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Mixtral 8x22B on 4.OA.A.3

Common Core Standard 4.OA.A.3

This standard covers the following:

Solve multistep word problems posed with whole numbers and having whole-number answers using the four operations, including problems in which remainders must be Interpreted. Represent these problems using equations with a letter standing for the unknown quantity. Assess the reasonableness of answers using mental computation and estimation strategies including rounding.

πŸ”— Problem

Problem: A songwriter creates a long ballad with many verses. Each verse has 162 words and he divides these into 18 lines per verse. This gives a certain number of words per line. To each line, he adds 34 more words as a refrain. What is the total number of words present in each line now?

Mixtral 8x22B:

 Reasoning: The songwriter divides 162 words into 18 lines, so each line has 162/18 = <<162/18=9>>9 words.
He adds 34 more words to each line as a refrain, so each line now has 9+34 = <<9+34=43>>43 words.
### Answer: 43

Expected answer: 43

Correct? Yes

πŸ”— Follow-up

Problem: Following from the previous problem, the songwriter then decides to add an extra refrain to the end of each verse. If the refrain has 39 words, determine how many words are in each line after this final addition.

Mixtral 8x22B:

 Reasoning: The songwriter adds an extra refrain of 39 words to each verse.
Since there are 18 lines in each verse, the extra refrain adds 39/18 = <<39/18=2.1666666666666665>>2.17 words to each line (rounded to two decimal places).
So, each line now has 43+2.17 = <<43+2.17=45.17>>45.17 words (rounded to two decimal places).
### Answer: 45.17 (rounded to two decimal places)

Expected answer: 82

Correct? No

πŸ”— Follow-up

Problem: In the previous problem, the songwriter added 34 words as the refrain to each line in his song. However, what if he had decided to keep the refrain a bit shorter and added only 28 words to each line instead? How many words would each line of the song contain in that case?

Mixtral 8x22B:

 Reasoning: The songwriter divides 162 words into 18 lines, so each line has 162/18 = <<162/18=9>>9 words.
He adds 28 more words to each line as a refrain, so each line now has 9+28 = <<9+28=37>>37 words.
### Answer: 37

Expected answer: 37

Correct? Yes

πŸ”— Problem

Problem: A penguin biologist counted 35 penguins on a small ice floe. In another part of the Antarctic, she counted a different group of penguins and found there were approximately 598 divided evenly among 26 ice floes. After returning to the first place, she found that the penguin population had increased by 49. Wishing to conduct another survey, she decided to take 33 more penguins into account. However, when she counted them again, she realized she had overestimated and had to subtract 10 from her calculations. Her final step was to add in the penguins she’d left at her base camp, which were 20 adults and 14 chicks. How many penguins did she count in total?

Mixtral 8x22B:

 Reasoning:

1. The biologist counted 35 penguins on the first ice floe.
2. In another part of the Antarctic, she found approximately 598 penguins divided evenly among 26 ice floes. So, each ice floe had 598/26 = <<598/26=23>>23 penguins.
3. The penguin population on the first ice floe increased by 49, so there were 35 + 49 = <<35+49=84>>84 penguins.
4. She decided to take 33 more penguins into account, but then realized she had overestimated and had to subtract 10 from her calculations. So, she added 33 - 10 = <<33-10=23>>23 penguins to her count.
5. Her final step was to add in the penguins she’d left at her base camp, which were 20 adults and 14 chicks. So, she added 20 + 14 = <<20+14=34>>34 penguins to her count.
6. In total, she counted 84 + 23 + 34 = <<84+23+34=141>>141 penguins.

### Answer: 141

Expected answer: 164

Correct? No

πŸ”— Problem

Problem: In a local park, a jungle gym has a total of 27 steps. If the top 19 steps are blue and rest along with another 19 steps are red, we get a certain number of colored steps. On another jungle gym, there are 34 green steps. What is the total number of colored steps on the two jungle gyms?

Mixtral 8x22B:

 Reasoning: The jungle gym has 27 steps in total, with the top 19 steps being blue. This means that the bottom 27-19 = <<27-19=8>>8 steps are red. Additionally, there are another 19 red steps, making a total of 8+19 = <<8+19=27>>27 red steps.
The total number of colored steps on the first jungle gym is 19 (blue) + 27 (red) = <<19+27=46>>46 steps.
The second jungle gym has 34 green steps.
The total number of colored steps on the two jungle gyms is 46 (first jungle gym) + 34 (second jungle gym) = <<46+34=80>>80 steps.
### Answer: 80

Expected answer: 61

Correct? No

πŸ”— Problem

Problem: If a cloud releases 47 millimeters of rainfall per hour over a one hour period, and the average cloud typically releases 775 millimeters of rainfall over the course of 31 hours, find the amount of rainfall from the following condition. Subtract 22 from the average rainfall of the typical cloud per hour then multiply this by 23. Add this result to a constant cloud factor of 42. Add this new result to the hourly rainfall of the initial cloud and subtract 2 from it. What is the resultant millimeters of rainfall?

Mixtral 8x22B:

 Reasoning:

First, find the average rainfall per hour of a typical cloud:
775 millimeters / 31 hours = <<775/31=25.00>>25 millimeters per hour

Next, subtract 22 from the average rainfall per hour of a typical cloud:
25 - 22 = <<25-22=3>>3 millimeters per hour

Then, multiply this result by 23:
3 * 23 = <<3\*23=69>>69 millimeters

Add this result to the constant cloud factor of 42:
69 + 42 = <<69+42=111>>111 millimeters

Add this new result to the hourly rainfall of the initial cloud:
47 + 111 = <<47+111=158>>158 millimeters

Finally, subtract 2 from this result:
158 - 2 = <<158-2=156>>156 millimeters

### Answer: 156 millimeters

Expected answer: 156

Correct? Yes

πŸ”— Follow-up

Problem: Now consider a different scenario where the initial cloud releases less rainfall, specifically 15 millimeters per hour over a one hour period. Keeping the other conditions from the previous problem the same (the average cloud releases 775 millimeters of rainfall over the course of 31 hours, subtract 22 from the average rainfall of the typical cloud per hour then multiply this by 23, add this result to a constant cloud factor of 42, and subtract 2 from the last result), how much rainfall would be produced in this scenario?

Mixtral 8x22B:

 Reasoning:

First, find the average rainfall per hour of a typical cloud:
775 millimeters / 31 hours = <<775/31=25.00>>25 millimeters per hour

Next, subtract 22 from the average rainfall per hour of a typical cloud:
25 - 22 = <<25-22=3>>3 millimeters per hour

Then, multiply this result by 23:
3 * 23 = <<3\*23=69>>69 millimeters

Add this result to the constant cloud factor of 42:
69 + 42 = <<69+42=111>>111 millimeters

Add this new result to the hourly rainfall of the initial cloud:
15 + 111 = <<15+111=126>>126 millimeters

Finally, subtract 2 from this result:
126 - 2 = <<126-2=124>>124 millimeters

### Answer: 124 millimeters

Expected answer: 124

Correct? Yes

πŸ”— Problem

Problem: Nadia likes to practice playing the piano. The other day she practiced for 45 minutes in the morning. In the same day, she also practiced for another 35 minutes in the afternoon and then another 35 minutes in the evening. How long did Nadia practice the piano in total that day?

Mixtral 8x22B:

 Reasoning: Nadia practiced for 45 + 35 + 35 = <<45+35+35=115>>115 minutes in total that day.
### Answer: 115 minutes

Expected answer: 115

Correct? Yes

πŸ”— Follow-up

Problem: Reflecting upon her previous practice sessions, Nadia thought she could do more. She decided to adjust her morning practice time from 45 minutes to 26 minutes. Still maintaining her afternoon and evening sessions at 35 minutes each, how many minutes in total would Nadia be practicing for the day with this adjustment?

Mixtral 8x22B:

 Reasoning: Nadia would now practice for 26 + 35 + 35 = <<26+35+35=96>>96 minutes in total that day.
### Answer: 96 minutes

Expected answer: 96

Correct? Yes

πŸ”— Problem

Problem: A popular clothing store sells dresses for $44 each. During a flash sale, they further reduce prices by a factor of 465 divided by 31. How much does a dress cost during the flash sale?

Mixtral 8x22B:

 Reasoning: The flash sale reduces the price of a dress by a factor of 465/31.
The reduced price of a dress is $44 \* (31/465) = <<44\*(31/465)=$3.03>>$3.03.
### Answer: $3.03

Expected answer: 660

Correct? No

πŸ”— Problem

Problem: A rope maker made 46 meters of rope on Monday. On Tuesday, he made as many meters of rope as he did on Monday, plus an additional 19 meters. However, by Wednesday, 9 meters of this rope had been damaged and was unusable. How many meters of usable rope does he have after Wednesday?

Mixtral 8x22B:

 Reasoning: The rope maker made 46 + 19 = <<46+19=65>>65 meters of rope on Tuesday.
He has a total of 46 + 65 = <<46+65=111>>111 meters of rope after Tuesday.
After 9 meters of rope were damaged, he has 111 - 9 = <<111-9=102>>102 meters of usable rope.
### Answer: 102

Expected answer: 56

Correct? No

πŸ”— Problem

Problem: Juliana bought 16 pairs of vintage earrings for a gift. Each pair costs $2. She also chose a special jewelry box that costs $25. In addition, she paid $48 for the gift wrapping service. How much did she spend in total for her gift?

Mixtral 8x22B:

 Reasoning: Juliana spent 16 \* $2 = <<16\*2=32>>$32 on the earrings.
She also spent $25 on the jewelry box and $48 on the gift wrapping service.
In total, she spent $32 + $25 + $48 = <<32+25+48=105>>$105 on her gift.
### Answer: $105

Expected answer: 105

Correct? Yes

πŸ”— Problem

Problem: If Emma takes 60 beads and divides them equally among 3 of her friends, each friend will get a certain number of beads. She then adds 4 more beads to each friend's pile to start making necklaces. How many beads does each friend have now?

Mixtral 8x22B:

 Reasoning: Emma divides 60 beads equally among 3 friends, so each friend gets 60/3 = <<60/3=20>>20 beads.
Emma adds 4 more beads to each friend's pile, so each friend now has 20+4 = <<20+4=24>>24 beads.
### Answer: 24

Expected answer: 24

Correct? Yes

πŸ”— Follow-up

Problem: After distributing the beads among her friends, Emma realizes that she actually wanted to divide her 60 beads evenly among 28 friends instead of 3. She recalculates and then adds 4 more beads to each friend's stack after the initial division. How many beads does each friend have now?

Mixtral 8x22B:

 Reasoning: Emma divides 60 beads equally among 28 friends, so each friend gets 60/28 = <<60/28=2.142857142857143>>2.142857142857143 beads.
Since Emma can't give a fraction of a bead, she rounds down to the nearest whole number, so each friend gets 2 beads.
Emma adds 4 more beads to each friend's pile, so each friend now has 2+4 = <<2+4=6>>6 beads.
### Answer: 6

Expected answer: 43/7

Correct? No

πŸ”— Problem

Problem: A young boy with a creative mind decided to build a kite. He started with 37 paper straws but decided that 4 were unnecessary and removed them. Later, he realized his kite was still too bulky and removed another 23 straws. He multiplied the remaining number of straws by 45, subtracted 49 from that total, and then took out 7 more straws. How many straws did the boy have left?

Mixtral 8x22B:

 Reasoning: The boy started with 37 straws and removed 4, leaving him with 37-4 = <<37-4=33>>33 straws.
He then removed another 23 straws, leaving him with 33-23 = <<33-23=10>>10 straws.
He multiplied the remaining number of straws by 45, resulting in 10*45 = <<10\*45=450>>450 straws.
He then subtracted 49 from that total, leaving him with 450-49 = <<450-49=401>>401 straws.
Finally, he took out 7 more straws, leaving him with 401-7 = <<401-7=394>>394 straws.
### Answer: 394

Expected answer: 394

Correct? Yes

πŸ”— Follow-up

Problem: After reflecting on his kite design, the young boy realized he made a mistake. When he multiplied the number of remaining paper straws by 45, he should have subtracted 25, not 49. If he corrects this calculation error and takes out 7 final straws as before, how many straws does he have now for his kite?

Mixtral 8x22B:

 Reasoning: The boy started with 37 straws and removed 4, leaving him with 37-4 = <<37-4=33>>33 straws.
He then removed another 23 straws, leaving him with 33-23 = <<33-23=10>>10 straws.
He multiplied the remaining number of straws by 45, resulting in 10*45 = <<10\*45=450>>450 straws.
He then subtracted 25 from that total, leaving him with 450-25 = <<450-25=425>>425 straws.
Finally, he took out 7 more straws, leaving him with 425-7 = <<425-7=418>>418 straws.
### Answer: 418

Expected answer: 418

Correct? Yes

πŸ”— Problem

Problem: At the zoo, there were 2 trips being hosted. Each trip was allowed to see 2 animals. However, each animal had 3 baby animals with them, making the number of animals seen per trip multiplied by 3. If each baby animal could be photographed 21 times, how many photos could be taken in total? Also, if 34 photos were spoiled and unusable out of the entire batch, but guests were given the opportunity to take an additional 30 photos later, how many usable photos would there be in total?

Mixtral 8x22B:

 Reasoning: Each trip saw 2 animals, and each animal had 3 baby animals, so each trip saw 2*3 = <<2*3=6>>6 baby animals.
Each baby animal could be photographed 21 times, so each trip could take 6*21 = <<6*21=126>>126 photos.
Since there were 2 trips, the total number of photos that could be taken was 2*126 = <<2*126=252>>252.
If 34 photos were spoiled and unusable, then there were 252-34 = <<252-34=218>>218 usable photos.
If guests were given the opportunity to take an additional 30 photos later, then there would be 218+30 = <<218+30=248>>248 usable photos in total.
### Answer: 248

Expected answer: 248

Correct? Yes

πŸ”— Follow-up

Problem: In the previous case at the zoo, imagine if each baby animal could only be photographed 16 times, instead of 21. Given the same spoiling rate of 34 photos and the additional opportunity to take 30 more photos later, how many usable photos would be available now?

Mixtral 8x22B:

 Reasoning: Each baby animal could be photographed 16 times, so each trip could take 6*16 = <<6*16=96>>96 photos.
Since there were 2 trips, the total number of photos that could be taken was 2*96 = <<2*96=192>>192.
If 34 photos were spoiled and unusable, then there were 192-34 = <<192-34=158>>158 usable photos.
If guests were given the opportunity to take an additional 30 photos later, then there would be 158+30 = <<158+30=188>>188 usable photos in total.
### Answer: 188

Expected answer: 188

Correct? Yes

πŸ”— Problem

Problem: In a literacy event, a group of learners were asked to write a word from letters. In the first round, they could form a word with 47 letters, but due to a mistake, they had to remove 30 letters. Then, they figured out they could still add 10 more letters to this word. In the next round, they removed 3 of these letters from the updated word. How many letters were there in the word after this last deletion?

Mixtral 8x22B:

 Reasoning: In the first round, the learners had a word with 47 letters. After removing 30 letters, they had 47-30 = <<47-30=17>>17 letters left. Then, they added 10 more letters, making the word have 17+10 = <<17+10=27>>27 letters. In the next round, they removed 3 letters, leaving them with 27-3 = <<27-3=24>>24 letters.
### Answer: 24

Expected answer: 24

Correct? Yes

πŸ”— Follow-up

Problem: In the continuation of the literacy event, the learners had the opportunity to add more letters to the word after the last deletion. They decided to add 39 more letters. How many letters were in the word after this final addition?

Mixtral 8x22B:

 Reasoning: After the last deletion, the word had 24 letters. The learners added 39 more letters, making the word have 24+39 = <<24+39=63>>63 letters.
### Answer: 63

Expected answer: 63

Correct? Yes

πŸ”— Follow-up

Problem: In revisiting the literacy event, let's consider a different scenario. When the learners formed the word with 47 letters and due to a mistake had to remove 30, instead of adding 10 letters, what if they added only 10 - 16 = -6 letters? What would the total number of letters be in the word after this change?

Mixtral 8x22B:

 Reasoning: In this scenario, the learners had a word with 47 letters. After removing 30 letters, they had 47-30 = <<47-30=17>>17 letters left. Instead of adding 10 letters, they added 10 - 16 = -6 letters. However, adding a negative number of letters is equivalent to removing that number of letters. So, they removed 6 letters from the 17 letters they had, leaving them with 17-6 = <<17-6=11>>11 letters.
### Answer: 11

Expected answer: 11

Correct? Yes

πŸ”— Problem

Problem: A turtle named Tommy moves at 74/37 miles per hour. If Tommy maintains his current speed for a while then slows down by 3 mph, then speeds up to his initial speed again, what would be his average speed?

Mixtral 8x22B:

 Reasoning: Tommy's initial speed is 74/37 = <<74/37=2>>2 mph.
If Tommy slows down by 3 mph, his new speed is 2 - 3 = <<2-3=-1>>-1 mph. However, since speed cannot be negative, we can assume that Tommy stops moving for a while instead of moving at a negative speed.
To find the average speed, we need to know the total distance traveled and the total time taken. Since we don't have this information, we cannot calculate the average speed.
### Answer: Cannot be determined without additional information.

Expected answer: 1

Correct? No

πŸ”— Problem

Problem: Liam has 40 sets of building blocks. Each set contains 16 blocks. How many building blocks does Liam have in total?

Mixtral 8x22B:

 Reasoning: Liam has 40 \* 16 = <<40\*16=640>>640 building blocks in total.
### Answer: 640

Expected answer: 640

Correct? Yes

πŸ”— Follow-up

Problem: After counting all the building blocks, Liam decides to give away 25 to his friend. How many building blocks does Liam have left after giving some to his friend?

Mixtral 8x22B:

 Reasoning: Liam has 640 - 25 = <<640-25=615>>615 building blocks left after giving some to his friend.
### Answer: 615

Expected answer: 615

Correct? Yes

πŸ”— Follow-up

Problem: What if Liam only had 38 sets of building blocks instead of 40? How many building blocks would he have in that case?

Mixtral 8x22B:

 Reasoning: If Liam had 38 sets of building blocks, he would have 38 \* 16 = <<38\*16=608>>608 building blocks in total.
### Answer: 608

Expected answer: 608

Correct? Yes

πŸ”— Problem

Problem: John has 24 pencils. Then he bought more such that the number of pencils he has now is equal to the number of what he had plus 7. How many pencils does John have now?

Mixtral 8x22B:

 Reasoning: Let x be the number of pencils John bought.
John has 24 + x pencils now.
According to the problem, the number of pencils he has now is equal to the number of what he had plus 7.
So, 24 + x = 24 + 7
Solving for x, we get x = 7.
John has 24 + 7 = <<24+7=31>>31 pencils now.
### Answer: 31

Expected answer: 31

Correct? Yes

πŸ”— Follow-up

Problem: After having a total of 31 pencils, John received a gift box with an additional 26 pencils. How many pencils does he have now?

Mixtral 8x22B:

 Reasoning: John had 31 pencils before receiving the gift box.
He received 26 more pencils.
So, John has 31 + 26 = <<31+26=57>>57 pencils now.
### Answer: 57

Expected answer: 57

Correct? Yes

πŸ”— Follow-up

Problem: Suppose originally, John only had 2 pencils instead of 24 and then he bought more such that the number of pencils he has now is equal to the number of pencils he had plus 7. How many pencils does John have now?

Mixtral 8x22B:

 Reasoning: Let x be the number of pencils John bought.
John has 2 + x pencils now.
According to the problem, the number of pencils he has now is equal to the number of pencils he had plus 7.
So, 2 + x = 2 + 7
Solving for x, we get x = 7.
John has 2 + 7 = <<2+7=9>>9 pencils now.
### Answer: 9

Expected answer: 9

Correct? Yes

πŸ”— Problem

Problem: The snowfall in City A, which lasts for 50 days, is currently 36 days in. In City B, there is a unique snow pattern where for every 14 days, it snows 98 inches. The total snowfall in inches in City A is expected to be the product of the remaining snowfall days in City A and the average daily snowfall in inches in City B. However, the snow removal has been keeping up and has managed to remove an amount of snow equal to the average daily snowfall in City B. How much snow in inches is left in City A after the snow removal?

Mixtral 8x22B:

 Reasoning: The remaining snowfall days in City A is 50-36 = <<50-36=14>>14 days.
The average daily snowfall in inches in City B is 98/14 = <<98/14=7>>7 inches per day.
The total snowfall in inches in City A is expected to be 14 \* 7 = <<14\*7=98>>98 inches.
The snow removal has managed to remove 7 inches of snow.
The amount of snow left in City A after the snow removal is 98 - 7 = <<98-7=91>>91 inches.
### Answer: 91 inches

Expected answer: 91

Correct? Yes

πŸ”— Problem

Problem: A pirate finds 28 rubies on the first day of his treasure hunt. On the second day, he finds another haul of rubies equal to the first day's find plus an additional 21 rubies. How many rubies does the pirate have in total after the second day?

Mixtral 8x22B:

 Reasoning: The pirate finds 28 + 21 = <<28+21=49>>49 rubies on the second day.
The pirate has 28 + 49 = <<28+49=77>>77 rubies in total after the second day.
### Answer: 77

Expected answer: 77

Correct? Yes

πŸ”— Follow-up

Problem: After the second day, the pirate continues his adventure and stumbles upon a third treasure chest containing 29 additional rubies. Unfortunately, he drops and loses 36 rubies while escaping a group of rival pirates. How many rubies does he have in total now?

Mixtral 8x22B:

 Reasoning: The pirate finds 29 additional rubies, so he has 77 + 29 = <<77+29=106>>106 rubies.
The pirate loses 36 rubies, so he has 106 - 36 = <<106-36=70>>70 rubies in total now.
### Answer: 70

Expected answer: 70

Correct? Yes

πŸ”— Follow-up

Problem: After reflecting on his loss, the pirate remembers that, on the first day, he actually only found 6 rubies, not 28. On the second day, he still found a number of rubies equal to what he found on the first day plus an additional 21 rubies. How many rubies did the pirate have in total after the second day, taking this into account?

Mixtral 8x22B:

 Reasoning: The pirate finds 6 + 21 = <<6+21=27>>27 rubies on the second day.
The pirate has 6 + 27 = <<6+27=33>>33 rubies in total after the second day, taking this into account.
### Answer: 33

Expected answer: 33

Correct? Yes

πŸ”— Problem

Problem: There were 47 inches of snowfall in January and an additional 7 inches in early February. On February 15th, there was an additional 17 inches of snowfall. Then, 48 inches of snow fell in March. In April, we had an additional 31 inches of snowfall early on, but then 27 inches melted by the end of the month. How many inches of snow does this sum up to at the end of April?

Mixtral 8x22B:

 Reasoning: In January, there were 47 inches of snowfall.
In February, there were 7 inches of snowfall in early February and 17 inches on February 15th, making a total of 7+17 = <<7+17=24>>24 inches for February.
In March, there were 48 inches of snowfall.
In April, there were 31 inches of snowfall early on, but 27 inches melted, making a total of 31-27 = <<31-27=4>>4 inches for April.
The total amount of snowfall from January to April is 47+24+48+4 = <<47+24+48+4=123>>123 inches.
### Answer: 123

Expected answer: 123

Correct? Yes

πŸ”— Follow-up

Problem: Following the same snowfall pattern, but this time if April were to receive a slightly higher snowfall, with an additional 44 inches of snowfall early on, but then 27 inches melted by the end of the month, how many inches of snow would this sum up to at the end of April now?

Mixtral 8x22B:

 Reasoning: In January, there were 47 inches of snowfall.
In February, there were 7 inches of snowfall in early February and 17 inches on February 15th, making a total of 7+17 = <<7+17=24>>24 inches for February.
In March, there were 48 inches of snowfall.
In April, there were 44 inches of snowfall early on, but 27 inches melted, making a total of 44-27 = <<44-27=17>>17 inches for April.
The total amount of snowfall from January to April is 47+24+48+17 = <<47+24+48+17=136>>136 inches.
### Answer: 136

Expected answer: 136

Correct? Yes

πŸ”— Problem

Problem: At a fair, a vendor sold balloons. On a particularly busy day, he sold 46 balloons every hour for 11 hours straight. After the fair had closed, he ended up selling an additional 31 balloons to some stragglers. How many balloons did he sell in total that day?

Mixtral 8x22B:

 Reasoning: The vendor sold 46 balloons/hour * 11 hours = <<46*11=506>>506 balloons during the fair.
He sold an additional 31 balloons after the fair had closed.
So, he sold 506 + 31 = <<506+31=537>>537 balloons in total that day.
### Answer: 537

Expected answer: 537

Correct? Yes

πŸ”— Problem

Problem: Mary and John decided to play a game of cards. In the first game, Mary scored 31 points and John scored 39 points. In the second game, their combined score was increased by 35 more points. During a special round, they could multiply their score by the difference between 27 and the number of cards left in the deck, which was 23. What was their final score in the special round?

Mixtral 8x22B:

 Reasoning: In the first game, Mary and John scored a combined total of 31 + 39 = <<31+39=70>>70 points.
In the second game, their combined score was increased by 35 more points, so they scored 70 + 35 = <<70+35=105>>105 points.
During the special round, they could multiply their score by the difference between 27 and the number of cards left in the deck, which was 23. So, their final score in the special round was 105 \* (27 - 23) = <<105*(27-23)=525>>525 points.
### Answer: 525

Expected answer: 420

Correct? No

πŸ”— Problem

Problem: A furniture company manufactured 17 upholstered seats and 18 wooden seats in the morning, and then produced another 29 in the afternoon. They repeated this production in the evening. Later on, they gave away 48 chairs to charity and used 7 chairs for quality testing. How many chairs are left after these operations?

Mixtral 8x22B:

 Reasoning: In the morning, the company produced 17 upholstered seats + 18 wooden seats = <<17+18=35>>35 chairs.
In the afternoon, they produced another 29 chairs.
So, in the morning and afternoon, they produced 35 + 29 = <<35+29=64>>64 chairs.
Since they repeated this production in the evening, they produced 64 \* 2 = <<64\*2=128>>128 chairs in total.
After giving away 48 chairs to charity and using 7 chairs for quality testing, they have 128 - 48 - 7 = <<128-48-7=73>>73 chairs left.
### Answer: 73

Expected answer: 73

Correct? Yes

πŸ”— Follow-up

Problem: Continuing from the last example, suppose the furniture company only crafted 15 wooden seats in the morning instead of 18 but kept the rest of operations unchanged. After repeating the same production, donating 48 chairs to charity, and using 7 for quality testing, how many chairs will be the company left with?

Mixtral 8x22B:

 Reasoning: In the morning, the company produced 17 upholstered seats + 15 wooden seats = <<17+15=32>>32 chairs.
In the afternoon, they produced another 29 chairs.
So, in the morning and afternoon, they produced 32 + 29 = <<32+29=61>>61 chairs.
Since they repeated this production in the evening, they produced 61 \* 2 = <<61\*2=122>>122 chairs in total.
After giving away 48 chairs to charity and using 7 chairs for quality testing, they have 122 - 48 - 7 = <<122-48-7=67>>67 chairs left.
### Answer: 67

Expected answer: 67

Correct? Yes

πŸ”— Problem

Problem: On a popular jungle gym, there are 46 monkey bars and 18 swinging ropes for the kids to play on. Nearby, a larger jungle gym was recently built to accommodate more kids. The new jungle gym contains 2 extra long zip lines and 20 regular zip lines, each requiring 31 special hooks to install. How many more hooks were used in the new jungle gym compared to the number of play components on the popular jungle gym?

Mixtral 8x22B:

 Reasoning: The new jungle gym has 2 extra long zip lines and 20 regular zip lines, which require 31 special hooks each.
The total number of hooks used in the new jungle gym is 2*31 + 20*31 = <<2*31+20*31=952>>952 hooks.
The popular jungle gym has 46 monkey bars and 18 swinging ropes, which is a total of 46+18 = <<46+18=64>>64 play components.
The difference in the number of hooks used in the new jungle gym compared to the number of play components on the popular jungle gym is 952 - 64 = <<952-64=888>>888 hooks.
### Answer: 888

Expected answer: 618

Correct? No

πŸ”— Problem

Problem: John has saved $168 and he decides to divide it evenly between 21 days. After doing so, he then gets an additional $47 from his job. He then receives another amount of money which is the sum of $12 and $45. How much money does John have now?

Mixtral 8x22B:

 Reasoning: John divides $168 by 21 days, which is $168/21 = <<168/21=8>>8 per day.
John then gets an additional $47 from his job, so he has $8\*21 + $47 = <<8\*21=168>>168 + $47 = <<168+47=215>>215.
John then receives another amount of money which is the sum of $12 and $45, which is $12 + $45 = <<12+45=57>>57.
John now has $215 + $57 = <<215+57=272>>272.
### Answer: 272

Expected answer: 112

Correct? No

πŸ”— Problem

Problem: A robot can stack 32 boxes in 1 minute. If it works non-stop for 4 minutes and then picks up 1 extra box, how many boxes will this robot have stacked in total?

Mixtral 8x22B:

 Reasoning: The robot stacks 32 boxes per minute, so in 4 minutes it will stack 32 \* 4 = <<32\*4=128>>128 boxes.
After stacking 128 boxes, the robot picks up 1 extra box, so the total number of boxes stacked is 128 + 1 = <<128+1=129>>129 boxes.
### Answer: 129

Expected answer: 129

Correct? Yes

πŸ”— Follow-up

Problem: After stacking boxes for 4 minutes, the robot takes a break. When it comes back, it accidentally knocks over 21 of the boxes. How many boxes remain stacked after the robot knocks some over?

Mixtral 8x22B:

 Reasoning: The robot stacked 128 boxes before taking a break. After knocking over 21 boxes, the number of boxes remaining is 128 - 21 = <<128-21=107>>107 boxes.
### Answer: 107

Expected answer: 108

Correct? No

πŸ”— Follow-up

Problem: Let's consider a different scenario: If, instead of picking up an extra single box after 4 minutes, the robot picked up an extra 11 boxes, how many boxes would this robot have stacked in total?

Mixtral 8x22B:

 Reasoning: The robot stacks 32 boxes per minute, so in 4 minutes it will stack 32 \* 4 = <<32\*4=128>>128 boxes.
After stacking 128 boxes, the robot picks up 11 extra boxes, so the total number of boxes stacked is 128 + 11 = <<128+11=139>>139 boxes.
### Answer: 139

Expected answer: 139

Correct? Yes

πŸ”— Problem

Problem: A female tiger gave birth to 26 cubs in all her lifetime. Unfortunately, 17 of them did not survive the harsh conditions of the wild. However, after growing up, 6 of the surviving tigers moved to other territories. How many tigers remained in the female tiger's territory?

Mixtral 8x22B:

 Reasoning: The female tiger had 26-17 = <<26-17=9>>9 surviving cubs.
After 6 of them moved to other territories, there were 9-6 = <<9-6=3>>3 tigers remaining in the female tiger's territory.
### Answer: 3

Expected answer: 3

Correct? Yes

πŸ”— Follow-up

Problem: Suppose that originally the female tiger had given birth to 24 cubs instead of 26 in her lifetime, and the same number of 17 cubs had not survived the harsh conditions of the wild. If the same number of surviving tigers, 6, moved to other territories, how many tigers would have remained in the female tiger's territory?

Mixtral 8x22B:

 Reasoning: The female tiger would have had 24-17 = <<24-17=7>>7 surviving cubs.
After 6 of them moved to other territories, there would have been 7-6 = <<7-6=1>>1 tiger remaining in the female tiger's territory.
### Answer: 1

Expected answer: 1

Correct? Yes

πŸ”— Problem

Problem: A colony of penguins originally started with 44 members. After a while, 39 new penguins join the colony. Later, from that group, 16 penguins leave to start a new colony elsewhere. To supplant the loss, another group of 35 penguins join the colony. How many penguins are in the colony now?

Mixtral 8x22B:

 Reasoning: The colony originally had 44 members. After 39 new penguins joined, the colony had 44+39 = <<44+39=83>>83 members.
After 16 penguins left, the colony had 83-16 = <<83-16=67>>67 members.
After another group of 35 penguins joined, the colony had 67+35 = <<67+35=102>>102 members.
### Answer: 102

Expected answer: 102

Correct? Yes

πŸ”— Follow-up

Problem: In the same penguin colony, they started off with 44 members. After a while, 39 new penguins join the colony. Later, from that group, 16 penguins leave to start a new colony elsewhere. This time, to supplant the loss, another group of 12 penguins join the colony, instead of 35. How many penguins are in the colony now?

Mixtral 8x22B:

 Reasoning: The colony originally had 44 members. After 39 new penguins joined, the colony had 44+39 = <<44+39=83>>83 members.
After 16 penguins left, the colony had 83-16 = <<83-16=67>>67 members.
After another group of 12 penguins joined, the colony had 67+12 = <<67+12=79>>79 members.
### Answer: 79

Expected answer: 79

Correct? Yes

πŸ”— Problem

Problem: A helicopter travels 10 miles in one minute. If the helicopter increases its speed by 40 miles, plus another 20 miles, how far will the helicopter travel in 12 minutes at this increased speed?

Mixtral 8x22B:

 Reasoning: The helicopter's original speed is 10 miles per minute.
The helicopter increases its speed by 40 miles, so its new speed is 10+40 = <<10+40=50>>50 miles per minute.
The helicopter increases its speed by another 20 miles, so its final speed is 50+20 = <<50+20=70>>70 miles per minute.
The helicopter travels for 12 minutes at this final speed, so it will travel 12*70 = <<12\*70=840>>840 miles.
### Answer: 840

Expected answer: 840

Correct? Yes

πŸ”— Follow-up

Problem: After re-evaluating its performance, the helicopter realized that its actual speed increase was lesser than initially thought. Instead of the initial 40 miles speed increase, the increase was just 2 miles. Given that the original speed of 10 miles and an additional bonus speed of 20 miles remained the same, how far will the helicopter be able to travel in 12 minutes at this revised speed?

Mixtral 8x22B:

 Reasoning: The helicopter's original speed is 10 miles per minute.
The helicopter increases its speed by 2 miles, so its new speed is 10+2 = <<10+2=12>>12 miles per minute.
The helicopter also has an additional bonus speed of 20 miles, so its final speed is 12+20 = <<12+20=32>>32 miles per minute.
The helicopter travels for 12 minutes at this final speed, so it will travel 12*32 = <<12\*32=384>>384 miles.
### Answer: 384

Expected answer: 384

Correct? Yes

πŸ”— Problem

Problem: A new telescope has a magnification power of 26. To further explore the universe, another telescope is required that needs to be exactly 41 in magnification strength. How much more magnification is required for the new telescope compared to the existing one?

Mixtral 8x22B:

 Reasoning: The new telescope needs to have a magnification strength of 41. The existing telescope has a magnification power of 26.
The difference in magnification strength is 41-26 = <<41-26=15>>15.
### Answer: 15

Expected answer: 15

Correct? Yes

πŸ”— Follow-up

Problem: The Space Institute realized that the initial magnification power of the existing telescope was actually 16, not 26 as previously thought. If they still want to reach a magnification strength of 41, how much more magnification is now needed compared to the existing telescope?

Mixtral 8x22B:

 Reasoning: The new telescope needs to have a magnification strength of 41. The existing telescope has a magnification power of 16.
The difference in magnification strength is 41-16 = <<41-16=25>>25.
### Answer: 25

Expected answer: 25

Correct? Yes

πŸ”— Problem

Problem: Sophie's parents give her $18 for every hour she works at the family business. On Monday, she worked 2 of those hours. Then she bought a $4 ice cream and another $4 coffee afterwards. She then added Monday's leftover amount to her pay for her next single hour of work. After that, she got an additional $45 as a bonus from her grandmother. How much money does Sophie have in total now?

Mixtral 8x22B:

 Reasoning: Sophie earned 2 \* $18 = <<2\*18=36>>$36 on Monday.
She spent $4 + $4 = <<4+4=8>>$8 on ice cream and coffee.
She had $36 - $8 = <<36-8=28>>$28 left over from Monday.
She earned another $18 for her next hour of work, so she had $28 + $18 = <<28+18=46>>$46.
She received a $45 bonus, so she had $46 + $45 = <<46+45=91>>$91 in total.
### Answer: $91

Expected answer: 91

Correct? Yes

πŸ”— Follow-up

Problem: In the same scenario, imagine if Sophie's parents now give her $5 for every hour she works at the family business instead of $18. She still works for two hours on Monday, spends the same amount on ice cream and coffee, works an additional hour, and receives the same $45 bonus from her grandmother. How much money does Sophie have in total now?

Mixtral 8x22B:

 Reasoning: Sophie earned 2 \* $5 = <<2\*5=10>>$10 on Monday.
She spent $4 + $4 = <<4+4=8>>$8 on ice cream and coffee.
She had $10 - $8 = <<10-8=2>>$2 left over from Monday.
She earned another $5 for her next hour of work, so she had $2 + $5 = <<2+5=7>>$7.
She received a $45 bonus, so she had $7 + $45 = <<7+45=52>>$52 in total.
### Answer: $52

Expected answer: 52

Correct? Yes

πŸ”— Problem

Problem: A towel company initially produced 30 beach towels and 6 hand towels. They then gave away 7 towels for charity, which leaves a certain amount of towels. They then decided to produce 14 more towels to add to their current stock. On the other hand, they made a special batch of 13 towels for every towel left after their charity activity and deducted 19 towels from this special batch, calling it their premium collection. They then noted 20 towels were damaged and removed it from this premium collection. After this, they deducted 3 more towels from the remaining premium collection and combined it with the total they had after their second batch of production. How many towels does the company have now?

Mixtral 8x22B:

 Reasoning:

1. The company initially produced 30 beach towels and 6 hand towels, which is a total of 30 + 6 = <<30+6=36>>36 towels.
2. They gave away 7 towels for charity, leaving them with 36 - 7 = <<36-7=29>>29 towels.
3. They then produced 14 more towels, adding to their current stock, making it 29 + 14 = <<29+14=43>>43 towels.
4. They made a special batch of 13 towels for every towel left after their charity activity, which is 13 * 29 = <<13*29=377>>377 towels.
5. They deducted 19 towels from this special batch, making it 377 - 19 = <<377-19=358>>358 towels.
6. They then noted 20 towels were damaged and removed it from this premium collection, making it 358 - 20 = <<358-20=338>>338 towels.
7. They deducted 3 more towels from the remaining premium collection, making it 338 - 3 = <<338-3=335>>335 towels.
8. They combined this with the total they had after their second batch of production, making it 43 + 335 = <<43+335=378>>378 towels.

### Answer: 378

Expected answer: 378

Correct? Yes

πŸ”— Problem

Problem: An extraterrestrial being from the planet Zorkon communicates that they have 50 special energy crystals. Then they explain that they'll get 20 more energy crystals in a few earth days. Additionally, their zorbcraft has a hidden compartment that contains 50 energy crystals and 6 extra lumino-gems, and they plan to add the upcoming energy crystals to this compartment as well. How many items (including both energy crystals and lumino-gems) would be in the zorbcraft's compartment at that time?

Mixtral 8x22B:

 Reasoning: The extraterrestrial being currently has 50 energy crystals and will get 20 more, making a total of 50+20 = <<50+20=70>>70 energy crystals.
The hidden compartment already contains 50 energy crystals and 6 lumino-gems, making a total of 50+6 = <<50+6=56>>56 items.
After adding the upcoming energy crystals, the compartment will contain 56+20 = <<56+20=76>>76 items.
### Answer: 76

Expected answer: 126

Correct? No

πŸ”— Problem

Problem: A park contains 43 Velociraptors. Then, the park added another set of dinosaurs which numbered 972, but as it so happens, each of these sections contained 27 dinosaurs. This meant the actual number of new dinosaur types added was less. After calculating the new dinosaur types, they found out that the number of Velociraptors was more. They found the difference and multiplied this difference by 7, as each of the Velociraptors laid 7 new eggs that week. How many total eggs were laid by the Velociraptors that week?

Mixtral 8x22B:

 Reasoning: The park added 972/27 = <<972/27=36>>36 new dinosaur types.
The difference between the number of Velociraptors and the new dinosaur types is 43-36 = <<43-36=7>>7.
The Velociraptors laid 7\*7 = <<7\*7=49>>49 eggs that week.
### Answer: 49

Expected answer: 49

Correct? Yes

πŸ”— Follow-up

Problem: Following up from the previous scenario, the park's wardens discovered that 46 of the eggs laid by the Velociraptors were not fertilized and not going to hatch. What is the number of Velociraptor eggs that are expected to successfully hatch?

Mixtral 8x22B:

 Reasoning: The number of Velociraptor eggs that are expected to successfully hatch is 49-46 = <<49-46=3>>3.
### Answer: 3

Expected answer: 3

Correct? Yes

πŸ”— Follow-up

Problem: Continuing off the previous scenario, the wardens realized that they had made a mistake in their calculations. Each box actually contained 46 dinosaurs, not 27. If this was the case, how many total eggs are expected to be laid by the Velociraptors this week?

Mixtral 8x22B:

 Reasoning: The park added 972/46 = <<972/46=21>>21 new dinosaur types.
The difference between the number of Velociraptors and the new dinosaur types is 43-21 = <<43-21=22>>22.
The Velociraptors laid 22\*7 = <<22\*7=154>>154 eggs that week.
### Answer: 154

Expected answer: 3521/23

Correct? No

πŸ”— Problem

Problem: There is a bowl containing 46 oranges. After Maria took 16 oranges from that bowl, how many oranges are left?

Mixtral 8x22B:

 Reasoning: Maria took 16 oranges from the bowl, so there are 46-16 = <<46-16=30>>30 oranges left in the bowl.
### Answer: 30

Expected answer: 30

Correct? Yes

πŸ”— Follow-up

Problem: Initially, Maria believed the bowl contained 46 oranges, but soon she realized her mistake and found out there were actually 49 in total. With this new information, after taking out 16 oranges, how many are left now in the bowl?

Mixtral 8x22B:

 Reasoning: Maria took 16 oranges from the bowl, which now contains 49-16 = <<49-16=33>>33 oranges.
### Answer: 33

Expected answer: 33

Correct? Yes

πŸ”— Problem

Problem: A toothbrush factory produces 37 toothbrushes per minute at the start of its morning shift. A little later, it increases its production to rate to 308 toothbrushes every 7 minutes. If this increased rate of production continued for 16 minutes, how many toothbrushes were produced in total?

Mixtral 8x22B:

 Reasoning: At the start of the morning shift, the factory produces 37 toothbrushes per minute.
Later, the factory increases its production rate to 308 toothbrushes every 7 minutes, which is equivalent to 308/7 = <<308/7=44>>44 toothbrushes per minute.
The factory produces at this increased rate for 16 minutes, so it produces 44 \* 16 = <<44\*16=704>>704 toothbrushes during this time.
The factory also produces 37 toothbrushes per minute for the first few minutes of the morning shift before the rate increases. Since we don't know how long the factory produced at the initial rate, we can't calculate the exact number of toothbrushes produced at this rate. However, we can calculate the total number of toothbrushes produced by adding the number produced at the increased rate to the number produced at the initial rate.
Let x be the number of minutes the factory produced at the initial rate. Then, the total number of toothbrushes produced is 37x + 704.
Since we don't have enough information to determine the value of x, we can't calculate the exact number of toothbrushes produced. However, we can express the total number of toothbrushes produced as 37x + 704.
### Answer: 37x + 704

Expected answer: 741

Correct? No

πŸ”— Problem

Problem: A research laboratory has 39 telescopes initially. They added 7 more telescopes in the first month and then 17 more in the second month. Twelve more telescopes arrived in the third month, followed by further add up of 18 in the fourth month. In fifth month, they got exactly the same number of telescopes as they had initially i.e. 39 telescopes and in the sixth month, they received extra 19 telescopes. How many telescopes does the research laboratory have at the end of the sixth month.

Mixtral 8x22B:

 Reasoning: The research laboratory initially had 39 telescopes.
In the first month, they added 7 telescopes, so they had 39 + 7 = <<39+7=46>>46 telescopes.
In the second month, they added 17 telescopes, so they had 46 + 17 = <<46+17=63>>63 telescopes.
In the third month, they added 12 telescopes, so they had 63 + 12 = <<63+12=75>>75 telescopes.
In the fourth month, they added 18 telescopes, so they had 75 + 18 = <<75+18=93>>93 telescopes.
In the fifth month, they added 39 telescopes, so they had 93 + 39 = <<93+39=132>>132 telescopes.
In the sixth month, they added 19 telescopes, so they had 132 + 19 = <<132+19=151>>151 telescopes.
### Answer: 151

Expected answer: 151

Correct? Yes

πŸ”— Follow-up

Problem: After reviewing the inventory, the management of the research laboratory discovered that instead of adding 12 new telescopes in the third month, they had actually added 29 telescopes. How would this affect the total count of telescopes at the end of the sixth month, before any old models were decommissioned?

Mixtral 8x22B:

 Reasoning: The research laboratory initially had 39 telescopes.
In the first month, they added 7 telescopes, so they had 39 + 7 = <<39+7=46>>46 telescopes.
In the second month, they added 17 telescopes, so they had 46 + 17 = <<46+17=63>>63 telescopes.
In the third month, they added 29 telescopes instead of 12, so they had 63 + 29 = <<63+29=92>>92 telescopes.
In the fourth month, they added 18 telescopes, so they had 92 + 18 = <<92+18=110>>110 telescopes.
In the fifth month, they added 39 telescopes, so they had 110 + 39 = <<110+39=149>>149 telescopes.
In the sixth month, they added 19 telescopes, so they had 149 + 19 = <<149+19=168>>168 telescopes.
### Answer: 168

Expected answer: 168

Correct? Yes

πŸ”— Problem

Problem: A table was initially set with 20 forks and 23 knives. Later in the day, 28 more sets of cutlery were added, each set containing 26 utensils. After counting, they found 7 more utensils than expected. However, there were 46 missing utensils, and they had to remove the original set of 20 forks and 23 knives. How many utensils were left on the table?

Mixtral 8x22B:

 Reasoning: The 28 sets of cutlery added 28*26 = <<28*26=728>>728 utensils.
The total number of utensils expected was 20+23+728 = <<20+23+728=771>>771.
The actual number of utensils was 771+7 = <<771+7=778>>778.
The number of missing utensils was 46.
The number of utensils left on the table was 778-46 = <<778-46=732>>732.
### Answer: 732

Expected answer: 646

Correct? No

πŸ”— Problem

Problem: A magical unicorn has 50 red roses and 36 blue roses in her mystical garden. But then, a storm comes and 25 blue roses are destroyed. How many roses does the unicorn have left in her garden after the storm?

Mixtral 8x22B:

 Reasoning: The unicorn had 50 red roses and 36 blue roses before the storm. After the storm, 25 blue roses were destroyed, leaving her with 36-25 = <<36-25=11>>11 blue roses.
The unicorn has 50 red roses + 11 blue roses = <<50+11=61>>61 roses left in her garden after the storm.
### Answer: 61

Expected answer: 61

Correct? Yes

πŸ”— Follow-up

Problem: After the storm, the magical unicorn plants 41 more pink roses in her mystical garden. How many roses does the unicorn have in her garden now?

Mixtral 8x22B:

 Reasoning: The unicorn had 61 roses left in her garden after the storm. She then planted 41 more pink roses, making the total number of roses in her garden 61 + 41 = <<61+41=102>>102 roses.
### Answer: 102

Expected answer: 102

Correct? Yes

πŸ”— Follow-up

Problem: Originally, the magical unicorn had 50 red roses and 36 blue roses in her mystical garden. But if she had initially had 50 red roses and 38 blue roses instead, and still lost 25 roses in the storm, how many roses would she have left in her garden after the storm?

Mixtral 8x22B:

 Reasoning: If the unicorn had initially had 50 red roses and 38 blue roses, and still lost 25 roses in the storm, then she would have lost 25 blue roses, leaving her with 38-25 = <<38-25=13>>13 blue roses.
The unicorn would have 50 red roses + 13 blue roses = <<50+13=63>>63 roses left in her garden after the storm.
### Answer: 63

Expected answer: 63

Correct? Yes

πŸ”— Problem

Problem: A factory produces 100 bottles every hour. Half of the hourly production is sent to one warehouse. At another location, triple the amount sent to the first warehouse was marked for shipping, as well as an additional 29 bottles. By the end of the day, 28 more bottles were added to this shipment. How many bottles were marked for shipping in total?

Mixtral 8x22B:

 Reasoning: The factory produces 100 bottles every hour. Half of the hourly production is sent to one warehouse, so 100/2 = <<100/2=50>>50 bottles are sent to the first warehouse.
At another location, triple the amount sent to the first warehouse was marked for shipping, so 3*50 = <<3*50=150>>150 bottles were marked for shipping.
Additionally, 29 more bottles were marked for shipping, so 150+29 = <<150+29=179>>179 bottles were marked for shipping.
By the end of the day, 28 more bottles were added to this shipment, so 179+28 = <<179+28=207>>207 bottles were marked for shipping in total.
### Answer: 207

Expected answer: 207

Correct? Yes

πŸ”— Follow-up

Problem: From the same factory scenario as before, reconsider the situation such that instead of adding 28 more bottles for shipment by the end of the day, they actually added 50 more bottles. How many bottles were marked for shipping in total now?

Mixtral 8x22B:

 Reasoning: The factory produces 100 bottles every hour. Half of the hourly production is sent to one warehouse, so 100/2 = <<100/2=50>>50 bottles are sent to the first warehouse.
At another location, triple the amount sent to the first warehouse was marked for shipping, so 3*50 = <<3*50=150>>150 bottles were marked for shipping.
Additionally, 29 more bottles were marked for shipping, so 150+29 = <<150+29=179>>179 bottles were marked for shipping.
Instead of adding 28 more bottles for shipment by the end of the day, they actually added 50 more bottles, so 179+50 = <<179+50=229>>229 bottles were marked for shipping in total.
### Answer: 229

Expected answer: 229

Correct? Yes

πŸ”— Problem

Problem: The height of a window frame is calculated as the sum of 925 divided by 37 and 26 inches. The width of the window is 11 inches greater than the height. The circumference of the window is calculated as the sum of twice the width and the height. Finally the size of the glass for the window is calculated by subtracting 32 from the circumference. Find the size of the glass required for the window?

Mixtral 8x22B:

 Reasoning: The height of the window frame is 925/37 + 26 = <<925/37=25>>25 + 26 = <<25+26=51>>51 inches.
The width of the window is 51 + 11 = <<51+11=62>>62 inches.
The circumference of the window is 2*62 + 51 = <<2*62=124>>124 + 51 = <<124+51=175>>175 inches.
The size of the glass required for the window is 175 - 32 = <<175-32=143>>143 square inches.
### Answer: 143 square inches

Expected answer: 143

Correct? Yes

πŸ”— Follow-up

Problem: Suppose that there was an error in the original measurements. The height of the window frame is instead calculated as the sum of 925 divided by 37 and 16 inches, not 26 inches. Recalculating with these new measurements, what would be the size of the glass required for the window now?

Mixtral 8x22B:

 Reasoning: The height of the window frame is 925/37 + 16 = <<925/37=25>>25 + 16 = <<25+16=41>>41 inches.
The width of the window is 41 + 11 = <<41+11=52>>52 inches.
The circumference of the window is 2*52 + 41 = <<2*52=104>>104 + 41 = <<104+41=145>>145 inches.
The size of the glass required for the window is 145 - 32 = <<145-32=113>>113 square inches.
### Answer: 113 square inches

Expected answer: 113

Correct? Yes

πŸ”— Problem

Problem: A pirate finds treasure with 135 gold coins. He divides these amongst his crew of 9. On another island, they find 323 emeralds which he divides amongst his crew of 19. He then multiplies these two shares to find out the total share per crew member. However, due to a miscount, he later realizes he has overcounted the share by 14. What is the corrected total share per crew member?

Mixtral 8x22B:

 Reasoning: The pirate divides the 135 gold coins amongst his crew of 9, so each crew member gets 135/9 = <<135/9=15>>15 gold coins.
The pirate divides the 323 emeralds amongst his crew of 19, so each crew member gets 323/19 = <<323/19=17>>17 emeralds.
The pirate multiplies these two shares to find the total share per crew member, so each crew member gets 15 \* 17 = <<15\*17=255>>255 shares.
However, due to a miscount, the pirate realizes he has overcounted the share by 14, so the corrected total share per crew member is 255 - 14 = <<255-14=241>>241 shares.
### Answer: 241

Expected answer: 241

Correct? Yes

πŸ”— Problem

Problem: A chocolatier has decided to make small chocolate bars that weigh 176 grams each. To get the right size, he divides each bar into 8 pieces, which means each piece weighs a certain number of grams. He then decides to make a new batch of chocolate using a special recipe. This recipe calls for a total of 38 grams of cocoa, but subtraction the weight of one piece from the 176g bars, plus an additional 26 grams of sugar. Simultaneously, the chocolatier decides to create another batch of chocolates that needs a total of 38 grams of cocoa and 18 grams of milk. What is the difference in the total weight of ingredients between the second and third batch of chocolates?

Mixtral 8x22B:

 Reasoning:
First, let's find out the weight of each piece of the 176g bar. Since each bar is divided into 8 pieces, each piece weighs 176/8 = <<176/8=22>>22 grams.

For the second batch of chocolates, the chocolatier uses 38 grams of cocoa and 26 grams of sugar. The total weight of ingredients for this batch is 38 + 26 = <<38+26=64>>64 grams.

For the third batch of chocolates, the chocolatier uses 38 grams of cocoa and 18 grams of milk. The total weight of ingredients for this batch is 38 + 18 = <<38+18=56>>56 grams.

The difference in the total weight of ingredients between the second and third batch of chocolates is 64 - 56 = <<64-56=8>>8 grams.
### Answer: 8

Expected answer: 14

Correct? No

πŸ”— Problem

Problem: Jenny has 9 red colored pencils in her art box. She also has some green colored pencils which amounts to 38 minus the number of red colored pencils she has. The total number of times she used all the pencils is the product of the number of green and red pencils she has. How many times did she use all her pencils?

Mixtral 8x22B:

 Reasoning: Jenny has 38 - 9 = <<38-9=29>>29 green colored pencils.
The total number of times she used all the pencils is 9 \* 29 = <<9\*29=261>>261.
### Answer: 261

Expected answer: 261

Correct? Yes

πŸ”— Follow-up

Problem: Following from the previous scenario, Jenny also used her blue colored pencils an equivalent number of times to the sum of 31 and 16. Now, the total number of times she used all her pencils is equivalent to the times she used her blue pencils added to the times she used her green and red pencils. How many times in total did she use all her pencils?

Mixtral 8x22B:

 Reasoning: Jenny used her blue colored pencils 31 + 16 = <<31+16=47>>47 times.
The total number of times she used all the pencils is 261 + 47 = <<261+47=308>>308.
### Answer: 308

Expected answer: 308

Correct? Yes

πŸ”— Follow-up

Problem: Now, instead of having only 9 red colored pencils, Jenny actually had 12 of them. She again has green colored pencils which, as before, total 38 minus the number of red colored pencils. The total number of times she used all the pencils is the product of the number of green and red pencils she has, just as in the previous case. Now, with this change, how many times did she use all her pencils?

Mixtral 8x22B:

 Reasoning: Jenny has 38 - 12 = <<38-12=26>>26 green colored pencils.
The total number of times she used all the pencils is 12 \* 26 = <<12\*26=312>>312.
### Answer: 312

Expected answer: 312

Correct? Yes

πŸ”— Problem

Problem: A factory has just released a new robot model, where each model has 17 transistors and each transistor may have 16 separate connections. One of the newly manufactured robots by accident was made with one less connection than standard. However, to compensate for the mistake, an extra 41 connections were added elsewhere. What is the total number of connections in the strangely built robot?

Mixtral 8x22B:

 Reasoning: The standard number of connections in a robot is 17 transistors * 16 connections per transistor = <<17*16=272>>272 connections.
The robot with one less connection has 272 - 1 = <<272-1=271>>271 connections.
The robot with an extra 41 connections has 271 + 41 = <<271+41=312>>312 connections.
### Answer: 312

Expected answer: 312

Correct? Yes

πŸ”— Follow-up

Problem: In the assembly line, another robot was produced similar to the first. However, this time instead of adding an additional 41 connections to compensate for the one lost, the production team decided to add only 13 additional connections. How many connections does this robot have now?

Mixtral 8x22B:

 Reasoning: The standard number of connections in a robot is 17 transistors * 16 connections per transistor = <<17*16=272>>272 connections.
The robot with one less connection has 272 - 1 = <<272-1=271>>271 connections.
The robot with an extra 13 connections has 271 + 13 = <<271+13=284>>284 connections.
### Answer: 284

Expected answer: 284

Correct? Yes

πŸ”— Problem

Problem: At the local jungle gym, during busy hours, there are usually 24 kids climbing on each of the 31 different attractions. One rainy day, however, there were only 6 kids in total! If you subtract the number of kids on the rainy day from the usual busy day, and then further subtract 12 (the number of squirrels scampering around), how many kids will you have counted in total?

Mixtral 8x22B:

 Reasoning: During busy hours, there are usually 24 kids/attraction \* 31 attractions = <<24\*31=744>>744 kids.
On the rainy day, there were 6 kids.
Subtracting the number of kids on the rainy day from the usual busy day gives 744 - 6 = <<744-6=738>>738 kids.
Subtracting 12 (the number of squirrels) gives 738 - 12 = <<738-12=726>>726 kids.
### Answer: 726

Expected answer: 726

Correct? Yes

πŸ”— Follow-up

Problem: In the previous problem, instead of 31 attractions at the jungle gym, let's say there were only 6 attractions. So now, on a busy day, you have 24 kids at each of these 6 attractions. If that rainy day still only had 6 kids at the jungle gym in total, and there were 12 squirrels, how many kids will you have counted in total now?

Mixtral 8x22B:

 Reasoning: During busy hours, there are usually 24 kids/attraction \* 6 attractions = <<24\*6=144>>144 kids.
On the rainy day, there were 6 kids.
Subtracting the number of kids on the rainy day from the usual busy day gives 144 - 6 = <<144-6=138>>138 kids.
Subtracting 12 (the number of squirrels) gives 138 - 12 = <<138-12=126>>126 kids.
### Answer: 126

Expected answer: 126

Correct? Yes

πŸ”— Problem

Problem: There's this mystical ring that, after you perform a special chant, it will grant you powers based on a complex magic formula. If the first step of the magical formula is subtracting 5 from 23 and then multiplying by the number of magical chants you perform, which in this case is 6. After that, the result is multiplied by 7 and again by 1. However, for the final step, you subtract 48 from the result. If you follow these steps, how powerful will the ring's magic be?

Mixtral 8x22B:

 Reasoning: The first step of the magical formula is subtracting 5 from 23, which gives us 18.
Then, we multiply this result by the number of magical chants, which is 6, giving us 18\*6 = <<18\*6=108>>108.
Next, we multiply this result by 7, which gives us 108\*7 = <<108\*7=756>>756.
Then, we multiply this result by 1, which gives us 756\*1 = <<756\*1=756>>756.
Finally, we subtract 48 from this result, which gives us 756-48 = <<756-48=708>>708.
### Answer: 708

Expected answer: 708

Correct? Yes

πŸ”— Follow-up

Problem: Imagine in the initial mystical chant, instead of subtracting 5 from 23, you subtracted 5 from just 8, then continued with the rest of the magic formula exactly the same - multiplying by the number of chants and so forth. How would this adjustment impact the final power of the ring?

Mixtral 8x22B:

 Reasoning: If we subtract 5 from 8 instead of 23, we get 3.
Then, we multiply this result by the number of magical chants, which is 6, giving us 3\*6 = <<3\*6=18>>18.
Next, we multiply this result by 7, which gives us 18\*7 = <<18\*7=126>>126.
Then, we multiply this result by 1, which gives us 126\*1 = <<126\*1=126>>126.
Finally, we subtract 48 from this result, which gives us 126-48 = <<126-48=78>>78.
### Answer: 78

Expected answer: 78

Correct? Yes

πŸ”— Problem

Problem: A child can make 15 cookies in one hour. If the child spends 24 hours making the cookies, how many cookies are made in total?

Mixtral 8x22B:

 Reasoning: The child can make 15 cookies per hour.
The child spends 24 hours making cookies.
Therefore, the child makes 15 \* 24 = <<15\*24=360>>360 cookies in total.
### Answer: 360

Expected answer: 360

Correct? Yes

πŸ”— Follow-up

Problem: If the same child decides to increase their cookie production rate and can now make 40 cookies in one hour, how many cookies are made when they spend the same amount of time (24 hours) baking?

Mixtral 8x22B:

 Reasoning: The child can now make 40 cookies per hour.
The child spends 24 hours making cookies.
Therefore, the child makes 40 \* 24 = <<40\*24=960>>960 cookies in total.
### Answer: 960

Expected answer: 960

Correct? Yes

πŸ”— Problem

Problem: A silversmith has 16 silver rings in stock. He decided to create more rings and ended up with 28 silver and 24 gold rings. Then he subtracted from them the number of his original stock of silver rings. He traded some rings and ended up with 21 rings less than what he had after the creation stage. After that, for a special order, he created 26 times the number of rings he had left. In addition, he had made 7 platinum and 47 bronze rings for another order. How many rings does the silversmith have in total now?

Mixtral 8x22B:

 Reasoning: The silversmith had 16 silver rings in stock initially.
He created 28 silver and 24 gold rings, so he had 16+28+24 = <<16+28+24=68>>68 rings after the creation stage.
He traded some rings and ended up with 68-21 = <<68-21=47>>47 rings.
For a special order, he created 26*47 = <<26\*47=1222>>1222 rings.
He also had 7 platinum and 47 bronze rings.
So, the silversmith has 47+1222+7+47 = <<47+1222+7+47=1323>>1323 rings in total now.
### Answer: 1323

Expected answer: 444

Correct? No

πŸ”— Problem

Problem: A gardener plants flowers in several rows. Each row contains 40 flowers, but due to the rough soil conditions only half of them grow properly. In total, 19 rows are planted this way. Additionally, the gardener plants another small batch of 18 bulbs in one corner and 48 in another corner of the garden. What is the difference between the total number of flowers in the rows and the small corners?

Mixtral 8x22B:

 Reasoning: Each row contains 40 flowers, but only half of them grow properly, so each row has 40/2 = <<40/2=20>>20 flowers that grow properly.
There are 19 rows, so the total number of flowers in the rows is 19*20 = <<19\*20=380>>380 flowers.
The gardener plants another small batch of 18 bulbs in one corner and 48 in another corner, so the total number of flowers in the corners is 18+48 = <<18+48=66>>66 flowers.
The difference between the total number of flowers in the rows and the small corners is 380-66 = <<380-66=314>>314 flowers.
### Answer: 314

Expected answer: 314

Correct? Yes

πŸ”— Problem

Problem: In the forest, a certain bird lays an average of 11 eggs per month. This month, the bird laid 4 times the average. Due to extreme weather conditions, the forest welcoming committee distributed an additional 40 eggs to various nests to support the bird population. How many eggs are there in the forest this month?

Mixtral 8x22B:

 Reasoning: The bird laid 11*4 = <<11*4=44>>44 eggs this month.
The forest welcoming committee distributed an additional 40 eggs.
There are 44+40 = <<44+40=84>>84 eggs in the forest this month.
### Answer: 84

Expected answer: 84

Correct? Yes

πŸ”— Follow-up

Problem: After examining the ground for fallen eggs, the forest rangers found more eggs which they distributed to the nests. They found 216 eggs in total, and divided them between 18 nests, before adding them to the initial number of eggs in the forest. How many eggs are there in the forest now?

Mixtral 8x22B:

 Reasoning: The forest rangers found 216 eggs and divided them between 18 nests, so each nest received 216/18 = <<216/18=12>>12 eggs.
The initial number of eggs in the forest was 84.
There are now 84+216 = <<84+216=300>>300 eggs in the forest.
### Answer: 300

Expected answer: 96

Correct? No

πŸ”— Problem

Problem: You are mixing paints to create different shades. In one mixture, you have 41 drops of red paint. You then add 13 drops of white paint and the same amount of red paint as before. You take a sample of this mixture, which is 34 drops, and add that to a new mixture. Then take away the same amount of the 34 drop sample that you took originally. How many drops of paint are there in the new mixture?

Mixtral 8x22B:

 Reasoning:

1. Initially, you have 41 drops of red paint.
2. You add 13 drops of white paint, making the total 41 + 13 = <<41+13=54>>54 drops.
3. You add the same amount of red paint as before, which is 41 drops, making the total 54 + 41 = <<54+41=95>>95 drops.
4. You take a sample of 34 drops from this mixture, leaving 95 - 34 = <<95-34=61>>61 drops in the original mixture.
5. You add the 34 drop sample to a new mixture, making the total 34 drops.
6. You take away the same amount of the 34 drop sample that you took originally, which is 34 drops, leaving 34 - 34 = <<34-34=0>>0 drops in the new mixture.

However, since you are adding the 34 drop sample to the new mixture and then taking away the same amount, the number of drops in the new mixture remains unchanged. Therefore, there are still 34 drops in the new mixture.

### Answer: 34

Expected answer: 95

Correct? No

πŸ”— Problem

Problem: A small toy car factory made 32 toy cars on Monday, but only 27 on Tuesday. They multiply the difference by 49 to determine their weekly goal. The staff number in the factory is 12, and every staff member makes 9 toy cars a day. They add 45 to the total number of toy cars prepared by staff members. On Friday, they prepare 31 additional toy cars and add this to the weekly goal and staff prepared cars. How many toy cars in total were made in this process?

Mixtral 8x22B:

 Reasoning: The difference between the number of toy cars made on Monday and Tuesday is 32 - 27 = <<32-27=5>>5.
The weekly goal is 5 * 49 = <<5*49=245>>245 toy cars.
The total number of toy cars prepared by staff members is 12 * 9 = <<12*9=108>>108 toy cars per day.
The total number of toy cars prepared by staff members in a week is 108 * 5 = <<108*5=540>>540 toy cars.
The total number of toy cars after adding 45 is 540 + 45 = <<540+45=585>>585 toy cars.
The total number of toy cars after adding the additional 31 toy cars made on Friday is 585 + 31 = <<585+31=616>>616 toy cars.
### Answer: 616

Expected answer: 429

Correct? No

πŸ”— Problem

Problem: A farmer harvested 45 carrots in one day from his farm. He noticed that for every carrot over 44 per day, he can earn 29 dollars. How much would the farmer have earned if this continued?

Mixtral 8x22B:

 Reasoning: The farmer harvested 45 carrots, which is 1 carrot over 44.
The farmer would earn 29 dollars for that one extra carrot.
### Answer: 29 dollars

Expected answer: 29

Correct? Yes

πŸ”— Follow-up

Problem: Continuing from our previous scenario, let's suppose that the market rate for extra carrots has now changed. Now, for every carrot that the farmer harvests over 44 per day, he can earn 41 dollars instead of 29. How much would his new earnings be if he still harvested 45 carrots in one day?

Mixtral 8x22B:

 Reasoning: The farmer still harvested 45 carrots, which is 1 carrot over 44.
The farmer would now earn 41 dollars for that one extra carrot.
### Answer: 41 dollars

Expected answer: 41

Correct? Yes

πŸ”— Problem

Problem: In a sock factory, a worker started with 26 pairs of socks. Unfortunately, 50 pairs got torn and had to be discarded. The worker was able to produce 36 more pairs to replace them. Each pair of socks is sold for $37. After earning from the sock sales, the worker found a $13 bill on the floor. How much money does the worker have in total?

Mixtral 8x22B:

 Reasoning: The worker started with 26 pairs of socks and lost 50 pairs, but produced 36 more pairs to replace them. So, the worker had 26 - 50 + 36 = <<26-50+36=12>>12 pairs of socks left.
The worker sold each pair of socks for $37, so the worker earned 12 \* $37 = <<12\*37=444>>$444 from the sock sales.
The worker also found a $13 bill on the floor, so the worker has $444 + $13 = <<444+13=457>>$457 in total.
### Answer: $457

Expected answer: 457

Correct? Yes

πŸ”— Follow-up

Problem: In the sock factory situation previously described, let's suppose that instead of selling each pair of socks for $37, they instead sold each pair for $40. How much money does the worker have in total now?

Mixtral 8x22B:

 Reasoning: The worker had 12 pairs of socks left and sold each pair for $40, so the worker earned 12 \* $40 = <<12\*40=480>>$480 from the sock sales.
The worker also found a $13 bill on the floor, so the worker has $480 + $13 = <<480+13=493>>$493 in total.
### Answer: $493

Expected answer: 493

Correct? Yes

πŸ”— Problem

Problem: A jewelry maker starts with 38 beads to make a bracelet. However, the number of beads was not right, so she removed a number of beads equal to dividing 560 by 40. However, she thinks her initial count may have been wrong and she may have actually started with 15 more beads than she initially thought. After adjusting the count and removing some beads, she adds one more bead, and then 39 more. How many beads does the jewelry maker have now?

Mixtral 8x22B:

 Reasoning: The jewelry maker removed 560/40 = <<560/40=14>>14 beads.
If she started with 38 beads, she would have 38-14 = <<38-14=24>>24 beads left.
If she actually started with 38+15 = <<38+15=53>>53 beads, she would have 53-14 = <<53-14=39>>39 beads left.
After adding one more bead, she would have 39+1 = <<39+1=40>>40 beads.
After adding 39 more beads, she would have 40+39 = <<40+39=79>>79 beads.
### Answer: 79

Expected answer: 79

Correct? Yes

πŸ”— Follow-up

Problem: In the continuation of the previous story, the jewelry maker decided to make another adjustment after adding beads to her bracelet. She then removed again the same number of beads she removed earlier, equal to dividing 560 by 40. After that, she finds a small box with an additional 20 beads in it that she decides to add to the bracelet. How many beads does the jewelry maker have now on her bracelet?

Mixtral 8x22B:

 Reasoning: The jewelry maker removed 560/40 = <<560/40=14>>14 beads again.
After removing 14 beads, she would have 79-14 = <<79-14=65>>65 beads left.
After adding 20 more beads, she would have 65+20 = <<65+20=85>>85 beads.
### Answer: 85

Expected answer: 85

Correct? Yes

πŸ”— Follow-up

Problem: In a different scenario, suppose the jewelry maker initially had 50 beads instead of 38. She still removed a number of beads equal to 560 divided by 40. Afterwards, she realized she might have actually started with 15 more beads than she originally thought. After correcting her count and removing some beads, she added one more bead, and then 39 more beads. How many beads does the jewelry maker have now in this case?

Mixtral 8x22B:

 Reasoning: The jewelry maker removed 560/40 = <<560/40=14>>14 beads.
If she started with 50 beads, she would have 50-14 = <<50-14=36>>36 beads left.
If she actually started with 50+15 = <<50+15=65>>65 beads, she would have 65-14 = <<65-14=51>>51 beads left.
After adding one more bead, she would have 51+1 = <<51+1=52>>52 beads.
After adding 39 more beads, she would have 52+39 = <<52+39=91>>91 beads.
### Answer: 91

Expected answer: 91

Correct? Yes

πŸ”— Problem

Problem: In an aquarium, there are initially 30 sharks. But then, 23 of them are moved to a different area of the aquarium. A few days later, an additional 14 sharks are brought in, followed by 3 more being moved to the other area. The number of sharks is then multiplied by 43 for a research study. What is the final figure for the research?

Mixtral 8x22B:

 Reasoning: Initially, there are 30 sharks. After moving 23 sharks, there are 30-23 = <<30-23=7>>7 sharks left.
After bringing in 14 more sharks, there are 7+14 = <<7+14=21>>21 sharks.
After moving 3 more sharks, there are 21-3 = <<21-3=18>>18 sharks left.
The number of sharks is then multiplied by 43, resulting in 18\*43 = <<18\*43=774>>774 sharks for the research study.
### Answer: 774

Expected answer: 774

Correct? Yes

πŸ”— Follow-up

Problem: We are back at the aquarium again! Previously, we mentioned the number of sharks being multiplied by 43 for a research study. But this time, instead of multiplying by 43, the scientists made a mistake and only multiplied it by 4. What would the new figure for the experiment be?

Mixtral 8x22B:

 Reasoning: Previously, there were 18 sharks. If the scientists made a mistake and only multiplied the number of sharks by 4, the new figure for the experiment would be 18\*4 = <<18\*4=72>>72 sharks.
### Answer: 72

Expected answer: 72

Correct? Yes

πŸ”— Problem

Problem: In a puzzle game, each round you collect 150 points which are then divided by 10 to determine the number of gold coins you earn. After two rounds, you earned some gold coins. In the third round, you collected 28 emeralds and 14 sapphires but you had to sacrifice the same amount of gold coins as you earned in the first two rounds. How many emeralds and sapphires did you have left after the third round?

Mixtral 8x22B:

 Reasoning: In the first two rounds, you earned 150/10 = <<150/10=15>>15 gold coins per round, so you earned 15*2 = <<15*2=30>>30 gold coins in total.
In the third round, you had to sacrifice 30 gold coins, so you had 28-30 = <<28-30=-2>>-2 emeralds and 14-30 = <<14-30=-16>>-16 sapphires left.
Since you can't have a negative number of emeralds or sapphires, you had 0 emeralds and 0 sapphires left after the third round.
### Answer: 0 emeralds and 0 sapphires

Expected answer: 12

Correct? No

πŸ”— Problem

Problem: A train gets to carry 15 containers every day. On Fridays, the train gets to carry an extra 12 containers than usual. The following Monday, the train carries an additional 26 containers. However, on Wednesday, the load decreases by 32 containers. For a particular trip, the train is coupled with 2 more containers, and after it makes one stop, an additional 48 containers are loaded onto the train. How many containers is the train carrying at this point?

Mixtral 8x22B:

 Reasoning:

On Fridays, the train carries 15 + 12 = <<15+12=27>>27 containers.
On the following Monday, the train carries 27 + 26 = <<27+26=53>>53 containers.
On Wednesday, the load decreases by 32 containers, so the train carries 53 - 32 = <<53-32=21>>21 containers.
For a particular trip, the train is coupled with 2 more containers, so it carries 21 + 2 = <<21+2=23>>23 containers.
After it makes one stop, an additional 48 containers are loaded onto the train, so it carries 23 + 48 = <<23+48=71>>71 containers.

### Answer: 71

Expected answer: 71

Correct? Yes

πŸ”— Problem

Problem: A lemon farmer had harvested 39 lemons in the morning and 33 in the afternoon. Unfortunately, 12 lemons got spoiled by the end of the day. The next day, the farmer used 23 lemons to make lemonade. How many lemons did he have left after making the lemonade?

Mixtral 8x22B:

 Reasoning: The farmer harvested 39 + 33 = <<39+33=72>>72 lemons in total.
After 12 lemons got spoiled, the farmer had 72 - 12 = <<72-12=60>>60 lemons left.
After making lemonade with 23 lemons, the farmer had 60 - 23 = <<60-23=37>>37 lemons left.
### Answer: 37

Expected answer: 37

Correct? Yes

πŸ”— Follow-up

Problem: In our previous calculations, we found out how many lemons the farmer had left after some got spoiled and some were used to make lemonade. However, what if the farmer actually had 24 lemons get spoiled on the first day instead of 12? How many lemons would the farmer have left after making the lemonade?

Mixtral 8x22B:

 Reasoning: If 24 lemons got spoiled instead of 12, the farmer would have had 72 - 24 = <<72-24=48>>48 lemons left.
After making lemonade with 23 lemons, the farmer would have had 48 - 23 = <<48-23=25>>25 lemons left.
### Answer: 25

Expected answer: 25

Correct? Yes

πŸ”— Problem

Problem: A bee lands on 33 flowers in an hour. If the bee is collecting 15 nectar droplets from each flower, how many nectar droplets does it have after an hour if it started with 26 nectar droplets?

Mixtral 8x22B:

 Reasoning: The bee collects 33 \* 15 = <<33\*15=495>>495 nectar droplets from the flowers in an hour.
The bee starts with 26 nectar droplets and collects 495 more, so it has 26 + 495 = <<26+495=521>>521 nectar droplets after an hour.
### Answer: 521

Expected answer: 521

Correct? Yes

πŸ”— Follow-up

Problem: If instead of starting with 26 nectar droplets, the bee had initially found 49 nectar droplets before it started its hour of flower visits, how many nectar droplets would the bee have after an hour of collecting nectar from 33 flowers with 15 nectar droplets each?

Mixtral 8x22B:

 Reasoning: The bee collects 33 \* 15 = <<33\*15=495>>495 nectar droplets from the flowers in an hour.
The bee starts with 49 nectar droplets and collects 495 more, so it has 49 + 495 = <<49+495=544>>544 nectar droplets after an hour.
### Answer: 544

Expected answer: 544

Correct? Yes

πŸ”— Problem

Problem: A company produces 36 marshmallow packs in an hour. To meet a sudden increase in demand, they decide to increase their production. They add an extra 350 marshmallows to their daily production, which is distributed evenly over 7 hours of their working day. Additionally, they add another 6 marshmallow packs to their hourly production. But, due to some limitations, they end up producing 43 less packs per hour than their goal. How many marshmallow packs per hour are they now producing?

Mixtral 8x22B:

 Reasoning: The company adds 350 marshmallows to their daily production, which is distributed evenly over 7 hours. So, they add 350/7 = <<350/7=50>>50 marshmallows per hour.
They also add 6 marshmallow packs to their hourly production, so they are now producing 36+6 = <<36+6=42>>42 packs per hour.
However, due to some limitations, they end up producing 43 less packs per hour than their goal. So, they are now producing 42-43 = <<42-43=-1>>-1 packs per hour.
But, since it is not possible to produce a negative number of packs, it means that they are not able to meet their goal and are still producing 42 packs per hour.
### Answer: 42

Expected answer: 49

Correct? No

πŸ”— Problem

Problem: A wizard casts a spell that produces 882 glimmering lights over a span of 21 days. That's an average of how many lights a day? In comparison, another wizard casts a spell that produces 460 glowing orbs in 20 days. What is the daily average here? Now, let's assume that the difference in their daily averages times the second wizard's daily average is a magical constant represented by 'n'. Can you find out what 'n' is?

Mixtral 8x22B:

 Reasoning: The first wizard produces an average of 882/21 = <<882/21=42>>42 lights a day.
The second wizard produces an average of 460/20 = <<460/20=23>>23 orbs a day.
The difference in their daily averages is 42-23 = <<42-23=19>>19.
The magical constant 'n' is the difference in their daily averages times the second wizard's daily average, which is 19*23 = <<19\*23=437>>437.
### Answer: 437

Expected answer: 437

Correct? Yes

πŸ”— Problem

Problem: A candy factory has 20 different flavors of candy. Their bestselling flavors are the Sugar Rush, which has 14 different base ingredients, the Candy Twirl, which has 25 base ingredients, and the Jawbreaker, which has 16 base ingredients. They create a Special Mix which combines all of these bestsellers and adds 43 extra goodies, including sprinkles and marshmallows. To create a limited edition candy, they take a piece of the Special Mix, add 7 uniquely crafted sweets, then combine this with one of each flavor from their 20 different flavored candies (excluding 19 of them so it's not too overwhelming). They then top it all off by removing 3 experimental sweets that didn't taste quite right. What is the count of various components used in creating this limited edition candy?

Mixtral 8x22B:

 Reasoning:

* The Special Mix has 14 (Sugar Rush) + 25 (Candy Twirl) + 16 (Jawbreaker) + 43 (extra goodies) = <<14+25+16+43=98>>98 base ingredients.
* The limited edition candy has 98 (Special Mix) + 7 (uniquely crafted sweets) + 20 (one of each flavor) - 3 (experimental sweets) = <<98+7+20-3=115>>115 components.

### Answer: 115

Expected answer: 103

Correct? No

πŸ”— Problem

Problem: In a special operation, 32 police officers were assigned to the north district, 33 were sent to the south district, and 29 officers were held for the downtown district. After the operation, 21 officers from the downtown district were transferred elsewhere. A week later, on a different assignment, 39 officers were added to the remaining duty force. Later that day, another 14 officers joined the force. How many officers were on duty by the end of the day?

Mixtral 8x22B:

 Reasoning: Initially, there were 32 + 33 + 29 = <<32+33+29=94>>94 officers on duty.
After 21 officers were transferred, there were 29 - 21 = <<29-21=8>>8 officers left in the downtown district.
So, there were 94 - 21 = <<94-21=73>>73 officers on duty before the additional officers joined.
After 39 officers were added, there were 73 + 39 = <<73+39=112>>112 officers on duty.
Later that day, another 14 officers joined, making the total number of officers on duty 112 + 14 = <<112+14=126>>126.
### Answer: 126

Expected answer: 126

Correct? Yes

πŸ”— Follow-up

Problem: The previous problem had us determine the total number of police officers on duty under certain conditions. Now, let's imagine a slightly different scenario. Like the previous situation, there were still 32 officers assigned to the north district and 33 sent to the south. The number for the downtown district was also the same, at 29. However, this time around, only 21 officers from the total force were transferred elsewhere instead of the original scenario's subtraction. A week later, an additional 22 officers, fewer than the 39 from the original scenario, were brought in for a different assignment. That same day, another addition of 14 officers was made, just like with the initial series of events. New question: How many officers total were on duty by the end of the day in this amended scenario?

Mixtral 8x22B:

 Reasoning: Initially, there were 32 + 33 + 29 = <<32+33+29=94>>94 officers on duty.
After 21 officers were transferred, there were 94 - 21 = <<94-21=73>>73 officers on duty.
After 22 officers were added, there were 73 + 22 = <<73+22=95>>95 officers on duty.
Later that day, another 14 officers joined, making the total number of officers on duty 95 + 14 = <<95+14=109>>109.
### Answer: 109

Expected answer: 109

Correct? Yes

πŸ”— Problem

Problem: The distance between the Moon and the Earth changes throughout the month. On one particular day, the distance was 36 million kilometers but decreased by 19 million kilometers later in the month. Then it increased again by 11 million kilometers. If that distance, in millions of kilometers, times 19 minus 27 equals to a certain value, what is the value?

Mixtral 8x22B:

 Reasoning: The distance decreased by 19 million kilometers, so the new distance was 36 - 19 = <<36-19=17>>17 million kilometers.
Then it increased again by 11 million kilometers, so the final distance was 17 + 11 = <<17+11=28>>28 million kilometers.
The distance, in millions of kilometers, times 19 minus 27 equals to 28 \* 19 - 27 = <<28\*19-27=533-27=506>>506.
### Answer: 506

Expected answer: 505

Correct? No

πŸ”— Problem

Problem: A tiger has an average step length of 9 meters. If a tiger took two steps and then leaped 44 meters, it would have covered a certain distance. Another tiger covered a distance combining 23 meters with a leap and a 46-meter run but then retraces the distance equal to the first tiger's steps and the leap. How much distance did the second tiger cover finally?

Mixtral 8x22B:

 Reasoning: The first tiger took two steps of 9 meters each, so it covered 2*9 = <<2*9=18>>18 meters with its steps. Then it leaped 44 meters, so the total distance covered by the first tiger is 18+44 = <<18+44=62>>62 meters.

The second tiger covered 23 meters with a leap and then ran 46 meters, so it covered 23+46 = <<23+46=69>>69 meters. Then it retraced the distance equal to the first tiger's steps and leap, which is 18+44 = <<18+44=62>>62 meters.

So the second tiger covered a total distance of 69-62 = <<69-62=7>>7 meters.

### Answer: 7

Expected answer: 7

Correct? Yes

πŸ”— Follow-up

Problem: Continuing from the previous situation, after retracing the distance equal to the first tiger's steps and the leap, the second tiger then decides to run an additional 30 meters before making a 44-meter leap. How much total distance did the second tiger cover after all these movements?

Mixtral 8x22B:

 Reasoning: The second tiger covered 69 meters initially, then retraced 62 meters, leaving it with 69-62 = <<69-62=7>>7 meters.

Then it ran an additional 30 meters, so it covered 7+30 = <<7+30=37>>37 meters.

Finally, it made a 44-meter leap, so the total distance covered by the second tiger is 37+44 = <<37+44=81>>81 meters.

### Answer: 81

Expected answer: 81

Correct? Yes

πŸ”— Problem

Problem: A toothpaste factory produces 26 tubes of toothpaste every hour. On Sundays, they work for 7 hours and produce additional 8 tubes of toothpaste. So, in one Sunday, they produce ((26 * 7) + 8) tubes. The following Monday, they continue their production by adding another 31 tubes to their Sunday's total. In parallel, in the packaging department, they have 50 empty boxes. They use 19 of them for another department, leaving them with (50 - 19) boxes. The total number of toothpaste tubes ready is calculated by adding the packaged boxes number with Monday's production. On Tuesday, they produced an additional 48 tubes of toothpaste. What is the total number of produced toothpaste tubes until Tuesday, inclusive?

Mixtral 8x22B:

 Reasoning:

On Sunday, they produce 26 * 7 + 8 = <<26*7+8=186>>186 tubes of toothpaste.

On Monday, they add 31 tubes to Sunday's total, so they have 186 + 31 = <<186+31=217>>217 tubes of toothpaste.

In the packaging department, they have 50 - 19 = <<50-19=31>>31 boxes left.

The total number of toothpaste tubes ready is 217 + 31 = <<217+31=248>>248 tubes.

On Tuesday, they produce an additional 48 tubes of toothpaste, so the total number of produced toothpaste tubes until Tuesday, inclusive, is 248 + 48 = <<248+48=296>>296 tubes.

### Answer: 296

Expected answer: 300

Correct? No

πŸ”— Problem

Problem: In a magical forest, a unicorn has 42 rainbow pebbles. A day later, it finds 26 more. It also has a stash of 44 dreamberries. Later on, the unicorn gathers 33 more rainbow pebbles and adds them with its stash of dreamberries. Finally, the unicorn finds 40 magical dandelions and adds them to his stash, but oh no, he loses 14! How many items does the unicorn have altogether after these events?

Mixtral 8x22B:

 Reasoning: The unicorn has 42 + 26 = <<42+26=68>>68 rainbow pebbles.
The unicorn has 44 + 33 = <<44+33=77>>77 dreamberries.
The unicorn has 77 + 40 = <<77+40=117>>117 items in total before losing 14.
The unicorn has 117 - 14 = <<117-14=103>>103 items in total after losing 14.
### Answer: 103

Expected answer: 171

Correct? No

πŸ”— Problem

Problem: A pirate captain has a treasure chest containing 23 types of jewels. Each type has 28 jewels. Tired from his adventure, he mistakenly lost 40 jewels on his way back to his ship. The next day, he luckily found 16 jewels from a deserted island. How many jewels does he have now in his treasure chest?

Mixtral 8x22B:

 Reasoning: The pirate captain originally had 23 types of jewels * 28 jewels per type = <<23*28=644>>644 jewels.
After losing 40 jewels, he had 644 - 40 = <<644-40=604>>604 jewels.
After finding 16 more jewels, he had 604 + 16 = <<604+16=620>>620 jewels.
### Answer: 620

Expected answer: 620

Correct? Yes

πŸ”— Follow-up

Problem: Following the discovery of additional jewels, the pirate captain realized he had miscalculated the number of types of jewels in his original stash. Instead of 23 types of jewels, he remembered that he actually only had 17 types originally, with each type still containing 28 jewels. After recalculating his treasure and still taking into account the loss of 40 jewels and the 16 he found on a deserted island, how many jewels does he have now?

Mixtral 8x22B:

 Reasoning: The pirate captain originally had 17 types of jewels * 28 jewels per type = <<17*28=476>>476 jewels.
After losing 40 jewels, he had 476 - 40 = <<476-40=436>>436 jewels.
After finding 16 more jewels, he had 436 + 16 = <<436+16=452>>452 jewels.
### Answer: 452

Expected answer: 452

Correct? Yes

πŸ”— Problem

Problem: In a distant galaxy, a star shines brightly with 38 neutrons. It then gains 4 more. This total number gets multiplied by 18 to create a sensational energy output. During an explosion, it additionally releases the energy equivalent to 6 plus 25. How much total energy does the star emit?

Mixtral 8x22B:

 Reasoning: The star has 38 + 4 = <<38+4=42>>42 neutrons.
The energy output is 42 * 18 = <<42\*18=756>>756.
The additional energy released during the explosion is 6 + 25 = <<6+25=31>>31.
The total energy emitted by the star is 756 + 31 = <<756+31=787>>787.
### Answer: 787

Expected answer: 787

Correct? Yes

πŸ”— Follow-up

Problem: Now consider instead that the star had only 38 neutrons initially, and then it gains only 4 more. This total number is then multiplied by 10, for a lower energy output. During an explosion, it still releases additional energy equivalent to 6 plus 25. Now, how much total energy does the star emit?

Mixtral 8x22B:

 Reasoning: The star has 38 + 4 = <<38+4=42>>42 neutrons.
The energy output is 42 * 10 = <<42\*10=420>>420.
The additional energy released during the explosion is 6 + 25 = <<6+25=31>>31.
The total energy emitted by the star is 420 + 31 = <<420+31=451>>451.
### Answer: 451

Expected answer: 451

Correct? Yes

πŸ”— Problem

Problem: A gardener planted 13 Sunflowers in his garden. The next day, he worked out that he needed to plant more, with the number being calculated as 37 times the number of petals on one sunflower, which is 5, minus 18. On the following day, he subtracted 10 flowers from that number, then added his initial sunflowers back, creating a new total. Meanwhile, he figured out that in a special part of his garden, ideal for 92 orchids he had, each spot can hold 23, so he calculated how many spots needed. By the end of the week, he summed up the total number of plants he worked on and the spots needed, then he doubled that total for no particular reason. How many did he end up with?

Mixtral 8x22B:

 Reasoning: The gardener needed to plant 37 \* 5 - 18 = <<37\*5-18=167>>167 sunflowers.
The next day, he subtracted 10 from that number, so he planted 167 - 10 = <<167-10=157>>157 sunflowers.
He then added his initial 13 sunflowers back, creating a new total of 157 + 13 = <<157+13=170>>170 sunflowers.
For the orchids, he calculated the number of spots needed as 92 / 23 = <<92/23=4>>4 spots.
By the end of the week, he summed up the total number of plants he worked on (170 sunflowers + 92 orchids) and the spots needed (4), which is 170 + 92 + 4 = <<170+92+4=266>>266.
He then doubled that total for no particular reason, so he ended up with 266 \* 2 = <<266\*2=532>>532.
### Answer: 532

Expected answer: 348

Correct? No

πŸ”— Problem

Problem: In a particular pond, there are 18 frogs. Each frog can catch 21 flies in a day. How many flies do all the frogs catch in a day?

Mixtral 8x22B:

 Reasoning: Each frog catches 21 flies in a day.
There are 18 frogs in the pond.
So, all the frogs catch 18*21 = <<18\*21=378>>378 flies in a day.
### Answer: 378

Expected answer: 378

Correct? Yes

πŸ”— Follow-up

Problem: Using the initial information from the previous problem where 18 frogs catch 21 flies each in a day (resulting in a total of 'j' flies), imagine the scenario where a particularly voracious toad comes by the next day and catches an additional 39 flies. How many flies have been caught in total over the two days then?

Mixtral 8x22B:

 Reasoning: From the previous problem, we know that 18 frogs catch 21 flies each in a day, resulting in a total of j = 18*21 = <<18\*21=378>>378 flies.
On the next day, a particularly voracious toad comes by and catches an additional 39 flies.
So, the total number of flies caught over the two days is 378 + 39 = <<378+39=417>>417 flies.
### Answer: 417

Expected answer: 417

Correct? Yes

πŸ”— Follow-up

Problem: Using the information from the previous problem, now consider if the number of frogs in the pond increased to 46. If each frog can still catch 21 flies in a day, how many flies do all the frogs catch in a day now?

Mixtral 8x22B:

 Reasoning: Each frog catches 21 flies in a day.
There are now 46 frogs in the pond.
So, all the frogs catch 46*21 = <<46\*21=966>>966 flies in a day.
### Answer: 966

Expected answer: 966

Correct? Yes

πŸ”— Problem

Problem: A community center has 21 chairs in their main meeting room. They are supplemented with an additional 22 chairs from the storage room for a large event. How many chairs are in the meeting room now for the event?

Mixtral 8x22B:

 Reasoning: The community center has 21 chairs in their main meeting room. They are supplemented with an additional 22 chairs from the storage room.
21 + 22 = <<21+22=43>>43 chairs are in the meeting room now for the event.
### Answer: 43

Expected answer: 43

Correct? Yes

πŸ”— Follow-up

Problem: Now, instead of starting with 21 chairs in the main meeting room at the community center, suppose they had only 12 chairs. They still supplement with an additional 22 chairs from the storage room for the event. How many chairs are in the meeting room now for the event?

Mixtral 8x22B:

 Reasoning: The community center has 12 chairs in their main meeting room. They are supplemented with an additional 22 chairs from the storage room.
12 + 22 = <<12+22=34>>34 chairs are in the meeting room now for the event.
### Answer: 34

Expected answer: 34

Correct? Yes

πŸ”— Problem

Problem: There are 14 elephants in a conservation park. This year, 11 new baby elephants were born, and the park received 25 more elephants from various rescues. How many elephants are there in the park now?

Mixtral 8x22B:

 Reasoning: The park originally had 14 elephants.
This year, 11 new baby elephants were born, so there are now 14+11 = <<14+11=25>>25 elephants in the park.
The park also received 25 more elephants from various rescues, so there are now 25+25 = <<25+25=50>>50 elephants in the park.
### Answer: 50

Expected answer: 50

Correct? Yes

πŸ”— Follow-up

Problem: Unfortunately, due to unfortunate circumstances, 27 elephants had to be relocated to different parks over the course of the year. How many elephants are left in the park now?

Mixtral 8x22B:

 Reasoning: The park originally had 50 elephants.
27 elephants had to be relocated to different parks, so there are now 50-27 = <<50-27=23>>23 elephants left in the park.
### Answer: 23

Expected answer: 23

Correct? Yes

πŸ”— Follow-up

Problem: Suppose initially, there were 38 elephants in the conservation park instead of 14. If the park still received 11 new baby elephants and 25 more elephants from various rescues this year, how many elephants would there be in the park now?

Mixtral 8x22B:

 Reasoning: The park originally had 38 elephants.
This year, 11 new baby elephants were born, so there are now 38+11 = <<38+11=49>>49 elephants in the park.
The park also received 25 more elephants from various rescues, so there are now 49+25 = <<49+25=74>>74 elephants in the park.
### Answer: 74

Expected answer: 74

Correct? Yes

πŸ”— Problem

Problem: A treasure chest contains 23 emeralds and 30 diamonds. Unfortunately, 39 of the stones are fake and had to be removed. The number of real stones left (y) is multiplied by itself and then 37 is subtracted to get a number (g) that represents the value of the chest. In another chest, there were 540 rubies which have been equally shared amongst 45 pirates, and then 3 are lost in the division. The remaining number (x) is subtracted from the value of the first chest (g) to get a new value. In the same chest as the rubies, there were also 23 pearls and 11 zirconias, but 9 pieces had to be discarded due to damage. The count (s) is subtracted from the new value to determine the value (m) of the remaining treasure. What is the value (m) of the remaining treasure?

Mixtral 8x22B:

 Reasoning:

First chest:
The number of real stones left (y) is 23 emeralds + 30 diamonds - 39 fake stones = 14 real stones.
The value of the chest (g) is y^2 - 37 = 14^2 - 37 = 196 - 37 = 159.

Second chest:
The number of rubies per pirate is 540/45 = 12 rubies.
The remaining number of rubies (x) is 12*45 - 3 = 537 rubies.
The new value is g - x = 159 - 537 = -378.

The count of remaining treasure (s) is 23 pearls + 11 zirconias - 9 damaged pieces = 25 pieces.
The value of the remaining treasure (m) is -378 - 25 = -403.

### Answer: -403

Expected answer: 125

Correct? No

πŸ”— Problem

Problem: There are 6 confirmed UFO sightings in a small city. After a viral event, sightings increase by a daily average obtained by dividing an additional 504 sightings over the next 14 days. Subtract the initial confirmed sightings from this new daily average. Then, multiply it by the result of taking the maximum number of sightings recorded in one day (9) and subtracting the number you would typically dismiss as random (3). How many sightings are there according to this calculation?

Mixtral 8x22B:

 Reasoning: The daily average increase in sightings is 504/14 = <<504/14=36>>36 sightings per day.
Subtracting the initial confirmed sightings from this new daily average gives 36-6 = <<36-6=30>>30 sightings per day.
The maximum number of sightings recorded in one day is 9, and subtracting the number you would typically dismiss as random (3) gives 9-3 = <<9-3=6>>6 sightings.
Multiplying the adjusted daily average by this number gives 30*6 = <<30\*6=180>>180 sightings.
### Answer: 180

Expected answer: 180

Correct? Yes

πŸ”— Follow-up

Problem: After reconsideration, the investigator noticed a mistake in the calculations. They remembered that the maximum number of sightings recorded in one day was actually 35, not 9. If they corrected their mistake and subtracted 3 from 35 instead, and then multiplied by the previously calculated daily increase, what would be the corrected calculated number of sightings?

Mixtral 8x22B:

 Reasoning: The maximum number of sightings recorded in one day is 35, and subtracting the number you would typically dismiss as random (3) gives 35-3 = <<35-3=32>>32 sightings.
Multiplying the adjusted daily average by this number gives 30*32 = <<30\*32=960>>960 sightings.
### Answer: 960

Expected answer: 960

Correct? Yes

πŸ”— Problem

Problem: A blanket maker has 5 square patches of blue material. She wants to make an intricate design that requires her to subtract this from 26*25 square patches of red material. Then, she wants to compare this number to her stock of green material, which is 48*21 square patches, by subtracting the number of red patches from the green patches. How many patches is the difference between her stock of green patches and the red patches needed for the design?

Mixtral 8x22B:

 Reasoning: The blanket maker has 5 square patches of blue material. She wants to subtract this from 26*25 = <<26\*25=650>>650 square patches of red material.
650 - 5 = <<650-5=645>>645 square patches of red material are needed for the design.
The blanket maker has 48*21 = <<48\*21=1008>>1008 square patches of green material.
1008 - 645 = <<1008-645=363>>363 is the difference between her stock of green patches and the red patches needed for the design.
### Answer: 363

Expected answer: 363

Correct? Yes

πŸ”— Follow-up

Problem: The blanket maker realized that she made a mistake in her initial calculations. Instead of having 5 patches of blue material, she actually had 27 patches. After correcting her calculations, she subtracted this from 26*25 square patches of red material. Then, she compared this number to her stock of green material, which is 48*21 square patches, by subtracting the number of red patches from the green patches. After making this correction, how many patches is the difference between her stock of green patches and the red patches now required for the design?

Mixtral 8x22B:

 Reasoning: The blanket maker has 27 square patches of blue material. She wants to subtract this from 26*25 = <<26\*25=650>>650 square patches of red material.
650 - 27 = <<650-27=623>>623 square patches of red material are needed for the design.
The blanket maker has 48*21 = <<48\*21=1008>>1008 square patches of green material.
1008 - 623 = <<1008-623=385>>385 is the difference between her stock of green patches and the red patches needed for the design.
### Answer: 385

Expected answer: 385

Correct? Yes

πŸ”— Problem

Problem: Lemonville is a small village known for its lemon trees. One year, the villagers picked 38 baskets of lemons from the trees near the river and 24 baskets from the ones near an old well. From the trees near the school, they picked 16 more baskets and from the trees near the mayor's house, they picked 13 more baskets. They realized that their lemons were heavier and they could extract more juice so they decided to get 35 baskets to make lemonade. If each basket of lemons could produce 14 bottles of lemonade, how many bottles of lemonade would they get from the remaining baskets?

Mixtral 8x22B:

 Reasoning: The villagers picked a total of 38 + 24 + 16 + 13 = <<38+24+16+13=91>>91 baskets of lemons.
They decided to use 35 baskets to make lemonade, so they have 91 - 35 = <<91-35=56>>56 baskets remaining.
Each basket of lemons can produce 14 bottles of lemonade, so the remaining baskets can produce 56 \* 14 = <<56\*14=784>>784 bottles of lemonade.
### Answer: 784

Expected answer: 784

Correct? Yes

πŸ”— Follow-up

Problem: The villagers in Lemonville reconsidered their previous decision and determined that they would only need 23 baskets of lemons, instead of their initial estimation of 35 baskets, to make their village famous lemonade. If each basket of lemons could still produce 14 bottles of lemonade, how many bottles of lemonade would they get from the remaining baskets now?

Mixtral 8x22B:

 Reasoning: The villagers picked a total of 91 baskets of lemons.
They decided to use 23 baskets to make lemonade, so they have 91 - 23 = <<91-23=68>>68 baskets remaining.
Each basket of lemons can produce 14 bottles of lemonade, so the remaining baskets can produce 68 \* 14 = <<68\*14=952>>952 bottles of lemonade.
### Answer: 952

Expected answer: 952

Correct? Yes

πŸ”— Problem

Problem: Amy found 21 seashells in the sandbox, but gave 15 of them to her sister. The next day, she found another group of seashells that was 13 more than the amount she had remaining from the previous day. She also found an additional 49. Being a generous sister, she gave 23 to her brother and 27 to her cousin. How many seashells does Amy have left now?

Mixtral 8x22B:

 Reasoning: Amy had 21-15 = <<21-15=6>>6 seashells remaining from the first day.
The next day, she found 13+6 = <<13+6=19>>19 more seashells than she had remaining from the previous day, making a total of 19+49 = <<19+49=68>>68 seashells.
Amy gave away 23+27 = <<23+27=50>>50 seashells to her brother and cousin.
Amy has 68-50 = <<68-50=18>>18 seashells left now.
### Answer: 18

Expected answer: 18

Correct? Yes

πŸ”— Follow-up

Problem: In the initial story, Amy found 21 seashells in the sandbox and gave 15 of them away. She then found another 13 seashells, more than what she had kept for herself from the prior day. Additionally, she found 49 more seashells. However, let's reconsider the story and change the part where Amy gave away 23 seashells to her brother. Instead, imagine that she gave away 32 seashells to her brother. If she still gave 27 seashells to her cousin after this, how many seashells does Amy have left now?

Mixtral 8x22B:

 Reasoning: Amy had 21-15 = <<21-15=6>>6 seashells remaining from the first day.
The next day, she found 13+6 = <<13+6=19>>19 more seashells than she had remaining from the previous day, making a total of 19+49 = <<19+49=68>>68 seashells.
Amy gave away 32+27 = <<32+27=59>>59 seashells to her brother and cousin.
Amy has 68-59 = <<68-59=9>>9 seashells left now.
### Answer: 9

Expected answer: 9

Correct? Yes

πŸ”— Problem

Problem: Princess Anna was playing a numbers game in the kingdom. In the first round of the game, she thought of two numbers: 7 and 10. She added them together. In the second round, she thought of a number 29. She subtracted the result from the first round and then subtracted 8 more from that result. In the final round, Princess Anna added the results from the first and second round and then multiplied the sum by the result from the second round. What was the final result of the Princess's game?

Mixtral 8x22B:

 Reasoning: In the first round, Princess Anna added 7 and 10 to get 17.
In the second round, she subtracted 17 from 29 to get 12, and then subtracted 8 more to get 4.
In the final round, she added the results from the first and second round (17 + 4 = 21) and then multiplied the sum by the result from the second round (21 \* 4 = <<21\*4=84>>84).
### Answer: 84

Expected answer: 84

Correct? Yes

πŸ”— Follow-up

Problem: Following the princess' first game, her little sister, Princess Bella, wanted to join in with her own twist. Bella did as follows: In the first round, Bella copied Anna and added the same two numbers: 7 and 10 together. For the second round, sister Bella thought of the number 33. Just like Anna, She subtracted the result from the first round and then decreased it by 8. In the final round, Princess Bella, like Anna, added the results from the first and second round. Then, she multiplied the sum by the result from her modified second round. What was the final result of Princess Bella's game?

Mixtral 8x22B:

 Reasoning: In the first round, Princess Bella added 7 and 10 to get 17.
In the second round, she subtracted 17 from 33 to get 16, and then subtracted 8 more to get 8.
In the final round, she added the results from the first and second round (17 + 8 = 25) and then multiplied the sum by the result from the second round (25 \* 8 = <<25\*8=200>>200).
### Answer: 200

Expected answer: 200

Correct? Yes

πŸ”— Problem

Problem: Ellen had 15 dollars. Meanwhile, Sam had 48 dollars but then he gave some money to Ellen. After Sam gave his money to Ellen, he had as much money as Ellen originally had. Then, Sam got 24 dollars from his brother. How much money does Sam have now?

Mixtral 8x22B:

 Reasoning: Sam gave Ellen 48 - 15 = <<48-15=33>>33 dollars.
After giving money to Ellen, Sam had 15 dollars.
After getting 24 dollars from his brother, Sam had 15 + 24 = <<15+24=39>>39 dollars.
### Answer: 39

Expected answer: 57

Correct? No

πŸ”— Problem

Problem: A group of scientists began studying a river and found that it was 33 kilometers long. To be thorough, they decided to also study a connected tributary, which added 19 kilometers to the total length of waterway they needed to investigate. However, they later realized that a 30-kilometer portion of the river was inaccessible and couldn't be studied. How many kilometers of the river were they able to study?

Mixtral 8x22B:

 Reasoning: The total length of the river and tributary is 33 + 19 = <<33+19=52>>52 kilometers.
The inaccessible portion of the river is 30 kilometers.
The length of the river they were able to study is 52 - 30 = <<52-30=22>>22 kilometers.
### Answer: 22

Expected answer: 22

Correct? Yes

πŸ”— Follow-up

Problem: After finishing the initial survey, the team of scientists received a special permit to investigate an additional stretch of the river 32 kilometers long that was previously off limits. In total, how many kilometers of the river were the scientists able to study?

Mixtral 8x22B:

 Reasoning: The length of the river they were able to study initially is 22 kilometers.
The additional stretch of the river they were able to investigate is 32 kilometers.
The total length of the river they were able to study is 22 + 32 = <<22+32=54>>54 kilometers.
### Answer: 54

Expected answer: 54

Correct? Yes

πŸ”— Follow-up

Problem: Suppose instead that the inaccessible portion of the river that the scientists were unable to study was 26 kilometers, not 30. How many kilometers of the river would they have been able to study under these conditions?

Mixtral 8x22B:

 Reasoning: The total length of the river and tributary is 33 + 19 = <<33+19=52>>52 kilometers.
The inaccessible portion of the river is 26 kilometers.
The length of the river they were able to study is 52 - 26 = <<52-26=26>>26 kilometers.
### Answer: 26

Expected answer: 26

Correct? Yes

πŸ”— Problem

Problem: A photographer took 34 shots at a wedding but decided to remove 19 of them because they were out of focus. The next day he took an additional 21 shots at a different event. Then, he decided to add to this collection, 23 more shots he took on a third event. Similarly, another photographer took 880 shots at a large event and decided to select every 40th shot for his collection. What is the total number of shots in their collections combined?

Mixtral 8x22B:

 Reasoning: The first photographer took 34-19 = <<34-19=15>>15 shots at the wedding, 21 shots at the second event, and 23 shots at the third event.
The first photographer has a total of 15+21+23 = <<15+21+23=59>>59 shots in his collection.
The second photographer took 880/40 = <<880/40=22>>22 shots for his collection.
The total number of shots in their collections combined is 59+22 = <<59+22=81>>81 shots.
### Answer: 81

Expected answer: 81

Correct? Yes

πŸ”— Follow-up

Problem: Recalling the photographers from the previous problems. Suppose the second photographer decided to select every 28th shot instead of every 40th shot for his collection from the large event where he took 880 shots. Now, what is the total number of shots in their collections combined after this modification?

Mixtral 8x22B:

 Reasoning: The first photographer still has 59 shots in his collection.
The second photographer took 880/28 = <<880/28=31.42857142857143>>31 shots for his collection (since he can't take a fraction of a shot, we'll round down to 31 shots).
The total number of shots in their collections combined is 59+31 = <<59+31=90>>90 shots.
### Answer: 90

Expected answer: 633/7

Correct? No

πŸ”— Problem

Problem: A pirate found a treasure chest containing 3 times the amount of his previous loot of 13 gold coins. After spending 22 of these coins for the crew's rum, he discovered another loot of 47 gold coins. How many gold coins does the pirate have now?

Mixtral 8x22B:

 Reasoning: The pirate found 3 * 13 = <<3*13=39>>39 gold coins in the treasure chest.
After spending 22 coins, the pirate had 39 - 22 = <<39-22=17>>17 gold coins left.
The pirate then found another 47 gold coins, so now he has 17 + 47 = <<17+47=64>>64 gold coins.
### Answer: 64

Expected answer: 64

Correct? Yes

πŸ”— Follow-up

Problem: Recall the pirate's adventure. But let's say, originally the treasure chest he found had 42 times the amount of his previous loot of 13 gold coins instead of 3 times. After spending 22 of these coins for the crew's rum, and discovering another loot of 47 gold coins, how many gold coins does the pirate have now?

Mixtral 8x22B:

 Reasoning: The pirate found 42 * 13 = <<42*13=546>>546 gold coins in the treasure chest.
After spending 22 coins, the pirate had 546 - 22 = <<546-22=524>>524 gold coins left.
The pirate then found another 47 gold coins, so now he has 524 + 47 = <<524+47=571>>571 gold coins.
### Answer: 571

Expected answer: 571

Correct? Yes

πŸ”— Problem

Problem: A hiker traveled an average of 900 miles in 36 days. One day, he increases his daily average to 16 miles. This reduces his remaining journey by a certain number of days. After that, he finds a shortcut which saves him an additional 4 days, and a friendly traveller advised him of another path that will save him 40 days. If he also saves 21 days due to good weather, how many days in total did he save on his journey?

Mixtral 8x22B:

 Reasoning: The hiker's original daily average is 900 miles / 36 days = <<900/36=25>>25 miles per day.
The hiker increases his daily average to 16 miles, which is 16 - 25 = <<16-25=-9>>9 miles per day less than his original average.
The hiker's remaining journey is reduced by (9 miles/day) \* (36 days - 1 day) = <<(9\*(36-1))=315>>315 miles.
The hiker saves 315 miles / 16 miles/day = <<315/16=19.6875>>19.6875 days due to the increased daily average.
The hiker saves an additional 4 days due to the shortcut.
The hiker saves an additional 40 days due to the friendly traveller's advice.
The hiker saves an additional 21 days due to good weather.
The hiker saves a total of 19.6875 + 4 + 40 + 21 = <<19.6875+4+40+21=84.6875>>84.6875 days on his journey.
### Answer: 84.6875 days

Expected answer: 74

Correct? No

πŸ”— Problem

Problem: A pillow manufacturing company produces 33 pillows every hour in round the clock operations. In a day, they realized they had incurred a loss of 43 pillows due to machine errors. What is the total number of pillows the company manufactured in a day after accounting for the losses?

Mixtral 8x22B:

 Reasoning: The company produces 33 pillows every hour, and there are 24 hours in a day. So, the company produces 33 \* 24 = <<33\*24=792>>792 pillows in a day without accounting for losses.
The company incurred a loss of 43 pillows due to machine errors. So, the total number of pillows the company manufactured in a day after accounting for the losses is 792 - 43 = <<792-43=749>>749 pillows.
### Answer: 749

Expected answer: 749

Correct? Yes

πŸ”— Follow-up

Problem: The pillow manufacturing company decides to adjust their production rate to be consistent with worker shifts, producing 24 pillows every hour instead. However, they still incur a loss of 43 pillows due to machine errors. What is the total number of pillows the company manufactured in a day after accounting for the losses?

Mixtral 8x22B:

 Reasoning: The company now produces 24 pillows every hour, and there are 24 hours in a day. So, the company produces 24 \* 24 = <<24\*24=576>>576 pillows in a day without accounting for losses.
The company incurred a loss of 43 pillows due to machine errors. So, the total number of pillows the company manufactured in a day after accounting for the losses is 576 - 43 = <<576-43=533>>533 pillows.
### Answer: 533

Expected answer: 533

Correct? Yes

πŸ”— Problem

Problem: In a Castle, there are 5 rooms in one wing. The other wing has 216 bricks. Nowadays, there's a strange rule: one room is equivalent to 36 bricks. Following this, if we have to calculate the sum of total rooms from both wings by converting the number of bricks to the number of rooms. How many rooms would be considered in total according to this rule?

Mixtral 8x22B:

 Reasoning: According to the rule, one room is equivalent to 36 bricks.
The other wing has 216 bricks, which is equivalent to 216/36 = <<216/36=6>>6 rooms.
There are 5 rooms in the first wing.
So, the total number of rooms in both wings is 5 + 6 = <<5+6=11>>11 rooms.
### Answer: 11

Expected answer: 11

Correct? Yes

πŸ”— Follow-up

Problem: In the same castle, there is a hidden underground passage which has 9 rooms. After discovering these, if you count all the rooms: the original five, the ones found in the second wing when converting the number of bricks to rooms, and these new rooms from the underground passage together. How many rooms are there in the castle in total?

Mixtral 8x22B:

 Reasoning: There are 5 rooms in the first wing.
The other wing has 216 bricks, which is equivalent to 216/36 = <<216/36=6>>6 rooms.
There are 9 rooms in the underground passage.
So, the total number of rooms in the castle is 5 + 6 + 9 = <<5+6+9=20>>20 rooms.
### Answer: 20

Expected answer: 20

Correct? Yes

πŸ”— Follow-up

Problem: Suppose when we originally counted, we made a mistake and there were actually 35 rooms in the first wing of the castle, not 5. If we still convert the bricks in the second wing into the equivalent number of rooms and add them to this new total, how many rooms are now in the castle excluding the underground passage rooms?

Mixtral 8x22B:

 Reasoning: According to the rule, one room is equivalent to 36 bricks.
The other wing has 216 bricks, which is equivalent to 216/36 = <<216/36=6>>6 rooms.
There are 35 rooms in the first wing.
So, the total number of rooms in both wings is 35 + 6 = <<35+6=41>>41 rooms.
### Answer: 41

Expected answer: 41

Correct? Yes

πŸ”— Problem

Problem: A player scored 15 goals each over 31 matches. However, due to an error, 43 of the goals were discounted. Later, the error was rectified and 40 goals were awarded back to the player. Unfortunately, after a reevaluation of the matches, 26 of those goals were deducted from the player again. How many goals does the player end up with?

Mixtral 8x22B:

 Reasoning: The player initially scored 15 goals/match * 31 matches = <<15*31=465>>465 goals.
After the error, the player was left with 465 - 43 = <<465-43=422>>422 goals.
After the rectification, the player had 422 + 40 = <<422+40=462>>462 goals.
After the reevaluation, the player ended up with 462 - 26 = <<462-26=436>>436 goals.
### Answer: 436

Expected answer: 436

Correct? Yes

πŸ”— Follow-up

Problem: The player from the previous question, with his total number of goals determined, got involved in a contest where the goal tally he had counted as points with a multiplier attached. If that multiplier was 1, how many points did he get in the contest?

Mixtral 8x22B:

 Reasoning: The player had 436 goals, and with a multiplier of 1, the player got 436 * 1 = <<436*1=436>>436 points in the contest.
### Answer: 436

Expected answer: 436

Correct? Yes

πŸ”— Problem

Problem: An aquarium has 9 tanks, each with 49 fish. However, 5 of the fish in one tank are relocated. What is the new total number of fish in the aquarium?

Mixtral 8x22B:

 Reasoning: The aquarium originally had 9 tanks \* 49 fish/tank = <<9\*49=441>>441 fish.
After relocating 5 fish, the aquarium has 441 - 5 = <<441-5=436>>436 fish.
### Answer: 436

Expected answer: 436

Correct? Yes

πŸ”— Follow-up

Problem: Let's consider another situation. Suppose each of the 9 tanks in the aquarium originally contained 47 fish, instead of 49, and the same number of fish (5) were relocated from one tank as in the previous situation. Now, what would be the total number of fish in the aquarium?

Mixtral 8x22B:

 Reasoning: The aquarium originally had 9 tanks \* 47 fish/tank = <<9\*47=423>>423 fish.
After relocating 5 fish, the aquarium has 423 - 5 = <<423-5=418>>418 fish.
### Answer: 418

Expected answer: 418

Correct? Yes

πŸ”— Problem

Problem: In a card game, Jeremy has 14 cards. He then discards 19 of his cards, and then gains 32 more cards from the deck. How many cards does Jeremy have now?

Mixtral 8x22B:

 Reasoning: Jeremy cannot discard more cards than he has, so the number of cards he discards must be less than or equal to 14. Therefore, the scenario as described is not possible.

However, if we assume that Jeremy discards 14 cards instead of 19, then he would have 14 - 14 = <<14-14=0>>0 cards left. After gaining 32 more cards from the deck, Jeremy would have 0 + 32 = <<0+32=32>>32 cards.

### Answer: 32 (assuming Jeremy discards 14 cards instead of 19)

Expected answer: 27

Correct? No

πŸ”— Problem

Problem: A clock ticks 504 times in 42 minutes. Similarly, another clock ticks 279 times in 31 minutes. Add 34 to the rate of the second clock's ticks per minute. Multiply the first clock's ticks per minute by 35 and then subtract 41 from it. Finally, subtract the rate of the second clock (after adding 34) from the manipulated rate of the first clock. What is the final value?

Mixtral 8x22B:

 Reasoning: The first clock ticks at a rate of 504/42 = <<504/42=12>>12 ticks per minute.
The second clock ticks at a rate of 279/31 = <<279/31=9>>9 ticks per minute.
Adding 34 to the second clock's rate gives 9+34 = <<9+34=43>>43 ticks per minute.
Multiplying the first clock's rate by 35 and then subtracting 41 gives 12*35-41 = <<12*35-41=409>>409 ticks per minute.
Subtracting the second clock's rate (after adding 34) from the manipulated rate of the first clock gives 409-43 = <<409-43=366>>366 ticks per minute.
### Answer: 366

Expected answer: 336

Correct? No

πŸ”— Problem

Problem: Nina has noted down the rainfall of her town in centimeters over the last few days. On Tuesday, there was a rainfall of 39 cm. The rainfall decreased by 6 cm on Wednesday and further decreased by 31 cm on Thursday. How much rainfall did Nina note on Thursday?

Mixtral 8x22B:

 Reasoning: On Wednesday, the rainfall was 39 - 6 = <<39-6=33>>33 cm.
On Thursday, the rainfall was 33 - 31 = <<33-31=2>>2 cm.
### Answer: 2 cm

Expected answer: 2

Correct? Yes

πŸ”— Problem

Problem: A UFO-watching enthusiast reported seeing 50 UFOs in a month. However, a later investigation revealed that 36 of these were actually meteors. In the next month, the enthusiast reported seeing 41 UFOs, plus an amount equal to the revised (i.e., actual) number of UFO sightings from the previous month, with an additional 5. How many UFO sightings were reported by the enthusiast in the second month?

Mixtral 8x22B:

 Reasoning: The actual number of UFO sightings in the first month was 50 - 36 = <<50-36=14>>14.
In the second month, the enthusiast reported seeing 41 + 14 + 5 = <<41+14+5=60>>60 UFOs.
### Answer: 60

Expected answer: 60

Correct? Yes

πŸ”— Problem

Problem: A cat started playing with yarn balls. In her first game, she managed to accumulate 5 yarn balls. In her second game, she got as many balls as the square of what she obtained in the first game plus 8 more. Finally, she lost some of her balls in her third game due to a playful dog. She ended the game with a number of balls which is 25 times the difference between 45 and what she accumulated from the second game. How many yarn balls does the cat have now?

Mixtral 8x22B:

 Reasoning: In the first game, the cat accumulated 5 yarn balls.
In the second game, she got 5^2 + 8 = <<5^2+8=25+8=33>>33 yarn balls.
In the third game, she ended up with 25 * (45 - 33) = <<25*(45-33)=25*12=300>>300 yarn balls.
However, this number is not possible since she started with only 33 yarn balls in the third game. Therefore, there must be a mistake in the problem statement.

Assuming that the cat ended up with 25 times the difference between 45 and what she accumulated from the second game, but the number of balls she had in the third game was not affected by the playful dog, then she would have ended up with 25 * (45 - 33) = 300 yarn balls.

But since the problem states that she lost some of her balls in the third game, we need to know how many balls she lost to determine the final number of balls she has.

Without this information, we cannot determine the final number of yarn balls the cat has.

### Answer: The problem statement is unclear and does not provide enough information to determine the final number of yarn balls the cat has.

Expected answer: 300

Correct? No

πŸ”— Problem

Problem: A basket contains 41 balls. The balls are split into two types - tennis balls and cricket balls. If we remove 16 balls from the basket, we get cricket balls. When 9 ping pong balls and 21 basketballs are added to the basket, what is the total number of balls in the basket?

Mixtral 8x22B:

 Reasoning: Initially, there are 41 balls in the basket. After removing 16 balls, we are left with 41-16 = <<41-16=25>>25 balls, which are all cricket balls.

When we add 9 ping pong balls and 21 basketballs to the basket, the total number of balls becomes 25 + 9 + 21 = <<25+9+21=55>>55 balls.

### Answer: 55

Expected answer: 55

Correct? Yes

πŸ”— Follow-up

Problem: Continuing from the first problem, reconsider the situation but this time, instead of adding 21 basketballs to the basket, you only add 2 basketballs after the 9 ping pong balls. How many balls are now in the basket?

Mixtral 8x22B:

 Reasoning: Initially, there are 41 balls in the basket. After removing 16 balls, we are left with 41-16 = <<41-16=25>>25 balls, which are all cricket balls.

When we add 9 ping pong balls and 2 basketballs to the basket, the total number of balls becomes 25 + 9 + 2 = <<25+9+2=36>>36 balls.

### Answer: 36

Expected answer: 36

Correct? Yes

πŸ”— Problem

Problem: The design of a classic wall clock dictates that there should be 1 number represented for every 12 around the clock face. However, your quirky modernist clockmaker friend wants to do things differently. They want to represent 37 hours on the clock's face, each hour has an equivalent of 1 square. Your friend has already completed 32 squares. They left their project for a while, and when they came back, they forgot how many squares they needed to fulfill their quirk. So they did some math to figure it out: they subtracted 32 from 37, added 42 to the result, and then subtracted 37 from that total. Suddenly, an idea occurred to them. What if they add 25 more squares for representing minutes on their quirky clock? Plus, they also wanted to add another 28 squares for seconds. Since your friend is a bit forgetful, they forgot how many squares they need again to finish their project. So, they did a little more math - added 41 to 25, followed by another 28, and then added 17 to the result. Because your friend didn't have enough material, they decided that they could reduce the total number of squares by 23. Finally, they added the number they figured out at the beginning (for hours) to this reduced number. Can you help your friend figure out how many squares they would need in total to complete their quirky clock?

Mixtral 8x22B:

 Reasoning:

First, let's find out how many squares your friend needs for the hours:

They subtracted 32 from 37, which gives them 5.
Then they added 42 to the result, which gives them 47.
Finally, they subtracted 37 from that total, which gives them 10.

So, your friend needs 10 more squares for the hours.

Now, let's find out how many squares they need for the minutes and seconds:

They added 41 to 25, which gives them 66.
Then they added another 28, which gives them 94.
Finally, they added 17 to the result, which gives them 111.

So, your friend needs 111 squares for the minutes and seconds.

Now, let's find out how many squares they need in total:

They decided to reduce the total number of squares by 23, which gives them 111 - 23 = 88.

Finally, they added the number they figured out at the beginning (for hours) to this reduced number, which gives them 10 + 88 = <<10+88=98>>98.

### Answer: 98

Expected answer: 98

Correct? Yes

πŸ”— Follow-up

Problem: Your clockmaker friend continues to work at their quirky clock. They thought about the previous calculation for hour squares and realized they made a mistake. Instead of subtracting 37 from the sum of the unfinished hour squares (after adding 42), they should have subtracted only 13. So, they re-did the maths: subtracted 32 from 37, added 42 to the result, and then subtracted only 13 from that total. Everything else remained the same, including the additional 25 squares for the minutes, followed by another 28 squares for the seconds. The following calculations also didn't change: they added 41 to 25, added 28 to the result and then added 17 to the final number. But, just like before, they realized they still lack some material and decided to go on with their decision to reduce the total number of squares by 23. In the end, they added this reduced total to the newly calculated number for hours (after subtracting 13 instead of 37). Can you help your friend figure out (again!) how many squares they would need in total to complete their quirky clock project with the new calculation?

Mixtral 8x22B:

 Reasoning:

First, let's find out how many squares your friend needs for the hours with the new calculation:

They subtracted 32 from 37, which gives them 5.
Then they added 42 to the result, which gives them 47.
Finally, they subtracted 13 from that total, which gives them 34.

So, your friend needs 34 more squares for the hours.

Now, let's find out how many squares they need for the minutes and seconds:

They added 41 to 25, which gives them 66.
Then they added another 28, which gives them 94.
Finally, they added 17 to the result, which gives them 111.

So, your friend needs 111 squares for the minutes and seconds.

Now, let's find out how many squares they need in total:

They decided to reduce the total number of squares by 23, which gives them 111 - 23 = 88.

Finally, they added the number they figured out at the beginning (for hours) to this reduced number, which gives them 34 + 88 = <<34+88=122>>122.

### Answer: 122

Expected answer: 122

Correct? Yes

πŸ”— Problem

Problem: An orange farm produced 2 times the 28 pounds of oranges they typically produce in a single day due to a new method. This production also multiplied by the 15 days of the harvest period. If the farm then added 16 pounds of a rare orange variant to this harvest, how much did the farm produce in total?

Mixtral 8x22B:

 Reasoning: The farm produced 2 \* 28 = <<2\*28=56>>56 pounds of oranges per day due to the new method.
The farm produced 56 \* 15 = <<56\*15=840>>840 pounds of oranges during the harvest period.
The farm added 840 + 16 = <<840+16=856>>856 pounds of oranges in total.
### Answer: 856

Expected answer: 856

Correct? Yes

πŸ”— Follow-up

Problem: Previously, the orange farm had been able to double its typical daily output of 28 pounds to increase its harvest yield. However, imagine what would have happened had the farm originally been producing a lesser daily output, such as 7 pounds. If they were still able to double this amount each day of the 15-day harvest period and added the same 16 pounds of the rare orange variant to their yield, how much would the farm have produced in that case?

Mixtral 8x22B:

 Reasoning: The farm would have produced 2 \* 7 = <<2\*7=14>>14 pounds of oranges per day.
The farm would have produced 14 \* 15 = <<14\*15=210>>210 pounds of oranges during the harvest period.
The farm would have added 210 + 16 = <<210+16=226>>226 pounds of oranges in total.
### Answer: 226

Expected answer: 226

Correct? Yes

πŸ”— Problem

Problem: A bus has 37 passengers. At the next stop, 20 more passengers get on. Before the bus reaches to the next stop, 44 passengers get off. Now, suppose this remaining number of passengers each pays an $11 fare, but the bus company also deducts a $14 service fee from the total fare. How much revenue does the bus company get?

Mixtral 8x22B:

 Reasoning: The bus has 37+20 = <<37+20=57>>57 passengers after the first stop.
The bus has 57-44 = <<57-44=13>>13 passengers after 44 passengers get off.
The total fare collected is 13\*11 = <<13\*11=143>>143 dollars.
The bus company gets 143-14 = <<143-14=129>>129 dollars in revenue.
### Answer: 129

Expected answer: 129

Correct? Yes

πŸ”— Follow-up

Problem: Following the previously described bus ride, where, after passengers got on and off, the company collected fare from each remaining passenger and deducted a $14 service fee, the company then had to pay a $23 parking fee for the bus at the end of the day. After all these expenses, how much revenue does the bus company have now?

Mixtral 8x22B:

 Reasoning: The bus company had 129 dollars in revenue after deducting the service fee.
The bus company had to pay a $23 parking fee, so the remaining revenue is 129-23 = <<129-23=106>>106 dollars.
### Answer: 106

Expected answer: 106

Correct? Yes

πŸ”— Follow-up

Problem: Suppose we revisit the scenario of the bus ride. This time, imagine that instead of 37 passengers initially on the bus, there were only 28 passengers. Then, the bus picked up 20 more passengers at the next stop, but 44 passengers get off before the next stop. The remaining passengers each pay a bus fare of $11, but the company also deducts a $14 service fee from the total fares. How much revenue does the bus company get in this situation?

Mixtral 8x22B:

 Reasoning: The bus has 28+20 = <<28+20=48>>48 passengers after the first stop.
The bus has 48-44 = <<48-44=4>>4 passengers after 44 passengers get off.
The total fare collected is 4\*11 = <<4\*11=44>>44 dollars.
The bus company gets 44-14 = <<44-14=30>>30 dollars in revenue.
### Answer: 30

Expected answer: 30

Correct? Yes

πŸ”— Problem

Problem: A pirate found a treasure chest with 13 emeralds, 42 rubies, and 19 sapphires. He gave away 43 of these precious gems to his crewmates. How many gems did the pirate have left?

Mixtral 8x22B:

 Reasoning: The pirate had a total of 13+42+19 = <<13+42+19=74>>74 gems.
He gave away 43 gems, so he had 74-43 = <<74-43=31>>31 gems left.
### Answer: 31

Expected answer: 31

Correct? Yes

πŸ”— Problem

Problem: A certain reserve has 16 ginger giraffes. They then bring in the same number of golden giraffes as they had of the ginger ones. Later, they decide to add another group of 46 greyish giraffes. What is the total number of giraffes in the reserve now?

Mixtral 8x22B:

 Reasoning: The reserve initially has 16 ginger giraffes. They bring in the same number of golden giraffes, which is also 16. So, the total number of giraffes after adding the golden giraffes is 16 + 16 = <<16+16=32>>32. Later, they add another group of 46 greyish giraffes. So, the total number of giraffes in the reserve now is 32 + 46 = <<32+46=78>>78.
### Answer: 78

Expected answer: 78

Correct? Yes

πŸ”— Follow-up

Problem: After successfully populating the reserve with various giraffes, unfortunately, 2 of the greyish giraffes suddenly moved out of the reserve. How many giraffes are there now in the reserve after the 2 greyish giraffes left?

Mixtral 8x22B:

 Reasoning: Initially, there were 78 giraffes in the reserve. After 2 greyish giraffes moved out, the total number of giraffes in the reserve is 78 - 2 = <<78-2=76>>76.
### Answer: 76

Expected answer: 76

Correct? Yes

πŸ”— Follow-up

Problem: Let's reconsider the original scenario where the reserve started with ginger giraffes. But this time assume that the reserve initially had 42 ginger giraffes instead of 16. They again brought in the same number of golden giraffes as the ginger ones. Later, they decided to add another group of 46 greyish giraffes. What would be the total number of giraffes in the reserve now under this new scenario?

Mixtral 8x22B:

 Reasoning: The reserve initially has 42 ginger giraffes. They bring in the same number of golden giraffes, which is also 42. So, the total number of giraffes after adding the golden giraffes is 42 + 42 = <<42+42=84>>84. Later, they add another group of 46 greyish giraffes. So, the total number of giraffes in the reserve now is 84 + 46 = <<84+46=130>>130.
### Answer: 130

Expected answer: 130

Correct? Yes

πŸ”— Problem

Problem: A turtle decides to swim. One day, it travels as many leagues as 11 plus 10, then multiplies that by 16 to get the total distance it swam that week. Later, it realized it had over calculated the distance by 41 leagues. What is the real distance it swam that week?

Mixtral 8x22B:

 Reasoning: The turtle traveled 11+10 = <<11+10=21>>21 leagues in one day.
The turtle traveled 21\*16 = <<21\*16=336>>336 leagues in one week.
The turtle over calculated the distance by 41 leagues, so the real distance it swam is 336-41 = <<336-41=295>>295 leagues.
### Answer: 295

Expected answer: 295

Correct? Yes

πŸ”— Follow-up

Problem: Continuing from the previous scenario, consider that the turtle realizes that it originally miscalculated the daily travel distance. Instead of swimming 11 leagues plus 10 a day, it actually swam 11 leagues plus 17 leagues a day. After multiplying that daily total by 16 for the week, and subtracting the over-calculated 41 leagues, how much did the turtle actually swim in the originally estimated week?

Mixtral 8x22B:

 Reasoning: The turtle actually traveled 11+17 = <<11+17=28>>28 leagues in one day.
The turtle traveled 28\*16 = <<28\*16=448>>448 leagues in one week.
The turtle over calculated the distance by 41 leagues, so the real distance it swam is 448-41 = <<448-41=407>>407 leagues.
### Answer: 407

Expected answer: 407

Correct? Yes