:
Reasoning: The gardener can fill <<952/380=2.5263157894736843>>2 boxes completely, and he can fill an additional <<(952 mod 380)=172>>172 grapes into the third box. Since the third box can only hold 380-172 = <<380-172=208>>208 grapes, there will be 172-208 = <<172-208=-36>>36 grapes left after filling as many boxes as possible. ### Answer: -36 (Note: In this case, a negative number indicates that there are more grapes than can be packed into boxes.)
Expected answer: 192
Correct? No
Problem: On a treasure map, there are 236 steps mentioned on the guide. If every 44 steps I make leads me to a significant place or clue, how many steps will be left after I reach the last significant place or clue?
Mistral 7B:
Reasoning: Let's find out how many groups of 44 steps there are in 236 steps. We can do this by dividing 236 by 44. 236 divided by 44 equals 5.363636... but since we cannot have a fraction of a step, we round down to 5 groups. Since each group consists of 44 steps, the total number of steps in these 5 groups is 5 * 44 = <<5*44=220>>220 steps. Now, we subtract the number of steps in the 5 groups from the total number of steps on the map to find the remaining steps. 236 - 220 = <<236-220=16>>16 steps are left after reaching the last significant place or clue. ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: Sarah blew 932 bubbles using her new bubble machine. The machine is designed to form groups of 507 bubbles each before releasing them. After forming complete groups, how many bubbles does it make in its final, incomplete group?
Mistral 7B:
Reasoning: First, let's find out how many complete groups Sarah's machine can form with the given number of bubbles: Number of complete groups = Total bubbles / Bubbles per group = 932 / 507 ≈ 1.84 Since the machine can't form a fraction of a group, we'll round down to 1 complete group. Now, let's find out how many bubbles are left after forming the complete groups: Remaining bubbles = Total bubbles - (Number of complete groups * Bubbles per group) = 932 - (1 * 507) = 425 ### Answer: 425
Expected answer: 425
Correct? Yes
Problem: Suppose Sarah uses her bubble machine again, this time to blow 904 bubbles. The machine is still designed to form groups of 507 bubbles each before releasing them. After forming complete groups, how many bubbles does it make in its final, incomplete group?
Mistral 7B:
Reasoning: First, let's find out how many complete groups Sarah's machine can form with the given number of bubbles: Number of complete groups = Total bubbles / Bubbles per group = 904 / 507 ≈ 1.78 Since the machine can't form a fraction of a group, we'll round down to 1 complete group. Now, let's find out how many bubbles are left after forming the complete groups: Remaining bubbles = Total bubbles - (Number of complete groups * Bubbles per group) = 904 - (1 * 507) = 407 ### Answer: 407
Expected answer: 397
Correct? No
Problem: At the park, there are 931 kids who want to use the swings. Each swing set can accommodate 34 kids at a time. If all the swing sets are filled continuously, how many kids will be waiting for their turn after all the swing sets are occupied?
Mistral 7B:
Reasoning: First, let's find out how many swing sets are needed to accommodate all the kids. Number of swing sets = Total kids / Kids per swing set = 931 / 34 = <<931/34=27>>27 swing sets. Since each swing set can accommodate 34 kids, the total number of kids that can be accommodated by all the swing sets is: Total kids accommodated = Swing sets * Kids per swing set = 27 * 34 = <<27*34=918>>918 kids. Since there are 931 kids in total, the number of kids waiting for their turn after all the swing sets are occupied is: Kids waiting = Total kids - Kids accommodated = 931 - 918 = <<931-918=13>>13 kids. ### Answer: 13
Expected answer: 13
Correct? Yes
Problem: In the previous scenario, let's say that some of the kids finished their swinging and left the park. Now, there are only 708 kids waiting to use the swings. Each swing set can still accommodate 34 kids at a time. Given this new number, how many children will be waiting for their turn after all the swing sets are occupied?
Mistral 7B:
Reasoning: First, let's find out how many swing sets are needed to accommodate the remaining kids. Number of swing sets = Remaining kids / Kids per swing set = 708 / 34 = <<708/34=21>>21 swing sets. Since each swing set can accommodate 34 kids, the total number of kids that can be accommodated by all the swing sets is: Total kids accommodated = Swing sets * Kids per swing set = 21 * 34 = <<21*34=704>>704 kids. Since there are 708 kids in total, the number of kids waiting for their turn after all the swing sets are occupied is: Kids waiting = Total kids - Kids accommodated = 708 - 704 = <<708-704=4>>4 kids. ### Answer: 4
Expected answer: 28
Correct? No
Problem: John has 943 dollar bills in his possession. He tries to stuff them in wallets that can each contain 433 dollar bills. After fully loading as many wallets as he can, how many dollar bills does he have left?
Mistral 7B:
Reasoning: John can fit 943/433 = <<943/433=2.1851851851851853>>2 wallets in his possession. Since he can't have a fraction of a wallet, he can only fit 2 wallets. The remaining dollar bills are 943 - (2 * 433) = <<943-(2*433)=-20>>-20. However, since John can't have a negative number of dollar bills, he must have made an error in his calculation or there is a mistake in the given information. ### Answer: There is an error in the given information or John made a mistake in his calculation.
Expected answer: 77
Correct? No
Problem: A helicopter pilot plans to transport 240 passengers over several trips. He can carry 177 passengers in one trip. How many passengers will be left behind after the helicopter makes the first full trip?
Mistral 7B:
Reasoning: The helicopter can carry 177 passengers in one trip. After the first full trip, there will be 240 - 177 = <<240-177=63>>63 passengers left behind. ### Answer: 63
Expected answer: 63
Correct? Yes
Problem: A gardener has 982 flowers to plant in flowerbeds. Each flowerbed can fit 555 flowers. After filling up as many flowerbeds as possible, how many flowers will the gardener have left to plant?
Mistral 7B:
Reasoning: The gardener can fill up 982/555 = <<982/555=1.77381961>>1 flowerbed with the remaining flowers being 982 - (1 * 555) = <<982-(1*555)=127>>127. Since the gardener cannot fill up a fraction of a flowerbed, the gardener will have 127 flowers left to plant. ### Answer: 127
Expected answer: 427
Correct? No
Problem: A farmer grows 203 strawberry plants. She wants to divide her plants into groups of 5 to sell. How many plants will be remaining if she divides them equally?
Mistral 7B:
Reasoning: The number of groups is 203/5 = <<203/5=40.6>>40 (rounded down to 40 since you can't divide plants). Each group consists of 5 plants, so the number of plants in each group is 5. The remaining plants are 203 - (40 * 5) = <<203-(40*5)=23>>23 plants. ### Answer: 23
Expected answer: 3
Correct? No
Problem: A gardener has 355 carrots. He wants to create bundles of 16. After creating as many bundles as he can, how many carrots will he have left?
Mistral 7B:
Reasoning: The number of bundles the gardener can create is 355/16 = <<355/16=21.9375>>21 (since he cannot create a fraction of a bundle). The number of carrots left after creating 21 bundles is 355 - (21 * 16) = <<355-(21*16)=14>>14. ### Answer: 14
Expected answer: 3
Correct? No
Problem: A total rainfall of 612 inches fell over a certain city in 29 consecutive days. If the rain fell in the same amount every day, how many inches of rain would be left to make the days evenly rainy?
Mistral 7B:
Reasoning: To make the days evenly rainy, we need to find the greatest common divisor (GCD) of 612 and 29. The GCD of 612 and 29 can be found using the Euclidean algorithm: 1. Divide 612 by 29: 612 ÷ 29 = 21 with a remainder of 4. 2. Divide the remainder (4) by the divisor (29): 4 ÷ 29 = 0 with a remainder of 4. Since the remainder is 0, the GCD is 29. However, since we want to find the number of inches of rain left to make the days evenly rainy, we need to subtract the GCD from the total rainfall: 612 - 29 = <<612-29=583>>583 inches. ### Answer: 583
Expected answer: 3
Correct? No
Problem: A truck company has got 514 boxes for delivery. Each truck can hold up to 371 boxes. If each truck is loaded to its full capacity, how many boxes will be left over?
Mistral 7B:
Reasoning: The number of boxes left over is the total number of boxes minus the number of boxes that can be carried by the trucks. 514 boxes - (514 mod 371) boxes = 514 - 1 boxes = <<514-1=513>>513 boxes. Since 371 is not a factor of 514, there will be 1 box left over. ### Answer: 1
Expected answer: 143
Correct? No
Problem: In a large sandbox, children create 684 sandcastles over the summer. The sandcastles were grouped into sets of 230 for a photography contest. After all the sets were completed, how many sandcastles were left that didn't form a complete set?
Mistral 7B:
Reasoning: First, let's find out how many complete sets were made: 684 / 230 = <<684/230=3>>3 complete sets. Since there were 3 complete sets, there must have been 3 * 230 = <<3*230=690>>690 sandcastles in the complete sets. Now, let's find out how many sandcastles were left: 684 - 690 = <<684-690=-5>>-5 sandcastles were left that didn't form a complete set. However, since it's impossible to have a negative number of sandcastles, it means that there was an error in the information provided, and the question cannot be answered as stated. ### Answer: The question cannot be answered as stated.
Expected answer: 224
Correct? No
Problem: A toy manufacturer has a production run of 735 toy cars. They package the cars in packs of 348 for bulk shipments. If all the toy cars are divided equally among packs, how many toy cars will be left over after all full packs have been filled?
Mistral 7B:
Reasoning: First, let's find out how many full packs can be made with the given number of toy cars: 735 / 348 = <<735/348=2.108125>>2 (rounded down to 2 full packs) Since there are 2 full packs, there will be no leftover cars if the production run is exactly divisible by the pack size. However, since the production run is 735, there will be some leftover cars. To find the number of leftover cars, we can subtract the number of full packs from the total number of toy cars: 735 - (2 * 348) = 735 - 696 = <<735-696=39>>39 ### Answer: 39
Expected answer: 39
Correct? Yes
Problem: The toy manufacturer decides in the next production run to make only 77 toy cars instead of 735. Again, they package the cars in packs of 348 for bulk shipments. If all the toy cars are divided equally among these packs, how many toy cars will be left over after all full packs have been filled?
Mistral 7B:
Reasoning: First, let's find out how many full packs can be made with the given number of toy cars: 77 / 348 = <<77/348=0.220703125>>0 (rounded down to 0 full packs) Since there are no full packs, all the toy cars will be leftover. ### Answer: 77
Expected answer: 77
Correct? Yes
Problem: In a forest, there are 386 animals. Each woodlands territory can support 95 animals. If the existing animals are evenly distributed among the territories, how many animals will be left in the last not fully occupied territory?
Mistral 7B:
Reasoning: First, let's find out how many territories there are in the forest. We can do this by dividing the total number of animals by the number of animals each territory can support: 386 animals / 95 animals per territory = <<386/95=4>>4 territories. Since there are 4 territories, the last territory will not be fully occupied because there are only 386 animals and not 95 * 5 = 475 animals. To find out how many animals are left in the last not fully occupied territory, we subtract the total number of animals that can be supported by the first 3 territories from the total number of animals: 386 animals - (95 animals * 3) = 386 - 285 = <<386-285=101>>101 animals. Since there are 4 territories, the last territory will have 101 / 4 = <<101/4=25.25>>25 animals and 25 - 95 = -70 animals. However, it's impossible to have a negative number of animals, so we round down to 25 animals in the last not fully occupied territory. ### Answer: 25 animals will be left in the last not fully occupied territory.
Expected answer: 6
Correct? No
Problem: A forest has 801 trees. A tree disease starts to spread and is expected to affect 646 trees. If all the diseased trees have to be cut down evenly, how many trees are likely to stay healthy after the disease has affected all possible trees?
Mistral 7B:
Reasoning: The number of trees that will stay healthy is the total number of trees minus the number of diseased trees. The number of trees that will stay healthy is 801 - 646 = <<801-646=155>>155 trees. ### Answer: 155
Expected answer: 155
Correct? Yes
Problem: A rope manufacturer has made a rope of 934 meters in length. This rope is supposed to be cut into smaller pieces, each piece being 902 meters in length. After cutting into the maximum possible number of equal pieces, how many meters will the last piece of the rope be?
Mistral 7B:
Reasoning: The number of pieces that can be made from the rope is the quotient of the total length of the rope and the length of each piece. The number of pieces is 934/902 = <<934/902=1.037142857142857>>1 (approximately). Since it is not possible to have a fraction of a piece, the manufacturer will cut one more piece than the quotient indicates. The last piece will be the remainder when the total length of the rope is divided by the length of each piece. The last piece will be 934 mod 902 = <<934 mod 902=32>>32 meters. ### Answer: 32
Expected answer: 32
Correct? Yes
Problem: Continuing from the previous scenario, suppose that the manufacturer only made a rope of 202 meters in length initially. Applying the same method of cutting rope into pieces that are each 902 meters long, how many meters would the piece of the rope be now?
Mistral 7B:
Reasoning: The number of pieces that can be made from the rope is the quotient of the total length of the rope and the length of each piece. The number of pieces is 202/902 = <<202/902=0.22361114753611147>>0 (approximately). Since it is not possible to have a fraction of a piece, the manufacturer will not be able to cut any pieces from the rope. ### Answer: 0
Expected answer: 202
Correct? No
Problem: A dairy farm produces 561 liters of milk each day. The milk is packaged into 550-liter containers. How many liters of milk are left over each day after filling the containers?
Mistral 7B:
Reasoning: The dairy farm can fill 550 containers with milk each day. The remaining milk after filling the containers is 561 - (550 * 1) = <<561-(550*1)=11>>11 liters. ### Answer: 11
Expected answer: 11
Correct? Yes
Problem: If the dairy farm increased its production and started producing 729 liters of milk each day instead of 561 liters, how many liters of milk would be left over each day after filling the 550-liter containers?
Mistral 7B:
Reasoning: The dairy farm can fill 550 containers with milk each day. The remaining milk after filling the containers is 729 - (550 * 1) = <<729-(550*1)=79>>79 liters. ### Answer: 79
Expected answer: 179
Correct? No
Problem: Jon has 259 puzzle pieces. If each puzzle requires 258 pieces, how many pieces will be left over once he completes a full puzzle?
Mistral 7B:
Reasoning: Jon needs 258 pieces for one puzzle, so he can complete one puzzle with 259-258 = <<259-258=1>>1 piece left over. ### Answer: 1
Expected answer: 1
Correct? Yes
Problem: In the previous problem, Jon had 259 puzzle pieces and each puzzle requires 258 pieces. Suppose instead each puzzle needs 542 pieces. How many pieces would Jon have left over after finishing as many full puzzles as possible with his 259 pieces?
Mistral 7B:
Reasoning: First, let's find out how many full puzzles Jon can make with his 259 pieces. To do this, we divide the total number of pieces by the number of pieces needed for one puzzle: 259 / 542 = 0.4764705882352941. Since Jon can't make a fraction of a puzzle, we round down to the nearest whole number, which is 0 puzzles. This means that Jon can't complete any full puzzles with his 259 pieces. Now, let's find out how many pieces are left over: 259 - (0 * 542) = 259. ### Answer: 259
Expected answer: 259
Correct? Yes
Problem: A jewelry maker has 673 beads. She plans to use exactly 49 beads for each bracelet. How many beads will she have left after creating as many bracelets as possible with the exact number of beads?
Mistral 7B:
Reasoning: The number of bracelets she can make is 673/49 = <<673/49=13.551020408163265>>13 bracelets (since she cannot make a fraction of a bracelet). She will have 673 - (13 * 49) = <<673-(13*49)=0>>0 beads left after creating as many bracelets as possible. ### Answer: 0
Expected answer: 36
Correct? No
Problem: A police station received 927 calls within a week. They have 311 operators who can handle the same number of calls each week. However, when the calls are divided equally, how many calls will the last operator handle?
Mistral 7B:
Reasoning: First, let's find out how many calls each operator can handle in a week: 927 calls / 311 operators = <<927/311=3>>3 calls per operator. Since there are 311 operators, the last operator will handle 3 calls as well. ### Answer: 3
Expected answer: 305
Correct? No
Problem: John has 764 pieces for his jigsaw puzzle, and every package should contain 589 pieces. If he separates these pieces into full packages, how many pieces will be left outside without a package?
Mistral 7B:
Reasoning: First, let's find out how many full packages John can make with 764 pieces: 764 / 589 = <<764/589=1.3041592653061224>>1 package and some leftovers. Since John cannot have a fraction of a package, he will make one less full package, leaving him with 589 pieces for the next package. The remaining pieces (764 - 589) = <<764-589=175>>175 pieces will be left outside without a package. ### Answer: 175
Expected answer: 175
Correct? Yes
Problem: If John had originally only 404 puzzle pieces, and each package can still only contain 589, how many pieces will be left outside the package now?
Mistral 7B:
Reasoning: Since John cannot make a full package with 404 pieces, all the pieces will be left outside the package. ### Answer: 404
Expected answer: 404
Correct? Yes
Problem: A dressmaker has 984 meters of fabric. She uses 217 meters of fabric to make each dress. After using all the fabric she can to make as many dresses as possible, how many meters of fabric will she have left?
Mistral 7B:
Reasoning: The dressmaker can make 984/217 = <<984/217=4.5034226218487>>4 dresses with the given amount of fabric. Since she cannot make a fraction of a dress, she will make 4 dresses and have 984 - (4 * 217) = <<984-(4*217)=-13>>-13 meters of fabric left. However, since it is not possible to have a negative amount of fabric, the dressmaker will need to buy more fabric to make the dresses. ### Answer: The dressmaker will need to buy more fabric to make the dresses.
Expected answer: 116
Correct? No
Problem: A company donates 639 sleeping bags for a camping event. Each campsite is supplied with 374 sleeping bags. If all the sleeping bags are divided equally among the campsites, how many sleeping bags will there be left?
Mistral 7B:
Reasoning: The number of sleeping bags per campsite is 374. To find out how many campsites there are, we divide the total number of sleeping bags by the number of sleeping bags per campsite: 639 / 374 = <<639/374=1.68553203125>>1 (rounded down to the nearest whole number). Since there is only one campsite, there will be no sleeping bags left over. ### Answer: 0
Expected answer: 265
Correct? No
Problem: A pizza restaurant made 620 pizzas today. They package up the pizzas in boxes that hold 578 each for delivery. If the pizzas are evenly distributed into these boxes, how many pizzas will be left over that don't fit into a box?
Mistral 7B:
Reasoning: The number of boxes needed to hold all the pizzas is 620/578. Since the number of boxes must be a whole number, we can't divide 620 by 578 exactly. This means that there will be some pizzas left over. To find out how many pizzas are left over, we can calculate the remainder when 620 is divided by 578: 620 % 578 = 44. ### Answer: 44 pisas will be left over that don't fit into a box.
Expected answer: 42
Correct? No
Problem: A factory made a total of 820 robots. It can store 684 robots in one storage unit. If the robots are evenly stored, how many robots will not fit and remain outside of the storage units?
Mistral 7B:
Reasoning: The factory can store 684 robots in one storage unit. To find out how many robots can be stored in 2 storage units, we multiply the capacity of one storage unit by 2: 684 * 2 = <<684*2=1368>>1368 robots. Since the factory made a total of 820 robots, and it can store 1368 robots in 2 storage units, the number of robots that will not fit and remain outside of the storage units is 820 - 1368 = <<820-1368=-548>>-548. However, since it's not possible to have a negative number of robots, we can conclude that all the robots can be stored in the storage units, and there will be no robots remaining outside. ### Answer: 0 (or None)
Expected answer: 136
Correct? No
Problem: A cloud changes its shape by reducing its water droplets. Initially, there were 516 droplets in the cloud. If the cloud loses water droplets at an equal rate and becomes entirely dry after every 289 droplets, how many droplets will be left when the cloud is dry after the final cycle?
Mistral 7B:
Reasoning: The cloud loses 289 droplets at a time. To find out how many times the cloud loses droplets before it becomes entirely dry, we divide the initial number of droplets by the number of droplets lost per cycle: 516/289 = <<516/289=1.7755102040816327>>1.7755 (approximately). Since the cloud cannot have a fraction of a droplet, we round down to the nearest whole number, which is 1. So, the cloud goes through 1 cycle and loses 289 droplets. After the first cycle, there are 516 - 289 = <<516-289=227>>227 droplets left. In the second cycle, the cloud loses another 289 droplets, leaving 227 - 289 = <<227-289=-62>>-62 droplets. Since the cloud cannot have a negative number of droplets, we know that the cloud becomes entirely dry after the first cycle, and there are no droplets left when the cloud is dry after the final cycle. ### Answer: 0
Expected answer: 227
Correct? No
Problem: A transport company needs to load 330 boxes into trucks. Each truck can hold exactly 4 boxes. After filling each truck to its full capacity, how many boxes will be left unloaded?
Mistral 7B:
Reasoning: The number of trucks needed to carry 330 boxes is 330/4 = <<330/4=82.5>>82 trucks (since we cannot have a fraction of a truck). Since each truck can hold exactly 4 boxes, the total number of boxes that can be loaded into 82 trucks is 82*4 = <<82*4=328>>328 boxes. The number of boxes left unloaded is 330 - 328 = <<330-328=2>>2 boxes. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: The transport company now needs to load a new batch of 274 boxes into trucks. Again, each truck can hold exactly 4 boxes. After filling each truck to its full capacity, how many boxes will be left unloaded this time?
Mistral 7B:
Reasoning: The number of trucks needed to carry 274 boxes is 274/4 = <<274/4=68.5>>68 trucks (since we cannot have a fraction of a truck). Since each truck can hold exactly 4 boxes, the total number of boxes that can be loaded into 68 trucks is 68*4 = <<68*4=272>>272 boxes. The number of boxes left unloaded is 274 - 272 = <<274-272=2>>2 boxes. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: A farmer harvested 649 potatoes this season. He decides to pack them into crates each containing 183 potatoes. How many potatoes will be left after all crates are filled to their maximum capacity?
Mistral 7B:
Reasoning: The number of crates needed to hold all the potatoes is 649/183 = <<649/183=3.5376271186440676>>3 crates (rounded up to 4 crates since you can't have a fraction of a crate). Since each crate can hold 183 potatoes, the total number of potatoes in the 4 crates is 4*183 = <<4*183=728>>728 potatoes. The number of potatoes left after all crates are filled is 649 - 728 = <<649-728=-79>>-79. However, since it's impossible to have a negative number of potatoes, we can conclude that the question has an error and there should be no potatoes left after all crates are filled. ### Answer: There should be no potatoes left after all crates are filled.
Expected answer: 100
Correct? No
Problem: A t-shirt company has a batch of 258 shirts in production. Each box can pack 67 shirts. If all the shirts are evenly distributed in the boxes, how many shirts would be left outside the boxes?
Mistral 7B:
Reasoning: First, let's find out how many boxes are needed to pack all the shirts: 258 shirts / 67 shirts per box = <<258/67=3.87719298245614>>4 boxes (since we cannot have a fraction of a box). Since each box can hold 67 shirts, the total number of shirts that can be packed in 4 boxes is 4 * 67 = <<4*67=268>>268 shirts. Now, let's find out how many shirts are left outside the boxes: 258 shirts - 268 shirts = <<258-268=-10>>-10 shirts. However, since it's impossible to have a negative number of shirts, there must be an error in the given information. The number of shirts in the batch should be less than 268 to ensure that all shirts can be packed in the boxes. ### Answer: There is an error in the given information. The number of shirts in the batch should be less than 268 to ensure that all shirts can be packed in the boxes.
Expected answer: 57
Correct? No
Problem: On a pirate ship, there are 995 gold coins that need to be evenly divided among the 267 pirates. If they split the gold up as evenly as possible, how many gold coins will be left over?
Mistral 7B:
Reasoning: First, let's find out how many groups of pirates there are by dividing the total number of gold coins by the number of pirates: 995 / 267 = <<995/267=3.7142857142857145>>3.714... (rounded to 4 decimal places). Since it's not possible to divide the gold coins evenly among the pirates, we'll round down to 3 groups. Now, let's find out how many gold coins each group will get: 995 / (267 * 3) = <<995/(267*3)=2.142857142857143>>2.142... (rounded to 4 decimal places). Since it's not possible to divide the gold coins evenly among the groups, we'll round down to 2 gold coins per group. Now, let's find out how many gold coins are left over: 995 - (2 * 267) = <<995-(2*267)=10>>10 gold coins. ### Answer: 10
Expected answer: 194
Correct? No
Problem: There are 776 snails all lined up in a row. If you group them in bunches of 375 snails, how many snails will be left in the final group?
Mistral 7B:
Reasoning: First, let's find out how many groups can be formed by dividing 776 by 375. 776 / 375 = <<776/375=2>>2 groups can be formed. Since there are 2 groups, there will be no snails left in the final group. ### Answer: 0
Expected answer: 26
Correct? No
Problem: A pillow factory produces 589 pillows per day. They package these pillows in boxes, and each box holds 198 pillows. If they pack as many full boxes as possible, how many pillows will be left outside the boxes at the end of the day?
Mistral 7B:
Reasoning: First, let's find out how many full boxes can be made with the given number of pillows: 589 pillows / 198 pillows per box = <<589/198=2.9621052631578947>>3 boxes (rounded down since we cannot have a fraction of a box). Now, let's calculate the number of leftover pillows: 589 pillows - (3 boxes * 198 pillows per box) = 589 - (3 * 198) = 589 - 594 = -5 (negative value indicates that there are actually fewer pillows than boxes). Since it's impossible to have negative pillows, there must have been an error in the calculation. Let's assume that the factory can pack a fraction of a box. In this case, the factory can pack 3 full boxes and an additional 99/198 of a box (rounded to the nearest whole number). The number of leftover pillows is then 589 - (3 * 198) - (198 * (99/198)) = 589 - 594 - 99 = -4 (still negative, so let's round up the number of full boxes to 4 and adjust the fraction accordingly). Now, the factory can pack 4 full boxes and an additional 198 * (1 - (99/198)) = 198 * (197/198) = 197 pillows. The total number of pillows is now 589 + 197 = 786. The number of leftover pillows is then 786 - (4 * 198) = 786 - 792 = -6 (still negative, so let's round up the number of full boxes to 5 and adjust the fraction accordingly). Now, the factory can pack 5 full boxes and an additional 198 * (1 - (99/198)) = 198 * (197/198) = 197 pillows. The total number of pillows is now 589 + 197 + 197 = 983. The number of leftover pillows is then 983 - (5 * 198) = 983 - 990 = -7 (still negative, so let's round up the number of full boxes to 6 and adjust the fraction accordingly). Now, the factory can pack 6 full boxes and an additional 198 * (1 - (99/198)) = 198 * (197/198) = 197 pillows. The total number of pillows is now 589 + 197 + 197 + 197 = 1080. The number of leftover pillows is then 1080 - (6 * 198) = 1080 - 1188 = -108 (still negative, so let's round up the number of full boxes to 7 and adjust the fraction accordingly). Now, the factory can pack 7 full boxes and an additional 198 * (1 - (99/198)) = 198 * (197/198) = 197 pillows. The total number of pillows is now 589 + 197 + 197 + 197 + 197 = 1387. The number of leftover pillows is then 1387 - (7 * 198) = 1387 - 1386 = 1 (finally, a positive number!). ### Answer: 1
Expected answer: 193
Correct? No
Problem: A jewelry maker has 633 beads. If she uses beads to make necklaces, with each necklace using exactly 30 beads, how many beads will she have left after making as many necklaces as she can?
Mistral 7B:
Reasoning: The number of necklaces she can make is 633/30 = <<633/30=21.1>>21.1 (rounded down to 21 since she cannot make a fraction of a necklace). She will have 633 - (21 * 30) = <<633-(21*30)=0>>0 beads left after making 21 necklaces. ### Answer: 0
Expected answer: 3
Correct? No
Problem: John has collected 365 coins. He decided to put equal numbers of them in his 140 wallets. However, he found out he would still have some coins left after evenly distributing them into these wallets. How many coins will John have left?
Mistral 7B:
Reasoning: Let's find out how many coins John can put in each wallet: Number of coins per wallet = Total number of coins / Number of wallets Number of coins per wallet = 365 / 140 = <<365/140=2.607142857142857>>2.607142857142857 coins per wallet (rounded down to 2 since he cannot have a fraction of a coin) Since John has 140 wallets, he can put 140 * 2 = <<140*2=280>>280 coins in the wallets. Now, let's find out how many coins John has left: Coins left = Total number of coins - Coins in wallets Coins left = 365 - 280 = <<365-280=85>>85 coins ### Answer: 85
Expected answer: 85
Correct? Yes
Problem: Now, suppose John comes across additional coins and his collection increases to 739 coins. He again tries to evenly distribute these coins among his 140 wallets. How many coins will John have left after this distribution?
Mistral 7B:
Reasoning: Since John already has 140 wallets, he will still distribute the coins in the same way as before: Number of coins per wallet = Total number of coins / Number of wallets Number of coins per wallet = 739 / 140 = <<739/140=5.278571428571429>>5.278571428571429 coins per wallet (rounded down to 5 since he cannot have a fraction of a coin) Now, let's find out how many coins John can put in the wallets: Coins in wallets = Number of wallets * Coins per wallet Coins in wallets = 140 * 5 = <<140*5=700>>700 coins Since John has 739 coins in total, he will have 739 - 700 = <<739-700=39>>39 coins left after distributing them among the wallets. ### Answer: 39
Expected answer: 39
Correct? Yes
Problem: A sock manufacturer produces 743 socks in a single production run. The socks are packed into cartons, each containing 451 socks. After filling up as many cartons as possible, how many socks are left unpacked?
Mistral 7B:
Reasoning: First, let's find out how many full cartons can be made with the given number of socks: 743 socks / 451 socks per carton = <<743/451=1.6448490192092895>>1 (rounded down to 1). So, 1 carton is filled, and there are 743 - 451 = <<743-451=292>>292 socks left. ### Answer: 292
Expected answer: 292
Correct? Yes
Problem: Now suppose the sock manufacturer changes their packaging method and each carton contains 179 socks instead of 451 socks. After filling up as many cartons as possible with 743 socks, how many socks are left unpacked?
Mistral 7B:
Reasoning: First, let's find out how many full cartons can be made with the new packaging method: 743 socks / 179 socks per carton = <<743/179=4.134764705882353>>4 (rounded down to 4). So, 4 cartons are filled, and there are 743 - 179*4 = <<743-676=67>>67 socks left. ### Answer: 67
Expected answer: 27
Correct? No
Problem: A total of 923 children want to slide down a slide at an amusement park. If 771 children can go down the slide without rest, how many children will be left waiting for their turn?
Mistral 7B:
Reasoning: The number of children left waiting for their turn is the total number of children minus the number of children who can go down the slide without rest. The number of children left waiting is 923 - 771 = <<923-771=152>>152 children. ### Answer: 152
Expected answer: 152
Correct? Yes
Problem: After the first 771 children go down the slide, another wave of children arrives and now there are 923 children in total waiting again. If 881 children can go down the slide without any break this time, how many children will be left waiting for their turn?
Mistral 7B:
Reasoning: First, we find out how many children can go down the slide without rest after the second wave arrives: 881 children. Then, we subtract the number of children who went down the slide after the first wave from the total number of children after the second wave: 923 - 771 = 152 children. Finally, we subtract the number of children who went down the slide after the second wave from the number of children who can go down the slide after the second wave: 881 - 152 = <<881-152=729>>729 children. ### Answer: 0 (No children will be left waiting for their turn)
Expected answer: 42
Correct? No
Problem: Superhero Iron Punch has to save 442 people from a collapsing building. He can teleport a maximum of 104 people at a time to safety. After teleporting as many full groups as he can, how many people will be left in the building for his last round of rescue?
Mistral 7B:
Reasoning: First, let's find out how many full groups Iron Punch can teleport: 442 / 104 = <<442/104=4.2428720701754385>>4 groups. Since Iron Punch can't teleport a fraction of a group, he can only teleport 4 groups of 104 people each, which is a total of 4 * 104 = <<4*104=416>>416 people. Now, let's find out how many people are left in the building: 442 - 416 = <<442-416=26>>26 people. ### Answer: 26
Expected answer: 26
Correct? Yes
Problem: What if there were actually 512 people in the collapsing building instead of 442? After Superhero Iron Punch teleports as many full groups of 104 people as he can to safety, how many people will be left in the building for his last round of rescue now?
Mistral 7B:
Reasoning: First, let's find out how many full groups Iron Punch can teleport: 512 / 104 = <<512/104=4.904761904761905>>5 groups. Since Iron Punch can't teleport a fraction of a group, he can only teleport 5 groups of 104 people each, which is a total of 5 * 104 = <<5*104=520>>520 people. Now, let's find out how many people are left in the building: 512 - 520 = <<512-520=-8>>-8 people. However, since it's impossible to have a negative number of people, there is an error in the problem. It seems that there are not enough people for Iron Punch to rescue everyone. ### Answer: There is an error in the problem. It's impossible to have a negative number of people.
Expected answer: 96
Correct? No
Problem: A card game manufacturer creates a deck of cards with 569 cards. Each card pack has 68 cards. After creating as many packs as possible, how many cards will the manufacturer have left over?
Mistral 7B:
Reasoning: First, let's find out how many packs can be made with 569 cards. Number of packs = Total cards / Cards per pack = 569 / 68 = 8.385285714285714. Since it's not possible to have a fraction of a pack, the manufacturer can make 8 packs. The remaining cards = Total cards - (Number of packs * Cards per pack) = 569 - (8 * 68) = 569 - 528 = 41. ### Answer: 41
Expected answer: 25
Correct? No
Problem: A stationery store received a shipment of 842 erasers. The store owner wants to display them in boxes, with each box containing 719 erasers. After filling as many boxes as possible, how many erasers will be left over?
Mistral 7B:
Reasoning: First, let's find out how many full boxes can be made with the given number of erasers: 842 erasers / 719 erasers per box = <<842/719=1.1864565217391303>>1 box with some erasers left over. Since it's not possible to have a fraction of a box, we'll round down to 1 full box and subtract it from the total number of erasers to find the remaining erasers: 842 erasers - 719 erasers per box * 1 box = <<842-719*1=123>>123 erasers will be left over. ### Answer: 123
Expected answer: 123
Correct? Yes
Problem: Suppose the stationery store owner later decided to display the erasers in smaller boxes, with each box containing 420 erasers instead. After filling as many boxes as possible, how many erasers will be left over now?
Mistral 7B:
Reasoning: First, let's find out how many full boxes can be made with the given number of erasers: 842 erasers / 420 erasers per box = <<842/420=2.004761904761905>>2 boxes with some erasers left over. Since it's not possible to have a fraction of a box, we'll round down to 2 full boxes and subtract it from the total number of erasers to find the remaining erasers: 842 erasers - 420 erasers per box * 2 boxes = <<842-420*2=202>>202 erasers will be left over. ### Answer: 202
Expected answer: 2
Correct? No
Problem: A farmer harvested 461 carrots from his garden. He packs them into boxes, each box can hold up to 244 carrots. After packing as many full boxes as possible, how many carrots will be left unpacked?
Mistral 7B:
Reasoning: First, let's find out how many full boxes the farmer can pack: 461 carrots / 244 carrots per box = <<461/244=1.88477192982041>>1 (since the farmer can't pack a fraction of a box). Now, let's find out how many carrots are left unpacked: 461 carrots - (number of full boxes * 244 carrots per box) = 461 - (1 * 244) = <<461-(1*244)=117>>117 carrots will be left unpacked. ### Answer: 117
Expected answer: 217
Correct? No
Problem: A penguin scientist counts 309 penguins in a colony. She decides to tag them in groups of 293 for easier tracking. How many penguins will be in the final, possibly incomplete, group?
Mistral 7B:
Reasoning: The scientist tags penguins in groups of 293. To find out how many full groups can be formed, we divide the total number of penguins by the number of penguins per group: 309 / 293 = <<309/293=1.0521739130434783>>1 (approximately). Since it is not possible to form a full group with a fraction of a penguin, we round down to the nearest whole number, which is 1 group. The remaining penguins will be in the final, possibly incomplete, group: 309 - (293 * 1) = <<309-(293*1)=16>>16 penguins. ### Answer: 16
Expected answer: 16
Correct? Yes
Problem: The penguin scientist realizes she made a mistake and there were actually only 262 penguins in each group. How many penguins will be in the final, possibly incomplete, group now?
Mistral 7B:
Reasoning: The scientist tags penguins in groups of 262. To find out how many full groups can be formed, we divide the total number of penguins by the number of penguins per group: 309 / 262 = <<309/262=1.1753906257506103>>1 (approximately). Since it is not possible to form a full group with a fraction of a penguin, we round down to the nearest whole number, which is 1 group. The remaining penguins will be in the final, possibly incomplete, group: 309 - (262 * 1) = <<309-(262*1)=47>>47 penguins. ### Answer: 47
Expected answer: 47
Correct? Yes
Problem: A sandwich shop has 580 slices of bread. They use 18 slices of bread for each sandwich-making batch. After using up the bread in these batches, how many slices will they have left?
Mistral 7B:
Reasoning: The number of batches they can make is 580/18 = <<580/18=32.222222222222226>>32 (rounded down to 32 since you can't make a fraction of a batch). Since they use 18 slices per batch, they will have 580 - (32 * 18) = <<580-(32*18)=580-576=4>>4 slices left. ### Answer: 4
Expected answer: 4
Correct? Yes
Problem: The sandwich shop's supplier delivered an additional batch of bread, bringing their total to 580 slices. If the shop still makes sandwiches using 477 slices of bread per batch, how many slices will they have left after the latest batch of sandwiches is made?
Mistral 7B:
Reasoning: First, let's find out how many batches they can make with the new total of 580 slices: 580/477 = <<580/477=1.2035762711864406>>1 (rounded down to 1 since you can't make a fraction of a batch). Since they use 477 slices per batch, they will have 580 - (1 * 477) = <<580-(1*477)=47>>47 slices left after the latest batch of sandwiches is made. ### Answer: 47
Expected answer: 103
Correct? No
Problem: A tailor has 925 meters of fabric. The tailor uses 529 meters of fabric to make each dress. If the tailor uses the fabric evenly for each dress, how many meters of fabric will be left over after completing the dresses?
Mistral 7B:
Reasoning: The tailor can make 925/529 = <<925/529=1.7456787143787825>>1.7457 dresses with the given amount of fabric. Since the tailor cannot make a fraction of a dress, they can only make 1 complete dress and will have 925 - (529*1) = <<925-529=396>>396 meters of fabric left over. ### Answer: 396
Expected answer: 396
Correct? Yes
Problem: After making some dresses, the tailor now only has 62 meters of fabric left. If the tailor continues to use 529 meters of fabric to make each dress, how many meters of fabric will be left over after making the dresses?
Mistral 7B:
Reasoning: The tailor can make 62/529 = <<62/529=0.11618032786885246>>0.1162 dresses with the remaining fabric. Since the tailor cannot make a fraction of a dress, they can only make 0 complete dresses and will have 62 meters of fabric left over. ### Answer: 62
Expected answer: 62
Correct? Yes
Problem: There are 976 tourists wanting to explore a castle. Each tour group throughout the day accommodates up to 530 people. After all the groups have taken off, how many tourists will be left for the last group of the day?
Mistral 7B:
Reasoning: First, let's find out how many complete groups can be formed with 976 tourists. 976 / 530 = <<976/530=1.8437>>1 (since we cannot have a fraction of a group) Now, let's calculate the number of remaining tourists for the last group: Remaining tourists = Total tourists - (Number of complete groups * Capacity per group) Remaining tourists = 976 - (1 * 530) = <<976-(1*530)=446>>446 ### Answer: 446
Expected answer: 446
Correct? Yes
Problem: What would happen if the number of tourists wanting to explore the castle was still 976, but this time each group could accommodate up to 726 people? How many tourists would be left for the last group of the day now?
Mistral 7B:
Reasoning: First, let's find out how many complete groups can be formed with 976 tourists when each group can accommodate up to 726 people. 976 / 726 = <<976/726=1.3462>>1 (since we cannot have a fraction of a group) Now, let's calculate the number of remaining tourists for the last group: Remaining tourists = Total tourists - (Number of complete groups * Capacity per group) Remaining tourists = 976 - (1 * 726) = <<976-(1*726)=250>>250 ### Answer: 250
Expected answer: 250
Correct? Yes