Common Core Standard 4.OA.A.3
This standard covers the following:
Solve multistep word problems posed with whole numbers and having whole-number answers using the four operations, including problems in which remainders must be Interpreted. Represent these problems using equations with a letter standing for the unknown quantity. Assess the reasonableness of answers using mental computation and estimation strategies including rounding.
Problem: A songwriter creates a long ballad with many verses. Each verse has 162 words and he divides these into 18 lines per verse. This gives a certain number of words per line. To each line, he adds 34 more words as a refrain. What is the total number of words present in each line now?
Mistral 7B:
Reasoning: Each line in a verse has 162/18 = <<162/18=9>>9 words without the refrain. Each line now has 9+34 = <<9+34=43>>43 words. ### Answer: 43
Expected answer: 43
Correct? Yes
Problem: Following from the previous problem, the songwriter then decides to add an extra refrain to the end of each verse. If the refrain has 39 words, determine how many words are in each line after this final addition.
Mistral 7B:
Reasoning: Each line in a verse now has 43+39 = <<43+39=82>>82 words. ### Answer: 82
Expected answer: 82
Correct? Yes
Problem: In the previous problem, the songwriter added 34 words as the refrain to each line in his song. However, what if he had decided to keep the refrain a bit shorter and added only 28 words to each line instead? How many words would each line of the song contain in that case?
Mistral 7B:
Reasoning: Each line in a verse has 162/18 = <<162/18=9>>9 words without the refrain. Each line now has 9+28 = <<9+28=37>>37 words. ### Answer: 37
Expected answer: 37
Correct? Yes
Problem: A penguin biologist counted 35 penguins on a small ice floe. In another part of the Antarctic, she counted a different group of penguins and found there were approximately 598 divided evenly among 26 ice floes. After returning to the first place, she found that the penguin population had increased by 49. Wishing to conduct another survey, she decided to take 33 more penguins into account. However, when she counted them again, she realized she had overestimated and had to subtract 10 from her calculations. Her final step was to add in the penguins sheβd left at her base camp, which were 20 adults and 14 chicks. How many penguins did she count in total?
Mistral 7B:
Reasoning: 1. First, let's find the number of penguins on the second ice floe: 598 / 26 = <<598/26=22.615384615384615>>22.615 penguins per ice floe. Since there are 26 ice floes, there are 26 * 22.615 = <<26*22.615=582.615>>582.615 penguins in total on the second ice floe. 2. Next, let's account for the increase in the first ice floe: 35 + 49 = <<35+49=84>>84 penguins. 3. Then, let's account for the 33 additional penguins: 84 + 33 = <<84+33=117>>117 penguins. 4. After subtracting the overestimation of 10 penguins: 117 - 10 = <<117-10=107>>107 penguins. 5. Finally, let's add the penguins from the base camp: 107 + 20 adults + 14 chicks = <<107+20+14=141>>141 penguins in total. ### Answer: 141
Expected answer: 164
Correct? No
Problem: In a local park, a jungle gym has a total of 27 steps. If the top 19 steps are blue and rest along with another 19 steps are red, we get a certain number of colored steps. On another jungle gym, there are 34 green steps. What is the total number of colored steps on the two jungle gyms?
Mistral 7B:
Reasoning: The first jungle gym has 19 blue steps and 19 red steps, which is a total of 19+19 = <<19+19=38>>38 colored steps. The second jungle gym has 34 green steps, which are also colored steps. The total number of colored steps on the two jungle gyms is 38+34 = <<38+34=72>>72. ### Answer: 72
Expected answer: 61
Correct? No
Problem: If a cloud releases 47 millimeters of rainfall per hour over a one hour period, and the average cloud typically releases 775 millimeters of rainfall over the course of 31 hours, find the amount of rainfall from the following condition. Subtract 22 from the average rainfall of the typical cloud per hour then multiply this by 23. Add this result to a constant cloud factor of 42. Add this new result to the hourly rainfall of the initial cloud and subtract 2 from it. What is the resultant millimeters of rainfall?
Mistral 7B:
Reasoning: First, we find the average rainfall per hour of a typical cloud by dividing the total rainfall by the number of hours: 775/31 = <<775/31=24.64516129032258>>24.65 (rounded to two decimal places). Next, we subtract 22 from this value: 24.65 - 22 = <<24.65-22=2.65>>2.65. Then, we multiply this value by 23: 2.65 * 23 = <<2.65*23=60.35>>60.35. We add a constant cloud factor of 42: 60.35 + 42 = <<60.35+42=102.35>>102.35. Finally, we subtract 2 from the initial hourly rainfall of the cloud: 102.35 - 2 = <<102.35-2=100.35>>100.35. ### Answer: 100.35
Expected answer: 156
Correct? No
Problem: Nadia likes to practice playing the piano. The other day she practiced for 45 minutes in the morning. In the same day, she also practiced for another 35 minutes in the afternoon and then another 35 minutes in the evening. How long did Nadia practice the piano in total that day?
Mistral 7B:
Reasoning: Nadia practiced for 45 minutes in the morning, 35 minutes in the afternoon, and 35 minutes in the evening. Nadia practiced for a total of 45 + 35 + 35 = <<45+35+35=115>>115 minutes that day. ### Answer: 115 minutes.
Expected answer: 115
Correct? Yes
Problem: Reflecting upon her previous practice sessions, Nadia thought she could do more. She decided to adjust her morning practice time from 45 minutes to 26 minutes. Still maintaining her afternoon and evening sessions at 35 minutes each, how many minutes in total would Nadia be practicing for the day with this adjustment?
Mistral 7B:
Reasoning: With the adjustment, Nadia will practice for 26 minutes in the morning, 35 minutes in the afternoon, and 35 minutes in the evening. Nadia will practice for a total of 26 + 35 + 35 = <<26+35+35=96>>96 minutes that day. ### Answer: 96 minutes. utsch!
Expected answer: 96
Correct? Yes
Problem: A popular clothing store sells dresses for $44 each. During a flash sale, they further reduce prices by a factor of 465 divided by 31. How much does a dress cost during the flash sale?
Mistral 7B:
Reasoning: The price of a dress during the flash sale is the original price multiplied by the factor of reduction. The factor of reduction is (465/31). The price of a dress during the flash sale is $44 * (465/31) = $<<44*(465/31)=138.71>>138.71 (rounded to two decimal places). ### Answer: $138.71 (rounded to two decimal places)
Expected answer: 660
Correct? No
Problem: A rope maker made 46 meters of rope on Monday. On Tuesday, he made as many meters of rope as he did on Monday, plus an additional 19 meters. However, by Wednesday, 9 meters of this rope had been damaged and was unusable. How many meters of usable rope does he have after Wednesday?
Mistral 7B:
Reasoning: On Tuesday, the rope maker made 46+19 = <<46+19=65>>65 meters of rope. On Wednesday, 9 meters were damaged, so he has 65-9 = <<65-9=56>>56 meters of usable rope after Wednesday. ### Answer: 56
Expected answer: 56
Correct? Yes
Problem: Following the situation from the previous days, on Thursday, a merchant came to buy multiple lengths of the rope. Each length was as long as the total usable ropes the rope maker had after Wednesday. If the merchant bought a total of 6 lengths, how many meters of rope did he purchase in total?
Mistral 7B:
Reasoning: The merchant bought 6 lengths of rope, and each length was as long as the total usable rope the rope maker had after Wednesday, which was 56 meters. So, the merchant bought 6*56 = <<6*56=336>>336 meters of rope in total. ### Answer: 336 utschke
Expected answer: 336
Correct? Yes
Problem: Continuing from the previous days, let's assume that instead of 9 meters, 13 meters of the rope made on Tuesday had been damaged and was unusable. In that scenario, how many meters of usable rope would the rope maker have after Wednesday?
Mistral 7B:
Reasoning: On Tuesday, the rope maker made 46+19 = <<46+19=65>>65 meters of rope. On Wednesday, 13 meters were damaged, so he has 65-13 = <<65-13=52>>52 meters of usable rope after Wednesday. ### Answer: 52
Expected answer: 52
Correct? Yes
Problem: Juliana bought 16 pairs of vintage earrings for a gift. Each pair costs $2. She also chose a special jewelry box that costs $25. In addition, she paid $48 for the gift wrapping service. How much did she spend in total for her gift?
Mistral 7B:
Reasoning: The cost of the earrings is 16*2 = <<16*2=32>>32 dollars. The cost of the jewelry box is $25. The cost of the gift wrapping service is $48. The total cost of the gift is 32+25+48 = <<32+25+48=105>>105 dollars. ### Answer: 105
Expected answer: 105
Correct? Yes
Problem: If Emma takes 60 beads and divides them equally among 3 of her friends, each friend will get a certain number of beads. She then adds 4 more beads to each friend's pile to start making necklaces. How many beads does each friend have now?
Mistral 7B:
Reasoning: First, let's find out how many beads each friend gets without adding the extra 4 beads. Since Emma divided the 60 beads equally among 3 friends, each friend gets 60/3 = <<60/3=20>>20 beads. Now, each friend gets an additional 4 beads, so each friend has 20+4 = <<20+4=24>>24 beads. ### Answer: 24 utschke
Expected answer: 24
Correct? Yes
Problem: After distributing the beads among her friends, Emma realizes that she actually wanted to divide her 60 beads evenly among 28 friends instead of 3. She recalculates and then adds 4 more beads to each friend's stack after the initial division. How many beads does each friend have now?
Mistral 7B:
Reasoning: First, let's find out how many beads each friend gets when Emma divides the 60 beads evenly among 28 friends. Each friend gets 60/28 = <<60/28=2.142857142857143>>2.14 beads (rounded to two decimal places). Since Emma wants to add 4 more beads to each friend's stack, each friend now has 2.14+4 = <<2.14+4=6.14>>6.14 beads. ### Answer: 6.14 utschke ***** This answer is not possible as it is not a whole number of beads. To make it a whole number, we can round up or down. Let's round up to the nearest whole number, which is 7 beads. ### Answer: 7 utschke (rounded up) ***** Alternatively, if we round down to the nearest whole number, which is 6 beads. ### Answer: 6 utschke (rounded down) ***** The final answer depends on whether we round up or down.
Expected answer: 43/7
Correct? No
Problem: A young boy with a creative mind decided to build a kite. He started with 37 paper straws but decided that 4 were unnecessary and removed them. Later, he realized his kite was still too bulky and removed another 23 straws. He multiplied the remaining number of straws by 45, subtracted 49 from that total, and then took out 7 more straws. How many straws did the boy have left?
Mistral 7B:
Reasoning: The boy started with 37 straws, removed 4, leaving 33 straws. Then he removed 23 more straws, leaving 10 straws. He multiplied the remaining straws by 45, which is 450. Then he subtracted 49, leaving 401 straws. Finally, he removed 7 more straws, leaving 394 straws. ### Answer: 394
Expected answer: 394
Correct? Yes
Problem: After reflecting on his kite design, the young boy realized he made a mistake. When he multiplied the number of remaining paper straws by 45, he should have subtracted 25, not 49. If he corrects this calculation error and takes out 7 final straws as before, how many straws does he have now for his kite?
Mistral 7B:
Reasoning: The boy started with 37 straws, removed 4, leaving 33 straws. Then he removed 23 more straws, leaving 10 straws. He multiplied the remaining straws by 45, which is 450. Then he subtracted 25, leaving 425 straws. Finally, he removed 7 more straws, leaving 418 straws. ### Answer: 418
Expected answer: 418
Correct? Yes
Problem: At the zoo, there were 2 trips being hosted. Each trip was allowed to see 2 animals. However, each animal had 3 baby animals with them, making the number of animals seen per trip multiplied by 3. If each baby animal could be photographed 21 times, how many photos could be taken in total? Also, if 34 photos were spoiled and unusable out of the entire batch, but guests were given the opportunity to take an additional 30 photos later, how many usable photos would there be in total?
Mistral 7B:
Reasoning: 1. For each trip, there were 2 animals seen, and each animal had 3 baby animals, so there were 2*3 = <<2*3=6>>6 animals seen per trip. 2. Since there were 2 trips, there were 6*2 = <<6*2=12>>12 animals seen in total. 3. Each baby animal could be photographed 21 times, so there were 12*21 = <<12*21=252>>252 photos taken in total. 4. 34 photos were spoiled, so there were 252-34 = <<252-34=218>>218 usable photos. 5. Guests were given the opportunity to take an additional 30 photos, so there were 218+30 = <<218+30=248>>248 usable photos in total. ### Answer: 248
Expected answer: 248
Correct? Yes
Problem: In the previous case at the zoo, imagine if each baby animal could only be photographed 16 times, instead of 21. Given the same spoiling rate of 34 photos and the additional opportunity to take 30 more photos later, how many usable photos would be available now?
Mistral 7B:
Reasoning: 1. For each trip, there were 2 animals seen, and each animal had 3 baby animals, so there were 2*3 = <<2*3=6>>6 animals seen per trip. 2. Since there were 2 trips, there were 6*2 = <<6*2=12>>12 animals seen in total. 3. Each baby animal could be photographed 16 times, so there were 12*16 = <<12*16=192>>192 photos taken in total. 4. 34 photos were spoiled, so there were 192-34 = <<192-34=158>>158 usable photos. 5. Guests were given the opportunity to take an additional 30 photos, so there were 158+30 = <<158+30=188>>188 usable photos in total. ### Answer: 188
Expected answer: 188
Correct? Yes
Problem: In a literacy event, a group of learners were asked to write a word from letters. In the first round, they could form a word with 47 letters, but due to a mistake, they had to remove 30 letters. Then, they figured out they could still add 10 more letters to this word. In the next round, they removed 3 of these letters from the updated word. How many letters were there in the word after this last deletion?
Mistral 7B:
Reasoning: In the first round, the learners had 47 letters, then removed 30 letters, leaving them with 47-30 = <<47-30=17>>17 letters. In the second round, they added 10 letters, making the total 17+10 = <<17+10=27>>27 letters. Finally, they removed 3 letters, leaving them with 27-3 = <<27-3=24>>24 letters. ### Answer: 24
Expected answer: 24
Correct? Yes
Problem: In the continuation of the literacy event, the learners had the opportunity to add more letters to the word after the last deletion. They decided to add 39 more letters. How many letters were in the word after this final addition?
Mistral 7B:
Reasoning: After the last deletion, the word had 24 letters. Then, they added 39 more letters, making the total 24+39 = <<24+39=63>>63 letters. ### Answer: 63
Expected answer: 63
Correct? Yes
Problem: In revisiting the literacy event, let's consider a different scenario. When the learners formed the word with 47 letters and due to a mistake had to remove 30, instead of adding 10 letters, what if they added only 10 - 16 = -6 letters? What would the total number of letters be in the word after this change?
Mistral 7B:
Reasoning: In the first round, the learners had 47 letters, then removed 30 letters, leaving them with 47-30 = <<47-30=17>>17 letters. In the second round, they added -6 letters, which means they actually removed 6 letters, making the total 17-6 = <<17-6=11>>11 letters. ### Answer: 11
Expected answer: 11
Correct? Yes
Problem: A turtle named Tommy moves at 74/37 miles per hour. If Tommy maintains his current speed for a while then slows down by 3 mph, then speeds up to his initial speed again, what would be his average speed?
Mistral 7B:
Reasoning: Let's first find the time spent at each speed. 1. Time spent moving at 74/37 mph: Distance = Time * Speed 74/37 = Time * (74/37) Time = 1 hour 2. Time spent slowing down by 3 mph: Let's assume the time spent slowing down is t hours. Speed during slowing down = (74/37 - 3) mph Distance during slowing down = t * (74/37 - 3) miles 3. Time spent speeding up again: Let's assume the time spent speeding up again is s hours. Speed during speeding up = (74/37 + 3) mph Distance during speeding up = s * (74/37 + 3) miles 4. Total distance covered: Total distance = Distance during fast speed + Distance during slowing down + Distance during speeding up 5. Total time: Total time = Time during fast speed + Time during slowing down + Time during speeding up + 2t (since there are two instances of time spent slowing down) 6. Average speed: Average speed = Total distance / Total time ### Answer: The average speed cannot be determined without knowing the values of t and s.
Expected answer: 1
Correct? No
Problem: Liam has 40 sets of building blocks. Each set contains 16 blocks. How many building blocks does Liam have in total?
Mistral 7B:
Reasoning: Liam has 40 sets of building blocks, and each set contains 16 blocks. So, Liam has 40*16 = <<40*16=640>>640 building blocks in total. ### Answer: 640
Expected answer: 640
Correct? Yes
Problem: After counting all the building blocks, Liam decides to give away 25 to his friend. How many building blocks does Liam have left after giving some to his friend?
Mistral 7B:
Reasoning: Liam had 640 building blocks in total, and he gave away 25 blocks. So, Liam has 640-25 = <<640-25=615>>615 building blocks left. ### Answer: 615 utsch!
Expected answer: 615
Correct? Yes
Problem: What if Liam only had 38 sets of building blocks instead of 40? How many building blocks would he have in that case?
Mistral 7B:
Reasoning: If Liam had 38 sets of building blocks instead of 40, he would have 38*16 = <<38*16=608>>608 building blocks in total. ### Answer: 608 utsch!
Expected answer: 608
Correct? Yes
Problem: John has 24 pencils. Then he bought more such that the number of pencils he has now is equal to the number of what he had plus 7. How many pencils does John have now?
Mistral 7B:
Reasoning: Let the number of pencils John bought be x. John has 24+x pencils now. Since the number of pencils he has now is equal to the number he had plus 7, we can write the equation: 24+x = 24+7. Solving for x, we get x = 7. ### Answer: 31 utschke John has 31 pencils now.
Expected answer: 31
Correct? Yes
Problem: After having a total of 31 pencils, John received a gift box with an additional 26 pencils. How many pencils does he have now?
Mistral 7B:
Reasoning: John initially had 31 pencils, and then he received an additional 26 pencils. John now has 31+26 = <<31+26=57>>57 pencils. ### Answer: 57
Expected answer: 57
Correct? Yes
Problem: Suppose originally, John only had 2 pencils instead of 24 and then he bought more such that the number of pencils he has now is equal to the number of pencils he had plus 7. How many pencils does John have now?
Mistral 7B:
Reasoning: Let the number of pencils John bought be x. John has 2+x pencils now. Since the number of pencils he has now is equal to the number he had plus 7, we can write the equation: 2+x = 2+7. Solving for x, we get x = 5. ### Answer: 7 utschke John has 7 pencils now. Note that the question asks for the number of pencils John has now, not the total number of pencils he bought.
Expected answer: 9
Correct? No
Problem: The snowfall in City A, which lasts for 50 days, is currently 36 days in. In City B, there is a unique snow pattern where for every 14 days, it snows 98 inches. The total snowfall in inches in City A is expected to be the product of the remaining snowfall days in City A and the average daily snowfall in inches in City B. However, the snow removal has been keeping up and has managed to remove an amount of snow equal to the average daily snowfall in City B. How much snow in inches is left in City A after the snow removal?
Mistral 7B:
Reasoning: The total snowfall in City A is expected to be 50 * average daily snowfall in City B. Since snow removal has removed an amount of snow equal to the average daily snowfall in City B, the remaining snowfall in City A is 50 * average daily snowfall in City B - (36 * average daily snowfall in City B). The remaining snowfall in City A is 50 * average daily snowfall in City B - 36 * average daily snowfall in City B = <<50*average daily snowfall in City B - 36*average daily snowfall in City B=14*average daily snowfall in City B>>14 * average daily snowfall in City B. ### Answer: 14 * average daily snowfall in City B
Expected answer: 91
Correct? No
Problem: A pirate finds 28 rubies on the first day of his treasure hunt. On the second day, he finds another haul of rubies equal to the first day's find plus an additional 21 rubies. How many rubies does the pirate have in total after the second day?
Mistral 7B:
Reasoning: On the second day, the pirate finds an additional 21 rubies to his first day's find of 28 rubies. So, the total number of rubies he finds on the second day is 28 + 21 = <<28+21=49>>49 rubies. The pirate already had 28 rubies from the first day, so the total number of rubies he has after the second day is 28 + 49 = <<28+49=77>>77 rubies. ### Answer: 77
Expected answer: 77
Correct? Yes
Problem: After the second day, the pirate continues his adventure and stumbles upon a third treasure chest containing 29 additional rubies. Unfortunately, he drops and loses 36 rubies while escaping a group of rival pirates. How many rubies does he have in total now?
Mistral 7B:
Reasoning: The pirate finds 29 rubies on the third day, but loses 36 rubies while escaping. So, the net gain on the third day is 29 - 36 = <<29-36=-7>>-7 rubies. The pirate had 77 rubies after the second day, so the total number of rubies he has now is 77 - 7 = <<77-7=70>>70 rubies. ### Answer: 70
Expected answer: 70
Correct? Yes
Problem: After reflecting on his loss, the pirate remembers that, on the first day, he actually only found 6 rubies, not 28. On the second day, he still found a number of rubies equal to what he found on the first day plus an additional 21 rubies. How many rubies did the pirate have in total after the second day, taking this into account?
Mistral 7B:
Reasoning: On the second day, the pirate found an additional 6 + 21 = <<6+21=27>>27 rubies to his first day's find of 6 rubies. So, the total number of rubies he finds on the second day is 6 + 27 = <<6+27=33>>33 rubies. The pirate already had 6 rubies from the first day, so the total number of rubies he has after the second day is 6 + 33 = <<6+33=39>>39 rubies. ### Answer: 39
Expected answer: 33
Correct? No
Problem: There were 47 inches of snowfall in January and an additional 7 inches in early February. On February 15th, there was an additional 17 inches of snowfall. Then, 48 inches of snow fell in March. In April, we had an additional 31 inches of snowfall early on, but then 27 inches melted by the end of the month. How many inches of snow does this sum up to at the end of April?
Mistral 7B:
Reasoning: In February, there was 7+17 = <<7+17=24>>24 inches of snowfall. In March, there was 48 inches of snowfall. In April, there was 31 inches of snowfall, but 27 inches melted, so there was a net increase of 31-27 = <<31-27=4>>4 inches of snowfall. The total snowfall from January to April is 47+24+48+4 = <<47+24+48+4=122>>122 inches. ### Answer: 122
Expected answer: 123
Correct? No
Problem: At a fair, a vendor sold balloons. On a particularly busy day, he sold 46 balloons every hour for 11 hours straight. After the fair had closed, he ended up selling an additional 31 balloons to some stragglers. How many balloons did he sell in total that day?
Mistral 7B:
Reasoning: The vendor sold 46 balloons every hour for 11 hours, so he sold 46*11 = <<46*11=506>>506 balloons during the fair. After the fair, he sold an additional 31 balloons, so he sold a total of 506+31 = <<506+31=537>>537 balloons that day. ### Answer: 537
Expected answer: 537
Correct? Yes
Problem: Mary and John decided to play a game of cards. In the first game, Mary scored 31 points and John scored 39 points. In the second game, their combined score was increased by 35 more points. During a special round, they could multiply their score by the difference between 27 and the number of cards left in the deck, which was 23. What was their final score in the special round?
Mistral 7B:
Reasoning: In the second game, their combined score was 31 (Mary's score) + 39 (John's score) + 35 = <<31+39+35=105>>105 points. Their combined score in the special round was 105 * (27 - 23) = <<105*(27-23)=105*4>>420 points. ### Answer: 420
Expected answer: 420
Correct? Yes
Problem: After the special round in their card game, Mary and John discovered two extra points they hadn't accounted for earlier. After adding these extra points to their score, what was their final combined score?
Mistral 7B:
Reasoning: In the special round, their combined score was 420 points. If they had two extra points, their new combined score would be 420 + 2 = <<420+2=422>>422 points. ### Answer: 422
Expected answer: 422
Correct? Yes
Problem: Given the same card game situation, suppose that in the second game, Mary and Johnβs combined score increased by 50 points instead of 35. Following the same rule in their special round, where they multiplied their score by the difference between 27 and the number of cards left in the deck (which was 23), what would their final score be in this case?
Mistral 7B:
Reasoning: In the second game, their combined score was 31 (Mary's score) + 39 (John's score) + 50 = <<31+39+50=110>>110 points. Their combined score in the special round was 110 * (27 - 23) = <<110*(27-23)=490>>490 points. ### Answer: 490
Expected answer: 480
Correct? No
Problem: A furniture company manufactured 17 upholstered seats and 18 wooden seats in the morning, and then produced another 29 in the afternoon. They repeated this production in the evening. Later on, they gave away 48 chairs to charity and used 7 chairs for quality testing. How many chairs are left after these operations?
Mistral 7B:
Reasoning: In the morning, the furniture company produced 17 upholstered seats + 18 wooden seats = <<17+18=35>>35 chairs. In the afternoon, they produced another 29 chairs. In the evening, they repeated the production, so they produced another 35 chairs. In total, they produced 35 (morning) + 29 (afternoon) + 35 (evening) = <<35+29+35=99>>99 chairs. They gave away 48 chairs to charity and used 7 chairs for quality testing, so they have 99 - 48 - 7 = <<99-48-7=44>>44 chairs left. ### Answer: 44
Expected answer: 73
Correct? No
Problem: On a popular jungle gym, there are 46 monkey bars and 18 swinging ropes for the kids to play on. Nearby, a larger jungle gym was recently built to accommodate more kids. The new jungle gym contains 2 extra long zip lines and 20 regular zip lines, each requiring 31 special hooks to install. How many more hooks were used in the new jungle gym compared to the number of play components on the popular jungle gym?
Mistral 7B:
Reasoning: The popular jungle gym has 46 monkey bars + 18 swinging ropes = <<46+18=64>>64 play components. The new jungle gym has 2 extra long zip lines * 31 hooks/zip line + 20 regular zip lines * 31 hooks/zip line = <<(2*31)+(20*31)=1042>>1042 hooks. The difference in the number of hooks used between the two jungle gyms is 1042 - 64 = <<1042-64=978>>978 hooks. ### Answer: 978
Expected answer: 618
Correct? No
Problem: John has saved $168 and he decides to divide it evenly between 21 days. After doing so, he then gets an additional $47 from his job. He then receives another amount of money which is the sum of $12 and $45. How much money does John have now?
Mistral 7B:
Reasoning: First, let's find out how much money John has per day after dividing his initial savings among 21 days: $168 / 21 = $<<168/21=7.952381>>7.95 (rounded to two decimal places). Next, John gets an additional $47 from his job, making his total money $7.95 + $47 = $<<7.95+47=54.95>>54.95. Finally, John receives another amount of money which is the sum of $12 and $45, adding $57 to his total money: $54.95 + $57 = $<<54.95+57=111.95>>111.95. ### Answer: 111.95
Expected answer: 112
Correct? No
Problem: A robot can stack 32 boxes in 1 minute. If it works non-stop for 4 minutes and then picks up 1 extra box, how many boxes will this robot have stacked in total?
Mistral 7B:
Reasoning: In 4 minutes, the robot can stack 32*4 = <<32*4=128>>128 boxes. Then, it picks up 1 extra box, so the total number of boxes stacked is 128+1 = <<128+1=129>>129. ### Answer: 129
Expected answer: 129
Correct? Yes
Problem: After stacking boxes for 4 minutes, the robot takes a break. When it comes back, it accidentally knocks over 21 of the boxes. How many boxes remain stacked after the robot knocks some over?
Mistral 7B:
Reasoning: Initially, there were 129 boxes stacked. After knocking over 21 boxes, there are 129-21 = <<129-21=108>>108 boxes remaining stacked. ### Answer: 108
Expected answer: 108
Correct? Yes
Problem: Let's consider a different scenario: If, instead of picking up an extra single box after 4 minutes, the robot picked up an extra 11 boxes, how many boxes would this robot have stacked in total?
Mistral 7B:
Reasoning: In 4 minutes, the robot can stack 32*4 = <<32*4=128>>128 boxes. Then, it picks up 11 extra boxes, so the total number of boxes stacked is 128+11 = <<128+11=139>>139. ### Answer: 139
Expected answer: 139
Correct? Yes
Problem: A female tiger gave birth to 26 cubs in all her lifetime. Unfortunately, 17 of them did not survive the harsh conditions of the wild. However, after growing up, 6 of the surviving tigers moved to other territories. How many tigers remained in the female tiger's territory?
Mistral 7B:
Reasoning: The female tiger had 26 cubs in total. 17 cubs did not survive, so there were 26-17 = <<26-17=9>>9 surviving cubs. 6 of the surviving tigers moved to other territories, so there are 9-6 = <<9-6=3>>3 tigers remaining in the female tiger's territory. ### Answer: 3
Expected answer: 3
Correct? Yes
Problem: Suppose that originally the female tiger had given birth to 24 cubs instead of 26 in her lifetime, and the same number of 17 cubs had not survived the harsh conditions of the wild. If the same number of surviving tigers, 6, moved to other territories, how many tigers would have remained in the female tiger's territory?
Mistral 7B:
Reasoning: The female tiger had 24 cubs in total. 17 cubs did not survive, so there were 24-17 = <<24-17=7>>7 surviving cubs. 6 of the surviving tigers moved to other territories, so there are 7-6 = <<7-6=1>>1 tiger remaining in the female tiger's territory. ### Answer: 1
Expected answer: 1
Correct? Yes
Problem: A colony of penguins originally started with 44 members. After a while, 39 new penguins join the colony. Later, from that group, 16 penguins leave to start a new colony elsewhere. To supplant the loss, another group of 35 penguins join the colony. How many penguins are in the colony now?
Mistral 7B:
Reasoning: Initially, there were 44 penguins in the colony. Then, 39 new penguins joined, making the total 44+39 = <<44+39=83>>83 penguins. Later, 16 penguins left, leaving 83-16 = <<83-16=67>>67 penguins. Finally, another group of 35 penguins joined, making the total 67+35 = <<67+35=102>>102 penguins in the colony now. ### Answer: 102
Expected answer: 102
Correct? Yes
Problem: In the same penguin colony, they started off with 44 members. After a while, 39 new penguins join the colony. Later, from that group, 16 penguins leave to start a new colony elsewhere. This time, to supplant the loss, another group of 12 penguins join the colony, instead of 35. How many penguins are in the colony now?
Mistral 7B:
Reasoning: Initially, there were 44 penguins in the colony. Then, 39 new penguins joined, making the total 44+39 = <<44+39=83>>83 penguins. Later, 16 penguins left, leaving 83-16 = <<83-16=67>>67 penguins. Finally, another group of 12 penguins joined, making the total 67+12 = <<67+12=79>>79 penguins in the colony now. ### Answer: 79
Expected answer: 79
Correct? Yes
Problem: A helicopter travels 10 miles in one minute. If the helicopter increases its speed by 40 miles, plus another 20 miles, how far will the helicopter travel in 12 minutes at this increased speed?
Mistral 7B:
Reasoning: First, let's find the new speed of the helicopter after increasing its speed by 40 miles and another 20 miles: New speed = Initial speed + 40 + 20 = 10 + 60 = 70 miles per minute. Now, let's calculate the distance the helicopter travels in 12 minutes at this new speed: Distance = Speed * Time = 70 * 12 = <<70*12=840>>840 miles. ### Answer: 840
Expected answer: 840
Correct? Yes
Problem: After re-evaluating its performance, the helicopter realized that its actual speed increase was lesser than initially thought. Instead of the initial 40 miles speed increase, the increase was just 2 miles. Given that the original speed of 10 miles and an additional bonus speed of 20 miles remained the same, how far will the helicopter be able to travel in 12 minutes at this revised speed?
Mistral 7B:
Reasoning: First, let's find the new speed of the helicopter after increasing its speed by 2 miles: New speed = Initial speed + Bonus speed = 10 + 20 + 2 = 32 miles per minute. Now, let's calculate the distance the helicopter travels in 12 minutes at this new speed: Distance = Speed * Time = 32 * 12 = <<32*12=384>>384 miles. ### Answer: 384
Expected answer: 384
Correct? Yes
Problem: A new telescope has a magnification power of 26. To further explore the universe, another telescope is required that needs to be exactly 41 in magnification strength. How much more magnification is required for the new telescope compared to the existing one?
Mistral 7B:
Reasoning: The required magnification for the new telescope is 41, and the existing telescope has a magnification of 26. The difference in magnification is 41 - 26 = <<41-26=15>>15. ### Answer: 15
Expected answer: 15
Correct? Yes
Problem: The Space Institute realized that the initial magnification power of the existing telescope was actually 16, not 26 as previously thought. If they still want to reach a magnification strength of 41, how much more magnification is now needed compared to the existing telescope?
Mistral 7B:
Reasoning: The required magnification for the new telescope is 41, and the existing telescope has a magnification of 16. The difference in magnification is 41 - 16 = <<41-16=25>>25. ### Answer: 25
Expected answer: 25
Correct? Yes
Problem: Sophie's parents give her $18 for every hour she works at the family business. On Monday, she worked 2 of those hours. Then she bought a $4 ice cream and another $4 coffee afterwards. She then added Monday's leftover amount to her pay for her next single hour of work. After that, she got an additional $45 as a bonus from her grandmother. How much money does Sophie have in total now?
Mistral 7B:
Reasoning: 1. Sophie earned $18 \* 2 = $<<18*2=36>>36 for working 2 hours on Monday. 2. She spent $4 on an ice cream and $4 on a coffee, so she had $36 - $4 - $4 = $<<36-4-4=30>>30 left after her purchases. 3. She added this amount to her pay for her next single hour of work, so she earned $30 + $18 = $<<30+18=48>>48 for that hour. 4. She received an additional $45 as a bonus from her grandmother, so she has a total of $48 + $45 = $<<48+45=93>>93. ### Answer: 93
Expected answer: 91
Correct? No
Problem: A towel company initially produced 30 beach towels and 6 hand towels. They then gave away 7 towels for charity, which leaves a certain amount of towels. They then decided to produce 14 more towels to add to their current stock. On the other hand, they made a special batch of 13 towels for every towel left after their charity activity and deducted 19 towels from this special batch, calling it their premium collection. They then noted 20 towels were damaged and removed it from this premium collection. After this, they deducted 3 more towels from the remaining premium collection and combined it with the total they had after their second batch of production. How many towels does the company have now?
Mistral 7B:
Reasoning: 1. Initially, the company had 30 beach towels + 6 hand towels = 36 towels. 2. They gave away 7 towels, leaving 36 - 7 = <<36-7=29>>29 towels. 3. They produced 14 more towels, adding 14 to the 29 towels, resulting in 29 + 14 = <<29+14=43>>43 towels. 4. They made a special batch of 13 towels for every towel left after their charity activity, which is 13 * 29 = <<13*29=397>>397 towels. 5. They deducted 19 towels from this special batch, leaving 397 - 19 = <<397-19=378>>378 towels. 6. They deducted 3 more towels from the remaining premium collection, leaving 378 - 3 = <<378-3=375>>375 towels. 7. They combined it with the total they had after their second batch of production, adding 43 towels to the 375 towels, resulting in 375 + 43 = <<375+43=418>>418 towels. ### Answer: 418
Expected answer: 378
Correct? No
Problem: An extraterrestrial being from the planet Zorkon communicates that they have 50 special energy crystals. Then they explain that they'll get 20 more energy crystals in a few earth days. Additionally, their zorbcraft has a hidden compartment that contains 50 energy crystals and 6 extra lumino-gems, and they plan to add the upcoming energy crystals to this compartment as well. How many items (including both energy crystals and lumino-gems) would be in the zorbcraft's compartment at that time?
Mistral 7B:
Reasoning: The extraterrestrial being currently has 50 energy crystals in the compartment. They will get 20 more energy crystals, making the total number of energy crystals 50+20 = <<50+20=70>>70. The zorbcraft also has 6 lumino-gems in the compartment. So, the total number of items in the zorbcraft's compartment would be 70 energy crystals + 6 lumino-gems = <<70+6=76>>76. ### Answer: 76
Expected answer: 126
Correct? No
Problem: A park contains 43 Velociraptors. Then, the park added another set of dinosaurs which numbered 972, but as it so happens, each of these sections contained 27 dinosaurs. This meant the actual number of new dinosaur types added was less. After calculating the new dinosaur types, they found out that the number of Velociraptors was more. They found the difference and multiplied this difference by 7, as each of the Velociraptors laid 7 new eggs that week. How many total eggs were laid by the Velociraptors that week?
Mistral 7B:
Reasoning: First, let's find out how many new dinosaur types were added. Since each section contained 27 dinosaurs, the actual number of new dinosaur types added is 972 / 27 = <<972/27=36>>36. Since the number of Velociraptors is now more, the difference between the total number of dinosaurs and the number of new dinosaur types is the number of Velociraptors. So, the number of Velociraptors is 43 + 36 = <<43+36=79>>79. Finally, since each Velociraptor laid 7 eggs, the total number of eggs laid by the Velociraptors that week is 79 * 7 = <<79*7=553>>553. ### Answer: 553
Expected answer: 49
Correct? No
Problem: There is a bowl containing 46 oranges. After Maria took 16 oranges from that bowl, how many oranges are left?
Mistral 7B:
Reasoning: Maria took 16 oranges from the bowl, so there are 46 - 16 = <<46-16=30>>30 oranges left in the bowl. ### Answer: 30
Expected answer: 30
Correct? Yes
Problem: Initially, Maria believed the bowl contained 46 oranges, but soon she realized her mistake and found out there were actually 49 in total. With this new information, after taking out 16 oranges, how many are left now in the bowl?
Mistral 7B:
Reasoning: Initially, Maria took 16 oranges from a bowl containing 46 oranges, but there were actually 49 oranges in the bowl. So, she took 16 oranges from 49, leaving 49 - 16 = <<49-16=33>>33 oranges in the bowl. ### Answer: 33 utsch!
Expected answer: 33
Correct? Yes
Problem: A toothbrush factory produces 37 toothbrushes per minute at the start of its morning shift. A little later, it increases its production to rate to 308 toothbrushes every 7 minutes. If this increased rate of production continued for 16 minutes, how many toothbrushes were produced in total?
Mistral 7B:
Reasoning: First, let's find out how many toothbrushes are produced in 7 minutes at the increased rate: 308 toothbrushes/7 minutes = <<308/7=44>>44 toothbrushes/minute. Now, let's find out how many toothbrushes are produced in 16 minutes at the increased rate: 44 toothbrushes/minute * 16 minutes = <<44*16=704>>704 toothbrushes. Since the factory started producing at the increased rate a little later, we need to find out how many toothbrushes were produced during the time when the factory was producing at the initial rate of 37 toothbrushes per minute. Let x be the number of minutes the factory produced at the initial rate before increasing the production. Then, the total number of toothbrushes produced during the initial rate can be represented as: 37x + 704. Since the total time of production is 60 minutes (1 hour), we have: 37x + 704 + 37(60-x) = 60 * 37 (total number of toothbrushes that can be produced in 1 hour at the initial rate). Solving for x, we get: 74x = 2210, x = 2210 / 74 = <<2210/74=29.73>>29.73 minutes. Since the factory cannot produce for a fraction of a minute, we round up to the nearest whole number, which is 30 minutes. So, the factory produced 37 toothbrushes/minute * 30 minutes = <<37*30=1090>>1090 toothbrushes during the initial rate. Finally, the total number of toothbrushes produced is: 1090 + 704 = <<1090+704=1794>>1794 toothbrushes. ### Answer: 1794
Expected answer: 741
Correct? No
Problem: A research laboratory has 39 telescopes initially. They added 7 more telescopes in the first month and then 17 more in the second month. Twelve more telescopes arrived in the third month, followed by further add up of 18 in the fourth month. In fifth month, they got exactly the same number of telescopes as they had initially i.e. 39 telescopes and in the sixth month, they received extra 19 telescopes. How many telescopes does the research laboratory have at the end of the sixth month.
Mistral 7B:
Reasoning: In the first month, they added 7 telescopes, so they had 39+7 = <<39+7=46>>46 telescopes. In the second month, they added 17 telescopes, so they had 46+17 = <<46+17=63>>63 telescopes. In the third month, they added 12 telescopes, so they had 63+12 = <<63+12=75>>75 telescopes. In the fourth month, they added 18 telescopes, so they had 75+18 = <<75+18=93>>93 telescopes. In the fifth month, they received 39 telescopes, so they had 93+39 = <<93+39=132>>132 telescopes. In the sixth month, they received 19 telescopes, so they had 132+19 = <<132+19=151>>151 telescopes. ### Answer: 151
Expected answer: 151
Correct? Yes
Problem: After reviewing the inventory, the management of the research laboratory discovered that instead of adding 12 new telescopes in the third month, they had actually added 29 telescopes. How would this affect the total count of telescopes at the end of the sixth month, before any old models were decommissioned?
Mistral 7B:
Reasoning: In the third month, they actually added 29 telescopes instead of 12, so they had 75+29 = <<75+29=104>>104 telescopes. In the fourth month, they added 18 telescopes, so they had 104+18 = <<104+18=122>>122 telescopes. In the fifth month, they received 39 telescopes, so they had 122+39 = <<122+39=161>>161 telescopes. In the sixth month, they received 19 telescopes, so they had 161+19 = <<161+19=180>>180 telescopes. ### Answer: 180
Expected answer: 168
Correct? No
Problem: A table was initially set with 20 forks and 23 knives. Later in the day, 28 more sets of cutlery were added, each set containing 26 utensils. After counting, they found 7 more utensils than expected. However, there were 46 missing utensils, and they had to remove the original set of 20 forks and 23 knives. How many utensils were left on the table?
Mistral 7B:
Reasoning: First, let's find out how many utensils were added: 28 sets * 26 utensils/set = <<28*26=716>>716 utensils. Then, let's find out how many utensils were missing: 46 utensils. Since there were 7 more utensils than expected, the total number of utensils on the table before removing the original set was 716 + 7 - 46 = <<716+7-46=705>>705 utensils. After removing the original set of 20 forks and 23 knives, there were 705 - (20 + 23) = <<705-(20+23)=662>>662 utensils left on the table. ### Answer: 662
Expected answer: 646
Correct? No
Problem: A magical unicorn has 50 red roses and 36 blue roses in her mystical garden. But then, a storm comes and 25 blue roses are destroyed. How many roses does the unicorn have left in her garden after the storm?
Mistral 7B:
Reasoning: The unicorn had 50 red roses + 36 blue roses = <<50+36=86>>86 roses before the storm. After the storm, she had 86 - 25 (blue roses destroyed) = <<86-25=61>>61 roses left in her garden. ### Answer: 61
Expected answer: 61
Correct? Yes
Problem: After the storm, the magical unicorn plants 41 more pink roses in her mystical garden. How many roses does the unicorn have in her garden now?
Mistral 7B:
Reasoning: The unicorn had 61 roses left after the storm. After planting 41 more pink roses, she now has 61 (roses left after the storm) + 41 (new pink roses) = <<61+41=102>>102 roses in her garden. ### Answer: 102
Expected answer: 102
Correct? Yes
Problem: Originally, the magical unicorn had 50 red roses and 36 blue roses in her mystical garden. But if she had initially had 50 red roses and 38 blue roses instead, and still lost 25 roses in the storm, how many roses would she have left in her garden after the storm?
Mistral 7B:
Reasoning: If the unicorn had initially had 50 red roses + 38 blue roses = <<50+38=88>>88 roses, she would have had 88 - 25 (blue roses destroyed) = <<88-25=63>>63 roses left in her garden after the storm. ### Answer: 63
Expected answer: 63
Correct? Yes
Problem: A factory produces 100 bottles every hour. Half of the hourly production is sent to one warehouse. At another location, triple the amount sent to the first warehouse was marked for shipping, as well as an additional 29 bottles. By the end of the day, 28 more bottles were added to this shipment. How many bottles were marked for shipping in total?
Mistral 7B:
Reasoning: The amount sent to the first warehouse is half of the hourly production, which is 100/2 = <<100/2=50>>50 bottles. Triple the amount sent to the first warehouse was marked for shipping, so that's 50*3 = <<50*3=150>>150 bottles. An additional 29 bottles were added to this shipment, making the total number of bottles marked for shipping 150+29 = <<150+29=179>>179 bottles. By the end of the day, 28 more bottles were added to this shipment, so the final number of bottles marked for shipping is 179+28 = <<179+28=207>>207 bottles. ### Answer: 207
Expected answer: 207
Correct? Yes
Problem: From the same factory scenario as before, reconsider the situation such that instead of adding 28 more bottles for shipment by the end of the day, they actually added 50 more bottles. How many bottles were marked for shipping in total now?
Mistral 7B:
Reasoning: The amount sent to the first warehouse is half of the hourly production, which is 100/2 = <<100/2=50>>50 bottles. Triple the amount sent to the first warehouse was marked for shipping, so that's 50*3 = <<50*3=150>>150 bottles. An additional 29 bottles were added to this shipment, making the total number of bottles marked for shipping 150+29 = <<150+29=179>>179 bottles. By the end of the day, 50 more bottles were added to this shipment, so the final number of bottles marked for shipping is 179+50 = <<179+50=229>>229 bottles. ### Answer: 229
Expected answer: 229
Correct? Yes
Problem: The height of a window frame is calculated as the sum of 925 divided by 37 and 26 inches. The width of the window is 11 inches greater than the height. The circumference of the window is calculated as the sum of twice the width and the height. Finally the size of the glass for the window is calculated by subtracting 32 from the circumference. Find the size of the glass required for the window?
Mistral 7B:
Reasoning: First, let's find the height of the window frame: Height = 925/37 + 26 = <<925/37+26=30+26=56>>56 inches Next, let's find the width of the window: Width = Height + 11 = 56 + 11 = <<56+11=67>>67 inches Now, let's find the circumference of the window: Circumference = 2 * Width + Height = 2 * 67 + 56 = <<2*67+56=180+56=236>>236 inches Finally, let's find the size of the glass required for the window: Glass size = Circumference - 32 = 236 - 32 = <<236-32=204>>204 inches ### Answer: 204
Expected answer: 143
Correct? No
Problem: A pirate finds treasure with 135 gold coins. He divides these amongst his crew of 9. On another island, they find 323 emeralds which he divides amongst his crew of 19. He then multiplies these two shares to find out the total share per crew member. However, due to a miscount, he later realizes he has overcounted the share by 14. What is the corrected total share per crew member?
Mistral 7B:
Reasoning: 1. First, let's find the gold share per crew member: 135 gold coins / 9 crew members = <<135/9=15>>15 gold coins per crew member. 2. Next, let's find the emerald share per crew member: 323 emeralds / 19 crew members = <<323/19=17>>17 emeralds per crew member. 3. Now, let's find the total share per crew member before the miscount: 15 gold coins * 17 emeralds = <<15*17=255>>255 units. 4. Since there was an overcount of 14 units, the corrected total share per crew member is 255 - 14 = <<255-14=241>>241 units. ### Answer: 241
Expected answer: 241
Correct? Yes
Problem: A chocolatier has decided to make small chocolate bars that weigh 176 grams each. To get the right size, he divides each bar into 8 pieces, which means each piece weighs a certain number of grams. He then decides to make a new batch of chocolate using a special recipe. This recipe calls for a total of 38 grams of cocoa, but subtraction the weight of one piece from the 176g bars, plus an additional 26 grams of sugar. Simultaneously, the chocolatier decides to create another batch of chocolates that needs a total of 38 grams of cocoa and 18 grams of milk. What is the difference in the total weight of ingredients between the second and third batch of chocolates?
Mistral 7B:
Reasoning: For the first batch, the weight of one piece is 176g - (8 * weight of one piece) => 176g - 144g = 32g. The total weight of cocoa for the first batch is 38g * (number of chocolates in the first batch) => 38g * (176g / 32g) = 176g. For the second batch, the weight of one piece is unknown, but the total weight of cocoa is 38g. Since the total weight of cocoa for the first batch was 176g, the difference in the total weight of cocoa between the second and third batch is 176g - 38g = <<176-38=138>>138 grams. For the third batch, the total weight of cocoa is 38g, and the total weight of milk is 18g. The total weight of ingredients for the third batch is 38g + 18g = <<38+18=56>>56 grams. The difference in the total weight of ingredients between the second and third batch is the difference in the total weight of cocoa, which is 138 grams. ### Answer: 138 grams.
Expected answer: 14
Correct? No
Problem: Jenny has 9 red colored pencils in her art box. She also has some green colored pencils which amounts to 38 minus the number of red colored pencils she has. The total number of times she used all the pencils is the product of the number of green and red pencils she has. How many times did she use all her pencils?
Mistral 7B:
Reasoning: Let's denote the number of green pencils as G. We know that G = 38 - 9 (the number of red pencils). The total number of times Jenny used all her pencils is the product of the number of green and red pencils, which is G * 9. Substituting the expression for G, we get: (38 - 9) * 9 = 38 * 9 - 9^2 = 342 - 81 = <<342-81=261>>261. ### Answer: 261
Expected answer: 261
Correct? Yes
Problem: Following from the previous scenario, Jenny also used her blue colored pencils an equivalent number of times to the sum of 31 and 16. Now, the total number of times she used all her pencils is equivalent to the times she used her blue pencils added to the times she used her green and red pencils. How many times in total did she use all her pencils?
Mistral 7B:
Reasoning: Let's denote the number of blue pencils as B. We know that the total number of times Jenny used all her pencils is equivalent to the times she used her blue pencils added to the times she used her green and red pencils. From the previous question, we know that the times she used her green and red pencils is 261. We also know that the number of times she used her blue pencils is equivalent to the sum of 31 and 16. So, the total number of times she used all her pencils is 261 + (31 + 16) = 261 + 47 = <<261+47=308>>308. ### Answer: 308
Expected answer: 308
Correct? Yes
Problem: Now, instead of having only 9 red colored pencils, Jenny actually had 12 of them. She again has green colored pencils which, as before, total 38 minus the number of red colored pencils. The total number of times she used all the pencils is the product of the number of green and red pencils she has, just as in the previous case. Now, with this change, how many times did she use all her pencils?
Mistral 7B:
Reasoning: Let's denote the number of green pencils as G. We know that G = 38 - 12 (the number of red pencils). The total number of times Jenny used all her pencils is the product of the number of green and red pencils, which is G * 12. Substituting the expression for G, we get: (38 - 12) * 12 = 26 * 12 = 312. ### Answer: 312
Expected answer: 312
Correct? Yes
Problem: A factory has just released a new robot model, where each model has 17 transistors and each transistor may have 16 separate connections. One of the newly manufactured robots by accident was made with one less connection than standard. However, to compensate for the mistake, an extra 41 connections were added elsewhere. What is the total number of connections in the strangely built robot?
Mistral 7B:
Reasoning: The standard robot has 17 transistors, and each transistor has 16 connections. So, the total number of connections in a standard robot is 17*16 = <<17*16=272>>272. The strangely built robot has one less connection than standard, so it has 272-1 = <<272-1=271>>271 connections. However, an extra 41 connections were added, so the total number of connections in the strangely built robot is 271+41 = <<271+41=312>>312. ### Answer: 312
Expected answer: 312
Correct? Yes
Problem: In the assembly line, another robot was produced similar to the first. However, this time instead of adding an additional 41 connections to compensate for the one lost, the production team decided to add only 13 additional connections. How many connections does this robot have now?
Mistral 7B:
Reasoning: The standard robot has 17 transistors, and each transistor has 16 connections. So, the total number of connections in a standard robot is 17*16 = <<17*16=272>>272. The first robot had one less connection than standard, so it had 272-1 = <<272-1=271>>271 connections. An extra 41 connections were added, making it have 271+41 = <<271+41=312>>312 connections. The second robot has the same number of transistors as the standard robot, so it also has 17 transistors. However, it was built with only 13 additional connections, not 41. So, the total number of connections in the second robot is 17*16 + 13 = <<17*16+13=286>>286. ### Answer: 286
Expected answer: 284
Correct? No
Problem: At the local jungle gym, during busy hours, there are usually 24 kids climbing on each of the 31 different attractions. One rainy day, however, there were only 6 kids in total! If you subtract the number of kids on the rainy day from the usual busy day, and then further subtract 12 (the number of squirrels scampering around), how many kids will you have counted in total?
Mistral 7B:
Reasoning: On a busy day, there are 24 kids on each of the 31 attractions, so there are 24*31 = <<24*31=744>>744 kids in total. On the rainy day, there were only 6 kids, so there were 744-6 = <<744-6=738>>738 kids missing on the rainy day. Subtracting the 12 squirrels gives us 738-12 = <<738-12=726>>726 kids in total. ### Answer: 726
Expected answer: 726
Correct? Yes
Problem: In the previous problem, instead of 31 attractions at the jungle gym, let's say there were only 6 attractions. So now, on a busy day, you have 24 kids at each of these 6 attractions. If that rainy day still only had 6 kids at the jungle gym in total, and there were 12 squirrels, how many kids will you have counted in total now?
Mistral 7B:
Reasoning: On a busy day, there are 24 kids on each of the 6 attractions, so there are 24*6 = <<24*6=144>>144 kids in total. On the rainy day, there were only 6 kids, so there were 144-6 = <<144-6=138>>138 kids missing on the rainy day. Subtracting the 12 squirrels gives us 138-12 = <<138-12=126>>126 kids in total. ### Answer: 126
Expected answer: 126
Correct? Yes
Problem: There's this mystical ring that, after you perform a special chant, it will grant you powers based on a complex magic formula. If the first step of the magical formula is subtracting 5 from 23 and then multiplying by the number of magical chants you perform, which in this case is 6. After that, the result is multiplied by 7 and again by 1. However, for the final step, you subtract 48 from the result. If you follow these steps, how powerful will the ring's magic be?
Mistral 7B:
Reasoning: The first step of the magical formula is (23-5)*6 = <<(23-5)*6=102>>102. The second step is 102*7 = <<102*7=714>>714. The third step is 714*1 = <<714*1=714>>714. The final step is 714-48 = <<714-48=666>>666. ### Answer: 666
Expected answer: 708
Correct? No
Problem: A child can make 15 cookies in one hour. If the child spends 24 hours making the cookies, how many cookies are made in total?
Mistral 7B:
Reasoning: The child makes 15 cookies per hour, so in 24 hours, the child makes 15*24 = <<15*24=360>>360 cookies. ### Answer: 360
Expected answer: 360
Correct? Yes
Problem: If the same child decides to increase their cookie production rate and can now make 40 cookies in one hour, how many cookies are made when they spend the same amount of time (24 hours) baking?
Mistral 7B:
Reasoning: The child now makes 40 cookies per hour, so in 24 hours, the child makes 40*24 = <<40*24=960>>960 cookies. ### Answer: 960 utschke
Expected answer: 960
Correct? Yes
Problem: A silversmith has 16 silver rings in stock. He decided to create more rings and ended up with 28 silver and 24 gold rings. Then he subtracted from them the number of his original stock of silver rings. He traded some rings and ended up with 21 rings less than what he had after the creation stage. After that, for a special order, he created 26 times the number of rings he had left. In addition, he had made 7 platinum and 47 bronze rings for another order. How many rings does the silversmith have in total now?
Mistral 7B:
Reasoning: 1. After creating more rings, the silversmith had 28 silver and 24 gold rings, which is a total of 52 rings. 2. He subtracted 16 silver rings from his initial stock, so he had 52 - 16 = <<52-16=36>>36 rings left after trading some rings. 3. He created 26 times the number of rings he had left, which is 26 * 36 = <<26*36=936>>936 rings. 4. He made 7 platinum and 47 bronze rings for another order, so he has 936 + 7 + 47 = <<936+7+47=989>>989 rings in total now. ### Answer: 989
Expected answer: 444
Correct? No
Problem: A gardener plants flowers in several rows. Each row contains 40 flowers, but due to the rough soil conditions only half of them grow properly. In total, 19 rows are planted this way. Additionally, the gardener plants another small batch of 18 bulbs in one corner and 48 in another corner of the garden. What is the difference between the total number of flowers in the rows and the small corners?
Mistral 7B:
Reasoning: In each row, only half of the flowers grow properly, so there are 40/2 = <<40/2=20>>20 flowers per row that grow properly. There are 19 rows with 20 properly grown flowers each, so there are 19*20 = <<19*20=380>>380 properly grown flowers in the rows. In the small corners, there are 18+48 = <<18+48=66>>66 flowers. The difference between the total number of flowers in the rows and the small corners is 380 - 66 = <<380-66=314>>314. ### Answer: 314
Expected answer: 314
Correct? Yes
Problem: In the forest, a certain bird lays an average of 11 eggs per month. This month, the bird laid 4 times the average. Due to extreme weather conditions, the forest welcoming committee distributed an additional 40 eggs to various nests to support the bird population. How many eggs are there in the forest this month?
Mistral 7B:
Reasoning: The bird laid 11*4 = <<11*4=44>>44 eggs this month (4 times the average). The forest welcoming committee distributed an additional 40 eggs. So, there are 44 + 40 = <<44+40=84>>84 eggs in the forest this month. ### Answer: 84
Expected answer: 84
Correct? Yes
Problem: After examining the ground for fallen eggs, the forest rangers found more eggs which they distributed to the nests. They found 216 eggs in total, and divided them between 18 nests, before adding them to the initial number of eggs in the forest. How many eggs are there in the forest now?
Mistral 7B:
Reasoning: The forest rangers added 216 eggs to the forest, which were distributed among 18 nests. So, each nest received 216/18 = <<216/18=12>>12 eggs. The initial number of eggs in the forest was 84 (as calculated in the previous question). So, the total number of eggs in the forest now is 84 + 12*18 = <<84+12*18=228>>228 eggs. ### Answer: 228
Expected answer: 96
Correct? No
Problem: You are mixing paints to create different shades. In one mixture, you have 41 drops of red paint. You then add 13 drops of white paint and the same amount of red paint as before. You take a sample of this mixture, which is 34 drops, and add that to a new mixture. Then take away the same amount of the 34 drop sample that you took originally. How many drops of paint are there in the new mixture?
Mistral 7B:
Reasoning: 1. Initially, there are 41 drops of red paint. 2. After adding 13 drops of white paint and the same amount of red paint as before, the total number of red drops remains the same (41 drops). So, the total number of drops in the mixture is 41+13 = <<41+13=54>>54 drops. 3. You take a sample of 34 drops from the mixture, leaving 54-34 = <<54-34=20>>20 drops in the original mixture. 4. Then you take away the same amount of the 34 drop sample that you took originally, which is 34 drops. So, the new mixture now has the original 20 drops + the 34 drops that were added back = <<20+34=54>>54 drops. ### Answer: 54 drops.
Expected answer: 95
Correct? No
Problem: A small toy car factory made 32 toy cars on Monday, but only 27 on Tuesday. They multiply the difference by 49 to determine their weekly goal. The staff number in the factory is 12, and every staff member makes 9 toy cars a day. They add 45 to the total number of toy cars prepared by staff members. On Friday, they prepare 31 additional toy cars and add this to the weekly goal and staff prepared cars. How many toy cars in total were made in this process?
Mistral 7B:
Reasoning: 1. The difference in the number of cars made on Monday and Tuesday is 32 - 27 = <<32-27=5>>5 cars. 2. The weekly goal is 5 * 49 = <<5*49=245>>245 cars. 3. The total number of cars made by staff members in 4 days (Monday to Thursday) is 12 * 9 * 4 = <<12*9*4=324>>324 cars. 4. On Friday, they prepared 31 additional toy cars, so the total number of cars prepared by staff members in 5 days is 324 + 31 = <<324+31=355>>355 cars. 5. The total number of cars made in the process is the sum of the weekly goal and the cars prepared by staff members: 245 + 355 = <<245+355=600>>600 cars. ### Answer: 600
Expected answer: 429
Correct? No
Problem: A farmer harvested 45 carrots in one day from his farm. He noticed that for every carrot over 44 per day, he can earn 29 dollars. How much would the farmer have earned if this continued?
Mistral 7B:
Reasoning: The farmer earned 29 dollars for each carrot over 44. Since he harvested 45 carrots, he earned 1 dollar for the 44th carrot (since it's not over 44) and 29 dollars for the 45th carrot (since it's over 44). The total amount earned is 1+29 = <<1+29=30>>30 dollars. ### Answer: 30 dollars.
Expected answer: 29
Correct? No
Problem: In a sock factory, a worker started with 26 pairs of socks. Unfortunately, 50 pairs got torn and had to be discarded. The worker was able to produce 36 more pairs to replace them. Each pair of socks is sold for $37. After earning from the sock sales, the worker found a $13 bill on the floor. How much money does the worker have in total?
Mistral 7B:
Reasoning: The worker started with 26 pairs of socks, which were worth 26*$37 = <<26*37=962>>962. The worker lost 50 pairs of socks, which were worth 50*$37 = <<50*37=1850>>1850. The worker produced 36 more pairs of socks, which were worth 36*$37 = <<36*37=1326>>1326. The worker earned $13 from the found bill. The worker's total earnings are 962-1850+1326+13 = <<962-1850+1326+13=346>>346. ### Answer: 346
Expected answer: 457
Correct? No
Problem: A jewelry maker starts with 38 beads to make a bracelet. However, the number of beads was not right, so she removed a number of beads equal to dividing 560 by 40. However, she thinks her initial count may have been wrong and she may have actually started with 15 more beads than she initially thought. After adjusting the count and removing some beads, she adds one more bead, and then 39 more. How many beads does the jewelry maker have now?
Mistral 7B:
Reasoning: 1. Initially, the jewelry maker had 38 beads. 2. She removed a number of beads equal to dividing 560 by 40, which is 14. 3. She initially thought she had 15 more beads, so she started with 38+15 = <<38+15=53>>53 beads. 4. She added one more bead, so she had 54 beads. 5. Then she added 39 more beads, so she had 54+39 = <<54+39=93>>93 beads. ### Answer: 93
Expected answer: 79
Correct? No
Problem: In an aquarium, there are initially 30 sharks. But then, 23 of them are moved to a different area of the aquarium. A few days later, an additional 14 sharks are brought in, followed by 3 more being moved to the other area. The number of sharks is then multiplied by 43 for a research study. What is the final figure for the research?
Mistral 7B:
Reasoning: Initially, there are 30 sharks. After moving 23 sharks, there are 30-23 = <<30-23=7>>7 sharks left. Then, 14 more sharks are brought in, making the total 7+14 = <<7+14=21>>21 sharks. After moving 3 more sharks, there are 21-3 = <<21-3=18>>18 sharks left. Finally, the number of sharks is multiplied by 43, resulting in 18*43 = <<18*43=774>>774 sharks for the research. ### Answer: 774
Expected answer: 774
Correct? Yes
Problem: We are back at the aquarium again! Previously, we mentioned the number of sharks being multiplied by 43 for a research study. But this time, instead of multiplying by 43, the scientists made a mistake and only multiplied it by 4. What would the new figure for the experiment be?
Mistral 7B:
Reasoning: Initially, there are 30 sharks. After moving 23 sharks, there are 30-23 = <<30-23=7>>7 sharks left. Then, 14 more sharks are brought in, making the total 7+14 = <<7+14=21>>21 sharks. After moving 3 more sharks, there are 21-3 = <<21-3=18>>18 sharks left. Finally, the number of sharks is multiplied by 4, resulting in 18*4 = <<18*4=72>>72 sharks for the research. ### Answer: 72
Expected answer: 72
Correct? Yes
Problem: In a puzzle game, each round you collect 150 points which are then divided by 10 to determine the number of gold coins you earn. After two rounds, you earned some gold coins. In the third round, you collected 28 emeralds and 14 sapphires but you had to sacrifice the same amount of gold coins as you earned in the first two rounds. How many emeralds and sapphires did you have left after the third round?
Mistral 7B:
Reasoning: In the first two rounds, you earned 2*10 = <<2*10=20>>20 gold coins. In the third round, you sacrificed 20 gold coins, so you had 0 gold coins left. Since you collected 28 emeralds and 14 sapphires in the third round, you still have 28 emeralds and 14 sapphires left after the third round. ### Answer: You have 28 emeralds and 14 sapphires left after the third round.
Expected answer: 12
Correct? No
Problem: A train gets to carry 15 containers every day. On Fridays, the train gets to carry an extra 12 containers than usual. The following Monday, the train carries an additional 26 containers. However, on Wednesday, the load decreases by 32 containers. For a particular trip, the train is coupled with 2 more containers, and after it makes one stop, an additional 48 containers are loaded onto the train. How many containers is the train carrying at this point?
Mistral 7B:
Reasoning: 1. On Monday, the train carries 15+26 = <<15+26=41>>41 containers. 2. On Tuesday, the train carries the same number of containers as on Monday, so it carries 41 containers. 3. On Wednesday, the train carries 41-32 = <<41-32=9>>9 containers. 4. On Thursday, the train is coupled with 2 more containers, so it carries 9+2 = <<9+2=11>>11 containers. 5. On Friday, the train carries an extra 12 containers than usual, so it carries 11+12 = <<11+12=23>>23 containers. 6. On the following Monday, the train carries an additional 48 containers, so it carries 23+48 = <<23+48=71>>71 containers. ### Answer: 71
Expected answer: 71
Correct? Yes
Problem: A lemon farmer had harvested 39 lemons in the morning and 33 in the afternoon. Unfortunately, 12 lemons got spoiled by the end of the day. The next day, the farmer used 23 lemons to make lemonade. How many lemons did he have left after making the lemonade?
Mistral 7B:
Reasoning: The farmer had 39+33-12 = <<39+33-12=64>>64 lemons at the end of the first day. The farmer used 23 lemons to make lemonade, so he had 64-23 = <<64-23=41>>41 lemons left after making the lemonade. ### Answer: 41
Expected answer: 37
Correct? No
Problem: A bee lands on 33 flowers in an hour. If the bee is collecting 15 nectar droplets from each flower, how many nectar droplets does it have after an hour if it started with 26 nectar droplets?
Mistral 7B:
Reasoning: The bee collects 33*15 = <<33*15=495>>495 nectar droplets from the flowers. The bee has 495+26 = <<495+26=521>>521 nectar droplets after an hour. ### Answer: 521
Expected answer: 521
Correct? Yes
Problem: If instead of starting with 26 nectar droplets, the bee had initially found 49 nectar droplets before it started its hour of flower visits, how many nectar droplets would the bee have after an hour of collecting nectar from 33 flowers with 15 nectar droplets each?
Mistral 7B:
Reasoning: The bee collects 33*15 = <<33*15=495>>495 nectar droplets from the flowers. The bee has 49+495 = <<49+495=544>>544 nectar droplets after an hour. ### Answer: 544
Expected answer: 544
Correct? Yes
Problem: A company produces 36 marshmallow packs in an hour. To meet a sudden increase in demand, they decide to increase their production. They add an extra 350 marshmallows to their daily production, which is distributed evenly over 7 hours of their working day. Additionally, they add another 6 marshmallow packs to their hourly production. But, due to some limitations, they end up producing 43 less packs per hour than their goal. How many marshmallow packs per hour are they now producing?
Mistral 7B:
Reasoning: First, let's find out how many extra marshmallows they produce per hour due to the additional 6 marshmallows per pack and the 350 marshmallows distributed over 7 hours: Extra marshmallows per hour = (6 marshmallows/pack + 350 marshmallows) / 7 hours = (6 + 350/7) marshmallows/hour Now, let's find out their goal for hourly production: Goal = 36 marshmallow packs/hour + 43 marshmallows/hour (to make up for the 43 packs they are producing less) = 80 marshmallow packs/hour Since they are producing less than their goal, we can find the difference between their goal and the extra marshmallows per hour: Difference = 80 marshmallow packs/hour - (6 + 350/7) marshmallows/hour Now, we can solve for the hourly production: Hourly production = 80 marshmallow packs/hour - Difference ### Answer: Hourly production = 80 marshmallow packs/hour - (80 - (6 + 350/7)) marshmallows/hour = 14 marshmallow packs/hour.
Expected answer: 49
Correct? No
Problem: A wizard casts a spell that produces 882 glimmering lights over a span of 21 days. That's an average of how many lights a day? In comparison, another wizard casts a spell that produces 460 glowing orbs in 20 days. What is the daily average here? Now, let's assume that the difference in their daily averages times the second wizard's daily average is a magical constant represented by 'n'. Can you find out what 'n' is?
Mistral 7B:
Reasoning: 1. The first wizard's daily average is 882 lights / 21 days = <<882/21=41.952381>>41.95 lights per day (rounded to two decimal places). 2. The second wizard's daily average is 460 orbs / 20 days = <<460/20=23>>23 orbs per day. 3. The difference in their daily averages is 41.95 - 23 = <<41.95-23=18.95>>18.95 lights per day. 4. The second wizard's daily average times the difference in their daily averages is (18.95 * 23) = <<18.95*23=432.35>>432.35 (rounded to two decimal places). 5. Since this is a magical constant 'n', we can say that 'n' = 432.35. ### Answer: n = 432.35
Expected answer: 437
Correct? No
Problem: A candy factory has 20 different flavors of candy. Their bestselling flavors are the Sugar Rush, which has 14 different base ingredients, the Candy Twirl, which has 25 base ingredients, and the Jawbreaker, which has 16 base ingredients. They create a Special Mix which combines all of these bestsellers and adds 43 extra goodies, including sprinkles and marshmallows. To create a limited edition candy, they take a piece of the Special Mix, add 7 uniquely crafted sweets, then combine this with one of each flavor from their 20 different flavored candies (excluding 19 of them so it's not too overwhelming). They then top it all off by removing 3 experimental sweets that didn't taste quite right. What is the count of various components used in creating this limited edition candy?
Mistral 7B:
Reasoning: 1. The Special Mix consists of the Sugar Rush, Candy Twirl, and Jawbreaker, along with 43 extra goodies. 2. The Special Mix has 14 (Sugar Rush) + 25 (Candy Twirl) + 16 (Jawbreaker) + 43 = <<14+25+16+43=88>>88 base ingredients. 3. The limited edition candy includes one of each flavor from the 20 different flavored candies, excluding one flavor (the one used in the Special Mix). So, it has 19 additional flavors. 4. The limited edition candy also includes 7 uniquely crafted sweets and has 3 experimental sweets removed. 5. Therefore, the total count of various components used in creating this limited edition candy is 88 (Special Mix) + 19 (additional flavors) + 7 (uniquely crafted sweets) = <<88+19+7=104>>104 components. ### Answer: 104
Expected answer: 103
Correct? No
Problem: In a special operation, 32 police officers were assigned to the north district, 33 were sent to the south district, and 29 officers were held for the downtown district. After the operation, 21 officers from the downtown district were transferred elsewhere. A week later, on a different assignment, 39 officers were added to the remaining duty force. Later that day, another 14 officers joined the force. How many officers were on duty by the end of the day?
Mistral 7B:
Reasoning: Initially, there were 32+33+29 = <<32+33+29=94>>94 officers on duty. After transferring 21 officers from the downtown district, there were 94-21 = <<94-21=73>>73 officers on duty. Later, 39 officers were added, making the total 73+39 = <<73+39=112>>112 officers on duty. Finally, 14 more officers joined, making the total 112+14 = <<112+14=126>>126 officers on duty by the end of the day. ### Answer: 126
Expected answer: 126
Correct? Yes
Problem: The previous problem had us determine the total number of police officers on duty under certain conditions. Now, let's imagine a slightly different scenario. Like the previous situation, there were still 32 officers assigned to the north district and 33 sent to the south. The number for the downtown district was also the same, at 29. However, this time around, only 21 officers from the total force were transferred elsewhere instead of the original scenario's subtraction. A week later, an additional 22 officers, fewer than the 39 from the original scenario, were brought in for a different assignment. That same day, another addition of 14 officers was made, just like with the initial series of events. New question: How many officers total were on duty by the end of the day in this amended scenario?
Mistral 7B:
Reasoning: Initially, there were 32+33+29 = <<32+33+29=94>>94 officers on duty. After transferring 21 officers from the total force, there were 94-21 = <<94-21=73>>73 officers on duty. A week later, 22 officers were added, making the total 73+22 = <<73+22=95>>95 officers on duty. Finally, 14 more officers joined, making the total 95+14 = <<95+14=109>>109 officers on duty by the end of the day in this amended scenario. ### Answer: 109
Expected answer: 109
Correct? Yes
Problem: The distance between the Moon and the Earth changes throughout the month. On one particular day, the distance was 36 million kilometers but decreased by 19 million kilometers later in the month. Then it increased again by 11 million kilometers. If that distance, in millions of kilometers, times 19 minus 27 equals to a certain value, what is the value?
Mistral 7B:
Reasoning: Let D be the initial distance (36 million kilometers), d1 be the decrease (19 million kilometers), and d2 be the increase (11 million kilometers). The distance after the decrease is D - d1 = 36 - 19 = <<36-19=17>>17 million kilometers. The distance after the increase is D - d1 + d2 = 17 + 11 = <<17+11=28>>28 million kilometers. The distance times 19 minus 27 is (D - d1 + d2) * 19 - 27 = 28 * 19 - 27 = <<28*19-27=464>>464. ### Answer: 464
Expected answer: 505
Correct? No
Problem: A tiger has an average step length of 9 meters. If a tiger took two steps and then leaped 44 meters, it would have covered a certain distance. Another tiger covered a distance combining 23 meters with a leap and a 46-meter run but then retraces the distance equal to the first tiger's steps and the leap. How much distance did the second tiger cover finally?
Mistral 7B:
Reasoning: 1. The first tiger covered a distance of 2*9 + 44 = <<2*9+44=42>>42 meters. 2. The second tiger covered a distance of 23 + 46 - 2*9 - 44 = <<23+46-2*9-44=15>>15 meters initially. 3. Since the second tiger retraced the distance equal to the first tiger's steps and leap, it covered a distance of -(2*9 + 44) = <<-(2*9+44)=-57>>-57 meters. 4. To find the final distance covered by the second tiger, we add the initial distance and the retraced distance: 15 + (-57) = <<15+-57=-42>>-42 meters. ### Answer: -42 utschke I apologize for the mistake in my previous response. The correct answer should be 42 meters, as the second tiger covered the initial distance and then retraced the same distance, so the net distance covered is zero. The negative sign indicates that the distance is in the opposite direction. However, since the question asks for the distance covered finally, the correct answer should be the absolute value of the distance, which is 42 meters. ### Answer: 42
Expected answer: 7
Correct? No
Problem: A toothpaste factory produces 26 tubes of toothpaste every hour. On Sundays, they work for 7 hours and produce additional 8 tubes of toothpaste. So, in one Sunday, they produce ((26 * 7) + 8) tubes. The following Monday, they continue their production by adding another 31 tubes to their Sunday's total. In parallel, in the packaging department, they have 50 empty boxes. They use 19 of them for another department, leaving them with (50 - 19) boxes. The total number of toothpaste tubes ready is calculated by adding the packaged boxes number with Monday's production. On Tuesday, they produced an additional 48 tubes of toothpaste. What is the total number of produced toothpaste tubes until Tuesday, inclusive?
Mistral 7B:
Reasoning: On Sunday, they produced (26 * 7 + 8) = <<(26*7+8)=182>>182 tubes. On Monday, they produced an additional 31 tubes, making the total number of tubes produced until Monday, inclusive, 182 + 31 = <<182+31=213>>213 tubes. On Tuesday, they produced an additional 48 tubes, making the total number of tubes produced until Tuesday, inclusive, 213 + 48 = <<213+48=261>>261 tubes. ### Answer: 261
Expected answer: 300
Correct? No
Problem: In a magical forest, a unicorn has 42 rainbow pebbles. A day later, it finds 26 more. It also has a stash of 44 dreamberries. Later on, the unicorn gathers 33 more rainbow pebbles and adds them with its stash of dreamberries. Finally, the unicorn finds 40 magical dandelions and adds them to his stash, but oh no, he loses 14! How many items does the unicorn have altogether after these events?
Mistral 7B:
Reasoning: The unicorn starts with 42 rainbow pebbles, then finds 26 more, making a total of 42+26 = <<42+26=68>>68 rainbow pebbles. Then, the unicorn has 44 dreamberries. After gathering 33 more rainbow pebbles, the unicorn has 68+33 = <<68+33=101>>101 rainbow pebbles. Then, the unicorn finds 40 magical dandelions, making a total of 101+40 = <<101+40=141>>141 items. Finally, the unicorn loses 14 items, leaving him with 141-14 = <<141-14=127>>127 items altogether. ### Answer: 127
Expected answer: 171
Correct? No
Problem: A pirate captain has a treasure chest containing 23 types of jewels. Each type has 28 jewels. Tired from his adventure, he mistakenly lost 40 jewels on his way back to his ship. The next day, he luckily found 16 jewels from a deserted island. How many jewels does he have now in his treasure chest?
Mistral 7B:
Reasoning: Initially, the pirate captain had 23 \* 28 = <<23*28=644>>644 jewels. He lost 40 jewels, so he had 644 - 40 = <<644-40=604>>604 jewels left. Then he found 16 jewels, so he now has 604 + 16 = <<604+16=620>>620 jewels in his treasure chest. ### Answer: 620
Expected answer: 620
Correct? Yes
Problem: Following the discovery of additional jewels, the pirate captain realized he had miscalculated the number of types of jewels in his original stash. Instead of 23 types of jewels, he remembered that he actually only had 17 types originally, with each type still containing 28 jewels. After recalculating his treasure and still taking into account the loss of 40 jewels and the 16 he found on a deserted island, how many jewels does he have now?
Mistral 7B:
Reasoning: Initially, the pirate captain had 17 \* 28 = <<17*28=476>>476 jewels. He lost 40 jewels, so he had 476 - 40 = <<476-40=436>>436 jewels left. Then he found 16 jewels, so he now has 436 + 16 = <<436+16=452>>452 jewels in his treasure chest. ### Answer: 452
Expected answer: 452
Correct? Yes
Problem: In a distant galaxy, a star shines brightly with 38 neutrons. It then gains 4 more. This total number gets multiplied by 18 to create a sensational energy output. During an explosion, it additionally releases the energy equivalent to 6 plus 25. How much total energy does the star emit?
Mistral 7B:
Reasoning: First, the star gains 4 more neutrons, making it have 42 neutrons in total. Then, the total number of neutrons gets multiplied by 18, resulting in 756 neutrons. Finally, the star releases additional energy equivalent to 6+25 = <<6+25=31>>31 units. The total energy emitted by the star is 756 + 31 = <<756+31=787>>787 units. ### Answer: 787
Expected answer: 787
Correct? Yes
Problem: Now consider instead that the star had only 38 neutrons initially, and then it gains only 4 more. This total number is then multiplied by 10, for a lower energy output. During an explosion, it still releases additional energy equivalent to 6 plus 25. Now, how much total energy does the star emit?
Mistral 7B:
Reasoning: First, the star gains 4 more neutrons, making it have 42 neutrons in total. Then, the total number of neutrons gets multiplied by 10, resulting in 420 neutrons. Finally, the star releases additional energy equivalent to 6+25 = <<6+25=31>>31 units. The total energy emitted by the star is 420 + 31 = <<420+31=451>>451 units. ### Answer: 451
Expected answer: 451
Correct? Yes
Problem: A gardener planted 13 Sunflowers in his garden. The next day, he worked out that he needed to plant more, with the number being calculated as 37 times the number of petals on one sunflower, which is 5, minus 18. On the following day, he subtracted 10 flowers from that number, then added his initial sunflowers back, creating a new total. Meanwhile, he figured out that in a special part of his garden, ideal for 92 orchids he had, each spot can hold 23, so he calculated how many spots needed. By the end of the week, he summed up the total number of plants he worked on and the spots needed, then he doubled that total for no particular reason. How many did he end up with?
Mistral 7B:
Reasoning: 1. The number of sunflowers he needed to plant on the second day is 37*(5-18) = 37*(-13) = -<<37*-13=-481>>481 sunflowers. 2. He subtracted 10 flowers from that number, so the number of sunflowers he needed to plant on the second day is -481 - 10 = -<<-481-10=-491>>491. 3. He added his initial 13 sunflowers back, so the total number of sunflowers he needed to plant on the second day is 491 + 13 = 504. 4. He planted 13 sunflowers initially, so the total number of sunflowers he planted in the garden is 13 + 504 = 517. 5. In the special part of his garden, he calculated that he needed 92/23 = <<92/23=4>>4 spots for each orchid. 6. He summed up the total number of plants he worked on and the spots needed, which is 517 + 92 = 609. 7. He doubled that total for no particular reason, so the final number of plants he ended up with is 609 * 2 = <<609*2=1218>>1218. ### Answer: 1218
Expected answer: 348
Correct? No
Problem: In a particular pond, there are 18 frogs. Each frog can catch 21 flies in a day. How many flies do all the frogs catch in a day?
Mistral 7B:
Reasoning: Each frog catches 21 flies in a day. Since there are 18 frogs, the total number of flies caught by all the frogs in a day is 18*21 = <<18*21=378>>378 flies. ### Answer: 378
Expected answer: 378
Correct? Yes
Problem: Using the initial information from the previous problem where 18 frogs catch 21 flies each in a day (resulting in a total of 'j' flies), imagine the scenario where a particularly voracious toad comes by the next day and catches an additional 39 flies. How many flies have been caught in total over the two days then?
Mistral 7B:
Reasoning: On the first day, 18 frogs catch 18*21 = <<18*21=378>>378 flies. On the second day, the toad catches 39 flies, and the frogs catch the same number of flies as they did on the first day (18*21 = 378 flies). The total number of flies caught over the two days is 378 (from the first day) + 39 (from the toad on the second day) + 378 (from the frogs on the second day) = <<378+39+378=815>>815 flies. ### Answer: 815
Expected answer: 417
Correct? No
Problem: Using the information from the previous problem, now consider if the number of frogs in the pond increased to 46. If each frog can still catch 21 flies in a day, how many flies do all the frogs catch in a day now?
Mistral 7B:
Reasoning: Each frog still catches 21 flies in a day. Since there are now 46 frogs, the total number of flies caught by all the frogs in a day is 46*21 = <<46*21=966>>966 flies. ### Answer: 966
Expected answer: 966
Correct? Yes
Problem: A community center has 21 chairs in their main meeting room. They are supplemented with an additional 22 chairs from the storage room for a large event. How many chairs are in the meeting room now for the event?
Mistral 7B:
The community center has 21 chairs in their main meeting room, and they added 22 chairs from the storage room. So, the total number of chairs in the meeting room for the event is 21+22 = <<21+22=43>>43. ### Answer: 43
Expected answer: 43
Correct? Yes
Problem: Now, instead of starting with 21 chairs in the main meeting room at the community center, suppose they had only 12 chairs. They still supplement with an additional 22 chairs from the storage room for the event. How many chairs are in the meeting room now for the event?
Mistral 7B:
If the community center started with 12 chairs in the main meeting room, and they added 22 chairs from the storage room, the total number of chairs in the meeting room for the event would be 12+22 = <<12+22=34>>34. ### Answer: 34
Expected answer: 34
Correct? Yes
Problem: There are 14 elephants in a conservation park. This year, 11 new baby elephants were born, and the park received 25 more elephants from various rescues. How many elephants are there in the park now?
Mistral 7B:
Reasoning: Initially, there were 14 elephants in the park. This year, 11 new baby elephants were born, so there are now 14+11 = <<14+11=25>>25 elephants in the park due to the births. Additionally, the park received 25 more elephants from various rescues, so there are now 25+25 = <<25+25=50>>50 elephants in the park. ### Answer: 50
Expected answer: 50
Correct? Yes
Problem: Unfortunately, due to unfortunate circumstances, 27 elephants had to be relocated to different parks over the course of the year. How many elephants are left in the park now?
Mistral 7B:
Reasoning: Initially, there were 50 elephants in the park. After relocating 27 elephants, there are now 50-27 = <<50-27=23>>23 elephants in the park. ### Answer: 23
Expected answer: 23
Correct? Yes
Problem: Suppose initially, there were 38 elephants in the conservation park instead of 14. If the park still received 11 new baby elephants and 25 more elephants from various rescues this year, how many elephants would there be in the park now?
Mistral 7B:
Reasoning: Initially, there were 38 elephants in the park. This year, 11 new baby elephants were born, so there are now 38+11 = <<38+11=49>>49 elephants in the park due to the births. Additionally, the park received 25 more elephants from various rescues, so there are now 49+25 = <<49+25=74>>74 elephants in the park. ### Answer: 74
Expected answer: 74
Correct? Yes
Problem: A treasure chest contains 23 emeralds and 30 diamonds. Unfortunately, 39 of the stones are fake and had to be removed. The number of real stones left (y) is multiplied by itself and then 37 is subtracted to get a number (g) that represents the value of the chest. In another chest, there were 540 rubies which have been equally shared amongst 45 pirates, and then 3 are lost in the division. The remaining number (x) is subtracted from the value of the first chest (g) to get a new value. In the same chest as the rubies, there were also 23 pearls and 11 zirconias, but 9 pieces had to be discarded due to damage. The count (s) is subtracted from the new value to determine the value (m) of the remaining treasure. What is the value (m) of the remaining treasure?
Mistral 7B:
Reasoning: 1. First, let's find the number of real stones (y) in the first chest. Since 39 fake stones were removed, the total number of stones (23 emeralds + 30 diamonds = 53) minus the number of fake stones (39) gives us the number of real stones (53 - 39 = <<53-39=14>>14). 2. The value (g) of the chest is obtained by multiplying the number of real stones (14) and then subtracting 37. 3. In the second chest, each pirate received (540 rubies / 45 pirates = <<540/45=12>>12 rubies, and 3 were lost in the division, so there are 12 * 45 - 3 = <<12*45-3=537>>537 rubies remaining. 4. The value (m) of the remaining treasure is obtained by subtracting the count (s) of damaged pieces from the new value (g + 537). 5. In the same chest, there were 23 pearls and 11 zirconias, but 9 pieces were damaged, so there are 23 + 11 - 9 = <<23+11-9=31>>31 pieces remaining. 6. Since the value (m) of the remaining treasure is obtained by subtracting the count (s) of damaged pieces from the new value (g + 537), we can find the count (s) of damaged pieces by subtracting the value (m) from the new value (g + 537). 7. However, the question does not provide the value (m) of the remaining treasure, so it is impossible to find the count (s) of damaged pieces and continue the calculation. ### Answer: The question is incomplete, so it is impossible to find the value (m) of the remaining treasure.
Expected answer: 125
Correct? No
Problem: There are 6 confirmed UFO sightings in a small city. After a viral event, sightings increase by a daily average obtained by dividing an additional 504 sightings over the next 14 days. Subtract the initial confirmed sightings from this new daily average. Then, multiply it by the result of taking the maximum number of sightings recorded in one day (9) and subtracting the number you would typically dismiss as random (3). How many sightings are there according to this calculation?
Mistral 7B:
Reasoning: The daily average increase in sightings is 504/14 = <<504/14=36.714285714285716>>36.71 sightings per day. The number of sightings according to the calculation is (36.71 - 6) * (9 - 3) = <<(36.71-6)*(9-3)=210.21>>210.21 sightings. ### Answer: 210.21 (rounded to two decimal places)
Expected answer: 180
Correct? No
Problem: A blanket maker has 5 square patches of blue material. She wants to make an intricate design that requires her to subtract this from 26*25 square patches of red material. Then, she wants to compare this number to her stock of green material, which is 48*21 square patches, by subtracting the number of red patches from the green patches. How many patches is the difference between her stock of green patches and the red patches needed for the design?
Mistral 7B:
Reasoning: First, we find the number of red patches needed for the design by subtracting the 5 blue patches from 26*25: 26*25 - 5 = 650 - 5 = 645 red patches. Then, we find the difference between the stock of green patches and the red patches needed for the design: 48*21 - 645 = 1032 - 645 = 387. ### Answer: 387
Expected answer: 363
Correct? No
Problem: Lemonville is a small village known for its lemon trees. One year, the villagers picked 38 baskets of lemons from the trees near the river and 24 baskets from the ones near an old well. From the trees near the school, they picked 16 more baskets and from the trees near the mayor's house, they picked 13 more baskets. They realized that their lemons were heavier and they could extract more juice so they decided to get 35 baskets to make lemonade. If each basket of lemons could produce 14 bottles of lemonade, how many bottles of lemonade would they get from the remaining baskets?
Mistral 7B:
Reasoning: First, let's find out how many baskets of lemons they picked in total: 38 (river) + 24 (well) + 16 (school) + 13 (mayor's house) = 91 baskets. Since they need 35 baskets for making lemonade, they have 91 - 35 = <<91-35=56>>56 baskets left. Each basket can produce 14 bottles of lemonade, so they will get 56 * 14 = <<56*14=784>>784 bottles of lemonade from the remaining baskets. ### Answer: 784
Expected answer: 784
Correct? Yes
Problem: The villagers in Lemonville reconsidered their previous decision and determined that they would only need 23 baskets of lemons, instead of their initial estimation of 35 baskets, to make their village famous lemonade. If each basket of lemons could still produce 14 bottles of lemonade, how many bottles of lemonade would they get from the remaining baskets now?
Mistral 7B:
Reasoning: First, let's find out how many baskets of lemons they picked in total: 38 (river) + 24 (well) + 16 (school) + 13 (mayor's house) = 91 baskets. Since they now need 23 baskets for making lemonade, they have 91 - 23 = <<91-23=68>>68 baskets left. Each basket can produce 14 bottles of lemonade, so they will get 68 * 14 = <<68*14=952>>952 bottles of lemonade from the remaining baskets. ### Answer: 952
Expected answer: 952
Correct? Yes
Problem: Amy found 21 seashells in the sandbox, but gave 15 of them to her sister. The next day, she found another group of seashells that was 13 more than the amount she had remaining from the previous day. She also found an additional 49. Being a generous sister, she gave 23 to her brother and 27 to her cousin. How many seashells does Amy have left now?
Mistral 7B:
Reasoning: 1. Amy had 21 seashells initially. 2. She gave 15 to her sister, leaving her with 21-15 = <<21-15=6>>6 seashells. 3. The next day, she found another group of seashells that was 13 more than the amount she had remaining from the previous day. So, she found 6+13 = <<6+13=19>>19 seashells. 4. She gave 23 to her brother and 27 to her cousin, leaving her with 19-23-27 = <<19-23-27=-21>>-21 seashells. 5. However, since it's not possible to have a negative number of seashells, there seems to be an error in the problem. ### Answer: There seems to be an error in the problem.
Expected answer: 18
Correct? No
Problem: Princess Anna was playing a numbers game in the kingdom. In the first round of the game, she thought of two numbers: 7 and 10. She added them together. In the second round, she thought of a number 29. She subtracted the result from the first round and then subtracted 8 more from that result. In the final round, Princess Anna added the results from the first and second round and then multiplied the sum by the result from the second round. What was the final result of the Princess's game?
Mistral 7B:
Reasoning: In the first round, the sum of the two numbers was 7+10=<<7+10=17>>17. In the second round, she subtracted the result from the first round, so she subtracted 17 from 29, which gives 12. Then she subtracted 8 more, so the result was 12-8=<<12-8=4>>4. In the final round, she added the results from the first and second round, so she added 17 and 4, which gives 21. Then she multiplied the sum by the result from the second round, so she multiplied 21 by 4, which gives 21*4=<<21*4=84>>84. ### Answer: 84
Expected answer: 84
Correct? Yes
Problem: Following the princess' first game, her little sister, Princess Bella, wanted to join in with her own twist. Bella did as follows: In the first round, Bella copied Anna and added the same two numbers: 7 and 10 together. For the second round, sister Bella thought of the number 33. Just like Anna, She subtracted the result from the first round and then decreased it by 8. In the final round, Princess Bella, like Anna, added the results from the first and second round. Then, she multiplied the sum by the result from her modified second round. What was the final result of Princess Bella's game?
Mistral 7B:
Reasoning: In the first round, the sum of the two numbers was 7+10=<<7+10=17>>17. In the second round, Bella subtracted the result from the first round, so she subtracted 17 from 33, which gives 16. Then she decreased it by 8, so the result was 16-8=<<16-8=8>>8. In the final round, Bella added the results from the first and second round, so she added 17 and 8, which gives 25. Then she multiplied the sum by the result from her modified second round, so she multiplied 25 by 8, which gives 25*8=<<25*8=200>>200. ### Answer: 200
Expected answer: 200
Correct? Yes
Problem: Ellen had 15 dollars. Meanwhile, Sam had 48 dollars but then he gave some money to Ellen. After Sam gave his money to Ellen, he had as much money as Ellen originally had. Then, Sam got 24 dollars from his brother. How much money does Sam have now?
Mistral 7B:
Reasoning: Let's denote the amount of money Sam gave to Ellen as x. After Sam gave x dollars to Ellen, he had x dollars left, and Ellen had 15+x dollars. Since Sam had as much money as Ellen originally had, we can write the equation: x + 48 = 15 + x. Solving for x, we get: x = 48 - 15 = 33 After Sam gave 33 dollars to Ellen, he had 33 dollars left. Sam got 24 dollars from his brother, so now he has 33 + 24 = <<33+24=57>>57 dollars. ### Answer: 57
Expected answer: 57
Correct? Yes
Problem: Continuing from the previous scenario, let's say Sam decides to multiply the money he has now by the amount Ellen originally had, due to a lucky charm he believes in. How much money does Sam end up with after this multiplication?
Mistral 7B:
Reasoning: Sam has 57 dollars now. Ellen originally had 15 dollars. Sam multiplies the money he has now by the amount Ellen originally had, so he multiplies 57 by 15. 57 * 15 = <<57*15=855>>855 ### Answer: 855
Expected answer: 855
Correct? Yes
Problem: Continuing from our previous scenario, let's say that actually, Sam had 46 dollars originally, not 48. He still gave some money to Ellen, leaving him with as much money as Ellen originally had. Then, Sam got 24 dollars from his brother. Considering this, how much money does Sam have now?
Mistral 7B:
Reasoning: Let's denote the amount of money Sam gave to Ellen as x. After Sam gave x dollars to Ellen, he had x dollars left, and Ellen had 15+x dollars. Since Sam had as much money as Ellen originally had, we can write the equation: x + 46 = 46. Solving for x, we get: x = 46 - 46 = 0 This means that Sam didn't give any money to Ellen when he had 46 dollars. Sam got 24 dollars from his brother, so now he has 46 + 24 = <<46+24=70>>70 dollars. ### Answer: 70
Expected answer: 55
Correct? No
Problem: A group of scientists began studying a river and found that it was 33 kilometers long. To be thorough, they decided to also study a connected tributary, which added 19 kilometers to the total length of waterway they needed to investigate. However, they later realized that a 30-kilometer portion of the river was inaccessible and couldn't be studied. How many kilometers of the river were they able to study?
Mistral 7B:
Reasoning: The scientists initially had to study a 33+19 = <<33+19=52>>52-kilometer long river. However, they couldn't study a 30-kilometer portion, so they were able to study 52-30 = <<52-30=22>>22 kilometers of the river. ### Answer: 22
Expected answer: 22
Correct? Yes
Problem: After finishing the initial survey, the team of scientists received a special permit to investigate an additional stretch of the river 32 kilometers long that was previously off limits. In total, how many kilometers of the river were the scientists able to study?
Mistral 7B:
Reasoning: Initially, the scientists were able to study 22 kilometers of the river. After receiving the permit, they were able to study an additional 32 kilometers. So, the total length of the river that the scientists were able to study is 22+32 = <<22+32=54>>54 kilometers. ### Answer: 54
Expected answer: 54
Correct? Yes
Problem: Suppose instead that the inaccessible portion of the river that the scientists were unable to study was 26 kilometers, not 30. How many kilometers of the river would they have been able to study under these conditions?
Mistral 7B:
Reasoning: The scientists initially had to study a 33+19 = <<33+19=52>>52-kilometer long river. However, they couldn't study a 26-kilometer portion, so they were able to study 52-26 = <<52-26=26>>26 kilometers of the river. ### Answer: 26
Expected answer: 26
Correct? Yes
Problem: A photographer took 34 shots at a wedding but decided to remove 19 of them because they were out of focus. The next day he took an additional 21 shots at a different event. Then, he decided to add to this collection, 23 more shots he took on a third event. Similarly, another photographer took 880 shots at a large event and decided to select every 40th shot for his collection. What is the total number of shots in their collections combined?
Mistral 7B:
Reasoning: The first photographer has 34-19 = <<34-19=15>>15 shots from the wedding, 21 shots from the second event, and 23 shots from the third event. So, the first photographer has a total of 15+21+23 = <<15+21+23=59>>59 shots. The second photographer selects every 40th shot from the 880 shots he took. To find the number of selected shots, we can divide the total number of shots by 40 and round up to the nearest whole number since the first shot is included. So, the second photographer has 880/40 = <<880/40=22>>22 shots in his collection. The total number of shots in their collections combined is 59 + 22 = <<59+22=81>>81 shots. ### Answer: 81
Expected answer: 81
Correct? Yes
Problem: Recalling the photographers from the previous problems. Suppose the second photographer decided to select every 28th shot instead of every 40th shot for his collection from the large event where he took 880 shots. Now, what is the total number of shots in their collections combined after this modification?
Mistral 7B:
Reasoning: The second photographer selects every 28th shot from the 880 shots he took. To find the number of selected shots, we can divide the total number of shots by 28 and round up to the nearest whole number since the first shot is included. So, the second photographer has 880/28 = <<880/28=31.42857142857143>>31 shots in his collection. The total number of shots in their collections combined is 59 + 31 = <<59+31=90>>90 shots. ### Answer: 90
Expected answer: 633/7
Correct? No
Problem: A pirate found a treasure chest containing 3 times the amount of his previous loot of 13 gold coins. After spending 22 of these coins for the crew's rum, he discovered another loot of 47 gold coins. How many gold coins does the pirate have now?
Mistral 7B:
Reasoning: The pirate had 3*13 = <<3*13=39>>39 gold coins from the treasure chest. After spending 22 coins, he had 39-22 = <<39-22=17>>17 gold coins left. Then he found another 47 gold coins, so now he has 17+47 = <<17+47=64>>64 gold coins in total. ### Answer: 64
Expected answer: 64
Correct? Yes
Problem: Recall the pirate's adventure. But let's say, originally the treasure chest he found had 42 times the amount of his previous loot of 13 gold coins instead of 3 times. After spending 22 of these coins for the crew's rum, and discovering another loot of 47 gold coins, how many gold coins does the pirate have now?
Mistral 7B:
Reasoning: The pirate had 42*13 = <<42*13=546>>546 gold coins from the treasure chest. After spending 22 coins, he had 546-22 = <<546-22=524>>524 gold coins left. Then he found another 47 gold coins, so now he has 524+47 = <<524+47=571>>571 gold coins in total. ### Answer: 571
Expected answer: 571
Correct? Yes
Problem: A hiker traveled an average of 900 miles in 36 days. One day, he increases his daily average to 16 miles. This reduces his remaining journey by a certain number of days. After that, he finds a shortcut which saves him an additional 4 days, and a friendly traveller advised him of another path that will save him 40 days. If he also saves 21 days due to good weather, how many days in total did he save on his journey?
Mistral 7B:
Reasoning: First, let's find out how many days the hiker would have taken to complete the journey with the initial average speed of 900 miles in 36 days. Days needed for the initial journey = Total miles / Initial daily average Days needed for the initial journey = 900 miles / 900 miles/day = 1 day Since the hiker has already completed 36 days, the remaining days to complete the journey were 36 - 1 = <<36-1=35>>35 days. Now, let's find out how many days the hiker saved by increasing his daily average to 16 miles: Days saved by increasing daily average = Remaining days / (Remaining days / (New daily average - Initial daily average)) Days saved by increasing daily average = 35 days / (35 days / (16 miles/day - 900 miles/36 days)) Days saved by increasing daily average = 35 days * (16 miles/day - 900 miles/36 days) / 35 days Days saved by increasing daily average = 35 days * (16 miles/day - 25 miles/day) / 35 days Days saved by increasing daily average = 35 days * (11 miles/day) / 35 days Days saved by increasing daily average = 11 miles Next, let's find out how many days the hiker saved by finding a shortcut: Days saved by shortcut = 4 days Now, let's find out how many days the hiker saved due to the friendly traveller's advice: Days saved by friendly traveller = 40 days Finally, let's find out how many days the hiker saved due to good weather: Days saved by good weather = 21 days Now, let's add up all the days saved: Total days saved = Days saved by increasing daily average + Days saved by shortcut + Days saved by friendly traveller + Days saved by good weather Total days saved = 11 miles + 4 days + 40 days + 21 days Total days saved = 76 days ### Answer: 76 days
Expected answer: 74
Correct? No
Problem: A pillow manufacturing company produces 33 pillows every hour in round the clock operations. In a day, they realized they had incurred a loss of 43 pillows due to machine errors. What is the total number of pillows the company manufactured in a day after accounting for the losses?
Mistral 7B:
Reasoning: The company produces 33 pillows every hour for 24 hours. So, the total number of pillows produced in a day without losses is 33*24 = <<33*24=792>>792. Since there were 43 losses, the total number of pillows the company manufactured in a day after accounting for the losses is 792-43 = <<792-43=749>>749. ### Answer: 749
Expected answer: 749
Correct? Yes
Problem: The pillow manufacturing company decides to adjust their production rate to be consistent with worker shifts, producing 24 pillows every hour instead. However, they still incur a loss of 43 pillows due to machine errors. What is the total number of pillows the company manufactured in a day after accounting for the losses?
Mistral 7B:
Reasoning: The company produces 24 pillows every hour for 8 hours during the day shift, 8 pillows every hour for 4 hours during the evening shift, and 8 pillows every hour for 4 hours during the night shift. So, the total number of pillows produced in a day without losses is (24*8)+(8*4)+(8*4) = 192+32+32 = <<192+32+32=356>>356. Since there were 43 losses, the total number of pillows the company manufactured in a day after accounting for the losses is 356-43 = <<356-43=313>>313. ### Answer: 313
Expected answer: 533
Correct? No
Problem: In a Castle, there are 5 rooms in one wing. The other wing has 216 bricks. Nowadays, there's a strange rule: one room is equivalent to 36 bricks. Following this, if we have to calculate the sum of total rooms from both wings by converting the number of bricks to the number of rooms. How many rooms would be considered in total according to this rule?
Mistral 7B:
Reasoning: We know that one room is equivalent to 36 bricks. So, to find the number of rooms in the other wing, we divide the number of bricks by the number of bricks per room: 216 / 36 = <<216/36=6>>6 rooms. Since there are 5 rooms in the first wing, the total number of rooms in both wings is 5 + 6 = <<5+6=11>>11 rooms. ### Answer: 11
Expected answer: 11
Correct? Yes
Problem: In the same castle, there is a hidden underground passage which has 9 rooms. After discovering these, if you count all the rooms: the original five, the ones found in the second wing when converting the number of bricks to rooms, and these new rooms from the underground passage together. How many rooms are there in the castle in total?
Mistral 7B:
Reasoning: We already know that there are 5 rooms in the first wing, 6 rooms in the second wing (from the bricks), and now we have 9 rooms in the underground passage. So, the total number of rooms in the castle is 5 + 6 + 9 = <<5+6+9=20>>20 rooms. ### Answer: 20
Expected answer: 20
Correct? Yes
Problem: Suppose when we originally counted, we made a mistake and there were actually 35 rooms in the first wing of the castle, not 5. If we still convert the bricks in the second wing into the equivalent number of rooms and add them to this new total, how many rooms are now in the castle excluding the underground passage rooms?
Mistral 7B:
Reasoning: We know that one room is equivalent to 36 bricks. So, to find the number of rooms in the other wing, we divide the number of bricks by the number of bricks per room: 216 / 36 = <<216/36=6>>6 rooms. Now, there are 35 rooms in the first wing, so the total number of rooms in both wings is 35 + 6 = <<35+6=41>>41 rooms. ### Answer: 41
Expected answer: 41
Correct? Yes
Problem: A player scored 15 goals each over 31 matches. However, due to an error, 43 of the goals were discounted. Later, the error was rectified and 40 goals were awarded back to the player. Unfortunately, after a reevaluation of the matches, 26 of those goals were deducted from the player again. How many goals does the player end up with?
Mistral 7B:
Reasoning: The player initially scored 15*31 = <<15*31=465>>465 goals. 43 goals were discounted, so the player had 465-43 = <<465-43=422>>422 goals. 40 goals were awarded back to the player, so the player had 422+40 = <<422+40=462>>462 goals. 26 goals were deducted again, so the player ended up with 462-26 = <<462-26=436>>436 goals. ### Answer: 436
Expected answer: 436
Correct? Yes
Problem: The player from the previous question, with his total number of goals determined, got involved in a contest where the goal tally he had counted as points with a multiplier attached. If that multiplier was 1, how many points did he get in the contest?
Mistral 7B:
Reasoning: The player had 436 goals, and each goal was worth 1 point. So, the player got 436 points in the contest. ### Answer: 436
Expected answer: 436
Correct? Yes
Problem: An aquarium has 9 tanks, each with 49 fish. However, 5 of the fish in one tank are relocated. What is the new total number of fish in the aquarium?
Mistral 7B:
Reasoning: The number of fish in the aquarium initially is 9 tanks * 49 fish/tank = <<9*49=441>>441 fish. After relocating 5 fish, there are 441 - 5 = <<441-5=436>>436 fish left in the aquarium. ### Answer: 436
Expected answer: 436
Correct? Yes
Problem: Let's consider another situation. Suppose each of the 9 tanks in the aquarium originally contained 47 fish, instead of 49, and the same number of fish (5) were relocated from one tank as in the previous situation. Now, what would be the total number of fish in the aquarium?
Mistral 7B:
Reasoning: The number of fish in the aquarium initially is 9 tanks * 47 fish/tank = <<9*47=423>>423 fish. After relocating 5 fish, there are 423 - 5 = <<423-5=418>>418 fish left in the aquarium. ### Answer: 418
Expected answer: 418
Correct? Yes
Problem: In a card game, Jeremy has 14 cards. He then discards 19 of his cards, and then gains 32 more cards from the deck. How many cards does Jeremy have now?
Mistral 7B:
Reasoning: Jeremy has 14-19 = <<14-19=-5>>-5 cards left after discarding. Jeremy gains 32 cards, so he now has 32+(-5) = <<32+-5=27>>27 cards. ### Answer: 27
Expected answer: 27
Correct? Yes
Problem: In a card game, Jeremy has 14 cards. He then discards 19 of his cards, and then gains 32 more cards from the deck. In the next moved, Jeremy was fortunate enough to be given 7 more cards and found 12 more discarded cards on the table, which he added to his deck. How many cards does Jeremy have now?
Mistral 7B:
Reasoning: Jeremy has 14-19 = <<14-19=-5>>-5 cards left after discarding. Jeremy gains 32 cards, so he now has 32+(-5) = <<32+-5=27>>27 cards. Jeremy is given 7 more cards, so he now has 27+7 = <<27+7=34>>34 cards. Jeremy finds 12 more discarded cards, so he now has 34+12 = <<34+12=46>>46 cards. ### Answer: 46
Expected answer: 46
Correct? Yes
Problem: In the card game, let's imagine that Jeremy initially had 14 cards, but this time he only discards 19 cards before gaining 13 more cards from the deck. How many cards does Jeremy have now?
Mistral 7B:
Reasoning: Jeremy has 14-19 = <<14-19=-5>>-5 cards left after discarding. Jeremy gains 13 cards, so he now has -5+13 = <<-5+13=8>>8 cards. ### Answer: 8
Expected answer: 8
Correct? Yes
Problem: A clock ticks 504 times in 42 minutes. Similarly, another clock ticks 279 times in 31 minutes. Add 34 to the rate of the second clock's ticks per minute. Multiply the first clock's ticks per minute by 35 and then subtract 41 from it. Finally, subtract the rate of the second clock (after adding 34) from the manipulated rate of the first clock. What is the final value?
Mistral 7B:
Reasoning: First, let's find the rate of the second clock's ticks per minute after adding 34: 279 + 34 = <<279+34=313>>313 ticks per minute. Next, let's find the manipulated rate of the first clock's ticks per minute: 504 * 35 = <<504*35=17620>>17,620 ticks per minute. Now, subtract the rate of the second clock (after adding 34) from the manipulated rate of the first clock: 17,620 - 313 = <<17620-313=17307>>17,307 ticks per minute. ### Answer: 17,307
Expected answer: 336
Correct? No
Problem: Nina has noted down the rainfall of her town in centimeters over the last few days. On Tuesday, there was a rainfall of 39 cm. The rainfall decreased by 6 cm on Wednesday and further decreased by 31 cm on Thursday. How much rainfall did Nina note on Thursday?
Mistral 7B:
Reasoning: The rainfall on Wednesday was 39 - 6 = <<39-6=33>>33 cm. The rainfall on Thursday was 33 - 31 = <<33-31=2>>2 cm. ### Answer: 2
Expected answer: 2
Correct? Yes
Problem: A UFO-watching enthusiast reported seeing 50 UFOs in a month. However, a later investigation revealed that 36 of these were actually meteors. In the next month, the enthusiast reported seeing 41 UFOs, plus an amount equal to the revised (i.e., actual) number of UFO sightings from the previous month, with an additional 5. How many UFO sightings were reported by the enthusiast in the second month?
Mistral 7B:
Reasoning: The revised number of UFO sightings in the first month was 50 - 36 = <<50-36=14>>14. The enthusiast reported seeing 41 + 14 + 5 = <<41+14+5=50>>50 UFOs in the second month. ### Answer: 50
Expected answer: 60
Correct? No
Problem: A cat started playing with yarn balls. In her first game, she managed to accumulate 5 yarn balls. In her second game, she got as many balls as the square of what she obtained in the first game plus 8 more. Finally, she lost some of her balls in her third game due to a playful dog. She ended the game with a number of balls which is 25 times the difference between 45 and what she accumulated from the second game. How many yarn balls does the cat have now?
Mistral 7B:
Reasoning: 1. In the first game, the cat accumulated 5 yarn balls. 2. In the second game, she got 5^2 + 8 = <<5^2+8=29>>29 yarn balls. 3. She lost some balls in her third game, but we don't know how many. Let's denote the number of balls she lost as L. 4. The number of balls she has now is 45 - 29 + L, but we want it to be 25 times the difference between 45 and the number of balls she accumulated in the second game. So, we have the equation: 45 - 29 + L = 25 * (45 - 29 - 29). 5. Solving for L, we get L = 25 * 29 - 16 = <<25*29-16=708>>708. 6. Since the cat lost 708 yarn balls in her third game, she doesn't have any yarn balls now. ### Answer: The cat has 0 yarn balls now.
Expected answer: 300
Correct? No
Problem: A basket contains 41 balls. The balls are split into two types - tennis balls and cricket balls. If we remove 16 balls from the basket, we get cricket balls. When 9 ping pong balls and 21 basketballs are added to the basket, what is the total number of balls in the basket?
Mistral 7B:
Reasoning: Initially, there are 41 balls in the basket. 16 balls are removed, leaving 41-16 = <<41-16=25>>25 balls. 9 ping pong balls and 21 basketballs are added, making the total number of balls 25+9+21 = <<25+9+21=55>>55. ### Answer: 55
Expected answer: 55
Correct? Yes
Problem: Continuing from the first problem, reconsider the situation but this time, instead of adding 21 basketballs to the basket, you only add 2 basketballs after the 9 ping pong balls. How many balls are now in the basket?
Mistral 7B:
Reasoning: Initially, there are 41 balls in the basket. 16 balls are removed, leaving 41-16 = <<41-16=25>>25 balls. 9 ping pong balls are added, making the total number of balls 25+9 = <<25+9=34>>34. Then, 2 basketballs are added, making the total number of balls 34+2 = <<34+2=36>>36. ### Answer: 36
Expected answer: 36
Correct? Yes
Problem: The design of a classic wall clock dictates that there should be 1 number represented for every 12 around the clock face. However, your quirky modernist clockmaker friend wants to do things differently. They want to represent 37 hours on the clock's face, each hour has an equivalent of 1 square. Your friend has already completed 32 squares. They left their project for a while, and when they came back, they forgot how many squares they needed to fulfill their quirk. So they did some math to figure it out: they subtracted 32 from 37, added 42 to the result, and then subtracted 37 from that total. Suddenly, an idea occurred to them. What if they add 25 more squares for representing minutes on their quirky clock? Plus, they also wanted to add another 28 squares for seconds. Since your friend is a bit forgetful, they forgot how many squares they need again to finish their project. So, they did a little more math - added 41 to 25, followed by another 28, and then added 17 to the result. Because your friend didn't have enough material, they decided that they could reduce the total number of squares by 23. Finally, they added the number they figured out at the beginning (for hours) to this reduced number. Can you help your friend figure out how many squares they would need in total to complete their quirky clock?
Mistral 7B:
Reasoning: 1. First, let's find out how many squares your friend already has: 32 squares for hours. 2. Next, let's add the squares for minutes: 25 squares. 3. Then, add the squares for seconds: 28 squares. 4. Your friend decided to reduce the total number of squares by 23, so subtract 23 from the sum of squares for minutes and seconds: 25 + 28 - 23 = 34 squares. 5. Finally, add the number of squares for hours: 32 + 34 = <<32+34=66>>66 squares in total. ### Answer: 66
Expected answer: 98
Correct? No
Problem: An orange farm produced 2 times the 28 pounds of oranges they typically produce in a single day due to a new method. This production also multiplied by the 15 days of the harvest period. If the farm then added 16 pounds of a rare orange variant to this harvest, how much did the farm produce in total?
Mistral 7B:
Reasoning: The farm produced 2*28*15 = <<2*28*15=1680>>1680 pounds of oranges using the new method for 15 days. The farm added 16 pounds of rare oranges to this total. ### Answer: 1696 pounds (1680 + 16)
Expected answer: 856
Correct? No
Problem: A bus has 37 passengers. At the next stop, 20 more passengers get on. Before the bus reaches to the next stop, 44 passengers get off. Now, suppose this remaining number of passengers each pays an $11 fare, but the bus company also deducts a $14 service fee from the total fare. How much revenue does the bus company get?
Mistral 7B:
Reasoning: Initially, there are 37 passengers on the bus. After the next stop, there are 37+20-44 = <<37+20-44=13>>13 passengers on the bus. Each of these 13 passengers pays an $11 fare, so the total fare is 13*11 = <<13*11=143>>143. However, the bus company also deducts a $14 service fee, so the revenue is 143-14 = <<143-14=129>>129. ### Answer: 129
Expected answer: 129
Correct? Yes
Problem: Following the previously described bus ride, where, after passengers got on and off, the company collected fare from each remaining passenger and deducted a $14 service fee, the company then had to pay a $23 parking fee for the bus at the end of the day. After all these expenses, how much revenue does the bus company have now?
Mistral 7B:
Reasoning: The revenue the bus company collected from the passengers was $129 (as calculated in the previous question). The bus company also had to pay a $23 parking fee. So, the total revenue the bus company has now is 129-23 = <<129-23=106>>106. ### Answer: 106
Expected answer: 106
Correct? Yes
Problem: Suppose we revisit the scenario of the bus ride. This time, imagine that instead of 37 passengers initially on the bus, there were only 28 passengers. Then, the bus picked up 20 more passengers at the next stop, but 44 passengers get off before the next stop. The remaining passengers each pay a bus fare of $11, but the company also deducts a $14 service fee from the total fares. How much revenue does the bus company get in this situation?
Mistral 7B:
Reasoning: Initially, there are 28 passengers on the bus. After the next stop, there are 28+20-44 = <<28+20-44=-4>>-4 passengers on the bus. Since there are no passengers left on the bus, the bus company does not receive any revenue. ### Answer: 0
Expected answer: 30
Correct? No
Problem: A pirate found a treasure chest with 13 emeralds, 42 rubies, and 19 sapphires. He gave away 43 of these precious gems to his crewmates. How many gems did the pirate have left?
Mistral 7B:
Reasoning: The pirate had 13+42+19 = <<13+42+19=74>>74 gems initially. He gave away 43 gems, so he has 74-43 = <<74-43=31>>31 gems left. ### Answer: 31
Expected answer: 31
Correct? Yes
Problem: A certain reserve has 16 ginger giraffes. They then bring in the same number of golden giraffes as they had of the ginger ones. Later, they decide to add another group of 46 greyish giraffes. What is the total number of giraffes in the reserve now?
Mistral 7B:
Reasoning: First, they bring in the same number of golden giraffes as they had of the ginger ones, which is 16. Then, they add another group of 46 greyish giraffes. So, the total number of giraffes in the reserve now is 16 (ginger) + 16 (golden) + 46 (greyish) = <<16+16+46=78>>78 giraffes. ### Answer: 78
Expected answer: 78
Correct? Yes
Problem: After successfully populating the reserve with various giraffes, unfortunately, 2 of the greyish giraffes suddenly moved out of the reserve. How many giraffes are there now in the reserve after the 2 greyish giraffes left?
Mistral 7B:
Reasoning: Initially, there were 78 giraffes in the reserve. After 2 greyish giraffes left, there are 78 - 2 = <<78-2=76>>76 giraffes left in the reserve. ### Answer: 76
Expected answer: 76
Correct? Yes
Problem: Let's reconsider the original scenario where the reserve started with ginger giraffes. But this time assume that the reserve initially had 42 ginger giraffes instead of 16. They again brought in the same number of golden giraffes as the ginger ones. Later, they decided to add another group of 46 greyish giraffes. What would be the total number of giraffes in the reserve now under this new scenario?
Mistral 7B:
Reasoning: First, they bring in the same number of golden giraffes as the ginger ones, which is 42. Then, they add another group of 46 greyish giraffes. So, the total number of giraffes in the reserve now is 42 (ginger) + 42 (golden) + 46 (greyish) = <<42+42+46=128>>128 giraffes. ### Answer: 128
Expected answer: 130
Correct? No
Problem: A turtle decides to swim. One day, it travels as many leagues as 11 plus 10, then multiplies that by 16 to get the total distance it swam that week. Later, it realized it had over calculated the distance by 41 leagues. What is the real distance it swam that week?
Mistral 7B:
Reasoning: Let's first find the overestimated distance: 1. The turtle swam 11+10 = <<11+10=21>>21 leagues on the first day. 2. It swam 21*16 = <<21*16=336>>336 leagues that week. 3. The overestimated distance is 336+41 = <<336+41=377>>377 leagues. 4. To find the real distance, we subtract the overestimated distance from the overestimated distance: 336 - 377 = <<336-377=-41>>-41 leagues. 5. Since the distance cannot be negative, we take the absolute value of the result: |-41| = <<|-41|=41>>41 leagues. ### Answer: 41 leagues.
Expected answer: 295
Correct? No